#help-27

1 messages · Page 30 of 1

sinful dust
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u substitution is a method used to simplify your equation. For example, you probably don't know how to solve x^4 - 52x^2 + 576 = 0, so if you say, for example u = x^2, you can rewrite your equation as u^2 - 52u + 576 = 0. In this form it's easier to solve. Let me know if this made sense.

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@tender saddle

tender saddle
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how do you know its that

real grail
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because we know how to solve equations of type :
ax² + bx +c = 0

sinful dust
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yes, I chose u=x^2 because I knew it generate a quadratic equation

tender saddle
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so I just look for a way to make a quadratic?

sinful dust
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yes

tender saddle
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ah okay

tender saddle
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left robin
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.

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suppose a set M

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left robin
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with
|M|=n

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prove that|Pot(M)|=2^n

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via induction

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so

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starting with 0 we get
M=emptyset
|M|=0
Pot(M)={emptyset}=1=2^0=2^n

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i am stuck on n+1

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it says i can't use binomialcoefficient

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i am given a hint though:
suppose a m in M and look at the subsets of M seperately that contain m and those who do not

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the problem is that i don't know how to apply that hint

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left robin
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<@&286206848099549185>

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thin gulch
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how do i multiply 4x(-2) with counters

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left robin
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what do you mean with counters?

thin gulch
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the yellow and red chips

left robin
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?

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i can't quite follow

thin gulch
left robin
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4x(-2)

red=-1
-2=2x(-1)=2xRed

therefore
4x(-2)=4x2xRed=8xRed

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i guess

thin gulch
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can you draw that

kindred agate
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what grade are you in

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jesus

thin gulch
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grade 8

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it’s 4 groups with 2s in them idk what to do next

kindred agate
thin gulch
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icon

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cool

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what do i do tho

thin gulch
kindred agate
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schools are 5 grades behind bc of covid damn

thin gulch
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what 😭

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do you know how to help me

kindred agate
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yes

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you add 8 counters of -1

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done

thin gulch
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how do i do -4 x (-2)

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ik it’s 8 but idk what to do

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i’ll just do the answer and make up my own counters

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yk

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nvm i got it

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night gust
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midnight bane
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so

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you can multiple the roots together as factors then plug in the y intercept to find the a value

night gust
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yeah but what do ipug them into

midnight bane
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the roots as factors would be x+1.6 and x+3.2

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Now multiply them together

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Get a quadratic form

night gust
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so like (x+1.6)(x+3.2)?

midnight bane
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Then solve for a which is the coefficient of the x^2 term

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yesA

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or

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You can find a first

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Then you dont need to multiply the factors

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Thats probably better

night gust
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how do i find a?

midnight bane
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y=a(x+1.6)(x+3.2)

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a is the stretch factor

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And i just realised the first doesn't work

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because stretch factor is different from the coefficient of the x^2 term

night gust
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i got x^2 +4.8 + 5.12?

midnight bane
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if that's what you got yes

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which just means no stretch factor

midnight bane
night gust
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says its wrong?

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so i just keep plugging it in?

midnight bane
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That's what you just did and you got 1 right

night gust
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does it want me to plug this in??

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should i do
25.6=0^2 + 4.8(0) +5.12? thats just false thouhg. unless i leave x as x????

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<@&286206848099549185>

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night gust
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restive river
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What is that number of left side of sigma denotes??

restive river
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1/N

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where N is the upper bound of the sigma notation

neon aspen
restive river
neon aspen
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Answer to what question

restive river
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multiplying by 1/N

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K my bad multiply

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So it's just that I have to multiply after finding sum?

neon aspen
restive river
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looks like the thing is just saying that the average of all velocities indexed by the set N is 0

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or the average velocity is just 0

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initial velocity

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K

neon aspen
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Conservation of momentum?

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Also is this physics at university

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Sorry I don't mean to sound obsessed with physics haha

restive river
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Nah total v of electrons after colliding

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In absence of EF

neon aspen
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I see

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This is uni level yeah?

restive river
neon aspen
restive river
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restive river
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From which eq did they derive marked eq?

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main gull
restive river
main gull
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It was probably derived previously in the book

restive river
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Is charge * MF = force?

main gull
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What's MF?

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Magnetic field?

restive river
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Magnetic field

main gull
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Pretty sure E is electric field

restive river
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K

main gull
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That's the unit for temperature, Kelvin

restive river
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Now I got it F=qE

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clear fulcrum
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can you multiply binomials without an area model

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@clear fulcrum Has your question been resolved?

clear fulcrum
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<@&286206848099549185>

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hello

clear fulcrum
hybrid snow
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Wdym area model

patent marsh
patent marsh
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is that what you mean by area model?

hybrid snow
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Oh that's

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Yeah there's a thing called FOIL

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takes less space than those models but eliminates the direct visual appeal

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You definitely can

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Introducing "AB AbBa ab"

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The new thing you'll hate

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At least it's easy to memorize 💀

patent marsh
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yeah FOIL is very crucial to learn!

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here's a really good example here too

hybrid snow
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FOIL goes hard

clear fulcrum
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thank you

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sand junco
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Sketch the region defined by the inequality Re(𝑧)<Im(𝑧).

sand junco
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i cant wrap my head around this :(

sonic smelt
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On an xy plane that would look the same way as x < y

sand junco
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oh

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why tho

sonic smelt
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x represents the real part and y represents the imaginary part

sand junco
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OHHHHHHHHH

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I GET IT

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THE Y VALUE IS ALWAYS GREATER THAN THE X

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thanks

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graceful lava
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graceful lava
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when calculating stuff like this how do we know what x is

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for example would it only be valid for x or would it be valid for x + 3 too

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and then what if the x also has 2 nested exponent etc

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how is it possible to even remember this

crimson hamlet
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u dont need to remember it

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first convert the b^x into e

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so e^xln(b)

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then differentiate it

graceful lava
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any other useful stuff like this?

crimson hamlet
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ln is simply log with base e

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when the base and the angle of the log are same the ans will be 1

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ln (e) = 1 can be written as e¹ = e

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subtle agate
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For example if (x+y)^3=100 can I just take the cube root of it or do I have to foil it out?

lean musk
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you can just cube root both sides

subtle agate
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Pk thank you

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ancient owl
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Find the formula for the Nth pattern--> 9(9)+7=88; 98(9)+6=888; 987(9)+5=8888\

ancient owl
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I've got the solution, i dont get it, a little explanation would help. Thanks!

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ancient owl
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<@&286206848099549185>

ancient owl
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spare abyss
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spare abyss
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I need to find out how much space the cube is taking up in the sphere

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With an equation using X for one of the cubes sides

real grail
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what about the radius of the sphere ?

spare abyss
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Don’t know it

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Need to find out using the Pythagorean theorem twice

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To get the diameter then divide it in two to get the radius

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But after that I’m kinda stuck since he wants us to only do it in one equation

real grail
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ahh I get it now

spare abyss
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yea I've been stuck here for a while

real grail
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it's sample

spare abyss
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?

real grail
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but hard to explain

spare abyss
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kk

real grail
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without drawing it

spare abyss
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i see

real grail
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the diametre = x* sqrt(3)

spare abyss
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yea

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i got that

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but now how do i continue the equation?

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in our math books this is how it says you find the spheres volume

real grail
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r = diameter /2

spare abyss
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yea but how do i do that in an equation

real grail
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volume of sphere - volume of the cube

spare abyss
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kk

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we have that

real grail
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actually you already have it

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isn't the cube take X^3 ?

spare abyss
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is ^3 the power of 3

real grail
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actually we don't need to calculate the volume of the sphere

spare abyss
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?

real grail
real grail
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since the question is "how much space the cube is taking up in the sphere"

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the volume of the cube is the volume is taking up in the sphere

spare abyss
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no... the answer needs to be in rational numbers.

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for example like this

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im trying to show pi/6 thats the answer for a similar question

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the answer needs to be in rational numbers which is what makes it so difficult

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do you understand at all?

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or am i making no sense

real grail
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I think that the question you want to ask is "The percentage of what the cube takes up from the sphere ".

spare abyss
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yea.

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im sorry this is hard since the question is written in swedish

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so im having to translate a bit

real grail
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the rest is easy

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just find the volume of the sphere

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V(sphere) = 4 * pi * (Xsqrt(3)/2)^3
= (4 * pi * X^3 * 3
sqrt(3))/8

spare abyss
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Is this what you mean?

real grail
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yeah

spare abyss
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how do you even begin to solve that? since this is supposed to end with like: V cube/ V sphere

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signal robin
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Yo I need help

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long sundial
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send q

signal robin
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I have to find an equation of Ta

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And then deduct f'(0)

long sundial
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what have u tried?

charred abyss
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do you know that second function?

long sundial
signal robin
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But

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Idk f'(0)

charred abyss
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yes I know but if you knew that function it would be easier

long sundial
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you can see 2 points that the tangent goes through

signal robin
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So I found f'(0)x+2

long sundial
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this will allow you to find the equation of the tangent

signal robin
long sundial
signal robin
real grail
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choose two point from (TA) to find his equation ?

long sundial
signal robin
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I found Ta=-x+2

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Because I have (2-0)/(0-2)=-1

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And g(0) is 2

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So -x+2 ?

charred abyss
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yeah but you could find it more easily

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you know the intersections

real grail
long sundial
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gradient of a tangent is the gradient of the curve at that point

signal robin
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Ok now how do I deduct f'(0) ?

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I have no idea

long sundial
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say i had the value of f'(0) and I wanted to find the tangent to f at 0

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the tangent is: y= mx+c

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c is our y intercept

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what is m?

signal robin
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-1 ?

long sundial
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yes but geometrically what is m

signal robin
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Idk

long sundial
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it's the gradient of a line

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if the curve is y=mx+c then c is the y intercept (at x=0 y=c) and m is the gradient

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f'(x) measures the gradient

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so if we are finding the tanget at 0 then m=f'(0)

real grail
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$f'(0) = \frac{f(x)- f(0)}{x - 0}$

woven radishBOT
#

Mehdi_Moulati

long sundial
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so in reverse what is the value of f'(0)

long sundial
signal robin
real grail
signal robin
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The gradient is -1

real grail
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if you use it in the TA it will give you the same result (-1)

signal robin
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So f'(0) is -1 ?

real grail
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yeah

signal robin
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Alright thank you so much

real grail
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👍

signal robin
#

Now I go sleep , good night brother

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tawdry zephyr
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i need help with this

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tawdry zephyr
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so what i did was i said both are =y so they are = to each other then i use calculator and got x=-1,89

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<@&286206848099549185>

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red cypress
#

Fx= e^x cosy
Fy= e^x siny
im having trouble finding the antiderivative of each with respect to x and y

long kettle
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What have you tried

red cypress
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well for the first one, e^x cosy, in terms of x

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well im not sure if i take the anti derivative of cos in this case, since its cosy and i find the antiderivative w.r.t. x

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am i overthinking this

long kettle
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If x and y are both independent variables, then y can be treated as a constant w.r.t. x

red cypress
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so would i get e^x siny? sorry still unsure

long kettle
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Why did cosy become siny?

red cypress
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*-e^x siny

long kettle
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You're integrating with respect to x

red cypress
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oh shit

long kettle
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cosy is not cosx

red cypress
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youre right

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so it remains e^x cosy

long kettle
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Don't forget to add a "constant"

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Since y is being treated as a constant, any function of y will do

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So instead of + C, you'd add + g(y)

red cypress
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i see

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nvm

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i was fine with integration up until i had to integrate w.r.t. x,y,z

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Fy= e^x siny would be.. -e^x cosy with respect to y?

long kettle
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Don't forget it's an indefinite integral

red cypress
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ah sorry, this just part of a larger problem, i just needed to figure out how to integrate w.r.t., i got the rest from here!

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zenith sentinel
devout snowBOT
zenith sentinel
#

need help w this one

real grail
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A\B = (A or B) - B - (A and B)

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B\A = (B or A) - A - (A and B)

stone stump
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assume there is an element x in AnB

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what can you say about x and the two sets in question?

zenith sentinel
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that x must exist in both sets

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?

stone stump
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well in both or in neither

zenith sentinel
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why neither?

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do we not assume it to be in A n B?

stone stump
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I mean just theoretically. either it is in both or it is in neither

zenith sentinel
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oh ok

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yh i see

stone stump
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but what can't happen is that it is in one of them but not the other

zenith sentinel
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yh since it is a intersection

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so then how do i proceed?

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<@&286206848099549185>

stone stump
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well is x in the LHS?

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is x in the RHS?

zenith sentinel
#

x can be in the right hand side assuming its present but cannot be in the left hand side?

stone stump
#

yes. why?

zenith sentinel
#

this is because on the left hand side (A \ B) means "in A not in B and (B\A) means "in B not in A" but since we assume x to be in sets A and B this is contradicting

#

but for the right hand side A u B will return x since its just applying "in A or in B"

#

is that true?

stone stump
#

yes

#

not the best wording but yes

zenith sentinel
#

ah ok thank you ill improve my explanations

#

.close

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rotund gull
devout snowBOT
rotund gull
#

i have x + y + z = 1,000,000

#

then I have .02x + .03y + .04z = 34,000

#

then I have 4x = y

#

this should be pretty straightforward, but i'm getting confused, any help would be great

restive river
#

oh man, that looks confusing asffff but lemme see.

rotund gull
#

This algebra video tutorial explains how to solve system of equations with 3 variables and with word problems. It contains two example word problems on investment and on total value.

New Algebra Playlist:
https://www.youtube.com/watch?v=nTn9gVqRfKY&list=PL0o_zxa4K1BUeF2o-MlNpbRiS-oE2Kn6J&index=2

Access to Premium Videos:
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▶ Play video
#

<@&286206848099549185>

#

solved it

#

.close

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visual flicker
#

Find or tho center of triangle with points A(2,6) B(8,6) and C (6,2)

compact birch
#

whats the question?

#

find or tho?

real grail
#

the center is $(\frac{Ax+Bx+Cx}{3},\frac{Ay+By+Cy}{3})$

woven radishBOT
#

Mehdi_Moulati

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flat elm
#

anyone knows beams and forces?

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visual flicker
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#

@flat elm Has your question been resolved?

compact birch
#

whats Mo

tame palm
#

Initial Moment

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tall geyser
#

(evaluate the limit)

devout snowBOT
tall geyser
#

I'm not sure where to start

compact birch
#

use a table of values

#

try x = 0.01, 0.001, 0.000001, 0.00000000000001

arctic field
compact birch
#

what value does it approach?

arctic field
#

that's not really a formal method

tall geyser
arctic field
#

you probably want to log the expression

tall geyser
#

(it's not "correct")

arctic field
#

and then apply l'hopitals

#

well

tall geyser
#

ok wait

arctic field
#

you might not need l'hopitals

tall geyser
#

so I'm at dy/y = (1+x^-1)

arctic field
#

dy?

tall geyser
#

logarithimic differentiation no?

arctic field
#

what's the derivative for

tall geyser
#

ln|y|

arctic field
#

oh hmm

#

i see what you're doing

#

seems backwards

tall geyser
#

wym

bleak sun
#

you could do e^xln(1+1/x)

tall geyser
#

hmm

arctic field
#

the limit doesn't evaluate to the logarithmic derivative

arctic field
tall geyser
#

wait i am confusion sry

#

what does the limit eval to then?

tall geyser
bleak sun
#

lim x-> 0 of xln(1+1/x)

#

then do

#

ln(1+1/x) / 1/x

#

l'hopital

arctic field
#

dont really need L'H for that

woven radishBOT
tall geyser
#

and now I'm confused

bleak sun
#

where did the y come from

tall geyser
#

ln|y|

arctic field
#

why are you taking derivatives?

tall geyser
#

wait that's a really fucking good question

#

😭

bleak sun
#

id just listen to snow they seem smart lol

arctic field
tall geyser
#

oh yeah I have not learned how to do exp yet

#

I'm on L'hopitals rule so im assuming im supposed to do that

arctic field
#

exp is just e^x

tall geyser
#

oh

arctic field
#

i wrote it like exp because e^x would look ridiculous

tall geyser
#

ok now im even more confused

woven radishBOT
arctic field
#

so like

tall geyser
#

ok now i ge tit

arctic field
#

okay good

#

so then you just want to evaluate the limit in the exponent

#

so like

tall geyser
#

wait am I not just back to where I started?

woven radishBOT
arctic field
#

the log lets you bring down the power

tall geyser
#

ok yeah

arctic field
#

now you can do a bit of rewriting

woven radishBOT
tall geyser
#

and then l'hoptials?

arctic field
#

well you dont necessarily need it if you know growth hierarchy

tall geyser
#

ok i dont know that

arctic field
#

like

woven radishBOT
arctic field
#

something of that nature

tall geyser
#

wait so what you're saying is that one of the two terms is dominant?

tall geyser
arctic field
#

well x -> 0+ is the same as 1/x -> infinity right?

#

so we can rewrite the limit with the substitution t = 1/x

tall geyser
#

oh this is true!

woven radishBOT
tall geyser
#

ok so the demoniator is the dominant term because it doesn't have the log around it?

arctic field
#

yes

tall geyser
#

so the limit is 0?

arctic field
#

that limit is 0

#

the original limit is not

#

because remember we put it all in the exponent of e^x

arctic field
tall geyser
#

ok yeah

arctic field
#

so what we actually have is e^0

tall geyser
#

oh so its just 1

arctic field
#

yep

tall geyser
#

dude I'm so sorry for being so difficult

#

😭

#

tysm

arctic field
#

np

tall geyser
#

.close

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#
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kind wind
#

how do i find the missing length

devout snowBOT
kind wind
#

i need it to figure out area

pallid silo
#

Your diagrams a bit unclear

kind wind
#

uh

pallid silo
#

Looks like you have the perimeter?

#

You should be able to solve for the length

#

2h + 2w = p

kind wind
#

2h + 2w = the missing side length?

pallid silo
#

What’s p

kind wind
#

perimeter?

bleak sun
#

the diagram is super unclear

pallid silo
#

Well you have height and perimeter

#

And your finding width

#

Which is your missing length

kind wind
#

this was the original question

pallid silo
#

Oh it’s not a square

kind wind
#

i need to find area

#

of the figure

pallid silo
#

Ok so the radius is 9m?

kind wind
#

yes

#

since its quarter circle

bleak sun
#

i dont think thats possible

pallid silo
#

Is perimeter given to you?

kind wind
#

no i did it myself

pallid silo
#

Well it could be any length

#

There needs to be something else

kind wind
#

idk

#

apparently its 3m

#

i dont get why

bleak sun
#

probably given in the question

main gull
#

Can you post a picture/screenshot of the actual question?

kind wind
#

oh wait i forgot to write a side length

#

my bad

pallid silo
#

Oh…

kind wind
#

this should be much better

pallid silo
#

Well you can get 3m from here

#

Wait that 9 is suppose to be x

#

Stupid mobile

#

One sec

kind wind
#

kk

pallid silo
#

Cause you know radius is 9m

kind wind
#

how did you know that it adds up to 12 because of the radius

pallid silo
#

Well the length is 12m

#

That’s given

#

And we know the radius is 9 m from the height

#

So the horizontal radius is also 9 m

main gull
kind wind
#

oh

#

im so stupid

main gull
#

Because you know the total length and the radius, you can find the side of the rectangle

kind wind
#

yeah

#

ty

#

.close'

#

.close

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#
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kind wind
#

i need help again 😭

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kind wind
wispy perch
#

can someone help me please

brisk totem
#

you already have the formula in front of you, plug the coefficients for the quadratic into the quadratic formula

wispy perch
visual flicker
#

What did U get

#

From plugging it in

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clever minnow
#

Help using systems of equations

devout snowBOT
clever minnow
#

Can someone show me how to do it step by step

topaz wedge
#

augmented matrix

ember palm
#

We gotta use matrix method?

topaz wedge
#

you dont have to

clever minnow
#

elimination

topaz wedge
#

solve for x in terms of z using the second equation

#

plug this into the third equation

#

then solve it for y

clever minnow
#

Ok

#

Can you write it out and show me please ?

#

The problem

topaz wedge
#

no

clever minnow
#

Wow😹

topaz wedge
#

i believe in u

#

x + 3z = 9

#

cmon

wooden wraith
#

Nobody is going to do just do it for you lol

topaz wedge
#

solve for x

wooden wraith
#

Have you solved 2-variable systems before?

clever minnow
#

Ok ok I’ll be back if I have trouble

#

.close

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#
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green yew
devout snowBOT
green yew
#

can plz someone help me in this maths plz?

zenith jacinth
#

induction maybe ?

#

and for alpha and beta, you take two cases to have a system i think

uncut crow
#

could also maybe try some sum of squares formula thing

#

square of (sum of first n positive ints) also has a nice formula

#

it’s the sum of the first n cubes

zenith jacinth
#

oh that

#

this one is good too

uncut crow
#

so it should just become subtracting a polynomial from another

devout snowBOT
#

@green yew Has your question been resolved?

green yew
#

I am not getting it. Can you please do it for me ? pleaseeee

charred adder
#

rarely anyone will do stuff for you so you gotta learn it by asking questions

green yew
#

Can you say me what should I do in the first step for this question?

charred adder
#

look up they provided instructions try them out if they don't work ask again

green yew
#

ok

green yew
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stray nova
devout snowBOT
stray nova
#

Is this step necessary

#

I initially got In(3x)

sinful gust
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royal aspen
#

is (the sum of two numbers is 48. find the maximum product and the two numbers ) and (Find two numbers whose sum is 48 and whose product is a maximum) the same but phrased differently?

royal aspen
#

english isnt my first langauge so phrasing really kills me

compact birch
#

sounds right

royal aspen
#

oh thank you

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#

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pulsar ermine
devout snowBOT
pulsar ermine
#

Is my solution the same as what the above solution is doing?

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#

@pulsar ermine Has your question been resolved?

stone stump
#

the second yes

#

the first no

#

to show that EuF=F, you need to take an element in EuF and show it is in F and you need to take an element in F and show it is in EuF

#

you did the second part (although you only said "trivially true" and didn't argue for it)

#

but you didn't do the other one

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#

@pulsar ermine Has your question been resolved?

pulsar ermine
#

I’m a bit confused? Did I first break down the cases that I need to show correctly which I denoted as (1) and (2)?

pulsar ermine
#

Is this what I need to show for the implication?

#

Would this be correct for showing (1)

stone stump
#

to show that A=B you need to take an element in A and show it is in B and vice versa

#

so here you need to take an element in EuF and show it is in F and then take an element in F and show it is in EuF

stone stump
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magic tapir
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#

Please don't occupy multiple help channels.

supple knot
#

.close

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tough shale
#

I'm unsure how to do this question

devout snowBOT
crisp turret
#

the question states the income of money is constant and the interest rate is continuously compounded and that is impossible (as far as i know).

#

but the function in both cases diverges to infinity

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rapid panther
#

Quick question. if the determination coefficient is 0.49 what would I say the model of the data is "good" or something else? or do I remove some more outliers to get it >0.50

rapid panther
#

would it be alright to remove the uk and finland as outliers?

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#

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polar bolt
polar bolt
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grand dragon
#

So I’m having issues with this problem. Let me show you guys my work too. I know one equation which is x+y=400 but I don’t really know if I’m sure about my other equation involving 9.65 and 6.50. Plus I’m unsure what to do with the value of 7.49 in the second equation. I attempted to do the work with the equation of 6.50x+9.65y=7.49(400) but I’m unsure if that is correct. When I tried it I got 404.8, which isn’t what I need. I need to get 400.

grand dragon
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#

@grand dragon Has your question been resolved?

grand dragon
#

<@&286206848099549185>

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grand dragon
#

.close

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hasty falcon
#

Hello, I need to find out if there exists some random variable independent from X~U(-1,1) such that X+Y~ 2Y. I should use characteristic functions.

hasty falcon
#

I tried in this way (sin t)/t * phi_{Y}(t) =phi_{X}(t)*phi_{Y}(t) = phi_{X+Y}(t) = phi_{2Y}(t) = \phi_{Y}(2t)

#

I valued the left side with k*pi for k=/=0, hence phi_{Y}(2kpi) = 0, it was an attempt to reach contradiction but it failed

#

$ \frac{\sin t}{t}\cdot\phi_{Y}(t)=\phi_{X}(t)\cdot\phi_{Y}(t)=\phi_{X+Y}(t)=\phi_{2Y}(t)=\phi_{Y}(2t)$

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#

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hasty falcon
#

.close

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chrome meteor
#

Please re open mines

devout snowBOT
chrome meteor
#

My science class is pretty small. There are just students in the class. My teacher, Ms. Microbe, has an unusual system for pairing us up for labs. She has given each of us a number from through , and on lab days, she pulls our numbers out of a bag to determine who is paired with whom. When we did our last lab, I happened to notice that the sum of each person's number with his/her lab partner’s number was a perfect square!! How were the partners assigned?_

#

So I know 18+17 is 35 and half of 35 is 15 what’s next?

brisk totem
#

what number when multiplied by itself gets you 35?

chrome meteor
#

15

brisk totem
#

hm, what's 15*15?

chrome meteor
#

35

brisk totem
#

are you sure about that

chrome meteor
#

Oh 30

#

30

brisk totem
#

are you sure that 15 multiplied by 15 is the same as 15 plus 15?

chrome meteor
#

225

#

Oops

supple knot
#

,calc 15 * 15

woven radishBOT
#

Result:

225
brisk totem
#

so with that in mind, and the knowledge that 18 plus something is a square number, find what something should be

chrome meteor
#

243?

brisk totem
#

okay, is there a student with the number 243 in the class?

chrome meteor
#

Idk

brisk totem
#

read the question again, what numbers do the students get?

chrome meteor
#

1-18

brisk totem
#

yes, so what number from 1 to 18, when added to 18, gets you a square number?

chrome meteor
#

9

brisk totem
#

and what number multiplied by itself gets you 18+9=27?

chrome meteor
#

How is that possible?

brisk totem
#

it's not, so is 9 the right answer?

chrome meteor
#

Yes

brisk totem
#

then what number multiplied by itself gets you 27?

#

you've told me that 18+9 is the square of some number, so you should be able to give me a number that when multiplied by itself, gets you 27

chrome meteor
#

It can only be one number for both?

brisk totem
#

well, that's what the question says, isn't it?

anyone's number, added to their partner's number, gets you a square number

#

so, the student with number 18 is paired to someone, and their sum is a square number

chrome meteor
#

9*3

brisk totem
#

is 9 equal to 3?

chrome meteor
#

9*3=27

brisk totem
#

that's correct, but the a square number is something you get when you multiply a number by itself

chrome meteor
#

So you want me to solve 18 or 27?

brisk totem
#

i want you to find a number that when added to 18, gets you a square number

real grail
#

5*5 - 18 = 7

chrome meteor
#

Ohhhh

real grail
#

so 7 is what's you looking for

brisk totem
#

giving out the answer is not exactly the most helpful but i suppose it speeds things up

chrome meteor
#

Thanks to both

brisk totem
#

now you can do the next simple cases: who's the student with the number 17 paired with?

chrome meteor
#

It’s still going omg

#

8

brisk totem
#

your question asks how were the partner's assigned

which means there are 9 pairs of 2, so you have to find 9 pairs

#

so far we've gotten 2

#

and who's number 16 paired to?

chrome meteor
#

9

#

You there?

brisk totem
#

yes

and you can use the same reasoning to ask yourself how to make square numbers to deduce the rest

chrome meteor
#

So I just go down 2 each time for my subtracting number?

real grail
#

1- pick a perfect number (let's call it n)
2- pick a number below the perfect number (let's call it x)
3- the other pair is n - x

chrome meteor
#

Ok

real grail
#

the definition of a perfect square is a number multiply by himself

#

like :
1 *1 = 1
2*2 = 4
3*3 = 9
4*4 = 16
5*5 = 25
...
all those numbers are perfect squares

chrome meteor
#

Ok

#

All the perfect squares I got are 9,4,9

#

Is that right?

real grail
#

right but 16 and 25 should be considered

chrome meteor
#

How would I get that

real grail
#

since sum of two student will give you a perfect square

#

17+8 = 25

chrome meteor
#

15+1=16

real grail
#

for exemple

chrome meteor
#

Is that right

real grail
#

yeah

chrome meteor
#

And how do I write out the anwser

#

Because it says “how were the partners assigned”

chrome meteor
brisk totem
#

i guess something in the form of (18, 7), (17,8), ... would suffice

chrome meteor
#

Ok

#

Tysm you guys helped me so much

devout snowBOT
#

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modest condor
#

studying for a precalc test tmr j wanted an answer rq
in something like log(4x-4) would the transformation be like 1 or 2

modest condor
#

would like the +4 be part of the x or separate

devout snowBOT
#

@modest condor Has your question been resolved?

trim vine
#

I’ll assume you mean transformation between points on log(x) on points on log(4x-4)

You have to use the format where the coefficient of x is just 1, so you have to distribute out the 4 to get log(4(x-1)). This is the format u wanna look at. So looks like horizontally shifted right and then squished by 1/4

modest condor
#

ok fine pretend its 4x - 3

#

im just using sample numbers ik i can factor it out

#

i j wanna know if its 1 or 2

trim vine
#

What’s 1 or 2??

#

Oh

#

None of them

modest condor
#

what

#

whats the transformation then

trim vine
#

I think it’s (x+1)/4

modest condor
#

(x, y) becomes what

#

wait what

#

dude literally how

#

in what universe

trim vine
#

What, are choice 1 and 2 the textbook choices?

modest condor
#

its not textbook choices im tryna study

#

how the hell is it x+1

#

oh i see what ur doing

trim vine
#

Oh I meant x-1

modest condor
#

but i dont think

#

that works

trim vine
#

(X-1)/4

modest condor
#

because the signs flip when you apply the transformation

#

its originally x - 4

#

so it becomes x + 4

trim vine
#

Oh then x+1 lol

modest condor
#

ok ill try this
if you have log(ax + b) + c = y

#

does (x, y) become ((x - b)/a, y + c)

#

or

#

does it become

#

(x/a - b, y + c)

#

does that help you understand my question if i use variables so you cant evade answering by factoring it

trim vine
#

But u r supposed to use the variables that u get AFTER factoring it out

modest condor
#

not necessarily

#

it doesnt always work out like that in every problem

#

and they do that on purpose

#

which does it become

trim vine
#

Hmmm

#

X/4 - 1

arctic field
trim vine
#

Played around with t, and it works

arctic field
#

by how you've written it you would assume that it's a squish of 1/4 followed by a shift of 1

modest condor
arctic field
#

if you do it the other way round then you gotta shift by 4

trim vine
#

I think I’ve come up with a generalizable method

#

G(x_i) = f(a(x-b))
X_i = a(x-b)
X_i/a = x-b
X_i/a + b = x

#

Idk what steps of logic I did, but looks like something is right about it, can’t put my finger on it

woven radishBOT
trim vine
#

Yoooo this is awesome

modest condor
#

yooo

devout snowBOT
#

@modest condor Has your question been resolved?

#
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cyan stream
#

What is the use of convolution in terms of signal processing?

cyan stream
#

I am having trouble trying to understand how convolution would be used accurately to produce a result

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#

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placid wedge
#

If we write Sym({1,2,3,4}) - symmetries of a square, as ${e, r, r^2, r^3, k_1, k_2, k_3, k_4}$ where $r_i$ are rotations, and $k_i$ are reflections. Why is it that the permutation $(1 3 2 4)$ seems to not be a part of this group?

woven radishBOT
#

todadqa

placid wedge
#

I have that the group written as permutations is

#

${e, (1 2 3 4), (1 3)(2 4), (1 4 3 2), (1 4)(2 3), (2 4), (1 2)(3 4), (1 3)}$

woven radishBOT
#

todadqa

placid wedge
#

Corresponding to the symmetries written as $r_is$ and $k_is$

woven radishBOT
#

todadqa

placid wedge
#

but then where tf is (1 3 4 2) or for that matter ( 1 3 2 4)

#

Clearly sym(X) must be closed and yet i can construct the above two using members of Sym(X)

devout snowBOT
#

@placid wedge Has your question been resolved?

placid wedge
#

<@&286206848099549185>

arctic field
#

(1342) isnt a symmetry of a square

devout snowBOT
#

@placid wedge Has your question been resolved?

placid wedge
#

isn't it a permutation of points on the square

arctic field
#

you're telling me the symmetries of a square let you randomly permute the vertices around?

#

you want to just take one vertex and move it just anywhere regardless of the other two vertices it is neighbouring?

placid wedge
#

Ohhhhhh

#

It is no longer the same square?

#

but why then is it a product of symmetries? e.g. (1 4)(2 3)(1 2)

woven radishBOT
placid wedge
#

wait

#

it isnt

arctic field
#

you shouldnt be able to get (1342) using just the elements of your group

placid wedge
#

but in my given example

#

1 goes to 2, 2 goes to 3, 3 stays. (1 3 ...)
3 goes to 3, goes to 2, stays. (1 3 2 ...)
2 goes to 1, stays, goes to 4. (1 3 2 4)

devout snowBOT
#
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pliant wind
devout snowBOT
pliant wind
#

can someone explain

#

how you get from 1 to 2

#

why does 1/N cancel with N=i=1

fallen quiver
#

$\mu$ is constant. So the $\sum_{i=1}^N \mu = N\mu$

woven radishBOT
#

Reacquired

supple knot
pliant wind
#

errr

#

N?

#

I dont know

#

It should be n righ

#

n-1)+1 = n?

#

@supple knot

#

so 1/N x N = mu.. I understand now ig..

#

but I have another question

#

where does hte 1/N come from intuitively

#

we know sample mean is 1/N Sum of N Xi..

supple knot
#

What's the average of 2 and 4?

pliant wind
#

3

supple knot
pliant wind
#

2+4

#

/2

supple knot
pliant wind
#

is there not 2 numbers?

supple knot
pliant wind
#

errr.. hmm so

#

what we have is basically lets say we had 10 numbers

#

it would be 1/10 x 10 (for every sum ofxi)?

#

is that what we are gathering?

#

if so that makes sense, if not I have no idea ll

supple knot
pliant wind
#

ahh okay

#

I understand it now

#

thank you very much

#

is it okay if I ask some variance questions at sometime

#

in one of these channels

#

You explain it the best

#

<3.

#

Ty and take care

#

haahah quickly

#

where did hte N come from AAHHA

#

the 1/N^2?

#

@supple knot before you depart my good sir.

supple knot
pliant wind
#

got it!

#

superb

#

really superb

#

<3333.

devout snowBOT
#

@pliant wind Has your question been resolved?

devout snowBOT
#
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loud ingot
#

I know a, c, and e are subspaces of R^3, but what is R^3 and like how do i even find it out?

Is R^3 just because its (x, y, z)?

Also for (a) for example, how would i know its in R^3 using the theorem? I don't understand the theorem at all.

charred bolt
#

The theorem basically states that it has to be closed under addition and scaling to be a sub space

loud ingot
#

OHHHh i see

charred bolt
#

That is, when you add the vectors they must be in the space still

loud ingot
#

so it'd be like

[u, 0, 0] + [v, 0, 0]' = [u + v, 0, 0]'

charred bolt
#

Yes

loud ingot
#

and since that follows the [a, 0, 0] thing

#

it follows vector addition

#

and i do the same for scalar multiplication

charred bolt
#

Yes

loud ingot
#

but how do i know if its a subspace of R^3?

#

If those 2 hold?

charred bolt
#

Since those vectors are in your R^3 they just have to be held under addition and scaling to be a sub space

loud ingot
#

how do we know if its in my R^3 though

#

an ordered triple?

charred bolt
#

Yeah

loud ingot
#

so like (x, y, z)

#

so R^2 would be (x,y)?

charred bolt
#

Yes

#

Yes

loud ingot
#

Ohhh. Thank you so much! I have a lot better understanding now

#

.close

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#
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forest hound
devout snowBOT
forest hound
#

i know how to set it up i just need help finding a certain number

#

let me send what i have set up

#

in()
(divided by)
-0.00012

#

i can figure out what goes in for ()

#

nvm😭

#

.close