#help-26
1 messages · Page 131 of 1
it's called J
echo hfd <. %: */ 256#.inv 16bc76466 16be5a6ec
echo hfd <. -: +/ 256#.inv 16bc76466 16be5a6ec
echo hfd <. +: % +/ % 256#.inv 16bc76466 16be5a6ec
echo hfd XOR 256#.inv 16bc76466 16be5a6ec
echo hfd AND 256#.inv 16bc76466 16be5a6ec
echo hfd OR 256#.inv 16bc76466 16be5a6ec
mult add inverse
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✅
@long stirrupwait sorry, is there a way to
like could we declare a variable
like
StageOne = echo hfd <. %: */ 256#.inv 16bc76466 16be5a6ec echo hfd <. %: */ 256#.inv 16bStageOne 16be5a6ec
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@noble crest oh wait you need commas in that case
like StageOne, 16be5a6ec
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I'm trying to figure out the amount of unique algorithms you can make on a Rubik's Cube with any n moves The algorithms must be unique, meaning that if two algorithms result in the same computation, they are the same algorithm. Using a quater turn metric *
Please don't occupy multiple help channels.
Please stay in one channel, or at least close your old one. Anyway, your problem is very hard to solve.
Imagine you could easily know how many unique algorithms existed with QTM, then we would have found God's number a lot sooner
The guy from the last channel left
Yeah but it's your channel
The only (known) way to find number of unique positions is by computationally searching.
it'll take some time ig.
I already closed it for you. In the future, do .close
uk?
U know
I know that the answer is "not easy to find an answer"
but for 2x2 and 3x3, the number of unique positions has already been calculated
But what about with only 3 moves
I'm asking the relationship between n (the moves) and how many computations
@rigid ivy
Why 18 after 1 move?
what?
What defines distance
Number of half-turn moves
half turn means you could do 3 twists on any one side
90, 180, or 270 degree rotation
But 3r=r'
Yes. And that's still a distinct twist from r and r2
That's single turn metric
Qtm and single turn metric are different
what don't you get?
Distance is just number of moves
And here, distance is number of quarter-turn moves
So how did they get those numbers
computers
Humans can't do the math?
Not currently, no.
There isn't a pattern like the nth term?
Nope
screenshot, please
But I'm asking about how many permutations can be made with 3 moves
1,068
what?
Yeah there's no known simple algorithm for it
That explains why I can't figure it out lol
yes
lol wait that’s funny i’m in another server tom rockicki (one of the people who proved god’s number is 20) is in
mentioned on this
Ask him to share the three known positions that require 26 QTM moves
where is the result that there are 3 stated?
here
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How do I find the column space?
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hi
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https://gyazo.com/8bacfcec9c7af79d8da6fb13bdcedda4 Im struggling reading what quadrant this angle would be in my guess is quadrant 2 but could someone explain to me why?
the angles increase counterclockwise
oh i see thank you
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please help me
show your work
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what constraints on b1, b2, b3 wold make this system on equations on Z mod 7 have 0 solutions, 1 solutions, or more than 1 solution?
so i row reduced the matrix
and got this
now we get 0 solutions if the bottom row if b's equals 0 mod 7
but what about 1 solution?
you get 0 solutions if 5b1+b2+b3 is NOT 0 mod 7
because then the system is inconsistent
oh yeah oops typo
otherwise, b3 = 2b1 + 6b2, and the last row can be removed
or mental typo rather
yeah
yeah
how many solutions does this system have?
well i need to constraint the b's to have only 1 solution
is it even possible now?
well that's what I was asking
because its asking when would it have 1 solution
unless it expects me to write never
never is an answer
well think about it
we either have 0 solutions
or a system that simplifies to "x1 = exactly this, and x2 + x3 = exactly this"
yeah so x2 = 6x3 + ...
but i thought there might be some trick with mod 7
x3 is left "undecided"
that im missing
doesn't change regarding the field
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could this be sec y° = 8/t?
Yep
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This is coming from a friend of mine. Im not quite sure what any of this is, but if somebody has questions or what not, feel free to ask lol
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what does the "and tan" do to our problem
and specifically, if tan = sin/cos, and you know the sign of cosine and that tan is negative, it gives you useful information about the sign of sine
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why isnt it k=0 and k=4 instead of k<0 andk>4
You want your discriminant to give you two distinct values. Think about what happens when you look at the whole quadratic formula and you substitute in b=k and c=k
im so sorry im not sure i understand
wouldnt we get the zeros if we substitute it in?
Apologies for my bad handwriting, im on my phone atm
But notice the plus and minus sign just before the square root
yeah
If you let a=1, b=k, and c=k, what happens inside the square root?
k^2 - 4k?
Correct! We want this value to be greater than zero
The reason we want it to be greater than zero is because when you take the square root of it, then apply the plus and minus, you will get two different results and hence two different x-intercepts
So now you have to solve k^2 - 4k > 0
ohh just like what was in the image right
Yep
but then shouldnt k be bigger than 0 and not smaller than 0?
That’s a good question, let’s see what is happening in the image
So when you get to k(k-4) > 0, think about what happens if you let k < 0
there are no roots right
Will the overall result be positive or negative?
ohhh i see so thats why we want k to be smaller than 0
You have a negative times a negative here
Yep
kk tysm
Ofc
hope you have a great day
Ty, you too :D
.close
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hi I'm having trouble with 11a
Where did the m come from?
It would be better if they told you what m is, but it's clear from context that it's a nonzero constant.
It doesn't actually matter the value of m, any one will give a tangent line
How would I incorporate m into the question though? What set of values am I making m
One thing you can do is express both as y = f(x) and show that their difference has a double root
This shows that the parabola "bounces" on the line in a single point
this is my working out right now
If i wanted to show my last eq is a dbrt, what would I do? Ive only learnt showing a specific point is a dbrt so im unaware if theres any other way to show
You have to show the discriminant is always 0
Then i use xm as my term?
a = m^2, b = -m , c = -16
No worries !
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Hello , sorry to bother anyone i just need help solving some math problems
I can help! (im not very good at math)
just post them can i can help
alrighty so
i think in this question you just wanna plug in your table and see if its true/or false
Yep! do you need help on how to?
Yes please
I gotchu!
ok so looking at your table, you're just going to plug in where r is as 1, and s is a 9
so in this case, for question A:
9=3(1)-12
3(1) basically means multiply 3 into 1
so 3-12 basically
3-12 would give us -9
which is not true
as 9 is not equal to -9
so we can do the same for the rest of the questions
you could also use somthing like slope to find out the equation(if you have learnt that)
slope = y2-y1/x2-x1
if you want i can show you how to get your answer using that, as its probably faster to *use
Yes please
slope is basically how much a function increases each time
*its the change in y(in this case they've given us s) in respect to our x(r in this case)
Oh Okay , I will try to solve this question , can I let you know if I think I figured it out or no ?
Yeah sure! just before you go lemme show you what you need to plug in
Okay
pardon my horrible handwritting lol
Thats okay lol
so have you found what or slope(or M value would be?)
Not exactly
anything i can help with?
Im just completely lost in all of this , my brain isn’t clicking to solve this math problem sorry
Ok i gotchu
we'd get -3
slope would give us -3
which leaves C, or D
its basically finding the equation of the line, which is y=mx+b
m being our slope(-3)
and b being out y intercept(where this graph would meet the line)
I think I get it a little more now
yeah
so basically you're going to want to do
0=-3(4)+b
and solve for b
this gets us our intercept
yep!
so now we can contruct our answer( and the equation of the line)
we have our b value
and our m value
so s=-3r+12
So it would be d right ?
yep!
Okay thank you so much for your help
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which type of contour should i use to find the inverse laplace transform of the following function using mellin's formula?
$f\left(x\right)=\frac{1}{x^{2}+1}$
Jill ♡
i chose x as my variable here
i know the solution is gonna be sin(t) but I dont know how to get there
i dont really understand how i can simplify this into something i can solve with the residue theorem
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Hi

lim x->a √x = √a, is that the same as lim x-> a √x = lim a->a √a
i mean in my textbook it says lim x->a √x - √a = 0, i.e. lim x->a √x = √a but i dont get how those both are the same
ok so
while solving limits
if u dont see any indeterminate forms
u substitute the value of x which is tending
ie here lim x→a so u substitute x=a
do u have idea about indeterminant forms?
not really no
ok
so indeterminant forms are something like
0/0
infinity/infinity
0 x infinity
0^infinity
1^infinity
infinity-infinity
and infinity^0
ever heard of these?
0^infty isn’t indeterminate (not to be a pedant about it)
ill learn them for sure
but lim x->a √x = √a
i didnt understand this above very well
oops mb 0^0
ok so if u dont see any of the mentioned cases
u can substitute x=a here
in root(x) - root(a) u see no indeterminant form
and as lim x→a u do x=a
so does that mean this is saying that lim x->a f(x) = f(a)
yes
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"Proof by deduction"
whats the point of completing the square??
Factor a quadratic
it makes it obvious that the polynomial can't be negative
because both (x+2)^2 and 1 are nonnegative
what about the inequality?
"nonnegative" means >= 0
so why did >=1 come into the sol?
because they want to show that it's strictly positive i guess
(x+2)^2 is >= 0
then you add 1 so now you're >= 1, which is strictly >0
And this is obviously positive
I see
questions similair to this, should i always do completeing the square?
for quadratics that's the most straightforward way
you could also use calculus if you want
differentiation?
yeah, the minimum will occur at a point where the derivative is zero
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Hello I was learning the proof of
limit x -> 0 sinx/x by squeeze thereum
However I have a question
lim x-> 0 (1) ≥ lim x-> 0 Sinx/x ≥ lim (x->0) cosx
Now if theta is approching from the 4th quadrant then the limit of sinx/x is negative but the COSX is positive
How can -ve ≥ +ve
How is this valid limit
If L.H.L of inequalities ≠ R.H.L
@neon iron Has your question been resolved?
Yes it's true for theta > -90° or 270°
Here is what I am asking: suppose theta is approching from the 4th quadrant and theta is now 300° = 5.236 radian
Now sin(5.236)/5.236 is -0.8660
And cos(5.246) is 0.5
Now sinx/x ≥ COSX is invalid for all the values of x in 4th quadrant
Then how can we say that it's true for
90° > x > -90°(or270°)
who said that it's true in the fourth quadrant?
x > -90°
Isn't this mean that it is approaching from the 4th quadrant?
no
where is the fourth quadrant?
seee for the values around x =0
what is the sinx/x there
we are simply not concerned with 4th quadrant here
🤔
I am not in good condition to understand this graph just tell me theoretically
x > -90° means x>270° then this mean it is approaching from 4th quadrant
Maybe I too dumb to understand this
I have to think for few minutes
Aaaaah
Yes
so we cannot simply say -pi/2 = 3pi/2
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nth term = n^3-3^n
starting from 1
$\sum_{k=1}^n k^3-3^k$
ifninity?
is this not what you meant?
no. sum of this expression, till n terms starting from 1, basically
i can reduce the question to:
Sum of powers of 3 till nth power.
$\sum_{i=1}^n (i^3-3^i)$
ℝαμΩℕωⅤ
yeah
the part with 3^i will be a geometric series
Flappie
yeah
so basically,
ar+ar^2+ar^3+ar^4
where r = 3 and a=1
ar(1+r+r^2+r^3+r^4.....)
ar(1+r(1+r+r^2+r^3+r^4......))
ar(1+r(1+r(1+r+r^2+r^3+r^4....)))
ikr its in gp. but how to get the suM?
3^n-(1/3) * 3^n - (1/3)*3^(n-1)..........
3 + (3+6) + ((3+6)+ 6+12)) + (((3+6) + 18) + 6+12+36)......
<@&286206848099549185>
geometric series
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i think it means base b^k
so u get b^kx=x?
you cant use the right hand side
use log_b(a) = loga/logb
its proven already
i dont get what ur saying
you start from the left hand side
and then use your log rules to get to the right hand side
does the bk get multiplied by x?
no
no
so what do u do
do you know your log rules?
@broken fulcrum Has your question been resolved?
ok
sorry went afk for a while
ok ive tried a lot can u just give a step by step solution?
.close
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nino
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solution
ask yourself can the degree of P be 1, or 2, etc..
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@everyone pls tell tthis
let one be n.
so (n-15)(n+17) = 0
therefore, the numbers are 15 and 17. 🙂
x = 15 or - 17. But since the odd integer can be positive only, x = 15. The other positive odd integer becomes 15 + 2 = 17. The larger integer = 17.
@livid gazelle Has your question been resolved?
The question says the product of two consecutive odd natural numbers, both n-15 and n+17 may or may not be odd, depending on the value of n.
(also it says that their product is equal to 255)
I'd just do (2n+1)(2n+3)=255, giving n=-9 and n=7, discarding n=-9 and substituting n=7 you get that the biggest is 17
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$\vert\vert\text{A}\vert\vert={\vert\text{A}\vert}^{n}$
pun pun
is this true?
where |A| is determinant and n is the order of that determinant
im feeling like its wrong but my teacher did a question using this property this morning
@neon iron Has your question been resolved?
whats the difference between | | A | | and | A |?
@neon iron Has your question been resolved?
but determinant is a scalar, so then a determinant of a scalar is just a scalar?
yea?
it should be a scalar
but what is the point of taking the determinant twice?
the determinant of a scalar is just the same scalar
so true
pun pun
i cannot image ||A|| is the determinant of the determinant of A
it must be a matrix norm
a scalar is just a 1x1 matrix, no?
wait that doesnt make sense
nvm
since then you wouldnt be able to multiply a scalar by a matrix
are they defining a norm here?
what's the context behind this
@neon iron Has your question been resolved?
man i dont know what a norm is
wait hold up
lemme just actually type the question
If A is a matrix of order 3 such that $\vert \text{A}\vert=5$ and $\text{B}=\text{adj}(\text{A})$, then the value of $||A^{-1}|(AB)^{T}|$ is equal to
fuck
pun pun
ok we good now
so this is the question
the solution is so cursed i dont even think its appropriate to send
I think the relevant property you're thinking of is that if (c) is a scalar and (A) is an (n\times n) matrix, then (\det(cA) = c^n \det A)
kalman_filtERIC
is this what you meant by the original question? @bleak crystal
ah shoot pinged wrong person, sorry
@neon iron
lmao im here
hold up
nah this is some other property, i know this property, but in this case i was not talking about this one.
should i just acutally send the solution
Sure
like the way our teacher made us solve that
oh ok
here @urban grove
$|adj(A)|=|A|^{n-1}$ where n is the order of the matrix
ive used this
i raised my original question because of this
OR we could just dump this solution and try to figure out some other way to solve this
pun pun
There is a line in here which is not valid
[\left|\frac{\operatorname{adj}(A)}{|A|}\right| = \frac{|\operatorname{adj}(A)|}{||A||}]
kalman_filtERIC
This line makes no sense
If we use this property though, with the scalar being 1/|A| and the matrix being adj(A)
We can see that it should be
[\left|\frac{\operatorname{adj}(A)}{|A|}\right| = \frac{|\operatorname{adj}(A)|}{|A|^3}]
kalman_filtERIC
And I believe that's what you're confused about? @neon iron
yea this thing makes sense
and i get it now
thanks a lot eric 😭
imma close now
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no problem! :)
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https://youtu.be/-ylIGciS7_8?t=166 what he does when he solves for the variable "a" confuses me, I dont really know how to cross multiply two equivalent fractions with one containing a variable and what he does Instead by swapping and multiplying by 2 confuses me even more
Watch Sal work through a harder Solving systems of linear equations problem.
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The point is you want a value of a such that no solution exists
Since one of the equations is $9x-14=-3$, you want the second equation to be equivalent to $9x-14=k$, where $k \neq -3$.
Ari
i.e. you want to the ratio of the x coefficient to the y coefficient to be -9/14
so $\frac{2}{-a}=\frac{9}{-14}$
Ari
Im sorry but I dont think thats the solution
the solution to the problem is 28/9 but thats not what im asking, im asking about what he was doing when solving for A
Ok I think I figured it out
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can help me combine this transfer function
from Pc(s)/E(s), i cannot from that
I thank god daily i no longer do signal theory
the Pc(s)/E(s) i did. it different with the answer from the book, i dont know why
i cannot shorten them as short as in the book
dont know where i wrong
4 hours for this
@sterile schooner Has your question been resolved?
Bro gave me the entire book
yeah, i said it in page 312
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no comprendo 😿
<@&286206848099549185> 😿
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guys im going to bed if some1 can help while i sleep plz do so it would be much appreciated, thank you
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doing PLU decomp
i get the correct pivot L and U matrix
but i dont get how when i multiply all of the matrices
i do not get A
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ouu matrix problem
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prove that tan200. Tan115 = 1+ tan200 + tan115
You know that tan 200 = tan(200 - 180) = tan 20 right
and similarly, tan 115 = tan(-65) = -tan 65
yes
65?
corrected
hold on
Do 180+20 instead?
it will be cot 20
waitnowaitno
in second and fouth quadrant tan changes to cot
so tan(180+20 = +tan20
tan(180-65) = -cot65?
✝️
no that's -tan 65
maybe this is related idk
oh wait it might be the tan addition formula
what
what
tan(a + b) = (tan a + tan b)/(1 - tan a tan b)
you should really revise your trig identities
and then just rearrange for tan 20 * tan 115
pattern recognition, I suspected it might work
this looks pretty similar to your question so I said I might as well try it
how
Rearrange for tan(20) tan(115)
its negative tho
but this is in multiplication
formula is in addition
you have multiplication and addition right here
tan(90+45) = -cot45
thats rhs
you have to solve via lhs only
am hella confused
that's a valid proof
we've started from something that is true and manipulated it to arrive at your identity
we didn't assume what we were trying to prove
what did u even do
ATellstep
tell step 1
what did u rearrange
yo
i understood
tan 315 = -1
tan(200+165) = -1
tan200+ tan165/ 1- tan200tan165 = 1
tan200 + tan165 = 1 - tan200tan165
Is that correct
115* not 165
tan200tan165 = 1-tan200tan115
what after this @smoky sparrow
...
@placid token I'll help you give me a sec I'll try it
alr
solved
send
my teachers gonna give a 0
@fast jay what abt this
thats out of my syllabus
that's true but why
see whole
tan 315 = tan(200+115) = -1
then tan(a+b)
tan 200+ tan115/ 1- tan200tan115 = -1
tan200+ tan115 = -1(1-tan200tan115)
well that's litterally what i did just inversely but ok, L teachers tbh
ye it's easy
ye
@fast jay
im still confused when to take negative signs
honestly my method was better because it shows more thatyou can see some patterns
but fine i guess
when converting cot to tan Or sin tto cos
angle in second and 4th quadrant means it negative
ye
the guy above you said that it was wrong
huh
well believe me
between 0 and 90 it's positive
90 and 180 negative
180 and 270 positive
270 360 negative
see this
same for cotangent but the result is 1/tan
?
11wrong ping
tan(200-180)?
is that possible
oh he messed up here
tan(200-180)=-tan20
there's a minus
try drawing this aswell and you see
oh wait
nope im stupid
there's no minus
so he was right here aswell
why not tan90-70
you always might have to draw the angles and look at the tangent if you are unsure
what tangents?
tan
then you won't make the exercise correctly
you'll get lost unless you're very good at it
i can solve it orally
if you can i guess
I'd check on paper
because you can't go wrong on paper, but you can in your mind
(although I messed up here)
ok
theres just too many forformulaes
i memorise one and another comes
tan3A
sin A
sinC + sinD
theres so many
and i mean a lot
ob
idk 16-17?
oh
don't just memorize, practice using them
18
right
at first you'll have to have the formula in front but then you won't need it
thnx @fast jay
np
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What in the hell does this mean
Do you know the quadratic formula
[ ax^2 + bx + c = 0 \implies x = \f{-b \pm \s{b^2 - 4ac}}{2a} ]
2z?
2z 
Peculiar
neon
my keyboard is secretly azerty
well its no longer a secret now is it 
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How can I shift this portion of the graph, so that the base touches the origin?
,rotate
Move it up by 1?
No sorry, maybe it's not clear from the photo, I have to move the undeleted part
I don’t know what the undeleted part is
Whats the issue
You need to shift the circle up by one?
No, i Need to shift this part
Do you have the original question?
Is this
So you want that line to be represented as the x-axis?
Then its equation would be y = 0
If its across the origin
I dont understand the purpose of the question
I have to move that part below, so that the base of that part is at the origin
Base of a straight line is something I have never heard
It's a one dimensional shape
I still don't understand the problem
What exactly are you trying to get? An equation?
Represented as an equation?
Wdym
Like $f(x) \rightarrow f(x) - \frac{\sqrt{2}}{2}$
quevivamexico
We can try this
Problema is its not a function... I dont know what the question is
If you wanted it to be at the origin you say "I would shift it vertically by -sqrt(2)/2 units"
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Can someone explain this to me please
have you tried plotting it in the complex plane?
Ive seen a couple problems so far that involve complex numbers and stuff but I dont remember learning it
Yeah i get that
so, how would you find this angle?
is that 5 times 12i?
whats this?
when you plot a point you usually draw a vertical and horizontal line to the axes so that you show where its at
i was thinking unit circle type stuff
in this case i did double, because i showed the x and y aswell as the x and y at the point
idk how i would find the angle of that
do you know how the find the angle here?
so you do know how to find the angle
is this a polar graph?
i got the angle of 296
but. the only thing im confused about
is why 5 is x axis and -12 is y axis
that doesnt seem quite right
why not
its -12i
I mean it was the correct answer
idk what thats supposed to mean
im getting 292.6 as my angle
yeah 292 sorry
do you know how to plot complex numbers?
do you mean like 2i + 3j + 4k?
thats not a complex number
that looks like a quaternion
I learned this with vectors
idk what you would call it exactly
youve never seen something like this?
ugh, that looks awful when i paste it here
anyway, its readable sorta
you are dealing with complex numbers
im pretty sure something like this is one of the first things you would learn with them
then how are you expected to solve smth like this?
idk tbh thats why I asked if someone could explain it to me
okay
the general form of a complex number is a+bi
we can graph complex numbers in a 2D plane
we take the real part (a) to be the x
and we take the imaginary part (bi) to be the y
seems simple enough
so, if you look at this
the x value is 3
and they y value is 4i
and so we can make a triangle with sides 3 and 4
and from there we can calculate its angle and thus write it in polar form
Flappie
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Let f : [0,1] → R be of class C1 such that f (0) = f (1) = 0. Show that for all a ∈ R, the function f′ + a f cancels on ]0,1[.
I need help. With rolle f cancel but for f'
well thats just clearly false. can you give a picture of the question
@short iris Has your question been resolved?
I am french but if you understand
cancels means equals 0 for all x in [0,1]?
no