#help-26
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if different sign do i subtract or add
-x represents the -1
same sign add ang keep the. differents sign subtract?
take the greater number then use it?
i get confused by the signs
no its not
yes
then if its regular adding
and subtracting
add them reguarly
like
if its -3
and then u have 2
just do
-3+2
in regular math you would get -1
which is equal to -x
okay i get it
yeah
may i ask what grade?
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help
you don t have to solve anything ...this is just an exemple
The steps are there, factorization (of both numerator and denominator) and then simplification
Then the zeroes of f(x) occur where numerator=0
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Can anyone tell me way to use the Cauchy or Bunhiacopxki inequality to solve this problem?
!occupied
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lol
can anyone help me?
try to make the first equation a+b+c=9 similar to the expressions inside the square root
idk but that seems like it will work
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use the kinematic equations
i am trying but im not sure if i got the right answer
which did you use
then i did t = (vf - v0)/a
idk what that one even is but i saw it in my textboook idk if it's right or not
i wasnt sure if i should use average speed or not either
in a dif eqaution
It’s a really dumb question but I need to prove that when a*b=0 a or b needs to be 0 I just don’t know how to write it down correctly
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ty
so you solved for a though eighth
and just used that value to find t in the other equation
well it should be negative
what did you put for v and vo
well it says initial v is the higher one
mhm 26.5
,w ((13.9)^2 - (26.5)^2)/790
,w calc (13.9-26.5)/-0.64435
so with significant numbers i should leave it as 19.6
bc there are 3 significant numbers in the equation
ok cool
thanks i will prob have a couple more questions if you are up for it
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What is gamma , beta functions and how walli's theorem is derived
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this is a question on computability theory
<@&286206848099549185>
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im being asked to show that 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 ..... = 1/3, but when i do it i keep getting 1 as my asnwer? what am i doing wrong
that is in fact 1
because it is 1
if you want to show something is 1/3, try 1/4 + 1/16 + 1/64 + ...
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🎉
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Hi, I'd appreciate a second pair of eyes on this calc hw (part b). I'm very tired so I could easily be missing something obvious, but this is something I get stuck on often, solving for zero when I can't isolate the variable easily.
Sample problem attached too--it's not helping me much since it doesn't elaborate on how that figure was reached.
Do you know how to solve quadratic equations?
You have effectively the quadratic $t^2 - t - 2 = 0$ (from your working out)
I guess I'm not sure how to plug this into quadratic. Can we walk through it?
This class has me very stressed so I might be blanking on really obvious things.
It might be
but sure we can walk through it 
Thank you so much.
Do you e.g. know the quadratic formula? Did you like trying to factor to solve quadratic equations, if you've solved them that way before?
Oh wait-
@vernal matrix
(t-2)(t+1) ?
Fixed 
And yep
there you go 
I'm not sure what to do with this now though to find the velocity. Which figure do i punch into v(t)?
Well, of course, you're happy that the solutions [to this = 0] become t = 2 and t = -1, right
yes--I get that part now I think
Cool
now, remember that you don't want negative time 
Thank you for making it make sense lol
With my first calc exam coming up Thursday I WILL be in this server a lot this week
i feel stupid ash sometimes bro cause i don’t really understand a lot of sh in school
Wait a moment 
hm?
Oh no I'm being slow
never mind 
Noooo you were fine
I just had a moment there 
If I want a sanity check on another question do I need to close this one out?
You can reuse this one if you'd like to 
Thank you 😄
This one...grr...by my logic the one I have selected is the only one that makes any sense. But the HW site is saying "one of your answers is incorrect" no matter which one I select.
I can only assume it's getting confused by a written answer field on a math hw...
Yo rabbit i got a question
Whats up? 🙂
College fresh, but it's my second bachelors
Thanks!
Does it check the written parts? Which were the other questions?
The entire section is what you see-it says the written part "will be scored later"
I wonder if it's defaulting to assuming it's wrong until the prof goes in. -_-
Hmmm, it might be something like that, yea
It should be f'(x) + 3 after all 
No problem 
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#odes-and-pdes message I think I dont quite understand this hint, why did we do this substitution?
@strong sable Has your question been resolved?
Why nobody😭
Instead of solving with the given y1 and y2, they’ve chosen a different y1 and y2 that share the same span as the original two solutions
This simply makes ur calculations easier
By all rights you don’t need to do this, but it will make ur calculations of the derivatives significantly easier
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Is there a Pi but it like sigma?
Like sigma is addition formula
[ \sum \prod ]
ananas
My teacher told me that this cannot be added, big pi is doing multiplication.
what
ren
While talking to my teacher about sigma, she told me about pi and it is the same formula as pi sigma, but the only difference is that instead of addition, multiplication is done.
Actually is it?
Because I still can't understand the issue.
$$\sum_{i=0}^n a_i = a_0+a_1+a_2+\ldots+a_n$$
Denascite
compared to the picture above
so yes
its the same thing except addition vs multiplication
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how do i find mathematically sec^-1x >=1
with inverse function, x = sec(1)
yeah but
do i take sec on both sides
but theres the inequality
and this fn isnt inc or dec all together
if you care about an inequality its always easier to first solve the equality
and then look on each side of the solution
fair enough
but what would u do if u couldnt?
is applying sec on both side valid?
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hey, refreshing some linear alg concepts here
if i have a matrix, if i consider the rows vectors and i take all the linear combintions between those vectors, that would be the row space, correct?
yes
but this linear combination is not something that is "expressed" somewhere in the Ax=b for example. right?
to express that linear combination i would have to write...
row1 * c1 + row2 * c2 right?
c1 and c2 are scalars
yes
just like A*x does columns
ah ok let me think about that one sec
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ok, yes. c is row vector before A ok.
C=59(F−32)
The equation above shows how temperature F, measured in degrees Fahrenheit, relates to a temperature C, measured in degrees Celsius. Based on the equation, which of the following must be true?
A temperature increase of 1 degree Fahrenheit is equivalent to a temperature increase of 59 degree Celsius.
A temperature increase of 1 degree Celsius is equivalent to a temperature increase of 1.8 degrees Fahrenheit.
A temperature increase of 59 degree Fahrenheit is equivalent to a temperature increase of 1 degree Celsius.
A) I only
B) II only
C) III only
D) I and II only
Someone will but open a separate channel
can u help me with that?
ok so when i have polynomials i write them in rows, and to solve for some value means i need to think about the combinations of the columns vectors really.
correct?
no it's not. i'm confused
yes it is, i need to find the linear combination of the column space of that matrix
right?
and my confusion is : if i think of the polynomial as a vector, can i graph it and think about it geometrically or not?
i mean can i graph the components? i mean i guess so, i would have a line and parabolas of higher degrees.. but it wouldn't have the same geometrical meaning as if i were using normal vectors
i need clarification on this ☝️
@molten crystal Has your question been resolved?
<@&286206848099549185> help
ok so we want to solve for when a polynomial is a linear combination of other polynomials. then we would want to write them as column vectors of a matrix, and solve the system Ax = b, because multiplying matrix A by a column vector x is the same as taking a linear combination of the columns of A using the entries of x as coefficients
you can think of a quadratic as an arrow vector in 3D space, with a constant axis, an x axis, and an x^2 axis. i'm not sure this is a very helpful interpretation though
ok
but usually i see to solve a system of equations i write the polys in rows
which is not what you wrote right? you want to find another polynomial, while i want to.... find... a what, a vector?
@loud oasis
a no, it would be like... geometrically, the intersection of the shapes of the polynomials
but say for example i want to calculate the linear combination [ a(3x-2) + b(7x+3) = x+9 ] then equating components we get [ \systeme{3a+7b=1,-2a+3b=9} ] in matrix form is [ \begin{amatrix}{2} 3 & 7 & 1 \ -2 & 3 & 9 \end{amatrix} ] see how the polynomials end up as columns?
cloud
i don't think that's really useful, because when we think of polynomials as vectors we are trying to find linear combinations (where we stretch and add graphs) to make their graphs identical
and.. when i have a simple system of equations, i just write the equations in rows , right?
yes, if we are solving a linear system of equations we write the equations as rows, and we can imagine the solution being the intersection of the rows
but for polynomials in linear algebra we are usually trying to solve for the coefficients of the polynomial rather than the variable
we can also consider the problem of finding the coefficients of a polynomial given the points of that polynomial, but that turns out to be another form of a system of linear equations
ok i think my brain was mixing too many concepts.
I tought x^2+y^2 = 1 was a polynomial
it is not, right?
it is an .. equation?
well it's a polynomial in 2 variables (x and y), but not in 1 variable (like x)
usually for linear algebra we are dealing with polynomials in one variable
so if i want to find the intersection between 2 circles i would have to write the 2 equations in 2 rows
we can't use linear algebra to solve for that because circles aren't linear equations
intersection of planes works instead?
yes, because planes are described with linear equations
i think the confusion is that there are 3 contexts where polynomials show up in linear algebra:
- if a polynomial is linear, then it's a linear equation and you can solve for their intersection using systems of linear equations techniques
- if you have some points on a polynomial, you can solve for the coefficients because it's linear if you count the coefficients as variables instead
- polynomials form a vector space and any problems involving vector spaces can involve that polynomial vector space
i have experience with 1
point 2 is like when i find coefficients for the fourier series right?
point 3 not sure i understand
for point (2), if you have for example the points $(1,3)$, $(-4, 5)$, $(3, 9)$ and you want to find a parabola they are on, then you can use the equation [ y = ax^2+bx+c ] and plug in the points 3 times: [ \begin{cases} 3 = a(1^2)+b(1)+c \ 5 = a(-4)^2 + b(-4) + c \ 9 = a(3^2) + b(3) + c \end{cases} ] then that's a system of linear equations in terms of $a,b,c$ and you can solve it like in case(1)
cloud
for point 3, have you learned the vector space axioms yet?
not sure what you refer to, the null space and co?
these
ah no i've never did this.
it will make sense after you've covered it then. don't worry about it for now
it's like the rules to be considered a vector space?
ok
ok thanks, I think i'm too tired now. It's better if i keep refreshing what i studied before
or i'll keep going in circles
i had to stop doing math for a while, now i'm slowly restarting, and new questions comes up
thanks @loud oasis
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Take everything to the left side and try and get everything over a common denominator
See if you can get it into that form
You have 8/y
So you’re basically trying to get everything over a common denominator
Which is y
It’s like if you have 1/3 + 1/5, you need to get a common denominator like 15
So don’t do that
It’s not expecting you to do that
It just wants you to put every term over y so that you can add them
Instead of multiplying by y
As I said
Do not multiply both sides by y
It doesn’t want you to do that
Eventually in the solution it will want that
Probably
Not really, it's more of a parametric.
But for your question of how they got between those 2 steps, they don’t multiply both sides by y
I mean it’s not something different, it’s just expressed in a different way
Like saying if y = 1 then 1 = 1/y
Different way of expressing the same information
$\frac{4y}{y} + \frac{8}{y} = \frac{10y}{y} - \frac{y^2}{y}$
eugene_krabs_has_cake
Taking things to the other side and combining the fractions gets you what it shows
As for whether it’s more practical to do this instead of just multiply by y and do it your way, I’ll say it’s probably more inefficient
But I’m purely answering your question
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can someone help me with this <@&286206848099549185>
what would m=0 look like
Hm
the line is horizontal
yes
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This is vertical, not horizontal
this is what it says when i try to do it

so what point do i put to make it horizontal
Any point that would be on that line
with this would i make it horizontal or vertical
Do you know what undefined slope means?
u mean rise over run?
If you have 0/# that means the slope is 0, but if it's #/0 that's undefined. # is used to denote that it can be any value
ok thanks
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@robust spear Has your question been resolved?
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I found the reccurance relation but have no clue how to do the induction proof at all
with n and b
yall r scared of this huh
keep doing calc 1 problems its chill
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uh i got a simple question, i aint got a clue what i did wrong here
@neon iron closing parentheses
wdym?
You're missing them
How did you input that matrix? Did you not go to the matrix menu?
oh i just realized i put in a paranthesis on accident
through the matrix menu
hold on real quick lemme re insert it
i have NEVER had this issue that is so random loll. thank you
But how did that matrix appear? If you picked the matrix, it should have had rref([A])
Not the entire matrix
i did like uh
2nd then pressed matrix and scrolled to rref
and then i pressed alpha and zoom
and thats how i was taught
ohhh i just realized i misread my equation. sorry! but thank you for the help, i just did it correctly. have a good night/day :)
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y=(x+y)(x+1)(x-1)² standard form?
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Need help with this
In Problems 15–22 determine whether the given set of functions is linearly independent on the interval (−, ).
Do I just have to conduct 3 ratio tests? to see if they're constants or nonconstants
It's nonchalant
can you think of any trig identities relating these 3 functions?
Well from what I'm getting from my notes I have to setup a function with C1cos2x + C2 + C3cos^(2)x = 0
But it just says lin dependent after that so idk how to confirm it
My professor didnt clarify, this is diff eq btw
Idk if I have to use trig identities but i know cos2x = cos^(2)x -sin^(2)x
is there any relationship between sin^2(x), cos^2(x) and 1 you could use on this identity?
@brazen ridge Has your question been resolved?
@brazen ridge Has your question been resolved?
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hi im doing calc bc hw and there is a integration by parts question
integral [ sin(2 + lnx) ]
if anyone could help thatd be awesome 🙂
Consider $\sin\left(2+\ln x\right)$ as $1\cdot\sin\left(2+\ln x\right)$
harshul
u = 1 dv = sin(2+lnx)
du = 0 v = integral [ sin(2+lnx)
that comes back to where we started no
You don't want to start off with integrating by parts
Think of a way you can convert that integral, somehow...
u = 2 + lnx
You'll get $\cos\left(2+\ln x\right)$
harshul
And then do it once again
You'll get -sin the second time
So you get a equation which is of the form $I = f(x) - I$
harshul
Where $I = \int\sin\left(2+\ln x\right),dx$
harshul
is that not the og problem
Yes but from this equation, you've found $I$ to be $\frac{f(x)}{2}$
harshul
So you're basically done
Let me work this out though since chartbit was pointing out something
why
Hold on
@vernal matrix help a brotha out
I'm actually a bit confused about the substitution
(well, actually, on doing it, it seems you could do it directly too-)
If we use u = 2 + ln x
then won't dx = xdu
Yes
Just proceed like I told
ya
but you want to choose "dv" as 1, and "u" as sin(2 + ln(x))
Then it'll be int sin u du x
You took du = 1 and v = sin(2+ln x)
By IBP the integral becomes uv - integral [ udv ]
u = x, dv = cos(2 + ln x) (1/x) dx
Don't know what's so confusing about this
i get stuck again
Do it a second time
integral [ cos(2+lnx) ]
.
Yeah apply IBP again just like you did
du = 1 and v = cos(2 + ln x)
Have you e.g. seen the integral of something like $\int e^{x}\sin(x) \dd x$ before?
@vernal matrix
You want the same integral to reappear
So that it gives you an equation like this
its too majestic
I've forgotten the constant of integration but you get the point
we saw an example like this in class and ur goated ass j reminded me
thats not real
You'll believe it's real after losing a mark for not writing it
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I am not sure how to proceed with t=tan(x/2)
just find the value of x sub in the sine
and then you gotta do simplification
or better use the relation of sin(2t) and tan(t)
yeah that'll be better
Okaayy lemme try
What about the integral limits??
pi and -pi
Do they become infinity when I subsitute dt
you have to change it with respect to substitution
Yea so +inf and -inf ryt??
Okayyy thnx a lot everyone
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heelo can i ask a question its a integration in partial fraction. How did it end up with B/x-2 dx? knowing that C already has (x-2)^2?
@violet sundial Has your question been resolved?
<@&286206848099549185>
thats how it works, the number of terms is the order of the pole
if the pole x=2 was repeated 3 times for example, i mean (x-2)^3 in the denominator
you'd have 4 terms
A/(x-1) + B/(x-2) + C/(x-2)² + D/(x-2)^3
ok i see thats the problem..
so if (x-2)^4..... then B/(x-2) , C/(x-2)^3, D/(x-2)^4 ?
ok consider an fraction in the form of $\frac{1}{(x+1)(x^2+2)}$ this we can write it as $\frac{A}{x+1}+\frac{Bx+c}{x^2+2}$
convergence
what it is called?
now lets apply this same logic on this fraction $\frac{1}{(x-1)(x)^2}$
convergence
so we can get that to be equal to $\frac{A}{x-1}+\frac{Bx+C}{x^2}$
convergence
A/x-1 + Bx+c?x^2
did you understand this?
convergence has a point here, solid example
hes giving you a simple example that leads to A/x + B/x², like why we do it like that
there's a difference between linear and quadratic
yep ik that
this is called partial fractions
ohh okay
thank you sir i fully understand it now..
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scalar triple product is defined as
[a b c] where a,b,c are vectors
And I can interpret it as
[(a) (b) (c)] just to separate the vectors
Now here’s a lil property that says
[a+ b c d]=[a c d]+[b c d]
Am having trouble whether it’s saying
[(a+b)(c)(d)]
or
[(a)+(b c d)]
ik I could jus derive it but that’s gonna take way too long
<(a+b) c d>
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"A rabbit races with a turtle over a distance of 1000 meters, the turtle starts with a velocity of 5m/min without breaks, but the turtle's velocity decreases by 0.001 for every 1 meter. The rabbit starts of with a velocity of 200m/min, and sleeps when it reaches halfway.
If the turtle won the race exactly 1 minute before the rabbit reached the finish line, find how long the rabbit slept (ln2 = 0.693, ln5 = 1.609)"
i think i should find the function for the position of the turtle
but i have no idea how to start
turtle's velocity is decreasing by 0.001 every 1 meter
yeah
do you recognize whats it
like if u increase decrease a constant repeatedly from a term
deceleration?
arithmetic progression
I kinda figured out something, but it might not be useful
?
1/5 + 1/{5+r} + 1/{5+2r} + ... + 1/{5+nr}
is there any way to find the value of some of series like this?
In my knowledge I can't think of any
i think its more like 5-5*0.999^x cause they habe ln values given?
ln would come from the setup of a differential equation
i dont think so
$t_{required}=\left(\frac{1}{5}+\frac{1}{5-0.001}+\frac{1}{5-2(0.001)}+...+\frac{1}{5-1000(0.001)}\right)-6$
zero idea how something like this could be solved
there is obviously some other way
wait am I tipping or what
we both are
,w sum from r=0 to 1000 1/{5-r0.001}
can i set it up like dx/dt = (constant) x?
wtf
Wolfram Alpha doesn't understand your query!
Perhaps try rephrasing your question?
Click here to refine your query online
<@&286206848099549185>
☠️
wolfram going crazy with this
wait
i got uh
dx/dt = 5 - (0.001)x for x meters travelled
yeah that's definitely better
i totally forgot what i was doing 
i got x = 5000 - Ce^(-t/1000)
^
no idea what theyre doung here 😭
integrate from x=0 to x=1000
oh
you'll get total time ig
my teachers have only used indefinite
at t=0 isn't x=0 too?
yeah
maybe that'll work
,w integrate 1/(5-0.001x) from 0 to 1000
oh yeah my bad
according to this the speed was changing instantaneously
so it was 5 for first minute
and just at the beginning of 2nd meter it turned into 5-0.001
so using integration gives only approximate answer
I wonder if there is any continuation to this to get the exact result
i put that in wolfram and it used some digamma function
can you share it?
with the exact syntax you entered in it
what is the -6 for
that was from your other message mb
yeah
(sum of that series)
how'd you find it?
python
oh
with that -6 or not?
without the -6 part
that series is just the time taken by turtle
tortoise whateve
but we need the time for which the bnuuy slept
not the series
the -6 at the end
what is that for?
that -6 is for thiss
5 mins and the turtle finished before by 1
lol
are you done with this problem?
how would you actually solve that series
i think so

for human applications, just using an integral
ig so
why do all the other problems look so easy compared to this one
this was easy too tho
fr
your other problems are generally way too difficult than this
lol
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Yh
oh
like how g(4) is definitely greater than g(3), even though you don't know the exact values
so is this the right arrangement:
$g'(0), 0, g'(4), g'(2), g'(-2)$
Devil Wears Prada
I think so, hard to say between 2 and -2 tho
not at all
they are very different
looks right to me
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stuck on this:
@halcyon willow Has your question been resolved?
that is basically what you do
i mean that should get you an answer
you might wanna set i.e. k^1/n < a <= (k+1)^1/n to get something nice
Idk why i didnt get the correct ans
huh
if anyone wanna try helping ping me
how did u directly write the first step? 
as in my final line?
first sorry
split it up into ur separate integrals
oh so i took a = k^(1/n) for now cus it's easy once we've done that
replace a for k^1/n?
then $\int_0^1 \floor{x^n} dx = \int_0^1 0 dx$
LY
can u write the integral for this i didnt get it
$\int_1^{2^{1/n}} \floor{x^n} dx = \int_1^{2^{1/n}} 0 dx$
LY
$\int_{(k-1)^{1/n}}^{k^{1/n}} \floor{x^n} dx = \int_{(k-1)^{1/n}}^{k^{1/n}} k-1 dx$
LY
ohhhh
yep
i've assumed k is an integer for now
cus when a isn't of the form k^1/n where k is an integer
the final integral is easy
i.e. sps this
then set a = k^1/n + t
then the final one is just
$\int_{k^{1/n}}^{k^{1/n}+t} \floor{x^n} dx = \int_{k^{1/n}}^{k^{1/n}+t} k dx$
LY
i dont see the t
in the integral tho
i get the how u made the integerals
since we gotta break floor fn when it is integer
but cant we not involve k and directly use a?
like you can
but it's often easier for questions like these to leave ur answers in terms of k
huhh
and then think about how you can find k in terms of a in the end
yeah the book used a series summation
but
its kinda different
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i was wondering how to start this problem, if i could get help it would be nice to know where to start
What's D?
Call D1 the region above the x-axis and D2 the region below the x axis
can you describe those x and y values?
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Am I doing this right?
Don’t forget you want h to go to zero, of course, and keep going 
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cansomeone give me a scenario or question something that helps me apply this
i get the concept but just want to be sure
like the more digits u have the less uncertainity
Example
Let's say we measure something as
3985.7 grams
If i round it to
4000
That's 1 significant digit
yep
Because you are less accurate to call it 4000 than 3990 for example
Let's say
The measurement was
4000.1
Now it's much more accurate to say 4000
Right?
yes
So then how can i tell from just seeing the number 4000 how accurate that is or how much we rounded?
Well
That's why it's better to use scientific notation
Rounding 3900 to 4000
It's 4 x 10^3
Rounding 4000.1 to 4000
It's 4.000 x 10^3
For sig figs the scientific notation helps you to see that
Ok
Without a decimal or other description you can't say
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Q6)
Part d, e, f and g,
Can anyone please explain how to solve them?
@final dust Has your question been resolved?
<@&286206848099549185>
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@final dust Has your question been resolved?
the not equal sign in the piece-wise means > and also <
ping me if yo uneed more help
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Shouldn't this just be 3?
uh mb
all good
@dusky plover Has your question been resolved?
why are there so many physics problems here?
also, i suggest you make a free-body diagram for this problem (i did not label it correctly, that's for you), as it 'll help you visualize the internal forces, which have no effect on the system, and external forces, which do .
the two masses are right though and the tensions connecting
F = MA
solve
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if f(x) = (ax^2 + bx + 10) / (x^2 + c), and f(x) has a removeable discontinuity at x=-2 and a vertical asymptote at x=2 and the limit of f(x) as x approaches -2 is 1/4, what is b, and c
c is -4 b/c (x-2)(x+2) on the bottom makes x^2-4
and (x+2) has to be on the top as well for removable discontinuity
thats where im stumped idk what to do next
Do you know what a is? (wow I can't actually read
)
Anyways, do you know what (x + 2) needing to be on the top (i.e. is a factor) of the numerator means for ax^2 + bx + 10?
(x+2)(ax+5)?
much love chartbit
All by yourself as well 
this is lowk what i needed
i cant lie
Sometimes it's the small bits 
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how do i factor this
can you factor 3x^2 + 4x + 1
i dont know how😰
do you know how to factor x^2 + 2x + 1
ok lets try something else
can you expand this
or do you need help on what it means to "expand" that
i need help
you need to know how to factor
and since you dont know how to factor,
you need to know how to expand
yes or no, can you expand this
what do you mean by expanding
are you familiar with distributive property
i dont know the names but
if you show me an example
then i can tell if i know or not
go guess what "expanding" means when given something like this and told to do something related to math on it
what things can you do to (x + 2)(x - 1)?
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May someone please explain how homie turned the 2 into 8/4?
Like I understand 8/4 = 2 but
-
Why express it as a fraction?
-
How did we know that?
-
My initial thinking was to do 2/1
If yoy have 8 pieces of pizza, how many pizzas can a person have when distriubted to 4 ppl
I mean like this reasoning is cool and all but what if in the future we dealing w/ more numbers and bigger numbers at that
calculate
Like I can't say "Oh yeah so this integer just gonna be expressed as a rational because I'm hard like that"
Was my inital thinking of doing 2/1 correct?
well look its not wrong but its a bit like
Idk if my algebra is wrong but I think I'm getting the wrong answer
if someone says ill swin to that place when they can take a boat
youre complicating it
Yeah I guess
look at what they did
they put 2 to
8/4
and added all the /4 together
to then get the 9/4
so its pretty easy to make it like that
But I'm just thinking ahead yfm, like these lil shortcuts are cool and all but they don't last long, like for GCD for example, we can keep spamming our calculator until we find one, or we can learn Eucledian algo. type shit
well i assume
theres some tests which your teacher wont allow calculators
so this is prety handy
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no
the third row of I is 0 0 1
three times the third row is 0 0 3
adding that to the first row which is 1 0 0 would give 1 0 3
you’re making the mistake of looking at the end result and then applying what they did
the wording is a bit vague, they meant "add 3 times the third row of I3 to the first row of I3"
See if we multiply third row by 3 then [0 0 3]
Then add this to first row
Simple
ah
okay yeah wroding
ty
.close
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!15m
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need all 5 awnswers please put in format as:
- A
- B
3.C - D
- A
Example^
<@&286206848099549185> its been 15
The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.
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could someone verify these 3 drawings are correct?
Please don't occupy multiple help channels.
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whats 2991- 81x
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Is the answer key wrong, shouldn’t the absolute value of r be greater than 1 in order to get the interval of convergence?
If that thing is greater than 1 then the sum doesn't converge at all
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whew