#help-26

1 messages · Page 101 of 1

hardy urchin
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how do I close this

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.close

topaz sinewBOT
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hardy urchin
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.reopen

topaz sinewBOT
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hardy urchin
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uh oh

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now how do i find cde

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...

topaz sinewBOT
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@hardy urchin Has your question been resolved?

topaz sinewBOT
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@hardy urchin Has your question been resolved?

hardy urchin
#

someone help

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.close

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topaz sinewBOT
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fierce zealot
#

what's an example of a series that converges conditionally

fierce zealot
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that is not an alternating series

solemn wigeon
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@noble laurel does such a series exist? Can you clear my doubt my sir?

noble laurel
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Perchance we can consider sin(n)/n

solemn wigeon
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Holy shit one exists

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Showing this one converges is a very cool exercise

fierce zealot
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hmm how do we show this

solemn wigeon
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Hint: integral test

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Second hint: break integral up by multiples of pi

fierce zealot
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but f(x) = sinx/x is not decreasing

wary tulip
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stupid nonexample is a series that’s eventually alternating but not alternating initially

fierce zealot
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I think we need the terms to be decreasing, positive, and the corresponding function to be continuous?

solemn wigeon
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This is the whole point of your question sir

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The alternating series test cannot work

noble laurel
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Sir

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the integral test

wary tulip
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i still am not sure integral test is going to work there

fierce zealot
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yes, I am not trying to apply alternating series test though

noble laurel
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also requires decreasing

solemn wigeon
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Erm

fierce zealot
wary tulip
solemn wigeon
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Well that is quite curious now isnt it

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it appears the integral test will not work

wary tulip
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my real analysis sir taught me this a few years ago

noble laurel
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Only just a few weeks ago you learned dirichlets test?

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No wonder you forgot BW

solemn wigeon
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I think this works or showing that the sum doesnt converge absolutely

wary tulip
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no it was 3 years ago

noble laurel
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Oh I thought you said

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a few weeks ago

solemn wigeon
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Really how do you show that $\qty|\sum_{i=1}^N sin(i)| < M$

thorny flameBOT
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Ultimate Chad

wary tulip
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euler’s formula

solemn wigeon
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Like e^{in}??? GEOMETRIC SERIES:??/

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Holy shits thats beautiful

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Thank you slayla you have cleared me doubt

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@noble laurel thats actually really cool

noble laurel
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He came here to clear a doubt and instead had his doubt cleared

wary tulip
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thank my real analysis sir

solemn wigeon
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Yes

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I would like to personally thank your real analysis sir

noble laurel
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@wary tulip Are you feeling better now that you've cleared some doubts?

wary tulip
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no

noble laurel
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I doubt that

fierce zealot
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is this the test youre talking abt?

wary tulip
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yea

solemn wigeon
fierce zealot
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so we need to choose a sequence

wary tulip
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it’s kinda a generalization of the alternating series test

solemn wigeon
fierce zealot
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1/n

solemn wigeon
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Yessir

solemn wigeon
fierce zealot
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oh

solemn wigeon
fierce zealot
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i see

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Ill try that. But just to confirm, Dirichlet's test is used to show the series $$|a_n| = sinn/n$$ doesnt converge?

thorny flameBOT
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WhoTao

solemn wigeon
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No its to prove that series does converge

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Wait what ???

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why are there absolute values

wary tulip
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very confusing question

fierce zealot
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So to get conditional convergence, we need to apply tests on sin(n)/n and |sin(n)/n|, right?

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If both converges, we get absolute convergence. If |sin(n)/n| fails to converge, its conditional

wary tulip
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use dirichlet’s test to prove sum sin(n)/n converges

fierce zealot
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i see. thanks.

topaz sinewBOT
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tight rivet
topaz sinewBOT
tight rivet
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??

tranquil verge
tight rivet
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For dy/du?

mortal path
# tight rivet

I think it's the opposite
dy/du is - cos (u)
And du/dx = 8x

tight rivet
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👍

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languid rivet
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angle of corner a

mortal path
languid rivet
#

Always adds up to 180

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Is it 90?

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tight rivet
topaz sinewBOT
tight rivet
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Why is number 3 incorrect

coarse tusk
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Will the domain be closed or open at the value -5/4?

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graceful smelt
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can someone help me with this? i'm not stuck at a particular point, i just don't know what this question is asking me to do

glacial adder
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it’s asking which of the follow y’s satisfies the above equation

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so you have to substitute in y

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and differentiate y to get y’

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and then plug it into the differential equation

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i’d say just do one by one

graceful smelt
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got it, thank you so much!

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paper junco
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I am trying to define f(x):

topaz sinewBOT
paper junco
#

we start from a sine function (in blue)
when we get to certain values of x that would yield a sin(x) above y=a or below y=b,
this new function would have to 'skip' these x values to values of sin(x) that are inside the green lines

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for practical purposes f(x) could be a triangle function with a different period than the sin(x)

ocean prairie
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Let $D := {x \in \mathbb{R} : b < \sin(x) < a}$, then just take $f: D \to \mathbb{R}$ with $x \mapsto \sin(x)$

thorny flameBOT
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DeadTomato

ocean prairie
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if you mean that

paper junco
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I don't have the knowledge for the notation from f : -> R and on, could please you explain?

ocean prairie
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is means that f only takes x values such that the sin value is in your region

paper junco
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i'm not trying to find a function that results in the black line in the upper graph, rather in the lower.

ocean prairie
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ah

paper junco
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right but in that case we would have the gaps, like the upper graph right?

ocean prairie
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yeah

paper junco
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the weird part about this function I'm trying to find is that there would be no gaps

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it would look like the lower graph, which gets rid of the gaps

ocean prairie
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i dont know if you can explicitly give such a function

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my idea would be to give a function that maps the Reals to our set D

paper junco
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it seems it would fall into a trap of dependencies

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conditions that depend on things that depend on this condition 😛

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but... I can think of this function, so... can't I define it?

ocean prairie
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im thinking of a way to map the reals to the set D in a way that it just removes the gaps

paper junco
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An idea:

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because this new function will be based on a periodic function
we can add the period amount later

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so its definition will look a bit ugly at first I imagine

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with a few conditions

ocean prairie
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well youd have to add g twice if you are at the second thing

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i think the best way is to show there is an order preserving bijection phi : R -> D

paper junco
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Have to go now, thank you!

ocean prairie
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alright

paper junco
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sorry one more thing, first time ever here for me

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when roughly will this channel disappear ?

ocean prairie
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write .close

topaz sinewBOT
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topaz sinewBOT
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dense condor
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Hello somebody! I need someone to confirm this for me please, I’ve been stuck on two answers. Thank you and have a great day!

shut obsidian
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This seems correct, f(f^(-1)(x)) should give x and it does.

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,w inverse 7sqrt(x - 8)

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Yeah

dense condor
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My bad

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I inputted a different number

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Let me resend

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This would’ve been my second option @shut obsidian

shut obsidian
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That's the same..

dense condor
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😅😅😅

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😅😅😅

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Okay thank you, have a great day man

shut obsidian
#

np

dense condor
#

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fathom zinc
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Does anyone have any tips or have a link to somewhere i can find tips on how to find isomorphisms between groups

hybrid lake
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any groups in particular?

fathom zinc
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Just looking for general tips it always takes ages for me to do it on tests

hybrid lake
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Well a trick can be considering where to send generators

fathom zinc
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What if the group isnt cyclic

hybrid lake
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Right, consider D8, then you just send the rotation generator somewhere of order 4 and you send the flip generator somewhere of order 2

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and then you hope that it satisfies xyxy^-1=e or something

fathom zinc
#

Ok thanks

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kind tendon
#

I have a question about part b of this problem. Have I set up the improper integral correctly, and have I done something wrong for it to come out to negative infinity instead of positive infinity?

torpid sparrow
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What is the limit when “a” goes to 0 of -ln(a)?

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@kind tendon

kind tendon
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is it not negative infinity?

torpid sparrow
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What is the limit of lna

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When a goes to 0

kind tendon
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OH

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oh

torpid sparrow
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If a is getting smaller than 1 and bigger than 0 it will be negative

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But u have a negative outside

kind tendon
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I didn't know off the top of my head. I (incorrectly) intuited lna to aproach infinity, but that is wrong

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I see what I did wrong now, thank you

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So the improper integral is set up correctly?

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This is my full solution. Makes sense to me

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north canyon
topaz sinewBOT
#

@north canyon Has your question been resolved?

neon iron
#

hello

#

!status

topaz sinewBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
north canyon
#

this is so crazy, where do I even begin sadcat

topaz sinewBOT
#

@north canyon Has your question been resolved?

hybrid lake
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what theorems have you learned?

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what class is this for @north canyon

north canyon
hybrid lake
#

okay, thats what I figured I think this has to do with AM GM

topaz sinewBOT
#

@north canyon Has your question been resolved?

radiant marlin
#

yea first step is

north canyon
radiant marlin
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just x y z I think

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like you apply AM-GM to the xyz part

topaz sinewBOT
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@north canyon Has your question been resolved?

keen hinge
#

@north canyon rewrite given inequality as $\frac{1}{x}+\frac{1}{y}+\frac{1}{z}\le 1$, what can you get from it?

thorny flameBOT
#

Caroline

north canyon
keen hinge
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Right

topaz sinewBOT
#

@north canyon Has your question been resolved?

north canyon
#

.close

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north canyon
#

.reopen

topaz sinewBOT
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north canyon
thorny flameBOT
#

Normed

north canyon
#

.close

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dusk raft
topaz sinewBOT
dusk raft
#

whats the procedure of solving questions like this

stone verge
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the letter is just a placeholder

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so you can let 2-u = 3x to find f(2-u)

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/ f(3x) = 2x + 1

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/ 2-u = 3x

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/ x = (2-u)/3

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/ f(2-u) = 2(2-u)/3 + 1

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check the second method

topaz sinewBOT
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stark crater
#

hi

topaz sinewBOT
blissful sentinel
#

hello

stark crater
#

please can anyone gimme explanation for the result of this series whether it is convergent or divergent ?

blissful sentinel
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do you know divergence tests

stone verge
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the numerator is a geometric series so theres an explicit formula for it

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then test convergence or divergence when you have all in terms of n

stark crater
#

Am sorry but I did not kinda get it can you explain the steps more for me

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I mean if n= inifinity then (1/3)^k won't belong to real numbers

stark crater
blissful sentinel
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if n=infinity then the numerator sum = 1/2

stone verge
#

$\sum\limits_{k=1}^n 1\cdot \left(\frac{1}{3}\right)^k$

thorny flameBOT
stone verge
#

that looks like a geometric series

stark crater
#

yep got it now next step now is?

stone verge
#

you know how to express the sum in a nice formula right

stark crater
#

do you mean to use the formula ?

stone verge
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yes

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but...

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im not sure if that one starts at k=1

stark crater
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the series of the numerator starts from k=1

stark crater
# stone verge yes

okay I used the sum of gemotric series formula here
and then used it on the substitued the value in the main series

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so now I got

stone verge
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this one starts at k=1

stark crater
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oh got you

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I think I got the solution but I did not understand it I will send it

stone verge
#

wdym

stark crater
#

Thank you!

#

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feral olive
#

Can someone help me approach this math problem?
So, I have $u_{n+1} = \frac{1}{n+1} + \sqrt{u_n}$ a sequence and I know that $u_0 = a$ where $a \in \mathbb{R}^+$

I need to find
$\lim_{n \to \infty} (\frac{u_n - 1 - \frac{2}{n}}{\frac{1}{n}})$
How would you guys try to solve this problem?

We know that $\lim{n \to \infty} (u_n) = 1$
And that $t_n$ which is a special case of $u_n$ where $t_0 = 4$, has for limit when $n \to \infty$ the limit: $\lim{n \to \infty} (t_n) = 1$ and $\lim_{n \to \infty} (\frac{t_n - 1 - \frac{2}{n}}{\frac{1}{n}}) =0$

thorny flameBOT
#

Smile!

topaz sinewBOT
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@feral olive Has your question been resolved?

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lethal yoke
#

could someone check if i found the right Interval of convergence

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@lethal yoke Has your question been resolved?

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@lethal yoke Has your question been resolved?

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oak quiver
#

A cube is divided into two cuboids. The body diagonal of the larger cuboid is 16% larger than that of the smaller cuboid. What is the ratio of the volumes of the two cuboids (small : large)?

stark panther
oak quiver
#

I tried it with a system of equations, but it didn't work at all

stark panther
#

by body diagonal im assuming that means from one corner of a cuboid to the opposite corner

vivid coral
oak quiver
vivid coral
#

Then we can get the body diagonals of the two cuboids and compare them

rare thunder
vivid coral
#

Actually you don't even need that

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body diagonal is cube root of (x^2 + y^2 + z^2) right

stark panther
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surely not

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because two sides will be the same as cube

stark panther
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yeah but we know h and b will be the same and I will be a percent of the orgianl length of the cube

oak quiver
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how do I get to the ratio of the volumes of the two cuboids?

stark panther
#

my thought would be to first find the ratio of the two new sides and then use that to calulcate volume of each one

vivid coral
#

So we get 1.16^2 times 2x^2 times y^2 = 2x^2 times (x-y)^2

stark panther
#

im getting something like that

vivid coral
#

Or just calling it x and y seems smarter

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So x = 1.16y anyways no?

stark panther
#

what are you calling x and y

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the diagaonal or length of new cuboids

vivid coral
#

Length I think

stark panther
#

then no

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we know the diagonal of one cuboid is 1.16 of the other

vivid coral
#

Oh wait yeah it's additive

stark panther
#

not the length

stark panther
oak quiver
#

no unfortunately I don't know the answer, it doesn't have to be exact

stark panther
#

because i have an answer but its quite long decimals so im not sure if its correct

topaz sinewBOT
#

@oak quiver Has your question been resolved?

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gleaming drum
topaz sinewBOT
gleaming drum
#

Answer sheet says t20=3,495,265

#

How

smoky sparrow
#

In other words, which function does the solution grow like?

gleaming drum
#

I got 9 but 10 is waffle to me

smoky sparrow
#

Have a look at this

#

You're probably missing out on some key information

#

Specifically, the characteristic root technique

#

(It is possible to do it by iteration which is what the previous examples there show)

gleaming drum
#

ah hold on

#

I got it

#

I tried doing it by hand

#

I got it on the calc

#

Just baffled on the difference lol

#

Also

#

Another question to add on

smoky sparrow
#

ok

gleaming drum
#

What is the primary difference of Recursive rule and explicit?

smoky sparrow
#

For a recursive relation, the next term depends on the current term and the previous terms

#

For an explicit one, it just depends on n

gleaming drum
#

n is any term yes?

smoky sparrow
#

So for an explicit relation, you can find the value of the nth term simply by subbing in n

smoky sparrow
#

For a recursive relation you can't do that

#

So an explicit form is much more useful

smoky sparrow
#

If you have the explicit one

gleaming drum
#

right, do you know any places to further study sequences in depth?

smoky sparrow
gleaming drum
#

Cheers man

#

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topaz sinewBOT
#
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#
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jade knot
topaz sinewBOT
jade knot
#

is there a formula for stuff like this

#

How would I go to solve this? Is it doable without a calculator and without writing out each individual iteration of 1.5^r

jade thunder
#

You can split them into the negative and positive parts

restive inlet
#

geometric series formula

jade knot
jade thunder
#

I mean the iteration over r

jade knot
smoky sparrow
jade thunder
#

Oh I guess the formula just works as well

jade knot
#

sorry I don't rlly understand what you mean Frosst

smoky sparrow
#

Yeah it does, just keep in mind what the first term is and how many terms there are

jade knot
#

but yeah the geometric series formula makes sense

jade thunder
#

Don’t mind what I said

smoky sparrow
#

(The number of terms is not 5)

jade thunder
#

It’s a long way that reduces to the same one that they said

jade knot
smoky sparrow
#

Yep

jade thunder
#

“Why 6?” Would be a good question to be able to answer

smoky sparrow
#

Yeah it's the off-by-one error

#

There are 10 numbers between 1 and 10

#

That's 10 - 1 + 1, so you need the +1

jade knot
#

oh I just thought it was coz of the 0

smoky sparrow
#

So it's not 4 - (-1)

jade knot
#

because -1, 0, 1, 2, 3, 4 is 6 terms 😅

smoky sparrow
#

Yeah same thing then

jade knot
smoky sparrow
#

Like finding the number of numbers between a and b

#

That's b - a + 1

jade knot
#

oh ok

#

thx

#

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#
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smoky sparrow
#

Npnp

jade knot
#

.reopen

topaz sinewBOT
#

jade knot
#

nvm I think I got it

#

.close

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#
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unique latch
#

What's this kind of function?

topaz sinewBOT
jade thunder
#

Looks like a parabola but it could be a lot of things

unique latch
#

A parabola

jade thunder
#

Is there more context?

unique latch
#

Well it's data actually

#

How fast powder is burning

#

It starts off at one point, picking up speed, peaks at the top point, then slows down

jade thunder
#

I don’t know enough physics or chemistry to really help you here soz

unique latch
#

Nah it's fine

#

I just needed the function name

split cloak
#

Negative parabola, i mean similar

unique latch
#

Similar parabola, is that what you're saying?

split cloak
#

Nah

#

I mean it's similar to negative parabola

unique latch
#

Alright thanks

#

Wait

#

Isn't that a hyperbola?

jade thunder
#

It could be a lot of things as I said

unique latch
#

Alright

#

But so far I can tell start at the same origin and move away from each other (They're a reflection)

sour estuary
#

thats a parabola

void crow
#

At the same time it looks like it has some limits as well

#

Like, the domain seems to only exist within 0 and 3.5

sour estuary
#

is that the full picture?

#

could you show the full graph maybe

unique latch
sour estuary
#

theres usually 4 quadrants, but if thats all you have than its for sure a parabola

unique latch
#

But then that begs the question, what's the difference between a hyperbola and parabola?

sour estuary
unique latch
#

Ah thanks

sour estuary
#

np

unique latch
#

Wait, what does the text say

sour estuary
unique latch
#

Alright thanks

topaz sinewBOT
#

@unique latch Has your question been resolved?

#
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copper siren
topaz sinewBOT
copper siren
#

i need help

#

i tried using a^2+b^2=c

#

but im not getting any of the awnsers

ruby acorn
#

Which triangle did you use it on?

#

like what were your a, b, and c?

copper siren
#

X^2+6^2=10

#

which i know is incorect

ruby acorn
#

No, that's a valid step, that tells you what the length from the center to C is.

#

so what's X there?

copper siren
#

it was the square root symbol I/--26 - 26

#

i cant imput it but it looked like that

#

hold on

ruby acorn
#

Oh wait, you're forgetting to square c

#

it's a^2+b^2=c^2

ruby acorn
copper siren
#

hmmm

#

your right!

#

so its x=8,-8

#

but 14 isnt one of the awnsers

ruby acorn
#

8 isn't the length from the center point to D, it's the length from the center point to C

#

there's another step

copper siren
#

solve as if it was right triangle?

ruby acorn
#

what do you mean?

copper siren
#

if we have length of center to c as 8 and 17 as a length can we solve for the missing length?

ruby acorn
#

yes

copper siren
#

so its 15 for missing length

#

plus six

#

for BD it is 21

ruby acorn
#

yep

copper siren
#

thank you

ruby acorn
#

np

copper siren
#

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#
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topaz sinewBOT
#
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topaz sinewBOT
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stoic shuttle
#

The square brackets represent greatest integer function

ivory sorrel
#

split it into multiple integrals

cursive patrol
stoic shuttle
#

ill try

#

yea ty fellas I got it

#

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tame thistle
#

does anyone know how to find this?

topaz sinewBOT
tame thistle
#

i've been struggling enough with this question

#

i have the answer but i just dont know how to do it

#

this is basically a translation of this situation:

smoky fractal
tame thistle
#

oh, is there a technique to put it into the ax+b form

#

i dont think ive learned that

#

i think i have found f(x) = -5x+2

strange jewel
glad otter
#

guys does anyone know vectors pls 😭

strange jewel
#

yeah i know

glad otter
#

pls help

smoky fractal
glad otter
#

ABCD parallelogram, M middle of BC and N middle of CD. find m knowing that AM+AN=mAC. all are vectors

#

i think its supposed to be easy but i have no clue how to do it

strange jewel
#

its simple just apply loop law

smoky fractal
#

Guys this channel is still being used by someone else

tame thistle
#

cus like [-1/15x+2] gives me 1 so

glad otter
smoky fractal
strange jewel
glad otter
smoky fractal
tame thistle
smoky fractal
tame thistle
#

for a purchase of ]40,45]$, the client gets 7 points in both stores

#

40 is excluded

#

so its an interval

glad otter
#

that problem is so weird, are u in high school? i would do f(x)=g(x) and find x but its not the same answer as yours so its wrong

smoky fractal
glad otter
#

right, from the way its formulated i understand the same amount of money are being spent and the same amount of points are being obtained

topaz sinewBOT
#

@tame thistle Has your question been resolved?

smoky fractal
#

I also checked it with this

tame thistle
#

its so weird

smoky fractal
#

Also at x=45 the values are not even close

tame thistle
#

i think drawing it its better

topaz sinewBOT
#

@tame thistle Has your question been resolved?

topaz sinewBOT
#

@tame thistle Has your question been resolved?

topaz sinewBOT
#

@tame thistle Has your question been resolved?

topaz sinewBOT
#

@tame thistle Has your question been resolved?

topaz sinewBOT
#
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neon iron
spiral yoke
#

ok

neon iron
#

Can anyone please tell me how they find p matrix?

#

Don't we construct p using eigenvectors associated with the matrix

loud oasis
#

P has its columns consisting of eigenvectors, yes

neon iron
#

In this quora answer the guy however didn't use the eigenvectors of A or B to construct P

Idk how he got it

#

<@&286206848099549185>

topaz sinewBOT
#

@neon iron Has your question been resolved?

topaz sinewBOT
#

@neon iron Has your question been resolved?

topaz sinewBOT
#
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topaz sinewBOT
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dusk raft
topaz sinewBOT
dusk raft
#

what would be the process?

#

I subbed in ax for y

#

and then I made them both have a common denominator

steady void
#

first simplify the algebriac fraction

#

then

#

sub whatever

brave brook
#

they want x and y in terms of a and b

#

so you can treat a and b as a constant

steady void
#

man what you talking about

#

this isnt integration

brave brook
#

for the answers I think x = ab/(a²+b)
y = a²b/(a²+b)

acoustic tangle
#

!nosols

topaz sinewBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

steady void
#

!nosols

topaz sinewBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

steady void
#

oh jinx

brave brook
steady void
brave brook
#

but can I put it in a spoiler?

steady void
#

no

brave brook
steady void
#

give working out to guide

steady void
#

gimme a sec

brave brook
#

ok

steady void
#

x will change a lot depending on a and b

#

and therefore a and b cannot be constant

brave brook
#

yes I know but you treat them as constant here, as in for all the possible a's and b's you just find the x and y as a general solution?

steady void
#

keyword: for all the possible as and bs

#

x=y is for all possible x and ys, yet x and y are not constants

#

all of these pronumerals are variables, not constants

#

constants are things that are CONSTANT

#

meaning they do not change

dusk raft
#

wtf

#

yo why nobody ping me

steady void
dusk raft
#

😭

steady void
#

they gave you the answer tho

dusk raft
#

uhhhh

#

I MAY have cropped out a bit at the to

#

p

#

saying a and b are constants ☠️

#

my bad

steady void
#

that doesnt affect anything

#

a and b just cant be 0

dusk raft
#

ight

#

.close

topaz sinewBOT
#
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brave brook
steady void
brave brook
steady void
#

not the definition of a constant

brave brook
steady void
topaz sinewBOT
#
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tawdry marten
#

How to do this?

topaz sinewBOT
tawdry marten
#

I do know basic derivative and basic l hospital but idk how to do when there is minus like that

#

L hopital*

delicate drift
#

the - means you have to calculate the left hand limit

tawdry marten
#

Idk what that is

#

What is left hand limit?

delicate drift
#

basically, when we calculate limits, we are tending the value of the variable to some value right?

tawdry marten
#

Yes

delicate drift
#

like here, the value of x is tending to be pi/2

tawdry marten
#

Yes

delicate drift
#

now, the value can tend to pi/2 from both ways

#

pi/2 - 0.00000001

#

or pi/2 + 0.000001

tawdry marten
#

Ohh okay

delicate drift
tawdry marten
#

Yes

delicate drift
#

so you consider that value of left hand limit

#

basically, the question wants to say that you have to consider sign convention of first quadrant while solving the limit

delicate drift
tawdry marten
#

So what to do?

#

We put -90 in x?

#

@delicate drift

delicate drift
#

no, no

#

did you evalute the limit using lhopital

tawdry marten
#

@delicate drift idk how to do it

#

.close

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#
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spice adder
topaz sinewBOT
spice adder
#

Can anyone help me with this?

ember lodge
#

Is this question telling you to find m?

spice adder
#

Yes

#

But i have x

#

And i don't know how to replace them

ember lodge
#

so f(m+1) = 2(m+1) - 4

#

ye

#

you just replace like thsi

#

this*

spice adder
#

I've tried

#

Wait

#

Is in parenthesis?

ember lodge
#

2m + 2 - 4 = m

spice adder
#

DAMN these parenthesis

ember lodge
#

ye

#

and luckily, m = 2 if I didn't make a mistake on calculation]

spice adder
#

It gives me 0

#

I open the parenthesis and i get -4+2

#

Which is -2

#

Wait

restive inlet
#

show your work

spice adder
restive inlet
#

where's m=-1 coming from / why are you using htat

spice adder
#

Oh wait

restive inlet
spice adder
#

I've prove that m is -1 because 2 times -1 equals -2

restive inlet
#

2 * -1 is indeed -2
but that says NOTHING about m being -1

#

why do you think that justifies m being -1

spice adder
#

Because the problem says to replace x with m+1

#

So we can get m

#

And I've did

#

I've opened the parenthesis

#

And it gave me after that m is -1

restive inlet
#

you don't have clear work showing how m is -1

spice adder
#

Clear work?

#

Would You mind showing me the clear work?

#

On paper

restive inlet
#

i still have no idea how you ended up getting m=-1

spice adder
#

The x

#

Like how it ask me to do it

restive inlet
#

yes, and then jumped to m=-1

spice adder
#

And I calculated

restive inlet
#

well there are multiple issues

spice adder
#

By showing that 2*m-2=m

#

Wait

restive inlet
#

you started with
$$2(m+1) - 4 = m$$
expanded to get
$$2m + 2 - 4 = m$$
THEN, the right side / presence of an equation disappeared (which was invalid btw) leaving you with
$$2m +2 - 4$$
which upon simplification gave
$$2m - 2$$
then BOOM out of nowhere
$$m = -1$$

thorny flameBOT
#

ℝαμΩℕωⅤ

spice adder
#

I'm cooked

restive inlet
#

go back to this equation

2m + 2 - 4 = m

spice adder
#

I know

#

That's where i am

restive inlet
#

you recognised that the left side simplifies to $2m - 2$ which leads to getting
$$2m - 2\ \red{ = m}$$
then solve that

thorny flameBOT
#

ℝαμΩℕωⅤ

spice adder
#

That's right

#

Is this right?

#

That's how i would have calculated

restive inlet
#

is what right

spice adder
#

Is 2m-2=m?

restive inlet
#

yes.

#

then solve that

spice adder
#

Now what the fuck do I do

restive inlet
#

then solve that

spice adder
#

HOW

restive inlet
#

,tex .algebra lesson

thorny flameBOT
#

ℝαμΩℕωⅤ

restive inlet
#

tldr, same operations to both sides of the equation to work towards isolating what you want

spice adder
#

So o move 2 over equal?

#

While changing the sing in front of him?

#

Coming as 2m=m+2?

restive inlet
#

yes, continue

topaz sinewBOT
#

@spice adder Has your question been resolved?

spice adder
#

Can anyone help me with this?

#

I'm actually cooked

topaz sinewBOT
#
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elfin escarp
topaz sinewBOT
elfin escarp
#

help needed

mint crescent
#

Didn’t someone already answer this

elfin escarp
#

no

mint crescent
elfin escarp
#

a different

#

question

#

i cant cant cant figure it out

mint crescent
#

You can still Google it

elfin escarp
#

how can i come up with this method

#

how

topaz sinewBOT
#

@elfin escarp Has your question been resolved?

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#
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ionic oar
#

If you have the equations of 3 lines is there an effective way to get the coordinates of the centroid of the triangle formed

ionic oar
#

Other than you know brute forcing and solving

#

.close

topaz sinewBOT
#
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ionic oar
#

.reopen

topaz sinewBOT
#

ionic oar
#

monseiur garrrlic

icy sky
#

best i can give you is find the intersections then average

ionic oar
#

-_-

#

yeah thats what i meant by

#

brute force

#

thanks anyways though

#

.close

topaz sinewBOT
#
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ionic oar
#

:)

icy sky
#

its not really brute force

ivory sorrel
#

the shoelace formula might work

icy sky
#

shoelace requires points

#

to find area

ivory sorrel
#

yes

ionic oar
#

coplanar yes

icy sky
#

not quite the right theorem to use

ionic oar
#

.reopen

topaz sinewBOT
#

ionic oar
#

the hell is shoelace

ivory sorrel
#

The shoelace formula, also known as Gauss's area formula and the surveyor's formula, is a mathematical algorithm to determine the area of a simple polygon whose vertices are described by their Cartesian coordinates in the plane. It is called the shoelace formula because of the constant cross-multiplying for the coordinates making up the polygon,...

icy sky
#

theres a mathologer video

ionic oar
#

oh that

#

thing

#

eh

#

¯_(ツ)_/¯

#

brute force it is

#

.close

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#
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topaz sinewBOT
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rugged plank
#

could someone help me determine whether this series converges or diverges?
$$\sum_{n=1}^\infty (-1)^n \frac{\ln n}{\sqrt n}$$

my book solved it by determining it is decreasing by the following:
$$f(x) = \frac{\ln x}{\sqrt x}$$
$$f'(x) = \frac{2 - \ln x}{2x^\frac{3}{2}} < 0 \text{ when } x > e^2$$
and then doing l'hopitals to get the limit of the series
$$\lim_{n \to \infty} \frac{\ln n}{\sqrt n} = \lim_{n \to \infty} \frac{\frac{1}{n}}{\frac{1}{2\sqrt n}} = \lim_{n \to \infty} \frac{2}{\sqrt n} = 0$$
and then stating it is convergent by the alternating series test

this makes total sense but i don't know how they found the bounds on which it is decreasing ($x \gt e^2$) and i would not be able to do this method on a test.
i tried comparing it to a p-test with the absolute value of the series, but it came out divergent and i had some flaws in my reasoning.
thanks!

thorny flameBOT
#

declspecl
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

rugged plank
#

like i can understand that $2 - \ln e^2 = 0$ but i honestly doubt i would be able to remember that quickly for a test, so im wondering if there are other methods

thorny flameBOT
#

declspecl

glacial adder
#

they just solved for when f’ equals 0

rugged plank
#

oh wait actually i guess you can do the numerator trick

#

and just ask when $2 - \ln x = 0$

thorny flameBOT
#

declspecl

glacial adder
#

there’s not really any other way than just straight up graph ln x/sqrt x

#

yeah

rugged plank
#

hmm alright ill just have to keep that trick in my mind

glacial adder
#

taking the absolute value sometimes help

#

but if the absolute value version diverges, it doesn’t mean the original series diverges

#

only if the abs version converges then the original converges

rugged plank
#

right, like the alternative harmonic i gotcha

#

makes sense ty 🙏 i get it conceptually ill just have to practice it

#

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#
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glacial adder
#

yeah practice makes perfect

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gloomy jacinth
#

Prove that for any numbers a, b, c, d belonging to the interval ⟨0, 1⟩ the inequality is true

gloomy jacinth
#

Someone has an idea

topaz sinewBOT
#

@gloomy jacinth Has your question been resolved?

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#

@gloomy jacinth Has your question been resolved?

gloomy jacinth
#

<@&286206848099549185>

elder shoal
#

this is an olympiad problem, and is probably not best asked here, but try expanding lhs and recall x^n>x^m for n<m, x in (0,1)

topaz sinewBOT
#

@gloomy jacinth Has your question been resolved?

bright panther
#

ask here^^

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fierce zealot
topaz sinewBOT
fierce zealot
#

I dont understand the first example

#

So we have $$a(x) = x^3+x+1, b(x) = x+1 \in \mathbb{Z}_3 (x)$$ and $$f(x) = x^2 \in \mathbb{Z}_3 (x)$$. But $$a(x) - b(x) = x^3 \equiv 0 \pmod{x^2}$$? WHy is that true

thorny flameBOT
#

WhoTao

fierce zealot
#

But x^2 | x^3, so x^2 |x^3

#

I dont think thats true?

#

Oh, I guess x^2|x^3 means there exists another polynomial q(x) such that x^2 * q(x) = x^3

#

where q(x) = x

#

Like that?

topaz sinewBOT
#

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wise osprey
#

How do I find the vertices of a hyperbola with the form xy=c? The exact problem is 9xy=16?

terse nest
#

i think the intersection between the line y=x and a hyperbola in the form of xy = c will be its vertices

#

so you are just solving the system of equations of
9xy = 16
x = y

#

sub the values in and you will find the vertices

wise osprey
#

Thanks you

#

.clos

#

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knotty tapir
topaz sinewBOT
knotty tapir
#

my question is on the second page

#

but u need the graphs from the first page

#

why is 5 b,c and d different

#

i thought if u wanted to go back u would take inverse

#

why do you ahve to change order of f and g for one not the order if ur going back in both

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#

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#

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dull ravine
topaz sinewBOT
dull ravine
#

can someone help me, i think im wrong bout this one

#

since B repeated it feels wrong

ruby mural
#

,calc 41*41

thorny flameBOT
#

Result:

1681
dull ravine
#

what

ruby mural
#

Nvm that

dull ravine
#

i c

ruby mural
#

2nd and 3rd are right

#

secA= cscB provided that A+B=90⁰

low nymph
#

they were clever enough to make answers match =w=

sour estuary
#

do you know what every value is?

low nymph
#

?

dull ravine
#

oh it was a trick one

sour estuary
#

do you know which one is hypotenuse

#

and opposite

#

and adjacent

dull ravine
#

ya opposite of right angle is hypo

low nymph
#

AB = 41 is clearly the hypotenuse 🤔

sour estuary
#

no tell me the values

dull ravine
#

oh

#

Hypo=41, Opposite of A is 9, Opposite of B is 40

low nymph
#

correct 👍

sour estuary
#

okay

#

so sin = opp/hyp

dull ravine
#

and adjacent of B is 9 and A is 40

sour estuary
#

cos = adj/hyp

#

tan = opp/ adj

#

can you tell me those

#

values

low nymph
#

to be fair, we already have a perfect answer 🤔

dull ravine
#

sinA= 9/41, sinB= 40/41

#

OHHH

#

ye ty i think i understand why E isnt a correct answer

sour estuary
#

and whys that

dull ravine
#

because only sinB can have 40/41

#

and sinB was not asked

sour estuary
#

yeah exactly

#

csc = hyp/opp

#

sec = hyp/adj

#

cot = adj/ opp

dull ravine
#

ic ty

#

oh wait

dull ravine
sour estuary
#

itd be good to write those down because if you mess those up everything is then messed

dull ravine
#

yeh ima write it

#

ight thx

#

.close

topaz sinewBOT
#
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topaz sinewBOT
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#

@deft marten Has your question been resolved?

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granite lintel
#

Hey i have problem how to find out range of function like this

granite lintel
#

it's inverse proportion

jovial wren
#

Range is all the possible outputs. Is there any value on the number line that y could never have?

topaz sinewBOT
#

@granite lintel Has your question been resolved?

granite lintel
#

because in the answers i have a R - (some number)

jovial wren
#

I don't understand what you mean by H(f).

#

Try throwing this equation up on desmos and looking at it. Is there any value that can never be reached on the y axis?

granite lintel
#

sorry i thought it's the same in the english

so when you have a function you domain which is or x and there is the other one for y

jovial wren
#

Domain means, all the possible y values you could get

#

oops, sorry

granite lintel
#

not x ?

jovial wren
#

Domain is all the possible x values you could stick in

#

Range is all the possible y values you could get out

granite lintel
#

yes

jovial wren
#

So... look at the equation on desmos and see... are there any y values you can't get out?

granite lintel
#

i don't think so

jovial wren
#

Bingo.

#

There is a y value you can't get.

granite lintel
#

?

jovial wren
#

0

granite lintel
#

why ?

jovial wren
#

For what x value is the y value 0?

#

Please provide the x such that 2 / (x-1) = 0

granite lintel
#

ok

#

so

#

it isn't possible

jovial wren
#

You can't divide 2 by anything and get 0

granite lintel
#

yes

jovial wren
#

The horizontal line is a y value that you can never have. The vertical line is an x value that you can never input.

#

I mean the dotted lines on desmos

topaz sinewBOT
#
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granite lintel
#

and if i would have this

jovial wren
#

That will shift the lines around.

granite lintel
#

like how can i found which number isn't part of range

#

from graph ?

topaz sinewBOT
#
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jovial wren
#

Start by viewing a whole bunch on desmos and look for the patterns

jovial wren
#

You probably can't use desmos on the test

granite lintel
#

yes

#

i see -2

#

isn't that asymptoty ?

jovial wren
#

Correct. You are shifting the horizontal asymptote down

granite lintel
#

yes but how can i find asymptote for y in the prescription ?

jovial wren
#

asymptote for y is the horizontal asymptote

granite lintel
#

like some method

jovial wren
#

Well, the method is to see that if you subtract 2 from the fraction, then the asymptote moves down by 2. So before the rnage was all reals except for 0, now the range is all reals except for -2.

granite lintel
#

ok

jovial wren
#

good luck!

granite lintel
#

thanks

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#

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ancient crag
topaz sinewBOT
ancient crag
#

Anyone that can explain this better than photomath?

#

Im supposed to use the formulas sin(2v)=2sin(v)cos(v), and cos(2v)=cos^2(v)-sin^2(v) to help solve it, but im a bit confused as to how

kind forge
#

does someone help me with this geometry question?
or knows an ai that solves geometry ?

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#

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