#help-26

1 messages · Page 5 of 1

haughty wren
#

if I may

#

$cot\theta - cot\theta \cdot cos^{2}\theta \newline cot\theta \cdot (1 - cos^{2}\theta) \newline cot\theta \cdot sin^2\theta$

thorny flameBOT
#

imTyp0

haughty wren
#

and then yeah just know cot is cos/sin

#

so that's sinxcosx, or if you want, sin(2x)/2

lucid junco
#

Ohhh

haughty wren
#

A good thing to do when doing these trig identities is to always take out what's in common. Then it almost always makes it easier to see what's next :)

lucid junco
#

So it becomes cos(theta)*sin(theta)?

haughty wren
#

yes

lucid junco
#

And we can’t simplify any further right

haughty wren
#

you could, but we could argue it's not really simplifying. If I was your teacher I wouldn't be mad if you left it at that

lucid junco
#

Ah okay cool. Thank you for the help!

haughty wren
#

no worries! Also just so you know, what @quick pawn said is 100% correct. It's just that there are many, many ways to solve trigonometric identities, and that's just the one I saw first :)

lucid junco
#

Cheers!

#

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lucid junco
#

Man I think I messed up somewhere I’m not sure what to do now

unborn lagoon
#

split the beginning fraction into 2 fractions

lucid junco
unborn lagoon
#

adding

lucid junco
#

o ok

unborn lagoon
#

cosx /sinx is not tanx

lucid junco
#

Like this?

lucid junco
unborn lagoon
#

its the other way around

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tsc

lucid junco
#

Fuck

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Welp

#

alrighty

unborn lagoon
#

you got it?

lucid junco
#

So I just do the same thing I did but just fix up the tan

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what would it look like if I had it the correct way around

unborn lagoon
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look what happenes when you fix the tan

lucid junco
#

is it supposed to be sin(x)/cos^2(x)

unborn lagoon
#

what

lucid junco
#

yes

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oh

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Bruh

unborn lagoon
#

yeah...

lucid junco
#

Well

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Hey

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Good exercise converting stuff in terms of sine and cosine

#

Lol thanks for the help

unborn lagoon
#

lol

lucid junco
#

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glossy imp
#

how would i go about solving this?

topaz sinewBOT
glossy imp
#

I have tried an alternating series test, ratio test, and divergence test with no success

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oh and a limit comparison test

vernal matrix
#

Part b?

glossy imp
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yes

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omg hello

vernal matrix
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Heeeey catLove

glossy imp
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:D

vernal matrix
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And that's the harmonic series, the absolute value of it diverges catThink

glossy imp
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how

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;-;

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could i compare it to a harmonic?

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so it converges conditionally?

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so how would i show that on paper?

vernal matrix
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Yea it converges conditionally (was gonna say that it doesn't converge absolutely, but does meet the criteria for conditional convergence)

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There's a theorem somewhere for conditional convergence that if you have some decreasing positive sequence that converges to zero, then the "alternating series of that sequence" converges at least conditionally

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As for not converging absolutely, you can compare the absolute value of the series to the harmonic series yea, as it would just be a scaled version of it

glossy imp
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hmmm okay

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im still confused on what test i would do to prove that initial one

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because the alternative series was inconclusive

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i think

vernal matrix
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Hmm, are you happy that the series $\sum_{k=1}^{\infty} \frac{1}{k}$ diverges?

thorny flameBOT
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@vernal matrix

glossy imp
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yes

vernal matrix
#

Then for the series you have, when you take the absolute value, you have
[
\sum_{k=1}^{\infty} \abs{\frac{(-1)^{k + 1}}{2k}} = \sum_{k=1}^{\infty} \frac{1}{2k} = \frac{1}{2} \sum_{k=1}^{\infty} \frac{1}{k}
]
and so you know that you can't converge absolutely from there

thorny flameBOT
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@vernal matrix

crisp loom
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I have tried an alternating series test
did you?

glossy imp
#

sorry i had to do something

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lemme do it now

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yeah i got that

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and now lemme compare it to a harmonic

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i have that now

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and how would i go from here?

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would it just be a geometric?

vernal matrix
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Well you've shown that it doesn't converge absolutely, and you showed that it converges conditionally by the alternating series test, so you're done, no?

glossy imp
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is that automatically assumed?

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im a bit confused by that

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how did i show it doesn’t converge absolutely

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im not as comfortable with AST as i am with other tests

vernal matrix
# glossy imp

At this point you compared the absolute series with the harmonic series, which showed that it doesn't converge absolutely

glossy imp
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ohhh okay

#

i suppose that makes sense

vernal matrix
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Hopefully it does sadCatThumbsUp

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Then, do you have the conditions for the alternating series test anywhere? catlove

glossy imp
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i don’t believe so

vernal matrix
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Finessing this one here catGiggle

vernal matrix
glossy imp
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ohhh okay

#

that makes sense

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thank you sm for your help

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:cuterabbitheart:

vernal matrix
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catlove lovely to help (and see!) you happyCat

glossy imp
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yes! thank you:)

#

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winged grove
#

for this question, did we have to use the numbers on the bottom of the graph? i just estimated that the limit is 4

winged grove
#

i'm not sure what the numbers on the bottom even mean

neon iron
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no the numbers on the buttom have no relation whatsoever

winged grove
neon iron
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yeah

winged grove
#

ok thx

neon iron
#

i mean as long as we dont have to prove |2x| is continous therefore u just have to calculate |-4|

winged grove
#

🙏

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topaz sinewBOT
sturdy oracle
#

The 5th term?

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Well this one's nice because the exponent is 5

neon iron
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binomial

sturdy oracle
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But if you really need to, use the binomial theorem

soft rune
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Yes, as simple as that

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Of course!

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Coefficient, they mean only the number preceding the variable x

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Variable part, they mean x^

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Yess

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This is an arithmetic series

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f[n] = -12 + 3n

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is our sequence here

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As, you can see, we are summing up from (-9) to (-12+3n)

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Which means we are summing up from f[1] to f[n]

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Right?

zealous coyote
#

hello?

soft rune
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Did you understand so far?

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It is our sequence

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Have you not studied sequences yet?!

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They resemble to function f(x), except instead of x (REAL), we use n (NATURAL)

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fine

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😋

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although try using f[n], gives you a feel as if you're dealing with functions f(x)

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just instead of x which is real

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we only consier the natural numbers n

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Anyways

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So yeahh, we have an arithmetic series here

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Have you guys studied arithmetic series?

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Yes

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it is already given, the sequence

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Look at the last

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They are asking you to compute the sum of this arithmetic series

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Until f[n] lol

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it is obvious!!

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from f[1] to f[n]

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because f[1]=-9

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you can just substitute

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Allright

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Since you have studied the arithmetic series

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I assume you have been given a formula

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There is a formula which you can use to find the sum of the arithmetic series

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You only need to know the first and last element

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first and last term of the series

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exactly

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you have it

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it is -12+3n

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-12+3n is the term

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it does not have to be a number

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Hahaha

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You just plug the first (-9) and (-12+3n)

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Since the last term is a function of the variable n

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The sum also will be a function of n

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One of the advantages of this is that after finding the closed form of the sum of the series

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You can plug any n

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And know the sum from the first term up to any nth term

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Yes, it is!

soft rune
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Well, first, f[0]=-2

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And not f[1]

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f[1]=0.8

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you can see, it is the following term

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and r=-0.4

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And not +0.4

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The sign of the terms is alternating

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Our sequence is:

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f[n] = (-2) . (-0.4)^n

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n=0,1,2,3,...

topaz sinewBOT
#

@crisp scarab Has your question been resolved?

soft rune
#

Simply that the sequence starts from index 0

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And not 1

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They all start from 0 lol

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The previous one did not start from 1

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The sequence from the previous exercise also starts from 0

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But we were interested in summing from the first term to the nth term

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Look, you can either start by 0, or by 1

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in case you start by 0

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f[n] = f[0] . r^n

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in case you start by 1

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f[n] = f[1] . r^(n-1)

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But which is better?

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I honestly prefer 0

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All the time

empty sail
soft rune
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Even if you think of it logically, in math way

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Sequences have a domain of definition which is the set of natural numbers

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0,1,2,3,...

soft rune
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0 simplifies work

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r^n

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not r^(n-m)

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Anyways, you just use your geometric series formula

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you have the first term, you have the last term

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which is n

empty sail
topaz sinewBOT
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ornate magnet
topaz sinewBOT
barren lion
#

,rccw

thorny flameBOT
ornate magnet
#

I want my answer to get checked

barren lion
ornate magnet
#

119 this is the answer

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One angle will be 60 degrees

drifting swift
#

so there are 119 possible values of the common difference?

ornate magnet
#

Integer values

drifting swift
#

what are they?

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also are we considering e.g. 59, 60, 61 and 61, 60, 59 as different progressions for this problem? the statement doesn't make that clear

barren lion
#

@ornate magnet

ornate magnet
barren lion
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wait

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the angles are in arithmetic progression?

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oh my god

ornate magnet
drifting swift
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arithmetic progressions with difference 0 exist

barren lion
#

i read Ls as in lengths

drifting swift
#

$\angle$s

ornate magnet
#

😑

thorny flameBOT
drifting swift
#

is what was meant

barren lion
#

i see

drifting swift
#

would have been easier not to abbreviate

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this is the same kind of "takes you a moment" abbreviation as "+ve"

ornate magnet
#

Common difference will range from [-59,59]

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Am i correct?

drifting swift
#

you appear to be

ornate magnet
#

Ok

#

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neon iron
#

$sin^2x = sin(x)^2$

topaz sinewBOT
thorny flameBOT
#

Ilvvus

neon iron
#

is this the same if i were to format it in a calculator

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i assume not

noble laurel
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Yes, although no one writes it the second way

neon iron
#

oh ok

thorny flameBOT
#

AustinU

noble laurel
#

is different

neon iron
#

alr then

noble laurel
#

If you were to write it the second way,

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write it like this

thorny flameBOT
#

AustinU

noble laurel
#

but, it is much more usual/normal to write it the first way you did

thorny flameBOT
#

AustinU

noble laurel
#

like so

neon iron
#

alr thanks

#

$(\frac{sinx}{cosx} + 2) (2 \frac{sinx}{cosx} +1) = (2 \frac{sin^2x}{cos^2x} +2)$

thorny flameBOT
#

Ilvvus

neon iron
#

why is this false?

noble laurel
#

because you didn't properly multiply

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use the box/foil method

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and you will see

neon iron
#

bruh

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im so stupid

noble laurel
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no worries, it happens

neon iron
#

its such a beginner mistake too

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forgetting to multiply each member with each other member

noble laurel
#

I still do the box method much too often XD

neon iron
#

we wouldnt be able to apply an algebraic identity here right

noble laurel
#

What do you mean by that?

neon iron
#

was thinking of this but nvm

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to speed up the process

noble laurel
#

I'd try to avoid using that, if you can see the general pattern on your own then use it to speed up the process

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but don't try to apply any formulas you can't really understand

neon iron
#

nah i do understand it

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im just having severe brain fog rn because its very late and im tired

noble laurel
#

Yeah no worries

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the reason it doesn't completely apply here is because the first term of the binomials isn't the same

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in one you have 2sin/cos and the other you just have sin/cos

neon iron
#

yeah

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alr then thanks a lot for the help

noble laurel
#

no problem!

neon iron
#

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karmic monolith
#

Fast way to do this?

topaz sinewBOT
karmic monolith
#

Idk what to do

#

I do not want to plug in these numbers to check

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how do i solve without plugging in numbers

vernal vale
#

what happened with your derivative?

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it does not look correct

sweet shard
#

It isn't

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But they're setting it to zero anyway so they divided by 3

karmic monolith
#

I put the 3 in front of x

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instead of multiplying 2 by 3 🤦‍♂️

pallid wedge
#

do you know how to derivative

karmic monolith
#

yes, i did it in image

pallid wedge
#

this is wrong

vernal vale
#

it looks fine

#

the derivative is wrong but its for finding critical points and they divided by 6

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bad form but whatever

karmic monolith
#

anywas, i give up apparently i can't solve without plugging in numbers

#

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neon iron
topaz sinewBOT
neon iron
#

is it times 2 since they are symmetrical ?

topaz sinewBOT
#

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wicked totem
#

So I want to calculate a probability. I have a game, where I have m amount of meteors I need to shoot down. For that I have c amount of cannons. Each of these has a default probability of hitting one single meteors of p = 0.8. Now, I want to get the probability, that all meteors get shot down. Note that a cannon can only shoot once.

My current solution can only calculate the probability that c amount of cannons can shoot down one meteor (see png)

I don't know any advanced probability things, I just drew a tree and looked at any path that leads to the probability of shooting down a meteor. (see png 2)

Is there a way to calculate the probability, that all meteors get shot down by the cannons, instead of only for one?

topaz sinewBOT
#

@wicked totem Has your question been resolved?

topaz sinewBOT
#

@wicked totem Has your question been resolved?

topaz sinewBOT
#

@wicked totem Has your question been resolved?

wicked totem
#

<@&286206848099549185>

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@wicked totem Has your question been resolved?

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summer badger
#

Need help with angles ;

How do I convert:

(30.0/0) facing south towards positive Z

To

(??/??) facing east towards positive X

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hollow bay
topaz sinewBOT
hollow bay
#

Can someone explain graphically why it's continous at 0

prisma mesa
#

this is the graph

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basically when it's slightly greater than 0, it's just 0. When it's slightly smaller, it's x*-1

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and x*(-1) at 0 is 0

topaz sinewBOT
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minor plume
#

im trying to find the range of this function however I cant quite get the final step the question is: Given the function f(x) = 1/(x^2 - 1), find the domain and range of the function.

minor plume
#

struggling with how to convert x=sqrt(1+1/y) into an answer

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<@&286206848099549185>

stable mulch
#

x=√(1+1/y)

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y cannot be zero

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and 1+1/y cannot be less than 0

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(it is in square root)

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say 1+1/y<0

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1/y<-1

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y>-1

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so y cannot be between 0 and -1

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can be -1, cant be zero

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{R/(-1,0]}

minor plume
#

so does that mean y is anything greater than 0

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or should i write it as y cannot equal specifically -1 and 0

stable mulch
#

it just cant be 0 and between 0 and -1

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can be everything else

minor plume
#

ok thanks

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but how can that be written in set builder notation

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bcs thats what my school requires

stable mulch
#

y>0 and y<=-1

minor plume
#

great thanks

stable mulch
#

or (0,inf)U(-inf,-1]

topaz sinewBOT
#

@minor plume Has your question been resolved?

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cinder oxide
cinder oxide
#

sometimes induction holds up, sometimes it doesn't

#

I've also heard Induction described with TAPE:
Test
Assume
Prove
Explain

pastel oracle
#

yes, I'd say finding patterns is important

hollow fractal
#

Progrssion

hollow fractal
pastel oracle
hollow fractal
knotty ledge
#

IYDEQYWNASA

hollow fractal
#

"This might be too detailed"

#

L

knotty ledge
#

avid has been around for a while, we know the level he's at right now

ashen sparrow
#

hes made Progrssion he is ready

pastel oracle
#

"detailed" != "difficult"

knotty ledge
#

whats your problem?

pastel oracle
#

<@&268886789983436800> likely troll

hollow fractal
#

He's just a MathWizard

#

Too intellectual for your understanding

knotty ledge
#

who

#

asked

knotty ledge
#

you do attract them avid

cinder oxide
#

.close

topaz sinewBOT
#
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#
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desert pulsar
#

How do I prove that every term in the sequence n^2-8n+21 is positive?

drifting swift
#

you could prove that n^2 - 8n + 21 is positive for all real n

desert pulsar
#

How do I do that

shut obsidian
frail reef
#

Why not just use the discriminant

restive inlet
#

completing the square would be useful

drifting swift
drifting swift
shut obsidian
desert pulsar
#

How do I use discriminate / completing the square

desert pulsar
lean dove
#

b²-4ac < 0

drifting swift
#

do you know how to complete the square

#

y/n

desert pulsar
#

I did that a long time ago

lean dove
#

because a > 0, so it opens upwards. Therefore it must not intersect the x axis for it to be positive. So it shouldn't have any roots, so b²-4ac < 0

desert pulsar
#

Isn’t it for quadratic equations?

drifting swift
#

well you have here a quadratic expression

#

why not complete the square on it

desert pulsar
desert pulsar
#

I guess I need to learn how to do that again

#

But how do I know it’s positive?

drifting swift
#

yes

frail reef
drifting swift
#

complete the square and it will become obvious to you. or not. if it doesn't you can post the completed-square form here and we can give you pointers.

desert pulsar
#

Okay

#

What about that complete induction thing? What’s that

drifting swift
#

dunno but you don't need induction of any kind here

frail reef
#

That’s for more complex proofs

frail reef
desert pulsar
#

Alright

#

@drifting swift @frail reef @lean dove

frail reef
#

Since (n-4)^2 has to be greater than it equal to 0

#

That expression must be greater than or equal to 5

#

And hence always positive

drifting swift
#

^

#

your thing is 5 + something nonnegative

#

it is not only positive, it is bounded below by 5

desert pulsar
#

I don’t understand

#

I’m sorry

frail reef
#

Square numbers are always positive

#

Correct?

drifting swift
#

@desert pulsar is it like
"i don't understand what some or all of the words mean in what you said"
or
"i understand what you're saying but not why it's true"

desert pulsar
#

The words you used

desert pulsar
frail reef
desert pulsar
#

Yes

frail reef
#

So treat the expression (n-4) the same way

#

You have written down (n-4)^2 + 5

#

You can rewrite that as (n-4)(n-4) + 5

#

From what I said before a number multiplied by itself must always be positive

desert pulsar
#

Oh

frail reef
#

So what you have there if you think about it is some positive number + 5

#

A positive number + a positive number can never be negative

desert pulsar
#

I see

#

The method I used is correct yes?

frail reef
#

Yes

desert pulsar
#

What about the discriminant method?

frail reef
#

All you need to do to finish it is say that since the brackets can’t be negative then when you plus it to 5 it must always be positive

#

Basically the same thing

desert pulsar
#

I got a negative number

frail reef
#

?

desert pulsar
#

Using b^2-4ac

frail reef
#

Yes that is the discriminant method

#

Do you know the quadratic formula?

desert pulsar
#

Yes

frail reef
#

Then you know that x = (-b +/- the square root of the discriminant)/2a

desert pulsar
#

Yes

frail reef
#

If you want to show that the expression is always greater than 0, a way to do that is to show there are no solutions for x

#

Since whatever x equals is where the expression crosses the x axis

desert pulsar
#

Mhm

frail reef
#

If you were to say for example that y = (x-4)^2 + 5

#

If the equation never crosses the x axis ( in other words it never goes negative) then there would be no solutions for x

#

When you figure out the determinant, if it is ever less than 0, you have proved that it never crosses the x axis

#

Since then x equals some number +/- a root of a negative number

#

Since you can’t do the root of a negative number, the equation has no solutions

#

Understand?

topaz sinewBOT
#

@desert pulsar Has your question been resolved?

desert pulsar
#

I understand it perfectly

#

Thank you

frail reef
#

np

desert pulsar
#

But don’t imaginary numbers exist

#

2i whatever

frail reef
#

Well yes but we are dealing with real numbers in this case

#

So I didn’t bother mentioning them

topaz sinewBOT
#
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cyan pasture
#

can someone give me the points for this graph

cyan pasture
#

<@&286206848099549185>

topaz sinewBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

molten vine
cyan pasture
#

ye

#

do u know the points for the equation

civic briar
#

(1, -2) (-5,5)

cyan pasture
#

than did i solve it right

#

cuz i plug them in the distance calculator

#

and got 9.21

#

@civic briar

pastel oracle
#

should be -2 - 5, not -2 + 5

cyan pasture
#

ohhhhh

#

im so stupid

#

tysm

#

wait one more

#

is the point (5,1) and (5,-5)

#

@pastel oracle

pastel oracle
#

(5, 1) is right, yes

cyan pasture
#

how about the other one

#

is it 5,-5

pastel oracle
#

no

cyan pasture
#

is it 1,-5

pastel oracle
#

no

cyan pasture
#

-1,-5?

pastel oracle
#

no

cyan pasture
#

bru what is it

#

than

pastel oracle
#

how did you get (5, 1) for the one point?

cyan pasture
#

cuz its goin 5 to the right

#

and up 1

pastel oracle
#

yes

cyan pasture
#

💀

#

ohhh

pastel oracle
#

same thing for the other point

cyan pasture
#

0,-5v

#

?

#

im i right sor

#

sir

pastel oracle
#

you shouldn't need to confirm, just count the number of lines to over and up/down

cyan pasture
#

i did that

#

i jus want u to confirm if iam right

civic briar
#

You are right. its (0, -5)

cyan pasture
#

thankks

topaz sinewBOT
#

@cyan pasture Has your question been resolved?

topaz sinewBOT
#
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topaz sinewBOT
#
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unborn lagoon
#

,rotate

thorny flameBOT
topaz sinewBOT
#

@sour robin Has your question been resolved?

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spare smelt
#

Every day the value of my $1 portfolio either doubles with probability p, or halves with probability 1-p. What is the expected long run value?

topaz sinewBOT
#

@spare smelt Has your question been resolved?

topaz sinewBOT
#
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topaz sinewBOT
#

@arctic surge Has your question been resolved?

sweet shard
#

!show

topaz sinewBOT
#

Show your work, and if possible, explain where you are stuck.

#

@arctic surge Has your question been resolved?

topaz sinewBOT
#
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knotty ledge
#

go troll somewhere else

#

.close

topaz sinewBOT
#
Channel closed

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lucid isle
#

21

karmic monolith
#

21

#

@knotty ledge Grow up brother

lucid isle
#

What is it then 😂

knotty ledge
lucid isle
karmic monolith
#

@knotty ledge You're acting childish. You should grow up and stop feeling the need to mess with people who are just bored.
Them taking up a single help channel isn't gonna change your life

#

@neon iron It's already closed you just have to wait for it to go away

knotty ledge
#

hahahaha what is your problem

karmic monolith
#

What is your problem?

#

You came in here to bother a guy who asked what 9+10 is

knotty ledge
#

i think you're being naive

karmic monolith
#

I think you're being naive

#

Leave the guy alone, he's not hurting you in any way

knotty ledge
#

i literally just told them to go and mess around literally anywhere other than a help channel

#

why are you so pressed

karmic monolith
#

Why? tho

#

They did nothing to you, but you felt the need to say that to them and close their channel before they got an answer to their question

#

Like seriously grow up and learn what empathy is

knotty ledge
#

okay you carry on living in your little naive and oblivious bubble

karmic monolith
#

If what they're doing has zero impact on your life or the life of others why do you feel the need to go out of your way to attack them

vivid flame
#

This isn't even the proper channel to joke around like that. This is the math help channel. Not the #chill channel.

rigid ivy
karmic monolith
#

so why waste your time attacking someone for asking what 9+10 is

#

just go to another channel

tender mantle
#

This is what the question was referring to

topaz sinewBOT
#
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sturdy oracle
#

.also that's something literally google can solve

#

.there's nothing wrong with a closing a channel that's obviously a Shitpost

topaz sinewBOT
sweet shard
#

<@&268886789983436800>

topaz sinewBOT
#
Channel closed

Closed due to the original message being deleted

sturdy oracle
#

Oh great another troll in the same exact channel

#

Rocket is here to save us

sweet shard
#

Ty wocket

knotty ledge
#

wocket... wacoon

topaz sinewBOT
#
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grizzled sigil
topaz sinewBOT
grizzled sigil
#

How do I find x?

frail dove
#

can you find an equation for x?

sweet shard
#

,rotate

thorny flameBOT
dreamy drum
# grizzled sigil

the total angle is 255, can you make an equation relating x to this amount?

#

oops

#

sorry I didn't notice y'all were helping

#

mb

grizzled sigil
#

? What do u mean by 225

#

Like I don't know the formula or anything to this

#

?

frail dove
#

hint: what is 2x+90°+3x equal to?

grizzled sigil
#

5x + 90°?

sturdy oracle
#

.close

topaz sinewBOT
#
Channel closed

Closed by @sturdy oracle

Use .reopen if this was a mistake.

grizzled sigil
#

. reopen

#

.reopen

topaz sinewBOT
#

sturdy oracle
#

Why did you reopen this

#

.close

topaz sinewBOT
#
Channel closed

Closed by @sturdy oracle

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topaz sinewBOT
#
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neon iron
#

hey

topaz sinewBOT
neon iron
topaz sinewBOT
# neon iron
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
neon iron
#

6

#

i dont know heo to do it

keen matrix
#

sum of interior angles of a quadrilateral is 360deg

#

use the givens and that info the compute x

neon iron
deft arch
#

In general the sum of interior angles for any polygon is 180(n-2) where n is the number of sides

keen matrix
thorny flameBOT
#

XxMrFancyu2xX

neon iron
#

And triangles are 180

keen matrix
#

plug in n=4 to the formula to achieve the desired result

neon iron
#

Is it because they have 3 edges

keen matrix
#

👍

keen matrix
neon iron
neon iron
sturdy oracle
keen matrix
#

nah idc but just came as a shock when I clicked it lmao

sturdy oracle
#

Personally if it's in your bio, idrc

#

It's not like a nickname but

#

This server just doesn't like it so I'd change it

empty sail
sturdy oracle
#

I get that but it's in a bio, not a nickname

neon iron
sturdy oracle
#

Not even in status, but I'm fine with it in status also

neon iron
#

not the hard r tho

sturdy oracle
#

But just note that can get you yeeted from here

neon iron
#

It's fine

#

I just needed help with 1 question

keen matrix
#

aight again we don't care but you prob won't be on the server for long after this

#

anyways

#

we or just I digress

neon iron
#

Can you give me the andwer

keen matrix
#

you have the equation $360=92+44+2x$

thorny flameBOT
#

XxMrFancyu2xX

neon iron
#

huh

#

yea

#

thats

#

my idea

#

Is it correct

keen matrix
#

but you did you're solving incorrectly

neon iron
#

so its the same thing but i worded the equation wrong ?

keen matrix
#

you said add 92 and 44 which is correct

#

but then take away 360 is not correct

#

this means $0=136-360+2x$ which is counterproductive

thorny flameBOT
#

XxMrFancyu2xX

neon iron
#

I said take away 136 from 360

#

Not 360 from 136 that would make it negative

keen matrix
#

ah you see doing math help at 11pm

#

not the greatest thing

#

my fault

neon iron
#

Lol its okay

#

But i get it now

#

Thanks

keen matrix
#

yw! have a good day ma'am also don't forget to close your channel pandaHugg

neon iron
#

thanks u too

#

!close

#

.close

topaz sinewBOT
#
Channel closed

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#
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loud violet
#

hi!! how do i find the x-intercepts for this graph?

#

🙂

sweet shard
#

And how that relates to f(x)

loud violet
#

i know

#

kind of

#

i dont know how tto find them if the graph is translates

cursive jackal
#

x intercepts is where y becomes zero , and vice versa

topaz sinewBOT
#

@loud violet Has your question been resolved?

topaz sinewBOT
#
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tight ridge
#

In a rational graph, can i x value that is a hole also be a virtical asymptote

tight ridge
#

tysm

#

ily

#

.close

topaz sinewBOT
#
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clever citrus
#

How would I write in two intervals?

topaz sinewBOT
clever citrus
#

somethnig like (0, 1] U [1, 5]?

#

wait no

#

shit

#

.close

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#
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winged grove
#

How do you solve both 2 and 3?

topaz sinewBOT
winged grove
#

youre on the wrong channel

topaz sinewBOT
#

@winged grove Has your question been resolved?

sweet shard
#

Then use half angle identity

winged grove
#

Thanks

#

.close

topaz sinewBOT
#
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#
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coarse urchin
#

I’m struggling to understand how a sequence of continuous functions can converge pointwise in [a,b] with a single continuous limit function without uniformly converging. I just don’t understand how that’s possible by definition if I can find a boundary for the superimum of every function

sweet shard
#

same reason as before

#

sequence grows unbounded to infinity, but its support goes to 0

topaz sinewBOT
#

@coarse urchin Has your question been resolved?

coarse urchin
sweet shard
#

because the sequence converges pointwise to 0

#

so |f_n(x)| converges to 0 as n goes to inf

coarse urchin
#

the sequence is unbounded to infinity and converges to 0?

#

in [a,b]?

sweet shard
#

the max of the function of grows unbounded yes

sweet shard
#

have you seen this before

thorny flameBOT
#

riemann

coarse urchin
#

No I have no idea what this means

coarse urchin
sweet shard
#

x is fixed, then n is taken to infinity

coarse urchin
#

But for every x and epsilon I can do that, no?

sweet shard
#

$||f_n||\y = \textrm{max}{x \in [0,1]} f_n(x)$

thorny flameBOT
#

riemann

sweet shard
coarse urchin
#

Evidently, can you please enlighten me then?

sweet shard
coarse urchin
#

thats cryptic

sweet shard
#

you're trying to claim something for all x at the same time

#

when the definition of pointwise specifically fixes x before taking the limit

coarse urchin
#

That's how I'm reading it

sweet shard
#

you're claiming you can change x to be x_max

#

but x is fixed

coarse urchin
#

I didn't claim to change anything

#

Well, not the x at least

sweet shard
#

x_max can depend on n

#

it's a sequence of functions

#

x_max doesn't need to be the same for all f_n

coarse urchin
#

So the trick is to make x_max shift?

sweet shard
#

that's at least one way yes, there might be more that i'm not thinking of

coarse urchin
sweet shard
#

converges pointwise to 0, in [a,b], where the maximum of the function is unbound
finding that is probably enough

coarse urchin
#

"any x"

#

Or do I still not understand the definition of pointwise convergence

sweet shard
#

"that x" need not be unique

coarse urchin
#

I'm not sure I understand

#

If it doesn't move isn't it inherently unique?

sweet shard
#

the x is x_max

#

a function can attain its max on multiple values on a domain

#

e.g. f(x) = 1 on [0, 1]

coarse urchin
#

Or did you mean "multiple n's"

sweet shard
#

multiple x values

sweet shard
coarse urchin
#

Like
|f_n(1)| < epsilon

#

Again, assuming it doesn't move at all

sweet shard
#

right that's why you need to change the support as well

coarse urchin
#

Damn.

#

Alright I'll give it another go I guess

#

Thank you

#

.close

topaz sinewBOT
#
Channel closed

Closed by @coarse urchin

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rain radish
topaz sinewBOT
rain radish
#

Numerical single digit: i.e. Answer is a single digit whole number

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nevermind got the answer. it is 6.

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.close

topaz sinewBOT
#
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topaz sinewBOT
#
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analog sierra
#

This is kinda chemistry and math together if anyone knows this could you tell me if it’s right or wrong and what the right thing is

empty sail
#

For the other two, do you know what that blank, unit means?

analog sierra
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What I’m asking

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Is

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Are they right

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For the

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Ones you just labeled off

empty sail
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all you do is count how many of each element is on the left and compare it with the right. If it's not the same, then doesn't follow law of conservation

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Can you count?

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Can you compare?

analog sierra
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Yes off SOREY

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Ofc sorry

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Model a is correct b incorrect ?

empty sail
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You don't need to get confirmation if it's right or not. Say you have 2 Si on the left side and 4 on the right, that doesn't follow conservation because you magically gained 2 Si

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If it was 2 Si on the left AND 2 on the right then it obeys because it's the same on both sides

analog sierra
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Ok so using that

empty sail
analog sierra
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What you just said

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Model a would be wrong

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Bc

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Fe on the left

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And O and fe

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4

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And 4 on the right

empty sail
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How many Fe's on the right?

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Next do O

analog sierra
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So it does follow

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Bc

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Same in the Medel

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With o

empty sail
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Does the amount of O's and Fe's on the left equal on the right side?

analog sierra
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Yes.?

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You mean right

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Bc there is 6 Os

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And 6

empty sail
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As I mentioned, it's not a hard task, you literally count and compare both sides

analog sierra
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Yea I did that

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And got follow the law

empty sail
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If it's 6 on the left and 6 on the right that means nothing was lost/gained, aka it follows

analog sierra
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Yes

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And onto model b

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There is

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Not enough Os

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On one side

empty sail
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So then does it follow?

analog sierra
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No it doesn’t

empty sail
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There you go, you can do the rest on your own and you don't need to get confirmation

analog sierra
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Okay

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So can I have help

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On the rest

empty sail
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Because as mentioned you just need to compare

analog sierra
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The other

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Bc the compare I see it’s easy as now lol

empty sail
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Do you know what formula mass means?

analog sierra
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It’s the

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G/mol

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303.27.?

empty sail
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Do you know how to find formula mass of molecules?

analog sierra
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Not really for this one, and it was a group work

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So not as much

empty sail
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Formula mass is the total mass of the molecule which is found by summing up the mass of all the elements in that molecule

analog sierra
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Im listening just noting it down

empty sail
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For example H20, the formula mass is 18 g/mol because you have 2 H and 1 O, where the mass of H is 1 and O is 16. So 2 x 1 + 16 = 18 g/mol

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Can you do that for Pb(SO4)?

analog sierra
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Im trying to right now

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This confused me

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I DONT think I can

empty sail
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As stated, you sum up the masses of all the elements in that molecule

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Pb(SO4)
How many Pb's are there?

analog sierra
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There

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Is

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4

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?

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1

empty sail
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What's the weight of Pb?

analog sierra
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207.2

empty sail
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Next S, how many S's are there?

analog sierra
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1

empty sail
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What's the weight of S

analog sierra
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S is

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32.065

empty sail
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How O's are there?

analog sierra
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4

empty sail
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What's the mass of O?

analog sierra
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15.999

empty sail
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What's the total mass of Pb in that molecule?

analog sierra
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255.264

empty sail
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?

analog sierra
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Wait

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Oh yea

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The 4 Os

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303.261

empty sail
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Yes that's the formula mass

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What's the units?

analog sierra
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261

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?

empty sail
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?

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Do you know what units means?

analog sierra
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I’m confused

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No I don’t right this sexouns

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Second

empty sail
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Units as in g, m, km, secs, etc

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Those are units

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What units is formula mass represented in?

analog sierra
#

huhhh

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I’m so confused

empty sail
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What units is formula mass?

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What units represents time?

analog sierra
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SI

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SORRY NY WI-FI

empty sail
analog sierra
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It’s seconds

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Si

empty sail
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What about speed?

analog sierra
#

And@merters

empty sail
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Speed?

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Speed meaning velocity

topaz sinewBOT
#

@analog sierra Has your question been resolved?

topaz sinewBOT
#
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#
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Show your work, and if possible, explain where you are stuck.
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neon sage
#

anyone know a quick method for solving polynomials

pliant briar
#

hi

#

so i have a very easy question to ask u

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for me it might be hard

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but plzzz help

#

what is wait le me check

topaz sinewBOT
#

@neon sage Has your question been resolved?

sweet shard
finite moth
topaz sinewBOT
#
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topaz sinewBOT
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snow token
#

Is there a difference between $x^{-\frac{\alpha+3}{2}}$ and $x^{\frac{-\alpha-3}{2}}$?

thorny flameBOT
#

Bennxy

snow token
#

Does the minus sign matter if it is placed outside or inside the fraction?

drifting swift
#

are you asking this because you saw this in a written solution and the two were apparently not treated as the same thing

snow token
#

No I was asking this because I saw that $x^{-0.5}* x^{- 1}* (x^\alpha)^{-0.5}$ was written as $x^{-\frac{\alpha+3}{2}}$

thorny flameBOT
#

Bennxy

snow token
#

And I thought it was $x^{\frac{-\alpha-3}{2}}$

thorny flameBOT
#

Bennxy

drifting swift
#

... and as has been explained to you, those two are one and the same.

snow token
#

But what if I had written it as $x^{-\frac{\alpha-3}{2}}$

thorny flameBOT
#

Bennxy

snow token
#

Will this still be the same?

neon iron
#

no

#

[
-\f ab = \f{-(a)}{b} = \f{a}{-(b)}
]
No matter what $a$ and $b$ are

thorny flameBOT
snow token
#

Huh wait

#

I feel stupid right now

#

But how are $x^{-\frac{\alpha+3}{2}}$ and $x^{\frac{-\alpha-3}{2}}$ the same?

thorny flameBOT
#

Bennxy

bold nebula
#

you can put the minus sign wherever you want

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here it's about the top

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-(alfa + 3) = - alfa - 3

snow token
#

So writing $x^{-\frac{\alpha-3}{2}}$ is the same as $x^{\frac{-\alpha-3}{2}}$?

thorny flameBOT
#

Bennxy

bold nebula
snow token
#

But won't this become $-(\alpha-3) = -\alpha+3$

thorny flameBOT
#

Bennxy

snow token
#

So the minus sign outside the numerator does effect the fraction

#

.close

topaz sinewBOT
#
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topaz sinewBOT
#
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Ask your math question in a clear, concise manner.
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half pike
#

can someone check if I did these right

topaz sinewBOT
safe burrow
#

you've made a mistake on part 8b

#

$(-2)^{3} = -8, so x^{3} - y^{3} = 1 + 8 = 9$

thorny flameBOT
#

OutOfNosh

neon iron
#

And another one on 8c