help-26

[candid salmon]

yeah i dont recommend ever learning row echelon form you will never need it unless youre in an exam and they tell u to learn it

calculators can do ref better than you and quicker than you

[echo granite]

we re not allowed to use calculator sadly :/

[candid salmon]

ah shit

[echo granite]

thank you @candid salmon i solved the question now 🙂

[candid salmon]

nice sorry for sending u down a rabbit hole lol

[echo granite]

no its ok i appreciate for your help

[candid salmon]

ok take care have a nice day

[echo granite]

you too

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[strong sable]

How can I proceed

[prisma mesa]

stirling's approximation could work

[strong sable]

Tysm

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[glass harbor]

ok so before 134, I've just been kinda mentally plugging numbers in. But that's not really working here. @~@ Is it just infinite?

[outer portal]

there’s one number that can’t be plugged in

have you only been thinking of positive numbers?

[glass harbor]

for this one, yes for some reason xD

I shall experiment w/ negatives

oki it does the same thing but just negative :<

[agile harness]

thou shall not divide by zero

🙏🏻🙏🏻

[outer portal]

no spoilers please

[glass harbor]

.... OH WAIT

I had literally input that, saw that it was undefined, and turned away 😭

[outer portal]

you also should write t^-1 as a fraction

[glass harbor]

a h

[outer portal]

so youll see it’s similar to a problem you did before

[glass harbor]

I apparently seriously need to review some exponent stuff 😓

[outer portal]

Maybe but a reminder also works

[glass harbor]

turning that into a fraction is stumping me and Idk why. I've done it before, hm

1/t^1 or something? ;-;

[outer portal]

That’s correct

[glass harbor]

OH YAY

[outer portal]

1/t

[glass harbor]

1/0 is undefined, but what about the +1?

[outer portal]

that doesn’t change that you still divided by 0

and if it worked before, adding 1 would still work

[glass harbor]

ohyeah

ahhh I see, alright

so just a hole at 0, cool :D

wait or a jump x-x

no a hole

Ithink

cause it's literally ~one~ spot

oh could I get help on this one as well? I'm staring at the answer sheet (which skips some questions, so it didn't have 134 for some reason) and still nervous about gettin there. :')

agh I keep forgetting I'm supposed to make a dif chat xD

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[glass harbor]

how did they get here @~@ An identityyy ??

[vale furnace]

Well, what is tan(2x)? Could it be expressed in a more useful form?

[glass harbor]

oh yeahhhh the double angles-

I'm so sorry, Idk what to do w/ this ;-;

[vale furnace]

Well, that’s one way but there’s an easier way.

Involving sin and cos

[glass harbor]

oH

is it just sin(2x)/cos(2x) ?

[earnest gate]

One question, you want a explanation for why the other image is the answer?

[glass harbor]

ye :>

it's seems so out of left field 😭

[earnest gate]

One min

[glass harbor]

no problemo

[crisp bloom]

nah

sin(x) / cos(x)

do you have a trigonometry class

[glass harbor]

that's normal tan tho ?

[crisp bloom]

ok

[glass harbor]

what

[crisp bloom]

just replace x with 2x then

[glass harbor]

so this ?

[crisp bloom]

yh

didnt see sorry

[glass harbor]

nah you're fine

I did

NOT mean to react djhaskldasd

[earnest gate]

The domain of tan(x) is R-((2k+1)pi/2) where k belongs to integers.

Means at all odd multiple of pi/2, it is discontious as it goes to infinity or - infinity as seen in the graph, so when it's 2x instead of x, (2k+1)pi/2 becomes (2k+1)pi/4 as all values become odd multiple of pi/2

One min, will draw graph

This should the graph of tan(2x), we can also observer infinite discontinuity at given intervals

You got it??

[glass harbor]

sorry had to move my cat, she was tryna push me off the chair lmao

I think almooost? I think I just hafta process it xD

OH

okay, I think I see what's happening

[earnest gate]

Drawing graph should help in these kind of question in visualization

[glass harbor]

true

[earnest gate]

I guess your doubt is clear right?

[glass harbor]

oh I never doubted it per say, I just didn't quite understand how to do the problem

I appreciate your help, thank you :D

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[neon iron]

Can anybody help me solve this?

[crisp bloom]

damn i'd also be interested to know how this is solved

[neon iron]

♥️

<@&286206848099549185>

[weary crystal]

what's there to solve? is this supposed to be set equal to 0?

[neon iron]

CUBIC EQUATIONS HOW TO FACTORISE?

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@neon iron Has your question been resolved?

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[sacred python]

Does anyone know how I can put the 2 on the same line as the fraction line? $$\lim_{n\to\infty} \frac{2 \dfrac{d}{dn}(lg(n))}{1}$$

[thorny flame]

shadox

[golden blade]

chartbit does

[vernal matrix]

Try #latex-help for that one

[vernal matrix]

I don’t but nice you have that faith in me

[fair thorn]

what do you mean

[golden blade]

$$\lim_{n\to\infty} 2\frac{\dfrac{d}{dn}(lg(n))}{1}$$ or $$\lim_{n\to\infty} \frac{\dfrac{d2}{dn}(lg(n))}{1}$$

[thorny flame]

bacc (unhelpful)

[golden blade]

😂

[fair thorn]

the second one doesn't even make sense

and the first one is cursed af

[sacred python]

xD

[golden blade]

improper fraction goes brr

[sacred python]

Thanks, but in the future, where is it? Can't find it in the side bar

[fair thorn]

??

[fair thorn]

wayyyy down

[golden blade]

ren got rengnored

[fair thorn]

😭

bacc why is your bio so fucking depressing

[sacred python]

I see preealg, precalc etc?

[vernal matrix]

Can’t remember whether studying hides it but in the Miscellaneous section

[fair thorn]

answer my question my guy

[sacred python]

Like

So it's not in the middle like a cdot

[thorny flame]

ren

[fair thorn]

question is why do you need a frac? the denom is one

[golden blade]

can you draw it on a paper???

[fair thorn]

and idt that's possible frankly

[sacred python]

No. Has to be LaTex

[golden blade]

bro

[sacred python]

Just so show my work

[fair thorn]

LaTeX

[golden blade]

i mean draw it to see what you mean

[fair thorn]

not LaTex

[sacred python]

From d/dn (n)

[fair thorn]

also var is n? first time i've seen that

[thorny flame]

ren

[fair thorn]

not possible

also that looks weird af

[sacred python]

ops, also parenthesis around lg(n)

[sacred python]

but even if it's centered, it means the same, hm+

[sacred python]

for comp sci

oh well, ty anyways guys

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[quasi prairie]

how would i do a on a gdc?

because it's asking for the inverse

[opal vault]

you're tasked to solve $3.1^{x-0.7}-8.4 = -3$

[thorny flame]

rafilou is not not born in 2003

[opal vault]

if you rearrange the equation a bit, and using logs, you'll find x-0.7, and following that, x

[quasi prairie]

hmm yes

[quasi prairie]

so there's no need for the use of a gdc?

[opal vault]

sorry not familiar with that abbreviation

[quasi prairie]

graphical display calculator

basically a graphing calculator

[opal vault]

no a simple calculator is enough

no graph needed

[quasi prairie]

got it

[quasi prairie]

but what does f^-1 mean?

[limber epoch]

f to the power of -1 is the inverse of the original equation, as far as I can remember

I might be wrong tho ‘cause my memory is faulty at times and I’ve been out of the academic life for 2 years 💀i think that’s what it means tho

[quasi prairie]

so it means x?

[plush tulip]

the inverse of f

if f(x) = y then x = f^-1(y)

graphically you can think of switching x and y

so either swapping the axes or reflecting the graph across the line y=x

[quasi prairie]

ohh so that's why we're able to equate the equation to -3

[plush tulip]

what

find x such that f(x) = -3

[quasi prairie]

this says = -3

i'm confused

[opal vault]

well yeah you want to find $f^{-1}(\mathbf{-3})$

[thorny flame]

rafilou is not not born in 2003

[plush tulip]

what's ur confusion

[opal vault]

so solve for x in $f(x) = -3$

[thorny flame]

rafilou is not not born in 2003

[opal vault]

f(x) being this expression

[opal vault]

it's exactly this equation you're solving x for

[quasi prairie]

for example, would f^(x) = a be the same as f^-1(a) ?

[plush tulip]

what's f^(x)

[opal vault]

you mean f(x) = a

[quasi prairie]

yes typo sorry

[plush tulip]

wdym same as

write it mathematically

[opal vault]

if there's a unique solution x to f(x) = a

then x = f^-1(a)

[plush tulip]

x and a are numbers

[quasi prairie]

aahhhh

i finally get it

[quasi prairie]

okay this makes more sense

thank you guys 🙏

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[dawn falcon]

Exercice : $$\int_0^1 \int_0^1 ... \int_0^1 \cos((x_1...x_n)^{1/n})dx_1...dx_n$$

[thorny flame]

Gontran

[dawn falcon]

I need to find this limit guys

[dawn falcon]

I wanted to use probability in order to come with like a law of large number so i need to transform this integral a bit

Is there a way to come though this with probabilities ?

@plush tulip

[plush tulip]

maybe

[dawn falcon]

Would you do it like this ?

[plush tulip]

that's an interesting approach but idk

[dawn falcon]

X_1,...,X_n iid maybe we can start like this

[chilly walrus]

i see (x_1 * ... * x_n)^1/n, i think AM-GM. have you tried it?

[dawn falcon]

Yes

But there is this cos

Idk how to deal with it

[hexed tendon]

probably just taylor expand cos then just integrrate

[dawn falcon]

$1/n\int_0^1 \int_0^1 ... \int_0^1 (x_1+...+x_n)dx$ is someting to look at

[thorny flame]

Gontran

[plush tulip]

this is a lower bound yes

u can compute that

or just keep the cos, u can still integrate it

cos(x1+..+xn/n)

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[smoky magnet]

Can you prove a perpendicular bisector here?

[smoky magnet]

we are given that O is a circle and all the radii of O are congruent

someone plz answer i see ppl helping ppl who asked after me plz

<@&286206848099549185>

<@&286206848099549185>

someone please help i have no clue how to do it.

<@&286206848099549185> NINE people who did this after me are all getting helped. can I please get some assistence too? I have been waiting for a long time and it has gotten frustuating.

[jovial jackal]

Sure what's your problem

[smoky magnet]

thank

you

the picture above

[jovial jackal]

That's eazy

[smoky magnet]

how do you do it

like do I need help?

[jovial jackal]

To prove that line segment DE is a perpendicular bisector of line segment AB, we can use the following steps:
Given:
Line segment AB
Point D is on line segment AB
Point E is not on line segment AB
Line segment DE is perpendicular to line segment ABTo Prove:
AD = DB (i.e., D is the midpoint of AB)

That's all I can do for ypu

You

Okay later

[smoky magnet]

what is AB?

thats not on the question at all

[neon iron]

Are you doing Geometry?

[smoky magnet]

yes

[neon iron]

What are you having issues with?

[smoky magnet]

how to do the problem lol

[smoky magnet]

this

[neon iron]

Send a screenshot

[smoky magnet]

i did

look up

[smoky magnet]

not my question.

[smoky magnet]

this one

[neon iron]

hmm

probably not

[smoky magnet]

ok

THANK you

almost an hour.

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[neon iron]

crazy

[smoky magnet]

fr

angered me a lot

if it happens again im lokey reporting or smt

[neon iron]

lol

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[bright arch]

Can someone help asap how to know if it’s asa or aas I’m confused

[river marsh]

i feel like its aniangle

[bright arch]

What

[river marsh]

6 is congruent and ASA

[bright arch]

How do yoy know

[river marsh]

ok notice that they share a side

[bright arch]

Is it because the middle one shares the side so it’s the left to right angle side angle

Yes

[river marsh]

yes

ok next

5

[bright arch]

How to do it

[river marsh]

4 i guess

[bright arch]

How to do 4

[river marsh]

its angle side angle

but i forgot the property name

[bright arch]

Oh are you using the angle in the middle because they reflect from both of the sides

They are like semetrical

Wait how is it angle side angle

[river marsh]

see the angle beside the side

the one without a label

[bright arch]

How do you know that that’s a angle that counts

Or is it because it’s on one whole side

Like if there’s 3 spots and 2 are filled one being angle and side then the furthest side will be a angle that works for both triangles?

So you the side needs to be the same?

[river marsh]

wait nvm

this is aas

i pulled a stupid

[bright arch]

How is it aas then

[river marsh]

they share an angle

[bright arch]

Oh

is this right

[river marsh]

yes

[river marsh]

?

[bright arch]

How to do number 7

[river marsh]

Angle side angle and yes

[bright arch]

What about 9

AAS?

Wait but there is no side

[river marsh]

im not really sure

for this one

[bright arch]

Oh ok

[ember atlas]

well #9 you cant be sure

you know they are similar by AA similarity

but you don't know if they are congruent without a side length

[river marsh]

oh yeah theres a no option lol

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@bright arch Has your question been resolved?

[bright arch]

So wont be congruent

So it wouldn’t be congruent?

Or it is congruent

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@bright arch Has your question been resolved?

[spiral junco]

Both the triangles r concurrent

First one u know one side and one angle is similar and other one is opposite angles

For 2nd triangle 2 angles r similar and common side

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[strong sable]

Why is this wrong

[neon iron]

the antiderivative of the first term is wrong

looks like you wrote r²e^r²

[strong sable]

Why?

de^r^2=2re^r^2

[neon iron]

thats irrelevant

[strong sable]

I don't understand

[neon iron]

differentiate the result

[neon iron]

this

[strong sable]

1/2(2re^r^2+2r^3e^r^2)

[neon iron]

yeah so you dont get r³e^r²

so its not r²e^r²

[strong sable]

Then what's the correct way

[neon iron]

substitution

and then ibp

[strong sable]

Why can't we directly ibp

[neon iron]

u can

i would substitute first tho

[strong sable]

Thx

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[silent seal]

can anyone help me with scatter plots?

[silent seal]

i understand scatter plots, like putting it into the calculator and stuff (currently i have a software of the calculator) but i dont understand this part.

[flint stump]

Its not very clear what you want from this screenshot, but I think you want to know what is linear regression's line equation and the correlation coefficient r?

At least thats what I guess from the blanks y = __ and r = _

[silent seal]

sorry, let me explain myself!

basically what do i do when approached by a question like this?

[flint stump]

It depends on what you are asked to do...

Again, can you tell what you are asked in this?

[silent seal]

ik how to do this perfectly fine

sorry!

i need to find that correlation coefficient and the equation for it (y = mx + b)

[flint stump]

Yeah, so you want linear regression, and correlation

[silent seal]

yes

[flint stump]

And you can calculate it if you see it in tabular form but cant if its in scatter plot?

[silent seal]

yes

[flint stump]

So, you can see the dots in the scatter plot right? They represent the entry in the tables

[silent seal]

ohh

[flint stump]

So you take a single point on plot like this, and drop perpendiculars on x and y axis

So for this specific point, the entry in the table would become
Distance | 80 | ....

Toll | 6 | ....
and so on

You do this for all points in the scatter plot, and you'd get the whole table

and then you calculate

[silent seal]

ohh i kinda understand, but what if you estimate for certain points on the plot that aren't directly on the line and you put it in the calculator wrong?

[flint stump]

That is a human error, cant do much about it ¯_(ツ)_/¯

[silent seal]

oh

[flint stump]

You need to cross check that you did it right

[silent seal]

gotcha

brb putting the points in the software

i got y = 0.08x + 0.35 and 0.90 for the correlation coefficient (r)

[flint stump]

0.9 looks pretty alright to me

the points do looks to be in somewhat linear relation

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[leaden hatch]

need someone to double check my math

[leaden hatch]

trying to find equations for lines that are tangent to both graphs at the same time

[keen raptor]

If you are just curious if you got the right answer, why not use a graphing calculator?

[leaden hatch]

i plugged it on desmos and it is not correct

[keen raptor]

Is it tangent to either one?

[leaden hatch]

neither are tangent to both

wait

omg i made a mistake in the beginning

a=-b+1

not -b+2

omfg

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@leaden hatch Has your question been resolved?

[leaden hatch]

fixed it, but it still deosnt work

<@&286206848099549185>

[heavy anchor]

what the

where is the question

[leaden hatch]

.close

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[jolly patio]

hey is it possible for you to solve this too

[jolly patio]

im getting a wrong number compared to the answer key

the answer i got via excel was

the answer key states the answer is

oh wait this is the whole question to help

[topaz sinew]

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@jolly patio Has your question been resolved?

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[coarse niche]

So finding basis means I need to find a set of vectors, that will span, for example in U1 case, a+2b-c+d = 0, and 2a-b-c-d=0
Usually my process for finding the basis is just putting it all in a matrix and getting it into echelon form, but I am not sure how to approach the question here, since it is given as equations
I would **greatly **appreciate any help or hints on how I might approach this

[topaz sinew]

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@coarse niche Has your question been resolved?

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@coarse niche Has your question been resolved?

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@coarse niche Has your question been resolved?

[azure grove]

if you dont get any help within the next few hours, you might want to ask this question in the linear algebra channel

oh wait, you've left the server

[sweet shard]

channel will close on its own

[azure grove]

oh, alr

thanks

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[rich wedge]

(pls ignore whatever is in pencil some of them are just copied from the answer key lmao)
can someone tell me how to do these?

[rich wedge]

oops left out the top it reads:

"solve the inequality algebraically"

i dont know how to do it though since i missed a class or two

[river marsh]

those who know?

[river marsh]

which ones?

[rich wedge]

3 through 5

i just need an explanation on how to do them

[odd forge]

make the rhs 0

the inequality side should be zero

for the first

x^2 +x -4 >16

minus 16 both sides

x^2 +x -20 >0

factor and sovle

[rich wedge]

but why are the answers in x<-5 and x>4 and not (-inf, -5]U[4, inf)

for all other questions it was in that form, why not these?

@odd forge

[odd forge]

x < -5 is same as (-inf, -5)

also no closed bracket bc x should not be -5

[rich wedge]

oh yeah forgot abt that

[odd forge]

like on number line

all the values of x before -5

[rich wedge]

yeah i knew that but i thought it was something different because how the answer key suddenly changed formats, thanks for clearing my concern!

[odd forge]

similarly try other questions

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[little pond]

Here’s what I have so far:

if $x^2 - x = k$, and k is an integer, then $x = \frac{1 \pm \sqrt{1 + 4k}}{2}$

That means that the fact that $x^n - x$ is an integer must imply that $1 + 4k$ is a perfect square, but that’s where I got stuck. How can I show that? I tried doing it out for n = 3 and n = 4, where I realised that the factorisation is $x(x-1)$(some other stuff), and since $x(x-1)$ is an integer, the rest of the stuff must be an integer too, but I wasn’t able to prove that - it’s definitely not true for n = 3 or n = 4, but I’m not sure how to deal with the n in the power.

[thorny flame]

Fear na bPónairí

[topaz sinew]

@little pond Has your question been resolved?

[topaz sinew]

@little pond Has your question been resolved?

[little pond]

<@&286206848099549185>

[prisma coral]

write x^n-1=(x-1)(x^n-1 + x^n-2+….1)

[median pivot]

if ur problem is with proving that 1 + 4k is a perfect square, go back to the equation x² + x = k. Multiply it by 4 and add 1 to it and see what u get

[prisma coral]

NVM

[topaz sinew]

@little pond Has your question been resolved?

[outer salmon]

Maybe binomial expansion would work? Different approach than yours though

Also May very well be a dead end

[topaz sinew]

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[serene dome]

What's the greatest common factor of this? I got x^5y^6 but the answer in my book says x^5y^7. What did I do wrong?

[icy sky]

seems like the book made a mistake

[serene dome]

That's what I was thinking.

I kept trying to figure out what I did wrong but I just think the book messed up.

[serene dome]

Also for this somehow the book got4b^8c^2d^6. Am I missing something?

[opal vault]

yeah it's 4b^6cd^6

book is riddled with bad solutions huh

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[agile harness]

nope

[winter osprey]

How is that the answer knief?

[agile harness]

$(64)^{1/3} \cdot m^{7/3} \cdot n^{-4/3}$

[thorny flame]

knief

[agile harness]

the 64^1/3 becomes 4

rewrite 7 as 6 + 1

$m^7 = m^6 \cdot m^1$

[thorny flame]

knief

[agile harness]

hence

$m^{7/3} = m^{6/3} \cdot m^{1/3}$

[thorny flame]

knief

[agile harness]

which is how we get m^2 m^1/3

then $n^{-4/3} = \frac{1}{n^{4/3}}$

[thorny flame]

knief

[agile harness]

rewrite 4 as 3 + 1

$n^{4/3} = n^{3/3} \cdot n^{1/3}$

[winter osprey]

It was going so smooth why can’t I just go how many times 1/3 goes into 7 again ahhhhh

[thorny flame]

knief

[winter osprey]

Yes I was doing this

But apparently N squared is twice wtf?

[agile harness]

hmm they wrote it differently actually

[winter osprey]

Do u think the answer key is wrong?

[agile harness]

it’s still the same but it’s unnecessary

no because

$\frac{n^{2/3}}{n^2} = n^{2/3 - 6/3} = n^{-4/3}$

[thorny flame]

knief

[agile harness]

which is correct

but i see no reason to write it that way

when you could write it the way i did

[winter osprey]

Why is n squared twice, im getting n with n left over

How did an extra 2 ns appear

I’ll just skip that for now

Thank u knief!

I’ve been stuck on this question for a couple days

Is the formula at the top the correct one to use?

[agile harness]

when dividing terms with like bases you subtract exponents

$\frac{x^n}{x^m} = x^{n-m}$

[thorny flame]

knief

[winter osprey]

OOOOO

ofc i shoulda known LOL

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[lethal cypress]

How do you answer an equatiom like this?

[topaz sinew]

@lethal cypress Has your question been resolved?

[lethal cypress]

<@&286206848099549185>

[safe needle]

Multiply the second equation by 2, and then do the first equation minus that. Then you do the third equation minus that, and then just substitute

[lethal cypress]

So just multiply the second equation by -2 and simplify?

That gives me 7x-11z=10. What do I do next?

[glass sun]

this is gaussian elimination

https://youtu.be/eDb6iugi6Uk?si=UZINh3VPkJHZkBM2

[lethal cypress]

I need to use elimination

I understand how to do regular 3 by 3's but not when their is missing parts

can I get some help?

<@&286206848099549185>

[gentle night]

Missing parts are equavilant to 0 multipled by the variable and you can see it in the video

Ok not sure about the video part

But yeah

[lethal cypress]

So just fill in the gaps by putting a 0 in the variables?

[gentle night]

3x + 4y = 19
You can right it as
3x + 4y + 0z = 19

[lethal cypress]

and then solve normally right?

[gentle night]

Pretty much yeah

[gentle night]

Yes

You solve it by gaussian elimination?

[lethal cypress]

no

[gentle night]

Ok so you solve it by substitution?

[lethal cypress]

I solve it liles this, not sure what its called

[gentle night]

Yeah it is called substitution
But like gaussian elimination is a little bit more easier to solve with in 3x3 and larger equations

If you are studying linear algebra then you will need it anyway

[lethal cypress]

Im learning basic stuff so I wasn't introduced to gaussian elimination just yet

I got 0x+2y+3z=8 and 4x+0y-5z=7

What would I multiply do cancel out the Y? Just zero?

[gentle night]

Y is are already cancelled

Because it is multiplied by 0

[lethal cypress]

So where do I go from there?

I did equations 1 and 2, cancelled out the Y's to get 3x+3z=27, so now when I do 2 and 3 and Y is already cancelled what should I do?

.close

[topaz sinew]

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[vivid venture]

can someone tell me how you’d continue from c?

[topaz sinew]

@vivid venture Has your question been resolved?

[vivid venture]

.close

[topaz sinew]

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[vivid venture]

.reopen

[topaz sinew]

✅

[rapid lake]

Assuming every calculation is correct

Take common factor 2cos(5)

[vivid venture]

so it's 2cos5(cos40+cos80)?

[rapid lake]

mmmm

[vivid venture]

wait

i think i know

u would expand cos40 + cos80

and then simplify that

right

[rapid lake]

expand it how?

[vivid venture]

2cos (A+B)/2 * cos(A-B)/2

[rapid lake]

you can try

I thought that too but idk if anything simplifies

[vivid venture]

so i got 2cos60cos20

mmm

when i plug cos40 + cos80 into my calculator

it's the same as cos20

oh wait

cos60 = 1/2

whoopsie

[rapid lake]

lol

you’re right

good job

[vivid venture]

thanks

can u help me with another qwuestion

[rapid lake]

I can try

[vivid venture]

im actually hard stuck on it

okay

part a

[rapid lake]

What is “t formulae”

What you have in the rhs is the formula for tan(2a)

[vivid venture]

no tan2a is 2tantheta / 1 - tan^2 30

[rapid lake]

is t-formulae substitution?

[vivid venture]

yes

[rapid lake]

idk tbh

first time I see t formulae

open a new channel and see if anyone can help I’d say

[vivid venture]

alr sure

i'll just leave this open

[topaz sinew]

@vivid venture Has your question been resolved?

[vivid venture]

.close

[topaz sinew]

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[topaz sinew]

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[maiden needle]

how do i begin rearranging this equation for a

[maiden needle]

actually wait

you can scratch the first part since vi = 0

so it'd be d = (1/2)a*t^2

[unreal tinsel]

double then divide by t²

[boreal mulch]

thats just s=ut+1/2at^2 right

[maiden needle]

it'd be 2d/t^2 ja?

i think so

[unreal tinsel]

yep

[maiden needle]

sweet

thanks

.close

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[tacit turret]

One message removed from a suspended account.

[tacit turret]

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

[topaz sinew]

Channel closed

Closed by @tacit turret

Use .reopen if this was a mistake.

[tacit turret]

One message removed from a suspended account.

[topaz sinew]

✅

[tacit turret]

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[agile harness]

but what is y

[tacit turret]

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One message removed from a suspended account.

[agile harness]

oh y’ is given

[tacit turret]

One message removed from a suspended account.

[agile harness]

and you need y’’

[tacit turret]

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One message removed from a suspended account.

[agile harness]

but we don’t know y?

[tacit turret]

One message removed from a suspended account.

[agile harness]

so

!xy

[topaz sinew]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[tacit turret]

One message removed from a suspended account.

[agile harness]

ok so

$y’ = \frac{y-2x}{2y-x}$

[thorny flame]

knief

[tacit turret]

One message removed from a suspended account.

[agile harness]

yep

looks good

now

y’’

differentiate

quotient rule

[tacit turret]

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One message removed from a suspended account.

[agile harness]

$y’’ = \frac{(2y-x)(y’-2) - (y-2x)(2y’ - 1)}{(2y-x)^2}$

[thorny flame]

knief
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[agile harness]

yes?

[tacit turret]

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One message removed from a suspended account.

[agile harness]

isn’t what

[tacit turret]

One message removed from a suspended account.

[agile harness]

i know

[tacit turret]

One message removed from a suspended account.

[agile harness]

now just substitute y’

[agile harness]

^

then die of boredom

[tacit turret]

One message removed from a suspended account.

One message removed from a suspended account.

[agile harness]

well i mean you should have a good idea of the answer

[tacit turret]

One message removed from a suspended account.

[agile harness]

just by looking at the choices

[tacit turret]

One message removed from a suspended account.

[agile harness]

and yea you just have to do algebra

[tacit turret]

One message removed from a suspended account.

[agile harness]

they did it this way on purpose

[tacit turret]

One message removed from a suspended account.

[agile harness]

did you even look at the denominator

[tacit turret]

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[agile harness]

what

[tacit turret]

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[agile harness]

they’re all cubed

in the denominator

[tacit turret]

One message removed from a suspended account.

[agile harness]

wdym

[tacit turret]

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[agile harness]

$y’’ = \frac{(2y-x)(\frac{y-2x}{2y-x}-2) - (y-2x)(2\frac{y-2x}{2y-x} - 1)}{(2y-x)^2}$

[thorny flame]

knief
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[tacit turret]

One message removed from a suspended account.

[agile harness]

💀💀

it’s not that bad

[tacit turret]

One message removed from a suspended account.

One message removed from a suspended account.

[agile harness]

nuh uh

multiply top and bottom by

2y-x

[tacit turret]

One message removed from a suspended account.

[agile harness]

ugh this is ugly actually

[tacit turret]

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One message removed from a suspended account.

[agile harness]

alright just get a common denominator i guess

wow they hate you

hated these y’’ ones

$y’’ = \frac{(2y-x)(y-2x-4y+2x) - (y-2x)(2y-4x-2y+x)}{(2y-x)^3}$

[thorny flame]

knief
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[agile harness]

yuck

[tacit turret]

One message removed from a suspended account.

[agile harness]

😭😭😭

yo for you

who’s not that great at algebra

just skip it

and go to the next

on the AP exam

you’ll waste so much time

and make a mistake

[tacit turret]

One message removed from a suspended account.

One message removed from a suspended account.

[agile harness]

💀💀

i’m sorry

i shouldn’t be doing this much work for you though

[tacit turret]

One message removed from a suspended account.

[agile harness]

you have to suffer through the algebra to learn

[tacit turret]

One message removed from a suspended account.

One message removed from a suspended account.

[agile harness]

no

don’t

do it

one step at a time

[agile harness]

you should be able to get to this point first

[tacit turret]

One message removed from a suspended account.

One message removed from a suspended account.

[agile harness]

well

do you even know how i got there first

you can combine some like terms

make it a binomial

[tacit turret]

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One message removed from a suspended account.

One message removed from a suspended account.

[agile harness]

did you get here?

[tacit turret]

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One message removed from a suspended account.

[errant flume]

sorry guys ive been lurking but i can help you simplfy this

[tacit turret]

One message removed from a suspended account.

[agile harness]

i know how

[tacit turret]

One message removed from a suspended account.

[agile harness]

i just don’t want to do it for them

unless you see a shorter way

[tacit turret]

One message removed from a suspended account.

One message removed from a suspended account.

[agile harness]

because i was just doing the math in my head

as i typed

[errant flume]

i believe in you 💪

[tacit turret]

One message removed from a suspended account.

[agile harness]

i didn’t want to simplify

[tacit turret]

One message removed from a suspended account.

[agile harness]

what

[tacit turret]

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

[agile harness]

where are you looking?

[tacit turret]

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[agile harness]

there’s an x?

[tacit turret]

One message removed from a suspended account.

[agile harness]

ahh ok

[tacit turret]

One message removed from a suspended account.

[agile harness]

yes

[tacit turret]

One message removed from a suspended account.

One message removed from a suspended account.

[agile harness]

and the other term?

[tacit turret]

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

[unreal tinsel]

,rotate

[agile harness]

hate reading handwriting

learn latex

🙏🏻🙏🏻🙏🏻

[tacit turret]

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

[agile harness]

the denominator is cubed

[agile harness]

in this step after getting the common denominator i factors out the 1/(2y-x) from the denomiantors of both terms in the numerator and moved it to the denomiantor

hence the ^3

[tacit turret]

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[tacit turret]

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[agile harness]

also in the last line it should be -6y^2

[tacit turret]

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One message removed from a suspended account.

One message removed from a suspended account.

[agile harness]

hmm there seems to be a mistake somewhere

[tacit turret]

One message removed from a suspended account.

One message removed from a suspended account.

[agile harness]

the answer choices don’t fit

$y’’ = \frac{(2y-x)(\frac{y-2x}{2y-x}-2) - (y-2x)(2\frac{y-2x}{2y-x} - 1)}{(2y-x)^2}$

[thorny flame]

knief
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[agile harness]

so we had this

lemme redo the math

[tacit turret]

One message removed from a suspended account.

One message removed from a suspended account.

[agile harness]

maybe

[agile harness]

this is definitely right

$y’ = \frac{y-2x}{2y-x}$

[thorny flame]

knief

[agile harness]

$y’’ = \frac{(2y-x)(y’-2) - (y-2x)(2y’-1)}{(2y-x)^2}$

[thorny flame]

knief
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[agile harness]

lets distribute first i guess

[tacit turret]

One message removed from a suspended account.

[agile harness]

$y’’ = \frac{2yy’ - 4y - xy’ + 2x - (2yy’ - y - 4xy’ + 2x)}{(2y-x)^2}$

[thorny flame]

knief
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[tacit turret]

One message removed from a suspended account.

[agile harness]

$y’’ = \frac{2yy’ - 4y - xy’ + 2x - 2yy’ + y + 4xy’ - 2x}{(2y-x)^2}$

[thorny flame]

knief
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[tacit turret]

One message removed from a suspended account.

One message removed from a suspended account.

[agile harness]

$y’’ = \frac{-3y + 3xy’}{(2y-x)^2}$

[thorny flame]

knief
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[agile harness]

now

[tacit turret]

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

[agile harness]

$y’’ = \frac{-3y + 3x(\frac{y-2x}{2y-x})}{(2y-x)^2}$

[thorny flame]

knief
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[agile harness]

then

[tacit turret]

One message removed from a suspended account.

[agile harness]

$y’’ = \frac{(-3y)(2y-x) + (3x)(y-2x)}{(2y-x)^3}$

[thorny flame]

knief
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[tacit turret]

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

[agile harness]

$y’’ = \frac{-6y^2 + 3xy + 3xy - 6x^2}{(2y-x)^3}$

[thorny flame]

knief
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[agile harness]

isn’t this what you had

[tacit turret]

One message removed from a suspended account.

[agile harness]

or am i bugging

[tacit turret]

One message removed from a suspended account.

[agile harness]

$y’’ = \frac{-6y^2 + 6xy - 6x^2}{(2y-x)^3}$

[thorny flame]

knief
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[agile harness]

🤔🤔

[tacit turret]

One message removed from a suspended account.

[agile harness]

send the answers again

[tacit turret]

One message removed from a suspended account.

[agile harness]

,w differentiate x^2 - xy + y^2 = 1

[thorny flame]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by c.knief

[agile harness]

same thing

ok

now

[tacit turret]

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

[agile harness]

,w differentiate $\frac{2x-y}{x-2y}$

[tacit turret]

One message removed from a suspended account.

[thorny flame]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by c.knief

[agile harness]

ahh but

those are partial derivatives

hold on

[tacit turret]

One message removed from a suspended account.

[agile harness]

^

derivative calculator agrees with me

which means i’m right

what’s new

your book is shit

[tacit turret]

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

[agile harness]

mfs cant even differentiate

[tacit turret]

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

[agile harness]

didn’t i tell you what book to use

🤔🤔

[tacit turret]

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

One message removed from a suspended account.

[tacit turret]

One message removed from a suspended account.

One message removed from a suspended account.

[topaz sinew]

Channel closed

Closed by @tacit turret

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[indigo estuary]

is the answer D?

or B

[coarse tusk]

Both look to be correct

[torpid matrix]

at least one of those is not correct

[indigo estuary]

ok thanks

D is 👍🏽

[torpid matrix]

specifically, B is wrong because you are summing the negative area into the integral before taking the ABS

[coarse tusk]

Ahh wait

I read option B wrong

[indigo estuary]

yea i realised

[coarse tusk]

Thought the mod was inside the integral

[indigo estuary]

all g

[vernal matrix]

Same initially

[indigo estuary]

alr thank you guys

.close

[topaz sinew]

Channel closed

Closed by @indigo estuary

Use .reopen if this was a mistake.

[torpid matrix]

I thought it was just obviously D then charbits reactions threw me for a loop

owned by sadcat

[vernal matrix]

Sorrryyy

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[glass harbor]

how did they get there @~@

[lusty marsh]

take 1/x^2 common

[glass harbor]

for the x^2?

oh

right no ok I'm following

[lusty marsh]

mhmm

then u cancel out x^2

and you're done

[glass harbor]

oh o.O lemme try to do this on paper rq

[wary tulip]

[glass harbor]

I get 7 D:

[lusty marsh]

hi laylaa 🤍

[lusty marsh]

how did u get there

send your work

[glass harbor]

lemme draw it out rq

well

Idk, words :')

[lusty marsh]

okay

[lusty marsh]

wym

shld i send u instead

[glass harbor]

oh ur fine, I just kinda

socially panicked for a sec xD

ok this is done weirdly, but it's kinda what happened in my head/on paper

I know it's very wrong, I apologize :')

[lusty marsh]

nw it's just me haha

[lusty marsh]

not really

[glass harbor]

oo another point of confusion, why is 1/x^2 allowed?

[lusty marsh]

hey hey it's fineee
it's difficult to understand things at times here

happens w me too

[lusty marsh]

ill send in a min

[glass harbor]

oki doke

oop

[lusty marsh]

wait

i just realised I did it the long way

a min

[glass harbor]

oki doke xD