#help-27

1 messages · Page 4 of 1

restive river
#

but for vertical asymptotes?

ionic belfry
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.close

restive river
ionic belfry
#

oh

ionic belfry
#

what makes the denominator 0?

restive river
#

x

ionic belfry
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it must be some number

restive river
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0

ionic belfry
ionic belfry
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its -3

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this number is the VA

restive river
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so only 1 va?

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thats -3

ionic belfry
#

yes

devout snowBOT
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@restive river Has your question been resolved?

restive river
#

for horizontal and slant asymptotes tho?

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sorry im having trouble understanding the lessons from my class ;(

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thanks in advance to those who answer <3

devout snowBOT
#

@restive river Has your question been resolved?

restive river
#

<@&286206848099549185>

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#

@restive river Has your question been resolved?

devout snowBOT
#

@restive river Has your question been resolved?

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little jewel
#

If a triangle has sides ½(n!), (n-2)!, (2-n)!, How do I find it's numerical area?

left robin
#

we can use heron's formula

devout snowBOT
#

@little jewel Has your question been resolved?

little jewel
left robin
#

yep

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i just tried it

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haha

little jewel
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Ah damn

left robin
#

there must be another way

little jewel
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<@&286206848099549185> any hint would be much appreciated

devout snowBOT
#

@little jewel Has your question been resolved?

violet wind
#

Well

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Factorials are not defined in any sort of way for negative integers

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Do we know n is an integer then?

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little jewel
#

.reopen

devout snowBOT
#

little jewel
violet wind
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so n=2 is the only consistent choice

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otherwise either n-2 or 2-n will be negative

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and you can't take the factorial of a negative integer

little jewel
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Interesting

violet wind
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not even with the gamma function (extension of factorials to real numbers)

little jewel
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Not familiar with that, but I will try to solve it with herons formula when n is 2

violet wind
#

that'll work yeah

little jewel
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Ah an equilateral

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Ig herons is too long, it's area is gonna be sin45

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Gonna verify one sec

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Ah doesn't work

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All 3 sides should equal 1

zinc veldt
#

just use the area of an equilateral triangle formula

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the sides are all 1

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anyway

little jewel
zinc veldt
#

that works too

little jewel
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Yeah

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Sin45

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Not an available answer

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All of the answers have sqrt (3)

zinc veldt
#

wouldn't the included angle be 60?

little jewel
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Jesus Christ my bad

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Yeah sqrt(3)/2 my brain automatically went for the 45 degree angles for some reasons

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Thanks guys!

#

.close

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frozen flicker
#

I dont get how to do this

devout snowBOT
frozen flicker
#

anyone can help?

devout snowBOT
#

@frozen flicker Has your question been resolved?

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@frozen flicker Has your question been resolved?

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@frozen flicker Has your question been resolved?

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median dirge
#

StOP

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opening help channels

pearl plume
#

.close

hallow hazel
#

@pearl plume its closed bruh

#

That guy closed everything

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radiant drift
#

@half minnow

devout snowBOT
radiant drift
#

i think i know the answer to this

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just want you to

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confirm

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so the first one, it converges at 1

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because 1/n=0

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and the second one

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the denominator is larger if i compare the numbers one by one

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so

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2>1

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4>3

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6>5

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is that right?

half minnow
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u gotta prove them tho right..?

radiant drift
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how do u prove it

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..
?

half minnow
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this looks like real analysis

radiant drift
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wtf is that

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is mine fake?

half minnow
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LOL

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what worksheet is this

radiant drift
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like

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all the other quesitons

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i asked u guys

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the same

half minnow
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yea where did you get it from

radiant drift
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my professor

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gave me

half minnow
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tf

radiant drift
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?

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wut

half minnow
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it's just a conundrum because the way you did it is intuitive enough

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and it relies on facts established beforehand

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so if this wasnt a real analysis course, you are correct

radiant drift
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but how would i actually prove it ?

half minnow
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you would need to use the definition of convergent sequence

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it goes like

radiant drift
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oh ik

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a limit exists

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if its monotonic bounded

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?

half minnow
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yep

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just show that

radiant drift
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ive never done that,,?

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lemme try

half minnow
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ok the first one is easy to show monotonicity

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yea u got this

radiant drift
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monotonicity means bounded??

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because it's intuitively increasing

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that doesn't need proof??

half minnow
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monotonicity doesnt imply bounded

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montonically bounded does imply convergent tho

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so you have to show the sequence is monotonic AND bounded separately

radiant drift
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like how??? if n is approaching infinity, 1/n just becomes smaller so the entire thing is increasing?

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like

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how do you prove that

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isn't that just fact

woven radishBOT
half minnow
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that's the proof of monotonicity

radiant drift
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do i do that by induction?

half minnow
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you can just substitute the definition in

woven radishBOT
radiant drift
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exaclty?

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and thats

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proven?

half minnow
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well show that its true lol

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subtract the ones off

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move 1/n to the other side

radiant drift
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ohohoho

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lol

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yay

half minnow
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its monotone increasing now wooo

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now you just need to show its bounded

woven radishBOT
radiant drift
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how

half minnow
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substitute definitions in, choose a convenient value of B

radiant drift
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it's less than 2?

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ig

half minnow
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u can use <= 1

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doesnt really matter

radiant drift
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right

half minnow
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ur subtracting something from 1, so its clearly less than 2

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at the same time, it will always be greater than or equal to 0

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just show that last part and you are golden

radiant drift
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wait so now it's lim 1-1/n<= 1

half minnow
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yea but thats guaranteed

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n is a natural

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and so 1/n will always be >= 0

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therefore 1-1/n <= 1

radiant drift
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right

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right

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OH

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OKOK

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lemme show u my work for confirmation

half minnow
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ok

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i think someone is watching me rn...

radiant drift
radiant drift
half minnow
# radiant drift

yea perfect but just show 1-1/n >= 0 so you can drop the absolute value bars

radiant drift
#

okok thxxxxxxxxxx

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as always

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.close

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fervent jewel
#

when is a DE linear?

devout snowBOT
fervent jewel
#

nvm got it

#

.close

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real mist
#

So i walked into my class and i dont understand how to do anything came in blind and i would like some assistance on my hw

real mist
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"Solve the following equation for a"

thin gust
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err

rare mantle
#

alright so you want to isolate a (essentially, "remove" the 5/6 from it)

real mist
rare mantle
real mist
#

The yt video didnt help btw

rare mantle
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because you want 1a

thin gust
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oh in terms of n?

rare mantle
thin gust
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okiee makes sense

rare mantle
real mist
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Hold on

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tbh i dont know anything on how to do that

thin gust
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oki for eg if u have 2x = 2

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what is x

real mist
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1

thin gust
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how did u get that

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divide 2 right

real mist
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Yeah

thin gust
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now for this qn

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u have 5/6 a = n

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what’s a

real mist
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wait let me get paper

thin gust
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okii

real mist
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back

thin gust
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hii

real mist
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Its 0.03 right?

thin gust
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what is 0.03?

real mist
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n

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waut

thin gust
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the value of n?

real mist
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Idk

thin gust
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aren’t u finding a in terms of n

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oki wait

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if u have 2x = 2

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u divide both sides by 2

real mist
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yeah

thin gust
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if u have 2x = 9

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what’s x

real mist
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4.5

thin gust
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yes

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if we have 2x = n

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what is x

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it’ll be n/2

real mist
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Oh

thin gust
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no need to find the value of n

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can just leave as n

real mist
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OH

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that makes sence

thin gust
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yesh

real mist
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wait

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so 5/6 should i turn it into a decimal

thin gust
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errr if I’m not wrong that’s going to be a never ending decimal

real mist
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O

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so keep it as 5/6

thin gust
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ya it’s better than way

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so if u have 5/6 a = n

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divide both sides by 5/6

real mist
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isolate the a?

thin gust
#

yesh

thin gust
real mist
#

O

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so n is the value of 1

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so

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1 / 5/6

thin gust
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yesh gd!

thin gust
real mist
#

1 divided by 5/6

thin gust
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yes

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what do u get

real mist
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1.2

thin gust
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ya

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so final answer for a is?

real mist
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a=1.2?

thin gust
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1.2 n

real mist
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a=1.2n?

thin gust
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yesh

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we have to leave as n because we don’t know what n is

real mist
#

so

thin gust
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just write 1.2n

real mist
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1.2n?

thin gust
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no need write a

real mist
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Thank you!

thin gust
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welcc (:

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but u understand right

real mist
#

Yeah

thin gust
#

okii

real mist
#

.close

devout snowBOT
#
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real mist
devout snowBOT
real mist
#

I have no clue on what to do, I think i have to dispute the numbers but it comes out as 1b + 3f +1a=g i am stuck in the "1b+3f+1a=1g" because i do not know what to do next!

tall knoll
#

Do you know what it means to solve for a?

real mist
#

nrl

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I got put into this class when i didnt sign up for it infact i failed the algbra test idk how im in it

tall knoll
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A hint: the equation (b+3f)a = g is solved for g

real mist
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so

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dis pute it?

tall knoll
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Que?

idle jackal
#

make a stand alone on one site

tall knoll
#

To dispute something is to argue about it

little jewel
real mist
real mist
little jewel
#

You needn't to if you just want to isolate a

real mist
#

needn't?

little jewel
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If you have AB = C can you isolate B

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Like how C is isolated

real mist
#

no

tall knoll
real mist
#

Oh

little jewel
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Ok what if you have 3X = 6 can you find the value of X

real mist
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yeah

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3x divided by 3 then 6 divided by 3 to get x=2

little jewel
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Exactly you divided by 3 to isolate X

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How would I do it in AB = C

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If I want to Find B

real mist
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ab divided by ab?

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OH

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ab divided by a?

little jewel
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Yes

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So what does b equal

real mist
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c?

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b=c

little jewel
real mist
#

how do u divide letters?

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i mean 1c divided by 1b?

little jewel
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You simply write it as C ÷ B

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You cannot find the value of the division so you leave it as symbols

real mist
#

OH

restive river
#

So basically, you have AB = C and you want to isolate B right?

little jewel
#

Yeah hopefully they got it

real mist
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so

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brb im do on paper

little jewel
#

Oh my god I realized I mixed it up

real mist
#

?

little jewel
#

@real mist Ayo we are diving by A to isolate B my bad

real mist
#

Oh

little jewel
real mist
#

Idk i got stuck n redoing it

restive river
#

When you’re doing a problem like that, just remember that you can do any operation on one side of the equal sign. However, you always need to do the same thing on the other side of the equality sign. In your previous example, you had 3X = 6 and you needed to to isolate X. What you can do is divide both side by 3. On the left, you have 3X/3 which is equal to B and on the right, you have 6/3 which is equal to 2. You’re left with X = 2

real mist
#

so

restive river
#

You can apply the same thing with AB = C

real mist
#

my thing is on the question im doing "(b+3f)a=g" I have 3 letters on the other side

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what do i do if i got 3?

restive river
#

What’s your question?

real mist
restive river
restive river
# real mist

I’m not sure I understand this question properly, but I would have a = g/(b + 3f)

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I don’t know what’s the thing with capitalization though

real mist
#

thats somethign else

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dont worry abt that

little jewel
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Ah guess I am a bit late

real mist
#

thats for the awnser so i dont f*** it up

restive river
#

Ha ok I think I might know where your confusion is

#

When you divide a polynomial by the same polynomial, you get 1

little jewel
#

I don't think they know what a polynomial is

real mist
#

nope

restive river
#

2

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Is poly

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It’s basically a thing with letters like X + 5X squared

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It’s not the exact definition, but that’s it in a nutshell

real mist
#

Like i said i didnt go to summer school for algbra and i failed that test im litrally going in w/o any info like NOTHING I didnt even know what 3x=6 was

restive river
#

If you have X/X, what do you get?

real mist
#

1

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1x*

restive river
#

1

real mist
#

Oh

restive river
#

Ok, just remember that when you divide a thing by the same thing, you always get 1

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3/3 is 1

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X/X is 1

real mist
#

Ye i understand that

restive river
#

(X + Y)/(X + Y) is 1

real mist
#

Yeah

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because u do anythign on the left side to the right

restive river
little jewel
#

You wanted to do distribution earlier

restive river
#

You know that you have to divide both sides by B + 3F

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If you want to isolate a, I wouldn’t recommend you distribute

little jewel
#

Ah yeah my bad

restive river
#

Just divide both sides by B + 3F

little jewel
#

They seem to need some practice in arithmetic

real mist
#

arthmetic?

little jewel
#

I wouldn't really consider this algebra, it's more arithmetic, but I guess you shouldn't worry about the difference for now

real mist
#

o

restive river
little jewel
#

You missed the a

restive river
#

Ha yeah sorry

real mist
restive river
#

I think I get where you’re confused

real mist
#

so like this?

little jewel
#

Yes

restive river
#

In this case, a is multiplied

little jewel
real mist
#

There

little jewel
# real mist

By the way the a is multiplied as kvlt mentioned, it's (b+3f) x a, not +

#

But the answer is correct

little jewel
#

You could think of it like this if you understand the AB = C example, b+3f is just a big symbol you are dividing by,

restive river
little jewel
real mist
#

Oh

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SO i got 1 more question

little jewel
#

Well I hope this has somewhat cleared up how this problem is solved

restive river
#

If you have AB/A, you can cancel the As

real mist
#

thats the way i turn it in?

little jewel
#

Yeah looks good, but the b is not capital?

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The b shouldn't be capital

real mist
#

Yeah

little jewel
#

Yeah looks fine

real mist
#

Thank you so much 😭

little jewel
#

Yeah you did it! And do take those summer classes next time

real mist
#

I will

#

😭

restive river
real mist
#

Bro THANK GOD discord added the student servers

#

i do not wanna be grounded rn

restive river
#

My pleasure

real mist
#

so

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it just changed on me to a whole diffrent unit

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w**

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all i do is basic algbra right

restive river
real mist
#

Ok

#

thxs

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Bye bye

restive river
#

Be careful with the inequalitie sign.

real mist
#

?

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Wdym

#

That?

restive river
#

Yes that

real mist
#

Why tho-

radiant arch
real mist
#

Oh i know about that

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but i understand that-

restive river
real mist
#

Yeah

#

somethin i understand

#

🥳

#

.close

devout snowBOT
#
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real mist
#

bro

devout snowBOT
real mist
#

im getting upset w this **

#

I do not understand where i messed up

little jewel
real mist
#

There ?

little jewel
#

Yes

real mist
#

9w-36w>w+24 I collected terms

little jewel
#

9w-36w is not 45w

real mist
#

Thats a plus symbol

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was i supposed to do (-) ?

little jewel
#

Wdym you wrote 9w-36w

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It equals -27w

real mist
little jewel
#

I have no clue what that +36 is

real mist
#

9+36

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adding

little jewel
#

What why

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What does 5x+4x equal

real mist
#

Well ****** i got a new problem

little jewel
real mist
#

O that was a question mb

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9x

little jewel
#

Yes so what's 9w-36w

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What is it equal to

real mist
#

45

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or -45

little jewel
#

My man

real mist
#

?

little jewel
#

What's 3-9

real mist
#

oh shitt-

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-6

little jewel
#

Yes so what's 9-36

real mist
#

-27

#

right?

little jewel
#

Yeah

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With the w

real mist
#

-27w

little jewel
#

Ye now try to solve it

real mist
#

wait

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I feel like im being dumb asf

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im about to pull an all nighter studying

little jewel
#

My man

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In the 2nd step

real mist
#

-4

little jewel
#

You are supposed to subtract 1w from both sides

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But you are adding

real mist
#

OMFG

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IM AN IDIOT

#

BRB

little jewel
#

Seems about right

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I would submit as 6/7 though

real mist
#

Ok

#

IT WORKED YES

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can i get help w one more quesetion

#

to make sure i got it?

little jewel
#

Sure

real mist
#

s0

#

-7c-(2c+2)>-4c-2+6c

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I distribute the 2c and 2 with -1

little jewel
#

Yeah

real mist
little jewel
#

My maaan

real mist
#

?

little jewel
#

-7-2

real mist
#

-9

little jewel
#

Then why -5c

real mist
#

because i had to add

little jewel
#

I am not sure what you are adding -7c-2c is -9c

real mist
#

because i had to do what i did for both numbers-

little jewel
#

What is your thought process when doing -7-2

real mist
#

When I put collected the -2c i added it so i went to the -7c and added 2c what got -5c

little jewel
#

You do realize -7-2 is the same as -7c-2c

real mist
#

yeah

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wait

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i fucked up even after that-

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Lemme redo-

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so now im stuck

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Thats just 0

#

so do i cancel it out right?

#

i feel dumb asf rn

little jewel
#

Idk what's the image about but yeah c< 0

real mist
little jewel
#

6c

#

Not 6

#

-4c + 6c

#

You forgot the c in the first step

real mist
#

OH

#

then

#

step 3 i messed up and it effected it right?

little jewel
#

1 was screwed so all the ones that followed were screwed but if you add the c in 3rd it could be fixed

real mist
#

Ok

#

now im confused-

little jewel
#

Clarify

real mist
#

all i have are "c" varibles

#

i do not have any constance

little jewel
#

And that's fine

real mist
#

O

little jewel
#

0 is a constant

real mist
#

so

little jewel
#

Solve it normally when you're at -9c > -4c+6c

real mist
#

O

little jewel
#

Is that an o or 0

real mist
#

so

#

awnser is c>-1.1

little jewel
#

How

real mist
little jewel
#

My man god forbid what's 6-4

real mist
#

2

little jewel
#

Then why 10

real mist
#

bc

#

-4-6

little jewel
#

It's -4+6

real mist
#

OHHHHHHHHHHHHHHHHHHHHHHHHHHH

#

im stupid at this point

little jewel
#

And you are missing the c

real mist
little jewel
#

No

#

You want to isolate c

#

Subtract 2c from both sides

real mist
#

how did u get 2

little jewel
#

Look what do you do to isolate X in 2x>x +1

real mist
#

2x divided by 2

#

then

little jewel
#

That wouldn't work since we still have X on both sides

real mist
#

o

#

Then no clue-

little jewel
#

Look take the x from the right and make it negative on the left, are you familiar with how to do this

real mist
#

nope

#

not at all

little jewel
real mist
#

yeah

#

but i dont understand when to like do both and to not

#

wait ill show u

#

NVM

#

like i dont know when to do what

main gull
# real mist but i dont understand when to like do both and to not

If you have the same variable on both sides, you need to get all the terms with variables on the same side, and everything else that doesn't have a variable to the other. That's when you need to do the opposite operation. If the variables are on the same side, you just need to perform the math with that sign

real mist
#

OH

#

thxs

main gull
little jewel
#

Yo dldh can you continue helping them with this problem, I suck at helping and it's 4 am so i gotta sleep

real mist
#

<@&286206848099549185>

#

acually im tired

#

NVM

#

.close

devout snowBOT
#
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devout snowBOT
#
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rotund gull
devout snowBOT
rotund gull
#

how do i find both points that have the same y, but that are integers?

#

domain is all real numbers given that the graph is to the degree of 5

#

but I don't understand the middle 2 fields... any help is much appreciated

#

turns out it was (to the left) 3, -36 and (to the right) 7, 28

#

but why?

devout snowBOT
#

@rotund gull Has your question been resolved?

rotund gull
#

.close

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#
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After 15 minutes, feel free to ping <@&286206848099549185>.
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wet herald
#

graphing

devout snowBOT
wet herald
#

so my question is the write the slope intercept form of the equation of the line through the given points

#

(-3,-3) (4,3)

#

I got y=6/7x but when I checked the answer sheet the answer was y=6/7x-3/7

#

and I'm confused as to where the -3/7 came from

devout snowBOT
#

@wet herald Has your question been resolved?

deep cove
#

Your y-intercept calculation may be wrong. It should not be 0. You may want to check on that 🙂

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deft bridge
#

Q: There are 20 used components in the box, 15 of which are working. Among them, 10 new components have been added (which are sure to work). The engineer takes randomly one. If it turns out to be working, how likely is it to be new?

I tried to solve the problem using
P(working) = 15/20 and P(new) = 10/20
15/20 * 10/20 = 3/8 (0.375)

This solution was not right. How should this be edited, as it doesn't seem as simple as calculating the odds of picking one working component and a new one?

devout snowBOT
#

@deft bridge Has your question been resolved?

devout snowBOT
#

@deft bridge Has your question been resolved?

topaz axle
#

It's just 10/25

#

the intuitive answer

#

P(working and new) / P(working) = (10/30)/(25/30)

deft bridge
#

I didn't note the +10 at all for some reason.. Thanks.

#

.close

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#
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pseudo basin
#

this is dumb as hell but i'm drawing a blank:

how do i show that $y \notin (x-1, y^2)$? i'm sure the statement is actually true but i am just blanking on how to prove it properly

(for context, that is an ideal in the ring $\bC[x,y]$)

woven radishBOT
pseudo basin
#

i would also like to avoid symbol-bashing if at all possible

#

i can show the original AG problem if anyone needs, though i'm pretty sure that i've reduced it to this correctly

devout snowBOT
#

@pseudo basin Has your question been resolved?

pseudo basin
#

fuck it

#

.close

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#
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deep quartz
#

I am experimenting with combining unlike terms. Can somebody on this server please take a look at this and, without criticizing the formatting or complaining that it's hard to read, take a look and tell me if I've done everything correctly? If so then I'm inclined to say that our entire system of mathematics is inherently flawed (which I've been trying to prove/fix for months now). But then I would sound pompous and mathematically undereducated, both of which are intermittently true. Thank you.

Let x² + x = y,
so that x(x) + x = y.

Let y(x) + x = z,
so that x + x = z/y
and 2x = z/y.

xx + x = x² + x
x + x = (x² + x)/x
(x[x] + x)/x

Let (x² + x) = y,
shown by (x[x] + x)/x
as (x² + x)/x
as (y)/x
as y/x
such that x² + x = y.

x² + x = y
= x(x) + x = y
x + x = y/x
2x = y/x
2x(x) = y
= 2x(1x) = y
= 2x¹(1x¹) = y
= 2x² = y

2x² = y
2x = √y
x = (√y)/2
2x = √y
2 = (√y)/x

x² + x = y
y = 2x²
x² + x = 2x²

Algebraically sound, yes?
But then it falls apart numerically.

x² + x = 2x²

1² + 1 = 2(1)²
1 + 1 = 2(1) = 2

2² + 2 = 2(2)²
= 4 + 2
= 2(4) = 6

3² + 3 = 3(3)²
= 9 + 3 = 3(9) = 27
12 = 27 🚫

4² + 4 = 4(4)²
16 + 4 = 4(16) 🚫

Any thoughts? In the meantime, I'll be working on 2 = (√y)/x.

deep quartz
#

You don't want Artificial Intelligence built on flawed mathematics, do you?

"No." The correct answer is "no."

#

@left robin I couldn't resist pinging you for round two.

left robin
#

This is wrong:
Let y(x) + x = z,
so that x + x = z/y

deep quartz
#

That's mega wrong

#

that fuck was I even doing there lmao

#

lemme go look

#

I see what I did, stupid careless mistakes @left robin brb

#

I just realize how late it was. I am genuinely sorry for pinging you at this hour. I hadn't realized what time it was. @left robin

#

To anyone available:

is it

(SET A)
y(x) + x = z
y(x)/x + x = z/x
y + x = z/x

and

y(x) + x = z
y(x)/y + x = z/y
x + x = z/y
2x = z/y

or is it

(SET B)
y(x) + x = z
(yx + x)/x = z/x
y + x/x = z/x
y + 1 = x/x
y + 1 = 1
y = 2

and

y(x) + x = z
(yx + x)/y = z/y
x + x/y = z/y

?

#

I feel like set B is the correct one but I'm not sure

#

It feels like a five-way stop and every way but the way I came leads off a steep cliff. >___>

devout snowBOT
#

@deep quartz Has your question been resolved?

devout snowBOT
#

@deep quartz Has your question been resolved?

devout snowBOT
#
Channel closed

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deep quartz
#

.reopen

devout snowBOT
#

deep quartz
#

I'm feeling stumped and could really use another set of eyes or two on this. Please && thank you. There are clear logical inconsistencies which are, for me, creating the mathematical equivalent of cognitive dissonance. Somewhat unpleasant. Am I hoping I'm just made some silly mistake somewhere.

ASSUME x = z + y
SO x = z + y
THEN y = x - z
AND z = x - y.

SO ASSUME 7 = 5 + 2
SO 7 = 5 + 2
THEN 2 = 7 - 5
AND 5 = 7 - 2.

SO x + z = y.

ASSUME x + x = y
SO x + x = y
THEN 2x = y
AND x = y/2
AND 2 = y/x.

SO ASSUME 7 + 7 = 14
SO 7 + 7 = 14
THEN 2(7) = 14
AND 7 = 14/2
AND 2 = 14/7.

Assume x² = y
So x² = y
Then x = √y
And y = x(x).

So assume 7² = 49
So 7² = 49
Then 7 = √49
And 49 = 7(7).

SO x² = y
THEN x(x) = y
AND x = y/x.

SO 3² = 9
THEN 3(3) = 9
AND 3 = 9/3.

%%%%%%%%%%%%%%%%%%

LET x² + x = y
SO x² = y - x
THEN x = √(y - x)
AND x = y - x².

SO 3² + 3 = 12
THEN 3² = 12 - 3
AND 3 = √(12 - 3)
AND 3 = 12 - 3².

SO x² + x = y
THEN (x • x) + x = y
AND x(x) + x = y
AND (y - x)/x = x
SO y/x - x/x = x
*SO y - x/x = x
(someone please tell me I've made an error on any arrangement of these two lines in particular unless I actually haven't, then don't)
BUT (y - x)/x =! y - (x/x)?
SO y - 1 = x
SO y = x + 1
SO x = y - 1.

SO 1² + 1 = 2
THEN (1 • 1) + 1 = 2
AND 1(1) + 1 = 2
AND (2 - 1)/1 = 1
SO 2/1 - 1/1 = 1/1 = 1
SO 2 - 1/1 = 1
SO 2 - 1 = 1
SO 2 = 1 + 1
SO 1 = 2 - 1

2² + 2 = 6
THEN (2 • 2) + 2 = 6
AND 2(2) + 2 = 6
AND (6 - 2)/2 = 2
SO 6/2 - 2/2 = 2
SO 6 - 2/2 = 2 = FALSE
BUT y - x/x = x = TRUE (see above
)
AND (6 - 2)/2 = TRUE
SO 6 - 2 = 2 = FALSE
BUT y - 1 = x TRUE
SO 6 = 2 + 1 = FALSE
BUT y = x + 1 = TRUE
SO 2 = 6 - 1 = FALSE
BUT x = y - 1 = TRUE.

y - x/x = x ?= TRUE?

What in the actual fuck is even going on here?

midnight dirge
#

...

#

maybe try

#

shortening the thing to your point

#

its a bit long atm

deep quartz
#

Everything included is imperative to its full comprehension.

stone stump
#

(y-x)/x=y/x-x/x=y/x-1

#

that's not the same as just y-x/x=y-1

#

(unless x=1)

#

the SO and THEN and AND don't help with the readability

midnight dirge
#

agree

#

its like adding a THEREFORE in front of each statement

deep quartz
#

I did add a few of those. Lol.

#

I use those to keep my own thoughts straight. Read around them.

midnight dirge
#

ok just

deep quartz
#

It isn't difficult to skim over something with the eyes, last I checked. Takes about a fraction of a second and requires minimal effort (and then none at all).

midnight dirge
#

ill just say

#

everytime u do a

#

divide by x

#

add a

#

x is not zero for every line after

#

u did quite a few divisions

#

and that is nearly always the source of errors

deep quartz
midnight dirge
pseudo basin
#

about half of that big message of yours is more or less walking in circles

deep quartz
pseudo basin
#

the meaningful part of any of this is that you go from y = x^2 + x to x = (y-x)/x = y/x - x/x, which is all correct

deep quartz
midnight dirge
#

...

pseudo basin
#

oh sorry, do you want to argue semantics???

deep quartz
#

Please take your undue hostility elsewhere. Thank you. @pseudo basin

midnight dirge
#

well

#

this is hillarious

pseudo basin
#

didn't even manage to get to my point...

deep quartz
pseudo basin
#

but ok, i'm out

deep quartz
pseudo basin
#

well i wasn't going to commit violations of tact at any point

#

but as i understood, you want me out.

dapper gazelle
midnight dirge
#

:c ann is super nice

pseudo basin
#

anyway!

dapper gazelle
#

If you really want a formal verifier run it through a calculator

midnight dirge
#

but is ok

deep quartz
dapper gazelle
#

run it through a calculator

pseudo basin
#

you go from y = x^2 + x to x = (y-x)/x = y/x - x/x, which is all fine and dandy
you also observe, correctly, that (y-x)/x in general need not equal y - x/x (i.e. y-1)
and then you seem surprised when that equality does indeed hold in a particular case, which one can only call a sheer coincidence.

deep quartz
dapper gazelle
#

Get an alternate calculator

deep quartz
pseudo basin
#

well sometimes things Just Happen

#

an equality that need not hold in general may sometimes become true for a particular choice of values for its variables.

#

there is usually not much significance to that fact.

deep quartz
deep quartz
pseudo basin
#

ah, no, it appears you've run with x=y-1 and in the last paragraph keep proclaiming it as true bc it happened to be true when you put x=1...

deep quartz
#

But I'm still not satisfied. How can it hold true with variable notation but then crash and burn so gloriously when the numerics are implemented?

pseudo basin
#

at no point does it crash and burn

#

what actually happened is that you made a hasty over-generalization.

#

and are suffering the consequences thereof.

#

your asterisked line

SO y - x/x = x
is the source of all these evils

deep quartz
deep quartz
pseudo basin
#

judge?

deep quartz
pseudo basin
#

you think i am making a value judgment here?

midnight dirge
#

kinda surprised u r actually helping him

deep quartz
restive river
#

can you guys help me out with this please

pseudo basin
arctic field
#

where did y - x/x = x even come from

restive river
#

ok

pseudo basin
deep quartz
deep quartz
dapper gazelle
#

,w x^2 + x - 1 = x

dapper gazelle
#

Amazing

midnight dirge
#

is that relavant

deep quartz
#

I've never really used Wolfram Alpha before. I'll ignore your sour demeanor and thank your for the suggestion, instead.

#

I think I just mispoke. Forgive me. I apologize. @dapper gazelle

pseudo basin
#

anyway

#

word of advice

deep quartz
#

But can you explain your contribution just now to me? Or was it intended to be obvious? I am still a rookie mathematician in every sense of n00bness about it lol.

deep quartz
dapper gazelle
deep quartz
pseudo basin
#

when you present your work for a math problem up for scrutiny, be it algebra or geometry or what
and people tell you that you messed up in a particular point in your argument/calculation/whatever
it means just that

#

it is never a value judgment

#

it is never a judgment on your personal character

#

nothing like that

dapper gazelle
deep quartz
# pseudo basin it is never a value judgment

It was your usage of the term "evil"
that I took an oppositional stance toward. Because I do these unusual things because I believe in a better world. That is why I wrongfully assumed.

vast rain
#

I was reading the long message

#

kinda lost on what it means at a high level

midnight dirge
#

there were a lot of unneccessary details which made it harder than needed to read

vast rain
#

like are the actual examples of the numbers necessary or am I ok just to skip them

deep quartz
vast rain
#

because I don't feel like checking all of that

deep quartz
#

(I wouldn't say "unnecessary" but only for the sake of that discussion)

vast rain
#

so I'm struggling to see what you concluded here

deep quartz
pseudo basin
vast rain
#

no like I don't know what you're actually stating

#

it's like you've written a bunch of statements down, some of which may be true and some of which may be false (I haven't checked them all)

#

but I don't see the high-level purpose of all of them

deep quartz
#

Start at %%%%%%%%%%%%%%%%%% for the meat of the post.

vast rain
#

like what unifies them all

#

SO x² + x = y
okay how did you conclude this

deep quartz
vast rain
#

can you just give a short definition of x and y

deep quartz
#

That was my mistake.

vast rain
#

you mean let x^2 + x = y?

deep quartz
arctic field
#

i still dont get how y - x/x = x

#

where did you even get that

pseudo basin
#

it's an ✨ algebraic screwup ✨

arctic field
#

amazing

pseudo basin
#

one i personally have seen many times, at that!

midnight dirge
#

from some addendum

vast rain
#

okay so you have y/x - x/x = x

how did you get to: y - x/x = x?

#

I agree that you can get to the former statement from your definition of "LET x^2 + x = y"

#

but I don't see how the latter statement follows from that

pseudo basin
#

do we need the same point made multiple times

vast rain
#

oh I must've missed that lol

dapper gazelle
deep quartz
midnight dirge
vast rain
#

I think we agree that y/x - x/x = x is ok

#

but not y - x/x = x

dapper gazelle
#

Oh

#

missing brackets

pseudo basin
#

yes as i said before

vast rain
#

In particular, a simple counterexample is where x = 2. In this case, you've defined y to be 6. Any you can see that y-x/x = 6-2/2 = 5 which is not equal to x

#

so there must be a problem with your logic between the two statements

#

or do you disagree?

deep quartz
vast rain
deep quartz
vast rain
#

that lets you get (y-x)/x = x at best

#

but that doesn't mean that y-1=x by any means

deep quartz
#

I must have that somewhere in here. Let me look. One moment. Sadness (or whatever that was before I said no) is no factor here.

vast rain
#

I don't understand these two steps

#

If you've made a typo, I suggest you go fix it so we can be 100% sure about what you're talking about

arctic field
deep quartz
# vast rain

Ah, yes. I will show you how the thought process looked in my head using pen and paper. Maybe that will help.

vast rain
#

I'd like to see how you got from the first statement to the second

deep quartz
#

@vast rain (The other day I also calculated a numerical value for i [I know this is impossible, yet...] and I would love for someone with your credentials to look over it. I spent about three hours on this server doing it publicly with other users correcting any mistakes as I went. The final calculation was i = 0.38107974512. I am aware that it must be erroneous.)

#

Now for that thought process I mentioned.

vast rain
#

like the imaginary unit?

#

i^2 = -1?

deep quartz
#

The solution to x² + 1 = 0.

#

Here is that thought process. I think I may have found my error (t)herein.

vast rain
#

well, it's a fairly easy mathematical proof to show that no real number satisfies the equation x^2 + 1 = 0

vast rain
#

but that doesn't let you conclude that y-x/x = x

#

that lets you conclude that y/x - x/x = x

#

which is consistent with how you defined x and y

deep quartz
#

Ah. I found it. Here it is:
y/x - x/x = x
y/x - 1 = x
y/x = x + 1
y/x - x = 1
@vast rain

#

But that isn't what was written and now I'm confused. ?__?

#

one sec

vast rain
#

yeah all of that is agreeable

deep quartz
#

Unless it was a transposition

vast rain
#

but that's not what was written

deep quartz
#

Which it may have been

vast rain
#

also you should check your work over computing the numerical value of i

#

because it certainly doesn't check out

deep quartz
#

Trying to work backwords from that point to figure out where I've gotten that from, I've tangentially gotten this (the following):

y/x - x/x = x
y/x - 1 = x
y/x = x + 1
y/x - x = 1
y - x = 1x
y - x = x
y = 2x
x = y/2

y - x/x = x
y - x = x²
y = x² - x
x = √(y + x)
x² = y + x

But still no luck on that peculiar line. Haven't quite given up yet though. I recall deriving (for lack of a better term) that line at least thrice over if not more and checking it against the similar parenthetical-inclusive entry. But now I cannot recall how I did so. Still trying tho. Although I feel like that (the above) included tangent is a fresh can of worms. Maybe. @vast rain

#

I already know

vast rain
#

how did you get from the first line to the second line?

deep quartz
#

I just saw ot

#

it

#

lol

#

yeah

#

whoops >___>

#

damn

#

Oh

#

Actually

#

I noticed my error before you did. Nevermind. 😋😇 I'll answer your recent question now.

#

That is another mistake. Thank you for correcting it. Here is the correction:

y/x - x = 1
y - x = 1 + x
y = 1 + 2x
y - 1 = 2x
x = (y - 1)/2

y = 1 + 2x
1 = y - 2x
1 + 2x = y

1 = y - 2x
1 - y = -2x
x = (1 - y)/-2

1 + 2x = y
2x = y - 1
2 = (y - 1)/x

2x = y - 1
2x - y = -1
2x = -1 + y
x = (-1 + y)/2
x - y = -1/2
x = -1/2 + y
-y = -1/2 - x
-y + x = -1/2
-1y + x = -1/2
(-1y + x)/-1 = (-1/2)/-1
(-1y + x)/y = (-1/2)/y

At this point I stopped and assumed more erroneous entries to be weeded out. I've underlined notably unusual suspects. @vast rain

vast rain
#

how did you get from the first line to the second?

#

I get y/x = 1+x, which is as close as I get

deep quartz
#

Is there; could there be; must there be a real number that sarisfies all of these conditions? Or would it be another sort of imaginary number?

vast rain
#

what conditions?

deep quartz
#

Another error. I always forget when shifting terms that it must be applied to that entire side of the equation rather than just its own coefficient. Or at least I'm pretty sure that is how it goes.

The correction:

y/x - x = 1
(y/x - x)x = 1x

What I did was this (is this actually erroneous as far as you presently conceive?):
y/x - x = 1
(y/x)x - x = 1/x
y - x = 1/x
[...]

deep quartz
# vast rain what conditions?

That is a good question. I suppose what I meant was the conditions of these variables (presently x & y) to function as variables, and their cons(is)tancy once assigned/ascribed with/by (a) value.

#

I'm sorry if that is poorly worded. It was a difficult question.

vast rain
#

also at the risk of sounding dismissive, there's likely no mathematical way you're going to be able to algebraically manipulate these things into anything other than something that's easily rearranged to y = x^2 + x. It's just not how it works. Someone more educated on the whole mathematical logic thing might be able to bring in some proof of completeness and soundness for a restricted system of mathematics that encompasses what you're using (I don't know enough to say that)

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but intuitively, there will always be a mistake in your algebraic manipulation if you're getting anything other than your assumptions

#

how did you get from the first line to the second?

deep quartz
vast rain
#

I mean you're not going to get anything deeper than what you've already defined: y = x^ 2 + x

dapper gazelle
vast rain
#

and I know there are issues with proving that mathematics itself is consistent, but I don't think you're going to show an inconsistency through these manipulations

deep quartz
dapper gazelle
#

What?

deep quartz
#

How is this system differentiated from traditional mathematics?

vast rain
#

as in the subset of algebraic manipulations you're using is probably proven to be complete and sound, i.e. what you're trying to do has already been proven to be impossible

dapper gazelle
#

did you just say no you to me?

deep quartz
deep quartz
deep quartz
#

j/k

deep quartz
dapper gazelle
#

What is your actual aim?

vast rain
#

anyway

#

before we get distracteed

deep quartz
vast rain
#

can you tell me how you got from the first line to the second line?

deep quartz
#

But I'll regret having said that.

vast rain
dapper gazelle
deep quartz
#

Because I know that that is impossible.

vast rain
#

but unfortunately, I think you need more powerful tools to do that

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simple numbers and summing them up

deep quartz
#

And then I hope to invent/discover a more consistent system as the fruit of my labors. (:

dapper gazelle
vast rain
#

I think that's proven, under some pretty weak assumptions, to be impossible without bringing in a higher level of mathematics

vast rain
deep quartz
vast rain
#

like I think that incompleteness is a really deep topic that maybe might be worth talking about

vast rain
deep quartz
vast rain
#

if you're interested in things like mathematical proof systems + logical systems, might be worth picking up a book on set theory and mathematical logic

deep quartz
vast rain
#

and so we can't really prove that our proof system won't derive statements that contradict each other

deep quartz
vast rain
#

so the alternative is that we define restricted proof systems which are only allowed to use certain things

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and then we use more powerful proof systems to prove that those proof systems are consistent within the more powerful proof system

deep quartz
vast rain
#

but I don't think that this is what you're doing here

dapper gazelle
deep quartz
deep quartz
dapper gazelle
#

• These channels are for pre-university homework-type questions

deep quartz
#

Perhaps truth is formally inconsistent. Who knows. Haha.

deep quartz
vast rain
#

there's a degree of self-reference involved, but the problem is that if you take mathematics as given, you can prove that there exist statements that are true that cannot be proven

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and further that sufficiently powerful proof systems cannot demonstrate their own consistency

vast rain
#

that's somewhat related. I think that's more in line with reverse mathematics

deep quartz
#

I deleted that post up there incidentally. Not a worry though lol.

deep quartz
deep quartz
# vast rain

We did get distracted but I'd really like to know if this is indeed erroneous or not. Lol sorry.

vast rain
#

I believe it is erroneous

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I don't see how you got from the first line to the second

vast rain
#

and I think the counterexample with x=2, y=6 is sufficient to show that.

deep quartz
#

Gonna take another few minutes to look it over. Maybe something will click.

vast rain
#

I'm pretty sure it was an oversight

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because I'm confident that the rules of basic algebraic manipulation are consistent lol

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the counterexample shows that whatever derivation you use will eventually derive 0=1

deep quartz
#

It interests me that it was those two lines where I noted that I must have made an error. But I only said that of 30+ minutes of verification. But now the logic of it has left me. Which kinda sucks lol. >:

deep quartz
midnight dirge
#

its a hoax

deep quartz
#

big math has to keep us invested

#

xD

deep quartz
vast rain
#

x = 2, y = 6

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y = x^2 + x, which satisfies your assumption

deep quartz
#

Could that have anything to do with the fact that zero = 1(0) (that is, one times [of] zero)? Meaning that it is a bit contradictory/paradoxical, for the empty/null set to actually technically be "one" empty/null set (because this implies that one is defined).

deep quartz
vast rain
#

the point is that your derivation is going to produce false statements

deep quartz
vast rain
#

and these are worthless, because if you can prove a false statement, then you can prove anything

deep quartz
#

I may be approach a solution to the peculiarity. One moment.

vast rain
#

I don't think you can

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it'd be tantamount to proving that 2 = 1 or something ridiculous like that

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which might be what you're trying to do

deep quartz
vast rain
#

but mathematicians will tell you this is almost certain to fail

deep quartz
#

But that is a bit philosphical and semantic-driven.

deep quartz
vast rain
#

then your proofs are likely not accepted because they contain flaws

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technically speaking, your proof system is considered inconsistent, but in reality, we just throw those proof systems in the dustbin

dapper gazelle
# deep quartz I've proven that 1 = 0 in the past. More than once, I think. Somewhere in my not...

Confirmation bias is the tendency to search for, interpret, favor, and recall information in a way that confirms or supports one's prior beliefs or values. People display this bias when they select information that supports their views, ignoring contrary information, or when they interpret ambiguous evidence as supporting their existing attitude...

Cognitive biases are systematic patterns of deviation from norm and/or rationality in judgment. They are often studied in psychology, sociology and behavioral economics.Although the reality of most of these biases is confirmed by reproducible research, there are often controversies about how to classify these biases or how to explain them. Sever...

deep quartz
dapper gazelle
vast rain
dapper gazelle
#

By that I mean, being able to 'prove anything'

vast rain
#

I always made a joke to my friends that my proof system is that "I'm always right"

dapper gazelle
deep quartz
deep quartz
vast rain
dapper gazelle
deep quartz
vast rain
#

and while that may technically be an unusual way to look at things, in reality, people will just laugh at you

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and the second option allows us to actually engage in logic, even in our daily lives, and this logic has proven useful

deep quartz
deep quartz
deep quartz
#

I think I just figured it out. @vast rain

vast rain
# deep quartz That is nothing new to me. Unfortunately.

well, if you accept your proofs as valid, then you also have to accept absurd things like "I (Saccharine) am the Pope."
A humorous proof from 0=1:

  1. 1 = 2. (Add 1 to both sides)
  2. The Pope and I are two men.
  3. The Pope and I are one man (apply step 1)
  4. I am the Pope.
#

I just don't think you're going to get anywhere with doing algebraic manipulations to try to prove something impossible. It doesn't work that way.
And for what it's worth, the way I find mistakes in your work is simply by looking for things that look impossible and searching for the last part when things were reducible to y = x^2 + x

deep quartz