#help-26
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yes
my bad i was thinking that it was possible to turn -1/ln(7) to -ln^1(7)
oh
ok
so (-1/ln(7))u + c
(4-7^x/ln(7)) + C
$^{1}/_{2}$
(っ◔◡◔)っ 🤍 cosygod 🤍
$\frac{1}{2}$
Ann
(っ◔◡◔)っ 🤍 cosygod 🤍
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the line y=2x-3 is reflected about the line y=x. find the equation of the reflected line
not sure how to do this at all
Change y and x position
no...
nevermind I misread that
for reflection about the line y=x there is a shortcut (as Calamity mentioned)
You can just replace y for x and x for y in your equation
so i swap x and y and isolate for y right
yes, you can isolate for y if you wish to
x=2y-3 <=> x+3=2y >=> y=(1/2)(x+3)
In this particular question it's possible to isolate y
in any expression containing at least one y, it is possible to solve for y, no?
not at all. consider x=sin(y)
It depends...
there's no way to isolate y
And maybe for some background info:
We can find the point at which our line and the line y=x intersect. We also know that the point (0,-3) will be at (-3,0) after the reflection. From these points we could also get the equation.
y=sin⁻¹(x) over the interval [-pi;pi]
yes, but that doesn't account for all branches
y= arcsin(x)
because a singular x value can have more than one (in this case, infinitely many) values of y associated with it
meaning y is not a function of x
I see
,w graph x=sin(y)
hence we define the inverse over a given interval
oh well wolframalpha just switched the x and y axes
that is still not “solving for y”
lmaoo
intellect 100
yes, that is called a partial inverse function
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Prove P(A∪B) = 1 - P(A'⋂B'), when A and B are arbitrary events.
what does + mean
- is union
I'm still not sure what comprises a complete proof, in this example.
if you mean union them why not write the union symbol
anyway (A u B)' = A' n B' is the crux of the proof...
if there are extra things your professor wants you to say in the proof then that's something to ask them about not us
Do you see it is evident in my truth table and reasoning?
it's fine yeah
Thank you for your help!
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@worn aurora Has your question been resolved?
have you heard of suvat equations?
yeah
they are the same for rotational motion
use the last one, where instead of s you get theta (angle), instead of u it's omega_i and instead of v it's omega_f
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Can someone help with this?
Assume for the sake of contradiction that there only exists n primes
but then show that with these n primes you can make an n+1th prime
How about assuming to the contrary that there are n number of primes listed?
wdym?
Like prove that there are more than n prime numbers for all natural numbers?
oh wait nvm
How is this solution?
Looks good, you don't even need the powers of alpha, and just take n = p1 * p2 * p3 * ... * pn
Thanks
maybe you need some form of induction though, since you only prove k + 1 primes exist
actually, nvm
that's the contradiction
Yea
maybe specify that those k are supposed to be the only ones
Ok
Sorry can you explain? I’m a bit confused here
You haven't explicitly stated in your assumption that the primes p1, ..., pk are the only ones
you just said that they were primes
Added the changes
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is PSL(2, C) an abelian group or no? 
Looking it up, no.
is it because matrix multiplication isn't commutative?
Well, that's necessary for sure
It's not so obvious though with PSL
What's your definition of PSL(2,C)? We can work with that
here
i want to prove that there is no isomorphism, because C^3 is abelian but PSL(2, C) isn't
@half sage Has your question been resolved?
@keen venture can you help please 
you could just try multiplying two random elements in both orders. you likely wont get the same results
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If S is relation defined this way:
в кое множество живеят x и y?
истинските числа
тоест реални?
да
добре
трябва да се докаже, че е релация на еквивалентност
за рефлексивност получавам просто x-x=0
0 е в целите числа
точно така
ами не, разсъждение няма да върви така
имаш, че x - y ∈ Z, и искаш да докажеш, че y - x ∈ Z
това следва директно от твърдението y - x = -(x-y)
защото -1 е цяло и Z е затворено относно умножение
или пък за всеки елемент има обратен по сложение, ако искаш
S
знае се, че x-y и y-z са цели, и искаме да докажем, че и x-z е цяло
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How to solve this guys? I tried pretty hard
either 4 or 14
Please provide reasoning
i was looking at the left diagnal. the last digit is -3 then plus 1
so i assumed thats the pattern-
@muted wadi Has your question been resolved?
i hate problems like these
hint: ||each number on the left diagonal is the result of the two numbers above it diagonally||
ty i wil look into it
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Q: Integration
$$
a_n=\int^{1}_{-1}\;(1-t^2)\cos(\pi n t)\;dt
$$
Struggling to see how this evaluates to the highlighted part in this image:
integration by parts
& used properties of even functions to rewrite the bounds
.close
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not sure where to start
Are you familiar with implicit differentiation in general?
Just like f''(x) = (f'(x))'.
u=y v=f"(x)?
You can give them other names if it helps : say you have y = f(x), y' = g(x) and y'' = h(x).
Now your equation is f(x)•h(x) + 2(g(x))^2 + 2•f(x) = 0
Can you take the derivative of that using the chain rule and product rule when necessary?
Ok that's the first term
But it's already useful since the derivative of h(x) is f'''(x) isn't it?
yes?
So now do that with the other terms to get a new equation, and this one will involve h'(x), which you want to solve for.
@worn raven Has your question been resolved?
You didn't do the chain rule properly for g(x).
But yeah
And then you can isolate h' and replace the functions with their actual expressions as derivatives of y.
wym what should it be?
You forgot to multiply by g'
ye but it wants dy^3/dx^3?
That's h'
We used those placeholder functions to help with realizing that those are just functions of x you can take the derivative of. Now you have (something) = 0 and you should isolate for h'(x)
ye i still dont really get it lol
This equation
Solve for h' in it
h'(x) = d3y/dx^3
okay so g(x) is what y? and g^x is dy/ax? h^x is dy^2/dx^2
f(x) = y. g(x) = dy/dx = f'(x) , h(x) = d2y/dy^2 = g'(x)
Yeah that works
It was just to try and help with chain rule and stuff
But it doesn't matter you could've done it like that to begin with 👍
i got
y(d^3y/dx^3)+dy/dx(d^2y+4d^2y/dx^2 +2)=0
ye the other set notation im not used to
so my brain was like brrr
I think that's good yeah. Now you can just isolate the third derivative like it was a normal variable
Yeah
yipppe
And now it works out since everything is in terms of y, y' and y''
an hour for part a now part b LMAO
Oh well
think i can figure this out just sub in numbers
Yeah essentially. You can plug values into the Taylor series
can i simplify d^2y+4d^2y/dx^2 to amke 5d^2y/dx^2
ye my specfication dosent do the taylor "swift" series lol
Yes it should be right
for part b what do i do when i found d^2y/dx^2
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How do I get PY
Is wp a+12?
Dunno
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Using the digits 1,2,3 and 4, without
repeat, one can form distinct 3-digit
numbers.
What is the average of all possible
numbers formed?
(A) 200
(B) 225.5
(C) 275
(D) 277.5
(E) None of the above
how would you do this non manually?
each digit appears in each position (100s, 10s, 1s) 6 times
welcome
sum of coefficients of polynomial f(x) is f(1)
yep
how bout this
got 2 things
$$\frac{a+b}{ab}=\frac{5}{a-b}$$
$$(\frac{a^2+b^2}{ab})^2$$
Skill_Issue
like if i tinker around i can get
$\frac{625}{(a-b)^2}-\frac{100}{a-b}+4$ for the lower equation but idk where to go from there
Skill_Issue
@pearl fog Has your question been resolved?
hint: ||manipulation you want to apply to top equation is multiply both sides by (a - b)||
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Erm i dont really need help
just wondering what the process would be from changing from d/dx^2 to d/dy^2
knowing the relation between y and x
it's chain rule
so use the chain rule of y = x/l twice?
yep
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“Find the length of AD”
Idk why I can’t do this is seems simple but idk what to do
I'm pretty sure you need more information
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Hi, I'd just like to get some help understanding the Gaussian Elimination process shown in the image shown :>
I'm specifically confused about the process that went into turning the numbers into zeroes
@neon iron Has your question been resolved?
in rows 2 and 3, the first column has value 2, so dividing those rows by 2 then multiplying by 3 gives a value of 3 in the first column
you can then subtract row 1 from rows 2 and 3, which gives zero
then it's the same thing for the second column
you could have also just immediately subtracted 2/3 * row 1 from row 2 and 3 to get zeros in the first column
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i need help with tetration, im not understanding this topic at all
What’s your question?
im stuck w the basics, take 2 tetrated to 3 for example
i don't understand how tetration works
its
((((2)^2)^2)^2)
i mesed up
it's okay 😭🙏
2 tetrated 2 is 16
the answer directly? or 2 raised to the power 16?
Ok its messed up
I am explaining the correct one
rn
2 tetrated 2 is just 2 ^2
its 4
@drowsy root
i see
so 2^2^2?
what's the pattern? when someone mentions tetrated to n, do i write power of the number n-1 times?
like, 3 tetrated to 2
will be 3^2^2
so 4 tetrated to 3 will be
4^4^4
4^4^4
what-
yes
yes
Dude its easy
the problems would get complicated due to the calculations involved in it
if i mention 3 tetrated to 3
yeah
you would certainly need a calculator
for pentation
Calculator
you don't get a calculator during exams until college anyway
Yeah
what procedure, i mean.
and pentation doesnt come in school
neither does tetration
.
@drowsy root Has your question been resolved?
@drowsy root Has your question been resolved?
no
@drowsy root Has your question been resolved?
.close
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Can someone help with this?
@calm gyro Has your question been resolved?
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Hi, I need help studying for physics, the problem says, 2 blocks, with masses m1=.3kg and m2=.5kg, are connected by a string and lie on a frictionless tabletop. A force F = 5.5N is applied to block m2. I am good with everything except finding the tension, I know how to do it but dont understand why i have to do it like that. The way I got the answer was doing .3 * the acceleration, but i still dont get why i am doing said calculation.
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@dark pond Has your question been resolved?
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The gradient of the curve y=ax^2+bx at the point (3,-3) is 5. Find the value of a and the value of b.
That's two equations you have there - do you know how to get them?
I found the derivative of the equation of the curve to be dy/dx=2ax+b
Yep 
So you have y and dy/dx
For a particular x value, you know the value of both of those
The only x value that was given is 3
Yep, so then what does that give you as y and dy/dx?
Sorry im confused
Are you saying to plug in x into the normal and derivative equations?
Yep - but the original equation will have an output value, and the derivative equation will have an output value too, that the question gives you
I see
So in the original equation it becomes -3=a(3)^2+b(3)
And in the derivative it becomes 5=2a(3)+b
@vernal matrix so the original equation becomes -3=9a+3b and derivative becomes 5=6a+b?
Yep 
Woo hoo!
So this is exactly where I got stuck. I have no idea what to do now 😭.
@vernal matrix would I have to somehow get them equal to eachother?
You could e.g. isolate b, say out of the second equation, then substitute that into the first one
Yep
then can work with that then find b
It's just a pair of linear simeultaneous equations of course 
I got a to equal 2
OMG
I finally understand the problem
Only took me almost 2 hours
,w 9a + 3b = -3, 6a + b = 5
Looks good 
And awww
well done 
Just type .close and it will do it for you 
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how would i go about doing this ?
would i first find ab
which is m
then find c m ?
<@&286206848099549185>
that didnt work btw XD
AB is the entire length of the base you would just need M which is the midpoint of AB, so use the Midpoint formula
ye a+b/2 ??
yes?
you would do that for each coordinate though so x = (2 + 2)/2, y = (2 + 4)/2, z = (0 + 0)/2
yes
You shouldn't need to find cm
find the distance between C and M
distance for each coordinate
so i do c-m?
I believe so yes
nice
that was right
Find the vector from C to the point that lies two-thirds of the way from C to M on the median CM.
now i do
c+m /3?
well that wasnt quite right
you should just be able to take what you got for the original question and multiply it by 2/3
1,2,-2 * 2/3?
yes
well that worked lol
Find the coordinates of the point in which the medians of ABC intersect. This point is the plate's center of mass.
now is this finally cm XD
and thats c+m / 2 ?
yea thats wrong lol
but I would do what you did for question 1 and apply it to midpoint of AC then find vector to B
then, midpoint of BC and vector to A
then find out where these all intersect and that gives you the center of mass
you could also try the avg method, (avg x, avg y, avg z) = midpoint
I mean center of mass
so for that would i just take all x's add them upp divide by 3 sa,e fpr y and z ?
only using the vertexes coordinates
yes, I am not 100% if it will work in this case, but its worth a shot
so 1+2+2 = 5/3x 2+4+1=7/3y 0+0+2/3 =2/3z
ay it worked
thx so much for the help frfr now i can finally go to bed lol
good night then
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.close
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I can't figure out what I did wrong here...
y(1) = 5 holds true here
c = 15^18/18-1 btw
and the integral of (1 + x) / x is just ln|x|+x, no?
I got
y^18 / 18 = ln|x| + x + C
and C = 5^18/18-1 because y(1) = 5
any clue what I did wrong 😭
Seems right
Why is it 15¹⁸/18 here tho?
I solved for C
oh my fucking god
thank you so much
Np
yeah I got it correct now
Nice
Hmm
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I tried constructing sectors to get radius and also construction of another circle with this chord as diameter. Didn't work
<@&286206848099549185>
sectors is good
you want to make use of angles here... specifically, the angle subtended by an arc is proportional to the arc length
So should I take separate angles for each arc length or same angle overall for arc length of 6?
you want to relate everything in terms of the same angle
because you are given the arc lengths (and therefore their ratios)
so you know the angles will be in the same ratio
for this purpose, i'd recommend picking a small angle to use as a unit
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how do i solve this?
please ping me
@languid blazehint: 3^n
im not sure where 3^n comes from
3^n counts ways to make 2 subsets that don't inersect
for each element you put it in A, or B or neither
not telling
4^n - 3^n
becacuse there are 4^n possible ordered pairs
and since we need want to find the number of ordered pairs that have an intersection we just substract the amount that dont have an intersection from the total
makes sense to me
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How the hell do I solve this number 7. And the answer is 176ft, how do I get there at all
,rotate
the question is written in a very difficult way to understand tho 
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Why am. I here
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could I just have a hint
like what substitution should I perform?
I was thinking maybe y/x=u?
would that work?
or is there another method?
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need help
with coordinate geometry
is the 3rd question of the exercise and the question from the other pic the same?
because i think they're the same but they have different answer so idk what's happening
sorry for the bad quality
also ping me please
@neon iron Has your question been resolved?
@neon iron they are different
,rotate
hmm
yea
so i have to T^2=SS_1 for the second question
and T=S_1 for the exercise one
ok yea i thought so
thanks for helping @ornate magnet
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someone please help
L and U matrices are correct
for some reason the x_1 and x_2 are not
ping me if you help
<@&286206848099549185>
@silent mortar Has your question been resolved?
hi im new and i have a question so when a twine has a strength of 4 tex, which means 1 km of this thread weighs 4 grams. Calculate the diameter of the thread in mm if the material density is 1.44 g / 2 square centimeters?
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ive went through the formulas a few times and looked them up and the selections i have now all seem to be true but im getting the answer wrong
D and E are both false due to commutativity
I'm iffy about A
B and C are both correct I'm pretty sure, I also tried submitting just B and C and that was wrong as well
C is not true, there's a very easy counterexample
A is fine, can you say what the inverse of A^3 is?
whats the counter example
can you find an example where A+B = 0?
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halp
i dunno thats the thing
do you know what that graph looks like
not for the one you have
the one you have given is in a different shape than yours
than $ax^2+bx+c$
DerTheo
thats why it was weird.
you can write that form as
$a(x-b)^2+c$
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DerTheo
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ik this is math
bu tlike
quick question
will #3 have a reaction?
cuz if theres 2 aqueous products it doesnt have reaction
my teacher said theres no reaction but other people said there is a reaction
@wild pawn Has your question been resolved?
<@&286206848099549185>
do i break up water if it is a product
in a net ionic equations
#old-network for chemistry server
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Hello anybody can explain me the question and how to get it?
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How do i get this guys
Yousef
$\frac{1}{r\pi3} + Sc{\pi_3} = 1 +\frac{S}{\frac{1}{r\pi3Cpi3}$
I don't know whatever topic this is srry
it's just constants
I just wanna know how I can simplify this expression
wait
P1=
Yousef
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$\frac{1}{r_{\pi_3}} + SC_{\pi_3} = 1 - \frac{S}{P_1}$
mehdi_moulati
like this @proud hinge ?
yes but can you write my p1 inside
$\frac{1}{r_{\pi3}} + SC_{\pi_3} = 1 - \frac{S}{-\frac{1}{r_{\pi3} C{\pi_3}}}$
mehdi_moulati
yes
like this bro
so how do i get the RHS
how do I go from left to right
?
we need some context bro for this exercice
okay bro
I will show you everything
I almost done
so im doing it in latex
im gonna send u the link
do you have latex?
so i can send it yo you
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I got the answer but the problem says to check answers mentally
How would I check answers from logarithms without a calculator?
You can plug it yourself in it
So long as you are aware that 3³=27
To get log(27) say
and make sure it works
But you've essentially already done the work
I remember my teacher warned us that logs can’t be negative
But in some cases they can?
I sort of forgot why
The input of a log cannot be negative. The output of a log can be negative.
Both x's here yield a positive input
(unless you are dealing with complex numbers)
So how would I know what negatives are good and bad?
I’m starting to understand but I think I just need an example
Because so far all the equations to me look the same
All input must be positive. No restriction on output.
$\log 5$ is okay, $\log (-1)$ is not
SWR
$\log_{-1} 1$ is not either, nor is $\log_{-1} (-1)$
SWR
If a certain x requires you to calculate the log of a negative value, then then that x is invalid because you cannot calculate a negative log
Ohh I think I understand now
The answers with negative being a solution are the ones with = number
And the ones with negatives not being solution are the ones with negatives in the log question itself
yes
@neon iron Has your question been resolved?
@neon iron Has your question been resolved?
@neon iron Has your question been resolved?
They said that on the final logs weren’t always going to take the positive
They would take the negative of a input in some scenarios
It is likely that your teacher believes that because there are questions such as $(-2)^x=-8$ gives $x=3$ that something like $\log_{-2} (-8)=3$ but for reasons that are harder to all explain here thats not strictly true.
Talos Teaches
At least its not possible without taking complex numbers into account. But this may be what they want
I believe so
@neon iron Has your question been resolved?
How is it not strictly true?
Majority of the times on tests and such it will not apply tho right
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How can I simplify $\ln\left(\sqrt{e^{x}}\right)$ ? I know ln(e) = 1 but does that apply through square roots as well?
water beam
numerous ways
you can either recognize ln(sqrt(x)) = 1/2 ln(x)
or that sqrt(e^x) = e^(x/2)
okay i did the algebra
you mean 0.5(x) right? ln(e^x)=x
I think so, but I could be wrong
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my x is not op's x
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First of all sorry for my broken English, I need help with a mathematical finance problem. Can someone help me?
send the question
A coupon bond is listed on the market with 9 months of residual life, half-yearly coupons at 6% per year, redemption value 105, market value 103,967. Calculate h(0;9/12)
I was already given h(0;3/12)= 0,0235
h(0;6/12)= 0,0254
h(0;1)= 0,0288
@honest shard Has your question been resolved?
no
@honest shard Has your question been resolved?
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Not a task i need help with, but does anyone of you have a summary pdf or similar for all hypothesis tests, with the formulas etc
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Could someone help me understand how i utilize the trig functions ?
Merineth
I'd do: $x = sin^{-1}\frac12$
$x = \sin^{-1} \left( \frac{1}{2} \right)$
How do i utilize my table properly to translate arcsin(1/2) into an actual value
gonna need to look up 1/2 in the sin column in your table.
I don't really understand the difference between if. x = sin(1/2) and x = sin^-1(1/2)
if. x = sin(1/2)
sin(1/2) means sin(0.5 radians)
the input of the sin function is to be interpreted as an angle
Okay so whenever i'm given arcsin, arccos etc i should interpret that using the table by converting it into Radians?
So arcsin(1/2) = pi/6 ?
yeah
and if i'm given 30* it could be interpreted as cos(sqrt(3/2)), sin(1/2) or tan(1/sqrt3)
?
Yeah, idk how to make the degree sign
no it would be the arccos, arcsin and arctan
the inverse functions tell you the angle
Merineth
I can't take arcsin or arccos on either side as it seems redundant
However if i assume the values of x
Idk tbh
Just a tiny little hint is what i need
That doesn't have much to do with inverse functions
No, i'm on trig now :3
cos(2x) = 1 - 2sin(x)^2
Merineth
That's just a quadratic
Can i use quadratic on it?
Of course
I was thinking it but what is p in this case?
p?
tf is that
Match this with your thing
But i'm not sure what p is
1
What's x here?
so sin(x) is my x
yuh
Right
Aah okay one moment then
if ur using this then please seek help
\pm
Merineth
$-\frac12 \pm\frac{\sqrt{5}}{2}$
Nel
That's your sin(x)
?
I assume i have to answer in Rad?
Probably yeah
$\frac{pi}{6} \pm \frac{\sqrt{5}}{2}$
Merineth
I don't know what you're doing but it's wrong
um did you have $\cos^2(x)$ or $\cos(2x)$
ℝαμΩℕωⅤ
you seemed to have conflated the two
I missed this, it's wrong
Merineth
Sure
Merineth
Definitely
,rotate
((1/2)/2)^2 = 1/16, not 1/8
Yeah, 4^2 = 16

Merineth
$sin(x)_1 = \frac12 \
sin(x)_2 = -1$
Right, 1/2
lol yea 💀
Merineth
So we get two answers
$x_1 = \frac{\pi}{6} + 2\pi k \
x_2 = -\frac{\pi}{2} + 2\pi k$
Merineth
Right
,w solve the equation sinx = cos2x
uh i assume that is corect?
Not sure let me graph it
🫶🏻
Right so sin(x) = 1/2 has two solution in [0,2pi)
Unfortunately your table only gives you one
aah oki
But sin(x) = sin(pi-x)
I think it's time to cook some food tho before i make another 4^2 = 8 mistake 🙂
Ok well basically you need both pi/6 + 2pik (your x_1) and pi-pi/6 + 2pik
(or 5pi/6 + 2pik)
That's the third answer from WA
And you can combine all three into one single answer that your material gives
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In case you want to play around with a graph:
https://www.desmos.com/calculator/gynefdla1y
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x^3-18x-35=0 i want to know about its roots
Should I use descartes rule?
depends on what you want to know about its roots
i'd try rational root theorem and seeing if there are any rational roots first
