help-27

[woven radish]

nvx

[hasty tide]

should i first multiply -4 4 and -8

[patent tartan]

sure you can do that

[hasty tide]

288a=4 and then 4/288 right?

then a would be a=72

[patent tartan]

(-4)(4)(-8) = 128

$128a = 4$

[hasty tide]

oh

[woven radish]

nvx

[hasty tide]

i did something wrong

a=1/32

[patent tartan]

right

,w plot (1/32)(x-4)(x+4)(x-8)

[woven radish]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Navix#0001

[hasty tide]

yea this works but now i have a issue with it

[patent tartan]

yes?

[hasty tide]

maybe i didnt mention it but it should be "easier" for people who want to turn right and with this one its a bit harder to turn right

green is from the first task where it was -1/8x^2+2

[patent tartan]

wdym by easier to turn right

thats why i asked if there were any restrictions

[hasty tide]

so the original streets are straight lines and the task was to 2 new streets i already did the first one its the green in this picture now i need to make another one which is without a bending jerk

[hasty tide]

yea my bad, soryy

[patent tartan]

so you want an extremal point to be at x=0

then you probably cant use a cubic function as its not symmetric around x=0

(or any other odd function)

[hasty tide]

would f(x)=ax^5+bx^4+cx^3+dx^2+ex+f work?

[patent tartan]

try it

[devout snow]

@hasty tide Has your question been resolved?

Channel closed

Closed by @hasty tide

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[covert thistle]

I don't understand this solution to show that the function is one-to-one

[covert thistle]

It seems like circular logic to me

[crystal rune]

A function is one-to-one iff f(x_1) = f(x_2) implies x_1 = x_2

[covert thistle]

Yes I know that definition but I don't understand how it's used

[crystal rune]

Well we first assume that g(x_1) = g(x_2) and work with that

and if we get x_1 = x_2, then that means g is injective

[covert thistle]

Yes but doesn't that only work to check the x axis?

[bright burrow]

You can also do this with a graph with a horizontal line test, since this graph is rather easy to draw

[covert thistle]

I know that, I just like to try to understand the explanations in the book

But what I wonder is why they don't just differentiate the function and see that that function is positive for all x

[bright burrow]

If x1 was not x2 then that would mean two different inputs which provide the same output, so not one one

[covert thistle]

But how does this prove that one input can't give 2 outputs?

[bright burrow]

Its a function, one input can never give 2 outputs

[covert thistle]

Ah, I must've missed that part

That explains it, thanks

.close

[devout snow]

Channel closed

Closed by @covert thistle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[formal pecan]

Just to confirm, when are we not allowed to use the Cauchy's integral formula to evaluate an integral?

[arctic field]

when the hypotheses of cauchy's integral formula dont hold

[midnight dirge]

WOW

for some holomorphic f

[sand dove]

All you have to do is to realise that -i is in the "inside" of Gamma

[wintry zodiac]

What is the fomula of square

[sand dove]

#❓how-to-get-help

[midnight dirge]

👽

[wintry zodiac]

Please tell

[formal pecan]

Thank you guys

[midnight dirge]

wait actually

[formal pecan]

.close

[devout snow]

Channel closed

Closed by @formal pecan

Use .reopen if this was a mistake.

[midnight dirge]

this is giving me ban bait vibes

[midnight dirge]

💕

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fickle schooner]

I need help with o'level mathematics is there any who wants to help me

[sonic smelt]

Don't ask to ask, just post the question right away

[devout snow]

@fickle schooner Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[slow fable]

going through my lecture slides

these were the only two i didn't have an answer in mind

[midnight dirge]

i think

the first is null

its saying

x and ~x

which is never

or

{}

[slow fable]

ah okay, makes sense.

[spare zealot]

"Cardinality" is just the number of elements in a set

[slow fable]

is null also the empty set?

[spare zealot]

So the cardinality of the set S = {1, 2, 3, B, H} is 5

Yes

$\emptyset = {}$

[woven radish]

lexitorius

[spare zealot]

That didn't work lol but you get the picture

[midnight dirge]

$\emptyset = {}$

[midnight dirge]

magic

[spare zealot]

You're built different

[midnight dirge]

yes

[spare zealot]

But yeah your cardinality is just the number of elements in a set

[midnight dirge]

aleph?

[slow fable]

so basically, since there does not exist an element that is p(x) and (not) p(x) . S belongs to the special set of null?

[midnight dirge]

aleph 1?

[midnight dirge]

i gues

[spare zealot]

Yeah $|\mathbb{R}| = \aleph_1$

[woven radish]

lexitorius

[slow fable]

just trying to make sure I understand it correctly by typing it out

[midnight dirge]

omg i guessed right

i havent learnt this but yay

[slow fable]

What's aleph_1? it was only written down in the slides, not expanded upon

[spare zealot]

It's basically a number denoting a type of infinity

I wouldn't be great at explaining it because I haven't worked with it much

[slow fable]

ah okay. just gotta know that the cardinality of R is aleph huh.

[midnight dirge]

smallest uncountable

no

aleph 1

aleph 0 is countable

countable inf

[slow fable]

and |N| is aleph_0?

[midnight dirge]

like natural numbers

yes

or rational numbers

[spare zealot]

Basically $\aleph_0$ or "Aleph-Null" is countable infinity

Yup

[woven radish]

lexitorius

[midnight dirge]

if i guess correctly~

hahaha

[slow fable]

thanks! I'll keep these in mind

[spare zealot]

And $\aleph_1$ or Aleph 1 is uncountable

[woven radish]

lexitorius

[spare zealot]

And then you can keep going into stuff I don't understand lol

[midnight dirge]

both r infinities tho

lol

[spare zealot]

Yeah

[slow fable]

appreciate it friends

.close

[devout snow]

Channel closed

Closed by @slow fable

Use .reopen if this was a mistake.

[midnight dirge]

np

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[valid axle]

why do we need more than base cases when doing strong induction

[valid axle]

?

How do I know the thing im trying to prove needs 1 base case or 2 cases or even 3 and more?

[prime egret]

Pretty sure base case is the same as normal induction

Just the assumption that it is true for all k_0<=i<=k

[valid axle]

I think depending on the complexity of the statement you will need to show that the the statement works for more than one cases when it comes to strong induction according to my professor and book.

But the problem Im having is how do I know i need more than one case? Because when I solve a question and then check the answers they have used multiple base cases and the only explanation they give is

"There are 2 base cases that needs to be tested"

[stone stump]

if you for example prove a formula for some recursive expression, then you need to apply the IH for lets say k-1 and k-2

now what if k is 2 for example

then you need to be able to apply the IH for both k=1 and k=0

so you have to show them both somehow

but you can't use the induction step for k=1 cause for k=1 the recursive formula doesn't even work

so you also need to show the base case k=1 separately

[devout snow]

@valid axle Has your question been resolved?

[stone stump]

dont just say no to the bot

say what you are still struggling with

[devout snow]

@valid axle Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lean crag]

find the relationship between a and b

i factored n out and got sqrt(n)(a+b+1)

and i think it is obvious that a+b+1=0

but isn t that infinity times 0 in the limit?

and it is undefined

i just need this clarification

[devout snow]

@lean crag Has your question been resolved?

[lean crag]

.close

[devout snow]

Channel closed

Closed by @lean crag

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[thin gulch]

ugh

[thin gulch]

i need help

with 2 things

in the windows folder where is my pic

how do i do the first one?

[tall knoll]

Use the pythagorean theorem

[thin gulch]

idk how

[tall knoll]

Do you know what it is?

[thin gulch]

its like c squared and a squared and b squared

[tall knoll]

It involves those, but you need to be more specific

There's an equation involving those 3 terms that you need to know

[thin gulch]

idk]

[tall knoll]

Then you need to look in your notes again

All of these questions are just plugging numbers into that 1 equation

So you really need to know it

[thin gulch]

ik square roots and squared numbers

i dont know where a and b are?

[ornate cloud]

A & b are the lines that who are 90° to each other

[thin gulch]

b is the 15 one?

[ornate cloud]

Sure

[thin gulch]

ok now what

[ornate cloud]

Which makes a..

[thin gulch]

a is the 8 cm its a squared

[ornate cloud]

Yeah

And if you put a and b in the formula

[thin gulch]

idk the formula

[tall knoll]

I've given you the name

If you can't find it, look it up

[thin gulch]

ong my memory is bad

ok thanks

.close

[devout snow]

Channel closed

Closed by @thin gulch

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[shy hearth]

I am confused on how to plug in the numb r

[modern vigil]

Just substitute the x in the equation with the x in the column

And find y

[small plover]

good evening

any tips how to be good at maths?

[supple knot]

,rotate

[shy hearth]

Well when I do my answer is always wrong

So I don’t know if I am doing the fractions wrong

[winter patrol]

show work

[winter patrol]

firstly you're missing the
$$\red{-}\frac x2 +2$$

[woven radish]

ℝamonov

[shy hearth]

Oh so it would be 3

[winter patrol]

no

would you be able to simplify just
x/2 when x= -2?

[whole wraith]

Dont u just replace the x with the numbers given?

[winter patrol]

you didn't copy down the correct thing

[shy hearth]

Wait would it be a positive 4??

[winter patrol]

no

[woven radish]

Ken_

[winter patrol]

if you're having difficulty don't skip ahead and try to follow my breakdown of the problem

if it was just
x/2, what would be the value of that when
x= -2?

[shy hearth]

3?

[winter patrol]

are you skipping ahead again?

[shy hearth]

I forgot how to do fractions kinda and I have a test about this tmrw

[winter patrol]

are you ignoring my questions?

[shy hearth]

Well wouldn’t you cross cancel or

[winter patrol]

are you ignoring my questions?

[shy hearth]

I don’t see the question?

I only see you went you typed the Ken_

[shy hearth]

This

So I am confused what you mean -

[winter patrol]

if it was just
x/2, what would be the value of that when
x= -2?

I asked that twice

[shy hearth]

Oh I didn’t see that

Well if it was x/2 then it would jsut be 1 if that’s what you mean

[whole wraith]

thats still wrong

[shy hearth]

So if it was -2 then it would be 3

[winter patrol]

are you skipping ahead again?

If it wasn't clear I was asking about the expression x/2 only, and was trying to heavily break down the problem

but subbing in x=-2 properly will get you
y = 3 if that's what you mean by saying 3

[woven radish]

Ken_

[whole wraith]

all u need to do is replace the x with the given numbers

[shy hearth]

So it’s 3

[whole wraith]

yes now u solved the -2 one?

do u want to go to the 0 one

[shy hearth]

No I am fine

[whole wraith]

ok

[shy hearth]

I don’t get what I did wrong with this

I said 3 earlier so

[whole wraith]

its because he asked u whats -2/2

and its -1

[shy hearth]

Yeah

Ok Nvm I’ll just start studying now thx

[whole wraith]

its -1 ok

[devout snow]

@shy hearth Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[magic oyster]

hello, how would I solve the trigonometrical equation z=2cis(pi/6) to the algebrical form

[supple knot]

,rotate

[magic oyster]

Ty

I have to Guess b for |z3*z4|=20

I simplifyed z3 to 2cos(-Pi/6)

And 2sen(-Pi/6)

And got z3=1.732-i

ohhh

✓3 is 1.732

[devout snow]

@magic oyster Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[glass bison]

how do I solve this problem:

[glass bison]

implicit derivatives

I still somehow struggle so badly on implicit derivatives

[spare zealot]

Here's an idea that might help conceptualize implicit diff

You know the chain rule?

[glass bison]

yeah f'(g(x)) * g'(x)

[spare zealot]

And how it's used when you're differentiating a function that has something other than x inside of it

You can sorta think of the variable y as a function of x

So if you want to find the derivative of y^3 with respect to x, you have to hit it with a "fake" chain rule, which is implicit differentiation

In doing so, you would generate 3y^2 as your "f'(g(x))"

And then dy/dx as your "g'(x)"

Since we don't actually know what the derivative of y itself is here, we just call it "dy/dx"

[wooden wraith]

you mean g'(x)

[spare zealot]

Correct, thanks

[wooden wraith]

Not even a fake chain rule really. That's actually exactly why implicit differentiation works

[spare zealot]

^

[wooden wraith]

It just is the chain rule

[spare zealot]

I just feel like that connection is usually drawn implicitly (lol) when it's taught

I was never explicitly told it was just a chain rule so I had to figure that part out myself lol

[glass bison]

what do we do with the 2x?

[spare zealot]

Find its derivative just like we would 2x in any other situation

Of course, we'd append our y drama to it

At least iirc

Unless I'm horribly mistaken

[wooden wraith]

Oh wait no, sorry, that isn't right

You'd use the product rule

[spare zealot]

I forgot if product rule applies or not

OKay cool my mistake

[wooden wraith]

It does, it's a product of 2x and y^3

[spare zealot]

We would evaluate the product rule $\frac{d}{dx}f(x)g(x)$ where $f(x) = 2x$ and $g(x) = y^3$

[woven radish]

lexitorius

[wooden wraith]

Right, and then utilize the chain rule like you said

[spare zealot]

Cool thanks I haven't done it in a while lol

[wooden wraith]

All good

Sorry, I'm about to be working so I can't help anymore but I think y'all got it

[spare zealot]

Yeah if they have more questions about it I should be good now

Thanks

[glass bison]

ok

so the first side would be 2(3y^2)?

[spare zealot]

Close

The first term would become 2(3y^2)(dy/dx)

Then you'll want to also do the same to the other terms

So take the derivatives of xy and 15

[glass bison]

x+y?

and 15 would be 0 right?

[spare zealot]

So when we take the derivative of y, we're hitting it with a chain rule too

So $\frac{d}{dx} xy = x * \frac{dy}{dx} + 1 * y$

[woven radish]

lexitorius

[spare zealot]

Where 1 is the derivative of x, and dy/dx is the derivative of y

[glass bison]

huh

isn't this the product rule?

[spare zealot]

Yeah, because xy is a product

The chain rule just comes up when we take the derivative of y

Since we're doing it in terms of x, we're doing a chain rule on the variable y itself

#help-27 message

That's where I showed that idea for the first term

Essentially any time we differentiate a y variable when we're working with respect to x, we need to multiply our answer by dy/dx

So d/dx y = 1 * dy/dx

[glass bison]

ok

[spare zealot]

<@&268886789983436800> - thanks

[glass bison]

So should it look something like this?

[spare zealot]

Yup

Then all of that is equal to d/dx of 15, which is 0

Then if you solve for dy/dx (like you might solve for y or x in algebra), you'll get a solution for what dy/dx is

[glass bison]

so how do I move all of this

like which one goes first?

[spare zealot]

You'll want to get everything that's not dy/dx on one side, and everything else on the other

I'd start by subtracting y from both sides

[glass bison]

Like this?

[spare zealot]

Yup

Now what can you do to separate y' from everything else on the left side?

[glass bison]

divide from both sides?

[spare zealot]

Close, let's employ the distributive property

Recall that $(ab + ac) = a(b + c)$

[woven radish]

lexitorius

[spare zealot]

Perhaps that will help

[glass bison]

Like this?

[spare zealot]

Exactly

Now you could divide both sides by (2(3y^2)+x) to get y' on its own

[glass bison]

should I have included the 1 in the problem?

[spare zealot]

The numbers multiplied by 1?

You don't need to really show the 1

Since 1 * y is just y

[glass bison]

hmm ok

because now my answer is completely different from the actual answer which is supposed to be this:

[spare zealot]

Wolfram isn't working with me so I'm not sure what ahppened

[devout snow]

@glass bison Has your question been resolved?

[glass bison]

.close

[devout snow]

Channel closed

Closed by @glass bison

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[restive river]

\

[left robin]

let width be x meters
then length is x+2 meters

area=width*length

A=x*(x+2)=x^2+2x

assume A=20 m^2

A=x^2+2x
20=x^2+2x
x^2+2x-20=0

from here on use a formula or complete the square

[restive river]

how do u solve

from that

i got

that

but idk how to do complete the square

like i got the x^2+2x-20=0

like

[left robin]

never done it before?

[restive river]

wont

there be

2 x

2 dif x vals

[left robin]

yes

[restive river]

nah ive done it

but like when i get 2 x vals

what one do i use

for like

the final

[left robin]

notice that x is a length

[winter patrol]

the one that makes sense in the context of the problem

[left robin]

negative lengths dont make too much sense

[restive river]

lmao okok thx

but like

if there was

no neg one

how would u do it

[winter patrol]

if somehow both values are valid, then they'll both be solutions

[devout snow]

@restive river Has your question been resolved?

[restive river]

wait

i got 5.36

what did i do wrong

.close

[devout snow]

Channel closed

Closed by @shrewd patio

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dire thunder]

@drifting torrent

<@&286206848099549185>

[proper drum]

What’s the problem?

[proper drum]

Is the triangle on the right the exact same but smaller?

[dire thunder]

No

[proper drum]

Alright I’m not seeing any indication of a right angle

[dire thunder]

Yes

[proper drum]

Does it ask you the question?

Or is it just the picture

Do they both have a the same angle?

Ask yourself what do you know about the 2 triangles

[devout snow]

@dire thunder Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[copper relic]

I’m a bit stuck at the end

[prime egret]

,w solve x^3 -13x^2 +53x-69=0

[woven radish]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Pure#9389

[prime egret]

$(-10)^2 \neq -100$

[woven radish]

Pure

[copper relic]

Ok thanks I understand

Close

[prime egret]

.close

[devout snow]

Channel closed

Closed by @prime egret

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[coral wolf]

Ill attach screenshots but the basic premise is:
there are three graphs that show the height of water in a bathtub over some time and you have to match the graph

graph a is a constant line going diagonally
graph b is a constant line straight right
graph c is a line that goes diagonally then straight then diagonally

option A = the bathtub is 3/4ths full
option B = the hot water is accidentally put in the bath so the tap is turned off to let the water cool before letting cool water into the bath
option C = the bath is filled to a steady rate

It thought the answer to this question is
a = C
b = A
c = B

however the textbook disagrees so now im confused.
Any welp would be nice, thank you

[rotund heron]

Your answer seems correct to me??

[coral wolf]

THATS WHAT IM SAYIN'

[rotund heron]

The answer key is probably wrong then

[coral wolf]

idk-

i feel like textbooks shouldnt make mistakes like that

oh okay then, dyk where i went wrong then? i am confused

[winter patrol]

you mixed up your lower case and upper case

[coral wolf]

heh?

theres no way graph a describes B though??

wait no i see what you mean-

but the question uses lowercase? so shouldnt teh answers be in capital??

[rotund heron]

The pic is the book solution

[rotund heron]

Right?

[winter patrol]

wait

[coral wolf]

no they are right but the book mixed up the capitals

i think

[winter patrol]

they're the ones that mixed them up

[coral wolf]

oh thank god i thought i was stupid

[rotund heron]

Yay

[coral wolf]

thanks that was a bit of a stress moment for me ngl

i just write .close now right?

mkayy thank you for your helppp

.close

[devout snow]

Channel closed

Closed by @coral wolf

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[spark ledge]

how would you go about solving this

[prime egret]

Well consider y=1/(1-x)

then consider y’

[spark ledge]

wdym y=1/1-x

[prime egret]

$y=\frac{1}{1-x}$

[woven radish]

Pure

[spark ledge]

how does that relate to the question though

im a little confused

[prime egret]

What’s $(1-x)^{-1}$

Using binomial theorem

[woven radish]

Pure

[spark ledge]

1/1-x

[prime egret]

.

Fine

Let’s do it another way

Call $S_{\infty}=1+2x+3x^2+…}$

[woven radish]

Pure
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

Pure

Pure

[spark ledge]

ok?

[prime egret]

Have you done it?

[spark ledge]

like the question?

[prime egret]

This

[spark ledge]

im not sure what it means

do you want me to get the formulas

and then just plug in the values

[prime egret]

$S_{\infty}=1+2x+3x^2+…$

[woven radish]

Pure

[prime egret]

The sum that we want

[spark ledge]

1/1-x + x/1-x ??

[prime egret]

$xS_{\infty}=x(1+2x+3x^2+…)$

[woven radish]

Pure

[prime egret]

$xS_{\infty}=x+2x^2+3x^3+…$

Now consider S_infty - xS_infty

[woven radish]

Pure

[prime egret]

$S_{\infty} - xS_{\infty} = (1+2x+3x^2 +4x^3+…) - (x+2x^2+3x^3+…)$

[woven radish]

Pure

[spark ledge]

oh

would it be smth like

1/1-x - x/1-x - 1/1-x^2 -...

[prime egret]

How did you get that

[spark ledge]

kind of guessed

im not rlly sure what you want me to do here

[prime egret]

I want you to compute this sum

$(1+2x+3x^2 +4x^3+…) - (x+2x^2+3x^3+…)$

What is this

[woven radish]

Pure

[spark ledge]

1+x+x^2+x^3+...

[prime egret]

Yes

And what is that

$1+x+x^2+x^3+...$

[woven radish]

Pure

[prime egret]

Is a certain type of series

[spark ledge]

geometric progression

[prime egret]

Yes

So $1+x+x^2+x^3+... = \frac{a}{1-r} = \frac{1}{1-x}$

[woven radish]

Pure

[spark ledge]

yup

[prime egret]

$S_{\infty} - xS_{\infty} =\frac{1}{1-x}$

[woven radish]

Pure

[prime egret]

Solve for S_inf

[spark ledge]

$S{\infty} =\frac{1}{1-x}+xS{\infty}$

[woven radish]

rarzzzzzz

[spark ledge]

this?

[prime egret]

No

$S_{\infty}(1 - x)=\frac{1}{1-x}$

This

[woven radish]

Pure

[spark ledge]

y is it that

[prime egret]

S_inf is a common factor

[spark ledge]

oh shit

im so dumb

the u just divide it

[prime egret]

Ye

[spark ledge]

lol

tysm

life saver

[prime egret]

Np

[spark ledge]

doryr for being a bit slow

[prime egret]

No worries

[spark ledge]

.close

[devout snow]

Channel closed

Closed by @spark ledge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[severe merlin]

You must show by calculation that the students can brew coffee for about 40 disposable mugs from 500 g coffee beans

[severe merlin]

You must show by calculation that the students can brew coffee for about 40 cups from 500 g coffee beans

[umbral raft]

Have you tried anything yet?

[severe merlin]

this question have i think about whole time

[umbral raft]

Have you tried anything yet?

[severe merlin]

yes i did

[umbral raft]

Any result?

[severe merlin]

that's what i've been trying to do but my brain can't figure it out so i need help

[umbral raft]

Incomplete question

[severe merlin]

oh wait

[severe merlin]

what do you mean

[umbral raft]

I mean the question is incomplete

Is there anything else or any other info relevant to the question?

[severe merlin]

yes

You need about 60 g of coffee beans to brew 1 L of coffee

[umbral raft]

Its the same as the other question I helped ya with

Apply the same logic

[severe merlin]

my brainn

[umbral raft]

Its a basic question come on think!

[severe merlin]

ahhh 40/500

[umbral raft]

Also do you mean 1 cup of coffee?

or 1L?

[severe merlin]

1l

no

[umbral raft]

then this must be 40L is it?

[severe merlin]

You must show by calculation that the students can brew coffee for about 40 disposable mugs from 500 g of coffee beans.

[umbral raft]

huh

[severe merlin]

i do not know how to do it

[umbral raft]

Think

[severe merlin]

my brain its holiday for me

[umbral raft]

If you can formulate a meaningful sentence then you can solve that question

But if you aren't willing to put any effort then neither am I

[severe merlin]

i tried so 60g beans for 1 liter so 60/500

[umbral raft]

How

Better question: why?

why would it be 60/500

[severe merlin]

because I'm thinking there's 60g for 1 litre and there's 500g of coffee beans so I'm thinking divide it by that so it gives a result

[umbral raft]

Yes

that is, 500/60

[severe merlin]

so it will be 8.3

so 8.3*40?

[umbral raft]

What is the question asking

[severe merlin]

You must show by calculation that the students can brew coffee for about 40 disposable mugs of 500 g coffee beans

[umbral raft]

And what was the other info

[severe merlin]

Students will sell the coffee in disposable mugs, each holding 0.2 L of coffee.

You need about 60 g of coffee beans to brew 1 L of coffee

[umbral raft]

🧍‍♀️ wait what

Did you just mix the two questions

or was it one all this time

[severe merlin]

these two i just send you is info

You need to show with calculation that the students can brew coffee for about 40 disposable mugs from 500 g coffee beans. this one is the question

[umbral raft]

thats too much coffee
I'll start over

[severe merlin]

ok

fine i just skip this question

[devout snow]

@severe merlin Has your question been resolved?

Channel closed

Closed by @severe merlin

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[crude nova]

𝐋𝐞𝐨𝐧𝐚𝐫𝐝𝐨 𝐭𝐡𝐞 𝐏𝐞𝐚𝐬𝐚𝐧𝐭 𝐢𝐬 𝐚 𝐜𝐥𝐞𝐯𝐞𝐫 𝐭𝐡𝐢𝐞𝐟, 𝐡𝐞 𝐬𝐭𝐞𝐚𝐥𝐬 𝐟𝐫𝐨𝐦 𝐭𝐡𝐞 𝐡𝐮𝐠𝐞 𝐬𝐚𝐟𝐞 𝐨𝐟 𝐭𝐡𝐞 𝐊𝐢𝐧𝐠 𝐢𝐧𝐢𝐭𝐢𝐚𝐥𝐥𝐲 𝐜𝐨𝐧𝐭𝐚𝐢𝐧𝐢𝐧𝐠 𝟓𝟎% 𝐠𝐨𝐥𝐝 𝐜𝐨𝐢𝐧𝐬 𝐚𝐧𝐝 𝟓𝟎% 𝐬𝐢𝐥𝐯𝐞𝐫 𝐜𝐨𝐢𝐧𝐬. 𝐎𝐧 𝐃𝐚𝐲 𝟏, 𝐡𝐞 𝐬𝐭𝐞𝐚𝐥𝐬 𝟏𝟎 𝐠𝐨𝐥𝐝 𝐜𝐨𝐢𝐧𝐬, 𝐚𝐧𝐝 𝐫𝐞𝐩𝐥𝐚𝐜𝐞𝐬 𝐢𝐭 𝐰𝐢𝐭𝐡 𝟏𝟎 𝐬𝐢𝐥𝐯𝐞𝐫 𝐜𝐨𝐢𝐧𝐬. 𝐇𝐞 𝐝𝐨𝐞𝐬 𝐭𝐡𝐞 𝐬𝐚𝐦𝐞 𝐨𝐧 𝐭𝐡𝐞 𝐬𝐮𝐜𝐜𝐞𝐞𝐝𝐢𝐧𝐠 𝐝𝐚𝐲𝐬, 𝐛𝐮𝐭 𝐢𝐧𝐜𝐫𝐞𝐚𝐬𝐢𝐧𝐠 𝐛𝐲 𝐚 𝐦𝐮𝐥𝐭𝐢𝐩𝐥𝐞 𝐨𝐟 𝟏𝟎. 𝐓𝐡𝐞 𝐬𝐚𝐟𝐞 𝐜𝐨𝐧𝐭𝐚𝐢𝐧𝐬 𝟏𝟔𝟓,𝟎𝟎𝟎 𝐜𝐨𝐢𝐧𝐬 𝐢𝐧 𝐭𝐨𝐭𝐚𝐥. 𝐈𝐟 𝐨𝐧 𝐃𝐚𝐲 𝐧, 𝐭𝐡𝐞 𝐬𝐚𝐟𝐞 𝐢𝐬 𝟐𝟓% 𝐠𝐨𝐥𝐝 𝐜𝐨𝐢𝐧𝐬 𝐚𝐧𝐝 𝟕𝟓% 𝐬𝐢𝐥𝐯𝐞𝐫 𝐜𝐨𝐢𝐧𝐬, 𝐟𝐢𝐧𝐝 𝐧.

[devout snow]

@crude nova Has your question been resolved?

[devout snow]

@crude nova Has your question been resolved?

[devout snow]

@crude nova Has your question been resolved?

[unreal saffron]

what is like ur question

[devout snow]

@crude nova Has your question been resolved?

[rotund heron]

find n

what have you tried?

@crude nova

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[restive river]

I have this shape, it's given that AB | | DC, EF | | DC, AB = 6cm, DC=12cm and AE = 2DE

I gotta calculate EF's length

[gleaming socket]

,rccw

[restive river]

apart from the basic stuff : AB | | EF | | DC, and marking ED as X and AE as 2X, I am not sure how to continue from here

[gleaming socket]

similar shapes?

[restive river]

didnt learn to use similar shapes with such a shape

only with triangles

[gleaming socket]

what is the property of a similar triangle

[restive river]

wdym property? I am just not a native english speaker

[gleaming socket]

well how do you know if two triangles are similar?

[restive river]

if they have 2 pairs of identical angles

[gleaming socket]

Angle AEF anf ADC are the same right?

[restive river]

yeah

[gleaming socket]

so are all the other three angles in both ABEF and EFDC are same

so ABEF is similar to EFDC

[restive river]

yeah

[gleaming socket]

when two shapes are similar the ratio between there corresponding sides is constant

from AE = 2DE we can find the ratio

[restive river]

yeah, the ratio should be 1:2 , but it doesnt seem to add up based on the answers that are included in the book we got(it should be 10cm, gives me 8cm)

[devout snow]

@restive river Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fiery elbow]

I need help solving this equation

[fiery elbow]

I’m stuck on dividing the derivatives

Also the (n k)

I’m new to derivatives

I only used [] instead of () to make it easier to tell derivatives from other things.

<@&286206848099549185>

.close

[devout snow]

Channel closed

Closed by @fiery elbow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[loud ember]

Is this correct ?

[devout snow]

@loud ember Has your question been resolved?

[devout snow]

@loud ember Has your question been resolved?

Channel closed

Closed by @loud ember

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[devout snow]

@high chasm Has your question been resolved?

[devout snow]

Channel closed

Closed due to the original message being deleted

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[onyx wind]

.open

.reopen

[velvet fractal]

Anyone know how to do this?

[devout snow]

@velvet fractal Has your question been resolved?

Channel closed

Closed by @velvet fractal

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[trail cloud]

My question is on #47: Solve |x-3| ^2 -4|x-3| = 12. I found -3 by setting |x-3|^2 = 0. How do I find the other root?

[gleaming socket]

,rccw

[gleaming socket]

Why did you set it equation to zero?

[vivid cliff]

aye aye

wassup

so

eh

hm

why did u

set

|x-3| to 0?

the qn

gave u a clue

let |x-3| be u

[trail cloud]

Sorry, I got busy, let me check my work

[vivid cliff]

yeye

npnp

take ur time

[trail cloud]

I didn't really have any reasoning behind it, I just tried it. Would setting x-3 to u and putting it into the quadratic formula give me the values for x?

I tried that, and it didn't work if I remember

[vivid cliff]

yeye

it should work

just try

cuz now u have

$|x-3|^2 -4|x-3| = 12$

[woven radish]

Springsskateboard

[vivid cliff]

move the 12 over

to the left side

$|x-3|^2 -4|x-3| -12 =0$

[woven radish]

Springsskateboard

[vivid cliff]

replace

|x-3| with u

$u^2 -4u-12=0$

[woven radish]

Springsskateboard

[vivid cliff]

now

u can either factorise

or

use formula

to solve

for u

and after u solved for u

that’s not

the final ans

cuz remember

what u allowed u to be

[trail cloud]

Add three to the answers?

[vivid cliff]

wdym

alr first

solve the quadratic

and tell me

what x u got

yeye

take ur time

[trail cloud]

I got x = 6, and x = -2

[vivid cliff]

no

u didn’t get x= 6 x=-2

you got u=6 u=-2

yeye

needa remember that

ye

alr so

you got the u values

remember what

u let u be?

we allowed u to be

|x-3|

so

$$u=6$$ OR $$u=-2$$

$$|x-3| = 6$$ OR $$|x-3|=-2$$

[woven radish]

Springsskateboard

[trail cloud]

So x = 9 and 1?

[vivid cliff]

$x-3 = 6$ or $x-3 = -6$

[woven radish]

Springsskateboard

[vivid cliff]

we have to

reject

$|x-3| = -2$

[woven radish]

Springsskateboard

[vivid cliff]

yeye cuz it’s

absolute

and can’t be negative

[vivid cliff]

so this is what we get

solve this

and 2 x values

will be ur ans

[trail cloud]

Ok, so 9 and -3

Thanks

[vivid cliff]

aye aye

npnp

[devout snow]

@trail cloud Has your question been resolved?

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[burnt quail]

Can anyone tell me where I've gone wrong? Book has a different answer

[hollow pollen]

no + C

• C cancels itself out

[prime egret]

Can’t cancel (2x+5) and 1/2x like that

[burnt quail]

Oh, I see what you mean with the +c

[hollow pollen]

but yeah you did the integral wrong also

[burnt quail]

Would I need to have a separate integral with 5/x^2+5 then?

[hollow pollen]

you need to use arctan

[hollow pollen]

yes

[burnt quail]

Oh I see, and that turns into like 5arctan or something

Ok cool

Thanks guys!

[hollow pollen]

sqrt(5) arctan

sqrt(5) arctan(x/sqrt(5))

[burnt quail]

Wait why sqrt5

[hollow pollen]

perhaps watch a video on arctan integrals

its a better explanation than i can give here

[burnt quail]

Alright, will do. Thanks again!

.close

[devout snow]

Channel closed

Closed by @burnt quail

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rare roost]

I need help understanding my teachers solution to this LDU factorization problem.

[rare roost]

Am I crazy, or is his solution not majorly wrong?

While I'm here, let me make sure I understand how its supposed to work.

1. Reduce the matrix to REF to create the upper matrix
   1a) Keep track of the row operations performed
2. Perform the opposing operations (addition becomes subtraction, vice versa) in the opposing order on the identity matrix to create the lower matrix
3. Divide reach row in the upper matrix by its leading coefficient. Those coefficients becomes the entires in the corresponding positions in the diagonal matrix

[devout snow]

@rare roost Has your question been resolved?

[devout snow]

@rare roost Has your question been resolved?

[rare roost]

Anyone have any thoughts?

[devout snow]

@rare roost Has your question been resolved?

Channel closed

Closed by @rare roost

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[restive river]

Just checking for understanding on this one:
Suppose $f:\mathbb{R}\to\mathbb{R}$ and $\lim_{h\to 0}[f(a+h)-f(a-0)]=0$. Is $f$ necessarily continuous at $a$?

[woven radish]

ESAllhands

[restive river]

I think it isnt necessarily continuous since this is just stating that the limit exists and doesnt say anything about the value of f(a) (removable discontinuity could exists)

[uncut crow]

try drawing an example with a discontinuous function

[restive river]

I did

[uncut crow]

what did you find?

[pseudo basin]

when you write f(a-0) is that meant to be read as f(a) or as a stupid notation for the left hand limit of f at a

[restive river]

oh - its probably obvious but that should have been an h and not a 0

[pseudo basin]

oh

[restive river]

yeah sorry

should be f(a+h)-f(a-h)=0

What I found was that if we take h to be zero its continuous. Otherwise we're just looking at the function value from the left and right at a point. If its a constant function then its continuous and the statement seems fine.

I just dont know if I think that means it's necessarily continuous

[uncut crow]

I might have a counterexample

f(x) = |x| + 1 for x not 0, f(0) = 0

with a = 0

[restive river]

right - this is similar to what I was thinking

[uncut crow]

f(a+h) = f(a-h) for all h

[restive river]

except, I hadnt considered the abs value so I wasnt coming up with a way for the difference to be 0

I like this

The best I had come up with was just to try to do something like a constant function with a removable discontinuity at a--but, that seemed too contrived

a removable discontinuity assigned* at a

[pseudo basin]

1/x^2 for x not 0, whatever you want for x=0

[restive river]

I like that one too

So, I was on the right track, just a little lost. Thanks for the help! I will likely be back here in a bit 😄

.close

[devout snow]

Channel closed

Closed by @lost sphinx

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[slow fable]

for the second one

would it be my boxed answer?

if not , can someone explain the correct answer?

[terse stone]

why do you think it's the right answer?

if you don't know, why did you choose it?

it's the correct answer btw

just curious what your thought process is

[slow fable]

Well, A - B cannot be the same as B - A. Pretty sure this is in the context of sets. Not sure what I could plug into these to prove by example. but no matter what values/sets A or B are, if you subtract them in whichever order, you results of each order will be different. So A and B must be empty sets to produce the same result to fit that statement.

Please do enlighten me on the mathematical reasoning. This was somewhat just me trying to use "common sense", a shot in the dark answer.

[terse stone]

ok

no, it's totally possible A - B = B - A

even if A and B are not empty sets

first of all, I was wrong. there are two correct answers

if A=B, then A-B=B-A

so, in set theory, A-B means removing anything that exists in B from A

for example, if A={2,3,4} and B={3,4,5}

A-B={2}

make sense?

[slow fable]

Yes, I understand so far.

[terse stone]

so, yeah the correct answer is A=B

[terse stone]

this is wrong

when A⋂B=empty set, A-B=A, B-A=B

make sense?

[slow fable]

Ah, okay. using the example you provided. I understand how it's A=B now.

thank you!

[terse stone]

yeah, so the answer you thought was correct answer for II, is actually the answer to III

[slow fable]

can you explain #3?

Can I use the same example you provided for that as well

or is there a different approach?

[terse stone]

as I said if A-B=A, it means there's nothing in B that exists in A, so A minus B is still A

that means A and B have no overlap

pretty simple

[slow fable]

Ohh okay

I see now

[terse stone]

if you like 5 different fruits and your brother likes 3 fruits and if you subtract your set of liked fruits with anything that your brother likes and you still get all 5 fruits, it means you and your brother don't like any fruit in common

right?

[slow fable]

correct

[terse stone]

that's it

set theory is really easy if you think about it from real-life perspective

[slow fable]

.close

[devout snow]

Channel closed

Closed by @slow fable

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[quaint citrus]

U want it checked?

[sage glade]

yes please

[violet wind]

,w derive x^9/(sqrt(x)+x)

[woven radish]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by monikanicity#0205

[sage glade]

yeah idk what i did wrong

[violet wind]

ah you have a rogue low power term that first appears as x^2 on the right

Like the very right most bit of writing on the entire picture

that's I think the mistake

[quaint citrus]

Yea it’s supposed to be an x^9

[sage glade]

ahhhh

i seee thank you one sec

[quaint citrus]

Also remember that minus sign distributes

[sage glade]

yup i caught it loool

okay i got it!

yeah the details are uber important

.close

[devout snow]

Channel closed

Closed by @sage glade

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[restive river]

Where is the y in last time? Considered as a constant so added to c1?

[restive river]

Ping me please. Thank you.

[devout snow]

@restive river Has your question been resolved?

[prime egret]

Yes it’s implied that y is a constant

[prime egret]

.

Because you write f’(x) and not y’

[devout snow]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[devout snow]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dreamy knoll]

I need confirmation

[dreamy knoll]

on my math problem

How do I type it in math

It's about finding y and x intercept

I wanna know if it is right or wrong

[prime egret]

Post a pic or write down your question

[dreamy knoll]

How do I write down my question here

Like the command

[prime egret]

Latex?

[dreamy knoll]

Yep

[winter patrol]

dollar sign in front and end

[prime egret]

Use the $ sign

[dreamy knoll]

Can you do an example in fractions?

[prime egret]

$\frac{a}{b}$

[winter patrol]

$\frac{numerator}{denominator}$

[woven radish]

Pure

ℝamonov

[austere sedge]

if you can this pls

[dreamy knoll]

$/frac{x-3}{x+9}$

[woven radish]

Null

[dreamy knoll]

I am finding the Y intercept here

[prime egret]

You have your channel

[dreamy knoll]

Is it $/frac {0, -1/3}$

[woven radish]

Null

[winter patrol]

\verb|\frac{write numerator here}{write denominator here}|
$$\frac{numerator}{denominator}$$

[woven radish]

ℝamonov

[prime egret]

It’s backslash not /

\

[winter patrol]

follow the braces as we're writing them

[dreamy knoll]

Is it $\frac {0, -1/3}$

[winter patrol]

don't make adjustments on your own

[woven radish]

Null
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[winter patrol]

it'll probably be better to just draw it in paint so we can focus on the problem

read the latex #resources and play around in #bots later

[dreamy knoll]

I'm finding the Y intercept, where X must be substitute to 0

Is the answer this?

[prime egret]

Yes

[winter patrol]

\verb|y = \frac{x-3}{x+9}|
$$y = \frac{x-3}{x+9}$$

[woven radish]

ℝamonov

[prime egret]

You could just type (x-3)/(x+9) and we’d understand it

[dreamy knoll]

Alright. Finding the x intercept.

(x-3)/(x+9), where f(x) must be 0

0 = x-3
-x = -3 = 3

[winter patrol]

bad notation

[dreamy knoll]

Just like how bad I am at programming

[winter patrol]

don't write stuff like
-3 = 3
unless its part of something like a proof by contradiction

don't be lazy and write illegal stuff and do it properly with a new line
-x = -3
x = 3

[dreamy knoll]

Oh. I got it.

So is x = 3?

[winter patrol]

yes, x = 3 means x = 3

[dreamy knoll]

Finding Y intercept in second question where X must be substitute to zero.

f(x) = (x+7)/(x-14)
f(0) = (0+7)/(x-14)
f(0) = (7) /(-14)
f(0) = (1) / (-2)

Finding X intercept in second question where f(x) must be zero.

f(x) = (x+7) / (x-14)
0 = x+7
-x = 7
x = -7

Finding Y intercept in third question where X must be substitute to zero.

f(x) = (2x)/(x+5)
f(0) = (2(0)) / (0+5)
f(0) = (0)/(5)
f(0) = 0

Finding X intercept in third question where f(x) must be zero.

f(x) = (2x)/(x+5)
0 = 2x
2x = 0
2x = 0

Finding Y intercept in fourthq uestion where X must be substitute to zero.

f(x) = (x-6)/(x-3)
f(0) = (0-6)/(x-3)
f(0) = (-6)/(-3)
f(0) = 2

Finding X intercept in fourth question where f(x) must be zero.

f(x) = (x-6)/(x-3)
0 = x-6
-x = -6
x = 6

Finding Y intercept in fifth question where X must be substitute to zero

f(x) = (2x+4)/(4x)
f(0) = (2(0)+4) / (4(0))
f(0) = (4)
f(0) = (4)/(1)
f(0) = 4

[winter patrol]

should be x=0 in the last line
you wrote 2x=0 twice

[prime egret]

Careful you’re dividing by 0

Ah

[winter patrol]

how'd a 0 end up in the denom there

[dreamy knoll]

Our teacher told us that denominator can't be zero, and instead put number one.

[dreamy knoll]

4x where X must be zero

[winter patrol]

you don't have 4x in your f(x) = (2x+4)/4

[prime egret]

You didn’t write x in the first line

[dreamy knoll]

Oh, sorry, re editted it.

[winter patrol]

well the function is undefined at 0

[prime egret]

Division by 0 is undefined and you can’t just change it to 1

[winter patrol]

it has no y-interecept

[dreamy knoll]

What should I put it?

[winter patrol]

well the function is undefined at 0
it has no y-intercept

[woven radish]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Pure#9389

[dreamy knoll]

Is that so? In our previous lesson, he taught us that when there's nothing in denominator, we should put 1. For example (a^3)/(a^2)

So it's always undefined?

[woven radish]

Pure

[dreamy knoll]

What If it is reversed as (a^2)/(a^3)?

[prime egret]

Division by zero is always undefined yes

[dreamy knoll]

Where theres nothing at top

Should I put one?

[prime egret]

That would be 1/a

[dreamy knoll]

OoooooooOooh. I feel genius now. My mind must have messed up that as for denominator.

[prime egret]

1/0 != 1

If that is what you asked

[dreamy knoll]

I mean, is this the answer on a^3/a^2?

[prime egret]

a^3 / a^2 = a

a^2 / a^3 = 1/a

[dreamy knoll]

So If there's no any value at numerator, I must always put one?

[prime egret]

$\frac{a^2}{a^3} = a^{2-3} = a^{-1} = \frac{1}{a}$

[woven radish]

Pure