#help-26

1 messages · Page 29 of 1

topaz sinewBOT
#
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wild brook
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So like

topaz sinewBOT
wild brook
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ignore the 20

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22^2022+22^2022^2+...

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I uh

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don't know now

topaz sinewBOT
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@wild brook Has your question been resolved?

topaz sinewBOT
#

@wild brook Has your question been resolved?

wet herald
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Are you familiar with the Chinese Remainder Theorem?

wild brook
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I just don't know how to apply it to

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Well

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Sum ._.

wet herald
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The last two digits are equivalent to taking the remainder mod 100. What two modulos does the CRT let you reduce it to?

wild brook
wet herald
wild brook
wet herald
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Keep reading. They give a lot of examples. See if you can apply some to your problem.

wild brook
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I'm left with more questions than answers

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that's the three line equal sign

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what's mod

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and even more

wild brook
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(22^2022)mod100=84^1011mod100

wet herald
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$a \equiv b mod n$ means that $n$ divides $a - b$. So you can view $b$ as the remainder with respect to $n$.

I'm pretty sure you haven't seen the examples, but the short answer reduce the base of the exponent with modulos and use Euler's Totient function to reduce the exponents.

thorny flameBOT
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chencking

wild brook
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=-16^1011mod100

wild brook
wet herald
#

You don't want to work with mod 100. Mod 100 is difficult. Try reducing it to smaller mods that are easier to work with using CRT. It's much more manageable.

wild brook
wet herald
wild brook
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It's just confusing to yk

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use for this specific question

wild brook
wild brook
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Like

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How

wet herald
wild brook
topaz sinewBOT
#

@wild brook Has your question been resolved?

topaz sinewBOT
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timid kraken
#

Hello. P(x) and Q(x) polynomials are equal. I need to find a,b,c,d,e. I found d,c,e, but can't find a and b. Please help

thorny flameBOT
still urchin
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You should equate the coefficients of the same powers like the coefficient of x^3 in p(x) is the same as the coefficient of x^3 in q(x)

clear lodge
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and you should also do the same for the coefficient in x^6 on both

timid kraken
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But there is no x⁶ on the Q

still urchin
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this means that its coefficient = 0

timid kraken
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а=0?

still urchin
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a+4=0

timid kraken
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Oh yea right

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Thanks

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,close

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.close

topaz sinewBOT
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frosty nacelle
topaz sinewBOT
frosty nacelle
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What did I do wrong here

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<@&286206848099549185>

elder ocean
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Help

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Please

topaz sinewBOT
# elder ocean

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

frosty nacelle
elder ocean
#

Ok

topaz sinewBOT
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topaz sinewBOT
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@frosty nacelle Has your question been resolved?

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frosty nacelle
#

.reopen

topaz sinewBOT
#

topaz sinewBOT
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@frosty nacelle Has your question been resolved?

frosty nacelle
#

<@&286206848099549185>

rustic cedar
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what is the problem

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I mean what does exercise say

topaz sinewBOT
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topaz sinewBOT
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tender girder
topaz sinewBOT
tender girder
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how do i simplify this

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I'm gonna throw up if I gotta spend half an hour doing another problem

icy sky
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Ok start with the negatives, what happens when you have two negative numbers multiplied together?

tender girder
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positiv3e

buoyant loom
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its 6

tender girder
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lol thank you Kaz

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how did you get 6

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I'm guessing like ummmmmmm 3 and 12 or something

buoyant loom
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3 x 12 = 36

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root 6

tender girder
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love you kaz

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.close

topaz sinewBOT
#
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neon iron
#

guys there is this math problem in which the bases of a trapezoid have a difference of 16cm . One of the bases is 7/3 of the other base and the area is of 240 cm². How do I find the height

elfin sparrow
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The bases differ by 16, and one base is 7/3 times the other base

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That's enough to find the length of both bases

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After that you can find the height since you're given the area

neon iron
elfin sparrow
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then you can solve the system

neon iron
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oh yeah I get it thanks

elfin sparrow
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awesome 👍

#

np

topaz sinewBOT
#

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neon iron
topaz sinewBOT
neon iron
#

can anyone explain these 2 lines

topaz sinewBOT
#

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meager apex
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Idk i been stuck on so many different versions of this problem for a min

meager apex
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here let me try again

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-4 -4= 7

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+2 +@ = 9

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3,-1/3

tall wolf
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-4-4≠ 7

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-4-4=-8

meager apex
tall wolf
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no 11 is mine

meager apex
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-4 + 11

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=7

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7+2=9

tall wolf
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there we go

meager apex
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3, -1/3

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?

tall wolf
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-1/3 is wrong just by plugging it in

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do you know how to properly solve absolute value?

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you have two cases

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one where everything inside the absolute value is multiplied by negative and one where everything inside stays the same sign

meager apex
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so its -3x+2

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?

tall wolf
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yeah

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equals 7

meager apex
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ok then let me try again

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7-2=5

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5/3, -1/3

tall wolf
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3 was originally correct

meager apex
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oh?

tall wolf
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-1/3 was not

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both answers you just gave are incorrect

meager apex
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I used -3x+2 tho

tall wolf
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you did it wrong

meager apex
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k

tall wolf
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-3x+6=11

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-3x=5

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does this make sense

meager apex
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-3/5 mmm

tall wolf
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nope

meager apex
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you added it to the 4 ok

buoyant loom
meager apex
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oh

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oh right

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makes sense i'll write that down

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🫡

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.close

topaz sinewBOT
#
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topaz sinewBOT
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rotund coyote
#

ive figured out the rest but im kinda struggling on this one

wispy hedge
rotund coyote
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nothing 😭

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<@&286206848099549185>

keen scaffold
jaunty wedge
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Are they talking about line plot or domain and range?

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Because if they are talking about line plot, then it is the biggest number minus the smallest

hard echo
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does anyone know the answer to this problem

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<@&286206848099549185>

topaz sinewBOT
jaunty wedge
rotund coyote
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erm

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ion know

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all i do know is

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is that this math work gotta be done by 8:30 ☠️

jaunty wedge
rotund coyote
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this a bunch of hooplah in my ehes

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eyes

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ngl

jaunty wedge
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Are you still stuck on that question?

rotund coyote
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yes 😭

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sorry man

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i done retaken this bout 3,4 times this my final chance to redeem myself

jaunty wedge
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damn

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lemme look this up

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just to be sure

rotund coyote
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aight

jaunty wedge
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I believe it is the second option

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The first option is the list of the domains and the third and fourth options are the lists of both the domains and the ranges. Only the second option is the list of ranges.

keen scaffold
jaunty wedge
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google

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I was just checking if what I remember of domains and ranges were correct

rotund coyote
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okay tysmm

jaunty wedge
jaunty wedge
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'Khan Academy' and 'The Organic Chemistry' specifically

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they are pretty good at explaining things and it makes it easier to understand

keen scaffold
rotund coyote
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this is an extra credit one idk if you wanna try and do it but if u do tysm 😭 @jaunty wedge

jaunty wedge
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it's the third option

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I think

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because when the tub is full, it's at 40

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but once it's empty it's at 0

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and since the table is going to go on until the water is all drained

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the range would be all the real numbers from 0 to 40

topaz sinewBOT
#

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tall canopy
#

can someone explain this math problem for me

tall canopy
sour walrus
#

You find area of rectangles by multiplying length and width. So, if you're given a length and a width, how do you find the area?

topaz sinewBOT
#

@tall canopy Has your question been resolved?

sour walrus
#

39.9 square meters. Is it making you put units?

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Or significant digits so you have to round or something?

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Because 39.9 m^2 sounds right.

topaz sinewBOT
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silver yacht
#

someone please help me with this - i’ve been stuck for quite a while now

silver yacht
#

i know that it goes to three but i don’t know how to show it

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part b*

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<@&286206848099549185>

topaz sinewBOT
#

@silver yacht Has your question been resolved?

topaz sinewBOT
#

@silver yacht Has your question been resolved?

keen venture
#

@silver yacht
Such a limit would be a solution to
x = ³√[7x + 6]

silver yacht
keen venture
#

You don't necessarily need to. Just need to show x = 3 works.

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So sub that in

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But if you did want to, this is a cubic and you can solve it with factorization

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But you shouldn't want to lol

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@silver yacht

silver yacht
topaz sinewBOT
#
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topaz sinewBOT
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oblique hill
#

Why is this the sinuse if sinuse is the opposite/hypothenuse

drifting swift
#

the hypotenuse is 1

oblique hill
#

.close

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oak ginkgo
topaz sinewBOT
oak ginkgo
topaz sinewBOT
#

@oak ginkgo Has your question been resolved?

stuck forum
#

use a different substitution

#

hint: d/dx of x^5 is proportional to x^4

topaz sinewBOT
#

@oak ginkgo Has your question been resolved?

rocky harness
topaz sinewBOT
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atomic kestrel
#

Does notQ implying notP give that Q implies P?

gritty trout
#

no, ~Q => ~P is logically equivalent to P => Q

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otherwise, suppose that you know if its not cloudy, then its not rainy. you can't conclude that if its cloudy, it is rainy

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because you'd start from something true and end up at something false FeelsBadMan

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but you can conclude that if its rainy, then its cloudy

atomic kestrel
atomic kestrel
#

.close

topaz sinewBOT
#
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tough viper
#

how come the average that in group A is higher than group B?

Group A has 3 people and now 6 school days passed

And how many days each person attended:

6, 5, 4

Group B has 6 people and 2 school days passed for them only

And how many days each person attended from group B:

2, 0, 2, 2, 2, 1

thorny flameBOT
#

riemann

tough viper
tough viper
#

and avg for group B is 75% OF OVERALL ATTENDANCE RATE but for group A it is 83%

knotty ledge
#

What does "average" in your question mean if not average attendance rate

knotty ledge
#

Missing 3 out of 18 is better than missing 3 out of 12

tough viper
#

huh

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wdym

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like 2 ppl missed 3 days but 2 people also missed 3 days

knotty ledge
#

There were 18 possible points of attendance in group A, they missed 3.
There were 12 possible points of attendance in group B, they missed 3.
Group B have a worse average as they missed 3 in 12, versus missing 3 in 18 for group A

topaz sinewBOT
#

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topaz sinewBOT
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topaz sinewBOT
rustic cedar
#

@tough viper .close

topaz sinewBOT
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raven wagon
#

i need help with trigonometry

topaz sinewBOT
drifting swift
raven wagon
#

uhm

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i am stupid and i need help by someone explaining how to do trigonometry

winged moat
#

There are a lot of things trigonometry

raven wagon
raven wagon
drifting swift
#
  1. don't call me bro
  2. that was an invitation to post your actual question rather than just "i need help"
raven wagon
#
  1. No need to be offended by that
  2. You need to actually read what I needed help with tf you acting like Greta Thunberg
main nova
#
  1. no need to escalate
#

which one of those you need help with?

drifting swift
#

the correct course of action on your part is to apologize and correct yourself, that's it

winged moat
#

Let's all keep calm 🙂

reef harness
#

@sheroz

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ah

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.close

topaz sinewBOT
#

@raven wagon Has your question been resolved?

drifting swift
#

oh it looks like they left lmfao

#

good riddance

#

.close

topaz sinewBOT
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safe sphinx
topaz sinewBOT
safe sphinx
#

help

#

<@&286206848099549185>

charred hearth
#

This doesn't feel like a full question?

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Is the first matrix multiplied by anything?

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@safe sphinx

topaz sinewBOT
#

@safe sphinx Has your question been resolved?

safe sphinx
#

it just says Find

topaz sinewBOT
#

@safe sphinx Has your question been resolved?

kindred finch
#

what you want to do is match up the entries. So y = 2x -7 is one equation

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can you do the rest?

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@charred hearth

safe sphinx
#

still confused

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<@&286206848099549185>

topaz sinewBOT
#

@safe sphinx Has your question been resolved?

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cyan sand
topaz sinewBOT
cyan sand
#

This is a proof I wrote, however I'n not sure if the logic is correct and/or I am writing with the proper notation?

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I feel like im supposd to state my assumptions a certain way, and my conclusion a certain way .

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<@&286206848099549185>

topaz sinewBOT
#

@cyan sand Has your question been resolved?

topaz sinewBOT
#

@cyan sand Has your question been resolved?

topaz sinewBOT
#

@cyan sand Has your question been resolved?

urban grove
# cyan sand

Where do you prove that A \subset B implies that A \cap (X \ B) = emptyset?

urban grove
# cyan sand

This proof doesn't work because you only proved it for specific sets A and B

#

but you need to prove it for all finite sets A and B

topaz sinewBOT
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surreal gazelle
#

is this lookign right?

topaz sinewBOT
#

@surreal gazelle Has your question been resolved?

topaz sinewBOT
#

@surreal gazelle Has your question been resolved?

neon iron
#

why (5; 19)?

surreal gazelle
#

well

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i am just lost in general on how to do it

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i pluged in 5 to the eqution and got 19

neon iron
#

do you know how to differentiate a function to get the 'gradient function'

neon iron
#

f(1) = (1)^2 - 6 = -5 correct?

neon iron
neon iron
#

do you know how to sketch tangent lines

#

or what a tangent line is

surreal gazelle
#

yes

neon iron
surreal gazelle
#

somewhere around (2,-3.5) ?

neon iron
#

the line would hit (1,-5) NervousSweat there could be a way to approach this problem without finding the gradient function idk

surreal gazelle
#

bro

neon iron
surreal gazelle
#

hummmmmmmmmmmmmmmmmmmmmmmm

#

tanget lines x value

neon iron
surreal gazelle
#

we just went over limits

#

not we are on this stuff

#

first day on this unit

topaz sinewBOT
#

@surreal gazelle Has your question been resolved?

surreal gazelle
#

eh, i give

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eager hill
#

kinda lost on how to get started on this question

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teal lark
#

given a manifold in n dimensions that lies in n+1 space (like a napkin on the table), how do we define a deformation along some axis so that some of its point get closer in dimension n+1 without changing their position on the manifold? (like folding a napkin in 2)

topaz sinewBOT
#

@teal lark Has your question been resolved?

sour dirge
thorny flameBOT
#

adzetto

sour dirge
topaz sinewBOT
#

@teal lark Has your question been resolved?

teal lark
#

thanks. im not sure i get it tho can u give a little bit more details

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sullen plover
#

if the integration of ( ln x) dx = x ln x - x, thn similarly the integration of (log x) dx = x log x - x, if the base for the log is cost let say a= 10?

mellow arrow
#

$\log_{10}x=\frac{\log_{e}x}{\log_{e}10}$

thorny flameBOT
#

B-eard

mellow arrow
#

log_e(10) is a constant

sullen plover
#

yhe

#

so the intgegration of log{a} x = x log x - x?

mellow arrow
#

well, the constant would remain there

#

$\int_{ }^{ }kx=\frac{kx^{2}}{2}+c$

thorny flameBOT
#

B-eard

sullen plover
#

like x log{10} x - x

mellow arrow
#

no

sullen plover
#

ohh

mellow arrow
#

$\int_{ }^{ }kx=k\int_{ }^{ }x$

thorny flameBOT
#

B-eard

sullen plover
#

yhe

teal lark
#

but how did you get to that equation

teal lark
#

yeah

#

like is tehre a general technique for finding folds of a manifold

sullen plover
#

yh

#

so what is the integration of log{a} x dx?

thick inlet
#

You have to do integration by parts I believe

mellow arrow
#

no

thick inlet
#

at least that's how I learned it

#

rewrite integrand as ln(x)/ln(a)

#

pull out 1/ln(a) as a constant

mellow arrow
#

$\int_{ }^{ }\frac{\log_{e}x}{\log_{e}10}=\frac{1}{\log_{e}10}\int_{ }^{ }\log_{e}x$

thorny flameBOT
#

B-eard

thick inlet
#

ye

#

you can make the integrand 1 * ln(x)

#

dv = 1, u = lnx

#

then ibp

sullen plover
#

yh

topaz sinewBOT
#

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main sparrow
topaz sinewBOT
thorn raven
#

hey I have a question. is cos^2(2x) equal to (cos^2 (x) - sin^2(x)) ^2?

topaz sinewBOT
main sparrow
restive inlet
#

how would you solve something like
3x=7

devout creek
#

What's the issue here?

main sparrow
restive inlet
#

you didn't seem to do anything except make a typo while copying what I asked

main sparrow
#

i need help not additude

restive inlet
#

I'm trying to help, but the intentions/meaning of your reply was very unclear

main sparrow
#

im confused on how to answer the question so i wouldnt know how to do that

devout creek
#

Hmm are you aware of algebra rules?

#

And equations?

restive inlet
#

I was attempting to give you similar less intimidating examples

#

for which the same idea can then be applied to this question

main sparrow
#

ok

restive inlet
#

try first reading the following, might take a while for the bot to compile

split igloo
#

If x=2, what's 3x?

restive inlet
#

,tex .algebra lesson

main sparrow
#

x=3?

split igloo
#

x=2

main sparrow
#

u said wuts 3x

#

.close

topaz sinewBOT
#
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split igloo
#

💀💀

split igloo
topaz sinewBOT
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maiden basalt
#

Hi

topaz sinewBOT
maiden basalt
#

So i tried searching geometric sequence because im confused now.im more confused

#

Im confused on how he got -16 and -128 it doesnt make sense

#

It just messed up sequencing

knotty ledge
#

Maybe don't ask chatgpt next time

maiden basalt
knotty ledge
#

Clearly

maiden basalt
#

Ohh

#

256, _, _, -32, 16

maiden basalt
#

Im confused on hownit become positive to negative to positive

kindred finch
topaz sinewBOT
#

@maiden basalt Has your question been resolved?

maiden basalt
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copper bay
topaz sinewBOT
copper bay
#

Hi, what does "negatively-sloped line passing through the equilibrium point which separates the graph of $f(x)$ from the horizontal axis." mean? The context is the phase plane of the 1D dynamical system $x'(t) = f(x(t))$

thorny flameBOT
#

Paschalis Chinos

copper bay
#

I guess that's what it means, where f(x) is in green?

#

if f(x) is differential at the equilibrium point and its a stable equilibrium, shouldn't such a line always exist?

#

Actually if the derivative of f(x) at 0 is is 0 then I guess it's not exponentially stable

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#

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candid sandal
#

Hi, F(x)= ∛x

  1. Calculate in f’(1)
  2. Determine the linear approximation of the function f at a=1
  3. What values does this linear approximation of ∛0.99, ∛1.01, ∛1.05 and ∛4 provide? Are these approximations by excess or by default? Justify graphically.
  4. Compare these 4 values to the values provided by the calculator. What do we observe?
candid sandal
#

Can someone help me please?

keen raptor
#

First, find f'(x)

candid sandal
#

i have already done a, b and c but i don't know how to find if it's by excess or by default

keen raptor
#

Maybe it's asking if they're over approximations or under approximations?

#

Did you translate it from another language?

candid sandal
#

yeah from french

keen raptor
#

"default" as in like debt?

#

Negative?

candid sandal
#

yeah

keen raptor
#

ok so it's asking whether the approximations are too high or too low

#

And it suggests looking at the tangent line on the graph to do that

candid sandal
#

so if L(4) = 2 and f(4) = 1,5 so its by excess?

keen raptor
#

Yeah

candid sandal
#

so all of them its by excess

keen raptor
#

Yeah

candid sandal
#

okey thank you so much

keen raptor
#

no prob

candid sandal
#

have a nice day

#

.close

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#
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keen raptor
#

u2

topaz sinewBOT
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plush prawn
#

Hi guys, why

topaz sinewBOT
plush prawn
#

$\frac{1}{n} < \epsilon \Longleftrightarrow n > \frac{1}{\epsilon}$

drifting swift
#

inappropriate use of = -- should be \iff instead

#

also it should be known that n and epsilon are both positive

plush prawn
#

yup

thorny flameBOT
plush prawn
#

My question is how can I isolate n?

prisma mesa
#

can we assume that n is natural number?

plush prawn
#

oh

#

yeah

prisma mesa
#

so since n is positive, you can multiply both sides by n

plush prawn
#

if I multiply n on the left and right side I get 1 < epsilon * n

prisma mesa
#

yeah, this works iff n is positive btw

#

if n was negative it would be 1 > epsilon * n

plush prawn
#

why do I have to change the direction of my disequality?

#

sorry for the bad english if that's the case

prisma mesa
#

generally, multiplying/dividing by negative number changes the "direction"

#

if 1 < 2 then -1 > -2

plush prawn
#

yeah but if I have 1<epsilon * n

#

I would have to divide epsilon

#

so it changes the direction?

plush prawn
prisma mesa
#

do you have information about epsilon?

#

Like epsilon > 0

plush prawn
#

yea assuming that its > 0

prisma mesa
#

so epsilon is positive

#

so you can divide both sides by epsilon without changing the direction

#

so 1/epsilon < n

plush prawn
#

oohhhhh

#

So i'd get

#

$\frac{1}{\epsilon} < n$

thorny flameBOT
plush prawn
#

so n > that

prisma mesa
#

yep

plush prawn
#

SHEESH

#

beautiful

#

thankssssssssssss

#

<3333333333333

prisma mesa
#

yw

plush prawn
#

.close

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topaz sinewBOT
#

@drowsy frost Has your question been resolved?

topaz sinewBOT
#

@drowsy frost Has your question been resolved?

gritty trout
#

yeah FeelsOkayMan

#

when you have <stuff> = 1/B, you can also just say that <stuff>^{-1} = B

#

or 1/<stuff> = B

topaz sinewBOT
#

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crisp niche
topaz sinewBOT
crisp niche
#

im still struggling to turn the 1st equation to the 2nd

#

im left with this, can we just think e^C as C since its a constant?

stuck forum
#

if that's ln, yes

crisp niche
#

it was from here

crisp niche
stuck forum
#

i'm looking at pg 90 and i'm guessing they took exponential of both sides

#

then took out e^K and turned it into another constant

#

bit of a poor notation, but they just called it K again

crisp niche
#

ah okayy thank you!

#

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cedar kindle
#

Why is there a ( -2x )?

topaz sinewBOT
cedar kindle
#

In step 2

crisp niche
#

its a derivative from -x^2

cedar kindle
#

Why do I need that. I thought I only needed the derivative of (1-x^2)^1/2?

crisp niche
#

thats part of it

#

if im not wrong

cedar kindle
#

.close

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fair drift
#

please can somone helo me wth this 3^(x+1) - 3^x = 162

fair drift
#

problem

tulip sequoia
#

You can do by trial and error. Try substituting values

fair drift
#

hello?

fair drift
#

but I want to work it out

tulip sequoia
#

Okay

fair drift
#

If you could help?

tulip sequoia
#

Write 3^(x+1) as 3×3^x

fair drift
#

yh

tulip sequoia
#

3×3^x - 3^x = 162

#

Take our factor 3^x

fair drift
#

yh

tulip sequoia
#

3^x × (3-1) =162

fair drift
#

wont that be 3^(3x-x)

#

=162

tulip sequoia
#

x is in exponent power

fair drift
#

alr

#

so thtats 3^2x =162

#

and 3^2x = 3^4 x 2

tulip sequoia
#

No
3^x × (3-1) =162
3^x × 2 = 162
Dividing by 2 on both sides
3^x = 81

fair drift
#

uve been helpfull thanks alot

#

im going to close it now

#

.close

topaz sinewBOT
#
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fair drift
#

im done

topaz sinewBOT
#
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queen jasper
#

I am revising and need answers to these questions. I have answers to them.

Questions 7,8,10 and 1 ii

topaz sinewBOT
#

@queen jasper Has your question been resolved?

queen jasper
#

<@&286206848099549185>

digital spire
#

Do you… need help on them?

#

I think it is generally inadvisable to just give the answers

thorny flameBOT
queen jasper
#

Oh mb

queen jasper
#

I’m close but not the answer

digital spire
#

Where are you up to for number 9?

queen jasper
#

I did number 9

digital spire
#

oh

#

You said you only did number 1

#

What about 10?

queen jasper
#

I meant I finished question 1 ii

digital spire
#

I’m a little bit confused. Which ones specifically would you like help on?

queen jasper
#

I think I put it

#

Yeah 7,8,10

#

Tbh 10 is the I’ve I’m struggling with most

digital spire
#

I see

queen jasper
#

If it’s purely imaginary then the real part has to be 0 ?

#

Therefore x + 3 should equal 0

#

So x = - 3

#

Oh right there can’t be imaginary on the bottom

digital spire
#

We have (x + 3) + (2 + y)i as the numerator

queen jasper
#

Yes

#

We need to get rid of imaginary at bottom then ?

digital spire
#

How can we do that?

#

Ideas?

queen jasper
#

Idk

digital spire
#

Try multiplying the top and bottom by the conjugate of the denominator

queen jasper
#

But surely that would times the x + 3 too so that would not help

digital spire
#

What do you mean?

queen jasper
#

Doing that would time (x + 3 ) aswell no ?

digital spire
#

Yes, but why is that an issue?

queen jasper
#

Because u would still have imaginary on bottom no ?

digital spire
#

The (x + 3) is the real part

queen jasper
#

Yes

digital spire
#

multiplying by the conjugate always gives you a real number

#

That was actually one of the questions you had to do!

#

Question 9

queen jasper
#

Yes but would u not have to multiply (x + 3 ) by the conjugate

digital spire
#

Ah, I see your confusion

#

The entire complex number is (x + 3) - (2 + y)i

#

They are not 2 separate complex numbers

queen jasper
#

Omg

#

Ty so much

#

Damn just completely didn’t realise that

#

Ty again !

digital spire
#

so multiplying by the conjugate, which is

#

(x + 3) + (2 + y)i

#

eliminates the imaginary bits

queen jasper
#

Yeah that makes sense !

digital spire
#

Now, then you simplify the top and then eventually get to where you need to be

queen jasper
#

Yeah that’s not that bad I just couldn’t figure out what to do

#

Ty

#

Acc if u have time I have one more question

digital spire
#

Sure

queen jasper
#

Lemme find the question rq

#

For part ii

#

If w is a root you should divide the whole thing by W right ?

round gorge
#

is it AoPS volume 1?

digital spire
#

The approach for that is noting that if all coefficients are real then also 1 - 2i will solve the equation

queen jasper
round gorge
#

art of problem sovling

queen jasper
round gorge
#

ok

queen jasper
digital spire
#

so then you can divide (personally dislike) or write
(z - (1 + 2i))(z - (1 - 2i))(z^2 + Bz + C)
and expand, compare coefficients

digital spire
digital spire
#

Substitute in 1 + 2i and use the factor theorem to note that the polynomial will equal zero

#

then 1 - 2i, same thing

queen jasper
#

Okay

#

Alr that makes sense

digital spire
queen jasper
#

So for the first method u divide by the factor

#

And then compare coefficients

queen jasper
#

Yes I thought so ?

digital spire
#

What we are doing there is expanding all that out and comparing with the known terms of the quartic in the question

neon iron
#

(send help i need an study buddy and i know such an small number of people that i have resorted to come back to my 2020 discord account because i have no other social media account)

digital spire
#

?

queen jasper
#

Surely we can not figure out yet

digital spire
#

We can because we’ll have expressions involving B and C

queen jasper
#

Sorry but I don’t understand how

#

How will u able to compare the coefficients of p and q

digital spire
#

We are given two terms of the quartic for free

#

We will make use of those

queen jasper
#

Yes

digital spire
#

then, we will substitute into the expressions of B and C representing p and q

#

to find them

#

Pretty long though

queen jasper
#

Okay we haven’t rlly been taught about quartile yet

#

If I just use an equation solver on calc could I just find B and C quickly

#

We are allowed to do so

digital spire
queen jasper
#

Quartic it was autocorrect srry

digital spire
#

like the easier thing is to sub in w and w*

#

set equal to 0

queen jasper
#

Okay sub it in

digital spire
#

Umm…

#

just a little bit concerning because it should stipulate p and q are real

#

but I’m sure that’s an oversight

queen jasper
#

Yeah it wouldn’t be that hard I hope 😅

digital spire
#

🕺

queen jasper
#

Okay ty so much for the help

#

I still don’t understand how to get B and C once u sub in W but I will watch a video about quartics in the morning

#

Ty

queen jasper
#

Alr so how would it work on a quadratic for example

#

So if u sub in eg 25 + p5 + 65 = 0

#

Obviously u can figure out p

#

But if there’s two terms ?

digital spire
#

Let me see if I can find a good example

#

Give me a sec

queen jasper
#

Ok ty so much

digital spire
#

Now, there are no unknowns in the original equation, true

#

But if there were, they would be findable as long as we still had the last terms

#

See that they have only compared the z^4, z^3 and constant terms

#

That means the z^2 and z terms could have had unknowns

#

and it still would have worked

queen jasper
#

Yes that makes sense now 👍

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We haven’t rlly gone through in class properly but we have done some stuff like this

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Except I remember that our teacher put a k infront of the the brackets e.g k(x - r/s)(x-x/y)

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Anyway I need to go now

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But Tysm!

#

If u have anything more advice or help feel free to dm me because it rlly helped !

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.closed

#

.close

topaz sinewBOT
#
Channel closed

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#
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quartz sigil
#

Goal is to reduce the number, and the correct answer is -8. I have been struggling and have no idea why the answer is 8x^14 instead of just x^14 on a)

vital relic
#

the power distributes to every term

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including the 2

solemn jay
solemn jay
quartz sigil
#

But wouldn't that make it 16x^14?

vital relic
#

theres a 2 on the bottom

solemn jay
#

,w (2x^5)^4

solemn jay
#

so its gona be

quartz sigil
#

i think thats enough help, ill close this thanks ill ask again if i fail to understand .close

solemn jay
#

$\frac{16x^{20}}{2x^6}$

quartz sigil
#

.close

topaz sinewBOT
#
Channel closed

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solemn jay
#

alr ig

thorny flameBOT
topaz sinewBOT
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tawdry yoke
#

I need help with the last one what should the angle be

tawdry yoke
#

Also what is the c for the last 2

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I want to check my answer

neon iron
tawdry yoke
#

Tan-1

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I got -41.2

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But the answer key says differs

neon iron
tawdry yoke
#

?

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I don’t understand sorry

neon iron
#

what was tan(\alpha) = ?

tawdry yoke
#

The angle?

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Or the side a

neon iron
#

$$\tan{\alpha} = ?$$

tawdry yoke
#

For the last three we have to find it

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It doesn’t tell you

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That’s what I need help with

neon iron
#

okay what is the definition of tan

neon iron
tawdry yoke
#

For the last one I got 41.2

#

Second to last I got -41.2

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And third to last I got -41.2

#

But the answer key is different answers

tawdry yoke
#

Opposite/adjacent

neon iron
#

right

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give me in this form please

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$$\tan{\alpha}=?/?$$

tawdry yoke
#

So is my answer wrong?

thorny flameBOT
#

sen

$$\tan{\alpha}=?/?$$
tawdry yoke
#

Tan-1=7/-8

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Was I wrong

neon iron
#

$$\tan{\alpha}=7/8$$

#

right?

thorny flameBOT
neon iron
#

$$\alpha=\tan^{-1}{(7/8)}$$

#

@tawdry yoke do you understand what i just did

thorny flameBOT
tawdry yoke
#

Yes

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But it’s -8

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Also which one we talking about from the three

neon iron
tawdry yoke
#

I am confused

#

What’s alpha

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A?

neon iron
tawdry yoke
#

Yes

neon iron
tawdry yoke
#

Which one

neon iron
tawdry yoke
#

The last three

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I did them

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Just I am not sure if they correct

neon iron
#

yes but now we're about to verify them

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and how you did them

#

what steps did you take

tawdry yoke
#

For angle I did tan for all of em

neon iron
#

you were given a=-7 b=-8 c=? A=?

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right

tawdry yoke
#

Yes for the last one

neon iron
#

tan A = ?/?

tawdry yoke
neon iron
#

ah i see

#
  1. tan^-1 = -7/-8 is wrong
#

tan^-1 is a function

#

like tan

#

eg tan(45)

#

tan^-1(3/2)

#

you do tan^-1 to get the angle

#

for example lets say we had sin(x) = 5/4 how would we get the angle x?

tawdry yoke
#

Did I do it wrong

neon iron
#

yes

tawdry yoke
#

How

neon iron
#

dont calculate anything just tell me what x is in terms of sin^-1

tawdry yoke
#

Stuck

neon iron
tawdry yoke
#

X is nothing

#

1

#

Not really sure

neon iron
#

no we dont do it this way this is why we use sin^-1 or cos^-1 or tan^-1

#

for my example

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sin(x) = 5/4
x = sin^-1(5/4)

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see what i did there?

tawdry yoke
#

Yes

neon iron
#

so what is y in cos(y) = 3/2

tawdry yoke
#

3.0

neon iron
tawdry yoke
#

-1

neon iron
#

cos(y) = 3/2
y = cos^-1(?

tawdry yoke
#

Cos^-1

tawdry yoke
neon iron
tawdry yoke
#

Yes I did sin^-1 to find the angle using opposite and hypotneuse

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U did*

neon iron
#

yes

tawdry yoke
#

Ok but what did I do wrong

neon iron
#

ok now what about if i want to find the angle y in cos(y) = 3/2

tawdry yoke
#

Did my calculating turn out wrong

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Cos^-1

neon iron
#

?

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what is y

neon iron
tawdry yoke
#

Y=cos-1

neon iron
#

of what?

tawdry yoke
#

3/2

neon iron
#

cos^-1 isnt a number

#

write it please

tawdry yoke
#

Y=Cos^-1=3/2

neon iron
#

no remember what i told you

glossy acorn
neon iron
glossy acorn
#

ok

neon iron
tawdry yoke
#

Adjacent and hypotenuse

neon iron
#

not a number

neon iron
#

i gave you sin(x) = 5/4

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i want the angle x

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we did the arc sin on the 5/4 to get x = sin^-1(5/4)

tawdry yoke
#

-1

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5/4

neon iron
#

hmmCat were sin^-1 cos^-1 tan^-1 explained to you in school

tawdry yoke
#

Yes they use to find angle that’s it

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And what they are

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Like

neon iron
tawdry yoke
#

Opp and aj

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Stuff like that

neon iron
#

y=Cos^-1(3/2)

tawdry yoke
#

Yes

neon iron
#

not cos^-1=3/2

neon iron
tawdry yoke
#

Yes

neon iron
#

okay one more last question

cos a = 10/3 find me the angle a

tawdry yoke
#

Calculator dose t work tho

neon iron
#

without the use of a calculator

tawdry yoke
#

Cos-1(10/3)

neon iron
#

yess

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a= cos^-1(10/3)

neon iron
tawdry yoke
#

Still get same answer 41.2 for last one

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For angle

neon iron
#

we'll use it later

tawdry yoke
#

Ok

neon iron
# tawdry yoke

in your last question you were given a=-7 b=-8 c=? A=? A(is the angle we want to find)

tawdry yoke
#

I get 654.96

neon iron
#

so again .. what is tan A = ?/?

neon iron
tawdry yoke
#

Tan-1(-7/-8)

neon iron
#

tan not tan^-1 first

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teachers want full working

neon iron
tawdry yoke
#

Yea that’s fine

neon iron
#

but before we got there

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what was tan?

tawdry yoke
#

Oppos and aj

neon iron
#

which is?

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who is opp and adj

tawdry yoke
#

It’s already listed

neon iron
tawdry yoke
#

-7//8

neon iron
neon iron
tawdry yoke
#

-7/8

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Tan-1(-7/-8)

neon iron
tawdry yoke
#

I honostly can’t really get through this I gotta study for the quiz I got tom

#

There’s more topics

neon iron
#

tan A = ?/?
A = tan^-1(?)

tawdry yoke
#

A=tan^-1(-7/-8)

neon iron
#

yes

tawdry yoke
#

Can you help me with another page after this

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YESSS

neon iron
#

but you first start with

tan(A) = -7/8
then

A = tan^-1(-7/8)

neon iron
tawdry yoke
#

w

neon iron
tawdry yoke
#

Ok

neon iron
tawdry yoke
#

Yay

#

41.2

neon iron
#

btw -7/-8 = 7/8 just write like thiskekw

neon iron
tawdry yoke
#

Oh

neon iron
#

we can get c

neon iron
tawdry yoke
#

Yea

#

I got -10.6

neon iron
#

can i please see your working

#

what identity did you use, sin, cos, tan?

tawdry yoke
#

Cos

neon iron
#

full equation pls