help-27

[restive river]

Hmm

I guess u can cancel our 1?

out*

[winter patrol]

sure

[restive river]

And -10 -10

[winter patrol]

wdym -10-10

[restive river]

Or how about just group them

like (1)

(1)(1)

and then (-10)(-10)?

like that?

[winter patrol]

no

[restive river]

group them

[winter patrol]

no

[restive river]

ok

[winter patrol]

wheres -10-10 coming from

[restive river]

here

[winter patrol]

doesn't tell me where -10-10 is coming from

[restive river]

oh

[winter patrol]

the right side of that equation is just the result of simplifying the 3^2 on the left side to 9

[restive river]

oh I see

[winter patrol]

the current goal is to simplify
$$9 - 4(1)(-10)$$

[woven radish]

ℝamonov

[winter patrol]

and in case it wasn't clear, a product is implied between expression/terms grouped by parentheses, and seeing as the 1 isn't needed,
$$9 - 4 \times (-10)$$
can you simplify that

[woven radish]

ℝamonov

[restive river]

5x(-10)?

ig

[winter patrol]

no

recall the order of operations

[restive river]

Oh

parenthesis first

Then multiplicatioh

then subtraction

I wonder how I passed 7th grade math

I never understood it

nor do I understand 8th grade math

[winter patrol]

you really need a major review

[restive river]

yep

my exam is on wednesday

and I have no ideaaa

but the group works are more important

so thats why im hussling to learn

[restive river]

its more grade

so

What to do

[winter patrol]

at this point,
i think you're better off learning algebra from scratch

you have way too many knowledge gaps to be doing quadratics

[restive river]

then again I have a group task tomorrow

[winter patrol]

my point still stands

[restive river]

I mean I kinda understand algebra better when my friend explained it

can u just try to teach me so I can atleast do something in the groupwork

[winter patrol]

you're heavily struggling to perform basic order of operations and struggling to apply concepts like substitution

[restive river]

I have mo idea what im doing

[winter patrol]

which is making it 100x longer than it should to go through this

[restive river]

Well I also thought lie

like

if I wanted to learn this topic of algebra

I probably needed to learn the basics

though I don't rlly have time

so

[winter patrol]

you need the basics

don't try to run before you can walk

[restive river]

And I have a groupwork tomorrow

[winter patrol]

especially not if you can't crawl yet

[restive river]

Yeah but its kinda too late to learn the basics right now cuz im already in 8th grade

[winter patrol]

never too later

[restive river]

algebra was introduced to us in 6th grade

[winter patrol]

its ESSENTIAL that you know the basics

[restive river]

I have a group task tomorrow

can you just walk me through with the basics while teaching me how the other thing works

[winter patrol]

trust me, you're better of learning the basics

[restive river]

So that I can atleast help in the groupwork

[winter patrol]

like go through the basic algebra course on khan

[restive river]

I will like tomorrow after the day because i have a test on wednesday

[winter patrol]

i've already spent more time than I planned on this and don't intend to proceed further

[restive river]

Okay

[winter patrol]

trust me, you're better of learning the basics
because it's pretty much near impossible to do anything of this stuff with quadratics without that

[restive river]

I mean do you think someone can still walk me through it and walk me through the basics while teaching me?

[winter patrol]

like even if you know some theory of quadratics, its meaningless if it takes you over an hour to apply it

depends how patient they are and how quick you can grasp it

it'll be much more efficient to learn the basics first

[restive river]

but what about tomorrows group work?

[winter patrol]

still

[restive river]

its graded for each members participation

[winter patrol]

basics first

without it, you won't be able to do anything

[restive river]

I mean I slightly understood something

[winter patrol]

spend less time trying to procrastinate / weasel your way of learning them

[restive river]

Alright I have an idea

do you think I can add you on discord?

[winter patrol]

no

don't add me

[restive river]

okay

[winter patrol]

i suppose if you really can't do those simple calculations you could always resort to using a calculator

assuming you can do the substitution step

[restive river]

they wont let us use calculators

[winter patrol]

as i outlined

[restive river]

nope

But I plan on doing this task solo and working on it on our task week

and learning everything during the task week which will get me the grade

I mean u tried to teach me I just didnt have enough knowledge to understand it

[winter patrol]

assuming you can do the substitution step
nope
I mean I slightly understood something
so what exactly did you understand

[restive river]

yes

Honestly nothing cuz it was mostly guided until I got the right answer

thats all

[winter patrol]

you should at least look up substitution which is pretty much replacing something with something of equivalent value

[restive river]

okay

anyways um

Im gonna go rest

ill see you around I guess

.close

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[devout snow]

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[flint eagle]

3 c please

[flint eagle]

I think you would split it up

So you do g(10) first

And then u do g inverse 7 and then subtract tjose 2 answers

But I’m not getting it right

[small raptor]

well what is g(10)

its 28

yes?

[flint eagle]

Yes

30-2

So yeah

[small raptor]

ok good

now the inverse of that function would be

[flint eagle]

Of g(10)?

[small raptor]

no

just find a formula for the inverse

[flint eagle]

Oh ok

[small raptor]

so we can work out g^-1 (7)

do u have the formula

[flint eagle]

Would u use 3t-2?

Is that what u use

[small raptor]

g(t) = 3t-2

but u need g^-1

[flint eagle]

Okok

One sec

[small raptor]

so re-arrange g=3t - 2 for t to get g^-1

[flint eagle]

X+2/3

[small raptor]

g^(-1)= (t+2)/3

Yes but (x+2) has to be in brackets as its all over 3

[flint eagle]

Now 28-3

Is 25

Yes

[small raptor]

Yes

so answer is 25

[flint eagle]

Ok thank you

I get it now

[small raptor]

all g

[flint eagle]

First you find inverse and then u plug in the 7

To make it easier

[small raptor]

Yea

thats how u do inverse function

do inverse than plug in the numbers

[flint eagle]

Ok thank you so much gang

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[zinc ravine]

How can i do the fourier transoformation on this?

[zinc ravine]

This is the answer i am looking for however i cant do it :/

[devout snow]

@zinc ravine Has your question been resolved?

[zinc ravine]

<@&286206848099549185>

[devout snow]

@zinc ravine Has your question been resolved?

[zinc ravine]

<@&286206848099549185> can someone help me?

[devout snow]

@zinc ravine Has your question been resolved?

[devout snow]

@zinc ravine Has your question been resolved?

[supple knot]

show your attempt

[supple knot]

define U(t)

[zinc ravine]

i dont have U(t), it is something general

[supple knot]

You absolutely do because the answer assumes U(t) is something specific. You just need to look for the definition.

[rotund gust]

kobk

[rotund gust]

hi

[devout snow]

@zinc ravine Has your question been resolved?

[wicked turtle]

presumably $$U(t) = \begin{cases}1 & \text{if }t \geq 0 \ 0 & \text{otherwise} \end{cases}$$ but @zinc ravine needs to confirm this

[woven radish]

Bungo

[wicked turtle]

if that is the case, then a hint would be to observe that f(t) can be expressed as the pointwise difference between a rectangle and a triangle, both of base width 2 and centered at t=0

[devout snow]

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[tiny rain]

hallo, can someone tell me if theres some mistake here? the answer for x is supposedly 0.295a but my answer is so far off

[devout snow]

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[tiny rain]

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[lean matrix]

me back

[lean matrix]

i cant understand well what questions saying

we need to find distance from (1,-2,3) to what?

please do ping me

[restive river]

Do you know the gradient @lean matrix

As in the operator

[lean matrix]

u mean $\nabla$?

[lean matrix]

[restive river]

Yes

[lean matrix]

nope

[restive river]

I think I can solve it using that with a parameterization of the line, but i don't remember the formulas u guys have for alternatives

[lean matrix]

[restive river]

I do not know how to do this in 3d system but i have studied straight line in 2d system and it kinda looks like the foot of perpendicular thing

[lean matrix]

idts its foot of perp

[restive river]

I mean the result for the same looks like it

[lean matrix]

wait i think i understand the question

[restive river]

X1-x2/a =y1-y2/b

[lean matrix]

wait

lemme

is it like this?

so we need to find where that green line intersects the plane

and then the distance between that point n red

oh okay i see

answer comes out to be 1

thanks u guys

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[restive river]

umm

[restive river]

can anyone explain me

factorization of quadratic equation by using the method of completing the perfect squsre

like it is totally going above my head

[devout snow]

@restive river Has your question been resolved?

[winter patrol]

have you done completing the square before?

[devout snow]

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[restive river]

I have to use taylor to the 4th order in xo=0 am i doing it right?

[restive river]

.close

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[restive river]

How does this turn into this

[proud mural]

25 * 5 = 125

[hollow pollen]

$\sqrt{125} = \sqrt{25 \cdot 5} = 5\sqrt{5}$

[proud mural]

$\sqrt{ab} = \sqrt{a}\sqrt{b}$

[woven radish]

Gijs

dog.

[restive river]

dog?

[proud mural]

what

[restive river]

Oh that's ur nickname

Thank you for your help dog.

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[high chasm]

im trying to prove arsinh

what am i doing wrong

acc nvr mind

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[real grail]

lol @high chasm

[devout snow]

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[stone stump]

,rotate

[stone stump]

they probably want a sentence as an answer

"42 of the customers eat eggs"

[devout snow]

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[empty flame]

Hello everyone

I have a quick question

Parts a and b

In part a I got the following relations

AC=8/cosa

BC=8tana

BH=8sina

But I am stuck at part b

I tried using similar triangle ratios but that didn't lead me to a result

How should i solve it

[supple knot]

this channel's occupied.

!help

[devout snow]

Please read #❓how-to-get-help

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[empty flame]

??

[empty flame]

.close

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[toxic kraken]

am i wrong?

[graceful cosmos]

It's a little vague, haha

I would like to see the more important points. Such as (0,1) and (1,3)

The asymptote and end behavior are good though

[hybrid snow]

It's a horrible graph is what I'll say

You can't tell if you have the right intercepts

[lusty sapphire]

@toxic kraken this is the key thing to make it better

[devout snow]

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[restive river]

Hey

[restive river]

Can someone help me with this

[knotty bolt]

what have you discovered so far

[restive river]

nothing

[knotty bolt]

bruh

what do the asymptotes mean

@restive river

[restive river]

idek

lol

[knotty bolt]

well, probably that the function is not defined there right

how would you get that effect

[devout snow]

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[devout snow]

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[exotic gale]

im not sure what the difference between the smaller and larger value is

[turbid shuttle]

there are two places on the graph where this statement is true. the first is when x -> 2 (which you found). for the next one, x -> greater than two (which is what it means by larger value). can you find it on the graph?

[exotic gale]

ohh i see

ill look again

ok i got it! ty!

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[sage kernel]

Did my teacher make a mistake?

[topaz beacon]

Yeah should be pi/12

Also r is 50

Who is this teacher 😂

[devout snow]

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[mild basin]

Not for marks but just curious, which one did I get incorrect?

Oh I put H for 1 and 4, my bad

I think 1 is E

and 4 is G?

or H?

[main gull]

And the 3rd and 4th are wrong

This chart is useful

[mild basin]

3 is F?

[main gull]

That's what the chart says, right?

[mild basin]

ty

still not correct

[main gull]

Look at 1

[mild basin]

Oh

1 should be G

[main gull]

Do you see what's wrong now?

Not quite

[mild basin]

*1 should be H

that's what I had originally

3 and 4 are correct?

[main gull]

Did you use that chart properly?

[mild basin]

It doesn't really indicate for division, afaikt

for 3 and 4

[main gull]

Yes it does

[mild basin]

just not sure if 3 is E or F

[main gull]

$\left(\frac{x}{12}\right)^2 = \left(\frac{1}{12} \cdot x\right)^2$

Do you agree?

[jaunty stream]

Instead of mugging a chart up id honestly advice learning the fundamentals of cartesian graph plotting. Makes stuff much easier when the stuff you get is unfamiliar

No. That would end up raising x to power 4 on one side

[woven radish]

dldh06

[main gull]

Copied wrong

[jaunty stream]

Perfect

[main gull]

Btw, replying to the latex, doesn't ping me, it comes from the bot, which is technically someone else

[jaunty stream]

Gotcha, my bad

[mild basin]

Gonna go with this as my final answer 🙂

I feel confident that it's correct

Double checked and triple checked my work

https://tenor.com/view/yes-guy-gif-19616555

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[supple knot]

Plug the value from the x column into the y=2x+2

[main gull]

Plug in each x value

[orchid crater]

you got this bro

[main gull]

What did you do?

Did you do the process that was stated?

At least you understand the process

I was actually confused on how you got those numbers

Since 2(-6) - 4 doesn't equal -10

But 2(-6) + 2 does equal -10

https://www.youtube.com/watch?v=1Ww6U__uy6A&t=9s&ab_channel=mathwithmrbarnes

Good video to watch

Then find the slope, and use that

Slope and point slope formula

Fyi use parentheses to separate numerator and denominator

https://www.youtube.com/watch?v=_JhI1MooXeU&ab_channel=Mario'sMathTutoring

Well, the first question is, do you know how to find slope from a table?

So as stated, this is slope formula

You are using (4, 8) and (7, 11)

It doesn't matter which coordinate point you use as 1 or 2, just as long as line up the coordinates in the formula

Like if you notice, y2 is lined up with x2

And y1 is lined up with x1

[pastel pasture]

Just make sure the difference of the y co-ordinates and x coordinates are in the same order

Is what he's trying to say

If you have (3, 4) and (6, 7), the slope would be
(4 - 7)/(3 - 6)
And not (7 - 4)/(3 - 6)

[main gull]

Not really, if you plug in the values into the formula properly, it outputs the proper sign

If you are having trouble understanding, then I do agree, you should ask you teacher for help

[devout snow]

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[last sequoia]

What's the fastest way to answer this question? Do I just create a system of linear equations in an augmented matrix to solve for a, b and c?

[last sequoia]

this is the answer

[graceful cosmos]

Yes

[last sequoia]

oh this is the full Q btw

do you think that I could potentially use some property from ii) to avoid the SLE?

[left robin]

i think either you "see" the solution or you calculate it with a matrix

this is a quite nice system so i think the standard matrix calculation would be easy

[last sequoia]

I am not getting their solution of a=5, b=-2, c=3 after several re-calculations

[left robin]

i didnt write the steps out though

[last sequoia]

I will reattempt it again

I think I messed up

Ah ok

I got it

I wrote w = (19,6,9) by accident

Do you know how to solve ii)?

[left robin]

for part ii) you can use:
A(w)=A(5x-2y+3z)=A(5x)+A(-2y)+A(3z)

this works because A is a quadratic Matrix, which in turn means that it is a linear transformation

[last sequoia]

yep

[left robin]

A(5x)=5Ax

and we know Ax

same for the others

again, this step also only works because we are dealing with linear transformations

[last sequoia]

ohhh

Ax = -3x ... etc

[left robin]

yes

[last sequoia]

because it's an eigenvector right

[left robin]

👍

[last sequoia]

ohhh

[left robin]

wait

[last sequoia]

I got stuck trying to find A individually

[left robin]

Ax=2x

[last sequoia]

yeah oops

[left robin]

x has eigenvalue 2

btw, just out of curiosity:
how weird is the name "eigen" to you?

or is that a normal word for you

[last sequoia]

For a person? Or for a concept

[left robin]

in math

like eigenvector or eigenvalue

[last sequoia]

Am indifferent

[left robin]

like, does it make intuitive sense what it should mean?

[last sequoia]

Not sure hahaha

[left robin]

im asking this, because im from germany and eigen comes from german
i always wondered if that word even makes sense to non german speakers

[last sequoia]

nope

[left robin]

interesting

[last sequoia]

does it make intuitive sense in German though?

[left robin]

yeah kinda

a bit

Mein Eigen = My Property/My Own
If something stay eigen, it stays itself
this could be interpreted as staying itself just by a factor (the eigenvalue)

[last sequoia]

Some professors might briefly mention its word origin from german in a lecture

[left robin]

anyway, thanks for the chat
i gotta go now, it's quite late

good night

[devout snow]

@last sequoia Has your question been resolved?

[devout snow]

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[storm cairn]

starting the line 192=a(0-0)^2+ 192 how would i solve for a

[main gull]

You messed something up

You don't plug in the coordinates of the vertex for x and y because it won't give you the proper value for a

[storm cairn]

So do i plug the x ints?

[main gull]

That works

[storm cairn]

Ok wait let me try that.

[main gull]

You use whatever info that isn't the vertex

[storm cairn]

Oh

is that a general rule?

[main gull]

Because if you notice 192=a(0-0)^2+ 192, 0 - 0 is 0

[storm cairn]

yeah it didnt make sense

[main gull]

And 0a is 0

[storm cairn]

yea

[main gull]

Which in the end won't make sense, unless you use a different coordinate point to plug in

[storm cairn]

Okay

thank you

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[cobalt bough]

these right?

[cobalt bough]

<@&286206848099549185>

[orchid sierra]

you don't have any answers (or work) for anyone to check
EDIT: Oh no, one of them just isn't labeled is all

[cobalt bough]

@orchid sierra so all is good?

everything is answered

[orchid sierra]

do you have more work somewhere?

[cobalt bough]

wdym..

[orchid sierra]

some of these just have single answers and no work. Numbers 1 and 2

[cobalt bough]

fam

you don't need work to solve that..

its common sense

just worried about these

[orchid sierra]

oh, is it now

[cobalt bough]

it is if u know the formula

[orchid sierra]

the circle theorems.

[cobalt bough]

its just half is it not?

For 1

[orchid sierra]

yes

[cobalt bough]

So am right then or

[orchid sierra]

I don't recall the theorem used in 3 though

looks nifty, I just don't remember it

[orchid sierra]

yeah this all looks fine to me

I don't see any typos

[cobalt bough]

ty

[devout snow]

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[devout snow]

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[autumn spire]

Can I find k here?

[hushed wraith]

,rotate

[hushed wraith]

what is k supposed to be? it just looks like a random point

[autumn spire]

It’s just a constant I'm supposed to find

This is a graph of w=4-4i

[pseudo basin]

... can you show the entire problem

exactly as it was given to you

[autumn spire]

It’s in Arabic..

[pseudo basin]

okay, then post the problem and translate it

[jaunty mantle]

Is there anymore info about k?

At this point it could be anything

[restive river]

just post it

i will try to translate it

[autumn spire]

The adjacent figure shows the graph of the complex number w in the complex plane where arg(z) = -pi/4

Arg(w)*

[hushed wraith]

okay...

[autumn spire]

Did i translate it badly?

[pseudo basin]

well, your translation doesn't include the question

nor does it say what k-7 has to do with w

[autumn spire]

Thats literally the question it says 1)find k

[pseudo basin]

so it doesn't say anything about k or what it has to do with w ??

[autumn spire]

Nope

[pseudo basin]

then it is impossible to find k.

[autumn spire]

Ah I see

thanks

😉

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[autumn spire]

.

Is this the right solution?

That’s what the teacher said

[restive river]

,rccw

[autumn spire]

Although he assumed that k-7

A=k-7*

And a=4 as shown in the graph

so idk how that’s possible

[pseudo basin]

is this that same problem from before?

k-7 does not AT ALL look like the real part of w in that diagram...

[autumn spire]

It is

That’s the solution my friend sent me

He says their teacher told them that

[pseudo basin]

bullshit diagram

[autumn spire]

That’s what I told him xdd

Thanks for ur help

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[shadow terrace]

In this q

How to find the coordinates of A B C

Of a triangle

This is the triangle

[hybrid snow]

Find intercepts of the line

But one of your lines seems incorrect

That y = 6x line ain't right

Your triangle should look like this

[restive river]

What. Another layla? with the purple heart?

is this some massive coincidence or an alt

[shadow terrace]

I don't understand this figure

How did we make it

[hybrid snow]

You graph the functions given

y = 3x
y = 6x
y = 9

You should know how to graph functions.

[uncut crow]

lmaoooo

massive coincidence

[restive river]

Doesn't explain why they would leave immediately after but...whatever

[devout snow]

@shadow terrace Has your question been resolved?

[devout snow]

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[obtuse pagoda]

how do you start solving a equation like log(x)*(x+a)=b where a and b are known?

[restive river]

Have you heard of the Lambert W function?

Oh hold on I don't think it can actually be used here nevermind-

[winter patrol]

no nice way to solve that,

[obtuse pagoda]

oh ok

ty anyways

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[mild basin]

Stuck on this third one, not sure where to start with finding the domain?

I don’t want it to be a negative root, that’s my only limitation

Otherwise I go into the realm of imaginary numbers

https://tenor.com/view/dr-strange-doctor-strange-get-real-gif-23815481

[hybrid snow]

Yield to the square roots

[bright burrow]

Ensure both square roots greater than equal 0

[hybrid snow]

So 3x-6 >= 0

And then

3sqrt(3x-6) - 6 >= 0

[hybrid snow]

Your second one's domain is incorrect btw

$\sqrt{x}^2 = x$ only for $x \geq 0$

[woven radish]

Umbraleviathan

[hybrid snow]

h(x) is just $3(\sqrt{3x-6})^2 - 6$

[woven radish]

Umbraleviathan

[mild basin]

Damn you’re right.. I think fourth one is incorrect too?

[hybrid snow]

Fourth is fine

[mild basin]

But it’s same situation as second, no?

[hybrid snow]

Your putting a polynomial into a polynomial

[hybrid snow]

That's just gonna be a domain of all reals regardless

[mild basin]

I can’t square the bracket to remove the radical sign?

[jovial mauve]

You can, here

[mild basin]

Where?

[jovial mauve]

sqrt{3x-6} in h(x)

[hybrid snow]

You can't I thought. I was taught you couldn't

And you had to yield to the domain of f(x)

[jovial mauve]

[hybrid snow]

Image is loading

[mild basin]

Why does the domain have to be greater than 2?

For the second example

[hybrid snow]

Because of f(x)

You have to yield to f(x)

[mild basin]

WA says my answer is correct for the composite function

root cancels sqrt

its like saying 2/1 * 1/2 in exponential form

2/2 = 1

[devout snow]

@mild basin Has your question been resolved?

[mild basin]

.close

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[rocky sequoia]

what is N / ker(f) where f is an equivalence relation where x = y mod 5

[stone stump]

the set N quotient by the set ker(f) I guess? a bit weird notation

N/f would make more sense

[rocky sequoia]

erm im not sure thats how it was given

[stone stump]

what is ker(f) supposed to be. we don't have stuff like a group here

[rocky sequoia]

its supposed to be the kernal i think?

[stone stump]

so do they just mean the elements that are equivalent to 0?

[rocky sequoia]

perhaps

[stone stump]

anyway, I assume they just mean the set of the equivalence classes

[rocky sequoia]

that sounds right

what would that look like?

[stone stump]

N/ker(f) = {[0], [1], ...,[4]}

[rocky sequoia]

hmm

so in the equivalence class you put the values they map to rather than the values they map from?

i did something like {{0,5,10,…},{1,6,11,…},etc}

[stone stump]

yeah that's what i mean

[0] = {0,5,10,...}

etc

somewhat standard notation

[left robin]

what is your N in this case?

[rocky sequoia]

the set of natural numbas

[left robin]

oh wait, obvious

[rocky sequoia]

oh cool

didnt know that

thank you @stone stump my questions answered now

[devout snow]

@rocky sequoia Has your question been resolved?

[devout snow]

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[pearl harness]

i have a string of numbers (an)n>=1 so that a1=a2=1 and an+2=2an+1-an, any n >=1

[pearl harness]

a2+a5=?

[hushed wraith]

$a_{n+2}=2a_{n+1}-a_n$ ?

[woven radish]

SilverSoldier

[pearl harness]

yes

My teacher doesnt explain shit

Can you tell me if a5 means like n3 or is it n5

[mellow panther]

what do you mean by a5 means like n3?

[pearl harness]

So I have to do this thing

a2+a5

I dont really get what the n does

Like is it a3+2 so its a5= 2an+1-an

I d really like the solve on this so I can maybe understand how it works

[mellow panther]

n is the index in an

So, for a5 since we only know about a(n+2), we need to take n=3

a2 is slightly more involved

[pearl harness]

So if we go for that

It would be

[mellow panther]

$a_{3+2}=2a_{3+1}-a_3$

[woven radish]

numbpy

[pearl harness]

so how do i find a3 tho

[mellow panther]

same process

[pearl harness]

I take n as 1?

[mellow panther]

yes

[pearl harness]

Thank uuuuuu

So a3 will be 2?

[mellow panther]

How did you get a numerical value?

[pearl harness]

a1 and a2 are equal to 1

ah shit

i didnt mention that

sorry

[mellow panther]

ohh, yeah

[pearl harness]

Well thanks alot

Man

[mellow panther]

sure bud

[pearl harness]

This discord server is op af

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[devout snow]

Please don't occupy multiple help channels.

[open pendant]

Fixed

Why does 3x in the final product move right

Sorry wait.

My answer was

16-3x
19-3x

But the correct answer is

3x-16
19-3x

Why does the 3x on top move to the left?

[devout snow]

@open pendant Has your question been resolved?

[open pendant]

<@&286206848099549185>

[sick marsh]

Well your answer is not quite correct

[open pendant]

Yes. Why does x shift over

[sick marsh]

Keep in mind that -(18-3x) gives -18+3x

[open pendant]

Yes

[sick marsh]

So the -3x becomes+3x

[open pendant]

2-18+3x

Why does it become

3x-18

[sick marsh]

Right then 2-18 gives

-16

[open pendant]

Yes

[sick marsh]

So you end up with -16+3x

[open pendant]

But that is wrong according to them

[sick marsh]

Which by commutativity is equal to 3x-16

[open pendant]

Why cant it be accepted as -16+3x though

Arent they both correct

[sick marsh]

I suppose it has to do with 3x-16 being the usual way one writes it down

[sick marsh]

Yes they are

[open pendant]

That's just silly through. What's the tule I'm missing here

[sick marsh]

You wrote (16-3x)/(19-3x) here though which isn't correct

[open pendant]

Oh I see

[sick marsh]

Well take a linear equation for example. We write it like y=ax+b

Not y=b+ax

[open pendant]

Okok I got it thanks

[sick marsh]

No worries

Probably also has to do with the positive term being first

[open pendant]

I know u guys are busy today. Appreciate the help

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[balmy cloud]

hey; unit circle related question , currently relearning trig; is it better to memorize the unit circle or know how to convert rads and degrees? have to work my way up to calc so looking for the method that is more helpful long term thank you

[hollow pollen]

dont memorize, understand

and you will need to understand both those things

[balmy cloud]

awesome thank you for the quick answer 🙏🏻

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[faint stream]

How how do I do this

I gotta test ina hour

[young lake]

case 1: (x-5) is positive
remove the mod, solve the quadratic, find x

case 2: (x-5) is negative
remove the mod, multiply -1 to it, solve the quadratic, find x

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[spark cove]

i have this difference equation

[small raptor]

mhm

[spark cove]

how can i say if there are bounded non constant solutions in the interval (−∞,0)

the general solution if i'm correct is y=ke^x^2 +1

$y=ke^x^2 +1$

[woven radish]

lordi
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[spark cove]

but i don't even understan the question very well

i know a no bounded set is a set that has an infinite number of elements

so should i study the value of y as x goes to infinity?

please tag me if you answer

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[spark cove]

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[vital shard]

how do i rearrange question e so that i can put it in vector form

i got y/2 = 5/2 - x/4

how can i deal with the -x/4

[hollow pollen]

you dont need to do anything like that

[vital shard]

wdym

[hollow pollen]

just do what you did with d

[vital shard]

ill end up with (y-5)/2 = -x/4

[left robin]

wouldn't it be this?

or is that not what is meant here

[vital shard]

thats not what is meant here

[hollow pollen]

im quite sure that actually works

but they probably want you to write vector + x times another vector

[vital shard]

yh

like that

[hollow pollen]

which you can deduce from this

[left robin]

yep

[vital shard]

can u guide me thru that please

cause ive been doing it differently

[left robin]

and then pull out the x

[vital shard]

ohhh

thanks

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[night geyser]

Having trouble solving this. I know I have to find the slope, the perp slope and the midpoint of a side and then do the same for another side and then set them equal. But, for one of the equations I get y=4, but then how do I get x?

[languid fossil]

if you have an equation y=mx+c then you cal plug in y=4 and solve for x

[night geyser]

Can you help me, I don't know how to do that

and where to plug it in

[languid fossil]

sure just gimme a minute to draw a diagram or two

[night geyser]

ok

thanks

[languid fossil]

So here's the triangle, with the midpoint of each side also marked

[night geyser]

yeah

got that

[languid fossil]

Now we want to extend the perpendicular bisectors

[night geyser]

yeah

[night geyser]

ah, this is a right triangle so it is the midpoint of the hypotenuse?

didn't notice that lol

[languid fossil]

Since AB is vertical, it's perp bis is y=4, and since AC is horizontal, it's will be x=3

[languid fossil]

Yep

[night geyser]

Drawing really helps actually, thanks so much

[languid fossil]

Alg

Drawing is almost always the best start point for geometry problems

[night geyser]

thanks for the advice ^^

.close

[devout snow]

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[outer fable]

Hello, I dont fully understand this exercise, can anyone help me?

[pseudo basin]

let me reiterate my question that you never answered:

have you worked with eigenthings before?

[outer fable]

My bad

Couldn't answer it

Eigenvalues

Yes I know a little about them

[pseudo basin]

@outer fable

oh. fuck.

your reply only loaded just now sorry

okay, so

do you know the definition of an eigenvector?

[outer fable]

It's like the vectors that when applied by a matrix it can change everything except direction

[pseudo basin]

well, that's one way of putting it...

an eigenvector of a transformation T is a vector x such that Tx is parallel to x.

[outer fable]

Yeah I don't know the formal thingys lol

[pseudo basin]

now, do you know what "reflection across the yz plane" means geometrically?

[outer fable]

Wow never heard it like that

Hmm

Nah not really

Having a hard time visualizing it

[pseudo basin]

do you know what a reflection is?

[outer fable]

Yeah

[pseudo basin]

okay

[outer fable]

It's like mirror

[pseudo basin]

then surely you would understand that reflection across the yz plane keeps all vectors parallel to it the same, while vectors perpendicular to the yz plane are flipped

do you understand this?

[outer fable]

Shi

I don't think I can see it

Wait I'm search images

Okay that didn't help

Wait

Nah I got it

[devout snow]

@outer fable Has your question been resolved?

[outer fable]

<@&286206848099549185>

Does anybody know?

[devout snow]

@outer fable Has your question been resolved?

[outer fable]

damn

[outer fable]

[rocky sequoia]

:0

looks like 1,1,-1

-1 0 0
0 1 0
0 0 1 looks to be the transformation theyre looking for

[outer fable]

Oh

Do you care to try to explain?

[rocky sequoia]

ah sorry didnt see the msg

[rocky sequoia]

that matrix is the reflection thr yz plane matrix right

and its eigen values are 1 1 -1

[devout snow]

@outer fable Has your question been resolved?

[outer fable]

Oh

So how did you know that matrix was the yz plane

[rocky sequoia]

apply that onto any vector it just times their x by -1

which mirrors it in the yz plane

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@outer fable Has your question been resolved?

[devout snow]

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[safe trench]

2b

[safe trench]

mean is 0.72

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[wet dock]

expectation of the |frequency - mean of the frequency|

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[quick dragon]

Hello,
Does any1 know how to find a specific point on a circle, where the requirement is, that the point is 20 degrees relative to horizontal?

[quick dragon]

I do have the equation for the circle

[rustic kiln]

Draw a triangle

you know an angle and a side

and from the circle equation you know the centre x and y

so you can calculate the length of the opposite and adjacent, add them accordingly to the centre x and y and find the point

[quick dragon]

So, how is the triangle supposed to be? A corner in radius, one in the unknown and another somewhere or?

[rustic kiln]

Draw a line from the centre to the point

draw a line from the centre to the x co-ordinate of the point parallel to the x axis

complete the triangle

[quick dragon]

The point that is parallel to the x-axis should be either the bottom part or the top part of the circle, right?

[rustic kiln]

what do you mean?

show me your diagram

excusing the bad drawing it should look like this

you know r from circle equation also

[quick dragon]

Between the two blue points, there has to be a point that is 20 degrees in regards to horizontal

The equation is given by:

[rustic kiln]

what are the coordinates of the blue points?

the point is this

[quick dragon]

A(-9.66 ; 9.82) & B(-2.50 ; 12.18)

[rustic kiln]

then you've got an incorrect problem or you've done some incorrect working

[devout snow]

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[white dew]

and thus, I die

Is this not what I’m supposed to do?

The calculation of the integral itself is correct, according to Symbolab

Which means I made a mistake converting the x and y into r and theta

Or so I think

I can’t actually see where I made a mistake

oh yikes

I drew y=0 instead of x = 0

whoops

.close

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[severe ermine]

.reopen

[warped relic]

This looks like an autocad drawing

[severe ermine]

Hey mate, it is

I have calculated the floor areas

The room is basically split into 2 different polygons

Two large ones, and two smaller ones

I would like to know the average width of the room

As there are two widths

[warped relic]

Okay...

[severe ermine]

The lenght is 3.114 meters

[warped relic]

Lemme revise my area/length measurements for a moment

[severe ermine]

The width in the bottom is 3.785 meters

And width at the top is 4.379 meters

[warped relic]

Okay consider the following

$\bar x _T \sum A_i = \sum \bar x _i A_i$

[woven radish]

VulcanOne

[warped relic]

Where Xt is the location of the centroid of the polygon

[severe ermine]

Right...

Whaat is the rest?

[warped relic]

Wait lemme think for a good way to express the average width because this doesn't feel like a good way to find it

I think a good way to get a good average would be to find the net area and then divide it by the length

@severe ermine

[severe ermine]

I will try that

Humm i am not sure that works..

Thinking about this

Anyone else has any ideas

How to calculate the width of this irregular polygon

[devout snow]

@severe ermine Has your question been resolved?

[severe ermine]

Can someone else help

<@&286206848099549185>

Can someone help

[severe ermine]

<@&286206848099549185>

[supple knot]

is the width just two different numbers? or can you write the width as a function with some domain?