help-26

[mint perch]

Is x’(0)=50 and x(0)=6

Nvm I solved it

.close

[topaz sinew]

Channel closed

Closed by @mint perch

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[neon iron]

i was wondering if i can get help

<@&286206848099549185>

[topaz sinew]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[neon iron]

1

[floral aspen]

Ok

[neon iron]

i dont know if this is a lot to ask

but i need with 12 questions not all of it just one of each

for this one my friend said you can use the same formula to solve if you lnow how to do it for all of them

[floral aspen]

Alright so for the first equation you need to simplify it into 4(x^2 - 2x + 1 ) - 80 = 0

Then you need to multiply what's inside the brackets by 4

@neon iron Tell me when you're done with this two steps

[neon iron]

ok

would it be 4x+16=100

so i multipleied what was in the brackets (x-1)^2

then i added 20 to get rid of it and added to 80 and got 100

[topaz sinew]

@neon iron Has your question been resolved?

[floral aspen]

, tex It should look something like this $4x^2 - 8x - 96$

[thorny flame]

mouadbouh3

[floral aspen]

, tex because, $4(x - 1)(x - 1) - 20 - 80 = 0$ = $4(x^2 - 2x + 1) -100 = 0$ = $4x^2 - 8x + 4 -100 = 0$ = $4x^2 - 8x - 96$

[thorny flame]

mouadbouh3

[floral aspen]

@neon iron

[neon iron]

yea

[floral aspen]

The final step is to calculate delta

[neon iron]

wait let me get this straight where did the 8 come from

i know theres a sqaure

[floral aspen]

4 times -2x

[neon iron]

but when its like this #(#)^2

[floral aspen]

, tex $4x^2 + 4(-2x) + 4(1) -100 =0$

[thorny flame]

mouadbouh3

[floral aspen]

@neon iron

[neon iron]

ok i see

its

some what

where did all these others come from

i understand 4x and then 8x

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[floral aspen]

. reopen

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[nimble cargo]

I need help with integrals / antiderivatives:

having the following integral:∫ (−20x)tan(5x^2)dx what will it be its result?

I got || 2ln(∣cos(5x^2)∣) ||

[nimble cargo]

Can anyone help me here?

[serene helm]

Put 5x^2=t

10xdx=dt

-2tant dt

Use formula sir

Udr

IDR*

[abstract wadi]

Yeah you're right.

[neon iron]

Please solve this question

[bitter hemlock]

!occupied

[topaz sinew]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[neon iron]

Please solve this question

[bitter hemlock]

seems right

[nimble cargo]

Thanks y'all

.close

[topaz sinew]

Channel closed

Closed by @nimble cargo

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[potent linden]

how do i solve 10?

[keen venture]

Remainder theorem. These two numbers:

• f(-3)
• The remainder, when f is divided by (x + 3)

Are the same number

[neon iron]

@keen venture hey bro if it's okay to pin you but

Can you help me if possible

[sweet shard]

!noadvert

[topaz sinew]

Please do not advertise your help channel or thread in other parts of the server. There are many people who need help, and no one person can be prioritized over other people, so please patiently wait. Anyone who chooses to help you is a volunteer who is doing so out of their own kindness.

[potent linden]

wait really?

thats so cool

is there like some sort of proof or reason thats true?

[topaz sinew]

@potent linden Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[snow forum]

did I make a mistake here by not making everything 0=0

I only made 1 equation 0=0 is that enough information to know that the whole thing has many solution/ is consistent , dependent

or do I NEED to make everything 0=0
or can I just make one equation 0=0 and that is enough

like this

[topaz sinew]

@snow forum Has your question been resolved?

[torpid matrix]

one equation is enough. This is because you are left with 0 = 0 and x+2y= 4. There is one (real) equation and 2 variables so there are infinite solutions

however, if you had 3 equations and 2 variables, and you showed one of them is 0=0 that would NOT mean infinite solutions

infinite solutions arises when there are more variables than equations (free variables)

does this answer your question? @snow forum

[snow forum]

sry im here

[snow forum]

oh yeahh I forgot about 2 veriables one equation = infinite solution thing

thank you so much

okay I got it now

.close

[topaz sinew]

Channel closed

Closed by @snow forum

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[neon iron]

if a circle touches y axis at a distaanc eof 4 unit from the origin and cuts the x axis off an intercept of 6 unit, the can we say that its radius would be 3?

[neon iron]

no we cant actually wait

.close

[topaz sinew]

Channel closed

Closed by @proven dome

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

@sleek halo Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[neon iron]

Need help asap

[neon iron]

<@&286206848099549185>

@pearl peak

@cold wagon

[acoustic pecan]

!15m

[topaz sinew]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

@neon iron Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[eternal spoke]

How do i say " the n th root of a" in wolfram alpha

[knotty ledge]

a^(1/n)

[eternal spoke]

Oh thats right

Thanks

.close

[topaz sinew]

Channel closed

Closed by @eternal spoke

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sour egret]

Is my equation correct for this scenario?
1.25x + 2.50y < 10

[neon iron]

yeah

[sour egret]

Ok Ty

.close

[topaz sinew]

Channel closed

Closed by @sour egret

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[scarlet pivot]

if a function is on a closed bounded interval the end points of the function are not inflection points right?

[scarlet pivot]

.close

[topaz sinew]

Channel closed

Closed by @scarlet pivot

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[exotic bough]

so

Can someone help me understand what I'm doing wrong here?

Since this is the formula for finding area between curves

[frail fiber]

how did you get a and b?

[exotic bough]

Now that you ask I'm immediately recognizing that they're wrong, but from looking at the graphs and thinking those were the bounds of the shaded area

how should I get a and b?

[frail fiber]

what are a and b exactly?

[exotic bough]

usually bounds for the shaded area betwen two curves

but the curves in this problem intersect already

[frail fiber]

yea that is fine..but how will you identify the points beforehand

?

[exotic bough]

I'm not sure

[frail fiber]

for your question a and b are the points where the 2 curves y = 7x^2 and y = x^2 + 5 intersect

now find the points a and b

[exotic bough]

oh ok

got it

ty

.close

[topaz sinew]

Channel closed

Closed by @exotic bough

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[granite light]

I dont undertstand what he did there

[radiant tapir]

he rationalized the denominator then separated the two fractions

$\frac{1}{\sqrt{x}} \cdot \frac{\sqrt{x}}{\sqrt{x}} = \frac{\sqrt{x}}{(\sqrt{x})^2} = \frac{\sqrt{x}}{x}$

[thorny flame]

MellowDramaLlama

[radiant tapir]

so do that first, then you'll have this

$\frac{\sqrt{x}sin(x)}{5x}$

[thorny flame]

MellowDramaLlama

[radiant tapir]

Now split and take the limit of both

I didin't put the limit part in b/c I'm lazy but the limit as x goes to 0 from the right is in there, lol

[radiant tapir]

Does that make sense?

[topaz sinew]

@granite light Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[high sorrel]

log(x(x+2)=6

then I convert into exp

[frail fiber]

yes

[high sorrel]

10^6=x^2+2x

i move 10000000 to other side

x^2+2x-10000000

[sweet shard]

Does your class use $\log = \log_{10}$?

[thorny flame]

riemann

[high sorrel]

Yea

[topaz sinew]

@high sorrel Has your question been resolved?

[sweet shard]

,tex .quadratic formula

[thorny flame]

riemann

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[nocturne remnant]

I need help

[nocturne remnant]

I need help solving this

[loud ingot]

Which

[nocturne remnant]

The top

I have no idea what I’m doing

@loud ingot

[loud ingot]

Do you know what [[x]] mean

[nocturne remnant]

No

[loud ingot]

It works like this

[nocturne remnant]

Oh

[loud ingot]

Greatest integer function

[nocturne remnant]

Ok

Can you explain to me how the x and y chart work.

I get it and don’t at the same time

.close

[topaz sinew]

Channel closed

Closed by @nocturne remnant

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[distant lintel]

sonCan someone help me understand why 2 is wrong?

[topaz sinew]

@distant lintel Has your question been resolved?

[distant lintel]

<@&286206848099549185>

Anyone?

[gleaming lion]

Sry

Don't know how to do this

[distant lintel]

Okay, are you familiar with multi var calc?

[gleaming lion]

💀💀

What?

No idea

Sorry I cant help

[distant lintel]

<@&286206848099549185>

[distant lintel]

.close

[topaz sinew]

Channel closed

Closed by @distant lintel

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sullen pecan]

if we have 0.84 correct to 2 significant figures

[sullen pecan]

how do we find out the error for calculating upper bound and lower bound

[acoustic pecan]

do you want the interval?

[sullen pecan]

no

the error

like

if they say 1.0 to 1 d.p

error is 0.1/2

we add error to 1.0 for upper bound and subtract for lower bound

[sullen pecan]

if they gave this

how would I find the error

[acoustic pecan]

oh i see

it would just be 0.01/2

0.835 to 0.845

[sullen pecan]

why 0.01

[acoustic pecan]

youre halving the digit space youre rounding to

[sullen pecan]

oh

isn't 0.01 like 1 sf though

[acoustic pecan]

the digit of the second significant figure of 0.84 is the second decimal place

so 0.01

the digit of 1dp in 1.0 is the first decimal place, so 0.1

[sullen pecan]

ohh so we basically thought of significant figures as signicant decimal places or smth

[acoustic pecan]

it makes sense because youre going half said digit up or down in the error interval

still just significant figures
but youre focusing on the digit you round to, whatever it may be

ive never seen it presented like this
but when i think of it in terms of computing an error interval, makes sense

1.0 0.95 to 1.05, length of that interval is 0.1

[sullen pecan]

I'm in igcse so interval is a scary term for me here

[acoustic pecan]

its not that bad
like with this if i said i rounded a number to 1dp and got 1.0
then $0.95\leq x \le 1.05$ is the error interval

[thorny flame]

AℤØ

[acoustic pecan]

oops

one moment

[sullen pecan]

oh yeah second should be one less than only

right?

[acoustic pecan]

yeah

its being dodgy

[sullen pecan]

I see.

thanks

[acoustic pecan]

thats all interval means, nothing scary

[sullen pecan]

I see

thank you very much

[acoustic pecan]

np

[sullen pecan]

.close

[topaz sinew]

Channel closed

Closed by @sullen pecan

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[white gull]

Can someone help me with my math homework

[peak scarab]

Maybe

[white gull]

I need to understand like the concept and how to solve some of them

[peak scarab]

Which one don’t you understand ?

[white gull]

Mainly 2 and 3rd page

[peak scarab]

Well for some of them :
Rate of change :
Cost in function of time

Slope is probably variable price cuz it changes depending on the time you choose

For the 3 pairs you can just draw the line and write 3 coordinates for points the line goes through

Idk what’s a partial variation English isn’t my first language sorry

[topaz sinew]

@white gull Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[agile moth]

just want to make sure I'm solving these correctly... Given a) does c = 10? because 13(11mod19)mod19 = 143 % 19 = 10

[dense ridge]

Yes

[topaz sinew]

@agile moth Has your question been resolved?

Channel closed

Closed by @agile moth

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[white gull]

tyy!!

[topaz sinew]

@white gull Has your question been resolved?

Channel closed

Closed by @white gull

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[neon iron]

I'm having trouble relating any of this to theta

*Only asked to solve for theta not x

I'm pretty sure all angles must add to 180

so -90 from the square thing on top

theta + other angle = 90

the top part I got 4 for it but visually it doesn't make sense lol

like AB

[topaz sinew]

@neon iron Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gentle lintel]

I don't know what to do

[restive inlet]

draw an altitude from point C to AB

that'll form a right triangle with an acute angle A

[gentle lintel]

whats that?

[restive inlet]

do you know what an altitude is

[gentle lintel]

no

[restive inlet]

perperndicular height relative to some base

essentially draw a line from C such that its perpendicular to AB

[topaz sinew]

@gentle lintel Has your question been resolved?

Channel closed

Closed by @gentle lintel

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sonic bone]

help pls what do i do with the 4 * 3 * 2 * 1 / 14

[potent silo]

Simplify

[sonic bone]

do i multiply it all together or what

im watching a video

but im confused

[potent silo]

You have $\frac{4 \times 3 \times 2 \times 1}{14}$

[thorny flame]

wlmmm

[potent silo]

Don't you know how to simplify this expression?

[sonic bone]

no

thats why im asking

[sonic bone]

ur not very helpful

.close

[topaz sinew]

Channel closed

Closed by @sonic bone

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[next sable]

help me pls

[twin furnace]

any one in particular? or all of them

[next sable]

all, there are more but these are the ones that I can't understand

[twin furnace]

i see

let's start with the rhomboid one

give me 1 sec

[next sable]

okay

Sorry if I'm late in responding, I'm using a translator because I speak another language.

[twin furnace]

no worries!

[next sable]

ok thx

[twin furnace]

i feel like we need to know what one of the angles is

since AB and CD are parallel, the angle ABD should be 90 degrees iirc

[next sable]

maybe

[twin furnace]

yeah

i want to say that angles A and C are both 60 degrees, and he angle BDH is 30

that allows you to solve the problem

but i'm not sure if that's a rhomboid property, since rhomboids and rhombuses aren't the same

[next sable]

okok

I will try to solve it

[twin furnace]

i feel like some of these problems need more info to solve

[next sable]

That's how my teacher gave them to me, maybe that's why I can't understand it.

[twin furnace]

hm yeah, i could be wrong, but it definitely looks that way

for example in the second one with the two circles

x just looks like an arbitrarily long line

i'd ask about any other assumptions

[next sable]

ok

[topaz sinew]

@next sable Has your question been resolved?

[topaz sinew]

@next sable Has your question been resolved?

[topaz sinew]

@next sable Has your question been resolved?

[next sable]

<@&286206848099549185>

[next sable]

pls helpp

.close

[topaz sinew]

Channel closed

Closed by @next sable

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[slender isle]

where to start in this example?

[neon venture]

,w -x² + x +1

[thorny flame]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by herels

[slender isle]

what then to do with the denominator?

Can you explain that?

[gritty mirage]

You can do the change of variables u=x-1/2

You get something with arcsin I believe

[slender isle]

?

[flat kindle]

split the the integral to two parts

the first is easy and the second will be arcsin

$\int \frac{2u}{\sqrt{\frac{5}{4}-u^2}}du$ is easy

[thorny flame]

WhereWolf(ping if needed)

[slender isle]

?

[flat kindle]

yes

left one just do another u sub

right one use the fact that $\int \frac{1}{\sqrt{1-x^2}}dx=\arcsin{x}+C$

[thorny flame]

WhereWolf(ping if needed)

[slender isle]

A little did not understand it

[flat kindle]

first the 9 is just a contsant pull it out

so we just need you turn 5/4 to 1

you can do that by a u sub again

[slender isle]

Can you show how you got 1?

[flat kindle]

the easiest way would be to factor 5/4 out

$\sqrt{\frac{5}{4}(1-(\frac{4}{5}x-\frac{2}{5}))}=\frac{\sqrt{5}}{2}\sqrt{1-(\frac{4}{5}x-\frac{2}{5})}$

oh i forgot the square

anyways factor 5/4

to get 1-(ax-b)^2

then let x=(u+b)/a

[topaz sinew]

@slender isle Has your question been resolved?

[slender isle]

.close

[topaz sinew]

Channel closed

Closed by @slender isle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jolly dragon]

What does it mean?

[ruby tree]

You have the definition of f(t), just calculate f(-10)?

[jolly dragon]

Ooooooh fuck I’m stupid

I thought it was related to the graph

[ruby tree]

Maybe for the next questions

[jolly dragon]

Thanks

.close

[topaz sinew]

Channel closed

Closed by @jolly dragon

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[eternal vessel]

what’s the difference between n and u in set notation

[onyx yacht]

∩ means intersection, it's the elements common to both sets.
U is union. It means a set that has all elements of both sets

If we're talking about two

Obviously this can be extended

[onyx yacht]

To more than 2

[eternal vessel]

ok so would this be correct

[onyx yacht]

9 is odd

[eternal vessel]

woops

i ahve swapped

thanks! 😁

[onyx yacht]

And there are some numbers that are outside A and outside B

You should write them as well

[eternal vessel]

ah 8 and 10

[onyx yacht]

Yes

[eternal vessel]

how would i go about answering this type of question

[onyx yacht]

Assume the dimensions of the rectangles to be x and y

And use the given figure

[eternal vessel]

ok thanks

[topaz sinew]

@eternal vessel Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frank wind]

Q2

[lament sage]

,rotate

[latent quail]

try using $7 = 3^{\log_3(7)}$ perhaps?

[thorny flame]

Ab

[frank wind]

Nah I took looks of both sides

But I only got 1 answer

[abstract wadi]

"looks" ?
You mean log, dont you?

[frank wind]

I don't understand how to get the other

[latent quail]

not taking the logarithm on the both sides.

[frank wind]

Yh lmao

[latent quail]

i am just expressing 7 in an another way

[abstract wadi]

It's the same thing, doesn't matter.

Intel, show your work.

Of how you get 1 solution.

[frank wind]

OK one sec

Shit I'm trying to find it lmao

Yh this is it

[frank wind]

Yo

<@&286206848099549185>

[fading flume]

yes

[abstract wadi]

Well. You cancelled y+2 factor from both sides.

Or course you lost a solution.

If y+2 = 0, then there's another solution.

[frank wind]

Yh I suspected this but how do I find the other

[abstract wadi]

...

[frank wind]

Ngl bro I'm not good at maths

I'm confused as fuck rn

[abstract wadi]

In the third line, if y + 2 = 0, both sides are zero.
So the solution you get from y+2 = 0, is also a solution.

y + 2 = 0, happens go be an equation, which'll get you another solution.

[frank wind]

Wait so 2?

[abstract wadi]

Not quite.

[frank wind]

-2

[abstract wadi]

yeah.

[frank wind]

Wait how would I get both solutions in one go

Is there like a quadratic

[abstract wadi]

Then don't cancel y+2

[abstract wadi]

$(y^2-4) \log(3) = (y+2) \log(7)$\
$y^2 - 4 = (y+2) \log_3(7)$\
$y^2 - \log_3(7)y - 4 - 2 \log_3(7) = 0$

[thorny flame]

! What the hell am I doing here?

[abstract wadi]

" Quadratic "

[frank wind]

Wait what where did log 3 go

On 2nd line

[topaz sinew]

@frank wind Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[uncut cave]

why does the - move up there instead of stay on the 5

[mild hearth]

makes things simpler

just always move things out it's just good practice

[uncut cave]

so if it was -4 it would also still go in front rather than stay on the 4

[mild hearth]

yes

ideally

[uncut cave]

i see thanks

.close

[topaz sinew]

Channel closed

Closed by @uncut cave

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[subtle egret]

context: (sorry for not using latex)
( topic: topology - metric spaces )

(C(E, d) /~, d^) is a metric space, such that:
C(E,d) is the set of sequences (elements are in E) which sequences are Cauchy for d distance.
~ is an equivalence relation defined by:
(x_n)n ~ (y_n)n
<=> lim d(x_n, y_n) = 0, for n -> +inf

Picture: I have to prove that we can define d^ distance on C(E,d) /~

At first, I thought I had to show d^ is a distance but it isn't what the questions asks me. Some hints would be welcome, stuck since yesterday

[topaz sinew]

@subtle egret Has your question been resolved?

[topaz sinew]

@subtle egret Has your question been resolved?

[topaz sinew]

@subtle egret Has your question been resolved?

[subtle egret]

<@&286206848099549185>

[subtle egret]

.close

[topaz sinew]

Channel closed

Closed by @subtle egret

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[edgy cosmos]

Can somoene help me with C

[subtle egret]

Try to see if 0 is in the subspace.

[edgy cosmos]

I get it for a and b, but I cant wrap my head around how to do that for C

[topaz sinew]

@edgy cosmos Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[white grove]

I am having trouble with personal finance math. To calculate compound interests is pretty difficult for me to understand.

[white grove]

<@&286206848099549185>

[topaz sinew]

@white grove Has your question been resolved?

[white grove]

no

[neon iron]

3% of 2000 = x . 3% of x easy as that

[white grove]

I'm not understanding what you mean

.close

[topaz sinew]

Channel closed

Closed by @white grove

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[eager valve]

Find the exact perimeter of a regular hexagon, given that its area is 96sqrt3 square inches

[mild hearth]

draw a diagram, label the sides and draw some more lines in

[topaz sinew]

@eager valve Has your question been resolved?

Channel closed

Closed by @eager valve

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[digital cave]

@acoustic pecan my brothaaa

[acoustic pecan]

ello

[digital cave]

wsg bro

[acoustic pecan]

the usual, maths and all that, you

[digital cave]

good but yk i will be better if solve dis

if i

like like what should i do

[acoustic pecan]

you tried subsitution or elimination?

[digital cave]

im trying to get better in elimination

[acoustic pecan]

what did you get to?

[digital cave]

what should i do when the system has one solution?

should i do x(-4) in the first equation?

( (multiply -4) first equation )

or wut

[acoustic pecan]

either is alright

[digital cave]

na im confused ash

[digital cave]

??

[acoustic pecan]

dw about it

try get y= something in terms of a and b, or x= something in terms of a and b

by elimination

multiplying the first equation by 4 is a good move

[digital cave]

it should be something like -12y+4ay=-2b+20 ??

[acoustic pecan]

that works

so what does y=

[digital cave]

1 sec

y=-b+10/-6+2a ?????

[acoustic pecan]

brackets

[digital cave]

where doeee

:(((

[acoustic pecan]

around the numerator and denominator

[digital cave]

oh

[acoustic pecan]

someone could easily read that as y=-b+(10/-6)+2a

[digital cave]

y=(-b+10)/(-6+2a)

like this right?

[acoustic pecan]

seems so

what happens if a is 3?

[digital cave]

0

[acoustic pecan]

is it?

[digital cave]

-6+2x3

right?

=0

[acoustic pecan]

is y 0?

[digital cave]

uhm it should not cuz that will be no solution

we need 1 solution

[acoustic pecan]

its undefined, yeah

graphically, when a is 3 the lines are parallel

so either there is no solution or infinite solutions, depending on b

[digital cave]

yea

[acoustic pecan]

by elimination, must be D then

[digital cave]

wait how

im still kinda confused

[acoustic pecan]

we established a cant be 3

[digital cave]

oh

[acoustic pecan]

all the options except d have a as 3

[digital cave]

got it

you god tier

bro

[acoustic pecan]

[topaz sinew]

@digital cave Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[indigo estuary]

Help

[indigo estuary]

How would u solve this

And this

[gleaming reef]

holy shit

it's been so long

[gleaming reef]

,rotate

[radiant tapir]

,rccw

[gleaming reef]

,rotate

[gleaming reef]

aight

the numerator would be like sm like this (cos(π)cos(x) - sin(π)sin(x)))cos(-x)

if iirc

and cos(-x) = cos(x)

so it would be like -cos^2(x)

and the denominator would be like

(sin(π)cos(x) - cos(π)sin(x))(cos(π/2)cos(x) - sin(π/2)sin(x)))

that would yield (sin(x))(-sin(x)) = -sin^2(x)

-cos^2(x)/-sin^2(x) = cot^2(x)

@indigo estuary

[topaz sinew]

@indigo estuary Has your question been resolved?

[indigo estuary]

How’d u get this

[gleaming reef]

sum formula for cos(x)

[indigo estuary]

Oh right yea ok

Lemme try solving it

[indigo estuary]

If u don’t mind explaining why is cos -x = cos x

[gleaming reef]

it's an even function

[indigo estuary]

Ik that but like

Nvm

[gleaming reef]

mhm as soon as you are done comprehending

or if you have any qs

you can close this channel

[indigo estuary]

Yea

[indigo estuary]

Gimme a sec

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[indigo estuary]

.reopen

[topaz sinew]

✅

[indigo estuary]

I’m still kinda confused

What do u do after this

[gleaming reef]

buddy

[gleaming reef]

,rotate

[gleaming reef]

did you forget what cos(π) is equal to?

or sin(π)

[indigo estuary]

Probably

[gleaming reef]

or sin(π/2)

[gleaming reef]

that's essential

[indigo estuary]

Idk what they are

[gleaming reef]

whatttt

[indigo estuary]

Oh

[gleaming reef]

@vernal vale what to do here

😭

[vernal vale]

huh where the question

[gleaming reef]

basically they can't simplify this

cuz they forgot what cos(π) is 😭

,w cos(π)

[thorny flame]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by nosqldb

[gleaming reef]

,w sin(π)

[thorny flame]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by nosqldb

[gleaming reef]

,w cos(π/2)

[indigo estuary]

Oh

[gleaming reef]

,w sin(π/2)

[indigo estuary]

Ok

[thorny flame]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by nosqldb

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by nosqldb

[gleaming reef]

you should know this @indigo estuary 😭

[indigo estuary]

When do u first learn this

[gleaming reef]

in the start of the precalculus

[indigo estuary]

Is my calculator meant to get a different answer

[indigo estuary]

Ohk

[gleaming reef]

your calc might be in deg

mode

[indigo estuary]

Oh I see

[indigo estuary]

Ohk so whenever I get something in pi, it’s in radians?

[gleaming reef]

what

stop taking shortcuts

[indigo estuary]

Wait wdym

[gleaming reef]

the calculator can be in degree mode

or radian mode

[indigo estuary]

So if I get sin (pi/2) for example and my calc is in deg mode, I convert pi/2 to degrees?

[gleaming reef]

sure

[indigo estuary]

Alr thx

Lemme try solving now with that knowledge

[gleaming reef]

mhm

[indigo estuary]

Ok I think I got it but is there an easy way to memorise or easily derive, sin/cos/tan(0/90/180/270/360)

Like for deriving, could I use the unit circle to get their values

[gleaming reef]

you just memorize it

[indigo estuary]

Damn ok

Thx for helping

.close

[topaz sinew]

Channel closed

Closed by @indigo estuary

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pulsar sun]

would a generating function of the form $\sum_{n=0}^{\infty} \alpha_n \sin(\beta_n)$ be the same thing as the fourier series of a function? Since the fourier series of a function is the same thing as the sum of n sine/cosine waves, and as n approaches infinity the sum presents a better and better approximation of the function itself?

[thorny flame]

ItzKraken

[knotty ledge]

the beta_n take a particular form in fourier series

[pulsar sun]

That is true and iirc its some scary integral, but except that in essence its the same thing right?

[knotty ledge]

the integrals are only to solve for the coefficients in a fourier series

youre perhaps confusing it with the fourier transform

[pulsar sun]

yeah thats what i meant, the coefficients are some scary integral

[pulsar sun]

Fourier transforms are scary

@knotty ledge in essence they are the same thing right?

[knotty ledge]

insofar as they both involve a sum of sines

[pulsar sun]

.close

[topaz sinew]

Channel closed

Closed by @pulsar sun

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lucid junco]

how am I supposed to integrate $\int_{ }^{ }\left(e^{x}+3\right)^{2}dx$, I tried $u = e^x + 3$ but that didnt work, surely $u = e^x$ doesnt make sense so what u-sub do I do?

[topaz sinew]

Please don't occupy multiple help channels.

[thorny flame]

water beam

[acoustic pecan]

it would probably just be easier to expand it

[lucid junco]

but what if i had (e^x+3)^100

like i dont wanna be in a situation where I can only expand

[idle grail]

Mathematica time

[past cradle]

What's the problem with that sub

[lucid junco]

it dont work

[past cradle]

$\int \frac{t^2}{t - 3} dt$

[thorny flame]

jewels!

[past cradle]

Right?

[lucid junco]

how do we get that?

[past cradle]

by subbing e^x + 3

[lucid junco]

oh wait

[past cradle]

• 9 - 9 in the numerator

[lucid junco]

$\int_{ }^{ }u^{2}\cdot\frac{du}{u}$

[thorny flame]

water beam

[lucid junco]

right

[past cradle]

u - 3

In the denominator

[lucid junco]

is this u = e^x only

[idle grail]

No

[past cradle]

e^x + 3

Well that's what it's meant to be for

[idle grail]

I’d also point out that this method still doesn’t make it easy to solve the integral for an arbitrary power

In general solving that integral for n will just be hard and you’d get a computer to do it

I think it probably is just easiest to expand this integral

[past cradle]

I just wanted to see why the asker's substitution doesn't work

Its just not one of those things that you'd do for an arbitrary power

[lucid junco]

$\int_{ }^{ }u^{2}\cdot\frac{du}{u-3}$

[thorny flame]

water beam

[lucid junco]

is what i got

[idle grail]

Yeah I’m talking to op not you, they’re against expanding it because they don’t want to “rely on a method that only works when they can calculate it” and wanted a more general method

[past cradle]

you can do + 9 - 9 in the numerator and split the fraction now

[idle grail]

I’m just trying to point out that integrals are just hard to solve in general and a lot of the time a solution method can’t be generalised. Most hard integrals just get solved numerically or sometimes symbolically by computers, because integrals are just hard to calculate

So take the path of least resistance when you can

[lucid junco]

well Im not in any job or university so I dont have the luxury of the computer in an exam

[idle grail]

Once again I’m just trying to point out that expanding the integral is a valid method, as is the u-sub, it’s not worse because it’s harder to generalise. You can’t really generalise it is my point

[lucid junco]

is this the add 0 trick

[lucid junco]

fair i guess

$\int_{ }^{ }u^{2}\cdot\frac{du}{u-3}=\int_{ }^{ }\frac{u^{2}}{u-3}du=\int_{ }^{ }\frac{u^{2}+3-3}{u-3}du$

[thorny flame]

water beam

[lucid junco]

wouldnt this work better

instead of +9-9

$\int_{ }^{ }\frac{u^{2}+3-3}{u-3}du=\int_{ }^{ }\frac{u^{2}-3}{u-3}du+\int_{ }^{ }\frac{3}{u-3}du$

[thorny flame]

water beam

[knotty ledge]

Well then what are you going to do with thr first integral?

The point of 9 was to use difference of two squares

[lucid junco]

you can cancel out u^2-3/u-3

to get u-3

[lucid junco]

cancel to get u-3

surely thats not illegal

[knotty ledge]

That's not how cancelling works

[lucid junco]

look

we have (u^2-3)

what if

ok nvm i just realised why it doesnt work

lol

[lucid junco]

could you provide an example

[knotty ledge]

a² - 4 = (a+2)(a-2)

[lucid junco]

$\int_{ }^{ }\frac{\left(u+3\right)\left(u-3\right)}{u-3}du$

[thorny flame]

water beam

[lucid junco]

@knotty ledge like this?

.close

[topaz sinew]

Channel closed

Closed by @lucid junco

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[topaz reef]

im not sure how to integrate vvxx .... honestly

like how is it vvx?

[tawny spade]

Is vxx d²v/dx² ?

If so, the integral of vxx dx is obviously just vx

[topaz reef]

its just pluggin in the condition 1 into V_T

[topaz reef]

im honestly not sure, i think maybe it is?

[tawny spade]

If it is then there you go i guess?

Im not too sure myself honestly

[topaz reef]

i follow what to do up to that point

even after that point i understand

lol

[tawny spade]

If Vxx is the second derivative of V in terms of x

Then the integral of Vxx dx is Vx

So if you have integral VVxx dx it's V times integral Vxx dx

Which is Vx

[topaz reef]

okay that makes sense

but by the same logic right the dervative of vvx should be vv_xx

[tawny spade]

Do you know of the product rule

[topaz reef]

yeah vv_x = v_xv_x + vv_xx

[tawny spade]

Yeah

[topaz reef]

which isnt equal to vv_xx

[tawny spade]

Its not

It shouldnt be

Or should it?

[topaz reef]

i mean if you integrate vv_xx and say its vv_x

whenever you differentiate it shouldnt it give you back the same?

[tawny spade]

You are right lol

I guess i just cant understand how v isnt a function of x

But yeah if we're doing that i guess V is a constant

So derivative of vvx = vvxx

[topaz reef]

i just dont understand this one part

i understand everything else lol

[topaz sinew]

@topaz reef Has your question been resolved?

[topaz sinew]

@topaz reef Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[formal ore]

how can we conclude m<=c????

[formal ore]

i cannot see any relation between a and b, it is pretty basic stuff ik

[acoustic tangle]

It's in the name, "the least common multiple"

Meaning it's always less than or equal to every other common multiple

[outer salmon]

c is a common multiple of a and b. So the least common multiple can’t be larger than c, because then it wouldn’t be the least common multiple, c would

[formal ore]

thanks dude

[topaz sinew]

@formal ore Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[umbral jungle]

is it possible to use l'hopital with a 0/inf indeterminate form?

[umbral jungle]

or is it just 0/0 and inf/inf

[acoustic tangle]

No

[flat kindle]

0/inf just approaches 0

[topaz sinew]

@umbral jungle Has your question been resolved?

Channel closed

Closed by @umbral jungle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[woeful iris]

Can someone explain this to me?

[woeful iris]

(The yellow part)

[odd pagoda]

M^17 = M^16 * M

and M^16 =(M^8)^2

and M^8 = (M^4)^2

and M^4=(M^2)^2

the idea being that you reduce mod 2773 at every step

[woeful iris]

Can you give me an example with numbers? (M = 920)

bc i didn't quite understand how to get to M=980

[odd pagoda]

so, first we square

920^2=846400 = 635 mod 2773

then we square again

635^2 = 403225 = 1140 mod 2773

[woeful iris]

how you get "635 "?

[odd pagoda]

1140^2 = 1299600 = 1836

calculator

846400 when divided by 2773 gives remainder 635

[woeful iris]

Ah ok

Ahhhhh now I think I understand thanks! @odd pagoda

.close

[topaz sinew]

Channel closed

Closed by @woeful iris

Use .reopen if this was a mistake.

[topaz sinew]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fathom sequoia]

can someone please help me solving this

[fathom sequoia]

i dont even understand the solution

[outer salmon]

It’s the limit as x approaches 1 from the left side (reply to deleted question)

[fathom sequoia]

but -1 is not greater than 0

how come -x^2 +3x + a is the equation

i understood how we found a

i didnt understand this

how is 1- greater than 0?

wait 1- is like -1?

[chilly walrus]

1- is not the same thing as -1

[fathom sequoia]

damn i totally forgot limits

[chilly walrus]

no, very very different

formally, 1- is $1 - \varepsilon$ for some $\varepsilon > 0$

[thorny flame]

artemetra

[chilly walrus]

as small as needed

$\lim_{x\to1^{-}}$ means ``limit to 1 but as we go from the left to the right''

[thorny flame]

artemetra

[fathom sequoia]

i think i got it

thanks alot

🙂

[chilly walrus]

np

[topaz sinew]

@fathom sequoia Has your question been resolved?

Channel closed

Closed by @fathom sequoia

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[polar blaze]

say i have a trapezoid with base lengths A and B, and an arbitrary positive number as the height. what length inside the trapezoid parallel to the bases cuts the trapezoid into 2 pieces of equal area, in terms of A and B?

[ruby tree]

!status

[topaz sinew]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[polar blaze]

im asking for the formula that i know exists

to solve a different problem

[ruby tree]

Why not derive it yourself?

[polar blaze]

dont know how

[ruby tree]

A good first step would be to draw a figure

[polar blaze]

yeah

i let the length be x now what

like idk how to write the heights in terms of x

wlog let b be longer

[ruby tree]

I'm not going to draw a figure for you

If you drew one, send it

[polar blaze]

sry for the orientation

[ruby tree]

,rccw

[polar blaze]

yep

however there's like 3 variables here... how do I write h1 and h2 in terms of x?

[ruby tree]

The 1/2 at the front shouldn't be there, though it doesn't matter since they cancel out on each side

[polar blaze]

yeah oops

the /2s cancel out too

[ruby tree]

Right

$h_1 (a+x) = h_2 (b+x)$

[thorny flame]

Nel

[polar blaze]

yep

how would i write h1 and h2 in terms of x a and b tho

[ruby tree]

Well let's first solve for x and see what we need

Can you do that?

[polar blaze]

sure i can try

one sec

[ruby tree]

Right

Give me 5min

[polar blaze]

k tysm

[ruby tree]

Alright sorry about that

So you found x but it looks like you need more information

[polar blaze]

np

[ruby tree]

Let's solve an easier problem: same kind of thing but with a triangle instead

[polar blaze]

yeah that would make a=0

[ruby tree]

Yes

Something like that

[polar blaze]

yeah

[ruby tree]

(not necessarily a right triangle but whatever)

Is there another relation you can see?

[polar blaze]

the ratio of h1 to h2 would be sqrt(2), use similar triangles to find x = b/sqrt(2)

i think

[ruby tree]

Huh maybe, I'm not sure how you arrived to that though

[polar blaze]

wlog assume this is a right triangle

h2+h1/h1 = b/x

[ruby tree]

No that would be (h1+h2)/h1 = b/x

[polar blaze]

yeah sorry

basically the whole triangle is 2x the area of h1*x

so the whole triangle's lengths are *sqrt(2) of the smaller one

area ratio

likewise of this was a triangular pyramid shrunk 2x its volume its side lengths would differ by a factor of cbrt(2)

so x would be b/sqrt(2)... now we have to add in the a

[ruby tree]

Ok yeah

[polar blaze]

if we take this shape to the other extreme e.x. a=b then x would be right in the middle and x=a=b

but now we have a trapezoid

[ruby tree]

That's good intuition even if you're not writing down the equations

For the trapezoid, I think there are two ways to look at it

First would be to chop it into triangles and make sure the line is the same in each triangle

Second would be to extend it into a triangle (unless the sides are parallel but that has a trivial solution)

[polar blaze]

hm ok

they make the prob harder tho

[ruby tree]

Go for the second option then

Does this make sense?

[polar blaze]

yep

[ruby tree]

So first I'd say find f in terms of a and b

[polar blaze]

wlog let f+g+h=10, f=10a/b

nvm let wlog =1

f=a/b

[ruby tree]

Yea I was gonna say just pick 1

Now we want the area of each trapezoid (with heights g and h) using the area of the whole triangle, right?

[polar blaze]

yeah

1/2(a+x)g=1/2(b+x)h

whole triangle one sec

,rccw

[polar blaze]

ignore the heights on the right

[ruby tree]

Ok that looks correct

[polar blaze]

,w ((a)/(b)+g)*(x)/(2)-(a^(2))/(2b) = g(a+x)/2 = (b/2) - (f+g)x/2 in terms of a and b

[thorny flame]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by auroraborealis13

[polar blaze]

...

,w ((a)/(b)+g)*(x)/(2)-(a^(2))/(2b) = g(a+x)/2 = (b/2) - (f+g)x/2 = (1/2)(b+x)h

[thorny flame]

Wolfram Alpha doesn't understand your query!
Perhaps try rephrasing your question?
Click here to refine your query online

Requested by auroraborealis13

[ruby tree]

Sorry I'm doing something else at the same time

[polar blaze]

np

[ruby tree]

Notice that x = a + (b-a)g/(g+h)

[ruby tree]

And this gives you x = (bh-ag)/(g-h)

[polar blaze]

yeah...

[ruby tree]

,w x = a + (b-a)g/(g+h), g = (-2 b h + sqrt(4 b^2 h^2 - 4 h^2 (a - b) (a + b)))/(2 (a + b)), a>0, b>0, h>0, g>0

[thorny flame]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by nelfeal

[ruby tree]

I feel like there is a better way

[polar blaze]

lol yeah

[ruby tree]

I can't figure out what's missing, I'm tired

[polar blaze]

same tbh

imma ping helpers in 15m

<@&286206848099549185> ikik yes i need to wait another minute shut up
orig prob:
say i have a trapezoid with base lengths A and B, and an arbitrary positive number as the height. what length inside the trapezoid parallel to the bases cuts the trapezoid into 2 pieces of equal area, in terms of A and B?

[worldly nimbus]

it makes no sense but my answer is x=(a+b)/2

[polar blaze]

wouldn't say thats the answer

[worldly nimbus]

ik

[polar blaze]

.....

[worldly nimbus]

it comes as b[y^2 +1]^2 + a[y^2-1]^2=2(a+b)

where y=(b-x)/(x-a)

@polar blaze

[topaz sinew]

@polar blaze Has your question been resolved?

[topaz sinew]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.