help-26

[mortal shadow]

This is my work

nvm i did it wrong

.close

[topaz sinew]

Channel closed

Closed by @mortal shadow

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vestal plume]

$$p=\text{Probability of success},;q=\text{Probability of failure}$$
$$X\sim Geo(n,p)$$
$$\text{P}(n \leq X \leq m)=\text{P}(X \geq n) \cap \text{P}(X \leq m)$$
$$=q^{n-1} \cap (1-\text{P}(X > m))=q^{n-1} \cap (1-(1-q^m))$$
$$=q^{n-1} \cap q^m$$
How does the final result evaluate to $$q^{n-1}-q^m$$?

[thorny flame]

MESSIAHOFALL69

[sweet shard]

That's an abuse of intersect symbol

[vestal plume]

Lol

Wait u mean the intersection symbol shouldn’t be there?

Or just the symbol looks weird on the latex?

[sweet shard]

intersection is between two sets, not two numbers

P(X>=n) is a number

[vestal plume]

So then how do i evaluate this probability?

Fuck the intersection symbol, but why are we subtracting q^m from q^(n-1)?

[sweet shard]

No idea what Geo(n, p) means

[vestal plume]

Geometric distribution

X is being modeled as geometric distribution

[sweet shard]

and why n <= X is the same n as in Geo(n, p)

[vestal plume]

Nah my bad it’s not the same

That’s actually wrong notation by me my bad

geometric distribution dont have fixed number of trials

So how do we evaluate this result?

[sweet shard]

Use P(X<=m) - P(X<n) = P(n<=X<=m)

[vestal plume]

Yes, but how?

Proof of this result?

Also, u mean P(x<=m)-P(x>=n)?

[topaz sinew]

@vestal plume Has your question been resolved?

[sweet shard]

No this is wrong

[vestal plume]

Well, wherefore did you obtain this?

[sweet shard]

You're still thinking in terms of intersection

[vestal plume]

Ohh i get it

https://tenor.com/view/always-sunny-frank-oh-my-god-i-get-it-gif-22328165

[vestal plume]

Ty

.close

[topaz sinew]

Channel closed

Closed by @vestal plume

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[south surge]

The radius of the base of the cone is 4 cm, and the generatrix makes an angle of 30° with the plane of the base. Find:

1. the height and generatrix of the cone;

2. the area of the axial section of the cone.

[south surge]

Id like to check if my work thus far is correct

[rigid ivy]

What is a generatrix?

[south surge]

You can just use the picture to see what it's talking about (I used Google translate so it's a bit wonky)

[south surge]

In this case it would be BC (or well AB is also one)

[rigid ivy]

So any of those lines from cone base to cone tip, basically

[south surge]

Well yea to the edge of the base (circle)

[vestal plume]

It is

[south surge]

Thank you!

.close

[topaz sinew]

Channel closed

Closed by @south surge

Use .reopen if this was a mistake.

[rigid ivy]

@south surge for 1), when it asks for the height, does it want the slant height BC or the perpendicular "true" height BO?

(Looks like you did both, so no worries i suppose)

[south surge]

I marked it beside the picture with question marks, I was looking for both

The slant and the actual height of the cone

[rigid ivy]

Yeah. My mistake for asking before reading

[south surge]

That was the first part of the task, the second part was to find the area of the triangle ABC which I calculated to be 5 1/3 (not sure if that's correct either, since I found a lot of other answers and ways of solving)

[south surge]

No worries, it can be a bit confusing anyway

[rigid ivy]

.reipen

.reopen

[topaz sinew]

✅

[rigid ivy]

(Reopening, assuming you wanted to ask about this now)

[south surge]

Well sure, I mean if the first part was correct then there's no way I could've botched the second part
So I believe the area of triangle ABC is 16/3 or 5 1/3

[rigid ivy]

5 1/3 feels off for me

How are you getting it?

First part is indeed correct btw

[south surge]

But by using the other formula (the one beside the ruler) I get a different answer

[rigid ivy]

,rccw

[south surge]

I can write it out by the other formula which gave me 16/√3
If necessary

[rigid ivy]

What is $a$ supposed to represent in your $S_{ABC}=\frac12ah$ on the left?

[thorny flame]

SWR

[south surge]

BC

[rigid ivy]

Mkay, and why BC?

[south surge]

That's just the formula I have
It's used for any triangle, not just a triangle which has equal sides (maybe that's the error)

So I'd need to specifically use the formula for a triangle with equal sides?

[rigid ivy]

The formula is correct for any triangle, but the values you use are significant

[south surge]

You can see it at top left, below the first triangle

I used S=1/2 a*h

[rigid ivy]

Yes, but consider what they are using to designate a and h in relation to the triangle

Damn. All of these sites are overflowing with ads

...

https://en.m.wikipedia.org/wiki/Area_of_a_triangle

[south surge]

So in my case "a" would be AC?

[rigid ivy]

Precisely

Height and base choices must be perpendicular

[south surge]

Yea I got it now, I was inattentive with the positioning of the triangle in the formulas, that's my bad

I got the answer 16/√3

Thank you

[rigid ivy]

Huzzah

[south surge]

.close

[topaz sinew]

Channel closed

Closed by @south surge

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lapis swallow]

Can't you calculate the probablity tho

[lapis swallow]

You would use the sample mean distribution right...

u = u and sigma = 35/sqrt(30)

why can you not find it simply because it is not a normal distribution?

i thought central limit theorem and finding the mean and sd for sample mean distribution doesn't require it to be normal

especially because part b literally calculates a similar problem...

[loud oasis]

the central limit theorem says that the distribution of sample means will become closer to normally distributed the larger the sample is

often we arbitrarily set 30 as roughly the smallest sample size where it's safe to assume the central limit theorem makes it roughly normal

[hardy wing]

clt says that the distribution of the sample means is normal for sufficiantly large populations, not that the distribution of the individual elements is normal. The latter statement doesn't make sense, that would mean that any distribution with more than 30 samples is normal.

clt would be valid if the question asked for the probability that the average passenger weighs mroe than 200lb, which is what part b is. big difference.

[topaz sinew]

@lapis swallow Has your question been resolved?

Channel closed

Closed by @lapis swallow

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[reef shoal]

What would be the equation for this line if I wanted x^2 to "start" at (10, 40)?

[reef shoal]

As in, I want to move the (0, 0) point to (10, 40)

Without affecting the curve

[main widget]

thats ur min point
which in completed sqr from would be
(x-10)^2 + 40
then expand this and ull get the new eqn

tho this shifts it

but it doesnt affect the overall shape if thats what ur asking

[reef shoal]

I'm trying to solve g(x) here. Which is usually g(x) = Cx^a when at origin?

Is it g(x) = C(x-3)^a+3?

g(7) = C(1-3)^a+3
g(7) = C*(-2)^a+3
C = 7/((-2)^a+3)

g(4) = (7/((-2)^a+3))(4-3)^a+3

a = 2

C = 7/((-2)^2+3) = 1

g(x) = (x-3)^2+3

What did I do wrong?

That wasn't right

<@&286206848099549185>

@main widget how do I do it so that it doesn't affect the overall shape?

[sacred kindle]

g(4)

[reef shoal]

Why? I took another point in the graph

(4, 4)

[sacred kindle]

First find C using
g(7)=C(−2)^a+3=7
Then use g(4)=C(1)^a+3=4 to find a

[fresh fiber]

U have 2 point one is min of g(x) that (3.3) and (4,4) i think u should solve with this hint

[sacred kindle]

That gives you
C(−2)^a+3=7
C(1)^a+3=4

And from here you can find c and a

[topaz sinew]

@reef shoal Has your question been resolved?

Channel closed

Closed by @reef shoal

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[empty ore]

Hello, would anybody be so kind to help me extract the formula this calculator utilizes?

https://www.yugioh.party/
d = Deck size
h = Hand size
a = Amount
m = Minimum
M = Maximum

I know how to calculate the probability if m = M or m = 1 using binomial coefficients, but I'm not sure how to combine the formulas

[slender musk]

I took a look at the javascript code and it seems to be using a recursive combinatorics algorithm to calculate the probability and it all seems too complex

It for sure doesn't have a closed form

For reference this is the code

[empty ore]

That doesn't sound fun

[slender musk]

There is no simple formula because of the sheer amount of cards you guys have and there are so many degrees of freedom that all affect each other when you have a lot of cards

[empty ore]

What if there was just one "type of card" to perform calculations on?

Like this

[chilly walrus]

in this configuration this is the console log of the calculations

[topaz sinew]

@empty ore Has your question been resolved?

[chilly walrus]

i am looking through the code rn and it's a bit hard to understand what exactly is going on for someone how has never played any yu-gi-oh but you should give it a shot, it's written really well

[empty ore]

That's odd, there shouldn't be anything Yu-Gi-Oh related

[chilly walrus]

wdym

the code relies on dealing cards and seeing what cards are in hand etc.

but i have personally no idea what any of that means

function recursiveCalculate(currentHand, currentHandSize, objects) {
    if (objects.length === 0 || currentHandSize >= getHandSize()) {
        if (currentHandSize == getHandSize()) {
            console.log("O: " + objects.length);
            var noChance = false;
            for (var i = 0; i < objects.length; i++) {
                if (objects[i].min != 0) {
                    noChance = true;
                    break;
                }
            }
            
            if (noChance) {
                return 0;
            }
        } else if (currentHandSize > getHandSize()) {
            return 0;
        }
        
        var newChance = 1;
        var output = "";

        for (var i = 0; i < currentHand.length; i += 2) {
            output += "(" + currentHand[i] + " choose " + currentHand[i + 1] + ") * ";
            newChance *= choose(currentHand[i], currentHand[i + 1]);
        }

        if (currentHandSize < getHandSize()) {
            output += "(" + getMiscAmt() + "choose " + (getHandSize() - currentHandSize) + ") * ";
            newChance *= choose(getMiscAmt(), getHandSize() - currentHandSize);
        }

        console.log(output.substring(0, output.length - 3));
        return newChance;
    }

    var obj = objects.pop();
    var chance = 0;

    for (var i = obj.min; i <= obj.max; i++) {

        currentHand.push(obj.amt);
        currentHand.push(i);

        chance += recursiveCalculate(currentHand, currentHandSize + i, objects);
        //console.log("N: " + chance);

        currentHand.pop();
        currentHand.pop();

    }

    objects.push(obj);

    return chance;
}

that's the only really important code

[empty ore]

Essentially it just calculates the probability of drawing a specific card an amount of times between m and M by drawing h cards from a deck of d cards

It's the same as those standard probability problems where you're asked to calculate the probability of drawing a specific card x amount of times by drawing y cards from a deck of z cards, except you're given a minimum and a maximum of cards you can draw in your hand

[topaz sinew]

@empty ore Has your question been resolved?

[empty ore]

Perhaps one of the <@&286206848099549185> can work this out?

[sweet shard]

write some formulas then

[empty ore]

Of that "standard problem" example?

[sweet shard]

extract your math formulas from here

[vernal ledge]

well, it looks like its using the recursive function to calculate the total number of ways to get the required set

and then dividing it by nCr

and converting it to percentage

but i guess thats already known

[empty ore]

I can only wish I were that good lmao

[sweet shard]

then you need someone who can read your code

try cs server

[empty ore]

I can read the code, but I have no clue how to translate it to a mathematical formula

But as far as I can tell from the answers there's no simple way to do what I want to achieve, is that correct?

[sweet shard]

you should try to get some numerical outputs then to find some concrete functions then

plot it to see if it fits any distributions

[empty ore]

Wait, I'll attempt to simplify the problem

[topaz sinew]

@empty ore Has your question been resolved?

[empty ore]

I'm trying to find ? and if there's a simple formula that describes all three

(Expand the image)

[empty ore]

Reference

[empty ore]

<@&286206848099549185> 🙏

[topaz sinew]

@empty ore Has your question been resolved?

[topaz sinew]

@empty ore Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[green parcel]

how are they going from the first step to the next step am so confused

[outer laurel]

ln 1 =0

-1 - (a ln a -a)

a - 1 - a ln a

[green parcel]

they took out a 1?

an a*

?

[outer laurel]

?

[green parcel]

idk

;--;

[outer laurel]

the - a at the end

[green parcel]

yes

[outer laurel]

inside the parentheses

[green parcel]

i have -1 - (aln a - a) rn

[outer laurel]

parentheses

are important

ok

distribute the invisible -1

-1 + -1(a ln a - a)

what do you get

[green parcel]

-1 - alna + a

[outer laurel]

move the a to the front

a ln a = ln a / (1 / a)

again parentheses are important here

[green parcel]

aln(a) = ln a / (1/a)

whys that again?

[outer laurel]

3 * 5 = 5 / (1 / 3)

[thick lily]

try working right to left, can you simplify 1/(1/a)?

[green parcel]

how did you know you had to go into that form tho

[green parcel]

hmm

[outer laurel]

looks like they intend to use lhopitals

but the funny thing is a ln a as a tends to 0 is also an indeterminate form

so you can still use lhopitals

[green parcel]

ohh

same reason they can just get rid of the a - 1 right?

don tunderstand why they can get rid of the -1 tho

nvm it dont matter if ukeep it in since ur gonna do l'hopitale anyway

[topaz sinew]

@green parcel Has your question been resolved?

Channel closed

Closed by @green parcel

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torn zinc]

first time doing this typa question, im so lost

[torn zinc]

how is the answer 10

[shadow salmon]

With this information given that sounds odd, as we know atleast that it can’t be higher than 7.5cm

[shadow salmon]

Do they share why they think so?

[torn zinc]

yea

[torn zinc]

just this

[shadow salmon]

Hm maybe I’m missing context but that seems like a mistake

For the histogram to even make sense that can’t be right

[neon iron]

The histogram for 0-6 has width 6 and 18 elements, so 18/6=3 units = 7.5 cm => 1 unit height = 2.5 cm

The histogram for 6-10 has width 4 and 16 elements, so 16/4 =4 units.
4 units => 4*2.5 cm = 10 cm

[topaz sinew]

@torn zinc Has your question been resolved?

[neon iron]

😭

[torn zinc]

wait uhhh

why does the elements has to be divided by the width?

[neon iron]

Histogram represents frequency of elements averaged across the interval, representing the total number of elements as area (arithmetic mean usually or maybe always)

[shadow salmon]

🤦‍♂️

Of course! Forget about that

[torn zinc]

oo i see

thanks! i get it now

[topaz sinew]

@torn zinc Has your question been resolved?

Channel closed

Closed by @torn zinc

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tardy bison]

given that positive real numbers a,b,c,d that satisfy the following equation
a + b + c = 11/2
4a + 3b + 4d = 16

find the maximum value of the expression
8ab + 5bc + 4ca + 4da + 3bd

[gray yacht]

Try using Lagrange multipliers if you know about it

First define the objective function and constraints, then express c and d in terms of a and b, then sub c and d into
f(a,b,c,d), then simplify each term, then optimize that function

[topaz sinew]

@tardy bison Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[tardy bison]

and then partial right?

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tardy bison]

partial derivatives

[gray yacht]

Yur

[tardy bison]

ok

[gray yacht]

It gets easier the more you do it

[tardy bison]

tq

[gilded plume]

is there a question?

[tardy bison]

For three positive integers $a$, $b$ and $c$. let $f(a, b, c)$be a function that represents the remainder of $abc$ when divided by $25$. Determine the value of
$$
\sum_{a=1}^{25} \sum_{b=1}^{25} \sum_{c=1}^{25} f(a, b, c).
$$

[thorny flame]

solstice

[gilded plume]

okay, we will break this into 2 cases:

when the f(a,b,c)=0

and when f(a,b,c) isn't 0

can you tell me what f(a,b,c)+f(25-a,b,c) will be?

assume that f(a,b,c) isn't 0

[tardy bison]

0?

[brittle belfry]

ayo

scary shit

[gilded plume]

well we take the positive remainders always

(modulo sum would be 0)

but the actual sum would be 25 right? (assuming it isn't 0 and 0)

[tardy bison]

oh yes

[gilded plume]

so i claim that we can pair terms together right?

[pseudo jetty]

,w sum k=1 to 25 of k

[thorny flame]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by tearfox

[pseudo jetty]

cube

[brittle belfry]

"cube"

[gilded plume]

so all the terms which aren't divisible by 25 will have an average value of 12.5

now, we simply need to calculate how many aren't divisible by 25

[pseudo jetty]

skull

[brittle belfry]

💀

[gilded plume]

surely this is the way to do it

[brittle belfry]

"simply"

25^3 cases

[gilded plume]

? i am saying the average term which isn't 0 is 12.5

so thus we just find the number of terms which aren't 0

[pseudo jetty]

,, \sum_{a, b, c} abc = \parens [\bigg] {, \sum_a a}^3

[tardy bison]

{1,2,...,25} = 5,10,15,20,25
25 - 5 = 20
20 * 20 = 400?

[gilded plume]

but we need to find the sum of the remainders?

[brittle belfry]

...

[pseudo jetty]

oh it's not just mod 25

okay

proceed

[gilded plume]

1. we have 3 not 2 numbers so you have to cube
2. you need to take into account the possibilities when exactly one of the numbers is divisible by 5 and none are divisible by 25

[tardy bison]

smh i forgor

[tardy bison]

15500

[gilded plume]

how did you get that?

im assuming 8000 of them came from the cubing case

[tardy bison]

well if you take none of a,b,c s divisible by 5 = 8000

exactly one of a,b,c is divisible by 5 = 6000

two of a,b,c are dibisible by 5=1500

[topaz sinew]

@tardy bison Has your question been resolved?

[topaz sinew]

@tardy bison Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dim lagoon]

hey i have a question
is there some kind of method to follow for calculating the sum of an infinite series,or do i just have to observe and cancel out terms until i can write it in a finite way?

[wooden moon]

There are some series that converge and some that diverge, there isn't a general formula that i know of which can solve all infinite series

[dim lagoon]

so i first have to check if they converge or diverge, and then if they converge i can try to calculate them?

when i say calculate i dont mean as a number btw

i mean as a formula

with variables

[wooden moon]

I mean not sure what you are trying to say tbh

[dim lagoon]

wait

my bad i got confused

i didnt mean infinite series

just series sums

sorry

[dim lagoon]

i mean is there a method to calculating these kind of sums

or do i just expand it and hope the terms cancel out

[empty heron]

partial fractions to get to the second equality

once u get here i hope you can see it telescoping tho

[surreal mural]

there's a lot of different sums with a lot of different ways to derive a formula, there is no general way

[dim lagoon]

nope cant see it, started learning series 2 days ago

[dim lagoon]

so i just have to expand it and observe

how would i do Σ k^2 from k=1 to n

[surreal mural]

that one is a bit tougher

[dim lagoon]

ye

So far I have tried this

[surreal mural]

I would first start with the sum of k, that's easier

[dim lagoon]

oh wait

So I can do this?

or is this wrong

[surreal mural]

no

that's like saying 1*1 + 2*2 = (1+2)*(1+2)

[dim lagoon]

oh ok

so how will the sum of k help

[surreal mural]

to have something easier to work with at first, because with k² it does become a bit more complicated

[topaz sinew]

@dim lagoon Has your question been resolved?

[dim lagoon]

Ok I got it

[surreal mural]

good, now for the sum of k², consider the sum of (k+1)³-k³ instead

[topaz sinew]

@dim lagoon Has your question been resolved?

[dim lagoon]

.close

[topaz sinew]

Channel closed

Closed by @dim lagoon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sinful bobcat]

Hi i have this problem and i tried doing substitutions and it does not work:
Solve this functional equation $(xf(x)+3x^2y)/(f(x)+y^2+2xy)+(y^3+3xf(y))/(f(y)+x^2+2xy)=(x+y)^3/f(x+y), f:\mathbb{N}^* \to \mathbb{N}^*$

[thorny flame]

Popescu V2

[topaz sinew]

@sinful bobcat Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[blissful raven]

pls help i cant solve this

[topaz sinew]

Please don't occupy multiple help channels.

[wooden moon]

?

[topaz sinew]

@blissful raven Has your question been resolved?

[fast dagger]

#❓how-to-get-help

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[limber snow]

hello

[limber snow]

im really lost

where do i begin with this question?

i have no idea how to interpret the question

[barren lion]

can try doing a cofactor expansion along the first row

[strong sable]

Do you know Vandermonde determinant?

[limber snow]

no i dont think ive learned that

im stuck on what the question is asking

[limber snow]

oh but i do know like regular determinants, are they the same thing

[barren lion]

it's asking you to show that the determinant of that matrix is not zero

[limber snow]

ohh got it

so for it to not be zero, it should be invertible

am i going somewhere with that idea?

[barren lion]

probably not

[limber snow]

yeah

[barren lion]

you can algebraically compute the determinant

[limber snow]

okay ill try that

[limber snow]

would these not be linearly dependent?

[barren lion]

would what?

[limber snow]

the columns

[limber snow]

this is what i have currently

[barren lion]

by "this" are you referring to the other message in here?

is that your alt

[limber snow]

oh yeah

thats just my ipad

its my alt

[barren lion]

now you can factor the result

[limber snow]

got it

but im sort of still stuck on the logic part

like what should be my line of thought when i approach a question like this?

[copper nacelle]

pls help 😔

[barren lion]

you can factor out another c in the first two terms and a b from the last one

[barren lion]

factoring is mostly intuition

[limber snow]

oh

[barren lion]

you can write the entire thing as a product

[copper nacelle]

what do you mean by that?

[barren lion]

should be (c-a)

[copper nacelle]

sorry i missed that

[limber snow]

what should we do now

[barren lion]

I think you can factor out (c-b) next? but it's going to be messy

[limber snow]

wait what is the goal of factoring?

[barren lion]

you can write it as a product of three binomials here

but it's not intuitive how you get there from that expression alone

the only other way I see is to rewrite (c-a) as (c-b + b-a) and then split it up

but none are intuitive unfortunately

ah you can also compute the determinant in another way by subtracting the first column from the other two, and then taking out factors of (b-a) and (c-a) from the second and third columns respectively

[limber snow]

thats a good point

thank you ill try that out

[barren lion]

the simplest way is to just "see" that this factors as blah blah blah

[barren lion]

this way also works, just checked

[topaz sinew]

@limber snow Has your question been resolved?

[limber snow]

thank you for your help btw!

[topaz sinew]

Channel closed

Closed by @limber snow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dull haven]

Simplify as much as possible

Pls explain every step

[serene sapphire]

it looks like you might have to expand the ( ) and group terms alike

terms alike: they have x and y at same powers; like xy, -xy, 100xy, xysqrt3 etc (just examples).

[dull haven]

How so

Like show me

[robust turtle]

multiply the xy(xy-x) then add/sub it

you will see things then

[dull haven]

x^2y^2-x^2

[robust turtle]

x^2y^2-x^2y

youre multiplying it by xy

bruh

[dull haven]

oh my fault

.close

[topaz sinew]

Channel closed

Closed by @dull haven

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[final pendant]

The CDF of random vector $(X, Y)$ at the point $(t, s)$ is defined as follows:
$$
F_{X, Y}(t, s) = \begin{cases}
0, & z < 0 \
1, & z > 1 \
z & otherwise,
\end{cases}
$$
where $z=min(t, s)$.

Find the probability that $(X-1)^2 + Y^2 < \frac{4}{5}$

[thorny flame]

Serpentri

[final pendant]

Not sure how to go about it

If I were to express z more explicitly, it’d be

$$
z = tH(s-t) + sH(t-s)
$$
Where $H$ is the Heaviside step function

[thorny flame]

Serpentri

[final pendant]

Don’t know why this decided to jump around… anyway

Originally, my method was to write the probability as a CDF:
$$P((X-1)^2+Y^2<4/5) = F(a > (X-1)^2+Y^2)|_{a=4/5}$$

[thorny flame]

Serpentri

[final pendant]

Then I tried to calculate it with the Bayes integral, after which I wanted to plug a=4/5 into the result

I realized that I do not, in fact, have a CDF for the circle, so I definitely need a different approach…

[sweet shard]

did you already try to calculate the marginal distributions

[topaz sinew]

@final pendant Has your question been resolved?

[final pendant]

What would they allow me to do?

[sweet shard]

not sure if it'll be useful for your problem specifically, just that it's a common technique to finding distribution function type questions. e.g.
https://www.probabilitycourse.com/chapter5/5_2_5_solved_prob.php

[topaz sinew]

@final pendant Has your question been resolved?

[final pendant]

Hm. I think I figured it out, I just needed to integrate the PDF on the overlap of [0, 1]x[0, 1] and the circle area

[final pendant]

This course seems like it might be good for my test preparation. Thank you!

[topaz sinew]

Channel closed

Closed by @final pendant

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[torn condor]

Im really struggling with this exercise. I have no idea how to approach the first part. We need the gradient at (1,1,0) but i cant seem to calculate it using the given

[torn condor]

<@&286206848099549185>

<@&286206848099549185>

[devout drift]

Wait some time between tagging xD

[topaz sinew]

@torn condor Has your question been resolved?

[topaz sinew]

@torn condor Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[timid elbow]

Hello, my math teacher gave us a challenge, we need to resolve 5 enigma related to cryptology, so far I've done 4 out of 5 but the last one seem too hard for me so I seek for help, I'll send a picture of the 5 enigma, and already give the answers I have and context if need some

[timid elbow]

Here are the 5 riddles, the first is a simple Caesar cipher, the second is also simple, using Pigpen, for the third you'll need the answer of the second one which is: The lovers date (14 February).
The binary translation gives us 1349, so 14 February 1349 is a famous disaster in Strasbourg, France.

The fourth is the riddle I can't solve.
And the fifth can be deciphered with Braille.

Note that the enigma are made for french people, but I can translate all the actual clue I've gather:

1. the first enigma was easy. the first clue: a line is worth a point.
2. Find the date of the lovers' day
3. February 14, 1349
5. SEND ME A PICTURE OF IT

And now that you have some context, the fun part. The fourth enigma was made by my teacher, you'll not find anything about these symbols online (trust me I searched for 5 hours, and later he confirmed that he created the symbols himself). He also said, that the previous enigma could help to find the answer of the fourth one, the same way we use the second enigma to find "February, 14" to complete the third one.

We are a full class of 15 peoples trying for days to understand the fourth enigma. If you want to try this challenge be aware that what you'll find will be in french probably, so translate anything you find, goodluck and I'll continue to search myself (ping me if you have specific question).

There is also the translation of what is writed on the enigma number 3: "On this date 10101000101, the double vowel gives V points and the point
gives X. But what happened that day?"

[cedar wagon]

En voilà une manière pédagogique de faire des maths

[timid elbow]

Ahah oui

[topaz sinew]

@timid elbow Has your question been resolved?

[topaz sinew]

@timid elbow Has your question been resolved?

[topaz sinew]

@timid elbow Has your question been resolved?

[topaz sinew]

@timid elbow Has your question been resolved?

[topaz sinew]

@timid elbow Has your question been resolved?

[vernal ledge]

theres only three types of curves in each symbol

[timid elbow]

wdym ?

[vernal ledge]

dot line circle

[timid elbow]

oh yeah we figured that aswell

[vernal ledge]

maybe two six letter words?

then how is each letter distinct?

[timid elbow]

it either 2 distinct word with different letter

[vernal ledge]

does french have several such six letter words?

[timid elbow]

I think, or it's number

and so some symbols could cover multiple number

or multiple letter

btw

my teacher gave this to 2 class, one group in the other class found the answer in 1h20

he said to "think out the box"

oh and btw, he gave those enigma during a class of cryptology, if it can help

[vernal ledge]

i can only see circles

[timid elbow]

for me vowels are the circle

so 2 vowel equal to V

but still make no sense

[timid elbow]

22 lines, 6 dots, 12 circles

maybe it can help

[timid elbow]

ok I resolved it

[timid elbow]

.close

[topaz sinew]

Channel closed

Closed by @timid elbow

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[thorny plinth]

less math related, but in python, is there a way to return an expression with a recurring term by only calculating it once? e.g. i want return (A @ x)**2 + norm(A @ x) but this calculates A @ x twice which is slow. Is there a way to evaluate the whole thing by doing A @ x only once? I know i can store it in a variable but if there is an even faster way? Is defining a function faster? basically everything here is looped many many times

[lean pebble]

why are you not satisfied with declaring a variable?

[thorny plinth]

is storing in memory slow? A @ x is huge

[lean pebble]

it will already be cached so "storing" it won't take any time

[thorny plinth]

i was thinking to have some function f, and loop over the function
def g: return f(A @ x)

[thorny plinth]

it works like that? ok then

[rigid ivy]

If you are worried about efficiency at this level, then python might be the worst language you could choose

[thorny plinth]

Its homework lol i dont have a choice

data analysis stuff and vectors are like hundreds of thousands of elements

[rigid ivy]

Rule of thumb: don't worry about efficiency until you need to

[lean pebble]

this sort of optimization will not account for anything anyway

[thorny plinth]

at least a little.. it takes like 15min to run atm

[lean pebble]

you are 100% doing something else wrong

[rigid ivy]

What bair is saying

[thorny plinth]

lol okok

[thorny plinth]

but this is still faster right? 👀

[rigid ivy]

In the way that cleaning a smudge off of a broken window is better, yea

[thorny plinth]

haha fair enough

.close

[topaz sinew]

Channel closed

Closed by @thorny plinth

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[halcyon whale]

Hitting gives 4 points
Missing deducts a point

No matter hit or miss, it deducts a point, that is, the net gain for hitting on the first throw is 4-1, or, 3, and hitting on the second throw is 4-2, or, 2

Basically: 4-n, where n is the amount of times you threw (hit and misses)

A round lasts until a hit.

Given the chance of hitting is: 1/10, and the chance of missing is 9/10.

You want to calculate chances of your net profit being -1 and smaller.

[coarse herald]

whats the answer

[topaz sinew]

@halcyon whale Has your question been resolved?

[halcyon whale]

66% but i don't understand

[coarse herald]

i got 0.6561

What you can do is think of it as 1- (getting 0,1,2,3)

if if you want a cool way you can think of it as a GP

[fickle oracle]

What's the question here?

[halcyon whale]

Elaborate please

[coarse herald]

you want scores from -1 onwards so instead what you can do is 1- (the scores you get from 0 onward)

does that make sense

[halcyon whale]

I understand that you need to find the complementary probability of something, just I don’t know what

0 as in the score or the throw number

[coarse herald]

The score

[halcyon whale]

So, mathematically, you did (9/10)^3 and then?

[coarse herald]

This will give you -3

you want 0 onwards

[halcyon whale]

Can you show me what you did like in math

[coarse herald]

lright

[halcyon whale]

Oh so I get it, the chance of you getting any value starting from x is just all the values on the opposite side of the number line from x

Thanks bro!

.close

[topaz sinew]

Channel closed

Closed by @halcyon whale

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[neon iron]

im being slow

what am i missing

[sweet shard]

Part a?

[neon iron]

what do u do

[sweet shard]

Use part a to find a simplification of cos^2(nπ/3)

[neon iron]

wdym simplificatiion

[sweet shard]

Should only have a few cases

[fiery saddle]

yeah

for example

[sweet shard]

In terms of something that's not cosine

[fiery saddle]

a1=cos^2(pi/3)

I believe that is 1/4?

[neon iron]

yh

yh

a2=1/4

a3=1

i got that

then what

[fiery saddle]

how is a3 1?

[sweet shard]

The pattern repeats

[neon iron]

it doesnt follow

like a series

[neon iron]

it just is

[fiery saddle]

oh wait

I am stupid

dont mind me lol

um a4=1/4

a5=1/4

a6=1

[neon iron]

this isnt a series right

[fiery saddle]

do you see pattern lol?

[neon iron]

yh

1/4 , 1/4 , 1

[fiery saddle]

i mean this is not sequence

[sweet shard]

Sum this up until n=50

[fiery saddle]

but what you are doing is

you are only going up to 50

[neon iron]

ok

[fiery saddle]

therefore there is 16 periods and 2 more

also adding extra n to all 50 values

[neon iron]

so

49/2

[fiery saddle]

it should be (1/4+1/4+1)*16+1/4+1/4+1+2+3+4+......+50

[neon iron]

yh

but howd u think of that

[fiery saddle]

this should be eh 24+1/2+1675

[neon iron]

i tried to treat it

as one big sequence

[fiery saddle]

wdym how did I think of that?

[neon iron]

like

[fiery saddle]

that is not arithmetic or geometric

[neon iron]

i was thinking

[fiery saddle]

you cannot use formula here

[neon iron]

oh yh

but

u treated

as 2 diff things

why cant u treat as one

[fiery saddle]

um, cause that just makes you do tons of extra work?

[neon iron]

how

wouldnt that be less?

cos

its

5/4 , 5/4 4

so then

[fiery saddle]

no

n is varying lol

n goes from 1 to 50

[neon iron]

yh

[fiery saddle]

while cos repeats

the n part is arithmetic

while the cos part is just a period

[neon iron]

ohhh

[fiery saddle]

that is why you treat it as 2 different things

[neon iron]

i seew

[fiery saddle]

your answer should be 1699+1/2

wutever that is lol

[coarse tusk]

!nosols

[topaz sinew]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

@neon iron Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[chilly cypress]

hello

[chilly cypress]

i already posted this in a forum but i didnt know which was better. i was wondering if somebody could help me find means for this problem. the question is like, "how many times do u read each day?" and i need to find 2 means for how many times they read a day for both anonymous and not anonymous. its tricky to me because theres like 2 components, the number of times they read a day, and then the number of people that selected that time.

ive posted this in 5 servers since 11pm wnd its 2am now and i just rlly want to finish this if anybody knows how to do it😭😭

[neon iron]

Remember that

when you have datapoints and their corresponding frequency

the mean is given by:

$$\mu = \frac{\Sigma^{n}{i = 1} f_ix_i}{\Sigma^{n}{i = 1} f_i}$$

[thorny flame]

Edmund Cloudsley

[neon iron]

remember that f is the frequency

and x is the corresponding datapoint

and mu is the mean

[chilly cypress]

what is i?

[neon iron]

is the index value

f_i is the frequency for the ith index and x_i is the data point for the ith index

[chilly cypress]

thank u i really appreciate that. is there any way u could help me to apply that formula to this situation? ive never used it before

[neon iron]

Its just the formula for the mean of n data points

How about I calculate the mean for anonymous for you

and then you do not-anonymous on your own?

Sounds like a deal?

[chilly cypress]

okay, that would be very helpful, thank u so much

[neon iron]

$$\text{Mean(Anonymous)} = \frac{0 \times 0 + 1 \times 3 + 2 \times 3 + 3 \times 10 + 4 \times 5 + 5 \times 3 + 5 \times 1}{0 + 3 + 3 + 10 + 5 + 3 + 1}$$

[thorny flame]

Edmund Cloudsley

[neon iron]

the last category is a bit problematic tho

5+ could mean anything above 5

therefore this would cause problems in calculating the ACTUAL value of the mean. Whatever we calculate wuld just be an estimate

[chilly cypress]

understood

[neon iron]

Perhaps you could approximate 5+ to something like 6 times or 7 times depending on whatever you find it to be suitable

or ignore it all together

[chilly cypress]

6 i think is a good substitute

[neon iron]

Yeah I guess that could work

[chilly cypress]

okay so do i just calculate this and then i should get the mean?

i got 3.16 for that

[topaz sinew]

@chilly cypress Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[neon iron]

I suppose that should be correct! I haven't verified it myself

[neon iron]

.close

[topaz sinew]

Channel closed

Closed by @echo oxide

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[short chasm]

I’m stuck on this

[oblique plover]

if i were you id look up what the definition of a linear pair and vertical angles are

[short chasm]

.close

[topaz sinew]

Channel closed

Closed by @short chasm

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[proud beacon]

help

[proud beacon]

what to do if there is {

[desert atlas]

its just a different form of a normal bracket

treat it as (

[acoustic tangle]

Not necessarily

Could you give the context?

[proud beacon]

uhm like in an equation

oh wait who are u talking

[acoustic tangle]

If what's inside {} is a subexpression, then what ashy said

[proud beacon]

oh just {

what happens if there is {

[acoustic tangle]

With no }?

[proud beacon]

just one bracket

no

no }

[lethal anchor]

piecewise function, perhaps

[desert atlas]

oh i realize could be used for piecewise functions as well

could you show the context

[acoustic tangle]

Or a system of equations

[lethal anchor]

show what you're talking about to avoid ambiguity and people guessing for you?

[proud beacon]

like find the value of x

[desert atlas]

that does not help

[proud beacon]

i dont have the exact equation but

yeah

[desert atlas]

was it a big bracket or small bracket

[proud beacon]

big

2 equations

[desert atlas]

was there a function

[proud beacon]

no

[lethal anchor]

Try to open a help channel with a more concrete question, because this could be a whole bunch of things

[proud beacon]

wait hold on

let me try to make

{ x + 6.5 = 7.66

whats x

something like that

[proud beacon]

a different form?

so its just ()

wait it's just (but { ?

no functions just the solution for x

[desert atlas]

a brace could mean literally anything in math

there are so many uses for it

we need specifics

[proud beacon]

classmate said if theres a bracket u solve it first

something like that

but again

im stuck hold on

[lethal anchor]

Then yes, thats commonly used to notate a system of equations. Something like this is common
[
\left{\begin{alignedat}{1}
3x + 2y &= 1 \
5x +4y &= 3
\end{alignedat}\right.
]

[thorny flame]

Aero

[proud beacon]

yeah like this

[lethal anchor]

Then there you have it

its a system of equations

[proud beacon]

okay thank you

how do I close this

[desert atlas]

.close

[topaz sinew]

@proud beacon Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[zenith cargo]

Good morning guys: I've been trying to solve this differential equation by sustituion and then Bernoulli. However, I don't seem to make when solving it after applying Bernoulli.

How would you guys solve it? I'll annex my current procedure.

Any help is appreciated.

[topaz sinew]

@zenith cargo Has your question been resolved?

[zenith cargo]

<@&286206848099549185>

[cinder fractal]

@zenith cargo I will try

wait a little bit

[zenith cargo]

alright no worries, thanks bro

[cinder fractal]

you tried to use lagrange method?

It seems to me that it will work. I am working on it.

forget

found more concise approach

[zenith cargo]

I don't really know how to solve the equation by Lagrange

[cinder fractal]

got you

do you know about solving DE using power series?

It seems to me that it will be more approachable if you know power series

@zenith cargo sorry. I will pass

[zenith cargo]

Don't worry bro, thanks for trying to help me out

I don't really know power series either

[cinder fractal]

I tried both seris and lagrange. way too much time to solve

[zenith cargo]

Mmm one can just pray for a problem like this not to be present at the exam

[cinder fractal]

by using lagrange I found this

[zenith cargo]

So by integration?

[cinder fractal]

Wait

I am integrating

forget

I am unable to integrate

it is not possible to solve this one analytically. only approximates

forget, man

skip the porblem. revisit again after a while

@zenith cargo

[zenith cargo]

Alright

Thanks for reaching out bro

The world needs more people willing to help like you

I hope you have a wonderful day

I'll keep on trying

<@&286206848099549185>

[topaz sinew]

@zenith cargo Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[worn pelican]

how to headsolve this one

[worn pelican]

-2 and that's it?

i can't connect the dots in this one thought

i know 1/6*1/6 = 1/36

you do it twice so 2

-2 because 1/

is that the logic behind it

[cursive pollen]

can anyone help me in my channel

[topaz sinew]

@worn pelican Has your question been resolved?

Channel closed

Closed by @worn pelican

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[runic carbon]

I was wondering if there are any flaws in this proof

[cursive pollen]

no

[fair moth]

It's a messy proof ngl

[topaz sinew]

@runic carbon Has your question been resolved?

[empty spoke]

the board writing is a bit hard to read but I think your proof is right. Basically exploit the fact that SVD gives two orthogonal change of basis matrices

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[runic carbon]

Oh my bad, ye lemme see how would it go. Thanks

[empty spoke]

okay

feel free to type .close when you no longer need help here

[runic carbon]

Just a quick question

Is this valid to say

[empty spoke]

yes since V is orthogonal so it preserves the Euclidean norm

(I'm off to grab lunch now if you have any further questions I'll check in maybe an hour)

[runic carbon]

I see, thanks!

If anything I'll DM you since I'll close this channel

Much appreciated mate!

.close

[topaz sinew]

Channel closed

Closed by @runic carbon

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[arctic raft]

i dont get it

[acoustic pecan]

what is acceleration, in terms of velocity and time

[arctic raft]

derivative of velocity

[acoustic pecan]

and what is velocity

[arctic raft]

derivative of position

[acoustic pecan]

you seem to be on top of this

[arctic raft]

and taking the double derivative of s i got

12t

and then i put 2 for t and got 24

but got it wrong which is why im confused

[acoustic pecan]

12t is a tad off

wait no sorry

ignore my nonsense

so its saying the answer is 4?

id say youre right with 24, i cant see any reason it would be 4

[arctic raft]

i mean thats what it says here

but it could just be my math teacher putting in the wrong answer

[arctic raft]

ok cool

do u know how this one works?

[acoustic pecan]

write 2^{xy}=e^{xyln(2)}

then do implicit differentiation with the chain rule

[arctic raft]

wait why

[acoustic pecan]

why what?

[arctic raft]

why is the first statement true

[acoustic pecan]

e^{lnx}=x
in the same way that ln(e^x)=x

if a=ln(x) then x=e^a=e^(lnx)

is a simple showing

[arctic raft]

oh is it like the thing thats like

a^x = ln a * a^x

[acoustic pecan]

thats the derivative of a^x, yeah

same idea

[arctic raft]

so wouldnt it be

ln(2) * 2^xy

im rly lost sorry

[vital pollen]

Ok that is the position

You need the acceleration

So derivative of position is velocity then derivative of velocity is position

Oh wait u got it

[arctic raft]

yes ty but i could still use some help for the second one

[acoustic pecan]

you need to use the chain rule

the derivative of 2^[xy] wrt x
is d/dx [xyln(2)] * 2^[xy]

[arctic raft]

thank you for trying i think this is above my intellectual level 😔

[rocky salmon]

Just reverse x and y

so 1/f’(3)

[arctic raft]

ok so

if f'(3) is 1/4

then wouldnt it be 4?

[rocky salmon]

Ohh

Different x

[acoustic pecan]

g'(3)=1/f'(g(3))

[rocky salmon]

Sorry

[arctic raft]

so is g(3) = 10?

[acoustic pecan]

yeah

[arctic raft]

and then f'10= 1?

i mean

1/2

ohh

got it

thank you

🙏

[acoustic pecan]

$$[f^{-1}(x)]'=\frac{1}{f'(f^{-1}(x))}$$

[thorny flame]

AℤØ

[acoustic pecan]

as a general thing

[arctic raft]

ok thank you i totally forgot abt this formula

.close

[topaz sinew]

Channel closed

Closed by @arctic raft

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lusty cedar]

can someone explain to me this mark scheme

.close

[topaz sinew]

Channel closed

Closed by @lusty cedar

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[glossy cipher]

hello

how do i set this up to solve

is this 2x+30x1/2=2x+27

[earnest herald]

do you know sine rule

[glossy cipher]

no

[earnest herald]

oh

[glossy cipher]

im so los

what therom do i need to solve this

i havent done geomtry in so long

[earnest herald]

properties of similar triangle

[glossy cipher]

thx

ohhh

im just cross multipling>

?

[earnest herald]

that should work

[glossy cipher]

kk

[earnest herald]

sort of

[glossy cipher]

2x+27/1 x 2x+30/1

wait

im lost

[topaz sinew]

@glossy cipher Has your question been resolved?

[sweet shard]

.close

[topaz sinew]

Channel closed

Closed by @sweet shard

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vivid hawk]

so

[topaz sinew]

Please don't occupy multiple help channels.

[vivid hawk]

Can anyone compare answers?

for this

please

[agile harness]

stay in your already open channel

[vivid hawk]

No one is going there..

[hollow plaza]

Hold up I think I got this

[agile harness]

and?

[hollow plaza]

Oh hey knief 👋

[agile harness]

what’s up goat

[vivid hawk]

Creating a new channel is faster

[agile harness]

.close

[vivid hawk]

I rather not wait another 20 minutes

[topaz sinew]

Channel closed

Closed by @agile harness

Use .reopen if this was a mistake.

[vivid hawk]

plus, it will close

[agile harness]

go to the other one

[vivid hawk]

Can you just close the other one then?

[agile harness]

go to the other one

[vivid hawk]

https://tenor.com/view/cat-look-cat-look-at-camera-silly-cat-in-a-cage-gif-889392959852579879

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gray tusk]

How would I be able to get started with this?

[pseudo horizon]

oh

all points on DE are equidistant from A and C

let's do the same for A and B

start with finding the midpoint of AB

well actually just construct the perpendicular bisector of AB

no need to find the midpoint

[gray tusk]

how would I do that?

[pseudo horizon]

you use circles centered at A and B

with radii AB

[gray tusk]

I get it

got it right

thanks dude

.close

[topaz sinew]

Channel closed

Closed by @gray tusk

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fluid trench]

how does this work i am so lost

[topaz sinew]

@fluid trench Has your question been resolved?

[sweet shard]

M^2 = M * M. Express that in terms of k

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[strong sable]

Can anyone help me understand this? Maybe some examples will help
I mainly don't quite understand the (mod C) part

[raven sparrow]

It's like a clock.
When you work mod C, it means that you consider all the numbers in ${0, 1, \ldots, C-1}$, and whenever you go \emph{over}, you wrap back.

[thorny flame]

Azyrashacorki

[raven sparrow]

So for instance, if you work mod 4, you only consider 4 elements :
0 is 0 (mod 4)
1 is 1 (mod 4)
2 is 2 (mod 4)
3 is 3 (mod 4)

Then the others wrap up :
4 is 0 (mod 4)
5 is 1 (mod 4)
6 is 2 (mod 4)
.
.
.

In general, you can say that some number $n$ is $a (\mod{C})$ if $n = C k + a$.
That means that $n$ is "$a$" more than a multiple of $C$.

[thorny flame]

Azyrashacorki

[raven sparrow]

What they're explaining in particular is the multiplicative group mod C.

If we work mod 8, then if we consider the number 3, we can ask ourselves : what is the inverse of this number? What number can I multiply 3 with to have the result "wrap" back to 1 ?

In this case, you might realize that 3 * 3 = 9, which is 1 (mod 8). So in this case, 3 is its own inverse.

The reason why they explain that the number must be coprime with C is that if we take 2 for instance we get
2 * 1 = 2
2 * 2 = 4
2 * 3 = 6
2 * 4 = 0
2 * 5 = 2
.
.
.

And notice that we never get to 1 ! That's because 2 is not coprime with 8.

[topaz sinew]

@strong sable Has your question been resolved?

[strong sable]

If we work mod 8, then if we consider the number 3, we can ask ourselves : what is the inverse of this number? What number can I multiply 3 with to have the result "wrap" back to 1 ?
Wait I'm stuck here. Let's say 2(mod 4) , then is there any number can we multiply 2 with to have the result wraps back to 1?

[raven sparrow]

Well 2 * 1 = 2
2 * 2 = 4 which is 0 (mod 4)
2 * 3 = 6 which is 2 (mod 4)

It's the same situation as with mod 8.
2 and 4 are not coprime, so there is no way we can have it wrap back to 1

[strong sable]

Damn this is a little hard to think

Ok i roughly understand now I want to ask how to understand that if GCD(f(x),g(x))=1 then there's h(x) such that f(x)h(x) = 1 mod g(x), are there any examples😿

I found one online but I can barely understand it

[topaz sinew]

@strong sable Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[burnt swift]

Squares are constructed on each of the sides of triangle $\triangle ABC$, as shown. If the perimeter of $\triangle ABC$ is $17$, then what is the perimeter of the nine-sided figure that is composed of the remaining three sides of each of the squares?

[thorny flame]

xbz

[desert atlas]

notice that the squares are 3 x perimeter of triangle abc

[burnt swift]

?

[desert atlas]

3 sides of small square, 3 sides of middle square, and 3 sides of large square

1 side of each sum to 17

so 3 sides of each would be 17x3

[burnt swift]

,calc 3 * 17

[thorny flame]

Result:

51

[burnt swift]

this?

[desert atlas]

yup

[burnt swift]

ty

.solved