help-26

[solemn merlin]

what is the step between equation 101 and 102?

context: V is a rectangular matrix, not guaranted to be square

A = UsigmaV^T

[spare smelt]

seems like they just applied the inverse, although it looks like there's more structure here? is this a diagonal matrix or something?

[solemn merlin]

oh ye

U, sigma, V^T are obtained from the singular value decompostiion

however, V is not square, though sigma is

i'm not sure how the inverse can be applied like that

if V were square it could be done

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[pliant oar]

V has orthonormal columns so $V_r^\top V_r = I_r$ and we can still use this property to reduce the inverse

[thorny flame]

TheWhiteShadow

[solemn merlin]

but VV^T doesnt create I

only V^T V

[jaunty leaf]

Note that (V Σ² V^T)(V Σ^(-2) V^T) = I
Hence V Σ^(-2) V^T is the inverse of V Σ² V^T

[solemn merlin]

how is this true?

this boils down to VV^T = I

how is that true

V has orthonormal columns and is not necessarily square

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[urban grove]

Wait, how is that possible? I thought this was a singular value decomposition

U and V should both be square orthogonal matrices; Sigma is the one that's not necessarily square

Thus V^T = V^-1

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[cobalt lynx]

Can someone check if my work looks correct?

[mint crescent]

,w y'+y=sin(e^x)

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[mint crescent]

,w integrate e^y y' = 2x + sin x

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[mint crescent]

you can check like this in #bots

[mint crescent]

but yeah both of these are fine

[cobalt lynx]

thanks so much!

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[foggy ingot]

For part d of this question what exactly am I meant to say or infer

[foggy ingot]

<@&286206848099549185>

[ivory sorrel]

!15m

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[neon iron]

Is this related to quadratic function?

ax²+bx+c=0

[foggy ingot]

Noooo I’ve figured it out tho so apparently I’m supposed to set the u(x) to be zero

[keen raptor]

this is calculus

[foggy ingot]

Make y the subject differentiate and that would give me the particular solution that I can’t obtain from the one family parameter of solutions

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[worthy sail]

Hey guys I need hwlp with answering derivative applications

[worthy sail]

Find the down interval of √3x*sin2x, 0≤x≤π

I don't understand how intervals work so it would be nice if you can explain it to me

[vast temple]

What's down interval?

[worthy sail]

Idk what's the english word

[fleet roost]

post the original question in ur language

Les't see if others can translate

[worthy sail]

Sure

[worthy sail]

Tentukan interval turun f(x)=

Btw is there any yt vids that can help me with derivatives?

[fleet roost]

Determine the interval where 𝑓(𝑥) is decreasing

[worthy sail]

Yeah

Can you help me

[fleet roost]

usually f(x) is decreasing when f'(x)<0

[worthy sail]

Oh yes, idk how to incorporate that

[fleet roost]

can you do the derivative?

[worthy sail]

√3*2cos2x?

[fleet roost]

umm is this the correct question?

[worthy sail]

Yeah

[fleet roost]

$\sqrt{3}x \sin 2x$

[thorny flame]

Ad_Night

[worthy sail]

Yeah that

[fleet roost]

this is not the derivate.. of that

[worthy sail]

Oh

[fleet roost]

Use uv formula

[fleet roost]

do you know about the uv formula?

[worthy sail]

My teacher did tell me to use it

U'V+V'U

[fleet roost]

Yepp.

Use that and tell me the derivative

[worthy sail]

Of each?

U=3x, U'=3

V=sin 2x V'=2cos2x?

[fleet roost]

U should get answer

$\sqrt{3} \sin{2x} + 2\sqrt{3}x \cos{2x}$

[thorny flame]

Ad_Night

[worthy sail]

The result is the decreasing interval?

[fleet roost]

The result is the interval where $\sqrt{3} \sin{2x} + 2\sqrt{3}x \cos{2x} < 0$

[thorny flame]

Ad_Night

[worthy sail]

Hmmm ok

How do I add that though if I don't know what x is?

[fleet roost]

👀 I don't even think solving x is possible. Let me check though

[worthy sail]

Yeah I thought so

Well that's fine then

I'll just look up yt vids and try to learn

Thanks for the help

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[soft thistle]

Is this matrix totally unimodular?

[long dawn]

I guess you could evaluate the determinant of every square submatrix and see

That would involve evaluating.. 726 square submatrices

There are some other tricks too, if you've worked with bipartite graphs the matrix can be represented as oen

e.g. create two sets among the five rows such that the sum of each column of each set is either 1, 0, or -1. If possible, it's totally unimodular

If my first set is rows 1,2,3 and second is rows 4,5, the sums for the first column would be 1-1+0=0 and 1+0=0, for example

If you can create two such sets with the rows that satisfies this for all six columns it's totes unimodular

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[gilded otter]

.rotate

How is this not correct"?

.rotate

[smoky sparrow]

,rotate

[smoky sparrow]

what aer you trying to do?

[gilded otter]

So basically i got 2/3 PI

and i need to calcute the grade

and the answer is 120

[smoky sparrow]

yeah, 2/3 pi radians is indeed 2/3 * 180 = 120 degrees

pi radians = 180 degrees

[gilded otter]

yea but i see what i did wrong

[smoky sparrow]

ah okay

[gilded otter]

I did (2/3) * pi / (2/360)

but it is (2/3) / (2/360)

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[gilded otter]

,rotate

[gilded otter]

How can i calculate BC with the given grades

or what did i wrong

[spark palm]

what's s in this case

[gilded otter]

Sinus = Overstaand (opposite) / Schuin (oblique)

grade of B = 30 degrees

[spark palm]

so if sine of 30 = -0.988031624093 isn't 0,45

[gilded otter]

mine says 0,45

[spark palm]

use desmos

[hollow drum]

Are you using degrees or radians?

[hollow drum]

That's radians

[gilded otter]

oh fuck

[spark palm]

i know

[gilded otter]

that is what was wrong

i had it on radions

[hollow drum]

Sin(30) is 0.5

[gilded otter]

i mean grades

than it is 2

got it, thnx guys! 🙂

[spark palm]

gg

[gilded otter]

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[crisp bloom]

can you also help me plss

you look smart

[spark palm]

k

[crisp bloom]

channel above this one

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[daring schooner]

guys how do I do this

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[hallow depot]

if you know PS then it is easy to find PY

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[daring schooner]

How do i do it

[daring schooner]

I’m sorry I left for a while

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[vocal dew]

why do I need to double the value of the tension (T) in part b?

[rich bobcat]

T is acting downwards on the string on the left side of pulley and also on the right side of the pulley

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[harsh heath]

Hi the yellow highlights are what's given in the question. starting from the 3rd yellow line, i am supposed to make a change of variables and use the integral provided to obtain the final answer at the bottom (that's typed out).

i'm getting stuck because i have a y^-2 instead of y^2 needed in the given integral and and i also have an additional (1/y) term. what am i doing wrong?

[rich bobcat]

take that 1/y inside the square root

[harsh heath]

ok trying that now

thank you its closer now! sorry if this is really dumb but how do i get that pink circled term?

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[sweet shard]

Factor 1/sqrt(1-Omega_M) from the integrand before integrating

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[marble belfry]

Can someone explain me how these two angles are equal?

[marble belfry]

how angle RSP and RPT are equal?

I am unable to understand it

[wispy timber]

I think this is something known, are you supposed to prove it?

[marble belfry]

No, but I am trying to understand it

<@&286206848099549185>

[wispy timber]

this is a quick proof

tell me if you need further explanation

[marble belfry]

Oh thx for the help, I got it 🫡

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[toxic mist]

I am getting the right hand side of the inequality

the left hand side seems to give me troubles

I figured out the three possible inequalities can be those ones marked by 1 2 and 3

2 does not yield a quadratic with solutions

1 gives the upper bound

and 3 does not seem helpful

From the third eqs i get this as a

its -1 not - of the whole fraction

nvm

seems like its the same fraction as the one

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[prime bane]

how is the second intergral solved? the one under the circled r

[loud oasis]

they use the two trig identities below to rewrite the integrand

[prime bane]

i noticed

ill highlight the parts that confused me gimme a sec

im unsure of how we got those values.

[loud oasis]

,, \frac 14 \sin^2 (2\theta) = \frac 14 \cdot \frac{1-\cos(2\cdot2\theta)}{2}

[thorny flame]

cloud

[prime bane]

OHH

right

greatful for your help, thank you.

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[severe zenith]

#discrete-math

can someone check this for me

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[severe zenith]

is it Suppose that a^\phi(n) \equiv 1 (mod n).

Then a^\phi(n) - 1 + t * n = 1, and hence, a^\phi(n) - t * n = 1

From this it follows that gcd(a,n) = 1

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<@&286206848099549185>

the question

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[craggy arrow]

Let f (x) = x2 − 3/4. Let f (n)(x) denote the composition of f with itself
n times. For example, f (3)(x) = f (f (f (x))). Let R be the set of complex
numbers that is the union of the roots of the polynomials f (n)(x2 + 3/4)
over positive integers n. Let B be the smallest rectangle in the complex
plane with sides parallel to the real and imaginary axes that contains R.
What is the square of the area of B?

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no yet

<@&286206848099549185>

[rigid ivy]

Dang this feels like the mandelbrot set almost

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[deep crow]

Is this the right power series representation of the function?

[sweet shard]

!show

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[odd pagoda]

you can always ask wolframalpha

[deep crow]

I’m not sure how to use wolframalpha

[deep crow]

1/(4+x) = 1/4 series (-x/4)^n = 1/4series (-1)^n (x/4)^n

derive = -1/(4+x)^2 = 1/4 series ( -1)^n (n) (x^(n-1))/ 4^n

multiply by -x^3

(1/4 series ( -1)^n (n) (x^(n-1))/ 4^n )(-x^3)

(series ( -1)^n+1 (n) (x^(n+2))/ 4^(n+1))

[keen raptor]

,w x^3/(4+x)^2

[thorny flame]

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[keen raptor]

First line last image

[deep crow]

how tho

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[silent siren]

Suppose f : R -> R is a nonconstant function such that f(x) \le f(y) whenever x \le y. Prove that there exist a \in R and c > 0 such that f(a + x) - f(a - x) \ge cx for all x \in [0,1].
- Berkley Problems in Mathematics - Problem 1.1.6 (Fa00)

Just checking a (trivial?) few things

1. "nonconstant" means there exist x, y \in R such that x \ne y and f(x) \ne f(y)?
2. "f(x) \le f(y) whenever x \le y" means f is increasing everywhere?

[silent siren]

It's a strange wording if this indeed just means "suppose f : R -> R is an increasing function".

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[loud oasis]

strictly speaking it's nondecreasing, because there could be regions where it is increasing and other regions where it is constant

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[lime gull]

For this question, why don't you have to change the bounds of x and y in order to change dxdy into dydx?

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[lime gull]

<@&286206848099549185>

[sweet shard]

Yea -x<=y<=x changes

[lime gull]

when I changed the bounds for y and x, I couldn't evaluate it

@sweet shard

[sweet shard]

Show your new integral and the rest of your work

[lime gull]

they just switched the dxdy to dydx

[sweet shard]

I see the issue now

They either typo'd or should have put dA instead at the very beginning

dA instead of dxdy

[lime gull]

so this is a question formatting issue?

.close

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[tacit sonnet]

I followed the intrustions my intrusctor gave me but maybe there's something I'm missing?

[finite storm]

That is a constant function

Maybe u forgot e^ something

[tacit sonnet]

I'm not familar with that what we've done is simply put the data on a table and have the calc give us y=ab^t

[finite storm]

Where is the ^t

[tacit sonnet]

i guess in this case it's just the x in the video intrusctions t was swapped for x

but I punched the data in and used the calc to solve for exponential regression is this the question above solved differently?

[finite storm]

Let me try punching it into my calc

[tacit sonnet]

ight I'm gonna try another thing as well

[finite storm]

Different b

[tacit sonnet]

I got the first part sorted out

working on the linear one now

I might be able to do this

[finite storm]

Firstly

ln is not linear

Linear regression is in the form Mx+c

[tacit sonnet]

I got it sorted

thanks for the help!

.close

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[vapid sonnet]

How many continuos map from Q to {0,1}

[smoky sparrow]

!status

[topaz sinew]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[vapid sonnet]

2

[vapid sonnet]

2

Like 1,2 is closed so preimage is closed

[ivory sorrel]

How are you defining continuity here

because the standard limit defn doesn't make much sense here

[vapid sonnet]

Ya I also think but it is just straight up question

[ivory sorrel]

Do you have any options?

[vapid sonnet]

It is true false

Like there are uncountable many maps

Or not

[ivory sorrel]

I think there are no continuous maps

[vapid sonnet]

If we take continuity in over Q then

Like Q is closed in Q

And we can divide Q in two open set In R which Is closed in Q and send one to 1 and one to 0

[topaz sinew]

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@vapid sonnet Has your question been resolved?

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[wooden osprey]

hello, id like to check my proof

well more like a disproof

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[still bough]

what was the formula for this?

[unreal tinsel]

it's a right triangle, you use pythagoras to find the diameter then the circumference

[deft pier]

root 8^2+6^2 (pythagoras) because any triangle in half a circle is a right

and the number you get is the diameter so you multiply by 1/2 to get the radius

and replace it in the circumference rule (2pi.r)

[topaz sinew]

@still bough Has your question been resolved?

[astral forge]

we assume it is a right triangle, but we do not know

[unreal tinsel]

it's a theorem on circles

[astral forge]

Nowhere it says the point is middle of the circle

[unreal tinsel]

right

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[stark crater]

Hi

[stark crater]

Can anyone pls explain the first step of the second pic of this question? why we changed the right hand side ?? to x^2--4x+4--4 ???

I don't understand

anyone pls :/

[main gate]

to make it into a perfect square ?

[stark crater]

I see.. but is there another way to compare things up instead of doing this? like keeping r.h.s as it is

[main gate]

nah I don't think so

the reason they did that is because they wanted to match the (x-2) from the power series to the right side and the remaining is just the constants

and by doing this we can compare the constants and make a relation

in this case 2c2 +2c0 = -4

and the coeff of (x-2)^2 is 1 thus we can also see that the relation between the constands for k =2 must be equal to 1
hence c4x4x3 -2c2+2c2 =1

[stark crater]

I see... Thanks

imma close this now

.close

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[stark crater]

.reopen

[topaz sinew]

✅

[stark crater]

Hey sorry for inconvenience

How can we write the recurrence relation ?

Do we equal the coefficient of (x-2)^k on the series to zero?

[topaz sinew]

@stark crater Has your question been resolved?

[stark crater]

<@&286206848099549185>

[stark crater]

When we said k>=3 after we wrote the recurrence eq? Why not k>=1?

<@&286206848099549185>

[shadow kayak]

Since we already have a solution for k = 1 and 2

for k = 1, the expression was supposed to be zero

for k = 2, the expression was supposed to be 1

for anything greater than 3, it must be 0

[stark crater]

Sorry, but I quiet didn't get it? When we had the sol for k=1 and 2 ?

I mean for the same question yet the right hand side was zero was said k>=1

Here

I think it is bcz we have (x-2)^2-4

😮

U mean bcz (x-2)^2 on r.h.s so we have first and second sol??

[shadow kayak]

Yes

we start from k =1, for which the coeff is 0

for k = 2, coeff is 1

for anything greater than or equal to 3, it's zero

So the key thing here is that they replaced y with it's power series, and equated both sides of the equation to get coefficients of the series

[stark crater]

Silly question, but how'd u know that coeff is 0? Where did u substitute k=1? In the recurrence relation or where?

[shadow kayak]

(x-2)^2 + 4 is the RHS

We're matching for (x-2)^k

is there a (x-2)^1 ?

[stark crater]

No

Just (x-2)^k

[shadow kayak]

Do you see a (x-2)^2?

[stark crater]

On L.H.S, No?

Oh hold up u mean on right hand side

Yes we have (x-2)^2 there

[shadow kayak]

That means when we substitute k = 2 here, we should get (x-2)^2 right?

[stark crater]

Yep correct

[stark crater]

But like that shouldn't it be k=1 ==> c_0=0
K=2 ==> c_1=1 ?

[stark crater]

C_0 here is 1

[shadow kayak]

exactly what happens

[stark crater]

I see...

Thanks alot for helping me out

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[tepid mauve]

I was wondering how I would do #7, as (1/2)(4^x) is not an option

[topaz sinew]

@tepid mauve Has your question been resolved?

[tepid mauve]

<@&286206848099549185>

[gloomy jacinth]

do you know what the graph of k is

[tepid mauve]

yes

[gloomy jacinth]

like the formula

what is it

[neon iron]

You got the inverse function wrong

[tepid mauve]

well i don't know exactky what it is, but i know that in logarithmic form, a<0 and b>1 or vice versa

[gloomy jacinth]

yes so using log

you can switch y and x to solve

[tepid mauve]

ok let me try

for the inverse function

i get

1/2(4^x)

[gloomy jacinth]

umm

[neon iron]

$4^{-0.5 x} \neq 4^{0.5} \cdot 4^{-1} \cdot4^{x}$

[tepid mauve]

oh

[tepid mauve]

because you would add them

[neon iron]

Yeah

[gloomy jacinth]

yea

[tepid mauve]

got it

it's a

thanks for the help

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[digital lagoon]

how to get 6

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[solid lynx]

/help

[lunar geode]

No.

.close

!ask

[pearl fog]

do you have a question?

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[lavish pebble]

how come b is 6000 and not 60?

[lavish pebble]

shouldnt it just be 0.6 x 100

[finite storm]

cm-2

[lavish pebble]

so it would be 0.6 x 100^2

[finite storm]

Why is b 6000 anyway

In kg m-2

Should be multiplied by 10^-4 =0.0001

[lavish pebble]

idk

[topaz sinew]

Show your work, and if possible, explain where you are stuck.

[hollow drum]

No

Because it's cm^2

100 cm = 1 m
Use that to figure out how many cm^2 is in 1 m^2

[lavish pebble]

?

[lavish pebble]

100cm is 1m not 10cm

[hollow drum]

Either way, how many cm^2 is in 1 m^2?

[lavish pebble]

100 idk

[hollow drum]

Use this
100 cm = 1 m

How would you get cm^2?

[lavish pebble]

x100?

idk

[hollow drum]

Have you heard of squaring?

[lavish pebble]

yea

[hollow drum]

So do you get that cm^2 = cm * cm?

[lavish pebble]

yea

[hollow drum]

So going from 100 cm to cm^2 what should you do?

[lavish pebble]

multiply it by 100

[hollow drum]

No technically you square it

[lavish pebble]

yea ik but 100^2 is 100x100 so im saying multiply it by 100 to square it

[hollow drum]

So what's 100 * 100?

[lavish pebble]

10,000

[hollow drum]

Then to convert 0.6 kg * cm^-2 would you multiply or divde by 10000?

[lavish pebble]

divide by 100^2

[hollow drum]

Why?

[lavish pebble]

cuz cm to m is /100

[hollow drum]

That's where you are getting confused at

$0.6 kg * cm^{-2} = \frac{0.6 \text{kg}}{1 \text{cm}^{2}}$

Do you agree?

[thorny flame]

CaptainNova22

[lavish pebble]

no clue

[hollow drum]

What do you mean? cm^-2 just means 1/cm^2

Based on exponent rules

[lavish pebble]

ah

ok yea

[hollow drum]

Now you're trying to convert cm^2 to m^2 because the SI unit for length is m

So you want units to cancel, correct?

[lavish pebble]

yea

[hollow drum]

So what would your next step look like for that?

[lavish pebble]

no idea

ive literally just been multiplying or dividing to convert them

[hollow drum]

Do you get this example?

Notice how the next fraction, the miles cancel out to leave km

That's the same process

$\frac{0.6 \text{kg}}{1 \text{cm}^{2}}$

That's what you have

[thorny flame]

CaptainNova22

[hollow drum]

What should the next frcation look like, which just the units? No values

[lavish pebble]

so this is just 0.6kg per cm^2

[hollow drum]

Yes that's what your problem gave

0.6 kg * cm^-2

[lavish pebble]

idk

cuz im only converting cm to m

and not the kg

[hollow drum]

$\frac{0.6 \text{kg}}{1 \text{cm}^{2}} \times \frac{cm^2}{m^2}$

[thorny flame]

CaptainNova22

[hollow drum]

Do you understand that you have to do something like that?

I didn't plug in the values

But notice how the cm^2 will cancel out

[lavish pebble]

yea

[hollow drum]

So which is the bigger unit, m or cm?

[lavish pebble]

m

no

cm

[hollow drum]

No

Cm is not bigger than m

Meter is bigger than centimeter

So 1 m = 100 cm

Then as mentioned before, you need cm^2

So you square both sides

To get 1 m^2 = 10000 cm^2

[hollow drum]

Plug those values into this here

[lavish pebble]

0.6kg / 10,000 cm^2 x 10,000cm^2 / 1m^2 ?

[hollow drum]

Why did you put 0.6kg / 10,000 cm^2?

It's 0.6 kg * cm^-2 which is 0.6 kg per 1 cm^2

Not 10000

[lavish pebble]

alright ic

[hollow drum]

So 0.6kg / 1 cm^2 x 10,000cm^2 / 1m^2

Do the math, what do you get?

[lavish pebble]

6000kg * m^-2

?

[hollow drum]

Yes

That's what the answer key says

https://www.youtube.com/watch?v=vWovdihteqs
You should watch this

[lavish pebble]

but i could of just done 0.6 x 100 ^2

[hollow drum]

Do you get why you would do that?

Because before you said divide by 100^2

[lavish pebble]

a

ok

[hollow drum]

I suggest watching this because isn't to just "multiply or divide to convert them", there's a process to doing it correctly

[lavish pebble]

alright thx

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[clever shard]

https://gyazo.com/bdc6156d21704da5b0efdec3cea3cddf

[clever shard]

whenever i put this into my calc it gives me question 1 as correct, but im confused on why it wouldnt be question #2

i thought for exponential equations ab^x the a will always be the initial value, so in this case 540?

[sudden flower]

by B you mean the second one?

[clever shard]

yes

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[primal stratus]

Is my proof valid? The answer sheet has a different one.

[empty spoke]

yeah your proof is correct

it's just that the answer sheet didn't make any explicit calculations, they're the same argument though

[primal stratus]

Okay great thanks so much

.close

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[jagged stirrup]

Can someone explain where the dx comes from here?

[jagged stirrup]

the lecturer states that we are "taking the derivative of u with respect to x", but if that so, if we are taking the derivative of x-1 with respect to x, would it just be 1, rather than 1 times dx

hes specifically saying "1 times dx", but i seriously dont understand where the dx is coming from

[steel mauve]

https://tenor.com/view/shrug-gif-16174777086572528592

[jagged stirrup]

another example here

[raven sparrow]

$u = x-1 \implies \frac{\dd{u}}{\dd{x}} = 1 \implies \dd{u} = \dd{x}$

[tacit sundial]

well they do that to express in terms of u

[thorny flame]

Azyrashacorki

[jagged stirrup]

oooh ok this makes sense

lik thats exact;y what i was imagining

thanks for that

[steel mauve]

i dont mean to interrupt, but can someone help me with my simple algebra problem?

[jagged stirrup]

you can have ur own personal channel

if u dont break rules, ppl more likely to help and u dont get banned, use the math help available channels

[steel mauve]

ok llama8594, i will

[jagged stirrup]

and thanks @raven sparrow

[gloomy jacinth]

if your question has been answered you can close the chat with .close have a goodnight ❤️

[jagged stirrup]

.close

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[hexed sand]

hi, what does this last part mean?

[oblique plover]

it means the person who is favored to win loses

[hexed sand]

how do i do this question

best of five im not sure how id calculate

@oblique plover

[oblique plover]

well the odds for boris to win are 5/4 right

[hexed sand]

yeah

[oblique plover]

and the odds for elena to win are 4/5

all ur doing is calculating what the odds are that elena wins

the upset victory is redundant info

just ment to confuse u probably

[hexed sand]

the answer key says 7808/19683

how do i get that

[oblique plover]

cloud seems to be cooking something up

[loud oasis]

you would want to start by calculating the odds of each person winning one game. then if you consider each chess game to have one of them win randomly (according to the probability you just calculated), you want to know the probability of elena winning at least 3 games out of 5

[oblique plover]

so ill let them answer

[hexed sand]

how would i calculate winning at least 3 out of 5

[loud oasis]

we have a problem where:

• you perform a certain number of trials
• each trial has the same probability of success and is independent of the other (at least, that's how we'll model it!)
• we want to know the probability distribution of how many successes we get
  does this probability distribution have a name / seem familiar to you?

[hexed sand]

uh i dont recall? havent learned from any lesson yet idk

[loud oasis]

have you been introduced to the binomial distribution?

[hexed sand]

nope

[loud oasis]

https://www.khanacademy.org/math/statistics-probability/random-variables-stats-library/binomial-random-variables/v/binomial-variables

i would recommend you look up resources on the binomial distribution (one such resource is above). this will give you the tools needed to solve the problem

[topaz sinew]

@hexed sand Has your question been resolved?

[topaz sinew]

@hexed sand Has your question been resolved?

[hexed sand]

ok i still cant get the answer

[topaz sinew]

@hexed sand Has your question been resolved?

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[still bough]

is this like a trick question

im confused

[loud oasis]

do you know the relationship between the number of sides and the sum of interior angles?

[still bough]

they are directly proportional?

[unique quarry]

theres a formula for calculating sum of interior angles

[still bough]

ok i counted ||23|| before looking at my number can you guys count to make sure im not going crazy

[woeful drift]

i agree

[still bough]

so would it be 3780 degrees?

that felt wildly wrong

[sweet shard]

Making you count 23 sides is a dick move

,calc 21 * 180

[thorny flame]

Result:

3780

[sweet shard]

If 23 is correct yea

[still bough]

Ok appreciate it

ill leave this open and let you know if it was right

@sweet shard it was 3780, appreciate it!

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[tacit sonnet]

tried a few things need a guiding hand if possible.

[turbid linden]

Do you know radioactive decay?

[tacit sonnet]

Yes, but not too well

[turbid linden]

OK how about exponential decay

[tacit sonnet]

yep

[turbid linden]

Do you think we can model that with it?

[tacit sonnet]

let me try 1 sec

thank you bro

[turbid linden]

Nice

[tacit sonnet]

life saver

got the exam on Wednesday time to study 💀

[turbid linden]

xd

[tacit sonnet]

.close

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[spring blaze]

how is the exponent rule applied here, i see they did 10-3 but i cant visualize that by trying to write it down

[neon iron]

i think you meant 10-7, anyways (r)(r)(r)(r)(r)(r)(r)(r)(r)(r) /~~ (r)(r)(r)(r)(r)(r)(r)~~

[spring blaze]

yeahhh

ohh i seeeeeeeeeeeeeeee

thanks a bunch, cleared up my confusion

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[cosmic nest]

can someone help me how to factor, f(x)=3x^2-12x+9

[unique quarry]

u can factor 3 out first

then ur left with an easy quadratic

[cosmic nest]

hm okay let me try it

?

[oblique plover]

3(x-3)(x-1)

[cosmic nest]

how do i end with that?

[oblique plover]

you just factor the inside normally

find 2 terms of 3 that add up to -4

[cosmic nest]

OHHHHHHHH

[oblique plover]

something clicked i guess?

nice

[cosmic nest]

that makes sense thank u so much

yeah

[oblique plover]

than x=0,3,1

if it asks for x values

[cosmic nest]

okay okay

how did u know i needed that omg

[oblique plover]

cause thats always the next question

[cosmic nest]

right 😭

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[summer steppe]

how do i solve the difference in the interval 0<=x<=720 degrees

[summer steppe]

The book doesnt give any clues but I think it may be something with this formula but im unsure how to use it

[smoky sparrow]

very true, you need this

$2 sin x + 3 cos x < -2$ implies $\sqrt{2^2 + 3^2} \sin(x + \arctan(3/2)) < -2$

[thorny flame]

south

[smoky sparrow]

pause for a moment to see why

[summer steppe]

ah Pythagorean theory for c

[smoky sparrow]

yes

and you can solve for v in tan v = b/a

[summer steppe]

Thanks

I get it now

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[atomic carbon]

Hello, I can help you.

[wooden osprey]

they already got it

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[deft narwhal]

help ToT

[main gate]

feynman technique

[deft narwhal]

like how

[main gate]

Consider I(a) and I(b) and differentiate both

then integrate

then add

basically take the integral as a function of a and b

[deft narwhal]

ok i'll try something

[main gate]

ans ||ln(a+1)-ln(b+1)||

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[proud relic]

I have no idea whats happening

[proud relic]

the answer is
D = |(-3-1-4)/Sqrt((1^2)+(1^2))| = 8/sqrt(2)

<@&286206848099549185>

[lyric iris]

here

cant read it

too grissy

[proud relic]

mb wait

△ABC
A(1,3)
B(-1,5)
C(-3,−1)

hc∩Midpoint of AB = ?
d(C,AB)

<@&286206848099549185>

man thats sum bs

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[obsidian mesa]

can yall help me lol

[dapper cairn]

.close

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[dapper cairn]

Try sending one more time

.close

[obsidian mesa]

.close

can u see it now?

[dapper cairn]

I can see it but this chat is “owned” by me

[obsidian mesa]

um...

okay??😭

[dapper cairn]

Pisscord

[obsidian mesa]

huh??

im so confused... i jus want the answer😭

[dapper cairn]

.close

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[short ruin]

P;ease help

[compact zodiac]

you know the concepts of the 4?

[short ruin]

No what does that mean

[compact zodiac]

i mean the corresponding angles and the others written in the quetion

do you know what they are

[short ruin]

No 😭

[short ruin]

Ok let me try

[compact zodiac]

now compare these with those in your questions

[short ruin]

I got it tysm

[compact zodiac]

yw

close this channel if you're done

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[short ruin]

/close

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[flint coyote]

A courier service advertises that its average delivery time is less than 3 hours for deliveries in the Vancouver area. The distribution of delivery times is known to be normal, with standard deviation hours. A random sample of deliveries yielded a sample mean delivery time of hours. Consider a test of the null hypothesis that the population mean is 3 against the one-sided alternative that the population mean delivery time is greater than 3. Answer the following, rounding your answers to three decimal places where appropriate.

(a) What is the test statistic?

(b) What is the p-value of the test?

[flint coyote]

I dont know where can i start

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[undone goblet]

so so far what iv tried to do

was use pythagore but it just seems wrong to me

question 1 btw

[compact zodiac]

u can use trig

[undone goblet]

tought about that for a second

so would need to calculate i2

then id have 2 angles out of the 3

[compact zodiac]

yeah

use the formula

[undone goblet]

last angle is easy to get

and then

just formula

and I get lenght of AM ?

[compact zodiac]

should be the case

[undone goblet]

so that should be right

but what am I to be using now ? 😭

oh wait nvm

got it I think

let me verify

[compact zodiac]

yeah you can find sin(i2) first

[undone goblet]

28 degrees

[compact zodiac]

take AM as x

[undone goblet]

arcsin(i2) is 28 degrees

[compact zodiac]

AI is given

you don't need arcsin

[undone goblet]

to get the angle nah ?

[compact zodiac]

don't complicate it

[undone goblet]

ight listening to you

[compact zodiac]

you need sine

not the angle directly

what is sin(i2)?

that you calculated?

[undone goblet]

0.471

[compact zodiac]

in fraction and root form

not decimal

?

i mean that's correct but you need it in frac

[undone goblet]

yeah dont know none about that mate

never learned that 😭

[compact zodiac]

sp how exactly did you calvulate that

[undone goblet]

pretty much

n1 x sin(i1) = n2 x sin(i2)

n1 being 1

sin i1 being 45 degrees

n2 being 1.5

and then we just solve for sin i2

[compact zodiac]

ok so now listen

[compact zodiac]

from here on, use non decimal values for sin(i1)

and then put everything up in fraction

sin(45)=sqrt(2)/2

then solve

[undone goblet]

yeah thats something we never did tho

[compact zodiac]

it is not that different

just abit quicker and less chaotic

[undone goblet]

but its not a "perfect" number tho ?

cant make it into a root

?

[compact zodiac]

we can

just try solving it

[undone goblet]

you mean solve i2 ?

[compact zodiac]

*sine(i2)

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[high quail]

The change is -30h-3h^2

how would I get an average rate of change

[sweet shard]

https://i.ytimg.com/vi/f_Q0qlwlclQ/maxresdefault.jpg

b = x+h and a=x

[high quail]

so would I do this

divide them?

got it

[sweet shard]

[high quail]

Thanks!

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[dusty mason]

How do I do c and d

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@dusty mason Has your question been resolved?

[obsidian zenith]

the normal force is just a force in the opposite direction exerted by the surface

the normal focre on m1 would just be the weight of m1 in the opposite direction

[dusty mason]

for D?

[obsidian zenith]

thats for c

think about what D would be then

[dusty mason]

so D would be

196 N then

[obsidian zenith]

196 N where?

[dusty mason]

Since 49 + 15 times 9.8

and the weight of them two added

together

is equal to normal force

[obsidian zenith]

but in what direction

you have the magnitude you just need to know where its going now

[snow tiger]

it says normal force caused by m1 so wouldnt it just be the weight of m1?

[obsidian zenith]

oh yeah it would be

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[elder glacier]

In 2019, the emission of greenhouse gases in Norway was 50.3 million tonnes of CO2 equivalents. CO2 equivalents mean that all greenhouse gases are converted to what they would correspond to as CO2. In 2020, Norway strengthened its climate target, and the goal was now to reduce emissions by at least 50% by 2030.
Use this to create a model for the emissions of greenhouse gases x years after 2019

[elder glacier]

how do i solve this?

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[mortal island]

please help
364cw1q1(i)

[mortal island]

i've got this so far

is it supposed to be this long?

or have i done smth wrong

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[sweet shard]

That's quite messy to follow your work

[mortal island]

yh ig

are you able to work it out from scratch?

if you're free

[sweet shard]

No

[mortal island]

alr

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[wraith night]

Not sure what Im doing wrong with the second order approximation

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[sharp badger]

how do i prove a limit does/does not exist in r3? I don't really know how to go about it. Do I choose different paths to approach the limit from or try to convert to a different coordinate system and try to solve it first

[loud oasis]

to prove it doesn't exist you show it has different limits along different paths. showing it does exist is harder, but squeeze theorem, change of coordinates and epsilon-delta are all possibilities

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[latent forum]

can help anyone me learn optimizations and related rate before my test tmmrw. I have a basic understanding but

[hoary burrow]

Post an example question you might expect to see on your test

[latent forum]

i think its stuff like this i kinda understand how to do it but idk

<@&286206848099549185>

mb but i really need help

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[ripe phoenix]

Help me umderstand this process

[ripe phoenix]

Exercise 47 just says this

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[fleet walrus]

Say I had an rng based system that chose either red or blue at a set chance percentage.

In the first case scenario, the system is set so I have 93.75% chance to get red

In the second scenario, I have a 50% chance to get red but I run the generator 4 times. If I get red within those 4 times, it counts as a red result. If it goes over 4, it counts as blue.

Would it be safe to assume that I could treat the second scenario as the first scenario (93.75% chance to get red)?

[fleet walrus]

Essentially, would it matter if I knew that the second scenario had a different probability and was rolled 4 times? Or would it not make a difference if I thought that the second scenario is one roll with 93.75% chance like the first scenario?

[clear lodge]

depends on what you're asked for in either

[fleet walrus]

I don’t understand

[clear lodge]

are you asked for chance of exactly one red? chance of at least one red?

[fleet walrus]

At least one red

Actually exactly

[clear lodge]

then no

[fleet walrus]

If you get a red the rolls end and it counts as red