#help-23
1 messages · Page 486 of 1
what's the length of the side opposite that
a/sina=b/sinb
and what letter would that be represented by
no
18 b
no
doesn't seem to be answering the question I initially asked
which letter represents the side opposite the 110° angle A
then ill study. based off my notes
no
from labelling convention, the lowercase letter represents the side opposite the respective capital letter angle/vertex
A?
ok so A = 110,
a = 18
agrred
<ACB or simply <C or C here is currently unknown
mhm
what's the length of the side opposite that
and what's the lowercase letter that represents it
these are not supposed to be trick questions
yeah
we don't really care about b here
side opposite B is b
ok so A = 110,
a = 18
c = 8
C is currently unknown so just leave it as C
now plug those values into the sine rule
now plug those values into the sine rule
18/sin110=8/sin C
where's x coming from
i meant c
r u kidding me
to get something in the form
sin(C) = whatever
the equation that tells you exactly what sin(C) is
similar to when asked to solve something for x, you end goal/result is an equation telling you exactly what x us
how are you getting 26.4
starting with
18/sin110=8/sin C,
do not touch your calculator yet,
manipule that equation algebraically
how do i solve ac
sin(C) =
how do i solve ac
AC is given
angle sums to determine the thirr angle
sin110x8=18C
no
what happened to the sin attached to the C
the principle is exactly the same
the principle is exactly the same
find AC
how
how do i find AC
what would the formula be
just write out the equation
and i'll follow along
angle sums to determine the third angle
write out the angle like u did here
C is 40
@thin bridge
@thin bridge
@thin bridge
@thin bridge
@thin bridge
yes applying angle sums C = 40 here
now go through exactly what I walked you through before
JUST WRITE THE FORMULA I HAVE TO GO DUDE
WRITE THE EQUATION
PLEASE
MY BLOOD LEVELS ARE HIGH BC OFU
identify angles and sides you know and are trying to determine and plug them into the sinevrule
FFS this rudeness
I'm out and blocking you niw
what happened here lol
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rip
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at least we know his "blood levels are high"
bless this person
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I know how to factorize, but i just dont know how they get to this step.
that’s a difference of percent squares
Difference of squares, yeah.
(a-b)(a+b) =a^2-b^2
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can someone explain what happened?
the rewrite using trig identities part
sin^2(θ) = 1 - cos^2(θ)
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damn u very rude
maybe close this @tall hatch
thought I agree it is quite rude
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Hi… may i know where i went wrong??? The correct answer is 2
For starters
On line 2
You didn't distribute the 4 properly
Wait no I'm dumb nvm that
I shifted the log on LHS to RHS so i can divide 50x^2
Wait
not that
I mean RHS to lhs
Mhm
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how did it become 1/202.52
divide top and bottom by 24.69
yea
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Small question for what do u use this its about statistic
?
nothing can be said about this without context, but
by the looks of it, all that is being shown here is that the sum of the deviations of a dataset from its own mean is zero
if you're specifically looking for a "use" for this, you could try and use it to check if you calculated the mean correctly (if the deviations don't add up to zero you didn't)
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For what values of p and q, the function f(x)= 3x^3 + 2x^2 - px + q, the factor of which is x-1, the function of f(-1) = 10?
what?
-1 + p = 10 - q
Your answers dont this
f(-1) = 10
i can't understand either lol
it makes sense
@sweet bone for every factor
Of a function
The function has a root there
Bla bla
So f(1) = 0
-1*
I did also 8, but not even teachers understood
i went to MATURA exam yesterday and we had this question
but, if u just replace p and q, the result won't be 10, if f(-1)
$f(x) = 3x^3 + 2x^2 -px + q$
IntelligentCake
We have full context
this
f(1) = 0
f(-1) = 10
you form simultaneous equations
you have one function
yeah
so do both of those you get 2 equations with p and q
then just solve
simultaneously
@glass sonnet what if we got the function as: f(x)= -3x^3 + 2x^2 + px + q
i changed the - to +
f(x)= 3x^3 + 2x^2 + px + q
this is the function that i got, i forgot that it was with plus
ok so just carry out same procedure?
lol
f(x)= 3x^3 + 2x^2 + px + q
I just want to know the answer cause it will happen that they review wrongly and i need to make a request about it
@glass sonnet
I won't tell you the answer
I'm here to help
not give answers
do f(1)
and f(-1)
then sovle
okay
@sweet bone Has your question been resolved?
i got
-8 and 3
that would be correct i guess
isnt it
thank you
very much
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the sum of all values of the real parameter for which one root of the equation is twice as large as the other
hint: a quadratic with roots $b$ and $2b$ would look like $2(x-b)(x-2b)=0$
Toby
if you this expand out, you can equate coefficients with the original quadratic and solve two equations in two unknowns
i would say solve the the quad like normal (consider a is just a number) to solve for x in term of a then apply the Vieta theorem?

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Reflecting about the x-axis means multiplying by -1. Visualize it graphically
a reflection in the x axis makes the y values negative
you have what y =
you just make that negative
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the jacobian here should be -1/2?
@zinc flint Has your question been resolved?
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?
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there are 2 points, s and t, both of them are real numbers that differ by 1. the graph of the function fa for a=0.5 has two points: (s|f0.5(s)) and (t|f0.5(t)), they both have the same slope.
find s and t (rounded) and give the slope of the two points for f0.5
Help xd
do you mean f(0.5s)
Yes
Yws
do you have f(x)?
nope
nvm there s one
if a is 0.5 the equation is
x* sqrt of e to the power of x
+1
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i keep getting the wrong answer, can someone explain how to do this, i think i am approaching it wrong
Do you have a cartesian equation of the plane?
@south linden Has your question been resolved?
i just miscalculated the cross product, i got it
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Hi guys

The problem is the one from above
Is an inequality btw
I need to find the intervals
You can do this mathematically by finding when the graph is = 0. and then testing for values that are lower and higher than those two values.
Since, x= -1, 2 make the equation equal to zero, you can plug in -2 into the equation and see what the sign is. Also, plug in 0 as 0 is inbetween -1,2 and then try 3.
You know that the equation is 0 when x is either -1 or 2.
So, if you plug in any number less than -1 into the equation what do you get?
Yeah
Choose any number less than -1 and input that as x. Let me know what you get
Okay, so that means from (-infinity, -1) The function is positive, AKA >0
Now plug any value between -1 and 2 and tell me what you get.
So from (-1,2) the function is negative, AKA less than 0
You can now plug in a number greater than 2, but it's a positive number.
Your interval where the function is less than 0 is (-1, 2). You know this because this is the only values of x where the function takes a negative value.
You can always use desmos.com to graph functions and just look at the values it crosses below 0.
With numbers
For example
(x-1)(x+1)>0
One of those numbers in the equation will be the answer
Right
?
Or am i wrong hahaha
I have a test tomorrow and they don't let us use a calculator or the phone 🤕
What you need to do is set each parenthesis =0.
so, x-1=0 and x+1=0
These values shows you where the function is exactly 0.
Now every value before, after, or in-between is either positive or negative. So, you take your two points and select any value below and see what the value is, positive or negative. If it is positive then it is >0. If negative <0.
So if your two numbers let's say are -100 and 100. Your three intervals to test are (-infinity, -100), (-100, 100), and (100, +infinity).
You choose any value for each interval as long as it is in the interval you are testing and input it into the function to see if it is positive or negative.
Ohh understood
If you have something like (x+1)(x+1) then you only test two intervals because both parenthesis yields -1 as the critical point.
AKA the parenthesis are the same thing.
Other than that, you can do this method for any amount of parenthesis. (x+5)(x-3)(x+999)(x+123)
You just end up with more intervals.
I understand
So I just have to put those two numbers and see if that results on a negative or positive answer
What two numbers?
Of my (x+a)(x-b)
You set x+a=0
This gives you the point on the x-axis that crosses 0
so those two numbers when plugged in will make the function = 0.
You have to choose one number that is lower than both, in-between both, and higher than both.
The values of those three "test" numbers tells you if the function is greater than or less than 0.
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how do i take the factorial of a binomial
like (3n+1)!
what's a binomial
sum of two terms?
hold on are you helping or just asking
just asking
to take a factorial of the sum you probably need to know which one is larger 🤔 ?
wdym
nothing, it's like entertainment until someone who can help sees this
I would imagine it would be like (3n+1)! = (3n+1) * 3n * 3n -1 * 3n -2 * ... * 2 *1
have no idea
That should be right.
It's something like this
can you explain
yea
Okay so (x)! = x* x-1 * x-2 * . . . * 2 * 1.
a factorial is taking a number and multiplying one less than the previous number until you get to 1
Because when you take factorials, it's goes to one
5! = 5 * 4 * 3 * 2 * 1
so you keep subtracting 1 until you get to *1.
Now let x = 3n +1
plug in and you get (3n+1) * (3n+1) -1 * (3n+1) -2 * . . .
ok but how do i get to 1 in a binomial
It automatically goes to 1, because that's the base case
All factorials will end at one, usually
i dont understand this
wdym automatically
like i get that it ends at 1
Are you asking how do you get down to multiplying by 1 or how do you get rid of the 1 in the (3n+1)?
5! = 5 * 4 * 3 * 2 * 1
6! = 6 * 5 * 4 * 3 * 2 * 1, etc
The base case is 1
right
there's nothing you can do is what they mean, you can't remove the factorial
i have to express it as a polynomial
It will look like this, there's not really a way to determine the values in between
so what do i do?
You should phrase your entire question again.
i have to express 3n+1 over 3n-2 as a polynomial
you can like, point at the . . . and say this is 3n
First step, clearly ask the question you have. Posting a screenshot/picture of the question you have helps a lot
hold on
Because asking how to expand (3n+1)! doesn't give much context
This?
This is almost your answer
actually that's not even equal to any polynomial
,w (3n+1) choose (3n-2)
Oh nevermind I'm dumb
im so lost
yes
Write it down and simplify
i dont understand the (3n+1)!part
For your values here
Are you sure
You need to understand factorials to understand binomial coefficients
Naaaahhhh that's not the definition
Also that's incredibly vague
Look in a textbook for the definition
Or your notes
do you understand what this means?
3n+1 C 3n-2?
how many ways 3n-2 can be chosen out of 3n +1?
giannis_money
5 c 2
what number is this equal to?
10
ie. in how many ways can you choose 3 things from 5 things?
yes
how did you get that?
i memorized the pascalls triangle till r6
how would you find a value you haven't memorised?
$\binom{n}{k} = \frac{n!}{(n-k)!k!}$
giannis_money
no
No n is a number
wdym
In this example n = 5 and 5 is a number
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Guess they figured out the definition of binomial coefficient
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,tex $\frac{r+5}{r^{2}-2r}$ - 1 = $\frac{1}{r^{2}-2r}$
tye
which steps are you having trouble with
up until this point
it’s out of context but
then the signs become the opposite of before after the last step
not sure what they mean by "change the sign"
but all they did was rearrange the terms
i.e. they moved -r^2 to the front
why
Always simpler to work with a postive leading term.
$\frac{a}{b}=0\iff a=0$
lirmirit
given that $b\neq0$
lirmirit
so for the future when i encounter scenarios like this will i just remove the denominator
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Might be a dumb question
Im trying to prove the second property of group homomorphism
@junior wagon how is the 0 power of an element defined in a group?
I've only seeing this for the 0 power of an element in my notes
so the order of $\phi(g)$ is infinite?
Kurama
not necessarily
your book should have defined powers of an element
but anyways, it's defined as g^0 = e
as in order of an element?
no
as in they should have defined what does the notation g^n mean for any integer n
this is a rather trivial matter, you can just assume g^0 = e
ok
thanks
I dont think they defined it
only defined order of an element and order of the gorup
do you plan on proving this by induction?
One sec..
@junior wagon Has your question been resolved?
Kurama
Kurama
yes
right. then multiply both sides by that, then I think that proofs it
ye
wait, but why can we take it out?
np
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<@&286206848099549185>
@real crater Has your question been resolved?
what have you tried
@real crater Has your question been resolved?
@real crater Has your question been resolved?
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is geometric rv the same as bernoulli rv?
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Hello guys, i have a question. On this equation $$\sqrt{3}sin^2x+\sqrt{3}cos^2x-2sinx=0$$
Lyuka
can i do something like this? $$\sqrt{3}\left(sin^2x+cos^2x\right)-2sinx=0$$
Lyuka
If i go on and finish the question i get the correct answer, but i am not sure if what i did can actually be done
Yes you can
oh thats cool, thanks
What step did you think you can;t do?
Since i was leaving "behind" -2sinx, i thought that maybe what i did wasnt actually possible
Well, thanks once again 🙂
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theta = (L * 2pi) / circumference.... right?
yea, Im trying to do it without r
but thanks, then i just have some computer nonsence going on 😄
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what to do in this question?
is finding maximum vlaue of the function given in option work?
i mean i will find maximum of a function and compare it with other other functions maximum .? will it work?
@blazing rune Has your question been resolved?
find the integral of all of those functions and compare
okay
but is there anymore feasible option ?
i mean to do this fastly?
i thought of finding integrals too but...it takes time
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what's your question?
yeah that looks right
What do I do next
part b?
you plug in the numbers
you know the function h(t)
and u know the t values
50 and 100
What does that look like again
so solve for h(50) and h(100) and then plug and evaluate this
,w h(t) = 0.00185(250 - t)^2, solve (h(100) - h(50)) / 50
yes
i guess so
did you approximate something
Check part b instructions
i mean you did rounding
Yes
@tidal nest Has your question been resolved?
,w h(t)=0.00185(250 - t)^2, solve (h(120.001) - h(120)) / 0.001
Ok
,w s(t)=4t^2 - 10t +13, solve (s(4) - s(1)) / (4- 1)
@dull sequoia
Bots not working for 3a
you wrote s(t)
yeah but you wrote solve h(4)
where did you write to divide by 3
use brackets properly
,w s(t)=4t^2 - 10t +13, solve (s(1.001) - s(1)) / 0.001
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Hello in my class i saw the following equation. N is a desitity function for a normal distribution, and D is a set of data (for example body height). So now is our aim to find a normal distribution N that fits our data the best. Why is it the case if we maximise this product on the right side?
is the thought right that this leads to the situation where the global maximum of this function is over the biggest cluster of data points?
@river cobalt Has your question been resolved?
<@&286206848099549185>
@river cobalt Has your question been resolved?
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hello, i dont know much about Factorization, how do i Factorize with this example
x^2 + x - 12 ? pls and ty
So a couple ways
List out positive and negative factors of -12
And then mix and match
x^2 + bx + c = (x + p)(x + q)
where p + q = b
p x q = c
Or you can also do this: you know that $(x+a)(x+b) = x^2 + (a+b)x + ab$
So now you match terms:
$$x^2+(a+b)x+ab$$
$$x^2+x-12$$
Now you have a system of equations:
$$a+b = 1$$
$$ab = -12$$
Umbraleviathan
This algebra video tutorial provides a basic introduction into factoring trinomials and factoring polynomials. It contains plenty of examples and practice problems on how to factor quadratic equations.
Here is a list of topics:
- Factoring The Greatest Common Factor - GCF
- Factoring Binomials
- How to Factor By Grouping Terms
- Factor...
i think this video can help
i found these rules, are they relevant to the question i sent? @whole acorn@stray socket
i dont think so
your question is ax^2 + bx + c
p + q = b
p x q = ac
for 3, a is 1 btw
i dont really understand what you sent, but the answer to what i sent is (x−3)(x+4) hower i want to know how to get there @whole acorn
the text on pink is the factorized equation
the black is the equation before it's factorized
@devout linden Has your question been resolved?
im guessing you said my question was the 4th one but it doesn't match the answer to my question that i sent @whole acorn?
(x−3)(x+4)
the text on pink is the factorized equation?
ok, how would you factorize x^2 + x - 12 to (x−3)(x+4)
?
ima just reverse explain this ok?
yes
try expanding (x - 3)(x + 4)
idk how i would do it right maybe mulitplyy everything by 3 ?
ok, x^2 + 4x - 3x - 12 ?
you can simplify that
x^2 + x - 12
ok so now that we've proven that it's correct ima explain how i factorize it
x^2 + x - 12
list factors of -12
idk what a common factor is
like..
factors of 10
5 x 2
10 x 1
common factor = 1, 2, 5, 10
just factor*
not common factor
negative 12 btw
-3 x 4 or 3 x -4, -1 x 12 ?
there are other numbers but ok
lets just continue
p + q = 1
p x q = -12
which pair of factors when sum'd is equal to 1
0.5 ??
?
pair of factors from here
try watching this for a more detailed explanation
no need to finish it
just stop at polynomials
ok so
x^2 + x is
x(x + 1)
wait
oh nvm
try expanding this @devout linden
(a + b)(a + c)
a^2+ ac + ab + bc
yes
now.. remember when you had to find common factors that when sum'd is equal to 1?
ac + ab will be = a
and bc = -12 : D
we didnt find common factors?
yeah we found factors
my bad
a = x, b = p, c =q btw @devout linden
ok wait lets try again
expand
(x + p)(x + q)
x^2 + xq + px + pq
yeah
what is p + q here?
so xq + px = x
and pq = -12
and it's x^2 + x - 12
do you understand btw
i dont think you do
im bad at explaining too
maybe ill be back soon
but i wont
i gtg
soon
https://www.youtube.com/watch?v=9MUDAr1PnlE&t=560s just watch this video
This algebra video tutorial provides a basic introduction into factoring trinomials and factoring polynomials. It contains plenty of examples and practice problems on how to factor quadratic equations.
Here is a list of topics:
- Factoring The Greatest Common Factor - GCF
- Factoring Binomials
- How to Factor By Grouping Terms
- Factor...
it'll help
ok when last question if you can when we factor -12 why did we have to know this
it doesnt have to be 1
but in this case it's 1
x^ bx + c = (x + q)(x + p)
in this case b = 1
(x + q)(x + p) = x^2 + xq + xp + pq
xq + xp makes x
cuz p + q = 1
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I'm relatively new to doing proofs, and I'm struggling to understand what is sufficient proof for something. For example, this is a pretty easy proof. I have two main questions about it though: First, is it asking me to prove that both a or v can be 0, or is it asking me to prove that at least one of them must be 0? Second, is it enough to say that we know that for all a in F, a*0=0 , and for all v in V, 0v=0, or do I need more than that?
This is a solution online, which makes sense to me, but I don't know if I actually need this much
@strange quest Has your question been resolved?
@strange quest Has your question been resolved?
Here's another example
This is obviously true because there would be no 0 vector unless b=0
but I don't really know how to put that into math instead of words
Like how to actually prove it
use the definition of subspace
SilverTongue
I think by definition of a subspace, they mean use the governing rules, like does it have an additive identity, etc
By showing those are satisfied (and that they're not when b != 0), it's been proved
Also good book, I'm reading it at the moment
Yeah I just started going through it, its great so far
a little bit tough learning some of this stuff alone without many ways to check my work lol
Yeah I wasn't expecting it to have no answers, a bit annoying
My question though is like
intuitively I can see that when isnt 0, there is no 0 vector in the subspace
but i dont get how to prove that
can I literally just plug it in and say it would be
(0,0,b,0)
and thats the proof?
cause theres no additive identity thats the issue
Can't find an actual solution online, but yeah that's what I did, that's all you'd need to write
Just that if x_4 = 0, then x_3 = b
then show that removes the additive identity
Just finished chapter 1 lol, exam season is keeping me busy
Stopped about a month ago
If you want I can add you and we can ask each other questions and work together through some parts lol
if not its cool
ah rip gl on exams
Tyty
That'd be sick yeah, gives me a reason to get back into it
ok great
.close
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You bid for a coin. You're confident that the price of the coin is between 0 and 100, if your bid is greater than the price, you win and sell it to your friend at the price of 1.5 times price. what's your bid to max your profit?
anyone wanna help me with this?
hmm I'm confused, do you buy the coin if you win? and if so, does it cost the price, or what you bid?
ok you must buy it otherwise you would just bid 100 always
tf is that, why don't you just bid 100 always
and if it costs the premade price then there is also no decision
so I think you must spend whatever you bid
"if your bid is greater than the price, you win and sell it to your friend at the price of 1.5 times price"
is "price" referring to the same number in all three occurrences in this sentence?
as opposed to "bid", the amount you pay?
yeah I think that too
cuz that makes the most sense
you win the bid
and get the coin
with the price you bid
the price you sell it at is 1.5 times the pretermined price though?
that was what I meant by my question, does "price" refer to the unknown actual value or to the amount you pay
I think price is the same everywhere there
that makes somewhat more sense, leaving aside the question of how you discover the actual value after bidding but it's unknown before bidding 😁
@vagrant sand Has your question been resolved?
how
so umm if you bid $N$ (where $N>1$) is the expected profit $\left(\sum_{k=0}^{N-1}\frac{1.5k}{101}\right)-N$?
thats the formula
did you get the same thing?
ok so let's say we bid 4
should that N in the summand be k instead?
k is the actual value of the coin?
yep, oops
Spring
I agree with that formula
there is a
1/101 chance the coin value is 0,
1/101 chance it's 1,
1/101 chance it's 2,
1/101 chance it's 3,
1/101 chance it's 4,
and so on
in the case the value is 0, we win 0, if it's 1 we win 1.5, if it's 2 we win 1.5*2, if it's 3 we win 1.5*3, and if it's anything else we win 0
so the expected gain from selling the coin is 0 + (1/101)*1.5 + (1/101)*3 + (1/101)*4.5 + 0 + 0 + ... + 0
and the expected profit is that - 4 since we spend 4 to bid
@vagrant sand does that make any sense?
oh also I'm assuming between 0 and 100 to mean including 0 and 100
@vagrant sand Has your question been resolved?
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Can this turn into b = 64/a and if so, how does it happen?
yes
so you wanna make the b the variable
so you wanna get rid of the 8 on the bottom of b
so you times it by itself by 8, and whether you do that, you always have to times whatever you're timesing to the other side too
so it would be 8/a(8) = b
because of 8*8, they cancel out which only give you b on the right side
8*8 = 64 therefore 64/a = b
np
64 = ab , b = 64/a
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