#help-27
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- its first derivatives can't be defined at origin since the vector function is discontinuous there
this theorem is an "if then". just because the assumptions dont hold for an electric field doesnt mean its not conservative
if x is a dog then x is an animal. but if x isnt a dog that doesnt necessarily mean x isnt an animal
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how do I do this
it’s so hard
no clear piece of paper no nothing
<@&286206848099549185>
help
my brain hurts
could you zoom in on the graph
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How is the point (0,1,2) found?
I randomly picked x=0 and solved for y and z. Hopefully this is the correct way?
Are you looking for points on this line?
If so all points on the line must satisfy the equation
So if you artificially add more constraints you can get a unique point from the line
Yes
🧐
What do you mean exactly
$z$ is already constrained to a plane.
草w
So you just added $x=0$ to find a specific point, given that a relationship between $x$ and $y$ exists
草w
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Hello
I’m confused on what it’s asking for the values
!help
Please read #❓how-to-get-help
If the edge length is given, find the volume
If the volume is given, find the edge length
How would you find it?
Could u give me a idea with the first one
No I haven’t been shown that yet
But I kinda have a idea it’s just the power of the 3rd?
If the side length is $s$, then the volume is $V=s^3$
SWR
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Hello guys,
Context: I'm working on a 3D project where I have a camera moving arround the Origin (0, 0, 0) and always directed to it
I need to set 2 points in a way they always seems to be at the same place on my screen, wherever my camera is
A bit like If i just marked a big dot on my screen and make my camera moving (the dot wont move because it's marked on the screen and not in the 3D space)
just take lines starting from your camera (maybe rotating as well if the camera can rotate). Make sure they're in the field of view. Pick a point on this line.
Basically using the fact that a pixel corresponds to a direction
The camera will move arround a sphere and will rotate to always be in the direction of the Origin
How do you take lines (I'm struggling to understand lines equation in 3D) (ps: sorry for my english i'm french 🙂 )
alors on peut aussi parler français en fait
si tu considère que tu as un repère local associé à ta caméra c'est simple
Incroyable ^^
Du coup pour être plus précis sur mon problème, j'ai une caméra qui pourra se déplacer sur n'importe qu'elle point de mon espace 3D mais sera toujours orienté en direction de mon Origin
Ce que je cherche à faire c'est avoir un point qui semble complètement immobile sur mon écran malgré les déplacements et rotation de ma caméra
J'ai cru voir que j'allais avoir besoin d'équation de droites dans l'espace
sinon vu que la caméra peut tourner en place il faut prendre ça en compte d'une manière ou d'une autre
Tourner en place c'est à dire ?
tu peux regarder le même point depuis le même endroit en mettant ta tête à l'horizontale
et à ce moment là l'image a tourné de 90°
Je suis d'accord
Les seules informations que j'ai aussi sont les coordonnées de ma camera et les coordonées initiale du point dans l'espace
Elle peut tourner mais elle s'oriente toute seule vers (0,0,0) je regarde si j'ai un moyen de récupérer ca 🤔
car si il y a possibilités comme ça il faut le prendre en compte et selon l'implémentation des rotations, ça se complique
où alors tu programme juste séparément le truc pour s'afficher à telle position sur l'écran plutôt que de poser un truc dans l'espace non ?
J'ai pas accès à la rotation de ma caméra mais elle peut se calculer avec ses coordonées non ? 🤔
J'ai vraiment besoin que ce point reste dans l'espace pour lui appliqué d'autres choses après 😦
ok
si tu sais comment elle tourne oui
mais sinon à une position correspond tout un cercle d'orientations secondaires
toutes les directions possibles de l'axe menton-nez si tu veux
Oui, pas sur de tout comprendre mon niveau de math est resté coincé à la première et encore ^^
Si tu veux je peux te montrer avec un partage d'écran la problématique ?
je vois le truc, mais sans connaître l'implémentation c'est compliqué de savoir qu'est ce qui ferait une bonne solution
car visiblement la rotation de ta caméra se fait implicitement, or on veut la connaître
Oui exactement
d'où l'intérêt d'un repère local qui donnerait l'orientation
Mais pourrait on déterminer sa rotation connaissant sa position et sa direction qui est tout simplement son point (C) vers O => CO (vecteur)
rotation et déplacement sont à priori indépendants
idéalement elle tourne pas
mais selon comment c'est codé...
t'utilise un logiciel type unity ou unreal engine je suppose ?
Enfaite j'ai des spheres qui sont affiché et je peux tourner en "orbite" autour de celles si (pour que mes spheres restent toujours dans mon écran)
J'utilise ThreeJs et D3js
donc tu code tout ça toi même en javascript ?
J'aurais préféré xD
Oui tout à la main 😄
donc tu t'est pas encore posé la question de l'orientation de la caméra
tu sais pas où sera le haut de l'écran
Si la caméra est toujours toujours orienté vers l'origin
on est en 3D
il y a 2 angles en sphérique
juste parce que tu définis ce qui est au milieu ne dit pas si tel point voisin sera dans la moitié haute ou la moitié basse de l'écran
C'est à dire je ne comprends pas le problème que j'ai du coup
donc c'est gênant pour fixer un point sur l'écran si on sait même pas où il va apparaître
Je sais ou il apparait initialement
Est ce que tu peux vocal sinon je peux te montrer visuellement ce que j'ai déjà
vocal ça va être un peu dur
On est pas obligé de parler c'est plus pour t'apporter un support visuel
je suppose que tu as un objet caméra dans l'un de ces modules
Oui
quand tu le fais pointer vers l'origine, tu peux pas définir une orientation secondaire de la même manière ?
Qu'est ce que l'on appelle une orientation secondaire ? 🤔
je programme pas des jeux moi
mais logiquement t'a 2 informations d'orientations pour ta caméra
ça devrait être documenté quelque part lol
Elle est géré automatiquement par D3js
Je sais que sur mon écran (le centre aussi bien en x que y est toujours l'origin)
et dans quelle direction est (1, 0, 0) par exemple ?
vers le haut, le bas, la droite, la gauche ? Si tu veux fixer un point sur l'axe des x positifs de ton écran il faut savoir quelle direction c'est en 3D
Dans ce cas là mon point serait à droit là
peu importe l'emplacement de la caméra ?
Du coup non si ma caméra n'est plus en (0,0,1) mais en (0,0,-1) la ca sera inversé et du coup ca serait à gauche
en si elle est en (-1, 0, 0) il est au centre
donc il est pas du tout toujours à droite
si il est détaché de l'origine
Là il serait toujours à droite pour moi 🤔
t'es même pas cohérent
Je suis perdu là
Reprenons, on va dire que ma camera se déplace à distance fixe (on rajoutera le problème de zoom plus tard) du centre O
Elle peux donc avoir pour coordonnées n'importe qu'elle point sur la sphere de rayon (distance Caméra à O)
Elle sera toujours orienté de sorte que le point central de mon écran sera O
et j'ai besoin d'afficher un point sur mon écran de manière fixe sur un plan 2D on pourrait dire (0, 90% de mon écran)
tu veux afficher quoi d'ailleurs ?
une sphère
est-ce que tu sais dans quelle direction réelle est le haut de l'écran ? i.e. le point (0, 1) (si (0, 0) est le centre) correspond à quelle direction depuis l'origine ? Car il faut savoir comment la caméra est tournée
savoir si la ligne (x, 0) de l'écran correspond à l'axe (t, 0, 0), (0, t, 0), (0, 0, t), (0, t, 2t) ou autre
en gros c'est ça le problème
une fois que tu sais ça c'est facile de placer un point à (0.45, 0) sur l'écran
Je dois comprendre ce que c'est une direction réelle (pour moi une direction c'est un vecteur)
le vecteur (1, 0, 0) définit l'axe (x, 0, 0) par exemple
évidemment
oh wait
à chaque point correspond tout une ligne
Oui je suis d'accord avec ca ^^
donc une ligne de l'écran correspond à une partie de plan
j'avais oublié
la question reste, en soit, on peut dire
la partie du plan associé à (x, 0) (l'axe horizontal de l'écran), à une profondeur telle que l'origine soit dedans, correspond alors à quelle direction ?
ce qui est pas forcément facile à savoir selon l'implémentation en fait
t'a pas un lien vers la documentation de ta caméra, si elle est bien ?
Je vais te trouver ca attends
elle est où la caméra la dedans
Tiens voilà j'ai un truc vraiment comme ca en therme de caméra : https://vasturiano.github.io/3d-force-graph/example/controls-orbit/
J'ai pas l'impression que ca soit vraiment documenté enfaite je peux juste set un type de graph: ForceGraph3D({controlType: "orbit"})
visiblement la caméra est toujours tournée de la même manière si elle est dans la même position
donc il suffit de connaître cette orientation
okay si tu veux je peux générer des coordonnées avec ma caméra et des points ?
ca peut nous permettre de déterminer son orientation
i.e. prendre un point de l'espace et trouver sa position sur l'écran ?
idéalement c'est quand même accessible quelque part
De mémoire D3js utilise la caméra de Threejs en fond jje vais fouiller dans le code source
Je devrais avoir sa direction par défaut
Il existe une fonction
Il semblerait que ca soit ca par défaut : -0 -0 -1
qui est la direction de quoi ?
elle commence en (0, 0, 1) ?
oui
tu viens donc de remarquer qu'elle pointe vers l'origine
ce qui serait pratique serait l'orientation qui permet de dire "quand je regarde depuis le vert clair, le rouge est en haut à droite"
plutôt qu'en bas par exemple
comme ça on peut déterminer que la droite c'est en gros le bleu clair
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Someone make this make sense
@barren pike Has your question been resolved?
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is this the same thing as assuming that p and q are coprimes?
well that's the definition of coprime
ahh tank you ^^' then i will continue with, whole values are refering to integers in this case right?
yeah
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Given are two parallelograms ABCD and AECF with common diagonal
diagonal AC, where E and F lie inside the parallelogram ABCD.
Show:
The circumcircles of the triangles AEB, BFC, CED and DFA have a point
in common.
tried with coordinates but is there a smarter way
do you have a diagramm of this ?
think you can help?
yes, i will think of this let me some times
ok
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oh ok
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I'm doing inverse trig functions can someone help me to do 47 please I dont get it
Like what angle is sin of 4/5
let arcsin(4/5) be equal to x
Ok
arcsin(4/5) = x
sin(arcsin(4/5) = sin(x)
4/5 = sin(x), right?
@restive river
the question is asking you to find cos(arcsin(4/5))
which is cos(x) now
and then you can solve :)
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sup
i need help on a question that is related to percentages
the q : K invests 400 for 3 years at 2.5% simple interest per year
work out : the amount of interest in 3 years
so im wondering
are you supposed to multiply 2.5 * 3
if you mean to ask whether you can just answer 7.5 and be right, no, you cannot.
but if you mean to ask whether that could be an intermediate step in the calculation, then yes.
thats what im asking
so basically : 7.5/100 * 400?
yes
then what abt : the amount of interest earned in 1 year
do the same calculation but with your time frame set to 1 year instead of 3 years.
no, the interest earned in 1 year isn't $2.5 as you just apparently said.
it's different?
in what way?
wait
is it just 2.5/100 * 400
@pseudo basin
that equals 10
was trying to get you to be more precise with your wording instead of just throwing numbers around.
ohh
yes, the interest earned in 1 year is (2.5/100) * 400
that helps actually ty
the next q : the total amount her investment is worth at the end of 3 years
does this mean you should add?
and again imprecision strikes.
"does this mean you should add?" add what?
add your age to the weight of president biden?
you add the principal to the interest.
again, no.
by your logic, the $400 investment is going to shrink to a mere $40 after all this. somehow.
Ann
do you mean that 400 is the principal and 30 is the interest?
or
2.5 is the interest?
400 is the principal, i.e. the amount originally invested
30 is the interest, i.e. the amount you gain on the investment
2.5**%** is the interest rate, i.e. the percentage of your principal which is added to the account every year as interest
yes...
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hello need help with letter b below
By the way, above, $\mathscr T_1$ is a topology on the set of real numbers. To answer b, can I use the arbitrary intersection of $U_n = (-1/n, 1/n)$ where $n \geq 2$ is an integer?
strikersigmaV
@gusty vale Has your question been resolved?
<@&286206848099549185>
How do you explain why the arbitrary intersection of $U_n$ is not in $\mathscr T_1$? I'm asking to confirm my guess.
strikersigmaV
@gusty vale Has your question been resolved?
are you told that T_1 is a topology or is it just that set given
Its a given in the problem.
I guess yeah, because otherwise b would be trivial
@vast rain am I right in assuming I can use any open interval like $U_n$ above? since they are open sets but their arbitrary intersection is not open: ${0}$. so I'm assuming that since its a topology, it can only have open sets
strikersigmaV
the topology defines the open sets
you can't use the standard topology's definition of open sets
I don't believe that (-1/n, 1/n) is open in that topology anyway, since all sets in that topology have to be of the form (a, infinity)
and yeah I can see how you would prove that it's a topology
probably the trick here is to use arbitrary intersections to construct an interval of the form [b, infinity) and then it's simple to argue it's not in the topology
stop giving false information smh
How about $U_n=(-1/n,\infty)$?
strikersigmaV
yeah seems like that would work
in general, any sequence of numbers that converges from below up to some number
I tried to help
bruh you gave blatantly false information about something you didn't know about
how is that more helpful than just rolling a die and giving an answer based on the number of it
even chatgpt is more helpful than that
since the arbitrary intersection of this new $U_n$ is still ${0}$. does the same logic apply?
strikersigmaV
oh sorry my bad yeah you're right its this one
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Can someone help me with this question?
can some one please help me with this question?
specifically the second part
"What if Max wants to know..."
the answer is this but I dont understand
the formula that I have for geometric distribution has (1-p)^x-1(p)
this one is missing the p
what happened to it?
@rich barn Has your question been resolved?
yes that's the density
why is it that the more trials i do the probability goes down?
(1-P)^x-1(P)
what answer are you looking for
$P(?) = (1-p)^{x-1} \cdot p$
riemann
What's the left hand side
x=6?
Specifically $P(X=6)$
riemann
So here $x=6$
riemann
But again, you're not asked to compute $P(X=6)$. what are you asked to compute?
riemann
You're making the same mistake as before of applying the formulas you memorized without appropriately interpreting them
Interpreting the formulas in probability is very important
Yes.
but why is it that as X bound increase the probability goes down
should it not be the other way
what does "X bound increase" mean
for example should not at least 6 be smaller then at least 7
because chances of not happening at 6 should be lower then chances of it happening at 7
because the more you try the more you are likely to encouter a defective light bulb
intelectually i dont unerstand it
you're not backing up anything you're saying with math
"should be" isn't justification
i dont know how to use that TeXit it
stop
if you can't explain it in this simple problem
the more you play the more chances you will encouter the ticket
you're not gonna be able to explain it in a more complicated lottery instance
ok then what should i explain?
in the context of your problem
so my chances of encountering a defective light bulb is 0.04
the first time i try the probability is 0.04
the second time i try it is 0.0384
the third time in try it is 0.0368
i feel like the probability should be going up
because the more light bulbs i test the more chances of me finding the defective light bulb
im sorry i just dont understand
math doesn't work around your feelings
can u please help me inteectually understand
Do you agree that $P(X=6)$ and $P(X=7)$ are two disjoint events?
riemann
which one is which?
yes they are independent
yes they are independent
hello?
Convince yourself that P(X > 5) = P(X=6) + P(X>6)
Or 6 and 7
Then compare which one's larger
could you explain why the mre light bulbs you test the less ur odds become of finding a defective light bulb
.
i donnt understand
does this make sense
probability of finding a def on 5 or bigger is proability of finding a defect on 6 or bigger then sixth?]
yes that makes sesne
apply it to your problem
riemann
use this relation
whenever you answer, you should ask yourself if you're using math or just emotion
if you're using emotion, that's not an answer
emotions? what are those
things like this
and this
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how do you get the 1 from 1- 1/21?
It's a probability axiom. The probability of the compliment of an event occurring is 1 - the probability of the event
when would you know when to do this?
how*
If the result is not odd, it has to be even. Thus the event of it being odd and even are complimentary
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i think
i might be confused about how bijections work on sets
sorry functions
im used to funcitons being defined
by like
for instance defined on f(x) = x^3
but not using just non empty sets without some equation
so the f: X -> Y means that the domain is X and the codomain is Y
f is some function, but they don't tell you what it is, i.e. what it does to every input in X
The domain and codomain are part of the defintion of the function
What it does to each element in the domain is also part of the definition
Here f : R -> R
You do $f$ first, then $g$. $f$ is not a surjection means that there exists some $y \in Y$ such that there is no $x \in X$ such that $f(x) =y $. $g$ is not an injection means that $g(y_1 ) = g(y_2)$ for some $y_1 \neq y_2$.
DavidL1450
chatgpt user?
doesn't seem like chatgpt
fair
Chath gpt does not render math text like that
it does write LaTeX
uh okay sorry where do i star
but it doesn't put the dollar signs
weirdly enough maybe you can try a diagram
It just seems like normal symbols you would use in text, not latex per se
I think it uses \( and \)
Like I haven't seen it use latex commands with backslashes
eh ive seen it use \boxed
Since $g$ is not an injection, $g(y_1) = g(y_2)$ means you must "lose information" when applying $g$. To make $g \circ f$ bijective, make $g$ lose information on elements that are outside the range of $f$.
DavidL1450
huh
I've seen it use \begin{align*} and \leq; it usually uses it if you give input in LaTeX
wait sorry can i ask about the question i asked
yeah so david's hint is pretty applicable here
We should back track a little
Does the statement make sense now
so you know that you can make X=Z and g circ f the identity, since you're asked for a bijection anyway
like idx?
yes like id_X
so pick g and f such that this works but f is not surjective and g is not injective
my understanding of identities is rlly bad
by identity I mean that $(g \circ f)(x) = x$, i.e. it spits the same thing out
Saccharine
well yeah, that's the idea
all that means is that it puts out the same thing it takes in
ohhhh
$id_{A} : A \to A$ is the function that maps every $x \in A$ to $x$, that is $id_{A}(x) = x$ for all $x \in A$
Mikkel
It won't make my "id"'s fancy 

so for it to not be a surjection or a bijection it needs to spit out an identity
Saccharine
no
im completely misunderstanding then
It's just that the identity-function is bijective, so it is an obvious choice for a function
For $g \circ f$
Mikkel
what so g circ f = h(x)
because it will literally spew out the same thing
well
g circ f (x)
Are you allowed to choose the elements in X, Y and Z, or do you need to keep it somewhat arbitrary?
Most probably allowed to specify them
[I think you can pick the sets X, Y, Z to be as you want them to be]
okay
(unlike the other exercise, this is an "existence" exercise rather than a "for all" type one)
yeah
if it outputs itself
then everything will have a unique output
for every unique input
Yes
Try to imagine sets
And an arrow between them
idk like x = {1, 2, 3}
Sure
so like x, y, z = {1, 2, 3}
Because if you are allowed to specify the elements chosen in X, Y and Z, you can just choose f : {1} -> {1, 2} defined with f(1) = 1, which is obviously not surjective, and g : {1, 2} -> {1}, defined by g(1) = 1, g(2) = 1 which is obviously not injective. Here you will get (g ∘ f) : {1} -> {1} such that (g ∘ f)(1) = 1, which is obviously bijective.
There's just an answer
I should really get out of the habit of writing "obviously" this much, when 50% of what I write is bull crap
No. Only 1 question per life time. Come again when you're reincarnated
you write obviously when you don't have a proof for it and the hw assignment is due in 15 minutes
uh oh another business major coming up
Well... Obviously
HAHAHA
Bruh, I had one economics course, and I hated it
they force us
What does the set [n] represent? The integers from 1 to n, or?
dopamine I believe in u
I don't
obviously you can do it, and the obviously isn't because the assignment is due in 15 minutes
no
obviously
It's 2 AM in 10 minutes for me 
it's ok I took the L on a lot of assignments in university
my math major friends made fun of me
but look I'm still breathing
Can you just like, choose not to do your assignments
set of natural numbers from 1 to n
but yeah i think my proof is like very wrong
did i even prove injectivity correctly
If this is where you proved it, not really
The aim of proving injectivity is that you assume that you have outputs being the same and show that you force the inputs to be the same
I don't know why you're making such a big deal out of it. You could just have said "The proof is trivial and left as an exercise for the grader", and it is practically proven already
hey at least you got a function that worked
Whereas you’ve assumed the inputs are the same
MY FAVOURITE PHRASE EXERCISE TO GRADER
Yea, you (tried to) show that it was well defined (that is, each input has a unique output) whereas for injectivity you need to show that each output has a unique input basically
Still reading through it now though 
I would say being well defined is trivial and left as an exercise to grader (sorry couldn’t resist!)
It’s not entirely clear to me how you’ve shown them to be equal 
Let me check the next page you have for you now!
cries cries
Assuming case 2 here is that 1 is not in either of the sets X and Y?
But otherwise happy 
...
And no, I'm uncultured lol 
Isn't that above average
Only by a little 😭😭
That's basically the injectivity and surjectivity bits that you need, from the top answer
I got A+s and As my first two quarters and then it slid to A-s and B+s, and by the end of my degree
we were at C-
if you drew a line through it
whwat did u study
I did computer science and statistics
a doublemajory thing except one was an online 10-week master's degree
is it {n} or {1} that i use
im suffering through cs
I want to get my master's 😭😭
You can use {1} too, the argument is almost identical
okay cool
Shouldn't you be graduate+ then
idk the master's degree was a joke so probably not LOL
If it's in computer science, wouldn't it be graduate++

do you guys enjoy math
Well played, made me giggle 
some aspects
okay can i ask more questions
other times it's very frustrating
but hang in there
there are very rewarding moments
IM NEVER LEAVING MY HOMEWORK FOR THE LAST MINUTE
dont worry
this is the first and last time
and it's pretty cool that you can use math to read about really cool things elsewhere
Me when I accidentally complete a master's degree. Whoopsi
i have no clue how to approach this
every day I'm more convinced it was a money grab from my university
Can't you accidentally solve the Riemann Hypothesis next time around
Of course the first step I would suggest is writing down definitions 
I'm one of them cool kids that doesn't pay for tuition

mine gave generous financial aid for the first 4 years, but those 10 weeks of online classes cost me $12000
like holy cow
all my internship money poof

I took intro CS for my last quarter there and got a B 😎
my school
love torture
i actually want to die everyday that im here
like no cap
But like, think how sad mom will get if you die
hmm okay so for this problem perhaps it's easiest to simply construct the input for any possible output
School will be a tiny fraction of your life that you just have to pass
maybe
loll
my attempt
cries
okokksdokoakosakd
asokdoafkgobgkdsz
Mind your language.

im trying to date a mathmajor so that i can get better at math

We don't fuck with people like that where I'm from.

i gotta fend for my survival
I once dated someone who failed high school math, but she absolutely loved making me teach her random things about linear algebra
of course she never learned anything, but that was an interesting type of crazy
Just prove it by assumption that it's true
huh
"If we assume the statement to be true, it is obviously true. Therefore the statement is proven"
Think I'm happy here
may want to justify the bottom line a bit, but good 
[bottom line holds because f is injective]
probably should add in the brackets for sets yeah?
like for a1
What course is this for?
my funeral
you also need to somehow write a_1 = a_2
Maybe that could be a proof-strategy. State that it is true, say you have a proof for it, die before you can show it
Dopamine's Last Theorem
well you don't know that you weren't insane already
i guess i did attempt to date a mtha major
wait whats wrong with this
right..
basically you need to show that f(a_1) = f(a_2) implies a_1 = a_2
yes for injectivity
F takes in subsets of B, by the way
so maybe you could take F({f(a_1)}) and demonstrate that this produces a_1
actually probably easier is to assume that f is not injective and then prove that F is not surjective
you need to change your proof for ->
you have a lot of choices
pick whichever one is most intuitive
none
okay how about I'll prove it this way:
assume that f is not injective and then prove that F is not surjective
and then you try to fix your proof maybe with some ideas from it
idk
i should take the L
dopamine we can't be taking Ls so fast
i am ready to drop out
change to business
pls we don't need more of those
i hate carnegie melon
LOL it's not a bad school is it
hmmm maybe you should take a lighter courseload and spend more time pondering things
math takes a little time to get used to
oh if you're doing CS, then this + linear algebra is probably all the math you ever need to take
you could go into something that doesn't involve it
calc 1, 2, 3, 2 discrete math courses and lin alg
also math gets more approachable as you gain experience in it
meth baby
unfortunately this is used everywhere LOL
usually, this just amounts to writing out definitions
and then trying to say things about them
for example, going with the approach I said before, let's assume f is not injective and try to prove that F is not surjective
f not injective means that there exist a_1 and a_2 such that a_1 != a_2 and that f(a_1) = f(a_2)
let's call f(a_1) = f(a_2) = b
ok..
Then, what's F({b})?
the inverse
if we pick F({b}) = {a_1}, then F is not surjective, because we cannot find any input that will give {a_2} [to justify this "because," show that if F(x) = {a_2}, then x = {b}]
and the same argument if you pick F({b}) = {a_2}
basically big F cannot generate both {a_1} and {a_2} if you have this collision, so F cannot be surjective
now try it the other way: assume that F is surjective, and try to prove that f is injective
so say that f(a_1) = f(a_2) = b, and now try to show that a_1 = a_2
LOL your messages in the artificial intelligence server are absolute chaos
STOP
is this your freshman year?
because I hate to be the party pooper, but uh second year gets MUCH HARDER LOL
Programming 
yikes that statement just made you deserve all of your suffering
doubly so
Anyways, wanna try this out?
okay I swear I'm not sociopathic and I actually have a lot of empathy for these people, but one of the funniest things to do when I was in university was look up when the assignments were due for the intro CS classes and then study near where the TAs were holding TA hours / help right before the deadline
and then just people watch
uh
its easier to leave programming to the last minute then math
because i just put the programming crack music on
and then i just draw the fuck out of my ipad
and solve the problem
most errors are almost always solved by print statements
debugging is good
debug my AI code and I'll do your math homework
how about that
I've spent days begging chatgpt to help me
im trying to make something recognize chessboards
but really just trying to better understand the related problems of VQA and captioning
Im trying to learn about rl and q learning
in highschool i was into a lot of comp vision shit
so I took an efficientnet to digital chessboards and now im trying to get a Transformer to generate text from it
but the stupid thing is training to give garbage
I used to know a lot about that, because one of my internships was doing random stuff with that
but it's all gone
just like most of the knowledge I got
yeah bc it was me
okay id be suffering less
if i didnt procrastinate this
but i did
so its on me
one direction is really easy
like you can show that if the subset relation holds, then f is an injection pretty easily
and then the other way was okay
oh yeah chatgpt actually gave a decent proof for it
NO STOP
well the right ideas kinda hard to parse
the "for some x in S cap T" is kinda unjustified LOL
since f is an injection is that for two subsets of A say C and D is if f(C) = f(D) then C=D and f(S) intersect f(T) means some variable x is in f(S) and f(T) while f(S intersect T) means some variable y is in S and T
is that even English
yes\
SyntaxError: invalid syntax
this si transitivity
chatgpt's argument is basically if you have an element f(x) in f[S] intersect f[T], then, you have f(x) = f(y) for some y in S and f(x) = f(z) for some z in T
but since f is injective, x = y = z
and therefore x is an element of S and an element of T
and therefore x is an element of S intersect T
and therefore f(x) is an element of f(S intersect T)
that mkes sense
you don't actually need the x either
Yeah why did they do it transitivity way
you could call it an element b in f[S] intersect f[T]
well it relies on transitivity
oh wait you don't
LOL
well
chatgpt is weird in a way I guess
functions are just relations
Proving this question with transitivity is the equivalent of using a for loop in the range of 1 million instead of a while true
sounds like something you'd do
I might be bad at this type of math but I’m not a dumbass
Can I just use transitifictu
not sure what you mean; transitivity is just a little part of the proof
but no you need to use injectivity somewhere
no but can i just do it the transitive way
what transitive way
@restive river Has your question been resolved?
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how do I prove that modular inverses are unique?
What does unique even mean in this case? That given a(mod k), there is only one other integer (x) at most satisfying ax(mod k) = 1?
But with the example, 3(mod 5), the modular inverses could be 2, 7, 12, 17, etc.
So what does "unique" exactly mean?
mod 5 those are all the same
only one of the numbers between 0 and n-1 is a multiplicative inverse for k
if b and c are two inverses of a, then b=b1=b(ac) = (ba)c=1c=c
but doesn't unique imply equivalence rather than congruence?
2 and 7 aren't the same number, they are congruent
I'm just getting confused with the terminology "unique" used
I thought unique implies that there is only one distinct number (x) that satisfies the ax(mod k)=1
Ok so unique in this case really means the set of values that share the same remainder class modulo k as x
The set of all congruent values is "unique"
when doing modulo you are always doing everything with equivalence classes
the equivalence classes themselves are the elements, the numbers you write down are just representants you choose
just like with fractions you dont make any distinction between 1/2 and 2/4
if I said there is a unique multiplicative inverse of 2 in Q then it is clear that I mean the equivalence class of 1/2 and I dont care about 2/4 or other ways to write it
Ok thank you!
That clears it up a lot
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can someone explain this too me i dont know where to start
Do you know the formula for arc length of a curve?
yeah i do
@heady gull Has your question been resolved?
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Hello
This is my matrix
-1/2 + i is an eigenvalue, can someone please confirm that the vector (0,1) isn’t an eigenvector associated to that eigenvalue ?
My teacher ended up with that eigenvector in class but it can’t be right, i found this :
Vecteur propre = eigenvector
What’s inspection ?
Inspection is just putting in the values and seeing whether they are right or wrong
Oh yes ofc should have done that, smart
Welp his whole correction of that exercise is wrong in that case
As someone who was wrong a lot yesterday, I know the feeling
Happens to the best of us
We suck just as much haha, should have corrected him in class
Could you try and find the solution to X’ = AX ?
It’s super long tho, might take you a while
Hahaha love you bro
Way easier than yesterday's since now there is no degenerate eigenvalue nonsense
Yep the matrix is diagonal
Still 3 matrix multiplications though, so easy to make one tiny mistake
Ended up finding this
happy to help
You probably won’t be able to help but you never know

Of that last problem?
A solution to the differential system that doesn’t depend on time
That’s the definition ( in my words granted haha )
Damn I've done stable points before...
I wish I wrote down the problem or book or chapter or anything!
Okay
Hahahab😂
So derivative with time must be 0
Yes that’s exactly it
So take derivative of solution and find the t that makes the matrix 0
I have a question regarding the fixed point but this might all be a little too distant for you 😔
In my lesson, an affirmation is made :
(I’ll try my best to translate)
The stability of a fixed/stable point for the non homogeneous equation is equivalent to the stability of (0,0) for the homogeneous equation
I have no idea why this is true
Can’t figure it out
My only book for differential equations does not go into stability, so I must have used a different book in school. 
No problem this question is a little specific haha, was kind of a stretch
This whole paragraph is taken out of context too, you don’t even have the system we’re looking at
My bad
It’s fine i’ll think about it some more and try and figure it out, I’m fairly sure it has something to do with the general solution including Xe in it
Yep can’t quite figure it out
Anyway i’ll free up the room for other people, thx for the help yet again @lusty sapphire you’re a legend ❤️❤️
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how are these equal?
is the +2 included in the product?
what is p_i
p_i is 2^{2^{i}}
i don't think they're equal then
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Is this supposed to say "f o g (x)"?

or "f o g" is the same thing as f(g(x)), the x is implied?
It's implied
hmmm, OK
f and g are called the functions
I have never seen it written like that, normally it's with (x)
So is f o g and g o f
the name of the function is f o g, so you'd find the domain of f o g, not f o g (x)
f(x) and g(x) are how the functions f and g are defined
f(x) is a number, f is a function
hmmm OK
so if I write f(g(x)) = sqrt(3x^2)
that's fine? or it should be written f o g = sqrt(3x^2)
either f(g(x)) or (f o g)(x)
