#help-26

1 messages · Page 114 of 1

deft wing
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yeah

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exactly

vernal vale
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what have you tried

deft wing
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I'm just unsure where to start.
$a_1$ is 2.

So $a_2$ would be $\sqrt{1+2}$ ?

thorny flameBOT
vernal vale
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yea

deft wing
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and A3 would be Sqrt(3+1)
Thanks.

vernal vale
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not quite

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$a_3 = \sqrt{ 1 + \sqrt{1+2} }$

thorny flameBOT
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jan Niku

deft wing
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ah, I see now.
$a_4 \coloneq \sqrt{1+\sqrt{1+\sqrt{1+2}}}$?

thorny flameBOT
vernal vale
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yea

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do you have an approach in mind?

deft wing
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I might find one if I considered the problem further.
Right now It seems pretty obvious that it does converge though.

vernal vale
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idk if obvious is fair lol

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but if you believe it sure

deft wing
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well, the result should get smaller, but not smaller than 0.

vernal vale
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yea

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so showing that it always gets smaller is probably one piece of this

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i mean, that will show its convergent

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not to what limit, though

deft wing
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And I'd still have to formally prove it.

vernal vale
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i dont think itll be that hard

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but itll take some cleverness

deft wing
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so I'd probably have to remember some of the the rules of squares. And then use that in the proof

vernal vale
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i think induction is the move

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im trying to remember how this works if you just extend it to the reals thonk

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do you know calculus?

deft wing
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This is part of the tasks for a second semester Analysis 1 course.

vernal vale
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its funny because the limit is so easy to find and this is the hard part lol

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okay so we assume that $a_n < a_{n-1}$

thorny flameBOT
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jan Niku

vernal vale
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and we'd like to show that $a_{n+1} < a_n$

thorny flameBOT
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jan Niku

vernal vale
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does that seem like an okay hint? @deft wing

deft wing
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It does!

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I also realized that the limit is the golden ratio.

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Thanks a bunch for the nudges. I'll .close this while I actually work the problem some more.

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.close

topaz sinewBOT
#
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vernal vale
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i just solved the polynomial

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lol

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i didnt recognize

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thats pretty nifty

deft wing
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yep. 1.6180 something

vernal vale
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hmm

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i wonder how you manipulate it to get out this approximation

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interesting

topaz sinewBOT
#
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supple rampart
#

Consider this disjunctive syllogism:
The UN will become more responsible or there will be a third world war
The UN will not become more responsible
Therefore, there will be a third world war

supple rampart
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Now the interpretation of 'or' in the sense of being strong or exclusive makes more sense to me
But the book says the inclusive 'or' also leads to this argument being valid

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and Im having trouble seeing that

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So from what I understand all exclusive 'or's can be interpreted as inclusive 'or'
but not all inclusive 'or's can be interpreted as exclusive 'or'

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<@&286206848099549185>

topaz sinewBOT
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@supple rampart Has your question been resolved?

topaz sinewBOT
#

@supple rampart Has your question been resolved?

radiant marlin
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xor is just missing the 11 part

supple rampart
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xor is exclusive or?

radiant marlin
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yea

supple rampart
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so xor is sort of contained in inclusive or? like its a specific case of it

radiant marlin
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right it's a more specific thing, inclusive or is more broad and includes another case

supple rampart
radiant marlin
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you could make syllogisms that work with either one or the other though

topaz sinewBOT
#

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final solstice
topaz sinewBOT
final solstice
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hello

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i am once again in need of assistance

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is it like that problem?

glacial adder
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yeah

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its just getting you to recognize why $\frac{d}{dx}\int_{f(x)}^{g(x)}v(t)dt=f'(x)v(f(x))-g'(x)v(g(x))$

thorny flameBOT
final solstice
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uh

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so does it matter if its u or not

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like is u just a variable or does it imply something else

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what do i do next

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plug in 2x and x^3?

final solstice
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<@&286206848099549185>

zenith cape
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hm

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try splitting the integraal in 2

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like this

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oh nvm

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I dont think It will work

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ok so then just do newton leibniz

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so I short words

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what u need to do is evaluate the integral as if you were just plugging the values in

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and then multiply by the derivative of the upper and bottom limit because of the chain rule

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I'm not sure if I am confusing u more

final solstice
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im so lost in the sauce rn

neon iron
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me too

final solstice
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.close

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neon iron
topaz sinewBOT
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gilded edge
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Any ideas on this?

topaz sinewBOT
#

@gilded edge Has your question been resolved?

gilded edge
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No, unsurprisingly

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@gilded edge Has your question been resolved?

gilded edge
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molten crystal
topaz sinewBOT
molten crystal
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w_x shoud be a + Ax + By

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no?

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I'm not sure i understand what they did on 8. It seems they just started with this random function.

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here's how it sounded to me:
the simplest function is this, but it's not valid for us cause it does not have interesting critical points so LOL why do i tell you. Here's a more complex function instead.

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oh i'm eval w_x at zero. so... this means at x=0?
a+Ax+By eval at x=0 is a+By
shouldn't the partial be written with double zero to indicate where it has been eval?

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it seems it is evaluated at origin, based on the result

topaz sinewBOT
#

@molten crystal Has your question been resolved?

topaz sinewBOT
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neon iron
#

.close

inner crypt
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can someone help me with this, i wasnt able to attend the class when our teacher tackled this

AB is a line 652 feet long on one bank of a stream, where A points to the north and B points to south, and C is a point on the opposite bank, directed to the east. m∠A = 53° 18' and m∠B = 48° 36'. Solve the distance from point A to C

topaz sinewBOT
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spark rain
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.

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Quick one

topaz sinewBOT
spark rain
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Is this right

mellow arrow
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no

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multiplying the inequality by -1 flips the sign of the inequality

spark rain
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How ?

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Let me caculate that

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Yeah I did everything right

spark rain
mellow arrow
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case 2 line 3

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you're multiplying by -1 on the next step

spark rain
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Like this ?

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I need to change the direction of the >

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@mellow arrow

restive inlet
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the work for each case still isn't quite complete.

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doing casework like this, you'd also need to state restriction for the case

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i.e. for case 1:, you're working under the condition that x+7 >= 0
and you need to state that
and determine where that overlaps with x<4

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similar idea for case 2

topaz sinewBOT
#

@spark rain Has your question been resolved?

topaz sinewBOT
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spark bison
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If there any formula for finding the smallest number to reach a palindrome after N iterations? For example, 89 is the smallest number to reach a palindrome after 24 iterations.

long stirrup
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not enough context

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i have zero guesses

spark bison
odd pagoda
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iterations of what

spark bison
long stirrup
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i'll do oeis hack

spark bison
#

.close

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exotic furnace
#

how would i solve this integral

topaz sinewBOT
exotic furnace
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would simpson’s rule work

topaz sinewBOT
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@exotic furnace Has your question been resolved?

exotic furnace
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no

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<@&286206848099549185> can anyone help

neon iron
exotic furnace
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i have the solution just not the steps if that helps in any way

neon iron
exotic furnace
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all of these questions have to do w trig identities btw

neon iron
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do you know this identity cos2A = 1-2sin^2A

exotic furnace
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yes

lone wadi
neon iron
exotic furnace
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high school

lone wadi
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Hate it when trig is used in int

neon iron
exotic furnace
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ill try wait

neon iron
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yes

exotic furnace
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what do i do then

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i just made it more difficult

neon iron
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show em

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me

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what you did

neon iron
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did you get this

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after using identity

exotic furnace
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yh

neon iron
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ok

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now multiply

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it

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i mean

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open the bracket

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you get a term with (cos8x)(cos10x)

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right ?

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rest all other terms are good to integrate

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do you follow ?

exotic furnace
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so 1/4 integral (cos8x-1)(cos10x-1)

neon iron
#

yes

exotic furnace
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alr i got it now thanks

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golden flare
#

is it the case that P(A | B) = P(A | B & C) + P(A | B & ~C)? Or is that invalid?

opal vault
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yeah, invalid

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counterexample : if C is independent from A and B, then the above statement would mean P(A|B) = 2P(A|B) (maybe doesn't require that C independent from B)

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which would mean P(A|B) = 0, which isn't true necessarily

golden flare
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would you be willing to construct a proof for P(A | B) ≈ 1 entails P(A | B & C) ≈ 1

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or is that not possible

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?

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(pls ping me)

opal vault
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P(A|B and C) = P(A and C|B)/P(C|B)

opal vault
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and maybe we can do it differently

golden flare
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P(A|B and C) = P(A and C|B)/P(A|B) so, if P(A and C|B) ≈ 0, then P(A | B) ≈ 1 does not entail P(A | B & C) ≈ 1

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?

opal vault
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just let Q(E) = P(E|B) where E is any event

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Q is a probability

golden flare
opal vault
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Q(A|C) = Q(A and C)/Q(C)

golden flare
#

makes sense

opal vault
golden flare
#

what is going wrong?

opal vault
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you have to start from the fact that for any probability Q, if Q(A) = 1, then Q(A n C) = Q(C)

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and then it becomes clear

golden flare
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but we want to show that it entails P(A | B & C) ≈ 1

opal vault
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no, P(A|B) = 1 implies P(A & C|B) = P(C|B)

golden flare
#

sry, my bad

opal vault
golden flare
#

using P(A|B and C) ≈ P(A and C|B)/P(A|B)
we have P(A|B and C) ≈ P(C|B)/P(A|B) then?

golden flare
opal vault
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P(A|B and C) ≈ P(A and C|B)/P(C|B)

golden flare
golden flare
#

hmmm

opal vault
golden flare
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P(A | B) ≈ 1 entails P(A | B & C) ≈ 1

opal vault
golden flare
opal vault
#

we have :

  • P(A|B and C) = P(A and C|B)/P(A|B)
  • P(A|B) = 1 implies that P(A and C|B) = P(A|B)
#

I don't know how to put it more straightforward than this

golden flare
#

LOGIC/PROBABILITY PROOF
there are 15 premises (you probably only need 4 of them tho)

  1. P(A | B & C) ≈ 1
  2. P(A | B) ≈ 1
  3. P(~A | ~B & C) ≈ 1
  4. P(~A | ~B) ≈ 1
  5. P( ~A & C | ~B) ≈ 1
  6. P(C & A | B) ≈ 0
  7. P(~C & ~A | ~B) ≈ 0
  8. P(C | A & B) ≈ 0
  9. P(C | A & ~B) ≈ 0
  10. P(C | A) ≈ 0
  11. P(~C | ~A) ≈ 0
  12. P(C | ~A & B) ≈ 1
  13. P(C | ~A & ~B) ≈ 1 [I made a typo in my initial problem, sorry.... I accidentally didn't put this premise in there, but put premise 12 twice]
  14. P(C | ~A) ≈ 1
  15. P( ~C | A) ≈ 1

we want to conclude that ¬(P(B | ¬A & C) ≈ 1) it's very important that these are approximate premises. This for example, means that you cannot use P(C | ~A) ≈ 1 to mean if ~A then C, that makes an assumption that you would need to support, i.e. P(C | ~A) ≈ 1 ≠ P(C | ~A) ≈ 1. Curious to hear what you come up with. Ping me if you want some preliminary results

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mental sorrel
#

I need help to find a grammar of type 0 for the following language

mental sorrel
#

$L_1 = {a^n b^m c^{nm} \mid n, m \in \mathbb{N} }$

thorny flameBOT
topaz sinewBOT
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@mental sorrel Has your question been resolved?

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@mental sorrel Has your question been resolved?

mental sorrel
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mossy fable
#

Can I get some help with number 8

topaz sinewBOT
#

Please don't occupy multiple help channels.

mossy fable
#

I closed my previous one 😭

neon iron
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differentiate and solve for 0

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find that x value and put it back into f(x) = 6

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and youll have an equation for k

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solve for k

mossy fable
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But I get multiple x values 😭

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Because the derivative is a quadratic

neon iron
#

differentiate again and find out which is the minimum value

mossy fable
#

.close

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neon iron
topaz sinewBOT
neon iron
#

i cant understand thesenotes help

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what are they tryna say

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spare fractal
#

Hi, can I please have help. I would appreciate it soo much. So I did this equation, and the black box is the simplified version but apparently it is incorrect

spare fractal
#

Help me

#

👹

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@spare fractal Has your question been resolved?

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runic iron
#

for the first one i got (2x)^2 = y but I'm not sure if i'm reading the question right... is it that for y = x it needs to be the same number as the prev equation .?

pastel oracle
#

that seems correct

runic iron
#

ugh... so this is basically trial and error .? pandathink

pastel oracle
#

trial and error for what?

runic iron
#

part (ii) lol

pastel oracle
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so it wants you to solve x = (2x)^2?

runic iron
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it's y = (2x)^2 and im not sure if i need 1 number or two

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it SAYS two but where would they go..???

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is it that its two possible values, so 2 answers?

pastel oracle
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if I'm understanding the question correctly, I think you need to solve x = (2x)^2

runic iron
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oohh ok

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ok nvmd i dont really understand cause i got [square root y]/4 = x

pastel oracle
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there shouldn't be a y

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solve the equation x = (2x)^2

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solve for x

runic iron
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oh

pastel oracle
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do you know how to solve it

runic iron
#

...trying and failing aha

pastel oracle
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it's a quadratic equation

runic iron
#

sigh

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It's getting late so this question could wait. I'll see to it tomorrow. Thank you for you're help though! 🙂

#

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regal leaf
#

whered i go wrong

topaz sinewBOT
regal leaf
topaz sinewBOT
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@regal leaf Has your question been resolved?

regal leaf
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.close

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deft harness
#

I have a short question to get a width do i divide area by length and is the same for length do divide area with width

brave acorn
#

For a rectangle?

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Yeah

topaz sinewBOT
#

@deft harness Has your question been resolved?

deft harness
#

Mb i went go do something , just a rectangle?

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@deft harness Has your question been resolved?

noble laurel
#

@tiny yew

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fallow igloo
topaz sinewBOT
fallow igloo
#

What’s the result of this?

#

I don’t know how to apply formulas onto this question

ivory sorrel
#

Binomial expansion?

#

will be nasty , yes

#

but it works

#

,w (5x-3)^4 /x

ivory sorrel
#

so integrate $625x^4 -1500x^3+1350x^2-540x+81$

thorny flameBOT
#

ƒ(Why am. I here)=I don't Know

fallow igloo
#

That’s large

#

Thanks 🙏

#

This is the original question, worth to be challenged

#

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lofty moth
topaz sinewBOT
lofty moth
#

How would this set of numbers be interpreted as?

loud oasis
#

the set of all real numbers x, such that sin(x) > 0

lofty moth
#

And would an element of that be pi/4

#

Since that’s a real number that satisfies sin(x)>0

loud oasis
#

yes

lofty moth
#

The set of numbers I posted above and the set of numbers here are identical right?

loud oasis
#

that set is the set of numbers satisfying sin(x) = 0, which makes it a different set

lofty moth
#

Isn’t it an interval though?

#

Like (5,9)

#

Means all the numbers between 5 and 9, exclusive

loud oasis
#

oh i see, it's using interval notation and set builder notation at the same time (which is a bit unusual)

lofty moth
#

So to conclude, they represent the same numbers right?

loud oasis
#

the way that interval is set up would include all real numbers other than multiples of pi

#

wait no, i'm misreading it

lofty moth
#

I think so. We could sub it k=0 to get (0, pi)

#

This is also when sin is positive

loud oasis
#

that seems to work, then

lofty moth
#

The only difference would be in HOW they represent them. The first method simply represents all the real numbers that satisfy sin(x)>0 while the other method represents the values in intervals

loud oasis
#

yes

lofty moth
#

Alright cool. Thanks a lot

#

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neon iron
#

im kind of stuck

topaz sinewBOT
#

@neon iron Has your question been resolved?

neon iron
#

<@&286206848099549185> sorry for the ping pls help

#

my attemp-

#

im pretty sure i did some mistake in rationalization or smth

#

its just very messed up

regal charm
#

and then implicit differentiation

neon iron
regal charm
#

okay fine

#

the rest just looks like trivial algebra to me

#

but anyway

#

$y' = \frac{2x - 2y y'}{2 \sqrt{y^2 - x^2}}$

thorny flameBOT
#

nyxie9151

regal charm
#

just cross multiply and isolate y'

thorny flameBOT
#

nyxie9151

regal charm
#

move the 2yy' to the other side and yeah you're mostly done

neon iron
#

ill try

#

i just took the wrong path

#

😿

#

done

#

Thnx a lot mate

regal charm
neon iron
#

.close

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hidden mauve
#

Hello/I tried to do this question by susituting y=k-x, and then discrimant>0 with the equation from the substituo0n but I am not getting K values. Please help thankyou

tawny spade
#

If its tangent then discriminant = 0

#

Because it has only one point touching

hidden mauve
#

Yes still I am not getting the surd form though

#

.help

topaz sinewBOT
#

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tawny spade
#

x²+(k-x)²=2x
x²+k²-2kx+x²=2x
2x²-2kx-2x+k²=0
2x²-(2k+2)x+k²=0
D=(2k+2)²-8k²=0
4k²+8k+1-8k²=0
4k²-8k-1=0

#

Right?

hidden mauve
#

You facrorised wring here

tawny spade
#

Whoops

hidden mauve
#

should be -(2k-2

#

its ok

#

I figured it out btw

#

(-2k-2)^2-4(2)(k^2)=0 (disdcriminat equation)

#

expands to -4K^2+8k+4=0

#

calc leads to 1+-(root)2

#

check with desmos

#

So thanks

#

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stuck ridge
#

I just made a list on my notes on how to get the the missing sides with trigonometry. I just wanna know if i what i noted was factual

So basically

If opp is given
And your finding
Hyp = opp/Sin∅(jus act like this is theta)
Adj = opp/Tan∅

If Adj given
And finding
Hyp = Adj • Cos∅
Opp = Adj • Tan∅

If Hyp given
And finding
Opp = Hyp • Sin∅
Adj = Hyp • Cos∅

Is this factual?

topaz sinewBOT
#

@stuck ridge Has your question been resolved?

stuck ridge
#

<@&286206848099549185>

topaz sinewBOT
#

@stuck ridge Has your question been resolved?

stuck ridge
#

Anyone there?

stuck ridge
#

Why is it wrong?

#

Let me check

#

Oh my god your correct

#

Thanks

#

Is that the only one wrong?

#

Alright thanks.

#

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#
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elder glacier
#

can i get help, preferrably visualised since english is not my first language

topaz sinewBOT
#

@elder glacier Has your question been resolved?

elder glacier
#

<@&286206848099549185>

vast dirge
#

you can use the equation of tangente

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old plover
#

How would I graph 4a?

topaz sinewBOT
old plover
#

Do I have, like, the right idea?

#

<@&286206848099549185>

#

I changed it to degrees, since that’s what we’re working w/

#

But where would I go from here?

topaz sinewBOT
#

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mellow agate
topaz sinewBOT
mellow agate
#

How is 3/4 wrong

tawny spade
#

6/48

#

Not 36/48

mellow agate
#

I keep making that mistake

#

Solving the square root then keeping it

#

What would 31. Be

#

Because 4 to the power of 4 is way over 21

#

So idk how that works

#

Just keep it as 21

#

Yeah

#

And rational fractional

#

So both

thorny flameBOT
#

faiyrose

mellow agate
#

I knew

#

The other one

#

So how would I do 4^21

#

You can’t right

#

Unless you simplify it

#

Could you turn it into 21^1/4

#

Alright so that’s the answer

thorny flameBOT
#

faiyrose

topaz sinewBOT
#

@mellow agate Has your question been resolved?

topaz sinewBOT
#
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karmic summit
#

Testing the significance of the least squares regression model, Stats and Probability

karmic summit
#

struggling to caculate the residuals thru the RESID function and giving me the wrong values

topaz sinewBOT
#

@karmic summit Has your question been resolved?

karmic summit
#

<@&286206848099549185>

topaz sinewBOT
#

@karmic summit Has your question been resolved?

karmic summit
#

.close

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paper dust
topaz sinewBOT
paper dust
#

i need help with this

#

im stuck

#

the problems is to evaluate the limit, workin with it as a defined integrer

topaz sinewBOT
#

@paper dust Has your question been resolved?

dusky mango
thorny flameBOT
dusky mango
#

@paper dust do you know how limit of sum tending to infinity can be converted to definite integration?

paper dust
#

not really

paper dust
#

.close

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scarlet spade
topaz sinewBOT
scarlet spade
#

Someone please help

#

i got 17.1 but i think i did it wrong

#

someone please help

#

wdym how

vernal matrix
scarlet spade
#

i set up an equation

#

cos(40)=(x-4)/x

#

then i just cross multiplied

scarlet spade
vernal matrix
scarlet spade
#

but idk i think i had an algebra issue

#

what answer did u get tho?

vernal matrix
#

We don't give solutions here

vernal matrix
scarlet spade
#

what?

vernal matrix
#

I'm saying you should explain the other steps you did from that point

#

(and also I think it's fine, so why do you think it's wrong?)

topaz sinewBOT
#

@scarlet spade Has your question been resolved?

topaz sinewBOT
#

@scarlet spade Has your question been resolved?

scarlet spade
#

someone

#

please help

neon iron
#

use cosine formula

verbal crater
scarlet spade
#

Is that correct?

verbal crater
#

lemme check

verbal crater
scarlet spade
#

Alr thx

scarlet spade
#

It kinda takes a while for people to respond here

verbal crater
#

well i also might take a while to respond because of time differences and stuff

#

but if you want you can

scarlet spade
verbal crater
#

sure

scarlet spade
#

I need to solve for h

#

I got about 50

verbal crater
#

lemme try this

verbal crater
#

about 50 seems good

scarlet spade
#

Wow u solved it quick

#

Wait can I see how u solved it?

#

Or did u not write it down

verbal crater
scarlet spade
#

Hm

#

Alr

verbal crater
#

oh thats for x btw

scarlet spade
#

Ik I was a little confused

#

So how did u solve for h once u got x?

verbal crater
#

put it back into tan(55) = h/x

scarlet spade
#

Oh alr

#

Sorry to bother again, but could u show me the steps to solve this problem?

scarlet spade
verbal crater
#

so multiply the x to the other side

#

put all x one side

#

solve

scarlet spade
scarlet spade
verbal crater
#

so you can?

scarlet spade
verbal crater
#

you have xsin(50)

#

and you have x

#

they both have a common x

#

so you can?

scarlet spade
#

Uh

#

Factor out something?

verbal crater
#

yep

scarlet spade
#

I don’t think I’ve been taught this before

#

What am I supposed to factor out

verbal crater
#

what do you see that can be factored

scarlet spade
#

Well the x

verbal crater
#

ok good

scarlet spade
#

But like how?

verbal crater
#

x - sin(50)x

#

factor the x

#

x(1 - sin(50))

scarlet spade
#

What the flip

#

How does it become a 1

#

I’m so confused

#

Ohhh

verbal crater
#

think of factoring is like dividing

#

x / x is 1

scarlet spade
#

When u distribute it becomes back

#

Alr I think I get it

#

X is about 17.1?

scarlet spade
verbal crater
#

yep

topaz sinewBOT
#

@scarlet spade Has your question been resolved?

topaz sinewBOT
#
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proper dagger
#

Is this as simple as 8C3 + 10C4?

topaz sinewBOT
opal vault
#

when you do 8C3 + 10C4, it means in english that you EITHER choose 3 men out of 8 OR choose 4 women out of 10

#

which isn't what you want is it @proper dagger ?

#

what operation symbolizes that you choose .... AND choose ....?

proper dagger
opal vault
#

yes

proper dagger
#

Yep, thank you that makes sense

#

.close

topaz sinewBOT
#
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topaz sinewBOT
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south pasture
#

hey this is gonna be a very weird question but can someone teach me how to find the area of a parabola/curve between the axis?

south pasture
#

i watched a few tutorials but i dont get it since i dont know anything abt calc

#

i need to learn it today as soon as possible

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#

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deft holly
#

post your question or close the channel

topaz sinewBOT
#
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south pasture
#

Hey can someone help me with this

topaz sinewBOT
winter egret
azure parrot
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ivory sorrel
#

$\frac{dy}{dx}=\frac{\left(2x^2+y^2\right)}{2xy-x^2}$

thorny flameBOT
#

ƒ(Why am. I here)=I don't Know

ivory sorrel
#

Solve this

#

so I started by dividing by $x^2$

thorny flameBOT
#

ƒ(Why am. I here)=I don't Know

ivory sorrel
#

$\frac{dy}{dx}=\frac{\left(2+\left(\frac{y^2}{x^2}\right)\right)}{\frac{2y}{x}-1}$

#

next $\frac{y}{x}=u$

thorny flameBOT
#

ƒ(Why am. I here)=I don't Know

#

ƒ(Why am. I here)=I don't Know

ivory sorrel
#

$u+\frac{xdu}{dx}=\frac{\left(2+\left(u^2\right)\right)}{2u-1}$

thorny flameBOT
#

ƒ(Why am. I here)=I don't Know

ivory sorrel
#

which is

#

$\frac{xdu}{dx}=\frac{\left(2+\left(u^2\right)\right)}{2u-1}-\left(\frac{u\left(2u-1\right)}{2u-1}\right)$

thorny flameBOT
#

ƒ(Why am. I here)=I don't Know

ivory sorrel
#

or

#

$\frac{xdu}{dx}=\frac{-u^2+u+2}{2u-1}$

thorny flameBOT
#

ƒ(Why am. I here)=I don't Know

ivory sorrel
#

which can be re-written as

#

$\frac{dx}{x}=\frac{\left(2u-1\right)}{-u^2+u+2}du$

thorny flameBOT
#

ƒ(Why am. I here)=I don't Know

ivory sorrel
#

which I feel is wrong

#

as all the options have square roots

ivory sorrel
thorny flameBOT
#

ƒ(Why am. I here)=I don't Know

ivory sorrel
#

or

#

$\ln\left(\frac{1}{x}\right)=\ln\left(C\left(\frac{y^2}{x^2}+\frac{y}{x}+2\right)\right)$

thorny flameBOT
#

ƒ(Why am. I here)=I don't Know

ruby mural
#

Is the final ans in form of y= something?

ivory sorrel
#

yes

ruby mural
#

Try isolating y and write it in terms of x

ivory sorrel
#

$\ln\left(\frac{1}{x}\right)=\ln\left(C\left(\frac{y^2+yx+x^2}{x^2}\right)\right)$

thorny flameBOT
#

ƒ(Why am. I here)=I don't Know

ivory sorrel
#

which is

#

$\frac{1}{x}=C\left(\frac{y^2+yx+x^2}{x^2}\right)$

thorny flameBOT
#

ƒ(Why am. I here)=I don't Know

ruby mural
#

Right

ivory sorrel
ruby mural
#

Yeah now solve the quadratic in y ig

fervent crag
#

Where did the 2 go

ruby mural
#

Oh yeah

#

2x² not x²

ivory sorrel
#

what 2

ruby mural
fervent crag
ivory sorrel
#

oh

#

$\frac{1}{x}=C\left(\frac{y^2+yx+2x^2}{x^2}\right)$

thorny flameBOT
#

ƒ(Why am. I here)=I don't Know

ivory sorrel
#

so this is right

#

$x=C\left(y^2+yx+2x^2\right)$

#

now i solve this as a quadratic in y , I suppsoe?

ruby mural
#

LHS is just x

fervent crag
#

X on lhs

thorny flameBOT
#

ƒ(Why am. I here)=I don't Know

ruby mural
#

Yup

thin adder
#

ew

#

i mean the solution is nasty lol

ruby mural
#

Lol

craggy haven
#

just quadratic formula

ivory sorrel
#

yeah

thin adder
#

yeh but gonna be some weird radical

ivory sorrel
#

thanks

torpid sparrow
#

It is not that bad

ivory sorrel
#

I think I'll just ask wolfram to do it, doubt this will come in my exam

ruby mural
#

Wolfram op

ivory sorrel
#

,w solve $x=C\left(y^2+yx+2x^2\right)$ as a quadratic in y

thin adder
#

lol

torpid sparrow
#

😹

ivory sorrel
#

guess, I'll do it

#

lol

thin adder
#

prob doesn't know what x or y is

#

2 variables

torpid sparrow
#

The input is wrong

craggy haven
#

,w solve x = C(y²+yx+2x²) for y

thorny flameBOT
craggy haven
#

oh

#

,w solve x = c*(y²+yx+2x²) for y

thorny flameBOT
thin adder
#

could honestly just replace x with a so it knows it's a ocnstant

#

oh there you go

ivory sorrel
#

yeah that checks out

#

thanks so much everyone!

#

and sorry for wolfram

#

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snow gyro
#

what is equivalent statements

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@snow gyro Has your question been resolved?

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signal fog
#

how would i do part A? do i do D-A = C-B?

topaz sinewBOT
lone dune
#

d - a = some multiple of (c - b)

signal fog
#

oh so lambda is 5 so its parrallel

#

how woudl i do part b?

lone dune
#

find the perimeter of the shape

signal fog
lone dune
#

the lengths of

signal fog
lone dune
#

no just pythagoras

signal fog
#

yer thats what i meant

signal fog
lone dune
#

did you do |DA + AB + BC + CD|

signal fog
lone dune
#

pretty sure you need to do |DA|+|AB|+|BC|+|CD|

#

if you do DA + AB + BC + CD correctly you should get (0, 0) I think

#

but that's not what you need to do

signal fog
lone dune
#

so that's the distance for 1 lap

signal fog
lone dune
#

5 minutes

#

you need it in km/h

signal fog
#

i think thats correct

#

ty for the help

#

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rocky dock
#

calculating this

#

i need help

topaz sinewBOT
rocky dock
#

i don’t know what to do

obsidian solstice
rocky dock
#

i know but that doesn’t really help me catscream

obsidian solstice
rocky dock
#

i am confused as to how to find the other one

obsidian solstice
#

You have a small triangle at the right

#

With height 3

#

And length 15-10

#

Do you agree?

rocky dock
#

yes

obsidian solstice
#

And that triangle is similar to the whole big triangle

rocky dock
#

it is 1/3 of the length of the big one that’s all i really figured out

#

but what would i do with that information

obsidian solstice
obsidian solstice
#

Yes

#

And that works because the triangles are similar

rocky dock
#

so would the slope be 9/15 kongouderp

#

or 3/5

obsidian solstice
obsidian solstice
rocky dock
#

oh

#

yes

#

could you help me with this follow up question too oooh kongouderp

#

never mind

#

i understand it

#

tysm 😊

#

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wispy burrow
topaz sinewBOT
wispy burrow
#

is it possible to find the rotations per second from this?

#

this is the data from an accelerometer that was on a rocket

#

the radius from the senter of the rocket to the accelerometer was 0.031 m

#

I've tried to find it myself but it has been hard

#

I've tried to find ω

#

can someone help?

#

the x axis is t measured in seconds

#

the y axis is the acceleration measured in g's

topaz sinewBOT
#

@wispy burrow Has your question been resolved?

wispy burrow
#

<@&286206848099549185>

topaz sinewBOT
#

@wispy burrow Has your question been resolved?

wispy burrow
#

<@&286206848099549185>

warm cipher
#

Sou analfabeto caralho

neon iron
#

idk

#

that's advanced level for me

#

to reach yet

warm cipher
#

Sabe português?

wispy burrow
wispy burrow
#

.close

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#
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opal bone
#

hi, this is a picture from my diffeq teacher's notes. I was wondering if anybody knew why f(x) changed from x^4e^x to x^2e^x

opal bone
#

hes using variation of parameters

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#

@opal bone Has your question been resolved?

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#

@opal bone Has your question been resolved?

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@opal bone Has your question been resolved?

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#

@opal bone Has your question been resolved?

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#

@opal bone Has your question been resolved?

radiant marlin
opal bone
#

Ah I see

radiant marlin
#

for example

opal bone
#

Does everything else being divided by the x^2 not really matter in this case

#

Acc I get it

#

Thanks

#

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next epoch
#

hello

topaz sinewBOT
sharp atlas
#

hi

next epoch
#

<@&286206848099549185> I NEED help with this questiom

#

hi relu

#

i m not sure but i wanna know the asnwer for this question....

sharp atlas
#

turn km/h to m/s

next epoch
#

can yuo please tell me the answer?

sharp atlas
#

🙄

next epoch
#

so i can know? and I will try to do working out

ocean terrace
#

relu

sharp atlas
ocean terrace
#

nice optimisation equation

sharp atlas
#

which one?

#

huh

#

what

sharp atlas
next epoch
#

can you guys please tell me the asnwer?

next epoch
ocean terrace
#

y=0, x<0
y=x otherwise

next epoch
#

thanks

sharp atlas
ocean terrace
#

relu

sharp atlas
#

what

ocean terrace
#

😭

#

search relu

sharp atlas
#

oh rectified linear unit

#

yeah

#

ik

ocean terrace
#

yes

sharp atlas
#

its just my name lmao

ocean terrace
#

my fav

sharp atlas
#

like my irl name

ocean terrace
#

:0

#

cool name

next epoch
sharp atlas
sharp atlas
past thorn
sharp atlas
topaz sinewBOT
#

@next epoch Has your question been resolved?

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south pasture
#

Hey can someone tell me whether this is correct

south pasture
keen scaffold
#

Firstly, what value did you get for cos(x) after using pythagorean identity?

keen scaffold
#

The answer -0.5802469... is correct, but that is not the same as -29/50

thin adder
#

$\sin x=\frac{8}{9} => \cos x=\sqrt{1-\frac{8^2}{9^2}} \text{ and } \sin(2x) = 2\sin x \cos x$

thorny flameBOT
#

Obotron

keen scaffold
south pasture
keen scaffold
keen scaffold
south pasture
#

Idk what to do here

south pasture
topaz sinewBOT
#

@south pasture Has your question been resolved?

thin adder
#

using the product rule

south pasture
#

Is it -16

south pasture
thin adder
#

what did you get for the derivative?

south pasture
#

idk man im confused i think i did it wrong

#

like

#

idk how to explain

thin adder
#

it would be easier if you could show me or write how you differentiated

#

then i could point out the mistake

south pasture
#

i did smthn like this but then continued on my head

south pasture
#

okay i got -28 and i moved on with the question

#

still, thanks

#

.close

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#
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languid marsh
topaz sinewBOT
chilly walrus
#

,rccw

thorny flameBOT
chilly walrus
languid marsh
#

21 and 22

chilly walrus
#

for 21

topaz sinewBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
languid marsh
#

I dojt know how to begin

#

What advantages does "pq is the midpoint of rst" even give us

chilly walrus
#

okay so

chilly walrus
languid marsh
chilly walrus
#

yes

languid marsh
#

so if the teacher brings midsegment then its always half the base

#

But

#

Why isnt this true for trapezoid

#

Oh wait

#

Wait

#

I got it

chilly walrus
#

that's a different story :)

languid marsh
#

This is the point

#

Ok thanks

#

Q22?

chilly walrus
#

find DL first

#

which is the midsegment of the triangle

languid marsh
#

Oh

#

Dl is 12

chilly walrus
#

yes

chilly walrus
languid marsh
#

So we will say

#

pq=1/2rt

#

?

#

Or 2pq=rr

#

Rt

chilly walrus
#

which question are we talking about

#

i thought we moved on to 22 already

languid marsh
#

they were both easy

chilly walrus
#

okay lol

languid marsh
#

but idk why i didnt know

chilly walrus
languid marsh
#

Thank u soooo much

chilly walrus
#

no problem!

#

if you are done, type ".close"

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#

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#
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charred ivy
#

can anyone help wit this?

topaz sinewBOT
woeful drift
#

!status

topaz sinewBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
charred ivy
stable minnow
#

pretty bad question in my op

charred ivy
#

yea im in a quiz rn and i aint learn this

stable minnow
#

I think you should plug in each point to the equation

woeful drift
#

Quiz?

stable minnow
#

then you will have 4 equations of C and D

#

and try and find some C and D that best expresses them

woeful drift
#

That's not how you find a best fit line

stable minnow
#

well no

#

but i would use python

#

so this is goofy

charred ivy
#

mhmm, okay i tried chatgbt and it gave the eq y=2 +(3/5t)

#

idk if thats correct and im trying not to fail 💀

stable minnow
#

☠️