#help-26
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Tis why i need a textbook
never heard of it
did you look at your dms
me š
uhhh no
š¤
uhh
yea
am i gonan be arrested
im scared
oh here is a funny lil example
of why i wish i could personalize math courses
nvm
My teacher just gives
weird definitions for things that i think might fuck people up in the future
interesting
like
pls tell me
what is e?
I would define it as
The number which
has a derivative of itself
but she was telling me it means something about the function being continuous
like how is that a definition
false
e*x
E^X
Lemme correct it
number which when rasied to the x power has a derivative of itself
also
sheās probably talking about continuous interest
im pretty sure there is something qwith like
compound interest
compounded continuously
$e = \lim_{x \to \infty} \left(1+\frac{1}{x}\right)^x$
knief
but isnt there something that defines it with eulers thing
and one that defines it as like
the value that makes some constant = to 1
what
a continued fraction?
iām not sure what youāre getting at
$e^(\pi i)=-1$
thatās not the definition of e
ā cj Ī£
thatās eulers identity
cant you use it to derive one tho?
i mean sure but this comes from having already defined e, pi, and i
wouldnt you only have to define 2 of them?
then solve 4 e
ig it would be backwards
do you know what im talking abt here tho
@ornate trellis Has your question been resolved?
Ok
so itās the the thing with exponential
i watched one of the 3b1b vids a while ago
thatās whatās iām thinking of
and i think he is essentially just describing the concept via constants
2^x= 2^x(c)
and i think what heās saying is what can we swap 2 with to make that c=1
and itās e
maybe you got a bit confused with something
that c is gonna be 1 no matter what it is
wether it's two or e
maybe he was talking about derivatives?
yeah
I thought i mentioned that it has something to do with derivatives of an exponential
so i think itās prettt much the same definition i was giving with a more technical explanation of why
iirc
i would guess he was talking about a the derivative of $a^{cx}=ca^{x}$, in this case that would only happen if a=e
UbuRoi
so.. is your question is what is the definition of e is? i scrolled back a little but i don't get exactly what you're asking :p
mkay so with the given equation he seems to suggest that as dt->0, the value of it approaches a weird constant. I think the point is heās trying to find what number would make that constant 1
oh it started with stuff about the unit circle now itās kinda evolved into what the definition of e is
@agile harness
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is the graph concave up, concave down, convex up, or convex down at f(1) and f(3)? I think its concave up and decreasing at f(1) and concave down and increasing at f(3). If this is correct, would that mean f''(1) < f''(3)?
wait what
but its decreasing
as x increases y is decreasing
but its still concave up-
does that mean its concave down then?
wait does decreasing / increasing matter?
you said its concave up at f(1), which means f " (1) is +
and its concave down at f(3), which means f " (3) is -
how can you say that something - is > something +
š
but is that actually correct
yes, thats what i told you
what you said is correct
except for the inequality
If this is correct, would that mean f''(1) < f''(3)?
no, its f " (1) > f " (3)
cuz as you said, concave up at x=1, meaning f " (1) +
and concave down at x=3, meaning f " (3) -
ok so concave up is when it curves inward but goes up? concave down is when it curves inward and goes down.. etc
i use another way
concave up when the slope is increasing
concave down when the slope is decreasing
its a better method
then how do I differentiate between concave and convex
i dont do math, i do engineering, i did not study this deeply
i suggest you wait for somebody else
oh ok
but again, what you said was correct
except for the inequality, you literally said something negative was greater than something positive lol
yeah but im just confused because idk what the graph actually is at f(1) and f(3)
at f(1) it seems to be decreasing
and increasing at f(3)
but then again it can be either convex or concave-
@ornate phoenix Has your question been resolved?
The graph is concave down at f(1) and concave up at f(3), meaning f''(1) < f''(3)
is that correct?
@ornate phoenix Has your question been resolved?
how do I close the channel
@ornate phoenix Has your question been resolved?
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If i remember correctly, im supposed to kind of remove lg out of both of the equations
but i think i may have fucked up somewhere and im not too sure if i did the logarithms correctly
$\log_{0.1}(k) = lg(k)/lg(0.1) = lg(k)/lg(10^{-1}) = lg(k)/(-1) = -lg(k)$
kaue
change of base formula
if you sub log base 0.1 with -lg(k) in the beginning it should be easier
yes i think i got that one correctly
oke lemme try ah
oh you did that sorry didn't see it
the logs are correct, but you need to solve for a
you wrote that
well yea then i wasn't sure how to proceed because i need to answer a interms of k
.
after solving the logs you got 4a = ak + k²
subtract ak
4a - ak = k²
factor a
a(4 - k) = k²
divide by 4 - k
a = k²/(4 - k)
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how can i show exactly two pre-image for every image?
more specifically, I was trying to prove this by contreadiction
specifically I said: suppose by contradiction that there is at least 3 pre-images for an image
the probelm is, can i just show that 3 unique pre-images are just not possible for an image?
i dont think i can, because at least 3 pre-images is an OR statement. Which is pre-images = 3 or # pre-omages > 3. So even if pre-images = 3 is false, we need to show that # pre-images > 3 is false as well. \
@silent frigate Has your question been resolved?
Well, if you canāt have 3, you canāt have more than 3, as your argument could be repeated by taking just 3 of the however many
hmmm. but dont we need to show both parts of the OR statement is false when doing a proof by contradiction?
or shoudl it not be an OR statement?
Well, the argument youāre likely to end up making can be used by taking just three elements: probably something like āsay you have a1, a2, a3 as three distinct inputs that get sent toā¦ā
hmmm
Anyways, if you had a^2 in the image, you know that a and -a get mapped to a^2: considering that p is a prime and at least 3, would a and -a be the same?
no
why not?
isnt a in a differnet residue class then -a
In this case it is, but be careful of why 
e.g. if you chose p as 2, it wouldnāt be true
Similarly if p werenāt prime but was even(!)
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Am I doing this right so far?
Problem 17
Not sure if my setup is correct
If it is how would I go from here
Kinda confused how to continue
Oh I got it right lol just gotta move that out of the brackets
:)
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.reopen
ā
How hard are Definite Integrals to learn?
Iām just curious
Cause I have to learn them by myself I canāt be in class tomorrow
Depends on ur interest š
you mostly don't actually use the riemann sum definition of the limit. vast majority of calculus class uses FTC to evaluate definite integrals
If you know how to evaluate an indefinite integral then definite integrals are basically the same thing
you just have to do a few more computations
If you rolling eyes at me again Iām gonna
Thanks
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serial killerš
ā
Am I doing 18 right
I don't count because I am irrelavant
Tf?
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@karmic dove Has your question been resolved?
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Hello I am currently doing this exercice
I need help with calculating the lax of Xmin
please don't insult me if im doing something stupid, I dropped out of my master for 1 year due to personal reasons and I just got back and now i feel like im clueless 95% of the time
this is what I tried doing so far but something feels off
@neon iron Has your question been resolved?
Here
Yes on the first line right
law
yes :c
non mais je fais mes Ʃtudes en france yes
en angalis
merci :c
well idk yet ! i need to calculate the mean and variance of Xmin and then the quadratic risk
idk how to do that yet, I will try and see
je peux te mp ?
oui pdp
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Hello I have a question about an exercise the them is Borel Cantelli lemma
How could I show this result ?
The chapter corresponding is Borel Cantelli lemma
I wish to understand its applications by the end of the day lol
the idea is to show that P(limsup{|Xn/cn| > epsilon}) = 0 for every epsilon > 0
So I need to construct such a sequence c_n ?
yes
So if I write A={limsup [X_n/c_n]>eps}
Well i'll think about why this concludes
Is There a link between limsup of sequences and of events ?
@dawn falcon Has your question been resolved?
@dawn falcon Has your question been resolved?
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how can i find the 116 condition of existence
Expression under the square root must be $\geq 0$ and denominators must be not equal to zero.
LooseEthics
First denominator tells us nothing, the second that $x \neq +-4$.
LooseEthics
Factor the quadratic, it must be greater than or equal to zero, so $x \in <-4, 4>$
LooseEthics
In the second root the denominator is negative in the interval, so -3x must also be negative, thus $x > 0$.
LooseEthics
Put all that together and you get $x \in <0, 4)$
LooseEthics
thanks
just a question
in the first one doesn't |x|+4 make us simplify the top one since we factorize it in (4-x)(4+x)
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How do I evaluate this limit?
I believe I have to utilize a method involving e and the natural log to manipulate the exponent, but I think Iāve made an error somewhere.
you can make it in the form as (1+1/u)^u
by splitting x/7 into two fractions multiplied together in order to match the reciprocal inside
I donāt follow you here
you know (1+1/u)^u as u approaches infinity = e right?
I was under the impression the method was the same / similar to another problem I had that I was able to solve
it doesnāt ring a bell at the moment, no
uh
Hereās the one I solved if this helps at all
how can you do these questions without that knowledge?
you learnt lāh before definition of e???
oh, the x/7 is outside the ln
not inide
inside
I guess so? Or maybe it was taught to me at one point and Iāve forgotten it
Does this method make sense?
hey
š
Got myself stuck again 
actually, would it make more sense to pull the 1/7 out of the limit completely?
im not sure how that would work out with the e involved but thats what i just noticed
yeah its more convenient that way
ill try it out
I can get it to 0/0 for LāH to apply but i think now im struggling to get the derivative right on the ln
would it just be 1/[1+(4/x)]? i think i just get 1/1/0 that way
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we are trying to prove this using the definition of limits, but we cant find a way to get something like n < M... , how should we approach this?
If you fix M, maybe first look at the equation 1/n - n = M
Can you solve that for n? Once you do, can you see when 1/n - n < M?
what's the definition you were given?
we are working on it
n>sqrt(m+1) and n> -1/m
Hmm not sure this is great if M is very negative
M>0
Yeah true
I think sqrt may even be a bit too fancy here
If you understand why the expression is going towards -infinity, I think you can find a rather simply choice for n (in terms of M)
we understand how to algebrically calculate what the limit is, but we aren't able to prove it with the definition, and that is what the excrsize asks us to do.
we get weird results for 1/n -n < -M and we don't know how to move forward
Do you understand in principle how to prove the definition holds for a given expression?
I can give you a hint for what n_0 can be
we were just substituting our succesion to an in the definition
yeah that would probably help us out
Take n_0 = M+1
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daniel_zein
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hi
If
I have a triangle
Two angles are given
And the side between them is given too
HOW To find its area?
Sine rule to find another side then and Area=½absintheta
Or you can use Heron's formula.
mhm
this is the best
thanks
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Hello, (the question states that these three points are collinear and itās asking to find a and b, the solvingās the part thatās lined with brown, ) someone please help me with this Iām stuck on the last part idk what to do after 8b+4a-60=0.
And if Iāve done anything wrong pls state so , thank you.
((@ me when someone answers))
Good morning [?]
Oh so it is morning for you
Lucky guess
Anyways we've been given that (a, 3) (5, -5) and (b, -9) are collinear
No itās not
You got one of the conditions
Now do you know* what will be the area of the triangle formed by these three points
but collinear means points on one line
yeah
so area of triangle would be zero
ye
do you know the formula for the area of triangle formed by three points?
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What value of k makes the two functions x/k and x! intercept at exactly one point?
On Desmos, I got approximately 1.1291738854501417
If there an exact answer though? or is it just impossible?
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why does this graph not go in the third quadrant?
for example, if x = -2, then y = -2, innit?
,calc (-2)^4.9
Result:
-28.395747408622 + 9.2263376223158i
but it should show it, even tho its complex, at point (-2, -2) it is true that (-2)^4.9 = (-2)^4.9
i guess your desmos is prob not configured to allow complex numbers
Well, you "shouldn't" be dealing with complex numbers really
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yes but i wouldnt
just expand
you wanna avoid absolute value equations
taking the square root would lead to
|2x-3| = 4|x|
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I rewrote the proof in
(ignore the underline)
Does this look fine?
(@gleaming thunder if you can read mathematical German haha - I know you started the LA lecture notes so most likely yes)
I find the phrasing in the original pretty bad
My lemma 0.7 is this
Yeah it looks fine
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why is the first direct sum you write true?
.reopen
ā
By lemma 0.7
(I posted that below the picture)
So yeah, it should look fine, right?
yeah
Thanks
And the reason it was proven that Im(A - lambda id)^k is invariant under A is so that we can even define this restriction of A
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How would i prove that composition of functions on the set of bijective functions from some set to itself is not commutative?
i understand to show that f o g isn't equal to g o f but how would i show that in notation if i cant just use some specific examples (b/c the set is arbitrary)
maybe i misinterpreted the question then
it says Let A be a set. Prove that (Bij(A), o), with Bij(A) being the set of bijective functions f: A -> A and o being composition of functions, is a group that is not commutative.
rip question
you're not misinterpreting the question, the question itself is fucked
you can show it's a group for any set tho yea
but the non-commutative part is not for all sets
just try and find some A such that it's not commutative
ahh the professor says that presenting one counterexample is sufficient
question wasn't clear that you dont have to prove it for all sets A
well the guy can't write
ĀÆ_(ć)_/ĀÆ
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Would I be able to get calc 1 help in about an hour? (De moivre's, implici diff, area v volume rate of change, etc...)?
for what particular reason
Studying
why in an hour
Cos im waiting on help now and deciding if I should go home and have help later
just make a ticket then instead of asking for help an hour later
if someone is aroudnto help then they might answer
Yeah I'm asking bc I hope if someone's here they see it and I'd know they fcan help
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I need to isolate those two µ
Need to make a excel sheet to solve µ with those other variables
Really forgot how to make this, brah šæ
solving that isnt so difficult
you have T=F[A+Bu+Cu]
Yeah but I need all the right side variables to be in the left side
@open kindle Has your question been resolved?
Yep, so you can distribute F to everything, then get all the u terms on one side and everything else on the other
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Does anyone have any idea how I could start this question?
As far as I am aware I know, I just need to find the derivative of this function, but I'm stuck on what to do next
@deft spade Has your question been resolved?
<@&286206848099549185>
To add to what I got, this is the equation of the tangent line
I'm still kind of stuck on what to do next from here, I'm not sure how to make this fit into the formula to find the area of the triangle
<@&286206848099549185>
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Bro what the hell I have to solve this with u sub
So far I have u = sin(1.5x) and du = 1.5cos(1.5x)dx and i guess the identity where cos^2(1.5x) = 1-u^2
Which is what the hint gave me but I am so lost
i think u is supposed to be 1.5x
nah u can do it with u = sin(1.5x)
then cos(1.5x)dx = du/1.5
so we know that u = sin(1.5x)
so then what does u^2 =?
lowkey had an epiphany
someone told me to separate cos into cos(1.5x)cos^2(1.5x) and so u^2 = sin^2(1.5x)
and it worked so far
This problem is still aids though
exactly thats what i was gonna tell u to do next lol
@half breach Has your question been resolved?
Wait can someone explain this garbage
My professor did it yesterday in class and this was some sorcery
I don't understand making u = something not even in the integral
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Hello, I can help you. Give me a moment to review it
it's right ??
yeah
thats why it took me a sec
i couldnt see it do i did full working
are u doing the limit as h goes to 0?
š oh-
not yet, at least. He wanted us to just simplify the difference quotient for this question
yes
:D
but that result is very important (its next in your course)
its the exact instantaneous rate of change
instantaneous velocity in this instance
we're doing a very weird mix of derivatives and then not derivatives
have you done limit h goes to zero
I'm not good at them, but I know them sorta
for derivatives?
I believe so š¤
do you know what the derivative of 40+40t-16t^2 is
it's kinda all blurring together at this point, but I think he's had us do it once or twice
-32t+40?
coincidence?
... OH
xD
the whole purpose of these difference quotients
is to do an instantaneous change
you are doing "gradient" or change in y over change in x
but doing it after a small gap of "h"
that explains so much š
or change in variables, whatever they are. gradient is an easy go to because you can see it, but it works for any function
haha
its always hard to get students to "see" this stuff
that's fair haha
š«”
do the velocity between t = 2 and t = 2.01
on a calculator
similar to what is in 7.
oh no
but with my numbers: f(2.01) and f(2)
I've been scared of 7
instead of t+h and t
so f(2.01) = 40 + 40(2.01) - 16(2.01)^2
and f(2) is the same with 2 in that place
then divide by (2.01-2)
what was your answer
my friend called so I had to tell him to call back later xD
lemme type this in super fast
haha all good
speedrun time
i have to go in a sec, i have a student
ooooh go ahead then!
I'll work this out B)
plot twist, anyone know what I should do with 5? Not sure what to do with just one set of points D:
OH WAIT is it point-slope-
mmm ok maybe not, this is going weirdly
also that wouldn't involve the DQ x-x
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What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
!show
Show your work, and if possible, explain where you are stuck.
what was your answer
25,15 and 5 have something in common
is 5 + a product of -2 and a fraction
are you familiar with PEMDAS?
can you think of a way to apply that here?
do it on a piece of paper, step by step
why 1?
That is incorrect, you donāt know the value of x and y. youāre assuming that x and y are 1 in this expression
letās work on it step by step
first, (25x - 15y)/5
can you simplify that
No
you can rewrite that expression in the following manner: (25x/5) - (15y/5)
can you simplify this?
correct
now
what are these terms being multiplied by?
No
look at the expression again
it can be rewritten as 5 - 2(5x-3y)
think about PEMDAS
almost
itās -2
what do you get after multiplying the terms by -2?
correct
yes
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Is the working for this question right?
Integration question
cos(2x) = cos²x - sin²x
Of course...
Oh damn
That was a stupid mistake
Thanks .-.
What would be the right answer then...
@plucky crypt Has your question been resolved?
What u have except the negative sign
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Where did i go wrong? The answer im supposed to get is q=-3 but i got q=-4 instead.
second pic, can you explain how you got to the 3rd step from 2nd step?
Because positive 4q will be negative 4q cuz it crosses the equal sign
Oh
that should just give you 15+4q instead of the quadratic
Ohh so should i move q to -1
So itāll be 15+4q=-q
15+4q = -q OR 5q = -15 OR q = -3
Ahh alright thanks
npnp
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if i have two non-negative functions, $f$ and $g$, continuous on $I_1$ and $I_2$ respectively, can we say that $f(x)+g(x)$ is continuous on $I_1 \cap I_2$?
artemetra
i assume it is continuous there but it can be continous on a "bigger" set too right?
also $I_1 \neq I_2$
artemetra
i first thought of $f(x)=\mathrm{mod}(x,1)$ and $g(x) = 1-\mathrm{mod}(x,1)$ but they are continuous on the same sets
artemetra
it is at least continuous on the intersection and can clearly also be continuous on a bigger set
depends on how well g and f behave on the other interval
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help
it's asking u to factorize it
That is the opposite of factorizing
Factor this
how do i factor it
$a+ab$
Samuel
How do you factor this?
aa + ab?
a (1+b)
idk how
sure?
a(1+b)?
Yes
You take out the common factor
In this case a
Open parenthesis and inside
You put the non factored part
For a to become a you multiply by 1
For ab you multiply by b
a(1+b)
Now in your exercise
but we didnt even learn this
15+3x
we only learnt k*(a+b) = ka+kb
Not 5x
3(5+x)
ok than ks
You learnt expanding
This is the opposite
It is like you learn to add and now you have to learn to subtract
okok now the question is 4x5 - 4x
What do you think
What is the common factor
4
4(5-4x)
You forgot to take out the 4 from 4x
Perfect
a(b-c)
As you can see is very easy
yes
i did it
my homework
that was hard
im more use to other types of maths
how do i close this
.close
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For a case like this, can i just start from 2 and decide the determinant ?
So I do 2 * ((c1)-(2**6)) - 0(
and just keep going ike that
until the 1 one come and then im done
yes
what's your answer
-2c^2 +2c + 18
ye
ahh fuck sake
i ment -c^2
and then + 2c + 18
how did u calculate it so fast?
This video explains how to find the determinant of a 3x3 matrix.
Introduction to Matrices: https://www.youtube.com/watch?v=yRwQ7A6jVLk
Adding and Subtracting Matrices:
https://www.youtube.com/watch?v=QXUbFzEd3Ww
Scalar Multiplication of Matrices:
https://www.youtube.com/watch?v=iJE...
watch this
because one of the entries was 0
Oh ye i know this

@jolly agate Has your question been resolved?
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i need help
do you know how to do differentiation?
yes
then you should understand the meaning of derivative, which is the slope of the function
what does it mean when the slope is 0
the y intercept are at points (0,0)
stationary
yes, then what is the derivative of this equation
y = 6x^1 - 3x^2
so you can then factorize it to get 3x(2-x) right, it should be obvious till this point
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How do I know when to solve for y or x in a system of differential equations?
can u give an example of what u mean?
i dont think it matters what u eliminate first
but here the obvious choice seems to be to eliminate x'
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I am not so sure about the worked solution
But I can instruct you on how you can solve these kinds of questions
i understand the concept
i just want to check if im missing something
cause rn the solution is wrong to me
500/sin30=750/sinx
x does not equal 131 in this equation
,w 3/4 radians to degrees
you wont get 131
,w 180-42.97
why would i subtrac it from 180
Cause
this is just wrong
Edmund Cloudsley
Yeah does look wrong to me too
then im correct
,w solve 0.848 radians to degrees
,w solve 180-48.59
Sorry I think I made an error in the wolfram alpha statement
Ambiguous case of the sine rule
what do you mean
NERDSTUDY.COM for more detailed lessons!
Let's learn the Ambiguous Case for Sine Law!
--
So, there are situations where the information weāre provided with for a triangle make it possible for there to actually be 2 DIFFERENT triangles created even after satisfying all the pieces of the given information. We call a situation like this, the āAm...
watch this videoā¦.this will help you understand why we subtract 180
how would i spot that though
Also remember this shorthand
$$\sin \theta = \sin (180-\theta)$$
Edmund Cloudsley
If it looks obtuse, remember that itās 180 minus the angle calculated
It is obtuse in this case
And not an acute angle
so i just go off looks
Yup I think so
One more thing
And this is just a suggestion
I personally feel that the triangle rule is not really a good way to do vector addition
Itās really hard to visualise (atleast for me) and thereās a better way to do it
To add vectors that are not perfectly horizontal or vertical, we take the x and y components of each vector and find the sums of the individual x components and individual y components. The sum of the x components is equal to the x component of the resultant vector, and the sum of the y components is equal to the y component of the resultant vec...
This video may help
Breaking the vector into vector components makes the job a lot easier
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How did bro do this this diagram? Usually I'd finda number between the certain specified values and plug them into the original question to see if the inequality holds, but this expression is long asl n I'm wondering if there's a shortcut
if u mean the red equation, it is the multiple of all equations above, so if there are even number of negative signs on the above, it is positive, else negative
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i am trying to prove that there exists a multiplicative inverse for (1 + x) if there is some n in N for which x ^ n = 0. i've been give the hint that i should think about the geometric summation formula, which makes sense, given that 1 + x is exactly that for n = 1. i don't think i need much, but i really don't see it
ah, forgot to mention, these are all elements of some Ring R
Perhaps they want you to use the formula for 1 - x + x^2 - x^3 + ... + (-x)^{n-1}
(1-q^n+1)/(1-q)?
Multiply this by 1+x
yes, so (1 - x + x^2 + ... + (-x)^{n-1})(1 + x) = 1
Which implies that (1 + x) has an inverse
yeah
thank you, i am not sure why they specifically hinted for the positive only variant then
well i guess itād make it trivial
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It's not positive only, it works for negative values as well
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Does anyone know why exactly we sometimes need to pool data when doing a chi squared test?
Is pooling important if we're doing the work on a computer?
@olive lichen Has your question been resolved?
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Is this correct
how did you get the domain
that's correct though
yes this is all correct
I got the domain by setting the inside of the ln as greater than zero
And for range I think all logarithmic equations ever are always R
Is this true?
yes and yes
exactly, cause logarithmic and exponential functions are inverse functions
oh you could have just noticed that domain of inverse is range of f(x)
and range of inverse is domain of f(x)
Thatās what I did haha
yeah cool
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Help please
this is my work
What is the problem asking u, in basic terms @patent lynx
area under the curve
-3 to 4
is that what you did


