help-26

[barren lion]

so (10x^2+29)/(4x^3+2) < epsilon + epsilon^3 < 2*epsilon

if epsilon > 1, then epsilon < epsilon^3

so (10x^2+29)/(4x^3+2) < epsilon + epsilon^3 < 2*epsilon^3

so you just need to adjust epsilon accordiningly (in the epsilon < 1 case, use N = 20/epsilon)

yes

[neon iron]

apologies btw

gonna be gone for about 7-10 mins

right

.close

[topaz sinew]

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[neon iron]

0 clue how to do this

[tranquil coyote]

the image isnt clear enough

[neon iron]

I got you

[glass rain]

opposite angles are equal

[boreal leaf]

Angle between 2 lines are equal

[glass rain]

interior angles of triangles sum to 180

[neon iron]

So

The 2 lines are 180 ik that

Its asking to solve for X

[tranquil coyote]

upload only the diagram

its still not clear

[empty sail]

Just click on the picture

[glass rain]

yeah equate it to the angle

[tranquil coyote]

i did

[empty sail]

It's clear if you click on it

[empty sail]

You should know these

[tranquil coyote]

the diagram

[empty sail]

Click on the picture

If I can read, so can you

[neon iron]

I was sending them separately

[tranquil coyote]

it looks like this my friend

[empty sail]

@tranquil coyote There's this one

Which is readable

[tranquil coyote]

y = 56/8

=7

[topaz sinew]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[tranquil coyote]

i can solve this

i ll try to send a pic

[topaz sinew]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[neon iron]

Okay thanks

[topaz sinew]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[empty sail]

You should apply these concepts

Knowing that info, you can create an equation to find x and y

[neon iron]

Alright so i got 4

Is that correct?

[tranquil coyote]

yes it is

well done

[neon iron]

Alr thanks

[topaz sinew]

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[meager apex]

I'm actually stuck trying to factor it here

[polar comet]

What are you having concern with

You good?

[winged moat]

You don't have a term with x

[polar comet]

I don't think need you one

[winged moat]

Not sure why do all of this then

[polar comet]

It's just normal equation

[winged moat]

Just put the constant on one side, divide by 2

and take positive and negative root

And you've got x

[polar comet]

yea

You got two solution for this algerbra

[winged moat]

One gets discarded

Obviously can't have a side with a negative length

[polar comet]

You can only use the one that is positive

Because the height cannot be negative

Otherwise this will be dramatic

[winged moat]

Maybe in another universe 👀

[polar comet]

He's not answering us

Disrespectful😡

JK😋

[winged moat]

Also nothing to factor here except factoring out 2

I guess they just thought there's an x next to -142

[meager apex]

oh

[meager apex]

so just divide both by and square root htem

?

[winged moat]

You're solving for x

$x^2 + x^2 - 142 - 2184 = 0$ equals \ $2x^2 - 2326 = 0$

[thorny flame]

USS-Enterprise

[winged moat]

How do we solve this?

[polar comet]

This question is the weirdest question i've seen in my life

I havn't seen any big values like this

[meager apex]

lmaoo

[polar comet]

7220

jesus

[meager apex]

the last one was 5 digits

[glass rain]

this should be 142x no?

[polar comet]

I know why do american always use calculators

[winged moat]

Oh nevermind I see the confusion!

I was only looking at the second line

Of course, you forgot an x at -142

You've got 2 * x * 71

[meager apex]

oh

[winged moat]

Thank you

So what you are doing is actually correct but you forgot an x

So anyway

[meager apex]

i see

[winged moat]

We have $x^2 + x^2 - 142x -2184 = 0$

[thorny flame]

USS-Enterprise

[meager apex]

right

[winged moat]

What do we do?

[meager apex]

for whatever reason i was stuck factoring it

at this part

[winged moat]

Have you learned the quadratic formula yet?

[meager apex]

I was thinking if i could use the quadratic formula

[winged moat]

Ah

[meager apex]

but it was 4 digits

a b c d

[polar comet]

bro

I usually don't do like this

[winged moat]

no

What's $x^2 + x^2$

[thorny flame]

USS-Enterprise

[polar comet]

But i guess this question is from the united states of america

[meager apex]

x^3

oops

[winged moat]

No

[meager apex]

2x^2

[winged moat]

Yes

[polar comet]

2x^2 bro

[meager apex]

ahhhhhh

ok

[winged moat]

So you've got $2x^2 - 142x - 2184 = 0$

[polar comet]

2x=x+x

[thorny flame]

USS-Enterprise

[meager apex]

ima draw it rq

[winged moat]

You see all numbers are a multiple of 2

So my suggestion divide by 2

Then use the quadratic formula if you can't find nice numbers to factor

[meager apex]

nearly done

[polar comet]

jesus crist

[meager apex]

was running out of space

[polar comet]

huh?

wait

Aren't that suppose to be 14x

How do you get 142

[meager apex]

142

[polar comet]

I don't get it

[winged moat]

Didn't use my suggestion 😦

[glass rain]

nah

its 71

not 7

[meager apex]

oh

didn't see

[winged moat]

Yeah

It's a good thing to see

Makes your life easier

[polar comet]

Wait for me

[meager apex]

want me to restart

[winged moat]

always try to simplify as much as you can

[polar comet]

I'll show you the full solution of solving it

[winged moat]

honestly I can't read what you wrote so I have no idea if you are correct

[meager apex]

not done just yet

[winged moat]

And everything is divided by 2a, not just the root

[meager apex]

i don't think this is right tho

[polar comet]

Why are you putting so many root

You are making it look worse then before

No one is going to understand the step of solving it

BRUH

[meager apex]

idk

[glass rain]

iits right tho

its 37636 though

which would be the square root of 194

[polar comet]

You're not going to do any other question like that

[glass rain]

then continue using the quadratic formula

i mean if you have a calculator you could

[winged moat]

ah sqrt(37636) = sqrt(194)

😅

[glass rain]

i was just saying that he was on the right track

[meager apex]

yea idk why i wrote that

its on my calculator

😭

[glass rain]

instead of forcing your method?

[meager apex]

ok

so 142 square root 194/4

[winged moat]

How'd you get to 141

[glass rain]

cause doing your method would also lead to the same answer

[meager apex]

142

[glass rain]

but in the form of x^2-71x-1092=0

[winged moat]

Yes. Would make their life quite easier

[glass rain]

idk depends

[glass rain]

for this you'd need trial and error

for quad eq you'd need a calculator

[winged moat]

I mean

You can solve both with the quadratic formula

[meager apex]

where would i go from this tho

[winged moat]

Easier to divide by 2 low numbers than later square 71 and multiply by (-2184) even on a calculator

[winged moat]

I have no idea what this means

[glass rain]

no square root anymore

and you forgot the +-

[meager apex]

though 142 +/- 194/4 isn't the answer

[glass rain]

and 4 is over 142+-194

[meager apex]

oh it is

[glass rain]

not just 194

[meager apex]

lmao

142+194=336/4 = 84

there we go

[winged moat]

$x_{1,2} = \frac{142 \pm 194}{4}$

[meager apex]

x=13 or 84

👍

[thorny flame]

USS-Enterprise

[glass rain]

not quite

[glass rain]

yeah 13 is negative tho

[meager apex]

ah ok

[glass rain]

but yep

[meager apex]

thank you guys

writing it all down

[polar comet]

bruh

Jesus

Sorry

I blamed on you

This quesiton cannot be done without using calculator

The worst ever

[glass rain]

its 84 and -13 lol

[meager apex]

its pain

lmao

all good thank you winster

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[polar comet]

-13

[polar comet]

lol

[polar comet]

Bro this ticket will be close

[boreal leaf]

Use another free channel @sour axle

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[brazen shale]

Bit stuck on this 3d vector geometry question, could use some help

Im stuck on part c)

Ik what to do but checking my answer in geogebra and it seems wrong

Here is my work so far

ah wait

think i found my mistake

yup

stupid sign errors

nvm

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[hard glacier]

i need to do this,please help with homework

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[naive vigil]

can somebody tell me if the answer to part d is just 2-3j

[uncut crow]

is j just the imaginary unit?

[naive vigil]

yes

[uncut crow]

Then yeah, I think (d) is just by definition 2-3j

[naive vigil]

thanks man

just double checking

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[fiery aurora]

Hi can someone help me with this maclaurin expansion please

[fiery aurora]

Idk where I’ve gone wrong

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[north sparrow]

yo

check dms

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[burnt ocean]

Why on the second one, the sign is <12 not <=12

[burnt ocean]

This is the answer key

[elder heath]

Must have been a typo since the words clearly say it is meant to be inclusive

[burnt ocean]

So.. it SHOULD be <= 12?

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[north sparrow]

yoooo i got you something

[north sparrow]

@urban thicket

[placid halo]

Adi what's ur question?

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[north sparrow]

.closr

.close

oh nvm

[north sparrow]

.close

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[graceful leaf]

ignore the X it was from my previous answer

[graceful leaf]

in accordance with this graph would question c be correcT?

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[urban thicket]

.reopen

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[topaz sinew]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[open citrus]

2

I’m not sure if what I’m doing is correct

[tropic gull]

2^3=y/4

y=4*2^3

y=32

[topaz sinew]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[tropic gull]

logab=c

a^c=b

[open citrus]

where did y go though

we can just bring it to the other side?

oh wait you multipled by 4

[tropic gull]

its just log base rules

[open citrus]

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[floral shard]

how do i do this

[sweet shard]

Factor

x(1-x) = ?

[floral shard]

i got to cost (1 - cost)/t

but idrk where to go from there

[boreal leaf]

1-cost/t

As limit approaches zero

What is it equal to?

[floral shard]

0

[boreal leaf]

That's iy

Answer is 0

[sweet shard]

cos0=1 so you use limit laws

,tex .limit rules

[thorny flame]

riemann

[floral shard]

ohhhh

[sweet shard]

Product

1*0=?

[floral shard]

is 0

i got it

tysm

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[neon iron]

Stuck on this part of the problem. Honestly just guessed for the first two boxes

[neon iron]

I think the part I got wrong is supposed to be standard deviation… but I don’t know which standard deviation and which formula… there’s so many

I get the 0.68 is the mean of the proportion, but I don’t get why it’s not 34/44, I thought that would match p hat

[topaz sinew]

@neon iron Has your question been resolved?

[keen venture]

You're using a normal approximation of a binomial distribution, so the binomial distribution SD is what you want

SD = sqrt(npq)

@neon iron

[neon iron]

Ahhhh

Wait how do u know it’s binomial distr

[keen venture]

The probability any course is taught by a full-time is 68%
What's the probability that, of 34 courses, at least 33 of them are full-time? That's given by a binomial distribution

You're using a normal approximation to actually get this probability though. So we construct a normal distribution by using the binomial's mean and SD

Sorry, I forgot about a needed division.

[neon iron]

Ahhh this is very helpful I will save that graphic. Thank you so much!

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[lucid junco]

Finding the region bounded by the curve y = 1/2 and y = sinx for the interval pi/6 to 5pi/6. Is this correct? I found the solutions for sinx to conveniently be the exact values as the provided bounds in the question so I guess I don’t need to do anything else other than this?

[knotty ledge]

The area between the curves would not be the area you've labelled A

[lucid junco]

Oh

[knotty ledge]

But the area above it, between the curves

[lucid junco]

Ohhhhh

Okay that makes sense

[junior acorn]

the integral you have written is correct but wrong diagram

[lucid junco]

But is the integral I wrote correct? Besides the area labelling

Okay

Cool

[knotty ledge]

Yeah you stumbled into the correct integral

[lucid junco]

Okay thanks I’ll fix the diagram

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[slate pelican]

Let B be a nxn-matrix, what is rank B and Null B, if the determinant is nonzero

[slate pelican]

i know that rank B + Nullity B = n

but i dont know how to proceed

[neon iron]

@slate pelican what is the rank of n×n matrix (by definition) if it is non-singular (non-zero determinant)?

[slate pelican]

the dimension of col/row space

[neon iron]

If the determinant is non-zero

What can you say about column vectors?

@slate pelican

[slate pelican]

they are linear independent?

[neon iron]

Yes

The matrix is n×n

[slate pelican]

so rank B = n then?

[neon iron]

So there are n linearly independent column vectors that form a basis of Rⁿ vector space (assuming matrix is real). Hence rank would be

n

Yes

[slate pelican]

ah, and then there is no Null space?

[neon iron]

Well

If the matrix is non-singular

There is a unique solution to Ax = 0

And A inverse exists

So this implies x=0 is the trivial solution

[slate pelican]

but then x = 0 is a basis for the nullspace?

oh nvn

there are no free variables so the dimension of the null space is 0

thx

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[humble nebula]

help

<@&286206848099549185>

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@humble nebula Has your question been resolved?

[humble nebula]

<@&286206848099549185>

pls help

pls ping too

[humble nebula]

.close

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[pearl grove]

Hey

[pearl grove]

How would I solve c if the formula calls for the first term

An=a1*r^n-1

[pseudo inlet]

Just a sec

[versed cairn]

let n=3

and then let n=6

[pearl grove]

Ok

[versed cairn]

a3rd = a1 * r^2
a6th = a1 * r^5

[pearl grove]

Ok

[versed cairn]

and then use the values of a3rd and a6th

a1 * r^2 = 9
a1 * r^5 = 72

then divide both equations so that u can get rid of the a1 and find the value of r

a1/a1 * r^5/r^2 = 72/9

and then use the value of r and find value of a1

[pearl grove]

Ok I’m writing it all down

R^10?

Then divide 72/9

Wait no

2.5

R^2.5

[versed cairn]

$$\frac{r^{5}}{r^{2}} = ? $$

[thorny flame]

JustToPro

[versed cairn]

never done this?

[pearl grove]

I have in algebra 2

You would multiply right

[versed cairn]

no

[pearl grove]

Add

[versed cairn]

same base , different powers when multiply add
same base , different powers when divide subtract

[pearl grove]

Ohh right right

R^3

[versed cairn]

yeah

[pearl grove]

72/9=8

R^3=8

Now I would plug it into A1

The 8?

[empty sail]

No you haven't found r yet

You have r^3

[pearl grove]

Ok

Find the value of r

Then use the values of r to find A1

After I have my r^3 how would I find the value of r?

[versed cairn]

$$r^{3} = 8$$
$$8 = 2^{3}$$

[thorny flame]

JustToPro

[pearl grove]

Ok

Thank you guys for the help

.close

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[buoyant girder]

can someone help me find the area

[buoyant girder]

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[twin schooner]

How do i solve this parametric equation?

[twin schooner]

I know how to solve parametrics, i just don't understand this one

[winged moat]

What do you have to do?

$\frac{m}{2}x + m = x - (m-1)x$

[thorny flame]

USS-Enterprise

[twin schooner]

Yes

[winged moat]

What would you do?

[neon iron]

.open

[winged moat]

#❓how-to-get-help

[twin schooner]

Gib moment. Eating rn if thats okay
Ill tell you in 10 min

[winged moat]

Take your time!

[twin schooner]

Could i give an example

Example

(sorry if cant read

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[tropic fern]

Berry

you have 3 vectors

in two dimensions

what does that tell you

that 1 vector can be expressed as sum of two other independent vectors

with that said you need only two independent vectors and the third is combinations of the two

@neon iron you can do this on another channel

two vectors are independent if a≠kb where a and b are vectors and k is scalar

does that make sense?

you need to be careful with the statements

matrix needs to have size NxN

and each vector in matrix needs to be independent or differently put the determinant of the matrix is ≠ 0

if you are not on a matrix with size NxN you are either looking at two vectors with 3 dimensions coordinates (spanning a plane) and their 0 is only when both vectors are 0

and the other case is your case

3 vectors in two dimension in that case it's impossible to have 3 independent vectors in a plane

you can try yourself and prove that statement by assuming the opposite

1 4
2 5
3 6

this one?

not quite those are two vector that lie on 3d but can only span 2d

but yes

if they are independent the only 0 is when both of them are scaled to 0

it doesn't matter

1 sec brb

what's your question exactly

for NxN matrix

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✅

[tropic fern]

if you reduce the matrix with whatever way and the leading columns are ≠0 you proved that whatever scaling you do on them, they still are independent to each other cause they can't be Expressed as a sum of two other vectors

all you are doing is applying scaling to each vector

i would suggest you check out 3blue1brown linear algebra he has one of the best explainings with visuals that really grind your intuition with matrices

it's not fun working solely with a big square bracket filled with numbers

there's always a bigger fish for example do you know what determinant of a matrix really means?

he has a pretty good video that explains determinants and how if determinant of a matrix is ≠ 0 it's a proof that the set is independent

yes

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[tardy vault]

A van merges onto a highway on ramp with a velocity of 52 km/h and accelerates at a rate of 2 m/s squared for 7.2 s

What is the displacement?

[drifting swift]

!status

[topaz sinew]

What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above

[neon iron]

!show

[topaz sinew]

Show your work, and if possible, explain where you are stuck.

[tardy vault]

Alr

(14.4)(7.2) + 1/2(2)(7.2) squared

156 m/s
@eragon... @drifting swift here

[drifting swift]

use the symbol ^ for exponents

[tardy vault]

Ah

[drifting swift]

also are you absolutely sure about your answer being 156 m/s and not 156 of any other unit?

also just to check...

,calc 52/3.6

[thorny flame]

Result:

14.444444444444

[drifting swift]

you may have rounded too crudely for the initial velocity.

[tardy vault]

155.8 was the answer

[drifting swift]

155.8 of what unit?

[tardy vault]

m/s

[drifting swift]

again, are you absolutely sure about that?

[tardy vault]

Yep

[drifting swift]

tell me

what kind of quantity does the problem ask for?

(looking for a word here)

(a word from the problem statement itself)

[tardy vault]

You're right it doesn't, but the teacher told us to assume it's m/s for all questions

[drifting swift]

???

[tardy vault]

huh

[drifting swift]

those were his exact words?
"whatever problem you do, ignore what kind of quantity it says it asks for, and always put the units as m/s no matter what"

[tardy vault]

idk bro

Yes

[drifting swift]

don't call me bro.

[tardy vault]

sorry

[drifting swift]

but also what the fuck is your teacher on

it's so nonsensical

[tardy vault]

no clue

[drifting swift]

i have trouble believing that he would really say that

the problem asks for a displacement, and displacements, like all distances, are measured in meters and not meters per second...

yet your teacher apparently demands that the units be transmogrified into m/s regardless.

[tardy vault]

ohhhh

Mb

[drifting swift]

which doesn't make any sense.

[tardy vault]

I meant meters

[drifting swift]

but you say your teacher forces you to do it.

WOW

WTF

[tardy vault]

Sorry

[drifting swift]

i asked you twice

[tardy vault]

Sorry I'm kinda sleepy

[drifting swift]

once you didn't answer, and the second time you said you were absolutely sure that you meant the wrong unit

if you are sleepy then why are you doing math

[tardy vault]

test

[drifting swift]

a test that's going on RIGHT NOW?

[tardy vault]

No

I'm studying it for it

It's tomorrow

[tardy vault]

are my steps right tho

[drifting swift]

they appear to be.

[tardy vault]

Alr

Thanks

Sorry once again

.close

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[cinder oxide]

"symmetric matrix", how would I find?

A symmetric matrix is a matrix that is equal to its transpose

so i just flip row for column and that is the answer here?

empty entries are considered 0's?

oh

A and A^T must be equal

got it

[drifting swift]

no, here they are blanks for you to fill.

[drifting swift]

yes, that's what "a matrix equal to its own transpose" means

[cinder oxide]

Row = Column, makes sense now

"symmetric" will remember this term

ty

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[molten crystal]

hi!
sometimes i find the + c is put before integration happens.

[molten crystal]

i think i understand that it makes no difference

is there some other reason why this is done sometimes?

is there just to remind that there will be another +c term ?

so you can carry on with the reasoning without having to solve the integral. ?

[topaz sinew]

@molten crystal Has your question been resolved?

[sweet shard]

well that +c is multiplying exp(-kt) out front

sometimes it's easier algebraically

but mathematically it's equivalent

[molten crystal]

ok 🙂 thanks

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[zealous rune]

hello can someone help me answer these questions

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[zealous rune]

can someone please help me

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[thorny kelp]

Does this seem right?

[golden mesa]

you haven't applied chain rule for differentiation

[thorny kelp]

I don’t see how it would differ from my approach? I would multiply down a power of 1 (keep the 3) and then cos2x would become 1 as it is to the power of 0 now, multiplied by the differentiation of cos2x which is -sin2x still makes it -3sin2x no? @golden mesa

Well I mean I know that I am apparently wrong but that is my current thought process

[golden mesa]

$(f(g(x))'=f'(g(x)),g'(x)$ where $f(g(x))=cos(2x)$

[thorny flame]

chlamydia

[golden mesa]

you are not applying this correctly

[thorny kelp]

Wait pause

Interesting

-6Sin2x?

[golden mesa]

yes

[thorny kelp]

Ok thank you

Does this now seem correct? @golden mesa

[golden mesa]

you really don't need to expand sin2x

[thorny kelp]

Good point now that you say that

[golden mesa]

also did you just say that 6x2=8

[thorny kelp]

God…

[thorny kelp]

This instead?

[golden mesa]

yup

[thorny kelp]

Thank you

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[mossy vapor]

300 deg counterclockwise about the unit circle is the same 60 deg clockwise about the unit circle. Both rotations refer to the same point along the circle

Since we define positive degrees as being those corresponding with counterclockwise rotation, the angles corresponding to clockwise rotations are negative

If you have an angle $\theta$, $$ \theta +n*360\deg \equiv \theta $$ where $n$ is any integer

[thorny flame]

thedude365

[mossy vapor]

You can only add/subtract integer multiples of 360 if you're trying to refer to the same angle

It's the same idea when reading an analog clock; 13 o'clock and 1 o'clock are the same time

(ignoring am/pm distinction)

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[dapper sparrow]

Am I messing up somewhere? this looks so wrong:

[sweet shard]

,w diff (ax +b) e^x

[thorny flame]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by rie.mann

[sweet shard]

,w diff e^x (ax+a+b)

[thorny flame]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by rie.mann

[dapper sparrow]

Ah

I see where I went wrong

thank you

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[supple rampart]

is the only possibility here to check is by getting matrix representation of the transformation

[knotty ledge]

you have two infinite dimensional vector spaces

(well just one, but twice)

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[strange topaz]

shouldnt the first answer be the correct answer

since they labeled the angels O and S instead of QOP and RST

<@&286206848099549185>

[split sky]

this is a modern geometry problem right?

[strange topaz]

yeah

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@strange topaz Has your question been resolved?

[civic dust]

my geometry is rusty but step 4 is wrong

side angle congruence aint a thing

[strange topaz]

yeah i noticed that too but the question says whati s the first error so shouldnt the angle being written wrong be a error too

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[raw canyon]

hey guys how should i do this problem? i tried solving for dy/dx and then moving the x over but my answer was wrong

[raw canyon]

<@&286206848099549185>

<@&286206848099549185>

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@raw canyon Has your question been resolved?

[vernal vale]

if it helps, you can make this into a function

then you can just treat it the way youd treat any old function y(x) where youre trying to find critical points

just isolate the y^2, then take the positive and negative roots

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[late ingot]

hey this is correct right? just makin sure

[late ingot]

.stop

[shrewd horizon]

it's .close

[late ingot]

ok

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[visual leaf]

I can't tell what I did wrong here

[keen venture]

f(x + h) = -(t + h)³

But you've got -(t - h)³

[visual leaf]

Wait but I learned it was supposed to be (t-h)

Nvm I see it now thanks

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[split badger]

can i get help on my practice final exam?

[split badger]

if someone can VC and i can share screen that would help alot

i dont know if im getting a calculator for the final exam

is it possible to figure this out without using a calculator

im pre-calc btw

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[split badger]

<@&286206848099549185>

[split badger]

<@&286206848099549185>

[split badger]

<@&286206848099549185>

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[unique dew]

Can i get help with calc hw

[unique dew]

Practice problems for my calc quiz tmr

[novel echo]

which part?

[unique dew]

21-31 are practice problems for quiz

[drifting steeple]

which question

[unique dew]

29

[drifting steeple]

Ok so for domain there are certain places where the equation is und

are you ever dividing by 0 for any value of t?

[unique dew]

-3

[drifting steeple]

so t cannot be that value

[unique dew]

How would i do the derivative part

[drifting steeple]

Use the quotient rule

one sec

[unique dew]

Okok

[drifting steeple]

that picture is hard to see lol

[unique dew]

Lol

[drifting steeple]

there

just follow that

if you need practice I can send you a youtube video for it

[unique dew]

Would appreciate it

How does this look so far @drifting steeple

[drifting steeple]

yup

[unique dew]

@novel echo

[drifting steeple]

thats it

[unique dew]

Okok

So through this I’m able to find the derivative?

[drifting steeple]

Yes

[unique dew]

Thanks

[drifting steeple]

https://www.youtube.com/watch?v=8jVDEcQ0wXk&

thats what i used to get through calc

glgl

[unique dew]

The domain correct?

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@unique dew Has your question been resolved?

[unique dew]

@drifting steeple is this the derivative of f(x)?

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[unique dew]

How do I find the derivative and domain of g(t)=1/root(t)

[drifting swift]

$t^{-1/2}$ can be differentiated with the power rule

[thorny flame]

Ann

[unique dew]

Wdym by that

Could you write it out for me?

[drifting swift]

do you know the power rule?

[unique dew]

Sorta

[drifting swift]

there's no sorta, you either do or you don't.

[unique dew]

Just searched it up like 30 min ago

This thingy right

[drifting swift]

$\dv{x} (x^p) = px^{p-1}$, yes

[thorny flame]

Ann

[drifting swift]

i'm saying that your function, 1/sqrt(t), is equal to t^(-1/2)

so this rule applies

[unique dew]

OHHH

[drifting swift]

kind of silly to apply the power rule to constants tbh

you're not wrong but it's very silly

[unique dew]

Yeah I was just tryna get used to the formula

@drifting swift

Would it be like this

[drifting swift]

you should not write your t's like this

give them a hook at the bottom so they don't look like plus signs

[unique dew]

Ooo

[drifting swift]

also you forgor the -1/2 coefficient out front

[unique dew]

Okok

@drifting swift hows this

[drifting swift]

you didn't fix what i told you to fix

you should redo this entirely

your last line is wrong in like 2 different ways

[unique dew]

Okok

@drifting swift

[drifting swift]

why did the t^(-1/2 - 1) slip down into the denominator

it's not supposed to do that

[unique dew]

Would the numerator be -1(t^(-1/2 -1))?

Confused

My bad

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[undone flicker]

How to solve this one?

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@undone flicker Has your question been resolved?

[jade thunder]

What have you tried

[undone flicker]

Tried to make augmented matrix

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[undone flicker]

.close

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[carmine pulsar]

im currently looking into the rubiks cube group and am confused if | G | = 43,252,003,274,489,856,000 is the order of the rubiks cube group or not. if its not, what is the order of the rubiks cube group then ?

[odd pagoda]

wikipedia says that it is

[carmine pulsar]

ahhh gtg ty for answer

.close

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[junior stratus]

Consider the following inequality $$t^4\geq C>0.$$ Is it correct that $t^2\geq \sqrt{C}$ or do we have $t^2\geq \pm \sqrt{C}$?

[thorny flame]

sunside

[odd pagoda]

well if t^2 is bigger than 5, then it is also bigger than -5

[acoustic tangle]

The latter is kind of ambiguous

But yeah like Denascite said you will have both t^2 >= sqrt(C) and t^2 >= -sqrt(C)

[junior stratus]

alright, thank you

.close

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[junior stratus]

.reopen

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✅

[junior stratus]

what if we take the sqrt once again, do we then have $$t\geq \sqrt[4]{C}\quad\text{and}\quad t\leq -\sqrt[4]{C}?$$

[thorny flame]

sunside

[odd pagoda]

(of course this only works here because t^2 is always >=0. had the question been about t^2 and t, then you would also need t <= -sqrt(C) )

[acoustic tangle]

Replace "and" with "or" and you will be fine

[junior stratus]

ok 👍

.close

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[crimson falcon]

need help

[crimson falcon]

is the answer - 3x+1/2x+3

[leaden tusk]

as long as that - isn't a negative, yes

remember parenthesis, though

what you wrote implies something different from what you actually meant

[crimson falcon]

oh

alright thanks

.close

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[icy falcon]

Can you solve this?

[icy falcon]

<@&286206848099549185>

[tough cargo]

!work

hmm wrong command

well what have u tried so far

[icy falcon]

I have one of the answers, but there is a family of solutions

[tough cargo]

hmm there's not that many possibilities I think

[icy falcon]

The solution I got was 4

But it’s one of many

[tough cargo]

Yeah ik

But many is too strong it's more like a few

What'd you do to find the 4 solution

[icy falcon]

My senior friend found all of them in 5 minutes using matrices and my teacher found all in 3 minutes using quadratics

I used guessing and checking, and found one

[tough cargo]

What was ur guess and check method ? Can still do it fairly fast that way imo

As long as u constrain $m$ to some values

[thorny flame]

992qqoloy

[tough cargo]

sooooo do u need anything else

if u need me again ping ig but Im leaving

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@icy falcon Has your question been resolved?

[icy falcon]

Ok I figured it out

.close

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[eager crater]

Anyone?

It’s on UCM

<@&286206848099549185>

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@eager crater Has your question been resolved?

[fresh wharf]

uhm, i would like to point out that this is a maths server and most likely you wont get any physics help in here.

[eager crater]

This is applied math tho

[fresh wharf]

but for the problem i would suggest resolve the vector to the tangential acc and use the relation between them

[eager crater]

And mech is included in math so I just assumed they someone would know😭

[fresh wharf]

with that logic i could ask a bio and philosophy q too

[eager crater]

But mechanics is included in math….

I am doing a level so it’s stats, mech and pure.

[fresh wharf]

i just said

what u need to do

[eager crater]

Oh I am sorry! it’s not the way😭 you would need to use like one of the formulas of the UCM and that’s where I am stuck

[fresh wharf]

ok 1 min

[eager crater]

Okay thank you!

[empty sail]

Yes mech uses math but this server doesn't handle the other stem related topics, that well, like mech, ee, physics, etc. It does calc, linear alg, geometry and those kinds of courses. Your best option, look for a physics server, there's one in #old-network, or google one

[eager crater]

I did! But it’s very empty so that’s why I just asked here

[empty sail]

You're going to get less of a response here

[fresh wharf]

centripetal acc = (-4^2 + -3^2)^1/2 = 5m/s^2

formula:-
centripetal acc = speed^2/radius
=> 5 = v^2/20
=> v = 10 m/s

hope it helps 🙏

[topaz sinew]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[fresh wharf]

i just did

but they couldnt understand

they needed the formula

@eager crater i reccomend reading your notes and organizing your fomulas

[eager crater]

Omg thank u sm!!

[fresh wharf]

ucm is pretty easy, buckle up for rotational motion with calculus and variable acceleration

[eager crater]

It’s not even homework tho I need to know the way😭😭

☹️☹️☹️

It is but it’s also confusing

[fresh wharf]

are u giving competitive exams or something?

like jee stuff?

[eager crater]

Wdym?

[fresh wharf]

are you giving any college entrance exams

?

[eager crater]

Oh no lol! I am still in school

This is just a regular test

[fresh wharf]

ok 👍

read your books and notes

[eager crater]

Thank u!!

[fresh wharf]

this was an extremely easy problem, practice more and more

[fresh wharf]

uw

[eager crater]

Yeah cuz this is my first year taking it let alone taking mechanics

[eager crater]

Thank u I will 🙏

[empty sail]

You're taking a test?

[eager crater]

Yeah

[fresh wharf]

at this point i dont even care 💀

[eager crater]

No! Not rn but this is most likely coming in our test

I meant this is just coming in one of those school tests plz

[fresh wharf]

ivve seen ppl asking whats sin^2 x + cos^2 x

[empty sail]

Are you currently taking a test or is that review?

[fresh wharf]

ok now dont waste any time and start doing those problems

[eager crater]

No

Just a review

[empty sail]

Okay because

• Cheating on tests and exams, as well as other forms of academic dishonesty, will result in an immediate ban.

That's in the rules

[eager crater]

I didn’t

[fresh wharf]

@empty sail mind helping me out with some combinatrics? #help-27

[topaz sinew]

Please do not advertise your help channel or thread in other parts of the server. There are many people who need help, and no one person can be prioritized over other people, so please patiently wait. Anyone who chooses to help you is a volunteer who is doing so out of their own kindness.

[fresh wharf]

bhai 🙏

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Remember:
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• After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gaunt cape]

can anyone explain how she/he got 8t and 4t

[gaunt cape]

<@&286206848099549185>