#help-27

1 messages · Page 1 of 1 (latest)

devout snowBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

manic sandal
#

what formula am i to use for b?

devout snowBOT
scarlet sequoia
manic sandal
#

so this formula should work right

scarlet sequoia
#

yes

#

equate it to 2555 and solve for 'n'

manic sandal
#

however once i apply this, i get a polynomial which if i work out leads to the incorrect answer

#

or ig it just doesnt match with the answers list

scarlet sequoia
#

what's your 'a' and 'd'?

manic sandal
#

for reference

scarlet sequoia
#

so

manic sandal
#

the value for b is the supposed correct answer

scarlet sequoia
#

$$S_{n}=\frac{(2 \cdot 5 + (n-1)4)n}{2}=\frac{(10+4n-4)n}{2}=\frac{(6+4n)n}{2}=$$
$$=(3+2n)n=2555$$

woven radishBOT
scarlet sequoia
#

you got this?

manic sandal
#

okay so

manic sandal
scarlet sequoia
#

yes

manic sandal
#

alright wait let me match it

#

this leads to the polynomial 2n^2 +3n -2555

scarlet sequoia
#

ye

#

can you solve it?

manic sandal
#

alright

#

once i solved it i came to the correct answer

#

thank you for your time

scarlet sequoia
#

there are two answers from which one is wrong

#

cuz n is natural number

manic sandal
#

we take the positive number

#

anyway thank you

#

.close

devout snowBOT
#
Channel closed

Closed by @manic sandal

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

devout snowBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

restive river
#

What does it mean when k times the unit digit and deleting the unit digit again?

supple knot
#

what a fucking mouthful

restive river
#

Oh so it's just 7

#

the question is kinda confusing

supple knot
#

yes because it's one giant word salad

restive river
#

alright thanks!

#

.close

devout snowBOT
#
Channel closed

Closed by @shrewd jasper

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lime linden
#

what is this formula called?

devout snowBOT
neon folio
#

What formula?

lime linden
#

alright this is the formula I was talking about?

supple knot
#

Not enough context

stone stump
#

density transformation formula or something?

lime linden
#

im dealing with jacobian matrix

#

the |J(x1, x2)|^-1 is the inverse determinant of a jacobian matrix

#

idk what the use of this is though

stone stump
#

iirc that's how you transform the density of a random variable

#

or something similar to this anyway

#

did you really find that formula without any other kind of context?

lime linden
stone stump
#

something like X=(X_1, X_2), then you set Y=g(X) or something and then the density of Y can be computed using that formula and the density of X

#

something like that

#

oh well thank you we apparently have context

lime linden
#

sorry

supple knot
#

Probably just change of variables

lime linden
#

wdym

supple knot
#

It doesn't have an official name because it's so simple

#

Change of variable is descriptive enough

lime linden
supple knot
#

Have you taken multivariate calculus?

lime linden
supple knot
#

You can just say no

lime linden
#

ok no

supple knot
#

Calculating probabilities or distribution functions with more than one dependent variable is sometimes hard in traditional Cartesian coordinates like x, y, z. So the Jacobian let's you evaluate them in other coordinates, say polar or spherical or cylindrical.

lime linden
#

you need anything in calc 3 for prob just double integrals, pd, and multivariate gaussian distributions

#

which is hwta i will go over now

#

whats the point of that vid?

supple knot
#

just an example of multivariate distribution

lime linden
#

when will i ever need to use that formula?

supple knot
#

how do i know

wooden veldt
lime linden
#

i mean in what situation willn i use it

#

so the joint density function of a multivariable function, is just its jacobian matrix right?

supple knot
#

no

#

joint density and jacobian are two different things.

lime linden
#

oh

#

wouldnt there be 2 formulas

#

for change of variables

#

?

supple knot
#

what 2 formulas are you thinking of and why do you care

lime linden
#

for changing variables formula

#

there is a g1 and g2

#

if you want to change the formulas of those respective equations

#

it would be 2 instead of 1

supple knot
#

what change? it's given to you

lime linden
#

the formula im talking about in 7.1

#

fy1, y2

#

im saying

#

if we want to use it

#

we would end up with 2 formulas

#

since there is functions g1 and g2

supple knot
#

7.1 is one formula. what other formula do you think there should be?

lime linden
#

if we want to change the variables of g1 and g2

#

wont there be 2 seperate formulas for each

supple knot
#

why would you change variables of g1 and g2

#

change how?

lime linden
#

idk what else will i do with the formula?

supple knot
#

go solve some problems in your book

#

you're asking vague questions with no direction

lime linden
#

for example, how would i apply the fy1y2 formula to this example

supple knot
#

apply how?

#

you're just supposed to find the change of variables

lime linden
#

for which equation?

supple knot
#

you're asked to find this

lime linden
#

yes

supple knot
#

the solution's given, what don't you understand about it?

lime linden
#

i understan

#

the solution -2 right?

supple knot
#

solution to what?

lime linden
#

the determinant of the jacobian matrix right?

supple knot
#

the jacobian is the determinant

lime linden
#

yes

#

so by finding the determinant of the jacobian matrix, i am finding the change of variables through that?

#

nvm ill just take a break

#

this is confusing

#

that formula

#

.close

devout snowBOT
#
Channel closed

Closed by @lime linden

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

vernal apex
devout snowBOT
vernal apex
#

I keep on getting this wrong

#

I put 0.95 for percentile, df1 = 3, df2 = 8

#

so qf(0.95,3,8)

devout snowBOT
#

@vernal apex Has your question been resolved?

vernal apex
#

<@&286206848099549185>

devout snowBOT
#

@vernal apex Has your question been resolved?

hot steeple
#

does qf test both sides

vernal apex
hot steeple
#

I looked it up a bit

#

Qf gives the chance that a random number is below or equal to a given percentile

vernal apex
#

Ok

#

my command seems correct then

#

I tried 0.11306 and 4.06618

#

both are wrong

hot steeple
#

In one i got 8 something

#

Using a switched around df1 and 2

vernal apex
#

That seems to big for a F stat

#

actually nvm

vernal apex
#

how u got that

vernal apex
#

.close

devout snowBOT
#
Channel closed

Closed by @vernal apex

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

devout snowBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

inland jolt
#

,w 2*sqrt(2)≥3-1/(2)

devout snowBOT
woven radishBOT
inland jolt
#

.close

devout snowBOT
#
Channel closed

Closed by @inland jolt

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

tardy brook
#

I read from some paper that if n=pq where p and q are distinct primes lambda(n)=lcm(p-1,q-1) then gcd(lambda(n),n)=1

tardy brook
#

can anyone have a proof or explain why that is true

#

also lambda(x) is carmichael's function of x

frail basin
#

i don’t think it’s true, for example p=3 q=7

tardy brook
#

yea I think of it after I ask the question

#

at page 226 second paragraph fifth line it says like that

#

I will close it now

#

.close

devout snowBOT
#
Channel closed

Closed by @tardy brook

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

twilit cobalt
devout snowBOT
twilit cobalt
#

anyone have a clue on how to do c)

devout snowBOT
#

@twilit cobalt Has your question been resolved?

devout snowBOT
#

@twilit cobalt Has your question been resolved?

devout snowBOT
#

@twilit cobalt Has your question been resolved?

devout snowBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

devout snowBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

keen urchin
#

Having an issue with this Taylor series, have no Idea what's wrong with it

keen urchin
wooden wraith
#

Your series is right

#

except that you called the variable x, rather than y

keen urchin
#

gah! that's a dumb oversight by me

#

thank you

wooden wraith
#

@keen urchin

#

Oh sorry for the ping lol

#

Happy to help

keen urchin
#

np, thx

#

.close

devout snowBOT
#
Channel closed

Closed by @keen urchin

Use .reopen if this was a mistake.

Please take a minute to participate in [our survey](#changelog message) if you haven't already!

devout snowBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

mild summit
#

I dont understand how they concluded that the primitive of sin^4t*cost is sin^5t/5

devout snowBOT
#

@mild summit Has your question been resolved?

devout snowBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

long rampart
#

if you increase your travel speed by x% why does your travel time not reduce by x%?

loud root
#

because they're not proportional:
$$speed=\frac{distance}{time}$$
if you reduce the speed by x%, the time is going to increase by $\frac{1}{x}%$

woven radishBOT
#

Andrea276

long rampart
#

Oh awesome thank you! I haven't mathed in a while and I have a placement exam as a non-traditional student. I was so confused why I couldn't get the same answer with x=k/y for an inverse relationship as just increasing both numbers by the percentage of the whole if that makes sense.

#

Sorry if it is a stupid question! I appreciate the insight!

loud root
#

Don't worry, it wasn't a stupid question, it's not obvious

long rampart
#

Thanks again!

#

.close

devout snowBOT
#
Channel closed

Closed by @long rampart

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

scarlet badger
#

Hi.
We're throwing 2 dies one after another. D_1 has 2/7 probability for "4", D_2 has 2/7 probability for "3". All other probabilities are normal ("1/7").

Is it correct to say that the probability space is (D_1 x D_2) U (D_2 x D_1)?

Is the probability function correct, if I say:
Pr(d_1, d_2) = {
2/7 * 2/7 if d_1 = 4 AND d_2 = 3
2/7 * (5 * 1/7) if d_1 = 4 AND d_2 != 3
(5 * 1/7) * 2/7 if d_1 != 4 AND d_2 = 3
(5 * 1/7) * (5 * 1/7) if d_1 != 4 AND d_2 != 3
?

scarlet badger
#

I've changed the Pr now

#

if we add up all 4 cases we'll land at 49/49

#

which correctly equals 1

#

but should there also be a Pr(d_2, d_1) with basically the same cases? This would account for that we start with dice_2 instead of dice_1

#

or does the order of arguments not matter in a Pr-function (like if it would matter, one would write the cases down)?

devout snowBOT
#

@scarlet badger Has your question been resolved?

scarlet badger
#

To reduce the question: Do I have to account for the order in defining a) probability space? b) probability function?

#

(D1 x D2) U (D2 x D1) true or false?

devout snowBOT
#

@scarlet badger Has your question been resolved?

wheat cave
scarlet badger
#

Hello @wheat cave

wheat cave
#

Hello @scarlet badger

scarlet badger
#

why would D1xD2 suffice? Is order not important in probability spaces?

wheat cave
#

Here it does not seems to matter

#

Dices are identical

scarlet badger
#

I was thinking of D1 = {1_a, 2_a, ..., 6_a}

wheat cave
#

I mean

scarlet badger
#

and D2 = {1_b, ...

#

it is indeed symmetric in this case

wheat cave
#

If i was doing it, my prob space would be [[1;6]]x[[1;6]]

scarlet badger
#

I'll do like that aswell then

#

while we're at it, can I ask you another question?

#

If I draw 5 of 52 poker cards at once, and want exactly 2 A's, exactly 2 J's or exactly 2 Q's

#

is the correct calculation 5C2 * 3 * 2/52 * 1/51

#

.close

devout snowBOT
#
Channel closed

Closed by @scarlet badger

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

restive river
#

what does a 4 component vector look like

devout snowBOT
lethal copper
restive river
#

but in a plane

#

in a thing

#

idk what u call it

lethal copper
#

You cant visualize it often its the time i think

restive river
#

oh okay

#

and what does <> mean

#

like <5,3>

lethal copper
#

In what context

restive river
#

idk

lethal copper
#

Where have you seen it

restive river
#

,rotate

woven radishBOT
lethal copper
#

Thats 2 dimensional x is 7 y is 3

restive river
#

hm

#

.close

devout snowBOT
#
Channel closed

Closed by @wanton sage

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

reef pilot
#

@analog trellis

devout snowBOT
reef pilot
#

it closed

analog trellis
#

Yes. It is the chain rule.

#

I might as well include the first part before this too since it's small for completeness.

reef pilot
#

i see

analog trellis
#

I'd set
F(x, y, z) = f(x, y, z) - 6 = 0 then differentiate with respect to y to obtain
f_2 + f_3 ∂z/∂y = 0, etc. (f_y + f_z ∂z/∂y = 0.)
Where f_2 is the derivative of f with respect to the second variable in the bracket, here it's y.
We just need to acknowledge here that z is considered the dependent variable and x, y are to be considered the independent variables.

#

It might not always be the most useful for the problem you have but there's a really nice memory technique for more complicated problems with more than one equation.

reef pilot
analog trellis
#

Like here.

#

Obviously, the memory rule won't be clear to you but you might not even want to worry about this stuff for your current studies.

#

The numerator and denominator are both different jacobians which can be computed and are easy to set up with the knowledge of the text. It saves you having to set up everything each time.

reef pilot
#

i see

#

thats usefull too know

#

.close

devout snowBOT
#
Channel closed

Closed by @reef pilot

Use .reopen if this was a mistake.

devout snowBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

vale valve
#

How do I determine the number of solutions to the equation -5 = x +3x^2
without solving it?

proud perch
#

Move all the terms to one side

vale valve
proud perch
#

find the discriminant

vale valve
#

Do I need to find the roots?

bold prism
bold prism
#

ah yes

vale valve
proud perch
#

But only the real solutions?

vale valve
#

how do I figure out the # of solutions without solving it?

vale valve
proud perch
#

Then yeah just take the discriminant

vale valve
#

So, 2?

bold prism
#

have you been taught complex solutions?

vale valve
#

Not that I remember

bold prism
#

yeah then its only real solutions

pseudo basin
#

have you been taught the discriminant

vale valve
#

yes

pseudo basin
#

this problem is a dead ringer for it

vale valve
#

I've been taught it 100% but I do not remember ;-;

#

I'll do some review for it later

pseudo basin
#

putting your equation in standard form yields:

3x^2 + x + 5 = 0

vale valve
#

Am I supposed to look for roots?

#

Because I know how to do that

loud root
pseudo basin
#

you are supposed to calculate the discriminant

loud root
#

You have to use the discriminant as Ann suggested

vale valve
#

Okay I'll do that

pseudo basin
#

and infer the solution count from the sign thereof

vale valve
#

I relearned how to find it by looking at my notes and got 61

#

as the discriminant

loud root
#

How did you find that?

vale valve
#

b^2-4ac

loud root
#

3x²+x+5=0
This is your equation, right?

vale valve
#

well that's the standard form, yeah

loud root
#

What's b?

vale valve
#

1?

loud root
#

Yes

#

a and c?

vale valve
#

a is 3

#

c is 5

#

OH WAIT

#

I JUST REALIZED WHAT I DID WRONG

#

I did -5 not +5

loud root
#

Yep

#

So you get 1²-4(3)(5)=-59

vale valve
#

Yeah I just got -59

#

So what do I do with that?

loud root
#

If the discriminant is less than 0, the equation has no real solutions, if it's 0 the equation has one real solution and if it's greater than 0 the equation has 2 solutions

vale valve
#

oh so roots

loud root
#

roots means real solutions

vale valve
#

oh

#

Tysm @loud root, @bold prism and @pseudo basin , appreciate it lots

#

(unrelated) I have not slept in 2 nights and I'm going to try my hardest to sleep tonight thank you once again

#

.close

devout snowBOT
#
Channel closed

Closed by @vale valve

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

silk plank
#

Hi everyone

devout snowBOT
silk plank
#

x>y
z>t

potent nebula
#

which letter can you not get

#

oh

#

nvm I see

#

ok

#

what have you tried

devout snowBOT
#

@silk plank Has your question been resolved?

silk plank
#

But its is nonsense

silk plank
timber pebble
#

which one are you looking at

#

its not really clear what youre tasked to do here

#

but i can be stupid sometimes so maybe its just not obvious to me thinkies

#

can you clarify?

silk plank
#

One of them are true

silk plank
#

I cannot find which one

timber pebble
#

alright

silk plank
#

Could u explain please

timber pebble
#

do you have gut feeling about any of them?

#

or we could just go in order

silk plank
timber pebble
#

so i would start like this

#

write down what you know, and what youre curious about

#

oops i accidentally a letter

#

here we go

#

@silk plank

#

the hope is that you start with one side of the inequality, and through clever substitution, you end up at the other side

#

and the inequality points in the correct direction

#

the work is logical; you need to make sure that when you make a substitution, the inequality is actually supposed to point one way or another afterwards

#

I am saying that if we replace 7t with 7z, we will have a larger quantity

#

because t < z, so it follows that 7t < 7z

#

make sense?

silk plank
#

Yessss

#

So then -13x<-13y

timber pebble
#

lets think it through

silk plank
#

And D

timber pebble
#

you start with x < y

silk plank
#

Yes

timber pebble
#

multiply by 13

#

still true

#

13x < 13y

#

what happens when you multiply by a negative

silk plank
#

Swap the inequality sign

timber pebble
#

yea

#

so -13x > -13y

#

another way of thinking of it is

#

if you substitute y for x

#

you are removing a larger amount than before

#

so you cannot say its bigger

#

do you see?

silk plank
timber pebble
#

oh

silk plank
#

That x less than y

timber pebble
#

y < x

#

well then

#

your gut instinct was correct

silk plank
timber pebble
#

good job

#

yea D

silk plank
#

Thank u a lot

timber pebble
#

sorry its late for me lol

#

np

silk plank
#

.close

devout snowBOT
#
Channel closed

Closed by @silk plank

Use .reopen if this was a mistake.

devout snowBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wary halo
#

the 3 question?

devout snowBOT
brazen star
#

factor out (2x^3 - x^2 - x)

#

or just divide by (2x^3 - x^2 - x)

#

either way works

#

@wary halo you there?

wary halo
#

yes

brazen star
#

ok ok

#

you got it?

wary halo
#

(x-2)-(2-x)=0 ?

opaque haven
#

you cant really divide by that term

#

factoring is the only option

#

if the term is equal to 0, which it very well could be, dividing by it is undefined

#

so youre gonna have to factor

devout snowBOT
#

@wary halo Has your question been resolved?

#
Channel closed

Closed by @wary halo

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lilac pulsar
#

hello can someone please help me with this question? i don't know what its asking or even where to start

plush light
#

hello

#

i think i could help

lilac pulsar
#

hello

#

where would i start??

#

i have the answers by the way i just dont know how to get there

plush light
#

Well, for the first one you could probably draw a graph monitoring the amount of drugs in the bloodstream.

#

Every 6 hours one serving of drugs are added to the bloodstream while the previous one is decreased by 0.625

#

$\left(a+\left(a+\left(a+\left(a\cdot0.375\right)\cdot0.375\right)\cdot0.375\right)\cdot0.375\right)$

woven radishBOT
#

dabbingpotato

plush light
#

This would be the first day I think

lilac pulsar
#

what does a represent?

#

amount of drug at the start?

#

these r the answers btw

plush light
#

a would be x in this situation

#

a is the amount of drug registered every time the user takes it

lilac pulsar
plush light
#

So for example if I got 2 mg of drug in my bloodstream every shot

lilac pulsar
#

yes

plush light
#

To solve part B, it would be x(1 + 0.375 + 0.375^2 ---- + 0.375^39)

#

$x(1+0.375+0.375^2 - + 0.375^39) = 8$

woven radishBOT
#

dabbingpotato

lilac pulsar
#

i still dont understand what u did for a

plush light
#

ok

#

say if I got 2mg every shot, every 6 hours there would be 0.375 of the drug left

#

right?

lilac pulsar
#

yes

plush light
#

so it would be 2*0.375

#

now say you got the it agian

#

you would add 2 mg to the amount you already have

#

so it would be 2+(2*0.375)

lilac pulsar
plush light
#

what is x

lilac pulsar
#

sorry *2

#

like it would just be 2*0.375 multiplied by 2

plush light
#

after 6 hours its 2*0.375

lilac pulsar
#

yes so 12 hours is just double that?

plush light
#

nope

#

x(1) this is when you first put it in

lilac pulsar
#

ohh so ur taking like 2 + 2*0.375 and multiply that whole thing by 0.375 yes?

plush light
#

x(1+0.375) this is second time your putting it in

plush light
#

x(1+0.375+0.375^2) this is after putting it in 3 times

#

x(1+0.375+0.375^2+0.375^3) after putting it in 4 times

lilac pulsar
#

so does x represent the dose in blood after 6 hours

plush light
#

x represents how much you put in each time

lilac pulsar
plush light
#

yep, if you just put it in

#

after 6 hours you put it in again, how much should be in your blood stream now?

lilac pulsar
#

ohhh

#

i get it now

#

ok can i have like 2mins i have to note this down

plush light
#

$x(1 + 0.375 + 0.375^2)$

woven radishBOT
#

dabbingpotato

plush light
#

Basically, the 1 represents the new batch of drugs coming into your bloodstream when you get the shot, the 0.375 represents the amount of drugs from the previous shot still remaining in your bloodstream, and the 0.375^2 represents the amount of drugs still left in you bloodstream from your first shot

#

Do you see how this equation works now?

lilac pulsar
#

yep

#

i'll try do b

plush light
#

its a bit challenging

lilac pulsar
#

yes so i think u should come back in 3 minutes because thats when i will get stuck kekw

#

nvm i got the answer i just dont know if i did it the right way

#

ook i solved c

#

thx a lot for ur help

devout snowBOT
#

@lilac pulsar Has your question been resolved?

#
Channel closed

Closed by @lilac pulsar

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

empty flame
#

hello

devout snowBOT
empty flame
#

i want to prove that abs(sum of the first n numbers) is less than or equal to the sum of absolute value of the first n numbers

#

what i did is that i used the formula of adding the first n numbers which is n(n+1)/2

#

the first one will be abs(n(n+1))/2

#

my problem is with the second one

midnight dirge
#

its triangle inequality applied n-1 times

pastel pasture
#

I don't think n is limited to naturals

empty flame
#

no its not limited to naturals

empty flame
#

here n(n+1)/2 isnt true ?

#

bc the summation isnt just of natural numbers

half vessel
#

you can prove it by induction and triangle inequality

midnight dirge
#

triangle inequality
|a+b| <= |a| + |b|
so applied n-1 times its
|a1 + a2 + ... + an| <= |a1| + |a2 + ... + an|
<= |a1| + |a2| + |a3 + ... + an|
<= |a1| + |a2| + |a3| + ... + |an|

#

expand the summation and u get that

half vessel
midnight dirge
empty flame
#

how can i express the second summation in terms of this formula

half vessel
main scarab
#

The name is such a clickbait
I thought this channel was asking calculus 😢😠😠

half vessel
empty flame
#

so its not a clickbait XD

midnight dirge
midnight dirge
midnight dirge
#

the starting triangle inequality? |a+b| <= |a| + |b|?

empty flame
#

i mean the first sum is abs(a1+a2+...+an-1+an)

midnight dirge
#

yes

empty flame
#

and the second is abs(a1) + abs(a2) + ...+abs(an-1) + abs(an)

midnight dirge
#

why so

empty flame
#

i can say that the first one is abs(n(n+1))/2 but i cant find a similar formula for the second one if i can then it will be solved

midnight dirge
#

wait what?

#

where did that come from

half vessel
#

Suppose $|a_1+...+a_n|\leq |a_1|+...+|a_n|$. For n+1 terms, by triangle inequality, $|a_{n+1}+a_1+...+a_n|\leq |a_{n+1}|+|a_1+...+a_n|\leq |a_{n+1}|+|a_1|+...+|a_n|$

woven radishBOT
#

JellyShark

empty flame
#

am i right ?

half vessel
#

yeah that's right

empty flame
#

i have a question

#

proof by induction is to show that the statement is true for 1 and suppose that its true for k then show that it is true for k+1 according to the assumption which will prove that the statement is true for all n ??

midnight dirge
#

um its morelike

#

define a proposition Pn

#

show that it is true for P1

#

assume Pk is true

#

show that P(k+1) is true when Pk is true

#

as P1 is true and Pk implies Pk+1, Pn is true for all n in N+

midnight dirge
#

because we generally start from 1 and we do it in increments of 1, so all natural numbers

empty flame
#

pictures of what

midnight dirge
#

if u want to show something in R then u have to use a different method

empty flame
#

this guy means something bad if i am right ?

main scarab
#

That guy is gone

midnight dirge
empty flame
empty flame
#

or some are constants ??

empty flame
#

but if u prove that its true for pk+1 and pk-1 then its true for all numbers bc you didnt put a condition that k belongs to N

midnight dirge
#

well

#

ur initial statement is P1 is true

#

or P0 whichever u show first

#

u cant possibly show all R is true as there are infinitely many numbers in R from 0 to 1 for instance

#

not by using induction anyway

empty flame
#

yea but you showed that its true for some constant k

midnight dirge
#

not that i know of anyway

#

yea but thats essentially saying for our base case so in the original statement

empty flame
#

where k is a number you dont specify where k lies

midnight dirge
#

yea we dont

#

but im saying the base case is

#

P1 => P2 => P3... => Pn

empty flame
#

yea but can P1 be a real number

midnight dirge
#

something like P1.5 is not true unless u first show it is true

empty flame
#

P is the statement so it can be that the statement will result in a real number after changing its variable by 1

midnight dirge
#

if u modify induction u might be able to do it but i dont think ive seen it

#

like instead of Pk implies Pk+1 u would have something like Pk implies Pk+delta where delta>0 or similar?

#

but ive never seen it used that way

#

or if u can even do that

#

in the case of Pk implies Pk+1, if u have P1 as true, u can get P2 as true, but u cant get P1.1 or P2.1 as true

#

u can show P1.1 is true and that will imply P2.1 is true as well but then there will be another real number eg 1.11, 1.111, 1.1111

#

and u have to show them one by one which u cant do to my knowledge

empty flame
#

but if you prove it for a rational number then cant u generalize that to all rational numbers like you do to natural numbers ?

midnight dirge
#

nope

#

its because the difference between each natural number is 1 so it works

#

but the difference between each real number can be infinitely small

empty flame
#

ok but i guess that if you show that its true for P2.1 for example then it should work for P2.2 and P2.3 and so on bc the difference is 0.1 between them ?

midnight dirge
#

no u have to show each separately

#

but 3.1 and 4.1 will be true

empty flame
#

hmm

midnight dirge
#

but generally ive mainly seen it in natural numbers as its used to show a certain property of a series so n will always be a natural number

empty flame
#

ok tysm

#

.close

devout snowBOT
#
Channel closed

Closed by @empty flame

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

restive river
devout snowBOT
restive river
#

Is this correct?

#

Since 1/2 in the k value

#

And the reciprocal would be 2?

#

It's fine I'll just put that as the answer

#

.close

devout snowBOT
#
Channel closed

Closed by @glad mica

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

restive river
devout snowBOT
restive river
#

How should i solve these types of questions

#

<@&286206848099549185> bleakcat

grim agate
#

Get some relation for ratio of roots of equation in terms of sum and product of roots

#

Let l m be roots of first equation and n o be roots of second equation

#

So we have $\frac l m = \frac n o$

woven radishBOT
grim agate
#

And $\frac m l = \frac o n$

woven radishBOT
grim agate
#

Add them so you’ll have a relationship to compare

#

$\frac m l + \frac lm = \frac n o + \frac o n$

woven radishBOT
grim agate
#

Can you solve now?

#

@restive river

restive river
#

in the option

#

there are numerical values

grim agate
#

Hmm?

grim agate
restive river
#

i dont think i would be able to solve by comparing

grim agate
#

$\frac {m^2 + l^2 } {ml} = \frac {n^2+o^2}{on}$

woven radishBOT
grim agate
#

$\frac {(m+l)^2 -2ml } {ml} = \frac {(n+o)^2-2no}{on}$

woven radishBOT
restive river
#

oh wait

grim agate
#

Now plug sum of roots and product of roots

restive river
#

smh

#

troll question

grim agate
restive river
#

terms cancel out as always

#

leaving 1 behind

grim agate
restive river
grim agate
#

Hmm?

restive river
#

and same happened for this one

grim agate
#

You suggesting (a,b,c)=(p,q,r)

#

?

restive river
#

nu

devout snowBOT
#

@restive river Has your question been resolved?

#
Channel closed

Closed by @restive bison

Use .reopen if this was a mistake.

devout snowBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

naive estuary
#

It's a bit tricky for me because of the 11 in the parentheses...so basically i have a bit of trouble starting it off

main gull
#

Using the concept of $a(b + c) = ab + ac$

woven radishBOT
#

dldh06

naive estuary
#

Ok

#

First -2 right?

#

So i can isolate 5h?

restive river
#

what do you mean first is -2?

#

use the concept he mentioned on $2(11-h)$

woven radishBOT
#

jswatj

naive estuary
#

Oh, what i meant was subtract 2 from the 2 in 5h+2

main gull
naive estuary
#

Quick question what do you mean by "$" just want to make sure

#

Variable?

main gull
#

Aka the math font text thing

#

Like 1/2 looks fine but $\frac{1}{2}$

woven radishBOT
#

dldh06

naive estuary
#

Oh

restive river
naive estuary
#

Yea i don't really get it....

#

Sorry

#

I figured it out another way.

#

.close

devout snowBOT
#
Channel closed

Closed by @naive estuary

Use .reopen if this was a mistake.

devout snowBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

finite shoal
#

Hey guys im about to be a sophmore and some of the stuff they have on this packet I’ve never seen before so I need some help thanks!

finite shoal
#

^47

#

I honestly don’t get what they tryna make me do so idk what they mean

#

Then this one is the last thanks!

#

Oops forgot about 27

midnight dirge
#

..ask one question at a time

finite shoal
#

Mb bro bro

midnight dirge
#

do u know what are piecewise functions

finite shoal
#

No

midnight dirge
#

this is an example

#

so depending on the value of x, the function will be a bit different

#

so they want u to give a function in this form to fit the graph given

finite shoal
#

So how do I give the function with the shape of the v

#

Its shaped like a v

midnight dirge
#

um ignore one side of the v first and try to find a function that fits that

finite shoal
#

I see on one half its -2 the other half is +2 slope

midnight dirge
#

mhm yes and what equation would say the one with a 2 gradient slope take one?

finite shoal
#

Huh

#

Like from the example I pick one ?

#

For the +2 slope

midnight dirge
#

yes

finite shoal
#

Can I write 2x

#

I see one is on the thing -1/2x so I’m guessing I can write the slope as one

midnight dirge
#

wait sry, what do u mean by that?

finite shoal
#

So on the example

#

It says

#

-1/2x

#

That’s the slope of a line there

#

So can I write plus or minus 2x

midnight dirge
#

wait did u move on to another Q?

finite shoal
#

No

#

Im still on the piecewise function

#

I just don’t know how to write the function I

#

Like idk how to write this as this type of function

midnight dirge
#

howd u get the -1/2x though

finite shoal
#

Nono I looked at the example

#

You posted

midnight dirge
#

oh..

#

um

#

that was just an example of a random piecewise function i got by searching it

#

to kinda visualise what it is

finite shoal
#

Sorry if im kinda slow I’ve never heard of this stuff befo

midnight dirge
#

not exactly related to urs especially not the numbers, maybe except by coincidence

#

yea anyway

#

um

#

so whats the point that the v is at

#

the bottom point

finite shoal
#

1,-4

midnight dirge
midnight dirge
#

then so what is the equation of a line that passes through 1,-4 with gradient of 2

finite shoal
#

Y=2x-7?

#

Wait idk cause the hraph is cut off

midnight dirge
finite shoal
#

-6

#

Y=2x-6?

midnight dirge
#

yep

finite shoal
#

Ok and the other one is y=-2x-2?

midnight dirge
#

and repeat that but with the slop being -2

#

yep

#

so then uve those 2

midnight dirge
#

so in this case the line is split into 2 parts, when x<=1 and when x>1

finite shoal
#

Yes

midnight dirge
#

and when its <=1 u use the equation u just calculated for the approriate line

finite shoal
#

Ok so if it’s more than 1 it’s postive if it’s less it’s negative

#

Slope

midnight dirge
#

in this case, yep

finite shoal
#

So how do I write it

#

X<1 y=2x-6?

#

And then x>1 y=-2x-2

midnight dirge
# midnight dirge

write it in this form, so u write the curvy thing, then u write
-2x-2 , x<1
2x-6 , x>=1

finite shoal
#

Ok is that it?

midnight dirge
#

yep

finite shoal
#

Alright can you help me on the next one?

midnight dirge
#

yea sure

finite shoal
#

47

#

Im guessing it’s saying the volleyball can be either 26.5 or 25.5

#

And its ok

#

I just don’t know how to write that basically

midnight dirge
#

they said absolute value inequality

#

|26 - x|<=0.5

#

this essentially means that x cannot differ from 26 by more than 0.5

finite shoal
#

Yes

midnight dirge
#

i had no idea what absolute value inequality was but i googled it haha

finite shoal
#

Yea dude these teachers

#

Makin me rmr stuff from like

#

2 years ago

#

And half this stuff I’ve never seen

midnight dirge
#

lol idt ive seen that term till now

finite shoal
#

Do you know what this question is asking

#

19,20,21

#

It gives x and y

#

And then it says to find y when x=3 which is weird

midnight dirge
#

they say x and y vary directly

#

this means that when 1 increases the other increases as well

#

aka if u draw a graph theyve a slope of 1

finite shoal
#

So if lets say

#

For 19

#

If x goes down by one to 5 it would be -42?

midnight dirge
#

oh crap
yes

#

im wrong u are right

#

haha

#

yea it instead means

#

if u draw a graph it passes through 0

#

oops

finite shoal
#

Yea

#

What about this one?

midnight dirge
#

i think u let the number of small windmills be x and the other be y

#

then u make an equation where the total energy made from them is 180

#

then make a graph

finite shoal
#

So basically

#

1.5x+2.5y=180?

midnight dirge
#

yea

#

but u shld also write a statement on which u let be x and y as it isnt stated in the question

#

so write a little statement on that

finite shoal
#

Isnt it a inequality

#

So don’t I gotta use

#

or <

midnight dirge
#

oh yea

#

mb again..

#

well at least 180 megawatts

#

so >=180 i guess

finite shoal
#

Yea

midnight dirge
#

and i guess u should then shade the region that is greater than 180

finite shoal
#

Yea I did that

#

I got the last one now

midnight dirge
#

27?

finite shoal
#

Ya

midnight dirge
#

so try to graph the function

#

it will be similar to the piecewise function we got first

finite shoal
#

So what do I use to graph it

#

D= a-1.50?

midnight dirge
#

um when the part in the absolute value is positive and when it is negative

midnight dirge
finite shoal
#

And then +1.50

midnight dirge
#

the other will be d=-(a-1.50)

#

d=-a+1.5

finite shoal
#

Ok i graphed it

#

So since it’s asking me for the values where it’s more than 1.50?

#

Becuase that’s the difference

midnight dirge
#

wait what

#

how does ur graph look like now?

finite shoal
#

It’s a v

midnight dirge
#

its asking for when d=0.25

finite shoal
#

So that’s like the postive difference right

#

They making money

midnight dirge
#

not really

#

it could be them making less money as well

#

its more like a being the prediction

finite shoal
#

So what values will d be .25?

midnight dirge
#

wait i mean 1.5 is the prediction

#

a=1.75 or 1.25

#

so the prediction is 1.5

#

a is the actual value

#

if a is more than 1.5, itll lead to some difference, same when a is less than 1.5

#

d is like how much is this difference i guess

finite shoal
#

Yes

#

So I need to find the value where it is 1.75

#

Because minus that is .25

midnight dirge
#

wait no

#

i already told u the answer

#

its just a = 1.75 and 1.25

#

but u should also probably draw that on th graph

#

so draw a line where d=0.25

finite shoal
#

Ok

#

Alright I did it

#

Thanks you so much man

midnight dirge
#

np

finite shoal
#

.close

devout snowBOT
#
Channel closed

Closed by @finite shoal

Use .reopen if this was a mistake.

devout snowBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

sinful creek
devout snowBOT
sinful creek
#

Did I mess up by multiplying my num. by just sqrt5 ??

exotic stump
#

i'm not exactly sure what you did for step 1

restive river
#

Okay so its difference of squares

#

aka like he said multiply by conjugate

sinful creek
#

where do you see the difference of squares?

#

my math eyes dont see them

restive river
#

(sqrt5 - 2)*(sqrt5 +2) = 5 - 4

#

= 1

sinful creek
#

ohhhh

restive river
#

so you multiply by (sqrt5 + 2) over itself

sinful creek
#

oohhhh

#

ok

#

lemme do it brb

restive river
#

and that gets your answer

exotic stump
#

try not to give answers directly

restive river
#

can you see why if you multiply the bottom and top by sqrt5 as you did why it would be incorrect though?

sinful creek
#

yes indeed, and how would I know when to take a conjugate of anything?

restive river
sinful creek
#

.0

#

.close

devout snowBOT
#
Channel closed

Closed by @sinful creek

Use .reopen if this was a mistake.

sinful creek
#

thanks for all the help guys :))

devout snowBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

drowsy trout
#

Hi, can anybody explain a theorem to me, i mean why it is true?

drowsy trout
#

Why would the max gradient be L

#

max norm*

#

Thanks in advance!

#

nvm im dumb i think i got it after washing my face

#

.close

devout snowBOT
#
Channel closed

Closed by @drowsy trout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lunar raft
#

I'm confusedbon why points C and R are congruent

wicked turtle
#

,rotate

woven radishBOT
wicked turtle
#

the markings indicate that the angle at C equals the angle at R, and the two sides that join at C have the same length as the two sides that join at R

lunar raft
#

The markings?

wicked turtle
#

the dark shaded "cone" at each angle

#

and the single and double ticks on the line segments

#

moreover the problem statement itself says "with congruent angles and sides marked"

lunar raft
#

Are T and A congruent?

wicked turtle
#

and says outright that angle C = angle R

wicked turtle
lunar raft
#

I dont get it

#

My teacher was talking about SAS and I don't know what that is

wicked turtle
#

what theorems do you know that allow you to conclude that two triangles are congruent?

lunar raft
#

Pythagoras

wicked turtle
#

well this isn't a right triangle so that won't help here

lunar raft
#

I dont get the 3 letter thing

wicked turtle
#

surely your teacher stated what SAS says when he/she mentioned it?

lunar raft
#

Like ssa

#

Or asa

#

No

#

I'm confused why it's sad

#

Sas

wicked turtle
woven radishBOT
lunar raft
#

Nvm

wicked turtle
lunar raft
#

Yes

wicked turtle
#

should surely be covered in there

lunar raft
#

Ok

#

.close

devout snowBOT
#
Channel closed

Closed by @lunar raft

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

red osprey
#

How would you approach #2?

devout snowBOT
topaz axle
#

how did you do #1?

red osprey
# topaz axle how did you do #1?

Im not sure if its right, but what I did was take the weight of cells and divided by the weight of a single cell to get the # of cells

#

it also says on the bottom of the page, that (a) and (b) are not consistent

devout snowBOT
#

@red osprey Has your question been resolved?

devout snowBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

devout snowBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

inner oyster
devout snowBOT
inner oyster
#

<@&286206848099549185>

devout snowBOT
#

@inner oyster Has your question been resolved?

still pulsar
inner oyster
#

yes

still pulsar
#

Gimme 5 mins, I'm on switching bus

inner oyster
#

aright its fine

still pulsar
#

find that hyp, and note that is the radius

#

then you can also observe that the angle that makes up the arc of the shaded region is 90 degrees from the triangle you just drew (also draw one on the other side)

#

this means the arc length is exactly <insert fraction> of the circle's circumference (use 2 pi r)

#

Solve for x, using the fact that the radius = the hyp, and the add the perimeters of the shaded area together

inner oyster
#

1/4(2(6)pi

#

right?

still pulsar
#

what does yhat simplify to

inner oyster
#

3

still pulsar
#

$3 \pi$

woven radishBOT
#

Rαιη

still pulsar
#

good, that's the arc perimeter

#

now how about 2x?

#

or need with that

inner oyster
#

idk how to solve for x

still pulsar
#

ok, you have the "triangles" drawn right?

inner oyster
#

ye

still pulsar
#

What is the length (base) and height of the triangle?

inner oyster
#

6x6

still pulsar
#

not quite

still pulsar
#

and point O

inner oyster
#

oh aright

#

can you tell me what you were referring to please

still pulsar
#

red line

#

sorry it's badly drawn, I'm on a bus

inner oyster
#

its fine

#

there r 3 triangles formed

still pulsar
#

Observe that point O to the verticle line (height) x

#

is exactly half of 2x

inner oyster
#

x+x/2?

still pulsar
inner oyster
#

yah

still pulsar
#

that will be

inner oyster
#

pythagorean theorem?

still pulsar
#

$a^2+b^2=c^2$

woven radishBOT
#

Rαιη

inner oyster
#

ya

still pulsar
#

so what is the answer?

#

or, what is the hyp

inner oyster
#

6

still pulsar
#

no

inner oyster
#

x^2+x^2=6

still pulsar
#

well

#

yeah, what is x

#

solve for x