#help-26

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drifting swift
#

ln(7) is just a number

#

so the integral of ln(7) dx is?

fathom sinew
#

then integral of ln(7) dx is ln(7)x

#

wa

drifting swift
#

yes

fathom sinew
#

my bad i was thinking that it was possible to turn -1/ln(7) to -ln^1(7)

#

oh

#

ok

#

so (-1/ln(7))u + c

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(4-7^x/ln(7)) + C

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$^{1}/_{2}$

thorny flameBOT
#

(っ◔◡◔)っ 🤍 cosygod 🤍

drifting swift
#

$\frac{1}{2}$

thorny flameBOT
fathom sinew
#

oh thanks

#

$\frac{4-7^{x}}{\ln(7)}$

thorny flameBOT
#

(っ◔◡◔)っ 🤍 cosygod 🤍

fathom sinew
#

alr thank u very much

#

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topaz sinewBOT
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jade wharf
#

the line y=2x-3 is reflected about the line y=x. find the equation of the reflected line

jade wharf
#

not sure how to do this at all

merry mason
#

Change y and x position

coarse tusk
#

no...

mental basin
#

nevermind I misread that

coarse tusk
#

for reflection about the line y=x there is a shortcut (as Calamity mentioned)
You can just replace y for x and x for y in your equation

jade wharf
coarse tusk
mental basin
#

x=2y-3 <=> x+3=2y >=> y=(1/2)(x+3)

merry mason
#

In this particular question it's possible to isolate y

jade wharf
#

yeah i got it

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(x+3)/2 = y

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thanks

mental basin
coarse tusk
coarse tusk
#

there's no way to isolate y

haughty mural
#

And maybe for some background info:

We can find the point at which our line and the line y=x intersect. We also know that the point (0,-3) will be at (-3,0) after the reflection. From these points we could also get the equation.

mental basin
coarse tusk
merry mason
coarse tusk
#

because a singular x value can have more than one (in this case, infinitely many) values of y associated with it

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meaning y is not a function of x

merry mason
#

I see

coarse tusk
#

,w graph x=sin(y)

thorny flameBOT
mental basin
coarse tusk
#

oh well wolframalpha just switched the x and y axes

cursive patrol
coarse tusk
#

lmaoo

cursive patrol
coarse tusk
jade wharf
#

take this elsewhere

#

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topaz sinewBOT
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fickle sorrel
#

Prove P(A∪B) = 1 - P(A'⋂B'), when A and B are arbitrary events.

drifting swift
#

what does + mean

fickle sorrel
fickle sorrel
#

I'm still not sure what comprises a complete proof, in this example.

drifting swift
#

if you mean union them why not write the union symbol

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anyway (A u B)' = A' n B' is the crux of the proof...

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if there are extra things your professor wants you to say in the proof then that's something to ask them about not us

fickle sorrel
fickle sorrel
drifting swift
#

it's fine yeah

fickle sorrel
topaz sinewBOT
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worn aurora
topaz sinewBOT
worn aurora
#

hey

#

what law should i use to get the angle?

topaz sinewBOT
#

@worn aurora Has your question been resolved?

chilly walrus
worn aurora
#

yeah

chilly walrus
#

they are the same for rotational motion

#

use the last one, where instead of s you get theta (angle), instead of u it's omega_i and instead of v it's omega_f

worn aurora
#

alright thanks lots

#

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calm gyro
#

Can someone help with this?

topaz sinewBOT
rose sierra
#

Assume for the sake of contradiction that there only exists n primes

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but then show that with these n primes you can make an n+1th prime

calm gyro
#

How about assuming to the contrary that there are n number of primes listed?

calm gyro
#

Like prove that there are more than n prime numbers for all natural numbers?

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oh wait nvm

calm gyro
cursive thorn
calm gyro
#

Thanks

cursive thorn
#

maybe you need some form of induction though, since you only prove k + 1 primes exist

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actually, nvm

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that's the contradiction

calm gyro
#

Yea

cursive thorn
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maybe specify that those k are supposed to be the only ones

calm gyro
#

Ok

calm gyro
cursive thorn
#

You haven't explicitly stated in your assumption that the primes p1, ..., pk are the only ones

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you just said that they were primes

calm gyro
#

Oh yea I’ll fix that

#

How is this now?

calm gyro
topaz sinewBOT
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half sage
#

is PSL(2, C) an abelian group or no? sadcat

keen venture
#

Looking it up, no.

half sage
keen venture
#

Well, that's necessary for sure

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It's not so obvious though with PSL

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What's your definition of PSL(2,C)? We can work with that

half sage
#

i want to prove that there is no isomorphism, because C^3 is abelian but PSL(2, C) isn't

topaz sinewBOT
#

@half sage Has your question been resolved?

half sage
#

@keen venture can you help please catlove

odd pagoda
#

you could just try multiplying two random elements in both orders. you likely wont get the same results

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exotic arch
#

If S is relation defined this way:

topaz sinewBOT
drifting swift
#

в кое множество живеят x и y?

exotic arch
#

истинските числа

drifting swift
#

тоест реални?

exotic arch
#

да

drifting swift
#

добре

exotic arch
#

трябва да се докаже, че е релация на еквивалентност

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за рефлексивност получавам просто x-x=0

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0 е в целите числа

drifting swift
#

точно така

exotic arch
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за симетричност имаме (x-y) и (y-x)

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трябва просто да ги прибавя ли?

drifting swift
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ами не, разсъждение няма да върви така

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имаш, че x - y ∈ Z, и искаш да докажеш, че y - x ∈ Z

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това следва директно от твърдението y - x = -(x-y)

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защото -1 е цяло и Z е затворено относно умножение

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или пък за всеки елемент има обратен по сложение, ако искаш

exotic arch
#

Да, а за транзитивност

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което е

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(x, y) ∈ R & (y, z) ∈ R -> (x, z) ∈ R

drifting swift
#

S

exotic arch
#

да, моя грешка

#

S

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просто го тълкувах по традиционната дефиниция

drifting swift
#

знае се, че x-y и y-z са цели, и искаме да докажем, че и x-z е цяло

exotic arch
#

момент

#

как знаем, че y-z е цяло? просто по дефиниция го допускаме ли?

drifting swift
#

точно така

#

в рамките на доказателството

exotic arch
#

ясно

#

тогава

#

това ще помогне ли?

#

с идеята, че утре имам контролно

#

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topaz sinewBOT
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muted wadi
#

How to solve this guys? I tried pretty hard

topaz sinewBOT
normal iris
#

either 4 or 14

muted wadi
normal iris
#

so i assumed thats the pattern-

topaz sinewBOT
#

@muted wadi Has your question been resolved?

cursive patrol
#

i hate problems like these

cursive patrol
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tame plaza
#

Q: Integration

topaz sinewBOT
tame plaza
#
$$
a_n=\int^{1}_{-1}\;(1-t^2)\cos(\pi n t)\;dt
$$
#

Struggling to see how this evaluates to the highlighted part in this image:

thorny flameBOT
loud oasis
#

integration by parts

tame plaza
#

That's disgusting. Thank you <3

#

Didn't see that at first

loud oasis
#

& used properties of even functions to rewrite the bounds

tame plaza
#

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worn raven
#

not sure where to start

topaz sinewBOT
rigid ivy
worn raven
#

yes

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e.g y^2= 2ydy/dx

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just like how am i differentiating f"(x) and f"(x)^2

raven sparrow
#

Just like f''(x) = (f'(x))'.

worn raven
#

u=y v=f"(x)?

raven sparrow
#

You can give them other names if it helps : say you have y = f(x), y' = g(x) and y'' = h(x).

Now your equation is f(x)•h(x) + 2(g(x))^2 + 2•f(x) = 0

#

Can you take the derivative of that using the chain rule and product rule when necessary?

worn raven
#

soo

#

u=y v=h(x)
= h(x)dy/dx+yh*(x)

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start represents a dash lol

raven sparrow
#

Ok that's the first term

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But it's already useful since the derivative of h(x) is f'''(x) isn't it?

worn raven
#

yes?

raven sparrow
#

So now do that with the other terms to get a new equation, and this one will involve h'(x), which you want to solve for.

worn raven
#

soo

#

h(x)dy/dx+yh*(x)+4g(x)+2dy/dx

topaz sinewBOT
#

@worn raven Has your question been resolved?

raven sparrow
#

You didn't do the chain rule properly for g(x).

#

But yeah

#

And then you can isolate h' and replace the functions with their actual expressions as derivatives of y.

worn raven
raven sparrow
#

You forgot to multiply by g'

worn raven
#

ye but it wants dy^3/dx^3?

raven sparrow
#

That's h'

worn raven
#

so whats h(x) dy^2/dx^2?

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h(x)dy/dx+yh*(x)+4g(x)g'(x)+2dy/dx

raven sparrow
#

We used those placeholder functions to help with realizing that those are just functions of x you can take the derivative of. Now you have (something) = 0 and you should isolate for h'(x)

worn raven
#

ye i still dont really get it lol

raven sparrow
#

Solve for h' in it

#

h'(x) = d3y/dx^3

worn raven
#

okay so g(x) is what y? and g^x is dy/ax? h^x is dy^2/dx^2

raven sparrow
#

f(x) = y. g(x) = dy/dx = f'(x) , h(x) = d2y/dy^2 = g'(x)

worn raven
#

to make itr easier for me i changed it back

#

to like dy/dx and studff

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right

raven sparrow
#

Yeah that works

#

It was just to try and help with chain rule and stuff

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But it doesn't matter you could've done it like that to begin with 👍

worn raven
#

i got
y(d^3y/dx^3)+dy/dx(d^2y+4d^2y/dx^2 +2)=0

worn raven
#

so my brain was like brrr

raven sparrow
worn raven
#

therefore

#

d^3y/dx^3=-dy(..........)/y?

raven sparrow
#

Yeah

worn raven
#

yipppe

raven sparrow
#

And now it works out since everything is in terms of y, y' and y''

worn raven
#

an hour for part a now part b LMAO

raven sparrow
#

Oh well

worn raven
#

think i can figure this out just sub in numbers

raven sparrow
#

Yeah essentially. You can plug values into the Taylor series

worn raven
worn raven
raven sparrow
worn raven
#

for part b what do i do when i found d^2y/dx^2

topaz sinewBOT
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orchid jetty
#

How do I get PY

topaz sinewBOT
orchid jetty
shadow shadow
#

Is wp a+12?

orchid jetty
#

Dunno

shadow shadow
#

Diagonal of parallelogram bisect each other

#

Use that

orchid jetty
#

Ok

#

It worked thanks

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neon iron
topaz sinewBOT
neon iron
#

nvm i got it

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.close

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pearl fog
#

Using the digits 1,2,3 and 4, without
repeat, one can form distinct 3-digit
numbers.
What is the average of all possible
numbers formed?
(A) 200
(B) 225.5
(C) 275
(D) 277.5
(E) None of the above

pearl fog
#

how would you do this non manually?

cursive patrol
pearl fog
#

ooh

#

thanks

cursive patrol
#

welcome

pearl fog
#

lemme see if i have another question wait

#

how bout this

cursive patrol
#

sum of coefficients of polynomial f(x) is f(1)

pearl fog
#

oh

#

never heard that before, good to know

cursive patrol
#

yep

pearl fog
#

how bout this

#

got 2 things
$$\frac{a+b}{ab}=\frac{5}{a-b}$$
$$(\frac{a^2+b^2}{ab})^2$$

thorny flameBOT
#

Skill_Issue

pearl fog
#

like if i tinker around i can get
$\frac{625}{(a-b)^2}-\frac{100}{a-b}+4$ for the lower equation but idk where to go from there

thorny flameBOT
#

Skill_Issue

topaz sinewBOT
#

@pearl fog Has your question been resolved?

cursive patrol
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rapid marten
#

Erm i dont really need help

#

just wondering what the process would be from changing from d/dx^2 to d/dy^2

#

knowing the relation between y and x

gray ridge
#

it's chain rule

rapid marten
#

so use the chain rule of y = x/l twice?

gray ridge
#

yep

rapid marten
#

thx

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merry portal
#

“Find the length of AD”

topaz sinewBOT
merry portal
#

Idk why I can’t do this is seems simple but idk what to do

ivory sorrel
#

I'm pretty sure you need more information

merry portal
#

Oh im so dumb

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The rest was next to it but I thought it was 2 questions

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neon iron
#

Hi, I'd just like to get some help understanding the Gaussian Elimination process shown in the image shown :>
I'm specifically confused about the process that went into turning the numbers into zeroes

topaz sinewBOT
#

@neon iron Has your question been resolved?

main shale
#

in rows 2 and 3, the first column has value 2, so dividing those rows by 2 then multiplying by 3 gives a value of 3 in the first column

#

you can then subtract row 1 from rows 2 and 3, which gives zero

#

then it's the same thing for the second column

#

you could have also just immediately subtracted 2/3 * row 1 from row 2 and 3 to get zeros in the first column

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drowsy root
#

i need help with tetration, im not understanding this topic at all

terse abyss
drowsy root
#

im stuck w the basics, take 2 tetrated to 3 for example

#

i don't understand how tetration works

shut belfry
#

((((2)^2)^2)^2)

drowsy root
#

so 2¹⁶?

#

should that not be 2 tetrated to 2?

shut belfry
#

i mesed up

drowsy root
#

it's okay 😭🙏

shut belfry
drowsy root
#

the answer directly? or 2 raised to the power 16?

shut belfry
#

Ok its messed up

#

I am explaining the correct one

#

rn

#

2 tetrated 2 is just 2 ^2

#

its 4

#

@drowsy root

drowsy root
shut belfry
#

2 tetrated 3

#

is 16

#

or 2^4

drowsy root
shut belfry
#

I took 2 tetrated 4

drowsy root
# shut belfry yea

what's the pattern? when someone mentions tetrated to n, do i write power of the number n-1 times?

shut belfry
#

yea

#

if 2

#

then

#

2^2

drowsy root
#

like, 3 tetrated to 2
will be 3^2^2

shut belfry
#

if 3 then

#

no

drowsy root
#

bro-

#

oh

#

I GET IT

shut belfry
#

3^3

#

4 tetrated 2

drowsy root
#

so 4 tetrated to 3 will be

shut belfry
#

4^4^4

drowsy root
#

4^4^4

drowsy root
shut belfry
#

yes

drowsy root
#

4 tetrated to 2 should be 4^4?

#

correct?

shut belfry
#

yes

drowsy root
#

ah i see

#

what about pentation

#

i get why they don't teach ts in high school ☠️

shut belfry
drowsy root
#

if i mention 3 tetrated to 3

shut belfry
#

Pentation is like 2 pentated 3 would be

#

um

#

65536

shut belfry
#

you would certainly need a calculator

#

for pentation

drowsy root
#

how'd u even do it-☠️

shut belfry
#

Calculator

drowsy root
shut belfry
#

Yeah

drowsy root
shut belfry
#

and pentation doesnt come in school

drowsy root
drowsy root
topaz sinewBOT
#

@drowsy root Has your question been resolved?

topaz sinewBOT
#

@drowsy root Has your question been resolved?

drowsy root
#

no

topaz sinewBOT
#

@drowsy root Has your question been resolved?

drowsy root
#

.close

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calm gyro
#

Can someone help with this?

topaz sinewBOT
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manic ravine
#

Hi, I need help studying for physics, the problem says, 2 blocks, with masses m1=.3kg and m2=.5kg, are connected by a string and lie on a frictionless tabletop. A force F = 5.5N is applied to block m2. I am good with everything except finding the tension, I know how to do it but dont understand why i have to do it like that. The way I got the answer was doing .3 * the acceleration, but i still dont get why i am doing said calculation.

manic ravine
topaz sinewBOT
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@dark pond Has your question been resolved?

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@dark pond Has your question been resolved?

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@dark pond Has your question been resolved?

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forest quartz
#

The gradient of the curve y=ax^2+bx at the point (3,-3) is 5. Find the value of a and the value of b.

vernal matrix
#

That's two equations you have there - do you know how to get them?

forest quartz
#

I found the derivative of the equation of the curve to be dy/dx=2ax+b

vernal matrix
#

Yep SCgoodjob2

#

So you have y and dy/dx

#

For a particular x value, you know the value of both of those

forest quartz
#

The only x value that was given is 3

vernal matrix
#

Yep, so then what does that give you as y and dy/dx?

forest quartz
#

Sorry im confused

#

Are you saying to plug in x into the normal and derivative equations?

vernal matrix
forest quartz
#

I see

#

So in the original equation it becomes -3=a(3)^2+b(3)

#

And in the derivative it becomes 5=2a(3)+b

#

@vernal matrix so the original equation becomes -3=9a+3b and derivative becomes 5=6a+b?

forest quartz
#

Woo hoo!

#

So this is exactly where I got stuck. I have no idea what to do now 😭.

#

@vernal matrix would I have to somehow get them equal to eachother?

vernal matrix
#

You could e.g. isolate b, say out of the second equation, then substitute that into the first one

forest quartz
#

I see, so b=5-6a

#

And then put it into the first one so -3=9a+3(5-6a)

vernal matrix
#

Yep SCgoodjob2 then can work with that then find b

#

It's just a pair of linear simeultaneous equations of course SCCOZY

forest quartz
#

I got a to equal 2

#

OMG

#

I finally understand the problem

#

Only took me almost 2 hours

vernal matrix
#

,w 9a + 3b = -3, 6a + b = 5

vernal matrix
vernal matrix
forest quartz
#

Thank youuuuu

#

How do I close this so someone else can use it?

vernal matrix
#

Just type .close and it will do it for you happyCat

forest quartz
#

Alright tysm for the help!

#

.close

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#
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thorny bison
topaz sinewBOT
thorny bison
#

how would i go about doing this ?

#

would i first find ab

#

which is m

#

then find c m ?

#

<@&286206848099549185>

#

that didnt work btw XD

outer delta
#

AB is the entire length of the base you would just need M which is the midpoint of AB, so use the Midpoint formula

thorny bison
#

ye a+b/2 ??

outer delta
#

yes?

thorny bison
#

that no work

#

unless i somehow did the wrong numbers

outer delta
#

you would do that for each coordinate though so x = (2 + 2)/2, y = (2 + 4)/2, z = (0 + 0)/2

thorny bison
#

2,2,9 + 2,4,0 is (4,6,0 )/2 is 2 ,3,0

#

so thats M

outer delta
#

yes

thorny bison
#

but cm i tried doing (M+C)/2

#

or do i do something diffrent

outer delta
#

You shouldn't need to find cm

#

find the distance between C and M

#

distance for each coordinate

thorny bison
#

so i do c-m?

outer delta
#

I believe so yes

thorny bison
#

nice

#

that was right

#

Find the vector from C to the point that lies​ two-thirds of the way from C to M on the median CM.

#

now i do

#

c+m /3?

#

well that wasnt quite right

outer delta
#

you should just be able to take what you got for the original question and multiply it by 2/3

thorny bison
#

1,2,-2 * 2/3?

outer delta
#

yes

thorny bison
#

well that worked lol

#

Find the coordinates of the point in which the medians of ABC intersect. This point is the​ plate's center of mass.

#

now is this finally cm XD

outer delta
#

I would assume so

#

probably stands for Center of Mass

thorny bison
#

and thats c+m / 2 ?

outer delta
#

I don't think so

#

you can try

thorny bison
#

yea thats wrong lol

outer delta
#

but I would do what you did for question 1 and apply it to midpoint of AC then find vector to B
then, midpoint of BC and vector to A
then find out where these all intersect and that gives you the center of mass

#

you could also try the avg method, (avg x, avg y, avg z) = midpoint

#

I mean center of mass

thorny bison
#

so for that would i just take all x's add them upp divide by 3 sa,e fpr y and z ?

outer delta
#

only using the vertexes coordinates

outer delta
thorny bison
#

so 1+2+2 = 5/3x 2+4+1=7/3y 0+0+2/3 =2/3z

#

ay it worked

#

thx so much for the help frfr now i can finally go to bed lol

outer delta
#

good night then 0ashcry , if you have no further questions, use .close

thorny bison
#

.close

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#
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heavy cove
#

I can't figure out what I did wrong here...

topaz sinewBOT
heavy cove
#

y(1) = 5 holds true here

#

c = 15^18/18-1 btw

#

and the integral of (1 + x) / x is just ln|x|+x, no?

ruby mural
#

Yeah

#

What equation did you get after integrating both sides exactly?

heavy cove
#

and C = 5^18/18-1 because y(1) = 5

#

any clue what I did wrong 😭

ruby mural
#

Seems right

ruby mural
heavy cove
ruby mural
#

Yes but you said it was 5¹⁸/18

#

-1

heavy cove
#

oh my fucking god

heavy cove
ruby mural
#

Np

heavy cove
#

yeah I got it correct now

ruby mural
#

Nice

heavy cove
#

we need to build an AI

#

that spots silly mistakes

ruby mural
#

Hmm

topaz sinewBOT
#

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neon iron
topaz sinewBOT
neon iron
#

I tried constructing sectors to get radius and also construction of another circle with this chord as diameter. Didn't work

#

<@&286206848099549185>

cursive patrol
#

you want to make use of angles here... specifically, the angle subtended by an arc is proportional to the arc length

neon iron
cursive patrol
#

you want to relate everything in terms of the same angle

#

because you are given the arc lengths (and therefore their ratios)

#

so you know the angles will be in the same ratio

cursive patrol
topaz sinewBOT
#

@fickle pendant Has your question been resolved?

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languid blaze
#

how do i solve this?

topaz sinewBOT
languid blaze
#

please ping me

long stirrup
#

@languid blazehint: 3^n

languid blaze
long stirrup
#

3^n counts ways to make 2 subsets that don't inersect

languid blaze
long stirrup
#

for each element you put it in A, or B or neither

languid blaze
#

ohh

#

would that be the final answer?

long stirrup
#

not telling

languid blaze
#

4^n - 3^n

#

becacuse there are 4^n possible ordered pairs

#

and since we need want to find the number of ordered pairs that have an intersection we just substract the amount that dont have an intersection from the total

long stirrup
#

makes sense to me

languid blaze
#

tysm

#

this gives me a much better understanding of combinatorics

topaz sinewBOT
#

@languid blaze Has your question been resolved?

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neon iron
#

How the hell do I solve this number 7. And the answer is 176ft, how do I get there at all

little ferry
#

,rotate

thorny flameBOT
little ferry
#

i assume it's a similar triangle in which the longest side is 80

#

8/16/20 ~ x/y/80

neon iron
#

OHHHH

#

Ok let me get the paper out, brb

little ferry
#

the question is written in a very difficult way to understand tho sully

neon iron
#

Yeah 😭

#

Why tho

#

I found out I had to use scaler

#

Done

#

Thanks

#

Ushdnwndjs

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#

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topaz sinewBOT
thorny flameBOT
#

Why am. I here
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

ivory sorrel
#

could I just have a hint

#

like what substitution should I perform?

#

I was thinking maybe y/x=u?

#

would that work?

#

or is there another method?

topaz sinewBOT
#
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ivory sorrel
#

.close

topaz sinewBOT
#
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neon iron
#

need help

topaz sinewBOT
neon iron
#

with coordinate geometry

#

is the 3rd question of the exercise and the question from the other pic the same?

#

because i think they're the same but they have different answer so idk what's happening

#

sorry for the bad quality

#

also ping me please

topaz sinewBOT
#

@neon iron Has your question been resolved?

ornate magnet
#

@neon iron they are different

neon iron
#

yea ok how

#

thanks for replying

#

@ornate magnet

ornate magnet
neon iron
#

,rotate

thorny flameBOT
neon iron
#

hmm

#

yea

#

so i have to T^2=SS_1 for the second question

#

and T=S_1 for the exercise one

#

ok yea i thought so

#

thanks for helping @ornate magnet

#

.close

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#
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silent mortar
topaz sinewBOT
silent mortar
#

someone please help

#

L and U matrices are correct

#

for some reason the x_1 and x_2 are not

#

ping me if you help

#

<@&286206848099549185>

topaz sinewBOT
#

@silent mortar Has your question been resolved?

split onyx
#

hi im new and i have a question so when a twine has a strength of 4 tex, which means 1 km of this thread weighs 4 grams. Calculate the diameter of the thread in mm if the material density is 1.44 g / 2 square centimeters?

silent mortar
#

channel is in use

#

.close

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#
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silent mortar
topaz sinewBOT
silent mortar
#

ive went through the formulas a few times and looked them up and the selections i have now all seem to be true but im getting the answer wrong

#

D and E are both false due to commutativity

#

I'm iffy about A

#

B and C are both correct I'm pretty sure, I also tried submitting just B and C and that was wrong as well

worthy storm
#

C is not true, there's a very easy counterexample

#

A is fine, can you say what the inverse of A^3 is?

silent mortar
worthy storm
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#

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brittle void
topaz sinewBOT
tawdry dagger
#

you’re moving it one to the right

#

so its x = 1

#

@brittle void

brittle void
#

wait but

#

i have a- thats -2

#

c is 0

#

but whats b

tawdry dagger
#

?

#

oh

#

is b the constant after x

#

in the brackets?

brittle void
#

i dunno thats the thing

tawdry dagger
#

do you know what that graph looks like

brittle void
#

thats the formula

#

nope i dont

tawdry dagger
#

not for the one you have

#

the one you have given is in a different shape than yours

brittle void
#

oh.

#

crap

tawdry dagger
#

than $ax^2+bx+c$

thorny flameBOT
#

DerTheo

brittle void
#

thats why it was weird.

tawdry dagger
#

you can write that form as
$a(x-b)^2+c$

brittle void
#

thank you so much!

#

.close

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thorny flameBOT
#

DerTheo

topaz sinewBOT
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wild pawn
#

ik this is math

topaz sinewBOT
wild pawn
#

bu tlike

#

quick question

#

will #3 have a reaction?

#

cuz if theres 2 aqueous products it doesnt have reaction

#

my teacher said theres no reaction but other people said there is a reaction

topaz sinewBOT
#

@wild pawn Has your question been resolved?

wild pawn
#

<@&286206848099549185>

#

do i break up water if it is a product

#

in a net ionic equations

sweet shard
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neon iron
#

Hello anybody can explain me the question and how to get it?

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proud hinge
topaz sinewBOT
proud hinge
#

How do i get this guys

grim sable
#

can you type it out

#

I can't read your handwriting, sorry

thorny flameBOT
#

Yousef

proud hinge
grim sable
#

I don't know whatever topic this is srry

proud hinge
#

I just wanna know how I can simplify this expression

#

wait

thorny flameBOT
#

Yousef
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rigid coyote
#

$\frac{1}{r_{\pi_3}} + SC_{\pi_3} = 1 - \frac{S}{P_1}$

thorny flameBOT
#

mehdi_moulati

rigid coyote
#

like this @proud hinge ?

proud hinge
#

yes but can you write my p1 inside

rigid coyote
#

$\frac{1}{r_{\pi3}} + SC_{\pi_3} = 1 - \frac{S}{-\frac{1}{r_{\pi3} C{\pi_3}}}$

thorny flameBOT
#

mehdi_moulati

proud hinge
#

like this bro

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so how do i get the RHS

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how do I go from left to right

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?

rigid coyote
#

we need some context bro for this exercice

proud hinge
#

okay bro

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I will show you everything

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I almost done

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so im doing it in latex

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im gonna send u the link

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do you have latex?

#

so i can send it yo you

#

,close

#

.close

topaz sinewBOT
#
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neon iron
#

I got the answer but the problem says to check answers mentally

neon iron
#

How would I check answers from logarithms without a calculator?

raven sparrow
#

You can plug it yourself in it

rigid ivy
#

So long as you are aware that 3³=27

raven sparrow
#

To get log(27) say

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and make sure it works

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But you've essentially already done the work

neon iron
#

I remember my teacher warned us that logs can’t be negative

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But in some cases they can?

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I sort of forgot why

rigid ivy
raven sparrow
#

Both x's here yield a positive input

rigid ivy
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(unless you are dealing with complex numbers)

neon iron
#

I’m starting to understand but I think I just need an example

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Because so far all the equations to me look the same

rigid ivy
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$\log 5$ is okay, $\log (-1)$ is not

thorny flameBOT
rigid ivy
#

$\log_{-1} 1$ is not either, nor is $\log_{-1} (-1)$

thorny flameBOT
neon iron
#

Ok

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But why are some answers not solutions?

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If they are negative

rigid ivy
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If a certain x requires you to calculate the log of a negative value, then then that x is invalid because you cannot calculate a negative log

neon iron
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Ohh I think I understand now

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The answers with negative being a solution are the ones with = number

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And the ones with negatives not being solution are the ones with negatives in the log question itself

rigid ivy
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yes

neon iron
#

Ok

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I think my teacher said there was a caveat

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Where the answer could be negative

topaz sinewBOT
#

@neon iron Has your question been resolved?

neon iron
#

I’m trying to remember the caveat

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Where the inputs of logs COULD be negative

topaz sinewBOT
#

@neon iron Has your question been resolved?

topaz sinewBOT
#

@neon iron Has your question been resolved?

neon iron
#

They said that on the final logs weren’t always going to take the positive

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They would take the negative of a input in some scenarios

thorn scroll
#

It is likely that your teacher believes that because there are questions such as $(-2)^x=-8$ gives $x=3$ that something like $\log_{-2} (-8)=3$ but for reasons that are harder to all explain here thats not strictly true.

thorny flameBOT
#

Talos Teaches

thorn scroll
neon iron
topaz sinewBOT
#

@neon iron Has your question been resolved?

neon iron
#

Majority of the times on tests and such it will not apply tho right

neon iron
#

.close

topaz sinewBOT
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lucid junco
#

How can I simplify $\ln\left(\sqrt{e^{x}}\right)$ ? I know ln(e) = 1 but does that apply through square roots as well?

thorny flameBOT
#

water beam

ivory sorrel
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It's ln((e^x)^1/2)

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and log(a^b)=blog(a)

drifting swift
#

numerous ways

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you can either recognize ln(sqrt(x)) = 1/2 ln(x)

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or that sqrt(e^x) = e^(x/2)

lucid junco
#

okay i did the algebra

ivory sorrel
lucid junco
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and got x/2

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as my answer

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is that right?

ivory sorrel
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I think so, but I could be wrong

lucid junco
#

okay i checked with desmos its right

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drifting swift
topaz sinewBOT
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honest shard
#

First of all sorry for my broken English, I need help with a mathematical finance problem. Can someone help me?

honest shard
#

A coupon bond is listed on the market with 9 months of residual life, half-yearly coupons at 6% per year, redemption value 105, market value 103,967. Calculate h(0;9/12)

I was already given h(0;3/12)= 0,0235
h(0;6/12)= 0,0254
h(0;1)= 0,0288

topaz sinewBOT
#

@honest shard Has your question been resolved?

honest shard
#

no

topaz sinewBOT
#

@honest shard Has your question been resolved?

honest shard
#

no

#

.close

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olive stream
#

Not a task i need help with, but does anyone of you have a summary pdf or similar for all hypothesis tests, with the formulas etc

olive stream
#

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topaz sinewBOT
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toxic aspen
#

Could someone help me understand how i utilize the trig functions ?

toxic aspen
#

For example

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If i was given: Solve $sinx = \frac12$

thorny flameBOT
#

Merineth

toxic aspen
#

I'd do: $x = sin^{-1}\frac12$

drifting swift
#

$x = \sin^{-1} \left( \frac{1}{2} \right)$

thorny flameBOT
#

Merineth

toxic aspen
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How do i utilize my table properly to translate arcsin(1/2) into an actual value

drifting swift
#

gonna need to look up 1/2 in the sin column in your table.

toxic aspen
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I don't really understand the difference between if. x = sin(1/2) and x = sin^-1(1/2)

drifting swift
#

if. x = sin(1/2)
sin(1/2) means sin(0.5 radians)

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the input of the sin function is to be interpreted as an angle

toxic aspen
#

Okay so whenever i'm given arcsin, arccos etc i should interpret that using the table by converting it into Radians?

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So arcsin(1/2) = pi/6 ?

modern rock
#

yeah

toxic aspen
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and if i'm given 30* it could be interpreted as cos(sqrt(3/2)), sin(1/2) or tan(1/sqrt3)

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?

modern rock
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explain?

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is that meant to be 30 degrees?

toxic aspen
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Yeah, idk how to make the degree sign

modern rock
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no it would be the arccos, arcsin and arctan

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the inverse functions tell you the angle

toxic aspen
#

What happens if i'm given

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Solve the equation : $sinx=cos2x$

thorny flameBOT
#

Merineth

toxic aspen
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I can't take arcsin or arccos on either side as it seems redundant

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However if i assume the values of x

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Idk tbh

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Just a tiny little hint is what i need

ruby tree
#

That doesn't have much to do with inverse functions

toxic aspen
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No, i'm on trig now :3

ruby tree
#

cos(2x) = 1 - 2sin(x)^2

toxic aspen
#

Aaah

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Yeah i got it to

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$sin^2(x) + sin(x) = 1$

thorny flameBOT
#

Merineth

toxic aspen
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But i'm not sure how to proceed

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i can't factor out sinx

ruby tree
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That's just a quadratic

toxic aspen
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Can i use quadratic on it?

ruby tree
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Of course

toxic aspen
#

I was thinking it but what is p in this case?

modern rock
#

p?

toxic aspen
modern rock
#

tf is that

ruby tree
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An odd way of writing the quadratic formula

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x^2 + px + q = 0

toxic aspen
#

Yeah

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Precisely

ruby tree
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Match this with your thing

toxic aspen
#

But i'm not sure what p is

modern rock
#

1

ruby tree
toxic aspen
#

so sin(x) is my x

modern rock
#

yuh

ruby tree
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Right

toxic aspen
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Aah okay one moment then

modern rock
toxic aspen
#

i got x to be

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$-1/2 \pm\sqrt{(5/4)}$

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(idk how to make +- with the bot

ruby tree
#

\pm

thorny flameBOT
#

Merineth

ruby tree
#

$-\frac12 \pm\frac{\sqrt{5}}{2}$

thorny flameBOT
ruby tree
#

That's your sin(x)

toxic aspen
#

ooh so

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i input that back into the equation?

ruby tree
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?

toxic aspen
#

I assume i have to answer in Rad?

ruby tree
#

Probably yeah

toxic aspen
#

$\frac{pi}{6} \pm \frac{\sqrt{5}}{2}$

thorny flameBOT
#

Merineth

toxic aspen
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Not sure how to express the last fraction

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since i don't have a table value

ruby tree
#

I don't know what you're doing but it's wrong

toxic aspen
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That seems to be the answer but

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Idk how to make the last fraction

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into 2kpi/3

restive inlet
#

um did you have $\cos^2(x)$ or $\cos(2x)$

thorny flameBOT
#

ℝαμΩℕωⅤ

toxic aspen
restive inlet
#

you seemed to have conflated the two

ruby tree
toxic aspen
#

i'll redo it

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Don't i get

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$2sin^2(x) + sin(x) -1 = 0$

thorny flameBOT
#

Merineth

ruby tree
#

Yes

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That's not what you had

toxic aspen
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Yeah my bad ;-;

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I divide everything by 2 now

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and then use the quadratic formula

ruby tree
#

Sure

toxic aspen
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I must be doing it wrong i think

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$-\frac14 \pm \sqrt{\frac58}$

thorny flameBOT
#

Merineth

ruby tree
toxic aspen
#

,rotate

thorny flameBOT
ruby tree
#

((1/2)/2)^2 = 1/16, not 1/8

toxic aspen
#

Really?

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I thought it was

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1/2)/2 = 1/4

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and then square them

ruby tree
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Yeah, 4^2 = 16

toxic aspen
#

I must be forgetting the priority rule

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OHGOD

ruby tree
toxic aspen
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Please forget that

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I'm hangry hahah

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okay so

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$-\frac14 \pm \frac34$

thorny flameBOT
#

Merineth

ruby tree
#

Yeah

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Simplify

toxic aspen
#

$sin(x)_1 = \frac12 \
sin(x)_2 = -1$

ruby tree
#

Right, 1/2

toxic aspen
#

lol yea 💀

thorny flameBOT
#

Merineth

toxic aspen
#

So we get two answers

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$x_1 = \frac{\pi}{6} + 2\pi k \
x_2 = -\frac{\pi}{2} + 2\pi k$

thorny flameBOT
#

Merineth

ruby tree
#

Right

toxic aspen
#

,w solve the equation sinx = cos2x

toxic aspen
#

uh i assume that is corect?

ruby tree
#

Ok so the first one is your x_2

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The second one is your x_1

toxic aspen
#

aaah yeah i see now

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wba 3rd?

ruby tree
#

Not sure let me graph it

toxic aspen
#

🫶🏻

ruby tree
#

Right so sin(x) = 1/2 has two solution in [0,2pi)

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Unfortunately your table only gives you one

toxic aspen
#

aah oki

ruby tree
#

But sin(x) = sin(pi-x)

toxic aspen
#

I think it's time to cook some food tho before i make another 4^2 = 8 mistake 🙂

ruby tree
#

Ok well basically you need both pi/6 + 2pik (your x_1) and pi-pi/6 + 2pik

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(or 5pi/6 + 2pik)

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That's the third answer from WA

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And you can combine all three into one single answer that your material gives

toxic aspen
#

Ah oki

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thanks Nel catlove

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see you tomorrow hopefully !

#

.close

topaz sinewBOT
#
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ruby tree
topaz sinewBOT
#
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real blaze
#

x^3-18x-35=0 i want to know about its roots

topaz sinewBOT
real blaze
#

Should I use descartes rule?

cursive patrol
#

depends on what you want to know about its roots

i'd try rational root theorem and seeing if there are any rational roots first

real blaze
#

How it works?

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Could you teach me in simple way?

cursive patrol
#

this image says it all i guess

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if a polynomial has a rational root, then the root must be of that form (could be positive or negative)