#help-27
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tho
oh
its a number that makes the denominator = 0 but mustnt the numerator
what makes the denominator 0?
x
0
does substituting 0 in place of x in (x+3) give us 0?
yes
@restive river Has your question been resolved?
for horizontal and slant asymptotes tho?
sorry im having trouble understanding the lessons from my class ;(
thanks in advance to those who answer <3
@restive river Has your question been resolved?
<@&286206848099549185>
@restive river Has your question been resolved?
@restive river Has your question been resolved?
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If a triangle has sides ½(n!), (n-2)!, (2-n)!, How do I find it's numerical area?
we can use heron's formula
@little jewel Has your question been resolved?
Huh, wouldn't that end up with a super sized unsimplifiable square root?
Ah damn
there must be another way
<@&286206848099549185> any hint would be much appreciated
@little jewel Has your question been resolved?
Well
Factorials are not defined in any sort of way for negative integers
Do we know n is an integer then?
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It's not mentioned but yeah should be since it's in a factorial
so n=2 is the only consistent choice
otherwise either n-2 or 2-n will be negative
and you can't take the factorial of a negative integer
Interesting
not even with the gamma function (extension of factorials to real numbers)
Not familiar with that, but I will try to solve it with herons formula when n is 2
that'll work yeah
Ah an equilateral
Ig herons is too long, it's area is gonna be sin45
Gonna verify one sec
Ah doesn't work
All 3 sides should equal 1
I used 2 sides*sine of included angle
that works too
wouldn't the included angle be 60?
Jesus Christ my bad
Yeah sqrt(3)/2 my brain automatically went for the 45 degree angles for some reasons
Thanks guys!
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I dont get how to do this
@frozen flicker Has your question been resolved?
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@frozen flicker Has your question been resolved?
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@half minnow
i think i know the answer to this
just want you to
confirm
so the first one, it converges at 1
because 1/n=0
and the second one
the denominator is larger if i compare the numbers one by one
so
2>1
4>3
6>5
is that right?
u gotta prove them tho right..?
this looks like real analysis
yea where did you get it from
tf
it's just a conundrum because the way you did it is intuitive enough
and it relies on facts established beforehand
so if this wasnt a real analysis course, you are correct
but how would i actually prove it ?
monotonicity means bounded??
because it's intuitively increasing
that doesn't need proof??
monotonicity doesnt imply bounded
montonically bounded does imply convergent tho
so you have to show the sequence is monotonic AND bounded separately
like how??? if n is approaching infinity, 1/n just becomes smaller so the entire thing is increasing?
like
how do you prove that
isn't that just fact
that's the proof of monotonicity
do i do that by induction?
you can just substitute the definition in
how
substitute definitions in, choose a convenient value of B
right
ur subtracting something from 1, so its clearly less than 2
at the same time, it will always be greater than or equal to 0
just show that last part and you are golden
wait so now it's lim 1-1/n<= 1
yea but thats guaranteed
n is a natural
and so 1/n will always be >= 0
therefore 1-1/n <= 1
ew creepy
yea perfect but just show 1-1/n >= 0 so you can drop the absolute value bars
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when is a DE linear?
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So i walked into my class and i dont understand how to do anything came in blind and i would like some assistance on my hw
what's the question?
"Solve the following equation for a"
err
alright so you want to isolate a (essentially, "remove" the 5/6 from it)
the qn only gave u this?
what can you multiply by 5/6 to get 1?
The yt video didnt help btw
because you want 1a
oh in terms of n?
yeah
okiee makes sense
@real mist
1
Yeah
wait let me get paper
okii
back
hii
Its 0.03 right?
what is 0.03?
the value of n?
Idk
aren’t u finding a in terms of n
oki wait
if u have 2x = 2
u divide both sides by 2
yeah
4.5
Oh
yesh
errr if I’m not wrong that’s going to be a never ending decimal
isolate the a?
yesh
that’s why we do this
yesh gd!
so what is this
1 divided by 5/6
1.2
a=1.2?
1.2 n
a=1.2n?
just write 1.2n
1.2n?
no need write a
Yeah
okii
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ok t*
I have no clue on what to do, I think i have to dispute the numbers but it comes out as 1b + 3f +1a=g i am stuck in the "1b+3f+1a=1g" because i do not know what to do next!
Do you know what it means to solve for a?
nrl
I got put into this class when i didnt sign up for it infact i failed the algbra test idk how im in it
A hint: the equation (b+3f)a = g is solved for g
Que?
make a stand alone on one site
To dispute something is to argue about it
Distribute?
YEAH
You needn't to if you just want to isolate a
needn't?
no
Need not
Oh
Ok what if you have 3X = 6 can you find the value of X
Exactly you divided by 3 to isolate X
How would I do it in AB = C
If I want to Find B
No you divide both sides by A like you did in this example
You simply write it as C ÷ B
You cannot find the value of the division so you leave it as symbols
OH
So basically, you have AB = C and you want to isolate B right?
Yeah hopefully they got it
Oh my god I realized I mixed it up
?
@real mist Ayo we are diving by A to isolate B my bad
Oh
Well how did it turn out?
Idk i got stuck n redoing it
When you’re doing a problem like that, just remember that you can do any operation on one side of the equal sign. However, you always need to do the same thing on the other side of the equality sign. In your previous example, you had 3X = 6 and you needed to to isolate X. What you can do is divide both side by 3. On the left, you have 3X/3 which is equal to B and on the right, you have 6/3 which is equal to 2. You’re left with X = 2
so
You can apply the same thing with AB = C
my thing is on the question im doing "(b+3f)a=g" I have 3 letters on the other side
what do i do if i got 3?
What’s your question?

I’m not sure I understand this question properly, but I would have a = g/(b + 3f)
I don’t know what’s the thing with capitalization though
thats for the awnser so i dont f*** it up
Ha ok I think I might know where your confusion is
When you divide a polynomial by the same polynomial, you get 1
I don't think they know what a polynomial is
nope
2
Is poly
It’s basically a thing with letters like X + 5X squared
It’s not the exact definition, but that’s it in a nutshell
Like i said i didnt go to summer school for algbra and i failed that test im litrally going in w/o any info like NOTHING I didnt even know what 3x=6 was
If you have X/X, what do you get?
1
Oh
Ok, just remember that when you divide a thing by the same thing, you always get 1
3/3 is 1
X/X is 1
Ye i understand that
(X + Y)/(X + Y) is 1
This
You wanted to do distribution earlier
You know that you have to divide both sides by B + 3F
If you want to isolate a, I wouldn’t recommend you distribute
Ah yeah my bad
Just divide both sides by B + 3F
They seem to need some practice in arithmetic
arthmetic?
I wouldn't really consider this algebra, it's more arithmetic, but I guess you shouldn't worry about the difference for now
o
On the left , you have (b + 3f)/(b + 3f)
You missed the a
Ha yeah sorry
I think I get where you’re confused
so like this?
Yes
In this case, a is multiplied
By the way the a is multiplied as kvlt mentioned, it's (b+3f) x a, not +
But the answer is correct
Kvlt?
You could think of it like this if you understand the AB = C example, b+3f is just a big symbol you are dividing by,
Ha ok. That’s what i originally thought
Yeah satanic kvlt the person helping you rn lol
Well I hope this has somewhat cleared up how this problem is solved
If you have AB/A, you can cancel the As
thats the way i turn it in?
Yeah looks fine
Yeah you did it! And do take those summer classes next time
My pleasure
so
it just changed on me to a whole diffrent unit
w**
all i do is basic algbra right
Exactly
Be careful with the inequalitie sign.
Yes that
Why tho-
when dividing both sides by a negative number, the sign switches around
Exactly
Ha cool
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bro
Yes
9w-36w>w+24 I collected terms
9w-36w is not 45w
I have no clue what that +36 is
Can you answer this
My man
?
What's 3-9
Yes so what's 9-36
-27w
Ye now try to solve it
-4
Sure
Yeah
My maaan
?
-7-2
-9
Then why -5c
I am not sure what you are adding -7c-2c is -9c
because i had to do what i did for both numbers-
What is your thought process when doing -7-2
When I put collected the -2c i added it so i went to the -7c and added 2c what got -5c
You do realize -7-2 is the same as -7c-2c
yeah
wait
i fucked up even after that-
Lemme redo-
so now im stuck
Thats just 0
so do i cancel it out right?
i feel dumb asf rn
Idk what's the image about but yeah c< 0
1 was screwed so all the ones that followed were screwed but if you add the c in 3rd it could be fixed
Clarify
And that's fine
O
0 is a constant
so
Solve it normally when you're at -9c > -4c+6c
O
Is that an o or 0
How
My man god forbid what's 6-4
2
Then why 10
It's -4+6
And you are missing the c
how did u get 2
Look what do you do to isolate X in 2x>x +1
That wouldn't work since we still have X on both sides
Look take the x from the right and make it negative on the left, are you familiar with how to do this
Remember this
yeah
but i dont understand when to like do both and to not
wait ill show u
NVM
like i dont know when to do what
If you have the same variable on both sides, you need to get all the terms with variables on the same side, and everything else that doesn't have a variable to the other. That's when you need to do the opposite operation. If the variables are on the same side, you just need to perform the math with that sign
That sign meaning don't do the opposite operation with that variable
Yo dldh can you continue helping them with this problem, I suck at helping and it's 4 am so i gotta sleep
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how do i find both points that have the same y, but that are integers?
domain is all real numbers given that the graph is to the degree of 5
but I don't understand the middle 2 fields... any help is much appreciated
turns out it was (to the left) 3, -36 and (to the right) 7, 28
but why?
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graphing
so my question is the write the slope intercept form of the equation of the line through the given points
(-3,-3) (4,3)
I got y=6/7x but when I checked the answer sheet the answer was y=6/7x-3/7
and I'm confused as to where the -3/7 came from
@wet herald Has your question been resolved?
Your y-intercept calculation may be wrong. It should not be 0. You may want to check on that 🙂
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Q: There are 20 used components in the box, 15 of which are working. Among them, 10 new components have been added (which are sure to work). The engineer takes randomly one. If it turns out to be working, how likely is it to be new?
I tried to solve the problem using
P(working) = 15/20 and P(new) = 10/20
15/20 * 10/20 = 3/8 (0.375)
This solution was not right. How should this be edited, as it doesn't seem as simple as calculating the odds of picking one working component and a new one?
@deft bridge Has your question been resolved?
@deft bridge Has your question been resolved?
It's just 10/25
the intuitive answer
P(working and new) / P(working) = (10/30)/(25/30)
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this is dumb as hell but i'm drawing a blank:
how do i show that $y \notin (x-1, y^2)$? i'm sure the statement is actually true but i am just blanking on how to prove it properly
(for context, that is an ideal in the ring $\bC[x,y]$)
Ann
i would also like to avoid symbol-bashing if at all possible
i can show the original AG problem if anyone needs, though i'm pretty sure that i've reduced it to this correctly
@pseudo basin Has your question been resolved?
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I am experimenting with combining unlike terms. Can somebody on this server please take a look at this and, without criticizing the formatting or complaining that it's hard to read, take a look and tell me if I've done everything correctly? If so then I'm inclined to say that our entire system of mathematics is inherently flawed (which I've been trying to prove/fix for months now). But then I would sound pompous and mathematically undereducated, both of which are intermittently true. Thank you.
Let x² + x = y,
so that x(x) + x = y.
Let y(x) + x = z,
so that x + x = z/y
and 2x = z/y.
xx + x = x² + x
x + x = (x² + x)/x
(x[x] + x)/x
Let (x² + x) = y,
shown by (x[x] + x)/x
as (x² + x)/x
as (y)/x
as y/x
such that x² + x = y.
x² + x = y
= x(x) + x = y
x + x = y/x
2x = y/x
2x(x) = y
= 2x(1x) = y
= 2x¹(1x¹) = y
= 2x² = y
2x² = y
2x = √y
x = (√y)/2
2x = √y
2 = (√y)/x
x² + x = y
y = 2x²
x² + x = 2x²
Algebraically sound, yes?
But then it falls apart numerically.
x² + x = 2x²
1² + 1 = 2(1)²
1 + 1 = 2(1) = 2
2² + 2 = 2(2)²
= 4 + 2
= 2(4) = 6
3² + 3 = 3(3)²
= 9 + 3 = 3(9) = 27
12 = 27 🚫
4² + 4 = 4(4)²
16 + 4 = 4(16) 🚫
Any thoughts? In the meantime, I'll be working on 2 = (√y)/x.
You don't want Artificial Intelligence built on flawed mathematics, do you?
"No." The correct answer is "no."
@left robin I couldn't resist pinging you for round two.
This is wrong:
Let y(x) + x = z,
so that x + x = z/y
That's mega wrong
that fuck was I even doing there lmao
lemme go look
I see what I did, stupid careless mistakes @left robin brb
I just realize how late it was. I am genuinely sorry for pinging you at this hour. I hadn't realized what time it was. @left robin
To anyone available:
is it
(SET A)
y(x) + x = z
y(x)/x + x = z/x
y + x = z/x
and
y(x) + x = z
y(x)/y + x = z/y
x + x = z/y
2x = z/y
or is it
(SET B)
y(x) + x = z
(yx + x)/x = z/x
y + x/x = z/x
y + 1 = x/x
y + 1 = 1
y = 2
and
y(x) + x = z
(yx + x)/y = z/y
x + x/y = z/y
?
I feel like set B is the correct one but I'm not sure
It feels like a five-way stop and every way but the way I came leads off a steep cliff. >___>
@deep quartz Has your question been resolved?
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I'm feeling stumped and could really use another set of eyes or two on this. Please && thank you. There are clear logical inconsistencies which are, for me, creating the mathematical equivalent of cognitive dissonance. Somewhat unpleasant. Am I hoping I'm just made some silly mistake somewhere.
ASSUME x = z + y
SO x = z + y
THEN y = x - z
AND z = x - y.
SO ASSUME 7 = 5 + 2
SO 7 = 5 + 2
THEN 2 = 7 - 5
AND 5 = 7 - 2.
SO x + z = y.
ASSUME x + x = y
SO x + x = y
THEN 2x = y
AND x = y/2
AND 2 = y/x.
SO ASSUME 7 + 7 = 14
SO 7 + 7 = 14
THEN 2(7) = 14
AND 7 = 14/2
AND 2 = 14/7.
Assume x² = y
So x² = y
Then x = √y
And y = x(x).
So assume 7² = 49
So 7² = 49
Then 7 = √49
And 49 = 7(7).
SO x² = y
THEN x(x) = y
AND x = y/x.
SO 3² = 9
THEN 3(3) = 9
AND 3 = 9/3.
%%%%%%%%%%%%%%%%%%
LET x² + x = y
SO x² = y - x
THEN x = √(y - x)
AND x = y - x².
SO 3² + 3 = 12
THEN 3² = 12 - 3
AND 3 = √(12 - 3)
AND 3 = 12 - 3².
SO x² + x = y
THEN (x • x) + x = y
AND x(x) + x = y
AND (y - x)/x = x
SO y/x - x/x = x
*SO y - x/x = x (someone please tell me I've made an error on any arrangement of these two lines in particular unless I actually haven't, then don't)
BUT (y - x)/x =! y - (x/x)?
SO y - 1 = x
SO y = x + 1
SO x = y - 1.
∴
SO 1² + 1 = 2
THEN (1 • 1) + 1 = 2
AND 1(1) + 1 = 2
AND (2 - 1)/1 = 1
SO 2/1 - 1/1 = 1/1 = 1
SO 2 - 1/1 = 1
SO 2 - 1 = 1
SO 2 = 1 + 1
SO 1 = 2 - 1
∴
2² + 2 = 6
THEN (2 • 2) + 2 = 6
AND 2(2) + 2 = 6
AND (6 - 2)/2 = 2
SO 6/2 - 2/2 = 2
SO 6 - 2/2 = 2 = FALSE
BUT y - x/x = x = TRUE (see above)
AND (6 - 2)/2 = TRUE
SO 6 - 2 = 2 = FALSE
BUT y - 1 = x TRUE
SO 6 = 2 + 1 = FALSE
BUT y = x + 1 = TRUE
SO 2 = 6 - 1 = FALSE
BUT x = y - 1 = TRUE.
y - x/x = x ?= TRUE?
What in the actual fuck is even going on here?
...I already have. Unfortunately.
Everything included is imperative to its full comprehension.
(y-x)/x=y/x-x/x=y/x-1
that's not the same as just y-x/x=y-1
(unless x=1)
the SO and THEN and AND don't help with the readability
I did add a few of those. Lol.
I use those to keep my own thoughts straight. Read around them.
ok just
It isn't difficult to skim over something with the eyes, last I checked. Takes about a fraction of a second and requires minimal effort (and then none at all).
ill just say
everytime u do a
divide by x
add a
x is not zero for every line after
u did quite a few divisions
and that is nearly always the source of errors
What do you mean by this?
this
about half of that big message of yours is more or less walking in circles
x is no zero for any of these calculations. Yet. Lol.
the meaningful part of any of this is that you go from y = x^2 + x to x = (y-x)/x = y/x - x/x, which is all correct
You say circle, which gets me back to where I started. I prefer to envision it as a spiral, ending in a new destination altogether.
...
oh sorry, do you want to argue semantics???
I wasn't arguing by any means. but now I'm not appreciating your hostile tone.
Please take your undue hostility elsewhere. Thank you. @pseudo basin
didn't even manage to get to my point...
I'm not laughing and neither were you.
but ok, i'm out
You're still welcome to make your point if you can make it tactfully.
well i wasn't going to commit violations of tact at any point
but as i understood, you want me out.
It's actually very difficult to skim through poorly written deduction
:c ann is super nice
anyway!
If you really want a formal verifier run it through a calculator
but is ok
Then can you suggested a preferential format so that I might restructure it?
run it through a calculator
you go from y = x^2 + x to x = (y-x)/x = y/x - x/x, which is all fine and dandy
you also observe, correctly, that (y-x)/x in general need not equal y - x/x (i.e. y-1)
and then you seem surprised when that equality does indeed hold in a particular case, which one can only call a sheer coincidence.
Yes. I saw it this first time. What do I do when my calculator (which is Google) begins to refuse (as it seemed) to provide further calculations?
Get an alternate calculator
I do believe in coincidence, though unexpectedly so.
well sometimes things Just Happen
an equality that need not hold in general may sometimes become true for a particular choice of values for its variables.
there is usually not much significance to that fact.
This seems good and fair to me. Any recommendations?
Lol tru
ah, no, it appears you've run with x=y-1 and in the last paragraph keep proclaiming it as true bc it happened to be true when you put x=1...
But I'm still not satisfied. How can it hold true with variable notation but then crash and burn so gloriously when the numerics are implemented?
at no point does it crash and burn
what actually happened is that you made a hasty over-generalization.
and are suffering the consequences thereof.
your asterisked line
SO y - x/x = x
is the source of all these evils
Haha. I can appreciate that. But I still don't quite understand. I did not equate x with 1 until after establishing the substratum of it all with variables. Or so I thought.
You are quick to judge a thing.
judge?
Yes.
you think i am making a value judgment here?
kinda surprised u r actually helping him
I did, yes. Now you have administered a measure of doubt.
can you guys help me out with this please
@restive river get your own channel. #❓how-to-get-help
where did y - x/x = x even come from
ok
ok well let me tell you that in fact there was no value judgment there at all
The pits of Hell, apparently. lmfao.
I understand. Then I apologize for assigning an unintended value to your statement.
,w x^2 + x - 1 = x
Amazing
is that relavant
I've never really used Wolfram Alpha before. I'll ignore your sour demeanor and thank your for the suggestion, instead.
I think I just mispoke. Forgive me. I apologize. @dapper gazelle
But can you explain your contribution just now to me? Or was it intended to be obvious? I am still a rookie mathematician in every sense of n00bness about it lol.
Yes, ma'am?
On assumption of y = x(x+1), then if y - x/x = x is an identity then it means nothing went wrong
I'm wondering the same thing.
when you present your work for a math problem up for scrutiny, be it algebra or geometry or what
and people tell you that you messed up in a particular point in your argument/calculation/whatever
it means just that
it is never a value judgment
it is never a judgment on your personal character
nothing like that
But if it only holds for certain values of x, then an equation is being solved, rather someone manipulating both sides of an identity
It was your usage of the term "evil"
that I took an oppositional stance toward. Because I do these unusual things because I believe in a better world. That is why I wrongfully assumed.
there were a lot of unneccessary details which made it harder than needed to read
like are the actual examples of the numbers necessary or am I ok just to skip them
I'm sorry about that. I wanted to ensure complete processional transparency.
because I don't feel like checking all of that
The preliminary examples are unnecessary. I will cordone them off. Just a minute.
(I wouldn't say "unnecessary" but only for the sake of that discussion)
so I'm struggling to see what you concluded here
So am I! 😂
i use "evil" in this context in a somewhat tongue in cheek way to mean "things that get in your way"
no like I don't know what you're actually stating
it's like you've written a bunch of statements down, some of which may be true and some of which may be false (I haven't checked them all)
but I don't see the high-level purpose of all of them
Start at %%%%%%%%%%%%%%%%%% for the meat of the post.
I haven't quite figured that out yet. Are you speaking mathematically, or of my personal intention for doing all this?
can you just give a short definition of x and y
no I mean mathematically
That should read "LET x^2 + x = y"
That was my mistake.
you mean let x^2 + x = y?
Yessir. My mistake 2.0 lol.
it's an ✨ algebraic screwup ✨
amazing
one i personally have seen many times, at that!
from some addendum
okay so you have y/x - x/x = x
how did you get to: y - x/x = x?
I agree that you can get to the former statement from your definition of "LET x^2 + x = y"
but I don't see how the latter statement follows from that
do we need the same point made multiple times
oh I must've missed that lol
bruh no quoting me
I thought someone had stated this to be correct previously?
LOL
In particular, a simple counterexample is where x = 2. In this case, you've defined y to be 6. Any you can see that y-x/x = 6-2/2 = 5 which is not equal to x
so there must be a problem with your logic between the two statements
or do you disagree?
I know that adding and subtracting fractions requires a common denominator. And so this intended to express that mechanic, if I recall.
but that doesn't mean that you can simply get rid of the /x behind the y
I agree that a problem can currently be perceived to exist regarding these calculations. I haven't said beyond that.
I must have that somewhere in here. Let me look. One moment. Sadness (or whatever that was before I said no) is no factor here.
I don't understand these two steps
If you've made a typo, I suggest you go fix it so we can be 100% sure about what you're talking about
Please pardon me. One moment.
my mans trademarked the word amazing
Ah, yes. I will show you how the thought process looked in my head using pen and paper. Maybe that will help.
I'd like to see how you got from the first statement to the second
@vast rain (The other day I also calculated a numerical value for i [I know this is impossible, yet...] and I would love for someone with your credentials to look over it. I spent about three hours on this server doing it publicly with other users correcting any mistakes as I went. The final calculation was i = 0.38107974512. I am aware that it must be erroneous.)
Now for that thought process I mentioned.
what do you mean by i?
like the imaginary unit?
i^2 = -1?
Yes. √-1. That i.
The solution to x² + 1 = 0.
Here is that thought process. I think I may have found my error (t)herein.
well, it's a fairly easy mathematical proof to show that no real number satisfies the equation x^2 + 1 = 0
every step in there is correct
but that doesn't let you conclude that y-x/x = x
that lets you conclude that y/x - x/x = x
which is consistent with how you defined x and y
Yes. You're right. I cannot for the life of me recall where that came from (yet). It must have come from somewhere. Another moment, please.
Ah. I found it. Here it is:
y/x - x/x = x
y/x - 1 = x
y/x = x + 1
y/x - x = 1
@vast rain
But that isn't what was written and now I'm confused. ?__?
one sec
yeah all of that is agreeable
Unless it was a transposition
but that's not what was written
Which it may have been
also you should check your work over computing the numerical value of i
because it certainly doesn't check out
Trying to work backwords from that point to figure out where I've gotten that from, I've tangentially gotten this (the following):
y/x - x/x = x
y/x - 1 = x
y/x = x + 1
y/x - x = 1
y - x = 1x
y - x = x
y = 2x
x = y/2
y - x/x = x
y - x = x²
y = x² - x
x = √(y + x)
x² = y + x
But still no luck on that peculiar line. Haven't quite given up yet though. I recall deriving (for lack of a better term) that line at least thrice over if not more and checking it against the similar parenthetical-inclusive entry. But now I cannot recall how I did so. Still trying tho. Although I feel like that (the above) included tangent is a fresh can of worms. Maybe. @vast rain
I already know
how did you get from the first line to the second line?
I just saw ot
it
lol
yeah
whoops >___>
damn
Oh
Actually
I noticed my error before you did. Nevermind. 😋😇 I'll answer your recent question now.
That is another mistake. Thank you for correcting it. Here is the correction:
y/x - x = 1
y - x = 1 + x
y = 1 + 2x
y - 1 = 2x
x = (y - 1)/2
y = 1 + 2x
1 = y - 2x
1 + 2x = y
1 = y - 2x
1 - y = -2x
x = (1 - y)/-2
1 + 2x = y
2x = y - 1
2 = (y - 1)/x
2x = y - 1
2x - y = -1
2x = -1 + y
x = (-1 + y)/2
x - y = -1/2
x = -1/2 + y
-y = -1/2 - x
-y + x = -1/2
-1y + x = -1/2
(-1y + x)/-1 = (-1/2)/-1
(-1y + x)/y = (-1/2)/y
At this point I stopped and assumed more erroneous entries to be weeded out. I've underlined notably unusual suspects. @vast rain
how did you get from the first line to the second?
I get y/x = 1+x, which is as close as I get
Is there; could there be; must there be a real number that sarisfies all of these conditions? Or would it be another sort of imaginary number?
what conditions?
Another error. I always forget when shifting terms that it must be applied to that entire side of the equation rather than just its own coefficient. Or at least I'm pretty sure that is how it goes.
The correction:
y/x - x = 1
(y/x - x)x = 1x
What I did was this (is this actually erroneous as far as you presently conceive?):
y/x - x = 1
(y/x)x - x = 1/x
y - x = 1/x
[...]
That is a good question. I suppose what I meant was the conditions of these variables (presently x & y) to function as variables, and their cons(is)tancy once assigned/ascribed with/by (a) value.
I'm sorry if that is poorly worded. It was a difficult question.
also at the risk of sounding dismissive, there's likely no mathematical way you're going to be able to algebraically manipulate these things into anything other than something that's easily rearranged to y = x^2 + x. It's just not how it works. Someone more educated on the whole mathematical logic thing might be able to bring in some proof of completeness and soundness for a restricted system of mathematics that encompasses what you're using (I don't know enough to say that)
but intuitively, there will always be a mistake in your algebraic manipulation if you're getting anything other than your assumptions
how did you get from the first line to the second?
I am not quite sure what this (the above quoted), or any of that (the above posted), meant or means. Sorry. 😅
I mean you're not going to get anything deeper than what you've already defined: y = x^ 2 + x
If you assume x=x don't expect to get x = x + 1 unless x = x implies x = x + 1 in the system you are working in.
and I know there are issues with proving that mathematics itself is consistent, but I don't think you're going to show an inconsistency through these manipulations
I'm working in an alternative system of mathematics that perfectly follows the rules of the standard system...?
What?
How is this system differentiated from traditional mathematics?
as in the subset of algebraic manipulations you're using is probably proven to be complete and sound, i.e. what you're trying to do has already been proven to be impossible
did you just say no you to me?
I think I was confused by what you said lol.
wat
but no I literally did not say that in any form on any channel of communication(s) lmao
What is your actual aim?
To disprove modern mathematics.
can you tell me how you got from the first line to the second line?
But I'll regret having said that.
the term of art for this is to demonstrate the inconsistency of modern mathematics
Don't do this in the help channels
Because I know that that is impossible.
but unfortunately, I think you need more powerful tools to do that
simple numbers and summing them up
Yessir. I like your phrasing much better than my own.
And then I hope to invent/discover a more consistent system as the fruit of my labors. (:
Seriously not a fit for the help channels either way
I think that's proven, under some pretty weak assumptions, to be impossible without bringing in a higher level of mathematics
hmm in this case, I agree. I dunno if it would include some of the deeper stuff in mathematical logic though
But I am a rookie mathematician seeking help from wiser a counsel. Is this not the case?
like I think that incompleteness is a really deep topic that maybe might be worth talking about
I'm just going to say that it's very unlikely that just using your techniques you'll be able to demonstrate anyhting
Some "incompleteness theorem" rings a bell in my mind. I am interested.
if you're interested in things like mathematical proof systems + logical systems, might be worth picking up a book on set theory and mathematical logic
Meh. That's okay then. I also enjoy it, just for the fun of it all. Raw calculation is immensely satisfying to me.
basically one of the deep philosophical problems in mathematics that emerged is that, in general, a mathematical proof system cannot show itself to be consistent
and so we can't really prove that our proof system won't derive statements that contradict each other
I'm definitely interested in set theory on a more philosophical level ("creatio ex nihilo").
so the alternative is that we define restricted proof systems which are only allowed to use certain things
and then we use more powerful proof systems to prove that those proof systems are consistent within the more powerful proof system
Ah. Sounds like the same complaint folks have about God/the Bible. How interesting.
but I don't think that this is what you're doing here
I should have seen this vague mix of words at first then.
"experimenting with combining unlike terms"
Make your aim clear before communication.
well, it's more mathematical
Have I not done so at any point? And yet I have not the slightest inkling of your own intentions here in your criticism of my post(s). That isn't quite fair to me.
Indeed. So likely closed to truth (but only perhaps).
• These channels are for pre-university homework-type questions
Perhaps truth is formally inconsistent. Who knows. Haha.
Ah. In that case, you were correct. I had not seen that prior to using the help channels in recent days.
I wouldn't say that. I don't think it's the same issue as the complaints against religion, which mostly involve circularity
there's a degree of self-reference involved, but the problem is that if you take mathematics as given, you can prove that there exist statements that are true that cannot be proven
and further that sufficiently powerful proof systems cannot demonstrate their own consistency
oh yikes lol
that's somewhat related. I think that's more in line with reverse mathematics
Are there any pertinent examples?
I deleted that post up there incidentally. Not a worry though lol.
examples of this principle, I mean(t).
We did get distracted but I'd really like to know if this is indeed erroneous or not. Lol sorry.
Wherein?
Yeah, and I still never figured out where the y - x/x = x. I sure wish I could because that would really help. Maybe it was truly just an oversight. Could've be, could be.
Gonna take another few minutes to look it over. Maybe something will click.
I'm pretty sure it was an oversight
because I'm confident that the rules of basic algebraic manipulation are consistent lol
the counterexample shows that whatever derivation you use will eventually derive 0=1
It interests me that it was those two lines where I noted that I must have made an error. But I only said that of 30+ minutes of verification. But now the logic of it has left me. Which kinda sucks lol. >:
there u go, math is fake
yay
winner winner chicken dinner
its a hoax
What counterexample? And how will this occur?
I gave you a counterexample
x = 2, y = 6
y = x^2 + x, which satisfies your assumption
Could that have anything to do with the fact that zero = 1(0) (that is, one times [of] zero)? Meaning that it is a bit contradictory/paradoxical, for the empty/null set to actually technically be "one" empty/null set (because this implies that one is defined).
Ah. Where does 0 = 1 come into play?
0=1 is just a placeholder for any false statement
the point is that your derivation is going to produce false statements
Understood.
and these are worthless, because if you can prove a false statement, then you can prove anything
I may be approach a solution to the peculiarity. One moment.
I don't think you can
it'd be tantamount to proving that 2 = 1 or something ridiculous like that
which might be what you're trying to do
Who is to say that "anything" is not the truth? What if nothing at all is objectively false? Then surely our mathematics should reflect this aspect of truth.
but mathematicians will tell you this is almost certain to fail
But that is a bit philosphical and semantic-driven.
I've proven that 1 = 0 in the past. More than once, I think. Somewhere in my notes. That is not my intention here, but it would be a conclusion that I would be content with.
then your proofs are likely not accepted because they contain flaws
technically speaking, your proof system is considered inconsistent, but in reality, we just throw those proof systems in the dustbin
https://en.wikipedia.org/wiki/Confirmation_bias
https://en.wikipedia.org/wiki/List_of_cognitive_biases
Confirmation bias is the tendency to search for, interpret, favor, and recall information in a way that confirms or supports one's prior beliefs or values. People display this bias when they select information that supports their views, ignoring contrary information, or when they interpret ambiguous evidence as supporting their existing attitude...
Cognitive biases are systematic patterns of deviation from norm and/or rationality in judgment. They are often studied in psychology, sociology and behavioral economics.Although the reality of most of these biases is confirmed by reproducible research, there are often controversies about how to classify these biases or how to explain them. Sever...
Yes. Thank you. Because I surely wasn't familiar with any of that content. Smartass. 😐
Inconsistency is a big problem unless it avoids issues of inconsistency
if you have proven that 1=0, you have two choices: you accept your proof as valid and therefore you accept every possible statement as true, or you accept your proof is invalid and still can talk about things like truth
By that I mean, being able to 'prove anything'
I always made a joke to my friends that my proof system is that "I'm always right"
If you speak about 'proving 1 = 0' unironically, don't expect mercy
Both options still offer a truth value. I tend to believe in a truly infinite reality as far as I can humanly conceive (of) it. Even in terms of truth and possibility and eventuality and falsehood.
Who are you that you would offer or deny mercy?
no, the first option basically throws your hands up in the air and says that truth is meaningless because anything you can think of is true
I'm 'not anyone' but certainly you love making enemies, so good luck with that
Meaning that all things are true is truth.
and while that may technically be an unusual way to look at things, in reality, people will just laugh at you
and the second option allows us to actually engage in logic, even in our daily lives, and this logic has proven useful
I do not count anyone as my enemy. But you can call me whatever you like to call me.
That is nothing new to me. Unfortunately.
This is agreeable.
I think I just figured it out. @vast rain
well, if you accept your proofs as valid, then you also have to accept absurd things like "I (Saccharine) am the Pope."
A humorous proof from 0=1:
- 1 = 2. (Add 1 to both sides)
- The Pope and I are two men.
- The Pope and I are one man (apply step 1)
- I am the Pope.
I just don't think you're going to get anywhere with doing algebraic manipulations to try to prove something impossible. It doesn't work that way.
And for what it's worth, the way I find mistakes in your work is simply by looking for things that look impossible and searching for the last part when things were reducible to y = x^2 + x
Greeting, our father of the clemency!
...j/k sorry >___>
