#help-23
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How do I solve question 10
do you know how to subtract fractions in general?
Yes I do
If the denominator is same just subtract
And if not
Find the LCM and do the same to the numerator and minus
@quasi bison
ok great
then convert both of these mixed fractions into improper fractions, then subtract them as you normally would
then, if desired, convert the result back into a mixed fraction
Yup
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Ask question
which one first?
they are both relatively easy but #2 involves less computation
so i guess let's start with that
I have the formula
Trevor earned $136.50 in simple interest by investing $650 at 4.2% per annum. How long did he hold the investment?
(transcribing the problem here for my own sake)
Yea
so you have the formula simple interest = principal * rate * time, yes?
everything here is known except time.
I don’t have t
yes, as i said.
Yeh
you don't have the time, but you have everything else
Correct
are you able to isolate T in the formula I = PRT?
So I remove t from the formula?
Ann
what do you mean
if you need to take a break then by all means go ahead
ping me once you're back
yes?
650 x (136.50 x 0.042)?
What does / mean?
division, what else?
And I is my 136.50
yes, the interest is 136.50 as the problem says
Okay let me solve
meanwhile i will transcribe the other problem for future reference
Jo decides to save for a vacation in 4 years by buying a $1000 GIC on June 1st each year for 3 years. (In the fourth year she also saves $1000 but does not invest it.) All of the GICs pay 4.2% interest, composed monthly. How much money will Jo have saved for her vacation over the four year period?
How do you transcribe it so fast?
took me 2 minutes?
Oh
Do you get paid to help people?
no
Result:
5
ok yes 5 years is correct
What if it was months
wym
Like for exp
are you asking how to answer the question if you were told to give the answer in months?
there are 12 months in a year. 5 years = 5*12 months = 60 months.
ok
4 is considerably more complicated, bc now we are dealing with not only compound interest but an annuity
it's an investment in which, in addition to compound interest being earned, new money is added into the account at regular intervals (usually every year, and usually an equal amount)
So it’s like a mix of compound and simple interest?
Ok let me make it simple
so you know the general principle of compound interest, right?
Yeh ik how to do compound
namely that each paying period the money in the account grows multiplicatively rather than additively as in simple interest
so for an investment of r% compounded annually, the value is multiplied by (1+r/100) every year.
T - 4 years
R - 0.042
Ok
you understand this, right?
Yeh that’s what I meant
you have to write the exponent symbol
Ok
anyway
i want you to understand the underlying principle behind compound interest
each year the value is multiplied by a fixed growth factor that depends on the rate
and also the compounding freq
???
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What is the conjugate of -3i ?
3i
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can someone help me
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✅
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how do significant figures work
i cant tell if im doing something wrong or if this pdf document is doing something wrong
shouldn't this be rounded to 0.1m
physics btw
400 is the springrate and 50 was the resilience
springrate?
dutch actually (unfortunately)
50 has 2 significant digits
that sounds so close to german haha
we call it elastizität
anyway
since the least amount of sig figs was 2 (from 50) the result should be rounded to 2
so 0.125 becomes 0.13
btw, if you plan on asking further physics questions in the future, you might wanna think about joining the physics discord
do they have a similar help channel system?
i have sent you the link if you want to
they have but it is not as good
they have 2 dedicated channels
so not one channel per person
but it still works
i see
but this discord is better definetly
your welcome
we all have to go through sig figs etc at one time xD
worst part was uncertainty
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Hi I have a question on this exercise (I'm going to translate) :
Helping with exams is strictly forbidden (just like kids before marriage)
In a bag we have 9 cards, numbered from 1 to 9.
We take away, simultaneously and without looking, 4 cards of the bag.
It's not a exam....
It was a exame of 2019
Special epoc
Don't believe me look it up
Plus I have a question I don't need the resolution
What's the probability of the minor number be 3 and the highest 8?
So I came up with
4x3x4!
9c4
But the solutions say it's
4c2
9c4
And I don't get why
@static remnant Has your question been resolved?
yeah, i agree with the solution
the hand looks like 3XX8, 2 X from 4,5,6,7
what does your solution even mean
so you pick 2 unknown cards
no idea
It's like from the for 4 cards between those numbers u gonna place 1
And from what we have now 3 cards u gonna place one
Then u multiple by 4! Cause it's the trades
the two cards come in a random order, if you do 4x3/2 then you can multiply by 4! as long as you also do it for the denominator
4×3 / 2 × 4!
9c4 × 4!
But why would I had to divide by 2
because you decided to multiply by 4!
it like, takes a fixed order to an unknown order
but you already have the two cards in an unknown order
So I don't multiple by 4! Cause the order doesn't Mather?
yes
i mean, you would have to do something else
some expression that would make a shuffled hand from your 2 shuffled cards
i don't know how it would look
it's an expression for nothing
i don;t know how to explain
1×1 means 3 then 8, ok
I was doing permutation
then 4×3 means you put two cards afterwards
Yes
that counts all hands multiplied by two
like it's not a finished step
it's not counting anything successfully
you have a fixed order mixed with random
3 then 8 then a permutation of two cards
Can't be
The resolution is 1/21
can't be what
Permutation of 2
I'm saying that in that place can be 4 cards and in the other one can be 3 cards
yes, and the 3 can be between them, and it can be last, and it can be second after 8
Yes but the order doesn't matter in this exercise
if you account for that it will work
you're not acting like it doesn't matter when you multiply 4 by 3
imagine you have two cards
first card can be 2 cards
second card can be one card
2×1 = 2
4×3 is that
Ik this is just confusing I hate probabilities
Idk when 1 place is supposed to handle 2 cards
I had to draw the difference between bottom but now I get it
Thx a lot
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why did you use a formula?
I gave an example below it
it's so that we can find the N for which that expression is largest
huh? I didn't do it but I don't think so
that was an example of the expression I wrote in a specific case
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The graph of function f can be shifted 4 to the left to obtain the graph of function g. If f(x)=x^3 What is equivalent to the function g?
In negative x-direction
Hint: If function f is shifted a units to the right, then the new function $g(x) = f(x-a)$
S🅱innoto
is it graphs?
normally
i think if you shift graph to the right dosent the value get bigger?
hm
why would it
oh right
so if it shifts to the right
x increases and y remains the same?
is that how shifting graph works?
?
.
No, it doesn't get bigger, it's just shifted
Yeah
To make it bigger/smaller, multiply the function by a constant
sigh try plotting y = (x-3)^3 using desmos or smtg and compare it against y = x^3
You'll see
Do you see the pattern now ?
Ok, apply the same logic to your original question and figure out the answer
it only wants the equation to be the same as usual
depending of the graph
if f shifted left
means (x+4)^3 to get the original one
the confusion was the cooleration of the shifting of the graph and the equation
fixed
thanks
My pleasure
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Hey !
you should be solving
what have you tried so far?
are you having trouble solving the zeros?
First I found the value of alpha and beta
ok
Then Idk what to do
just plug in the values
I guess we need to substitute
do you know sum and product of quadratic roots?
Ofc
what are they?
Why
that will come handy here?
Alpha + Beta = -b/a
since your roots are complex it is easier to use that
Alpha.beta
= c/a
What ?
$\frac{a}{b} + \frac{b}{a} = \frac{a^{2} + b^{2}}{ab}$
kinglacto
Ohhh
this isnt enough tho
So we need to simplify this ?
Yeah
Sub the value
Of the
Sum of zeroes
And
Product
Of zeroes ig
you need the expression to be in terms of (a + b) and (ab)
Oh yes
yeah
In numerator can we use an identity ?
you have to complete the square
How though
Hkw
how do we do that?
well you could try squaring (a + b)
yeah im just motivating you to figure it out on your own
what?
but theres a problem
What ?
(a + b)^2 != a^2 + b^2
(a + b)^2 = a^2 + b^2 + 2ab
if i wanted a^2 + b^2 in the RHS
what could i do?
well you should
Now
the LHS, on simplification, isnt equal to a^2 + b^2, is the problem
you should know that a^2+b^2 and (a+b)^2 are not the same
ig this can be applied
$\frac{\big(a + b\big)^{2}}{ab}$ is what you're suggesting
kinglacto
Yes
but thats wrong
How
.
.
to prove you're wrong
yes but this expression isnt our original expression
Ik we need to solve further
$\frac{\big(a + b\big)^{2}}{ab} \neq \frac{a}{b} + \frac{b}{a}$
kinglacto
Bruhh
?
$\ (a+b)^2 \neq \ (a^2+b^2)$
Yes
$a^{2} + b^{2} = \big(a + b\big)^{2} - 2ab$
kinglacto
does this make sense?
No
can you prove it?
Diegoro
How -2ab came
dw about it
is the equation correct or wrong?
Wrong ig
try expanding
you must know how to expand (a+b)^2
expand (a + b)². you will find pretty quickly that a² + b² = (a + b)² - 2ab, which is an equivalent way of writing the resulting expansion. you can verify this by simplifying the right side.
ok look, this is correct ok?
-2ab ?
+2ab right ?
@potent trench did you not see this?
Oh ..
you need to calm down.... its ok
we can start over
expand (a + b)^2
Ahhhh
do you think (5+6)^2 and 5^2 + 6^2 the same?
a2 + 2ab + b2
clearly not
now if you subtract 2ab.. what do you get?
Oo
But why though
.
@potent trench are you familiar with these ?
Bruhhh
How a + b ² can have two different identities
wait sorry nvm
so do you know these?
Yes
yes
Which one were usiny
now in the second equation
Using
does this make more sense now?
subtract both sides with 2ab
to get the result of a^2+b^2
Wait
good ques.... just go with it for now
Yes
you get a^2+b^2 = (a+b)^2-2ab
$\big(a + b\big)^{2} = a^{2} + b^{2} + 2ab \newline$ subtracting 2ab from both sides
$ \newline \big(a + b\big)^{2} - 2ab = a^{2} + b^{2} + 2ab - 2ab = a^{2} + b^{2}$
kinglacto
apply that here
did you forget your original question?
Waitt
..m
do you remember this?
the reason we are doing all of this is, is because ... we know the values of (a + b) and (ab) ONLY
and we need our expression to be in terms of those... and nothing else
Yes
But why didn't we do this a+b²/ab
bc thats not equal to our original expression
.
didnt I explain (a+b)^2 is not the same as a^2+b^2??
you should have learned these stuff before quadratics imo

and recognising to do these steps will come with practice... in case you felt we pulled all of this out of nowhere
I did
Bruh
Ok anyone of you got final ans ?
thats your job im afraid
Tell idm
i do
.....
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?
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are you sure about the question?
Depends on the context
just show your orginial question
divide everything by 3
so ur factors are 2, 15, 8
then find what x = 0
in this case -1/2 or 8 works
can u use calculator?
or you can just use this
$$ax^2 + bx + c = 0$$
$$p * q = ac$$
$$p + q = b$$
$$\frac{(ax + p)(ax + q)}{a} = 0$$
MarveI
wow i've never seen that
still kept my teacher's powerpoint til this day
that's using the quadratic equation
"solve by factoring"
oh yeah my bad ig
MarveI
MarveI
@lean otter Has your question been resolved?
If you want to solve by factoring at first, you can see what the factored version would look like for any roots that you might find
So $x²-\frac{15}{2}x-4=(x+x_1)(x+x_2)$
Epsilia aka Mellow
$=x²+(x_1+x_2)x+x_1x_2$
Epsilia aka Mellow
So your roots here are obviously $x_1$ and $x_2$
Epsilia aka Mellow
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timeout lel
\tableflip
Epsilia aka Mellow
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the period of sin(3x) is 2π * 1/3. in my math book there's the general rule that for sin(kx) or similar, the period is 2π * 1/k. what's the proof for this?
period of sin is 2pi => sin((2pi)/(2pi) x) has a period of 2pi => sin((2pi)/k x) has a period of k
you're either stretching it out or inward
Umm sin(0) = 0
sin(2pi) = 0
Period is 2pi
So for sin(kx) kx should be 2pi
x = 2pi/k
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I need help with solving logarithms.
First one being
Log4(x^2 +8x-1) = 2+log4(X-1)
Use log(a)-log(b)=log(a/b)
No, a and b denote the two equations in your question.
Hmm okay then how would I proceed
Should be easy from here on
Yeah sure
But you have solved it already if I am not wrong
At least you have done the main part
Not according to my teacher. I'm supposed to solve for x and I'm somewhere in the process
Thus I'm wondering if this is the right approach to solving it
The approach is correct. Beyond this, there are usually two ways you can go about it. One is the long method of finding all 3 roots of the cubic equation. The other is to guess one root by mental calculation and find the other 2 using polynomial division.
I usually do the 2nd method. Here I can already see x=1 satisfies the equation so I divide (x^3 - 3x + 2) by (x-1)
I see mmh I'd like to see how the other method is if u may take me through it
I'll recommend watching this video. It explains well with steps.
Learn how to Solve Advanced Cubic Equations using Synthetic Division. Also learn how to Check your Answer Algebraically and Graphically (Graph of the Cubic Equation is Provided). Step-by-Step Tutorial by PreMath.com
Thank u
I'll leave it at that for tonight and go through them once more before bed🙂 👍
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Hi, self studying can be quite challenging not to waste some energy using weak resources . Am trying to learn everything around permutations and combinations. Can someone give me some keywords or a map to learn it correctly. Please note i dont care about learning it for some exam i just wanna grasp the concept really well and to be able to apply it in real life. Thank you.
i will tell you the way i learnt it
or the way i was taught with
- Fundamental principle of counting
- Permutation and Combination: Basic definition and properties
- Formation of groups
4)Principle of inclusion and exclusion
5)Permutation of alike objects - Circular Permutation
- Total number of combinations
- Divisors
- Total distribution
- Derangement
@obtuse lily Has your question been resolved?
Thank you 🌻
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I'm stuck on this trig question:(
The roots throw me off
replace all the non y values with a b c d e f g however many you need
$ay = b - cy$ where $a=\sqrt{2}, b = 7, c=\sqrt{3}$
Frosst
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How to solve 5(c)?
what
5(c) = c+c+c+c+c
it's conditional probability
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same as before
(4,2)+(4,2)+...
Yeah I mean for 3 additions it's overkill
4(4,2)
For square and multiply
then next question is 9(4,2)
is that even plausible considering I'm not using exponents
or is the same technique applicable?
You can do (x,y)=(4,2)+(4,2) and then (x,y)+(x,y)=4(4,2).
Same technique, do 8(4,2) and then add (4,2)
don't undertsand how i'm suppose to pull ans answer from that
Yeah square and multiply works anytime you're repeating an operation
What categorist is trying to say is that 9(4,2) = 2*(4*(4,2)) + (4,2)
4(4,2) = 4P
So if you already know 4(4,2) it's easy to get 9(9,2) from that @tall drift
image is loading
I need to pull an answer from the equation
because it's going into another equation
would be x110 times easier i you could type the lower exponents in chaat
I mean if you use _ for subscript I'd understand
so how would i compute (4,2)squared + (4,2)squared
aPlatypus
so I need to compute P = dG where d = 4 and G = (4,2)
But it's OK I get you
P = 4(4,2)
so
per example its saying (4,2)_2 + (4,2)_2
on Z_7 table
which is numbers {0,1,2,3,4,5,6}
so im assuming anything over 6 and it loops back to 0 and up
4 + 4 = 8 so 6 > 0 > 1
Well (4,2)_2 + (4,2)_2 that's 2*(4,2)_2 i.e. 2*(2*(4,2))
That gives you 2*(4,2)
so it would just be (4,2) + (4,2)?
Multiply again by 2
but multi is just addition
That's 4*(4,2)
so how am i too pull a point from this bc now where back at the inital question 4(4,2)
P = 4(4,2)
I mean yeah, but the point of square and multiply is to have the intermediate result
see for these assignment there are no exampes so I'm not sure what the answers are even to look like
Like you compute ( (4,2) + (4,2) ) + ( (4,2) + (4,2) )
That's the way you'd compute it "square and multiply like"
so on the first (4,2) + (4,2) = (1,4)
I.e first you get (4,2)+(4,2)
(1,4) + (1,4)
The group law is not addition in Z_7 unfortunately lol
You still have to use that table
Given that curve,...
okay then whats the group law order of 11 referring to?
the table
bc all I see in the book is that order n=11 is the number of points on the grpah
but dont understand where that plays into the equation
Sounds like it's useful in the signature
so 11 (x,y) on the table are used?
Maybe not just now
ahhhhhhh
So stop being hyperfocused on n=11
Yeah ok
signer picks a random number, k, between 1 and n – 1 and computes kG, a point with the coordinates (x, y)
9(4,2)
8p + P
hold up im send pic rn
for you to confirm
Yeah it's good
(x,y) = (6,2)
says signer sets r = x mod n
r = 6 mod 11
which is equal to 6
so r = 6
excuse the bottom s = bc division prior to addition
but would i divide then the quotient mod 11?
ex 24 / 9 = x mod 11
or 9 mod 11 = 9 so 24 / 9 = x
We're working in the integers mod 11 here
Having a final result which is not an integer is problematic
hmmm
The closest equivalent of dividing by a number k mod 11 is multiplying by the inverse k^-1 mod 11
Why -9 ?
Nah
9^-2 = -9 * -9
9^-1 mod 11, is the integer such that 9*9^-1 = 1 mod 11
Uh do you know how to find an inverse mod 11 ?
That's like bread and butter in crypto
Like I understand if you're not familiar with elliptic curves
But this is like very basic stuff
its another number or set of numbers that give the same output?
x=6
just trying to pass at this point man.. this is the lasst assignment then 4 exams and a project tby frieday
It's a way to cancel multiplication
Solution: x = 6
Indeed, we have 24 * 6 = 144
and 144 = 1 mod 11```
bc 144 give you 1 mod 11
so would the x = 6 replace the (24 / 9 mod 11)
or replace the 9 mod 11
hmm
S = 8 + 144
S=152
You want x such that 9x = 1 mod 11
Then s = 32/9 mod 11 = 32x mod 11
(x is the inverse of 9 mod 11)
I mean they have parentheses in the formula right
damn you caught that
wait wait so was the 9^-1 neccessary
bcc 32 / 9 mod 11 now
or we were calculating i tthat way the whole time
I see where the mistake was correcting it on my side
9^-1 is the way of expressing "I divide by 9" in modular arithmetic
You can write it 32*9^-1 or 32/9 whatever
But if you don't know how to get the inverse of 9 you're screwed to end the calculation
im dumb was doing 32
9*5 on the other hand
mmmmm
That's what 9^5 = 1 mod 11 means
s = 160 mod 11, s = 6
kay
Well, so what's the point Q now ?
Do they say something about it in your book?
I hope it's not a pain to calculate again
srry
srry mouse double clicks every time i click, makes it hard to screenshot
and mousepd is broken
say s = inverse of s in signature
s = inverse of signature s = k / (h + rd) mod n
w is the inverse
mmmmmm
That's what they call it at least
Just compute wh
why is there two equal signs in the equation?
And forget about the hk stuff
1/6(8) = 8/6 = 4/3
The middle part is just some rewriting of wh
(Probably if want to prove the signature schema is correct or something)
We're still working mod 11 remember
Anyway I didn't see it was so late now
I gtg to sleep now
I mean both
But it's really the 1/6 you have to take care of
inverse?
8 = 8mod 11 so...
1/6 * x mod 11
Yes
If you're still stuck and nobody comes, leave me a DM
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What do you remember about the Perimeter of a rectangle
2 (w + h)
Have you calculated either of those quantities yet?
I'm not sure how
Remind us what answers have you already found
What did you find already
?
@knotty hornet are you still with us
Sorry
I found the expressions that represent with and length of the frame
^
ohh
💡
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can someone help me go through this one by one
Lets start with HDF since we know the values of <FHD and <HFD
<FHD is 40 deg
and <HFD is 30 deg
we know that a triangle has a total of 180 deg
so 40+30 = 70
<hdf should be 110
correct
from there we can figure out <BDE
because <BDE is back to back with <HDF, the degs are the same
so <BDE is 110 deg
is it because of the reflective property?
Im not sure about reflective property as I havent heard that term, I wasnt taught in english terms
ah its ok dont worry about it then
alright so moving on
we have both <BDE and <HDF, adding those two together we get 220 (110+110)
we know that a full circle is made of 360 deg
so 360-220 should get you 140
and since <BDH and <EDF are back to back, we can conclude that they have the same values
so we can just do 140/2 which gives 70
OH I SRR
and so <BDH and <EDF are both 70 deg
see*
from there we can find the deg of the triangle BDH
at H we can see that there are 4 right angles
right angles being 90 degs
and on triangle HDF we see that there is a 40 deg at <DHF
so to find out the deg of <BHD we can just do 90-40
which gives 50 deg
oh okok
now that we have notes of a couple angles, <BHD = 50, <BDH = 70
correct
then <abc is also 60
wait maybe
its the same way we figured out <bdh and <edf
which left us with 240 then 240/2 which <cbd is 120 and <abh is 120 also?
correct
good job
<IHB and <IHJ is pretty straight forward, those are both right angles
yeah
we can figure out <KHJ by subtracting 30 from 90
whixh is 60
for <GFD we can use the straight line to our advantage
yes
180-30?
yesyes
I believe we determined all angles?
i think so thank you so much
no worries :)
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Seems obvious but how do i prove this, prove that in every tournament with n players, you can order the players p1,p2,pn in a way such that p1>p2>...>pn ">" means won with. (extremal principle)
@primal gazelle Has your question been resolved?
i don't get it
@primal gazelle Has your question been resolved?
In other words prove u can order the players in a way one won with the previous one and so on, so at the end would be the one that lost to everyone
but how
i don't understand
3>2>1>4?
but 1 didn't do anything to 4, didn;t even live longer
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Can anyone show me where I did wrong?
when differentiating sin the "inside" doesn't change
wdym?
it should be -4x-3 in the sin at the end
i get what you have done but these online systems dont always accept all answers so even though yours is technically correct i would guess it wanted -32sin(-4x-3)
But one of my calculators said it's wrong
It said the answer was $-32\cos \left(3+4x\right)$
AirToastie
for the 2nd derivative?
why did you put cos, the question is sin