#help-26

1 messages · Page 76 of 1

real blaze
#

-35 or 35?

cursive patrol
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-35, -7, -5, -1, 1, 5, 7, 35

real blaze
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-5,+7 or +7-5

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Yes

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X=5 satifies

mossy tree
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no

real blaze
#

Why not?

knotty ledge
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Odd degree polys will have atleast one real root if that's what you mean

real blaze
#

So it can be more than 3 ?

knotty ledge
#

Not for a cubic no

mossy tree
#

can cut more than once

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for example: f(x) = (x-1)(x-2)(x-3)

So f(x) is third degree

real blaze
#

I meant in our quation we have no x^2 term

mossy tree
#

But we can clearly observe that it cuts in three places

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No it can't

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If that were the case it would have to be something of degree 4 or higher

real blaze
mossy tree
#

so the question you asked:

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Does a cubic function that does not contain an x² term intersect the x-axis three times?

real blaze
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Yes yes

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I meant it is possible or not?

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I am interested to know about what kind of roots will be there

mossy tree
#

so

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I looked into it a bit

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can cut three times again

ax³+cx = x(ax²+c)

x = 0 or x = ±√(-c/a)

real blaze
#

I see, what you found?

mossy tree
#

There can be 3 roots if -c/a > 0

real blaze
#

Could you make any equation with it?

mossy tree
#

yes

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like what

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i can say x³-5x

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maybe

real blaze
#

So if we look at descart rule

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3 real roots ☺️👌

#

Let's work out with our main problem with Descartes it represents (3 real roots, 1 real 2 complex roots)

mossy tree
#

in which situation?

#

@real blaze

real blaze
#

This one

topaz sinewBOT
#

@real blaze Has your question been resolved?

real blaze
#

.close

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sonic pawn
topaz sinewBOT
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topaz sinewBOT
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@sonic pawn Has your question been resolved?

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toxic zealot
#

I need to show $a_n = 1+ 1/a_{n-1}$ converges to the golden ratio

thorny flameBOT
#

Junojuno

chilly walrus
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multiply both sides by a_{n-1}

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and recall that $\phi^2 = \phi + 1$

thorny flameBOT
#

artemetra

last parcel
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$an=1+1

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$an=1+1$

thorny flameBOT
#

brahim3579

last parcel
#

iam professionalsully

topaz sinewBOT
#

@toxic zealot Has your question been resolved?

toxic zealot
#

Formally

topaz sinewBOT
#

@toxic zealot Has your question been resolved?

mossy tree
#

@toxic zealot What exactly is the problem?

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x² = x+1, then x = golden ratio

#

we know that already

#

so what is the problem?

toxic zealot
#

,close

#

.close

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hallow depot
#

lol

topaz sinewBOT
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crisp raptor
#

I crafted myself a problem to get better at integrating in the R^2 plane with double integrals, I want to calculate the Area A with double integrals

crisp raptor
#

$\int_{x_1}^{x_2} dx\int_{y_1}^{y_2} dy$

thorny flameBOT
crisp raptor
#

where y_1 and y_2 are functions of x of x_1 and x_2 are functions of y how can would I try solving this problem?

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I also calculated all the functions that represent the line segments if that helps

supple mist
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i would not use integration.

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💀

crisp raptor
ancient falcon
#

How do you get better at integrating without using integration?

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ed was solid 5 minutes ago, but... damn, people can't read today

supple mist
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but wouldn’t you craft a better problem

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instead of a damn triangle

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which there a countless better methods to find areas of

ancient falcon
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Plus, I'm really spicy today 😉

supple mist
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@crisp raptor i have problem sets for finding areas in R^2

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i can give you a few problems

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that are integration focussed btw

crisp raptor
supple mist
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fine

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if you insist

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integrate from the green line to the red line from 1 to 1.5

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and then green line to blue line from 1.5 to 2.5

crisp raptor
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I could integrate von y=1 to y=2.5 (green line) and then subtract 1 to 2.5 from the red one right? and so on then I just repeat that untill im done

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would that work

crisp raptor
supple mist
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w/ respect to y you should be doing 1 to 3

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intersection is at y=3

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but yes that would work

crisp raptor
#

ops

supple mist
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this isn't double integration btw

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you don't need a double integral to solve this

distant vine
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technically you can with a double integral if you integrate dxdy on the domain of the triangle

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but pls dont

supple mist
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yeah but why.

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💀

distant vine
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even a single integral is pushing it for calculating the area of a triangle

supple mist
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i already said this

crisp raptor
#

$\int_{A} d\lambda^2$

supple mist
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tobi insisted tho

thorny flameBOT
supple mist
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to do it with integration

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i'll just write what it would be

crisp raptor
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yes the first integral would just give me the function that im integrating (f,g and h right)

supple mist
#

yeha i think thats right

thorny flameBOT
#

ed
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

crisp raptor
#

$\int_{A} d\lambda^2 y^2 x^2$

thorny flameBOT
crisp raptor
#

then I have to do it like this

supple mist
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oh

crisp raptor
#

thats a reason why I want to learn this

supple mist
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i see

crisp raptor
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I can have a whole function f(x,y) where I integrate over the domain of the triangle

supple mist
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yes

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you sholud have led with that

crisp raptor
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because we integrate the 1 function ofc its the area

supple mist
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$\int_1^{\frac 32}\int_{\frac43x-\frac13}^{6x-5} x^2y^2,dy, dx$

thorny flameBOT
supple mist
#

this would be one part

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then you would do between the yellow and green line

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similarl

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y

crisp raptor
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I understand the x integral can you please explain why you choose 4/3x-1/3 on the bottom and 6x-5 on the top

supple mist
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6x-5 is the red line

crisp raptor
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are we integrating the purple part

supple mist
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yes

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we ar

supple mist
crisp raptor
#

it should be right?

supple mist
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yes

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it is true

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the signed area

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thats why red is the upper bound

crisp raptor
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because then we only have 2 different integrals?

crisp raptor
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wait I dont wanna integrate from x=1 to x=4 here because then I would have to solve g(x) and f(x) for x right?

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that would also work

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or what is the reason why you did not do that

supple mist
#

so we just take two double integrals

crisp raptor
#

,w integrate from 1 to 3/2 (6x-5-(4/3x-1/3))

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,w integrate from 3/2 to 4 (2/5x+17/5-(4/3x-1/3))

crisp raptor
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im confused

cyan mesa
crisp raptor
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what is that function

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for purple

cyan mesa
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-3/4(x-1.5)+4

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The length of the purple line is actually 1.4

crisp raptor
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oh

cyan mesa
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So the area should be 3.5

crisp raptor
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thanks!!

cyan mesa
crisp raptor
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then everything works

crisp raptor
cyan mesa
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Distance

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sqrt((x2-x1)^2+ ….))

crisp raptor
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ah the norm of the vector in R^2 ?

cyan mesa
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Err no idea honestly

crisp raptor
#

it just gives you the length

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and its the formula you used

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just didnt remember

cyan mesa
crisp raptor
#

thans I understood this now

#

.close

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real blaze
#

We need to check the nature of the roots of the cubic equation
X^3-18x-35=0

By descartes rules of sign

real blaze
restive inlet
#

that isn't a quadratic equation

real blaze
#

Yes typo

#

@restive inlet

topaz sinewBOT
#

@real blaze Has your question been resolved?

real blaze
#

<@&286206848099549185>

placid valley
#

so what is the equation then? Def not a quadratic though

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or is it a typo

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are you tryin to solve it or whats your question?

real blaze
#

descartes rule is wrong?

#

how to find quickly about nature of roots

topaz sinewBOT
#

@real blaze Has your question been resolved?

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frail girder
#

how do I show that this system of equations has an infinite amount of solutions?

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neon iron
#

How do I determine for which value of the real parameter a>0 the finite and non-zero limit exists

cursive patrol
#

you find the product of the left-most terms of the series expansions of (sinx), ln(1 + x^2), and sqrt(e^4x - 1)

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if a exceeds this product, the limit will go to infinity. if it falls short of this product, the limit will go to 0

neon iron
#

use well known limits like sinx/x, ln(1+x)/x, (e^(x)-1)/x

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i think

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for example ln(1+x²)/x^a
a must be 2 for it to be a nonzero limit

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#

@obsidian otter Has your question been resolved?

obsidian otter
#

<@&286206848099549185>

keen valley
#

whats the probability of the final score being 2

fair thorn
#

no

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since you have other possibilites

keen valley
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(0 and 2)

fair thorn
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*possibilities

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e.g. 1 and 1

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or 2 and 0

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which is separate from 0 and 2

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try solving the probabilities for each of these events separately and then adding them together

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no

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don't do that

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what's the probability of 1, 1?

obsidian otter
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OH nvm I only took probability of 1 only once 🤦‍♂️

fair thorn
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yea lol

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so what's the answer?

obsidian otter
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1/12

fair thorn
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absolutely

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gj

obsidian otter
#

Thank you!

fair thorn
#

np lol

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i didnt even do anything

obsidian otter
#

still thanks for pointing out my mistake haha

#

.close

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neon iron
#

if f(x) = x^2-2x+1 write an expression representing g(x) if (g(x) = 2f(x+1) -3

neon iron
#

if f(x) = x^2-2x+1 write an expression representing g(x) if (g(x) = 2f(x+1) -3

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Im confused how on to do it because of the x+1

acoustic pecan
#

what would you do if i asked for f(5)

neon iron
#

just replace x with 5

acoustic pecan
#

just do the same with x+1

neon iron
#

so I put x+1 instead of x in the f(x) one?

acoustic pecan
#

yup

neon iron
#

alright thank you

acoustic pecan
#

eg if f(x)=5x then f(x+1)=5(x+1)

neon iron
#

thanks

#

I was confused

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cause I tried to do the thing +1

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but i didnt work

#

have a good one

#

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lament fractal
#

can someone pls help me understand what happened on the 4th step how did we get 3/2 ,3x, and 2x

robust zenith
lament fractal
#

what about the 3/2

robust zenith
#

Check out the 3x in the denominator in sin(3x)/(3x). That 3 wasn't there before, so they compensate with the 3 in the numerator of 3/2.

#

The 2 in the denominator of 3/2 cancels with the 2 in the numerator of (2x)/sin(2x).

lament fractal
#

ohh

#

thx so much

robust zenith
#

np

topaz sinewBOT
#

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placid drum
topaz sinewBOT
placid drum
#

for part d why is the 4th term used and not the 5th

#

btw $f(x)=\sum_{n=1}^{\infty}(-1)^{n+1}\frac{x^{n+1}}{3^n\cdot n}$

thorny flameBOT
topaz sinewBOT
#

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terse crane
topaz sinewBOT
terse crane
#

,rotate 270

thorny flameBOT
terse crane
#

i dont get diff quotient

neon iron
#

Do you remember the slope you learn about for lines

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you know

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y = mx + b

terse crane
#

rise over run

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ou

neon iron
#

yeah

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so what is m if you remember

terse crane
#

slope

neon iron
#

yes but how u calculate it

terse crane
#

y two minus y one

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over x two

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minus x one

neon iron
#

yeah

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so like

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thats exactly what the difference quotient is about

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so like

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do you know what a secant line is

terse crane
#

yes

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goes through two lines

neon iron
#

no

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two points

terse crane
#

points

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MY BAD

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WAIT

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I MENT

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POINTS

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😭😭

neon iron
#

on the graph of a function

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so like

terse crane
#

yes

neon iron
#

say

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the first point is some point x okay?

terse crane
#

k

neon iron
#

so we have [
m = \f{y_2 - y_1}{x_2-x_1}
] for the slope of a line

thorny flameBOT
neon iron
#

we will try and calculate the slope of the secant line

terse crane
#

kk

neon iron
#

thats what the difference quotient is. It is representing the slope of the secant

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anyways x_1 = x like we said

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so now x corresponds to f(x) on the graph yes?

terse crane
#

yea

neon iron
#

that's our y_1

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so cool

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now say the second point x_2 is like a distance h away from x

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so x_2 = x+ h

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clear?

terse crane
#

wdym by x_2

#

_

neon iron
terse crane
#

ouh

#

okok

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gotit

neon iron
#

that x_2 corresponds to f(x_2)

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but we just said x_2 = x +h

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so f(x+h)

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putting all together this all basically means

#

[
m = \f{y_2 - y_1}{x_2 - x_1} = \f{\m f{x+h} - \m f x}{x+h - x} = \f{\m f{x+h} - \m f x}h
]

thorny flameBOT
neon iron
#

that's what the difference quotient is. It is a representation of the slope of the secant line

terse crane
#

yea

neon iron
#

if you are still confused i could link you a video maybw

terse crane
#

do u have any helpful vids

#

just in case

neon iron
#

check out khan academy they most definitely have something explaining it

terse crane
#

kk

#

.close

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agile harness
#

factor the denominator

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what do u notice

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yes

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and if u plug in 1 u get 0

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substitute

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like let x=1

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u get -1/0

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which is undefined

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so we have to do more work

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there’s a vertical asymptote at x=1

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so it’s going to approach either infinity or negative infinity

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so we just need to know if the other factors make it negative or positive

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coming from the left of 1

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vertical asymptotes occur when the denominator =0

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so since we’re coming from the left of one it’s really like 0.999

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if we take x to be a little less than one

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is x-1 positive or negative

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is x-2 positive or negative

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is x-3 positive or negative

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(negative)(negative)(negative)=?

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yes

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so it should approach negative infinity

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yes

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the limit =negative infinity

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well u can show the algebra

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with the factors

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and like a sign chart

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showing that less than one the factors r all negative

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and 3 negatives makes a negative

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and a vertical asymptote at zero means itll approach either positive or negative infinity

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hold i’ll show u

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yea at one

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sorry

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because it’s in the denominator

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setting the denominator =0 gives a vertical asymptote

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unless u get 0/0

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which dan be different

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yes

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hold

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u make intervals

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like less than one they’re all negative

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so when u multiply them u get negative

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in between 1 and 2 only x-1 is positive

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multiplying them u get positive

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and so on

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and the 1,2, and 3 r just the zeros of the 3 factors

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u don’t in this case im just showing u how to determine where a function is positive or negative for all intervals

#

for rational functions

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yup

#

ur welcome

topaz sinewBOT
#
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remote heath
topaz sinewBOT
remote heath
#

I started with integration by parts

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but it doesnt make any sense to me

#

since f(x) and g(x) arent given

gray harbor
#

Where’d you get to with integration by parts?

remote heath
#

here

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@gray harbor

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wait i confused myself

#

i see now

#

the answer would only be f(1)g(1) - f(0)g(0)

gray harbor
#

You need a 2

remote heath
#

and ignoring the second part of the formula

#

yes bc its -2

#

bc they gave me the value of the second part

#

i see thanks

#

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west marten
#

if i have found my nullity(T) = [-1,1,-1,1]

west marten
#

why does this make the dimnesion = 1

vernal matrix
#

The kernel spanned by (-1, 1, -1, 1)?

west marten
#

yes

vernal matrix
#

Then your basis of the kernel has one element, so dimension is 1

west marten
#

which elements

#

i see four numbers

vernal matrix
#

The vector (-1, 1, -1, 1)

#

Do you have the original question?

west marten
#

yh

#

find A the relative standardbasis for R^4

#

find ker(T) and im(T)

#

i dont undertand how it is one dimensional

vernal matrix
#

Because the kernel is spanned by the vector $\pmqty{-1 \ 1 \ -1 \ 1}$

thorny flameBOT
#

@vernal matrix

west marten
#

yes how is that a one dimensional vector

#

how can a vector be 1 dimesional

#

that isnt even a line

vernal matrix
#

This is a line

west marten
#

how is that a line

vernal matrix
#

And it's not the vector that is 1 dimensional, but the kernel, because remember that the dimension of a space is how many elements are in a basis

native moth
#

Saying "one dimensional vector" is a bit confusing, I think it means to state 1 dimensional vectorspace

west marten
#

i thought what mattered was linearly independent-ness

vernal matrix
pseudo jetty
#

It's the line $\ds \set {\mat[b]{-1\1\-1\1}t \where t \in \R}$

thorny flameBOT
west marten
#

yes i have wrote that on my paper

#

i must have a completely misunderstood idea of matrices then

native moth
#

Huh

west marten
#

i thought if you have 4 linearly independent things its would span r^4

vernal matrix
#

4 linearly independent vectors

west marten
#

so what exactly does the coeffeicents in front it represent then

native moth
#

Where is 4 linearly independent things here, hmm

west marten
#

what is x1,x2,x3,x4

vernal matrix
#

Those are the entries of your vector

#

Those are real numbers (considering you're in R^4)

west marten
#

so it isnt (x,y,z,q)

#

gggggg

#

so this is a line in a four-dimensional space

#

so

#

[-1,1,-1,1]

pseudo jetty
#

$\ds \set {\mat[b]{-t\t\-t\t} \where* t \in \R}$

west marten
#

is a point in R^4

thorny flameBOT
pseudo jetty
#

you could also write it like this

west marten
#

and the span is the set of scalars you can add onto this

native moth
west marten
#

that would make a line

#

(-1,1,-1,1) is a point in a four dimensional space and if you times it by a scalar, lets say 2, you get (-2,2,-2,2) and if you keep this up you'll get a line

native moth
west marten
#

i changed it

topaz sinewBOT
#

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craggy haven
#

yeah unfortunately we can't help on quizzes here. good luck!

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winter tartan
#

Can someone point out where these steps are wrong? The answer I get is different from the correct answer.
(2x^(ln(x)-2)(2(ln(x))^2-ln(x)+1)

sweet shard
#

what's the question

winter tartan
#

wait

#

(b)(i) modified, the fact may not be useful

sweet shard
#

both exponential disappeared

winter tartan
#

oh yeah, I used lim[h->0]((e^x-1) / x) = 1

#

multiplying ((ln(x+2h))-(ln(x))^2)/((ln(x+2h))-(ln(x))^2)

sweet shard
#

that all sounds wrong

sweet shard
winter tartan
#

oh wait i meant x -> 0 haha

sweet shard
#

once you take the limit of h, there should be no more h variables left

winter tartan
#

as i think (ln(x+2h))-(ln(x))^2 approaches 0 when h approaches 0

#

wait i have to write it down

#

i forgot to write lim[h->0] in the next few steps

sweet shard
winter tartan
sweet shard
#

why is ln(x) multiplying ln(1+ 2h/x) ?

winter tartan
#

uh oh

#

oh sorry, the ln(x) should not be there

#

so that makes the answer 2x^ln(x) (ln(x))

#

but still different

topaz sinewBOT
#

@winter tartan Has your question been resolved?

sweet shard
winter tartan
#

wait

#

last step should be 2x^(ln(x)-2) ln(x)

sweet shard
#

what did you do from the first to the second lines here

winter tartan
#

use lim[h->0] (ln(1+h)/h) = 1

sweet shard
winter tartan
#

(facepalm)

#

i will retake my calc for sure

#

but now i have 2x^(ln(x)-2) only

topaz sinewBOT
#

@winter tartan Has your question been resolved?

dense rain
#

I have no interest in going through this kind of algebra, but the intent of my hint earlier in the day was that it would be helpful if you used the fact that, -under the limit-,

$ln(1+\frac{h}{x}) = h\ln\left[\left(1+\frac{h}{x}\right)^{\frac{1}{h}}\right] = \frac{h}{x}\ln\left[\left(1+h\right)^{\frac{1}{h}}\right]$

so that using the continuity of the natural log, the limit

$\lim_{h\to 0} \ln\left[\left(1+h\right)^{\frac{1}{h}}\right] = \ln(e).$

thorny flameBOT
#

JessicaK

dense rain
#

You were asked to use this fact:

#

That should be a sign that it should show up somewhere in your work

topaz sinewBOT
#

@winter tartan Has your question been resolved?

winter tartan
#

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hardy meteor
#

this is the drivation of langrange's equation from hamilton's principle. i don't get from 2.8 to the last equation. first term vanishes but how does second term equal to the following?

hardy meteor
#

from Classical Mechanics by Goldstein page 37

loud oasis
#

the second term is combined with the first integral from (2.7)

#

since (2.8) only deals with the second integral from (2.7)

hardy meteor
#

im so dumb. thank you

#

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balmy spruce
#

$f(x)=\begin{cases} (2x+\sqrt{x})^2 ,if \ x\geq 0 \ (2x+\sqrt{-x})^2, if \ x<0
\end{cases}$
\the slope of tangent (T) of f at A(-1,-1) is
\a)1.5
\b)1.65
\c)2.5

thorny flameBOT
#

pirate king

balmy spruce
#

isnt this question wrong or not enough information ?

#

or am i missing something

#

A(-1,-1) is not on f

#

so assuming that this was not chosen by mistake

#

then A(-1,-1) is on (T)

#

but thats all

#

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olive stream
#

can someone give me the formula for teststastistic, if i want to do a hypothesis test about the y intercept of linear regression

olive stream
#

I cannot find it online

topaz sinewBOT
#

@olive stream Has your question been resolved?

olive stream
#

<@&286206848099549185>

olive stream
#

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golden sky
topaz sinewBOT
golden sky
#

Idk how to do a)

restive inlet
#

apply gradient (slope) formula

golden sky
#

Line ab is perpendicular to line bc

#

And I calculate gradient first

#

And since the multiply to - 1

#

I just solve

#

Right

#

Wait

#

I got the quadratic b^2 - 7b +14 =0

#

I put it in desmos I got 6 and 1

#

And since b is greater than 3

#

It's 6

#

But

#

When I use quadratic equation Ion get that

#

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ruby obsidian
#

Why is the x-coordinate of the center of mass of the upper half of the circle equal to the x coordinate of the center of mass of the full circle?

ionic oar
#

because of symmetry

#

there is the same amount of mass on either side

#

which means your x coordinate would always be on the line of the center of the circle

ruby obsidian
ruby obsidian
#

oh wait

#

sio like

ionic oar
#

do you intuitively get what a center of mass is

ruby obsidian
#

nono i get ur logic for the circle

#

i was just thinking about if that same logic owuld work on the caridoid too

#

ok so to answer "Why is the x-coordinate of the center of mass of the upper half of the circle equal to the x coordinate of the center of mass of the full circle?"

#

first, the line of the center of the circle is where both sides of the object will have equal amount of mass (assuming the object has constnat desnity)

#

so even when we're considering just the upper half of an object that is horizontally cut, because that sliced shape will have equal mass on each side from the line of the center of the circle

#

the x-coord of the center of mass is always on the line of the center of the circle

#

and this logic applies to any object of constant denisty

#

would this be a "correct" description?

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#

@ruby obsidian Has your question been resolved?

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hoary wraith
#

Good Day!
Quick question, if I have the following function, does that mean that my co-domain is between 0-1?
Or how can I read it?

vapid sonnet
#

Range is different

hoary wraith
#

And because I cant reach all values between 0-1 my function is not surjective?

meager dawn
#

the function is not surjective and it doesn’t satisfy the intermediate value property lol

#

it doesn’t take any of the values from 1/4 to 3/4

#

for example

vapid sonnet
#

Oh yes

#

My mistake

meager dawn
#

if all of those steps are possible

#

if it’s not possible to do that then you have to just reason about the function, which is a bit harder

hoary wraith
meager dawn
# hoary wraith So when I sketch the function and find gaps like below, I can assume it is not s...

yes sort of, but like the function can go back down later (if you were given a different, slightly wackier function) if you know that over your entire domain, you’ll never reach that y value then you know that it’s not surjective, in this example i can draw the horizontal line y=1/2 and realize that my function never takes on the value 1/2, which is in our codomain, so we know it’s not surjective

hoary wraith
#

And this part determines my Domain to Co-Domain relation?

#

So we project from (0-1) to (0-1)?

meager dawn
meager dawn
hoary wraith
#

Okay great, thanks!

#

I will have a look at a few examples

#

.close

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toxic stirrup
#

what does the 15 in L_15 mean

topaz sinewBOT
toxic stirrup
#

to split it into 15 parts?

woeful drift
#

probably

toxic stirrup
#

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fast adder
#

Can anyone help me solve two problems about Carnot's cycle?

ionic oar
#

could give it a shot

#

although the physics server is better for it

fast adder
#

Oh is there one?

ionic oar
fast adder
#

Also the problems are in Spanish I'm translating them rq

#

Thanks I'll join that one

#

A reversible heat engine works between two thermal reservoirs, one of them at 443K and the other one at 783K. Find the efficiency of the engine. Find the work made by the engine if we provide 7000kcal and the heat transfered to the cold reservoir.

#

A reversible heat engine operates between two thermal reservoirs, one of them at temperature T and another one at 280K. If it provides 1000kJ/min of heat to the cold reservoir and develops a usable power of 40kW, find the temperature of the hot reservoir.

#

<@&286206848099549185>

ionic oar
thorny flameBOT
#

Norbert Baudin

topaz sinewBOT
#

@fast adder Has your question been resolved?

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tepid valve
#

hi

topaz sinewBOT
tepid valve
#

W=true

icy sky
#

thats correct

#

iirc if you had
(A iff B) iff (B iff C)
then you should have same columns

icy sky
#

if i remember correctly

#

iff is the <=>

tepid valve
#

okey

#

but its not equal its ^

#

wait

#

I misread something

#

Its not equal it implies

#

I thought that two parts should be equal, but the one part implies the second one

#

I understand now

tepid valve
#

.close

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stray dew
#

how do i know whether i can integrate a function or not. say for example

stray dew
#

these two

#

left picture it should have an integral sign for 4te^2t

#

the left picture im supposed to do integration by parts

raven sparrow
#

Second picture does not have an anti derivative in terms of elementary functions

stray dew
#

right picture its a new method but how would i confirm that none of the normal integration methods would not work

raven sparrow
#

It means that you won't be able to integrate it using your normal methods since you can't express its primitive using only powers/trig/logs/exponentials/etc

#

Now the proof of that is not something of that level

stray dew
raven sparrow
#

By looking at it you just learn to recognize those integrals that won't work under any method . Like here, parts won't help whatever you do, and there's just one thing you can u-sub and is gives nothing.

#

Some others could be sin(sqrt(x))

stray dew
#

what else gives it away

#

i know i need two parts for it

#

so i have 2

#

u and v

raven sparrow
#

Left picture gives it away because the t factor will "simplify" the integral when doing parts

#

Because the derivative of t is 1

stray dew
#

wouldnt i have 4t as u

#

du is 4

#

oh wait

#

for picking dv, it needs to be something easy to integrate so id go with e^2t

#

and v would be 1/2e^2t

raven sparrow
#

I'd say, usually, composition of log, sqrt and exponentials are suspicious.

stray dew
#

or harder

raven sparrow
#

Yeah

stray dew
#

oh ok

#

ty

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#

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dry hull
#

$\sum_{n \geq 2} \frac{x}{n^{1 + x}}$ i need to find for which values of x this converges

thorny flameBOT
#

uwupachkii

dry hull
#

i find x > 1

#

so that we can compare it to a riemanns serie

rigid ivy
#

x>0 maybe?

dry hull
#

but then the follow up question is the norm of it

#

oh yeah surely

#

exercise asks for largest interval

#

for x = 0 it works

#

we define $f_n : x \rightarrow \frac{x}{n^{x + 1}}$ and we need to find for $n \geq 2$, $|| f_n|^I_{\infty}$

thorny flameBOT
#

uwupachkii

dry hull
#

i decided i would find the derivative because i dont see obvious marjoration

#

and the derivative cancels when x = 1

#

and damn it is correct

#

so yeah interval is more than >1

dry hull
#

idk why i thought it would diverge if 1+x was not stricly superior than 2

#

thanks guys !

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tight rivet
topaz sinewBOT
tight rivet
#

Is 0.1 correct

topaz sinewBOT
# tight rivet Is 0.1 correct
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
radiant tapir
#

first off be careful of your units. 0.1 feet would be a very, very tiny building

#

it's one mile away

#

try converting miles to feet first

tight rivet
#

5280

radiant tapir
#

ok good. Now re-do the work with that information 🙂

tight rivet
#

Tan(6)=x/5280 5280tan(6)=x?

#

555

#

Is that right

radiant tapir
#

yep seems right to me 🙂

tight rivet
#

@radiant tapir

#

How do I do this

#

My vertex is right?

#

@sweet shard

sweet shard
tight rivet
#

How

#

I thought u plug in x to find y

sweet shard
#

yea but your x is wrong

#

when the x value is left of the y axis, then that x value is negative

tight rivet
#

4/(2 times 1/2)

#

For x?

sweet shard
tight rivet
#

-b/2a

sweet shard
#

a = -1/2

tight rivet
#

Oh

sweet shard
tight rivet
#

How about find the maximum or minimum value of f in that graph

#

Does that mean the highest/lowest x intercept

sweet shard
#

no, y = f(x), so min/max of f means min/max of y

sweet shard
tight rivet
#

I didn’t take the full picture

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#

@tight rivet Has your question been resolved?

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cyan harbor
#

Given that Megan is the second place, the formula is technically like this 5p2

cyan harbor
#

Or am I wrong

wary tulip
#

second runner up means 3rd place?

cyan harbor
#

I think that's 2nd place

wary tulip
#

what are champion and first runner-up then?

cyan harbor
#

oh yeah it makes sense

#

But Megan is already the 2nd runner up

#

So 5p2 I think

wary tulip
#

if megan is included in the 5 contestants (which i would assume) then it should be 4P2

cyan harbor
#

She is included

#

Look at 13-14

wary tulip
#

uh that means she's not included in the 5 lol

#

but also that's information you should have included in the original question

cyan harbor
#

So it's technically 5p3?

wary tulip
#

no

#

5P2 is right

cyan harbor
#

Oh okay

#

Thanks

#

.close

topaz sinewBOT
#
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#
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ancient valve
topaz sinewBOT
ancient valve
#

What do I do

woeful drift
#

you use the hint

topaz sinewBOT
#

@ancient valve Has your question been resolved?

ancient valve
woeful drift
#

Because all right triangles satisfy that property, and anything that isn't a right triangle doesn't

ancient valve
#

I do not get it

#

Nvm I'm stupid

woeful drift
#

They explain in multiple steps where 180 comes from

ancient valve
#

!close

#

.close

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visual leaf
#

The tutorial said that this integral diverges as x^-1/2 is a p function where p=1/2 < 1

What does this even mean?

visual leaf
#

(Like what is a P function and why does this mean it diverges here

woeful drift
#

It refers to expressions of the form 1/x^p

#

The integral of 1/x diverges, so anything with a smaller power than 1 also diverges

visual leaf
#

I see I see
Why does the integral of 1/x diverge then?

woeful drift
#

Well what is the antiderivative of 1/x?

visual leaf
#

ln|x|+c

#

Ohhh ok I see

#

And if u put infinity in for x it goes to infinity so it diverges

woeful drift
#

Indeed

visual leaf
#

Aigh thanks for helping 👍

#

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#
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tight rivet
topaz sinewBOT
tight rivet
#

How do I do this

silver wasp
#

is this a calculus problem?

restive birch
#

the equation describes a parabola with a maximum turning point

tight rivet
silver wasp
#

okay do you know how a parabola looks based on the equation?

tight rivet
#

It goes down

silver wasp
#

nice

#

where is the maximum then?

tight rivet
#

I dunno

#

-5/2(-0.001)

#

?

restive birch
#

that is the x-coordinate of the vertex

tight rivet
#

Isn’t that part of the maximum

restive birch
#

yes

#

to find the vertex from this equation, you have to use the formula u just used

#

x = -b/2a

#

to find the axis of symmetry

#

once u have x, you sub that value into the given equation to find y

#

then u have vertex (x,y)

tight rivet
#

So is y the maximum profit then?

restive birch
#

yes

tight rivet
#

4400?

restive birch
#

ye

tight rivet
#

Thanks

#

.close

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lime zenith
#

We are supposed to use limit comparison with a geometric series to find if the sum of a (n) is convergent or not. I have no clue how to even start this

worthy storm
#

for large n, which term is going to dominate in the numerator? and which term in the denominator?

topaz sinewBOT
#

@lime zenith Has your question been resolved?

astral thicket
#

does B+2=4^n?

lime zenith
#

I tried making b(n) = 4^n/19^3n but couldn’t figure out from there

#

Is that the right track?

worthy storm
lime zenith
#

😭

worthy storm
lime zenith
#

So then the limit would just equal 1 and b(n) would be convergent so the series converges?

astral thicket
#

I don't know what that means

worthy storm
worthy storm
astral thicket
#

ok

lime zenith
#

Lmao

#

Well the limit would equal 1 just because you have terms cancelling out on top and bottom since as n approaches infinity, the other terms can be ignored

#

And then b(n) is convergent bc it’s a geometric series where abs value or r < 1

#

So for this one, would you make b(n) equal to (4^.4n/19^(n+3))^6?

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#
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lime zenith
#

.reopen

topaz sinewBOT
#

topaz sinewBOT
#

@lime zenith Has your question been resolved?

topaz sinewBOT
#

@lime zenith Has your question been resolved?

lime zenith
#

<@&286206848099549185>

#

😦

vapid sonnet
#

Hey

#

You need a bn right such that an/bn convergent

vapid sonnet
lime zenith
#

Bruh we didn’t learn that yet

hearty anvil
lime zenith
#

Im saying that there’s probably a way to solve it without the ratio test that I should know

hearty anvil
#

aight lemme take a gander

hearty anvil
lime zenith
#

The second picture I sent is my current problem, but the instructions are the same

hearty anvil
#

4n^2 / (19^(n+3)) because its the highest term of both

#

and u can use that one which happens to be geometric to know if it converges or not

#

the limit comparison test says that if one converges the other does too

#

after proving that they are both greater than 0 ofc

topaz sinewBOT
#

@lime zenith Has your question been resolved?

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#
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#
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pulsar sun
#

in the above, if I replace n with with 1/j for some real integer j

pulsar sun
#

is that allowed?

chilly walrus
#

no

pulsar sun
#

why btw?

chilly walrus
#

doing n choose 2k won't make sense then

pulsar sun
#

well is there like no formula for cos(x/n) then?

chilly walrus
chilly walrus
pulsar sun
#

just too tough to generalize?

chilly walrus
#

basically

pulsar sun
#

i do remember bprp finding cos(theta/3) and it being multivalued or smthin like that

chilly walrus
#

what i did is set $T_n(\cos(\frac{\pi}{n})) = \cos{\pi}$

#

and i get a polynomial

pulsar sun
#

like there were multiple different formulas out of which only 1 was (supposed) to be correct

chilly walrus
thorny flameBOT
#

artemetra

chilly walrus
#

is discord media down again

pulsar sun
#

the latex isnt loading

chilly walrus
#

shit

#

lol

pulsar sun
chilly walrus
#

$d$

thorny flameBOT
#

artemetra

chilly walrus
#

dead

pulsar sun
#

wait u is real right

#

what if we replace u

chilly walrus
#

you can

#

you'll get a complex polynomial

pulsar sun
#

💀

pulsar sun
chilly walrus
#

wait

chilly walrus
#

yeah it's fine

#

that's how chebyshev polynomials were derived tho

#

lol

pulsar sun
pulsar sun
#

so

#

we have polynomials

chilly walrus
#

yes

chilly walrus
#

yes

pulsar sun
#

we replace x with cos(u) to get cos(nu) correct

chilly walrus
#

mhm

pulsar sun
#

then if replace x with cos(pi/n) why do we get cos(pi) and isnt that -1?

chilly walrus
#

it is -1

#

$\frac{\pi}{n} \cdot n = \pi$

thorny flameBOT
#

artemetra

pulsar sun
#

Mhm WAIT OH we put pi/n in cos nx i see i see

chilly walrus
pulsar sun
chilly walrus
#

$\frac{e^{ix/n}-e^{-ix/n}}{2}$

thorny flameBOT
#

artemetra

chilly walrus
#

does that work?

#

not satisfying tho!

pulsar sun
#

as a substitution? idrk

pulsar sun
pulsar sun
chilly walrus
#

i made a formula for any integer degree

#

like $\cos(n\textdegree)$

pulsar sun
#

hmm

thorny flameBOT
#

artemetra

chilly walrus
#

wtf

pulsar sun
#

i suppose i was expecting something like cos(nx) chebyshev polynomial thingy

chilly walrus
#

you understood

pulsar sun
#

yes i understood

chilly walrus
#

you can easily multiply the angle inside cos

#

dividing tho is really hard

pulsar sun
#

Hmm did u try doing x=1/u sub urself ever? if u wrote an essay/paper/whatever on this?

chilly walrus
#

not really since that formula breaks for non-integers

#

you can try but you are gonna have to do (1/2)! type stuff

chilly walrus
#

yea

pulsar sun
#

oof

#

hmm..

#

well tyvm

#

.close

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#
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chilly walrus
#

np

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arctic rock
topaz sinewBOT
arctic rock
#

How--?

#

(10Cr) (1)^10-r x (-x)^r

#

but that doesnt work