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Hey guys.
Where is the general channel?
if you have a question, please ask now 
otherwise, I'm gonna close this channel
hm, well
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can someone help me with this integral? the question asks me to evaluate the integral. What i dont understand is that after I finish integrating and substituting the upper and lower values of the integral, i end up with 'ln | 0 |' and i believe its undefined there. So i dont understand if i did something wrong along the way or if im missing something
,w limit of (3x^2-x+5)/(x^3-x) at x=1
well, doesn't look like the integral exists
,w integrate (3x^2-x-5)/(x^3-x) from 1 to 2
okay. thank you, i was confused if i did something wrong but i guess it doesnt exist.
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@pseudo sonnet Thank you so much.
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I am trying to understand this function:
Not sure what the TT symbol is
it's like the Sigma but for products instead of sums
Oh so everything right of it from 1 to i-1 is multiplied by itself
it's a product of i-1 terms
each term looks like (1-alpha_j)
with different values of j
i guess "term" might not be the right word
is it like a nested forloop where as i increases it restarts the capital pi?
for i in N:
product = 1
for j in [1...i-1]:
product *= 1-alpha[j]
C_p += c[i] * alpha[i] * product
return C_p```
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I have an issue with quadratic equations
@ripe maple Has your question been resolved?
Yea. Thx though
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how do i implicitly differntation
so would xy be 1 times dy/dx
y + x timed dy/dx?
Yeps I guess
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please someone explain it to me
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how do i begin to solve this?
@still bough Has your question been resolved?
<@&286206848099549185>
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hi, i'm stuck in this question (my working is below the question in blue)
2520cm
so around 8870 cm^3?
👍
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ur welcome
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Does anybody know how I can solve this equation with exact values
start by factoring a 2cos^2x out of the first 2 terms then factor by grouping
you also need to factor a -1 from the second 2 terms in order to factor this way
maybe will help with finding values?
Yeah I tried that but then I keep getting stuck
can i see your work
hmm
Square both sides then expand and simplify maybe?
i mean maybe but seems tedious
just looked at the answers and they seem really really messy
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how to answer?
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help plz
this is the answer to the queston and I was wondering why my teacher adds a plus one in the blue box
plz @ me when replying
thx
I have to get going within the next 30 mins also
so hopefully i can get some help before then
acc no my question is why are we minusing 233 from 112
@twin pollen Has your question been resolved?
You need it to be between days 112 and 233 since those are the endpoints of the interval
ic alr. i dont get this tho
@twin pollen Has your question been resolved?
sorry wrong question this is it
f(x) is the notation for a function
you cant change stuff about it
other than the x inside
so u cant say this @desert atlas
nope
the notation f|x| makes no sense
cause for this question my teacher kinda did that
:
like for a why is there all the sudden absolute value lines
@desert atlas
oh ok but like for a cant u also just write y= f(x+4)
since the orginal graph is y=f(x)
and its going to left by 4
@desert atlas
this is fine as well
yes it shifts the graph to the left
so then why did my teacheer add those absolute value lines?
@desert atlas
is it because the orginal graph of y= f(x) can also be written as y= f(lxl)
ya idk why i said that im just tryna make it make sense
it makes all y values positive
right @desert atlas
?
stop pinging me
oh sorry
what does it do geometrically to the graph
but what if there is a vertical translation down
then would it still not be negative
oh ok
so then bavk to my question of why is there all the sudden absolute value lines in my teachers answer
because the graph shows it
wait so y=f(x) is like input x into a specific function?
right
im confused on difference between y= lxl and y = f(lxl)
cause my teacher gave us this
y = |x| is the absolute value function
y = f(|x|) could be anything
depending on f(x)
if u have (y-6) squared and u take the root shouldnt it be plus minus
@desert atlas
o wait sorry for pinging
my bad
sqrt (x^2) = |x|
but how
and so does that mean that root of 9 and root of 3 different
i meant root of 3 squared
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could this be solved just by plugging in the integral into my calculator and adding 1200?
@quiet phoenix Has your question been resolved?
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How would I prove that the set of rationals with 10|p| \geq q is dense
wdym
By p and q do you mean numerator and denominator?
although this is the same as (-1)/2, hmm
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
Isn’t this false
It is?
It is notably empty on the subset between 0 and 1/10 right
I mean one counter example I thought of is 1/10 and -1/10
oh right, I messed up my defns
sorry
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thanks
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How would you calculate the depth of a well from just knowing the speed of sound, the amount of time it takes to hear a rock hit the bottom and how fast the rock is falling?
if you hear the echo back in 4 seconds, that means the well is 2 sound seconds deep
how fast the rock is falling depends on the g
if it's stated that it's okay to assume the temperature is 20 degrees C, then speed of sound is 343 m/s
u can use that fact to determine the exact depth of the well, based on how many seconds it took for the sound of the rock hitting the bottom to reach the top of the well
for that second part, a hint is that you can use the kinematic equations for free fall!
which cannot be solved unless you first solve how deep the well is
@modern berry Has your question been resolved?
Speed of sound is 333 m/s and the rock is falling 4.9x^2 meters every x seconds
okay, so use 333 m/s as the velocity value to solve for the well depth
what formula could be used for that?
hold on, but the seconds taken to hear the rock fall is not given right?
okay
so isolate distance: distance = velocity/time
distance = velocity * time
oh yeah, sorry
it's ok!
so d=333*2
yes
d=666
yes
for the second part, since now you have a distance
you can use kinematic equations to solve for the velocity of the rock as it is about to hit the floor
it would be the final velocity
that you are looking for
note that you should choose the equation that does not have any variable that is not given in your problem!
there are actually two valid equations you can use
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rho(h) is the density of a liquid in a container upto a depth h from the free surface and is given by rho(h) = k(1 + h/b) where k and b are positive constants with units of density and height respectively. How would you calculate the density of the liquid upto a depth d? Would you just put in h=d? Or how would I integrate it?
If you want the average density of the material you would need to integrate and then divide by the height. If you want the density at the depth d then you just plug in the equation.
how would you integrate it? i started by writing dm/dV = rho(h)
dm = rho(h) × A dh ( A is the area of the bottom)
idk what to do next
No response, sad
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Given the following linear map:
[
f: \mathbb{R}^3 \to \mathbb{R}^3
]
such that ( f(x,y,z) = (3x, x+y, y-z) ). Given the basis ( \mathcal{B} = { v_1, v_2, v_3 } ), where ( v_1 = (1,0,0) ), ( v_2 = (0,1,0) ), and ( v_3 = (0,0,2) ), determine the matrix associated with the linear map ( f ) with respect to the basis ( \mathcal{B} ): ( \mathcal{M}_{\mathcal{B}}^{\mathcal{B}} )
jandro0103
Advice on what I should start?
well, M_B^B and M_B, B is the same thing
since it's the same basis in and out you needn't worry about it much
@jade thunder thx
@jade thunder like that?
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can some one help me problem inner product 105 so that i have ideas to solve 105 to 108 , i think inner product is x1x2+y1y2 so what i should do now and when i have the idea can i apply same idea for 107 c
That’s the dot product, which is an inner product.
An inner product is a generalization of a dot product.
An inner product is a generalization of the dot product. In a vector space, it is a way to multiply vectors together, with the result of this multiplication being a scalar. More precisely, for a real vector space, an inner product <·,·> satisfies the following four properties. Let u, v, and w be vectors and alpha be a scalar, then: 1. =+. 2. =...
You need to verify that your <v>u satisfies the 4 inner product properties.
wow i see 4 propertise, ive used them a lot in high school now i know their name are inner product hh
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Hi
@steel frost Has your question been resolved?
Whole question
@steel frost Has your question been resolved?
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is this correct?
Looks correct
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Hello, can someone explain what does this mean?
Badr
all polynomials except... $0_\mathbb{K}[X]$, i have no idea what that is
Badr
so... just 0?
then what will 1_{K[X]} mean? is it the highest degree?
Yep, or otherwise, 0 + 0X + 0X^2 + ...
As for the 1_{K[X]}, well, the polynomial 1 + 0X + 0X^2 + ... (with the 0 and 1 from K of course)
sorry i am still confused
is it related to this?
so n = 0 => 0
n = 1 $a_kx^0+a_kx^1$
Badr
something like this?
You could choose n = 0 for both, and a0 as the 0 or 1 from K for the respective 0 and 1 from K[X]
$0_\mathbb{K[X]} = 0 \
1_\mathbb{K[X]} = a_k \
2_\mathbb{K[X]} = a_0+a_1x \
3_\mathbb{K[X]} = a_0+a_1x+a_2x^2$
Badr

The 0 and 1 are referring to the fact that those are the 0 and 1 from the ring K[X]
what ring?
K[X], the ring of polynomials in X over K
so then 0 and 1 are just 0 and 1?
Pretty much, yep (any other coefficient of X, or any higher power of, is zero)
Not quite no, and usually these aren't used
this confuses me so much. so then all polynomials with a degree of two or less?
You only care about 0 and 1 because of e.g. "0 + anything is the same thing, and multiplying 1 by anything doesn't change it"
No, not at all, they are specifically 0 and 1 only
$0_{\mathbb{K}[X]}$ is only $0 (+ 0X + 0X^2 + \ldots)$, and $1_{\mathbb{K}[X]}$ is only $1 (+ 0X + 0X^2 + \ldots)$
@vernal matrix
Whole point being those are the additive and multiplicative identities of K[X]
so these are not used at all
There may be cases where they are, but I have rarely seen them (and in the cases I have seen, then e.g. 2 is just taken as 1 + 1, 3 is just 1 + 1 + 1 etc, with the 1 from the respective ring that you're from)
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if you have 5 types of balls and 20 of each in a box. You pick 70 of them at random, how many ways can u do this?
It's convenient to think about the 30 that aren't being chosen here
let's say the number of balls that wasn't being chosen was smaller, like 15
Would you be able to solve it then?
um
maybe in each subset u could number the balls
so in the questions the balls were coloured
Red Blue Green Purple Orange
So you could do like R1 ... R20, B1,...,B20 etc
now u have 100 individual balls
number of ways of picking 15 of them is 100 x 99 x 98 x ... x 86
but we need to now divide by something
The thing you need to divide by to correct for overcounting varies depending on how many balls of each color you have
So this method doesn't work
Have you heard of stars and bars?
what do u mean
oh right i see
There's no "something" that you'll be able to find
no
okay cool
Do you know inclusion exclusion?
Dreyuk
yeah ive seen that
i think i might have seen stars and bars before
it rings a bell
nvm no inclusion exclusion but stars and bars
but i'll need to brush up on it
number of nonnegative integer solutions to a+b+c+d+e = 15 basically
why is that important
oh right
how many reds how many blues etc
and then they add up to 15
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I feel like the first question should have a simple solution but the usual method doesn't work for me here
if anyone has an idea that would be helpful
@ruby wadi Has your question been resolved?
man I feel like it's very simple
How about geometric mean?
[v_(n+1)]*[v_(n-1)] = [v_n]^2
Put in values
I think you get a linear outta this
Solve it
Get alpha
@ruby wadi
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✅
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I'm writing some notes for myself regarding linear algebra. Is this a mathematically correct definition of the transpose operation?
I think it is, but leyt someone else confirm
correct
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how do i find x
5x + 3x = 180 degrees
well yes but thats because i made a new pararell line is that okay
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I have an idea but dont know what to do next
What is the idea
i use (2x-3)/(x-1) as F and i get (2x-3)/(x-1)+(x-3)/(x-2) and I think im supposed to plug (x-3)/(x-2) into the equation but idk
F(F(x)) would be difficult to compute yes. But not impossible. The main concern is how you came up with that guess in the first place
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Can someone help me understand supremum and infamum. I seem to keep confusing it with max and min
Say you have a set A = [0,2]
The sup A and max A would be 2
Inf A and min A 0
Now say you have a set B = (0,2)
I understand that the max B and min B dont exist
But I don't understand why Sup B is 2 and Inf B is 0
Can you define supremum for me
Least upper bound
do you agree 2 is an upperbound
Sure, now expad upon the definition of an upper bound
No, because it is not in the set B
upper bound means any value which is greater than or equal to all members of a set
My guess is that it would be the number before 2 in the set of Reals
What number is that
Im not sure if its even possible to write it
if I have a number in the set say $2 - \varepsilon$ and $2$, can you find me a number between tehm
ƒ(Why am. I here)= I don't know
I understand that part
it doesnt have to be in the set, right?
no
Ah ok
So in (0,2) that smallest number you could produce in the upper bound would be 2
yes
Cause I domt think its possible to write a number before that in the set of Reals
yes
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help how do i find C
oh wait
x = c
cuz x + 3x = 4x
but how do i get x
i got x = 36
with the equation
x = 180 - 4x
and yup
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Hi for part b, I used reverse chain rule and got everything right except the bounds. How do I know what numbers the bounds change to? (hopefully that makes sense)
when applying the "reverse chain rule", what was your substitution?
hint: try seeing denominator
I didn't substitute anything i just applied
this concept
alright, so what was f(x) in your case?
this is what i did
yeah so you are actually almost right
yea its just the bounds right?
but but the last line here, you substituted incorrectly
oh huh?
oh crap the 0
not only that
wait what
so what is [
\frac{(5\cdot 1^2 + 1)^{-2}}{-2}
]
Aero
-1/72?
yeah
isn't that what i wrote
oh mb lol
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<@&286206848099549185> what is a trajectory equation? Explain it in brief with some examples if possible, thanks!!
equation of trajectory
trajectory is the path of an object with mass, such as a kicked ball
like this
Can we say there's a quadrilateral where at the end, the particles are moving? And then we have to find the equation of the curve?( what I meant through the curve is that diagonals of that quadrilateral(let's take square) are behaving as the two curves and we have to find out their equations
Should i show you that figure @cunning kayak
show
yes we can say
Will you help me out with one more doubt man? I'm trying to figure how does that happened
It's from the nuclear physics
jee adv 💀
However there was one solution where that educator did that with another thing( I wanna figure out, how?
sure i rule out
i mean yeah dont ask me
Hahha, my bad
Bbye then, thanks for the help
Lee me add you
done
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why do i need to use induction to prove the h_n=2^n-1? this seems sufficient
because youre just assuming the pattern continues
its not a complete proof
by all means its logically sound to make that conclusion, its just not a proof of it for all n
well basically you're saying "...and this pattern continues/repeat this process n times" but induction is exactly that but formalised
ofc if like ur like quite far ahead in ur mathematical career, i doubt u'll need to prove it that formally but basically here u want to say "continue this process n times" and the way to do that is induction
but it's correct to assume that when i've proved the relation h_n=2h_{n-1}+1 though
like it's in fact correct
it's a correct assumption
if i have the recurrence relation proved
u dont make any sense
i have the recurrence relation and the base cases
you can determine the closed form without proving it. This is a derivation but not a proof
Where is your base case?
Hay I'm 15. and i had a math test not to long ago, one pat of a problam was 48÷3, and i used a method i had thought of two day's ago, and dont remember if i came up with it or not so heres it breakdown:
Step 1: factorization.
Express the divided number (48) as a product of two numbers: 48 = 8•6.
Step two: first divison.
Divide the second factor (6) by the divisor (3) to get 6÷3=2.
Step three: second multiplication.
Multiply the first factor (8) by the result of the first factor by the result of the first division 8•2=16.
And that's hoe i solved it so what methid is it?
!help
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im confused
so the measure of the other two angles are 0-180 right
there are 3 angles and 100 is in the middle
yall idk
is 100 the starting point or is 0 the starting point
Alright so an arithmetic progression
Is where each number in the sequence has the same difference from its previous number
Right
yes
why 3x and 2k
Sorry I was having lunch
And yea I made a typo
x+(x+k)+(x+2k)=3x+3k
x is the first term
x+k is the second
And x+2k is the third
So 3x+3k=180
Or x+k=60
Oh and this quite coincidentally gives us our second term
So we can find all 3 measures now
@frozen sun
oh
so since one angle is 100, and another angle is 60, then the last angle is probably 20
cuz they all have a difference of 40
and add up to 180
tyvm for your time 😭🙏
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I'm up to part (d) and i'm not quite sure how I can show that $100 < l < 110$ and $64 < w < 75$
Michele
could you send a screenshot
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Two capillary tubes AB and BC are joined end to end at B, AB is 16cm long and of diameter 4mm whereas BC is 4cm long and of diameter 2mm. The composite tube is held horizontally with A connected to a vessel of water giving a constant head of 3cm and C is open to the air. Calculate the pressure difference between B and C. (In centimeters of a column of water)
I tried to solve this by solving for the pressure difference between A and B, which is rho * g* h which is 1 * 980 * 3 = 2940 Ba
Then I recalled the equation of continuity
a1V1 = a2V2 a1 = pi * 0.2 ^2 a2 = pi * 0.1^2 V1 = pi/8 * 2940 * 0.2^4/(η * 16) V2 = pi/8 * p * 0.1^4/(η4)
We want to find p/(rho g) to find the column of water
However when solving for p ( i got 47040) which corresponds to 48 cm of water, but the answer is 2.4 cm How did I go wrong by a factor of 20?
Here is the solution online (which I didn't understand)
https://youtu.be/K7SCruah6ds?si=cMvtRLFyX8eOxQeC
Please don't occupy multiple help channels.
here is an image for reference, note that the numbers are different
also i tried my method for this one too, and again my answer is off by a factor of 20
close one channel
i asked like 4 times and no one helped so i think ill keep both up
<@&286206848099549185>
you literally posted it twice in the span of one minute
close one
nobody is reading that in one minute
I think you may get more help in the physics server for this question
you can check my previous messages
can you just please close one channel
would you help
@iron blaze Has your question been resolved?
<@&286206848099549185>
@iron blaze Has your question been resolved?
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How to start solving this one?
approach (0,0) along two different paths. if the limit is different for those paths, the limit can't exist
for example, maybe one path is along the line y = x
@quartz geyser Has your question been resolved?
approach it along say x=0 and x=y
@quartz geyser Has your question been resolved?
So should I put x=y and compute?
0/35(x²)
->
What to do now?
this
by approach, U mean the +h stuff?
first just plug x=0, so only y left under the limit. Then usual rules for calculating the limit of one variable.
0o0
btw, what is the final answer for limit here?
I put y=x and it seems to give 0?
yep
So I got -1/2 there
And tried putting y=0 and got 1/3 there
Is this the correct progression?
yes, but at this point -1/2 is enough. So you took two different paths approaching (0,0): one along the line x=0 and the one along the line x=y. They gave different results (-1/2 and 0). What is the conclusion?
It's not continuous at that point
that is the corollary. The main conclusion is: the limit does not exist
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How would I find all the intervals in which
h(t)-6.8cos(pi/30(t))+8.3
h(t)-6.8cos(pi/30(t-12))+8.3
h(t)-6.8cos(pi/30(t-24))+8.3
h(t)-6.8cos(pi/30(t-36))+8.3
h(t)-6.8cos(pi/30(t-48))+8.3
these five graphs are all greater than 1.86 meters within two periods.
@twin apex Has your question been resolved?
<@&286206848099549185>
I don’t need the answer I just need to know the way to do it algebraically
<@&286206848099549185>
@twin apex Has your question been resolved?
what is h(t)?
have a better way to ask my question
h(t)=-6.8cos(pi/30(t))+8.3
h(t)=-6.8cos(pi/30(t-12))+8.3
h(t)=-6.8cos(pi/30(t-24))+8.3
h(t)=-6.8cos(pi/30(t-36))+8.3
h(t)=-6.8cos(pi/30(t-48))+8.3.
Each one of these five graphs represents a blade on a windmill. within 120 seconds (two periods) how do I find all the intervals in which all graphs are simultaneously greater than 1.86 meters
the context of the question is you are stuck in a windmill and within two periods which is 120 seconds in this case, you have to find all the intervals somebody who is 1.86 meters tall would be able to walk out
how do i solve this algebraically
You'd have to find the intervals for each function, and then calculate their intersection
how would i calculate that, is there some sort of formula or i would just have to manually see where they intersect and dont
Let's start with just $h_1(t)=-6.8\cos\left(\frac{\pi}{30}t\right)+8.3$ for now. We want to find when $h_1(t)>1.86$. So we must solve
$$1.86>-6.8\cos\left(\frac{\pi}{30}t\right)+8.3$$
SWR
I’ve gotten to this point so far
I have where they are all part of the interval individually but idk how to find when they all are simultaneously
You need to do interval intersections
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Hi, I need help with dividing decimals as i've never done it before and I have a math midterm tmr. I heard you are supposed to multiply the numbers by 10 then place them but it's still quite confusing.
It helps to multiply by a whole fraction in such a way that it eliminates the decimals.
so multiply it by 100 if its 5.76/0.3
im also watching math with mr. j lol
No, just 2.
10/10 is a whole fraction that is equal to 1. That is a valid math operation that you can use to simplify a problem.
ok
Another example.
yw
That's what I do. No point in complicating it by counting decimal positions and adding it on at the end imo.
ok ty
You could do 123/3 = 41 and add the decimal to get 4.1 but that come across as hacky.
Or 12.3/3 = 4.1 which also more direct.
Up to you.
Now that I think about, just eliminating the decimal in the denominator seems the easiest route.
1 more question
how do you know when you're dividing that the decimal is repeating
As in 0.3333...?
yeah smth like that
Well, when you start doing the division, it will start repeating at some point.
👍
im in seventh grade so im just starting but could you give me a random division equation and let me try to solve it and then i tell you my answer and you see if it's wrong or not
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hey
@weak vessel Has your question been resolved?
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So if you know how to derivative
You can just derivative the formula
If you dont, just use x=anypoint
Calculate y
This algebra video explains how to write a linear equation in slope intercept form y=mx+b. It also explains how to identify the slope and y-intercept from the equation as well as how to graph the linear equation.
Linear Equations - Free Formula Sheet:
https://bit.ly/3WxIvJF
Algebra 1 Final Exam Review:
https://www.youtube.com/watch?v=U0Y8...
Watch it yourself
And then y2-y1/x2-x1
Unfortunately not that applicable to this question
You don't have to calculate anything
I mean most basic way
i like basil too
The slope is 4
!noans
The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.
But yea I guess
It's just a 1 second question if you know your stuff
Ok
I got it
Thanks
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This is going to sound stupid but how would you solve this
Im really bad with fractions
what do you mean solve? it's not an equation
is it equal to something
so you want to simplify it?
$\frac{x+4}{1-(x+4)}$
lex.in.a.teacup
like that ^
This what you should get after multiplying numerator and denominator by x+4
@half compass
no the denominator is -x-3
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how do i solve 36?
i lowk forgot
𝐴
A is the amount of money accumulated after
𝑡
t years, including interest.
𝑃
P is the principal amount (the initial money you invested or borrowed).
𝑟
r is the annual interest rate (decimal form, so 5% would be 0.05).
𝑛
n is the number of times the interest is compounded per year.
𝑡
t is the number of years the money is invested or borrowed for.
$A = P \left(1 + \frac{r}{n}\right)^{nt}$
Slimy
oh yes thank you
i just forgot what to do when i plug all the values in
since im looking for t
would you happen to know?
i don’t trust ai
it won’t solve the problem if you didn’t plug in values
i didn’t accuse you of anything i just said i didn’t trust ai
um its fine lol
np
got it in my own :))
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I need help studying for a math test in pre calc tomorrow, I have the study guide. Mainly in questions 7,8 ,and 9
@fading grove Has your question been resolved?
<@&286206848099549185>
For 7 and 8, try thinking about what each of those transformations do to the graph of a function. Plug in some values into the transformed function for which you know their image, and go from there. More generally, try thinking, given some function $f : \mathbb{R} \to \mathbb{R}$, what $f(x + a)$ and $f(ax)$ look like for some $a \in \mathbb{R}$.
ucheo
For 9, use the properties of logarithms: $\log(ab) = \log(a) + \log(b)$, $\log(a/b) = \log(a) - \log(b)$, etc.
ucheo
@fading grove Has your question been resolved?
are you able to explain over vc?
I don't think this server has voice channels.
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for question b
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how to solve this question
i'll move somewhere else
thanks
np
i am sharing my solution
This is what I solved
What I don't understand is, shouldn't it be 2 times -cosycosx?
can someone help please
@wintry nymph sorry for the tag, but can you delete your question.. so that it doesnt create a confusion.. sorry i dont know how this server works
oh yeah sure
,rotate ccw
no i think because the terms are the partial derivatives of -cosxcosy with respect to x and y
but arent we adding both the terms?
-cosxcosy is a function of both x and y to differentiate it you will take the partial derivatives with respect to both x and y which gives you the terms
i don't know how much this would help but have you looked at this
https://youtu.be/HF_wG2VTf4c
?
Hello, People!
Here is a video of Exact equation problem. Performing partial derivative of M and N, also integration as well under certain conditions. Please do watch the video till end to learn better.
My hearty thanks to all the subscribers, supporters, viewers and well-wishers❤.
With Love,
Chinnaiah Kalpana🍁
Note:
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How am I supposed to solve for sin(-45) with only the hypotenuse value? cant use pythagorean theorem because i only have 1 sides values
Whoa you discover the other angle of triangle is 45° too
You realise now it's an Isosceles triangle!!
awesome balls now what
Now you further understand it's an Right Angled Isosceles, and you can figure out the lengths
how do i do that
Bruh
lmao
Let one side be a
Then other side is a too
Then apply pythagoras theorem
a² + a² = 1² !!!!!
Pythagoras was really a chill guy, no ?
🤧
Shall I say you
i just woke up
The triangle in the figure
Is a right angled triangle
yes
It's a right angled Isosceles triangle
yes
Can you figure out the length of hypotenuse?
Cool
So lets consider the length of one unknown side "a"
Since its an Isosceles, another unknown side from the figure can also be said to be of length "a"
okay
because its an isosceles the unknown sides are the same length
Have you ever drawn them on a paper and verified ?
yes
He said, "If it's a right, you just remember me, coz i am the only man who was always right"