help-26

[gaunt cape]

nvm i got it

.close

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[lofty glacier]

hi

[lofty glacier]

so ive got a maths test tomorrow on all of these topics

Angles between parallel lines
Averages
Bearings
Best Buys
Compound Measures
Converting between metric units
Expanding Brackets
Factors and Multiples
Fraction, Decimals & Percentages
Ordering Integers
Perimeter, Area and Volume
Pie Charts
Place value
Probability
Real Life Graph
Ratio and Proportion
Simplifying Expressions
Standard Form
Solving Equations
Transformation

my knowledge for half of them is lacking

is there anything that can be done

[drifting swift]

no you're fucked

expect to score 50% on the test

maybe less

[wheat grove]

i guess you could get some of the other ones out of the way, but uhh trying to get all of that done at this point seems rather pointless

[acoustic pecan]

id focus on solidifying what you do know to make sure you'll at least get that, as for the rest, hope is little

[wheat grove]

but if you already know the tougher ones, you could skim through the easier ones but again it all just depends

[lofty glacier]

name some easier ones

i already know for the last questions

its gonna be

impossible

[wheat grove]

depends on whether they know the easier ones or tougher ones and how well they know them

[keen matrix]

Ordering Integers is really easy

[lofty glacier]

i think

the one that will cause me the most trouble

is fractions decimals and percentages

like if its something like

a mixed fraction multiplied by another or divided

il be lost

[keen matrix]

like $\frac{\frac{1}{2}}{\frac{1}{3}}$?

[thorny flame]

FancyBredFries

[lofty glacier]

no what the fuck is that lol

i mean

like

its easy ngl i just forgot how to do it

lemme find a pic

maybe something like this

[drifting swift]

if these fractions were not mixed, would you know what to do? Y/N

[wheat grove]

what fancy gave you was a simpler version of this

[lofty glacier]

ye

[drifting swift]

right

[lofty glacier]

thats easy

[drifting swift]

do you know how to convert to and from mixed fractions?

[lofty glacier]

nah

i dont think i remember

[drifting swift]

ok then that's something for you to review

"convert between mixed and improper fractions" on youtube

[lofty glacier]

i think most of my marks are gonna be for working out

because i remember most the methods

i just think ill slip up

it is also a higher paper so im pretty fucked but ill try my best

[wheat grove]

there isnt much you could do for that at this point, except making sure that you well rested, confident and making sure you thoroughly review your answers

[wheat grove]

whats a higher paper?

[lofty glacier]

fair

[lofty glacier]

in england there are foundation classes and higher classes

basically lower ability and higher ability

[wheat grove]

also what are some topics you dont know?

[lofty glacier]

ngl bearings always get me

i just guess for those questions

its like the boat moved 30 degrees mark where it is

or smth like thta

[wheat grove]

that should not be that hard either, if you are careful with what the question says. review the main rules and a few questions

[topaz sinew]

@lofty glacier Has your question been resolved?

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[frank narwhal]

where do the numbers 2 + 30 and 5 - 9 come from?

[gritty trout]

2 + 30 = 2(1) + 3(10)

5 - 9 = 5(1) + 3(-3)

[frank narwhal]

eh..? where are all these numbers coming from

i cant really make sense of it in a meaningful way

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@frank narwhal Has your question been resolved?

[frank narwhal]

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[shrewd crow]

.reopen

<@&286206848099549185>

[wheat grove]

!15min

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Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[wintry kraken]

can i help you ?

[frank narwhal]

if youd like but im starting to live with the fact i'll never understand it

friend showed me some graph thats like

AE + BG for just entry A which is...?

[wintry kraken]

you wanna get A B

put A and B like this

then you'll do the intersection of lines and colons ( sorry for mistakes in english )

in the circle

( 1 * 2 ) + ( 3 * 10 )

2 + 30

[frank narwhal]

ohhh okay

[wintry kraken]

( 2 * - 2 ) + ( 4 * 10 )

etc ...

[frank narwhal]

thats..a confusing way to do it but i see the pattern now

[wintry kraken]

yes but its easier in the beginning

i think

just be careful because AB different BA

[frank narwhal]

got it tyvm man

[wintry kraken]

np ^^'

[topaz sinew]

@shrewd crow Has your question been resolved?

[scarlet flare]

When the function variable is changed from f(x) to f(x+2), its graph will move 2 units to the left, if it were f(x - 2), it will move to the right. This is due to properties of the graphs of functions. Finally, if the graph of f(x) intersects the X axis at (-7, 0) and (-3, 0), then f(x + 2) would intersect the x-axis at (-9, 0) and (-5, 0). For the other thing about f(-x), when you put the variable in its negative form, the graph of its function is inverted with respect to the Y axis, as if it were a mirror. So, if f(x) cuts the x-axis at (-7, 0) and (-3, 0), then f(-x) would cut the x-axis at (7, 0) and (3, 0).

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[neon iron]

Benjamin invests money in a bank account which gathers compound interest each year.

After
2
 
years
2years there is
$
658.20
$658.20 in the account.
After
5
 
years
5years there is
$
710.89
$710.89 in the account.

Work out the annual interest rate of the bank account.
Give your answer as a percentage to 1 d.p

[neon iron]

How do i solve this

.close

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[worldly scroll]

how do i simplify the dot product of (2x-3y) dot (4x+5y)?

[sweet shard]

are x and y numbers?

[worldly scroll]

no

[sweet shard]

the dot product of sums expands similarly as numbers do

$(u + v) \cdot w = u \cdot w + v \cdot w$

[thorny flame]

riemann

[sweet shard]

and $(a u) \cdot v = a (u \cdot v)$

[thorny flame]

riemann

[sweet shard]

for vectors u, v, w

and scalar a

[worldly scroll]

ive gotten to a point where its

8|x|^2 - 2xy - 15|y|^2

but im not sure if thats entirely right or if and how to simplify it further

[sweet shard]

looks right

[worldly scroll]

is that the furthest it can go?

[sweet shard]

yes

[worldly scroll]

ok perfect thank you

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[void owl]

Hello, I'm reviewing studying some linalg for a robotics class midterm and am looking at these basis and dimension examples. I'm confused about the difference between the first and second one. How exactly does this notation work? does (C,C) only mean the complex part of complex numbers? Also I haven't taken a linear algebra class so this is pretty confusing for me

[knotty ledge]

(A,B) is considering A as a vector space over B

You can consider C as both a vector space over C or over R

[knotty ledge]

B here is just "where do your scalars in the scalar multiplication come from"

[void owl]

could you explain what it means for a vector space to be over another in simple terms

[knotty ledge]

Literally this

Viewing C as vector space over C, our scalar mult comes from C, so all we need is 1 and we can get any complex number by just scalar multiplying 1 by the complex number we want

If we view C as a vector space over R, we can only multiply by real numbers

We can't just have 1 as a basis as nothing we multiply 1 by will give us say 3+4i as we have to multiply by a real number

So we also need i in the basis (for example, bases aren't unique)

[void owl]

gonna have to put a pause on this but i might reopen a help later, do you mind if i ping you in it? got a meeting rn

[knotty ledge]

I will likely be asleep, plenty of helpers know LA though

There is also #linear-algebra

[void owl]

ok, thank you anyways

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[daring oak]

for this i set vector u = < 7, 8, -4 > and vector v = < -4, 7, 8 >

then i found the dot product to be -4, and the product of their magnitudes is 129. So arccos(-4/129) is 1.602 radians, right?

<@&286206848099549185>

i just did the problem again and saw that it says acute angle. So should the dot product be positive 4 instead of -4? Doing so makes it so that the angle is 1.540 radians, is this correct?

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@daring oak Has your question been resolved?

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[cinder owl]

this is not equal right

[cinder owl]

where -1 is the preimage

[odd pagoda]

why do you think that

[cinder owl]

maybe C has values that arent in the range of f?

Let f : X → Y be a function, let A, B ⊆ X and let C, D ⊆ Y

doesnt say X = Y

[odd pagoda]

ok can you give an example?

[cinder owl]

i am thinking

well like

if C = the real numbers and A equals the Natural numbers

[gritty trout]

you had really great insight here, but now i think you've become sort of confused

[cinder owl]

yes

this class always confuses me 💀

[gritty trout]

its okay. try to come up with sets X,Y, a function f : X --> Y, and a set C \subseteq Y using this reasoning

[cinder owl]

i mean wouldnt c just have values that arent a subset of X

[gritty trout]

C is a subset of Y, so it always (if X \neq Y at least) has values that aren't a subset of X

[cinder owl]

yes

it doesn explicitly state they are not equal tho

why can we assume that

[gritty trout]

well Denascite asked you for an example

to show that f(f^{-1}(C)) is not always equal to C

that means you have to come up with specific sets X,Y, a specific function f : X --> Y, and a specific subset C of Y such that f(f^{-1(C)) does not equal C

so you can make X and Y different in your example if you want. or you could make them the same

[cinder owl]

oh like a counter example to prove c isnt a subset

[gritty trout]

yeah, a counterexample to the claim "for all sets X,Y and functions f : X --> Y, if C is a subset of Y then f(f^{-1}(C)) = C"

[cinder owl]

well if C is bigger then any subset of X thne the counter example holds

im ngl preimage always messes with me

[gritty trout]

you have to produce specific, well-defined functions and sets to form a counterexample.

[cinder owl]

i dont know

im stuck

[gritty trout]

well, you should probably come up with some sets and function f between them first, then see if you can choose a subset C of the codomain such that f(f^{-1}(C)) does not equal C

if you can't, you have to think about why you can't

[gritty trout]

using your nice insight to guide you

[cinder owl]

its hard arbitrarily

[gritty trout]

i feel like you can probably think of some sets and a function between them

[topaz sinew]

@cinder owl Has your question been resolved?

[cinder owl]

C = {1,2, 3, 4}, f(-1) = 1, f(-2) = 2?

[gritty trout]

So f is defined on {-1, -2}? What is the codomain of f?

[cinder owl]

actually no im genuinely so confused

like you would need to define x and y to have a counter example right

[gritty trout]

yeah you need a function f : X —> Y and X and Y have to be specified

[cinder owl]

c = {−1,1} f: R --> R where f(x) = x ^2

nothing ever maps to -1

[gritty trout]

Pog. That works

f(f^{-1}({-1,1})) = {1} ⊂ {-1,1}

For some general theory: if f is surjective, they ARE equal for all C

And in general f(f^{-1}(C)) = C ∩ im f

Where im f is the image (or range) of f

[cinder owl]

also do you have any tips on proving surjectivity i always find it difficult for some reason

[gritty trout]

idk it probably depends a bit on the situation, but usually you just have to show it directly

[cinder owl]

i proved injectivity fine here but struggling to do surjectivity

[gritty trout]

It might be easier to do the contrapositive for the backward direction

Which is the inverse of the forward direction

[cinder owl]

why do you need to prove directions

whenever i did surjectivity before

[gritty trout]

It says if and only if

[cinder owl]

it was just

ohhh

[gritty trout]

So you have to prove if f is surjective, then that thing is true. And if that thing is true, then f is surjective

[cinder owl]

rip i dont think i fully did injectivity correctly then

[gritty trout]

yeah theres no injectivity in this proof. I assumed you meant a very similar theorem that you didn’t send when you said that

mayb u did

[cinder owl]

oh yeah there was like a part 1, which was like the same thing but with injectivity

[gritty trout]

pog

[cinder owl]

thanks for helping, i appreciate it

[gritty trout]

np

[cinder owl]

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[velvet fulcrum]

bro stole it

are you raking a test

[supple bay]

No.

Can I use distribution law and simplification like I did?

[velvet fulcrum]

only on negative numbers

[supple bay]

I don’t think so tbh

I’m out of ideas on how to arrive at q and u tho

[velvet fulcrum]

when $(a u) \cdot then v = a (u \cdot v)$

[thorny flame]

.

[supple bay]

This isn’t multiplication

[velvet fulcrum]

use this as your reference

[supple bay]

This is finite maths

[velvet fulcrum]

oh mb

[abstract grove]

not (A and B) is not A or not B

[velvet fulcrum]

if $(divison) \cdot then v = a (a nor b )$

[thorny flame]

.

[supple bay]

@abstract grove can I use the rules like I did it?

Like I said I don’t think so

[abstract grove]

Idk it's too small for me to read on phone

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@supple bay Has your question been resolved?

[topaz sinew]

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[neon iron]

Question: What is the probability of rolling 4 different numbers in 6 dice rolls, assume a fair 6-sided die

does 6C4 * (6 * 5 * 4 * 3 * 3 * 3)/6^6 work?

[hasty sail]

Hey

[hasty sail]

yep thats riggiht

[neon iron]

Hi 🙂

[hasty sail]

I got about 0.463

[neon iron]

When I compute it I get 1.041666 which I don't think is the right answer

[hasty sail]

C(6, 4) = 6! / (4!(6 - 4)!) = 15
15 ways to choose 4 different numbers.

P(6, 6) = 6! / (6 - 6)! = 6! / 0! = 720
720 ways to arrange these 4 different numbers in 6 rolls.

P(2, 2) = 2! / (2 - 2)! = 2! / 0! = 2
2 ways to roll the remaining 2 numbers in the remaining 2 rolls.

6^6 = 46,656

21,600 / 46,656 =~ 0.463

thats the thought proccess

but I just plugged values into my graphing calc

[hasty sail]

computing error most likely

15 x 2 x 720 = 21600

6^6 = 46656

need any more help pls just ping me

[neon iron]

Yeah so I did 6C4=15, 6 * 5 * 4 * 3 * 3 *3=3240, 6^6= 46656 so then:

15*3240/46656=1.0416

but i'm not really sure why that's wrong

[hasty sail]

where is 153240 is coming from?

[empty sail]

It's formatted because of discord

[neon iron]

sorry that was an error it's supposed to be 15 * 3240

[empty sail]

Surround the text with `

So it doesn't do that

[hasty sail]

supposed to be 15*2*720

4 different number and 15 ways to choose them
2 ways to roll the remaining to fair die
720 ways to arrage 4 different numbers.

[neon iron]

ah ok

[neon iron]

but why does this not work or what is the mistake here?

[hasty sail]

why are you doing 6C4

i'm still not understand that

[neon iron]

My thinking was getting the first number is 6/6 then the second was 5/6 then 3rd 4/6 then 3/6 then you have to repeat one of those numbers twice, then there is 6C4 ways to arrange the unique numbers

[hasty sail]

There are thre things you need to care for:
how many ways to choose them
how many ways to arrange them
how many ways to roll the remaining die

[hasty sail]

ohhh

i see where the logic is going wrong

two scenarios:

1. The repeated number is the same as one of the first three numbers
2. The repeated number is different from the first three numbers

[neon iron]

ok

is there a way I could account for those scenarios and solve it similar to how I was or is my original way just fundamentally wrong aha

[hasty sail]

Number of ways to choose 4 different numbers out of 6: 6C4 = 15.

Number of ways to arrange these 4 different numbers in 6 rolls: 4P4 = 4! = 24

Number of ways to choose the remaining 2 numbers (the ones not chosen): 2C2 = 1

Number of ways to arrange these 2 remaining numbers in the last 2 rolls: 2P2 = 2! = 2

[hasty sail]

account for all possible change

[neon iron]

ah ok

I think I get it now

thank you!

.close

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[sharp dew]

How do I find the derivative of tan^4(x/12)?

[sharp dew]

I wonder if i can assume the trig function as a variable like x,y,z

Then differentiate it

[novel echo]

just power rule, chain rule, and trig identity

[sharp dew]

Is it correct

[odd jacinth]

your mistake is that f'(x) = 4p'p^3

not 4p^3

because of chain rule

[golden mesa]

how do you have the same question as #help-1

[sharp dew]

Do I needed to apply chain rule to this question

[odd jacinth]

yes

[sharp dew]

Cause his my brother that I never met my whole life, and probably we re non-blood-relative

But we share the same question

[sharp dew]

Why? D/dx P^4 = 4P^3

[novel echo]

f(x) = tan^4(x/12)

g(x) = tan(x/12)

h(x) = x/12

[sharp dew]

Isn’t it true

[sharp dew]

What does it mean

[novel echo]

functions for chain rule

[odd jacinth]

you're mistaking derivatives
when you write f(x) = p^4
then when you take the derivative you want df/dx
but if you say 4p^3 it is df/dp

you forgot to use chain rule so a dp/dx is missing

[sharp dew]

I can’t seems to understand what is h(x)

It is not a trig function

It seems out of context

In my point of view

[novel echo]

try to look at $tan^{4}(\frac{x}{12})$ as $f(g(h(x)))$

[thorny flame]

saad

[sharp dew]

What I had been taught to do the derivative of tan, is to split it in the form of sin/cos. Then differentiate it

[novel echo]

this is incorrect because you differentiated only 1 function

[novel echo]

huh

[sharp dew]

This

[novel echo]

you never learned about these derivatives?

[sharp dew]

Only the sin and cos

[sharp dew]

Where did you get that exotic table from

[novel echo]

thats not exotic at all, its very common, you should memorize those

[sharp dew]

No, I think the arrangements of word is terrific and neat

[sharp dew]

Where the picture from

[novel echo]

google.com

[sharp dew]

I see

Terrific

.close

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[limpid mica]

im trying find the Wronskian with this ODE, and also solve it, but im apparently not getting the right wronskian

[limpid mica]

i have to verify that e^-2x and e ^3x are part of the fundamental set

the part on the right is what im getting as the wronskian

those cant be combined can they

i mena i do realize i got the signs wrong

but even then its not right

ok so i got the wronskian now. just need to figure out how to solve

think im good now

.close

[topaz sinew]

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[finite ridge]

All the roots of
[x^2 + px + q = 0]are real, where $p$ and $q$ are real numbers. Prove that all the roots of
[x^2 + px + q + (x + a)(2x + p) = 0]are real, for any real number $a$.

[thorny flame]

Dzlta

[finite ridge]

i've tried completing the square, but it hasn't really worked? not sure what to do (i feel like im missing something obvious)

[topaz sinew]

@finite ridge Has your question been resolved?

[finite ridge]

<@&286206848099549185> it's been more than 15 min so ig ill ping

[chilly trail]

hint: use discriminant formula to show a minimum

[finite ridge]

oh

wait i think i get what you mean

[chilly trail]

or in other words use the discriminant to show its greater than or equal to zero

[finite ridge]

my dad showed me that earlier but i dont know how it's relevant

[chilly trail]

bc if a quadratic polynomial has positive coefficients and its discriminant is >= 0 then its roots are real

[finite ridge]

oh like use discrimminant for the x^2+px+q part and discrimminant for the (x+a)(2x+p) part?

[chilly trail]

yes

second one

you wanna prove that the discriminant of 3x^2+x(2p + 2a) + ap + q = 0
is greater or equal to zero

[chilly trail]

dyk why @finite ridge

[finite ridge]

yeah because if the discrimminant is below 0 then it's the sqrt of a negative number

[chilly trail]

yuh

[finite ridge]

wait where does this come from

oh

[chilly trail]

simplification

[finite ridge]

bruh nvm ye idk how i didnt see that

[chilly trail]

nah ur g

what class is this for

[finite ridge]

oh so jut discrimminant dang i overlooked that

aops intermediate alg

we on like review tho

[chilly trail]

ohhh swaggg

like the online course?

[finite ridge]

ye

[chilly trail]

bro i wish

[finite ridge]

i've lost motivation in like math tho

[chilly trail]

😩

why

[finite ridge]

im gonna go to calc and then just stop

all my friends are better than me

[chilly trail]

so?

albert einstein is better than me at math, so are a lot of other people

its never a good idea to compare urself to friends

find people on ur level and study with em,

[finite ridge]

and im going to major in buisness and uh well contest math isnt really the most useful for like being a consultant (i think)

something in buisness or just buisness

[finite ridge]

tru ig but like it's kinda hard to avoid bc he shows off a lot

[chilly trail]

i mean its always good to keep the brain sharp

[finite ridge]

fair fair

[chilly trail]

well then he a bitch lmao

[finite ridge]

lol

[chilly trail]

half joking

[finite ridge]

he like actually doesnt have social skills tho

can i friend u? u seem p chill

if nah thats g

[chilly trail]

i already friended u

[finite ridge]

1 step ahead

anyways cya imma close now

/close

wait

whats the command

i frogoror

.close

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[tepid oak]

Hello, I'm new here. They say the smartest question of all is 2x+3, is that true? Or can someone prove me wrong.

[topaz sinew]

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[slate spade]

gelo

[slate spade]

i need help

i wasnt in class for 4 weeks

due to illness

i missed every lesson

this is the hw

i really need to do this

can someone help

nobody be helping

[topaz sinew]

@slate spade Has your question been resolved?

[slate spade]

bro no

it hasnt been resolved

[topaz sinew]

@slate spade Has your question been resolved?

[slate spade]

still no.

[topaz sinew]

@slate spade Has your question been resolved?

[slate spade]

NO

[golden mesa]

what do you know

[golden mesa]

did you ask for notes or something

[topaz sinew]

@slate spade Has your question been resolved?

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[neon iron]

I really don't understand what is happening here 😭

[neon iron]

Like, for example,
12 = 2 * 2 * 3
And the sum of these factors is 7

But if I use the generalized form given in the pic, I get 35/2.

I just want to know whether that generalized form is correct or not

Also I'm confused about the second point.

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[shrewd stirrup]

I don't know how to approach Problem 5. I can follow along with the hints and understand what's going on, but I don't know where to go from there (Problem 4 included so you can see what the 2nd hint is referring to)

[versed cairn]

by the ` they mean differentiate right?

[cursive thorn]

Hint: you can write a as e^ln(a)

nvm, didn't read the bottom

What happened when you tried doing that?

[shrewd stirrup]

Here's me following along with the hints

[cursive thorn]

If you have e^(tln(a)) you can directly differentiate

the "t times" doesnt really make sense here since t doesn't have to be an integer

[shrewd stirrup]

So e^(tln(a)) matches the form of e^(bt), right? Then e^(tln(a))' should take the form of be^(bt). But the derivative of e to anything is just itself, though right? Which does not take the form be^bt

[cursive thorn]

The derivative of e to anything is not always itself, take e^ln(t) for example, the derivative isn't e^ln(t), but 1, since e^ln(t) = t

You have to use the chain rule

[shrewd stirrup]

We haven't covered the chain rule yet 😅 This exercise was for the product rule

[cursive thorn]

that doesn't matter since the derivative of e^(bt) is already given, to derive this you use the chain rule, but here you don't have to

So what is the derivative of e^(t * ln(a))?

[shrewd stirrup]

e^(t * ln(a)) = e^ln(a^t) = a^t
a^t' = ta^t-1? Or is that completely off base

[cursive thorn]

Yeah, that's wrong. You can't use that formula when the variable is in the exponent

But the derivative of e^(t * ln(a)) is already given, if you set b = ln(a)

[topaz sinew]

@shrewd stirrup Has your question been resolved?

[shrewd stirrup]

So all I really need to do is plug ln(a) into b in the derivative? I'm still not exactly sure what rule that is coming from. Is that a property of e?

Ohhhhh, I see 😁

I still don't quite get why the derivative of e is that, but I guess that's not really part of the question

[gray storm]

Chain rule and the fact that d/dx e^x=e^x

[shrewd stirrup]

I've not covered chain rule yet, so I'll keep that in mind when I do

Thanks all!

.close

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[fierce zealot]

For part 3

.close

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[hasty fossil]

can someone explain what integrals used for like explaining to a brainless monkey, im just curious abt that what it does (i know basic functions idk how to describe but yeah)

[pastel oracle]

finding areas under a curve is a major use

[ionic oar]

Generally speaking it gives you the combined effect of small changes

If you mean real world applications

[hasty fossil]

uhhh.

[hasty fossil]

how come?
like what i can use it for?

ive seen many things especially

the edx near an integral

[ionic oar]

the what?

You can find the centre of mass for example

$\frac 1M \int_S r\dd{m}$

[thorny flame]

NEON

[pastel oracle]

maybe study this stuff on Khan Academy: https://www.khanacademy.org/math/integral-calculus

[ionic oar]

You can use it to calculate work done $\int \vec{F}\cdot \dd{\vec{x}}$

[thorny flame]

NEON

[ionic oar]

Bunch of other stuff

huge range of uses in physics

[pastel oracle]

tbh your question is kinda like asking "what can I use computers for", it's too broad

[topaz sinew]

@hasty fossil Has your question been resolved?

[hasty fossil]

prob thats because im so dumb, i didn'T see that in school thats why it makes no sense to me right now ig, i will learn in 2 weeks, thanks

[topaz sinew]

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[devout mist]

there is a single round robin tournament with 7 teams
top 4 qualify for next stage (no game can end in draw)
assuming there are 2 really good players who beat everyone except 1 of each other, how much of a chance is guaranteed to qualify with 3 wins in 6 games?

[devout mist]

.close

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[devout mist]

.reopen

[topaz sinew]

✅

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@devout mist Has your question been resolved?

[topaz sinew]

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[devout mist]

.reopen

[topaz sinew]

✅

Please don't repeatedly close and claim a new channel with the exact same question. This erases all previous progress made towards your problem and is confusing for helpers, making it more difficult to help you. Please be patient, even if your channel has not received much attention.

@devout mist Has your question been resolved?

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[odd pagoda]

power set

probably

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[snow musk]

Hello I was wondering if anyone knows how to find the average of 2 p values?

[snow musk]

its for hypothesis testing

[lapis raft]

wdym by average?

mean?

[snow musk]

I have two p values, one states that my results are not significant while the other states my results are significant so Id like to find the mean of it to figure out if overall my hypothesis is significant or not

but im not sure if im allowed to just average the p values using the usual method of adding the two values together the dividing by 2

[lapis raft]

why not?

[snow musk]

I searched up online and a lot state i have to use chi values and stuff but I wasnt rly sure if i was allowed to just average?

[lapis raft]

guess what

there are many averages

geometric, harmonic

[snow musk]

im referring to mean

[lapis raft]

then adding and dividing is fine

[snow musk]

alright then

thanks

.close

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[scarlet pivot]

Why can dy/dx * x/y be rewritten as dy/y * x/dx

[lapis raft]

dy/y is change of y by y

so it's nonsense

[scarlet pivot]

wait maybe

i put stupid question

there

dy/dx • x/y = dy/y * x/dx

why and how

[lapis raft]

yes, you can use it that way

anyways that's weird

[scarlet pivot]

?

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[scarlet pivot]

.close

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[plush prawn]

$\sum{i=0}_{h}2^i$

[plush prawn]

.close

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[delicate cradle]

How do I do this

If someone could just walk me through it as I do not understand it and it is in my test coming up

[hasty sail]

Uh hello

you should make an attempt before asking

just try so its easier to help in which concept your going wrong

hint: ||try and get a common denominator||

[delicate cradle]

Ok but do I first need to times both denominator by 2 or no

Because of the front 2

[hasty sail]

common denominator is x^2 - 4

so i'd multiply and divide 2 by x^2 - 4

[delicate cradle]

Yeah I got that

[hasty sail]

multiply the second term wiht x+2

the third term with x-2

and simplify

[delicate cradle]

Wait one second

So after I got $x^2-4$ what do I do

[thorny flame]

Yakin_OmegaΩ

[hasty sail]

???

thats what the question is dawg

add the "X" terms and constants to get Ax+B

divided by x^2 - 4

[delicate cradle]

This is what I got

So do I multiply 2 by numerator

?

[neon iron]

a= 3 , b = -18

[thorny flame]

Yakin_OmegaΩ

[delicate cradle]

First one is wrong sorry If I can ask Why did you times $x^2-4$ by 2

[thorny flame]

Yakin_OmegaΩ

[delicate cradle]

On the numerator part

Close

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[vestal otter]

can someone help me with c. of example 3 using law of syllogism

[vestal otter]

i tihnk i get the idea sort of but idk how to write it

[gritty trout]

i'm not sure how to help you write it, other than to say what is the point and what is the line segment?

[junior pumice]

write what

they showed it in logic

p -> q (p implies q)
p      (p is true)
-------
q      (then q must be true)

[vestal otter]

the point is M and the line segment is AB

[vestal otter]

i gotta write a conclusion

[gritty trout]

i feel like this is mainly an exercise in english and substituting symbols for the words that describe them. it's hard to explain how to do it without appealing to just logic

like, in a., you had "she"

[junior pumice]

if (a point is a midpoint of a line segment), then (that point divides the line segment into two congruent segments)
(M is the midpoint of AB)

M divides AB into two congruent segments.

[gritty trout]

this later became "mary"

[vestal otter]

okay thank you

idk why we gotta learn this

[junior pumice]

its logic. extremely important for higher math and computer science type curriculum.

[gritty trout]

it's the rationality that's built inside of you as a human

its less of learning and more of recalling something you already know to gainmore proficiency in it

[vestal otter]

okay

[junior pumice]

it may seem redundant right now, but this is the building up of your knowledge to meet a tougher challenge later on. i assume this is the beginning of a logic course.

[vestal otter]

what about

b. if a polygon is regular, then all angles in the interior of the polygon are congruent
if a polygon is regular, then all its sides are congruent

[vestal otter]

i gotchu

[junior pumice]

these are two implications and no statements. what is the problem asking for?

[vestal otter]

use the law of syllogism to write a new conditional statement that follows from the pair of true statements.

[junior pumice]

both are implying that if a polygon is regular, then (...), so we have one condition for two implications. just combine both statements into one. in logic this is the same as

p -> q
p -> s
------
p -> q ^ s

[vestal otter]

so would it be

if a polygon is regular, then all it's sides and angles in the interior are congruent

[junior pumice]

yeah, sounds good to me.

q <-> s is another conclusion of this

you can write if all angles in the interior of a polygon are congruent, then all its sides are congruent

without seeing the rest of the problems i couldn't tell you which is "more correct"

[vestal otter]

ohhh

okay i get that

.close

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[inner meteor]

I don’t understand where I went wrong

[acoustic pecan]

you cant combine the fractions like you did

and $a^b - a^c \neq a^{b-c}$

[thorny flame]

AℤØ

[acoustic pecan]

they need to have a common denominator

everything after the 4th line is illegal

[inner meteor]

Okay, so can I simplify 4th line or no?

[acoustic pecan]

multiply the numerator and denominator of the left fraction by (4x-1) and then you can combine them via the subtraction

though im not sure how much simplifying is really going to occur

[inner meteor]

Okay thank you 😊

[acoustic pecan]

id probably leave it as it is tbh

no prob

[inner meteor]

.close

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[mental harness]

30 people are at a sleepover and voting on movies to watch. They each vote on one of 12 possible movies randomly. What is the expected number of movies that nobody voted to watch?

[mental harness]

is it sum from 1 to 11 (n/12)^30, then times that by 12

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[wet moat]

#help-21｜아리스킨충1 its super easy its like 4 grade do it for me just pls

it’s number line fraction

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Please do not advertise your help channel or thread in other parts of the server. There are many people who need help, and no one person can be prioritized over other people, so please patiently wait. Anyone who chooses to help you is a volunteer who is doing so out of their own kindness.

[wet moat]

come on

[meager ledge]

<@&286206848099549185>

[worthy storm]

don't spam in other people's channels

[wet moat]

ok i wolnt

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[limpid mica]

i am trying to solve this DE. I tried using order reduction and then integrating factor, but im not getting something i know what to do with

[limpid mica]

wait oops

i wasnt supposed to use integrating factor

i got it now

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[hushed cipher]

Could someone check if I did this right?

[spare monolith]

What do you mean by new domain? What does the original question say?

[hushed cipher]

The original domain was

-180 <= x/2 <= 180

i mena

-180 <= x <= 180

yeah wait lemme redo this i think i did something wrong

[hushed cipher]

Hey would this be correct

as like the domain for U

i know i have to redo the whole question

[spare monolith]

Do you have a picture of the original question?

[hushed cipher]

No, not really my friend just gave me this question.

as in like he wrote it out

Wait but I can write it out if youd like

$cos(\frac{x}{2}) = -\frac{\sqrt{3}}{2}$ where $-180 <= x <= 180$

[spare monolith]

I'm getting a whole different angles outside of your domain. I might be doing something wrong, or the question isn't clear.

[thorny flame]

0_0

[hushed cipher]

Yeah I think the answer was no solutions in the domain

[spare monolith]

That makes sense then.

[hushed cipher]

Wait lemme redo the working out and see if i get the same answer

[hushed cipher]

could u just

tell me if

this new domain is correct

[spare monolith]

The key in such problems is to apply cos^-1 on both side.

[hushed cipher]

for u

[spare monolith]

You don't have to change the domain. Let it be as it is.

[hushed cipher]

Oh alr

Actually I just realised

-90 degrees to 90 degrees is positive for cosine

and since it says

cos(x/2) = -sqrt(3)/2

There aren't any solutions

[spare monolith]

That's also a solution.

[hushed cipher]

hm?

Oh u mean thats also a correct answer?

[spare monolith]

My bad, it isn't

[spare monolith]

No, it isn't.

[hushed cipher]

Wait so let me this clear, there aren't any solutions correct?

[spare monolith]

For a angle of 260, it gives the angle of 130, which is negative cos value.

[spare monolith]

Yeah.

[hushed cipher]

angle of 260 is outside the domain though isn't it?

[spare monolith]

If x is a angle of 260.

[hushed cipher]

but then x would be outside the -180 to 180 domain

[spare monolith]

Argh, my brain isn't working.

[hushed cipher]

Since A and C are positive that means there aren't any solutions correct?

[spare monolith]

You're right.

[hushed cipher]

thank you.

.close

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[nocturne remnant]

4(k+3)+2=4.5(k+1)

[ocean hare]

are you trying to solve for k?

[nocturne remnant]

How do I solve this?

Yes

[ocean hare]

have you heard of distributive property

[nocturne remnant]

Yes

[ocean hare]

do you know how to apply it to 4(k+3) + 2

[nocturne remnant]

Yes

[ocean hare]

can you do it for me?

[nocturne remnant]

4k+12+2

For the left

[ocean hare]

good

simplify it more now

[nocturne remnant]

4.5k+4.5 for the right

[ocean hare]

yes

so what's your equation so far

[nocturne remnant]

4k+14=4.5k+4.5

[ocean hare]

ok good

now collect like terms

[nocturne remnant]

Do I bring the 4.5 over to the left

[ocean hare]

you could do that yes

[nocturne remnant]

Or should I bring the 14 over

[ocean hare]

either way works

[nocturne remnant]

Then do I bring the 4.5 over to the 14?

@ocean hare

[ocean hare]

i would recommend that yes

because it would not give us a negative number

it seems to me you already know how to do this lmao

[nocturne remnant]

So it would be 9.5

[ocean hare]

yes

[nocturne remnant]

Do I minus 4.5k-4k

Ok

I got the answer it’s 19

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[grizzled charm]

Struggling to understand what to do.

Have to use an augmented matrix turned to rref to solve btw

I have the answer I'm supposed to get and the equations but dont understand them

[fallow harness]

i'm not sure what the fancy words mean but can you just do

P=30
W=2L
L=W/2
P=W+2L
30=W+2L
W=30-2L
W=30-2(W/2)
W=30-W
2W=30
W=15
30=15+2L
15=2L
15/2=L

[grizzled charm]

Wait so why is it -2l

[fallow harness]

30=W+2L
(subtract 2L from both sides)
30-2L=W

[grizzled charm]

So W is the wudth, L is length

ok

So you set the two sides as the same variable and made equations?

[fallow harness]

L and W are interchangeable for other letters, I just used them for convenience sake. L is the length of the two sides that are equal, and W is the length of the side that is double L

hence W = 2L

[grizzled charm]

Ok

So how can I write this problem into a system of equations

Cause I get the logic behind solving like that but

I need to understand how one would solve it like this

With 3 variables and matrices

[fallow harness]

what math class are you in

[grizzled charm]

Algebra 2

[fallow harness]

thats so interesting, i never had to use matrices for something like that

[grizzled charm]

Neither have I my teacher has never used matrices like this

But this is his sheet its not from the textbook

But I can solve normally just dont get how with matrices

[fallow harness]

in the above picture you sent. x, y, and z represent each individual side length

[grizzled charm]

Ok

So why did they set two equations to zero

For the 1st equation x+y+z=30 makes sense

But why -2x+0y+z=0? Why not 2x+z=30? I tried making them like that, as well as the inverse but it didnt work

[fallow harness]

weird im in calculus and i dont quite understand. sorry bro, i would try to figure it out if i had a bit more time but id recommend asking chatgpt if nobody else helps you

[grizzled charm]

A dude in dms just plugged his mathgpt thing

A few minutes ago have you used it?

[fallow harness]

nah i usually use chatgpt but i might try it

send to me

[grizzled charm]

Ok

.close

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[violet solar]

i dont understand how courageous, intelligent and ambitious are equivalent

[topaz sinew]

@violet solar Has your question been resolved?

[violet solar]

damn

???????

lol

[odd jacinth]

any x > 0 is nor courageous, nor intelligent, nor ambitious
and any x < 0 is courageous, intelligent and ambitious

so to tell that the 3 are equivalent

you need 0 to be either the 3, or none of the 3

and 0 is the 3

[violet solar]

hi, i understand what you mean, but 0 cannot courageous

[odd jacinth]

that's where you're wrong

[violet solar]

mmh

[odd jacinth]

for all a > 0, 0 < a

0 is courageous

[violet solar]

ok I understand, thank you so much

https://tenor.com/view/nodding-happy-yes-yeah-agree-gif-9470192629442860968

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[ruby bluff]

for 1h how would you do it

if all of them are constants

[topaz sinew]

@ruby bluff Has your question been resolved?

[odd jacinth]

1+omega+omega² = (1-omega^3)/(1-omega)

since omega is not 1, denom is not 0, and numerator is since omega^3 = 1 by def

[ruby bluff]

how does the denominator not being 0

make the whole thing equal -1

[odd jacinth]

the denom is (1-omega)

since they tell you omega is not real, it's not 1

so 1-omega is not 0

[ruby bluff]

wait i still dont get it

where did you get 1+w+w^2

from

isnt it a+bw+cw^2

1-w^3/1-w

[odd jacinth]

I don't understand what you're saying

[ruby bluff]

wait were talking about this question right

[odd jacinth]

oh that's what you meant by 1h

[ruby bluff]

yea

mb

[odd jacinth]

my bad tired, I read 1h or idk what I read

the trick is that you can multiply a fraction by w/w

or w^2/w^2

without changing it's value

[ruby bluff]

oh

wait

thats smart

[odd jacinth]

for example (a+bw+cw²)/(b+cw+aw²) = w²(a+bw+cw²)/w²(b+cw+aw²)
= (aw²+b+cw)/(bw²+c+aw)

[ruby bluff]

oh ok

but then how would you cancel everything out

if you dont know what a and b is

cos if a is bigger than b

[odd jacinth]

you can do what I did with the 2 fractions

so maybe you can get a sum that simplifies nicely

[ruby bluff]

ohh

ok ok

tyty

ill try that

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[topaz elm]

how do i do this

[royal glacier]

I'll tell you what I learned in school

lets say x is that number

try multiply it by 100000, so that first repeating section comes in front of the decimal point

then what is 100000x?

[topaz elm]

129789.789...

[royal glacier]

then sub it by original x

point is that decimal points are being erased

so 99999x=?

[topaz elm]

129788.492?

[royal glacier]

ah sorry

sorry for the confusion

sub by 100x

to make decimals equal

I mean so 100000x-100x

[topaz elm]

ohh

129660

[royal glacier]

so 100000x-100x=12789.789... - 12.789...

yes

so 99900x=129660

then x=129660/99900

[topaz elm]

oo that is a neat method

[royal glacier]

so ratio of two integers

[topaz elm]

thank you

[royal glacier]

np

[topaz elm]

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[chrome magnet]

Given, $ab+bc+cd=0$
Prove that:
$x^{\frac{1}{a}}\times x^{\frac{1}{b}}\times x^{\frac{1}{c}}=1$

[thorny flame]

neon

[karmic dove]

looks interesting

[sharp dew]

yes

[haughty wren]

unsure but if you use exponent properties and combine 1/a + 1/b + 1/c, you might get what you want

[karmic dove]

i think here is mistake

[chrome magnet]

That gives $x^{\frac{bc+ac+ab}{abc}}$

[thorny flame]

neon

[karmic dove]

instead of cd i think should be ac

[chrome magnet]

and i don't know how to prorgess further

[chrome magnet]

maybe

[haughty wren]

wait where does d come from?

[chrome magnet]

given in question

[haughty wren]

then please post full question :\

[inner arch]

it's there

[chrome magnet]

what? thats the full question

[haughty wren]

Are you sure? Because what Filga says makes sense. It would become x^(0/abc), x^0, 1

so did you misread a d?

[chrome magnet]

I guess it's a mistake in the book itself, let me post the image of the question

[haughty wren]

yeah please do

[chrome magnet]

,rotate

[chrome magnet]

there @haughty wren

qno 41

[haughty wren]

that's odd

[chrome magnet]

So i guess the question is wrong, I'll inform my math teacher later today

[inner arch]

yeah, definitely wrong

[chrome magnet]

thanks both of you!

[inner arch]

you can find values for abcd that fit the first equation where the second is absolutely false

[chrome magnet]

yeah...

ty

.close

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[heady ridge]

How would I simply this?

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[lean bone]

how do I do this 😭😭😭

I will marry you if you help me

[empty sail]

You factored out a GCF, right?

[lean bone]

yes!!!

here’s where I got somehow

[empty sail]

What happened to it?

[lean bone]

I thought I did something

[empty sail]

The GCF is x, and you factored that out

[lean bone]

yes

[empty sail]

But you never included it

[lean bone]

oh 😧

[empty sail]

It's not in your roots or factored form

[lean bone]

it kinda is

I think???

it’s on the outside?

[empty sail]

I don't see it on the outside here

[lean bone]

OH

BUT IS THIS INSIDE RIGHT

J DONT KNOW…….

[empty sail]

Yeah

You didn't include the x in your factored form

[lean bone]

OKAY 👍👍

AHHHH

THE ASSIGNMENT CLOSED

I WILL JUST CRY MYSELF TO SLEEP NOW

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[vital dragon]

whaaa… i literally just don’t get it at all sorry

[karmic dove]

you need to use transformations of functions

shifting functions up and down, left and right, that sort of things

[strong roost]

does parabola congruency mean it has the same x^2 coefficient

[karmic dove]

i presume that's what it is

[vital dragon]

i have no idea what’s going on

i’m only in gr11 btw idk if that will change anything

i’m smooth brain

[strong roost]

a(x-h)^2+k is vertex form

[karmic dove]

not the same but the same by absolute value

[strong roost]

assuming that's what congruency means a has to be -2/3

i think

[karmic dove]

yes

[strong roost]

the function is greatest when (x-h)^2 is 0

so k is 5 and h is -4

so yea

[karmic dove]

https://www.mathsisfun.com/sets/function-transformations.html

[vital dragon]

wait so like

my equation is y = 2/3x^2(x+4) + 5