#help-26

1 messages · Page 131 of 1

long stirrup
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you could memorize 6 versions of this lol

noble crest
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im interested

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what are the 6 versions?

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and uh

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what language is this

long stirrup
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it's called J

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echo hfd <. %: */ 256#.inv 16bc76466 16be5a6ec
echo hfd <. -: +/ 256#.inv 16bc76466 16be5a6ec
echo hfd <. +: %  +/ % 256#.inv 16bc76466 16be5a6ec
echo hfd XOR 256#.inv 16bc76466 16be5a6ec
echo hfd AND 256#.inv 16bc76466 16be5a6ec
echo hfd OR 256#.inv 16bc76466 16be5a6ec
noble crest
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is

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the first line multi, second add, third inverse?

long stirrup
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mult add inverse

noble crest
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alr

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i guess

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thats solved, thx

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.close

topaz sinewBOT
#
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noble crest
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.reopen

topaz sinewBOT
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noble crest
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@long stirrupwait sorry, is there a way to

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like could we declare a variable

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like

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StageOne = echo hfd <. %: */ 256#.inv 16bc76466 16be5a6ec echo hfd <. %: */ 256#.inv 16bStageOne 16be5a6ec

long stirrup
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a =. 256#. <. %: */ 256#.inv 16bc76466 16be5a6ec

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no 16b, just a

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or StageOne

noble crest
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alr

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thank you

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i will learn to memorize this

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.close

topaz sinewBOT
#
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long stirrup
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@noble crest oh wait you need commas in that case

noble crest
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its already good enough tbh

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1:00

long stirrup
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like StageOne, 16be5a6ec

noble crest
#

ill keep it in mind

topaz sinewBOT
#
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terse seal
#

I'm trying to figure out the amount of unique algorithms you can make on a Rubik's Cube with any n moves The algorithms must be unique, meaning that if two algorithms result in the same computation, they are the same algorithm. Using a quater turn metric *

topaz sinewBOT
#

Please don't occupy multiple help channels.

rigid ivy
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Imagine you could easily know how many unique algorithms existed with QTM, then we would have found God's number a lot sooner

terse seal
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The guy from the last channel left

rigid ivy
terse seal
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Can I get rid of it as mine

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I don't wanna annoy anyone

rigid ivy
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The only (known) way to find number of unique positions is by computationally searching.

inner wren
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it'll take some time ig.

rigid ivy
terse seal
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Thanks

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So uk the ans

rigid ivy
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uk?

terse seal
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U know

rigid ivy
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I know that the answer is "not easy to find an answer"

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but for 2x2 and 3x3, the number of unique positions has already been calculated

terse seal
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But what about with only 3 moves

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I'm asking the relationship between n (the moves) and how many computations

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@rigid ivy

rigid ivy
terse seal
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Why 18 after 1 move?

rigid ivy
terse seal
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What defines distance

rigid ivy
terse seal
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So 1 can lead to 12

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Y does it say 18

rigid ivy
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Because there are 18 possible first moves in HTM

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Here's QTM

terse seal
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Why not 12 ht moves

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6 sides 2 directions

rigid ivy
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90, 180, or 270 degree rotation

terse seal
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But 3r=r'

rigid ivy
terse seal
rigid ivy
terse seal
#

Qtm and single turn metric are different

terse seal
#

I don't entirely get it but than you

rigid ivy
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what don't you get?

terse seal
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Distance

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What is it

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How many moves till solved??

rigid ivy
rigid ivy
rigid ivy
terse seal
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So how did they get those numbers

rigid ivy
rigid ivy
terse seal
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Humans can't do the math?

rigid ivy
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Not currently, no.

terse seal
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There isn't a pattern like the nth term?

rigid ivy
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Nope

terse seal
rigid ivy
terse seal
rigid ivy
terse seal
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Oh

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So that's 12×11^n-1 is an estimqte

rigid ivy
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Yes. It's just a lower bound

terse seal
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But I'm asking about how many permutations can be made with 3 moves

rigid ivy
terse seal
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And if was computers

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So there is no pattern??

rigid ivy
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what?

terse seal
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Like you can't figure it out on ur own

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You need python

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Or something

rigid ivy
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Yeah there's no known simple algorithm for it

terse seal
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That explains why I can't figure it out lol

rigid ivy
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yes

rustic finch
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lol wait that’s funny i’m in another server tom rockicki (one of the people who proved god’s number is 20) is in

rustic finch
rigid ivy
rustic finch
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where is the result that there are 3 stated?

rigid ivy
rustic finch
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oh

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ok i’ll ask lol

topaz sinewBOT
#

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topaz sinewBOT
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bright dagger
#

How do I find the column space?

topaz sinewBOT
bright dagger
topaz sinewBOT
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crisp vapor
#

hi

topaz sinewBOT
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brittle atlas
blazing shoal
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Its in Q1 because the domain is from 0 to pi/2

brittle atlas
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hmm

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the angle is less then pi/2 so how come it wouldn't be left of 90 degrees?

blazing shoal
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the angles increase counterclockwise

brittle atlas
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oh i see thank you

blazing shoal
topaz sinewBOT
#

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neon iron
#

please help me

topaz sinewBOT
vernal vale
#

show your work

topaz sinewBOT
#

@halcyon kite Has your question been resolved?

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celest quest
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what constraints on b1, b2, b3 wold make this system on equations on Z mod 7 have 0 solutions, 1 solutions, or more than 1 solution?

celest quest
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so i row reduced the matrix

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and got this

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now we get 0 solutions if the bottom row if b's equals 0 mod 7

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but what about 1 solution?

opal vault
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you get 0 solutions if 5b1+b2+b3 is NOT 0 mod 7

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because then the system is inconsistent

celest quest
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oh yeah oops typo

opal vault
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otherwise, b3 = 2b1 + 6b2, and the last row can be removed

celest quest
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or mental typo rather

opal vault
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so reduced echeloned system

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with 2 equations

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3 unknowns

celest quest
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yeah

opal vault
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how many solutions does this system have?

celest quest
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well i need to constraint the b's to have only 1 solution

opal vault
celest quest
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i dont know thats what im asking lol

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i mean the question imples its possible

opal vault
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well that's what I was asking

celest quest
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because its asking when would it have 1 solution

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unless it expects me to write never

opal vault
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never is an answer

celest quest
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it is but its usually a wrong one

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so the answer here is never?

opal vault
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well think about it

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we either have 0 solutions

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or a system that simplifies to "x1 = exactly this, and x2 + x3 = exactly this"

celest quest
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yeah or the solutions are relative to x2

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or x3

opal vault
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yeah so x2 = 6x3 + ...

celest quest
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but i thought there might be some trick with mod 7

opal vault
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x3 is left "undecided"

celest quest
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that im missing

opal vault
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doesn't change regarding the field

celest quest
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right

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alright thanks

#

.close

topaz sinewBOT
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prisma grail
#

could this be sec y° = 8/t?

topaz sinewBOT
lean pebble
#

Yep

topaz sinewBOT
#

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fossil matrix
topaz sinewBOT
fossil matrix
# fossil matrix

This is coming from a friend of mine. Im not quite sure what any of this is, but if somebody has questions or what not, feel free to ask lol

topaz sinewBOT
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neon iron
#

what does the "and tan" do to our problem

topaz sinewBOT
neon iron
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and tan less than 0

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what does that mean i have to factor

raven sparrow
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Can you visualize when tan(theta) < 0?

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LIke quadrant-wise

neon iron
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ohhhh

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its quadrant 2 and 4

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rigghr

cinder sequoia
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and specifically, if tan = sin/cos, and you know the sign of cosine and that tan is negative, it gives you useful information about the sign of sine

neon iron
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cause negative

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makes sense

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thanks guys!

#

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rancid viper
#

why isnt it k=0 and k=4 instead of k<0 andk>4

kindred cloud
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You want your discriminant to give you two distinct values. Think about what happens when you look at the whole quadratic formula and you substitute in b=k and c=k

rancid viper
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im so sorry im not sure i understand

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wouldnt we get the zeros if we substitute it in?

kindred cloud
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Apologies for my bad handwriting, im on my phone atm

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But notice the plus and minus sign just before the square root

rancid viper
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yeah

kindred cloud
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If you let a=1, b=k, and c=k, what happens inside the square root?

rancid viper
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k^2 - 4k?

kindred cloud
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Correct! We want this value to be greater than zero

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The reason we want it to be greater than zero is because when you take the square root of it, then apply the plus and minus, you will get two different results and hence two different x-intercepts

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So now you have to solve k^2 - 4k > 0

rancid viper
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ohh just like what was in the image right

kindred cloud
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Yep

rancid viper
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but then shouldnt k be bigger than 0 and not smaller than 0?

kindred cloud
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That’s a good question, let’s see what is happening in the image

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So when you get to k(k-4) > 0, think about what happens if you let k < 0

rancid viper
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there are no roots right

kindred cloud
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Will the overall result be positive or negative?

rancid viper
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negative

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oh wait

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im stupid

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it wil be positive i think

kindred cloud
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No you’re not, I’m glad you caught it

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Yes it will be positive ;)

rancid viper
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ohhh i see so thats why we want k to be smaller than 0

kindred cloud
#

Yep

rancid viper
#

kk tysm

kindred cloud
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Ofc

rancid viper
#

hope you have a great day

kindred cloud
#

Ty, you too :D

rancid viper
#

.close

topaz sinewBOT
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deft holly
#

hi I'm having trouble with 11a

topaz sinewBOT
deft holly
#

Where did the m come from?

raven sparrow
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It would be better if they told you what m is, but it's clear from context that it's a nonzero constant.
It doesn't actually matter the value of m, any one will give a tangent line

deft holly
raven sparrow
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One thing you can do is express both as y = f(x) and show that their difference has a double root

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This shows that the parabola "bounces" on the line in a single point

deft holly
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this is my working out right now

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If i wanted to show my last eq is a dbrt, what would I do? Ive only learnt showing a specific point is a dbrt so im unaware if theres any other way to show

raven sparrow
#

You have to show the discriminant is always 0

deft holly
raven sparrow
#

a = m^2, b = -m , c = -16

deft holly
#

Ahhh

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Okok

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Thanks

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.close

raven sparrow
#

No worries !

topaz sinewBOT
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vocal mauve
#

Hello , sorry to bother anyone i just need help solving some math problems

cinder stream
#

I can help! (im not very good at math)

cinder stream
vocal mauve
cinder stream
#

alrighty so

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i think in this question you just wanna plug in your table and see if its true/or false

vocal mauve
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Do I calculate it ?

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like the numbers ?

cinder stream
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Yep! do you need help on how to?

vocal mauve
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Yes please

cinder stream
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I gotchu!

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ok so looking at your table, you're just going to plug in where r is as 1, and s is a 9

cinder stream
#

so 3-12 basically

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3-12 would give us -9

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which is not true
as 9 is not equal to -9

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so we can do the same for the rest of the questions

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you could also use somthing like slope to find out the equation(if you have learnt that)

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slope = y2-y1/x2-x1

cinder stream
vocal mauve
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Yes please

cinder stream
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*its the change in y(in this case they've given us s) in respect to our x(r in this case)

vocal mauve
#

Oh Okay , I will try to solve this question , can I let you know if I think I figured it out or no ?

cinder stream
vocal mauve
#

Okay

cinder stream
#

pardon my horrible handwritting lol

vocal mauve
#

Thats okay lol

cinder stream
#

so have you found what or slope(or M value would be?)

vocal mauve
#

Not exactly

cinder stream
#

anything i can help with?

vocal mauve
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Im just completely lost in all of this , my brain isn’t clicking to solve this math problem sorry

cinder stream
#

Ok i gotchu

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we'd get -3

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slope would give us -3

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which leaves C, or D

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its basically finding the equation of the line, which is y=mx+b
m being our slope(-3)
and b being out y intercept(where this graph would meet the line)

vocal mauve
#

I think I get it a little more now

cinder stream
#

yeah

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so basically you're going to want to do
0=-3(4)+b

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and solve for b

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this gets us our intercept

vocal mauve
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okay I’ll attempt to solve it

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B would be 12?

cinder stream
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yep!

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so now we can contruct our answer( and the equation of the line)

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we have our b value

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and our m value

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so s=-3r+12

vocal mauve
#

So it would be d right ?

cinder stream
#

yep!

vocal mauve
#

Okay thank you so much for your help

topaz sinewBOT
#

@vocal mauve Has your question been resolved?

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drifting briar
#

which type of contour should i use to find the inverse laplace transform of the following function using mellin's formula?

drifting briar
#

$f\left(x\right)=\frac{1}{x^{2}+1}$

thorny flameBOT
#

Jill ♡

drifting briar
#

i chose x as my variable here

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i know the solution is gonna be sin(t) but I dont know how to get there

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i dont really understand how i can simplify this into something i can solve with the residue theorem

topaz sinewBOT
#

@drifting briar Has your question been resolved?

drifting briar
#

i think i got it

#

yea

#

.close

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bright plank
#

Hi

topaz sinewBOT
wooden moon
bright plank
#

lim x->a √x = √a, is that the same as lim x-> a √x = lim a->a √a

dense crescent
#

a=a

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how would u say a tends to a

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→ means x is approaching a but not equal to a

bright plank
#

i mean in my textbook it says lim x->a √x - √a = 0, i.e. lim x->a √x = √a but i dont get how those both are the same

dense crescent
#

ok so

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while solving limits

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if u dont see any indeterminate forms

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u substitute the value of x which is tending

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ie here lim x→a so u substitute x=a

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do u have idea about indeterminant forms?

bright plank
#

not really no

dense crescent
#

ok

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so indeterminant forms are something like

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0/0

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infinity/infinity

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0 x infinity

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0^infinity

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1^infinity

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infinity-infinity

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and infinity^0

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ever heard of these?

meager dawn
bright plank
#

ill learn them for sure

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but lim x->a √x = √a

i didnt understand this above very well

dense crescent
dense crescent
#

u can substitute x=a here

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in root(x) - root(a) u see no indeterminant form

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and as lim x→a u do x=a

bright plank
#

so does that mean this is saying that lim x->a f(x) = f(a)

dense crescent
#

yes

bright plank
#

ok thanks ill look into it.

#

.close

topaz sinewBOT
#
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quick holly
#

"Proof by deduction"

topaz sinewBOT
quick holly
#

whats the point of completing the square??

cedar wagon
#

Factor a quadratic

worthy storm
#

it makes it obvious that the polynomial can't be negative

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because both (x+2)^2 and 1 are nonnegative

quick holly
#

what about the inequality?

worthy storm
#

"nonnegative" means >= 0

quick holly
worthy storm
#

because they want to show that it's strictly positive i guess

#

(x+2)^2 is >= 0
then you add 1 so now you're >= 1, which is strictly >0

quick holly
#

I see

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ty!

gilded edge
#

You can say that

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That is rewritten as

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(x+2)^2 +1

gilded edge
quick holly
#

I see

quick holly
worthy storm
#

for quadratics that's the most straightforward way

quick holly
#

I see

#

thanks

worthy storm
#

you could also use calculus if you want

quick holly
#

differentiation?

worthy storm
#

yeah, the minimum will occur at a point where the derivative is zero

quick holly
#

i see

#

alright thanks

quick holly
#

.solved

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neon iron
#

Hello I was learning the proof of
limit x -> 0 sinx/x by squeeze thereum
However I have a question
lim x-> 0 (1) ≥ lim x-> 0 Sinx/x ≥ lim (x->0) cosx
Now if theta is approching from the 4th quadrant then the limit of sinx/x is negative but the COSX is positive
How can -ve ≥ +ve
How is this valid limit
If L.H.L of inequalities ≠ R.H.L

wooden moon
#

so it's true for pi/2>theta>-pi/2

#

enough for us in this case

topaz sinewBOT
#

@neon iron Has your question been resolved?

neon iron
# wooden moon so it's true for pi/2>theta>-pi/2

Yes it's true for theta > -90° or 270°
Here is what I am asking: suppose theta is approching from the 4th quadrant and theta is now 300° = 5.236 radian
Now sin(5.236)/5.236 is -0.8660
And cos(5.246) is 0.5
Now sinx/x ≥ COSX is invalid for all the values of x in 4th quadrant
Then how can we say that it's true for
90° > x > -90°(or270°)

wooden moon
#

who said that it's true in the fourth quadrant?

neon iron
#

x > -90°
Isn't this mean that it is approaching from the 4th quadrant?

wooden moon
#

no

#

where is the fourth quadrant?

#

seee for the values around x =0

#

what is the sinx/x there

#

we are simply not concerned with 4th quadrant here

neon iron
#

🤔
I am not in good condition to understand this graph just tell me theoretically
x > -90° means x>270° then this mean it is approaching from 4th quadrant
Maybe I too dumb to understand this
I have to think for few minutes

wooden moon
#

sinx/"x"

#

we're also dividing by the angle

neon iron
#

Aaaaah
Yes

wooden moon
#

so we cannot simply say -pi/2 = 3pi/2

neon iron
#

Yes

#

Thank you so much

#

🙏

#

God bless you

#

.close

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inner wren
#

nth term = n^3-3^n
starting from 1

topaz sinewBOT
inner wren
#

sum

#

i'm unable to get the sum 3^n

lime perch
#

$\sum_{k=1}^n k^3-3^k$

inner wren
#

ifninity?

lime perch
#

is this not what you meant?

inner wren
#

no. sum of this expression, till n terms starting from 1, basically

#

i can reduce the question to:
Sum of powers of 3 till nth power.

restive inlet
#

$\sum_{i=1}^n (i^3-3^i)$

thorny flameBOT
#

ℝαμΩℕωⅤ

inner wren
#

yeah

restive inlet
#

the part with 3^i will be a geometric series

inner wren
#

GP?

#

geometric progression?

#

ok

thorny flameBOT
#

Flappie

inner wren
#

yeah

#

so basically,

ar+ar^2+ar^3+ar^4
where r = 3 and a=1
ar(1+r+r^2+r^3+r^4.....)
ar(1+r(1+r+r^2+r^3+r^4......))
ar(1+r(1+r(1+r+r^2+r^3+r^4....)))

ikr its in gp. but how to get the suM?

#

3^n-(1/3) * 3^n - (1/3)*3^(n-1)..........

#

3 + (3+6) + ((3+6)+ 6+12)) + (((3+6) + 18) + 6+12+36)......

#

<@&286206848099549185>

wooden moon
#

geometric series

inner wren
#

ikr

#

ok, yk just give the formula

wooden moon
inner wren
#

ok, i'lll see. gtg

#

.close

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#
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broken fulcrum
topaz sinewBOT
broken fulcrum
#

help

#

whats logbkx supposed to mean

#

ie the lhs

lime perch
#

i think it means base b^k

broken fulcrum
wooden moon
#

do you need to prove log x^n = n log x

#

or that is proven

lime perch
wooden moon
#

use log_b(a) = loga/logb

broken fulcrum
broken fulcrum
lime perch
#

you start from the left hand side

#

and then use your log rules to get to the right hand side

broken fulcrum
#

does the bk get multiplied by x?

wooden moon
#

no

lime perch
#

no

wooden moon
#

b^k is the base

#

as already stated by flappie

broken fulcrum
#

so what do u do

lime perch
#

do you know your log rules?

broken fulcrum
#

ik these

topaz sinewBOT
#

@broken fulcrum Has your question been resolved?

broken fulcrum
broken fulcrum
broken fulcrum
#

.close

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thorny flameBOT
#

nino
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

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inner wren
#

solution

topaz sinewBOT
cursive patrol
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livid gazelle
#

@everyone pls tell tthis

topaz sinewBOT
inner wren
#

let one be n.

halcyon kestrel
#

Hold on

#

What do you want us to tell? The answer?

#

Or how it works?

inner wren
#

so (n-15)(n+17) = 0
therefore, the numbers are 15 and 17. 🙂

halcyon kestrel
# halcyon kestrel Or how it works?

x = 15 or - 17. But since the odd integer can be positive only, x = 15. The other positive odd integer becomes 15 + 2 = 17. The larger integer = 17.

topaz sinewBOT
#

@livid gazelle Has your question been resolved?

light anvil
#

I'd just do (2n+1)(2n+3)=255, giving n=-9 and n=7, discarding n=-9 and substituting n=7 you get that the biggest is 17

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neon iron
#

$\vert\vert\text{A}\vert\vert={\vert\text{A}\vert}^{n}$

thorny flameBOT
#

pun pun

neon iron
#

is this true?

#

where |A| is determinant and n is the order of that determinant

#

im feeling like its wrong but my teacher did a question using this property this morning

topaz sinewBOT
#

@neon iron Has your question been resolved?

mellow cypress
neon iron
#

|A| means determinant of A

#

and | |A| | means determinant of determinant of A?

topaz sinewBOT
#

@neon iron Has your question been resolved?

lime perch
lime perch
#

but what is the point of taking the determinant twice?

#

the determinant of a scalar is just the same scalar

golden blade
#

so true

wary tulip
#

pun pun

#

i cannot image ||A|| is the determinant of the determinant of A

#

it must be a matrix norm

lime perch
#

a scalar is just a 1x1 matrix, no?

#

wait that doesnt make sense

#

nvm

#

since then you wouldnt be able to multiply a scalar by a matrix

pseudo sonnet
#

what's the context behind this

topaz sinewBOT
#

@neon iron Has your question been resolved?

neon iron
#

man i dont know what a norm is

#

wait hold up

#

lemme just actually type the question

#

If A is a matrix of order 3 such that $\vert \text{A}\vert=5$ and $\text{B}=\text{adj}(\text{A})$, then the value of $||A^{-1}|(AB)^{T}|$ is equal to

#

fuck

thorny flameBOT
#

pun pun

neon iron
#

ok we good now

#

so this is the question

#

the solution is so cursed i dont even think its appropriate to send

urban grove
#

I think the relevant property you're thinking of is that if (c) is a scalar and (A) is an (n\times n) matrix, then (\det(cA) = c^n \det A)

thorny flameBOT
#

kalman_filtERIC

urban grove
#

is this what you meant by the original question? @bleak crystal

#

ah shoot pinged wrong person, sorry

#

@neon iron

neon iron
#

lmao im here

#

hold up

#

nah this is some other property, i know this property, but in this case i was not talking about this one.

#

should i just acutally send the solution

urban grove
#

Sure

neon iron
#

like the way our teacher made us solve that

#

oh ok

#

here @urban grove

#

$|adj(A)|=|A|^{n-1}$ where n is the order of the matrix

#

ive used this

#

i raised my original question because of this

#

OR we could just dump this solution and try to figure out some other way to solve this

thorny flameBOT
#

pun pun

urban grove
#

[\left|\frac{\operatorname{adj}(A)}{|A|}\right| = \frac{|\operatorname{adj}(A)|}{||A||}]

thorny flameBOT
#

kalman_filtERIC

urban grove
#

This line makes no sense

urban grove
#

We can see that it should be

#

[\left|\frac{\operatorname{adj}(A)}{|A|}\right| = \frac{|\operatorname{adj}(A)|}{|A|^3}]

thorny flameBOT
#

kalman_filtERIC

urban grove
#

And I believe that's what you're confused about? @neon iron

neon iron
#

OHHH

#

seems like i wrote wrong things in my notes

neon iron
#

and i get it now

#

thanks a lot eric 😭

#

imma close now

#

.close

topaz sinewBOT
#
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urban grove
#

no problem! :)

topaz sinewBOT
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delicate cave
#

https://youtu.be/-ylIGciS7_8?t=166 what he does when he solves for the variable "a" confuses me, I dont really know how to cross multiply two equivalent fractions with one containing a variable and what he does Instead by swapping and multiplying by 2 confuses me even more

Watch Sal work through a harder Solving systems of linear equations problem.

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rose sierra
#

The point is you want a value of a such that no solution exists

delicate cave
#

I understand that

#

its how he solves for a that confuses me

rose sierra
#

Since one of the equations is $9x-14=-3$, you want the second equation to be equivalent to $9x-14=k$, where $k \neq -3$.

thorny flameBOT
rose sierra
#

i.e. you want to the ratio of the x coefficient to the y coefficient to be -9/14

#

so $\frac{2}{-a}=\frac{9}{-14}$

thorny flameBOT
delicate cave
#

Im sorry but I dont think thats the solution

rose sierra
#

isn't that literally what he wrote

#

without the negative signs on each side

delicate cave
#

the solution to the problem is 28/9 but thats not what im asking, im asking about what he was doing when solving for A

#

Ok I think I figured it out

#

.close

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sterile schooner
#

can help me combine this transfer function

sterile schooner
#

from Pc(s)/E(s), i cannot from that

gilded edge
#

I thank god daily i no longer do signal theory

sterile schooner
#

the Pc(s)/E(s) i did. it different with the answer from the book, i dont know why

gilded edge
#

Whats the books answerr

#

Can I see

sterile schooner
#

page 312

#

modern control engineering book

sterile schooner
#

dont know where i wrong

#

4 hours for this

topaz sinewBOT
#

@sterile schooner Has your question been resolved?

gilded edge
#

Bro gave me the entire book

sterile schooner
topaz sinewBOT
#

@sterile schooner Has your question been resolved?

sterile schooner
#

<@&286206848099549185>

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steel mauve
#

no comprendo 😿

topaz sinewBOT
steel mauve
#

<@&286206848099549185> 😿

topaz sinewBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

#

@steel mauve Has your question been resolved?

steel mauve
#

<@&286206848099549185>

#

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steel mauve
#

.reopen

topaz sinewBOT
#

steel mauve
#

.close

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steel mauve
#

.reopen

topaz sinewBOT
#

steel mauve
#

guys im going to bed if some1 can help while i sleep plz do so it would be much appreciated, thank you

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@steel mauve Has your question been resolved?

steel mauve
#

<@&286206848099549185>

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proven tundra
topaz sinewBOT
proven tundra
#

doing PLU decomp

#

i get the correct pivot L and U matrix

#

but i dont get how when i multiply all of the matrices

#

i do not get A

topaz sinewBOT
#

@proven tundra Has your question been resolved?

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#

@proven tundra Has your question been resolved?

neon iron
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placid token
#

prove that tan200. Tan115 = 1+ tan200 + tan115

placid token
#

im still confused

#

asf

smoky sparrow
#

and similarly, tan 115 = tan(-65) = -tan 65

placid token
smoky sparrow
#

corrected

placid token
#

ye

#

whats next

smoky sparrow
#

hold on

placid token
#

it will be cot 20

#

waitnowaitno

#

in second and fouth quadrant tan changes to cot

#

so tan(180+20 = +tan20

#

tan(180-65) = -cot65?

#

✝️

smoky sparrow
placid token
#

tan becomes cot in second quadran

#

second and fourth

smoky sparrow
#

oh wait it might be the tan addition formula

placid token
#

what

smoky sparrow
placid token
#

what

smoky sparrow
#

you should really revise your trig identities

placid token
#

yes

#

how did u get tan(a+b)?

smoky sparrow
#

and then just rearrange for tan 20 * tan 115

smoky sparrow
#

this looks pretty similar to your question so I said I might as well try it

smoky sparrow
#

like don't be afraid to try different stuff

placid token
#

how did u get ttan(20+115)

smoky sparrow
placid token
smoky sparrow
#

tan(135) is -1

placid token
#

formula is in addition

smoky sparrow
placid token
placid token
#

you have to solve via lhs only

#

am hella confused

smoky sparrow
#

we've started from something that is true and manipulated it to arrive at your identity

#

we didn't assume what we were trying to prove

placid token
#

ATellstep

#

tell step 1

#

what did u rearrange

smoky sparrow
#

you're probably in disbelief I know

placid token
#

bruh

#

how did u get tan(20+115)

#

?!?!

#

there isn't any a+b

smoky sparrow
#

dude I'm done discussing this with you

#

sleep on it and come back the next morning

placid token
#

yo

placid token
#

tan 315 = -1

#

tan(200+165) = -1

#

tan200+ tan165/ 1- tan200tan165 = 1

#

tan200 + tan165 = 1 - tan200tan165

#

Is that correct

#

115* not 165

#

tan200tan165 = 1-tan200tan115

#

what after this @smoky sparrow

#

...

fast jay
#

@placid token I'll help you give me a sec I'll try it

fast jay
#

solved

placid token
fast jay
placid token
#

i understood

fast jay
#

hm

#

i see no other way tbh

placid token
#

my teachers gonna give a 0

fast jay
#

tell them they are delusional from me

#

so how

placid token
placid token
fast jay
#

that's true but why

placid token
#

tan 315 = tan(200+115) = -1

#

then tan(a+b)

#

tan 200+ tan115/ 1- tan200tan115 = -1

#

tan200+ tan115 = -1(1-tan200tan115)

fast jay
#

well that's litterally what i did just inversely but ok, L teachers tbh

placid token
#

tan 200+ tan 115 = -1 + tan200tan115

#

damn i solved it

fast jay
#

in fact

#

you messed up some signs before

placid token
#

@fast jay

#

im still confused when to take negative signs

fast jay
#

honestly my method was better because it shows more thatyou can see some patterns

#

but fine i guess

placid token
#

when converting cot to tan Or sin tto cos

fast jay
placid token
fast jay
#

huh

#

well believe me

#

between 0 and 90 it's positive

#

90 and 180 negative

#

180 and 270 positive

#

270 360 negative

placid token
fast jay
#

same for cotangent but the result is 1/tan

placid token
fast jay
#

try drawing it

placid token
#

tan(200-180)?

#

is that possible

fast jay
#

oh he messed up here

#

tan(200-180)=-tan20

#

there's a minus

#

try drawing this aswell and you see

#

oh wait

#

nope im stupid

#

there's no minus

#

so he was right here aswell

placid token
fast jay
#

you always might have to draw the angles and look at the tangent if you are unsure

fast jay
#

tan

placid token
#

I'm so lazy

#

i refuse to draw

fast jay
#

then you won't make the exercise correctly

#

you'll get lost unless you're very good at it

placid token
fast jay
#

if you can i guess

#

I'd check on paper

#

because you can't go wrong on paper, but you can in your mind

placid token
#

(although I messed up here)

placid token
#

theres just too many forformulaes

#

i memorise one and another comes

fast jay
#

which ones

#

there's only tan(a+b) and tan(a-b)

placid token
#

sin A

#

sinC + sinD

#

theres so many

fast jay
#

practice a lot

#

i remember all of them and I've done them 3 years ago

placid token
#

can u guess my age

#

?

fast jay
placid token
#

ob

fast jay
#

idk 16-17?

placid token
#

oh

placid token
#

16

fast jay
#

makes sense

#

yeah practice a lot

placid token
#

and u?

#

if you're comfortable

fast jay
#

don't just memorize, practice using them

fast jay
placid token
fast jay
#

at first you'll have to have the formula in front but then you won't need it

placid token
#

thnx @fast jay

fast jay
#

np

placid token
#

.close

topaz sinewBOT
#
Channel closed

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topaz sinewBOT
#
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Show your work, and if possible, explain where you are stuck.
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glossy adder
#

What in the hell does this mean

topaz sinewBOT
ionic oar
#

Do you know the quadratic formula

#

[ ax^2 + bx + c = 0 \implies x = \f{-b \pm \s{b^2 - 4ac}}{2a} ]

rapid wyvern
#

2z?

pseudo jetty
#

2z hmmcat

rapid wyvern
#

Peculiar

thorny flameBOT
ionic oar
pseudo jetty
#

well its no longer a secret now is it thonkZoom

topaz sinewBOT
#

@glossy adder Has your question been resolved?

topaz sinewBOT
#
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#
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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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icy rapids
#

How can I shift this portion of the graph, so that the base touches the origin?

icy rapids
#

,rotate

thorny flameBOT
jade thunder
#

Move it up by 1?

icy rapids
#

No sorry, maybe it's not clear from the photo, I have to move the undeleted part

jade thunder
#

I don’t know what the undeleted part is

icy rapids
#

The one between the points (0,1),(-1/√2,1/√2),(1/√2,1/√2)

#

<@&286206848099549185>

solid fog
#

You need to shift the circle up by one?

icy rapids
#

No, i Need to shift this part

solid fog
#

Do you have the original question?

icy rapids
#

Is this

solid fog
#

So you want that line to be represented as the x-axis?

#

Then its equation would be y = 0

#

If its across the origin

#

I dont understand the purpose of the question

icy rapids
#

I have to move that part below, so that the base of that part is at the origin

solid fog
#

Base of a straight line?

#

Do you speak spanish

icy rapids
#

Yes

#

No

solid fog
#

Base of a straight line is something I have never heard

#

It's a one dimensional shape

#

I still don't understand the problem

#

What exactly are you trying to get? An equation?

icy rapids
#

I need to move that red part to the origin

solid fog
icy rapids
#

Wdym

solid fog
#

Like $f(x) \rightarrow f(x) - \frac{\sqrt{2}}{2}$

thorny flameBOT
#

quevivamexico

icy rapids
#

We can try this

solid fog
# icy rapids .

Problema is its not a function... I dont know what the question is

#

If you wanted it to be at the origin you say "I would shift it vertically by -sqrt(2)/2 units"

topaz sinewBOT
#

@icy rapids Has your question been resolved?

topaz sinewBOT
#
Channel closed

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#
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Show your work, and if possible, explain where you are stuck.
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devout veldt
#

Can someone explain this to me please

topaz sinewBOT
lime perch
#

have you tried plotting it in the complex plane?

devout veldt
#

Ive seen a couple problems so far that involve complex numbers and stuff but I dont remember learning it

lime perch
#

i know the drawing is shit but bear with me

#

does this make sense?

devout veldt
#

Yeah i get that

lime perch
#

so, how would you find this angle?

devout veldt
#

is that 5 times 12i?

lime perch
#

its meant to be a minus

#

same as this

devout veldt
#

then (5-12i) - 12i no?

#

that would be the reference angle

lime perch
devout veldt
#

I think you lost me

#

why is -12i at the 270 angle

lime perch
#

what??

#

its just plotting a point

devout veldt
#

oh ok i got it

#

dont worry

lime perch
#

when you plot a point you usually draw a vertical and horizontal line to the axes so that you show where its at

devout veldt
#

i was thinking unit circle type stuff

lime perch
#

in this case i did double, because i showed the x and y aswell as the x and y at the point

devout veldt
#

idk how i would find the angle of that

lime perch
#

do you know how the find the angle here?

devout veldt
#

yeah

#

that inverse tan

lime perch
#

so you do know how to find the angle

devout veldt
lime perch
#

it can be either

#

you can write it as (x,y) or as (r,theta)

devout veldt
#

i got the angle of 296

#

but. the only thing im confused about

#

is why 5 is x axis and -12 is y axis

lime perch
devout veldt
#

why not

lime perch
devout veldt
#

I mean it was the correct answer

devout veldt
lime perch
#

im getting 292.6 as my angle

devout veldt
lime perch
#

do you know how to plot complex numbers?

devout veldt
#

do you mean like 2i + 3j + 4k?

lime perch
#

thats not a complex number

devout veldt
#

then no

#

i didnt learn them i dont think'

#

no recollection of it

lime perch
devout veldt
#

idk what you would call it exactly

lime perch
#

youve never seen something like this?

#

ugh, that looks awful when i paste it here

#

anyway, its readable sorta

devout veldt
#

no

#

never seen that

#

am i supposed to learn that in precal or under?

lime perch
#

you are dealing with complex numbers

#

im pretty sure something like this is one of the first things you would learn with them

devout veldt
#

im in summer classes rn and i havent seen it

#

probably good to know though

lime perch
devout veldt
#

idk tbh thats why I asked if someone could explain it to me

lime perch
#

okay

#

the general form of a complex number is a+bi

#

we can graph complex numbers in a 2D plane

#

we take the real part (a) to be the x

#

and we take the imaginary part (bi) to be the y

devout veldt
#

seems simple enough

lime perch
#

the x value is 3

#

and they y value is 4i

#

and so we can make a triangle with sides 3 and 4

#

and from there we can calculate its angle and thus write it in polar form

devout veldt
#

that really helps

#

cause I kept seeing i and didnt know what it meant

lime perch
#

i is the complex number

#

by definition $i^2=-1$

thorny flameBOT
#

Flappie

devout veldt
#

oh yeah and how i is sqrt-1

#

i remember now

#

never remember graphing it though

lime perch
#

well, its a very useful tool

#

so use it

devout veldt
#

thank you

#

.close

topaz sinewBOT
#
Channel closed

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topaz sinewBOT
#
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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

short iris
#

Let f : [0,1] → R be of class C1 such that f (0) = f (1) = 0. Show that for all a ∈ R, the function f′ + a f cancels on ]0,1[.
I need help. With rolle f cancel but for f'

short iris
#

= 0

#

@grim pulsar

odd pagoda
#

well thats just clearly false. can you give a picture of the question

topaz sinewBOT
#

@short iris Has your question been resolved?

short iris
rose sierra
#

cancels means equals 0 for all x in [0,1]?

short iris
#

no