help-27

[vivid cliff]

is it

divisible by a square number

[molten dirge]

4

[vivid cliff]

alr

any other

bigger square numbers

[molten dirge]

16

[vivid cliff]

nice

so

$\sqrt{32} = \sqrt{16 \cdot 2}$

[woven radish]

Springsskateboard

[vivid cliff]

which is

$\sqrt{16}\cdot{\sqrt{2}}$

[woven radish]

Springsskateboard

[vivid cliff]

ye?

[molten dirge]

Yea

[vivid cliff]

what is

sqrt 16

[molten dirge]

Uhhhhh

Crwp

I dont know what you are asking sorry

[vivid cliff]

what number squared

gives u

16

[molten dirge]

Oh

4

[vivid cliff]

exactly

so

it’s 4

so now

u have

[molten dirge]

5 times 4 radical 2?

[vivid cliff]

$5\cdot{4}\cdot{\sqrt{2}}$

[woven radish]

Springsskateboard
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[vivid cliff]

yeye

[molten dirge]

Oh ok

[vivid cliff]

ew

[molten dirge]

Lol

[vivid cliff]

ignore that

yeye

so just simplify

and ur g

[molten dirge]

Alright thanks

.close

[devout snow]

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[vivid cliff]

npnp

[devout snow]

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[old snow]

Hello I’m confused

so i solved for x and y for 4/3x=2y

And i have to plug one into 3x-y=-28

Im not getting any of the correct answers, which are at the top of the paper

[devout snow]

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[old snow]

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[restive river]

,ask sqrt of sqrt of cbrt of sqrt of cbrt of sqrt of sqrt of 6

[woven radish]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Kousei Arima#0408

[midnight dirge]

um

whats ur q

also p cool i thought u had to use ,w

[earnest stirrup]

are you asking why is it 288?

[honest meadow]

question being?

[restive river]

yes

[earnest stirrup]

where theres no number it means the 2nd root

and 2* 2 * 3 * 2* 3* 2* 2=288

or with exponentials, if you have questions about why its multiplication: sqrt means ^(1/2) and cuberoot is ^(1/3)

[restive river]

oh thanks

.close

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[sacred dock]

help

[neon folio]

do you know what alternate interior angles are?

[sacred dock]

those are same side exterior

i believe

[sacred dock]

but yes

[neon folio]

ok

do you know what alternate external angles are

good]

?

[sacred dock]

yes

[neon folio]

good

[sacred dock]

i was replying so u got a ping lol

[neon folio]

how do we calculate the red angle

?

[sacred dock]

supplementary angles?

[neon folio]

yes

so?

[sacred dock]

idk the next step

thats where im stuck

[neon folio]

if two anglesa re supplementary?

what does that mean?

[sacred dock]

they add to 180

[neon folio]

good

so isnt the red angle just 180-(3x+5)

?

[sacred dock]

do we simplify that?

[neon folio]

yes

[sacred dock]

i got -3x+175

calculator

[neon folio]

yes

it correct

now

the red angle

with which angle is it alternate external?

[sacred dock]

2x-15?

[neon folio]

yes

and if they are alternal external

what does that mean

?

[sacred dock]

idk

[neon folio]

if two angles are alternate external

or alternate internal

or corresponding

it means

they are equal

.

right?

[sacred dock]

ys

[neon folio]

good

so

what do we do now

[sacred dock]

uh

[neon folio]

what is the red angle

the one we calculated

?

the measure

[sacred dock]

x=-20?

[neon folio]

no

x cant be negative

angles cant have negative value

the red one is -3x+175

and it is alternate external with 2x-15

and we know they are equal

so what do we do?

to find x

[sacred dock]

-3x+175+2x-15?

[neon folio]

no

they are equal

we dont add them

if a=x and b=y

and a=b

doesnt that mean x=y ?

[sacred dock]

yes

[neon folio]

good

now apply that to our problem

[sacred dock]

how so

[neon folio]

our a is the red angle

our b is the other angle

if a=-3x+175

and b=2x-15

and a=b

what does that mean?

[sacred dock]

...

[neon folio]

look above

[sacred dock]

congruent?

[neon folio]

yes

oof

a=x and b=y
and a=b, means x=y

a=-3x+175 and b=2x-15
and a=b, means .....

[sacred dock]

idk 😭

[neon folio]

think

idk how to explain it better]

this should be obvious

(

[sacred dock]

..

...

....

.....

......

.......

........

.........

pls

[neon folio]

do you get this:

a=x and b=y
and a=b, means x=y

?

[sacred dock]

yes

i do

but idk whats next

[neon folio]

a=-3x+175 and b=2x-15
and a=b, means .....

we do the EXACT same thing here

[sacred dock]

help me out here

[neon folio]

no

i wont

if you won't think

i can't help you

you learn nothing if i just give you the answer

[sacred dock]

i dont know whats next tho

im confused

[neon folio]

"i dont know"

doesnt matter

think

write me after 3 hours

if you dont get it by then

i will tell you the answer

[sacred dock]

ok

will do

.close

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[old snow]

Hello I’m having a problem with the question mark parts

So i have 4/3x=2y

And i either have to solve for x or for y so I can plug it into the equation

so i tried to solve for x which i got x=8/3

But when I plug that in I’m not getting the correct answer

the correct answer is at the top of the page.

[woven radish]

nHail

[old snow]

The second one

[bleak tide]

Okay

So whichever one you solve for should be in terms of the other

If you just say x=8/3, that might be true for a value of y, but not all of them

[old snow]

So if I solve for x it’ll be y= 8/3 ?

[bleak tide]

Where is x in that?

Solving for x means rearranging that equation into something like x = <something, likely involving y>

[old snow]

Okay I’ll try again

So if I solve for y

It’ll be y=2x/3 ?

[bleak tide]

Yes

You have to keep both the x and y around, they can't just disappear

[old snow]

Like this?

[bleak tide]

I think you're substituting into the wrong equation

Your goal in this question is to "fix" the original f(x,y) by making it into an f(x)

[old snow]

Oh right i plugged it in for x when I needed to plug it in for y

[bleak tide]

And that means getting rid of the y

So if you find out that y is equal to something that is only in terms of x (this is what you did), then you can plug that into the first function

[old snow]

So my teacher has us plug it in for the equation that it’s subjected to

Im order to find a point

Once I find one point for one of the variables then I’ll be able to easily find the others

[bleak tide]

Uh

Can you post the whole rest of the question then?

[old snow]

should I upload a question from one of the notes that we did in the lesson, it explains the process that I’m doing way easier

[bleak tide]

Alright ignore everything I said then, I don't know this method

[old snow]

alright can anyone else help

I just need to help with step 3

Im stuck on finding either x or y for

4/3x =2y

So i solved and got y=3x/8

I plugged that in but I’m not getting the correct answer :(

<@&286206848099549185>

somethings wrong but idk what

[proper drum]

What were your steps?

Here’s how you solve it

[devout snow]

@old snow Has your question been resolved?

[old snow]

That’s not correct

When I plug y into the equation it’s not giving me the answer the teacher gave me

[proper drum]

Hang on

[old snow]

Thanks

[proper drum]

I checked and they equal each other

Which means it’s correct

There are 2 ways of writing the answers though

3 if you wanna approximate the decimal

[old snow]

These are the answers my teacher gave me

I have to find the critical points

[proper drum]

This is the problem?

[old snow]

Yes

[proper drum]

Alright one sec

[old snow]

Thank you

[proper drum]

Can’t you convert it to this?

Forgot the ^2 hang on

So can you convert it to that?

[old snow]

I’ll try but that’s not what was in the lesson

[proper drum]

Well I’m just trying to figure out what it’s asking

[old snow]

sorry i have to use the Method of Lagrange Multipliers to get the critical points

this is a similar question from my lesson of it makes it any more clear

[proper drum]

Ah I see

[old snow]

if you’re not able to help me then that’s fine I’ll go over my lesson again

[proper drum]

So we are trying to find the minimum values of x and y?

[old snow]

yes correct

[proper drum]

Alright this might take a bit

[old snow]

I think I’m stuck on parts 3 and 4

I just need to find out at least one point in order to solve the other two

[wintry thistle]

Did you divide here, where x = -2 / (1,5) y

[old snow]

Thanks for the help

.close

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[potent arrow]

prove that A∩(B∪C)=(A∩B)∪C if C⊆A

[potent arrow]

my teacher did with assumption that C⊈A

[uncut crow]

that seems weird

are you sure that's what they did?

[potent arrow]

wait i will post a picture

[outer garnet]

,rotate

[uncut crow]

what does that say?

if only?

[potent arrow]

if and only if

[topaz beacon]

it may help to get intuition by drawing a venn diagram

[potent arrow]

its discrete structures 1

[uncut crow]

I think the confusion is in the structure of the proof and the statements

which a venn diagram won't help with

[potent arrow]

i also had confusion to understand how he got the contradiction

because i didn't was on the class

[uncut crow]

the picture you posted isn't a proof of this though?

[potent arrow]

yes it is proof

by him

but i dont understand how he got contradiction

[uncut crow]

A∩(B∪C)=(A∩B)∪C if C⊆A
are you sure?

[potent arrow]

yes

[uncut crow]

are you sure it's not the converse of that?

[potent arrow]

how you mean its converse?

[uncut crow]

if A∩(B∪C)=(A∩B)∪C, then C⊆A

[potent arrow]

he writed on the table proove that ---- if and only if C⊆A

that was the task

where i writed assumption thats where he started

[uncut crow]

ok but there are 2 parts to that

[uncut crow]

and I think this is the part being proved in the picture

[potent arrow]

i just need to know how he got contradiction

[uncut crow]

you need to understand this is what's being proved if you want to know how he got the contradiction

[potent arrow]

i understand the task, but i dont understand x belongs to c, then x belongs to (A∩B)∪C

[uncut crow]

if C is not a subset of A, then there exists an x in C such that x is not in A

that x is in (A∩B)∪C but not in A∩(B∪C) so A∩(B∪C) is not equal to (A∩B)∪C

[potent arrow]

thx ❤️

.close

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[quaint citrus]

Show ur work

Did u take the derivative

[violet veldt]

no

[quaint citrus]

Do that first

[violet veldt]

idk how

[quaint citrus]

Do u know chain rule

[violet veldt]

bruh

no

[quaint citrus]

U should learn that first before trying to do the problem

https://youtu.be/B1YkgNDbx5o

[violet veldt]

bruh

i just

want

some help with this question

maybe a step by step

[devout snow]

@violet veldt Has your question been resolved?

[winter patrol]

watch the video

[devout snow]

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[restive river]

why are the angles different? trigonometry/geometry/physics

[restive river]

.reopen

[devout snow]

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[devout snow]

@restive river Has your question been resolved?

[devout snow]

@restive river Has your question been resolved?

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[feral scarab]

I drew a diagram but i’m not getting my answer

I started off with this

And now i have this but i’m having trouble finding that theta

[polar wharf]

iirc what you need to do is actually add the vectors and find their magnitude

Which is to say figure out the total horizontal distance for each leg of the journey

Add those together

Figure out the total vertical distance for each leg of the journey

Add those together

Doing so will get you the final position of the plane

[feral scarab]

I don’t get you

[polar wharf]

So as an example

Well rather to explain a little

When you travel at an angle

You are traveling "diagonally"

But you can think of this diagonal movement as consisting of a horizontal component

And a vertical component

The trig functions sin and cos are able to break down a "diagonal" movement into the vertical and horizontal components

Lets say you are traveling at a bearing of 60 degrees

This equates to the angle of 30 degrees for the usual unit circle measurement

Suppose you travel 100km in this direction

You can use sin and cos to figure out how far horizontally and how far vertically you moved

Horizontal distance is

Cos30 * 100

Cos x * d where x is the angle on the unit circle and d is the total distance traveled in that direction

Vertical distance is

Sin30 * 100

Sin x * d

Your final position on the x-y axes can be described as that point:

(Cos30 × 100 , Sin30 × 100)

Say you change the bearing to 150 degrees and travel 100 km more

First you need to figure out how much horizontal/vertical distance the second part of the journey has

Start by finding the correct angle on the unit circle

150 degree bearing is equivalent to -60 degrees or 300 degrees on the unit circle

Then the horizontal component of the movement is

Cos300×100

And vertical is

Sin30×100

What you need to find your total distance traveled is add the horizontal components together and the vertical components

This will get you the final position which can be given by this point:

(Cos30×100 + Cos300×100 , Sin30×100 + Sin300×100)

The x and y coordinates there are the legs of the right triangle you'd use to find the final distance

[feral scarab]

I see

[polar wharf]

This is a process related to* decomposing a vector which you'll examine in more detail later on

[feral scarab]

Hmm i see

Ok i get it, thanks

[polar wharf]

You're welcome

GL

[feral scarab]

.close

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[honest geode]

i've got c as the answer is it correct?

[outer garnet]

Yes

[honest geode]

thank you

.close

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[weak dagger]

Hi, I have been stuck on this problem for a while now, as I'm quite unsure of how to turn the formulas of a cone into a usable equation: "A cone shaped water tank with a radius of 10cm and a height of 20cm, oriented vertically and pointing downwards, has water flowing out the bottom at a speed of 5cm^3/s. Find the speed of the water's surface (sinking) when it has sunk by 4cm. Anyone have a clue?

[midnight dirge]

lol

idt thrs a speed for water surface

[weak dagger]

Clarified a little

[midnight dirge]

water level?

[weak dagger]

Sorry, the tank is full

[teal star]

Is it a differentiation question

[weak dagger]

Yes, do you have any tips about the equations I'll be working with?

[teal star]

dv/dt is given

Ryt

Try differentiating volume with time and equating it to 5

V=1/3 • πr^2h ig

Is that any good

Igtg

[devout snow]

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[weak dagger]

Does this make sense?

[devout snow]

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[hollow path]

I'm trying to create an algorithm that assigns you a number from 1-101 depending on a different number, let's say x

So, if x=100 then you get the number 2 - 100x=2
And finally, if x=1.000.000 then you get the number 101 - 1.000.000x=101

[midnight dirge]

so

mod

[hollow path]

modular arithmetic?

[midnight dirge]

ye

[hollow path]

alr I'll give it a try thanks

[midnight dirge]

do mod 100+2

[hollow path]

.close

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[midnight dirge]

[devout snow]

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[small raptor]

https://gyazo.com/4a171db484f8fd6177a2ce07afd90d63

[small raptor]

can someone help me with 2b PLEASEEEE idk what to do

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[karmic trout]

What next to do

[devout snow]

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[devout snow]

@karmic trout Has your question been resolved?

[supple knot]

You could multiply the top and bottom by ab to get nonnegative powers of a and b

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[woven marsh]

An island economy grows coconuts and provides medical services. For each coconut harvested, coconut farmers need to eat half a coconut and receive 45 minutes of medical attention. For every four hours of
medical service provided, doctors on the island need to eat a coconut and
receive half an hour of medical attention.
The island economy ultimately exports 100 coconuts, but imports 50 hours
of medical services (by Zooming with doctors based in Canada).
a) Represent this economy as a system of equations

[woven marsh]

How do i get the system of equations

I got this but it seems incorrect

x = total cocunuts and y = total medical services given

[devout snow]

@woven marsh Has your question been resolved?

[devout snow]

@woven marsh Has your question been resolved?

[woven marsh]

<@&286206848099549185>

[woven marsh]

RIP

still waiting

[woven marsh]

<@&286206848099549185>

[trim vine]

Can u translate your math equation into English words?

[woven marsh]

x = 100 (required amount of cocounts) + cost of cocunut farmer + cost of medecine

y = 50 (required medecine services) + cost of cocounuts + cost of medical services

after doing system of equations i find that im doing the formula im using is wrong as it equals to negative numbers and thats not right

[devout snow]

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[woven marsh]

<@&286206848099549185>

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[pallid ibex]

Number 5 i can solve the first part but i dont understand how to solve second part of r^2

[devout snow]

@pallid ibex Has your question been resolved?

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[devout snow]

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[devout snow]

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[gusty merlin]

Hi

[gusty merlin]

This question pls, I’m a bit confused how to solve it - I’ve marked 1,10 and 8,3 on a cartesian plane but am unsure of what to do next

[vivid cliff]

aye aye

wassup

so

hm

u don’t need

to

mark it

[gusty merlin]

Hiii that was so quick

[vivid cliff]

or anything

[gusty merlin]

Oh

[vivid cliff]

just needs use

gradient formula

you know it?

[gusty merlin]

What’s the gradient formula

I’ve never heard of it

All I’ve heard of is rise/run

[vivid cliff]

$\frac{y_2-y_1}{x_2-x_1}$

[woven radish]

Springsskateboard

[gusty merlin]

I have no idea how to use it

[vivid cliff]

oh damn

alr

[gusty merlin]

So we just take away

Let me try and solve it

And let me tell u

[vivid cliff]

then ig just use

rise over run

can u show me

[midnight dirge]

i hate that

[gusty merlin]

Ofc

[vivid cliff]

what uve marked

on ur plane

[gusty merlin]

I’ll try to use urs coz I deleted the plane - I’ll show u what I get

[vivid cliff]

yeye

sure

take ur time

[gusty merlin]

There

[vivid cliff]

eh

I thought

u marked it

on a Cartesian

plane

[restive river]

[gusty merlin]

I got rid of it tho I can mark it again if u want

[vivid cliff]

yeye

mark

also btw

when u mark it

see the

direction

the line is going

toward

[gusty merlin]

Alr

@vivid cliff

[vivid cliff]

aye

exactly

negative

gradient

now

calculate

rise and run

first the rise

[gusty merlin]

How do I do that tho

Like how do I find the rise and run do I make a triangle

[vivid cliff]

yep a triangle

now

calculate

the length

is the sides

[gusty merlin]

Oh okay!!!

[vivid cliff]

the vertical one

is the rise

horizontal is run

[gusty merlin]

I got 7 7

[vivid cliff]

yeye

nice

so

what’s 7/7

[vivid cliff]

yeye noice

so

what’s 7/7

[gusty merlin]

1

[vivid cliff]

ye

BUT

that’s not

ur final ans

cuz

[gusty merlin]

-1

OMG

[vivid cliff]

yeye

nice

you got it

[gusty merlin]

Let me do the next one

[vivid cliff]

let’s go

yeye

[gusty merlin]

And the u can leave

[vivid cliff]

gd luck bro

yeye

[gusty merlin]

Such a genius

[vivid cliff]

nahhhh

[vivid cliff]

alr

plot it

[gusty merlin]

Alr

I can’t find one that goes to 20

[vivid cliff]

eh alr it’s fine

lemme try and find

[gusty merlin]

Okay thank youu

[vivid cliff]

just put

20 at the top

[gusty merlin]

I can do the y1-y2 formula if u want

[vivid cliff]

u comfortable with learning that

alr yeye sure

[gusty merlin]

I know how to use it now but since there’s a negative idk what to do

[vivid cliff]

cuz that’s much faster

so

if you have

a coordinate

[gusty merlin]

Exactly

[vivid cliff]

say

(2,3)

the x coordinate is

x1

the y

is y1

if u label the x coordinate x ONE

the y HAS to be y ONE

not y2

ye?

[gusty merlin]

Like that?

[vivid cliff]

alr so

now what u do

is replace the

[gusty merlin]

1-2?

[vivid cliff]

x2 on 5

with y2

[gusty merlin]

Oh

[vivid cliff]

and the x1 on 20

with y1

[gusty merlin]

Wait what

Ohhh

[vivid cliff]

yeye

[gusty merlin]

Got ya

[vivid cliff]

u can’t have (x1, y2) yk

it needs to be (x1, y1) and (x2, y2)

[gusty merlin]

1x20=20
-2x5=-10

[vivid cliff]

oh

but why

[gusty merlin]

^

[vivid cliff]

yeye

but why do u

do it

[gusty merlin]

Idk u told me to

🤷🏽‍♂️

[vivid cliff]

wait what

I did?

I never said

to multiply them

tho

[gusty merlin]

I thought this meant multiply

x2 is on 5

[vivid cliff]

ah nah

aye

x2 as 5

this is

what I meant

[gusty merlin]

OHHHH

[vivid cliff]

yeye

[gusty merlin]

done

[vivid cliff]

your -2 can be x1 and 5 be y1 also

any way is fine

alr so

now show me

what u have

[gusty merlin]

Alr

[vivid cliff]

nice

so

now

use this formula

[gusty merlin]

Sure

[vivid cliff]

perfect

yea

exactly

nice

[gusty merlin]

IM SO SMART

[vivid cliff]

IKR

[gusty merlin]

LAST ONE

[vivid cliff]

now try with this

[gusty merlin]

I PROMISE LET ME DO THIS ONE

[vivid cliff]

ull see it’s the same

so basically

just assign to either

[vivid cliff]

yeye sure

[gusty merlin]

I’ll do that one later, I got one more and I’ll see if it works - it’s a complete different equation so it might be better

[vivid cliff]

same thing

choose one pair

to be x1 y1

and the other pair

x2 y2

and use formula

[gusty merlin]

Yup

[vivid cliff]

for this

[gusty merlin]

I’ll try

[vivid cliff]

u can alr see

what the gradient is

but try with the formula

[gusty merlin]

I’ll try - first time using this formula I usually draw them out

[vivid cliff]

yeye its fine

take ur time

in the future

u won’t be drawing it out

to find gradient

ull be using this mostly

[vivid cliff]

yeye

so

y2 - y1 is 0

[gusty merlin]

3/0= undefined

[vivid cliff]

u flipped

y2 - y1 is

numerator

x2 - x1 is denominator

ye

[gusty merlin]

Oh ao it’s 0/3

[vivid cliff]

yep

[gusty merlin]

0/-3 is 0

[vivid cliff]

ye

[gusty merlin]

So the answers 0

[vivid cliff]

yepp

nice

[gusty merlin]

ONG

STOP

IM SO SMART

THANK YOUUU

[vivid cliff]

IKR

yeye

npnp

[gusty merlin]

ILL BE USING THAT FORMULA IN THE FUTURE

[vivid cliff]

yeeee

u got this bro

💪

[gusty merlin]

OMGGGG

Thank youu have a great day

[vivid cliff]

yeye u too

npnp

[gusty merlin]

.close

[devout snow]

Channel closed

Closed by @gusty merlin

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• Show your work, and if possible, explain where you are stuck.
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[gusty merlin]

Hii

[gusty merlin]

This equation, I have no idea what to do or how to solve it, this help from a helper would be lovely

Please @ me if ur interested in helping me 🙃

[prime egret]

Let’s do it bracket by bracket then we will sum them later

What is $6(2a-4c)$? @gusty merlin

[woven radish]

Pure

[gusty merlin]

6x2= 12a

6x4=24c

[prime egret]

So we have $12a -24c$ for the first brackets. Agreed?

[woven radish]

Pure

[gusty merlin]

Yes

[prime egret]

Okay now for the second bracket $6(6a-4b)$

[woven radish]

Pure

[gusty merlin]

36a-24b

[prime egret]

Yes

And last one 3(4b-8c)

[gusty merlin]

12b -24c

[prime egret]

Okay

So we have

$\frac{(12a-24c)-(36a-24b)+(12b-24c)}{4}$

[woven radish]

Pure

[prime egret]

Agreee?

[gusty merlin]

Yes

[prime egret]

Oh why is it -36a in the second bracket?

[gusty merlin]

OHHH WAIT MB

Fixed since were taking away we don’t need the negative

@prime egret

[prime egret]

Right so now let’s get rid of the brackets

[gusty merlin]

How

[prime egret]

$\frac{12a-24c-(36a-24b)+12b-24c}{4}$

[woven radish]

Pure

[prime egret]

We can easily write this

[gusty merlin]

Oh okayyy

[prime egret]

But the second term is a bit more complicated

We have a minus sign in front of the bracket

[gusty merlin]

Right

So how do we do that

[prime egret]

We have to also distribute this minus sign

[gusty merlin]

Correct

[prime egret]

We flip the signs of the things inside the brackets

$\frac{12a-24c-36a+24b+12b-24c}{4}$

[woven radish]

Pure

[prime egret]

You see what I’ve done there?

[gusty merlin]

Oh okay, so now need for the brackets

Yes I do

[prime egret]

Right so any idea what you’d do from here?

[gusty merlin]

Nope

This is my first time doing anything like this

It was homework and my parents never learnt this

[prime egret]

Right

Do you know about grouping like terms?

Say you have $10x + 2x$

[woven radish]

Pure

[gusty merlin]

Or yea I think

[prime egret]

This would be 12x

Right?

You just add the number

[gusty merlin]

Like that?

[prime egret]

Yes

So what’s the final result?

[gusty merlin]

Let me solve it!!

Would it be 36-12?

[prime egret]

12-36 is not 36-12

But it would be -(36-12)

[gusty merlin]

12 comes before 36 so I do I keep it like that or do I change it to 36-12

[prime egret]

12 comes before 36 so you’d get a negative result

[gusty merlin]

Correct

[prime egret]

It would be equal to 36-12 but negative

[gusty merlin]

Ohh okay

In red

[prime egret]

Oh wait careful there. Everything is right except the c one

It should be -24c -24c

Not 24c-24c

[gusty merlin]

Oh

It’s still 0 tho

So now what I do

Because we’re looking for x y and z

[prime egret]

-24c-24c is not 0

[gusty merlin]

Ohh my Siri was broken

-48

[prime egret]

Well now we have $\frac{-24a + 36b -48c}{4}$

[woven radish]

Pure

[prime egret]

We can split this into 3 fractions

$\frac{-24a}{4} + \frac{36b}{4} + \frac{-48c}{4}$

[woven radish]

Pure

[prime egret]

Can you simplify these?

[gusty merlin]

Yes u can because they are all factors of 4

Let me solve it brb

[prime egret]

Correct

Now we need to factor out the common factor of these numbers

Do you know how to do that?

[gusty merlin]

It’s 3

I’m not that dumb maybe a little but not that much

So now I’ve gotten the common factor which is 3 what do I do now?

[prime egret]

Take out -3 as the question says X is negative

[prime egret]

Did not mean to offend you, was simply trying to make sure you were able to follow

[gusty merlin]

Oh that that was sarcasm!!!! Didn’t mean to sound rude

Sorry forgot you’ve never met me in real life 😭😭

[prime egret]

[gusty merlin]

Done

[prime egret]

No worries lol

Alright show me what you’ve got

[gusty merlin]

I just wrote negative -3 and the whole equation

-3(6a+9b-12c)

[prime egret]

So $-3(2a-3b+4c)$

[woven radish]

Pure

[gusty merlin]

Ohhh yea that I could do

What now?

[prime egret]

That’s it

Now you could find X Y Z

[gusty merlin]

But it wants the answer to x, y and x

Is c = x and b = y and a=z

[prime egret]

No no

You were told

$X(2a + Yb + Zc) = -3(2a-3b+4c)$

[gusty merlin]

“ Complete the simplification below by finding the values of the capitalise pronumerals. X is a negative number.”

[woven radish]

Pure

[gusty merlin]

That’s all I was told

Correct

[prime egret]

You can compare the coefficients here

[gusty merlin]

What do write in for y and z tho

[prime egret]

So X=-3

Agreed?

[gusty merlin]

Correct

[prime egret]

Looking at this Yb = -3b

What’s Y

[gusty merlin]

-3

[prime egret]

Should be -3

[gusty merlin]

Yes

So y also equals -3?

[prime egret]

Yes

[prime egret]

So what about Z, again look at this

[gusty merlin]

Z is 4

[prime egret]

Yes

[gusty merlin]

That?

[prime egret]

Yeah should be right

[gusty merlin]

Omg thank you so muchhhh

[prime egret]

Npnp

[gusty merlin]

Literally u deserve everything coz this lasted way longer than I expected

I have another question on this but I’ll let u go coz it’ll probs take the same amount of time

So make sure to have an amazing day and thank you so so much again

[prime egret]

Yeah Im at a beach right now but I have to go back to my hotel soon.

[prime egret]

Thanks you too.

Cya later.

[gusty merlin]

Omg if u told me that sooner I would of made if super quick

I’m so sorry for wasting ur time

[prime egret]

Don’t worry about it

I was just sunbathing anyway

[gusty merlin]

Now u made me feel bad u should be able to relax and scroll through Insta etc whilst sunbathing

I hope the rest of ur trip coz super duper well

.close

[devout snow]

Channel closed

Closed by @gusty merlin

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[golden eagle]

is this question valid?

i mean he didn't put any restrictions on the order of the matrix..

[pseudo basin]

valid in what sense?

i mean, given that we are talking about the expression $X^TAX$, one would assume $A$ is a square matrix of the same size as $X$...

[woven radish]

Ann

[pseudo basin]

because otherwise the expression is undefined

[golden eagle]

exactly this is what confused me

he didn't declare that

[pseudo basin]

it can be inferred from context

[golden eagle]

ok thank you so much!

i will try again now

.close

[devout snow]

Channel closed

Closed by @golden eagle

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Remember:
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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

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[twin quarry]

hello ive been trying to do this since yesterday

really need help

its due tmrw and I dont understand this

hold on

can I screen share with u

wait nvm

its fine

[meager jackal]

$4x^2 + x = 3x + 5$

[twin quarry]

1 sec

[woven radish]

Noone

[meager jackal]

Then solve for x

[twin quarry]

arent these different methods

[meager jackal]

Since LHS are same right?

[twin quarry]

lhs?

oh

left hand side

yeah

[meager jackal]

Left hand side

[twin quarry]

lemme subsitute

[meager jackal]

,w 4x^2 + x = 3x + 5

[woven radish]

Lambda

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Noone#3876

[twin quarry]

what just happened

so x is?

can u explain how u got this

[meager jackal]

Here

[twin quarry]

yeah

then u just

moved them over?

[twin quarry]

how u get 2 lines tho

[meager jackal]

I just use calculator

[twin quarry]

so whats x

[meager jackal]

U can count it

[meager jackal]

This is in fraction form

[twin quarry]

i think so

-b square root b -4ac / 2a?

b^2

i mean

[meager jackal]

Yes

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

[woven radish]

Noone

[twin quarry]

what are the values

[meager jackal]

U can sub a b c and solve it

[woven radish]

Lambda

[twin quarry]

then use

the formula

for both equations

?

[meager jackal]

$4x^2 - 2x - 5 = 0$
$a = 4, b = -2, c = -5$

[woven radish]

Noone

[twin quarry]

ok let me use it for the first one

[meager jackal]

And use that formula

[twin quarry]

tell me iif its right

oh ok

[woven radish]

Lambda

Lambda

[twin quarry]

wheres the problem

oh ok

I also need y value

do i sub it in

needs to look like this

[twin quarry]

is this right

how do u do that