help-27

[limber wraith]

I subsituted a for 2 and 5 for b and the result isnt the same as a^3 + b^3

something must be wrong

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[raw hamlet]

what is tan in terms of the sides in a triangle?

[short walrus]

tangent

[raw hamlet]

i know that

[short walrus]

In geometry, the tangent line to a plane curve at a given point is the straight line that "just touches" the curve at that point. Leibniz defined it as the line through a pair of infinitely close points on the curve.

[raw hamlet]

ok not that tangent

[short walrus]

Tan(35°): = Opposite/Adjacent

[raw hamlet]

I wanted you to recall the trig definition of tangent

yes

opposite/adjacent

[short walrus]

yeah

[raw hamlet]

which side is opposite to Q?

[short walrus]

55 is ops

73 is adj?

[raw hamlet]

not quite

adjacent refers to adjacent leg, not the hypotenuse

[short walrus]

so 48 is adj?

[raw hamlet]

yes

[short walrus]

ok ok

so

tan(q)=55/73?

or tan(q)=73/55?

[raw hamlet]

55/48

opposite/adjacent

[short walrus]

oh yeag

[devout snow]

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[charred bolt]

I know that L_s is a partial limit from previous exercises.

So I could say that we know for any given epsilon > 0 there exists an N in N so that for some n>=N we will have that x_n in (L-eps, L+eps)

Same with L_s

dont know how to use this to solve this though

<@&286206848099549185>

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[low swallow]

why MUST 5 be 5 * 1? Why not 1 * 5?

[hollow pollen]

same thing

[dim perch]

^

[low swallow]

i figured but in another example it says could which is why i asked

[hollow pollen]

5 is prime

so it cant be factored into integers

[low swallow]

ohhh

[dim perch]

if you had seen 3 or 2 then itd also be “must”

[low swallow]

yea got it. thank you

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[craggy rover]

Hi

[craggy rover]

If (a,1) (1,-1) and (11,4) are colinear, find a

Only using distance formula and no slope something

<@&286206848099549185>

[hybrid snow]

!15m

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[craggy rover]

Help

<@&286206848099549185>

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[crimson kelp]

I need help with this question

I think I have an idea but I'm not sure about it

do I need to multiply √20 with 147 then convert it to miles?

[main gull]

That says quiz, are you allowed to be getting outside help on this?

[crimson kelp]

Not clarified anywhere so I guess I am

[crimson kelp]

[cyan obsidian]

It looks a lot like an ongoing exam-like evaluation that you're being graded on. Unless you have been explicitly told you're allowed to get external help, the assmption should be you're not.

[crimson kelp]

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[empty creek]

Number 6 can anyone help with chemistry please

[restive river]

you have to apply the gas law PV = nRT

n = w/M

M is the molar mass of Helium

[empty creek]

Ok what is R again?

[restive river]

oh wait ddid u say 6 or 8?

[empty creek]

6

[restive river]

ooof...was talking about 8

[empty creek]

Oh

We can do 8 aswell

I need to do that one too

[restive river]

R is a constant

[empty creek]

Hmm?

[restive river]

i forgot the value u can look it up

type gas constant R value

[empty creek]

8.3144598

[restive river]

yes

n will be 11.7/4

as 4 is the molar mass of Helium

convert T into Kelvin

which is temperature

[empty creek]

You add 260 right

273*

[restive river]

yeah

pressure should be in Pascals

N/m2

basically all standard units

V = nRT/P

1 atm = 10^5 Pa

[empty creek]

So I need to plug in all the info for that?

[restive river]

yes

[empty creek]

I don’t understand what the atm is

Or like what I do with it

[restive river]

just an unit for pressure

[empty creek]

Ok

[restive river]

basically 1 atm = 10^5 Pa

Pascal (Pa) is the standard unit of pressure

[empty creek]

What is n?

[restive river]

n is number of moles

n = weight/Molar mass

[empty creek]

Ok

[restive river]

weight = 11.7 given in question

Molarmass u can look it up for Helium

11.7 / 4

[empty creek]

Yeah

[restive river]

its 4 for Helium

[empty creek]

Was trying to type that

2.75

[restive river]

yea

T = 223K

n=2.75

[empty creek]

Like this?

[restive river]

almost correct

convert pressure

into pascals

1 atm = 10^5 Pascals

[empty creek]

Ok

[restive river]

multiply by 10^5

[empty creek]

26200

[restive river]

here is sample problem

[empty creek]

Saving to my phone

Is that kills pastels?

[restive river]

?

[empty creek]

Killapascells?

Killapascals

[restive river]

is what

[empty creek]

26200

[restive river]

Pascals

you multiply atm with 10^5 to get pascals

[empty creek]

Ok

This?

[restive river]

you will get the Volume in m^3 as you used all SI units

looks correct

[empty creek]

Ok I’m multiplying now

[restive river]

wait

[restive river]

how is 11.7/4 2.75?

2.92

[empty creek]

Oops

Thanks

?

[restive river]

if ypu typed the numbers right thiis should be it

i guess

[empty creek]

Answer sheet says 204 L

[restive river]

yeah thats correct

thiis is in m^3

because u used SI units

convert m^3 to Liters

[empty creek]

How?

Sorry I can’t remember this shit for the life of me

[restive river]

type on google " convert meter cube to Liters"

[empty creek]

You just multiply it by a thousand

How about 10?

[restive river]

same equation to be used

but here u have to calculate the weight

n (number of moles) = weight(w)/Molar Mass(M)

PV = nRT

PV = wRT/M

w = PVM/RT

just check on google on how to convert atm to Pascal

[empty creek]

Ok

[restive river]

and all other stuff

same thing with 12

question 12 wants u to find Molar mass (M)

[empty creek]

Ok how do I find M from here

Divide by M on both sides ?

Then divide both sides by 30.01?

[restive river]

keep M on top

[empty creek]

Oh

Then how do I solve for M if it is on top?

[restive river]

move the numbers next to M

to the other side

[empty creek]

Like divide by them?

[restive river]

like multiply and divide

based on where they are at bottom or top

or u can just solve the 4 numbers next to M

then divide by the result u get

[restive river]

looks good now multiply the denominator

[empty creek]

Ok

Key says 5.16 g NO

[restive river]

check the calculations

wait

which question are u doing

[empty creek]

10

[restive river]

10 says to calulate weight

not molar mass

12 says molar mass

n = w/M

w is weight

M is molar mass

[empty creek]

Oh

[restive river]

it says mass in the question

[empty creek]

Makes sense

[restive river]

but it basically means weight

why would they ask u to calculate molar mass of NO when its already known

google it how much

[empty creek]

Ok

30.01

[restive river]

lets just say n = mass(w)/Molar mass(M)

[empty creek]

Is w mass or weight

[restive river]

its whatever u call it lol.

i guess mass is more accurate

since ur school follows it

[empty creek]

Pop

Ok*

[restive river]

lets make n (no of moles) = mass(w)/ Molar mass(M)

i would recommend check what notations ur teacher uses

I am from India so we prolly use different symbols than u

[empty creek]

Wouldn’t it be M = w/n

Damn

[restive river]

yes

[empty creek]

Nice English

[restive river]

[empty creek]

Fr tho

[restive river]

Its like my native language

[empty creek]

Cool

[restive river]

along with 4 other languages

[empty creek]

Wow

If I don’t have the mass how can I find the mols

[restive river]

from PV = wRT/M

PV = nRT

u get n from here

n = w/M

w = nM

u want the mass right?

[empty creek]

Ye

[restive river]

M = 30.01

not w

w is the mass u are trying to find out

[empty creek]

Oh

[restive river]

M is molar mass

u checked google for

[empty creek]

Ok

[restive river]

molar mass is generally specific to a gas

it basically mean how much 1 mole of this substance weighs

means*

[empty creek]

Ok

So then I dived the other side by w?

[restive river]

u are trying to find out w so why divide

[empty creek]

To get it by itself

[restive river]

divide and multiply the numbers around it

[empty creek]

Oh yeah

[restive river]

liek last time

[empty creek]

I’m gonna simplify rq

[restive river]

whats the answer

[empty creek]

.05098858914

How do I get that to grams

[restive river]

thats in kilograms

[empty creek]

Ohh

[restive river]

multiply by thousand

50 grams?

[empty creek]

I need 5.6

[restive river]

did u convert atm to pascals?

[empty creek]

I think so

Wait

No

[restive river]

u also forgot to convert Liters to meter cube

[empty creek]

How

[restive river]

check the google convertor

[empty creek]

Ok

[restive river]

i dun remember

convert everything to SI units

SI unit for
Volume - meter cube
Pressure - Pascal
T - Kelvin

[empty creek]

Fucking finally

You’ve been an immense help to me

[restive river]

👍

No worries

[empty creek]

Is it Alrighr if I add you and ask you some other time?

Bec you are prolly the most helpful person I’ve found on here

[restive river]

Sure but I use discord super rarely

[empty creek]

Ok sounds good

I turn in HW late all the time so Dw about it

[restive river]

Yes but try asking here first

I dont open discord for days

[empty creek]

Ok will do

[restive river]

Just use when I am bored

[empty creek]

Lmao

Aight night (or morning for you)

[restive river]

Yes morning but good night to u

[empty creek]

!close

.close

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[gentle mantle]

all my calculators are failing here

[gentle mantle]

not sure how to solve it with one

[jagged kestrel]

good luck passing the test if you made a habit of just plugging everything into the calculator
not saying i haven't done just that from time to time
do as i say not as i do

[gentle mantle]

passing grade is a 55, got a 75 on the last exam

should be k

[jagged kestrel]

k
just ik ive seen you here before asking about calculators

[gentle mantle]

I dont want to work on this hw

[jagged kestrel]

a lot of math classes you can get away with that on hw but then you're useless on the test (where it's actually important) and so you fail

[gentle mantle]

im really good in class tho

[devout snow]

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[winter brook]

if it helps, convert them all into y=mx+b form

that will make it much more clear

[restive river]

do u wana know an easy way?

[jagged kestrel]

you can rule out 3 of them just looking at the y and the constant on the other side

the trick with sat questions is knowing how to do that sort of thing

[green sierra]

a c e are out

[restive river]

plug in (0,2) and (3,0)

[jagged kestrel]

the other two are easy if you just look at the sign of what the slope will be

[winter brook]

tru

[jagged kestrel]

during the SAT i wouldnt waste time writing this out

[green sierra]

finding x intercept is what im having trouble with

[winter brook]

was the SAT very time constrainting?

idk, i never got to take it so lol

[jagged kestrel]

think about where that will fall on the graph for each of the 2 slopes (of the possible answers one is negative one is positive)

you dont have to actually find the numbers to tell which is right

[jagged kestrel]

yes

[vast rain]

no it isn't

when I took it, I was bored out of my mind

did all of the questions thrice

[jagged kestrel]

youre just built different ig

[vast rain]

the math section isn't

[jagged kestrel]

i remember not finishing and having to guess on a bunch

[vast rain]

back when I did it, there was an essay though

that was actually time constrained

you just physically couldn't write the essay more than twice in the time they gave you

[jagged kestrel]

they still have an essay unless they changed it since i took it
but its optional

i remember when i took it i spent too long outlining it and only got like halfway through writing the essay

[vast rain]

I had the issue where if I wanted to revise a paragraph or change the structure of it

there was no way to do so

[jagged kestrel]

well i think you could erase what you wrote
but that would take a bunch of time

[vast rain]

yeah takes too much time

because then you have to rewrite everything

[jagged kestrel]

ye

[jagged kestrel]

wish I took maths more seriously in hs
wouldve helped me out big time in college
i took the sat twice
i got a 1290 the first time
then did worse the second time

[vast rain]

I took it once seriously but I was going for a perfect score

but then rip didn't get it

[jagged kestrel]

@green sierra did you figure this out
sorry if we're clogging up your help channel

[vast rain]

then some college consultant said I shouldn't do it again

[green sierra]

you guys over here talking about how smart yall are and im over here struggling 😂

[jagged kestrel]

i mean i got in where i wanted to go with the 1290, so ig it was fine
maybe shouldve aimed higher but it's w/e

[vast rain]

so do you know how to find the intercepts from equations of the form Ax+By = C?

[green sierra]

i know how to find y. at least i think. ex y int for b is 2

[vast rain]

how do you find them

[green sierra]

ok for b) -2x+3=6 then 3y=2x +6

then

y=2/3 x + 2

[jagged kestrel]

ye

[green sierra]

which y int is 2

[vast rain]

nah nah there's a faster way to do it

[green sierra]

to find x int is it 0= 2/3 x +2

[vast rain]

and arguably more insightful than doing a rearrangement and reading the values off

let's say you have 3x+2y=6 as the equation of your line

the x-intercept is the point at which the line crosses y = 0

and therefore, if you substitute that in, you get 3x = 6, and therefore x =2

and therefore (2, 0) is your x-intercept

likewise, the y-intercept is the point at which the line crosses x = 0

substituting that in, you get 2y = 6

and therefore (0, 3) is your y-intercept

[green sierra]

ok thank. that was so much easier than what ever the fuck i was doing

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[silent lynx]

hey

[silent lynx]

is this always going to be increasing and concave up

[jagged kestrel]

i couldn't help noticing youre taking an exam

https://tenor.com/bodJL.gif

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[devout snow]

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[wary ermine]

.reopen

[devout snow]

✅

[jagged kestrel]

dont help them cheat on a test @wary ermine

[wary ermine]

its a test?

i think it should have ended

[jagged kestrel]

idk this was in the last thing they posted

which means "take the exam"

[wary ermine]

oh no

i deleted those

[devout snow]

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[devout snow]

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[queen onyx]

no. h

Someone help

[umbral raft]

!status

[devout snow]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[umbral raft]

@queen onyx ^

and which question do you need help with?

[queen onyx]

no. h

1/tan A

That one

Wait I’ll send you what I did

[umbral raft]

ah thats what u meant

[umbral raft]

okay

[queen onyx]

Here

[stark anvil]

2tanA is not equal to tan2A

[queen onyx]

Wdym

[stark anvil]

$\frac{2}{tan2A} - \frac{1}{tan2A} ≠ \frac{1}{tanA} - \frac{1}{tan2A}$

Im sorry idk how to type the unequality sign

[queen onyx]

No no I took lcm of tanA and tan2A

[woven radish]

ColdTee

[queen onyx]

Hm

[stark anvil]

The lcm should be tanAtan2A

Not tan2A

[queen onyx]

Why though

[stark anvil]

WDYM

Do you mean why its not tan2A

And tan2AtanA instead

[queen onyx]

Ye

Oh wait

Nvm

Ok I got it

Then how do I solve it

[stark anvil]

That's not for me to find out

But i can give some hints

[stark anvil]

This is a hint

If they arent equal use the identity to convert

The denominators as equal to take lcm

[queen onyx]

Can I do this?

[stark anvil]

Why is tanA - 1 in the numerator

[queen onyx]

I was trying out smth but it’s wrong

Can you help now?

@stark anvil

[stark anvil]

Yeah

Show me what you did

[queen onyx]

Nothing after this

I couldn’t make them the same denominator

[stark anvil]

Use $tan2A = \frac{2tanA}{1-tanA}$

[woven radish]

ColdTee

[stark anvil]

It will be easier to take lcm

Then

[devout snow]

@queen onyx Has your question been resolved?

[queen onyx]

Now

@stark anvil

[stark anvil]

Im sorry how did you get cosec(2A) from that

[devout snow]

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[queen onyx]

No we have to prove it

[queen onyx]

It’s a prove that question

[stark anvil]

Can you send the question again

[devout snow]

@queen onyx Has your question been resolved?

[devout snow]

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[sterile smelt]

is ECD 78?

because IVH is 78

that means

ECD is 78

bcus vertically opposite?

<@&286206848099549185>

anyone bruh?

[devout snow]

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[slim rivet]

Can someone explain why the two terms seem to switch? (this is the wave function)

[slim rivet]

As its, 1(sinx) i thought that would mean k(sin(a)) = 1, and vice verca to the 3cos, meaning k(cos(a))=3

How come its the other way around?

[placid rover]

ksinxcosa is equal to the term sin x

sin x = k sin x cos a

sin x = (k cos a)sin x

1 = k cos a

equate coefficients at the end

[slim rivet]

Ohh okay

Thanks!

.close

[devout snow]

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[soft cradle]

https://gyazo.com/3d04fe0b3ccc2710082c842ffcf1939e

[soft cradle]

help

[restive river]

hello

[soft cradle]

hi

[restive river]

what have you got till now?

[soft cradle]

i was trying to find the common ratio between them

but

all different

[restive river]

yea it's not in a general form

well, you can always multiply a certain integer with some of the term to get it in a more general form : D

did you get a small hint of what you can do?

[soft cradle]

no, im clueless tbh

i did do questions like it and got it right

but

they were not fractions

[restive river]

i get it

well, let's just exclude the denominator for now

just look at the numerator

what is the sequence for the numerator?

[glossy dew]

hmm, its turning to e 399/798, 342/798, 266/798, 210/798, and 171/798

[restive river]

oooh no that's a bit too complicated

dw there's a simpler method : D

the numerators got 1,3,1,5,3 right?

[glossy dew]

ok...

[restive river]

a rather unconventional form

[glossy dew]

yes

[soft cradle]

yes

[restive river]

wouldn't life be easier if it was in the form of n+1?

[soft cradle]

definitely

[restive river]

why can't you just multiply certain integers in some of the terms to get that form?

[restive river]

these can be written as 2,3,4,5,6 can't they?

[jovial mauve]

+2 -2 +4 -2 +6 -4 -2... in the numerator

[soft cradle]

yup

[restive river]

what numbers have i multiplied in each of them?

[glossy dew]

ahh i get you (:

[restive river]

; D

[soft cradle]

hold on

[restive river]

@soft cradle take your time and think on it : D

[soft cradle]

u multiplied 1 by 2, and 1 by 4, and 3 by 2

[restive river]

correct

can you form a new series with this?

just multiply the numerator and denominator with the numbers you've told

[soft cradle]

same denominators, yes?

[restive river]

no no if you're multiplying something with the numerator, also multiply it with the denominator

[soft cradle]

oh yeah right

[restive river]

see the main essence of this way is to make the sequence easier for you to solve, and when we simply the fractions, they return back to their original forms : )

now, take your time and make the new series

@ me once you're done : D

[soft cradle]

ok

not sure if this is correct

@restive river

[restive river]

it's absolutely correct : D

now, you can make the numerator and denominator into separate sequences?

[soft cradle]

the numerators do have a common ratio now

but the denoms dont

[jovial mauve]

Common ratio?

Are you sure?

[soft cradle]

which is +1

[restive river]

look again

carefully look

[jovial mauve]

That is "common difference"

[restive river]

there is a proper difference

[soft cradle]

difference mb

[jovial mauve]

What pattern do you see in the numbers in denominator?

[restive river]

did you find the common difference @soft cradle

[restive river]

if @soft cradle can't find it i'll tell : )

I want to give them a moment to think

[jovial mauve]

[soft cradle]

+3 +5 +5 +9

[restive river]

eh not really

[soft cradle]

thats the only i see really

[restive river]

should i tell?

[soft cradle]

yes pls

[restive river]

it's n^2 + 3

[soft cradle]

god im dumb

[restive river]

1^2 + 3, 2^2 + 3, 3^2 + 3.... and so on : )

[restive river]

no you're not, you're a pretty fast learner

don't beat yourself up over it

[soft cradle]

ight i can do it now

[restive river]

can you solve the question now?

[soft cradle]

thx for ur help

[restive river]

you're welcomee ❤️

[jovial mauve]

There is a way to digest that n²+3.

[soft cradle]

.close

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[dusty valley]

The graph of a sinusoidal function has a maximum point at (0, 10) and it's midline at ($\pi/4, 4)$. Graph the sinusodial function. I've done this but the website says I'm still wrong. Can somebody graph this for me so I can see my error?

[woven radish]

j4w4

[fathom thicket]

what does it mean by midline

[mortal drum]

average of maximum and minimum value ig

not sure tho

[dusty valley]

This is a trigonometry question.

So you would probably have had to taken that course to even know what the question is asking.

[fathom thicket]

?

im just asking what a midline is

doesnt seem to be anything specific to trigonometry

sounds more like a graphing term

[mortal drum]

im still a student i am here so i can learn from ppl's problems

[dusty valley]

Okay, well lets all sit back and let somebody who answers this help us all then. 🙂

Because that's why I'm asking the question also, to learn.

[fathom thicket]

yh

youre right

googled it

[mortal drum]

bit of logic always works

[fathom thicket]

@dusty valleypretty sure this is what you wanted

[dusty valley]

Wow, you are a fast learner bro. 🙂 It does look like what I want.

[mortal drum]

theere is a literal answer on google

i just searched the same question

[dusty valley]

I don't think your graph is quite right though because a full rotation of a circle begins to repeat on a graph. And at 2$\pi$ on the graph it should begin repeating.

[woven radish]

j4w4

[fathom thicket]

heres a normal cos(x) graph

you can see that, when it reaches the midline

it goes 3 more times

till it goes back to normal

[dusty valley]

Maybe your graph is right. It does look right.

Ah, I guess I had the thoughts in my head wrong. I was thinking that the full rotation of the circle would be x at 8 units out since it was moving at 1/4 of pi at a time.

It would be 2 units out.

I can't quite see at what x unit your graph begins to repeat, it's not an integer I don't think.

[fathom thicket]

it repeats at pi

[dusty valley]

But it looks like it begins repeating at about 2.6

[fathom thicket]

no

thats from 2 to 4

so it looks like it begins repeating at 3.2

[dusty valley]

I'll look again

[dusty valley]

Oh well, yes, I guess you can pick different coordinates all day long and they would still be right for calling boundaries on repeats.

So, what is the formula that you used to draw the graph?

[fathom thicket]

6cos(2x) + 4

[dusty valley]

Okay, thank you very much. I had $y = 6cos(\pi/4x) +4$

[woven radish]

j4w4

[dusty valley]

So you didn't even put pi in the equation. That's interesting. I'm not sure why I thought I needed to do that.

[fathom thicket]

why would i, x already takes some form of pi input to get to the midline

i just needed to shift it

[dusty valley]

Okay, so x, is in fact, the pi, so ..... yeah, I'm just learning but thank you. You know this better than I do.

I had x and pi in the equation so I doubled up in error there since x represents the pi.

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[restive river]

can someone explain how $x^3y^2$ becomes $3x^2y^2+2x^3y y^\prime$

[restive river]

oh i just realized

is it the product rule

[pseudo basin]

indeed

btw you can just type the apostrophe for the prime symbol

$2x^3 yy'$

[woven radish]

Ann

[restive river]

ok thanks

.close

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[rotund dawn]

not sure how to move forward from here

<@&286206848099549185>

[wicked river]

what do you require

[rotund dawn]

if i try to isolate the left side by multiplying i end up subtracting an expression from the right side which will leave me without y prime

[wicked river]

no i mean

what do you need to find

[rotund dawn]

dy/dx

[wicked river]

try squaring first

then differentiate

bring the terms with y prime on one side

[rotund dawn]

squaring first to eliminate the square root on the left you mean?/

[wicked river]

yeah

[rotund dawn]

the first step

[wicked river]

yep

[rotund dawn]

ok. is the previous work that i've done wrong, or have i just made it more complicated?

[wicked river]

you have made it more complicated

[rotund dawn]

ok

makes sense that i got lost

[wicked river]

yeah

[rotund dawn]

:peepolaugh:

[wicked river]

try not to directly derivate

and simplify it before doing so

[rotund dawn]

ok

i'll try taht

thanks

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[devout snow]

@restive river Has your question been resolved?

[devout snow]

@restive river Has your question been resolved?

[untold lance]

ahhh maybe you should try posting a better quality picture?

it's hard to read

[untold lance]

i think not. though, you can try asking this in #real-complex-analysis

i'm sure someone who has mastered,real analysis would be able to help you

[devout snow]

@restive river Has your question been resolved?

[devout snow]

@restive river Has your question been resolved?

[devout snow]

@idle turret Has your question been resolved?

[dusty valley]

Is there a way to pin or highlight a dot on Desmos without me having to drag my mouse back and forth for 20 minutes?

Is this channel closed? I don't understand why it's not pinning messages and the bot keeps asking if the question has been resolved but nothing is even pinned.

[torn nexus]

ye

[dusty valley]

Kan ye?

Is it you?

You're amazing....so amazing...

[torn nexus]

me

yep i am

[dusty valley]

Who would crown me as their king?

[dusty valley]

I've been doing more of these sinusoidal graphing questions and I've realized that sometimes you must use the pi symbol along with the x. That is the part I haven't learned yet. When to include and when not to include it. How can I know?

Is this channel DEAD?

[dusty valley]

As the silence lingers ... so does my rage ...

[devout snow]

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[lone elbow]

help pls

[magic pine]

do you know how to find the area of the parallelogram?

[lone elbow]

b x h

[magic pine]

and do you know how to find the area of the circle?

[lone elbow]

pie r2

[magic pine]

if you remove the parallelogram, the area will be:
the area of the cirlce - the rea of the parallelogram

[devout snow]

@lone elbow Has your question been resolved?

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[lone elbow]

help pls

[devout snow]

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[rare mantle]

$\Sigma_{n=1}^\infty = ({\frac{4n+5}{2n-1})}^{3n-2}$

[woven radish]

Kihei

[rare mantle]

would it be right to say it diverges by nth term test?

cuz 2^infinity

[upper schooner]

,w lim ( (4n+5)/(2n-1))^(3n-2), n to inf

[woven radish]

Results provided by WolframAlpha

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Upgrade to WolframAlpha Pro!

Requested by chartbit#3171

[rare mantle]

kk

the answer key only mentions root test for some reason

i mean ig that could work too but thats just extra

[upper schooner]

I would be a bit careful with how to argue it but yea

[upper schooner]

Guessing it's the easiest way to do it?

[upper schooner]

Doing this limit is a bit of pain I would think

[rare mantle]

is 2^infinity not valid?

i mean uh

is it indeterminate

[topaz beacon]

No its determinate

1^inf is not tho

[rare mantle]

so is it okay to solve the limit by saying 2^infinity = infinity?

cuz the stuff in the parantheses can be l'hopitaled to 2?

@topaz beacon

?

[topaz beacon]

Why are you lhopping

Divide each by n

Amd youre good

[rare mantle]

I mean yeah it's still 2 tho right

[topaz beacon]

Yes

[rare mantle]

but my question is this

[topaz beacon]

Yes its still infinity

[rare mantle]

okok

ty

.close

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[magic pine]

what have you tried

[lofty sage]

so far ive found that alpha = 5pi/3 so then the sin(alpha) will be -sqrt(3)/2.

i found the cos(beta) = sqrt(8)/3 but i believe this is wrong

[magic pine]

well you are in quadrant 3

so what should the sign be?

[lofty sage]

negative?

[magic pine]

yes

[lofty sage]

i plugged everything into the sum formula [sin(a+b) = sin(a)cos(b)+cos(a)(sin(b)] and got -1-sqrt(24)/6

[magic pine]

im assuming it's all over 6

[lofty sage]

yeah

[magic pine]

then i think it should be fine

[lofty sage]

hmm the site says its still wrong

[magic pine]

oh

sin(a)cos(b) will be positive

[lofty sage]

wdym?

[magic pine]

sin(a) is negative

and cos(b) is negative

so sin(a)cos(b) should be sqrt(24)/6, not -sqrt(24)/6

[lofty sage]

oh i see, so its [-1+sqrt(24)]/6

the negatives cancel out

[magic pine]

i believe so

[lofty sage]

ty for clarifying its correct now

i gotta stop making these mistakes lol

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[carmine swallow]

whats the answer?

.close

[devout snow]

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[humble shuttle]

Help on these 2

pls

[dense nymph]

Average rate of change is C(105)-C(100)/105-100

Change in C(x) over change in x

[humble shuttle]

Is c = 37?

[dense nymph]

I don’t see a part c

[humble shuttle]

I do C(105) = 3000 + 17(105) + 0.1(105)^2 = 5887.5

C(100) = 3000 + 17(100) + 0.1(100)^2 = 5700

[dense nymph]

Yeah add them up and divide by 5

[humble shuttle]

wait

LOL

ok i got it

thank uuuu

[dense nymph]

Sorry I meant subtract

No problem

[humble shuttle]

i divided by 5

and got the right answer

For the 2nd one what do I do

2nd image

Im lost

[dense nymph]

I’m guessing you are supposed to use the definition of the derivative

Like the f(x+h) thing

[humble shuttle]

yes

f(x+h) - f(x)/h

[dense nymph]

Yeah

Have you learned the power rule

[humble shuttle]

kinda

Lol what

[dense nymph]

Uh

Wait

Don’t you replace t with t+h

[dense nymph]

Wait

Why did you divide by h again

[humble shuttle]

oh

[dense nymph]

Honestly I forgot most of this

[humble shuttle]

Lol

thanks

I got it right now

[dense nymph]

Great

[humble shuttle]

i kept putting /h

thanks

.close

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[dense nymph]

Npnp

[devout snow]

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[rare mantle]

!status

[devout snow]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[sterile smelt]

6

[rare mantle]

what do you need help with?

[sterile smelt]

im confused

how to get

the shaded part

[rare mantle]

do you know the formula for area of a trapezoid?

[sterile smelt]

no

[rare mantle]

also

[sterile smelt]

oh so

[rare mantle]

it’s not actually a trapezoid

it’s a rectangle combined with a trapezoid

so you will need to split it and solve each area separately

[sterile smelt]

base of the trapezoid is 9 and 21

height is

12

[sterile smelt]

hm?

[rare mantle]

if you look carefully, the bottom portion is a rectangle

a 3 x 21 rectangle

[sterile smelt]

63

[rare mantle]

right

so the top portion is a trapezoid

[sterile smelt]

there is 2 base?

[rare mantle]

no

you have 2 shapes here

you already solved for the rectangle

[sterile smelt]

12x9?

[rare mantle]

so now you need to find the trapezoid area

[rare mantle]

well use the formula

[rare mantle]

this is correct

[rare mantle]

this is not

[sterile smelt]

okay

[rare mantle]

are you confused?

[sterile smelt]

i used mixed

fraction

thing

right?

[rare mantle]

for what?

[sterile smelt]

this

[rare mantle]

yeah

[sterile smelt]

nvm

[rare mantle]

but your height of the trapezoid is not 12

[sterile smelt]

i do in google

[rare mantle]

do you see why?

[sterile smelt]

yea

its

9

[rare mantle]

yea

[sterile smelt]

135

is area?

[rare mantle]

yep

and add that with 63 for the total

[sterile smelt]

135+63

is

198

12x21

is

252

54

each unshaded side

is 27?

54 total

27 each

is that correct?

[rare mantle]

is this a different problem?

[sterile smelt]

oh nvm

its asking

for the shaded

could you help

me

with one more

wait nvm

thats all

thank you so much

have a nice day

!

.close

[devout snow]

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[rare mantle]

🫡

[devout snow]

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[zinc whale]

this right?

[supple knot]

No

[zinc whale]

0 and pi then huh

[supple knot]

2 of your answers are wrong and one is missing a pi *n

[zinc whale]

so 0 and pi are my answers then huh

[devout snow]

@zinc whale Has your question been resolved?

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[devout snow]

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[agile summit]

is this right not done it in class yet but have read over some stuff

[pseudo basin]

3^2 - 3^2 = 2x+6...?

where do you get that from?

[hushed wraith]

U can't just add the things inside the logs

[devout snow]

@agile summit Has your question been resolved?

[devout snow]

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[foggy topaz]

X> -1/3 find the smallest integer that satisfies the inequality

[foggy topaz]

what does satisfy the inequality mean

[placid rover]

taking a simpler example

x > 1

x = 2 satisfies it because 2 > 1

x = 0 doesn't satisfy it because 0 > 1 is false

[foggy topaz]

X is > negative 1 over 3

[foggy topaz]

oh

so X in my questions case can be anything above negavtive 1/3?

thats an integer

[icy depot]

Yes , x can be anything greater than $\frac{-1}{3}$

[foggy topaz]

oo

so how bout 0

[placid rover]

'greater than' is the technical term. Not 'above'

[foggy topaz]

no right

[icy depot]

Yes,

[woven radish]

Samarth

[humble garnet]

x can be any of the points above -1/3 and the equality will still work

[placid rover]

is 0 bigger than -1/3?

[foggy topaz]

yes

[placid rover]

then why do you think 'no'

[foggy topaz]

but what is the integer bigger than -1/3

[placid rover]

is 0 an integer?

[humble garnet]

yes

[foggy topaz]

no

[placid rover]

wrong.

integers are {0, 1, -1, 2, -2, 3, -3, ...}

[humble garnet]

What do you mean 0 is not an integer

[placid rover]

positive and negative whole numbers and 0

[foggy topaz]

but -1/3 is

-2

-2 over 6

[placid rover]

-1/3 is not an integer yes...?

[foggy topaz]

yea

[placid rover]

ok, but that isnt an issue

[foggy topaz]

it should be -1 then

[placid rover]

let's step back

"what's the biggest integer that's smaller than 10.5"

Can you answer this question

[foggy topaz]

10

[placid rover]

ok

[foggy topaz]

ujikwehfgyujawsevgujVYJG

[placid rover]

This is asking a similar question

X > -1/3, find the smallest such integer X

In other words, find the smallest integer bigger than -1/3

Think carefully why the way I rephrased the question is correct