#help-27
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well done
no worries!
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Am i allowed to take the limit like this ?
yes
so its okay to just take the lim in the root and not get rid of the root before?
well
if $\lim_{x \rightarrow a} f(x)$ exists and there is a function $g$ such that, $g$ is continuous in $\lim_{x \rightarrow a} f(x)$
then: $g(\lim_{x \rightarrow a} f(x)) = \lim_{x \rightarrow a} g(f(x))$
alr
in a basic level if the argument of the limit is a continuous function you can take the limit of the argument of the said function
check #old-network, here is definitely not the place
Thats easier to understand
Thank you alot 🙂
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Guys, I need some help.
I've started a project with a friend of mine. The project is to translate the walking movement of legs into the game movement. We have a flex sensor on each leg tied to a knee brace. We measure the angle output by the sensor to determine if the leg is bending to a certain point. We use a microcontroller. When a leg passes a certain point/angle we record it as a valid movement. Between 2 valid records(alternate steps/legs) we obtain the time difference and convert this to a value to move the joystick. Microcontroller + Digital potentiometer connects with the joystick(Using a PS controller and we wanted to be able to use this on PS too, currently connected testing on PC).
Now our main concern is to detect when we stopped walking. Let's say I walk slowly and I suddenly stop, we need to move the joystick to the center instantly. We thought this kind of problem is mostly mathematically inclined and we have been stuck with this problem for months.
Please let know if this is the wrong channel
This graph is from the flex sensor on each leg. Each sensor output angle value
indicating on that graph the points where walking has stopped would be useful
if there even is any stopping on that graph
Spikes are when stop bending leg and straighten it back
I will put some clear data grsph
why do they only happen for one leg
in general it's weird that the blue graph is lower than the red
shouldn't they both be roughly the same just shifted left/right?
@keen sluice Has your question been resolved?
The issue is that with the placing of the flex sensor. Not much of identically looking data output
The narrow bends you see here when the leg is bend. So when the leg is straightened value is around -30 and -40 (Just negate minus, sensors has been placed flipped hence getting minus). Even though we tried placing the sensors identically same, the output values are bit different when compared to each other.
So once again, our main concern is making some sort of algorithm to get when the leg is totally stopped. By looking at the graph we can do that 🙂
Let's consider walking slowly, so the time between 2 steps would be around 1sec (for ex) and when we run that time will be smaller.
What we have tried so far,
*Monitor the time between 2 steps and see if the next step is going to be within the previous time-period and move the joystick to center. Problem is if we run and then switch to walk it will still center the joystick since the time taken is rather higher.
Also when walking let's say the time between 2 steps is 1 sec and if stopped walking, it will still wait for 1 sec before moving joystick to center (this is the main thing we are concerned about).
Please guide us. Any help means a lot. Thanks!
@keen sluice Has your question been resolved?
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Discrete Math Show the following semantic implications using derivations and rules of inference.
(p ^ q) ^ (q -> r) entails r
I did
- p^q premise
- q->r premise
- p 1, simplification
- r 3,2 modus ponens
ill be honest I absolutely have no idea what I'm doing here
this is wrong and im unsure why
your question would be more reable in latex. Symbols are \lor \land \implies
,, ((p\land q) \land (q \implies r)) \implies r
ahhh thanks
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In the figure, m(2^)=m(3^) and m(1^)=m(4^) are given
Prove that triangle ABC = triangle ADC
!status
What step are you on?
- I don't know where to begin
- I have begun but got stuck midway
- I got an answer but I'm told it's wrong
- I got an answer and would like my work checked
- I have a question about someone else's worked solution
- None of the above
! status
What step are you on?
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- I have begun but got stuck midway
- I got an answer but I'm told it's wrong
- I got an answer and would like my work checked
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- None of the above
Oh well lol
1
Ye
Two triangles are congruent, if they have a side and the 2 opposite angles of this side are respectively congruent
Oh
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Hello, how do i "mathematically" write a portion of a cartesian plane (for example a square)
you mean the set of points contained within a square?
or the area under a curve but without using integrals
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The question is to find the equation of the tangent line in standard form using the point at P(-2,3)
Using the methods that I thought were correct I did this, however the correct equation is 10x + y +17 = 0
I don’t really see what I did wrong… just adding that in the lesson we didn’t use the equation of the curve at all
The only thing I can see that I did wrong is not properly finding y2
I which might be the case
Thank you for all help in advance
I'm assuming f(x) = 3x^2 + 2x -5
What is f'(-2) then
Also your limit is wrong
,tex \dxlimitdef
$e^{\text{Umbraleviathan}}$
ah wait nvm, figured it out dumb mistake by me you were right, i misunderstood the way we wrote the questions
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How is $A=P^{-1}BP$ equivalent to $AP=PB$?
(they are all matrices, and in particular A and B are square)
mesmeriSe
I thought if we multiply by P on the left on both sides then we would get
PA=BP?
this is equivalent to AP=PB?
who is claiming that is the case?
my lecture notes
can you show them
okayyy phew right thank you im bad at linear alg and i lost all my confidence after seeing this 😭
seems like you know how matrix multiplication works so dont worry haha
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how would i figure out d
thinking it has something to do with room temp being 20
not sure
how to start
do you generally know how to find the rate of change on a function that describes like amount(time) ?
no
so this question was given to you pre-calculus?
well, what would the first derivative of this function describe?
but you know what the first derivative is yes
like, the first derivative of an distance(time) function would be the velocity(time) function
no, I mean like practically
wdym
clearly there must be some real life appliance of derivatives, idk but this is how most are approached to it
anyway, you should catch up to that some time, I won't explain that now
just know that the first derivative of your temperature(time) function is the change of temperature(time) function
so, to find the initial rate of cooling take the first derivative and plug in 0 for t
ah wait, is your T`(t)=-40e^-3/2t ?
are you sure?
we talking T or t
the function is T(t), or Temperature(time)
yes
so set temp to 0
Jigglyproff
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look at the table and find the correct rule to apply
How
$f(x)=e^x$
$f`(x)=e^x$
Jigglyproff
So it stays at 80e^0.5t?
not quite, you have to apply something here because you have \
$e^{n\cdot x}$ and not just $e^x$
Jigglyproff
Oh ok so 80e^3/2t
do you remember the chain rule and the product rule
Chain rule?
So 80e^-3/2t?
no...
can you tell me your choices of f and g
so that you can differentiate e^{-t/2}
Idk
or that works too
Idk what that is
but I recommend revising your calculus skills before continuing further down the examples
use this for now, since the chain rule for e^nx functions is a bit nicer
Ok
+1, for such physics graphs-related that must become more second-nature to you
So what is the derivative?
do you understand thishttps://cdn.discordapp.com/attachments/903486480075354182/1066840837994066061/image.png
Not really
bruh just tell us
Didn’t want to seem really dumb
it is dumb to not ask for help when you need help, thats what ppl say from kindergarten on
no shame in wanting to learn
Alr sorry
anyway
chain rule is used to find the derivative of composed functions, aka functions like $f(x)=h(g(x))$\
in your case, you have $h(a)$ as $e^a$ and g(x) as $-0.5x$, a being g(x) evaluated\
to get the derivative of this, you do $h`(g(x))\cdot g`(x)$
What’s H and G in this tho?
Jigglyproff
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new functions I made up to show that you have some kind of matryoshka
like
you have a function, then you wrap that function in another function, so you need chain rule to get the derivative of this
What’s the other function in this then?
anyway, I told you g(x) and h(x) though
So what will 80e^-1/2t turn into
Maybe it would help for me to work back from the derivative
jus do this right
the last line, with replacement, basically says\
$\frac{d}{dx}(e^{-0.5x})\cdot \frac{d}{dx}(-0.5x)$
Jigglyproff
So I get -0.5x ?
where
.
what happened to the e
the left factor is a bit off
yeah, I have no real way to show it better
So e^-0.5t
20 disspears
sure
you arent done yet
Oh
$e^{-0.5t}$ is just the left term
Jigglyproff
80e^-40t ?
no...
how about going step by step
starting from the original function T(t) = 20 + 80e^{-t/2}
I think you know the derivative of a sum is just sum of the terms differentiated
so as you said, yes 20 "disappears"
well, I will write the full thingy rn, but keep explaining
so all is left to finding the derivative of 80e^{-t/2}
do you remember the product rule
since we have the product of the terms 80 and e^{-t/2} we need that
Ok
a reminder: $\left(f(x)g(x)\right)' = f'(x)g(x) + f(x)g'(x)$
biggboy
I think you can figure what f(x) and g(x) are
I think there might a be a gap of knowledge Cus I recon you both American
in this example*
not really american
im european, this was 11th grade for me
hmm
then I recommed using the internet to learn
there are a lot of channels on youtube that will teach you this
idk why they give homework on a subject you guys haven't gone over but, yeah
Ok but what’s the derivative Cus I can work bsck from that which would help me
$T(t)=20+80e^{-0.5t}$\
$T`(t)=\frac{d}{dx}(80)+\frac{d}{dx}(80e^{-0.5t})$\
$T`(t)=\frac{d}{dx}(80)+80\cdot \frac{d}{dx}(e^{-0.5t})$\
$T`(t)=0+80\cdot e^{g(x)} \cdot \frac{d}{dx}(g(x))$, where $g(t)=-0.5t$\
$T`(t)=80\cdot e^{-0.5t} \cdot (-0.5)$
Jigglyproff
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I mean if you can reverse engineer from that you can surely understand our explanations...
but here
this is the work
if you are supposed to be able to do this, I can only recommend watching some yt vids on derivatives
the $\frac{d}{dx}$ of a function
Jigglyproff
Or tell me a derivative of a different example
the derivative of a function describes the slope
Ok
Ok
you can see that the derivative is below 0 before the slope of f(x) hits the minimum, thats because before that f(x) is 'going down'
then f`(x) goes above 0, because f(x) starts rising
Courses on Khan Academy are always 100% free. Start practicing—and saving your progress—now: https://www.khanacademy.org/math/ap-calculus-ab/ab-differentiation-1-new/ab-2-1/v/derivative-as-a-concept
Why we study differential calculus. Created by Sal Khan.
Watch the next lesson: https://www.khanacademy.org/math/ap-calculus-ab/ab-derivative-int...
khan is good
It is -40e^-0.5t ?
yes
Nice
well, just had to put the factors together
now you can put t=0 and t=2
no
if you put 0 for t inside that new T`(t) function, you get the slope when time is 0
Why does t = 2 aswell
alas, T`(0)=initial cooling
By anyrhing to power of 0 = 1
sure
its $40\cdot e^0$, not $(40e)^0$
*ans
Jigglyproff
yes
the initial cooling, yes
Cool
also, you need units
that is also what you have to figure out some time, but now I tell you
since we took the derivative of time, the function now gives units in change of time, so divided by the units of time one t is large
and since 1t = 1 minute, your function T`(t) now has degree celcius per minute as unit
so its $-40\frac{°c}{min}$
Jigglyproff
thanks u too
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marc
Just split it into cases: Casper gets 1 pencil, Casper gets 2 pencils, Casper gets 3 pencils,…, Casper gets 5 pencils.
oh I’m dumb lol why didn’t I think of that
They are subtracting the number of ways Casper gets at least 6 pencils
Search up stars and bars
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Could someone help me walk through the steps for the last prompt - being able to find the angle between the two functions
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@high oxide Has your question been resolved?
@high oxide Has your question been resolved?
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Garuda
Do you know mean value theorem for derivatives yet
your two f(c) are different. Which one is it
first one
Garuda
Oh maybe it's just intermediate value theorem. Did you try that
Yes it is it but i don't understand how to use it @supple knot
@bitter swan Has your question been resolved?
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@bitter swan Has your question been resolved?
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Hello
Your application of Pythagorean theorem is wrong
Wym
x^2+5^2=12^2 right?
wym by application
What is your hypotenuse?
my hypotenuse is x
application = "how you use it"
ohh
How do you figure that?
Why do you believe that x is the hypotenuse?
the hypotenuse is directly across from the 90degree angle no?

Also there is no label for the right angle
ok, good luck 🙂
i think i got the answer so when you get the answer i can make sure its right : D
Depends on if that's what your teacher wants
i would write it just in square root form
but yeah i agree
i dont think so, do you wanna see my work for it?
Yeah that would help alot
First, do you know Pythagorean theorem
i know pythagorean theorem
Not the purpose of the server to give out answers
No im just looking at the work
And that is?
i was only gonna show my work and explain it throughout
The form is
Still don't do that
k
A^2 + b^2 = c^2
Do you agree that a and b are the legs of the right triangle and c is the hypotenuse?
Yes
So what is a and b?
b is indeed b. Can't argue that
And then c is?
12
Yes
Not quite
No
??
my fault
Those are important
That is terribly formatted
Almost there
A + 10 + 144
And also, you said x is a, so why do you have a in there still?
dldh06
And also it's A^2 + 5^2 = 12^2
Where is the ^2 for a?
And this
10.9
Yes
Apply that same thinking process to the rest
Label your a, b, and c
Plug in the values, solve
yo, just wanted to thank you, i see now that ive been teaching wrong.
thx for "enlightening" me. 
dawg could of just sent him dm
Or use #discussion/ #serious-discussion
What?

I wasn't asking that
Im an idiot bruh
i didnt even do the steps
i need to start paying more attention because mans be pointing out everything
Ok
I got some surface areas next
Now wit surface areas
Im 100% Good with these
so no need to relearn anything
I think i got this
lol
Here is my advice for you, follow a structure of something like this: equation, given, find, solution. If you know what topic you are doing, then you should know the equation/formula you are going to apply. Then label all the given info based on the formula you're using, write what you are finding, then find the solution
So above, it was Pythagorean Theorem so you know the equation that is going to get applied is a^2 + b^2 = c^2
👍
Label what you are given based on the triangle you have. Declare what you are finding, then do the work to find the solution
I really appreciate you alot
Always helpful
Ima fill this out
give me couple mins
Hello
I found a calculator
im good
.reopen
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hi
Damn
can i get help
it says to treat x as a constant
so does that means that the limit is the function
?
do i have bad intuition or is that a mistake
i feel like it should be ' trate a 'h' como una constante'
@silent lynx Has your question been resolved?
Yes
I think
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anyone know how to find a mean median and mode on a histogram? im so lost
so i would have to do it for both axis for the graph?
OHH I SEE
thank you so much
quick question
if i do the mean, would i calculate all the x's then divide it by the number of x's there is?
wait a damn minute
im so lost now
😭
i would divide it by 10 right?
where are you getting 11 from im lost
oh i thought it was by this
i aplogize
😭
okay
so im finding the total of this?
that would be 27
let me do the other one
394?
and the mean would be 14.5?
oh girl i ate that
thank u so much
^^
what would be a good central tendency for money earned in baby sitting? im debating on mean
also how would i do it with a fraction? i have no clue how to do it
@foggy fulcrum Has your question been resolved?
im not getting it
cus its fractions and whole numbers
i would say it would most likely fit a mode tendency right
@foggy fulcrum Has your question been resolved?
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Hello, can someone help me. I have to find the general number of a progression where i know x0 , x1 and a vague formula
one option would be to compute the first few terms and then try to guess a formula and prove it by induction
but probably not the best idea here
the other idea is to first assume that x_n could be lambda^n for some lambda
that gives you an equation lambda^2=7lambda-10
this you can solve for lambda
which will get you two solutions lambda1 and lambda2
you can show that the space of all sequences which satisfy the recurrence relation is a subspace of dimension 2
so it is spanned by the two sequences (lambda1^n)_n and (lambda2^n)_n
that means any other sequence has to be of the form x_n = a*lambda1^n + b*lambda2^n
with the two initial values you are given you can solve for a and b
yes
and what do i have to do know cause i couldnt understand
so i can plug x_0 instead of a and x_1 instead of b
well this is a linear system of equations with 2 variables and 2 equations
7 = a+b
20 = 5a+2b
I would hope that you know how to solve these
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youre welcome
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if i have tan3x=4 and im tryna solve and the range is from -90 to 90 how do i get the negative solution?
there is no negative solution
if tan3x = 4, there is only one x between -90 and 90 such that tan3x = 4
and it is positive
lol what
,w plot y=tan3x
ohh wait
yeah wait ur right
got the positive solutions
but can't remember how to get the other one
been awhile
?
huh what
i got -0.605 and 0.442 and 1.489
ye
like pi/2
ohh
so i shud have said there is only one value for 3x between -90 and 90
not x
yh
i think you just need to convert -0.605 and 0.442 and 1.489 into degrees
thats way longer lollll
hi guys!
so tan3x = 4 = tanalpha, say
then 3x = n*pi + alpha (n is an integer)
x = (n/3)*pi + (alpha/3)
find n such that this x is between -pi/2 and pi/2
so we'll have to check arctan(4) in the range of -270° to 270°
i remember the rule i think
find first solution
then minus 180
tan is the different one
ah good point lol
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im doing a very similar problem any ideas?
im guessing there is a formula for R but idk
@ivory bluff Has your question been resolved?
<@&286206848099549185>
yeah
@ivory bluff Has your question been resolved?
@ivory bluff Has your question been resolved?
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so my question is i dont get how we got 9 for y
so if can explain please
<@&286206848099549185>
im sorry i need to be fast
We do not support cheating in exams
no im not cheating this is a quiz
istg it isnt
so can you help please
what proof i can give that you guys can beleive that im not cheating
just looks like an open book assignment tbh
yeah but i just dont understand anything
bro you how did you guys know i was cheating
im not
but like what made you think that
can you guys please help me
Are those your answers?
hd pls
yes but the last one is unaswered
im not sure i know it
Everything is filled in
They all look answered to me
wait no mb it is the correct answers
see
?
Submit and see
https://tryitands.ee/ moment
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Hi. This is a very open ended question: Tell me something interesting about the number 2023 or explain why you think it is a completely uninteresting number. There's no right or wrong answer but i just wanna see how creative the answer could get
what thoughts do you have about it
If we add the cubes of the integers from 2 to 9 and subtract the 1 , we get 2023!
but i was looking for something more interesting
Wrong, you get 2023
2023! is much bigger xD
xD

yep
,W sum of x^3 from 2 to 9
:0
and then subtract 1
it's a Niven number
i want a unique answer.
Suppose 2023 is completely uninteresting number. If it is, you can create an interesting fact, that 2023 is completely unintersting number! Therefore number 2023 must be interesting
I mean for a unique answer that no one's thought of, just make shit up that results in 2023
It is a multiple of 7 with sum of digits equal to 7.
I just found an interesting fact. It's current year :0 I bet nobody noticed that
omg how did i miss that
yeh, niven
yeah
niven?
When you add 1 to itself 2023 times, you get 2023 :0
the name for numbers with that property
bruh
Wow it's a square number, it can be written as (sqrt(7)*17)^2
Sorry, imma find some interesting fact. I will try to find natural number n, such that n*2023 will be prime number
@magic tapir Has your question been resolved?
phoestaclies
@magic tapir Has your question been resolved?
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How did you get your red 2x?
I multiplied 3 sqrt 2x by 3 sqrt 2x
And why do you think that is equal to 2x?
cause i was watching a video on rationalizing denominators
oh yeah youre right
would i still multiply it by 3 sqrt 2x
or what would i do here
like this?
i dont get why you would add the 2 though
Yeah, brackets would make it less ambiguous
Well do the calculation and see what happens
Ok let me try one sec
whats the point in doing that though
Do it, and you'll see
$\frac{\sqrt[3]{3}}{\sqrt[3]{2x}}\cdot \frac{\left(\sqrt[3]{2x}\right)^2}{frac{\left(\sqrt[3]{2x}\right)^2}$
ΣAC
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
so the point of doing it was to get rid of the cube root on the bottom?
Yep exactly, just one wasn't enough
would this method apply to all cube roots?
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i ended up getting like 653 somehow. i know that linear speed is v=rw
so i did 13*16pi
nvm, i got it lol
.close
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can someone please help me find the variance and standard deviation for this set of data
im supposed to use a graphing calculator but idk how to use it
i get different answers compared to a online calculator
pls ping when u reply
To find the variance and standard deviation for the set of numbers (57, 68, 79, 82, 99, 115):
First, find the mean (average) of the data: (57 + 68 + 79 + 82 + 99 + 115) / 6 = 85.
Next, find the variance by subtracting the mean from each of the given numbers, then square the result of each subtraction:
(57 - 85)² = (-28)² = 784
(68 - 85)² = (-17)² = 289
(79 - 85)² = (-6)² = 36
(82 - 85)² = (-3)² = 9
(99 - 85)² = (14)² = 196
(115 - 85)² = (30)² = 900
Then, add up the results from each of the above calculations to get the variance: 784 + 289 + 36 + 9 + 196 + 900 = 2,214.
Finally, take the square root of the variance to get the standard deviation: √2214 = 47.14.
Therefore, the variance of the given set of numbers is 2,214, and the standard deviation is 47.14.
@trim thunder
Didn't I tell you before not to give out answers?
i get 83.3 for the mean
Show your work, and if possible, explain where you are stuck.
This is what the calculator says
i just added those same values and divided by six and got 83.3333333
Make sure you typed in the correct values
No the person who did the work above, did it wrong
OH
im supposed to put the mean-the data value in the second colum then find the variation on the calculator
i got the right answer when i did that
didnt know i had to inputt those values
.close
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i've got the rest down except the negation, i dont know how to opposite the if and then
Please don't occupy multiple help channels.
Convert this statement into a logically equivalent form. Then apply negation. You might need to use DeMorgan's Law here.
"If P then Q" is defined as "(not P) or Q"
hm so
if a quad is a square, then it is not a rectangle
would that be it>
oooh wait conversion lemme convert it that could help
p <> q is true
to negate that it'd be -(p<>q)
hm
-p uh
wuz the negation of <> (if,then)?
What is <>
hm so if p>q is true, then to negate that would be -(p>q) = -p < -q? right
but there is no < sign
I added parentheses here to clarify
ok so p is isolated
WAIT
THE OR
wait no
dang it
idk the opposite of if then
i am so lost
$p \rightarrow q := (\neg p) \vee q$
so the opposite of if then is or?
SWR
in that case, it would be "A quadrilateral is not a square, or it is not a rectangle."
is that it?
dang it
Looks good
which translates to "A quadrilateral is a square, and it is not a rectangle."
das gotta be it
My advice : try to slow down. It feels like you're thinking faster than you're doing
i am told that a lot, i will try to apply ur advice
It's all good. I was like that in my younger days
so the answer is ""A quadrilateral is a square, and it is not a rectangle."
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A bire tire has a radius of 9in what is the circumference of the circle. Could you lead me through the problem?
What is the formula for the circumference of a circle?
that is not
$$C=\pi d$$
Bestower
Nonono
C= 2(3.14) r
R is 9
BTW the problem is in the terms of pi
Bestower#6073
Hello
<@&286206848099549185>
do you know how to substitute 9 into this equation?
,calc 18 * 3.14
Result:
56.52
are you supposed to use 3.14 for pi?
.
oh oops
How you get that
you have it here, but you used 3.14 instead of pi
Pi =3m14 simpliefied
write it as $2 \pi r$. then multiplication can be done in any order, so it's equal to $2 r \pi$
riemann
you're not supposed to substitute 3.14 for pi because of this
9is radius
Why is no sub
There
Sorry
Why is there no sub for pi
Why do you leave pi by itself
Sp is that what Terms of pi mean
Leave pi on its own
?
yes



