help-26

[topaz sinew]

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[arctic dirge]

yo

[arctic dirge]

The cumulative frequency of the 3rd bin in a frequency distribution table represents the number of data values that are less than the maximum value of the 3rd bin

right?

i just need yes or no

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[wet loom]

Since there is no variable on the integral, how would i slove this

[rigid ivy]

That should tell you everything you need to know

[wet loom]

wait what

do i just find the integral

and then the derivative?

[rigid ivy]

you don't need to

integral is definite, with constants as bounds

[wet loom]

wait

so the integral and derivative cancel each other out

?

[rigid ivy]

No, it's simpler than that

The integral will just be some number

it doesn't matter what the number is, it'll just be some number

[wet loom]

ohh

so the derivative of that would be 0

?

[rigid ivy]

yes

[wet loom]

ohh ok ty

I actually love you

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[wet loom]

why is this wrong

[odd pagoda]

because thats not a definition

thats a theorem

[wet loom]

o

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[forest trout]

ABC is right triangle

how do I find x

I’m not sure the angle above is 45 degree

[opaque crow]

Try using cosine law

And SohCahToa to confirm angles in the right angle

[forest trout]

but |BD| are not straight

[opaque crow]

BD isn’t relevant

[misty remnant]

i don’t think those 2 angles are 45 at the top

[opaque crow]

Also the hypotenuse isn’t 3

[forest trout]

Yeah I erased thrm after ss

they arent 45

[misty remnant]

nice nice

[forest trout]

let me calculate it again

its 41 in square root

[opaque crow]

Yep

So now we can find the angles in the right triangle

How would you do that?

[forest trout]

I really have no idea

[opaque crow]

Try using SohCahToa

For angle BAC

[forest trout]

Im trying to understand SohCahToa method

[opaque crow]

What about it?

[forest trout]

I heard that method for the first time

what O and H refers to

[opaque crow]

Are you asking what it refers to?

[forest trout]

I mean the Soh is sin() = O/H

[opaque crow]

Yep

[forest trout]

so the O refers to which angle

and H

[forest trout]

Ill ask this to my teacher, anyways ty for help Im a bit dumbass cant get it fully

I guess that will be better

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[neon iron]

how do i rearrange so both parts are convergent

[raven sparrow]

What is the largest sin^2(n) can be for any n?

[neon iron]

idk 1

i forgor trigonometry 😭

[raven sparrow]

Yes. 1.

So can you give an upper bound for that sequence?

[steep nebula]

the biggest value for sin(x) is one, so squaring will also be one

[neon iron]

its going to be 1

okay this has helped me

i can do the rest now

thanks

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[topaz sinew]

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[white haven]

why is it 6cm? I know it needs to use tangent properties but I just cant deduce what is the diameter of the circle

[finite storm]

Ok

So

Lines tangent to the circle forms a right angle

[white haven]

ye

[finite storm]

Use Pythagoras

Then apply similar triangle

[white haven]

so you mean, use the theorm to find that EB is 8

[finite storm]

Yes

The

N

There are two right triangles, right?

[finite storm]

${\frac{AB}{AC} = \frac{OC}{OE}}$ where O represents the center of the circle

[white haven]

OH

[thorny flame]

:D

[white haven]

wait what

wait

or u meant OC/AB=CE/BE

i think i get it now

thanks for the idea of similar triangles

[finite storm]

No, like

U can only apply similar triangles if the angles are similar

In this case, the right angle and the left acute angle of the triangle

[white haven]

yeah

so its OC/AB=CE/BE

because triangle COE is upside down

[finite storm]

Why BE and CE tho

[white haven]

wait

this is the two similar triangles look like when they are reorientated

[white haven]

in the question its inverted vertically

it will be easier to see the similar sides if u reorientated it

[finite storm]

Yes, when reoriented

AE is the similar to OE and AB is similar to OC

[white haven]

yeah and BE is similar to CE

[finite storm]

Yes

[white haven]

because if i use this two sets then ill have 2 unknowns

[finite storm]

I’m not functioning 😭

[white haven]

so i use this instead

[finite storm]

He

Ye

I’m

🥴

[white haven]

do u get now

[finite storm]

Yes

[white haven]

i love how we both helped each other to understand this question

this is great

mutual assistance

its nice meeting u and thanks for helping me to figure it out

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[strong sable]

the radius of convergence can be determined by the Root Test or the Ratio Test

[strong sable]

can anyone walk me thru this or give me an example

[loud oasis]

https://tutorial.math.lamar.edu/Classes/CalcII/PowerSeries.aspx

has a few worked examples

[glacial adder]

basically uses the idea that the ratio and root test gives you an inequality to work with

[strong sable]

why this? Any way to visualize this?

[finite storm]

If I have to guess

Issues with alternative series

But not sure

[glacial adder]

well the ratio test and the root test are inconclusive when the limit equals 0

[thorny flame]

y0shi

[glacial adder]

where R is the radius of convergence

but when this is equal to 1

the test becomes inconclusive, hence you need to use other tests to see if it is convergent on those endpoints

[topaz sinew]

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[topaz sinew]

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[topaz sinew]

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[topaz ruin]

there is 8 stones that have different weight and there is scale where u can only put one stone each side . what is the least amount of weighing that will tell us which one is the heaviest and second heaviest stone

[topaz ruin]

guys can u help me here

<@&286206848099549185>

[restive inlet]

!15m

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@topaz ruin Has your question been resolved?

[brittle rune]

Still need help?

First, put all stone on it. Assess the result, if it is 230 kg then remove one stone. If it gets to 210 kg then the rock weighs 20kg

Simple.

[restive inlet]

wrong type of scale

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[wicked burrow]

How do you find B in this case

I understand what the column space is, but I don't really know how to apply it here

I tried row reducing

It didn't really do anything useful

[topaz sinew]

@wicked burrow Has your question been resolved?

[topaz sinew]

@wicked burrow Has your question been resolved?

[wicked burrow]

<@&286206848099549185>

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@wicked burrow Has your question been resolved?

[wicked burrow]

forget it

.close

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[lusty cedar]

.close

.reopen

Im rly confused

.close

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[topaz sinew]

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[ember glacier]

how do i figure out what this is

[near steeple]

Nupe 😉 Thats not it. I can see why you put it but that's probably not the answer.

[rustic summit]

yo can someone help me u just gotta tell me if the answers are right or wrong

[ember glacier]

how do i figure out the answer then?

[near steeple]

The only rotation you have at hand is a rotation of center O, so would keep the right angle closer to the origin than the rest -> Not c

[ember glacier]

okay

[near steeple]

If you just reflect with y=0, then all the vertexes go below the line -> not d

The translation <2,-4> would shoot M on K and N above the grid -> not a

So its a glide reflection, can you figure out the rest ?

[ember glacier]

its e ?

cause i feel like b is too simple

[near steeple]

Ahahah come on give a nice justification at least xD

But yeah its E

[ember glacier]

okay thank you so much

[near steeple]

err wait

are u in the us ?

the circle thing changes meaning i think

[ember glacier]

oh

im in the us yes

[near steeple]

Oh yes E anyway, reflection and translation commute here not prob 😉

[ember glacier]

thank you sooooooo much!!!

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[cedar charm]

I have been stuck on this problem for some time

I'm thinking of using difference of two squares

A^2 - b ^2 = ( a - b) ( a +b)

<@&286206848099549185>

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@cedar charm Has your question been resolved?

[dry oxide]

Noticeeeeeee that 12 is 3 x 4 and 75 is 3 x 25

Now you multiply both terms resp by 25 and 4

And then they again will be both perfect squares…now try solving

You have to subtract them now…and get possible pairs of a and b from a^2 - b^2 = (a+b)(a-b)

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[unkempt raft]

how do i start

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@unkempt raft Has your question been resolved?

[thorny plinth]

I havent done it, but maybe first try like k=1, k=2 to get an intuition for the problem. Also, if x is the middle number (k+1th), then it's quite easy to see that m1 < x and x < m2

Also why the same question as dryft?? where is this from?

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[spring tide]

Help

[spring tide]

Just a quick question

For the question above did I just do log 10

Since the log don’t have any number

[cedar wagon]

Log (x) = log_10 (x)

[cedar wagon]

Idk if this was what you ask

[spring tide]

Yeah

Like this?

If I do question like c

[spring tide]

This one

[cedar wagon]

Yeah its the same as log(x)

[spring tide]

Ok thank you

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[humble spoke]

Alright so i'm working on converting functions into series' and for some reason i'm caught up with this one $f(x)=\frac{x}{25+x^2}$. I'm just not sure how I should approach it, I can't factor the denominator, I feel like decomposition would be pretty difficult here, yet i'm sure i'm just missing some very clear algebra.

[thorny flame]

lILi

[vernal vale]

can we use the derivative of geometric trick

oh, hello again

[humble spoke]

I know I could use derivative but there are questions later on that are clearly directed at using differentiation and integration

Hii

The one I'm working on right now, I'm fairly certain, is intended to be figured out algebraically

[vernal vale]

idk if you have seen the trick

you know calculus right

[humble spoke]

Yeah it's calc 2

[vernal vale]

okay

[humble spoke]

I know derivatives and Integrals

And I know how to differentiate and integrate series'

[vernal vale]

$\frac{1}{1+x} = \sum _0 ^\infty (-1)^n x^n$

[humble spoke]

Yes im aware of that

[vernal vale]

try taking the derivative of both sides. then multiply both sides by x

[humble spoke]

Wait

Oh interesting

[vernal vale]

this is the usual trick to get something like what you have

[humble spoke]

What about the degree of the denominator?

[vernal vale]

how do you mean?

[humble spoke]

Just to be clear, this is the first thing the professor taught us when we started this subject

[vernal vale]

well, try taking the derivative

im not sure the exact sub that pulls your problem out ill play w it

[humble spoke]

Yeah that's what my issue has been

I understand what I'm trying to do

What I'm trying to get to

And how I can get there

I'm just struggling to figure out how to manipulate this one specifically

[vernal vale]

right so

[thorny flame]

jan Niku

[vernal vale]

lets start here

differentiate both sides

multiply by x

what do you get?

@humble spoke you can type or send pic

if youre able

no rush

[humble spoke]

I had been getting food for most of our conversation so I had to use my phone

back on my pc again

[vernal vale]

lol same

im stuck in a cab

actually ive been flying all day

[humble spoke]

I see

[vernal vale]

ive got the answer i can help walk you there if you want

[vernal vale]

or at least start here

[humble spoke]

This is the full question. Again, I want to use an algebraic solution over a calculus solution if possible for this one, as questions later on explicitly state if we should use differentiation or other methods

[vernal vale]

well im sorry im not sure how youd start

[humble spoke]

that's fair

[vernal vale]

the problem is very suggestive of this technique

[humble spoke]

anyways $-\frac{x}{1+x}=\sum\limits_{n=1}^{\infty}n(-1)^nx^{n}$

[vernal vale]

close

[humble spoke]

oh hold on

[thorny flame]

lILi

[vernal vale]

yea

multiply by -1

both sides

just edit ur tex

[humble spoke]

$\frac{x}{1+x}=\sum\limits_{n=1}^{\infty}n(-1)^{n+1}x^{n}$

[thorny flame]

lILi

[vernal vale]

okay

and ....

[humble spoke]

the main issue point for me is the denominator $25+x^2$

[thorny flame]

lILi

[vernal vale]

the denominator is missing a square

[humble spoke]

that's the only thing giving me issues

[vernal vale]

oh wait i dont have the answer 😭

more work

[humble spoke]

Honestly my first instinct with this problem was to integrate but that would've just led to a natural log and it got nowhere

[vernal vale]

,w Series[x/(x^2 + 25), {x, 0, Infinity}]

[thorny flame]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by janniku

[vernal vale]

ugh

[humble spoke]

[vernal vale]

okay fine

i mean, this makes sense

actually

yea

[humble spoke]

that's like, one or two imaginary numbers

[vernal vale]

1s

[humble spoke]

I'm gonna go ahead and input erroneous answers in order to get the provided solution because it has absolutely no effect on the final grade

[vernal vale]

okay

im curious

[humble spoke]

...I HAD IT

[vernal vale]

😶

[humble spoke]

The only reason I didn't pursue it was because I wasn't sure if I could carry the square through

[vernal vale]

square?

show answer

[humble spoke]

the initial transition into a series

[vernal vale]

ah, ya

okay

Oh

i see

how silly

[humble spoke]

I wasn't sure if $[-(\frac{x}{5})^2]^n$ would be an option

[thorny flame]

lILi

[vernal vale]

well

now we both know

sorry fren

[humble spoke]

So i'm gonna go ahead and assume that the $x$ in $\frac{1}{1-x}=\sum\limits_{n=0}^{\infty}x^n$ is pretty much just a $u$

[thorny flame]

lILi

[humble spoke]

just, that's the idealised form

well

no nevermind that's a bad take

the actual brute force process of conversion would likely break down if you put anything in place of x

Either way, I should've just gone with my gut, I would've been done with this a while ago

Thank you for trying though

[vernal vale]

good luck

and you had it, counts for smth!

[humble spoke]

Yep

Oh well, might see you again depending on how this homework goes. Either way, thank you

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[torn flare]

Three numbers a,b,c in that order, are in geometric sequence with common ratio r.
Given further that a,2b,c in that order, are in arithmetic sequence, determine the possible value(s) of r.

I am unaware on how to solve a question like this does anyone have a text book or video they can guide me towards so i can learn i have frantikly searching for a method or teaching but cant and ChatGPT wont teach it to me XD

[topaz sinew]

@torn flare Has your question been resolved?

[rose sierra]

How can you express b and c in terms of a and r?

[topaz sinew]

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[torn flare]

.reopen

[topaz sinew]

✅

[torn flare]

I know that arithmetic
d = 2b - a = c - 2b
and
GeoMetric b = ar and c = ar^2

wait since both d and r are the same value does that mean whenever r is the same value i can substatute the two equations together

[rose sierra]

d and r are not the same value

But basically, we know that
a, 2ar, and ar^2 is an arithmetic sequence

So like you said, we know that ar^2 - 2ar = 2ar - a

How can we continue from here

[torn flare]

wait didnt you just do what i said?

substatute equation 2 into equation 1

this is what i mean by they are the same

[rose sierra]

Well, you said that d and r are the same, which isn't true

or not necessarily true I should say

[torn flare]

oh ofc

d is common difference and r is common ratio

[rose sierra]

right

[torn flare]

would this be easier in vc?

[rose sierra]

I can't vc rn sorry

[torn flare]

all good

[rose sierra]

But you're pretty much there

[torn flare]

😭

im so lost ngl bro

[rose sierra]

Do you get this step

[torn flare]

this is the step i dont get
so i understand what it is thats the equation for each term

1st term = a
2nd term = 2ar
3rd term = ar^2

[rose sierra]

So based on the fact that a, b, c, is a geometric sequence, I rewrote b as ar, and c as ar^2.

[torn flare]

if i asked why

does that makes sense

[rose sierra]

Because that's how a geometric sequence is defined

Each term is the previous term multiplied by r

[torn flare]

Oh so essentially youre turning the arithmetic sequence itself

into a geometric sequence in this case?

because a b c are the the same?

you can express them as each other

[rose sierra]

wut 😵

I'm just rewriting b and c in terms of a and r

That's it

[torn flare]

see thats the part i dont understand 😭

[rose sierra]

Okay, do you understand that
a, ar, ar^2
is a geometric sequence

[torn flare]

yes

[rose sierra]

Alright. Since we're given that a, b, c is also a geometric sequence, then we know
a=a
b=ar
c=ar^2
for some value of r

[torn flare]

yes that makes sense to me

that part makes sense but what im trying to ask is why youre doing that exactly because its not more so i want to solve this question but get my head around how to do these types of questions

im sorry if im being highkey dumb af

[rose sierra]

no worries lol

[rose sierra]

The reason this is useful is because we also know that a, 2b, and c is an arithmetic sequence

So a, 2ar, ar^2 is an arithmetic sequece, which means that
ar^2 - 2ar = 2ar - a

which allows us to solve for r

[torn flare]

mhm so youre substuting a b c into its place

[rose sierra]

right

[torn flare]

wait thats why i was getting confused i kept thinking with both equations 😭

So essentially you one of the two either arithmetic or geometric and turn a b c into what it actually is

d = 2b - a = c - 2b

d = 2(ar) - a = ar^2 -2(ar)

d = 2ar - a = ar^2 - 2ar

Move everything to the left side to make it 0

2ar + 2ar - ar^2 - a = 0

4ar - a - ar^2 = 0

Then we use Quadratic Formula

it just clicked LOL

@rose sierra in your opinion for a question like this is it always quadratic equation or are there other ways to solve it e.g if its not in the form x^2 + bx + c

[rose sierra]

It's only quadratic because there are 3 terms

if there were 4 terms you'd have a cubic

[torn flare]

wait also just to make it clear it becomes

r^2 - 4r - 1 because we are always assuming a != 0

[rose sierra]

yes

[torn flare]

we can also solve like this right?

@rose sierra

[rose sierra]

Yes that's another way to do it

and then substitute 2b=a+d and c=a+2d

but I think that's harder

[torn flare]

straight up impossible

I think thats my other question is there ever a way to know which way is the correct way or do you just solve one if its not that solve the other way

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[severe marsh]

hello

[severe marsh]

how do i find theta if it is acute

?

thanks

do i go through sin

is sin theta=5?

[raven sparrow]

No. $\cot(x) = \frac{1}{\tan(x)}$, so you can write it in terms of $\tan$ and use $\arctan$.

[thorny flame]

Azyrashacorki

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[north pendant]

"the function f is determined by f(x) = 1/x and x is changing from 1 to 2, what are the values of delta y & dy"

[north pendant]

alright delta y should be -1/2, but now how should i find dy?

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[spring tide]

help

[spring tide]

I need someone explain to me

[deft holly]

whats the q?

[restive inlet]

explain what

[deft holly]

what we doing

[spring tide]

That’s the question

They just reflect the plus and minus

I just wanna said what should I change for the step that I solve

@deft holly

@restive inlet

Sorry for response so late

My phone is dead

<@&286206848099549185>

[deft holly]

wait

so

what exactly is wrong?

the graph

[rigid cloak]

Fr

[deft holly]

the roots?

[deft holly]

ayo

[spring tide]

No

[rigid cloak]

Yo

[spring tide]

I mean what should I change for the step

[rigid cloak]

u asking minima maxima?

[spring tide]

Cause it just like the same question but just the plus-minus sign is change

[spring tide]

No

😭

[rigid cloak]

Okkk tell me clearly

[deft holly]

wdym by same q

same q as what

[spring tide]

This two

Just the sign is different

[deft holly]

ahhh

[spring tide]

I just wonder are the step same?

Cause the answer is the same

I just wondering

[deft holly]

just stick a neg bracket like -(P(x))

ans are the same yea, the graph will just be flipped

[spring tide]

But is the step same too?

Should I just like copy and paste?

The step

[deft holly]

yea just copy and paste but put a neg bracket at the start

[rigid cloak]

-ve will do what

if u change x to -x

[rigid cloak]

It will flip the graph about y axis

[spring tide]

Like that?

[deft holly]

i would put it on the eq

other side

sorry

not the P(x) i just wasnt bothered to write the eq out

[rigid cloak]

@spring tide

[deft holly]

so the side of the roots

[rigid cloak]

See in -P(x)

The graph will flip about y axis

What is above y will go below

[deft holly]

kinda works still tho it just looks weird

[rigid cloak]

And what is below will go above

[spring tide]

Ok

But I just still wondering if the equation

[spring tide]

I don’t get it, can u said it more clearly sry

Like that?

[deft holly]

yeye

like that

[spring tide]

Oh ok

Ty

And the synthetic division is the same right?

[rigid cloak]

Got it

Always remember

If in a P(x) becomes -P(x)

Flip the graph about y Axis

[spring tide]

Ok

And is the synthetic division the same?

[deft holly]

yep

cause we already took the - out

[rigid cloak]

Fr

Fr

[spring tide]

Ok thanks u guys

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[pearl fog]

find all positive integer pairs (d,j) such that $d^j=j^{d-j}$

[thorny flame]

Skill_Issue

[pearl fog]

d>j ig

[topaz sinew]

@pearl fog Has your question been resolved?

[subtle grotto]

You can begin with trial and error for one of the integers, such as j.

Start with j = 0, 1, 2, 3

From there, try to discover a pattern

[pearl fog]

um

say j=2, d could be more than 1 no?

[brave fox]

does rewriting it as => d^j = j^d / j^j => (dj)^j = j^d help?

do we have d^j mod j-1 = 1?

doesn't help much for j=2 ngl

i think if j has prime factor p, then d^j mod p = 0 => d mod p = 0 is this correct?

because otherwise we have
0 * d mod p = 0 & non-zero x * d mod p = 0 which would mean x has no multiplicative inverse, but it must?

[topaz sinew]

@pearl fog Has your question been resolved?

[pearl fog]

a little

[pearl fog]

sorry i genuenly dont havw any clue what ykur talking about

[brave fox]

i don't really either sorry. I just think it's an interesting problem, but i'm bad at diophantine equations

what i noticed: if d > j, then d=j^(p/q)

for example we can have 8^something = 2^something else or 8^something = 4^something else

but never 3^something = 2^something else

and in particular for j that don't have powers in their prime decomposition d = j^(positive integer)

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[pearl fog]

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[pearl fog]

a

.close

bot.?

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[north steeple]

please could someone help

[topaz sinew]

@north steeple Has your question been resolved?

[primal patrol]

whatve you tried

here's a hint: dy/dz = (dy/dx)/(dz/dx)

[topaz sinew]

@north steeple Has your question been resolved?

[north steeple]

thanks

i think i get it from there 🙂

just was very confused with the first step

[primal patrol]

sure

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[rancid fog]

Is there an algebraic way to find all solutions for an equation of type (5/3*x mod 1) - (x mod 1) = 0.5

[rancid fog]

I need this to calculate circular movement

[topaz sinew]

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@rancid fog Has your question been resolved?

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[ember lynx]

hi, I would like to know why in the first task they multiplicate the probability with the number of students picked (3) and in the second task they don't multiplicate the probability with the number of doors opened.

task 1:
Homework control* - 1_328
At the beginning of the mathematics
lesson, a teacher randomly selects 3 students
who have to explain the solutions to the
homework problems on the board. There are
12 boys and 8 girls present.

Task:
Calculate the probability that
2 boys and 1 girl will be chosen to explain
the solutions!

(b for boys m for girls)

[ember lynx]

one second I'll send the 2nd task

Advent calendar* - 1_353 -

In an Advent calendar, 4 of the 24 windows
were accidentally left unfilled.

Task:
Calculate the probability that
when you open the third window you will

find the first empty window!

b for filled doors, l for unfilled doors

[hidden horizon]

what's the answer for this question Find the equation of the ellipse with foci ( , ± 2 0) , vertices ( , ±3 0)
its in indian syllabus

[ember lynx]

huh-

[topaz sinew]

@ember lynx Has your question been resolved?

[topaz sinew]

@ember lynx Has your question been resolved?

[ember lynx]

<@&286206848099549185>

[atomic stream]

So, in the first problem, you want to choose 3 students, where 2 of them must be boys and 1 of them must be a girl. You are multiplying by 3, which is the number of different ways you can choose when there are "duplicates"

[ember lynx]

so because you can either choose (b,b,g) or (b,g,b) or (g,b,b) - so 3 ways you can choose, you multiply it by 3?

and in the second you don't have to multiply by 3 because you only have to calculate one optimal outcome?

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[lusty trail]

Was solving one prob

And got to this part

Dunno how to get it done after this point

🙏

.close

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[round parcel]

How do i write 4(1-1/sqrt2)^2+2(1-1/sqrt2)^2+(1-1/sqrt2)^2+(1-1/sqrt2)^2/2.... as an infinite series?

[round parcel]

plz ping

[chilly walrus]

the "(1-1/sqrt2)^2" seems to be constant, let's call it k

[round parcel]

yes

[chilly walrus]

thus we get 4k + 2k + k + k/2 + ...

[round parcel]

ohhh

so it would be

[chilly walrus]

does this make it any easier?

[round parcel]

ok yes thx

sry my brain was not working, i'm more of a physics dude

so it would be (2^(n+1))*(1-1/sqrt2)^2?

[chilly walrus]

yea, sum of that

[round parcel]

thank you so much!!!!

[chilly walrus]

$\sum_{n=1}^\infty 2^{n+1}\cdot \left(1-\frac{1}{\sqrt{2}}\right)^2$

[thorny flame]

artemetra

[round parcel]

yep thanks so much

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[dapper lagoon]

Does anyone understand this? Ive been tryna figure it out but nothing..

[dapper lagoon]

If someone could explain it w steps that‘d be amazing

[carmine lynx]

A and B are just randomly placed?

[dapper lagoon]

I have like no clue, ts was assigned to me like this

[carmine lynx]

maybe given inadequate details it would be impossible

bcuz a is constrangly moving around

so OBA is not fixed

it is unsolvable ig ?

[dapper lagoon]

Hm

[carmine lynx]

idk any clue what it may be or what u ve learnt 💀 ?

[golden jay]

nah i solved it

just gotta extend CO up

[carmine lynx]

teach me master turtle ToT

[golden jay]

then fiddle around with the angles

and arcs

[dapper lagoon]

Oh

Thats

Smart

[carmine lynx]

WHAT HOW

anyone teach me pls

id understand

[dapper lagoon]

Idk im in a math server

Anything yall say sounds smart

[golden jay]

try do what i told u then come back

[carmine lynx]

@golden jay THATS IMPOSSIBLE

bcuz A is moving

naur dont trust him 🙄

that sounds suspicious

[dapper lagoon]

Do i trust a dog or a fucking ninja turtle

the fucking ninja turtle it is

[carmine lynx]

trust me :3

...

[dapper lagoon]

[carmine lynx]

y is this illegal ;-;

anyways it is for sure unsolvable

[dapper lagoon]

But howw

All the infos r the ones on the pic

there r no other infos

😔

[carmine lynx]

oh @golden jay im very sry :(

it is solvable

@dapper lagoon sry too ToT

i lost

[dapper lagoon]

Howww

😭

[carmine lynx]

connect OA

=> ACB = 1/2 AOB

=> AOB = 2 * 40 = 80

and OAB is an isosolesce triangle

-> 2 OBA + 80 = 180

=> OBA = 50

[dapper lagoon]

Did a dog just save my arse

[carmine lynx]

:3

[dapper lagoon]

I GET IT

I LOVE YOU

PLEASE DONT EVR DIE

[carmine lynx]

aw i lub u to 😍 🫶

[dapper lagoon]

Youre so skibidi

.Close

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[mortal sphinx]

Hi

[mortal sphinx]

@acoustic pecan

Can you check if this is correct

Sorry for the trouble

[acoustic pecan]

they seem alright

[mortal sphinx]

Ok thank you

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[onyx cloak]

help factoring this

[vernal vale]

what have you tried

[onyx cloak]

2 and 3

but any other number is a decimal

[vernal vale]

the answer is decimal

[onyx cloak]

whats the answer?

[vernal vale]

,w factor x^2-2x-6

[thorny flame]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by janniku

[vernal vale]

gee thanks wolfram

[cedar wagon]

Its like 1 +- sqrt(6) so isint really factorable

[onyx cloak]

how do I do this than

[vernal vale]

holy xy

[cedar wagon]

You right, i forgot how to add

Lmao

[vernal vale]

@cedar wagon can u help them with this

im tired and thought it was a quadratic question

i dont feel like doing a word problem atm

[cedar wagon]

0.30 am 💀

[vernal vale]

5pm

[cedar wagon]

Ima try

[cedar wagon]

Kek

[onyx cloak]

this is what they told me to do

and I tried to do that'

but like

[tribal cliff]

You can just use completing the square on this one and it would show the same result

[onyx cloak]

It didnt wijr

[cedar wagon]

I think jamal should just watch the speedometer

[cedar wagon]

Where does it goes wrong ?

[onyx cloak]

I got it down to factoring

but apparently the factor I got it down to was wrong

<@&286206848099549185>

[cedar wagon]

Idk where their 8 comes from

[onyx cloak]

its how long the trail is

in that problem it was 8 miles

[cedar wagon]

Ok, i understood 3 miles in the text mb

[cedar wagon]

Why do you start with a 3 on top then ?

[onyx cloak]

distance over rate equals time

[cedar wagon]

But distance is 8 ?

No ?

[onyx cloak]

its a different problem soryr

this is a test that is a past assignment

[cedar wagon]

Ok ok

[cedar wagon]

Can you show that green one which is cut please ?

[cedar wagon]

Ty

So 3/x +2 = (2x+3)/x
So we have (2x+3)(x-2)=3x
Which is
2x^2 -4x +3x -6 -3x =0

2x^2 -4x -6 = 0
x^2 -2x -3 =0

I let u factor

[onyx cloak]

x+1 x-3

3 mph

thank you

[cedar wagon]

You're welcome

Avoid that green step, put a fraction = fraction and do cross product

Way less calculation, so less mistakes

[onyx cloak]

so

(3x+2)x(x-2)=3x

[cedar wagon]

No

2x +3

Not 3x +2

[onyx cloak]

why

[cedar wagon]

Ima latex it

$\frac{3}{x}+2 = \frac{3}{x} + \frac{2x}{x} = \frac{2x+3}{x}$

[thorny flame]

YakuBros

[cedar wagon]

See

[onyx cloak]

kinda

[cedar wagon]

And after i just use the rule saying that $\frac{a}{b} = \frac{c}{d} <=> ad = bc$

[onyx cloak]

makes sense

thank you

[thorny flame]

YakuBros

[onyx cloak]

.close

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[grim sable]

find the distance between each vertex of the triangle

[near forum]

so plot it on a graph?

how do i plot it though

[icy sky]

are you allowed to use vectors?

[near forum]

i HAVE to use

vectors

[icy sky]

ok, so which one is useful in showing perpendicular? dot product or cross product?

[near forum]

cross

[icy sky]

why

[near forum]

um idk i just guessed

im new to vectors

didnt understand the lesson so i came here

[icy sky]

cross product is 0 when two vectors are _?

[near forum]

im not sure

[cedar wagon]

The result of cross product is the area of the polygon made by the vectors, so if its 0 ?

[near forum]

its not a vector

idk

its not a polygon?

[cedar wagon]

The result of cross product is 0 when the vectors are colinear

[icy sky]

yaku can you take over? i have to go

thanks

[cedar wagon]

Which means that they have the same direction, but not neccessarly the same norm or that they both go in the same way

What about dot product ?

When dot product is equal to zero that means the vectors are orthogonals

Perpendicular if you prefer

But with vectors we use orthogonal

So to show that this is a right triangle what do we do ? @near forum

[near forum]

we have to have vectors

dot product instead @cedar wagon

sorry my mom called me

[cedar wagon]

So find AB AC and BC

[near forum]

is this the correct formula for dot product

[cedar wagon]

Find the vectors first

[near forum]

AdotB = |A| x |B| costheta

[cedar wagon]

Its one of the formula, too complicate to use there

[near forum]

vectors

sorry but how do i find the vector

[cedar wagon]

Ima latex it

$AB(x_B-x_A , y_B-y_A , z_B-z_A)$

[thorny flame]

YakuBros

[near forum]

OH

ok so

AB (-3-1, 2-2, 4-3)?

AB (-4, 0, 1)

[cedar wagon]

Perfect

[near forum]

now AC, BC

[soft surge]

hows that perfect

[near forum]

wat

its wrong?

[soft surge]

no nevermind

[cedar wagon]

Nah keep going

[soft surge]

give me one

[near forum]

AC (1-1, -4-2, 3-3)

AC (0,-6, 0)

[soft surge]

yeah true

is the "," x?

[near forum]

0 = x
-6 = y
0 = z

x y z

[soft surge]

i resolve this?

[cedar wagon]

?

[soft surge]

can yall give ms smth to

solve it

[near forum]

uhm u can verify if my CB is correct

[soft surge]

that's basic

[near forum]

BC ( 1+3, -4-2, 3-4)

[soft surge]

u just replace the unkown letters with it numbers

[near forum]

BC (4, -6, -1)

[soft surge]

true

[near forum]

ok now next

[cedar wagon]

Ok so we have two way of process now

[near forum]

is it ok if we dont close this btw?"

plz

[cedar wagon]

?

[near forum]

close the chat

[cedar wagon]

We havent finish

[near forum]

ok

thx

[cedar wagon]

So 2 possibility:
You use pythagore
Or you use dot product

Pythagore is better in this case since we dont know which angle is 90

If we knew that its for example a right triangle and Angle b is 90, then we would use dot product efficiently

Anyway lets go for pythagore ?

[near forum]

ah okok

a^2 + b^2 = c^2

what is our a, b and c here tho?

[cedar wagon]

So the formula for the norm of a vector is : $AB^2 = (x_{AB})^2 + (y_{AB})^2 + (z_{AB})^2$

[thorny flame]

YakuBros

[cedar wagon]

We will see

[near forum]

what about AC and CB

oh

wait

i get it

[cedar wagon]

Apply formula for them

[near forum]

so first let me try AB

AB^2 = 17?

sqrt 17

[cedar wagon]

Let it as 17 since pythagore is a^2 + b^2 = c^2

Dont take the root

[near forum]

oh okay

so just 17

AB = 17

[cedar wagon]

No AB^2

[near forum]

ok mb

[cedar wagon]

Like this

[near forum]

ok AB^2 = 17

[cedar wagon]

What about the others ?

[near forum]

AC^2 = 36

BC^2 = 53

[cedar wagon]

And what is AB^2 + AC^2 = ?

[near forum]

BC^2

[cedar wagon]

U chad

[near forum]

hehehe

[cedar wagon]

So its a right triangle or no ?

[near forum]

yes

[cedar wagon]

Great, and now what about the next question ?

[near forum]

we gotta use the formula

A = 1/2 x b x h

to find the height

we gotta find the perpendicular uhhh thing

i think

am i going in the right direction?

oh wait no

its a right triangle

OH

A = 1/2 x (36) (17)

o

was that a good try

[cedar wagon]

Not quite

You have AB^2 = 17 so AB = ?

[near forum]

sqrt 17

[cedar wagon]

So ?

[near forum]

A = 1/2 (sqrt 17) (6)

[cedar wagon]

Which is ?

[near forum]

3sqrt17

[cedar wagon]

Gg wp

[near forum]

thank you very much

just a heads up before we close this.

ur gonna see me again

very shortly.

like immediately after.

[cedar wagon]

If its a short question why not 💀

[near forum]

okok should i close this or post it again?

[cedar wagon]

I think you should close it and post it in another new channel to get a refresh, you will probably get help faster

[near forum]

okay, thank you very much for the help though

+vouch @cedar wagon
+rep @cedar wagon

have urself a great day unless i see u again

.resolved

.resolve

.finished

[cedar wagon]

.close

[near forum]

.close

[topaz sinew]

Channel closed

Closed by @near forum

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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[timber bison]

f(x)=ln(x), [1,3] trying to find all the numbers c that satisfy the MVT. I'm trying to see if my work is good

[topaz sinew]

@timber bison Has your question been resolved?

[timber bison]

Realized that it was sideways

<@&286206848099549185>

.close

[topaz sinew]

Channel closed

Closed by @timber bison

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bronze patio]

an someone help me find the Surface Area for this

[ivory sorrel]

!status

[topaz sinew]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[ivory sorrel]

ok, so can you find the curved surface area of both cylinders ?

[bronze patio]

oh wait nvm

i figured it out

i realised where i went wrong soz

thx anyways

.close

[topaz sinew]

Channel closed

Closed by @bronze patio

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.