help-26

[long stirrup]

so good luck

[odd flower]

i have not answerd

i have given hint

[long stirrup]

i didn't say you did

[odd flower]

then tf u on abt

[supple shard]

Thanks a lot for your help

[long stirrup]

i didn;t read your message

[supple shard]

I don’t want an answer i needed help with the approach cuz after all I wanna be able to solve them on my own

.close

[topaz sinew]

Channel closed

Closed by @supple shard

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vocal dew]

hihi I'm doing some random vector reflection in planes questions that I've seen online.
Just wanted to check my answer to this question

[vocal dew]

my answer:

[smoky sparrow]

what's your working?

[smoky sparrow]

just checking to make sure you don't have arithmetic mistakes, one sec

[vocal dew]

yup nws

[smoky sparrow]

,w (6 + 4t) * 2 + (2 + 5t) * -1 + (-2 - t) * 4 = 4

[thorny flame]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by sooouth.

[smoky sparrow]

,w 2(6 + 2p) - (2 - p) + 4(-2 + 4p) = 4

your reasoning is excellent by the way

but yes your process is right

since you started at my p = 0 for 6i + 2j - 2k
and where the normal line to the plane is at p = 2/21
the reflection must be at p = 4/21

and then the line connecting point A and the point where p = 4/21

wait.....

sorry

[thorny flame]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by sooouth.

[vocal dew]

haha I was about to say

[smoky sparrow]

I typed it wrong you're correct

[vocal dew]

I was sure I double 2/21 but I wasn't sure where u got 2/13

[vocal dew]

tysm for checking my work, I appreciate it ur time 😄

.close

[topaz sinew]

Channel closed

Closed by @vocal dew

Use .reopen if this was a mistake.

[smoky sparrow]

no worries!

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[swift basin]

I'm sending what the method i tried, wait a second

[swift basin]

nah

it's borken

wait a second

this is what i did, let's see if latex got it

Ok nevermind it's wrong ima explain it into words

(sorry for broken english) To be continuous, left limit and right limit and the value of f(x) in that point should be all the same right?

To be honest, i don''t know which standard limit should i use to make my life easier

Because those limits value should be 0, since f(x0)=0

but my solution is infinite

that's kinda sad

This is college calculus 1

Oh, shoot. I forgot to send my solution.

Above orange should apporach 0, instead orange below should apporach 1

[topaz sinew]

@swift basin Has your question been resolved?

[swift basin]

<@&286206848099549185>

I still haven't solved this limit - I've been trying since 1hr

[topaz sinew]

@swift basin Has your question been resolved?

[tawny garnet]

Now if beta is less than 1 it will be zero

If beta is greater than or equal to 1

Alpha will be +or- ✓2

@swift basin

[swift basin]

wait a second im reading

thanks in advance

Oh you used taylor... sorry to have wasted your time, i didn't tell you that

@tawny garnet i can't use taylor, only standard limits

[tawny garnet]

Oh
I see

But can you confirm is my answer correct (if you have the answer)

[swift basin]

I don't know, but my friend also got square root 2, so i think that might be correct.

[tawny garnet]

K

[swift basin]

I'm practising on older exams

so i don't know the answers

[tawny garnet]

Wait
Let me try without taylor then

[swift basin]

thanks

[tawny garnet]

@swift basin is it fine now?

I didn't used taylor this time

[swift basin]

Im reading

Sorry for being late

[swift basin]

Could you please tell me when it starts

Im havign trouble reading it

[tawny garnet]

Sorry

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[tawny garnet]

I just break the numerator

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tawny garnet]

.reopen

[pseudo pond]

Am I doing this problem correct?

[crimson kayak]

Use u sub

[pseudo pond]

i

did?

[crimson kayak]

Then u didn't get the answer?

[pseudo pond]

uhm

[pseudo pond]

im just asking if i did this correct

[plush tulip]

yes looks correct

next time you can check ur answer on wolfram alpha or desmos

[crimson kayak]

It's correct

[pseudo pond]

ok ty

[plush tulip]

altho not all ur steps are super accurate

[plush tulip]

like you should change the limits when you write du

[pseudo pond]

alright

[plush tulip]

and there should be du in the 3rd last line

[pseudo pond]

ill do that next time

[plush tulip]

cool

[pseudo pond]

thank u

[plush tulip]

np

[pseudo pond]

.close

[topaz sinew]

Channel closed

Closed by @pseudo pond

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[graceful cove]

I am trying to prove that a(b-c)=ab-ac with field axioms

[graceful cove]

So x(y+z) = xy+xz

I say x = a y = b and z= -c

But I run into an issue with showing that (-1)c = -c

[plush tulip]

you need to show that (-1)*c is the additive inverse of c

what's c + (-1)*c

[graceful cove]

0

So we just use the axiom of x+ y =0

[plush tulip]

wdym

x + y = 0 is the definition of y = -x

[graceful cove]

Is that how you would prove it

[plush tulip]

yes, why are you unconvinced?

c + (-1)*c = 0 means that (-1)*c is an additive inverse of c

and additive inverse is unique so (-1)*c is THE additive inverse of c, aka -c

[graceful cove]

But does this show that +(-c) equals -c

[graceful cove]

How do you proof this?

[surreal mural]

c + (-1)c = 1c + (-1)c then use distributive axiom

[topaz sinew]

@graceful cove Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[obsidian gale]

I have

[icy rapids]

What

[thorny flame]

Zbigniew Ziobro

[vestal totem]

sigh

[obsidian gale]

I divide ,, Sin(50 degrees) : 8 = c

[thorny flame]

Zbigniew Ziobro

[vestal totem]

sigh

[obsidian gale]

?

[icy rapids]

The question is not clear

[obsidian gale]

I have this equation

[sharp chasm]

@obsidian gale fix LaTeX

[sharp chasm]

LaTeX Is wrong

[vestal totem]

yes don't use latex if you're just gonna make it super ugly

[obsidian gale]

how what?

[vestal totem]

it's just much harder to read

[obsidian gale]

how to add degrees into LaTex?

[vestal totem]

$\sin(50)=\frac{8}{c}$, assume everything in degrees idr the symbol

[thorny flame]

Percy

[vestal totem]

that works.

[sharp chasm]

^{\circ}

[heady robin]

Wow

Chaos

[vestal totem]

$\sin(50^\circ)$

[thorny flame]

Zbigniew Ziobro

Percy

[obsidian gale]

i did it

[vestal totem]

beautiful

[sharp chasm]

[obsidian gale]

Muhammad

[icy rapids]

,w sin(50°)

[obsidian gale]

prophet of allah

[thorny flame]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by sofficino9188

[sharp chasm]

[obsidian gale]

either way

do i divide with 8

to find c

[heady robin]

Actually

Easier to multiply by c then divide by sin (50)

[vestal totem]

what do you even wanna do

find c or

[obsidian gale]

yo ueamn?

[heady robin]

It will make it c = 8/sin (50)

[obsidian gale]

,, \sin(50^\circ) * c = 8$

[heady robin]

Pulg into calculator and that’s it

[obsidian gale]

,, sin(50^\circ) * c = 8$

[heady robin]

Bro

Just use keyboard

[sharp chasm]

Whats blud doing

[heady robin]

Easier and faster

[obsidian gale]

sin(55 degrees) * c = 8

[icy rapids]

$\sin(50^{\circ}) * c = 8$

[heady robin]

Ok yeah i got what you’re doing

That’s the first step

[obsidian gale]

c = 8 / sin(50*)

[thorny flame]

IceCream

[sharp chasm]

Finally

[obsidian gale]

mhm

and move so its

[sharp chasm]

https://tenor.com/view/mr-bean-thumbs-up-gif-9541697652570218256

[obsidian gale]

divide 8 with sin50

[icy rapids]

$c = \frac{8}{sin(50^{\circ})}$

[obsidian gale]

??

[thorny flame]

IceCream

[obsidian gale]

yup

but can't i do

[heady robin]

Yup

[obsidian gale]

sin(50*) / 8 = c

[sharp chasm]

Minister uses this terminology

[obsidian gale]

i only know how to count money

[sharp chasm]

[icy rapids]

No

[sharp chasm]

Blud is the main character here

[obsidian gale]

i wanna move 8

so it'll equal to c

[icy rapids]

Explain the steps you take

[obsidian gale]

OK OK

Sin(55*) = 8 / c

i move 8

so

division

[heady robin]

You obey math rules, not the other way around

[obsidian gale]

Sin(55*): 8 = c

[icy rapids]

Ok

[obsidian gale]

how?

[icy rapids]

Its 50

[heady robin]

Dont mind me continue

[obsidian gale]

its 55 actually i looked at my triangle

[icy rapids]

Its 1/c not c

[obsidian gale]

!trolling

!uselesss

[vestal totem]

what is going on here

[obsidian gale]

wym

can ANYONE EXPLAIN WHY I CANT DO THAT?

[icy rapids]

When you divide by 8 you are left with 1/c on the right

[heady robin]

You divided both sides by 8 and got 8 to the other side, but 8/c when divided by 8 will equal 1/c not c

[obsidian gale]

why?

where's 1?

[icy rapids]

Explain why it becomes c

[obsidian gale]

its gonna be c alone

[icy rapids]

Why

[obsidian gale]

8:8 / c

OOOOHH

1 / C

OOOOOOHHHHHHHH

yeah rightttt

should've said that

[heady robin]

Imagine it like this, 8/c * 1/8, 8 will cancel with the other and leave 1 and c

[icy rapids]

Do you know that 1 is the neutral element of multiplication?

[obsidian gale]

its 9,77

[heady robin]

Ye i think he got it with the big oh moment

[icy rapids]

What is an equation?

[sharp chasm]

Bro is creating a new kind of mathematics

[icy rapids]

So 1/2 = 2

What its Just no sense

[heady robin]

Mohammed this place is crowded make side jokes another place bro💀

[obsidian gale]

fr its so crowded

[vestal totem]

it's kinda weird

[sharp chasm]

Bro Is not cooking

[vestal totem]

what are you guys even doing

i cant undererstand shit here

[heady robin]

Well since you have an answer now, show the full steps

[obsidian gale]

what full steps?

[heady robin]

I suspect you lack sleep

[obsidian gale]

i already calculated it

[icy rapids]

The creator of the help says that 1/c = c

[sharp chasm]

I don't understand what this guy needs

[heady robin]

Show every step you took, then the calculation you made

[obsidian gale]

8

[heady robin]

That’s a good start

[sharp chasm]

😭

[heady robin]

You gonna confuse him more honestly 💀

[icy rapids]

I cancel

[vestal totem]

yeah same

[heady robin]

Oh my days

[obsidian gale]

i showed you

the calculation

??

what else?

[vestal totem]

i suspect this post lacks coherence

[obsidian gale]

<@&286206848099549185> can anyone NORMAL come here? all these dudes are joking herer

[heady robin]

Well your work is good

[icy rapids]

Why are we joking?

[heady robin]

He solved the problem

[slate bronze]

What is the question

[obsidian gale]

ur now telling me my equation is wrong

"oh my days"

[heady robin]

OH MY DAYS

[obsidian gale]

"I cancel"

UR TELLING ME THAT I DID SOMETHING WRONG, AREN'T YOU?

[heady robin]

Not really that you dud smth wrong

You did good to solve

[obsidian gale]

ok then

[heady robin]

But where did the value of 55 and 8 come from

[obsidian gale]

why r u disappointed when i sent the photo

[icy rapids]

But why are you deleting the messages above?

[obsidian gale]

The height of the triangle is 8 cm blud

[heady robin]

Since there’s c in sin and c in the other side, one would presume they’re same value

[vestal totem]

write one big message about what your problem is and what you're doing about it and i'll read it with minimum levity

[heady robin]

Sorry, but can you show me the question and what it says

[obsidian gale]

ok in a new channel.

this is a mess.

[heady robin]

No

[obsidian gale]

c.lose

.close.

[heady robin]

Ignore everyone

Show

[obsidian gale]

.close

[topaz sinew]

Channel closed

Closed by @obsidian gale

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[narrow karma]

i dont understand why phi is the same as tgphi

[topaz sinew]

@narrow karma Has your question been resolved?

[narrow karma]

.close

[topaz sinew]

Channel closed

Closed by @narrow karma

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ruby heron]

Need help with 23 and 25, thats as far as i got with 23, but my limit seems to be infinity. Which is wrong. So idk what i did wrong. As for 25? I dont know how to do that at all

[agile harness]

how is the limit infinity?

$\lim_{k \to \infty} \frac{k^k}{(k+1)^{k+1}}$

[thorny flame]

knief

[ruby heron]

Ok i guess its more of an indeterminate form

Either way i think i messed up somewhere

[agile harness]

nope

[ruby heron]

Then im lost

[agile harness]

evaluate this

perhaps write (k+1)(k+1)^k

what is

[ruby heron]

Idk

[agile harness]

$\lim_{k \to \infty} \frac{k^k}{(k+1)^k}$

[thorny flame]

knief

[ruby heron]

Is it 1/k+1? Probably not cuz im thinkin of factorials

[agile harness]

what

[agile harness]

well i guess what’s really important here is, is this finite or infinite

[ruby heron]

Infinite?

[agile harness]

🤔

so you think k^k is bigger than (k+1)^k

[ruby heron]

No its not

[agile harness]

so how is it infinite

[ruby heron]

Idk man

Idk how to evaluate it further

[agile harness]

i mentioned this because i was hoping you’d see that here the denominator is larger

[ruby heron]

Yeah i get it

Now

[agile harness]

so what does the limit evaluate to

[agile harness]

this one

[ruby heron]

0?

[agile harness]

yep

[ruby heron]

Is there any way algebraically to simplify it further or is it just direct substitution?

[agile harness]

in general you should know x^x is bigger than almost everyone

[heady robin]

Me personally i would offer a dollar or two to get away from someone holding a knife, but you do you

[ruby heron]

I guess a lot of the same letter trjpped me out

[ruby heron]

Whwt

What

[heady robin]

Im joking nvm me

[agile harness]

i mean just think about it, as k gets larger we will have like (100000000) as the base in the denominator whereas the numerator we will just have 6 has the base

[ruby heron]

Yeah i get that part

Like i said i think all the k's have just been trippin me out

So you quite literally can just directly substitute it from there?

No need for further simplification?

[agile harness]

substitute what

[ruby heron]

K for infinity

[agile harness]

you’re doing the ratio test

[ruby heron]

Yeah

[agile harness]

yea the limit goes to zero

hence the radius is what

[ruby heron]

😐

[agile harness]

review the ratio test

[ruby heron]

I think when we went over radius n such

[agile harness]

or are you only determining convergence/divergence

[ruby heron]

That was a different section

[agile harness]

and not interval of convergence

[ruby heron]

Just convergence and divergence

We have learned IOC

but im kinda behind

So i kinda just taught myself the tests for the most part

I havent gotten myself to that yet

Is the answer infinity?

[agile harness]

alright what about 25

[agile harness]

for the radius?

[ruby heron]

Yes

[agile harness]

yep

[ruby heron]

Yeah i think i remember somethin like that

No idea how to explain it

Just remember the limit reachin 0 and it having a ROC of infinity

Or some shit like that

Idk

[ruby heron]

This i have no idea how to do

[heady robin]

God bless “or some shit like that idk” it saves so much time and effort

[agile harness]

well surely you have some idea

[ruby heron]

For this one? No

My brain is kinda fried

[ruby heron]

Like i said, im kinda behind

Im surprised i was even able to answer it tbh

Lemme look at it again

Wait

🤨

The multiplication is throwin me off rn

[agile harness]

what does the product remind you of

what other operation have you seen that used a bunch of consecutive products

[ruby heron]

1/n

[agile harness]

🤔

[ruby heron]

Im guessing

Lmao

[agile harness]

1/n?

!

[ruby heron]

Oh

Well thankfully he said hes not puttin one on the exam that looks like that

Amirite? Up top

✋

[agile harness]

putting what

25?

[ruby heron]

Yeah

[heady robin]

I have a small a question if i may ask

[ruby heron]

Sure

[agile harness]

✋🏻

[agile harness]

i don’t see why not

[ruby heron]

@agile harness so it is (2n-1)!/(3n-1)!?

Is it&

[heady robin]

For 25 the sum is just (2n-1)/(3n-1) from n = 1 to n= infinity right? Well 3n-1 is always greater than 2n-1, so shouldn’t it just converge to 0?

[ruby heron]

So ratio test?

[agile harness]

no

$\sum_{n=1}^{\infty} \frac{(2n-1)!!}{(3n-1)!!}$

[thorny flame]

knief

[agile harness]

not the same as (2n-1)/(3n-1)

[agile harness]

yep

[heady robin]

Alr got it

[ruby heron]

Fuck

[heady robin]

Thanks

[ruby heron]

Thats kind of an ugly ratio test is it not

Im layin in bed cuz im like mentally exhausted

[agile harness]

and

[agile harness]

fire

my fault

[ruby heron]

Lmao

[agile harness]

i meant fire

lol

[ruby heron]

Crazy typo

I was like damn dude

[agile harness]

bro the d is right next to the f

[ruby heron]

Here lemme try it here

[agile harness]

and the r next to the e

😭😭

[ruby heron]

Lim n->inf |(2(n+1)-1)!/(3(n+1)-1)! ● (3n-1)!/(2n-1)!|

[agile harness]

😟😟

https://www.overleaf.com/learn/latex/Learn_LaTeX_in_30_minutes

[ruby heron]

(2n+1)!/(3n+2)! ● (3n-1)!/(2n-1)!

Nah i aint got 30 min for that rn

[agile harness]

brother i’ll do the typing

😭

[ruby heron]

Lmao

I actually dont even know what to do anymore

Im kinda stuck

On how that simplifies

[agile harness]

$\lim_{n \to \infty} \frac{(2n+1)!!}{(3n+2)!!} \cdot \frac{(3n-1)!!}{(2n-1)!!}$

[thorny flame]

knief

[ruby heron]

Yup

See u knew what i was doin

[agile harness]

now rewrite the left two factorials

[agile harness]

nah i did that myself

[ruby heron]

Oh

[agile harness]

i didn’t read a letter of what you wrote

[ruby heron]

Well i did that

[agile harness]

cant hurt my eyes

[ruby heron]

Boom

[agile harness]

^

[ruby heron]

(3n-1)!/(3n+2)! ● (2n+1)!/(2n-1)!

[agile harness]

my eyes

[ruby heron]

Thats all i got

[agile harness]

brother

[ruby heron]

[agile harness]

n! = n * n-1 * n-2 …

[ruby heron]

Ye

[agile harness]

so n! = n * (n-1)!

cancel some bitches

[agile harness]

^

[ruby heron]

U see i get that part

I know what youre askin of me

What im tellin u

Is that i dont know how

[heady robin]

Cancel some bitches is actually such a fire line 🔥

[ruby heron]

OHHH

Wait

HANG ON

[heady robin]

https://tenor.com/view/neuron-activation-neuron-gif-1455356329209493514

[agile harness]

well (2n+1)! looks like (2n+1)(2n-1)(2n-3)(2n-5)…

[agile harness]

my fault gang

i didn’t see you wrote that

spoiled it

[ruby heron]

((2n +1)(2n))/(3n+2)(3n+1)(3n)

Oh

Did i do it

[agile harness]

no

[ruby heron]

FUCK

[agile harness]

you don’t subtract 1, you subtract 1 from n

maybe it’s easier to see for something like (2n)!

this is just the product of the even numbers

it’s like

[ruby heron]

2 * 4 * 6

[agile harness]

1 * 2 * 4 * 6 * … (2n-2)(2n)

[ruby heron]

So on n so forth

Yeah

Your notation is a bit better

But i see wym

Lmao

[agile harness]

so how is this useful

[ruby heron]

Oh

Wait

Lemme try again

So i shouldve subtracted 2 cuz of 2n

And for the 3n one i should subtracted 3

🤨

[agile harness]

you’re really doing

2n * 2(n-1) * 2(n-2) etc

[agile harness]

(3n-1)(3(n-1)-1)(3(n-2)-1) etc

[ruby heron]

Yo lemme be real for a second

Where the fuck did all this review come from

One section im doin straight integrals

Then im doin surface area, washer n shell method, polar coord shit

[agile harness]

ap calc

[ruby heron]

Now all of a sudden im seeing more factorials and limits than ive ever seen in my life

[agile harness]

that’s how it is

[agile harness]

yea that’s just because american public school education is shit

[ruby heron]

Im in calc 2, i didnt take ap calc in high school

[agile harness]

oh shit lol

[ruby heron]

I chose ap stats

[agile harness]

ap stats is fire though

[ruby heron]

Hated it

[agile harness]

nah it was dope

[ruby heron]

Hate stats in general tbh

[heady robin]

It do be not calc 2 without washer and polar coord

[ruby heron]

No bro

People say that about integrals and infinite series

Washer method can go die tbh

[agile harness]

damn

[heady robin]

I agree

[agile harness]

washer easy asf

[heady robin]

Wash your clothes then

[ruby heron]

^

Bros stinky

[agile harness]

alright

good luck

[heady robin]

Actually i need to check on my clothes

[ruby heron]

Nah wait lol

[heady robin]

We apologize

The unfunny part is that someone is pinging him for help too

[ruby heron]

Lol

[agile harness]

you mean @hazy dirge

[heady robin]

Yeah

[agile harness]

lol

[heady robin]

I’ll go sleep

I wont do my hw

I absolutely need the marks

But whatever

I lack sleep

[agile harness]

just do it

[ruby heron]

(2n+1)(2(n+1)-1)(2(n+2)-1)

Wait

Was i supposed to go down

With the n+2

[heady robin]

Sleep time is past due

And the hw takes hours

[ruby heron]

Was it supposed to be just n

[heady robin]

I simply cannot

[agile harness]

what

[ruby heron]

Im strugglin with this shit

I fuckin hate factorials

[heady robin]

But

They’re fun

Granted i only used them like twice in my life

[ruby heron]

Im just cooked

Im so fuckin tired

I spent like 3 or 4 hours doin hw before bed

Woke up n im already 2 hours deep again

[heady robin]

Isnt this the final question

[ruby heron]

...no.

This is like a halfway point of this assignment

[heady robin]

How many left

[ruby heron]

Then i got like 3 more assignments after

[heady robin]

Damn

[ruby heron]

Im so fucked dude

[heady robin]

Time management

Do easier ones and do most of them

[ruby heron]

Ive been managing quite well

This is an easier one

Fml

[heady robin]

Then set down for the hard

[ruby heron]

Infinite series is gonna make me lose my shit

[heady robin]

What the other assignments?

[ruby heron]

Power series which idk shit about

Power series representing functions or somethin like that

Sounds like a lot of yappin

[heady robin]

Is that power rangers or smth

[ruby heron]

And then taylor and mclaurin series which shouldnt be bad

Fuck if i know

[heady robin]

Is there anything that isnt Σ

[ruby heron]

No

This entire chapter is that

[heady robin]

Cant help you

[ruby heron]

Lmao

[heady robin]

All ik is

[ruby heron]

1/n is divergent

[heady robin]

Σ n, from n=1 to infinity, = N(N+1)/2

https://tenor.com/view/gauss-intensifies-maths-matemáticas-gif-24613101

[ruby heron]

Nice.

[topaz sinew]

@ruby heron Has your question been resolved?

[agile harness]

@ruby heron fym your question hasn’t been resolved

[ruby heron]

i still didnt figure out how to reduce the thingy lmao

@agile harness this is where im at rn

WAIT

I fucked up lol

[agile harness]

alright brother did you get this

[ruby heron]

Back to square 1

I know i can drop off the absolute value btw

My brain just started automatically puttin ir

It

[agile harness]

alright so you’re all caught up now

(2n+1)! = (2n+1)(2n-1)(2n-3)…

so it’s just (2n+1)(2n-1)!

boom

cancels

(3n+2)! = (3n+2)(3n-1)(3n-4)…

so it’s just (3n+2)(3n-1)!

boom

cancels

what’s left

[ruby heron]

2n+1/3n+2

2/3 is the lim

Less than 1

Converges by ratio

[ruby heron]

Im tryna wrap my head around this shit lol

[agile harness]

remember the n goes n -> n-1 -> n-2 etc

so i’m replacing n with n-1 and so on each step

not (2n-1)-1

but

2(n-1) - 1

and so on

the 2 factors in

and we’re really subtracting 2 each time

[ruby heron]

(2n+1)! = (2n+1)(2(n-1)-1)(2(n-2)-1)...

Like that?

[agile harness]

no

[ruby heron]

Aw

😔

[agile harness]

the third one should be 2(n-2)-1

only the n part is changing

[ruby heron]

Ok

[agile harness]

remember that (2n-1)! is really just product of consecutive odd numbers

[ruby heron]

So 2(n-3)-1 is the next

[agile harness]

1 * 3 * 5 * 7 and so on

so the difference between each term is 2

[ruby heron]

(3n+2)! = (3n+2)(3(n+1)-1)(3(n)-1)

That doesnt make sense to me

[agile harness]

hmm

(3n+2)! = (3n+2)(3(n-1) + 2) and so on

[ruby heron]

Ohhhh

Wait

So why does the +2 stay

But in the previous one

The +1 turns to -1

My bad for havin u deal with this for this long

Im like legit tryin to wrap my head around this lol

[agile harness]

hold up

[ruby heron]

Aight

[agile harness]

yea hold on i meant !!

[ruby heron]

....what

[agile harness]

i just got out of the car

anyways

yea that’s probably why he isn’t putting it on the test lol

because technically

it’s a double factorial

[ruby heron]

What the fuck

[agile harness]

lol let me change the notation

[torpid sparrow]

[ruby heron]

Also, can you explain how lim n-> inf lnn/n^(1/2) approaches 0?

Feel like everythins gettin jumbled rn

[torpid sparrow]

Lnn grows slowlier than sqrtn

[agile harness]

ln slow asf

[torpid sparrow]

I hope slowlier is word in english

[ruby heron]

Slower

It woulda just been slower

[torpid sparrow]

Lol right

[ruby heron]

Lmao

So its like sayin 1/700

Then 2/900

So on n so forth

Ok

Do i need to show any work for that

Do i have to do lhospitals or

Cuz that seems annoying

[torpid sparrow]

That depends on the context

[ruby heron]

Just evaluating the limit for this other series im workin on

[torpid sparrow]

@agile harness will tell u, i didnt read anything from this channel

[ruby heron]

It was a lot

[agile harness]

oh lol

yea i fucked up the notation

[ruby heron]

Nvm lhospitals wasnt bad

I just did it. Looks way better

[agile harness]

lhopitals op

@ruby heron where did you see the balloon

[ruby heron]

Front yard

@agile harness

Ay is this bitch decreasin?

[agile harness]

240p bro

[ruby heron]

My camera bro

Thats the best ur gonna get

ah yeah its decreasin huh

lnn is bigger or at least will eventually get bigger than 2

[agile harness]

well since n > 1 we know 2-ln(n) is going to be negative with a positive denominator so yea the derivative is negative

[ruby heron]

yeah

[agile harness]

yea pretty soon

[ruby heron]

i realized

i can take out a negative too huh

-(2+lnn)

wait

-(lnn-2)

[agile harness]

🤔

[ruby heron]

lol

sorry im buggin today

[ruby heron]

I feel like the decreasin looks more obvious with the numerator like this

thats what i was tryna say

[agile harness]

🤷🏼‍♂️

[ruby heron]

aight whatever

continue helpin me with 25

what notation went wrong

what do i gotta do, im so fuckin lost rn on it lol

[agile harness]

write !! instead of !

because what i was doing was really !! where we go 2n+1 to 2n-1 and so on

instead of 2n+1 to 2n

that would be factorial

!

[agile harness]

^

[ruby heron]

are u sure double factorials is needed for this

[topaz sinew]

@ruby heron Has your question been resolved?

Channel closed

Closed by @ruby heron

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wooden osprey]

is there an intuitive way to immediately tell how many dimensions is this?

i think of it as something like, (z1, z2, z3, z4, z5) is five dimensions, but since 6z1 = z2, i can rewrite it as (z1, 6z1, z3, z4, z5), which reduces it to four dimensions

but what about the z3 + 2z4 + 3z5 = 0?

[loud oasis]

well in general we would expect each linearly independent equation to reduce it by one dimension

[wooden osprey]

so this is 3 dimensions?

hm

i thought it would be 2, since 6z1 = z2 is a "line", while z3 + 2z4 + 3z5 = 0 is a "plane", so instead the latter should reduce by 2 dimensions

[loud oasis]

the easy way to calculate a basis is to regard the subspace as the null space / kernel of a particular matrix / linear transformation (then apply gauss et al.)

[loud oasis]

they are all 4D hyperplanes because of the fact we are in C^5

[wooden osprey]

ah i see

okay thanks

.close

[topaz sinew]

Channel closed

Closed by @wooden osprey

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sterile laurel]

Sin,cons,tan

[sterile laurel]

Help

[deep crow]

Soh cah Toa

Opposite is the one across from the angle

Hypotoneous is the slanted one

[sterile laurel]

I know 😞 I want someone to guide me in a call

[deep crow]

Adjacent is the one rigjt next to the angle

I can guide u thru the first one not on call tho

[sterile laurel]

Ok ok

What do I have to do first

[deep crow]

Do yk what ur given

In terms of adj, hyp, opp

[sterile laurel]

I’m missing opposite

[deep crow]

Yeah

[sterile laurel]

Yes yes

[deep crow]

So u have adj, and angle and ur tryna find opposite

So u can do like

X/10 = tan(23)

Then solve for x

Cause u have opposite and adj which fits tan perfectly

[sterile laurel]

How do we find tan

[deep crow]

tan(23)?

U have to use a calculator

[sterile laurel]

Like a^2 b^2=c^2 you need to multiply them and add them then it divide it it give you c^2

Do I have to use a calculator ?

[deep crow]

Wdym

[sterile laurel]

Like do I have to use a calculator to solve it because all formulas that I have learn it a calculator just speeds up the process

[deep crow]

Well I mean finding tan(23) is super hard

Cause it’s not a special angle

[sterile laurel]

Can you teach me it or nah

[deep crow]

Ion know how to find tan(23) without a calculator 😭

[sterile laurel]

😭oh

Dang

But I think with a calculator I’m good

[deep crow]

Do u get how to do it tho

[sterile laurel]

Kinda

[deep crow]

Did u find the value for the fiest one?

[topaz sinew]

@sterile laurel Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tawny garnet]

isn't this question wrong

as how can p,q,r,s can be coplanar

anybody?....

[topaz sinew]

@tawny garnet Has your question been resolved?

[topaz sinew]

@tawny garnet Has your question been resolved?

[topaz sinew]

@tawny garnet Has your question been resolved?

[topaz sinew]

@tawny garnet Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[open abyss]

this dont feel right so far

[wooden moon]

you did something wrong here

you should've multiplied sin^2 with 2 cos^2x term as well

[open abyss]

ohhhhhhhhhhhh

yea

right

mb

wat

[wooden moon]

😮

hmm I think what you did right there is not proper division

[open abyss]

oh

u right

one sec

[wooden moon]

you should get 1 - 2 cos^2 x sin^2 x

[open abyss]

why would i get 1

OHH

WAIT

[wooden moon]

sin^2x/sin^2x

[open abyss]

i turn the first sin^2x into 1-cos^2x

?

[wooden moon]

no

you have to factor out the common term before dividing

like this sin^2x(1 - 2 sin^2xcos^2x)

[open abyss]

why do i need to do that

???????????????

[topaz sinew]

@open abyss Has your question been resolved?

[open abyss]

<@&286206848099549185>

[wooden moon]

because the sin^2x is dividing both sin^2x and 2sin^4xcos^2x

[open abyss]

ohh

so what now

i could turn the 1 into sin^2+cos^2 but that wouldnt rly do anything

@wooden moon

bro plz

[wooden moon]

$\sin^4 x + \cos^4 x \ = \sin^4 x + \cos^4 x + 2\sin^2x \cos^2x - 2\sin^2x \cos^2x
\ = (\sin^2x + \cos^2x)^2 - 2\sin^2x \cos^2x
\ = 1 - 2\sin^2x \cos^2x$

[open abyss]

what

[thorny flame]

Pro_Hecker

[open abyss]

????

[wooden moon]

you can do this to LHS

[open abyss]

why do u just add + 2sin^cos^2 - 2sin^2cos^2

where are u getting that from

[wooden moon]

its like adding 0 it does nothing

we can simplify

that's why I added 2sin^2xcos^2x

[open abyss]

so ur just adding random stuff for it to work

[wooden moon]

No, it's a way to simplify

[open abyss]

alr man

[wooden moon]

its also an identity

do you know about $a^4 + b^4 = (a^2 + b^2)^2 - 2a^2b^2$

[thorny flame]

Pro_Hecker

[open abyss]

no

alr well i guess i get it now

ty

.close

[topaz sinew]

Channel closed

Closed by @open abyss

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sonic ibex]

Is this what I have to do

[topaz sinew]

@sonic ibex Has your question been resolved?

[topaz sinew]

@sonic ibex Has your question been resolved?

[topaz sinew]

@sonic ibex Has your question been resolved?

[topaz sinew]

@sonic ibex Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[golden igloo]

given a function f(x), determine f′′(1) can someone please help me i was doing this for 4 hours and i cannot do that anymore

[neon venture]

which function do u have ?

[golden igloo]

derivation

third

[neon venture]

nah, what is f here ?

[golden igloo]

look im doing 6

[golden igloo]

function

i dont think u can solve that

if u dont know what is function

[neon venture]

you want to take the derivative of x arctan(x), correct ?

well, the second derivative

[golden igloo]

i need to derivaste it 3x

three times

[neon venture]

ok, did you take the first derivative ?

[golden igloo]

ye

[neon venture]

what did you find

[golden igloo]

1/2

[neon venture]

wrong

[golden igloo]

ik

thats why im askin

[solemn venture]

\begin{gathered}
f(1)=1 \cdot \arctan (1)=\frac{\pi}{4} \
f^{\prime}(1)=\arctan (1)+\frac{1}{1+1^2}=\frac{\pi}{4}+\frac{1}{2} .
\end{gathered}

[thorny flame]

ay147912
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[neon venture]

dont give the answer, he need to know how it works

!answer

[solemn venture]

oh i m sorry i will write the steps down

[golden igloo]

thx

[neon venture]

and its f''(1) he wants

[solemn venture]

First you get the single derivative that is ..

$f^{\prime}(x)=\frac{(x+1) \cdot 1-(x-2) \cdot 1}{(x+1)^2}=\frac{(x+1)-(x-2)}{(x+1)^2}=\frac{3}{(x+1)^2} .$

[thorny flame]

ay147912

[solemn venture]

then you compute the second order derivative like

$f^{\prime \prime}(x)=\frac{d}{d x}\left(\frac{3}{(x+1)^2}\right)=3 \cdot \frac{d}{d x}\left((x+1)^{-2}\right)=3 \cdot(-2) \cdot(x+1)^{-3}=\frac{-6}{(x+1)^3} .$

[thorny flame]

ay147912

[solemn venture]

the third order derivative is

$f^{\prime \prime \prime}(x)=\frac{d}{d x}\left(\frac{-6}{(x+1)^3}\right)=-6 \cdot \frac{d}{d x}\left((x+1)^{-3}\right)=-6 \cdot(-3) \cdot(x+1)^{-4}=\frac{18}{(x+1)^4} .$

[thorny flame]

ay147912

[solemn venture]

and so notice that $f^{(n)}(x)=\frac{(-1)^{n+1} \cdot n!}{(x+1)^{n+1}} .$

[thorny flame]

ay147912

[solemn venture]

At $x=1$ if you plug in $x=1$ into the above formula, you get

$$
f^{(n)}(1)=\frac{(-1)^{n+1} \cdot n!}{(1+1)^{n+1}}=\frac{(-1)^{n+1} \cdot n!}{2^{n+1}} .
$$

[thorny flame]

ay147912

[neon venture]

hmm, you are doing too much
why the n-th derivative ?

[solemn venture]

isnt this what the question says ?

sorry it was not in english 😦

[neon venture]

f''(1) to calculate

[solemn venture]

is this $f^{(n)}(1) $?

[golden igloo]

thx

its 6

[neon venture]

no, second derivative

[solemn venture]

im sorry i read nth derivative

only second ?

so for $f(x)=x \cdot \arctan (x)$
we get $f^{\prime}(x)=\arctan (x)+x \cdot \frac{1}{1+x^2} .$

[thorny flame]

ay147912

[solemn venture]

doing the double derivative you get $f^{\prime \prime}(x)=\frac{1}{1+x^2}+\frac{1 \cdot\left(1+x^2\right)-x \cdot 2 x}{\left(1+x^2\right)^2}$

[golden igloo]

i need to derivate it 3x

[thorny flame]

ay147912

[solemn venture]

which can be written as $f^{\prime \prime}(x)=\frac{1}{1+x^2}+\frac{1+x^2-2 x^2}{\left(1+x^2\right)^2}=\frac{1}{1+x^2}+\frac{1-x^2}{\left(1+x^2\right)^2} .$

[thorny flame]

ay147912

[solemn venture]

the truple derivative is $f^{\prime \prime \prime}(x)=-\frac{2 x}{\left(1+x^2\right)^2}+\frac{-2 x}{\left(1+x^2\right)^2}-\frac{4 x\left(1-x^2\right)}{\left(1+x^2\right)^3} .$

[thorny flame]

ay147912

[golden igloo]

huh

[golden igloo]

so this is the exuality?

can u show me progress

@solemn venture

[solemn venture]

i did step by step

[golden igloo]

can u show me like u know

1step -

bc that other guy just typing

and idk what is

that and that

you know

[golden igloo]

1

[golden igloo]

2

like that

@solemn venture

[topaz sinew]

@golden igloo Has your question been resolved?

[topaz sinew]

@golden igloo Has your question been resolved?

[topaz sinew]

@golden igloo Has your question been resolved?

Channel closed

Closed by @golden igloo

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[balmy pebble]

Can someone help me with this exercice

[topaz sinew]

@balmy pebble Has your question been resolved?

[balmy pebble]

I can translate in english

We have to find Un and Vn and the sequence have to respect the condition

The limit of Un when n->+infinite is plus infinite

And the limit of Vn when n->+ infinite is -infinite

So this two condition are the base

And the other condition depend on the exercise

For the little a Lim when n->+infinite (Un + Vn) =0 and Un - Vn cannot make zero , i have to find the sequence Un and Vn when this is possible

Hummm

<@&286206848099549185>

[topaz sinew]

@balmy pebble Has your question been resolved?

[topaz sinew]

@balmy pebble Has your question been resolved?

[topaz sinew]

@balmy pebble Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ionic hornet]

Hi

[ionic hornet]

Had a question on my last Ext 2 exam

for complex numbers

regarding the argand diagram

->

There exists a triangle ABC

where A resides on -3 on the Real axis

and B resides on 3 on the real axis

C is represented as "a + ib"

ACDE forms a square with centre z1

and BCFG forms a square with centre z2

prove that for -3 < a < 3 and b > 0

z1 is perpendicular to z2

not really sure how to approach this question

i understand in particular cases

but not the generalisied format

also they gave us a diagram

[topaz sinew]

@ionic hornet Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.