#help-23

1 messages · Page 487 of 1

safe radishBOT
hybrid wren
#

How do I solve question 10

quasi bison
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do you know how to subtract fractions in general?

hybrid wren
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If the denominator is same just subtract

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And if not

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Find the LCM and do the same to the numerator and minus

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@quasi bison

quasi bison
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ok great

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then convert both of these mixed fractions into improper fractions, then subtract them as you normally would

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then, if desired, convert the result back into a mixed fraction

hybrid wren
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9/2-11/4

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That

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So 18/4-11/4

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7/4 = 1 3/4???

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Wait did I just solve this

hardy lion
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Yup

hybrid wren
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Loll brahh

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Thx

safe radishBOT
#

@hybrid wren Has your question been resolved?

safe radishBOT
#
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coarse birch
#

Ask question

safe radishBOT
coarse birch
#

Need help with question 4 and 2

quasi bison
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which one first?

coarse birch
#

The easier one ahh

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I got question 3

quasi bison
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they are both relatively easy but #2 involves less computation

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so i guess let's start with that

coarse birch
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I have the formula

quasi bison
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Trevor earned $136.50 in simple interest by investing $650 at 4.2% per annum. How long did he hold the investment?
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(transcribing the problem here for my own sake)

coarse birch
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Yea

quasi bison
coarse birch
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So I’m finding how many years

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Yes

quasi bison
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everything here is known except time.

coarse birch
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I don’t have t

quasi bison
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yes, as i said.

coarse birch
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Yeh

quasi bison
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you don't have the time, but you have everything else

coarse birch
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Correct

quasi bison
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are you able to isolate T in the formula I = PRT?

coarse birch
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So I remove t from the formula?

quasi bison
#

no

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i was trying to get you to go from $I = PRT$ to $T = \frac{I}{PR}$

flat frigateBOT
coarse birch
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Ok

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Can I get 2min real quick

quasi bison
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what do you mean

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if you need to take a break then by all means go ahead

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ping me once you're back

coarse birch
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Just gonna write it

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That’s all

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On my paper

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@quasi bison

quasi bison
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yes?

coarse birch
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650 x (136.50 x 0.042)?

quasi bison
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don't use x for multiplication

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and no that isn't correct anyway

coarse birch
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O

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So what would it be than?

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650 divide by p multiply r

quasi bison
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i mean... i gave you the formula with T isolated

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T = I/(PR)

coarse birch
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What does / mean?

quasi bison
#

division, what else?

coarse birch
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Oh

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So what I said is correct than?

quasi bison
#

no

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650 is your principal.

coarse birch
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And I is my 136.50

quasi bison
#

yes, the interest is 136.50 as the problem says

coarse birch
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Okay let me solve

quasi bison
#

meanwhile i will transcribe the other problem for future reference

Jo decides to save for a vacation in 4 years by buying a $1000 GIC on June 1st each year for 3 years. (In the fourth year she also saves $1000 but does not invest it.) All of the GICs pay 4.2% interest, composed monthly. How much money will Jo have saved for her vacation over the four year period?
coarse birch
#

How do you transcribe it so fast?

quasi bison
#

took me 2 minutes?

coarse birch
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Oh

quasi bison
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plus i'm on my phone

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but i do have some years of practice typing in general

coarse birch
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Do you get paid to help people?

quasi bison
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no

coarse birch
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Is 5 years correct?

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Or is it 5 months?

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How can I know

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What it is

quasi bison
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your interest is measured per annum

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,calc 136.50/(650*0.042)

flat frigateBOT
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Result:

5
quasi bison
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ok yes 5 years is correct

coarse birch
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What if it was months

quasi bison
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wym

coarse birch
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Like for exp

quasi bison
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are you asking how to answer the question if you were told to give the answer in months?

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there are 12 months in a year. 5 years = 5*12 months = 60 months.

coarse birch
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Alright

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I’m finished with 2

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Move on to 4

quasi bison
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ok

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4 is considerably more complicated, bc now we are dealing with not only compound interest but an annuity

coarse birch
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I never learned annunity in class

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Can you explain what that is?

quasi bison
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it's an investment in which, in addition to compound interest being earned, new money is added into the account at regular intervals (usually every year, and usually an equal amount)

coarse birch
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So it’s like a mix of compound and simple interest?

quasi bison
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would not call it that

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i think maybe it's easier to do this symbolically rn

coarse birch
#

Ok let me make it simple

quasi bison
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so you know the general principle of compound interest, right?

coarse birch
quasi bison
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namely that each paying period the money in the account grows multiplicatively rather than additively as in simple interest

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so for an investment of r% compounded annually, the value is multiplied by (1+r/100) every year.

coarse birch
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T - 4 years
R - 0.042

quasi bison
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shh

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no numbers just yet

coarse birch
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Ok

coarse birch
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A = p(1+r)t

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Ik this

quasi bison
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...missing the exponent symbol there

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(1+r)**^**t

coarse birch
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Yeh that’s what I meant

quasi bison
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you have to write the exponent symbol

coarse birch
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Ok

quasi bison
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anyway

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i want you to understand the underlying principle behind compound interest

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each year the value is multiplied by a fixed growth factor that depends on the rate

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and also the compounding freq

coarse birch
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So like 100+100+100?

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Or 4.6% + 4.7% + 4.8%

quasi bison
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???

coarse birch
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Like example

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What’s the formula?

quasi bison
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...

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would prefer not to enable "what's-the-formula-ism l

coarse birch
#

Alright

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I gotta go sleep thanks for helping

safe radishBOT
#

@coarse birch Has your question been resolved?

safe radishBOT
#
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safe radishBOT
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modest hollow
#

What is the conjugate of -3i ?

safe radishBOT
lean chasm
modest hollow
#

.close

safe radishBOT
#
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high wadi
safe radishBOT
high wadi
#

can someone help me

safe radishBOT
#

@high wadi Has your question been resolved?

safe radishBOT
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high wadi
#

.reopen

safe radishBOT
#

high wadi
#

can someone help me? Im confused

safe radishBOT
#

@high wadi Has your question been resolved?

safe radishBOT
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nimble arch
#

how do significant figures work

safe radishBOT
nimble arch
#

i cant tell if im doing something wrong or if this pdf document is doing something wrong

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shouldn't this be rounded to 0.1m

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physics btw

grizzled shoal
#

it depends on what is given

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from what have you derived 50 and 400?

nimble arch
#

400 is the springrate and 50 was the resilience

grizzled shoal
#

springrate?

nimble arch
#

400/50 gives the extraction

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idk the proper english term

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1 sec

grizzled shoal
#

ah german?

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alles klar

nimble arch
#

dutch actually (unfortunately)

grizzled shoal
#

50 has 2 significant digits

nimble arch
grizzled shoal
#

that sounds so close to german haha

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we call it elastizität

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anyway

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since the least amount of sig figs was 2 (from 50) the result should be rounded to 2

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so 0.125 becomes 0.13

nimble arch
#

wait why 0.13

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ooh nvm

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well i was right then

grizzled shoal
#

btw, if you plan on asking further physics questions in the future, you might wanna think about joining the physics discord

nimble arch
#

do they have a similar help channel system?

grizzled shoal
#

i have sent you the link if you want to

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they have but it is not as good

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they have 2 dedicated channels

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so not one channel per person

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but it still works

nimble arch
#

i see

grizzled shoal
#

but this discord is better definetly

nimble arch
#

mhm

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appreciate u helping

grizzled shoal
#

your welcome

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we all have to go through sig figs etc at one time xD

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worst part was uncertainty

nimble arch
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yeah for a moment it destroyed my perceptive of reality

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all clear now tho

grizzled shoal
#

haha i can relate

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have a good day^^

nimble arch
#

u2

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.close

safe radishBOT
#
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static remnant
#

Hi I have a question on this exercise (I'm going to translate) :

static remnant
neat kiln
#

Helping with exams is strictly forbidden (just like kids before marriage)

static remnant
#

In a bag we have 9 cards, numbered from 1 to 9.
We take away, simultaneously and without looking, 4 cards of the bag.

static remnant
#

It was a exame of 2019

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Special epoc

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Don't believe me look it up

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Plus I have a question I don't need the resolution

static remnant
#

So I came up with

4x3x4!

9c4

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But the solutions say it's

4c2

9c4

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And I don't get why

safe radishBOT
#

@static remnant Has your question been resolved?

buoyant shadow
#

yeah, i agree with the solution

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the hand looks like 3XX8, 2 X from 4,5,6,7

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what does your solution even mean

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so you pick 2 unknown cards

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no idea

cobalt tapir
#

ln(4 − x)^2

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can any1 help me with this one?

raven heart
#

@cobalt tapir you should go in a seperate help channel

static remnant
#

Then u multiple by 4! Cause it's the trades

buoyant shadow
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the two cards come in a random order, if you do 4x3/2 then you can multiply by 4! as long as you also do it for the denominator

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4×3 / 2 × 4!

9c4 × 4!

static remnant
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But why would I had to divide by 2

buoyant shadow
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because you decided to multiply by 4!

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it like, takes a fixed order to an unknown order

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but you already have the two cards in an unknown order

static remnant
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So I don't multiple by 4! Cause the order doesn't Mather?

buoyant shadow
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yes

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i mean, you would have to do something else

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some expression that would make a shuffled hand from your 2 shuffled cards

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i don't know how it would look

static remnant
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Ok, but like why I don't do like

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And then divide by the possiblr cases

buoyant shadow
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it's an expression for nothing

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i don;t know how to explain

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1×1 means 3 then 8, ok

static remnant
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I was doing permutation

buoyant shadow
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then 4×3 means you put two cards afterwards

static remnant
buoyant shadow
#

that counts all hands multiplied by two

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like it's not a finished step

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it's not counting anything successfully

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you have a fixed order mixed with random

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3 then 8 then a permutation of two cards

static remnant
#

The resolution is 1/21

buoyant shadow
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can't be what

static remnant
#

Permutation of 2

buoyant shadow
#

you went off somewhere

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i don't know what you're doing

static remnant
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I'm saying that in that place can be 4 cards and in the other one can be 3 cards

buoyant shadow
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yes, and the 3 can be between them, and it can be last, and it can be second after 8

static remnant
#

Yes but the order doesn't matter in this exercise

buoyant shadow
#

if you account for that it will work

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you're not acting like it doesn't matter when you multiply 4 by 3

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imagine you have two cards

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first card can be 2 cards

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second card can be one card

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2×1 = 2

static remnant
#

Ok gotcha now

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But now I don't understand why it can't be

4c1 * 3c1

buoyant shadow
#

4×3 is that

static remnant
#

Ik this is just confusing I hate probabilities

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Idk when 1 place is supposed to handle 2 cards

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I had to draw the difference between bottom but now I get it

#

Thx a lot

safe radishBOT
#

@static remnant Has your question been resolved?

#
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vagrant sand
#

why did you use a formula?

safe radishBOT
vagrant sand
#

@solar hazel

#

also how did you come up with it as well?

solar hazel
solar hazel
vagrant sand
#

ah

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so

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the answer is $4?

solar hazel
#

huh? I didn't do it but I don't think so

#

that was an example of the expression I wrote in a specific case

safe radishBOT
#

@vagrant sand Has your question been resolved?

safe radishBOT
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safe radishBOT
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neat swallow
#

The graph of function f can be shifted 4 to the left to obtain the graph of function g. If f(x)=x^3 What is equivalent to the function g?

neat swallow
#

i dont get this part

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(shifted 4 to the left)

vast obsidian
#

In negative x-direction

winged river
flat frigateBOT
#

S🅱innoto

neat swallow
#

is it graphs?

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normally

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i think if you shift graph to the right dosent the value get bigger?

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hm

neat swallow
#

oh right

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so if it shifts to the right

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x increases and y remains the same?

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is that how shifting graph works?

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?

neat swallow
winged river
neat swallow
#

whats shifting

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moving the entire line?

winged river
#

Yeah

neat swallow
#

if line is moved to the right

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value of x increases and y remains

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?

winged river
#

To make it bigger/smaller, multiply the function by a constant

neat swallow
#

(x-4)^3

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x got bigger

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needs to subtract number from x

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is this how it works?

winged river
#

sigh try plotting y = (x-3)^3 using desmos or smtg and compare it against y = x^3

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You'll see

neat swallow
#

its the same

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only shifted

winged river
#

Do you see the pattern now ?

neat swallow
#

shifted right 3 unit

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yes

winged river
#

Ok, apply the same logic to your original question and figure out the answer

neat swallow
#

it only wants the equation to be the same as usual

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depending of the graph

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if f shifted left

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means (x+4)^3 to get the original one

winged river
#

I'm sorry, what's the confusion now ?

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Try to pinpoint it for me ?

neat swallow
#

the confusion was the cooleration of the shifting of the graph and the equation

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fixed

#

thanks

winged river
#

My pleasure

neat swallow
#

.close

safe radishBOT
#
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potent trench
#

Hey !

safe radishBOT
potent trench
#

?

#

Sorry

#

Wrong question

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The question is

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Can anyone solve ?

neat kiln
#

you should be solving

potent trench
#

Bruh if I got the ans why would I ask

#

I tried like 5 times

upper badge
#

what have you tried so far?

solemn ridge
#

are you having trouble solving the zeros?

potent trench
solemn ridge
#

ok

potent trench
#

Then Idk what to do

solemn ridge
#

just plug in the values

potent trench
#

I guess we need to substitute

neat kiln
#

do you know sum and product of quadratic roots?

potent trench
#

Ofc

neat kiln
#

what are they?

potent trench
#

Why

neat kiln
#

that will come handy here?

potent trench
#

Alpha + Beta = -b/a

upper badge
#

since your roots are complex it is easier to use that

potent trench
#

Alpha.beta
= c/a

potent trench
upper badge
#

$\frac{a}{b} + \frac{b}{a} = \frac{a^{2} + b^{2}}{ab}$

flat frigateBOT
#

kinglacto

potent trench
#

Ohhh

upper badge
#

this isnt enough tho

potent trench
#

So we need to simplify this ?

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Yeah

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Sub the value

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Of the

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Sum of zeroes

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And

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Product

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Of zeroes ig

upper badge
#

you need the expression to be in terms of (a + b) and (ab)

potent trench
#

Oh yes

upper badge
#

yeah

potent trench
#

In numerator can we use an identity ?

upper badge
#

you have to complete the square

potent trench
#

How though

upper badge
#

so you have a^2 + b^2

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and you need to express it with an (a + b) or (ab) atleast

potent trench
#

Hkw

upper badge
#

how do we do that?

potent trench
#

How*

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That's what am asking

upper badge
#

well you could try squaring (a + b)

upper badge
potent trench
#

We can take square common

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Then

upper badge
potent trench
#

( a + b )²

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Now we can

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Substitute

upper badge
#

but theres a problem

potent trench
#

What ?

upper badge
#

(a + b)^2 != a^2 + b^2

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(a + b)^2 = a^2 + b^2 + 2ab

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if i wanted a^2 + b^2 in the RHS

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what could i do?

potent trench
#

Idk

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What now?

upper badge
#

you dont want 2ab in the RHS

potent trench
#

Dc about rhs

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Just simplify lhs

upper badge
#

well you should

potent trench
#

Now

upper badge
#

the LHS, on simplification, isnt equal to a^2 + b^2, is the problem

neat kiln
#

you should know that a^2+b^2 and (a+b)^2 are not the same

potent trench
potent trench
#

Ahhh

#

Wait

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Am talking about numerator bro

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(a + b )²/ab ?

upper badge
#

$\frac{\big(a + b\big)^{2}}{ab}$ is what you're suggesting

flat frigateBOT
#

kinglacto

potent trench
upper badge
#

but thats wrong

potent trench
#

How

upper badge
upper badge
potent trench
#

Why are you expanding?

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No need to expand

upper badge
#

to prove you're wrong

potent trench
#

We know the value of a + b right

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So we can just substitute

upper badge
potent trench
#

Ik we need to solve further

upper badge
#

$\frac{\big(a + b\big)^{2}}{ab} \neq \frac{a}{b} + \frac{b}{a}$

flat frigateBOT
#

kinglacto

potent trench
upper badge
#

what?

#

ok its fine

potent trench
#

?

neat kiln
#

$\ (a+b)^2 \neq \ (a^2+b^2)$

potent trench
#

Yes

upper badge
#

$a^{2} + b^{2} = \big(a + b\big)^{2} - 2ab$

flat frigateBOT
#

kinglacto

upper badge
#

does this make sense?

potent trench
#

No

upper badge
flat frigateBOT
#

Diegoro

potent trench
upper badge
#

dw about it

potent trench
#

<@&286206848099549185>

#

Bruhh

upper badge
#

is the equation correct or wrong?

potent trench
#

Wrong ig

upper badge
#

try expanding

potent trench
#

Bruh

#

Am done

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I have to eat snacks

#

Wait a sec

neat kiln
#

you must know how to expand (a+b)^2

lean otter
# potent trench How -2ab came

expand (a + b)². you will find pretty quickly that a² + b² = (a + b)² - 2ab, which is an equivalent way of writing the resulting expansion. you can verify this by simplifying the right side.

upper badge
neat kiln
potent trench
upper badge
#

you need to calm down.... its ok
we can start over
expand (a + b)^2

potent trench
#

Ahhhh

neat kiln
#

do you think (5+6)^2 and 5^2 + 6^2 the same?

potent trench
#

a2 + 2ab + b2

neat kiln
#

clearly not

upper badge
potent trench
potent trench
potent trench
#

Understood a bit

neat kiln
#

@potent trench are you familiar with these ?

potent trench
neat kiln
#

wait no

#

the second one should be (a-b)^2

potent trench
#

How a + b ² can have two different identities

neat kiln
#

stupid google

upper badge
#

wait sorry nvm

neat kiln
#

so do you know these?

potent trench
#

Yes

neat kiln
#

yes

potent trench
#

Which one were usiny

neat kiln
#

now in the second equation

potent trench
#

Using

upper badge
neat kiln
#

subtract both sides with 2ab

potent trench
#

But why ???

neat kiln
#

to get the result of a^2+b^2

potent trench
#

Wait

upper badge
neat kiln
#

(a+b)^2 = a^2+b^2+2ab right?

#

now subtract 2ab both sides

potent trench
#

Yes

neat kiln
#

you get a^2+b^2 = (a+b)^2-2ab

potent trench
#

And how

upper badge
#

$\big(a + b\big)^{2} = a^{2} + b^{2} + 2ab \newline$ subtracting 2ab from both sides
$ \newline \big(a + b\big)^{2} - 2ab = a^{2} + b^{2} + 2ab - 2ab = a^{2} + b^{2}$

flat frigateBOT
#

kinglacto

neat kiln
#

did you forget your original question?

potent trench
#

Waitt

potent trench
upper badge
# potent trench But why ?

the reason we are doing all of this is, is because ... we know the values of (a + b) and (ab) ONLY
and we need our expression to be in terms of those... and nothing else

neat kiln
#

(a^b+b^2)/ab

#

now we can rewrite it as:

potent trench
upper badge
#

bc thats not equal to our original expression

potent trench
#

Pff

#

Shit

upper badge
neat kiln
potent trench
#

Yes

#

You did

#

Oh

#

Now I get it

neat kiln
#

you should have learned these stuff before quadratics imo

upper badge
#

and recognising to do these steps will come with practice... in case you felt we pulled all of this out of nowhere

potent trench
#

Bruh

#

Ok anyone of you got final ans ?

upper badge
#

thats your job im afraid

potent trench
#

Tell idm

upper badge
#

i do

potent trench
#

Bruh ok I got my ans as 3

#

Yours ?

#

@upper badge

#

?

upper badge
#

that doesnt look right

#

what did you solve?

potent trench
upper badge
#

.....

potent trench
#

I am so disappointed

#

.close

safe radishBOT
#
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potent trench
#

?

safe radishBOT
potent trench
#

.close

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neat kiln
#

are you sure about the question?

dull sequoia
#

Depends on the context

neat kiln
#

just show your orginial question

proper bough
#

divide everything by 3

#

so ur factors are 2, 15, 8

#

then find what x = 0

#

in this case -1/2 or 8 works

#

can u use calculator?

whole acorn
#

or you can just use this

#

$$ax^2 + bx + c = 0$$
$$p * q = ac$$
$$p + q = b$$
$$\frac{(ax + p)(ax + q)}{a} = 0$$

flat frigateBOT
#

MarveI

proper bough
#

wow i've never seen that

whole acorn
#

still kept my teacher's powerpoint til this day

#

that's using the quadratic equation

#

"solve by factoring"

proper bough
#

oh yeah my bad ig

whole acorn
#

@lean otter still here?

#

ok so

#

$2x^2 - 15x - 8 = 0$

flat frigateBOT
#

MarveI

whole acorn
#

you got this already

#

find ac first

#

should be easy

flat frigateBOT
#

MarveI

whole acorn
#

ok nvm you're afk

#

ima just go

safe radishBOT
#

@lean otter Has your question been resolved?

brave edge
#

If you want to solve by factoring at first, you can see what the factored version would look like for any roots that you might find

#

So $x²-\frac{15}{2}x-4=(x+x_1)(x+x_2)$

flat frigateBOT
#

Epsilia aka Mellow

brave edge
#

$=x²+(x_1+x_2)x+x_1x_2$

flat frigateBOT
#

Epsilia aka Mellow

brave edge
#

So your roots here are obviously $x_1$ and $x_2$

flat frigateBOT
#

Epsilia aka Mellow

brave edge
#

Now how to find them

#

$x²-\frac{15}{2}x-4=x²+(x_1+x_2)x+x_1x_2$

safe radishBOT
#
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whole acorn
#

timeout lel

brave edge
#

\tableflip

flat frigateBOT
#

Epsilia aka Mellow

safe radishBOT
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woeful scaffold
#

the period of sin(3x) is 2π * 1/3. in my math book there's the general rule that for sin(kx) or similar, the period is 2π * 1/k. what's the proof for this?

lean chasm
#

you're either stretching it out or inward

analog flare
#

Umm sin(0) = 0
sin(2pi) = 0
Period is 2pi
So for sin(kx) kx should be 2pi
x = 2pi/k

woeful scaffold
#

got it

#

.close

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graceful locust
#

I need help with solving logarithms.
First one being
Log4(x^2 +8x-1) = 2+log4(X-1)

graceful locust
#

Like that?

lean otter
graceful locust
#

Hmm okay then how would I proceed

lean otter
graceful locust
#

Yea I'm slowly grasping it thanks

#

And I have another if I may

lean otter
graceful locust
#

Both logs have a base of 2 if its not visible

lean otter
#

At least you have done the main part

graceful locust
#

Not according to my teacher. I'm supposed to solve for x and I'm somewhere in the process

graceful locust
lean otter
#

I usually do the 2nd method. Here I can already see x=1 satisfies the equation so I divide (x^3 - 3x + 2) by (x-1)

graceful locust
#

I see mmh I'd like to see how the other method is if u may take me through it

lean otter
graceful locust
#

Thank u

#

I'll leave it at that for tonight and go through them once more before bed🙂 👍

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safe radishBOT
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obtuse lily
#

Hi, self studying can be quite challenging not to waste some energy using weak resources . Am trying to learn everything around permutations and combinations. Can someone give me some keywords or a map to learn it correctly. Please note i dont care about learning it for some exam i just wanna grasp the concept really well and to be able to apply it in real life. Thank you.

thin token
#

i will tell you the way i learnt it

#

or the way i was taught with

#
  1. Fundamental principle of counting
  2. Permutation and Combination: Basic definition and properties
  3. Formation of groups
    4)Principle of inclusion and exclusion
    5)Permutation of alike objects
  4. Circular Permutation
  5. Total number of combinations
  6. Divisors
  7. Total distribution
  8. Derangement
safe radishBOT
#

@obtuse lily Has your question been resolved?

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sand pivot
safe radishBOT
sand pivot
#

I'm stuck on this trig question:(

trim venture
#

I dont think it is of trignometry

#

just find y its a linear equation

sand pivot
#

The roots throw me off

dull sequoia
#

replace all the non y values with a b c d e f g however many you need

#

$ay = b - cy$ where $a=\sqrt{2}, b = 7, c=\sqrt{3}$

flat frigateBOT
#

Frosst

safe radishBOT
#

@sand pivot Has your question been resolved?

plucky elk
#

.close

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gray plaza
#

How to solve 5(c)?

safe radishBOT
rancid wagon
#

what

woven anchor
#

5(c) = c+c+c+c+c

gray plaza
#

<@&286206848099549185>

maiden jetty
#

it's conditional probability

safe radishBOT
#

@gray plaza Has your question been resolved?

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tall drift
safe radishBOT
tall drift
#

how would I go about calculating 4(4,2) whilst there are 11 points on the graph

raven heart
#

(4,2)+(4,2)+...

tall drift
#

check this

#

highlights in yellow

raven heart
#

Yeah I mean for 3 additions it's overkill

tall drift
#

4(4,2)

raven heart
#

For square and multiply

tall drift
#

then next question is 9(4,2)

#

is that even plausible considering I'm not using exponents

#

or is the same technique applicable?

sweet mica
#

You can do (x,y)=(4,2)+(4,2) and then (x,y)+(x,y)=4(4,2).

sweet mica
tall drift
#

don't undertsand how i'm suppose to pull ans answer from that

raven heart
#

What categorist is trying to say is that 9(4,2) = 2*(4*(4,2)) + (4,2)

tall drift
#

4(4,2) = 4P

raven heart
tall drift
#

image is loading

#

I need to pull an answer from the equation

#

because it's going into another equation

#

would be x110 times easier i you could type the lower exponents in chaat

raven heart
#

I mean if you use _ for subscript I'd understand

tall drift
#

so how would i compute (4,2)squared + (4,2)squared

raven heart
#

There's a latex bot also

#

$a_2$

flat frigateBOT
#

aPlatypus

tall drift
#

so I need to compute P = dG where d = 4 and G = (4,2)

raven heart
#

But it's OK I get you

tall drift
#

P = 4(4,2)

#

so

#

per example its saying (4,2)_2 + (4,2)_2

#

on Z_7 table

#

which is numbers {0,1,2,3,4,5,6}

#

so im assuming anything over 6 and it loops back to 0 and up

#

4 + 4 = 8 so 6 > 0 > 1

raven heart
#

Well (4,2)_2 + (4,2)_2 that's 2*(4,2)_2 i.e. 2*(2*(4,2))

tall drift
#

2 + 2 = 4

#

(1,4)_2

#

so it would just be (4,2) + (4,2)?

raven heart
#

That gives you 2*(4,2)

tall drift
raven heart
#

Multiply again by 2

tall drift
#

but multi is just addition

raven heart
#

That's 4*(4,2)

tall drift
#

so how am i too pull a point from this bc now where back at the inital question 4(4,2)

#

P = 4(4,2)

raven heart
tall drift
#

see for these assignment there are no exampes so I'm not sure what the answers are even to look like

raven heart
#

Like you compute ( (4,2) + (4,2) ) + ( (4,2) + (4,2) )

#

That's the way you'd compute it "square and multiply like"

tall drift
#

so on the first (4,2) + (4,2) = (1,4)

raven heart
#

I.e first you get (4,2)+(4,2)

tall drift
#

(1,4) + (1,4)

raven heart
#

Then you add that new thing to itself

#

Yeah

tall drift
#

(2,1)

#

wait wait

#

but the order is 11 now

raven heart
#

Uh where do you get (1,4)

#

You have to use the table

tall drift
#

from Z_7

raven heart
#

The group law is not addition in Z_7 unfortunately lol

#

You still have to use that table

#

Given that curve,...

tall drift
#

okay then whats the group law order of 11 referring to?

raven heart
tall drift
#

bc all I see in the book is that order n=11 is the number of points on the grpah

#

but dont understand where that plays into the equation

raven heart
#

Sounds like it's useful in the signature

tall drift
#

so 11 (x,y) on the table are used?

raven heart
#

Maybe not just now

tall drift
#

ahhhhhhh

raven heart
#

So stop being hyperfocused on n=11

tall drift
#

LOL

#

so (4,2) + (4,2) = (6,5)

#

(6,5) + (6,5) = (3,6)

#

P = (3,6)

raven heart
#

Yeah ok

tall drift
#

signer picks a random number, k, between 1 and n – 1 and computes kG, a point with the coordinates (x, y)

#

9(4,2)

#

8p + P

#

hold up im send pic rn

#

for you to confirm

raven heart
tall drift
#

(x,y) = (6,2)

#

says signer sets r = x mod n

#

r = 6 mod 11

#

which is equal to 6

#

so r = 6

#

excuse the bottom s = bc division prior to addition

#

but would i divide then the quotient mod 11?

#

ex 24 / 9 = x mod 11

#

or 9 mod 11 = 9 so 24 / 9 = x

raven heart
#

We're working in the integers mod 11 here

#

Having a final result which is not an integer is problematic

tall drift
#

hmmm

raven heart
#

The closest equivalent of dividing by a number k mod 11 is multiplying by the inverse k^-1 mod 11

tall drift
#

24 * 9^-1?

#

which is 24 * -9

raven heart
#

Yeah

#

Uh

tall drift
#

-216?

#

mod 11

raven heart
#

Why -9 ?

tall drift
#

inverse

#

9^-1

#

would 9^1 = 9

#

so 9^-1 = -9

raven heart
#

Nah

tall drift
#

9^-2 = -9 * -9

raven heart
#

9^-1 mod 11, is the integer such that 9*9^-1 = 1 mod 11

tall drift
#

8 + 24/1 mod 11

#

8 + 24 mod 11

#
    • 2
#

8 + 2

#

10

#

S = 10?

raven heart
#

Uh do you know how to find an inverse mod 11 ?

#

That's like bread and butter in crypto

#

Like I understand if you're not familiar with elliptic curves

#

But this is like very basic stuff

tall drift
#

its another number or set of numbers that give the same output?

#

x=6

#

just trying to pass at this point man.. this is the lasst assignment then 4 exams and a project tby frieday

raven heart
#

It's a way to cancel multiplication

tall drift
#
Solution: x = 6
Indeed, we have 24 * 6 = 144
and 144 = 1 mod 11```
#

bc 144 give you 1 mod 11

#

so would the x = 6 replace the (24 / 9 mod 11)

#

or replace the 9 mod 11

#

hmm

#

S = 8 + 144

#

S=152

raven heart
#

You want x such that 9x = 1 mod 11

#

Then s = 32/9 mod 11 = 32x mod 11

#

(x is the inverse of 9 mod 11)

tall drift
#

addition prior to the divison?

#

PEMDAS doesnt apply here?

raven heart
#

I mean they have parentheses in the formula right

tall drift
#

damn you caught that

#

wait wait so was the 9^-1 neccessary

#

bcc 32 / 9 mod 11 now

#

or we were calculating i tthat way the whole time

#

I see where the mistake was correcting it on my side

raven heart
#

9^-1 is the way of expressing "I divide by 9" in modular arithmetic

#

You can write it 32*9^-1 or 32/9 whatever

#

But if you don't know how to get the inverse of 9 you're screwed to end the calculation

tall drift
#

a * x = 1 mod m

#

x = 10

#

now the 1 mod 11 is canceled and we're left with 32 * 10

raven heart
#

Uh you're sure about the 10

#

9*10 is not 1 mod 11

tall drift
#

im dumb was doing 32

raven heart
#

9*5 on the other hand

tall drift
#

would thatmake whats left in the equation S = 32 / 9 * 5

#

canceling the mmod 11

raven heart
#

32/9 becomes 32*5 (mod 11)

#

5 is the inverse of 9 mod 11

tall drift
#

mmmmm

raven heart
#

That's what 9^5 = 1 mod 11 means

tall drift
#

s = 160 mod 11, s = 6

raven heart
#

kay

#

Well, so what's the point Q now ?

#

Do they say something about it in your book?

#

I hope it's not a pain to calculate again

tall drift
#

srry mouse double clicks every time i click, makes it hard to screenshot

#

and mousepd is broken

#

say s = inverse of s in signature

#

s = inverse of signature s = k / (h + rd) mod n

raven heart
#

w is the inverse

tall drift
#

mmmmmm

raven heart
#

That's what they call it at least

tall drift
#

wh=hk (h+rd)=u

#

1/6(8) = 8(9) * (8+6(4) = u

#

((1/6)(8)) = 72(32) = u

raven heart
#

Just compute wh

tall drift
#

why is there two equal signs in the equation?

raven heart
#

And forget about the hk stuff

tall drift
#

1/6(8) = 8/6 = 4/3

raven heart
#

The middle part is just some rewriting of wh

#

(Probably if want to prove the signature schema is correct or something)

raven heart
#

Anyway I didn't see it was so late now

#

I gtg to sleep now

tall drift
#

okay

#

thanks for the help thus far

#

would the 1/6(8) be mod 11

#

or just the 1/6

raven heart
#

I mean both

tall drift
#

hmm

#

ok

raven heart
#

But it's really the 1/6 you have to take care of

tall drift
#

inverse?

raven heart
#

8 = 8mod 11 so...

tall drift
#

1/6 * x mod 11

raven heart
tall drift
#

okay thanks

#

goodnight

raven heart
#

If you're still stuck and nobody comes, leave me a DM

tall drift
#

sounds good ::))

#

.close

safe radishBOT
#
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knotty hornet
safe radishBOT
knotty hornet
#

How would I determine

#

question #3?

royal kiln
knotty hornet
royal kiln
#

Have you calculated either of those quantities yet?

knotty hornet
royal kiln
#

What did you find already

#

?

#

@knotty hornet are you still with us

knotty hornet
#

I found the expressions that represent with and length of the frame

royal kiln
knotty hornet
#

ohh

royal kiln
#

💡

safe radishBOT
#

@knotty hornet Has your question been resolved?

safe radishBOT
#
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knotty hornet
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.close

visual meteor
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can someone help me go through this one by one

worn shadow
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Lets start with HDF since we know the values of <FHD and <HFD

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<FHD is 40 deg

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and <HFD is 30 deg

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we know that a triangle has a total of 180 deg

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so 40+30 = 70

visual meteor
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<hdf should be 110

worn shadow
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correct

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from there we can figure out <BDE

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because <BDE is back to back with <HDF, the degs are the same

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so <BDE is 110 deg

visual meteor
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is it because of the reflective property?

worn shadow
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Im not sure about reflective property as I havent heard that term, I wasnt taught in english terms

visual meteor
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ah its ok dont worry about it then

worn shadow
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alright so moving on

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we have both <BDE and <HDF, adding those two together we get 220 (110+110)

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we know that a full circle is made of 360 deg

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so 360-220 should get you 140

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and since <BDH and <EDF are back to back, we can conclude that they have the same values

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so we can just do 140/2 which gives 70

visual meteor
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OH I SRR

worn shadow
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and so <BDH and <EDF are both 70 deg

visual meteor
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see*

worn shadow
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from there we can find the deg of the triangle BDH

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at H we can see that there are 4 right angles

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right angles being 90 degs

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and on triangle HDF we see that there is a 40 deg at <DHF

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so to find out the deg of <BHD we can just do 90-40

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which gives 50 deg

visual meteor
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oh okok

worn shadow
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now that we have notes of a couple angles, <BHD = 50, <BDH = 70

visual meteor
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so 50+70 is =120 180-120 <bhd = 60?

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no wait

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i meant <hbd is 60

worn shadow
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correct

visual meteor
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then <abc is also 60

worn shadow
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yup

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can you figure out <abh and <cbd?

visual meteor
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wait maybe

worn shadow
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its the same way we figured out <bdh and <edf

visual meteor
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which left us with 240 then 240/2 which <cbd is 120 and <abh is 120 also?

worn shadow
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correct

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good job

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<IHB and <IHJ is pretty straight forward, those are both right angles

visual meteor
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yeah

worn shadow
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we can figure out <KHJ by subtracting 30 from 90

visual meteor
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whixh is 60

worn shadow
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for <GFD we can use the straight line to our advantage

worn shadow
visual meteor
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180-30?

worn shadow
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yep

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and that should be the value of <GFD

visual meteor
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yesyes

worn shadow
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I believe we determined all angles?

visual meteor
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i think so thank you so much

worn shadow
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no worries :)

visual meteor
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.close

safe radishBOT
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primal gazelle
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Seems obvious but how do i prove this, prove that in every tournament with n players, you can order the players p1,p2,pn in a way such that p1>p2>...>pn ">" means won with. (extremal principle)

safe radishBOT
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@primal gazelle Has your question been resolved?

buoyant shadow
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i don't get it

safe radishBOT
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@primal gazelle Has your question been resolved?

primal gazelle
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In other words prove u can order the players in a way one won with the previous one and so on, so at the end would be the one that lost to everyone

buoyant shadow
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but how

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i don't understand

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3>2>1>4?

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but 1 didn't do anything to 4, didn;t even live longer

safe radishBOT
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@primal gazelle Has your question been resolved?

safe radishBOT
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Ask your math question in a clear, concise manner.
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upbeat ridge
safe radishBOT
upbeat ridge
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Can anyone show me where I did wrong?

half glade
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when differentiating sin the "inside" doesn't change

upbeat ridge
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wdym?

ruby pelican
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it should be -4x-3 in the sin at the end

ruby pelican
upbeat ridge
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But one of my calculators said it's wrong

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It said the answer was $-32\cos \left(3+4x\right)$

flat frigateBOT
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AirToastie

ruby pelican
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for the 2nd derivative?

upbeat ridge
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Yes

ruby pelican
upbeat ridge
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I already did the derivative

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So I changed it to cos