Drenitor
#help-26
thorny flameBOT
shell seal
Does that make sense?
topaz sinewBOT
@dreamy drum Has your question been resolved?
dreamy drum
Does that make sense?
sorry I had to go for a bit
yup that makes a lot more sense now
thanks for all the help
I'll try the other parts on my own for now
thanks again
.close
neon iron
how can I solve this question ```*A boat can travel 16 miles up a river in 2 hours. The same boat can travel 36 miles downstream in 3 hours. What is the speed of the boat in still water? What is the speed of the current?
*```
topaz sinewBOT
how can I solve this question ```*A boat can travel 16 miles up a river in 2 hou...
@neon iron Has your question been resolved?
misty seal
When a boat is travelling up the river his speed is v1 - v2
v1 is the speed of the boat and v2 is speed of the river
so you know that s = v * t in the first case, you have 16 = (v1 - v2) * 2
and in the second you have 36 = (v1 + v2) * 3
sorry i meant s = v * t
neon iron
no need to say sorry, keep explaining please
misty seal
basically when the boat is going against the river, the final speed is v1 - v2 where v1 - speed of boat and v2 - speed of river
and when its going downstream the boat has a speed of v1 + v2
neon iron
but how can I know the speed of the boat or the speed of the current?
misty seal
so you know that s = v * t in the first case, you have 16 = (v1 - v2) * 2
16 = (v1 - v2) * 2 you can divide by 2 and get 8 = v1 - v2
misty seal
and in the second you have 36 = (v1 + v2) * 3
36 = (v1 + v2) * 3 you can divide by 3 and get 12 = v1 + v2
topaz sinewBOT
topaz sinewBOT
Available help channel!
toxic bane
topaz sinewBOT
topaz sinewBOT
@toxic bane Has your question been resolved?
toxic bane
do you know the formula for volume of a sphere
4/3 pi. r^3
hmmm
alright
thank you
.close
topaz sinewBOT
topaz sinewBOT
Available help channel!
neon iron
For c) I understand the different implications would be
topaz sinewBOT
For c) I understand the different implications would be
neon iron
Those are all equivalent, but my question is how do you like, exclusively point out that the inverse for example would be the negation of the fact that it is a positive integer as well?
For example
"if a positive integer isn't prime...." Then the negation of that being "if an integer isn't positive and is prime..."
Like I know it is plain wrong in this example to say something like that, but in general how do you dictate what exactly you should be negating for example?
vale jacinth
Converse of p->q is q->p
Contrapositive or p->q is not q -> not p
Inverse of p->q is not p -> not q
neon iron
Yes I do know that. That isn't what my question is
vale jacinth
You want to know the negation of “a positive integer isn’t prime”?
“a positive integer is prime”
“A positive integer” together is a noun, no need to change it I think
I would only change “is”<->”isn’t”, “are”<->”aren’t”, “does”<->”doesn’t” “do”<->“don’t” “can”<->”can’t”
In a sentence
I don’t change any noun
neon iron
I guess if you wanted to specify that you wanted to change it then you have to say something like
"If a number is a positive integer and prime..."
Then the negation of that would be
"If a number isnt a positive integer or prime..."
topaz sinewBOT
topaz sinewBOT
Available help channel!
undone flicker
How many ways are there to arrange the letters in the word GARDEN with the vowels in alphabetical order ?
topaz sinewBOT
How many ways are there to arrange the letters in the word GARDEN with the vowel...
undone flicker
My answer is 120
opal vault
The answer should be 360, please show us your work that you've attempted
undone flicker
AE GRDN
So here i assumed that it will be 5!
opal vault
A and E dont have to be next to each other
potent silo
For example, AGERDN works
undone flicker
So there will be 360
halcyon tree
the vowels have to occupy first and second positions
undone flicker
Noo
halcyon tree
or the 5th and 6th
undone flicker
They just have to be alphabetical order
opal vault
the vowels have to occupy first and second positions
No
halcyon tree
hmm
opal vault
So yes 360
Because out of the 720 permutations, half of them will have A before E, and half with E before A
halcyon tree
okay so it's 6!/2!
topaz sinewBOT
@undone flicker Has your question been resolved?
topaz sinewBOT
topaz sinewBOT
Available help channel!
fervent juniper
How to solve this kind of qns?
topaz sinewBOT
How to solve this kind of qns?
fervent juniper
outside is 7
c + x + f + d = 9
b + d + x + e = 14
f + x + e +a = 23
a + b + c = 12
and Im stuck here now
fervent juniper
do i not use inclusion exclusioon principle?
somber blaze
When I have few groups, I adjust by attempts, when have lot, I do by exclusion, do what best suit you
when find the awnser, tell me
fervent juniper
yes
somber blaze
C and T have interception
fervent juniper
yes they have
somber blaze
M and C have too, but M and T don't
just guess some values
if C = 10 (only drink Coffe,
13 drink the others
fervent juniper
yes
somber blaze
the C + T + M (only drink one) > 12
fervent juniper
ohhhhh
somber blaze
so, we need to take more
fervent juniper
okay now i get it let me try again
somber blaze
I really don't know if have a best way to do it, but I always do this and worked well, only the time is bad for hard exams :/
fervent juniper
somber blaze
ah, that's right, I got lost, sry :p
I've forgot the real question: how many students
XD
fervent juniper
thank youu
fervent juniper
do you know how to do like this type of qns
In a game, an object X and an object Y are travelling along a
straight path from Point M to Point N. The object Y starts from
rest at Point M with constant acceleration of 0.35 m/s2
for 150s, decelerates uniformly for 10 s, then stops to rest for another
10 s and finally decelerates uniformly to come to rest at Point N
in the last 40 s. The object X starts from rest at Point M and
moves with constant acceleration for 40 s until it reaches a
velocity of 30 m/s. It maintains this velocity for 50 s before
decelerating uniformly to rest at Point N, completing the entire
journey in 150s.
Suppose both the objects meet each other between 90 s and
150 s, determine the time when they meet in seconds (m
represents metres and s represents seconds).
@somber blaze
fervent juniper
nooo noo this one is math
somber blaze
hum, interesting
I'll try, but I don't promise that I can
yeah, 1x0 to this question XD
Can't remember the formulas
fervent juniper
its okay thank u
topaz sinewBOT
@fervent juniper Has your question been resolved?
undone flicker
topaz sinewBOT
distant nymph
Well, one way is that you write all numbers in 9k+r form and then just check (r^3 mod 9).
topaz sinewBOT
@undone flicker Has your question been resolved?
fickle fable
how can I solve this?
meager apex
how does this = 2 square root 37?
topaz sinewBOT
how does this = 2 square root 37?
craggy haven
$\sqrt{148} = \sqrt{4\cdot37} = \sqrt4\cdot\sqrt{37} = 2\sqrt{37}$
thorny flameBOT
hayley!
meager apex
mmm ok
craggy haven
it's a very common technique, removing square factors from square roots like this
meager apex
it's a very common technique, removing square factors from square roots like thi...
well how would i do this cus when i do square root of 148 on the calc it gets this
craggy haven
you have to find the factors of 148
meager apex
you have to find the factors of 148
well then how would they get 4 square root of 5 from the square root of 113 when 113's only factors are 1?
craggy haven
,calc 4^2 + 8^2
thorny flameBOT
Result:
80
where'd you get 113?
meager apex
{2-(6)}^2 + (9-2)^2
= square root 8^2 + 7^2 = 113
craggy haven
why are we doing (9-2)^2?
bold nebula
$\DistanceBetweenTwoPoints$
thorny flameBOT
Modus
empty raft
hey i need help with this
topaz sinewBOT
hey i need help with this
empty raft
what does it mean by intial value of the domain?
worthy storm
the smallest value
craggy haven
i think it just means "the domain is [something, 2] and what is that something"
empty raft
the smallest value
so when y is two, what is the lowest value of x?
isnt there only 1 value?
worthy storm
what are the values of x where the function is defined?
empty raft
what are the values of x where the function is defined?
0-2
empty raft
[0,2]
topaz sinewBOT
topaz sinewBOT
Available help channel!
simple dagger
topaz sinewBOT
simple dagger
Im unsure how to actually answer the question
for 6(a), I belive it is " As X approces -3 from the left" But what do i do with the lim h(x)?
<@&286206848099549185>
swift hinge
for 6(a), I belive it is " As X approces -3 from the left" But what do i do with...
That is it, it says when you put x=-3 in h(x) and approach from left what do you observe
simple dagger
we observe that it approaches y=-4?
swift hinge
Yep
simple dagger
Is that how i would answer the question?
and for (d), is it just asking what is going on with the graph at x=-3?
swift hinge
and for (d), is it just asking what is going on with the graph at x=-3?
Yes, what do you see AT x=-3?
simple dagger
at x=-3, there is a "hole" in the graph, so it doesnt exist, X cannot = -3
simple dagger
would me answer be a word answer?
swift hinge
would me answer be a word answer?
wdym?
simple dagger
wdym?
What is my answer suposed to look like? I think im understanding the concept but im unsure how to answer
swift hinge
Oh like the 'english part'
simple dagger
For (c), does it mean that X is approching -3 from both sides?
simple dagger
Oh like the 'english part'
Yes
swift hinge
For (c), does it mean that X is approching -3 from both sides?
Yep if both sides suffice the existence of curve then lim exist
swift hinge
Yes
Probably that, When we approach the curve from <this> side we see that the curve is defined just <before/after> this point''
Write what you understand
simple dagger
Yep if both sides suffice the existence of curve then lim exist
But -3 doesnt exist? Or would it be that they are reaching both positive and negative infinity without reaching -3
swift hinge
But -3 doesnt exist? Or would it be that they are reaching both positive and neg...
When they put limit they want you to approach it by any side, they don't want you to be at that point
That's definition of limit
simple dagger
Got it, so then my answer would be the left side reaches positive infinity, and the right side reaches negative infinity?
swift hinge
Got it, so then my answer would be the left side reaches positive infinity, and ...
for (c) ?
simple dagger
Yes
swift hinge
No no, in limit you dont talk about the point but very very close to point
It should be like, the curve exists/ is defined near x=-3
simple dagger
Ohh, so the answer for (c) would be about where the curve becomes a curve?
Like "As X approches -3, the curve is defined at y=4"?
swift hinge
Yes
swift hinge
Ohh, so the answer for (c) would be about where the curve becomes a curve?
Like...
specify approaches -3 from both sides too
try g and i now
simple dagger
(g) As x approches 0 from both sides, the negative X values reach negative infiinity and the possiive x values reach positive infinity?
(i)AS x approches 2 from both sides, they with both reach positive infinity but does not hit y=2?
swift hinge
Well why do you tend to go to infinity often
Keep it simple
for g is we come from LHS it gives y=+1 and if we come from RHS it gives y=-1 hence Limit does not exist
Because limit exists only when we get same value approaching from right and left
for i yes limit exist because we get y= +2 when we approach from either lhs or rhs
simple dagger
Okay so I just should make it more simple
swift hinge
Mhm
simple dagger
So if i were to do K
It would be, As X approches 5 from the right, it goes to y=3?
swift hinge
Yes
simple dagger
Because i also saw some Khan videos, and he uses "infinity" a lot, but unfortunitly i missed this day of class due to military
swift hinge
Oh
simple dagger
Okay, got it!
thank you
swift hinge
Np
simple dagger
.close
vital moth
Hi eveyone
topaz sinewBOT
Hi eveyone
vital moth
How is $\sum_{j=1}^{n}{\lambda i f{a_i}}(a_j)=\lambda _j$
Shouldn't it be $=\lambda _i$ instead
thorny flameBOT
calculus is fun
vale jacinth
Only when i=j, the term remains, and you are taking sum indexed by i
thorny flameBOT
calculus is fun
vital moth
Only when i=j, the term remains, and you are taking sum indexed by i
The sum is indexed by j
It starts from j=1
So when j=i the term remains
vital moth
Tysm
vale jacinth
Np
vital moth
I want to ask a question
vale jacinth
Sure
vital moth
Do you know greub's book on linear algebra
vale jacinth
I don’t
I only began reading math from undergraduate level in English
The first book in English I read was basic algebra by Jacobson, I never read linear algebra in English
vital moth
Oh ok I just wanted to know if there are newer editions becausw newer editions will have less typos
vale jacinth
I see
vital moth
The first book in English I read was basic algebra by Jacobson, I never read lin...
Ohh ok
Tysm for help have a nice day/night
vale jacinth
You too
vital moth
.close
topaz sinewBOT
fervent juniper
topaz sinewBOT
fervent juniper
Hello how do I solve this type of qns?
Gradient of QR = 10/a
Gradient of PD = -a/10
cold plover
topaz sinewBOT
Available help channel!
untold raft
how do i take the derivatives of $f(x)=\left{0\le x\le20:2,x\ge20:\left(x/5\right)-2\right}$
topaz sinewBOT
how do i take the derivatives of $f(x)=\left{0\le x\le20:2,x\ge20:\left(x/5\righ...
thorny flameBOT
Kaiyan
Compile Error! Click the 
reaction for more information.
(You may edit your message to recompile.)
untold raft
$f(x)=\left{0\le x\le20:2,x\ge20:\left(x/5\right)-2\right}$
thorny flameBOT
Kaiyan
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)
scenic flare
split it
grand shoal
hi may i know if my answer is correct
topaz sinewBOT
hi may i know if my answer is correct
vale jacinth
hi may i know if my answer is correct
Correct
topaz sinewBOT
Please explain this second order ODE solution
scenic flare
rewrite as
x'' = lambda² * x
thereby you seek a function which when deriving gives you the same function multiplied by lambda, a constant
which you get via the exponential:
e^(lambda*x)
however in front of the exponential can be an arbitrary factor as it doesn't influence the derivative
which you may call A
Ae^(lambda*x)
until here understandable?
neon iron
until here understandable?
Yes
scenic flare
k, now since you have the second derivative
the characteristic of the equation is the factor r (I'll just call it r) being r² = lambda² for the second derivative
and its roots are both lambda & -lambda
which is why you have an additional term for the negative exponent
Consider the solution as a linear combination of exponentials for these roots
the other factor has another constant in front of it, call it B
and you get the mentioned solution
whenever you have a differential equation with a factor, you usually can apply this principle
here it was
X(x) must be of shape constant*e^(factor*x)
except you get two factors, lambda and -lambda
therefore also two terms
scenic flare
Thank you so much for your kind help 🙂
np :)
molten wren
hi
stiff willow
suppose on the contrary that (c,a) = d > 1. Then what must (c,b) be?
undone flicker
what will be value of cos^(-1)x in terms of tan^(-1)x
topaz sinewBOT
what will be value of cos^(-1)x in terms of tan^(-1)x
acoustic tangle
You can start by simplifying cos(arctanx)
undone flicker
acoustic tangle
Well, or with that
Draw a right triangle where one of the acute angles has its cosine value equal to x (for simplicity you may pick the leg adjacent to that angle be of length x and the hypotenuse be of unit length)
What's tan(that angle) equal to?
undone flicker
tan sqrt(x^2-1)
acoustic tangle
You mean just sqrt(1 - x^2)/x perhaps?
acoustic tangle
tan is opp/adj
undone flicker
then yes
acoustic tangle
Yeah, so tan(arccos(x)) = sqrt(1 - x^2)/x
undone flicker
of course
acoustic tangle
And so arccos(x) = arctan(sqrt(1 - x^2)/x) + pi n forsome integer n
undone flicker
cos thita= x
tan(arccos) so tan(thita)
acoustic tangle
Yeah
acoustic tangle
Alternatively, if you started with cos(arctan(x)), you would get plus or minus arccos(1/sqrt(1 + x^2))
The plus or minus corresponds with the sign of x
acoustic tangle
Yeah
undone flicker
what is plus minus you mentioned?
acoustic tangle
cos(z) = smth usually implies that z = plus or minus arccos(smth) + 2pin
But here 2pin is absent because we are replacing z with arctanx
And arctan's range is from -pi/2 to pi/2
undone flicker
.close
neon iron
If CD is bisector then x is 50 but I can't proove that.
topaz sinewBOT
If CD is bisector then x is 50 but I can't proove that.
muted temple
If CD is bisector then x is 50 but I can't proove that.
what is DCB
neon iron
15
muted temple
if CD is bisector, what is ACB
neon iron
30
neon iron
15
muted temple
what is ADC
neon iron
115
neon iron
if CD is bisector, what is ACB
But I don't know if CD is bisector
muted temple
oh, u were trying to prove CD is bisector?
can you send the full question
apologies for the confusion
neon iron
Ye
muted temple
Ye
do you have any working so far?
my initial guess was to use the cosine rule, but that winds up with a large equation
neon iron
do you have any working so far?
The line from D AC with 100°. Line's length would be a if CD is bisector
muted temple
have you learnt about sine rule?
neon iron
Yes
muted temple
i found a solution using that
consider triangle ABC
wait before that are you allowed to use calculators?
neon iron
Yes
thorny flameBOT
shik
muted temple
do u agree?
neon iron
Yea
neon iron
We can find a/b ratio from DBC
muted temple
ye, try it out and see if it works
halcyon willow
what does this repeated root thing mean?
topaz sinewBOT
what does this repeated root thing mean?
halcyon willow
i only see 1 root of those equations 2,3 respectively
azure thicket
If you have something like $(x-a)(x-b)(x-c)$
thorny flameBOT
Pealover
halcyon willow
oh i get it here a=b=c=3 thats why there are three roots?
azure thicket
Yes
halcyon willow
also
why does it say that odd degree function will have graph like uk in both +y and -y?
halcyon willow
trying to learn when |f(x)| can and can not be derivable vs not
azure thicket
If we consider that f is derivable
Then for |f| we just have to check if it is derivable on 0
halcyon willow
Then for |f| we just have to check if it is derivable on 0
and we do that using differentiation right?
azure thicket
Yes
topaz sinewBOT
@halcyon willow Has your question been resolved?
deft path
Hi there. I am going through a text and they seem to have rewritten something like this
[π^\dagger π+\nablaϕ^\dagger\cdot\nablaϕ+m^2ϕ^\daggerϕ=π^\daggerπ-ϕ(x)(\nabla^2-m^2)ϕ^\dagger(x)]
This book uses $g_{μν}=\text{diag}(1,-1,-1,-1)$ although I dont believe it is relevant. I am not sure if this is a purely mathematic way of rewriting it or if it is physics related, if someone sees that this is simply some vector calculus identity I would highly appreciate help in seeing it. Note that $[ϕ,π]\neq0,[ϕ^\dagger,π^\dagger]\neq0$ whilst all other possible commutators are $0$
topaz sinewBOT
Hi there. I am going through a text and they seem to have rewritten something li...
thorny flameBOT
hooman
knotty ledge
seems to suggest that $\nabla \phi^\dagger \cdot \nabla \phi = -\phi\nabla^2\phi^\dagger$
thorny flameBOT
ΣΑCu
knotty ledge
and i dont see immediately why that should be true, or if it is in general
this is the closest identity i can think of
deft path
ah i see it$$\nabla(ϕ\nablaϕ^\dagger)=ϕ\nabla^2ϕ^\dagger+\nablaϕ^\dagger\cdot\nablaϕ$$ which with some surface integral logic and reordering i believe that should give this equality. sorry i should have mentioned that we are integrating over this
thorny flameBOT
hooman
sweet shard
**hooman**
there's a lot more assumptions you're leaving out probably
fiery ridge
nice
deft path
yeah that is a bit of a problem when asking physics related questions in here 😅 if i give all the context then suddenly the post will be so long that noone reads it
ok i think i can work with this from here, thanks @knotty ledge 😄
.close
hardy shuttle
topaz sinewBOT
hardy shuttle
Not sure what I did wrong.
knotty ledge
you can't cancel like that
noble laurel
well then you've done every other problem incorrectly
hardy shuttle
So this is wrong?
noble laurel
the difference here is that is a product. not a sum.
hardy shuttle
I’m confused
hardy shuttle
Oh
noble laurel
not multiplying
hardy shuttle
Bc of the + 1
noble laurel
$$\frac{(x-2)+1}{(x-2)(x+1)}=\frac{(x-2)}{(x-2)(x+1)}+\frac{1}{(x-2)(x+1)}$$
thorny flameBOT
Austin
noble laurel
see how the (x-2) can only cancel on the left fraction and not the one on the right
that is why it is incorrect
because (1) doesn't have a factor of (x-2) to cancel with the denominator
bright skiff
What you have gotten to is indeterminate form.
knotty ledge
you should simplify the numerator first, and your x-1 in the bottom changed to a x+1
hardy shuttle
@knotty ledge
knotty ledge
you still wrongly cancelled the x-2 like we said not to
hardy shuttle
omg
why did i do that
so what do you mean simplify the numerater?
can i do x - 1?
knotty ledge
you're welcome!
hardy shuttle
can i get help on one more
knotty ledge
sure
knotty ledge
check your denominator factoring
hardy shuttle
check your denominator factoring
on the top right?
knotty ledge
2x+3-5x^2
knotty ledge
yes but what happens when you expand -5x(x+1)
knotty ledge
yea
knotty ledge
why doesnt that help?
hardy shuttle
because when I do ((x+1)(-2x+5))/(-5x-3) and plug in 1 i get 0
but the answer is -3/8
hardy shuttle
ahhh idk what happened
thanks
im good now
the calc part is easy, i just gotta touch up on my algera 🤝
.close
neon iron
$x^{2} + 2x -15 > 0$
topaz sinewBOT
$x^{2} + 2x -15 > 0$
thorny flameBOT
Chocolate
neon iron
how can I find the solution of x
supple sun
Do you know quadratic formula ?
neon iron
I get $3 > x > -5$ but it's wrong
thorny flameBOT
Chocolate
neon iron
Do you know quadratic formula ?
which one?
supple sun
b^2-4ac
neon iron
yes I know it
in this case I find the correct numbers, -5 and 3, but my answer is wrong
why my answer is wrong?
bright skiff
Since we have the factored form, lets plug in the numbers for each of the three sections made by the asymptotes,
supple sun
It’s because it’s positive before and after the roots
bright skiff
$(-6+5)(-6-3)=3, (0+5)(0-3)=-15, (4+5)(4-3)=9
oops
$(-6+5)(-6-3)=3, (0+5)(0-3)=-15, (4+5)(4-3)=9$
supple sun
You found the roots -5 and 3
thorny flameBOT
whynoms
bright skiff
-6 is a number in the first section, 0 is a number inbetween the roots, and 4 is a number greater than both roots.
supple sun
your polynomial is of sign of a which is in this case positive before and after the roots
bright skiff
And, when x is lower than -5, we get a positive result, when -5<x<3 we get a negative result, and when x is greater than 3 we get a positive result.
neon iron
And, when x is lower than -5, we get a positive result, when -5<x<3 we get a neg...
what does that means?
neon iron
So it will be positive when x<-5 and x>3
but how can I find the correct answer?
supple sun
You found the roots -5 and 3, there’s a rule for polynomial which is, if the dominant coefficient is positive then your polynomial is positive before and after the roots of the polynomial. If the dominant coefficient is negative then your polynomial is negative before and after the roots of the polynomial
Here you dominant coefficient is 1 so it’s positive
neon iron
You found the roots -5 and 3, there’s a rule for polynomial which is, if the dom...
so the solution cannot be negative?
supple sun
What do you mean by the solution can’t be negative
neon iron
I'm trying to understand, what you means by "it's positive"
if its positive than you may want to say the solution cannot be negative?
supple sun
No what I mean by "it’s positive " is the dominant coefficient of your polynomial is superior to 0
Like 9x^2+x+2, here the dominant coefficient is 9 and it’s superior to 0 so this expression will be superior to 0 before and after the root(s) of the polynomial
bright skiff
I'm trying to understand, what you means by "it's positive"
The original inequality was that $(x-3)(x+5)\ge0$
thorny flameBOT
whynoms
bright skiff
That means we're trying to find all the times when (x-3)(x+5) is positive or equal to 0.
oops
not equal to
Sorry.
neon iron
**Chocolate**
@bright skiff this is the original one
bright skiff
Correct, but I'm giving the factored equation.
supple sun
It’s the same
neon iron
maybe if someone solved it step by step I may understand
because I could not understand your explanations sir Josepsh.P
supple sun
Ok no worries
Just give me one minute
The expression is the sign of a before and after the roots of the polynomial.
Here a=1>0
@neon iron
neon iron
<@456226577798135808>
why sometimes it's x < -5 and ...., and sometimes it is x < -5 or ...
what is the different between or and and in this example
supple sun
Where are the "or" I don’t see them ?
neon iron
also in the right image, should not the answers be the numbers between -5 and 3?
neon iron
like what does the graph V means?
supple sun
It’s the graph of the function
neon iron
but the correct answer according to the website I'm using, it should be **x < -5 or x > 3
**
or not and
so I'm confused why sometimes it is and and sometimes it is or
supple sun
The "or" can be inclusive, which mean, one or the other or the two
Don’t know if I made myself clear
neon iron
in the above example is it inclusive? and why not
x∈(−∞,−5)∪(3,∞)
I guess U means or
not and
topaz sinewBOT
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dark sandal
The number of pairs of shoes at different locations of a retail chain is recorded to the left.
2|7 = 27
Find the median and type it below.
topaz sinewBOT
The number of pairs of shoes at different locations of a retail chain is recorde...
dark sandal
<@&286206848099549185>
topaz sinewBOT
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dark sandal
The number of pairs of shoes at different locations of a retail chain is recorde...
this one
has been 14 minutes
bright skiff
The number of pairs of shoes at different locations of a retail chain is recorde...
What do you know about medians?
dark sandal
What do you know about medians?
wdym
i thought the median would be 6 for that
but its not
bright skiff
6 is not a value in this distribution.
dark sandal
So what would be the answer?
bright skiff
There is 46, 56, and 86 but no 6.
dark sandal
Ohh
46, 56, 86 are neither of the answers tho
itll say this when the answer is typed : "Keep trying! Hint: the median should be between two numbers, so take their average"
bright skiff
There are 20 values in the distribution.
Do you know how to use a stem and leaf plot?
dark sandal
nah
im taking stats this year this is my summer work
i just dont know the answer to that question
are you aware of what it is? because ill just take the answer, ill understand it when they teach it later
bright skiff
Ohh gotcha
bright skiff
are you aware of what it is? because ill just take the answer, ill understand it...
I can help you learn
They're not that difficult.
dark sandal
ngl i waited last minute
bright skiff
😭
dark sandal
so i need to get it done, school is tomorrow for me 😂
bright skiff
me fr
to use a stem and leaf plot, you will reference the key
The stem is the one digit value, and the leaves are the greater than one digit values
If a certain row is 1 | 3 4 5 5, that means (assuming the key is (1|0=10), 13, 14, 15, and 15 are values in this distribution.
Since there are 20 values in this distribution
We can be sure that the median is the 10th + 11th value divided by 2.
What are the 10th and 11th values?
bright skiff
are you aware of what it is? because ill just take the answer, ill understand it...
and also,
dark sandal
What are the 10th and 11th values?
not sure
bright skiff
we are not supposed to just give an answer here...
dark sandal
Ah i understand but its not like youll get in trouble 😂
bright skiff
Well, lets make it into regular values, following the key.
19, 27, 29, 31, 38, 38, 40, 46, 47, 49, 50, 55, 56, 61, 70, 73, 77, 81, 82 and 86
Now, what's the median of this distribution?
dark sandal
52.5
topaz sinewBOT
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@dark sandal Has your question been resolved?
bright skiff
Oop I thought someone else would have done this by now
bright skiff
52.5
if you're still here, no
The tenth value is 49
The eleventh value is 50.
It's a counting error, we all make them
topaz sinewBOT
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wild pawn
topaz sinewBOT
wild pawn
yeah i got no idea
can someone give me ideas on what to do
i already expanded cos(pi + x)
idk what to do with it
worthy storm
how far did you get, can you show your work?
wild pawn
ye
wait
oh my god 💀
im so stupid
why didnt i think of that lmfao
alr thanks
i got it
.close
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slate current
t^3/t^7
flat kindle
it is?
uncut gale
yes thats right
uncut gale
yes
slate current
wait
uncut gale
i mean assuming u mean t and not 3t then yes thats right
slate current
then wtf am i on
uncut gale
when u divide powers w same base u subtract the bases
t^2 - t^3 = t^(-1) which can be written as 1/t
slate current
i tried to test it with 4x6/4x8, which is 3/4, which is not 1/4x2
6x/8x
1/2x
?????
uncut gale
idk where u got 1/4x2 from
slate current
but its not equal to 4x6/4x8 which is like dumb
uncut gale
4^6 isnt 4x6
uncut gale
haha np
slate current
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neon iron
fast check is this good?
topaz sinewBOT
fast check is this good?
drifting swift
why did you not combine 9x - 4x into 5x
and -9 + 1 into -8
but otherwise yes it seems good unless i missed some arithmetic bullshit
cinder rock
when simplifying you leave it as simple as possible usually
your answer is correct but unusually written
drifting swift
I mean do I have to?
well no, you can of course always leave them as is
craggy haven
it's like paying for something in small coins
drifting swift
but then why not fragment the 9x into 6x + 2x + 0.5x + 0.1x + 0.0234x + 0.3766x
cinder rock
just write x + x + x + x + x + x + x + x + x - x - x - x - x - 1 - 1 - 1 - 1 - 1 - 1 - 1 - 1 - 1 + 1
so easy
neon iron
cus profesor will think I'm cheating
drifting swift
for what
cinder rock
write the step down like you did, but add another step underneath will it simplified
neon iron
Yea and leave "EZ"
drifting swift
has your professor already accused you of cheating?
neon iron
No like if I even try to write like your example that's sus especially for D student in math
I tried before
drifting swift
this doesn't answer my question.
has your professor already accused you of cheating before, yes or no
neon iron
no
drifting swift
then what is this bullshit about "professor will think i'm cheating"
if he thinks you are cheating, let him. if he accuses you, it's on him to provide proof or at least evidence.
analog herald
topaz sinewBOT
analog herald
shit
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Available help channel!
small fiber
i understand what the question is asking but don’t know how to find the equation besides guess and check
topaz sinewBOT
i understand what the question is asking but don’t know how to find the equation...
neon iron
i understand what the question is asking but don’t know how to find the equation...
,rotate
thorny flameBOT
neon iron
i understand what the question is asking but don’t know how to find the equation...
question 5?
small fiber
both 4 and 5
silk pewter
X² doens't have 3 zeroes
neon iron
what it means f(x) = (x-a)(x-b)?
it have roots in a and b
generalize it to 3 roots
and change a, b, c to 1, 2 and 3
silk pewter
Yep
small fiber
i don’t know what that is lol
silk pewter
$f(x) = (x-a)(x-b)(x-c)(x-d) \dots$ where the alphabets represent your zeroes
thorny flameBOT
Bettim
neon iron
yeah
small fiber
but the degree has to be greater than one
neon iron
and in b) u can use -x^2 - 1
or just -x^2
simpler
ow wait
you have to have all 3 properties at the same time
sorry
small fiber
yah
silk pewter
,w graph -|(x-1)(x-2)(x-3)|
thorny flameBOT
elfin sparrow
,w graph -|(x-1)(x-2)(x-3)|
that's not a polynomial
neon iron
((x-1)(x-2)(x-3))^2
silk pewter
,w graph -(((x-1)(x-2)(x-3))^2)
thorny flameBOT
elfin sparrow
((x-1)(x-2)(x-3))^2
that'll work but it's upside down, you want f(x) <= 0
small fiber
how do you switch it
neon iron
"-"
neon iron
f(x)>= 0 => -f(x) <= 0
small fiber
how would you do 5
small fiber
how did you figure that out
neon iron
all y values are in a line y = 1
so let this line be the roots
and then u add one up
to the polynomial
small fiber
is roots just like the base line?
small fiber
ohhh
thorny flameBOT
Requested by illiiilliliil.
small fiber
but you need degree greater than 1
neon iron
it is
neon iron
yeah but you're thinking only about case two
small fiber
wait wdym
neon iron
,w expand x(x-1)(x-2) + 1
thorny flameBOT
neon iron
this is cubic
small fiber
so for these type of questions do you just find the point pass through stuff first
neon iron
yea, kinda
neon iron
**Bettim**
just remember this
neon iron
you're welcome
small fiber
.close
small fiber
I don’t know where to start
topaz sinewBOT
I don’t know where to start
strong silo
can you get a more clear image
thorny flameBOT
opal vault
If r(t) = ..., what is r² in terms of t ?
stuck flax
(2/3t^3,t)^2?
That times 4pi
vague pike
last try could someone help me solve the last part of this practice problem that I am doing I need help.
topaz sinewBOT
last try could someone help me solve the last part of this practice problem that...
torpid pendant
You already have the correct functions for each side.
So you can easily find the area of a side, correct? Then if you multiply by the cost per area, then you get the cost for 1 side.
All that remains is to add the cost for all the sides together.
vague pike
i m kinda lost still?
So, the area of each side of the box, in terms of x, are:
Top of the Box: x^2
One Side of the Box: 50 / x
Bottom of the Box: x^2
Cost for bottom = Area * Cost per area = x^2 * 38¢/ft²
@torpid pendant
torpid pendant
Precisely.
Now you do that for each face, yes? And you add them all up based on how many faces there are.
There is 1 top face, 4 lateral faces, and 1 bottom face.
vague pike
holy
torpid pendant
Do you understand?
vague pike
Top of the Box:
Area: x^2
Cost per area: 28¢/ft²
Cost for top = Area * Cost per area = x^2 * 28¢/ft²
One Lateral (Side) Face of the Box:
Area: 50 / x
Cost per area: 10¢/ft²
Cost for one lateral face = Area * Cost per area = (50 / x) * 10¢/ft²
Bottom of the Box:
Area: x^2
Cost per area: 38¢/ft²
Cost for bottom = Area * Cost per area = x^2 * 38¢/ft²
this ?
torpid pendant
Yes.
torpid pendant
Why?
Let's say I give you this: the top face costs 28¢, one side face costs 50¢, and the bottom costs 38¢. What would you do to find the total cost?
torpid pendant
Show your work, what did you do to reach the answer?
How many side faces are there?
vague pike
3 right
torpid pendant
Think of a box in real life, how many of each side are there?
torpid pendant
Each side. Are there 6 top faces, 6 bottoms faces?
There is 1 top face, 4 side faces, and 1 bottom face, right?
vague pike
66x^2 + 200 − 200/x
torpid pendant
Where did you get the +200 - 200/x?
vague pike
vague pike
im using it as a sorta ti-84 calc
torpid pendant
Well, it did not simplify correctly.
If you want to simplify, I recommend using WolframAlpha or something.
sweet shard
Don't use chatgpt for math
vague pike
yeah
vague pike
Well, it did not simplify correctly.
so would i put in the top equation into wolframAlpha
vague pike
Well, it did not simplify correctly.
my friend said he was gonna help me thanks tho
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sonic flume
don't know what im doing wrong
topaz sinewBOT
don't know what im doing wrong
topaz sinewBOT
don't know what im doing wrong
Show your work, and if possible, explain where you are stuck.
sonic flume
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peak crown
topaz sinewBOT
oblique hedge
Negative what
peak crown
neg infinity
oblique hedge
There you go
peak crown
.close
storm halo
How do I find the c for which f(c)=-2 on #19?
topaz sinewBOT
How do I find the c for which f(c)=-2 on #19?
neon iron
How do I find the c for which f(c)=-2 on #19?
3c^2 -4c -3 = -2
you know how to solve this?
rustic sparrow
what am i doing wrong
rustic sparrow
ok i closed the other one i forg i had it
rustic sparrow
ok so what do i do
tall wolf
or put theta instead of x when you define it
rustic sparrow
or put theta instead of x when you define it
wdym ?
thorny flameBOT
Arctrices
rustic sparrow
what am i doing wrong
read the question
tall wolf
thats unrelated to graphing
restive inlet
the issue was that you had different variables on each side of the equation
rustic sparrow
the issue was that you had different variables on each side of the equation
no matter how many 0's i add its still 0
restive inlet
,W sin(pi/-0.1)
thorny flameBOT
rustic sparrow
similarly those would all end up being multiples of 10
wdym ?
restive inlet
1/0.01 = ?
rustic sparrow
10
restive inlet
1/0.001 = ?