#help-26
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which part?
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sup
why is the domain x not equal to 0 and x not equal to 3
shouldnt it be x not equal to 0 and x not equal to 1?
It’s of f(g)
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a trapezoids bases are 4 and 12 i got a line that is parallel to the bases and it crosses the touching parts of the diagnals find the lenght of that line
@slender sonnet Has your question been resolved?
<@&286206848099549185>
.close
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Hi. I teacher gave me this task and asked us to research or ask family members to help ,but I can't find it on google and none of my family members are available . Can you please help me😁
can you provide a better picture of the angles? thanks
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Unsure on what this means/how they got there
@obsidian peak Has your question been resolved?
<@&286206848099549185>
@obsidian peak Has your question been resolved?
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@obsidian peak Has your question been resolved?
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Does this look right
@gritty moon Has your question been resolved?
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Can someone help me
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@heavy forge Has your question been resolved?
@heavy forge Has your question been resolved?
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how do i do this
do what
real
how do i find the measure of the each angle
generally by an inverse function
how would i do that?
a calculator preferably
have you ever seen sin^-1 (arcsin), cos^-1 (arccos) or tan^-1 (arctan)
hello where can i get help
yess
i use that?
so i just insert that with 0.8173?
(sorry to interrupt, but note this is only true for x values within the range of arcsin)
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@marsh harness Has your question been resolved?
<@&286206848099549185>
We want to start this by figuring out the shift up (C) and the amplitude (A). Also, this will have to be a cosine since we are forced to use either sin(kx) or cos(kx) and cosine is the only one that will give a max on the y-axis
To find A, we take the distance to the highest y-value which is 7, and the distance to the smallest y-value which is |-5|=5. The average of these distances should be our amplitude (A)
So the amplitude would be 2 then?
Once you know that, then you can solve for C, which should be the middle value of the y's
so start at -5 and count up 6 units to find C
So it’d be 1
Yes
A=6, C=1, so that last thing we need to figure out is the value of k
what is the period of cosine? do you know?
2pi?
Correct
the general formula for cos(kx) is (distance between the peaks) = 2 pi / k
so count how many steps from one peak to the next peak
That would just be multiplying 2pi with six right?
Ok I see now
alr so putting it altogether: $6 \cos(\frac{\pi}{3}x) + 1$ I think
haha all good! glad you figured it out
dont forget to close the channel when you ar ehappy
Thank u for the help sir
you bet!
Idk how to close the channel
.close
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so q = 8 + 5sqrt(3), 8 - 5sqrt(3) ? (checking my answer)
@regal sluice Has your question been resolved?
Looks good.
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How can I calculate $$\int_0^1 y^{x-1} (1-y)^n dy$$
kheerii
(Here n is an integer and x is any real number such that none of x,x+1,x+2…,x+n are zero)
looks suspiciously similar to the beta function
kheerii
sounds legit
Is there a way to do it without beta and gamma functions?
choose function 🤔 i assume not
Choose function?
Why not
It's by definition Beta
I don't know what you are expecting if you don't use properties of the beta or gamma function. Anything you do is going to be just reproving properties of beta from scratch, and any alternative method is just going to a tongue in cheek, unhelpful alternative that is doing exactly that but more obtuse.
I guess I should give more context
The original question is about binomial
The 7th question
What I did was I defined a function $$S(y)=\sum_{r=0}^n \frac{(-1)^n}{x+r} ^nC_r y^{x+r}$$
kheerii
Then I differentiated and integrated to get S(1), which gave me my integral
We have not been taught beta function yet
I guess im missing some other easier way to solve this then
!xy bro
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
partial fractions that shit
lmao
I just did lmao
i'm saying you just pulled a massive xy on us
damn

Yeah that makes sense
I mean, the integral is also interesting in its own way
I got it solved by parts
Hey
as you would
yes im here to help
blud
The "no knowledge or cleverness" approach I would probably use is multiply both sides of the equation by x(x+1)(x+2)..(x+n), then try to prove that identity by induction.
Yes that is what we were told to do
I don’t like induction though
But thanks!
Are you even listening to yourself and recognize how frustrating you are, by being given an explicit method you were told to do, then instead you come up with the beta function, but you don't want to use the beta function, and somehow defend all of this by saying the integral was interesting, which of course it is, it's a special named function, which you didn't want to use after all?
I know sorry
Just thought I had an interesting idea so I wanted to explore it, and I know induction can be used to prove this
It is a good solution and what we were told to do just wanted to know if there was some other way
Pfd answered my question
.close
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@neon iron Has your question been resolved?
@neon iron Has your question been resolved?
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Can someone help me with this task, I can't even draw a sketch? The two altitudes of a rhombus, constructed from obtuse angles, divide each other into segments with a length ratio of 1:2. Calculate the angles of the rhombus.
did you figure this out
No
the two altitudes of a rhombus Im guessing look like this
you think you want to try this out now or have me continue
Can you continue
theres a couple of properties you can use about these altitudes that you can justify by symmetry
for one, both altitudes are equal in length
another is that AC is a line of symmetry through the shape
also the two thin "red" triangles are congruent
imagine the intersection point is G, I mean that ∆DFG is congruent to ∆BEG
now they happen to tell you that the length ratio is 1 : 2
that would mean FG : GB = 1 : 2 and EG : GD = 1 : 2
try labelling side EG and FG to be 1 for convenience
from this, you can find the other lengths along the red lines
and then recognize that the lengths you have are familiar
you think you can continue from here?
whats your progress so far
whats the length of GE
cmon
G is where the two dashed lines intersect
I got it, thank you so much
???
@lucid mulch Has your question been resolved?
I solved the task, thank you for your help and sorry for taking up so much time
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np
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M and m are the maximum and minimum value of a+b+c, with a,b,c natural numbers that satisfy :
ab+bc+2ca = abc + c + a + 2
Find 10M+m
@wind loom Has your question been resolved?
<@&286206848099549185>
You can get (a-1)(b-2)(c-1)=(a-1)+(b-2)+(c-1) so you have three integers whose product equals their sum
I think you can show that the largest possibility for those integers is 1, 2, 3 which gives a=2, b=5, c=3
Is this correct?
Yeah
Could only be lower when a=b=c=1 because they are natural numbers but that doesnt satisfy the equation
Suppose n be in the set {1,2,…,100}
so (n^2 + 10)^2 is not quartic of an integer. Find all n
I think that (n^2+10)^2 is never a quartic
Because if it is a quartic then n^2+10 has to be a square
But modulo 4 thats not possible
So 1<= n <= 100 is the answer?
Which is 100
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Among four friends, A owes money to B, B owes money to C, C owes money to D, and D owes money to A. A,B and C; When each of them gives 60 money to D, no one owes anything to anyone.
B's debt to C is 5 times the debt D owes to A
How much money does C owe to D
@restive inlet
@neon iron Has your question been resolved?
@eternal wing
don't ping random users
and the scenario doesn't make much sense
sorry about the ping
it feels like youre missing some info
really?
i.e. has is something like A's debt to B wiped
when A doesn't give any money to B
it's the whole question tho
like you can make an equation but it would have two variables, with one equation adding to 180
when d gets 180, no one owes anything to anyone
unless they're doing stuff like paying off someone else's debt
debt D owes to A = Y
B's debt to C is 5 times the debt D owes to A = 5 Y
information required is definitely in this sentence
x is A owes to B
y is B owes to c
z is c owes to d
w is d owes to a
yeah
is it like
x+y+z+w=180?
B owes to c is 5W
yeah
you will never be able to solve that
i dont know
.......
try setting up some equations for the debts
C owes x to D
then B owes x−60 to C
then A owes x−120 to B
then D owes x−180 to A
huh?
that's what they're saying
i don't get it
A,B,C owe 60 more than they are owed, while D owes 180 less
they just expect you to get it idk
this type of approach doesn't work?
it probably also works
i don;t think it's 180
i know it's 480 becaus i already found x
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Can someone help me? I dont understand what the derivate of 3^x is
try deriving it from first principals
recall that the limit of a^x-1/x at x =0 is ln(a)
Yes i dont know..
.
use the limit definition of the derivative
Okay will search an explanation on that
still dont get it
maybe cause there isnt an explanation in my native language
what's you native language maybe someone here can help in that language
dutch
ping helpers, maybe someone can help
<@&286206848099549185>
hi
hi
consider: $$3 = e^{\ln(3)}$$
ℝαμΩℕωⅤ
hm yes
and you can use that to differentiate 3^x using expontial chain rule
(and more generally, a^x)
they didnt use the chain rule in the first half wait
chain rule is everywhere
yes
Yes but what do i do with the x?
yes..
did you consider what i mentioned above
My book only explained the basics
consider: $$3 = e^{\ln(3)}$$
this leads to $$3^x = e^{\ln(3)x}$$
Like 2x is 2
ℝαμΩℕωⅤ
So i dont know what kind of rules there are
chain rule is one of the first things they should teach you,
its also present in that ss you posted
which q are u talking about
the one with a worked solution
not really
kinda yea
yeah
but chain rule is still pretty simple
it looks tough in that ss tho
imo
why tf would they use 0.5 instead of 1/2
I just need to remember this?
do NOT be lazy with ditching the d/dx operator
pretty much
.rotate
Aha okay
,rotate
you wouldn't say
2 = 0
would you?
i would haha
if you have to differentiate $a^x$, you simply just say \frac{d}{dx} a^x = ln(a)(a^x)
have you applied chain rule or been taught about it in any way before?
me?
yes
consider: $$3 = e^{\ln(3)}$$
this leads to $$3^x = e^{\ln(3)x}$$
,rotate
Look at the yellow box
try applying the chain rule to differentiate
$$e^{\blue{\ln(3)x}}$$
ℝαμΩℕωⅤ
consider doing a sub like
$$u = \ln(3)x$$
if you feel the need
$$\dv{y}{x} = \dv{y}{u} \dv{u}{x}$$
ℝαμΩℕωⅤ
that's converting between radical and exponential form
(no differentiation is happening in that step)
Yes but later on
power-chain rule
that was from the power rule
But they are using it 2 times like there
Yes
Power rule?
yes
Ohh isee
its the deriviative rule for differentiating power functions
Cause that is what you do with differentiate?
i don't know what you mean
what you did there
again don't be lazy with not writing d/dx
yes sorry
i WILL make an extreme effort to point it out everytime until you stop
2 * 2 = 4 minus 1x so 4x
so $\frac{d}{dx} an^x = axn^(x-1)$
yeh, the new power 1 is the result of 2-1
similarly for your question
yes
-0.5 is the result of 0.5-1
Yes
yea
that gets simplified with all the other parts being multiplied
Yes..
it came to the front
which they did
So multiplied by 1
wdym
it basically states
multiplied by 1
mhm
do you mean that the 2 * 0.5 simplifies to 1?
or are you just unnecessarily stating multiplication by 1
can u state the chain rule real quick
Uhm
i only know what to do dont really know what it is?
alright
if u have something like
i've typed out one form above
$x^2(x-1)^2$
sin
THANK U
how would you differentiate this?
Oh aha
how did u get that?
its wrong
how?
Uhm i differentiate the x^2 into 2x and took the ()^2 and multiplied it with 1
well you're starting with something of degree 4,
the stated result is only degree 2
which makes it immediately visibly wrong
Oh wait
hmm
that's not how chain rule works
other rules were violated too
there is a way to use chain rule
Okay wait let me see
isn't it just better to use product rule?
uv' + vu'
probably, doesn't mean you can't use chain rule
why overcomplicate it
and teach him how to do it with chain rule
it will be pretty confusing
do you know the product rule?
.
?
Yea
alright perfect
That is the product rule right
so it basically states that
.
if you have uv
chain rule would be required after product rule, like in the other examples
(it just won't be entirely clear whether if it was considered here)
you differentiate u
then v
get u' and v'
then use the formula: uv'+vu'
in my example
$x^2 = u, (x-1)^2 = v$
sin
yeah im tryna make it easier for u
i dont see anything in this 🙂
You mean this?
following the notation in your book
$$f(x) = x^2, g(x) = (x-1)^2$$
ℝαμΩℕωⅤ
it is kind of a complicated question since
dont think that is the notation
ill show u how give me a second
your book is literally using f(x) and g(x)
that's for the example given to you
.
lets come back to this
similarly in this question, both product and chain rule would be used.
yes
$2 . (3x-1)^($\frac{1}{2}$)
you don't understand that part?
i only dont know how
to get this now
yes
fikrst part is clear now
first part i do understand so this one
hold on
well
when a power is in the denominator
when it comes to the numerator
it becomes negative
thats an exponent rule...
yes i know that
i try to understand wiat
okay where does the 3 in the numerator comes from
oh the three?
yes
you differentiate $(3x-1)^-0.5$ by chain rule
oh wiat
sin
no i see
mhm
is because wait
mhm?
yes
Yes i got it
perfect
Thank u very much!
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I think im interpreting this question wrong
Cause I’m only going from 0-5 so I have 2(7-4)
6
Ignore the 9 I used 6 and tried it for shits n giggles
The bars are the absolute value function
Also, why multiply by 2?
Uhhh
Form given by video didn’t realize earlier
Alright so it’s abs value
Of 7-4
Yeah that dosent make sense
No it's the integral of the absolute value
We care about the effect of the absolute value function:
Every negative area will flip over the y-axis, and become a positive area
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hello
i just dont understand anything
one of those triangles area is 18 i think
those rectanglualr faces are 54
i dont understand what to do
<@&286206848099549185>
Equilateral triangle so all sides equal
So area of rectangle will be 9x6
The prism has 3 rectangular faces
3xarea of one rectangular face
54*3=162
What do u not understand?
Yea
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i did 3/8
that it's not a flying mammal
Might wanna pay attention to the word mammal there.
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why does this laplace transform get e^-2(s+5)
what did they combine?
@topaz tulip Has your question been resolved?
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What does the upside triangle functions represent?
Its it the same as delta?
or average rate
the gradient
oh no
it's an operator, often referred to as del or nabla (the symbol)
Oh yeah
Thank you! ( i have not learnt about gradients yet )
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Hello
Can someone tell me the name e(x) v(x) and that weird thing so I can look it up its statistics
It pretty much says that we want to find minimal or maximally by looking at points where gradf=scaled up gradg
Ex?
Thats is the expectation of some variable
E(x) usually is the mean of random variable and it is the expected value after many many iterations
Gaussian*
When we have a sum symbol along with x and f(x), that is basically the discrete definition of expectation. We take the sum of all x with its output and add them all up
We can also have an integral in the continuous case
F(x) is given to you
They gave the probably mass functions
You have an x and a pmf, so you can find the expectation by summing them, x and y pmfs respectively
which one is the pmf
why does e(x) = x *f(x)
what does E(x) stand for
what does v(x) stand for
and what does meu represent
E(x) is simply because we multiply each value by its probability
The probability is a function that takes the value and spits some number between 1 and 0
So the probability of each value scales the value itself and tells us how probable it is. Then we add all these terms up and find the expected value for the variable x.
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Hello. Got a weird question that I don't know if there's an answer, or how to correctly ask.
On the bottom Venn diagram. How can I write the shaded part of B? Is there some simple way to write it as I would complement of A, where I draw a line over the A.
I would like a letter or something to represent only the shaded part. Ones only in B and are out of B∩A and B∩C
ohh thanks. hadn't learned that yet!
i even made up some symbol just so i could write it haha
thanks!
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Hello, I am doing a proof in multivariable calculus using the epsilon-delta definition and I am stuck here
I recall from earlier calculus that I could set the distance to be 1, but in this case there's x and y so not sure how to tackle that
polar coordinates might help
Uhh can this be done without the use of polar coordinates? I do not recall this being brought up
Polar coordinates is something you learn before calculus
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) Find ALL vectors orthogonal to the plane P : ~x (s; t) = s (0; 2; 3; 0) +
t(0; 3; 4; 0). What geometrical object does they represen
so this is a hyperplane?
do i do dot product of those twovectors?
well it'll be a subspace, of what dimension?
i dont understand do you mean 4 dimensional?
do i just put this into a rref
]d
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how do you find initial velocity without an angle?
They're asking for the magnitude of the vector
oh
you can also find the angle using tan(vy/vx)
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How do I even do this
use the definition of the derivative
try to get it as close as possible to the form shown in the hint
you're done now
It says the answer is 8to the power of x loge8
you can use log rules to put the 3 in the exponent
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can someone explain why Im wrong and how to fix
I flipped row 1 and 2
then divided row 1 by 4
then multiplied row 1 and added to row 2
to get the row reduced form
Try the opposite order. That is, swap E1 and E3
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I hate these types of problems
I always get lost on when to flip and subtract etc
So like
Let me show this work
Brb 2 mins
Is there like a rule that i can follow that help me with all these types of problems cuz i feel like there is too many scenarios
Specifically these rational ones
Like i want to just flip everything but idk
I will just flip everything thats not a negative and post an updated shown work
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A central angle of a circle with radius 150 cm cuts off an arc of 200 cm.
so i wanna find the area of a sector with that central angle
my radian measure is 900/3pi and degree measure is 95.49
i plugged everything in for A = (1/2)r^2(theta)
150^2/2 * 900/3pi
i got 10,602,875.21
is this sum correct it just seems impossibly large lol maybe im overthinking
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can l'hopital's rule only be used if direct substitution leads to an indeterminate form?
It's the limit is in indeterminate form
,tex \frac{-10x+20}{3x^2-6x-4}
Oogy Boogy
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hm
so if i can use direct substitution and not get an indeterminate form
then i cant use l'hotital's?
No I didn't say that
i have this limit
i was wondering if i can just use l'hopita's twice in a row
(-10x + 20) / (3x^2 - 6x -4)
-10 / (6x-6)
and now when i plug in 4 i get the wrong answer
This isn't indeterminate form
.
There's a limit expression here
That's correct
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hi, i need help with this . It says solve a system of linear equations
write as a matrix and use gaussian elimination
ok thanks
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I want to find X but when I put the function in cymath it tells me that I need x to find x ? why
https://www.cymath.com/answer?q=(S-0.5)%3D(SX)%2F((sqrt(k%2BX^2)))%3AX
but if I put values in the function it found X
https://www.cymath.com/answer?q=(50-0.5)%3D(50X)%2F((sqrt(41%2BX^2)))
!original
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
I want to find X
and I need x to find x?
but if I put value it finding me the x value
Whats the goal?
can you post what you did
I don't really know what am I doing
I got 2 parameters and I want to create a function that find x by using those 2 parameters
I want the K and S to be > 0
is it possible to find x? I only use S and K as a positive number
The definition area is x > 0
I mean I am trying to find x 😦
can I add conditions?
I don't know 😭
The fuck
I need to find X
Why are you making it harder to look for your question
You need to do this
the problem is that I creating a 2D game and I want to find a formula that will help me calculate X for S > 0.5 and K > 0 and found the value of X when y = S - 0.5
There's no y here
There's no y here either
I mean like y of collition between two functions
There's only one function here
I meant like this
I am so so so sorry it's just my head thinking so much
From here you can square both sides to get rid of the square root
Then multiply by (k+X^2)
The rest is algebra to solve for X
Do those first two steps then show what you get
No
You can't just square only one term
You have to square all the terms
you right
a = b implies a^2 = b^2
you are the king I was so unfocused thank you
sorry it suppose to be -Sk + 0.5k not - 0.5k right?
,w solve for x in (s-1/2)=sx/sqrt(k+x^2)
Numerator looks wrong
Oh wait no
Oh there are two solutions because of the square
After you take the square root, you'll get 2 solutions
x^2 = a implies x=sqrt(a) or -sqrt(a)
Yea you have a sign error somewhere
(SX)^2 and not SX^2
It looks like you'll always get 2 solutions for x for your given range of K>0 and S>1/2
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do i just do 2-1 for the first one and plug that in for t and so on
(X+Y)/2
Y(t) = 16t - 1.86t^2
Plug in for difference in height and divide by time period
that's t
0.5
i plugged that in
and divided that by 0.5
it was wrong for some reason
f(2) - f(1) / 2-1
That's distance travelled vertically divide by the time it took to do so
v = d/t
aight i'll try that
Lmk
cus what i did was subtract and then plug that into one f(x)
instead of plugging in the two values into two f(x)s
and subtracting then dividing
yeah i'm getting different results now hopefully theyre' right
Yeah no cuz the equation is quadratic and hence different differences at different intervals of the same period
So average velocity at 0-1 may be different from that at 4-5
Even though they're both 1 second
If you do the subtraction beforehand you fail to consider that
@wintry coyote was that right?
I'm checking