#help-23

1 messages · Page 486 of 1

humble grove
#

is it above or bottom

thin bridge
#

what's the length of the side opposite that

humble grove
#

a/sina=b/sinb

thin bridge
#

and what letter would that be represented by

humble grove
#

c

thin bridge
#

no

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not c

humble grove
#

oh i mean

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14 b

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wait

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bruh

thin bridge
#

no

humble grove
#

18 b

thin bridge
#

no

humble grove
#

8 b

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u said opposite

thin bridge
#

doesn't seem to be answering the question I initially asked

humble grove
#

idk what ur saying bro

#

please just tell me the formula

#

thats alli need

thin bridge
#

which letter represents the side opposite the 110° angle A

humble grove
#

then ill study. based off my notes

thin bridge
#

no

#

from labelling convention, the lowercase letter represents the side opposite the respective capital letter angle/vertex

humble grove
#

A?

thin bridge
#

lowercase

#

a is opposite A

humble grove
#

a

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18 is side a

thin bridge
#

b is opposite B
etc

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should be very simple and intuitive to remember

humble grove
#

okay

#

memorized it

#

what now

thin bridge
#

ok so A = 110,
a = 18

humble grove
#

agrred

thin bridge
#

<ACB or simply <C or C here is currently unknown

humble grove
#

mhm

thin bridge
#

what's the length of the side opposite that

#

and what's the lowercase letter that represents it

#

these are not supposed to be trick questions

humble grove
#

ok

#

8 b

humble grove
#

easy

#

doiine

#

one

thin bridge
#

no

#

both wrong

humble grove
#

OH

#

8 c

#

14 b

#

my bad

thin bridge
#

writing too much

#

the side opposite C is c and has length 8m

humble grove
#

yeah

thin bridge
#

we don't really care about b here

humble grove
#

side opposite B is b

thin bridge
#

ok so A = 110,
a = 18
c = 8
C is currently unknown so just leave it as C
now plug those values into the sine rule

humble grove
#

okay fine

#

now what

thin bridge
#

now plug those values into the sine rule

humble grove
#

18/sin110=8/sin C

thin bridge
#

where's x coming from

humble grove
#

i meant c

thin bridge
#

capital C

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capitals for angles

humble grove
#

right

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now what do i do

thin bridge
#

and then first solve for sin(C)

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and then use inverse sine to determine C

humble grove
#

how the fuck do i find sin C

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if i dont know what sin C is

humble grove
thin bridge
#

wdym

#

rearrange the equation

humble grove
#

can u write smth for me

#

so ik what to do

#

fffs

thin bridge
#

to get something in the form
sin(C) = whatever

#

the equation that tells you exactly what sin(C) is

#

similar to when asked to solve something for x, you end goal/result is an equation telling you exactly what x us

humble grove
#

26.4

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is C

#

now what

thin bridge
#

how are you getting 26.4

humble grove
thin bridge
#

starting with
18/sin110=8/sin C,
do not touch your calculator yet,
manipule that equation algebraically

humble grove
#

how do i solve ac

thin bridge
#

sin(C) =

humble grove
#

how do i solve ac

thin bridge
#

AC is given

humble grove
#

pretend it isnt there

#

bc its an answer key

#

how do i solve it

thin bridge
#

angle sums to determine the thirr angle

thin bridge
#

no

humble grove
#

fin

#

lets stick top what i sent

#

p-lease

#

please

thin bridge
#

what happened to the sin attached to the C

humble grove
#

i have to go in 2 mins

#

bro enough

#

enoyugh

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enough

thin bridge
#

the principle is exactly the same

humble grove
#

stick to what i just sent

#

this

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nothing else

thin bridge
#

the principle is exactly the same

humble grove
#

find AC

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how

#

how do i find AC

#

what would the formula be

#

just write out the equation

#

and i'll follow along

thin bridge
#

angle sums to determine the third angle

humble grove
#

C is 40

#

@thin bridge

#

@thin bridge

#

@thin bridge

#

@thin bridge

#

@thin bridge

thin bridge
#

yes applying angle sums C = 40 here

humble grove
#

yeah

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now what

#

quick please

#

i gtg

thin bridge
#

now go through exactly what I walked you through before

humble grove
#

JUST WRITE THE FORMULA I HAVE TO GO DUDE

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WRITE THE EQUATION

#

PLEASE

#

MY BLOOD LEVELS ARE HIGH BC OFU

thin bridge
#

identify angles and sides you know and are trying to determine and plug them into the sinevrule

#

FFS this rudeness

humble grove
#

can you just

#

please

#

please

#

write out an equation

thin bridge
#

I'm out and blocking you niw

humble grove
#

ive been patient for 30 mins

#

alr

#

bye

ionic brook
#

what happened here lol

safe radishBOT
#

@humble grove Has your question been resolved?

safe radishBOT
#
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hollow torrent
safe radishBOT
hollow torrent
#

no no im not opening omg

#

.close

safe radishBOT
#
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hollow torrent
#

bless this person

safe radishBOT
#
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toxic viper
#

I know how to factorize, but i just dont know how they get to this step.

lost maple
#

that’s a difference of percent squares

spice grove
#

Difference of squares, yeah.

plucky elk
#

(a-b)(a+b) =a^2-b^2

toxic viper
#

.close

safe radishBOT
#
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humble mesa
#

can someone explain what happened?

safe radishBOT
humble mesa
#

the rewrite using trig identities part

quasi bison
#

sin^2(θ) = 1 - cos^2(θ)

humble mesa
#

omg i’m so dumb

#

ty

safe radishBOT
#

@humble mesa Has your question been resolved?

turbid canyon
#

I don't know how it solve at all

safe radishBOT
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tall hatch
safe radishBOT
trim trench
#

maybe close this @tall hatch
thought I agree it is quite rude

tall hatch
#

yea

#

.close

safe radishBOT
#
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sacred stream
#

Hi… may i know where i went wrong??? The correct answer is 2

fierce ore
#

For starters

#

On line 2

#

You didn't distribute the 4 properly

#

Wait no I'm dumb nvm that

tired imp
#

RHS is wrong

#

you just threw away the log without properly handling both sides

sacred stream
#

Wait

tired imp
#

not that

sacred stream
#

I mean RHS to lhs

tired imp
#

till here you're right

sacred stream
#

Mhm

tired imp
sacred stream
#

Oh 🤦‍♂️

#

Thanks for pointing out

#

. Close

#

.close

safe radishBOT
#
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odd thistle
#

how did it become 1/202.52

safe radishBOT
glass sonnet
#

divide top and bottom by 24.69

delicate sierra
#

,w 24.69/5000.13

#

oops wrong order

#

,w 5000.13/24.69

flat frigateBOT
delicate sierra
#

yea

odd thistle
#

oh my

#

thank you!

#

.close

safe radishBOT
#
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raw wagon
#

Small question for what do u use this its about statistic

raw wagon
#

?

quasi bison
#

nothing can be said about this without context, but
by the looks of it, all that is being shown here is that the sum of the deviations of a dataset from its own mean is zero

#

if you're specifically looking for a "use" for this, you could try and use it to check if you calculated the mean correctly (if the deviations don't add up to zero you didn't)

safe radishBOT
#

@raw wagon Has your question been resolved?

safe radishBOT
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sweet bone
#

For what values of p and q, the function f(x)= 3x^3 + 2x^2 - px + q, the factor of which is x-1, the function of f(-1) = 10?

sweet bone
#

My answer was p=-8 and q=3.

#

But i'm not sure if it is correct.

lean otter
#

-1 + p = 10 - q

glass sonnet
#

use the factor theorem

#

so f(1) = 0

lean otter
glass sonnet
#

f(-1) = 10

sweet bone
glass sonnet
#

it makes sense

lean otter
#

@sweet bone for every factor

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Of a function

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The function has a root there

#

Bla bla

#

So f(1) = 0

sweet bone
#

-1*

glass sonnet
#

@sweet bone I get 8 and 3

#

not -8 for p

sweet bone
#

I did also 8, but not even teachers understood

#

i went to MATURA exam yesterday and we had this question

#

but, if u just replace p and q, the result won't be 10, if f(-1)

glass sonnet
#

$f(x) = 3x^3 + 2x^2 -px + q$

flat frigateBOT
#

IntelligentCake

glass sonnet
#

yes it is

#

I got 10 if I did f(-1)

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p = 8

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q = 3

sweet bone
#

okay just wait a minute

#

i need to write full context of the question

glass sonnet
#

We have full context

glass sonnet
#

f(1) = 0

#

f(-1) = 10

#

you form simultaneous equations

sweet bone
#

May u tell me how did u solve?

#

If u have time

glass sonnet
#

ok

#

you have a factor of x-1

#

use factor theorem

#

what does a factor of x-1 mean

sweet bone
#

common thing?

#

of these functions

glass sonnet
#

you have one function

sweet bone
#

yea

#

this factor will link factors and zero of the polynom

#

right?

#

just like u did

glass sonnet
#

yes so if you plug in f(1) you get 0 right?

#

seeing as its a factor

sweet bone
#

yea

#

if i do f(-1) i get 10

glass sonnet
#

yeah

#

so do both of those you get 2 equations with p and q

#

then just solve

#

simultaneously

sweet bone
#

@glass sonnet what if we got the function as: f(x)= -3x^3 + 2x^2 + px + q

glass sonnet
#

what?

#

that is your function

sweet bone
#

i changed the - to +

#

f(x)= 3x^3 + 2x^2 + px + q

#

this is the function that i got, i forgot that it was with plus

glass sonnet
#

ok so just carry out same procedure?

sweet bone
#

lol

#

f(x)= 3x^3 + 2x^2 + px + q

#

I just want to know the answer cause it will happen that they review wrongly and i need to make a request about it

#

@glass sonnet

glass sonnet
#

I won't tell you the answer

#

I'm here to help

#

not give answers

#

do f(1)

#

and f(-1)

#

then sovle

sweet bone
#

okay

safe radishBOT
#

@sweet bone Has your question been resolved?

sweet bone
#

i got

#

-8 and 3

#

that would be correct i guess

#

isnt it

#

thank you

#

very much

#

.close

safe radishBOT
#
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haughty pollen
#

the sum of all values ​​of the real parameter for which one root of the equation is twice as large as the other

lean otter
#

hint: a quadratic with roots $b$ and $2b$ would look like $2(x-b)(x-2b)=0$

flat frigateBOT
haughty pollen
#

x1= 2b and x2 = -b?

#

maybe

lean otter
# flat frigate **Toby**

if you this expand out, you can equate coefficients with the original quadratic and solve two equations in two unknowns

robust kite
haughty pollen
#

thank you guys

#

.close

safe radishBOT
#
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safe radishBOT
obtuse jackal
#

Reflecting about the x-axis means multiplying by -1. Visualize it graphically

glass sonnet
#

a reflection in the x axis makes the y values negative

#

you have what y =

#

you just make that negative

safe radishBOT
#
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safe radishBOT
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zinc flint
#

the jacobian here should be -1/2?

safe radishBOT
#

@zinc flint Has your question been resolved?

zinc flint
#

<@&286206848099549185>

zinc flint
#

?

safe radishBOT
#

@zinc flint Has your question been resolved?

safe radishBOT
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tribal grail
#

there are 2 points, s and t, both of them are real numbers that differ by 1. the graph of the function fa for a=0.5 has two points: (s|f0.5(s)) and (t|f0.5(t)), they both have the same slope.

find s and t (rounded) and give the slope of the two points for f0.5

tribal grail
#

Help xd

glass sonnet
#

do you mean f(0.5s)

tribal grail
glass sonnet
#

ok so |s-t| = 1

#

f'(0.5s) = f'(0.5t) ?

tribal grail
#

Yws

glass sonnet
#

do you have f(x)?

tribal grail
#

nope

#

nvm there s one

#

if a is 0.5 the equation is

#

x* sqrt of e to the power of x

#

+1

safe radishBOT
#

@tribal grail Has your question been resolved?

tribal grail
#

got it

#

.close

safe radishBOT
#
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safe radishBOT
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south linden
#

i keep getting the wrong answer, can someone explain how to do this, i think i am approaching it wrong

lean otter
#

Do you have a cartesian equation of the plane?

safe radishBOT
#

@south linden Has your question been resolved?

south linden
plucky elk
#

.close

safe radishBOT
#
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spice jacinth
#

Hi guys

safe radishBOT
spice jacinth
#

Can someone help me with this exercise

#

Please

final halo
spice jacinth
#

The problem is the one from above

#

Is an inequality btw

#

I need to find the intervals

wise shell
#

You can do this mathematically by finding when the graph is = 0. and then testing for values that are lower and higher than those two values.

#

Since, x= -1, 2 make the equation equal to zero, you can plug in -2 into the equation and see what the sign is. Also, plug in 0 as 0 is inbetween -1,2 and then try 3.

spice jacinth
#

How?

#

I need to do it in an algebraic way

wise shell
#

You know that the equation is 0 when x is either -1 or 2.

#

So, if you plug in any number less than -1 into the equation what do you get?

spice jacinth
#

Yeah

wise shell
#

Choose any number less than -1 and input that as x. Let me know what you get

spice jacinth
#

Okok

#

A positive number

#

X>0

wise shell
#

Okay, so that means from (-infinity, -1) The function is positive, AKA >0

#

Now plug any value between -1 and 2 and tell me what you get.

spice jacinth
#

A negative number

#

Again

wise shell
#

So from (-1,2) the function is negative, AKA less than 0

#

You can now plug in a number greater than 2, but it's a positive number.

#

Your interval where the function is less than 0 is (-1, 2). You know this because this is the only values of x where the function takes a negative value.

spice jacinth
#

Ohh, so

#

If I have two x in a parenthesis

wise shell
#

You can always use desmos.com to graph functions and just look at the values it crosses below 0.

spice jacinth
#

With numbers

#

For example

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(x-1)(x+1)>0

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One of those numbers in the equation will be the answer

#

Right

#

?

#

Or am i wrong hahaha

#

I have a test tomorrow and they don't let us use a calculator or the phone 🤕

wise shell
#

What you need to do is set each parenthesis =0.

#

so, x-1=0 and x+1=0

#

These values shows you where the function is exactly 0.

#

Now every value before, after, or in-between is either positive or negative. So, you take your two points and select any value below and see what the value is, positive or negative. If it is positive then it is >0. If negative <0.

#

So if your two numbers let's say are -100 and 100. Your three intervals to test are (-infinity, -100), (-100, 100), and (100, +infinity).

#

You choose any value for each interval as long as it is in the interval you are testing and input it into the function to see if it is positive or negative.

spice jacinth
#

Ohh understood

wise shell
#

If you have something like (x+1)(x+1) then you only test two intervals because both parenthesis yields -1 as the critical point.

#

AKA the parenthesis are the same thing.

#

Other than that, you can do this method for any amount of parenthesis. (x+5)(x-3)(x+999)(x+123)

#

You just end up with more intervals.

spice jacinth
#

I understand

#

So I just have to put those two numbers and see if that results on a negative or positive answer

wise shell
#

What two numbers?

spice jacinth
#

Of my (x+a)(x-b)

wise shell
#

You set x+a=0

#

This gives you the point on the x-axis that crosses 0

#

so those two numbers when plugged in will make the function = 0.

#

You have to choose one number that is lower than both, in-between both, and higher than both.

#

The values of those three "test" numbers tells you if the function is greater than or less than 0.

spice jacinth
#

Wow

#

Thank you so much!!!!

#

.close

safe radishBOT
#
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ripe zephyr
#

how do i take the factorial of a binomial

safe radishBOT
ripe zephyr
#

like (3n+1)!

buoyant shadow
#

what's a binomial

ripe zephyr
#

sum of two terms?

buoyant shadow
#

got it

#

yeah

ripe zephyr
#

hold on are you helping or just asking

buoyant shadow
#

just asking

#

to take a factorial of the sum you probably need to know which one is larger 🤔 ?

ripe zephyr
#

wdym

buoyant shadow
#

nothing, it's like entertainment until someone who can help sees this

wise shell
#

I would imagine it would be like (3n+1)! = (3n+1) * 3n * 3n -1 * 3n -2 * ... * 2 *1

ripe zephyr
#

have no idea

wise shell
#

That should be right.

ripe zephyr
#

can you explain

wise shell
#

Do you know what a factorial is?

#

firstly

ripe zephyr
#

yea

wise shell
#

Okay so (x)! = x* x-1 * x-2 * . . . * 2 * 1.

ripe zephyr
#

what do you mean by 21

#

*2 *1

#
  • 2 * 1
wise shell
#

a factorial is taking a number and multiplying one less than the previous number until you get to 1

worthy hemlock
wise shell
#

5! = 5 * 4 * 3 * 2 * 1

#

so you keep subtracting 1 until you get to *1.

#

Now let x = 3n +1

#

plug in and you get (3n+1) * (3n+1) -1 * (3n+1) -2 * . . .

worthy hemlock
#

Fyi, n! = n * (n - 1)!

#

That's the general rule for factorials

ripe zephyr
#

ok but how do i get to 1 in a binomial

worthy hemlock
#

It automatically goes to 1, because that's the base case

#

All factorials will end at one, usually

ripe zephyr
#

wdym automatically

#

like i get that it ends at 1

wise shell
#

Are you asking how do you get down to multiplying by 1 or how do you get rid of the 1 in the (3n+1)?

ripe zephyr
#

but how do i get there

#

how do i open (3n+1)!

worthy hemlock
#

5! = 5 * 4 * 3 * 2 * 1
6! = 6 * 5 * 4 * 3 * 2 * 1, etc
The base case is 1

ripe zephyr
#

right

buoyant shadow
#

there's nothing you can do is what they mean, you can't remove the factorial

ripe zephyr
#

i have to express it as a polynomial

worthy hemlock
wise shell
#

Look, (3n+1) ! = (3n+1) * 3n * 3n-1 * 3n-2 * 3n-3 * 3n-4* . . .

#

3n is only so big.

ripe zephyr
#

so what do i do?

wise shell
#

You should phrase your entire question again.

ripe zephyr
#

i have to express 3n+1 over 3n-2 as a polynomial

wise shell
#

(3n+1)! / (3n-2)!

#

?

buoyant shadow
#

you can like, point at the . . . and say this is 3n

worthy hemlock
ripe zephyr
#

hold on

worthy hemlock
#

Because asking how to expand (3n+1)! doesn't give much context

wise shell
ripe zephyr
#

nono

#

my bad

#

1 sec

#

so itd be (3n+1)!/(3n-2)! x (-1)! right?

plucky elk
#

catThink actually that's not even equal to any polynomial

#

,w (3n+1) choose (3n-2)

flat frigateBOT
plucky elk
#

Oh nevermind I'm dumb

ripe zephyr
#

im so lost

plucky elk
#

It cancels nicely

#

Do you know the definition of binomial coefficient?

ripe zephyr
#

yes

plucky elk
#

Write it down and simplify

ripe zephyr
#

i dont understand the (3n+1)!part

plucky elk
plucky elk
#

You need to understand factorials to understand binomial coefficients

ripe zephyr
#

its the thing you multiply values by to find a polynomial

#

right

#

?

plucky elk
#

Also that's incredibly vague

#

Look in a textbook for the definition

#

Or your notes

unique bison
#

do you understand what this means?

ripe zephyr
#

3n+1 C 3n-2?

unique bison
#

yes

#

what does that mean?

#

any other interpretations you know of?

ripe zephyr
#

how many ways 3n-2 can be chosen out of 3n +1?

unique bison
#

yes

#

what's $\binom{5}{2}$?

flat frigateBOT
#

giannis_money

ripe zephyr
#

5 c 2

unique bison
#

what number is this equal to?

ripe zephyr
#

10

unique bison
#

ie. in how many ways can you choose 3 things from 5 things?

#

yes

#

how did you get that?

ripe zephyr
#

i memorized the pascalls triangle till r6

unique bison
#

how would you find a value you haven't memorised?

ripe zephyr
#

i dont know much of the theory

#

well usually i have the calc

unique bison
#

$\binom{n}{k} = \frac{n!}{(n-k)!k!}$

flat frigateBOT
#

giannis_money

ripe zephyr
#

bruh i forgot

#

ok

#

so in the case n is a binomial

unique bison
#

no

plucky elk
ripe zephyr
#

wdym

plucky elk
ripe zephyr
#

.close

safe radishBOT
#
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plucky elk
#

Guess they figured out the definition of binomial coefficient

safe radishBOT
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fierce cosmos
#

,tex $\frac{r+5}{r^{2}-2r}$ - 1 = $\frac{1}{r^{2}-2r}$

flat frigateBOT
fierce cosmos
#

i know the answer but some of the steps i’m having an unusual time figuring out

ionic brook
#

which steps are you having trouble with

fierce cosmos
#

up until this point

#

it’s out of context but

#

then the signs become the opposite of before after the last step

ionic brook
#

not sure what they mean by "change the sign"

#

but all they did was rearrange the terms

#

i.e. they moved -r^2 to the front

fierce cosmos
ionic brook
#

for that part

#

they multiplied both sides by -1

fierce cosmos
#

why

spice grove
#

Always simpler to work with a postive leading term.

ionic brook
#

its not necessary but

#

yea basically what @spice grove said

fierce cosmos
#

also for when the numerator was set to zero?

#

what happened

ionic brook
#

$\frac{a}{b}=0\iff a=0$

flat frigateBOT
#

lirmirit

ionic brook
#

given that $b\neq0$

flat frigateBOT
#

lirmirit

fierce cosmos
#

is what you’ve shown essentially this

ionic brook
#

yes

#

if a fraction equals zero

#

its numerator equals zero

fierce cosmos
#

so for the future when i encounter scenarios like this will i just remove the denominator

ionic brook
#

yup

#

just make sure the denominator does not equal zero though

fierce cosmos
#

okay, thanks

#

appreciate it

#

.close

safe radishBOT
#
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junior wagon
#

Might be a dumb question

safe radishBOT
junior wagon
#

Im trying to prove the second property of group homomorphism

flat frigateBOT
#

Kurama

#

Kurama

#

Kurama

unique bison
#

@junior wagon how is the 0 power of an element defined in a group?

junior wagon
#

I've only seeing this for the 0 power of an element in my notes

#

so the order of $\phi(g)$ is infinite?

flat frigateBOT
#

Kurama

unique bison
#

not necessarily

#

your book should have defined powers of an element

#

but anyways, it's defined as g^0 = e

junior wagon
unique bison
#

no

junior wagon
unique bison
#

as in they should have defined what does the notation g^n mean for any integer n

#

this is a rather trivial matter, you can just assume g^0 = e

junior wagon
#

ok

#

thanks

#

I dont think they defined it

#

only defined order of an element and order of the gorup

unique bison
junior wagon
#

I did for the positive case

#

n>0

unique bison
#

now you know it's trivially true for n=0

#

how about n<0?

junior wagon
#

One sec..

safe radishBOT
#

@junior wagon Has your question been resolved?

flat frigateBOT
#

Kurama

junior wagon
#

I think I can take the -n out?

#

like $\phi(g^{-n}) = (\phi(g))^{-n}$

flat frigateBOT
#

Kurama

unique bison
#

yes

junior wagon
#

right. then multiply both sides by that, then I think that proofs it

unique bison
#

ye

junior wagon
#

wait, but why can we take it out?

unique bison
#

n < 0

#

-n > 0

junior wagon
#

oh

#

make sense

#

thanks

unique bison
#

np

junior wagon
#

.close

safe radishBOT
#
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safe radishBOT
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real crater
safe radishBOT
#

@real crater Has your question been resolved?

real crater
#

<@&286206848099549185>

safe radishBOT
#

@real crater Has your question been resolved?

glass sonnet
#

what have you tried

real crater
#

i don't know

#

i wasn't too sure what to do

safe radishBOT
#

@real crater Has your question been resolved?

safe radishBOT
#

@real crater Has your question been resolved?

safe radishBOT
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vagrant sand
#

is geometric rv the same as bernoulli rv?

safe radishBOT
#

@vagrant sand Has your question been resolved?

limber smelt
#

bernoulli just means that it's either true or false.

#

i believe

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pine tulip
#

Hello guys, i have a question. On this equation $$\sqrt{3}sin^2x+\sqrt{3}cos^2x-2sinx=0$$

flat frigateBOT
pine tulip
#

can i do something like this? $$\sqrt{3}\left(sin^2x+cos^2x\right)-2sinx=0$$

flat frigateBOT
pine tulip
#

If i go on and finish the question i get the correct answer, but i am not sure if what i did can actually be done

compact wraith
#

Yes you can

pine tulip
#

oh thats cool, thanks

compact wraith
#

What step did you think you can;t do?

pine tulip
#

Since i was leaving "behind" -2sinx, i thought that maybe what i did wasnt actually possible

#

Well, thanks once again 🙂

#

.close

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agile raven
#

theta = (L * 2pi) / circumference.... right?

neat kiln
#

Yes

#

Or

#

You can simplify to:

#

theta = L/r

agile raven
#

yea, Im trying to do it without r

#

but thanks, then i just have some computer nonsence going on 😄

#

.close

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blazing rune
safe radishBOT
blazing rune
#

what to do in this question?

#

is finding maximum vlaue of the function given in option work?

#

i mean i will find maximum of a function and compare it with other other functions maximum .? will it work?

safe radishBOT
#

@blazing rune Has your question been resolved?

lean otter
blazing rune
#

okay

#

but is there anymore feasible option ?

#

i mean to do this fastly?

#

i thought of finding integrals too but...it takes time

#

.close

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tidal nest
safe radishBOT
dull sequoia
#

what's your question?

tidal nest
#

How to setup

#

(H(100)-h(50))/50

#

For 2a)?

dull sequoia
#

yeah that looks right

tidal nest
#

What do I do next

dull sequoia
#

part b?

tidal nest
#

No

#

A)

#

In equation

dull sequoia
#

you plug in the numbers

#

you know the function h(t)

#

and u know the t values

#

50 and 100

tidal nest
#

What does that look like again

dull sequoia
#

it's in the question

#

h(t) = 0.00185(250 - t)^2

#

you know t = 50 and t = 100

dull sequoia
tidal nest
#

One sec

#

@dull sequoia this correct?

dull sequoia
#

,w h(t) = 0.00185(250 - t)^2, solve (h(100) - h(50)) / 50

dull sequoia
#

yes

tidal nest
#

I coulda used that bot?

#

,w h(t)=0.00185(250 - t)^2, solve (h(0.001) - h(0)) / 0.001

dull sequoia
#

i guess so

tidal nest
#

@dull sequoia I messed up part b

dull sequoia
#

did you approximate something

tidal nest
#

Check part b instructions

dull sequoia
#

i mean you did rounding

tidal nest
#

Yes

dull sequoia
#

well when u round early

#

it wont work

#

you can see -0.924998 is close to -1

safe radishBOT
#

@tidal nest Has your question been resolved?

tidal nest
#

,w h(t)=0.00185(250 - t)^2, solve (h(120.001) - h(120)) / 0.001

tidal nest
#

Ok

#

,w s(t)=4t^2 - 10t +13, solve (s(4) - s(1)) / (4- 1)

#

@dull sequoia

#

Bots not working for 3a

dull sequoia
#

you wrote s(t)

tidal nest
#

Oh

dull sequoia
#

yeah but you wrote solve h(4)

tidal nest
#

Uh

#

Still not dividing by 3

#

Why’s it doing that

#

@dull sequoia

dull sequoia
#

where did you write to divide by 3

tidal nest
#

4 - 1

#

Is denominator

dull sequoia
#

use brackets properly

tidal nest
#

,w s(t)=4t^2 - 10t +13, solve (s(1.001) - s(1)) / 0.001

tidal nest
#

.close

safe radishBOT
#
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river cobalt
#

Hello in my class i saw the following equation. N is a desitity function for a normal distribution, and D is a set of data (for example body height). So now is our aim to find a normal distribution N that fits our data the best. Why is it the case if we maximise this product on the right side?

river cobalt
#

is the thought right that this leads to the situation where the global maximum of this function is over the biggest cluster of data points?

safe radishBOT
#

@river cobalt Has your question been resolved?

river cobalt
#

<@&286206848099549185>

safe radishBOT
#

@river cobalt Has your question been resolved?

safe radishBOT
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devout linden
#

hello, i dont know much about Factorization, how do i Factorize with this example
x^2 + x - 12 ? pls and ty

stray socket
#

List out positive and negative factors of -12

#

And then mix and match

whole acorn
#

x^2 + bx + c = (x + p)(x + q)
where p + q = b
p x q = c

stray socket
#

Or you can also do this: you know that $(x+a)(x+b) = x^2 + (a+b)x + ab$

So now you match terms:
$$x^2+(a+b)x+ab$$
$$x^2+x-12$$

Now you have a system of equations:
$$a+b = 1$$
$$ab = -12$$

flat frigateBOT
#

Umbraleviathan

whole acorn
#

This algebra video tutorial provides a basic introduction into factoring trinomials and factoring polynomials. It contains plenty of examples and practice problems on how to factor quadratic equations.

Here is a list of topics:

  1. Factoring The Greatest Common Factor - GCF
  2. Factoring Binomials
  3. How to Factor By Grouping Terms
  4. Factor...
▶ Play video
#

i think this video can help

devout linden
#

i found these rules, are they relevant to the question i sent? @whole acorn@stray socket

whole acorn
#

your question is ax^2 + bx + c

#

p + q = b
p x q = ac

#

for 3, a is 1 btw

devout linden
#

i dont really understand what you sent, but the answer to what i sent is (x−3)(x+4) hower i want to know how to get there @whole acorn

whole acorn
#

the text on pink is the factorized equation

#

the black is the equation before it's factorized

safe radishBOT
#

@devout linden Has your question been resolved?

devout linden
#

im guessing you said my question was the 4th one but it doesn't match the answer to my question that i sent @whole acorn?

#

(x−3)(x+4)

whole acorn
#

wdym it doesnt match

#

oh wait

devout linden
#

the text on pink is the factorized equation?

whole acorn
#

it's not equal to 0

#

nvm

devout linden
#

ok, how would you factorize x^2 + x - 12 to (x−3)(x+4)
?

whole acorn
#

ima just reverse explain this ok?

devout linden
#

yes

whole acorn
#

try expanding (x - 3)(x + 4)

devout linden
#

idk how i would do it right maybe mulitplyy everything by 3 ?

whole acorn
#

just multiply it?

#

multiply x-3 with x+4

devout linden
#

ok, x^2 + 4x - 3x - 12 ?

whole acorn
#

you can simplify that

devout linden
#

x^2 + x - 12

whole acorn
#

ok so now that we've proven that it's correct ima explain how i factorize it

#

x^2 + x - 12

#

list factors of -12

devout linden
#

idk what a common factor is

whole acorn
#

like..

#

factors of 10

#

5 x 2
10 x 1

common factor = 1, 2, 5, 10

#

just factor*

#

not common factor

devout linden
#

jaha

#

3 x 4

#

or -3 x 4

whole acorn
#

negative 12 btw

devout linden
#

-3 x 4 or 3 x -4, -1 x 12 ?

whole acorn
#

there are other numbers but ok

#

lets just continue

#

p + q = 1
p x q = -12

#

which pair of factors when sum'd is equal to 1

devout linden
#

0.5 ??

whole acorn
#

?

whole acorn
devout linden
#

or 1 x 1

#

-3+4

whole acorn
#

yes

#

-3 + 4

#

and just...

#

(x + -3)(x + 4)

#

factorized

#

easy

whole acorn
#

no need to finish it

#

just stop at polynomials

devout linden
#

wait i understand what we did to -12, but what happend to x^2 + x?

#

@whole acorn

whole acorn
#

ok so

#

x^2 + x is

#

x(x + 1)

#

wait

#

oh nvm

#

try expanding this @devout linden
(a + b)(a + c)

devout linden
#

a^2+ ac + ab + bc

whole acorn
#

yes

whole acorn
#

ac + ab will be = a

#

and bc = -12 : D

devout linden
#

we didnt find common factors?

whole acorn
#

yeah we found factors

#

my bad

#

a = x, b = p, c =q btw @devout linden

#

ok wait lets try again

#

expand
(x + p)(x + q)

devout linden
#

x^2 + xq + px + pq

whole acorn
#

yeah

whole acorn
#

so xq + px = x

#

and pq = -12

#

and it's x^2 + x - 12

#

do you understand btw

#

i dont think you do

#

im bad at explaining too

devout linden
#

maybe ill be back soon

whole acorn
#

but i wont

#

i gtg

#

soon

#

This algebra video tutorial provides a basic introduction into factoring trinomials and factoring polynomials. It contains plenty of examples and practice problems on how to factor quadratic equations.

Here is a list of topics:

  1. Factoring The Greatest Common Factor - GCF
  2. Factoring Binomials
  3. How to Factor By Grouping Terms
  4. Factor...
▶ Play video
#

it'll help

devout linden
#

ok when last question if you can when we factor -12 why did we have to know this

whole acorn
#

it doesnt have to be 1

#

but in this case it's 1

#

x^ bx + c = (x + q)(x + p)

#

in this case b = 1

#

(x + q)(x + p) = x^2 + xq + xp + pq

#

xq + xp makes x

#

cuz p + q = 1

devout linden
#

ok ty

#

i will let you go now

#

.close

safe radishBOT
#
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#
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strange quest
#

I'm relatively new to doing proofs, and I'm struggling to understand what is sufficient proof for something. For example, this is a pretty easy proof. I have two main questions about it though: First, is it asking me to prove that both a or v can be 0, or is it asking me to prove that at least one of them must be 0? Second, is it enough to say that we know that for all a in F, a*0=0 , and for all v in V, 0v=0, or do I need more than that?

strange quest
#

This is a solution online, which makes sense to me, but I don't know if I actually need this much

safe radishBOT
#

@strange quest Has your question been resolved?

safe radishBOT
#

@strange quest Has your question been resolved?

strange quest
#

Here's another example

#

This is obviously true because there would be no 0 vector unless b=0

#

but I don't really know how to put that into math instead of words

#

Like how to actually prove it

plucky elk
#

use the definition of subspace

strange quest
#

What do you mean?

#

The fact that $0 \in U$ must be true?

flat frigateBOT
#

SilverTongue

austere spade
#

I think by definition of a subspace, they mean use the governing rules, like does it have an additive identity, etc

#

By showing those are satisfied (and that they're not when b != 0), it's been proved

#

Also good book, I'm reading it at the moment

strange quest
#

a little bit tough learning some of this stuff alone without many ways to check my work lol

austere spade
#

Yeah I wasn't expecting it to have no answers, a bit annoying

strange quest
#

My question though is like

#

intuitively I can see that when isnt 0, there is no 0 vector in the subspace

#

but i dont get how to prove that

#

can I literally just plug it in and say it would be

#

(0,0,b,0)

#

and thats the proof?

#

cause theres no additive identity thats the issue

austere spade
#

Can't find an actual solution online, but yeah that's what I did, that's all you'd need to write

#

Just that if x_4 = 0, then x_3 = b

#

then show that removes the additive identity

strange quest
#

Oh cool ok

#

thanks

#

How far have you gotten in the book?

austere spade
#

Just finished chapter 1 lol, exam season is keeping me busy

#

Stopped about a month ago

strange quest
#

If you want I can add you and we can ask each other questions and work together through some parts lol

#

if not its cool

strange quest
austere spade
#

Tyty

austere spade
strange quest
#

ok great

strange quest
#

.close

safe radishBOT
#
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safe radishBOT
#
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vagrant sand
#

You bid for a coin. You're confident that the price of the coin is between 0 and 100, if your bid is greater than the price, you win and sell it to your friend at the price of 1.5 times price. what's your bid to max your profit?

vagrant sand
#

anyone wanna help me with this?

solar hazel
#

hmm I'm confused, do you buy the coin if you win? and if so, does it cost the price, or what you bid?

#

ok you must buy it otherwise you would just bid 100 always

potent roost
#

tf is that, why don't you just bid 100 always

solar hazel
#

and if it costs the premade price then there is also no decision

#

so I think you must spend whatever you bid

potent roost
#

possibly

#

1.5*actual price - 100 would be your profit

#

assuming you bid 100

light shoal
#

"if your bid is greater than the price, you win and sell it to your friend at the price of 1.5 times price"

#

is "price" referring to the same number in all three occurrences in this sentence?

#

as opposed to "bid", the amount you pay?

solar hazel
#

I think you lose the money you bid

#

as in that becomes the cost of the coin

potent roost
#

yeah I think that too

#

cuz that makes the most sense

#

you win the bid

#

and get the coin

#

with the price you bid

light shoal
#

the question is absurd then

#

the more you pay the greater your profit

solar hazel
#

the price you sell it at is 1.5 times the pretermined price though?

light shoal
#

that was what I meant by my question, does "price" refer to the unknown actual value or to the amount you pay

solar hazel
#

I think price is the same everywhere there

light shoal
#

that makes somewhat more sense, leaving aside the question of how you discover the actual value after bidding but it's unknown before bidding 😁

safe radishBOT
#

@vagrant sand Has your question been resolved?

vagrant sand
solar hazel
#

so umm if you bid $N$ (where $N>1$) is the expected profit $\left(\sum_{k=0}^{N-1}\frac{1.5k}{101}\right)-N$?

vagrant sand
#

thats the formula

solar hazel
#

did you get the same thing?

vagrant sand
#

i didnt do it

#

dont even know where to start

solar hazel
#

ok so let's say we bid 4

light shoal
#

k is the actual value of the coin?

solar hazel
#

yep, oops

flat frigateBOT
#

Spring

light shoal
#

I agree with that formula

solar hazel
# solar hazel ok so let's say we bid 4

there is a
1/101 chance the coin value is 0,
1/101 chance it's 1,
1/101 chance it's 2,
1/101 chance it's 3,
1/101 chance it's 4,
and so on
in the case the value is 0, we win 0, if it's 1 we win 1.5, if it's 2 we win 1.5*2, if it's 3 we win 1.5*3, and if it's anything else we win 0
so the expected gain from selling the coin is 0 + (1/101)*1.5 + (1/101)*3 + (1/101)*4.5 + 0 + 0 + ... + 0
and the expected profit is that - 4 since we spend 4 to bid

#

@vagrant sand does that make any sense?

#

oh also I'm assuming between 0 and 100 to mean including 0 and 100

safe radishBOT
#

@vagrant sand Has your question been resolved?

safe radishBOT
#
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peak whale
#

Can this turn into b = 64/a and if so, how does it happen?

primal kelp
#

yes

#

so you wanna make the b the variable

#

so you wanna get rid of the 8 on the bottom of b

#

so you times it by itself by 8, and whether you do that, you always have to times whatever you're timesing to the other side too

#

so it would be 8/a(8) = b

#

because of 8*8, they cancel out which only give you b on the right side

#

8*8 = 64 therefore 64/a = b

peak whale
#

Ahhh got it!

#

Thank you so much!

primal kelp
#

np

rancid wagon
peak whale
#

Thank you!

#

.close

safe radishBOT
#
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hybrid wren