#help-26
1 messages · Page 11 of 1
yes I think this is the correct answer
@oak sequoia Has your question been resolved?
What is the condition?
The largest number appearing is 9.
So even if 9 doesn't appear, you still don't get anything that's greater than 9
so it's fine
so it doesn't matter if you select 1 7 times or 9 7 times
whatever you're getting the largest of those is not exceeding 9
..... 
This is the correct answer btw, none of the options were correct
ok wtf.... your code is wrong
what does trail() return
it returns a boolean value
knowing python the boolean value will get changed to either 0 or 1
Yeah
the question asks the probabilty of the largest number being 9
so it does matter if we dont get any 9s
that's why remove all the cases were we dont pick 9
i.e. (8/15)^7
so the final answer comes out to be (9/15)^7 - (8/15)^7
hmm if it asks to give you that the largest number picked is exactly 9 then I guess it should be equal to (9^7 - 8^7)/(15^7)
doesn't is 9 mean the exact same as exactly 9
honestly I don't know about that
but I can tell you that what you did is correct if it asks for "exactly 9"
ask who made the question I guess
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you're welcome
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im having a bit of problem with this question
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
2
You're given the antiderivative so you can differentiate it to work backwards
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Hello so I tried solving this homework exercise and I wanted to check if it was right. I used the formulas we learned a couple of days ago but the answers seem weird? I just wanna see if I make some error
Ps I Translated from French to English so it may not be all correct English terms
Looks good!
Although it looks like you can't decide whether to call the intersection point I or H
Is it all right?
(or is that M)
Yeah the math is right, just the name of that point keeps changing
Sometimes it's I and sometimes it's H
Lol 😂 if the math is right I’m fine with changing the letter xD
Thank you so much
np 👍
How do I close the channel^^
you can type .close
.close
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equation 1 :
x + 1 = 4 , x is not equal to 0
equation 2:
2x + 2 = 8
are these equations equivalent?
I think they are, because they have the same set of solutions (that's just 3).
I am asking this, because one equation has a condition, and the other one doesn't have.
yeah...
but it could be any condition,
so, as long as it doesn't affect the solution set, it doesn't matter... i suppose

@neon iron Has your question been resolved?
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Hey can someone please help me with this question?
A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 38 years now, the son's age five years back was?
A. 12
B. 14
C. 19
D. 33
So far,
I let the father's age be F
and the son's age as S
So the father's age now is 38
Let P be the fathers age when the son was born
38 - S = P
Wait hold on
so
lets change it
let X be the number of years ago
and the father's age be F which is 38
and the son's age be S
So 38 - X = S
How do I solve from there?
what do I substitute?
Hint, at present the father is twice as old as the son
He's telling his son he had his age when he was born
Yes
Wait, did I misread? 🤔
19 is correct as the father's age when the son was born
but how did you get that other then common snense
like how do we solve it?
If the son is X years old at present and the father was X years old when he was born, then the father is 2X old at present
So, if the father is 38, the son is 19, and five years ago he was 14

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Isn't it no because P(A intersection B) != P(A)P(B)
makes no sense
how can you say that equals P(B)
what does it mean for A, B to be mutually exclusive
having a mathematical definition for that term "mutually exclusive" might help you out
they know what it means, that's the first thing they write there
oh well i didn't see 😦
P(A intersection B) is a empty set. So all that's left would be P(B) which is given.
Where?
2nd line
the probability that A happens given B happened should be 0 since they are ME right?
but you've written that it's P(B)
Wait why would it be 0? I wrote a condition for P(B), that it had to be greater than 0.
which, if they are ME, must be 0
if B has happened
A CANNOT also happen
otherwise they wouldn't be ME
so then P(A|B) = 0
similarly for P(B|A)
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is this a typo from textbook
Probably yeah
@dense anvil Has your question been resolved?
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how would you find the vertex's of a nth degree polynomial
do you know calculus
do you have an nth degree polynomial you’re trying to find the vertices of?
dont have a specific one just wanted to know
one way would be to differentiate it and then set the derivative to be equal to 0
a routine thing to do, if you know calculus
What led you to this question?
uhhh i was drawing
polynomials
but it wasnt required to find the vertex
just the intercepts
If you want a method you can apply, then here’s one: let p(x) be a polynomial, like $$ p(x) = ax^n + bx^{n - 1} + cx^{n - 2} +\cdots + z $$
(a + b)^2 = a^2 + b^2
Then consider $$ p’(x) = nax^{n - 1} + (n-1)bx^{n-2} + \cdots + z_1 $$
Set p’(x) = 0, then the resulting solutions will be the x coordinates of the vertices
You’ll learn why this works in calculus
(a + b)^2 = a^2 + b^2
chain rule?
what
nvm
ok tytyty
.close
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What branch or topic of math does this Question belong to?And also help me with the answer.
Synthetic Geometry?
or Euclidean geometry
well euclidean geometry is a subfield of synthetic geometry
You could use Apollonius's theorem
Relates the legs and medians of a triangle
Synthetic geometry like coordinate geometry?
the opposite
Synthetic geometry doesn't use a coordiante system
just uses the postulates, axioms, theorems or whatever
Gotcha TQ bro
@neon iron Has your question been resolved?
Yes
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is the limit e not supposed to have a little negative on it?
and how did they get - infinity, i could just conclude that its divergant
ln x goes to -inf as x goes to 0
technically yes but when M -> e with M > e, the limit does not exist
same thing here, x going to 0- wouldn't make sense
so when do I need to use the negative, and when can i just put it the number
always put the sign if you're not sure it can be removed
what do you mean by "put in the number"
replace M by e here for example ?
yeah by number i mean the limit that makes the integral improper
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this is so random but uhh
i just randomly thought about this
so if we have like the number 5 for example
half of it is 2.5
but if we have 5 objects
lined up
the middle on is the 3rd one
is there a technical name for that middle number
why is yours censored
me redefining stuff 😭😭😭

in complicated ways

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how do u do this
I try taking k to be 1 and simplifying the expression
But it doesn't reduce to smth meaningful
Show your work, and if possible, explain where you are stuck.
which part?
you want to find k, not set k to be 1
use calc for part a
Can u specify how
a (differentiable) function is constant iff the derivative is 0 everywhere
yes
i cant solve this tho
why not?
i dont know how
rearrange for k...?
you may be able to just use trig identities for these but it'll prolly be long and inefficient
1-3sin^2xxcos^2x + k(1-2sin^2xcos^2x)
Simplify the expression
-3-2k=0
k=3/2

i think
u might be able to juse use sin^2+cos^2
and make it squared
and cubed
to get the expression?
or possibly express cos in terms of sin vice versa

its much simpler than that
i think derivative is harder:(
k= what?
equate to 0 and rearrange
i need to bike home
@timid moth Has your question been resolved?
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how do you do a and b?
is this the correct working out?
arent they the same anyway
cause its an isoceles
it is
so how do i write the answer for a and b
i dont know
how do you work out that xbc is 75 degrees without knowing it is
wait a min
this stuff isnt even on our test
oh my god i wasted so much time learning this
im gonna close this thanks for the help.
you 2
.close
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we can find the perimeter
How?
since the three sides with x are joined by two right angles, you can draw in another side temporarily to create a square with side length x
then figure out the remaining two sides using pythagoras
?
@rancid rock Has your question been resolved?
Can someone please help
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help
Yeah no worries lmao I was doing that
I have to revise scientific notation calculations for an exam
(4,8 x 10^8) + (1,2 x 10^7)
(7,2 x 10^-3) ÷ (2 x 10^-5)
(3,5 x 10^-9) - (4,1 x 10^2)
(2,5 x 10^4) x (3 x 10^6)
i only know how to solve the multiplication one
how do i solve the others
are you familiar with the properties of exponents
like (a^n)^m =a^mn
sorry, i learn math in fr🤮nch
these? lemme send u a pic
yes
oh yeah ik them
ok for this one you can just divide 4.8 by 1.2
but my question is how do we do it if we have differents exponents (m & n) and numbers (a & b)
$$ \frac{4.8(10^8)}{1.2(10^7)} $$
$$\frac{4.8}{1.2} \frac{10^8}{10^7}$$
brandon_hu
what
what's this beautiful mathematical visualization tool?
do you get that
its in the formulas yes
ohhh i forgot we can put it in the form of a fraction
bruhhhh my bad
latex
how does it work, please tell me
can you do this one @low fable
yes
its simple i just got it
but about the addition
if we have different exponents and numbers, how does it work
||just wanted to say that i am not stupid, i just forgot everything i've seen in maths during this year||
thats okay
so?
ok so for this one you have two options
write it normally then add
then convert to scientific notation
yes?
isnt that too long?
ok, what about 7x10^7 - 7x10^6
then just move the decimal one to the left and add 1 to the exponent
this problem, in a math exam, i just wrote 70000000-700000=63000000=6,3x10^7
then make it scientific notation
but the teacher said the justification was a complex one
that is also correct
is there a simpler justification?
yes but i didnt get all points
I think it's easier to understand if you try to visualize the numbers in your cranium
my cranium tiredium
i didnt say i dont know how to do it
i said how do i justify the calculation
in a simpler way
10^6 is 1 one decimal place smaller than 10^7
you can either lower the highest exponent or raise the lowest
whatever is easier for you
so 10^7 + 10^6 is just (1+0.1) 10^7
the decimal moves over one because it's one smaller
ohhh yeah u just reminded me this is how she said we should answer!
thx bro
ok now onto the next chapter
statistics
(btw if yall wondering i am revising for DNB, its to pass to 10th grade, the exam is tmr and i havent revised anything)
i have 11 chapters to revise
in 6hours
luckily i still remember some things
let me tell u what i need to learn for statistics chapter
and histograms
hello?
i do not know french
I order croissant
whats moyenne in english i forgot
i am not fr🤮nch, i just study in a fr🤮nch school
oh yeah the average
do we say weighted average in english too?
,,
,,help
Please use ,help tex for command help.
,help tex
Render LaTeX code.
,, <equations>
,tex <code>
,align <align block>
,texsp <code>
,texw <code>
,tikz <code>
Click
to show more information.
,, 1*1
YOOOOOOO IT WORKS
,, (1,83^-2)/(93x)
,, (1,83^(-2)//(93x)
,, (1,83^(-2))//(93x)
nvm bro is stupid
,, (1,83^-2//(93x)
Mended
see? he's stopid
we just dont know the syntax
delete him
you can write incredibly complex stuff in latex
do u know averages and medians
thats for later
yes ik
divide by the number of terms
do we say weighted averages in english?
like for example
do we say 11x3+12x7+13x12+16x10+15x6+16x2/3+7+12+10+6+2
production of honey in kgs
and the other one number of beehives
the average is 13.875kg per beehive
thats the weighted average (in french)
that sounds right
so you guys say it in english?
maybe
population is all of the individuals studied
and character is the studied particularity
for example here the population is the beehives
I mean for the most part it is the same
and the character its the amount of honey they produce
o sorry wrong channel
np
that makes sense
ok got it?
yes
now you of course know whats a median
The values of the series are arranged in ascending order;
We divide the total workforce by 2;
If the total count is odd, then the median is the central value;
If the total frequency is even, then the median is the half-sum of the two central values.
do u know this
yes
ok
what about " l'étendue "
like the difference between the biggest and the smallest value
its a dispersion indicator or smthing
the more the étendue is big, the more the serie is dispersed
yeah we should pass statistics chapter its easy
@dusk fossil do u know something called " calcul littéral "
and remarquable identities
ping me when u get back
i am familiar i just never knew they had a name
(a+b)²= something like that
there are 3 of themm
im familiar with all of this
entering college
10th?
13th
bruh
ur older than me which i do not accept
anyways
yeah lets skip this chapter as well
i'll just do some exercices to be sure
u know what man
i'll do some exercices real quick for all my chapters
whats your biggest struggle
then come back if i have some problems
thats the problem , i dont know
ok just ping me
let me do a mock exam
will do
Yup
🥐
Kebab ????
LETS GO ENFIN QUELQUN

t'es en quelle année d'étude
1ere année de master
l'order croissant
oaaa c'est loin ca
yes 🥐 order
i order croissant
Mais c'est un master en enseignement par contre
chuis dans la merde j'ai le brevet demain
ah tu va devenir prof?
Ui
bah bonne chance hein?
Tu t'y es pris a temps du coup ?
non comme un gros con
Aïe
j révise au dernier jour
is it true that parisians speak in reverse french
Yup
parisians are weird
and sometimes those reversed words become reversed
im not even french
thats weird
ahh le verlan
de ouf
how does that even occur
i guess they just get bored after living in a city that smells like piss
i dunno it just happened
i see who you are
you are my enemy
myyy enemy
you are my enemy
idk what they are saying
man i hate thalès and pythagore although they're simple
thales
theorem
@elder leaf tu connais yvan monka?
Oui
i know latin
mortis
and i can kinda under stand this
C'est un bon truc pour la surface du cours, mais pour comprendre le fond, il faut le travailler avec des exos qu'il ne donne pas forcément
bien sur j vais faire des brevets example
c'est nécessaire sinon tu va rien comprendre aux problèmes
Sus scrofa domesticus
Yes
thats not correct
cap
it would be tu sum scrofam domesticam es or sum scrofam domesticam es
latin is a dead language
the sus is redundant
ah yes astaghfirullah i forgot
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Hi, I’m trying to solve this inverse laplace transform, this is what I did, where is my error? I don’t get the same result of wolfram
@uncut agate Has your question been resolved?
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maybe remove your helper role if you're not willing to read two sentences
Thank you! 🙏🏻
If it’s hard to read then I can take another photo for you but I don’t understand how you can call yourself a “helper” if you can’t read to lines of question?
<@&268886789983436800>
true irony
can one of you help me please (with the q)
thanks for dealing with the other guy btw
<@&286206848099549185>
If the person doesn't win either of the games, there are two scenarios where that happens: draw in chess and lose in pool OR lose in chess and lose in pool. How I do probability trees is I "travel" along the paths, multiplying along the way. So we'd multiply draw in chess times lose in pool, then do the same for the other scenario, then add the two probabilities
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using sohcahtoa to solve this
how do u determine if the the values r negative or not
cause who says the hypotenuse, 7, can't be negative
(need this for future problems)
like how did they determine that 7 should be positive
have you ever heard of "All Students Take Calculus"?
rings a bell
but i dont remember
starting in quadrant 1 and going counter clockwise, it'll tell you which trig function is positive in which quadrant:
Q1: All positive
Q2: Sin positive
Q3: Tan positive
Q4: Cos positive
Hence, "all students take calculus"
that's how you determine what's positive and negative
can you demonstrate how it would work in the problem above i sent
csc (theta) = -7/3
so
according to this, csc would be positive?
$csc(\theta) = -\frac{7}{3}\\$
$csc(\theta) = \frac{1}{sin(\theta)} = -\frac{3}{7}$.
MellowDramaLlama
that tells us that the sin term is negative
sec = 1/cos as well, so if sec < 0, then cos < 0
so we know we're in Q3
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I just need some help figuring out how to solve for range.
I already set f(x) as “y” and went to solve for x, to which I got x = +/- 2, but I’m not entirely sure if my process to get to that answer was correct, or what to do now that I’ve got what “x” equals.
Are you familiar with the definition of the range?
All possible outputs from a function, right?
Yes! 😄
Hmmmmmm...
Well, to help myself atleast see what I'm working with, I threw it into a graph, and now I'm wondering if the answer is just +/- Infinity, because it just keeps towards +/- 4, but never reaching there, as is what I figured out when I got the domain
I like your domain 🙂
Er... although the "other" question I would have now is, without a graph, how would you show that..? If it's clear through a graph that the answer isn't infinity, do I just "say" what the range is?
Putting f(x) as y and solving for x got me to +/-2, but the graph shows a much more believeable +/- Infinity
I'm not familiar with this method, sry
Well by common sense / "say".
Usually, the domain will limit the range
however, here the domain doesn't impose restrictions on the maximum and minimum values of the output
So the domain is just telling me where the limit will be, but not how high/low the value of the output will be
That sounds about right! And then you find those values of the extremes, that would be your range
A light example:
f(x) = 4x for -1 < x < 4
Also called Domain: (-1, 4)
Then the range would be:
4 * -1 and 4 *4:
Range: [-4, 16]
The domain is all numbers greater then -1 and less then 4.. right?
o-
saw the edit
Hehe nice.
Minor mistake: The < should be <= and same for >= I believe
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Ye sure Lemme látex it rq homey
np
$210 \pi m^2 \cdot 1.5 mm = 210 \pi m^2 \cdot 1.5 mm \cdot \frac {1 m}{1000 mm} = \frac {210 \pi m^2 \cdot 1.5 m}{1000} = \frac {315 \pi m^3}{1000} = \frac {63 \pi m^3}{200}$
northsteve
@half edge THANK YOU

NP BRUDA

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domain of $e^{\frac{-1}{|t|}}$
steamhahasteamhaha
Is it all except 0?
what do you mean by full support
like as in every input value is valid
oh ok
the domain is R in other words
i wouldnt use the word support that word is taken by something else
I wasn't sure at first becuase isn't e^-infinity = 0? 🤔
yeah good point
e^x trends to 0 as x goes to negative infinity
-infinity isn't a number unless you're working in something called the projective plane (you're not)
how about this one
$\frac{\ln (1-t)}{t}$
is it $( -\infty, 0) \cup (0, 1)$
\cup for union btw
seems right to me
steamhahasteamhaha
ty
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hiya
I’m stuck after reaching -1/(uk+2)
do i have to prove uk >0 with mathematical induction first or is there another method
Wym?
Oh + 1 - 1?
I'd argue it's quite clear that u_n > 0 for all n
But you care about bounding it above
ohhh okay ty
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can anyone help me with math
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heres the diagram
for part b i dont get how the magnitude of the acceleration when the string is slack = gsintheta
acceleration due to gravity is directly down at g
but we care about the acceleration in the direction down the slope
hmm so 3gsintheta would be wrong? because that's just a component rather than acceleration?
well... it's probably the component we care about
Is the surface frictionless?
yeah
Alright, so we can set up the system of equations mg - T = ma and T - mgsin(theta) = ma
(Assuming the hanging object is going down, if something goes wrong then we do the other case)
It says so?
why would the hanging object go up?
pretty sure B is going to fall and hit the ground with a loud bang
'B is immediately brought to rest by impact with the ground'
yeah im asking about A's acceleration when string goes slack
after it hits
B can't hit the ground if it goes up 
Anyway, here you can solve for T easily
Or you wanted to start with part b/c?
yeah im asking about part b😭
if A comes to rest the surface is definitely not frictionless
i see where you're coming from thats technically true
but question said smooth fixed plane so i guess they simplified it in that sense
Alright, so, since B travelled a distance of 0.8m, A must have also travelled that amount but on the inclined plane
plus the string doesnt break anyway it just goes slack
So CD = 0.8m
oh "instantaneous rest" as in it just stops yeah ok i see
only part i dont really get is why the acceleration is gsintheta
everything else is quite standard, u use the final velocity as initial velocity and work out the remaining distance to add on to 0.8
i'm very confused by this question because from what you've said it doesn't seem to require g at all
When you draw the mg vector for A and project it onto the inclined plane, you get mgsin(theta)
F = ma
isnt this the point where it has instantaneously stopped though
isnt that only for motion
ah now im so confused
does it talk about g sin theta for part (b) or part a?
part b
Weird, it's more relevant in part a
Anyway, if only gravity is acting upon an object on an inclined plane, then its acceleration will be F/m or mgsin(theta)/m and hence gsin(theta)
okay i kinda am getting it, used f = ma as it is still moving and hasnt stopped yet
and i got a = -g sin theta
im wondering if they just made it positive because its the 'magnitude' of the acceleration
since surely if its going to stop, acceleration has to be negative as its basically decelerating
Magnitude is always nonnegative, yeah
shit question
but makes sense now, ill just use f=ma if its moving
thanks both
.clse
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Hello, how to show that $2^{n} - 1$ is a prime number only when n is prime
lilisworld
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hello! i recently learned how to attack geometry problems with vectors, and i wanted to try it on an AIME problem. (i know vectors may not be the best way to do this, but i want to learn and practice)
whenever I try my "slick vector method", i get a wrong answer
if you consider A as (0, 0, 0)
then A->B + A->C + A->D = A->G
(sorry i don't know how to notate vectors)
so B + C + D - 3A = G - A
2A = B + C + D - G
so then, as my textbook told me, I can put the origin wherever i want
so i set the origin to point P
then i know the lengths of B, C, D, and G cuz they're given in the problem, and from that i should be able to find A
but when i plug in these values, i get a messy radical expression which doesn't match the given answer
So you set the origin to A, and to P?
uh
so i derived this with the origin as A
if i move the origin, does that make the equation invalid
2 times a point = the sum of 3 points, minus another point?
Or, these are vectors from the origin to these points, given that the origin is A?
We typically call the origin "point O", and then a vector from O to B would be "OB"
My major concern is I don't see any statement about P at all in your write up
oooh okay
2OA = OB + OC + OD - OG
now from my understanding, i could set O wherever I wanted
so i wanted to set O to P
Problem is that choosing the origin twice is essentially saying A = P
I see you're trying to decouple these two settings, but
- You don't really gain anything from a temporary O
- You're likely mistaken at this point
Now, I think you can still do this work without setting A as the origin anywhere. Your first equation can still say:
AB + AC + AD = AG
Okay wait I think I see what you're saying. Let O be any point
i feel like this claim should hold for any O
@buoyant bane Has your question been resolved?
i think i can ping <@&286206848099549185>
if this claim is true for any O, why does it not work for point P?
@buoyant bane Has your question been resolved?
i took a shower and realized why i'm wrong
i'm plugging in the magnitudes of the vectors rather than the vectors themselves, so of course it will give me a nonsense answer
lesson learned: if you ever can't figure out a problem, take a shower
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I'm not very good at integration
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<@&286206848099549185> can y'all help me with physics problem?
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what is the value of zero factorial
1
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Hi. Please someone help me.
Please don't occupy multiple help channels.
Draw a 6-sided shape that divides the shape into 4 equal parts using only one possible line.
closed your other channel
is there a picture to go with this?
Just that.
But that's not answer
It's just for showing 6-sided shape
So?
<@&286206848099549185>
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@snow girder Has your question been resolved?
@sweet shard can you help me?
no, i can't read this
It's just this
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@snow girder Has your question been resolved?
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looks like an injection problem
injection/injective is synonomous to one-to-one
https://www.khanacademy.org/math/linear-algebra/matrix-transformations/inverse-transformations/v/surjective-onto-and-injective-one-to-one-functions
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hey
sequence of functions
if the sequence converges uniformly, then the function f inherits integradability from the sequence
does someone have a nice proof for this?
i want to change this then to show or not show the same for improper integrals
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How would the diagram for this look? Im having trouble visualizing it
Hello
Start by drawing the object
Preferably on an horizontal surface
A point object
Like this?
20 degrees to each other
that seems like what I have in my head
20 degrees is a lot smaller than that but hey it's a diagram
The angle between the force vectors is 20 degrees
? Isnt the angle between the 2 vectors in my diagram 20 degrees? Or am i understanding it wrong
Draw the arrows to indicate their direction
The angle between their tails is the angle between them
the resultant
or should it be in the other direction maybe?
oh okok
Also that equation you wrote is wrong
o what equation do i use for it?
No no
?
ok ill use that formula and see if i get the correct answer
I don't think it's the cosine law
oh yeah cosinelaw is -2abcostheta
How did it go
oneee sec im trying to fully understand it first
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For $f(x,y) = xy$ on $4x^2+y^2 = 8$, how can I find max and min using Lagrange Multipliers?
KN
$f_x = \lambda g_x \implies y = \lambda 8x$
KN
$f_y = \lambda g_y \implies x = \lambda 2y$
KN
Then $y = 16 \lambda^2y$
KN
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$\lim_{{x \to 0}_{y \to 0}} \frac{y^2 + \sin x}{x^2 + \sin y}$ where $(x,y) \to (0,0)$ along $x = y^2$
neonperseus
idk how to write it in LaTeX the way the worksheet puts it
But I've never done this before
So uh
How do you
so, lim (y^2+sin(y^2))/(y^4+sin(y))?
Can you treat it like seperate limits
Oh
lmao
I'm overthinking
I was gonna plot graphs and do wierd shit
Thanks ann
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