help-26

[willow silo]

Obiviusly OMAN is a deltoid because ON=OM and AN=AM

I can't get to the second diagonal to calculate the area

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[unborn kraken]

can someone help explain this question to me and help me come up with a question

[tranquil verge]

,rccw

[tranquil verge]

dose he mean for example the equation x=3 and y=4
then the point would be (3,4)?

[unborn kraken]

i think so cause that fits all the boxes, but would my question be find horizontal and vertical for point 3,4

[tranquil verge]

that might be it, but it would be easy if this is the case

[unborn kraken]

i know thats why im skeptcial of the wording of the question

[unborn kraken]

what does it mean by different x and y coordinates?

[tranquil verge]

if he doesn't mention the word " horizontal" and "vertical" then i would assume the two lines to be in angle, then that would make sense

[tranquil verge]

idk, but it seems to me that there is not much in the question

maybe im wrong since english is my second language

[unborn kraken]

ah okay ty

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[proud ridge]

ok i have no idea what im doing, im supposed to write this is parametric vector form and idk what to do next

[keen venture]

Looks pretty good! Anything here concerning you?

You've lost an x3 in the final answer

[proud ridge]

this is the teacher's solution

[keen venture]

Oh you were never supposed to have that x3 in your answer

[proud ridge]

yeah...

but why not?

[keen venture]

Top equation reads:
x1 - x2 + x4 = 2

But you wrote:
x1 - x2 + x3 = 2

[proud ridge]

ohhh

[proud ridge]

also for x3 = shouldn't it be x3 = x4+1?

[proud ridge]

but here it says **-**x4+1

[keen venture]

Yep! Excellent call, this seems like a mistake

[proud ridge]

okay im gonna try the question again and could you check after pls?

[keen venture]

Sure

[keen venture]

,w matrix row reduce {{1,-1,-1,2,1},{2,-2,-1,3,3},{-1,1,-1,0,-3}}

[thorny flame]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by kaynex

[keen venture]

Yeah seems good

Oh wait, you've dropped a negative

[proud ridge]

so for the final answer the only difference is it'll be
x4 (-1)
(0)
(1)
(1)

[keen venture]

ye

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[nocturne osprey]

could someone guide me through this?

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[vapid notch]

using formula 1/4p * (x-h)^2 + k

where p is the dist from focus to parabola point

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[neon iron]

express as a product. 1+sin(a). Please provide your answer in radians and use π where appropriate.

[grim sable]

you can use the sum to product formulas

1 = sin(pi/2)

so sin(pi/2) + sin(a) = your answer

and we have this

So you answer is just 2sin((pi/2 + a)/2)cos((pi/2-a)/2)

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[noble laurel]

What is your doubt?

Actually why did you blur whatever this is out?

Is it a test?

Interesting why it would have your school name on it but okay. What's confusing you about it?

No it's fine

[bitter hemlock]

@noble laurel clear that doubt

so what'd you get for the derivatives of each coordinate function?

[noble laurel]

https://tenor.com/view/order66-will-do-will-be-done-star-wars-revenge-of-the-sith-gif-22742954

[bitter hemlock]

dx/dt on your paper is wrong, what's the derivative of tan x ?

you confused it with cot x

ya thats correct, but here you wrote -csc^2 ?

but the dy/dt is not what the dx/dt was supposed to be

we just said it's this

i guess you can write it all in terms of sin and cos: sin / cos^3

cos^2

at the end

anyway just do the derivatives carefully, write it all in terms of sin and cos, then when you plug the squares into the arc length formula probably find a common denominator and something will cancel out somewhere

try to do that work correctly and come back if you have any trouble

isnt there a - in the dy/dt

well youre squaring it so i guess doesnt matter

seems right otherwise

[bitter hemlock]

sorry but i've gotten kind of busy, can't respond

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[neon iron]

I feel like im making a very basic error / typo but I cant see it at all

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[vernal matrix]

The z one shouldn't that be cos?

The x and y ones "combine" to make a sin^2(f)

[neon iron]

oops...

I just went and checked my textbook I miswrote that z = rsin(phi) in my notes

urhgughsuruhsrj

I was so sure about it LMAO

ty

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[naive breach]

just started distributions what the hell is expected value and why are there 3 different formulas

[sturdy oracle]

One's for discrete random variables, one is for continuous random variables

[naive breach]

So one would be for binomial distirbutions & one for normal distributions?

[vernal matrix]

The binomial one is gained by working with the discrete one

[sturdy oracle]

https://tenor.com/view/family-guy-dancing-bird-is-the-word-trashmen-surfin-bird-gif-27644963

Binomial is discrete

[naive breach]

and the continous formula is used for normal distrbutions...?

[sturdy oracle]

Yup

[vernal matrix]

(along with any other continuous one)

[naive breach]

Still a bit confused as to what E(X) = np is then

[sturdy oracle]

It's saying that the expected value of the binomial distribution is equal to the number of things times the probability of successes

So if you like

Well I mean idk how to prove it lol I just know that the expected value of a binomial distribution is np

[naive breach]

and that can also be represented as xp(x)

(i think? idk im dumb)

[sturdy oracle]

No because p is the probability of success

Like p is gonna be a constant

[naive breach]

yep

[sturdy oracle]

Say you have n observations

n is the number of observations

n is also gonna be a constant

[naive breach]

trials * probability of success

but like

how does that thing

become

[sturdy oracle]

well I mean so

f(x) is the binomial distribution

f(x) is whatever discrete distribution

In the case of binomial distribution, $f(x) = \binom{n}{x}p^x(1-p)^{n-x}$

[thorny flame]

Peter Griffin

[sturdy oracle]

Replace it in the summation and some genius was able to simplify it down to np

[naive breach]

which is the probability of p(X=x) occuring

amazing

beautiful

thank you peter griffin

but um

[sturdy oracle]

https://tenor.com/view/peter-griffin-gif-11725800145853034187

[naive breach]

legit the same thing with variance

variance is npq and this

how

when do i use which

[sturdy oracle]

Well Var[X] is Σ(X-μ)^2f(X)

How they got that

Give me a sec

Well you can start from there

My mental math brain is having a bit of a sloozy since I'm suffering from a bad food coma lol

Currently lying on the couch trying not to fall off

[naive breach]

lmao ironic

[naive breach]

see this is confusing because this is the same as npq

yet in questions

you use the two at different times

[sturdy oracle]

ΣX^2 f(X) - 2ΣXμ f(X) + Σμ^2 f(X)

Well npq is variance for binomial distributions

You get npq by going through the variance process with binomial distribution

npq doesn't apply to all

[naive breach]

but i assumed discrete could be applied to binomial

[sturdy oracle]

This becomes E[X^2] - 2ΣXμ f(X) + μ^2

[sturdy oracle]

Discrete is applied to binomial. Same process. What they did was like how they found the expected value; they replaced f(x) with the binomial distribution

$\sum (X - np)^2 f(X)$

[thorny flame]

Peter Griffin

[sturdy oracle]

And somehow some genius found that equaled to npq

[sturdy oracle]

So this image here is the general case. But npq is specifically only for binomial distribution

It's like a shortcut for binomial distributions

Instead of having to use the general formula

[naive breach]

okay beautiful

that makes

more sense

so if i'm given a table a value

of values

[naive breach]

i should opt for this

[naive breach]

and this

[sturdy oracle]

Well you need to know it's distribution first

But if you know its probabilities

Then you can just use the general case

[naive breach]

as in like

it says

erm lemme see

wouldnt be -1**

[sturdy oracle]

Yeah pretty much

[naive breach]

And to clear up the distribution would essentially be probabilities of x occuring

[sturdy oracle]

Well yea

[naive breach]

thank you peter

may you get more lemons in life

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[sharp dew]

At

[sharp dew]

At

Aaaaa

Instant velocity, power, or anything else

How do you guys denote them

V_I?

[smoky sinew]

Instant velocity?

Wym

I think its just denoted by V_t where t is the time

Why

[sharp dew]

I see

What about the “average”

[smoky sinew]

Average velocity over some time frame?

[sharp dew]

For sure

[smoky sinew]

Not sure about the notation for it

[loud oasis]

i would say that $v$ is the instantaneous velocity on its own, whereas average velocity would be $v_\text{avg}$ or $\ab<v>$

[thorny flame]

cloud

[smoky sinew]

I was taught that v represented velocity at current time

If you wanted instananeous velocity at a time t we used to do v_t

[sharp dew]

What if I want to state that the average velocity is for a particular time span

[smoky sinew]

Context?

Bc for some problems they give u notation

[sharp dew]

Like the average velocity is for the time span between t=1 and t=5

[smoky sinew]

But in general you can kinda make your own shit up

[sharp dew]

I do not want to confuse people

[smoky sinew]

Just say “define the average velocity from time A to time B to be…”

[loud oasis]

i would write v_avg(1 ≤ t ≤ 5) but it's mostly a style preference

[sharp dew]

That takes too much effort to write down

[stone verge]

v with a bar

[sharp dew]

That seems terrific

[sharp dew]

v has already a vector which has a hat above its head.

[stone verge]

a flat hat?

[sharp dew]

That’s confusing IMO

[stone verge]

v_{avg}

[lucid junco]

v with a squiggle underneath

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[supple socket]

can someone explain how i can understand to know how to write the domain based on the inequality?

[supple socket]

my brain isn't comprehending

[smoky sinew]

Its the interval

All numbers between those 2 points

Including points in this case

[supple socket]

but i dont understand the rules to rewrite the inequalty in that form

[naive breach]

okay simple

if im not wrong you're asking how something like

$3 \le x \le 5$

will become

$[3,5]$

[thorny flame]

[DATA-LOST]

[supple socket]

yes

[naive breach]

so basically

theres a few sets of rules

your lower limit will come first, and then your upper limit when you put into (a,b) form

then you have to decide if you use brackets [] or parantheses ()

if you have:

$ \le or \ge $

$then use brackets [ ]$

[thorny flame]

[DATA-LOST]

[naive breach]

else if you have infinity or normal less than and greaer than

use paranthesis

[supple socket]

i appricate it! this 6 week course is kicking my ass

[naive breach]

nws i feel you

[supple socket]

tried asking the professor for help. its an online course but shes says she cant help due to a family emergency and ill need to refer to the textbook or the library tutor

fml

[naive breach]

dang bruh it's like a 1 minute question

but i hope it makes sense now

[supple socket]

it does!

[naive breach]

it'll become second nature as you practice and come across it

what're you taking?

[supple socket]

college algebruh!

[naive breach]

calculus and allat

good luck

[supple socket]

no its not even calc lmaoo

[naive breach]

wait huh

[supple socket]

im in my first year lmao

first semester

[naive breach]

lmao then just algebra and graphing

idk how it works for you wherever you're at

[supple socket]

pretty much

i suppose

[naive breach]

🥴 wait till you get to integration

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[limber ridge]

Want to check my methods solving this question

[limber ridge]

$R(x)=(500-x)(180+\frac{2x}{10})$

[thorny flame]

The Great D

[limber ridge]

where R(x) represents the revenue earned with a discount of x euros

$R(x)=(500-x)(180+\frac{x}{5})$

[thorny flame]

The Great D

[limber ridge]

$R'(x)=\frac{500-x}{5}-(180+\frac{x}{5})$

[thorny flame]

The Great D

[limber ridge]

but at this point, setting R'(x) equal to 0 gives me a negative x

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[neon iron]

I dont understand how they got from line 1 to line 2

[worthy storm]

looks like a typo

second term should be 2000/r

and that should read 0 < r <= 2000 as r=0 is obviously not allowed

[neon iron]

yeah I was going to say, let me look at the line afterwards to see if they persisted with this error

seems not

[worthy storm]

yea

[neon iron]

alright well, thank you

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[gilded creek]

xln(d) + ln(d-1) = ln(x)
Is anyone able to solve this for d?

[cursive mango]

You can combine all the logs into one right

[half edge]

ye just combine the two on the left

Then youll basically have a clear path to answer

[dusty token]

or bring right to left n them combine?

[half edge]

whats the point

[dusty token]

same thing my bad

[half edge]

or maybe just e^ both sides?

who knows

[gusty bane]

this seems fairly difficult

you get d^x(d-1) = x

[dusty token]

yea

[half edge]

hold on lemme try

[gusty bane]

yeah it looks like it's lambert-y

[half edge]

Wow wait yea

i totally screwed up the first combination

My fault

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@gilded creek Has your question been resolved?

[gusty bane]

@gilded creek do you have more context?

as it is, solving for d is a bit hopeless

[gilded creek]

i wanted it to be solved for d

[gusty bane]

yes but that probably can't be done with elementary functions

do you have more context

[gilded creek]

I can give more context but I am currently occupied. Ill try it again later.

[gusty bane]

if you could that would be helpful

[gilded creek]

e^a = d

[gusty bane]

is there more context than this

like an original problem

[gilded creek]

It will take some time to explain i dont have now, i will just ask again later and provide more context, ty for trying though.

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[hot bramble]

hey

[hot bramble]

im pretty sure i ddi this wrong

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[hot bramble]

<@&286206848099549185>

please

[hot bramble]

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[distant linden]

whats the point of me doing p(0) and p(24) ? plz

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[distant linden]

I dont get how to find the domain for the question ?

i heard that u should minimize one of the variables by setting it equal to 0 and finding the max value of the other variable

but it doesnt work here ?

how am i supposed to know which variable to set to 0 to find the domain ?

[dusty token]

you just gotta maximize the area

do you know that after differentiating area and equating it to zero, we either get maxima or minima (we can check which one is it by double differentiating, if its positive then minima, if its negative then maxima)

[distant linden]

yes

[dusty token]

so in this case, double differentiating of area is negative, so whatever the value of x we get after equating the differential to zero will me the maximum value of area

[distant linden]

okay yes

[dusty token]

so wuts the maximum area u gettin?

[distant linden]

1562.5

[dusty token]

me too

is it correct?

[distant linden]

yes

[dusty token]

cool

[distant linden]

but why is the domain 0 < x < 100

[dusty token]

area cant be negative

so i guess thats why the domain thingy

area in terms of x, its is greater than zero

[distant linden]

oh

did they do w = 100 here and thats why its the domain

[dusty token]

huh?

[distant linden]

sorry this is what they taught me

im confused aswell

setting l = 0

causing w = 100

[dusty token]

domain is the set of possilbe values for x

[distant linden]

yea

[dusty token]

like this

you familiar with wavy curve method used to find the domain?

[distant linden]

ohh

do u mean interval testing?

[dusty token]

idk wut its called in ur texts

[distant linden]

the line thing u did

[dusty token]

yea yea

we call it wavy curve method

[distant linden]

I understand now

[dusty token]

i searched up, yup it is interval testing

[distant linden]

I kind of forgot how to do inequalities tho

[dusty token]

yea we reverse the sign when we multiply negative number on both sides

[distant linden]

oh yea thatt

[dusty token]

like after my second step i did that

[distant linden]

i see

I have a question

how do you know which equation to do interval testing on

the one you're trying to maximize ?

[dusty token]

hmm here it wasnt necessary to find the domain

do you understand that this is the domain of the widht of that compound?

[distant linden]

i didnt honestly

so when doing problems I shoudl use the variables x and y instead?

x = domain ?

[dusty token]

the domain basically tells wut are the possible values of width, like in this case it was greater than zero and lesser than 100 (it cant be greater than hundred)

[distant linden]

ohhhhhhh

im understanding it more now

why do some people set l = 0 to find the domain tho?

[dusty token]

so it wasnt asked in the question to find the domain of width so.. who told you to find the domain tho?

[dusty token]

thats actually a wrong approach, the more appropriate approach is area>0 (area cant be zero or less than zero, think practically)

[distant linden]

oh ok

[dusty token]

oh i didnt read that, my bad

[distant linden]

so whatever the equation you're trying to maximize or minimize > 0

2400w - 2w^2 > 0

how would u do that tho

[dusty token]

nah nah, its as per the given condition. Here in this question there wasnt a condition specified, but we know for a fact that area cant be less than zero in real life

[distant linden]

oh ok

[dusty token]

wait ill show ya

as simple as that

0<w<1200

[distant linden]

ohhh ok

I tried it here and it worked

[distant linden]

how come its a wrong approach? my teacher taught it

i would like to do the faster way thats why im malding lmao

[dusty token]

yea correct, therefore x belongs to (0,15) U (20,∞)

i understand you would like to do it faster (my gf wanted me to it faster too) but understanding the logic behind what we just did is more important in my opinion

[distant linden]

Ur right bc i didnt understand the last way

[dusty token]

interval testing one?

[distant linden]

no no

the l = 0

I understand the interval testing but im scared i might not be able to do inequalities after not doing it for so long

Ill youtube it lol

[dusty token]

dude im just trippin, i need to put my shit up (its 3.47am here rn)

[dusty token]

yea just learn the fuck out of it

[distant linden]

loll

tysm for ur help i've struggled with this stupid domain thing for days

no one could explain it

[dusty token]

yea just learn, n then practice a few hours n u gud asf

[distant linden]

ty ty

ill close now

[dusty token]

well then gn i g

[distant linden]

goodnight!

.close

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[whole otter]

I need help

[whole otter]

I tried (1585) (0.09) (196/365) which its not working

.close

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[stable wren]

how do I find the exact value of this

[topaz sinew]

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[wooden osprey]

use unit circle

oh

[stable wren]

oops

uh

[wooden osprey]

open new channel

[stable wren]

.close

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[covert acorn]

hi

[covert acorn]

Im trying to do this problem

but I believe the bounds I am using are wrong

how do I figure the bounds that are needed for the formula

[topaz sinew]

@covert acorn Has your question been resolved?

[covert acorn]

<@&286206848099549185>

[stone verge]

what formula

[topaz sinew]

@covert acorn Has your question been resolved?

[covert acorn]

i just dont know how to get the bounds

[stone verge]

ok so there should be a point that is "repeated" there to be a loop

there is t1 and t2 with the same (x,y)

(x(t1),y(t1)) = (x(t2),y(t2))

maybe this gives you an idea

[covert acorn]

theres no point where theres the same x and y

for two different t values

[stone verge]

to type the parametric in Desmos you should use (6t-2t^3, 6t^2)

[covert acorn]

dont i have to do x = and y =

[stone verge]

that's implicit

(x,y) = (6t-2t^3, 6t^2)

[stone verge]

this is what you need

$6t_1 - 2t_1^3 = 6t_2 - 2t_2^3$ and $6t_1^2 = 6t_2^2$

[thorny flame]

svcccccccccccc

[covert acorn]

im still confused

would the bounds be

[stone verge]

what confuses you

ok you want $<x(t_1),y(t_1)>=<x(t_2),y(t_2)>$ with $t_1 \neq t_2 $

[thorny flame]

svcccccccccccc

[stone verge]

if $t_1 = t_2$ then is the same point but at the same time. You want to go two times through the same point but at different times

ok

[thorny flame]

svcccccccccccc

[covert acorn]

yea that makes sense

im just confused on how to get that point

[stone verge]

$x(t) = 6t-2t^3$ and $y(t) = 6t^2$. What would be $x(t_1)=x(t_2)$ and $y(t_1)=y(t_2)$?

[thorny flame]

svcccccccccccc

[covert acorn]

this right?

[stone verge]

yes, but it would had be better to keep the subscript

[covert acorn]

ok

so bounds would be from 0 to root 3?

[stone verge]

no and that was the thing to keep track of the subscript

from -sqrt3 to sqrt3

[covert acorn]

what

oh

[stone verge]

ok wait

[covert acorn]

cause 0 is part of that range right

[stone verge]

no

[covert acorn]

so u would go from -root3 to root 3

[stone verge]

.

[covert acorn]

can you show me it

im not understanding it with that image

[covert acorn]

ok ty

so that should be the bounds right?

or no

[stone verge]

yes

[covert acorn]

so i got 41.569

idk if thats right or not

can I do this?

with the integral from -root3 to root 3

[covert acorn]

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[safe geode]

if an object with mass 2kg is moving right at speed 4m/s and hits an object b with unknown velocity ends up with the object a having a final velocity to the right of 1m/s. what is the mass of object b?

[safe geode]

a)1
b)2
c)3
d)4

[fair thorn]

!status

[topaz sinew]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[safe geode]

2

ive tried cons of momentum

relative speed

i cant find an answer

[neon iron]

the objects a and b stick?

[safe geode]

unknown

[topaz sinew]

@safe geode Has your question been resolved?

[topaz sinew]

@safe geode Has your question been resolved?

[topaz sinew]

@safe geode Has your question been resolved?

[vernal ledge]

huh

are you sure the options are right?

[safe geode]

They arent together after collision

Since it was never stated they are

[radiant marlin]

you have to assume elastic for some reason

[safe geode]

This is taken from indonesian physics olympiad questions

[vernal ledge]

hmm

[radiant marlin]

nvm I give up I hate this question

[safe geode]

Lmao

[vernal ledge]

im still getting b=8

both cases don't work

[topaz sinew]

@safe geode Has your question been resolved?

[arctic briar]

If b is moving at 0 speed then it should be 6kg from ratios

But it’s unknown speed so you can’t know the mass

Oh right 1-4

If B was 1kg then it was moving left at 5m/s

If b was 2kg it would have been moving left 2m/a

If b was 3m then it would have been moving left 1m/s

If b was 4kg then if would have been moving left at 0.5m/s

This is for sticky collisions btw

Non sticky could be any range of energy transfers so you don’t know

[scenic flare]

the task obv doesn't provide enough information

if I denote the object A as 1 and object B as 2

we're given

for an elastic collision (since you mentioned we were not to assume it may be plastic), we'd know under the conditions of it being energy-lossless:

[topaz sinew]

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[scenic flare]

&

combine them:

reinsert into first to get v2:

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[scenic flare]

now for any value m2, be it 1kg, 2kg, 3kg or 4kg, there exists a solution for v2 & u2

[scenic flare]

@safe geode

which means you either provided insufficient information (e.g. lossless plastic) or the task is useless

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[bold sonnet]

How can I draw a 3d plane from its equation just by looking at it? (if that is even possible)

[bold sonnet]

I've got the cylinder x^2+y^2=4 which ik how it looks

and the plane z=4+x+y that cuts through it

but I don't know what it looks like

[chilly walrus]

might be helpful to convert it into parametric form

from there you'll be able to plug in specific values and get results

[craggy haven]

can also find its intercepts

so like set x = y = 0 and see what z is

and do the same for the other two

then plot those three points and that should give you an idea of your plane

[bold sonnet]

great thank you

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[plucky fern]

Could anyone help me with 9 math problems i think it would be easy for you guys but not me

[radiant sparrow]

we're not allowed to provide full solutions, you can show us work and get help in the steps

[plucky fern]

Can i get a channel

So i can send it

[craggy haven]

https://tenor.com/view/youve-already-got-one-danny-mullen-you-have-obtained-it-earlier-you-already-have-it-gif-27023982

[topaz sinew]

@plucky fern Has your question been resolved?

[plucky fern]

No

[topaz sinew]

@plucky fern Has your question been resolved?

[plucky fern]

<@&286206848099549185>

[topaz sinew]

@plucky fern Has your question been resolved?

[sick torrent]

have two angles equal
the two triangles are symmetrical
ratio of Perpendicular to base of first triangle is equal to ratio of perpendicular to base of second triangle

P1/B1= P2/B2

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[thorny totem]

the answer I’m getting while figuring this out doesn’t make sense

[orchid lotus]

i believe the answer is -2 over root 40

for sin theta

[worthy storm]

you should be calculating (-6)^2 and (-2)^2, not -6^2 and -2^2

[topaz sinew]

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

[worthy storm]

!nosols

[topaz sinew]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[orchid lotus]

yeah i was gonna explain after they answered

mb

[thorny totem]

Idk how to rationalize mbb

[worthy storm]

nw, it's preferred to guide the helpee to solve it themselves, they'll learn better that way

[worthy storm]

r will always be positive, so you can ignore the negative solution

[thorny totem]

Oh really?

Oh true

Duh

[worthy storm]

yea, it's the hypotenuse, right?

[thorny totem]

Yeah

[orchid lotus]

@worthy storm could u also help me on my question after u help them cuz no one replied to me yet 😦

[worthy storm]

yea, i'll take a look

[orchid lotus]

thanks

[thorny totem]

Is Y the adjacent or the opposite?

Opposite right

[orchid lotus]

yea i think so

[thorny totem]

Not sure how to simplify this sorry

[orchid lotus]

so basically

you multiply the numerator and denominator by 2 root 10

[thorny totem]

Uh uh

[orchid lotus]

so like

multiply it by 2 root 10 over 2 root 10

cuz 2 root 10 over 2 root 10 is just 1 right?

like that

cuz esentially your just multiplying by 1

[thorny totem]

and then

[orchid lotus]

what did u get after u multiplied it

?

[thorny totem]

erm..

[orchid lotus]

lol no worries

what does that equal to

[thorny totem]

Square root of 10 over square root of 10? 😭😭

4 square root of 10

[orchid lotus]

yes

now

what is

[thorny totem]

Uh

4square root of 10?

or 20..

[worthy storm]

sqrt(10) times sqrt(10) is what?

[thorny totem]

Oh

Just 10 right..

[orchid lotus]

yeah

[thorny totem]

oh..

[orchid lotus]

so

what is the 2 times 2 lol

[thorny totem]

Ermmmm 4?

[orchid lotus]

yea

so what is 4 times 10

[thorny totem]

40

[orchid lotus]

yeah

so

just do

4 root 10 over 40 and thats your answer

[thorny totem]

Should I simplify it more

[orchid lotus]

you could if u want

depends on how your teacher wants it

[thorny totem]

Oki tysm sry I lowkey forgot about rationalizing

[orchid lotus]

no problem

[thorny totem]

.close

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[neon fiber]

im genuinely confused

so i have $\mu=45$, $\sigma=1.677$, and i need to find the probability that a randomly selected value is less than 42. right

and i got z-score of like -1.79 which is correct btw
so now to get the probability we just find P(Z<-1.79)

so I did normPDF(42, 45, 1.677) which gave me like 0.048
and this was wrong. first of all why was this wrong

then I did normPDF(-1.79, 0, 1) which gave me 0.08 which was also wrong
why is this wrong too bye

so then I went the long way and used normCDF
$\frac{1-\text{normCDF}(-1.79,1.79,0,1)}{2}$
which is basically getting the outer probability for z < -1.79 and z > 1.79 then dividing by 2 to get just z < -1.79

and I got 0.0368, which is the correct answer

I absolutely do not get why the first two methods didn't work can someone explain 😭 thank youu

[thorny flame]

cheryy

[neon fiber]

<@&286206848099549185>

[drifting patrol]

[topaz sinew]

@neon fiber Has your question been resolved?

[neon fiber]

<@&286206848099549185> pls😔

[spare cliff]

Oh

Normally

The form of the standard normal dist is P(Z<z) right

But since the one you're finding is P(Z<-z)

Using the symmetry property

It's really just 1 - P(Z<z)

So, since u're looking for P(Z<-1.79), it's just 1 - P(Z<1.79), which is 1 - 0.96327 or 0.0368

[topaz sinew]

@neon fiber Has your question been resolved?

[neon fiber]

but shouldn't just using P(Z<-z) also work 😭

[neon fiber]

when I did normPDF(1.79, 0, 1) it gave me $\approx{0.0804}$

[thorny flame]

cheryy

[neon fiber]

[neon fiber]

<@&286206848099549185>

[neon fiber]

[neon fiber]

[neon fiber]

<@&286206848099549185> someone pls help- ive been here for like 4 hours 💪

[topaz sinew]

@neon fiber Has your question been resolved?

[reef grove]

$x = 42$, $\mu = 45$ and $\sigma=1.677$

You need to find $P(X<42)$

$$\begin{align*}
&P(X<42) \
\iff &P(Z<\frac{x-\mu}{\sigma})\
\iff &P(Z<\frac{42-45}{1.677})\
\iff &P(Z<-1.789 \approx -1.79)\
\iff &0.0367 &\text{(use a table)}
\end{align*}
$$

[thorny flame]

Snapis
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

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[finite mortar]

For this

[finite mortar]

Why has he calculated the determinant like this

[odd pagoda]

why not

[finite mortar]

Lol I thought there’s only one formula

[radiant marlin]

it's wrong

[finite mortar]

Is it actually wrong

😭I just did it and got that but like

Idk man my professor wrote this💀

[odd pagoda]

well he multiplied out wrong the second line

[finite mortar]

LOL oh yeah

[odd pagoda]

there are lots of formulas

[radiant marlin]

you can do the 2nd row like this and add a minus sign

[finite mortar]

Yeah I used trad method and got same thing so I guess he did it for funsies

[odd pagoda]

this is just expanding along the third column

[finite mortar]

Oh

[radiant marlin]

oh he did a column omg

[finite mortar]

😭

Yeah

[radiant marlin]

just going wild

[finite mortar]

Hahahahaa

It’s calm idk why he contradicted his own textbook lol

Anyway thanks

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[neon iron]

i don't understand how to do the last question

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[foggy bloom]

is this correct?

[topaz sinew]

@foggy bloom Has your question been resolved?

[foggy bloom]

<@&286206848099549185>

!close

.close

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[gusty meadow]

How tf do I do the bottom problems involving chain rule

Let's start with e^2x

[merry phoenix]

Assuming you don't want to go down the route of integration by substitution, reverse engineer the chain rule when differentiating

What do you get when you differentiate e^2x?

[gusty meadow]

OH

SUBSTITUTION

TY I'M SO DUMB

💀

[gusty meadow]

E^2x

LMFAO I'M BRAINDEAD SORRY

[merry phoenix]

2e^2x XD

Don't forget to differentiate the power lol

[gusty meadow]

Oh

Yeah I'm failing this test tmr

💀

Let's call it ggs

[merry phoenix]

Lmao dw integration tends to make more sense ironically once you've studied all of it as you can spot patterns and approach it in different ways

But anyway just finishing off the e^2x problem

We know it differentiates to 2e^2x

So if you're integrating e^2x

[gusty meadow]

Ty tho

[merry phoenix]

You basically want to integrate 2e^2x as that integrates to e^2x

[gusty meadow]

Ye

[merry phoenix]

So we basically just change it to$\frac{1}{2} \int 2e^{2x}$

[thorny flame]

TayBee

[merry phoenix]

As that way we know that 2e^2x integrates to e^2x (+c)

so we get 1/2 * e^2x + c

But yeah anyway

[gusty meadow]

Lmao I'm too dumb for this

[merry phoenix]

Once you've done 1000 more of those they're quite chill

[gusty meadow]

I'll just go w/ substitution

[gusty meadow]

Kk

I got a test tmr

[merry phoenix]

Yeah if youve learned how to integrate by substitution it always works if a little longer

[gusty meadow]

But I'll get more practice later

[gusty meadow]

Alr

[merry phoenix]

Gl haha

[gusty meadow]

Ty

Random question

Btw

What math are you in rn?

In collehe

And what grade are u in

[merry phoenix]

A bit further along, finished my engineering degree recently XD

So I'm a heretic compared to the pure mathematicians here but calculus is my vibe lol

[gusty meadow]

I'm majoring in engineering too!

[merry phoenix]

An excellent choice lol

[gusty meadow]

Hopefully marine engineering

But that's pretty hard to even get into, let alone pass

[merry phoenix]

Ooh fun, I was mechanical/medical

[gusty meadow]

So I'm thinking civil engineering

[gusty meadow]

Niceee

[merry phoenix]

Civil is fun too, everything = 0 in civil

[gusty meadow]

Civil is easy I heard after the first 2 years

[gusty meadow]

I doubt that

Dont civil engineers work with everything like in society

[merry phoenix]

Well unless you like what happened in Baltimore, it's generally preferable for civil structures to be static at all times

[gusty meadow]

Yeah true

What abt water

[merry phoenix]

So f = d/dt (mv), we like a being 0 lmao

[gusty meadow]

Hydrodynamics

[merry phoenix]

Oh yeah if you go into water then my condolences

That is horrendous

[gusty meadow]

I'm just speculating

[merry phoenix]

That being said I love fluid mechanics

But the maths is grim

[gusty meadow]

U probs have to do that in college

Niceee

Did u ever do ap physics or ap calc in high school

They didn't add fluids to the curriculum until

[merry phoenix]

I'm in the UK but I did higher level maths physics compsci IB

[gusty meadow]

Well next year

So I lucked out

Right b4 they added it

[merry phoenix]

Dodging a bullet

[gusty meadow]

Nice nice

Ty for ur help man

Wait

Do u have a job

How's finding work

[merry phoenix]

Did an engineering degree but didn't become an engineer, I'm a pilot, start flying people around for BA next year lol

[gusty meadow]

I'm like only majoring in engineering cause I'm good at math and I like building things

And I can get most jobs with an engineering

[gusty meadow]

W

NICEEEEE

[merry phoenix]

Yeah top tier degree for jobs tbf

[gusty meadow]

Do u wish u majored in like

Aeronautical engineering or smth

Aviation science

[merry phoenix]

Nah I intentionally didn't do aero engineering tbf because I decided if the aviation market collapses and I lose my job as a pilot I want a completely different field that will recruit me XD

[spiral slate]

avoid aeronautical eng like the plague

[merry phoenix]

Also that ^

My housemates did aero and oh boy some of it put my fluid mechanics to shame

[gusty meadow]

Nice

[merry phoenix]

That being said if you hate electronics they did far less of that than me

[gusty meadow]

LOL

[gusty meadow]

I never did electronics in my life

For the first time today I soldered

And I have two arduino grove kit things sitting at home I got from hackahtons but never used

[merry phoenix]

Shakes from the memories of my arduino project in first year intro to electronics

[gusty meadow]

I kinda wanna try it

I could make an alarm trap

If my brother decides to sneak into my room

[merry phoenix]

Yeah very satisfying when you get it right

[gusty meadow]

It'll log

And I'll catch him lmao

[merry phoenix]

Not as satisfying as a nice picture out of a finite element analysis tool but pretty satisfying nonetheless

[merry phoenix]

Wise plan

[gusty meadow]

XD

Is it easy to do that?

[merry phoenix]

Easy enough XD Arduino isn't too bad provided you work methodically

[gusty meadow]

Nice!

My friend made a pressure tester or smth

It was kinda cool

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@gusty meadow Has your question been resolved?

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[warped hollow]

I am currently trying to do question 4 of my practice set but I cannot seem to get it right. My best idea of what the correct solution would be is the one I have in the box above the question right now

[warped hollow]

I am trying to find the FOL representation for the statement Except for Isla, all Jilly-Joell's master swers have a ptarmigen

I wasn't sure if the except means specifically that Isla doesn't get one, or if that shes simply not in the guaranteed to get one group

also if I needed to specify that isla works for Joe and is a master sewer

I tried all these variations I'm thinking of though and they were all wrong

<@&286206848099549185>

[topaz sinew]

@warped hollow Has your question been resolved?

[topaz sinew]

@warped hollow Has your question been resolved?

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[old plover]

How come tossing a coin’s considered a mutually exclusive event if there’s a .5 chance of heads and .5 chance of tails?

Don’t the probability of both have to equal 0?

[loud oasis]

is it possible to have a coin land on heads and tails simultaneously?

[old plover]

Ik it’s not

But I mean mathemtically speaking, how do u prove that?

[alpine mist]

P(H or T) = P(H) + P(T) - P(H and T)
1 = .5 + .5 - P(H and T)

So P(H and T) = 0, thus mutually exclusive.

[keen venture]

Mind you, probability is full of these kinds of assumptions. We don't typically prove something that we can otherwise assume is mutually exclusive

[topaz sinew]

@old plover Has your question been resolved?

[vernal ledge]

maybe, but maths just assumes no weird stuff like perfectly balancing between heads and tails happens

so idk, in real life it might be something like
P(H) = 0.48, P(T) = 0/47, P(perfectly balanced) = 0.0001, P(losing the coin) = 0.0032, something like that

theres like so many factors for the coin to land on heads or tails in real life

and they keep on changing

so mathematically, no

but in reality, maybe

oh wait

you mean like heads AND tails?

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[dusk field]

i need help with this

[woeful stone]

let u=tan(x)

[dusk field]

i have u^2 + 2u - 1 = 0

but idk if im just being stupid from there

but it does not seem factorable

[woeful stone]

So what did you get as the discriminant

[distant nymph]

There is an identity hidden which makes it all very simple.

Try and see if you can spot some double angle identity.

[dusk field]

2sqrt2 right

[keen venture]

Even if it isn't factorable, you can always use the quadratic formula

[woeful stone]

yep. no need to simplify. sqrt(8) is good

[dusk field]

im not quite sure, can 2tan(x) be rewritten into tan(2x)? i know 1 - tan^2(x) is sec^2(x) but thats not a double angle

[dusk field]

👍

[distant nymph]

Try carrying the whole RHS to LHS.

[dusk field]

oh wow i did not see that

so that would become 2tan(x)/1-tan^2(x) which then becomes tan(2x)=1

that makes everything way easier

actually wait that would lead me just back to where i started right

[keen venture]

Damn good catch. That is slick

[dusk field]

cause if i just solve for 1 i would just end up at tan^2(x) + 2tan(x) = 1

now using the quadratic formula i would get u = -1 +- sqrt2

but im not sure where to proceed from there because its looking for actual radian answers from [0, 2pi)

like exact answers

[smoky sparrow]

Yeah that's the problem

[dusk field]

you know what i found the answers graphing it

its pi/8, 5pi/8, 9pi/8, 13pi/8

im just confused on how i could get there without graphing

[keen venture]

If tan(2x) = 1
Then 2x = π/4, 5π/4, 9π/4...

[dusk field]

yeah i just realized that

because if the answers are over 8 then it would have to be divided by 2

thanks guys i appreciate it

.close

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[stray wagon]

I don’t really understand how to get to the answer, however I was able to make the following deductions:

• The first and last number in the table must be 1, 8 respectively

• We need to use catalan numbers (though im not sure how and why, my tutor told me its used here)

• Whenever you are on the first row, everytime you go right or down, then the number is greater, and vise versa for the second row

• Using permutations since it is ordered. Also there are no repetitions

[radiant marlin]

oh yea this question is really complicated

[vernal ledge]

hmm ok

so lets say this 2 by 4 grid is a maze

and you start from 1 at the top left

and try to reach 8 at the bottom right

by moving either down or right

but now you will realise that each path you can take is a series of ascending order of numbers

like take the example filled grid

and consider all the paths

12458, 13678, 12678, 12478

all are in ascending order

we can also see here that 2 must be at a square adjacent to 1

and 7 must be at a square adjacent to 8

and yeah thats where im at for now

ill let you know if i make any progress