#help-27

1 messages · Page 52 of 1

wooden wraith
#

Can you show your work?

gloomy ingot
#

cos 3/5 cos 5/13 + sin 4/5 sin 12/13

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and then i just put that into the calculate to get an answer

wooden wraith
#

hm

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Those fractions don't go in the trig functions

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Those fractions are the values of the trig function

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if cos(a) = 3/5

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don't write cos(3/5)

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just replace the whole cos(a) with 3/5

mellow panther
#

Do you know the relation between sin and cos?

#

@gloomy ingot

gloomy ingot
crimson sleet
#

you got the value of alpha?

gloomy ingot
#

got the answer now

wooden wraith
gloomy ingot
#

yeah

#

so in the future if its a = 3/5 i would use it how i did previously but if its cos(a)= 3/5 i can just put the raw fraction in

wooden wraith
#

yes if you had a value for a, you could just plug it in for a

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but in these types of problems, you're usually just playing around with the trig values

gloomy ingot
#

alrigh thats fine than kyou

#

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radiant drift
devout snowBOT
#

Please don't occupy multiple help channels.

radiant drift
radiant drift
#

nvm

#

i got it

#

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radiant drift
#

nvm this next line is confusing

#

how to get from line 1 to 2

turbid shuttle
#

reopen the channel

radiant drift
#

.reopen

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radiant drift
#

@restive river ^

lunar harbor
#

You can ping the 'helpers' role after 15 min, but please don't ping individual helpers.

radiant drift
#

shut up

#

rbit is my brother

lunar harbor
radiant drift
#

@restive river sucks

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zenith lagoon
devout snowBOT
turbid shuttle
#

Show your work

zenith lagoon
#

So ,
Perimeter of Circle = 2Πr
Perimeter of Semi Circle = 2Πr / 2
= Πr
Radius = Diameter / 2
= WX / 2
= 14 / 2
= 7 cm
Perimeter = Πr
= 22/7 * 7
= 22cm
Perimeter of square = 4a ( but here its 3a )
4 * 3
= 12
Now 22 + 12 = 36

But the answer is incorrect its B

#

wait .
How to find WT and XU

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we need to add that also

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so how?

turbid shuttle
#

Well you know WX, and you know TU since STUV is a square

zenith lagoon
#

wait
22 + 14 +12

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= 48

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Bruh so damn confused

#

its 36 or 44 or 48

#

Help me

devout snowBOT
#

@zenith lagoon Has your question been resolved?

zenith lagoon
#

<@&286206848099549185>

crimson sleet
#

yo gimme a min

#

solving

#

the answer should be 30 cm

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@zenith lagoon

zenith lagoon
#

ohh

crimson sleet
#

you want me to explain?

#

ryxzan?

zenith lagoon
#

yes

crimson sleet
#

alr so one side of the square is 4cm

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and the diameter of the semicircle is 14 cm

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so the radius is 7 cm

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perimeter of the semi circle is 2pir/2

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which is pir

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so perimeter = 22/7 x 7

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= 22cm

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now since its on one side of the square we will subtract 4cm from the perimeter of the semicircle

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so the perimeter now is 22-4 = 18cm

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now add the remaining three sides with 18 cm

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so 18 + 12 = 30 cm

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there ya go

zenith lagoon
#

but 30 is not in the option

crimson sleet
#

what are the options?

zenith lagoon
devout snowBOT
#

@zenith lagoon Has your question been resolved?

zenith lagoon
#

yoo help me

#

<@&286206848099549185>

wooden veldt
#

You know WX = 14 and TU = 4. Use this to find TW and UX

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fierce rune
#

Hi :) struggling to setup the integral here, I can't seem to find one without y^2 (need y on its own so they don't evaluate to 0, i think?)

fierce rune
#

because they're square I thought the integral $\int_{-2}^{2}y^2 dx$ works

woven radishBOT
#

Syrenate

fierce rune
#

but it just gives 0, obviously

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open pendant
devout snowBOT
open pendant
#

bruh

#

when i cube root it

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i do not get 0.79

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what is happening here

turbid shuttle
devout snowBOT
#

@open pendant Has your question been resolved?

open pendant
#

What are u typing on your calc

#

I type

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^3sqrt0.50

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@turbid shuttle

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violet matrix
devout snowBOT
violet matrix
#

Can someone check if I did these correctly

#

Rrly not sure of my answers

small raptor
#

You forgot your plus C

violet matrix
small raptor
#

,w int 1/(sinx +1)

small raptor
#

Yea

#

both seem fine I think

violet matrix
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raven cape
#

hey guys

devout snowBOT
raven cape
#

after integrating I got (2x-1)^2 / 4 + C

#

is this correct?

topaz beacon
#

Wtf

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You can separate it by integrating 2x and 1 eah

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Each*

raven cape
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but why can't I integrate it together

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like this (2x-1)^2/ 2 * 2 + C

topaz beacon
#

Integration doesnt work like that

analog trellis
topaz beacon
#

Trust me, its easier if you just separate

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wha

analog trellis
#

My school called it reverse chain rule. But only works for linear inside.

topaz beacon
#

Oh my god it does

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#

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analog trellis
#

You just have to beware answers in the back of the book might look nothing alike though.

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restive river
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amber arrow
#

yo nayone

restive river
#

Would this be the correct answer?

hybrid snow
hybrid snow
restive river
hybrid snow
#

Close the channel

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open pendant
devout snowBOT
open pendant
#

how come its b^2

#

i dont get b^2

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theres only 1 b....

fossil chasm
#

yeah it should be ab not b^2

open pendant
#

weird

#

this is khan academy and hes like 10 minutes past this without correction

#

thanks

#

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little jewel
devout snowBOT
little jewel
#

How to find shaded area

sick fulcrum
#

nothing is shaded

little jewel
#

The pee color is apparently shading

sick fulcrum
#

everything looks pee colored to me tho

little jewel
#

smh

sick fulcrum
#

guessing the semicircle looking thingv

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integrate

little jewel
#

Yeah

little jewel
real grail
#

Calculate the integral of y

sick fulcrum
#

there are only 2 things to integrate

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one of them is very boring to integrate

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and too easy

red sierra
#

either you can subtract the integral pi/4 to 3pi/4 from the area of the rectangle

sick fulcrum
#

the other one is less easy

real grail
little jewel
#

Wait

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So

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2-csc^2x

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Integrate that

red sierra
#

yeah

little jewel
#

And it gives area

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Ah

red sierra
#

or you could calculate the rectangle area and subtract integral pi/4 to 3pi/4

#

either way would work

#

why would you not?

little jewel
real grail
fresh horizon
#

pee on the question

little jewel
#

2x+cotx?

real grail
little jewel
#

I am either an idiot for doing the integration wrong or substituting with the bounds wrong

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Or both

red sierra
little jewel
#

After substitution is it not pi/2 + 1 - 3pi/2 +1

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So -pi/2 + 2

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Ah I reversed it oops

#

I am an idiot I got it thanks

devout snowBOT
#

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vale barn
#

hey

devout snowBOT
vale barn
#

we have this function of the cauchy density distribution

#

$f(x) = \frac{K}{1+x^2}$

woven radishBOT
#

RickyDicky

vale barn
#

from -inf < x < inf

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i have to find the value of K and the distribution function F_x(x)

pseudo basin
#

do you know the defining property of a probability density function

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well, one of

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but the most important one

vale barn
#

ugh no

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apparently it has to be >0

pseudo basin
#

sure but thats not the one i meant here

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no, i meant that $\int_{-\infty}^{\infty} f(x) \dd{x} = 1$

woven radishBOT
vale barn
#

hmm

vale barn
#

like why is it = 1

#

im really new to probability so i just need a little bit more explanation if you could offer it

pseudo basin
#

$\int_a^b f_X(x) \dd{x} = P(a < X < b)$

woven radishBOT
pseudo basin
#

where X is your random variable and f_X is its density function

#

thats the point of the density function

vale barn
#

oh

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$\int_{-\infty}^{\infty}\frac{K}{1+x^2}\dd{x}=1 \rightarrow K = \frac1{\pi}$

pseudo basin
#

badtex but yes

woven radishBOT
#

RickyDicky

vale barn
#

is there a \imply or is it \implies

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or do i have to use \rightarrow

pseudo basin
#

\implies

vale barn
#

ah

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$F_x(x) = \int_{-\infty}^{\infty} \frac{1}{\pi(1+x^2)}\dd{x} = \frac1{\pi}\cdot\left(\arctan(x) + \frac{\pi}{2}\right)$

pseudo basin
#

\arctan

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also missing \right)

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also screwed up notation with the integral

woven radishBOT
#

RickyDicky

vale barn
#

okay

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and now what about finding the variance of this

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var(x)

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expected value and variance

pseudo basin
#

your notation there was bad but i got too distracted to point out how exactly

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$F_X(x) = \int_{-\infty}^x \frac{1}{\pi(1+t^2)}\dd{t} = \frac1\pi \left( \arctan(x) + \frac\pi2 \right)$

woven radishBOT
pseudo basin
#

this is what it should have been

vale barn
#

Right

#

thats what i did in my notebook

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but went too quickly on writing the tex so i messed it up

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from -inf to x

pseudo basin
#

anyway

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$E[X] = \int_{-\infty}^{\infty} x f_X(x) \dd{x}$

woven radishBOT
pseudo basin
#

in your case the expectation ||does not exist||

vale barn
pseudo basin
#

i happen to have seen this particular problem before, but int x/(1+x^2) dx is not hard to calculate symbolically

vale barn
#

$\frac1{2\pi}\left[\ln(1+x^2)\right]^{\infty}_{-\infty}$

woven radishBOT
#

RickyDicky

vale barn
#

the integral does not converge

pseudo basin
#

yes exactly

vale barn
#

$Var(x)=E(x^2)-[E(x)]^2$

woven radishBOT
#

RickyDicky

pseudo basin
#

when the expectation fails to exist, so too do any other higher moments.

vale barn
#

ah

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$Var(x) \rightarrow \inf$

woven radishBOT
#

RickyDicky

vale barn
#

covariance is just sqrt(var(x)) right?

#

and that doesnt exist either

pseudo basin
#

it's \infty not \inf

#

also that's bad notation anyway

vale barn
#

woops

pseudo basin
#

better to just say in words

#

Var(X) does not exist

#

thats it

vale barn
#

yeah okay

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#

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jaunty seal
#

quick question, we have to like find x here: 2x^2-4x=0
i wrote:
2x(x-2)=0
2x=0 —> x=0/2=0 and x=2

jaunty seal
#

is this correct

gray gust
#

yeah

jaunty seal
#

Ok tysm

#

.close

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hollow pollen
jaunty seal
#

thanks again :)

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robust mason
#

Help

devout snowBOT
robust mason
#

Alright so can someone solve these for me pls

#

And explain it to me if possible

gentle mantle
#

what are you asking?

robust mason
#

To solve the question

gentle mantle
#

the english in that is kinda, weird

robust mason
#

It's still understandable though?

dull otter
robust mason
#

Do you know french

dull otter
#

oui

gentle mantle
robust mason
#

French isn't my native but if you can understand the exercise in french and explain it to me in English that would be great

dull otter
#

envoyez-le en francais s'il vous plait

warped relic
#

Looks like the straight line equation question which asks about y-intercept and slope and then asks for the equation itself

robust mason
#

Alright here

dull otter
warped relic
#

Wow

dull otter
warped relic
#

Chief we don't give answers. We explain them

dull otter
#

f(-2) = -4

dull otter
robust mason
#

Thank u

dull otter
robust mason
#

I see, so how do I find it

dull otter
#

the height is where that arrow hits the line

dull otter
robust mason
#

3?

dull otter
#

my bad, what i meant to say was where does the arrow intersect with the line

#

the line is f(x)

robust mason
#

By the way sorry but where do we get the x from

dull otter
#

f(1) means what does the function equal at x=1

#

imagine f(x) = x+2

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f(1) = 1+2 =3

dull otter
robust mason
#

Oh I see

#

Although not completely but I'm starting to understand it a bit

dull otter
#

that's ok

robust mason
#

So how did you find f(-2)

dull otter
#

i will explain a bit better with this graph

#

this is the graph of the function f(x) = x+2

dull otter
# dull otter

the axis which is horizontal or lying flat is called the x axis

#

the numbers on the x axis represent our x values

robust mason
#

Oh

#

I see

dull otter
#

the vertical axis is called the y axis

#

it represents the value of the function

robust mason
#

So x=2?

dull otter
#

for f(1)?

robust mason
#

Ah

dull otter
#

i was asking

#

did you mean f(1)

robust mason
#

Yes

dull otter
#

ok well x doesnt equal 2

#

f(1) = 2 yes

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but this is only when x =1

#

f(1) = 2

#

the thing inside the bracket is x

dull otter
#

f(x) = x+2 right

robust mason
#

I see

dull otter
#

look at when x = 2

#

f(2) is equal to 2+2 which is equal to 4

#

f(x) = x+2

#

f(2) = 2+2

#

f(2) = 4

#

look at the point which is right above 2

robust mason
#

Damn so complicated

dull otter
#

it's not really

#

you just have to notice the pattern

dull otter
robust mason
#

Yes

dull otter
#

the point right above 2 is 4

#

notice that?

robust mason
#

Oh yeah

dull otter
#

when x=0
f(x) = x+2
f(0)=0+2
f(0)=2

#

notice that the point above 0 is 2?

#

btw we can start calling "the point above" as y

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or better, f(x) = y

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y=x+2

dull otter
robust mason
#

I see

#

no sadly

dull otter
#

the flat line is the x-axis

#

we call it the x-axis because it represents the x values

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the line which is standing is called the y-axis, it represents the value of the function

robust mason
#

Oh I see

dull otter
#

what is f(1) in this case then

robust mason
#

2

dull otter
#

what is f(1)

f(x) = x+2

#

f(1) =?

robust mason
#

x+1?

#

Lmao

#

Sorry for dumb tbh

dull otter
#

f(x) = x+2

#

f(1) means we are letting x =1 in x+2

#

so f(1)

#

?

robust mason
#

Damn my brains fried wait

dull otter
#

ya bro just watch organic chemistry tutor

robust mason
#

Whats that

dull otter
robust mason
#

Thanks for pointing it out

devout snowBOT
#

@robust mason Has your question been resolved?

devout snowBOT
#

@robust mason Has your question been resolved?

robust mason
#

My question has not been solved

supple knot
robust mason
#

Alright

#

.close

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stark obsidian
devout snowBOT
#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
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@stark obsidian Has your question been resolved?

stark obsidian
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.close

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white wagon
#

Ideas to show the sequence -1,1,1-1,-1,1,1,... and sequence -1,-1,-1,-1,1,1,1,1... without using mod?

white wagon
#

Solved.

supple knot
#

.close is the command u want

sonic smelt
#

a_n = 1/3 - 4/3 * cos(2pin/3), starting at n = 0

#

Not any ideas yet for the second one

white wagon
#

.close

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white wagon
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somber rampart
#

Hi, can someone explain this to me?
This seems to be correct:

somber rampart
#

But using the quotient rule I get a slightly different result:

#

What am I doing wrong? I'm going crazy

restive river
#

would help if you showed what you tried to get there

supple knot
#

,w diff e^(x/2) / (x^2+3)

restive river
somber rampart
#

I just used the quotient rule, so the numerator being f(x), and the denominator g(x):

f'(x)g(x) - f(x)g'(x) / g(x)^2

torn vessel
#

you put the 2 you get in the denominator from differentiation e^x/2
But that only affects the first term, you need to get a common denominator with the second term befor eyou can do that

somber rampart
#

I differentiated e^(x/2) to get (1/2) e^(x/2), and just pulled down the 2

#

is that wrong?

torn vessel
#

yes

#

because now it affects the -2x * e^(x/2), which it shouldnt

#

until you get a common denominator there

somber rampart
#

oh, i see now

#

aaalright

#

thank you, that helped

#

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soft shore
#

idk where to start

restive river
#

do you know the definition for a probability density function?

soft shore
#

well

#

I'd be lying if I said I did

restive river
#

would be helpful to review your notes then

#

basically, for (a), we use the definition to equate the integral of f(x) to 1

#

(ie "the sum of the probability of all events is 1")

soft shore
#

hmm I see

#

thanks for the pointer, I'll review now

#

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quasi wasp
#

I’m not sure where to go from here

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restive river
quasi wasp
#

So are we thinking something like this to solve as a quadratic?

#

@restive river

restive river
#

yeah

quasi wasp
#

Hmmm how would I turn that 7^x/2 into a quadratic to power 2?

restive river
#

let u=7^(x/2)

restive river
quasi wasp
#

That’s smart thinking that. The 7^x/2 would turn into u and -7^x would be -u^2

restive river
#

yup 👍

#

then its a quadratic in u

quasi wasp
restive river
#

hmm

restive river
quasi wasp
#

I thought when you stretch something by b it meant that f(x) = (bx)

restive river
#

apparently its x/b

#

the point at x=1 of the old function needs to become x=2 of the new

#

,w roots x^2-x-12

restive river
#

roots make more sense too

quasi wasp
#

That does make a lot of sense

#

So now we have -3 and 4

#

However

quasi wasp
#

So which value do I sub in

restive river
#

you still have to take logs

quasi wasp
restive river
#

7^x=u=4

#

solve for x

quasi wasp
#

That worked well thank you @restive river

#

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vital kindle
#

if we have a loop that iterates i and j in it like

  for (int j=0; j<10 j++)
    WORK

then this is 10^2 of the work like this
**********
**********
**********
**********
**********
**********
**********
**********
**********
**********

but if the pattern is
for(int i=10; i>0; i--)
  for (int j=0; j<i j++)
    WORK
**********
*********
********
*******
******
*****
****
***
**
*```
vital kindle
#

its not WORK^2 but what is it?

#

is it like (WORK^2)/2 ?

restive river
vital kindle
#

thanks

#

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@proper thicket Has your question been resolved?

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@proper thicket Has your question been resolved?

soft shore
#

cos theorem?

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left zodiac
devout snowBOT
left zodiac
#

Can someone help me with this linear equation

#

And explain it to me

#

not rlly

#

i can

#

i think

#

um 0?

#

um

#

dontknow🥺

#

i dont know where the 10 is coming from

#

oooohh

#

10

#

is this connected to polynomials

#

yes

#

kinda

#

i know more than before

#

wait a min

#

is it 2?

#

oh i think its 8

#

oh wait

#

I think I got it

#

if you cant understand handwriting its x^2-16=x^2-8^2-(x-8)(x+8)

#

<@&286206848099549185>

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#

@left zodiac Has your question been resolved?

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@left zodiac Has your question been resolved?

left zodiac
#

.close

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pulsar pawn
devout snowBOT
pulsar pawn
#

Is it the 2nd bullet?

#

The point is negative for the function but it’s increasing based on the first derivative

exotic stump
#

i think you're mixing up x and y here

pulsar pawn
#

Oh so it’s f > 0

exotic stump
#

yes

pulsar pawn
#

Alright and then f’ > 0

exotic stump
#

yes

pulsar pawn
#

Alright thank you

#

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green kelp
#

General form is ax+by+c=0

#

Bring the 12 to left side

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#

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finite stream
#

idk how to solve this

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finite stream
#

<@&286206848099549185>

novel arrow
supple knot
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novel arrow
#

<@&286206848099549185> ❤️

finite stream
#

.

novel arrow
#

I'm new here 🙂

#

!help

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supple knot
novel arrow
#

Ok

finite stream
#

im beyond struggling

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amber aurora
devout snowBOT
amber aurora
#

i don’t even know where to start🤷

#

<@&286206848099549185>

green kelp
#

As u know distance is speed x time

#

Just assume that he traveled x kilometres with bus

#

Then the distance he traveled with car would be 520-x

amber aurora
#

yeah

daring plover
#

Let t = time, let d = distance.

#

t_bus + t_car = 6h.

#

d_bus + d_car = 520km.

#

The two equations for the distances traveled by the bus and the car would be:

#

d_bus = 80(t_bus)

#

d_car = 100(t_car)

#

Then you just have to do some substitution.

amber aurora
#

how

green kelp
#

Ok I'm back

green kelp
#

You're given total time = 6 hours

#

So x/80 + (520-x)/100 = 6

#

Find x from this

amber aurora
#

idk how

#

#

4/80+(520-2)/100=6??

red sierra
#

The question asks for the time, so it's much convenient to set the unknowns as the time

amber aurora
#

i remember you jay

red sierra
#

Yeah I remember you too

amber aurora
#

so how do i do this the other guy keeps leaving after saying a couple things

red sierra
#

So the question asks for the time spent on each the bus and the car, right?

amber aurora
#

yeah

red sierra
#

If you say that the time on the bus is x and the time on the car is y

#

What would x+y be?

amber aurora
#

6

#

hours

red sierra
#

Good

#

So x+y=6
That's ur first equation

amber aurora
#

ok

red sierra
#

Now you need to set the second equation using the total distance

#

Since the bus' speed is 80km/h, how much distance did it travel after x hours?

amber aurora
#

idk

#

x is an unknown value

red sierra
#

You need to express the distance the bus traveled using x

amber aurora
#

80(x) + 100(y) = 520?

red sierra
#

Great

#

That's your second equation

#

Now all you need to do it solve x and y using the system of equations:
x+y=6
80x+100y=520

#

It's the same thing as we did last time

amber aurora
#

x=6-y

red sierra
#

Great

amber aurora
#

and then substitute

red sierra
#

Yup

#

Then you'll be able to find y

amber aurora
#

80(6-y) + 100(y) = 520 right?

red sierra
#

Yeah

#

Tell me when you find y

amber aurora
#

y =2

red sierra
#

Nice

#

Then you can find x

#

Did you get x?

amber aurora
#

4

red sierra
#

Great

amber aurora
#

because 6-2 is 4

#

advanced fr

red sierra
#

So you're answer would be
Time spent on bus: 4hours
Time spent on car: 2hours

amber aurora
#

ty

red sierra
#

Np

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#

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red sierra
#

.close

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thin gulch
#

how do i find common denominators of 1/2 + 3/4

devout snowBOT
#

Please don't occupy multiple help channels.

thin gulch
#

??

#

like factors of both of the 2 denominators?

#

no idk

#

ok

#

there are a lot of common denomaintors?

#

ok thx

#

i have another question

#

how do i represent these fractions like in that picture

#

a

#

1 a first

#

umm idk

#

it’s b?

#

nvm wait

#

i think it’s c?

#

idk.

#

i wrote 3/4 and 1/2 idk wym

#

yea same

#

it’s c right

#

help

#

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summer pewter
#

Is this mathematically solvable?

devout snowBOT
summer pewter
#

Actually these other 2 equations are also available if needed

#

Wait, x3+y3+z3=36 not 11 😅

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#

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dense quartz
#

How is 3A not congruent

devout snowBOT
dense quartz
#

Can someone explain how its not congruent for 3A

#

cause idk the reason for it

hushed wraith
#

the SAS case of congruence requires that the angle be between the equal sides

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#

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restive river
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indigo isle
#

I can send questions here right :>

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indigo isle
pseudo basin
#

anyway

#

!status

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#
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
indigo isle
#

1 and 3

pseudo basin
#

show the answer you got

indigo isle
#

but this doesnt cover if it was g g b g b b

#

hmm

#

<@&286206848099549185> :)

pseudo basin
#

@indigo isle sorry, was away

#

subtractive counting is gonna be hard here

indigo isle
#

Thats okay!

#

mhm im listening

pseudo basin
#

the only four ways you can have girls not sitting adjacent is GBGBGB, GBGBBG, GBBGBG, BGBGBG

#

so 4 * 3!^2 surely

indigo isle
#

yep thats correct, but how did you know to ^2

#

oh nvmm!! I see it now

#

You're a star! Thank you!

#

.close

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fleet gorge
#

All the angles are equal in octagon. Find Area

fleet gorge
#

wrote it.

#

.close

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shy mural
#

help please

devout snowBOT
shy mural
#

lets say f is x^2

#

and [a,b] is [1,5]

#

,w sketch x^2 from 1 to 5

woven radishBOT
shy mural
#

how does that achieve its global max and min

#

between those 2 points?

#

<@&286206848099549185> 🙏

long sundial
#

The function is only defined on the domain [a,b], so the global maximum is on that domain.

shy mural
#

oh

#

oke got it thanks

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midnight sluice
#

we throw a die n times, let X be the number of times 5 is received, let Y be the number of times 4 is received
express using n the covariance of X and Y

midnight sluice
#

lets see

#

[
cov(X,Y)=\sum_{x}\sum_{y}((x-\mathrm{E}(X))(y-\mathrm{E}(Y))P(X=x,Y=y)
]

woven radishBOT
#

metnal

midnight sluice
#

im not even sure where to start with this

violet wind
#

I think maybe break X and Y down into events representing individual dice rolls somehow

#

though I don't really understand the formula. I'm used to E(XY) - E(X)E(Y), is that one allowed?

#

no, I suppose I get it

midnight sluice
#

yeah its allowed

violet wind
#

In that case, calculate E(XY), E(X), and E(Y) for one trial

#

One dice roll

#

Then add up all the rolls using linearity of expectation

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thin ravine
devout snowBOT
thin ravine
#

How do I solve this

sick fulcrum
#

,tex \factoid original

woven radishBOT
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lethal osprey
#

how do i convert the first equation to the second on

tame ruin
#

Given a right angled triangle. Determine the length of the median belonging to the hypotenuse,
if the legs are 12 cm and 16 cm long.

pseudo basin
#

@tame ruin the other person got here first -- youll have to open a new one

#

oh you did alreadyt

tame ruin
#

ok

lethal osprey
#

yeah

#

so its -9(....)?

#

-1

#

1

#

yes

#

i think after multiplying is just -9((-2/3)^n-1)

#

2x+6

#

-2x-6

#

wdym 2 common

#

2(-x-3)

restive river
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How come?

lethal osprey
#

so when im multiplying -1 by 9((-2/3)^n-1) im multiplying -1* 9 and -1(-2/3) and -1*-1?

restive river
#

1 is positive

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in the second image

lethal osprey
#

im still a little confused

restive river
#

1

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positive

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But you said that the insides wasnt multiplied but was apparently left out

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Thus, i said that 1 is positive which means that it was multiplied

lethal osprey
#

if i multiply it inside the bracket it would be 1(2/3)^n)...

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since -1* -2/3^n and -1 *-1

restive river
#

-(-2/3) = 2/3

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Makes sense

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-2/3

lethal osprey
#

is it possible if you like write it out? i think thats easier for me to understand

#

ahhhhhhhhhhhhhh

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okay nowi get it

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wait why did u delete it

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ok

#

yep got it

#

thx btw the arabic name guy

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idk how to @ your name lol

#

.close

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short tendon
#

hi

devout snowBOT
short tendon
#

ive tried doing that by subbing A and -9/40 into the tan(a-b) formula but I think thats wrong

#

any help?

devout snowBOT
#

@short tendon Has your question been resolved?

short tendon
#

<@&286206848099549185>

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<@&268886789983436800> sry idk if im supposed to tag you

wicked rover
#

pls dont tag mods for math help

short tendon
#

oh ok

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sorry

polar chasm
short tendon
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yeah

polar chasm
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Do you know why this is true?

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Does it make sense?

short tendon
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ohhhhhhhhhhhhhhhhhhh

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yeah that kind of makes sense

#

do you just ignore 9/40

polar chasm
#

And do you know what tan(A/2+A/2) is?

polar chasm
polar chasm
short tendon
#

wait no

#

its that formula no?

polar chasm
short tendon
short tendon
#

i meant

polar chasm
#

Forget about everything else, and just focus on simplification of this

#

There is one very obvious thing you can do.

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you could also ignore the tan

short tendon
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tana?

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ahhhhh

polar chasm
#

And do you know what it is?

#

as a number ;)

short tendon
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tana?

#

no

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ohhhhhh

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9/40

polar chasm
#

correct

short tendon
#

yhhhhhhhhhh

polar chasm
short tendon
#

then simplify

#

so you get a to be 0.221314

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tysm

polar chasm
#

You shouldn't use arctan I think

short tendon
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why not

polar chasm
#

You should us formula for tan(A+B)

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Which is this thing

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It would be too ez if you could just arctan it

short tendon
#

when i put that into photomath i get 0.22

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might be so

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because its only part (ii) of a q

polar chasm
#

That's true but that's kind of cheating xD

short tendon
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its acc rly simple im just stupid

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and i need sleep

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haha

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tysm anyway

polar chasm
#

Okay then.

#

also make sure you turn the A into tan(A/2)

short tendon
#

yep

#

thanks

#

.close

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plain escarp
devout snowBOT
plain escarp
#

Please help

knotty bolt
upper schooner
#

!status

devout snowBOT
#
What step are you on?
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2. I have begun but got stuck midway
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keen niche
#

(algebra, groups and rings)

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keen niche
#

.close

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mild basin
devout snowBOT
mild basin
#

Am I on the right track here for finding the range or way off the mark?

#

I’m not sure what I need to do for the inverse equation.. isolate y on it’s own, yeah? So is making the inverse equation = 0 a bad idea?

pseudo basin
#

you may have made your life somewhat more complicated here, but i'm not sure to what extent.

#

probably up to and including the penultimate line there's nothing you could've done significantly better

mild basin
#

Yeah.. this is a long convoluted way to get to the range

pseudo basin
#

wait, you're asked to get the range? just that...?

pseudo basin
#

might you be better off finding the extrema by calculussy means

mild basin
#

I thought I would just replace x with the smallest domain value (which is 2) but that’s not correct

pseudo basin
#

that's part of it but not all

#

the most important part is finding the zeros of f'

mild basin
#

What I mean to say is, calculus is more effective than algebra for finding range?

pseudo basin
#

for such mildly-complicated functions, yeah, i'd say so.

mild basin
#

Finding the range can always be done both ways, however right? Via algebra or calculus

pseudo basin
#

with algebra you may struggle a lot

mild basin
#

Yes, which is where I am at

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I’m looking at =0 and thinking it may give some false positives

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I could divide and multiply the left hand side as much as I want, to remove terms, and it will still equal zero

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But that may also be risky and could be eliminating answers, I’m not sure…

mild basin
#

The right hand side will always be zero, so long as you are not dividing by a variable

#

I guess I have run into my “limit” with algebra. Time to learn calculus to help solve range

devout snowBOT
#

@mild basin Has your question been resolved?

radiant drift
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uncut quarry
#

Hello

devout snowBOT
uncut quarry
#

Any help on how to prove this?

vast latch
#

Can anyone help?

uncut quarry
#

Man find another channel

supple knot
devout snowBOT
supple knot
#

and delete your message

supple knot
uncut quarry
#

They belong to R*

low holly
woven radishBOT
#

tushar

uncut quarry
#

Ok and after that?

low holly
#

set a := a/b, b := b/c, c := c/a

uncut quarry
#

Ah ok i understood

#

Thanks man

#

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neon folio
#

Can a log have a negative result?

devout snowBOT
slow mist
#

yeah

#

it can

#

but it can't have a negative input

nova ibex
#

^

neon folio
#

Ok thanks

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slow mist
#

@uncut quarry chill man he closed

uncut quarry
#

I did nothing man

neon folio
#

You can add something if you want

devout snowBOT
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fiery thorn
#

I am currently working in my math investigation for school. My inicial idea was to model access ramps and use optimization to find the best relationship between values (like length, cost, gradient etc) but after some drawing and starting my calculations I realized that all the ideas I had have a linear relationship. I am stuck on how to approach this investigation. I am open to suggestions or just your thoughts wether this topic is worth pursuing. thanks

jaunty mantle
#

Looks like you want a multi input function?

fiery thorn
#

im not sure what that is

wooden veldt
#

this is a pretty hard question to answer as we don't know what your school want from you in an "investigation"

fiery thorn
#

its from the IB diploma programme it is for the Internal Assesment

jaunty mantle
supple knot
fiery thorn
#

I am struggling with ideas to then actually create a rough draft

jaunty mantle
#

Actually I want to ask

supple knot
jaunty mantle
#

How is your gradient thing a linear relationship

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I’m pretty sure most escalators are only 30 deg

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Going any higher pretty much makes it impossible to climb at all

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And escalators have steps

fiery thorn
#

what i found was that access ramps have a gradient between 1/12 and 1/16

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and I couldn't equate it to another variable without the linear relationship

jaunty mantle
#

Also, isn’t length directly linked to the gradient

fiery thorn
#

yeah

jaunty mantle
#

I think the main problem here is a not very well defined “best relationship between values”

#

Best based on what?

fiery thorn
#

My idea was to use 3 factors as the judge of that which would be the length someone would have to walk to reach a specified height (I was thinking of climbing 3 meters in height) the cost of building it assuming it was just concrete and the gradient of the ramp