#help-26

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topaz sinewBOT
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topaz sinewBOT
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thorn cairn
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Hey guys.

topaz sinewBOT
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Please don't occupy multiple help channels.

thorn cairn
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Where is the general channel?

pseudo sonnet
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if you have a question, please ask now kongouderp

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otherwise, I'm gonna close this channel

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hm, well

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blazing tartan
#

can someone help me with this integral? the question asks me to evaluate the integral. What i dont understand is that after I finish integrating and substituting the upper and lower values of the integral, i end up with 'ln | 0 |' and i believe its undefined there. So i dont understand if i did something wrong along the way or if im missing something

ivory sorrel
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,w limit of (3x^2-x+5)/(x^3-x) at x=1

ivory sorrel
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well, doesn't look like the integral exists

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,w integrate (3x^2-x-5)/(x^3-x) from 1 to 2

blazing tartan
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okay. thank you, i was confused if i did something wrong but i guess it doesnt exist.

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topaz sinewBOT
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thorn cairn
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@pseudo sonnet Thank you so much.

topaz sinewBOT
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rain hinge
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I am trying to understand this function:

topaz sinewBOT
rain hinge
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Not sure what the TT symbol is

pseudo horizon
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it's a capital pi

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it stands for "product"

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it's like the big sigma

coarse tusk
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it's like the Sigma but for products instead of sums

rain hinge
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Oh so everything right of it from 1 to i-1 is multiplied by itself

pseudo horizon
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it's a product of i-1 terms
each term looks like (1-alpha_j)

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with different values of j

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i guess "term" might not be the right word

rain hinge
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is it like a nested forloop where as i increases it restarts the capital pi?

pseudo horizon
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for i in N:
    product = 1
    for j in [1...i-1]:
        product *= 1-alpha[j]
    C_p += c[i] * alpha[i] * product
return C_p```
rain hinge
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Wow I see it

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Thx!

topaz sinewBOT
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@rain hinge Has your question been resolved?

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ripe maple
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I have an issue with quadratic equations

topaz sinewBOT
ripe maple
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Give me a similar problem to solve

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That the roots are not negative

topaz sinewBOT
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@ripe maple Has your question been resolved?

desert atlas
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use vietas formula to find the quadratic

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and solve the quadratic to find the roots

ripe maple
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fast sluice
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how do i implicitly differntation

topaz sinewBOT
desert atlas
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differentiate term by term

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using the chain rule for terms with a y

fast sluice
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so would xy be 1 times dy/dx

desert atlas
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no

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product rule

fast sluice
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y + x timed dy/dx?

hoary burrow
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Yeps I guess

fast sluice
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x turns into 1 and y turns into dy/dx

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y+x * dy/dx + 1 + dy/dx = 2x * 2 dy/dx

desert atlas
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product tule again

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for x^2 y^2

fast sluice
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oh whoops

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2x * y^2 + x^2 * dy/dx^2

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topaz sinewBOT
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desert atlas
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uh no it would be 2y dy/dx

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not dy/dx ^2

topaz sinewBOT
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tiny pawn
topaz sinewBOT
tiny pawn
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please someone explain it to me

topaz sinewBOT
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@tiny pawn Has your question been resolved?

topaz sinewBOT
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@tiny pawn Has your question been resolved?

tiny pawn
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.close

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velvet briar
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@topaz sinew

topaz sinewBOT
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still bough
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how do i begin to solve this?

topaz sinewBOT
#

@still bough Has your question been resolved?

still bough
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<@&286206848099549185>

topaz sinewBOT
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@still bough Has your question been resolved?

topaz sinewBOT
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@still bough Has your question been resolved?

topaz sinewBOT
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wispy hedge
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hi, i'm stuck in this question (my working is below the question in blue)

deep forum
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area*depth should give volume

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depth is 14cm/s, find out what it is for 3 minutes

wispy hedge
deep forum
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👍

wispy hedge
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yay ty

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topaz sinewBOT
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deep forum
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ur welcome

topaz sinewBOT
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glossy sun
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Does anybody know how I can solve this equation with exact values

dusk lava
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start by factoring a 2cos^2x out of the first 2 terms then factor by grouping

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you also need to factor a -1 from the second 2 terms in order to factor this way

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maybe will help with finding values?

glossy sun
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Yeah I tried that but then I keep getting stuck

dusk lava
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can i see your work

glossy sun
dusk lava
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hmm

glossy sun
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Square both sides then expand and simplify maybe?

dusk lava
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i mean maybe but seems tedious

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just looked at the answers and they seem really really messy

topaz sinewBOT
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@glossy sun Has your question been resolved?

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topaz sinewBOT
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exotic saddle
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how to answer?

topaz sinewBOT
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twin pollen
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help plz

topaz sinewBOT
twin pollen
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this is the answer to the queston and I was wondering why my teacher adds a plus one in the blue box

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plz @ me when replying

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thx

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I have to get going within the next 30 mins also

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so hopefully i can get some help before then

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acc no my question is why are we minusing 233 from 112

topaz sinewBOT
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@twin pollen Has your question been resolved?

mint crescent
twin pollen
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ic alr. i dont get this tho

topaz sinewBOT
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@twin pollen Has your question been resolved?

twin pollen
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sorry wrong question this is it

desert atlas
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f(x) is the notation for a function

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you cant change stuff about it

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other than the x inside

twin pollen
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so u cant say this @desert atlas

desert atlas
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nope

twin pollen
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but all the y values are positive

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@desert atlas

desert atlas
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the notation f|x| makes no sense

twin pollen
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cause for this question my teacher kinda did that

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:

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like for a why is there all the sudden absolute value lines

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@desert atlas

desert atlas
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f(|x|) is fine

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f( ) refers to the function taking in the input

twin pollen
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oh ok but like for a cant u also just write y= f(x+4)

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since the orginal graph is y=f(x)

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and its going to left by 4

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@desert atlas

desert atlas
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yes it shifts the graph to the left

twin pollen
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so then why did my teacheer add those absolute value lines?

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@desert atlas

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is it because the orginal graph of y= f(x) can also be written as y= f(lxl)

desert atlas
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no

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do you what the absolute value does?

twin pollen
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ya idk why i said that im just tryna make it make sense

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it makes all y values positive

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right @desert atlas

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?

desert atlas
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stop pinging me

twin pollen
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oh sorry

desert atlas
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what does it do geometrically to the graph

twin pollen
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it make like a triangle

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kinda

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like y=lxl makes like an upside down triangle thing

desert atlas
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ok but not just |x|

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if you absolute value any graph

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what is the change

twin pollen
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there would be no negative y valies

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right

desert atlas
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yes

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the negative sections of the graph would be flipped

twin pollen
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but what if there is a vertical translation down

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then would it still not be negative

desert atlas
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if theres a shift down

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then it could be negative

twin pollen
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oh ok

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so then bavk to my question of why is there all the sudden absolute value lines in my teachers answer

desert atlas
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because the graph shows it

twin pollen
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wait so y=f(x) is like input x into a specific function?

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right

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im confused on difference between y= lxl and y = f(lxl)

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cause my teacher gave us this

desert atlas
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y = |x| is the absolute value function

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y = f(|x|) could be anything

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depending on f(x)

twin pollen
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ok ic

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thanks

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i might have one more question

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actually

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one sec

twin pollen
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if u have (y-6) squared and u take the root shouldnt it be plus minus

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@desert atlas

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o wait sorry for pinging

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my bad

desert atlas
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sqrt (x^2) = |x|

twin pollen
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but how

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and so does that mean that root of 9 and root of 3 different

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i meant root of 3 squared

desert atlas
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sqrt 9 is 3

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sqrt 3^2 is 3

topaz sinewBOT
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@twin pollen Has your question been resolved?

topaz sinewBOT
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topaz sinewBOT
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quiet phoenix
topaz sinewBOT
quiet phoenix
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could this be solved just by plugging in the integral into my calculator and adding 1200?

topaz sinewBOT
#

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topaz sinewBOT
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@quiet phoenix Has your question been resolved?

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topaz sinewBOT
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ivory sorrel
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How would I prove that the set of rationals with 10|p| \geq q is dense

chilly walrus
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if q is negative

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then this always holds

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no?

ivory sorrel
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wdym

chilly walrus
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take for example 1/(-2)

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10*1 > -2

gilded plume
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By p and q do you mean numerator and denominator?

chilly walrus
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although this is the same as (-1)/2, hmm

topaz sinewBOT
gilded plume
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Isn’t this false

ivory sorrel
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It is?

gilded plume
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It is notably empty on the subset between 0 and 1/10 right

ivory sorrel
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I mean one counter example I thought of is 1/10 and -1/10

ivory sorrel
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sorry

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ivory sorrel
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thanks

topaz sinewBOT
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modern berry
#

How would you calculate the depth of a well from just knowing the speed of sound, the amount of time it takes to hear a rock hit the bottom and how fast the rock is falling?

deep forum
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if you hear the echo back in 4 seconds, that means the well is 2 sound seconds deep

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how fast the rock is falling depends on the g

warm turtle
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u can use that fact to determine the exact depth of the well, based on how many seconds it took for the sound of the rock hitting the bottom to reach the top of the well

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for that second part, a hint is that you can use the kinematic equations for free fall!

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which cannot be solved unless you first solve how deep the well is

topaz sinewBOT
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@modern berry Has your question been resolved?

modern berry
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Speed of sound is 333 m/s and the rock is falling 4.9x^2 meters every x seconds

warm turtle
modern berry
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what formula could be used for that?

warm turtle
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hold on, but the seconds taken to hear the rock fall is not given right?

modern berry
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yes it is

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2 seconds

warm turtle
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okay

warm turtle
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velocity = distance/time

modern berry
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so isolate distance: distance = velocity/time

warm turtle
modern berry
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oh yeah, sorry

warm turtle
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it's ok!

modern berry
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so d=333*2

warm turtle
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yes

modern berry
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d=666

warm turtle
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yes

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for the second part, since now you have a distance

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you can use kinematic equations to solve for the velocity of the rock as it is about to hit the floor

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it would be the final velocity

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that you are looking for

warm turtle
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note that you should choose the equation that does not have any variable that is not given in your problem!

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there are actually two valid equations you can use

modern berry
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okay thanks

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topaz sinewBOT
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topaz sinewBOT
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static juniper
#

rho(h) is the density of a liquid in a container upto a depth h from the free surface and is given by rho(h) = k(1 + h/b) where k and b are positive constants with units of density and height respectively. How would you calculate the density of the liquid upto a depth d? Would you just put in h=d? Or how would I integrate it?

whole geode
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If you want the average density of the material you would need to integrate and then divide by the height. If you want the density at the depth d then you just plug in the equation.

static juniper
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how would you integrate it? i started by writing dm/dV = rho(h)
dm = rho(h) × A dh ( A is the area of the bottom)
idk what to do next

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No response, sad

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sharp chasm
#

Given the following linear map:

[
f: \mathbb{R}^3 \to \mathbb{R}^3
]

such that ( f(x,y,z) = (3x, x+y, y-z) ). Given the basis ( \mathcal{B} = { v_1, v_2, v_3 } ), where ( v_1 = (1,0,0) ), ( v_2 = (0,1,0) ), and ( v_3 = (0,0,2) ), determine the matrix associated with the linear map ( f ) with respect to the basis ( \mathcal{B} ): ( \mathcal{M}_{\mathcal{B}}^{\mathcal{B}} )

thorny flameBOT
#

jandro0103

sharp chasm
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Advice on what I should start?

jade thunder
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well, M_B^B and M_B, B is the same thing

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since it's the same basis in and out you needn't worry about it much

sharp chasm
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@jade thunder thx

thorny flameBOT
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jandro0103

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jandro0103

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jandro0103

sharp chasm
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@jade thunder like that?

jade thunder
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yep

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good job

sharp chasm
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nice!

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topaz sinewBOT
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halcyon owl
#

can some one help me problem inner product 105 so that i have ideas to solve 105 to 108 , i think inner product is x1x2+y1y2 so what i should do now and when i have the idea can i apply same idea for 107 c

alpine mist
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An inner product is a generalization of the dot product. In a vector space, it is a way to multiply vectors together, with the result of this multiplication being a scalar. More precisely, for a real vector space, an inner product <·,·> satisfies the following four properties. Let u, v, and w be vectors and alpha be a scalar, then: 1. =+. 2. =...

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You need to verify that your <v>u satisfies the 4 inner product properties.

halcyon owl
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wow i see 4 propertise, ive used them a lot in high school now i know their name are inner product hh

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steel frost
#

Hi

topaz sinewBOT
steel frost
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Can someone help

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<@&286206848099549185>

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<@&286206848099549185>

topaz sinewBOT
#

@steel frost Has your question been resolved?

steel frost
#

No it hasnt

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<@&286206848099549185>

neon iron
#

What have you tried?

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@steel frost

steel frost
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Change of question i did that

neon iron
#

Which specific part do you require help with?

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Or is it just all of them?

steel frost
topaz sinewBOT
#

@steel frost Has your question been resolved?

topaz sinewBOT
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sharp flower
#

is this correct?

topaz sinewBOT
vernal shard
sharp flower
#

alright ty

#

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topaz sinewBOT
topaz sinewBOT
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@brittle summit Has your question been resolved?

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eager flicker
#

Hello, can someone explain what does this mean?

eager flicker
#

the $\mathbb{K}[X]/{0_{\mathbb{K}[X]}}$

thorny flameBOT
eager flicker
#

all polynomials except... $0_\mathbb{K}[X]$, i have no idea what that is

thorny flameBOT
vernal matrix
#

The zero polynomial

#

B is some polynomial in K[X] apart from the zero one

eager flicker
vernal matrix
eager flicker
#

sorry i am still confused

#

is it related to this?

#

so n = 0 => 0
n = 1 $a_kx^0+a_kx^1$

thorny flameBOT
eager flicker
#

something like this?

vernal matrix
#

You could choose n = 0 for both, and a0 as the 0 or 1 from K for the respective 0 and 1 from K[X]

eager flicker
#

$0_\mathbb{K[X]} = 0 \
1_\mathbb{K[X]} = a_k \
2_\mathbb{K[X]} = a_0+a_1x \
3_\mathbb{K[X]} = a_0+a_1x+a_2x^2$

thorny flameBOT
vernal matrix
#

The 0 and 1 are referring to the fact that those are the 0 and 1 from the ring K[X]

eager flicker
#

what ring?

vernal matrix
#

K[X], the ring of polynomials in X over K

eager flicker
#

so then 0 and 1 are just 0 and 1?

vernal matrix
#

Pretty much, yep (any other coefficient of X, or any higher power of, is zero)

eager flicker
#

and two is just a polynomial of degree 2?

#

with any given coefficient

vernal matrix
#

Not quite no, and usually these aren't used

eager flicker
#

this confuses me so much. so then all polynomials with a degree of two or less?

vernal matrix
#

You only care about 0 and 1 because of e.g. "0 + anything is the same thing, and multiplying 1 by anything doesn't change it"

#

No, not at all, they are specifically 0 and 1 only

#

$0_{\mathbb{K}[X]}$ is only $0 (+ 0X + 0X^2 + \ldots)$, and $1_{\mathbb{K}[X]}$ is only $1 (+ 0X + 0X^2 + \ldots)$

thorny flameBOT
#

@vernal matrix

vernal matrix
#

Whole point being those are the additive and multiplicative identities of K[X]

eager flicker
#

oh

#

thank you so much

eager flicker
vernal matrix
#

There may be cases where they are, but I have rarely seen them (and in the cases I have seen, then e.g. 2 is just taken as 1 + 1, 3 is just 1 + 1 + 1 etc, with the 1 from the respective ring that you're from)

topaz sinewBOT
#

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glossy wave
#

if you have 5 types of balls and 20 of each in a box. You pick 70 of them at random, how many ways can u do this?

keen raptor
#

It's convenient to think about the 30 that aren't being chosen here

#

let's say the number of balls that wasn't being chosen was smaller, like 15

#

Would you be able to solve it then?

glossy wave
#

um

#

maybe in each subset u could number the balls

#

so in the questions the balls were coloured

#

Red Blue Green Purple Orange

#

So you could do like R1 ... R20, B1,...,B20 etc

#

now u have 100 individual balls

#

number of ways of picking 15 of them is 100 x 99 x 98 x ... x 86

#

but we need to now divide by something

keen raptor
#

The thing you need to divide by to correct for overcounting varies depending on how many balls of each color you have

#

So this method doesn't work

#

Have you heard of stars and bars?

glossy wave
#

oh right i see

keen raptor
glossy wave
#

like u if u had 3 yellow balls

#

you would divide by 3!

#

but that could change?

glossy wave
keen raptor
#

Well this problem is probably too difficult then

#

I'd start by learning that

glossy wave
#

okay cool

keen raptor
#

Do you know inclusion exclusion?

glossy wave
#

um maybe

#

ill need to see the formula or smth

keen raptor
#

I think that also shows up

#

only in the form $|A \cup B| = |A| + |B| - |A \cap B|$

thorny flameBOT
#

Dreyuk

keen raptor
#

actually maybe you don't even need that

#

ok

glossy wave
#

yeah ive seen that

#

i think i might have seen stars and bars before

#

it rings a bell

keen raptor
#

nvm no inclusion exclusion but stars and bars

glossy wave
#

but i'll need to brush up on it

keen raptor
#

number of nonnegative integer solutions to a+b+c+d+e = 15 basically

glossy wave
#

why is that important

#

oh right

#

how many reds how many blues etc

#

and then they add up to 15

topaz sinewBOT
#

@glossy wave Has your question been resolved?

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ruby wadi
topaz sinewBOT
ruby wadi
#

I feel like the first question should have a simple solution but the usual method doesn't work for me here

#

if anyone has an idea that would be helpful

topaz sinewBOT
#

@ruby wadi Has your question been resolved?

ruby wadi
#

man I feel like it's very simple

sharp vigil
#

How about geometric mean?

#

[v_(n+1)]*[v_(n-1)] = [v_n]^2

#

Put in values

#

I think you get a linear outta this

#

Solve it

#

Get alpha

#

@ruby wadi

ruby wadi
#

what

#

I don't even see what you're attempting to do

ruby wadi
#

I got it

#

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ruby wadi
#

.reopen

topaz sinewBOT
#

ruby wadi
#

man I'm so dumb for that

#

how did I not see it

#

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south peak
#

I'm writing some notes for myself regarding linear algebra. Is this a mathematically correct definition of the transpose operation?

ivory sorrel
#

I think it is, but leyt someone else confirm

young geyser
#

correct

south peak
#

That's 3 votes of confidence. I'll take that.

#

Thank you, all.

#

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frozen sun
#

how do i find x

topaz sinewBOT
frozen sun
#

im kinda stuck

#

do i make new pararell lines

zinc spire
#

5x + 3x = 180 degrees

frozen sun
#

well yes but thats because i made a new pararell line is that okay

zinc spire
#

Yes

#

Just supplementary angles

frozen sun
#

okay i think i got it

#

x = 22.5

#

checked with a protractor

#

ty

#

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dull scaffold
topaz sinewBOT
dull scaffold
#

I have an idea but dont know what to do next

sweet shard
#

What is the idea

dull scaffold
#

i use (2x-3)/(x-1) as F and i get (2x-3)/(x-1)+(x-3)/(x-2) and I think im supposed to plug (x-3)/(x-2) into the equation but idk

sweet shard
#

F(F(x)) would be difficult to compute yes. But not impossible. The main concern is how you came up with that guess in the first place

topaz sinewBOT
#

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kindred hollow
#

Can someone help me understand supremum and infamum. I seem to keep confusing it with max and min

kindred hollow
#

Say you have a set A = [0,2]

#

The sup A and max A would be 2

#

Inf A and min A 0

#

Now say you have a set B = (0,2)

#

I understand that the max B and min B dont exist

mystic jay
#

the supremum of a set S

#

is K

kindred hollow
#

But I don't understand why Sup B is 2 and Inf B is 0

ivory sorrel
kindred hollow
mystic jay
#

do you agree 2 is an upperbound

ivory sorrel
#

Sure, now expad upon the definition of an upper bound

kindred hollow
mystic jay
#

upper bound means any value which is greater than or equal to all members of a set

kindred hollow
#

My guess is that it would be the number before 2 in the set of Reals

kindred hollow
ivory sorrel
#

if I have a number in the set say $2 - \varepsilon$ and $2$, can you find me a number between tehm

thorny flameBOT
#

ƒ(Why am. I here)= I don't know

mystic jay
#

it doesnt have to be in the set, right?

kindred hollow
#

Correct

#

Oh

#

Wait

#

So sup doesnt have to be in the set either?

mystic jay
#

no

kindred hollow
#

Ah ok

#

So in (0,2) that smallest number you could produce in the upper bound would be 2

mystic jay
#

yes

kindred hollow
#

Cause I domt think its possible to write a number before that in the set of Reals

mystic jay
#

yes

kindred hollow
#

Ok, that makes sense

#

That answers my question

#

Thank you everyone

#

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frozen sun
#

help how do i find C

topaz sinewBOT
frozen sun
#

oh wait

#

x = c

#

cuz x + 3x = 4x

#

but how do i get x

#

i got x = 36
with the equation
x = 180 - 4x

#

and yup

#

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hoary fable
#

Hi for part b, I used reverse chain rule and got everything right except the bounds. How do I know what numbers the bounds change to? (hopefully that makes sense)

lethal anchor
cunning kayak
#

hint: try seeing denominator

hoary fable
#

this concept

lethal anchor
hoary fable
#

this is what i did

lethal anchor
#

yeah so you are actually almost right

hoary fable
#

yea its just the bounds right?

lethal anchor
#

but but the last line here, you substituted incorrectly

hoary fable
#

oh huh?

lethal anchor
#

the algebra is wrong

#

can you see it?

hoary fable
#

oh crap the 0

lethal anchor
#

not only that

hoary fable
#

wait what

lethal anchor
#

so what is [
\frac{(5\cdot 1^2 + 1)^{-2}}{-2}
]

thorny flameBOT
hoary fable
#

-1/72?

lethal anchor
#

yeah

hoary fable
#

isn't that what i wrote

lethal anchor
#

oh i read that as -1/12

#

lol

#

but yeah the 0 is incorrect

hoary fable
hoary fable
#

.close

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#
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cunning kayak
#

uhm, wait lemme check

#

yup correct

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torpid inlet
#

<@&286206848099549185> what is a trajectory equation? Explain it in brief with some examples if possible, thanks!!

cunning kayak
#

equation of trajectory

trajectory is the path of an object with mass, such as a kicked ball

#

like this

torpid inlet
#

Can we say there's a quadrilateral where at the end, the particles are moving? And then we have to find the equation of the curve?( what I meant through the curve is that diagonals of that quadrilateral(let's take square) are behaving as the two curves and we have to find out their equations

#

Should i show you that figure @cunning kayak

cunning kayak
#

show

torpid inlet
#

At the end which are the vertices, particles are there moving around

cunning kayak
#

yes we can say

torpid inlet
#

Will you help me out with one more doubt man? I'm trying to figure how does that happened

#

It's from the nuclear physics

cunning kayak
#

yeah my physics sucks XD

#

i am good at math

#

but sure

#

my nuclear is good

torpid inlet
#

So, I had already found out the answer

cunning kayak
#

jee adv 💀

torpid inlet
#

However there was one solution where that educator did that with another thing( I wanna figure out, how?

cunning kayak
#

sure i rule out

torpid inlet
#

Man?

#

Excluding you mean? I don't know the meaning of rule out!!

cunning kayak
#

i mean yeah dont ask me

torpid inlet
#

Hahha, my bad

cunning kayak
#

my phy is not good

#

ask anything in maths, sure

torpid inlet
#

Bbye then, thanks for the help

torpid inlet
cunning kayak
#

done

torpid inlet
#

Bbye man!

#

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mystic siren
#

why do i need to use induction to prove the h_n=2^n-1? this seems sufficient

acoustic pecan
#

because youre just assuming the pattern continues

#

its not a complete proof

#

by all means its logically sound to make that conclusion, its just not a proof of it for all n

hearty turret
#

ofc if like ur like quite far ahead in ur mathematical career, i doubt u'll need to prove it that formally but basically here u want to say "continue this process n times" and the way to do that is induction

mystic siren
#

like it's in fact correct

mystic siren
#

if i have the recurrence relation proved

acoustic pecan
#

it is a correct assumption

#

its not a complete proof of it

mystic siren
#

i have the recurrence relation and the base cases

celest charm
rigid ivy
dawn tulip
#

Hay I'm 15. and i had a math test not to long ago, one pat of a problam was 48÷3, and i used a method i had thought of two day's ago, and dont remember if i came up with it or not so heres it breakdown:

Step 1: factorization.
Express the divided number (48) as a product of two numbers: 48 = 8•6.

Step two: first divison.
Divide the second factor (6) by the divisor (3) to get 6÷3=2.

Step three: second multiplication.

Multiply the first factor (8) by the result of the first factor by the result of the first division 8•2=16.

And that's hoe i solved it so what methid is it?

topaz sinewBOT
#

@mystic siren Has your question been resolved?

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frozen sun
#

im confused

topaz sinewBOT
frozen sun
#

so the measure of the other two angles are 0-180 right

#

there are 3 angles and 100 is in the middle

#

yall idk

#

is 100 the starting point or is 0 the starting point

hoary burrow
#

Alright so an arithmetic progression

#

Is where each number in the sequence has the same difference from its previous number

#

Right

frozen sun
#

yes

hoary burrow
#

So

#

Let's notate this difference as k

frozen sun
#

but how do i get 180 from 100 with the same difference

#

bro just left

hoary burrow
#

Gimme a sec

#

So where x is the first term

#

3x+2k=180

frozen sun
hoary burrow
#

Sorry I was having lunch

#

And yea I made a typo

#

x+(x+k)+(x+2k)=3x+3k

#

x is the first term

#

x+k is the second

#

And x+2k is the third

#

So 3x+3k=180
Or x+k=60

#

Oh and this quite coincidentally gives us our second term

#

So we can find all 3 measures now

#

@frozen sun

frozen sun
#

oh

#

so since one angle is 100, and another angle is 60, then the last angle is probably 20

#

cuz they all have a difference of 40

#

and add up to 180

#

tyvm for your time 😭🙏

#

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strong shore
topaz sinewBOT
strong shore
#

I'm up to part (d) and i'm not quite sure how I can show that $100 < l < 110$ and $64 < w < 75$

thorny flameBOT
#

Michele

desert atlas
#

could you send a screenshot

strong shore
#

Figured it out

#

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iron blaze
#

Two capillary tubes AB and BC are joined end to end at B, AB is 16cm long and of diameter 4mm whereas BC is 4cm long and of diameter 2mm. The composite tube is held horizontally with A connected to a vessel of water giving a constant head of 3cm and C is open to the air. Calculate the pressure difference between B and C. (In centimeters of a column of water)

I tried to solve this by solving for the pressure difference between A and B, which is rho * g* h which is 1 * 980 * 3 = 2940 Ba
Then I recalled the equation of continuity
a1V1 = a2V2 a1 = pi * 0.2 ^2 a2 = pi * 0.1^2 V1 = pi/8 * 2940 * 0.2^4/(η * 16) V2 = pi/8 * p * 0.1^4/(η4)
We want to find p/(rho g) to find the column of water

However when solving for p ( i got 47040) which corresponds to 48 cm of water, but the answer is 2.4 cm How did I go wrong by a factor of 20?
Here is the solution online (which I didn't understand)
https://youtu.be/K7SCruah6ds?si=cMvtRLFyX8eOxQeC

topaz sinewBOT
#

Please don't occupy multiple help channels.

iron blaze
#

here is an image for reference, note that the numbers are different
also i tried my method for this one too, and again my answer is off by a factor of 20

odd forge
#

close one channel

iron blaze
#

<@&286206848099549185>

gilded plume
#

you literally posted it twice in the span of one minute

#

close one

#

nobody is reading that in one minute

ivory sorrel
#

I think you may get more help in the physics server for this question

iron blaze
gilded plume
iron blaze
#

would you help

topaz sinewBOT
#

@iron blaze Has your question been resolved?

iron blaze
#

<@&286206848099549185>

topaz sinewBOT
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@iron blaze Has your question been resolved?

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quartz geyser
topaz sinewBOT
quartz geyser
#

How to start solving this one?

weary crystal
# quartz geyser

approach (0,0) along two different paths. if the limit is different for those paths, the limit can't exist

#

for example, maybe one path is along the line y = x

topaz sinewBOT
#

@quartz geyser Has your question been resolved?

ivory sorrel
#

approach it along say x=0 and x=y

topaz sinewBOT
#

@quartz geyser Has your question been resolved?

quartz geyser
#

So should I put x=y and compute?

wintry hill
#

and then try another paths

quartz geyser
quartz geyser
wintry hill
quartz geyser
#

by approach, U mean the +h stuff?

wintry hill
#

first just plug x=0, so only y left under the limit. Then usual rules for calculating the limit of one variable.

quartz geyser
#

0o0

wintry hill
quartz geyser
wintry hill
#

yep

quartz geyser
#

Is this the correct progression?

wintry hill
#

yes, but at this point -1/2 is enough. So you took two different paths approaching (0,0): one along the line x=0 and the one along the line x=y. They gave different results (-1/2 and 0). What is the conclusion?

quartz geyser
#

It's not continuous at that point

wintry hill
#

that is the corollary. The main conclusion is: the limit does not exist

quartz geyser
#

Thank you.
Understood.

#

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twin apex
#

How would I find all the intervals in which

h(t)-6.8cos(pi/30(t))+8.3
h(t)-6.8cos(pi/30(t-12))+8.3
h(t)-6.8cos(pi/30(t-24))+8.3
h(t)-6.8cos(pi/30(t-36))+8.3
h(t)-6.8cos(pi/30(t-48))+8.3

these five graphs are all greater than 1.86 meters within two periods.

topaz sinewBOT
#

@twin apex Has your question been resolved?

twin apex
#

<@&286206848099549185>

twin apex
#

I don’t need the answer I just need to know the way to do it algebraically

twin apex
#

<@&286206848099549185>

topaz sinewBOT
#

@twin apex Has your question been resolved?

twin apex
twin apex
# rigid ivy what is h(t)?

h(t)=-6.8cos(pi/30(t))+8.3
h(t)=-6.8cos(pi/30(t-12))+8.3
h(t)=-6.8cos(pi/30(t-24))+8.3
h(t)=-6.8cos(pi/30(t-36))+8.3
h(t)=-6.8cos(pi/30(t-48))+8.3.
Each one of these five graphs represents a blade on a windmill. within 120 seconds (two periods) how do I find all the intervals in which all graphs are simultaneously greater than 1.86 meters
the context of the question is you are stuck in a windmill and within two periods which is 120 seconds in this case, you have to find all the intervals somebody who is 1.86 meters tall would be able to walk out

how do i solve this algebraically

rigid ivy
#

You'd have to find the intervals for each function, and then calculate their intersection

twin apex
rigid ivy
thorny flameBOT
twin apex
#

I’ve gotten to this point so far

#

I have where they are all part of the interval individually but idk how to find when they all are simultaneously

rigid ivy
topaz sinewBOT
#

@twin apex Has your question been resolved?

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#
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supple yarrow
#

Hi, I need help with dividing decimals as i've never done it before and I have a math midterm tmr. I heard you are supposed to multiply the numbers by 10 then place them but it's still quite confusing.

sterile finch
#

It helps to multiply by a whole fraction in such a way that it eliminates the decimals.

supple yarrow
#

im also watching math with mr. j lol

sterile finch
#

100/100

#

You want a whole fraction.

supple yarrow
#

and that would b

#

be

#

.2?

torpid sparrow
#

No

#

2 = 2

sterile finch
#

No, just 2.

supple yarrow
#

alr

#

dont you have to move the point back?

sterile finch
#

10/10 is a whole fraction that is equal to 1. That is a valid math operation that you can use to simplify a problem.

supple yarrow
#

ok

sterile finch
#

Another example.

supple yarrow
#

👍

#

ty

sterile finch
#

yw

supple yarrow
#

well the divisor

sterile finch
#

That's what I do. No point in complicating it by counting decimal positions and adding it on at the end imo.

supple yarrow
#

ok ty

sterile finch
#

You could do 123/3 = 41 and add the decimal to get 4.1 but that come across as hacky.

supple yarrow
#

alr

#

ty

sterile finch
#

Or 12.3/3 = 4.1 which also more direct.

#

Up to you.

#

Now that I think about, just eliminating the decimal in the denominator seems the easiest route.

supple yarrow
#

how do you know when you're dividing that the decimal is repeating

sterile finch
#

As in 0.3333...?

supple yarrow
sterile finch
#

Well, when you start doing the division, it will start repeating at some point.

supple yarrow
#

👍

supple yarrow
#

.close

topaz sinewBOT
#
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weak vessel
#

hey

topaz sinewBOT
weak vessel
#

anyone know how to do this?

#

<@&286206848099549185>

topaz sinewBOT
#

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weak vessel
#

.close

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hollow bough
topaz sinewBOT
spring tide
#

So if you know how to derivative

#

You can just derivative the formula

#

If you dont, just use x=anypoint

#

Calculate y

fallow igloo
#

Watch it yourself

spring tide
#

And then y2-y1/x2-x1

hoary burrow
#

You don't have to calculate anything

spring tide
#

I mean most basic way

frigid wyvern
faint thistle
hoary burrow
topaz sinewBOT
# faint thistle The slope is 4

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

hoary burrow
#

But yea I guess

hollow bough
#

I think I understand what y’all said tho

hoary burrow
#

It's just a 1 second question if you know your stuff

hollow bough
#

I got it

#

Thanks

#

.close

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#
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#

Please don't occupy multiple help channels.

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half compass
#

This is going to sound stupid but how would you solve this

half compass
#

Im really bad with fractions

leaden gorge
#

is it equal to something

half compass
#

mb its solving for y

#

i forgot to draw that

#

its that = y

leaden gorge
#

so you want to simplify it?

half compass
#

yea

#

not solve

#

duh

#

mb

#

(duh on my part )

leaden gorge
#

wait one sec

#

yeah multiply all 3 parts by x+4

sharp vigil
#

$\frac{x+4}{1-(x+4)}$

thorny flameBOT
#

lex.in.a.teacup

leaden gorge
#

like that ^

sharp vigil
#

This what you should get after multiplying numerator and denominator by x+4

#

@half compass

half compass
#

ok

#

i see

#

so its x+4 / -x-4?

leaden gorge
half compass
#

oh yea combine the 1 - 4

#

mb

#

.close

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potent linden
#

how do i solve 36?

topaz sinewBOT
potent linden
#

i lowk forgot

pearl brook
#

𝐴
A is the amount of money accumulated after
𝑡
t years, including interest.
𝑃
P is the principal amount (the initial money you invested or borrowed).
𝑟
r is the annual interest rate (decimal form, so 5% would be 0.05).
𝑛
n is the number of times the interest is compounded per year.
𝑡
t is the number of years the money is invested or borrowed for.

#

$A = P \left(1 + \frac{r}{n}\right)^{nt}$

thorny flameBOT
potent linden
#

oh yes thank you

#

i just forgot what to do when i plug all the values in

#

since im looking for t

#

would you happen to know?

pearl brook
#

would not just be 4

#

cuase quartly

potent linden
#

uhhh

#

t is for time passes

#

n is for number of times

pearl brook
#

oh

#

my bad

potent linden
#

nw

#

^^

#

i think i have to use logs but idk how

#

in what way

pearl brook
#

yeah

#

i dm you what ai siad

potent linden
#

i don’t trust ai

pearl brook
#

ok

#

dont trust me

#

sorry for being annyoing

potent linden
#

it won’t solve the problem if you didn’t plug in values

#

i didn’t accuse you of anything i just said i didn’t trust ai

pearl brook
#

yeah

#

ik

#

i did not mean like that either my bad

#

mb

potent linden
#

um its fine lol

pearl brook
#

np

potent linden
#

got it in my own :))

pearl brook
#

nice

#

you just leaked your caluctor fx-991 plus

potent linden
#

indeed

#

good calc

#

.close

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#
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fading grove
#

I need help studying for a math test in pre calc tomorrow, I have the study guide. Mainly in questions 7,8 ,and 9

fading grove
topaz sinewBOT
#

@fading grove Has your question been resolved?

fading grove
#

<@&286206848099549185>

grim pike
thorny flameBOT
grim pike
#

For 9, use the properties of logarithms: $\log(ab) = \log(a) + \log(b)$, $\log(a/b) = \log(a) - \log(b)$, etc.

thorny flameBOT
topaz sinewBOT
#

@fading grove Has your question been resolved?

fading grove
#

are you able to explain over vc?

grim pike
#

I don't think this server has voice channels.

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#

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neon iron
topaz sinewBOT
neon iron
#

for question b

topaz sinewBOT
#

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neon iron
#

how to solve this question

topaz sinewBOT
wintry nymph
#

i'll move somewhere else

neon iron
#

thanks

wintry nymph
#

np

neon iron
#

i am sharing my solution

#

This is what I solved

#

What I don't understand is, shouldn't it be 2 times -cosycosx?

#

can someone help please

#

@wintry nymph sorry for the tag, but can you delete your question.. so that it doesnt create a confusion.. sorry i dont know how this server works

wintry nymph
#

oh yeah sure

molten spoke
#

,rotate ccw

thorny flameBOT
coarse herald
neon iron
#

but arent we adding both the terms?

coarse herald
#

-cosxcosy is a function of both x and y to differentiate it you will take the partial derivatives with respect to both x and y which gives you the terms

pallid harness
# neon iron can someone help please

i don't know how much this would help but have you looked at this
https://youtu.be/HF_wG2VTf4c
?

Hello, People!

Here is a video of Exact equation problem. Performing partial derivative of M and N, also integration as well under certain conditions. Please do watch the video till end to learn better.

My hearty thanks to all the subscribers, supporters, viewers and well-wishers❤.

With Love,
Chinnaiah Kalpana🍁

Note:

  • Let M(x,y)dx+N(x,y)d...
▶ Play video
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obsidian sparrow
#

How am I supposed to solve for sin(-45) with only the hypotenuse value? cant use pythagorean theorem because i only have 1 sides values

wispy pier
#

🙂

#

45° right ?

#

And one right angle

obsidian sparrow
#

-45

#

yes

wispy pier
#

Whoa you discover the other angle of triangle is 45° too

#

You realise now it's an Isosceles triangle!!

obsidian sparrow
#

awesome balls now what

wispy pier
#

Now you further understand it's an Right Angled Isosceles, and you can figure out the lengths

obsidian sparrow
#

how do i do that

wispy pier
#

Bruh

obsidian sparrow
#

lmao

wispy pier
#

Let one side be a

#

Then other side is a too

#

Then apply pythagoras theorem

#

a² + a² = 1² !!!!!

#

Pythagoras was really a chill guy, no ?

obsidian sparrow
#

yea

#

a^2 + a^2 is just a^2 is it not

wispy pier
#

🤧

obsidian sparrow
#

2a^2

wispy pier
#

Shall I say you

obsidian sparrow
#

i just woke up

wispy pier
#

Is a right angled triangle

obsidian sparrow
#

yes

wispy pier
#

It's a right angled Isosceles triangle

obsidian sparrow
#

yes

wispy pier
obsidian sparrow
#

i already know the hypotenuse

#

its 1

wispy pier
#

Cool

#

So lets consider the length of one unknown side "a"

#

Since its an Isosceles, another unknown side from the figure can also be said to be of length "a"

obsidian sparrow
#

okay

wispy pier
#

Nah say me

#

What you understood

obsidian sparrow
#

because its an isosceles the unknown sides are the same length

wispy pier
#

Have you ever drawn them on a paper and verified ?

obsidian sparrow
#

like right neow

#

yea

wispy pier
#

Cool !

#

So now we go ahead

#

With what sir pythagoras taught us

obsidian sparrow
#

yes

wispy pier
#

He said, "If it's a right, you just remember me, coz i am the only man who was always right"

obsidian sparrow
#

wait no

wispy pier
#

Cool

#

You did it

#

Eureka!

obsidian sparrow
#

no

#

its wrong