#help-26
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$cot\theta - cot\theta \cdot cos^{2}\theta \newline cot\theta \cdot (1 - cos^{2}\theta) \newline cot\theta \cdot sin^2\theta$
imTyp0
and then yeah just know cot is cos/sin
so that's sinxcosx, or if you want, sin(2x)/2
Ohhh
A good thing to do when doing these trig identities is to always take out what's in common. Then it almost always makes it easier to see what's next :)
So it becomes cos(theta)*sin(theta)?
yes
And we can’t simplify any further right
you could, but we could argue it's not really simplifying. If I was your teacher I wouldn't be mad if you left it at that
Ah okay cool. Thank you for the help!
I’ll try keep that in mind
no worries! Also just so you know, what @quick pawn said is 100% correct. It's just that there are many, many ways to solve trigonometric identities, and that's just the one I saw first :)
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Man I think I messed up somewhere I’m not sure what to do now
split the beginning fraction into 2 fractions
Like splitting it so I can perform multiplication? Or keep it into adding
adding
o ok
cosx /sinx is not tanx
Like this?
Wait wut
you got it?
So I just do the same thing I did but just fix up the tan
what would it look like if I had it the correct way around
look what happenes when you fix the tan
is it supposed to be sin(x)/cos^2(x)
yeah...
Well
Hey
Good exercise converting stuff in terms of sine and cosine
Lol thanks for the help
lol
.close
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how would i go about solving this?
I have tried an alternating series test, ratio test, and divergence test with no success
oh and a limit comparison test
Part b?
Heeeey 
:D
And that's the harmonic series, the absolute value of it diverges 
how
;-;
could i compare it to a harmonic?
so it converges conditionally?
so how would i show that on paper?
Yea it converges conditionally (was gonna say that it doesn't converge absolutely, but does meet the criteria for conditional convergence)
There's a theorem somewhere for conditional convergence that if you have some decreasing positive sequence that converges to zero, then the "alternating series of that sequence" converges at least conditionally
As for not converging absolutely, you can compare the absolute value of the series to the harmonic series yea, as it would just be a scaled version of it
hmmm okay
im still confused on what test i would do to prove that initial one
because the alternative series was inconclusive
i think
Hmm, are you happy that the series $\sum_{k=1}^{\infty} \frac{1}{k}$ diverges?
@vernal matrix
yes
Then for the series you have, when you take the absolute value, you have
[
\sum_{k=1}^{\infty} \abs{\frac{(-1)^{k + 1}}{2k}} = \sum_{k=1}^{\infty} \frac{1}{2k} = \frac{1}{2} \sum_{k=1}^{\infty} \frac{1}{k}
]
and so you know that you can't converge absolutely from there
@vernal matrix
I have tried an alternating series test
did you?
sorry i had to do something
lemme do it now
yeah i got that
and now lemme compare it to a harmonic
i have that now
and how would i go from here?
would it just be a geometric?
Well you've shown that it doesn't converge absolutely, and you showed that it converges conditionally by the alternating series test, so you're done, no?
is that automatically assumed?
im a bit confused by that
how did i show it doesn’t converge absolutely
im not as comfortable with AST as i am with other tests
At this point you compared the absolute series with the harmonic series, which showed that it doesn't converge absolutely
Hopefully it does 
Then, do you have the conditions for the alternating series test anywhere? 
i don’t believe so
Finessing this one here 
That's basically the "decreasing positive sequence that converges to zero" statement that I said here
lovely to help (and see!) you 
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for this question, did we have to use the numbers on the bottom of the graph? i just estimated that the limit is 4
i'm not sure what the numbers on the bottom even mean
no the numbers on the buttom have no relation whatsoever
is 4 correct anyways?
yeah
ok thx
i mean as long as we dont have to prove |2x| is continous therefore u just have to calculate |-4|
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binomial
But if you really need to, use the binomial theorem
Yes, as simple as that
Of course!
Coefficient, they mean only the number preceding the variable x
Variable part, they mean x^
Yess
This is an arithmetic series
f[n] = -12 + 3n
is our sequence here
As, you can see, we are summing up from (-9) to (-12+3n)
Which means we are summing up from f[1] to f[n]
Right?
hello?
Did you understand so far?
It is our sequence
Have you not studied sequences yet?!
They resemble to function f(x), except instead of x (REAL), we use n (NATURAL)
fine
😋
although try using f[n], gives you a feel as if you're dealing with functions f(x)
just instead of x which is real
we only consier the natural numbers n
Anyways
So yeahh, we have an arithmetic series here
Have you guys studied arithmetic series?
Yes
it is already given, the sequence
Look at the last
They are asking you to compute the sum of this arithmetic series
Until f[n] lol
it is obvious!!
from f[1] to f[n]
because f[1]=-9
you can just substitute
Allright
Since you have studied the arithmetic series
I assume you have been given a formula
There is a formula which you can use to find the sum of the arithmetic series
You only need to know the first and last element
first and last term of the series
exactly
you have it
it is -12+3n
-12+3n is the term
it does not have to be a number
Hahaha
You just plug the first (-9) and (-12+3n)
Since the last term is a function of the variable n
The sum also will be a function of n
One of the advantages of this is that after finding the closed form of the sum of the series
You can plug any n
And know the sum from the first term up to any nth term
Yes, it is!
Well, first, f[0]=-2
And not f[1]
f[1]=0.8
you can see, it is the following term
and r=-0.4
And not +0.4
The sign of the terms is alternating
Our sequence is:
f[n] = (-2) . (-0.4)^n
n=0,1,2,3,...
@crisp scarab Has your question been resolved?
Simply that the sequence starts from index 0
And not 1
They all start from 0 lol
The previous one did not start from 1
The sequence from the previous exercise also starts from 0
But we were interested in summing from the first term to the nth term
Look, you can either start by 0, or by 1
in case you start by 0
f[n] = f[0] . r^n
in case you start by 1
f[n] = f[1] . r^(n-1)
But which is better?
I honestly prefer 0
All the time
You sound like someone who codes
Even if you think of it logically, in math way
Sequences have a domain of definition which is the set of natural numbers
0,1,2,3,...
I do actually!
0 simplifies work
r^n
not r^(n-m)
Anyways, you just use your geometric series formula
you have the first term, you have the last term
which is n
Btw, if you never saw it yet, I wanted to dm you
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,rccw
I want my answer to get checked
send it through
so there are 119 possible values of the common difference?
Yes
Integer values
what are they?
also are we considering e.g. 59, 60, 61 and 61, 60, 59 as different progressions for this problem? the statement doesn't make that clear
i'd assume the answer would be even because of this
@ornate magnet
Yes
No one case will be 60,60,60
Yes
arithmetic progressions with difference 0 exist
i read Ls as in lengths
$\angle$s
😑
Ann
is what was meant
i see
would have been easier not to abbreviate
this is the same kind of "takes you a moment" abbreviation as "+ve"
you appear to be
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$sin^2x = sin(x)^2$
Ilvvus
Yes, although no one writes it the second way
oh ok
AustinU
is different
alr then
AustinU
but, it is much more usual/normal to write it the first way you did
AustinU
like so
alr thanks
$(\frac{sinx}{cosx} + 2) (2 \frac{sinx}{cosx} +1) = (2 \frac{sin^2x}{cos^2x} +2)$
Ilvvus
why is this false?
no worries, it happens
its such a beginner mistake too
forgetting to multiply each member with each other member
I still do the box method much too often XD
we wouldnt be able to apply an algebraic identity here right
What do you mean by that?
I'd try to avoid using that, if you can see the general pattern on your own then use it to speed up the process
but don't try to apply any formulas you can't really understand
nah i do understand it
im just having severe brain fog rn because its very late and im tired
Yeah no worries
the reason it doesn't completely apply here is because the first term of the binomials isn't the same
in one you have 2sin/cos and the other you just have sin/cos
no problem!
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Fast way to do this?
Idk what to do
I do not want to plug in these numbers to check
how do i solve without plugging in numbers
do you know how to derivative
yes, i did it in image
this is wrong
it looks fine
the derivative is wrong but its for finding critical points and they divided by 6
bad form but whatever
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@neon iron Has your question been resolved?
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So I want to calculate a probability. I have a game, where I have m amount of meteors I need to shoot down. For that I have c amount of cannons. Each of these has a default probability of hitting one single meteors of p = 0.8. Now, I want to get the probability, that all meteors get shot down. Note that a cannon can only shoot once.
My current solution can only calculate the probability that c amount of cannons can shoot down one meteor (see png)
I don't know any advanced probability things, I just drew a tree and looked at any path that leads to the probability of shooting down a meteor. (see png 2)
Is there a way to calculate the probability, that all meteors get shot down by the cannons, instead of only for one?
@wicked totem Has your question been resolved?
@wicked totem Has your question been resolved?
@wicked totem Has your question been resolved?
<@&286206848099549185>
@wicked totem Has your question been resolved?
.close
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Need help with angles ;
How do I convert:
(30.0/0) facing south towards positive Z
To
(??/??) facing east towards positive X
@summer badger Has your question been resolved?
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Can someone explain graphically why it's continous at 0
this is the graph
basically when it's slightly greater than 0, it's just 0. When it's slightly smaller, it's x*-1
and x*(-1) at 0 is 0
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im trying to find the range of this function however I cant quite get the final step the question is: Given the function f(x) = 1/(x^2 - 1), find the domain and range of the function.
struggling with how to convert x=sqrt(1+1/y) into an answer
<@&286206848099549185>
x=√(1+1/y)
y cannot be zero
and 1+1/y cannot be less than 0
(it is in square root)
say 1+1/y<0
1/y<-1
y>-1
so y cannot be between 0 and -1
can be -1, cant be zero
{R/(-1,0]}
so does that mean y is anything greater than 0
or should i write it as y cannot equal specifically -1 and 0
this
it just cant be 0 and between 0 and -1
can be everything else
ok thanks
but how can that be written in set builder notation
bcs thats what my school requires
y>0 and y<=-1
great thanks
or (0,inf)U(-inf,-1]
@minor plume Has your question been resolved?
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https://www.youtube.com/watch?v=iSaRqVkImfw is Mathematical Induction more or less about finding patterns?
From Thinkwell's College Algebra
Chapter 9 Sequences, Series, and Probability, Subchapter 9.4 Mathematical Induction
sometimes induction holds up, sometimes it doesn't
I've also heard Induction described with TAPE:
Test
Assume
Prove
Explain
yes, I'd say finding patterns is important
Progrssion
I usually do Base Case, Assumption, Induction, Conclusion
@cinder oxide this might be too detailed for you, but see if it helps: https://math.stackexchange.com/a/1255268/993372
BCAIC?
Bruh you don't need to make acronyms out of everything
IYDEQYWNASA
BYDNTMAOOE
You assuming he isn't intelligent enough?
"This might be too detailed"
L
avid has been around for a while, we know the level he's at right now
hes made Progrssion he is ready
"detailed" != "difficult"
whats your problem?
<@&268886789983436800> likely troll
you do attract them avid
.close
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How do I prove that every term in the sequence n^2-8n+21 is positive?
you could prove that n^2 - 8n + 21 is positive for all real n
How do I do that
For natural n, complete induction would probably work
Why not just use the discriminant
completing the square would be useful
you meant discriminant for sure
overkill
Yeah, probably
How do I use discriminate / completing the square
What’s this
b²-4ac < 0
Not really
I did that a long time ago
because a > 0, so it opens upwards. Therefore it must not intersect the x axis for it to be positive. So it shouldn't have any roots, so b²-4ac < 0
Isn’t it for quadratic equations?
So I should just prove it is negative and I’m good to go
That’s all?
I guess I need to learn how to do that again
But how do I know it’s positive?
yes
Yeah sorry it autocorrected I think
complete the square and it will become obvious to you. or not. if it doesn't you can post the completed-square form here and we can give you pointers.
dunno but you don't need induction of any kind here
That’s for more complex proofs
Can be used for proving things like summations but you only need to complete the square for this
Since (n-4)^2 has to be greater than it equal to 0
That expression must be greater than or equal to 5
And hence always positive
^
your thing is 5 + something nonnegative
it is not only positive, it is bounded below by 5
@desert pulsar is it like
"i don't understand what some or all of the words mean in what you said"
or
"i understand what you're saying but not why it's true"
The words you used
Yes
Ok so do you know that a number multiplied by the same number can never be negative?
Yes
So treat the expression (n-4) the same way
You have written down (n-4)^2 + 5
You can rewrite that as (n-4)(n-4) + 5
From what I said before a number multiplied by itself must always be positive
Oh
So what you have there if you think about it is some positive number + 5
A positive number + a positive number can never be negative
Yes
What about the discriminant method?
All you need to do to finish it is say that since the brackets can’t be negative then when you plus it to 5 it must always be positive
Basically the same thing
I got a negative number
Alright
?
Using b^2-4ac
Yes
Then you know that x = (-b +/- the square root of the discriminant)/2a
Yes
If you want to show that the expression is always greater than 0, a way to do that is to show there are no solutions for x
Since whatever x equals is where the expression crosses the x axis
Mhm
If you were to say for example that y = (x-4)^2 + 5
If the equation never crosses the x axis ( in other words it never goes negative) then there would be no solutions for x
When you figure out the determinant, if it is ever less than 0, you have proved that it never crosses the x axis
Since then x equals some number +/- a root of a negative number
Since you can’t do the root of a negative number, the equation has no solutions
Understand?
@desert pulsar Has your question been resolved?
np
Well yes but we are dealing with real numbers in this case
So I didn’t bother mentioning them
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can someone give me the points for this graph
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you mean the equation?
(1, -2) (-5,5)
than did i solve it right
cuz i plug them in the distance calculator
and got 9.21
@civic briar
should be -2 - 5, not -2 + 5
ohhhhh
im so stupid
tysm
wait one more
is the point (5,1) and (5,-5)
@pastel oracle
(5, 1) is right, yes
no
is it 1,-5
no
-1,-5?
no
how did you get (5, 1) for the one point?
yes
same thing for the other point
you shouldn't need to confirm, just count the number of lines to over and up/down
You are right. its (0, -5)
thankks
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,rotate
@sour robin Has your question been resolved?
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Every day the value of my $1 portfolio either doubles with probability p, or halves with probability 1-p. What is the expected long run value?
@spare smelt Has your question been resolved?
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@arctic surge Has your question been resolved?
!show
Show your work, and if possible, explain where you are stuck.
@arctic surge Has your question been resolved?
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Closed by @knotty ledge
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21
What is it then 😂
what?
Tell ‘em 😂
@knotty ledge You're acting childish. You should grow up and stop feeling the need to mess with people who are just bored.
Them taking up a single help channel isn't gonna change your life
@neon iron It's already closed you just have to wait for it to go away
hahahaha what is your problem
i think you're being naive
i literally just told them to go and mess around literally anywhere other than a help channel
why are you so pressed
Why? tho
They did nothing to you, but you felt the need to say that to them and close their channel before they got an answer to their question
Like seriously grow up and learn what empathy is
okay you carry on living in your little naive and oblivious bubble
If what they're doing has zero impact on your life or the life of others why do you feel the need to go out of your way to attack them
This isn't even the proper channel to joke around like that. This is the math help channel. Not the #chill channel.
We're volunteer helpers and appreciate not having our time or resources wasted. Simple as that
Exactly
so why waste your time attacking someone for asking what 9+10 is
just go to another channel
This is what the question was referring to
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.are you not familiar with the 9+10 meme? It's a common Shitpost in here
.also that's something literally google can solve
.there's nothing wrong with a closing a channel that's obviously a Shitpost
<@&268886789983436800>
Closed due to the original message being deleted
Ty wocket
wocket... wacoon
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How do I find x?
can you find an equation for x?
,rotate
the total angle is 255, can you make an equation relating x to this amount?
oops
sorry I didn't notice y'all were helping
mb
hint: what is 2x+90°+3x equal to?
5x + 90°?
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✅
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hey
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
sum of interior angles of a quadrilateral is 360deg
use the givens and that info the compute x
OK but how do i know its 360
In general the sum of interior angles for any polygon is 180(n-2) where n is the number of sides
$S=180(n-2)$
XxMrFancyu2xX
And triangles are 180
plug in n=4 to the formula to achieve the desired result
Is it because they have 3 edges
👍
ayo your about me 💀
So do i add 92 and 44 and then take away from 360 and then divide the answer by 2
It was a dare sorry if it offends you
It could get you banned from this server (for some reason) so I'd change it
nah idc but just came as a shock when I clicked it lmao
Personally if it's in your bio, idrc
It's not like a nickname but
This server just doesn't like it so I'd change it
It's more because it has a racial slur
I get that but it's in a bio, not a nickname
its normal nowadays a lot of discord servers r starting to allow it
Not even in status, but I'm fine with it in status also
not the hard r tho
But just note that can get you yeeted from here
aight again we don't care but you prob won't be on the server for long after this
anyways
we or just I digress
Can you give me the andwer
this is slightly wrong
you have the equation $360=92+44+2x$
XxMrFancyu2xX
but you did you're solving incorrectly
so its the same thing but i worded the equation wrong ?
you said add 92 and 44 which is correct
but then take away 360 is not correct
this means $0=136-360+2x$ which is counterproductive
XxMrFancyu2xX
yw! have a good day ma'am also don't forget to close your channel 
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Do you know what x intercepts are on the graph
And how that relates to f(x)
check where y becomes zero - here y means function itself
x intercepts is where y becomes zero , and vice versa
@loud violet Has your question been resolved?
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In a rational graph, can i x value that is a hole also be a virtical asymptote
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How would I write in two intervals?
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How do you solve both 2 and 3?
youre on the wrong channel
@winged grove Has your question been resolved?
Find sine and cosine of u first
Then use half angle identity
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I’m struggling to understand how a sequence of continuous functions can converge pointwise in [a,b] with a single continuous limit function without uniformly converging. I just don’t understand how that’s possible by definition if I can find a boundary for the superimum of every function
same reason as before
sequence grows unbounded to infinity, but its support goes to 0
@coarse urchin Has your question been resolved?
I just don’t understand how that’s possible by definition
because the sequence converges pointwise to 0
so |f_n(x)| converges to 0 as n goes to inf
the max of the function of grows unbounded yes
i should have said sup norm grows unbounded
have you seen this before
riemann
No I have no idea what this means
But can't I take that max (assuming it's always in the same position) and make it so |f_n(max) - 0| < epsilon?
no
x is fixed, then n is taken to infinity
But for every x and epsilon I can do that, no?
$||f_n||\y = \textrm{max}{x \in [0,1]} f_n(x)$
riemann
you're not really reading the definition of pointwise convergence correctly
Evidently, can you please enlighten me then?
"every"
.
thats cryptic
you're trying to claim something for all x at the same time
when the definition of pointwise specifically fixes x before taking the limit
"For any x, and any epsilon, you can find an n large enough so that |f_n(x) - f(x)| < epsilon
That's how I'm reading it
go back here and compare
you're claiming you can change x to be x_max
but x is fixed
Just take x_max and make sure its smaller than epsilon
I didn't claim to change anything
Well, not the x at least
x_max can depend on n
it's a sequence of functions
x_max doesn't need to be the same for all f_n
So the trick is to make x_max shift?
that's at least one way yes, there might be more that i'm not thinking of
So I need a sequence, that converges pointwise to 0, in [a,b], where the maximum of the function is unbound, and ever shifting?
converges pointwise to 0, in [a,b], where the maximum of the function is unbound
finding that is probably enough
But if it doesn't shift, can't I just take that x and bind it with a large enough n?
"any x"
Or do I still not understand the definition of pointwise convergence
"that x" need not be unique
the x is x_max
a function can attain its max on multiple values on a domain
e.g. f(x) = 1 on [0, 1]
Oh like, the maximum just has multiple maximums?
Or did you mean "multiple n's"
multiple x values
the max of this function is 1. it attains that max on all of [0, 1]
But if that's true, I'll find an n where the max is at most epsilon, and then shrink that epsilon to naught, until the value itself is close to 0?
Like
|f_n(1)| < epsilon
Again, assuming it doesn't move at all
right that's why you need to change the support as well
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Numerical single digit: i.e. Answer is a single digit whole number
nevermind got the answer. it is 6.
.close
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This is kinda chemistry and math together if anyone knows this could you tell me if it’s right or wrong and what the right thing is
The model questions, all you do is count how many of each element is on the left and compare it with the right. If it's not the same, then doesn't follow law of conservation
For the other two, do you know what that blank, unit means?
Im reading
Sorry
Ok so
You see
What I’m asking
Is
Are they right
For the
Ones you just labeled off
all you do is count how many of each element is on the left and compare it with the right. If it's not the same, then doesn't follow law of conservation
Can you count?
Can you compare?
You don't need to get confirmation if it's right or not. Say you have 2 Si on the left side and 4 on the right, that doesn't follow conservation because you magically gained 2 Si
If it was 2 Si on the left AND 2 on the right then it obeys because it's the same on both sides
Ok so using that
Model A, how many Fe's are on the left?
What you just said
Model a would be wrong
Bc
Fe on the left
And O and fe
4
And 4 on the right
Does the amount of O's and Fe's on the left equal on the right side?
As I mentioned, it's not a hard task, you literally count and compare both sides
If it's 6 on the left and 6 on the right that means nothing was lost/gained, aka it follows
So then does it follow?
No it doesn’t
There you go, you can do the rest on your own and you don't need to get confirmation
Because as mentioned you just need to compare
Do you know what formula mass means?
Formula mass
It’s the
G/mol
303.27.?
Do you know how to find formula mass of molecules?
Formula mass is the total mass of the molecule which is found by summing up the mass of all the elements in that molecule
Im listening just noting it down
For example H20, the formula mass is 18 g/mol because you have 2 H and 1 O, where the mass of H is 1 and O is 16. So 2 x 1 + 16 = 18 g/mol
Can you do that for Pb(SO4)?
As stated, you sum up the masses of all the elements in that molecule
Pb(SO4)
How many Pb's are there?
What's the weight of Pb?
207.2
Next S, how many S's are there?
1
What's the weight of S
How O's are there?
4
What's the mass of O?
15.999
What's the total mass of Pb in that molecule?
255.264
?
Units as in g, m, km, secs, etc
Those are units
What units is formula mass represented in?
.
What about speed?
And@merters
@analog sierra Has your question been resolved?
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anyone know a quick method for solving polynomials
hi
so i have a very easy question to ask u
for me it might be hard
but plzzz help
what is wait le me check
@neon sage Has your question been resolved?
just ask your question
for all polynomials, it's not very easy
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Is there a difference between $x^{-\frac{\alpha+3}{2}}$ and $x^{\frac{-\alpha-3}{2}}$?
Bennxy
Does the minus sign matter if it is placed outside or inside the fraction?
no
both are same
are you asking this because you saw this in a written solution and the two were apparently not treated as the same thing
No I was asking this because I saw that $x^{-0.5}* x^{- 1}* (x^\alpha)^{-0.5}$ was written as $x^{-\frac{\alpha+3}{2}}$
Bennxy
And I thought it was $x^{\frac{-\alpha-3}{2}}$
Bennxy
... and as has been explained to you, those two are one and the same.
But what if I had written it as $x^{-\frac{\alpha-3}{2}}$
Bennxy
Will this still be the same?
Huh wait
I feel stupid right now
But how are $x^{-\frac{\alpha+3}{2}}$ and $x^{\frac{-\alpha-3}{2}}$ the same?
Bennxy
you can put the minus sign wherever you want
here it's about the top
-(alfa + 3) = - alfa - 3
So writing $x^{-\frac{\alpha-3}{2}}$ is the same as $x^{\frac{-\alpha-3}{2}}$?
Bennxy
this one ^
for this one it would be -alfa + 3
But won't this become $-(\alpha-3) = -\alpha+3$
Bennxy
Ohh yeah right
So the minus sign outside the numerator does effect the fraction
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can someone check if I did these right
OutOfNosh
And another one on 8c
