#help-26

1 messages · Page 189 of 1

topaz sinewBOT
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@ruby magnet Has your question been resolved?

ruby magnet
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<@&286206848099549185>

topaz sinewBOT
#

@ruby magnet Has your question been resolved?

night sonnet
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do u have a formula sheet you refer too?

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thick oyster
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f(x) = 3x^1/4 - x^3/4

topaz sinewBOT
thick oyster
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the domain would include 0?

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ok thx

#

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supple bay
topaz sinewBOT
supple bay
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Could someone please help me with this problem?

topaz sinewBOT
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@supple bay Has your question been resolved?

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spring zenith
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<@&286206848099549185> can u guys explain proportionality to me in more detail pls

topaz sinewBOT
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Please don't occupy multiple help channels.

tawny citrus
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It just means that when one value grows, the other does aswell but with an added constant as a factor as far as im aware?

spring zenith
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yea but i dont get it

tawny citrus
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lets say x is proportional to y

spring zenith
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ok

golden blade
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1/2
2/4
3/6
are all proportional because they are the same ratio

tawny citrus
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then x = ky and k is any Number

spring zenith
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oh

tawny citrus
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Just like a linear function

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and when you devide both variables, they always = that konstant k

spring zenith
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thx soooo much

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so basicly

versed escarp
static marlin
spring zenith
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ok

tawny citrus
spring zenith
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ok sooo

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its like 1/2

tawny citrus
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no not specifically

spring zenith
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and u can also do

tawny citrus
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it can be any number

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Depends on the function

spring zenith
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oh so like 2 and 6

tawny citrus
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right, just anyyyyy number

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Its just when one variable grows, the other grows aswell but either slower (k < 1) or it grows faster (k>1) , it relates both Variables

spring zenith
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ok thxs soooo much 4 ur time☺️

static marlin
spring zenith
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um

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5 and 10?

tawny citrus
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hahaha

spring zenith
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@static marlin 5 and 10?

little lantern
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5/10 = 1/2

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3/6 = 1/2

spring zenith
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ohhhhh thxs

little lantern
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(blahblah * 1) / (blahblah * 2) = 1/2

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🎉

spring zenith
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☺️

tawny citrus
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If you had a function y=1/2 x , the proportionalityfactor would be 1/2, because every time x increases in 1, y increases by a half of x

static marlin
spring zenith
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so u divide?

tawny citrus
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and if you have a function with an inserted point like 10 = 5k, k= 10/5 = 2

static marlin
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k is always the same number,

tawny citrus
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right

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x and y change but k stays the same

spring zenith
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k will always be same then

tawny citrus
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yes

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In the same function atleast

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when you get k, you can get any other value pair for x and y

spring zenith
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ok what does k stand 4 then

tawny citrus
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its just a random variable

spring zenith
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oh

tawny citrus
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you could also call it c or d

spring zenith
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or z

static marlin
tawny citrus
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it just signifies a number

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that is constant

spring zenith
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ok

tawny citrus
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constant = any number

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usually people use k or c and other letters depending on the context

spring zenith
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so any letter 4 k

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thxs

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i get it now

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☺️

tawny citrus
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yea just make sure its not x or y

spring zenith
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ok

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byeeeee thxs soooo much @tawny citrus

tawny citrus
spring zenith
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u really helped

tawny citrus
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Glad to hear

static marlin
spring zenith
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🤩

tawny citrus
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Same we did this in 7th grade but i didnt understand it then either hahaha

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Never to late to learn math

static marlin
tawny citrus
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@spring zenith you have to close the chat I think

tawny citrus
static marlin
tawny citrus
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and Vectors

static marlin
tawny citrus
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Oh damn

static marlin
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He just tells us the formula and that’s it

tawny citrus
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Well prove him wrongcatking

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Show him the real Sigma is(Gen Z math pun ontop)

static marlin
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9th grade physics was just one big nightmare

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It’s easier now on 10th grade

tawny citrus
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What is your nineth grade physics?

static marlin
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Energy and electric

tawny citrus
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I see

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I love E&M but i always struggle with it for no reason

static marlin
tawny citrus
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and mechanical energy is so annyoing

static marlin
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Isn’t it like Kinetic e. + potential e.?

tawny citrus
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Yea

little lantern
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energy is useful tho it's a lot nicer than using newton's laws

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sometimes

tawny citrus
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Thats definitly true

little lantern
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but it's weird bc it's a separate approach

tawny citrus
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Exactly

little lantern
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the guy who invented energy i think fought with newton, his name was leibniz

tawny citrus
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The fact that i can cross check with kinematics is so wierd

topaz sinewBOT
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@spring zenith Has your question been resolved?

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grand ether
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I need help with this :

topaz sinewBOT
grand ether
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find : $\frac{(\cos\theta+i\sin\theta)^{4}}{(\sin\theta+i\cos\theta)^{5}}$

thorny flameBOT
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yøung matr!x

grand ether
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<@&286206848099549185>

torpid matrix
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does cos(theta)+isin(theta) ring any bells?

wild flume
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hint: e^itheta

topaz sinewBOT
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@grand ether Has your question been resolved?

grand ether
torpid matrix
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which part do you not know?

grand ether
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bro

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$\sin\theta+i\cos\theta = \cos(90-\theta)+i\sin(90-\theta)$

thorny flameBOT
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yøung matr!x

grand ether
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according to the law of multiplication of comp

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complex numbers

earnest apex
grand ether
earnest apex
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wdym didn't take that

grand ether
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ik what eulers number is

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but it's not solved that way

torpid matrix
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this is like almost certainly intended to be solved by converting to e^(itheta) form

earnest apex
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Yeah

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What else do you think of doing

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Taking the conjugate

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If so, good luck

grand ether
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$(\cos\theta+i\sin\theta)^4=\cos4\theta+i\sin4\theta$

thorny flameBOT
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yøung matr!x

earnest apex
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Yeah that's from Euler's form

grand ether
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then after this step ?

earnest apex
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Write it in e^it notation

grand ether
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can you show me

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I didn't take that

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btw your pfp = $BA\sin\theta$

thorny flameBOT
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yøung matr!x

earnest apex
earnest apex
grand ether
grand ether
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isn't it

earnest apex
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Electric

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Well that's besides the point

grand ether
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anyy ways

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can you jus show me the steps

earnest apex
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No, do it on your own

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Here's Euler's form

grand ether
earnest apex
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cos t + i sin t = e^it

grand ether
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oh

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but what about the denominator

grand ether
earnest apex
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Proof of the Euler's form may be found using Taylor series

earnest apex
grand ether
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I think I found it

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Thx man I will work on it

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.close

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hollow axle
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We model a speed control system for a bicycle using a chain, a front sprocket (P) with a radius R = 10 cm, and several rear sprockets (P₁) with different radii r₁ between 2 cm and 8 cm. The front and rear sprockets are connected by a non-slip chain. (See Figure 1)

  • Let ω be the angular velocity of the front sprocket (P) and ω₁ the angular velocity of a rear sprocket (P₁) with radius r₁.
    Show that: ω₁ = (R/r₁)ω (1 pt)
  • 2.1. Calculate the number of turns n₁ made by the rear sprocket P₁ with radius r₁ = 2 cm when the front sprocket makes one turn. (0.5 pt)
    2.2. Let nᵢ be the number of turns made by the rear sprocket (Pᵢ) with radius rᵢ corresponding to the maximum value of rᵢ. Calculate nᵢ
fathom atlas
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question, if i post multiple questions will they be answered here? (like 3)

hollow axle
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That's what I did for n1

earnest apex
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Well I'm gonna try to solve this

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lemme read it

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Do you know why v_chain is constant

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@hollow axle

hollow axle
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?

earnest apex
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no, because the chain is a rigid object

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every point on the chain has to be moving with the same speed as every other point on the chain

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i just revised my rotational mechanics a day ago, came in handy :)

hollow axle
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And for the second Qs . What I did .is it right?

earnest apex
hollow axle
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And that's what I did for the last Qs

earnest apex
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what you've written is the number of radians

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you need to remove that 2pi

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Number of turns made is number of radians / 2pi

hollow axle
# earnest apex

If I am looking for the radius ri corresponding to the maximum value of ni, how can I do it

earnest apex
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since n_i = r/r_i

hollow axle
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According to what's given in the exercice

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Because we have r between 2cm and 8

earnest apex
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yeah

hollow axle
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I truly appreciate your help. Thank you

#

.close

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earnest apex
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viral mirage
#

can someone explain how they determined A and theta

topaz sinewBOT
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@viral mirage Has your question been resolved?

topaz sinewBOT
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@viral mirage Has your question been resolved?

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unique dew
topaz sinewBOT
unique dew
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Where do i begin

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Preparing for my calc 2 midterm

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And need desperate help

finite storm
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evaluate this integral

unique dew
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Thanks

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Lemme try it out

finite storm
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first

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im thinking a long ass integral by parts

unique dew
finite storm
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its v^3

loud oasis
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you can reduce the number of integrations by parts by starting with a substitution

topaz sinewBOT
#

@unique dew Has your question been resolved?

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wet holly
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i solve for what?

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M?

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cuz if so Idk how I'd do that

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u were asking for a friend?

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idk bro

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im in calc

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tag heplers

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yeah

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never heard of it

placid turtle
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Weight of M?

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Well first you need to draw M

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Then arrow from M pointing down

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Label as W = Mg

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Yeah

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Draw arrow upward to the left

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Which is the left rope

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Should be 54 degrees with vertical

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No two arrows up

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Idk about that

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But I do it

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Same for right arrow

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One down one up right and one up left

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To represent tension force

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Yeah?

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Yeah?

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Ok np

topaz sinewBOT
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tight rivet
topaz sinewBOT
tight rivet
#

How come the denomiator also becomes 3-(4/n)?? shouldn’t it become 1/(3n-4) times 1/n? why does it cancel out

final jungle
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You multiply 1/n to both the numerator and denominator, so it's (3n-4) x 1/n on the denominator and 2n x 1/n on the numerator

topaz sinewBOT
#

@tight rivet Has your question been resolved?

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eternal grove
#

I don't understand this notation

topaz sinewBOT
eternal grove
#

Can someone explain this in English

finite storm
#

[e = \frac{1}{1!} + \frac{1}{2!} + \frac{1}{3!} + \frac{1}{4!} + ...]

eternal grove
#

Why are there !

thorny flameBOT
finite storm
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from mclaurin

eternal grove
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What?

finite storm
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mclaurin series

river marsh
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English pal do you understand it

true coral
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for example 2! = 1x2, 5!=1x2x3x4x5

river marsh
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i thought this guy was trolling at first but notation kinda got real

eternal grove
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I'm serious lol

true coral
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so which is confusing

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the summation notation or the factorial notation

eternal grove
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The picture I showed you lol idk

true coral
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yes but which part of the picture

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all of it?

eternal grove
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Yeah

river marsh
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does e represent eulers number?

eternal grove
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Yes

river marsh
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oh wow

true coral
eternal grove
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I never learned any of these series or notations

river marsh
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,w sum 1/n!, n=0 to infinity

thorny flameBOT
true coral
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the first thing to note is summation notation

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basically what it does is run through every number from n = 0 to n = infinity by substituting n into the equation 1/n!

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for example the sum of 1/n would then be 1/1+1/2+1/3+1/4 + ... + 1/infinity

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if the sum was from n = 0 to infinity

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that's basically what's happening

eternal grove
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Yeah, but why are we doing this? It would end up being infinity anyway

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The summation notation makes sense but it doesn't make sense why we are using it here

true coral
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if you look at it it sums to e

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that's why we're doing it

eternal grove
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Oh ok

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Then what is the first part

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Of the picture

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With the weird E

true coral
topaz sinewBOT
#

@eternal grove Has your question been resolved?

topaz sinewBOT
#

@eternal grove Has your question been resolved?

topaz sinewBOT
#

@eternal grove Has your question been resolved?

topaz sinewBOT
#

@eternal grove Has your question been resolved?

topaz sinewBOT
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remote grail
#

how do i find a maximum of a multivar function with boundaries for each var

remote grail
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as i understood i have to take both partial ders and set em to 0

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and solve system of eq

eager compass
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Yes

remote grail
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but i dont think it works

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like

eager compass
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That‘s The First Part

remote grail
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say x^2y-xy^2

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so i get

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x^2-2xy=0
2xy-y^2=0

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x(x-2y)=0
y(2x-y)=0

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so either x=0

eager compass
#

Do you mean $x^{2y} - xy^{2}$ or $x*{2}y - xy^{2}$

thorny flameBOT
#

FluxusX2

remote grail
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huh

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i mean (x^2)y

eager compass
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Yeah I write it wrong with latex but I got it

remote grail
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or y=0

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then x =0

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or x-2y=0
then x=2y
plug into y(2x-y)=0=>y(4y-y)=0 => 3y^2=0 y=0

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so all answers are 0

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for second eq too cuz symmetrical eq

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or what do you call eq where you can change variaables and the eq deosnt change

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yeah, symmertric

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buuttt

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wait

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say x=1 y=1/2
1/2-1/4=1/2

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so 0;0 is NOT the right answer

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why

eager compass
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You need to find values of x and y so that together the equation you have = 0

remote grail
#

eh?

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solve the sys of eq you meant or

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what

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k walk me through it

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or just tell me what's wrong with what i did

eager compass
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You have your function f and first you take the partial derivative f_x and f_y then you search the solutions of f_x = and f_y = 0

Then you should have something like x = some value and y = some value so that P(x, y) are 0 when you use them in both partial derivatives

remote grail
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i understood part one of your process

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whats P(x,y)

eager compass
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So you should have f_x = 2yx - y^2 and f_y = x^2 - 2xy

remote grail
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yeah,

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thats what i said

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youre just telling me things i just sent you

eager compass
remote grail
#

uhh

eager compass
remote grail
#

what

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how can a point equal something

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Then you should have something like x = some value and y = some value so that P(x, y) are 0 when you use them in both partial derivatives

explain

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x is some value, yeah that is 0 , y too

eager compass
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Your function f(x, y) = value. You set the coordinates of a point in your function and get a value out of it

remote grail
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whaaat

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just evaluate the function with the values i found you meant?

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eh what

eager compass
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No no

remote grail
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so?

eager compass
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Forget P(x,y) it just confuses you

remote grail
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that was my point

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why would i need that

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alr, so what do i do after solving sys of eq

eager compass
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You want to search all x, y where f_x = 0 and f_y = 0

eager compass
remote grail
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well YEAH<<< thats what i told you

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solve sys of eq

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yes

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next?

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plug and evaluate func?

eager compass
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Yeah and you found x = 0 and y = 0

remote grail
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...YEAhh

eager compass
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Now you want to build the H-Matrix

remote grail
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WHAT

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matrix??

eager compass
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The Hesse matrix

remote grail
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eh never heard of it

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and i bet its not necc for finding the extrema of a func

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its just as you said formal notation to make it confusing

eager compass
#

You want to do that to find out if it’s an extrema or a minima

remote grail
#

extrema are maxima and minima....

eager compass
#

Maxima I meant

remote grail
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SO just plug in?

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alr, retelling you whole process until we reach disagreement

eager compass
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If you plug it in you get 0 what do you wanna find out with that?

remote grail
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start with f(x,y)=(x^2)y-x(y^2)

eager compass
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0, 0 is an extreme yes but you don’t know if it is a minima or maxima

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Or do you really just need to say it’s an extrema?

remote grail
#

ok, now:
f_x=2xy-y^2
f_y=x^2-2xy

remote grail
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ok, so

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let f_x=f_y=0

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2xy-y^2=0
x^2-2xy=0

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correct?

eager compass
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Yes

remote grail
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ok.

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y(2x-y)=0
x(x-2y)=0

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so from #1 y=0 then x=0 from #2

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from #2 x=0 then y=0 from #1

#

from #1 2x-y=0 then 2x=y then x(x-4x)=0 | x^2(-3)=0 | x^2=0 | x=0 and y=0

#

from #2 x-2y=0 then x=2y then y(2x-y)=0 | y(4y-y)=0 | y^2(3)=0 | y^2=0 | y=0 and x=0

eager compass
#

Yes

#

So 0, 0 is an extrema

remote grail
#

so (0;0) is the only

#

yeah

#

plug and get f(0, 0)=0

#

right?

eager compass
#

Yes

remote grail
#

but say f(1, 0.5)=1x0.5-1x0.25=0.25

#

so this is more than f(0, 0)

#

so f(0, 0) is NOT the maximum

eager compass
#

Yes

remote grail
#

uhh?

#

so why did i not get the maximum??

eager compass
#

You told me extrema can be maximum or minimum

remote grail
#

yeah???

#

so youre telling me (0,0) is minimum?

#

right?

fallow heart
#

It could also be a saddle

eager compass
remote grail
#

eh

#

what

fallow heart
remote grail
#

so why did the process not work

fallow heart
remote grail
#

i heard its the right process

eager compass
remote grail
remote grail
#

what

fallow heart
#

!original

topaz sinewBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

remote grail
#

f(x,y ) =x^2y-xy^2 how to find maximum

#

idk

#

i mean, im more curious why the process didnt work

#

not about solving the problem

#

and what to do if it doesnt work

#

what is the process then if this is not the correct one

eager compass
#

You did everything right. You found a counter example to show that it is not a maxima nor a minima so you could either assume it is a point of inflection or there is no extrema for this function

remote grail
#

ehh

#

huh

#

so this is not the way to finding the extrema?

#

with 1 var func it is

eager compass
# remote grail what is the process then if this is not the correct one

Usually you do everything you did for now. You did the partial derivatives then solved the equations. Then what you usually wanna do is set the hessian matrix implement your values in the matrix you found where you think that there are the extremes and then you want to take the determinant of the matrix and depending of the result you will know if it is a maxima minima or point of inflection

remote grail
#

what is that mateix

#

what

remote grail
#

so i got an answer here

#

so it must be an extrema

#

but it is not

#

so this is not the correct process for doing it

#

because its not consistent

#

its not guaranteed to work

eager compass
remote grail
#

what is then?

#

ok, so let me get this clear: is what i did the correct process?

#

for finding the extrema of a 2 var func?

#

huuuuuuuuh

eager compass
remote grail
#

ehh

eager compass
#

I’m kind of busy rn so I can’t help you further rn. But if you need more help to understand write me a pm so I can answer it later

remote grail
#

so theres some algorithm that converts the sol i got into the extrema?

#

what.

eager compass
remote grail
#

but it HAS to be an extrema

#

if its not then why even do this entire thing

eager compass
#

It can also be a point of inflection

remote grail
#

ehh

#

isnt there an algorithm that finds only extrema?

#

because as i undersrtood there isnt

#

alr

eager compass
#

You need to do it with the hessian matrix

remote grail
#

so is there or not?

topaz sinewBOT
#

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nimble rover
#

I have homework due in 4 hours, and its 15 questions, can someone help me with this?

nimble rover
#

@lusty marsh yes the first one

#

Its a new topic section and im very confused

clear lodge
#

you should have been given the formulas for the trig functions of the double angle

lusty marsh
#

if theta lies in q4, only cos and sec will be positive

nimble rover
#

thank you

clear lodge
#

you're explicitly asked to use the identities to compute your stuff

#

i guess they also assume you know the values of the trig functions for 30°, 45° and 60°

lusty marsh
nimble rover
#

I think its sin2theta/costheta

#

wait

#

im just still confused

lusty marsh
#

first find sin theta from the given info

lusty marsh
nimble rover
#

:/

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wanton tide
#

How do I integrate

$\int e^x \sin(3x) \sin(x) dx $
``` I've changed it to `cos(2x) - cos(4x)` but I don't know what to do next...
thorny flameBOT
#

xCirno

lusty marsh
#

maybe try putting $sin(3x)$ as $3sin(x)-4sin^3(x)$

thorny flameBOT
#

swerriee

dense lily
#

How about solving -½(cosP - cosQ)=sin3xsinx

wanton tide
wanton tide
lusty marsh
#

it's too long

wanton tide
#

oh

dense lily
#

I'm going to try it

spare monolith
#

If you do sin(2x+x), you're left solving $\int e^x sin^3x$, if that is any help.

thorny flameBOT
wanton tide
#

is $\int e^x sin^3x$ solvable though?

thorny flameBOT
#

xCirno

wanton tide
#

I think the answer shouldn't be that long

lusty marsh
#

,w integral of e^x.sin(3x).sin(x)

dense lily
wanton tide
#

My teacher told this, for the integration in the form of $\int(e^{ax}{f(x) + f'(x)}dx)$. Integrate only $\int(e^{ax}f(x) dx)$ with $u = f(x)$ and $dv = e^{ax} dx$ for integration by parts.

thorny flameBOT
#

xCirno

wanton tide
spare monolith
spare monolith
#

It is, but it’s long.

dense lily
#

,w int e^x sin3xsinx

thorny flameBOT
dense lily
#

,w int e^xcos2x

thorny flameBOT
dense lily
#

,w -int e^xcos4x

thorny flameBOT
dense lily
wanton tide
#

I think so because the sine values are different

#

right?

dense lily
#

Not really, that method actually works.

wanton tide
#

oh

#

it just comes back to be the original integral

topaz sinewBOT
#

@wanton tide Has your question been resolved?

topaz sinewBOT
#

@wanton tide Has your question been resolved?

topaz sinewBOT
#

@wanton tide Has your question been resolved?

topaz sinewBOT
#

@wanton tide Has your question been resolved?

stone schooner
# wanton tide How do I integrate ```tex $\int e^x \sin(3x) \sin(x) dx $ ``` I've changed it t...

check this out
and let me know if you dont get anything
https://socratic.org/questions/how-do-you-integrate-e-x-cos-x

topaz sinewBOT
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next rain
#

Always distribute before multiplying da brackets togetha?

agile harness
#

what

next rain
agile harness
#

order doesn’t matter

#

do it however you’d like

next rain
#

ty

#

.solved

topaz sinewBOT
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desert goblet
#

[
\qty|2x - 6| < 0
]

topaz sinewBOT
thorny flameBOT
desert goblet
#

How does this explanation look to show that it is No solution?

torpid matrix
#

not rigorous but correct

desert goblet
torpid matrix
#

ie i think it should be fine for test corrections since it shows you know why

desert goblet
#

thank you

desert goblet
#

curious

torpid matrix
#

"abs cant be negative" is not a well defined statement, you really mean something more like "the range of abs(f(x)) is R^+ U 0", so therefore...

#

idk im bad at analysis but your work is an explanation, not a proof

desert goblet
#

alright thank you

#

.close

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topaz sinewBOT
#

@wraith swan Has your question been resolved?

shadow salmon
#

Hm, i might have an idea.

So I’ll basically call a as the special element u got e from.

We have that for every b there exists y such that b = y*a.
Now notice that
y*a = y*(a*e) = (y*a)*e. (1)

But b = y*a for all b, so we have by (1) that

b = b*e for all b.

#

Ugh I guess I’ll have to live with the bad formatting

#

Hope it’s readable

#

Ah I see

#

Ur welcome!

topaz sinewBOT
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static venture
topaz sinewBOT
static venture
#

Can someone help me find what a and b are, these are simultaneous equations

placid drum
#

it might help to factor out the b term

#

in each equation

#

having it as a constant * b

static venture
#

Hmm ok

placid drum
#

u can also do elimination after multiplying the top equation by 2

static venture
#

I had this here

static venture
placid drum
#

ye multiply the top by 2

#

and then do elimination

static venture
#

Oh and then find b

#

By dividing the stuff next to b?

#

Yup I get the answer

#

Thank u so much 😄

#

.close

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unique river
topaz sinewBOT
unique river
#

can anyone solve this?

pearl peak
#

geometric series formula for the first bit, divide the top and bottom of the the first limit by x^3, and use lhopitals for the last bit

topaz sinewBOT
#

@unique river Has your question been resolved?

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hard pendant
#

You are given the following identity cscA = sec(0.95). Given that angle a lies in the second quadrant, find the value of a that makes this true.

is 2.52 rad the correct answer in this scenario

timid star
#

Yes

hard pendant
#

ok

#

.close

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oak cairn
topaz sinewBOT
oak cairn
#

Ok so i gotta solvethis

#

and this is what i finished with

#

so denominator is -4/3 and -1

#

and numurator is 0 and -2

#

bc -x(x+2)

#

but im rlly confused bc the teacher did this

#

but cant i still get the same answer without doing that???

#

except the problem is that im not getting the same answer

#

oops

#

nvm

#

bye guys

#

im tired

#

i just realized my mistake

#

AHAH

agile harness
#

all good

oak cairn
#

no

#

NO

#

I STILL DONT

#

WAIT

#

NO

#

nope stil dont get it

agile harness
#

welp

#

what happens when you divide by a negative

#

for inequalities

oak cairn
#

oh u have to flip the sign...

agile harness
#

indeed

glass maple
#

also (ditto)

oak cairn
#

ya but what if im just factoring it out tho

glass maple
#

must be an old teacher

agile harness
#

so they clearly divided

oak cairn
#

would i get the same answer

#

just -x^2 - 2x > 0

agile harness
#

no idea why you’re writing ditto but yea

oak cairn
#

im not writting that

#

its the teachers work

#

i just dont have my phone on me to send a pic of my work

#

wait so for inequalities i cant just factor out a -1

#

and if i do, i have to flip the sign?

agile harness
#

if you divide by a negative you must flip the sign yes

oak cairn
#

mhmi see ok one sec im gonna recheck my work

#

oh

#

wow

#

ok i got it

#

yep

#

interesting

#

ok thanks!

#

.close

topaz sinewBOT
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lilac rover
#

Can anyone help?

topaz sinewBOT
snow brook
#

post le problem

wooden osprey
#

!da2a

topaz sinewBOT
#

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

lilac rover
#

K

fading owl
lilac rover
#

I’m sorry I have bad handwriting

fading owl
#

Do you know how to factorise quadratic equation?

lilac rover
#

Nope I’m in 6th grade and this is a advanced math practice sheet that I don’t understand

fading owl
#

Oh

lilac rover
#

I have to go in 10 minutes too so I think I’m just gonna ask someone tomorow

fading owl
#

Note that x^2-5x+6=(x-2)(x-3)

#

Can you do the same for the other expressions?

lilac rover
#

I’ll try

fading owl
#

🙂

lilac rover
#

Ok I gtg now

fading owl
#

Bye

lilac rover
#

By

snow brook
#

cya

topaz sinewBOT
#

@lilac rover Has your question been resolved?

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graceful leaf
topaz sinewBOT
graceful leaf
#

this is something that should be memorized?

#

a bit tedious ):

little pine
#

if you can convert the values on the left to a fraction, the value on the right is just it's denominator

graceful leaf
#

wait wot

#

thts hwo they did it

#

OH

#

I get what u just said

#

Ok ok

#

wait so 0.66 as a fraction

#

66/100

#

33/50

#

:/

hollow drum
#

0.66 is just about 2/3

graceful leaf
#

oh

#

so not the simplest form thing im doing

hollow drum
#

And if you're allowed a calculator, you don't need to memorize anything

graceful leaf
#

oh

#

iam

hollow drum
#

You want to multiply until you don't have a decimal, so with 2.66, start with 2. So 2.66 times 2 = 5.32, you still have a terrible decimal, so next try 3, so 2.66 * 3 = 7.98 and that's really close to 8 so there you go

#

You multiplied by 3 hence you do C_1 and multiply that 1 by 3

graceful leaf
#

ohhhh

#

Got it

#

tHank so much

#

so mcuh better than sitting here memorizing this 😭

#

.close

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uneven grotto
#

Lets say I can multiply two integers A and B, both in the range [1, 255]. What is the smallest composite (non-prime) number that cannot be obtained by multiplying A and B

uneven grotto
#

My thinking is that it is 2 * 257 or 514 since 257 is the smallest prime number above 255. Would this be correct?

little pine
#

why not 256?

sweet shard
#

,calc 2 * 128

thorny flameBOT
#

Result:

256
sweet shard
little pine
#

lemme try to brute force this though

topaz sinewBOT
#

@uneven grotto Has your question been resolved?

little pine
#

yup, 514

#

and 0, not sure if you'd count that

uneven grotto
#

gotcha, thanks

topaz sinewBOT
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low monolith
#

how to find y using 3x - y =2 with x= 2

topaz sinewBOT
agile harness
#

substitute x = 2

golden blade
#

algebra

low monolith
#

this is linear equation

golden blade
#

mb

hard ravine
#

yes but if you know one value

#

you can find the other

#

in any linear equation

low monolith
#

3(2) - y = 2

hard ravine
#

so expand and solve

low monolith
#

do i have to transpose

#

-y = 2 - 6

topaz sinewBOT
#

@low monolith Has your question been resolved?

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toxic sphinx
topaz sinewBOT
toxic sphinx
#

can someone please solve this question, i want to know if i got it right

pearl fog
#

what did you get?

sweet shard
#

Just show your work

toxic sphinx
pearl fog
toxic sphinx
#

i made it up

#

i just wanted to test my solving skills

#

bc

pearl fog
#

😭

toxic sphinx
#

im not very good at this

#

so

#

you could say

#

i have a

#

skill issue

#

badum tshhhh

fallow igloo
sweet shard
topaz sinewBOT
#

@toxic sphinx Has your question been resolved?

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viral fulcrum
#

is 6-x = 6+6x in mod7?

topaz sinewBOT
#

Please don't occupy multiple help channels.

warped thistle
topaz sinewBOT
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neon iron
neon iron
#

I’ve done OSSU for computer science and I’ve found that to be pretty nice

#

But what I’ve heard is that it’s not even close to an actual CS degree

#

What about this one?

sweet shard
#

...

#

Help channels are for math questions, not curriculum

neon iron
#

My bad

#

.close

topaz sinewBOT
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ivory sorrel
topaz sinewBOT
toxic sphinx
#

oh sorry a dense set

ivory sorrel
#

Let $T(x,y,z) = (2x-4y+3z,6x)$.
\
$T(x_1,y_1,z_1)+T(x_2,y_2,z_2)= (2(x_1+x_2)-4(y_1+y_2)+3(z_1+z_2),6(x_1+x_2) = T(x_1+x_2,y_1+y_2,z_1+z_2)$

thorny flameBOT
#

A dense set

alpine mist
#

For the reverse direction you can choose certain vectors to show that properties of linear transformations only hold if b and c are 0.

ivory sorrel
#

If T(x,y,z) = (2x-4y+3z+b,6x+cxyz) were linear, then $T(0)=0_v$. Clearly $T(0,0,0) \neq (0,0)$ if $b \neq 0$
\
At the same time linearity would mean that $T(x_1+x_2,y_1+y_2,z_1+z_2) = T(x_1,y_1,z_1)+T(x_2,y_2,z_2)$ We thus hypothesize that $(2x_1-4y_1+3z_1,6x_1+cx_1y_1z_1)=(2(x_1+x_2)-4(y_1+y_2)+3(z_1+z_2),6(x_1+x_2)+c(x_1+x_2)(y_1+y_2)(z_1+z_2)$.
\

thorny flameBOT
#

A dense set

ivory sorrel
#

They clearly aren't the same for all vectors unless c=0

alpine mist
#

you should be a little more careful, that works for some vectors. So you'd need a 'for all vectors' somewhere in there.

#

otherwise, that seems fine.

#

you can also construct a counter example for when c != 0.

ivory sorrel
#

I could, but I'm not a huge fan of counter-examples

#

.close

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#
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ivory sorrel
#

Thanks!

topaz sinewBOT
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solid zephyr
topaz sinewBOT
solid zephyr
#

how do i use limit comparison test

#

i compared it to 1/2^n

#

but idk how to take the limit with a factorial

clear lodge
#

you'd show that n!>2^n

mortal steeple
#

1! < 2^1

#

🤓☝️

clear lodge
#

same with 2 and 3, but he's talking limit

solid zephyr
#

wait what

#

oh im stupid

#

ok ty

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civic cairn
topaz sinewBOT
civic cairn
#

I do not understand how to do question 7 but i know how to do question above that

#

here is the answer key

tardy wave
#

approximus prime

civic cairn
#

chat pls help

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@civic cairn Has your question been resolved?

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crude thunder
#

when i have projection onto line, would the term pp^t/p^tp cancel to 1 ? in my textbook they just switch it as p^tx/p^tp but i dont see why we dont just cancel it out

crude thunder
#

i dont see why dont we just do y=b but this seems wrong

tough nest
#

$a a^T \neq a^T a$

thorny flameBOT
#

Katharine

crude thunder
#

can you please show me what would the upper term be equal to in case ov a = 2 1 -3?

#

im not really sure how to calculate it

tough nest
#

what kind of vector is a

#

vertical?

#

let me say it this way

#

let a be a 1xn vector

#

then $a a^T$ is a scalar

thorny flameBOT
#

Katharine

smoky sparrow
# crude thunder

if $a$ has dimensions $m \times n$, then $(m \times n) (n \times m) \to (m \times m)$

but $(n \times m)(m \times n) = (n \times n)$

the dimensions are totally different!

tough nest
#

and $a^T a$ would be a nxn matrix

thorny flameBOT
#

south's secret twin brother

#

Katharine

tough nest
#

those things flip if a is a nx1 vector

smoky sparrow
#

a should be a vector in this situation so n = 1

#

so you get the matrix $a a^t$ multiplied by the column vector $b$

what happens is that you get another column vector as $y$, with the same dimensions as $b$

thorny flameBOT
#

south's secret twin brother

smoky sparrow
#

specifically, a a^t will be m by m, and b will be m by 1

#

so their product is an m by 1 vector

topaz sinewBOT
#

@crude thunder Has your question been resolved?

topaz sinewBOT
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terse bronze
topaz sinewBOT
terse bronze
#

im unsure about my ans to this one

#

I graphed the absolute function and found the max value within the range to be 4

#

so would it just be 4m/s

smoky sparrow
#

,w d/dt (4t e^(-t^2) - 1) = 0

smoky sparrow
#

t = 1/sqrt(2) is a critical point and it's also a local maximum
(as $t \to \infty, v(t) \to 0$ so it can't be a local minimum)

thorny flameBOT
#

south's secret twin brother

smoky sparrow
#

(given that v(t) is positive there)

topaz sinewBOT
#

@terse bronze Has your question been resolved?

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terse bronze
#

@smoky sparrow

topaz sinewBOT
terse bronze
#

but we're just trying to find when the absolute value of the function is greatest

#

not necessarily the local max or local min

#

so when we graph the abs function find where that value is greatest for speed?

#

what is wrong with my approach?

smoky sparrow
#

ah good catch

terse bronze
#

so what would be the correct ans for solving this?

#

is my method wrong or?

smoky sparrow
#

I think you just graphed it wrong

#

but yeah we do have to check the critical points and the endpoints
then take the absolute value

#

in this case the maximum speed is |v(0)| = |-1| = 1

terse bronze
#

oh I see

#

tysm

#

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chilly walrus
topaz sinewBOT
chilly walrus
#

do we really need MVT for this? doesn't this just follow from the fact that f is strictly monotone?

#

BWOC, assume $\exists x_1, x_2 \in I, x_1 \neq x_2$ s.t. $f(x_1) = f(x_2) = 0$. But because $f$ is strictly monotone, it is injective on $I$ so $f(x_1) = f(x_2) \implies x_1 = x_2$, a contradiction

thorny flameBOT
#

artemetra

chilly walrus
#

like i get how to prove it using MVT but wouldn't the above approach also work just as well?

obsidian solstice
chilly walrus
#

.close

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little iron
#

is this a real parabola? I have never seen a parabola like this
is chat GPT trolling or am I dumb?

little iron
#

<@&286206848099549185> pls I need help

#

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gaunt aspen
#

Chatgpt sucks at making stuff like that

#

Use desmos

#

@little iron

little iron
little iron
neon iron
#

Chat gpt on some weird stuff

little iron
neon iron
#

😭

#

U got this

little iron
#

ty

topaz sinewBOT
#
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echo granite
#

i dont know how to solve questions in this form

echo granite
#

!status

topaz sinewBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
echo granite
frosty iron
#

try to do something with the third and second equation

echo granite
#

okk but should i tryna convert it to row echalon form or

frosty iron
#

have no idea what that is lol

echo granite
#

😭

frosty iron
#

sorry

echo granite
#

its alr

frosty iron
#

isnt it just linear equations or am i misunderstanding

echo granite
#

yes

crisp bloom
#

thats where the difficulty is

echo granite
#

exactly

frosty iron
#

oops mb

candid salmon
#

If u are relating it to row echelon form

#

You know theres 3 types

#

Turn the equations into a matrix and try figure out what c’s you need to fit each of the types of solns

#

If u arent using row echelon form then u can do it a different way but im assuming u learn row echelon form and need to apply it here

echo granite
#

thank u for advice im working on that right now thanks 🙂

topaz sinewBOT
#

@echo granite Has your question been resolved?

candid salmon
#

ok i just got home and looked and it is quite hard

#

i thought u could do it that way but its unnecessarily hard compared to using the det

#

for a system to have a unique solution the det of A must be non zero

#

so instead of doing ref and working stuff out just work out the det and youll get an equation for C right

#

you need a c where det A is NOT 0

#

now you can take the c's that do make det A = 0 and sub them in to see which ones fit each type of equation @echo granite

echo granite
#

oh ok i see

candid salmon
#

it should simplify it to a 3 min question

echo granite
# candid salmon

i tried to use diffirent c values to find out 3 types of row echelon form but it took my half hour so far and i dont even finished it yet

#

the det is better

#

lemme try