#help-26
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<@&286206848099549185>
@ruby magnet Has your question been resolved?
do u have a formula sheet you refer too?
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f(x) = 3x^1/4 - x^3/4
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Could someone please help me with this problem?
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<@&286206848099549185> can u guys explain proportionality to me in more detail pls
Please don't occupy multiple help channels.
It just means that when one value grows, the other does aswell but with an added constant as a factor as far as im aware?
yea but i dont get it
lets say x is proportional to y
ok
1/2
2/4
3/6
are all proportional because they are the same ratio
then x = ky and k is any Number
oh
Just like a linear function
and when you devide both variables, they always = that konstant k
Can you please close the other channel you opened
Yes because 1/2 = 0,5 2/4 = 0,5 3/6 = 0,5
ok
Right and then you d have y = 0.5x , or the other way around, depending on your function
no not specifically
and u can also do
oh so like 2 and 6
right, just anyyyyy number
Its just when one variable grows, the other grows aswell but either slower (k < 1) or it grows faster (k>1) , it relates both Variables
ok thxs soooo much 4 ur time☺️
Tell me 2 random numbers
hahaha
@static marlin 5 and 10?
ohhhhh thxs
☺️
If you had a function y=1/2 x , the proportionalityfactor would be 1/2, because every time x increases in 1, y increases by a half of x
so u divide?
and if you have a function with an inserted point like 10 = 5k, k= 10/5 = 2
k is always the same number,
k will always be same then
yes
In the same function atleast
when you get k, you can get any other value pair for x and y
ok what does k stand 4 then
its just a random variable
oh
you could also call it c or d
or z
It’s the rate of x/y
ok
constant = any number
usually people use k or c and other letters depending on the context
yea just make sure its not x or y

u really helped
Glad to hear
How old are you tho? This was kind of a beginner unit in my country
🤩
Same we did this in 7th grade but i didnt understand it then either hahaha
Never to late to learn math
Yeah tell me about it 😭
@spring zenith you have to close the chat I think
real struggle
We do more math in the physics class than the math class
Same our teacher gave us a quick explaination for derivs and integrals because math is always so behind physics haha
and Vectors
My teacher says “your ability to do math is so weak” instead of teaching it
Oh damn
He just tells us the formula and that’s it
What is your nineth grade physics?
Energy and electric
And tens of threads under these
and mechanical energy is so annyoing
Isn’t it like Kinetic e. + potential e.?
Yea
Thats definitly true
but it's weird bc it's a separate approach
Exactly
the guy who invented energy i think fought with newton, his name was leibniz
The fact that i can cross check with kinematics is so wierd
aHAHaha
Those two
truee
@spring zenith Has your question been resolved?
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I need help with this :
find : $\frac{(\cos\theta+i\sin\theta)^{4}}{(\sin\theta+i\cos\theta)^{5}}$
yøung matr!x
<@&286206848099549185>
convert the top and the bottom into a different form
does cos(theta)+isin(theta) ring any bells?
hint: e^itheta
@grand ether Has your question been resolved?
yes
obviously, they are reversed
both the top and the bottom are can be converted into the other form (see heavenly lambs answer) then exponentiated and combined
which part do you not know?
yøung matr!x
this is the denominator
according to the law of multiplication of comp
complex numbers
just put them in euler's form
didn't take that
wdym didn't take that
idk it's not in the lesson
ik what eulers number is
but it's not solved that way
this is like almost certainly intended to be solved by converting to e^(itheta) form
$(\cos\theta+i\sin\theta)^4=\cos4\theta+i\sin4\theta$
yøung matr!x
Yeah that's from Euler's form
then after this step ?
Write it in e^it notation
yøung matr!x
How did your prof even teach you this without using Euler's form
Wrong, it's integral e ds
I am a self studying high school student
please
cos t + i sin t = e^it
.
By this (cos t + i sin t)ⁿ = e^int = cos nt + i sin nt
Proof of the Euler's form may be found using Taylor series
My job is over, you think now
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We model a speed control system for a bicycle using a chain, a front sprocket (P) with a radius R = 10 cm, and several rear sprockets (P₁) with different radii r₁ between 2 cm and 8 cm. The front and rear sprockets are connected by a non-slip chain. (See Figure 1)
- Let ω be the angular velocity of the front sprocket (P) and ω₁ the angular velocity of a rear sprocket (P₁) with radius r₁.
Show that: ω₁ = (R/r₁)ω (1 pt) - 2.1. Calculate the number of turns n₁ made by the rear sprocket P₁ with radius r₁ = 2 cm when the front sprocket makes one turn. (0.5 pt)
2.2. Let nᵢ be the number of turns made by the rear sprocket (Pᵢ) with radius rᵢ corresponding to the maximum value of rᵢ. Calculate nᵢ
question, if i post multiple questions will they be answered here? (like 3)
Well I'm gonna try to solve this
lemme read it
Do you know why v_chain is constant
@hollow axle
no, because the chain is a rigid object
every point on the chain has to be moving with the same speed as every other point on the chain
i just revised my rotational mechanics a day ago, came in handy :)
And for the second Qs . What I did .is it right?
And that's what I did for the last Qs
wrong, n_i won't be R/r_i * 2pi
what you've written is the number of radians
you need to remove that 2pi
Number of turns made is number of radians / 2pi
If I am looking for the radius ri corresponding to the maximum value of ni, how can I do it
if r is a constant, to maximize n_i you need to minimize r_i
since n_i = r/r_i
So, r=2cm ??
According to what's given in the exercice
Because we have r between 2cm and 8
yeah
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np, im glad to help you
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can someone explain how they determined A and theta
@viral mirage Has your question been resolved?
@viral mirage Has your question been resolved?
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Shiii
its v^3
you can reduce the number of integrations by parts by starting with a substitution
@unique dew Has your question been resolved?
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i solve for what?
M?
cuz if so Idk how I'd do that
u were asking for a friend?
idk bro
im in calc
tag heplers
yeah
never heard of it
Weight of M?
Well first you need to draw M
Then arrow from M pointing down
Label as W = Mg
Yeah
Draw arrow upward to the left
Which is the left rope
Should be 54 degrees with vertical
No two arrows up
Idk about that
But I do it
Same for right arrow
One down one up right and one up left
To represent tension force
Yeah?
Yeah?
Ok np
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How come the denomiator also becomes 3-(4/n)?? shouldn’t it become 1/(3n-4) times 1/n? why does it cancel out
You multiply 1/n to both the numerator and denominator, so it's (3n-4) x 1/n on the denominator and 2n x 1/n on the numerator
@tight rivet Has your question been resolved?
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I don't understand this notation
Can someone explain this in English
[e = \frac{1}{1!} + \frac{1}{2!} + \frac{1}{3!} + \frac{1}{4!} + ...]
Why are there !
k
from mclaurin
What?
mclaurin series
English pal do you understand it
! indicates a factorial
for example 2! = 1x2, 5!=1x2x3x4x5
i thought this guy was trolling at first but notation kinda got real
I'm serious lol
The picture I showed you lol idk
Yeah
does e represent eulers number?
Yes
oh wow
this is what it expands into
I never learned any of these series or notations
,w sum 1/n!, n=0 to infinity
the first thing to note is summation notation
basically what it does is run through every number from n = 0 to n = infinity by substituting n into the equation 1/n!
for example the sum of 1/n would then be 1/1+1/2+1/3+1/4 + ... + 1/infinity
if the sum was from n = 0 to infinity
that's basically what's happening
Yeah, but why are we doing this? It would end up being infinity anyway
The summation notation makes sense but it doesn't make sense why we are using it here
the reason is because it's not infinity
if you look at it it sums to e
that's why we're doing it
that's the summation symbol
@eternal grove Has your question been resolved?
@eternal grove Has your question been resolved?
@eternal grove Has your question been resolved?
@eternal grove Has your question been resolved?
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how do i find a maximum of a multivar function with boundaries for each var
as i understood i have to take both partial ders and set em to 0
and solve system of eq
Yes
That‘s The First Part
Do you mean $x^{2y} - xy^{2}$ or $x*{2}y - xy^{2}$
FluxusX2
then y=0
or y=0
then x =0
or x-2y=0
then x=2y
plug into y(2x-y)=0=>y(4y-y)=0 => 3y^2=0 y=0
so all answers are 0
for second eq too cuz symmetrical eq
or what do you call eq where you can change variaables and the eq deosnt change
yeah, symmertric
buuttt
wait
say x=1 y=1/2
1/2-1/4=1/2
so 0;0 is NOT the right answer
why
You need to find values of x and y so that together the equation you have = 0
eh?
solve the sys of eq you meant or
what
k walk me through it
or just tell me what's wrong with what i did
You have your function f and first you take the partial derivative f_x and f_y then you search the solutions of f_x = and f_y = 0
Then you should have something like x = some value and y = some value so that P(x, y) are 0 when you use them in both partial derivatives
So you should have f_x = 2yx - y^2 and f_y = x^2 - 2xy
A point at the coordinates x, y
uhh
Yes I just want to clarify so we don’t get confused
what
how can a point equal something
Then you should have something like x = some value and y = some value so that P(x, y) are 0 when you use them in both partial derivatives
explain
x is some value, yeah that is 0 , y too
Your function f(x, y) = value. You set the coordinates of a point in your function and get a value out of it
No no
so?
Forget P(x,y) it just confuses you
that was my point
why would i need that
alr, so what do i do after solving sys of eq
You want to search all x, y where f_x = 0 and f_y = 0
Just some formal notation
well YEAH<<< thats what i told you
solve sys of eq
yes
next?
plug and evaluate func?
Yeah and you found x = 0 and y = 0
...YEAhh
Now you want to build the H-Matrix
The Hesse matrix
eh never heard of it
and i bet its not necc for finding the extrema of a func
its just as you said formal notation to make it confusing
You want to do that to find out if it’s an extrema or a minima
extrema are maxima and minima....
Maxima I meant
If you plug it in you get 0 what do you wanna find out with that?
start with f(x,y)=(x^2)y-x(y^2)
0, 0 is an extreme yes but you don’t know if it is a minima or maxima
Or do you really just need to say it’s an extrema?
ok, now:
f_x=2xy-y^2
f_y=x^2-2xy
!
ok, so
let f_x=f_y=0
2xy-y^2=0
x^2-2xy=0
correct?
Yes
ok.
y(2x-y)=0
x(x-2y)=0
so from #1 y=0 then x=0 from #2
from #2 x=0 then y=0 from #1
from #1 2x-y=0 then 2x=y then x(x-4x)=0 | x^2(-3)=0 | x^2=0 | x=0 and y=0
from #2 x-2y=0 then x=2y then y(2x-y)=0 | y(4y-y)=0 | y^2(3)=0 | y^2=0 | y=0 and x=0
Yes
but say f(1, 0.5)=1x0.5-1x0.25=0.25
so this is more than f(0, 0)
so f(0, 0) is NOT the maximum
Yes
You told me extrema can be maximum or minimum
It could also be a saddle
Exactly
but then f(0.5, 1)=-0.25
eh
what
That's why you need the Hessian, as Fluxus was previously saying...
so why did the process not work
What exactly do you think did not work?
i heard its the right process
It did work but your not at the end
i did not find all the extrema
!original
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
f(x,y ) =x^2y-xy^2 how to find maximum
idk
i mean, im more curious why the process didnt work
not about solving the problem
and what to do if it doesnt work
what is the process then if this is not the correct one
You did everything right. You found a counter example to show that it is not a maxima nor a minima so you could either assume it is a point of inflection or there is no extrema for this function
Usually you do everything you did for now. You did the partial derivatives then solved the equations. Then what you usually wanna do is set the hessian matrix implement your values in the matrix you found where you think that there are the extremes and then you want to take the determinant of the matrix and depending of the result you will know if it is a maxima minima or point of inflection
look i mean when you solve it and get an answer, its always one of the extrema, when you dont get an answer theres no extrema
so i got an answer here
so it must be an extrema
but it is not
so this is not the correct process for doing it
because its not consistent
its not guaranteed to work
Look on google
what is then?
ok, so let me get this clear: is what i did the correct process?
for finding the extrema of a 2 var func?
huuuuuuuuh
It’s the right beginning of it you need to understand what the hessian matrix is and then your got imo
ehh
I’m kind of busy rn so I can’t help you further rn. But if you need more help to understand write me a pm so I can answer it later
It tells you if it is an extrema
It can also be a point of inflection
ehh
isnt there an algorithm that finds only extrema?
because as i undersrtood there isnt
alr
You need to do it with the hessian matrix
so is there or not?
@remote grail Has your question been resolved?
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I have homework due in 4 hours, and its 15 questions, can someone help me with this?
you should have been given the formulas for the trig functions of the double angle
if theta lies in q4, only cos and sec will be positive
Encontrado en Google en onlinemathlearning.com
thank you
you're explicitly asked to use the identities to compute your stuff
i guess they also assume you know the values of the trig functions for 30°, 45° and 60°
so what's the answer for the first acc to u
first find sin theta from the given info
do uk this?
:/
@nimble rover Has your question been resolved?
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How do I integrate
$\int e^x \sin(3x) \sin(x) dx $
``` I've changed it to `cos(2x) - cos(4x)` but I don't know what to do next...
xCirno
maybe try putting $sin(3x)$ as $3sin(x)-4sin^3(x)$
swerriee
How about solving -½(cosP - cosQ)=sin3xsinx
hmm let me try
yeah I can't figure out how to solve it with that form
oh
I'm going to try it
If you do sin(2x+x), you're left solving $\int e^x sin^3x$, if that is any help.
Good
is $\int e^x sin^3x$ solvable though?
xCirno
I think the answer shouldn't be that long
,w integral of e^x.sin(3x).sin(x)
Cos P - Cos Q = -2sin0.5(P+Q)sin0.5(P-Q)
My teacher told this, for the integration in the form of $\int(e^{ax}{f(x) + f'(x)}dx)$. Integrate only $\int(e^{ax}f(x) dx)$ with $u = f(x)$ and $dv = e^{ax} dx$ for integration by parts.
xCirno
yeah I did that too, no chance
,w \int exp(x) sin(x)^3
It is, but it’s long.
,w int e^x sin3xsinx
,w int e^xcos2x
,w -int e^xcos4x
Are you sure?
Not really, that method actually works.
@wanton tide Has your question been resolved?
@wanton tide Has your question been resolved?
@wanton tide Has your question been resolved?
@wanton tide Has your question been resolved?
check this out
and let me know if you dont get anything
https://socratic.org/questions/how-do-you-integrate-e-x-cos-x
int e^xcos(x)dx = e^x/2(cosx+sinx) + C Going to have to use integration by parts twice. For u(x) and v(x), IBP is given by int uv' dx = uv - int u'vdx Let u(x) = cos(x) implies u'(x) = -sin(x) v'(x) = e^x implies v(x) = e^x int e^xcos(x)dx = e^xcos(x) + color(red)(inte^xsin(x)dx) Now use IBP on the red term. u(x) = sin(x) implies u'(x) = cos(x) ...
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Always distribute before multiplying da brackets togetha?
what
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[
\qty|2x - 6| < 0
]
nick
not rigorous but correct
what could i do to make it better
ie i think it should be fine for test corrections since it shows you know why
thank you
"abs cant be negative" is not a well defined statement, you really mean something more like "the range of abs(f(x)) is R^+ U 0", so therefore...
idk im bad at analysis but your work is an explanation, not a proof
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@wraith swan Has your question been resolved?
Hm, i might have an idea.
So I’ll basically call a as the special element u got e from.
We have that for every b there exists y such that b = y*a.
Now notice that
y*a = y*(a*e) = (y*a)*e. (1)
But b = y*a for all b, so we have by (1) that
b = b*e for all b.
Ugh I guess I’ll have to live with the bad formatting
Hope it’s readable
Ah I see
Ur welcome!
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Can someone help me find what a and b are, these are simultaneous equations
it might help to factor out the b term
in each equation
having it as a constant * b
Hmm ok
u can also do elimination after multiplying the top equation by 2
I had this here
Oh and then find b
By dividing the stuff next to b?
Yup I get the answer
Thank u so much 😄
.close
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can anyone solve this?
geometric series formula for the first bit, divide the top and bottom of the the first limit by x^3, and use lhopitals for the last bit
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You are given the following identity cscA = sec(0.95). Given that angle a lies in the second quadrant, find the value of a that makes this true.
is 2.52 rad the correct answer in this scenario
Yes
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Ok so i gotta solvethis
and this is what i finished with
so denominator is -4/3 and -1
and numurator is 0 and -2
bc -x(x+2)
but im rlly confused bc the teacher did this
but cant i still get the same answer without doing that???
except the problem is that im not getting the same answer
oops
nvm
bye guys
im tired
i just realized my mistake
AHAH
all good
oh u have to flip the sign...
indeed
also (ditto)
ya but what if im just factoring it out tho
must be an old teacher
well it’s not on the left anymore
so they clearly divided
ok but what if i just left it like this tho
would i get the same answer
just -x^2 - 2x > 0
no idea why you’re writing ditto but yea
im not writting that
its the teachers work
i just dont have my phone on me to send a pic of my work
wait so for inequalities i cant just factor out a -1
and if i do, i have to flip the sign?
if you divide by a negative you must flip the sign yes
mhmi see ok one sec im gonna recheck my work
oh
wow
ok i got it
yep
interesting
ok thanks!
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Can anyone help?
post le problem
!da2a
No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/
K

Do you know how to factorise quadratic equation?
Nope I’m in 6th grade and this is a advanced math practice sheet that I don’t understand
Oh
I have to go in 10 minutes too so I think I’m just gonna ask someone tomorow
I’ll try
Can think of it later
🙂
Ok I gtg now
Bye
By
cya
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if you can convert the values on the left to a fraction, the value on the right is just it's denominator
wait wot
thts hwo they did it
OH
I get what u just said
Ok ok
wait so 0.66 as a fraction
66/100
33/50
:/
0.66 is just about 2/3
And if you're allowed a calculator, you don't need to memorize anything
You want to multiply until you don't have a decimal, so with 2.66, start with 2. So 2.66 times 2 = 5.32, you still have a terrible decimal, so next try 3, so 2.66 * 3 = 7.98 and that's really close to 8 so there you go
You multiplied by 3 hence you do C_1 and multiply that 1 by 3
ohhhh
Got it
tHank so much
so mcuh better than sitting here memorizing this 😭
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Lets say I can multiply two integers A and B, both in the range [1, 255]. What is the smallest composite (non-prime) number that cannot be obtained by multiplying A and B
My thinking is that it is 2 * 257 or 514 since 257 is the smallest prime number above 255. Would this be correct?
why not 256?
,calc 2 * 128
Result:
256
I think this is right. You just check that 257 itself is prime
@uneven grotto Has your question been resolved?
gotcha, thanks
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how to find y using 3x - y =2 with x= 2
substitute x = 2
algebra
this is linear equation
mb
3(2) - y = 2
so expand and solve
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can someone please solve this question, i want to know if i got it right
what did you get?
Not how this server works
Just show your work
x^2-888x+3344=0
huh this doesent have a real solution
oh
i made it up
i just wanted to test my solving skills
bc
😭
im not very good at this
so
you could say
i have a
skill issue
badum tshhhh

I don't recommend lying to helpers if you want help
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is 6-x = 6+6x in mod7?
Yes
@viral fulcrum Has your question been resolved?
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All the undergrad folk
how accurate is this curriculum? I just want to pursue this for the purpose of knowledge and not actually doing a degree or smth….just wanted to expand what I know
I’ve done OSSU for computer science and I’ve found that to be pretty nice
But what I’ve heard is that it’s not even close to an actual CS degree
What about this one?
Closed by @echo oxide
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i legit made it up, why are you being so stuck up
oh sorry a dense set
Let $T(x,y,z) = (2x-4y+3z,6x)$.
\
$T(x_1,y_1,z_1)+T(x_2,y_2,z_2)= (2(x_1+x_2)-4(y_1+y_2)+3(z_1+z_2),6(x_1+x_2) = T(x_1+x_2,y_1+y_2,z_1+z_2)$
A dense set
For the reverse direction you can choose certain vectors to show that properties of linear transformations only hold if b and c are 0.
If T(x,y,z) = (2x-4y+3z+b,6x+cxyz) were linear, then $T(0)=0_v$. Clearly $T(0,0,0) \neq (0,0)$ if $b \neq 0$
\
At the same time linearity would mean that $T(x_1+x_2,y_1+y_2,z_1+z_2) = T(x_1,y_1,z_1)+T(x_2,y_2,z_2)$ We thus hypothesize that $(2x_1-4y_1+3z_1,6x_1+cx_1y_1z_1)=(2(x_1+x_2)-4(y_1+y_2)+3(z_1+z_2),6(x_1+x_2)+c(x_1+x_2)(y_1+y_2)(z_1+z_2)$.
\
A dense set
They clearly aren't the same for all vectors unless c=0
you should be a little more careful, that works for some vectors. So you'd need a 'for all vectors' somewhere in there.
otherwise, that seems fine.
you can also construct a counter example for when c != 0.
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how do i use limit comparison test
i compared it to 1/2^n
but idk how to take the limit with a factorial
you'd show that n!>2^n
same with 2 and 3, but he's talking limit
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I do not understand how to do question 7 but i know how to do question above that
here is the answer key

approximus prime
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when i have projection onto line, would the term pp^t/p^tp cancel to 1 ? in my textbook they just switch it as p^tx/p^tp but i dont see why we dont just cancel it out
$a a^T \neq a^T a$
Katharine
ive read, that the upper term is called dyade
can you please show me what would the upper term be equal to in case ov a = 2 1 -3?
im not really sure how to calculate it
what kind of vector is a
vertical?
let me say it this way
let a be a 1xn vector
then $a a^T$ is a scalar
Katharine
if $a$ has dimensions $m \times n$, then $(m \times n) (n \times m) \to (m \times m)$
but $(n \times m)(m \times n) = (n \times n)$
the dimensions are totally different!
and $a^T a$ would be a nxn matrix
those things flip if a is a nx1 vector
a should be a vector in this situation so n = 1
so you get the matrix $a a^t$ multiplied by the column vector $b$
what happens is that you get another column vector as $y$, with the same dimensions as $b$
south's secret twin brother
specifically, a a^t will be m by m, and b will be m by 1
so their product is an m by 1 vector
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im unsure about my ans to this one
I graphed the absolute function and found the max value within the range to be 4
so would it just be 4m/s
,w d/dt (4t e^(-t^2) - 1) = 0
no, check your work again
t = 1/sqrt(2) is a critical point and it's also a local maximum
(as $t \to \infty, v(t) \to 0$ so it can't be a local minimum)
south's secret twin brother
(given that v(t) is positive there)
@terse bronze Has your question been resolved?
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@smoky sparrow
but we're just trying to find when the absolute value of the function is greatest
not necessarily the local max or local min
so when we graph the abs function find where that value is greatest for speed?
what is wrong with my approach?
ah good catch
I think you just graphed it wrong
but yeah we do have to check the critical points and the endpoints
then take the absolute value
in this case the maximum speed is |v(0)| = |-1| = 1
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do we really need MVT for this? doesn't this just follow from the fact that f is strictly monotone?
BWOC, assume $\exists x_1, x_2 \in I, x_1 \neq x_2$ s.t. $f(x_1) = f(x_2) = 0$. But because $f$ is strictly monotone, it is injective on $I$ so $f(x_1) = f(x_2) \implies x_1 = x_2$, a contradiction
artemetra
like i get how to prove it using MVT but wouldn't the above approach also work just as well?
Yes, it would work and you don't even need continuity
cool, thanks!
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is this a real parabola? I have never seen a parabola like this
is chat GPT trolling or am I dumb?
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oh ok ty
What the hell
💀
yes that was the reaction when I saw that
Chat gpt on some weird stuff
fr
ty
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i dont know how to solve questions in this form
!status
What step are you on?
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2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
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try to do something with the third and second equation
okk but should i tryna convert it to row echalon form or
have no idea what that is lol
😭
sorry
its alr
isnt it just linear equations or am i misunderstanding
yes
well it asks for possible values of c
thats where the difficulty is
exactly
oops mb
If u are relating it to row echelon form
You know theres 3 types
Turn the equations into a matrix and try figure out what c’s you need to fit each of the types of solns
If u arent using row echelon form then u can do it a different way but im assuming u learn row echelon form and need to apply it here
thank u for advice im working on that right now thanks 🙂
@echo granite Has your question been resolved?
ok i just got home and looked and it is quite hard
i thought u could do it that way but its unnecessarily hard compared to using the det
for a system to have a unique solution the det of A must be non zero
so instead of doing ref and working stuff out just work out the det and youll get an equation for C right
you need a c where det A is NOT 0
now you can take the c's that do make det A = 0 and sub them in to see which ones fit each type of equation @echo granite
oh ok i see
it should simplify it to a 3 min question
i tried to use diffirent c values to find out 3 types of row echelon form but it took my half hour so far and i dont even finished it yet
the det is better
lemme try
