#help-26

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elder terrace
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When i try to equate equations i end up stuck

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with many variab;es

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<@&286206848099549185>

willow chasm
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which part?

elder terrace
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a

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runic vale
#

sup

topaz sinewBOT
runic vale
#

why is the domain x not equal to 0 and x not equal to 3

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shouldnt it be x not equal to 0 and x not equal to 1?

jade thunder
#

It’s of f(g)

willow chasm
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substitute g(x) in f(x)

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you will find your answer

topaz sinewBOT
#

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slender sonnet
#

a trapezoids bases are 4 and 12 i got a line that is parallel to the bases and it crosses the touching parts of the diagnals find the lenght of that line

topaz sinewBOT
#

@slender sonnet Has your question been resolved?

slender sonnet
#

<@&286206848099549185>

slender sonnet
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fiery zenith
#

Hi. I teacher gave me this task and asked us to research or ask family members to help ,but I can't find it on google and none of my family members are available . Can you please help me😁

boreal mulch
topaz sinewBOT
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@fiery zenith Has your question been resolved?

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obsidian peak
#

Unsure on what this means/how they got there

obsidian peak
#

I'm not quite sure how they get the common part.

topaz sinewBOT
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@obsidian peak Has your question been resolved?

obsidian peak
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<@&286206848099549185>

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@obsidian peak Has your question been resolved?

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@obsidian peak Has your question been resolved?

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@obsidian peak Has your question been resolved?

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gritty moon
topaz sinewBOT
gritty moon
#

Does this look right

topaz sinewBOT
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@gritty moon Has your question been resolved?

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heavy forge
#

Can someone help me

topaz sinewBOT
#

Please don't occupy multiple help channels.

heavy forge
#

Here

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trigonometry

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solve the rectangular triangles whose measurements are known

topaz sinewBOT
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@heavy forge Has your question been resolved?

topaz sinewBOT
#

@heavy forge Has your question been resolved?

agile lantern
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What do you mean by solve the triangles?

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what's the context

topaz sinewBOT
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@heavy forge Has your question been resolved?

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gritty matrix
topaz sinewBOT
gritty matrix
#

how do i do this

acoustic pecan
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do what

golden frigate
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real

gritty matrix
acoustic pecan
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generally by an inverse function

gritty matrix
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how would i do that?

acoustic pecan
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a calculator preferably

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have you ever seen sin^-1 (arcsin), cos^-1 (arccos) or tan^-1 (arctan)

neat cape
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hello where can i get help

acoustic pecan
acoustic pecan
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if sin(x)=y for example then arcsin(y)=x

gritty matrix
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so i just insert that with 0.8173?

bright heron
gritty matrix
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thanks @acoustic pecan

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marsh harness
topaz sinewBOT
#

@marsh harness Has your question been resolved?

topaz sinewBOT
#

@marsh harness Has your question been resolved?

marsh harness
#

<@&286206848099549185>

polar torrent
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We want to start this by figuring out the shift up (C) and the amplitude (A). Also, this will have to be a cosine since we are forced to use either sin(kx) or cos(kx) and cosine is the only one that will give a max on the y-axis

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To find A, we take the distance to the highest y-value which is 7, and the distance to the smallest y-value which is |-5|=5. The average of these distances should be our amplitude (A)

marsh harness
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So the amplitude would be 2 then?

polar torrent
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I get A=6

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(7+5)/2

marsh harness
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I’m confused

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Is that the whole equation?

polar torrent
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to find A only

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A = (7+5)/2

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A=6

marsh harness
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Ok I get u

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What’s next

polar torrent
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Once you know that, then you can solve for C, which should be the middle value of the y's

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so start at -5 and count up 6 units to find C

marsh harness
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So it’d be 1

polar torrent
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Yes

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A=6, C=1, so that last thing we need to figure out is the value of k

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what is the period of cosine? do you know?

marsh harness
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2pi?

polar torrent
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Correct

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the general formula for cos(kx) is (distance between the peaks) = 2 pi / k

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so count how many steps from one peak to the next peak

marsh harness
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6

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Across the x axis

polar torrent
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Good!

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so lets set 6 = 2 pi / k and solve for k

marsh harness
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That would just be multiplying 2pi with six right?

polar torrent
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its actually division

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k = 2pi/6 = pi/3

marsh harness
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Ok I see now

polar torrent
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alr so putting it altogether: $6 \cos(\frac{\pi}{3}x) + 1$ I think

thorny flameBOT
marsh harness
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So wouod it be sin6(pi/3) plus 1

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It said it was wrong

polar torrent
marsh harness
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Wait nvm it’s correct I put sun instead of cos

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My mistake

polar torrent
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haha all good! glad you figured it out

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dont forget to close the channel when you ar ehappy

marsh harness
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Thank u for the help sir

polar torrent
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you bet!

marsh harness
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Idk how to close the channel

polar torrent
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.close i think

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but you have to do it 🙂

marsh harness
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.close

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regal sluice
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so q = 8 + 5sqrt(3), 8 - 5sqrt(3) ? (checking my answer)

topaz sinewBOT
#

@regal sluice Has your question been resolved?

sterile finch
regal sluice
#

.close

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coarse tusk
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How can I calculate $$\int_0^1 y^{x-1} (1-y)^n dy$$

thorny flameBOT
#

kheerii

coarse tusk
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(Here n is an integer and x is any real number such that none of x,x+1,x+2…,x+n are zero)

cursive patrol
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looks suspiciously similar to the beta function

coarse tusk
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It does

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I should get $$\frac{n!}{x(x+1)(x+2)…(x+n)}$$

thorny flameBOT
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kheerii

coarse tusk
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So it would become B(x,n+1)?

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I don’t really want to use the beta function though

cursive patrol
coarse tusk
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Is there a way to do it without beta and gamma functions?

cursive patrol
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choose function 🤔 i assume not

coarse tusk
sweet shard
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It's by definition Beta

dense rain
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I don't know what you are expecting if you don't use properties of the beta or gamma function. Anything you do is going to be just reproving properties of beta from scratch, and any alternative method is just going to a tongue in cheek, unhelpful alternative that is doing exactly that but more obtuse.

coarse tusk
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I guess I should give more context

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The original question is about binomial

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The 7th question

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What I did was I defined a function $$S(y)=\sum_{r=0}^n \frac{(-1)^n}{x+r} ^nC_r y^{x+r}$$

thorny flameBOT
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kheerii

coarse tusk
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Then I differentiated and integrated to get S(1), which gave me my integral

coarse tusk
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I guess im missing some other easier way to solve this then

pseudo jetty
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!xy bro

topaz sinewBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

pseudo jetty
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partial fractions that shit

cursive patrol
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lmao

coarse tusk
coarse tusk
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Is it really that simple

pseudo jetty
coarse tusk
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damn

pseudo jetty
coarse tusk
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I mean, the integral is also interesting in its own way

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I got it solved by parts

pseudo jetty
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yeah you do the beta recurrence thing

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without explicitly doing beta

coarse tusk
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Ye

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How would I do pfd tho

sour geyser
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Hey

pseudo jetty
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as you would

sour geyser
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yes im here to help

pseudo jetty
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blud

dense rain
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The "no knowledge or cleverness" approach I would probably use is multiply both sides of the equation by x(x+1)(x+2)..(x+n), then try to prove that identity by induction.

coarse tusk
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I don’t like induction though

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But thanks!

pseudo jetty
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not to worry, induction doesn't like you either

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you can just evaluate x=0,...,-n

dense rain
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Are you even listening to yourself and recognize how frustrating you are, by being given an explicit method you were told to do, then instead you come up with the beta function, but you don't want to use the beta function, and somehow defend all of this by saying the integral was interesting, which of course it is, it's a special named function, which you didn't want to use after all?

coarse tusk
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Just thought I had an interesting idea so I wanted to explore it, and I know induction can be used to prove this

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It is a good solution and what we were told to do just wanted to know if there was some other way

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Pfd answered my question

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.close

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topaz sinewBOT
topaz sinewBOT
#

@neon iron Has your question been resolved?

topaz sinewBOT
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@neon iron Has your question been resolved?

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lucid mulch
#

Can someone help me with this task, I can't even draw a sketch? The two altitudes of a rhombus, constructed from obtuse angles, divide each other into segments with a length ratio of 1:2. Calculate the angles of the rhombus.

lucid mulch
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No

outer portal
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the two altitudes of a rhombus Im guessing look like this

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you think you want to try this out now or have me continue

lucid mulch
#

Can you continue

outer portal
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theres a couple of properties you can use about these altitudes that you can justify by symmetry

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for one, both altitudes are equal in length

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another is that AC is a line of symmetry through the shape

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also the two thin "red" triangles are congruent

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imagine the intersection point is G, I mean that ∆DFG is congruent to ∆BEG

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now they happen to tell you that the length ratio is 1 : 2

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that would mean FG : GB = 1 : 2 and EG : GD = 1 : 2

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try labelling side EG and FG to be 1 for convenience

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from this, you can find the other lengths along the red lines

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and then recognize that the lengths you have are familiar

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you think you can continue from here?

lucid mulch
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I ll try

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I don t know

outer portal
lucid mulch
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Nothing

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No progress

outer portal
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whats the length of GE

outer portal
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G is where the two dashed lines intersect

lucid mulch
#

I got it, thank you so much

outer portal
#

???

topaz sinewBOT
#

@lucid mulch Has your question been resolved?

lucid mulch
# outer portal ???

I solved the task, thank you for your help and sorry for taking up so much time

topaz sinewBOT
#
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outer portal
#

np

topaz sinewBOT
#
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wind loom
#

M and m are the maximum and minimum value of a+b+c, with a,b,c natural numbers that satisfy :
ab+bc+2ca = abc + c + a + 2
Find 10M+m

wind loom
#

How to find the maximum?

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i found that m = 2+1+1=4

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Help <@&286206848099549185>

topaz sinewBOT
#

@wind loom Has your question been resolved?

wind loom
#

<@&286206848099549185>

neon iron
#

You can get (a-1)(b-2)(c-1)=(a-1)+(b-2)+(c-1) so you have three integers whose product equals their sum

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I think you can show that the largest possibility for those integers is 1, 2, 3 which gives a=2, b=5, c=3

wind loom
neon iron
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Yeah

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Could only be lower when a=b=c=1 because they are natural numbers but that doesnt satisfy the equation

wind loom
#

Suppose n be in the set {1,2,…,100}
so (n^2 + 10)^2 is not quartic of an integer. Find all n

neon iron
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I think that (n^2+10)^2 is never a quartic

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Because if it is a quartic then n^2+10 has to be a square

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But modulo 4 thats not possible

wind loom
#

Which is 100

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.close

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sour geyser
#

.reopen

topaz sinewBOT
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neon iron
#

Among four friends, A owes money to B, B owes money to C, C owes money to D, and D owes money to A. A,B and C; When each of them gives 60 money to D, no one owes anything to anyone.
B's debt to C is 5 times the debt D owes to A
How much money does C owe to D

neon iron
#

@restive inlet

topaz sinewBOT
#

@neon iron Has your question been resolved?

neon iron
#

@eternal wing

restive inlet
#

don't ping random users
and the scenario doesn't make much sense

neon iron
#

sorry about the ping

trim jasper
#

it feels like youre missing some info

neon iron
#

really?

restive inlet
#

i.e. has is something like A's debt to B wiped
when A doesn't give any money to B

neon iron
#

it's the whole question tho

trim jasper
#

like you can make an equation but it would have two variables, with one equation adding to 180

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when d gets 180, no one owes anything to anyone

restive inlet
#

unless they're doing stuff like paying off someone else's debt

neon iron
#

yeah

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yes yes

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when A gives money to D

trim jasper
neon iron
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D's debt is wiped

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is it like

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if i consider

trim jasper
neon iron
#

x is A owes to B
y is B owes to c
z is c owes to d
w is d owes to a

neon iron
#

is it like

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x+y+z+w=180?

neon iron
#

yeah

trim jasper
neon iron
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y=5w

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then how should i approach?

trim jasper
#

i dont know

neon iron
#

.......

trim jasper
#

i have to study

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sorry

#

<@&286206848099549185>

tawdry dagger
#

try setting up some equations for the debts

long stirrup
#

C owes x to D
then B owes x−60 to C
then A owes x−120 to B
then D owes x−180 to A

neon iron
#

huh?

long stirrup
#

that's what they're saying

long stirrup
#

A,B,C owe 60 more than they are owed, while D owes 180 less

#

they just expect you to get it idk

neon iron
long stirrup
#

it probably also works

neon iron
#

according to question

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x+y+z+w=180?

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all the debts will be neutralized

long stirrup
#

i don;t think it's 180

neon iron
#

60+60+60

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they pay it to D

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and no one owes anything to anyone

long stirrup
#

i know it's 480 becaus i already found x

neon iron
#

okie hold up

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b owes to c is 5 times D owes to A

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what about this condition?

neon iron
#

.close

topaz sinewBOT
#
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terse ingot
#

Can someone help me? I dont understand what the derivate of 3^x is

terse ingot
topaz sinewBOT
terse ingot
#

It says 3^x * ln(3)

#

But why? Is there any guide for al these things?

ivory sorrel
#

try deriving it from first principals

terse ingot
ivory sorrel
#

recall that the limit of a^x-1/x at x =0 is ln(a)

terse ingot
#

Yes i dont know..

terse ingot
ivory sorrel
#

use the limit definition of the derivative

terse ingot
#

Okay will search an explanation on that

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still dont get it

#

maybe cause there isnt an explanation in my native language

ivory sorrel
#

what's you native language maybe someone here can help in that language

terse ingot
#

dutch

ivory sorrel
#

ping helpers, maybe someone can help

terse ingot
#

<@&286206848099549185>

tawdry dagger
#

hi

terse ingot
#

hi

restive inlet
#

consider: $$3 = e^{\ln(3)}$$

thorny flameBOT
#

ℝαμΩℕωⅤ

terse ingot
#

hm yes

restive inlet
#

and you can use that to differentiate 3^x using expontial chain rule
(and more generally, a^x)

terse ingot
#

they didnt use the chain rule in the first half wait

void crow
#

thats a rule

terse ingot
#

But i dont unsterstand why 3^x becomes ln(3)

restive inlet
#

chain rule is everywhere

void crow
#

yes

terse ingot
#

Yes but what do i do with the x?

void crow
#

ln(3)^(3^x)

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not ln(3) only

terse ingot
void crow
#

its a differentiation rule

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pretty much

restive inlet
#

did you consider what i mentioned above

terse ingot
restive inlet
#

consider: $$3 = e^{\ln(3)}$$
this leads to $$3^x = e^{\ln(3)x}$$

terse ingot
#

Like 2x is 2

thorny flameBOT
#

ℝαμΩℕωⅤ

void crow
#

alr

#

s

terse ingot
#

So i dont know what kind of rules there are

restive inlet
#

chain rule is one of the first things they should teach you,
its also present in that ss you posted

restive inlet
#

the one with a worked solution

void crow
#

thats chain rule?

#

they've made it

#

severely overcomplicated

restive inlet
#

not really

void crow
#

kinda yea

restive inlet
#

how so?

#

there are multiple things going on there, chain rule is just one of them

void crow
#

yeah

#

but chain rule is still pretty simple

#

it looks tough in that ss tho

#

imo

#

why tf would they use 0.5 instead of 1/2

terse ingot
#

I just need to remember this?

restive inlet
#

do NOT be lazy with ditching the d/dx operator

void crow
terse ingot
#

.rotate

terse ingot
void crow
#

,rotate

thorny flameBOT
restive inlet
#

you wouldn't say
2 = 0
would you?

terse ingot
#

i would haha

void crow
#

if you have to differentiate $a^x$, you simply just say \frac{d}{dx} a^x = ln(a)(a^x)

restive inlet
#

have you applied chain rule or been taught about it in any way before?

void crow
#

hate the bot

#

sm

restive inlet
#

yes

terse ingot
#

Yes chain rule i know that

restive inlet
#

consider: $$3 = e^{\ln(3)}$$
this leads to $$3^x = e^{\ln(3)x}$$

terse ingot
#

,rotate

thorny flameBOT
#

ℝαμΩℕωⅤ

terse ingot
#

Look at the yellow box

restive inlet
#

try applying the chain rule to differentiate
$$e^{\blue{\ln(3)x}}$$

thorny flameBOT
#

ℝαμΩℕωⅤ

restive inlet
#

consider doing a sub like
$$u = \ln(3)x$$
if you feel the need
$$\dv{y}{x} = \dv{y}{u} \dv{u}{x}$$

thorny flameBOT
#

ℝαμΩℕωⅤ

terse ingot
#

And rhis one?

restive inlet
#

that's converting between radical and exponential form

#

(no differentiation is happening in that step)

terse ingot
#

Yes but later on

restive inlet
#

power-chain rule

terse ingot
#

later on

#

Wait

#

Somehow 0,5 change to -0,5 and there is another 0,5

restive inlet
#

that was from the power rule

terse ingot
#

But they are using it 2 times like there

restive inlet
#

where

#

are you referring to this part?

terse ingot
#

Yes

restive inlet
#

yeh, that's from applying power rule

#

do you know what power rule states?

terse ingot
#

Power rule?

restive inlet
#

yes

terse ingot
#

Ohh isee

restive inlet
#

its the deriviative rule for differentiating power functions

terse ingot
#

-0,5 * 1

#

Are they doing that?

restive inlet
#

no

#

multiplying by original power
then new power is decreased by 1

terse ingot
#

I know

#

But the -0,5 needs to be multiplied by something

restive inlet
#

why?

#

numbers can stand alone

terse ingot
#

Cause that is what you do with differentiate?

restive inlet
#

i don't know what you mean

terse ingot
#

Okay like this

#

,rotate

thorny flameBOT
void crow
#

what you did there

restive inlet
#

again don't be lazy with not writing d/dx

terse ingot
void crow
#

was multiplied the power to the number behind x, and subtracted 1

#

from the power

restive inlet
#

i WILL make an extreme effort to point it out everytime until you stop

terse ingot
#

2 * 2 = 4 minus 1x so 4x

void crow
#

so $\frac{d}{dx} an^x = axn^(x-1)$

restive inlet
#

yeh, the new power 1 is the result of 2-1

void crow
#

fuck no

#

ew

#

i hate bot

#

anyways

restive inlet
#

similarly for your question

void crow
restive inlet
#

-0.5 is the result of 0.5-1

terse ingot
#

Yes

restive inlet
#

no need to attach extra multiplication by 1 to that

#

-0.5 is fine as it is

void crow
#

yea

terse ingot
#

I know

#

But what happens with the 0.5

restive inlet
#

that gets simplified with all the other parts being multiplied

terse ingot
#

Yes..

void crow
restive inlet
#

which they did

terse ingot
#

So multiplied by 1

void crow
#

see they're using the chain rule

#

right

restive inlet
#

wdym

void crow
#

it basically states

restive inlet
#

multiplied by 1

terse ingot
#

Aha i see

#

Okay but waut

#

Wait*

void crow
#

mhm

restive inlet
#

do you mean that the 2 * 0.5 simplifies to 1?
or are you just unnecessarily stating multiplication by 1

void crow
terse ingot
void crow
#

mhm?

#

let's try something

terse ingot
#

i only know what to do dont really know what it is?

void crow
#

if u have something like

restive inlet
#

i've typed out one form above

void crow
#

$x^2(x-1)^2$

thorny flameBOT
void crow
#

THANK U

void crow
terse ingot
#

2x * 2 (x-1)

#

?

void crow
#

not quite there

#

jk

#

ur right

terse ingot
#

Oh aha

void crow
#

how did u get that?

restive inlet
#

its wrong

void crow
#

how?

terse ingot
#

Uhm i differentiate the x^2 into 2x and took the ()^2 and multiplied it with 1

restive inlet
#

well you're starting with something of degree 4,
the stated result is only degree 2

#

which makes it immediately visibly wrong

terse ingot
#

Oh wait

void crow
#

hmm

terse ingot
#

I dont diffeentaite the 2x

#

Cause it is x^2 * …

#

And not x^2 +

void crow
#

AH FRICK

#

MY BAD

restive inlet
#

that's not how chain rule works
other rules were violated too

void crow
#

my bad my bad

#

u don't use chain rule there

#

you use product rule

restive inlet
#

there is a way to use chain rule

terse ingot
#

Okay wait let me see

void crow
#

isn't it just better to use product rule?

void crow
restive inlet
#

probably, doesn't mean you can't use chain rule

void crow
#

why overcomplicate it

#

and teach him how to do it with chain rule

#

it will be pretty confusing

void crow
terse ingot
#

,rotate

thorny flameBOT
terse ingot
void crow
terse ingot
void crow
#

alright perfect

terse ingot
#

That is the product rule right

void crow
#

so it basically states that

terse ingot
void crow
#

if you have uv

restive inlet
#

chain rule would be required after product rule, like in the other examples
(it just won't be entirely clear whether if it was considered here)

void crow
#

you differentiate u

#

then v

#

get u' and v'

#

then use the formula: uv'+vu'

#

in my example

terse ingot
#

,rotate

thorny flameBOT
terse ingot
#

What is stated in the red

#

Right

void crow
#

$x^2 = u, (x-1)^2 = v$

thorny flameBOT
void crow
#

yeah im tryna make it easier for u

terse ingot
void crow
#

okay

#

hold on

#

ill do it on a piece of paper and show you

terse ingot
restive inlet
#

following the notation in your book
$$f(x) = x^2, g(x) = (x-1)^2$$

thorny flameBOT
#

ℝαμΩℕωⅤ

void crow
#

it is kind of a complicated question since

terse ingot
void crow
#

you use chain rule and product rule

#

both here

terse ingot
#

Yes

#

We do yes

void crow
#

ill show u how give me a second

restive inlet
terse ingot
#

Yes but the x^2

#

part

restive inlet
#

that's for the example given to you

terse ingot
#

Oh aha yes okay

#

this is an example of one the exercises

#

,rotate

thorny flameBOT
void crow
#

chain rule when differentiating v on the right hand side big box

terse ingot
#

yes i see

#

you are only doing it the other way around

terse ingot
void crow
#

yes

#

so now ur clear what is chain rule

#

and product rule

#

right?

void crow
#

similarly in this question, both product and chain rule would be used.

terse ingot
#

yes

void crow
#

$2 . (3x-1)^($\frac{1}{2}$)

terse ingot
void crow
terse ingot
terse ingot
terse ingot
#

first part i do understand so this one

void crow
#

hold on

terse ingot
#

but the fraction one i dont

void crow
#

when a power is in the denominator

#

when it comes to the numerator

#

it becomes negative

#

thats an exponent rule...

terse ingot
#

yes i know that

void crow
#

ill show it to u

#

hold on

#

,rotate

#

oH SHIT

#

HOLD ON

#

,rotate

thorny flameBOT
void crow
#

there we go now we're good

#

clear?

terse ingot
#

i try to understand wiat

void crow
#

okay

#

let me know what u don't understand

terse ingot
#

okay where does the 3 in the numerator comes from

void crow
#

oh the three?

terse ingot
#

yes

void crow
#

you differentiate $(3x-1)^-0.5$ by chain rule

terse ingot
#

oh wiat

thorny flameBOT
terse ingot
#

no i see

void crow
#

mhm

terse ingot
#

2x * 0,5 * 3

#

right

void crow
#

yes

#

and (3x-1)^-0.5

terse ingot
#

is because wait

void crow
#

mhm?

terse ingot
#

This rule?

void crow
#

yes

terse ingot
#

Aha

#

Okay

void crow
#

the fraction exponent rule

#

got it now?

terse ingot
#

Yes i got it

void crow
#

perfect

terse ingot
#

Thank u very much!

void crow
#

ur welcome

#

close the ticket

#

;-;

terse ingot
#

oh yes

#

haha

#

.close

topaz sinewBOT
#
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topaz sinewBOT
#
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compact sequoia
topaz sinewBOT
compact sequoia
#

I think im interpreting this question wrong

#

Cause I’m only going from 0-5 so I have 2(7-4)

#

6

#

Ignore the 9 I used 6 and tried it for shits n giggles

keen venture
#

The bars are the absolute value function

compact sequoia
#

It’s still 6

#

Oh wait

keen venture
#

Also, why multiply by 2?

compact sequoia
#

Uhhh

#

Form given by video didn’t realize earlier

#

Alright so it’s abs value

#

Of 7-4

#

Yeah that dosent make sense

keen venture
#

No it's the integral of the absolute value

#

We care about the effect of the absolute value function:
Every negative area will flip over the y-axis, and become a positive area

compact sequoia
#

So 11

#

The abs value of the areas below

#

Thanks!

#

.close

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#
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viscid slate
#

hello

topaz sinewBOT
viscid slate
#

i just dont understand anything

#

one of those triangles area is 18 i think

#

those rectanglualr faces are 54

#

i dont understand what to do

#

<@&286206848099549185>

slate bronze
# viscid slate

Equilateral triangle so all sides equal
So area of rectangle will be 9x6

The prism has 3 rectangular faces

3xarea of one rectangular face

viscid slate
#

54*3=162

slate bronze
#

What do u not understand?

slate bronze
viscid slate
#

oh

#

i get it

#

ty

#

.close

topaz sinewBOT
#
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viscid slate
#

i did 3/8

topaz sinewBOT
viscid slate
#

its wrong

#

<@&286206848099549185>

craggy haven
#

that it's not a flying mammal

viscid slate
#

yh 3?*

#

3/8

#

whale,lion,penguin

abstract wadi
#

Might wanna pay attention to the word mammal there.

viscid slate
#

7/8

#

@abstract wadi and @craggy haven ty

#

.close

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#
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topaz tulip
#

why does this laplace transform get e^-2(s+5)

topaz tulip
#

what did they combine?

topaz sinewBOT
#

@topaz tulip Has your question been resolved?

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neon iron
#

What does the upside triangle functions represent?

neon iron
#

Its it the same as delta?

#

or average rate

#

the gradient

#

oh no

#

it's an operator, often referred to as del or nabla (the symbol)

#

Oh yeah

#

Thank you! ( i have not learnt about gradients yet )

#

.close give_heart_FB

topaz sinewBOT
#
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willow cliff
#

Hello

topaz sinewBOT
willow cliff
#

Can someone tell me the name e(x) v(x) and that weird thing so I can look it up its statistics

tiny oracle
# neon iron oh no

It pretty much says that we want to find minimal or maximally by looking at points where gradf=scaled up gradg

#

Ex?

#

Thats is the expectation of some variable

tiny oracle
# willow cliff

E(x) usually is the mean of random variable and it is the expected value after many many iterations

#

Gaussian*

#

When we have a sum symbol along with x and f(x), that is basically the discrete definition of expectation. We take the sum of all x with its output and add them all up

#

We can also have an integral in the continuous case

willow cliff
#

Okay and the others

#

can you tell me how they got f(x)

tiny oracle
#

F(x) is given to you

#

They gave the probably mass functions

#

You have an x and a pmf, so you can find the expectation by summing them, x and y pmfs respectively

willow cliff
#

which one is the pmf

#

why does e(x) = x *f(x)

#

what does E(x) stand for

#

what does v(x) stand for

#

and what does meu represent

tiny oracle
#

E(x) is simply because we multiply each value by its probability

#

The probability is a function that takes the value and spits some number between 1 and 0

#

So the probability of each value scales the value itself and tells us how probable it is. Then we add all these terms up and find the expected value for the variable x.

topaz sinewBOT
#

@willow cliff Has your question been resolved?

topaz sinewBOT
#

@willow cliff Has your question been resolved?

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#
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west thorn
#

Hello. Got a weird question that I don't know if there's an answer, or how to correctly ask.
On the bottom Venn diagram. How can I write the shaded part of B? Is there some simple way to write it as I would complement of A, where I draw a line over the A.

west thorn
#

I would like a letter or something to represent only the shaded part. Ones only in B and are out of B∩A and B∩C

craggy haven
#

B \ (A u C)

#

\ is set subtraction

west thorn
#

ohh thanks. hadn't learned that yet!

#

i even made up some symbol just so i could write it haha

#

thanks!

#

.close

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dull quail
#

Hello, I am doing a proof in multivariable calculus using the epsilon-delta definition and I am stuck here

dull quail
#

I recall from earlier calculus that I could set the distance to be 1, but in this case there's x and y so not sure how to tackle that

sweet shard
#

polar coordinates might help

dull quail
#

Uhh can this be done without the use of polar coordinates? I do not recall this being brought up

sweet shard
dull quail
#

Oh, I see. I will check that out then

#

Thanks

#

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nimble olive
topaz sinewBOT
nimble olive
#

) Find ALL vectors orthogonal to the plane P : ~x (s; t) = s (0; 2; 3; 0) +
t(0; 3; 4; 0). What geometrical object does they represen

#

so this is a hyperplane?

#

do i do dot product of those twovectors?

worthy storm
nimble olive
#

do i just put this into a rref

#

]d

topaz sinewBOT
#

@nimble olive Has your question been resolved?

topaz sinewBOT
#

@nimble olive Has your question been resolved?

nimble olive
#

.close

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vernal rivet
topaz sinewBOT
vernal rivet
#

how do you find initial velocity without an angle?

keen venture
#

They're asking for the magnitude of the vector

vernal rivet
#

oh

pseudo sonnet
#

you can also find the angle using tan(vy/vx)

vernal rivet
#

.close

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elder terrace
#

How do I even do this

topaz sinewBOT
loud oasis
#

use the definition of the derivative

elder terrace
#

Yeah but I just end up with this

#

The one with the box around it

loud oasis
#

try to get it as close as possible to the form shown in the hint

elder terrace
#

Do I multiply the numerator by 3 now?

#

Idk what to do from here

loud oasis
#

you're done now

elder terrace
#

It says the answer is 8to the power of x loge8

loud oasis
#

you can use log rules to put the 3 in the exponent

elder terrace
#

Ok Ty

#

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fast saddle
#

can someone explain why Im wrong and how to fix

fast saddle
#

I flipped row 1 and 2
then divided row 1 by 4
then multiplied row 1 and added to row 2

#

to get the row reduced form

keen venture
#

Try the opposite order. That is, swap E1 and E3

fast saddle
#

Doesnt work

#

.close

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whole sleet
topaz sinewBOT
whole sleet
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I hate these types of problems

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I always get lost on when to flip and subtract etc

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So like

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Let me show this work

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Brb 2 mins

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Is there like a rule that i can follow that help me with all these types of problems cuz i feel like there is too many scenarios

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Specifically these rational ones

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Like i want to just flip everything but idk

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I will just flip everything thats not a negative and post an updated shown work

topaz sinewBOT
#

@whole sleet Has your question been resolved?

topaz sinewBOT
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severe lichen
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A central angle of a circle with radius 150 cm cuts off an arc of 200 cm.

severe lichen
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so i wanna find the area of a sector with that central angle

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my radian measure is 900/3pi and degree measure is 95.49

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i plugged everything in for A = (1/2)r^2(theta)

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150^2/2 * 900/3pi

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i got 10,602,875.21

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is this sum correct it just seems impossibly large lol maybe im overthinking

topaz sinewBOT
#

@severe lichen Has your question been resolved?

severe lichen
#

<@&286206848099549185>

topaz sinewBOT
#

@severe lichen Has your question been resolved?

topaz sinewBOT
#
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topaz sinewBOT
#
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Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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eternal spoke
#

can l'hopital's rule only be used if direct substitution leads to an indeterminate form?

sweet shard
eternal spoke
#

,tex \frac{-10x+20}{3x^2-6x-4}

thorny flameBOT
#

Oogy Boogy
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

eternal spoke
#

hm

eternal spoke
#

then i cant use l'hotital's?

sweet shard
#

No I didn't say that

eternal spoke
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i have this limit

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i was wondering if i can just use l'hopita's twice in a row

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(-10x + 20) / (3x^2 - 6x -4)

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-10 / (6x-6)

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and now when i plug in 4 i get the wrong answer

sweet shard
eternal spoke
sweet shard
eternal spoke
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what

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so what did you say

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you just said

sweet shard
eternal spoke
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no indeterminate form -> no l hopitals

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correct?

sweet shard
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That's correct

eternal spoke
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good

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thats what i asked

eternal spoke
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of course

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ok thanks

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.close

topaz sinewBOT
#
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topaz sinewBOT
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warm vector
#

hi, i need help with this . It says solve a system of linear equations

pearl peak
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write as a matrix and use gaussian elimination

warm vector
#

ok thanks

topaz sinewBOT
#

@warm vector Has your question been resolved?

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inner drum
rigid ivy
#

!original

topaz sinewBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

inner drum
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I want to find X

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and I need x to find x?

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but if I put value it finding me the x value

lusty frigate
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Whats the goal?

inner drum
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to find a function that x is only in one side I think

lusty frigate
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can you post what you did

inner drum
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I don't really know what am I doing

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I got 2 parameters and I want to create a function that find x by using those 2 parameters

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I want the K and S to be > 0

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is it possible to find x? I only use S and K as a positive number

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The definition area is x > 0

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I mean I am trying to find x 😦

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can I add conditions?

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I don't know 😭

sweet shard
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The fuck

inner drum
sweet shard
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Why are you making it harder to look for your question

inner drum
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I can't add conditions on cymath

inner drum
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the problem is that I creating a 2D game and I want to find a formula that will help me calculate X for S > 0.5 and K > 0 and found the value of X when y = S - 0.5

inner drum
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sorry for bad english

sweet shard
inner drum
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y = (S - 0.5)

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wait

inner drum
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imagine in desmos

sweet shard
inner drum
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I mean like y of collition between two functions

sweet shard
inner drum
inner drum
inner drum
sweet shard
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From here you can square both sides to get rid of the square root

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Then multiply by (k+X^2)

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The rest is algebra to solve for X

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Do those first two steps then show what you get

inner drum
sweet shard
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You can't just square only one term

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You have to square all the terms

inner drum
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you right

sweet shard
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a = b implies a^2 = b^2

inner drum
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you are the king I was so unfocused thank you

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sorry it suppose to be -Sk + 0.5k not - 0.5k right?

sweet shard
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,w solve for x in (s-1/2)=sx/sqrt(k+x^2)

sweet shard
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Numerator looks wrong

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Oh wait no

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Oh there are two solutions because of the square

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After you take the square root, you'll get 2 solutions

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x^2 = a implies x=sqrt(a) or -sqrt(a)

sweet shard
inner drum
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(SX)^2 and not SX^2

sweet shard
# thorny flame

It looks like you'll always get 2 solutions for x for your given range of K>0 and S>1/2

topaz sinewBOT
#

@inner drum Has your question been resolved?

#
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topaz sinewBOT
#
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wintry coyote
topaz sinewBOT
wintry coyote
#

do i just do 2-1 for the first one and plug that in for t and so on

placid veldt
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(X+Y)/2

wintry coyote
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so (1+2)/2 for the first one as an example

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and plug it in for t

placid veldt
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Yeah

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Wait

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No

half edge
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Y(t) = 16t - 1.86t^2

placid veldt
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Its height is given by the eq

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Differentiate

wintry coyote
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i gotta do it without differentiating

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i'm reviewing for limits

placid veldt
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Then what you said initially

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Distance / time

wintry coyote
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but what i did before was

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1.5-1 for example

placid veldt
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Plug in for difference in height and divide by time period

wintry coyote
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that's t

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0.5

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i plugged that in

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and divided that by 0.5

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it was wrong for some reason

placid veldt
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f(2) - f(1) / 2-1

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That's distance travelled vertically divide by the time it took to do so

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v = d/t

wintry coyote
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aight i'll try that

placid veldt
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Lmk

wintry coyote
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cus what i did was subtract and then plug that into one f(x)

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instead of plugging in the two values into two f(x)s

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and subtracting then dividing

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yeah i'm getting different results now hopefully theyre' right

placid veldt
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Yeah no cuz the equation is quadratic and hence different differences at different intervals of the same period

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So average velocity at 0-1 may be different from that at 4-5

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Even though they're both 1 second

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If you do the subtraction beforehand you fail to consider that

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@wintry coyote was that right?

wintry coyote
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I'm checking