help-23

[quasi bison]

is that something you think is illegal?

[forest fossil]

no no I get it now

I think I miss understood u

because I understood from you, k isn't 2

thank you soo much

appreciate your help @quasi bison Thanks

[safe radish]

@forest fossil Has your question been resolved?

[safe radish]

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[valid vale]

how to find AD when you know AB parallel to CE, BC=3, and you know the area of ABCE is equal to the area of CDE

[neat kiln]

what have you tried

[valid vale]

3x=yx y is ED and i know that to find the area of ABCE which is a parallelogram is the same as finding triangle (a*h) but that doesnt really work

x is AB

i mean AE*

[karmic ravine]

The area information gives you the relation between AE and ED. Since you already know AE, u can then figure out ED

But u have to figure out how to use that area info

Hint : try to remember how the area of parallelogram and triangle is calculated

[valid vale]

area parallelogram ah triangle ah /2

[karmic ravine]

Yeah

Now they both have the same height ?

Clearly?

[valid vale]

yea

[neat kiln]

ah = ah/2 here

since they have the same height you can cancel them

so a=a/2

the a's are different though

AE=ED/2

we know AE because AE || BC which is 3

understood @valid vale

[valid vale]

so a=6?

because 1/2a=3

[neat kiln]

a is the ED here right

it is 6

now can you do AD?

[valid vale]

3+6

[neat kiln]

yes

[valid vale]

alright thanks

.close

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[pastel hare]

Why multiply and divide by 2?

And when would I know when to do it?

[dull sequoia]

ok do you see how when u do f'(x)

sry misread thought itwas something else

look at the rule on line 2

you want it in the form of ∫ [f(x)]^n * f'(x) dx

now u can pretend there's an f'(x)

if u just multiply the inside by 2

because f(x) = 2x + 3, f'(x) = 2 (on the right)

but you cant make a 2 out of nowhere

so you divide the entire integral by 2 at the front

so you multiplied the integral by 2/2 and put the top 2 inside as f'(x)

and the 1/2 in the front to balance out that 2 u put inside

u'll know to do it if the f(x) is easy to differentiate, has no x's

cos if the inside is like x^2 - 3

then u can't make it in the form ∫ [f(x)]^n * f'(x) dx

cos the f'(x) is gonna be 2x

and u cant just magically make 2x outta nothing

For example here you have an x outside you can also do a 2/2 to get the derivative of f(x)

the point is you want to "find f'(x)" somewhere so u can use this rule

[pastel hare]

Oh ok.

.close

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[pastel hare]

.reopen

[safe radish]

✅

[pastel hare]

So would we only multiply/divide by 2 here be the derivative of 2x + 3 is 2?

[dull sequoia]

yes

if the inside said something like 4x-2

then u would multiply and divide by 4

[pastel hare]

ah thanks for clarifying.

[dull sequoia]

but i gave an example where the inside derives to 2x

but you do have an x outside

so it's like halfway there

[pastel hare]

right

thanks again

.close

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[lean otter]

Hi, I'm trying my make a histogram but I'm trying to figure out how to group this data. My values range from 4.2 to 4.8. Is this how i would write it?

[drowsy moss]

typically the intervals of a histogram are equal in length

[lean otter]

but if i was group 4.2 to 4.8 is that how i would do it

[drowsy moss]

either more/less intervals or if you want 4 intervals divide (4.8-4.2) by 4 and that's the length of each subinterval. I don't know what your data is or what the question is. So that's about all I can tell you.

[lean otter]

idk if this helps. these are just revision questions but i just wana make sure im getting them right before i move on

that was my previous answer and it was wrong my tutor stated i should group them

this is the question - (a) Arrange the data into equal classes

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[pine tulip]

6^x=-36, why is this statement true: "does not admit solutions in the real field"

[pine tulip]

but not: it has a single solution of -2

[quasi bison]

no

6^-2 is 1/36, not -36

[pine tulip]

i see, so it doesnt become x=-2

[quasi bison]

of course it doesn't.

[pine tulip]

you are right, thanks

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[knotty nexus]

Just looking at this question in general from my textbook...

I'd just like to speculate - because the cubic function is in essence, symmetrical, and the area under the function would provide the displacement.

Would it be appropriate to approximate the function as a triangle in this circumstance, rather than integrating a+bt+ct^2+dt^3 ? to find displacement? 1/2bh

It seems the question is worded in a way where it wants me to find variables a,b,c,d

[knotty nexus]

Otherwise the long-winded way would be as follows:
$$v=f(tt)=a+bt+ct^2+dt^3\\quad \frac{dv}{dt}=a=b+2ct+3dt^2\ t=0,t=15\text{s}\Rightarrow b=0$$ So on so forth

$$2ct+3dt^2=0$$

Within 15 seconds $$\int_0^{15} {ds} ...$$

[dull sequoia]

that is smart

it would work

[flat frigate]

Antoan

[knotty nexus]

Okay, I thought it was unorthadox at first, I think in theory would be able to get the same answer...

[dull sequoia]

yeah it sounds smart

[knotty nexus]

Ah yes, I literally got the same answer

[dull sequoia]

depending on the marks of the question that might be how you solve it

if it's like a 1 or 2 mark question it wouldnt be expecting integration

[knotty nexus]

Yeah I considered that, looked at the solution and seems they've gone through a pathway of trying to find variables a b c d from inspection from graph and process of elimination. Then integrated for v

Then substitution in s = s0 + v0t + 1/2at^2 🤡

Thanks for the second view

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[lean otter]

okat so i need to find the hedges area is it 834 or 816?

[lean otter]

thanks

[upbeat swan]

bro

ive seen you today

[lean otter]

yes

[upbeat swan]

same problem

lol

[lean otter]

I JUST NEED THE HEDGE

i spend too much on my work

everything is completed

[sacred wren]

just assume the hedge has a thickness of 0, and calculate the maximum hedgeness

[upbeat swan]

,rotate

[flat frigate]

Couldn't find an attached image in the last 10 messages.

Jun 3, 2022, 5:23 PM

[lean otter]

all of them r 3

[upbeat swan]

Eea5S1

[lean otter]

;rotate

[upbeat swan]

,rotate

[sacred wren]

so make a diagram, 3ft wide rectangles joined at right angles such that the doubly connected side has a total length of 100ft

[lean otter]

but some on the side have 89

so its one 100

then 89

[upbeat swan]

omg

the hedges are just 3 rectangles

[lean otter]

WDYM OMG?

yes

i know

dummy

but my friend got 816

and i got 834

[upbeat swan]

ok

[lean otter]

i need to know which is correct

[upbeat swan]

whats the area of a rectangle?

[lean otter]

l times w

[upbeat swan]

yes

so...

[lean otter]

i need to add them together

omg

this is due

in 20

just need a answer

[upbeat swan]

,w (89*3)2+973

[flat frigate]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Mike Oxbig#0599

[lean otter]

omg

no

there are two 89s mutiple by 3

then one 100 times 3

got it

[upbeat swan]

wrong

[lean otter]

WDYM WRONG?

[upbeat swan]

)

i will draw in paint

so

[lean otter]

this doesnt make any sense

seriosuly

[lean otter]

also this is 100

[upbeat swan]

so

area of abcd is 89 times 3

right?

[lean otter]

yes

,w (893)2+100*3

[flat frigate]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by goolb#8116

[upbeat swan]

same with area of efgh

right?

[lean otter]

yes

[upbeat swan]

ok

what do you need now?

area of what?

[lean otter]

the entire thing

so

is it 834

or 816

[upbeat swan]

ok

we have 2 pieces out of 3

[lean otter]

wait

no

[upbeat swan]

what do we need now

[lean otter]

you see those lines

[upbeat swan]

area of what

[lean otter]

the V

in the rectangles

arent there

[upbeat swan]

bro

tell me

area of what do we need

what is missing

whats the 3rd part

[lean otter]

no

i need to find the area OF THE ENTIRE HEDGES

[upbeat swan]

i understand that

just tell me

pls

[lean otter]

i am telling you

you need to find the areas of

[upbeat swan]

ok

ok

[lean otter]

all the hedges

[upbeat swan]

i get that

[lean otter]

this party

[upbeat swan]

we have abcd and efgh

what more do we need?

with letter

s

[lean otter]

here

one minute

you see the highlighted part

right

[upbeat swan]

yes

bro

i get that

[lean otter]

THATS WHAT I NEED THE AREA FOR

[upbeat swan]

pls listen

ok?

[lean otter]

i am

[upbeat swan]

can u listen

[lean otter]

dummy

[upbeat swan]

good

[lean otter]

my question is

[upbeat swan]

ok

ill answer

cuz ur stubborn af

[lean otter]

is 816

or 834

omg

[upbeat swan]

area of hedges is abcd+efgh+xyhc

xyhc

[lean otter]

yes

[upbeat swan]

this is what i wanted you to tell me

we already have the first 2

we need area of xyhc

right?

[lean otter]

yes

its 300

[upbeat swan]

good

[lean otter]

the other two are 267

[upbeat swan]

no

[lean otter]

wdym

[upbeat swan]

segment dg is 100

[lean otter]

89 times 3

[upbeat swan]

we need ch

area is not 100*3

[lean otter]

so

[upbeat swan]

how big is ch

?

its not 100

see?

so

[lean otter]

okay

then how do we

get

[upbeat swan]

ill tell you how

ch

ch

is

dg

[sacred wren]

(2(86)+100)3

[upbeat swan]

CH is DG-AB-EF

ok?

[lean otter]

yea

[upbeat swan]

good

so how long?

[lean otter]

94

[upbeat swan]

yes

so what

whats the area

of xyhc

not 100*3

its...

[lean otter]

282

[upbeat swan]

,calc 94*3

[flat frigate]

Result:

282

[upbeat swan]

good

so

whats the final answer?

[lean otter]

816

SO ITS 816

[upbeat swan]

,calc (89*3)2+282

[flat frigate]

Result:

816

[upbeat swan]

yes

[lean otter]

THANK THE FUCKING STARS

[upbeat swan]

what?

oh

so you got it wrong

ur friend was right

[lean otter]

THANK THE STARS

[upbeat swan]

)

be more careful

[lean otter]

no he checked everything

that was the only thing i got wrong

so im not complaining

[upbeat swan]

you should be

you could have gotten 100

always aim for the best

dont be like the losers]

bye

[lean otter]

i know that dummy

tysm

[upbeat swan]

np

[lean otter]

.close

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[pliant grove]

Hi guys, I'm trying to solve question 3. What I tried to do is finding the formula for the area, for which I got A=300y-y^2. However, I am stuck after that.

[glacial fractal]

where did the 300y come from

[plucky elk]

dafuq is kanye building a fence for

[glacial fractal]

he need space

he got money and shit

[plucky elk]

surely your area should have 600, x, y, and 5 somewhere

[pliant grove]

600 = 2x + 2y
2x = 600 - 2y
x = 300 - y
a= x times y
a= (300-y)y
a= 300y-y^2

[glacial fractal]

why 2x

[pliant grove]

this is how i got the 300y you were talking about

[plucky elk]

why even 600 = 2x + 2y

[pliant grove]

cuz he got 600m of fencing for all the sides

[plucky elk]

there's like 6 vertical ones

and 2y accounts for the 2 horizontal ones

[glacial fractal]

ye got 6 of them xs

[pliant grove]

oh shit is the 600m of fencing considering the sticks on the xs

fack

[plucky elk]

fack is the correct answer

[upbeat swan]

haha

[plucky elk]

https://open.spotify.com/track/0fMWtRhzOoWoCo7dRHVEEa?si=b47b52839fd64647

[glacial fractal]

later bitches

duuududududuududuuuu

[polar obsidian]

Pls I don't think u understand the question

They asked for the area

[pliant grove]

yeah thats why i tried to get the area

i got a= 300y-y^2 before realising that i need 6 sticks for the first calculation to get there

[polar obsidian]

Formulae for area of rectangle which is ( length*breadth)

[pliant grove]

yeah

[polar obsidian]

600= xy
Making x subject formula

x=600/y

[upbeat swan]

no

[glacial fractal]

xy isnt 600 tho

[upbeat swan]

600 is the perimiter, not the area

[polar obsidian]

Ok

[glacial fractal]

2y+6x=600

[pliant grove]

is this idea right tho without considering the fact that there's 6 extra sticks i didnt count

wait no

cuz u cant use the sticks in the area calculation

i hate this so much

[glacial fractal]

Cool

[upbeat swan]

perimeter would be $6x+2y=600$

[glacial fractal]

2y

[upbeat swan]

yeah mb

[flat frigate]

Mike Oxbig

[polar obsidian]

What I would say is since 600 is the perimeter

Formulae for perimeter is 600= 2(x+y)
600= 2x+2y
Making x subject formula= x= 300-y

Then the area would be
X= 300-y/y

[glacial fractal]

Well you are wrong

[neat kiln]

90s kid spotted

You boomer

[pliant grove]

nah that can't be the formula for the perimeter because you didn't count all the adjacent pens in it

[pliant grove]

and also the whole thing is quadratics so the area is gonna be a quadratic

[neat kiln]

Lithium why you got a goat profile?

[pliant grove]

i like the pic

[neat kiln]

Are you actually goat of math?

[pliant grove]

nah

[glacial fractal]

You should be

[neat kiln]

Well I am a goat too

[pliant grove]

indeed

.close

[safe radish]

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[glacial fractal]

Why

[upbeat swan]

lmao

[neat kiln]

Kanye wanna fence the goats

[upbeat swan]

bro had enough

[glacial fractal]

yoi didnt solve it @dreamy wolf

We gotta build ye a fence

[safe radish]

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[glacial fractal]

I think so too

[upbeat swan]

my man just gave up mid-problem

[glacial fractal]

Yeah

@pliant grove We got a problem

[upbeat swan]

i dont think he's coming back

[glacial fractal]

me neither

[upbeat swan]

ok

bye then

[glacial fractal]

Im scared of green

[upbeat swan]

lol

[plucky elk]

the channel will auto close soon anyway

[glacial fractal]

aaah

[upbeat swan]

more green )

[glacial fractal]

fuck

[upbeat swan]

[glacial fractal]

Hmm

@safe radish good morning

[upbeat swan]

lol

imagine he responds

[glacial fractal]

The audacity of this bitch smh

not even saying it back

[upbeat swan]

wanna tag some mods now?

see if they respond

[glacial fractal]

Yes

Too bad they don't know I'm 12

[upbeat swan]

woah

[plucky elk]

worse than pinging mods for math help

[upbeat swan]

woah

[glacial fractal]

for legal reasons thats a joke

[upbeat swan]

lol

they do know math, right?

[glacial fractal]

well they should

[upbeat swan]

ive never seen one help

[glacial fractal]

Too big ego

Why would you help when you can ban

[upbeat swan]

fr

[safe radish]

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[stray ridge]

Hii

[stray ridge]

Can someone explain to me

How to read this graph to indentify when x is bigger or smaller than 1, 2 and 3?

1/x-2 < x-2

Crosses at 1 and 3

Asymptote x=2

When is 1/x-2 smaller than x-2?

What?

<@&268886789983436800> some guy came in here sending and deleting middle finger emoji’s

[quasi plume]

its dealt with

[stray ridge]

Perfect, thank you!

[safe radish]

@stray ridge Has your question been resolved?

[dreamy wolf]

What

Why have you pinged me

[safe radish]

@stray ridge Has your question been resolved?

[stray ridge]

You see this as two separate graphs right? With the x axis splitting them

So up until the x axis x=1 and x=2 is where 1/x-2 is smaller than x-2 right? And then 1/x-2 is smaller up until x-2 crosses it at x=3?

1<x>2 or x>3?

[pliant grove]

had to go to dinner lel

[cobalt parrot]

you should bre getting 1<x<3

[safe radish]

@stray ridge Has your question been resolved?

[stray ridge]

I don’t know, answer page says 1 < x < 2 or x > 3 is correct.

[cobalt parrot]

are your answer pages always correct

[stray ridge]

Well if you believe it’s incorrect please elaborate on your findings

[cobalt parrot]

1/(x-2) < x-2
1 < x^2 -4x +4
0 < x^2 - 4x + 3
0 < (x-3)(x-1)
x = 3, x = 1,
at these intervals the roots are lesser than 0

so it should be (-inf,1) U (3, inf)

[safe radish]

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[lyric hatch]

It's asking for the definite integral from 0 to 1, right?

[thin bridge]

no

consider doing a sketch

[lyric hatch]

Is this accurate?

[thin bridge]

no, that isn't what they want

they're interested in the region bounded by the tangent line, your curve and the x-axis

[lyric hatch]

This?

[thin bridge]

no

[lyric hatch]

-_-

[thin bridge]

they're only interested in this part

[lyric hatch]

Ohhh I see

So all I gotta do is the integral of the line - the integral of the parabola, right?

[thin bridge]

not quite

you gotta be careful with your integrals and bounds here

[lyric hatch]

tks

.close

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[nocturne pagoda]

lets say i have 1 in 43 million chance to hit a certain pattern and I try to hit the pattern 1000 times are my chances still exactly 1 in 43 million? and I cant decide what pattern I get so I cant avoid ones i already did

[nocturne pagoda]

just trying to settle an argue with a friend :}

[nova creek]

The chances are the exact same for your next try, yes. Although if you're asking about the odds of getting the pattern over 1000 tries, then the probability is larger

[nocturne pagoda]

larger probability means that if i compare a man who tried once to man who tried 1000 times the man is there a difference or their chance are like exactly the same

[nova creek]

Let's put it this way: if you were to place a bet either that a guy would get the pattern in one try, or that a guy would get the pattern at least once in 1000 tries, you would have a higher chance of cashing in on the guy who tries 1000 times

[thin token]

i argue that it is 1000 times more probable

[nova creek]

I think 1000 times more probable is a little high

Haven't calculated it though

[nocturne pagoda]

Ok thanks

[nova creek]

It's important to note, though, that each individual try still has the same 1 in 43 million probability

[thin token]

see

1000 times is the probability that it will show up at least once

[nocturne pagoda]

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[lime turret]

Can someone explain how they used the conditions to get those equation?

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@lime turret Has your question been resolved?

[royal kiln]

https://youtu.be/gCs4YKiHIhg

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[kind dove]

can someone help me to prove b) ?

[safe radish]

@kind dove Has your question been resolved?

[plucky elk]

Did you try using the definition of Omega

[kind dove]

yes, but I didnt come up with anything

i proved big O, but im struggling with big omega

[plucky elk]

Show your attempt

https://proofwiki.org/wiki/Definition:Big-Omega

[kind dove]

i was just wondering if i can get rid off some terms

[plucky elk]

Show what you think is the proof

[kind dove]

i dont have the proof

[plucky elk]

You can, but you have to prove it

[kind dove]

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[unreal oasis]

Hi there I needed help with this question, I managed to get up to part D but I am not sure of how to start the question

[unreal oasis]

The coordinates of the centre of the circle (A) is (4,-5)
The gradient of line AQ is 1/3
The length of the radius is square root 40

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@unreal oasis Has your question been resolved?

[unreal oasis]

<@&286206848099549185>

[soft fulcrum]

(4, -5) *

[unreal oasis]

Sorry about that

Since APBQ is a square that would mean it also has a gradient of 1/3 but how can we find a point on that line

[safe radish]

@unreal oasis Has your question been resolved?

[unreal oasis]

<@&286206848099549185>

[sacred wren]

Well, you could use some trig to find the vertical shift between AQ and PB, since they share a slope they should only differ by a constant

[unreal oasis]

Oh yh I got it now

Thanks

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[violet sundial]

for c

i get a negative number

SO IT DOESNT FIT WTHIN THE RANGE

DOMINA

[frosty grove]

you know that the tan function is a periodic function with a period of pi, which means that for every a: tan(a) = tan(a + pi)

so if lets say -0.5 is a solution, then also -0.5 + pi is a solution

[violet sundial]

OH

thank you

.CLOSE

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[candid depot]

how do you do this question? do you just do (axb)xc where x is cross product

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[meager mulch]

How do I write a linear equation for this table? I can usually do it if the x goes up by one each time, but here it goes up by two, so?

[heavy frost]

Still use the chang in y over change in x to get slope

[meager mulch]

Oh, wait-

That's what I was missing!

Thank you.

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[violet sundial]

is there a way to solve this without a calculator

[stray socket]

Yeah

[violet sundial]

how

[stray socket]

$$\sin{(u+v)}= \sin{(u)}\cos{(v)} + \sin{(v)}\cos{(u)}$$

[flat frigate]

Umbraleviathan

[stray socket]

You have that

So you can fill in known information

[violet sundial]

ye so sin (12/13) = ?

like it is not a exact value

[stray socket]

$$\sin{(u+v)}= \frac{3}{5}\cos{(v)} + \frac{12}{13}\cos{(u)}$$

[flat frigate]

Umbraleviathan

[stray socket]

Now you gotta find out what cos(v) and cos(u) is

[violet sundial]

ohhhhhhhhh

[stray socket]

It states that sin(u) = 12/13

[violet sundial]

yea ok

makes sense

[stray socket]

So sine is opposite over hypotenuse

[violet sundial]

imma try solve it

[stray socket]

So draw a right triangle

[violet sundial]

YE

cos is 5/13

[stray socket]

Yeah

You got it lol

[violet sundial]

cos of v is that

ok

then multiple

and solve

[stray socket]

Well no

Well yes

My bad lol

[violet sundial]

lol

thanks for the quick response

[stray socket]

I saw the v and thought "that's a really pointy u"

Lol np

[violet sundial]

lmao

all g

thank you

cyz

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[calm void]

$16x⁴-4x²+4x-1$

[flat frigate]

Nepal

[potent roost]

yes?

[calm void]

I have confusion

See it

[cosmic grove]

?

[calm void]

This one

[flat frigate]

Nepal

[cosmic grove]

yes all I see is a polynomial, and ?

[calm void]

Factorize it

Pls

Or tell me what should i do

@cosmic grove

[exotic phoenix]

Did you try factorizing it?

[cosmic grove]

,w 16x^4 - 4x^2 + 4x -1

[flat frigate]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Ｈｅｒｅｌｓ#1420

[worthy hemlock]

Factor it

[calm void]

Answer isn't coming

[exotic phoenix]

What is going wrong?

[worthy hemlock]

Then post your work/attempt

[calm void]

Ok

[exotic phoenix]

You need to show the numbers who is boss

[maiden jetty]

,w factor 16x^4 - 4x^2 + 4x -1

[calm void]

Once click more

[exotic phoenix]

Please post your attempt here

[flat frigate]

Results provided by WolframAlpha

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Requested by 秋水#5244

[opaque oak]

note that $-4x^2+4x+1$ is the square of some expression

[flat frigate]

Takumi

[cosmic grove]

you mean 4x^2 - 4x + 1

[calm void]

Ans didn't came what's wrong here

[cosmic grove]

16x^4 - (4x^2 - 4x +1) = 16x^4 - (2x-1)^2 = (4x^2)^2 - (2x-1)^2

[worthy hemlock]

You went from 4x - 1 to 2x^2 - 1^2, you magically made an x appear

[calm void]

i thought 4 is square of 2

[worthy hemlock]

But where does the extra x come from?

[calm void]

,w factor 16x^4 - 4x^2 + 4x -1

[calm void]

Thanks bro answer came

[worthy hemlock]

What I'm asking is, you started with 4x - 1, then wrote 2x^2 - 1^2, my question is how did it become x^2?

Where did that extra x come from?

[calm void]

I didn't get you bro

Anyway thanks for helping

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[brave scarab]

Suppose n is an even and is an odd number

by the definition of odd n = 2j+1, and definition of even n = 2k

this means that n+m = (2k) + (2j+1) = 2j +2k +1 = 2(j+k)+1

thus n is of the form of 2k and m is 2j+1 , where the sum of n and m is equals to 2(j+k)+1. we conclude that n+m is odd.

[brave scarab]

did i answer the no. 3 correctly? am i missing something?
also cut me some slack (this is my first time writing a proof)

[buoyant shadow]

it's perfectly mathed and badly phrased

i don't know how to make it better just wanted to share :)

[brave scarab]

Oooooh, thank youuuu maybe i should go to proof Chanel and request some advice how should i phrase it

[potent roost]

maybe mention $j, k \in \mathbb{Z}$

[flat frigate]

Swas.py

[brave scarab]

where tho? in first sentence or in conclusion?

ooooh i get it

thanks swas

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[potent roost]

When you define the 2 numbers

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[scarlet sage]

how do I do part d

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@scarlet sage Has your question been resolved?

[final halo]

Show that there is not a time t, where both boats have the same position

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[rancid widget]

How do I estimate the mean of a population from bucketed survey answers.

I’ve got a survey running and 5 discrete but differently sized buckets representing a continuous bounded positive variable

Big enough N.

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[vague urchin]

I suppose you could do something like Σn_i*x_i/Σn_i where n_i is the number of observations in the i-th bucket and x_i is the midpoint of the i-th bucket. Although I don't know if there's a better, more standard way to do this

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[plucky elk]

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[meager mulch]

Hi! Could someone help me out with this? :)

[glacial fractal]

Well you write an equation

[meager mulch]

Do I divide the 1.01% by 4?

[glacial fractal]

Why would you do that

[meager mulch]

"compounded quarterly"

[glacial fractal]

So your money multiplies by 1.01 each 3 months?

[meager mulch]

I believe the money goes up by 0.2525% every three months.

[glacial fractal]

oh yeah mb

[meager mulch]

so how do I express that in an equation?

That's kind of where I'm stuck..

Wait, I think I got it.

Thank you. :)

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[glacial fractal]

That was easy

All I had to do was say shit

[meager mulch]

Yep, lol.

made me rethink some stuff.

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[pallid nymph]

Find the moment as a Geometric Vector about the point A(-5, -11, 3), if a force of 450N acts in the direction of $\vec{d} = (-3, 1, -4)$ at the point B(7, -4, 1). Is the moment in or out?

[flat frigate]

ohNoiAmHere

[pallid nymph]

i got the magnitude, im pretty sure it's in since the angle between vectors is above 90

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@pallid nymph Has your question been resolved?

[pallid nymph]

<@&286206848099549185>

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@pallid nymph Has your question been resolved?

[near flint]

i dont know how in or out works but yes the angle should be above 90°

[plucky elk]

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[fervent flint]

Prove using cardinality definition that |AUB|=|A|+|B| if A and B are both disjoint and non empty finite sets

[fervent flint]

If we suppose |A|=m and |B|=n then |AUB|=m+n so we need to prove that there is a bijection from N(m+n) to AUB

Not sure what to do after this. Probably need to define a new function but idk how

[peak estuary]

well informally speaking, the bijection is just how you count the elements

how would you count the elements from AUB ?

you first count the elements from A and then after that count the elements from B

does that give you an idea on how to define the function you are looking for ?

f:{1, ..., n+m} to AUB ?

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[kind dove]

I have class of 14 boys and 14 girls. They are going to the cinema. They are going to sit in single row which has 28 seats. In how many ways can they sit if following conditions are met:
we are going from left to right in a row
THESE PEOPLE CANT SIT IN THIS ORDER
• Iveta, Nina, Filip;
• Urban, Kika, Tomas, Maja;
• Silvia, Lenka, Emil, Denis.
but
THIS IS ALLOWED
. . . , Filip, Nina, Iveta, . . . ; . . . , Silvia, Lenka, Tomas, Emil, Denis, . . .

[kind dove]

basically we cant have group like this in row, in this order

[royal kiln]

can you revise this so it is more clear who MUST sit next to whom and who CANNOT sit next to whom?

because first you say they can't and then you say it is allowed, which is it

[buoyant shadow]

these exact substrings are not allowed

permutations of them are fine and it's ok to have them as subsequences

[royal kiln]

ok, thank you

You can count the ways to seat all the attendees first
and subtract the ways to seat people in the way that isn't allowed

[kind dove]

i think we need to use PIE

principle of inclusion and exclusion

[buoyant shadow]

yeah that makes sense

[royal kiln]

I think counting the "wrong" ways involves stars-and-bars with the 17 kids who can sit in any order

[kind dove]

is it $28! - (26!+ 25! + 25! - 25! - 25! - 23! + 20!)$ ?

[flat frigate]

Michal

[buoyant shadow]

i don't know, it's magic to me

[kind dove]

same xD

[royal kiln]

https://en.wikipedia.org/wiki/Stars_and_bars_(combinatorics)

[buoyant shadow]

i don't think stars and bars are relvant

[kind dove]

yes, because order matters

i think

[royal kiln]

absolutely it is

the 3 groups of kids who would be in the forbidden order is 3!

[buoyant shadow]

no michal did the right thing, you glue them together and it becomes a smaller permutation, and you want to eliminate the double counted stuff

[royal kiln]

the number of ways you can wedge those kids between the 17 kids who can sit in any order is stars-and-bars

and the number of ways to permute the kids who can sit in any order is...I guess, 17!

as often is the case, this sounds enormous

[royal kiln]

how did you derive this?

[kind dove]

principle of inclusion and exclusion

28! all permutations

[royal kiln]

clearly

[kind dove]

26! permutations with first group

25! permutations with second group

25! permutations with third group

then minus permutation of group 2 and 3 together

etc

[buoyant shadow]

we can directly get these "amounts"
A + AB + AC + ABC
B + AB + BC + ABC
C + AC + BC + ABC

AB + ABC
AC + ABC
BC + ABC

and there's like a certain interleaving that eliminates all the right stuff

[kind dove]

last one, i add permutations of all groups

[buoyant shadow]

but i can't verify if they did it right lmao

[royal kiln]

hrm, this looks like a tidier method than I was thinking of, that's for sure

[kind dove]

hmm, i noticed that i incorrectly interpreted the problem

I have class of 14 boys and 14 girls. They are going to the cinema. They are going to sit in single row which has 28 seats. In how many ways can they sit if following conditions are met:
we are going from left to right in a row
FOLLOWING GROUPS CANT SIT NEXT TO EACH OTHER
• Iveta, Nina, Filip;
• Urban, Kika, Tomas, Maja;
• Silvia, Lenka, Emil, Denis.
but
THIS IS ALLOWED
. . . , Filip, Nina, Iveta, . . . ; . . . , Silvia, Lenka, Tomas, Emil, Denis, . . .

[royal kiln]

ok, so group composition can be permuted? and those cases would also not be allowed? I think that is assumed, right?

[buoyant shadow]

sum of this

A + AB + AC +           ABC
B + AB            + BC + ABC
C +           AC + BC + ABC
``` minus sum of this```
AB + ABC
AC + ABC
BC + ABC

plus ABC

[buoyant shadow]

what changed?

[kind dove]

its about groups, classmates can permute in a group

[buoyant shadow]

yeah, Filip, Nina, Iveta is a permutation of a forbidden group, which makes it allowed

[kind dove]

like the groups cant be directly next to each other, there must be space between

[buoyant shadow]

i think the allowed examples don't support this

[kind dove]

in allowed example is a space between groups

[royal kiln]

28! - [(28-(3-1))! + (28-(4-1))! + (28-(4-1))!] + (28-(3+4+4-1))!

this is based on the wikipedia explanation.

fuck, math got good on the internet

[buoyant shadow]

in allowed example the groups are not present in the first place

well the first one is

also note the semi colon

it means you have two separate examples

i got a different answer from you btw, i get 28! - (26! + 25! + 25! - 23! - 23! - 22! + 20!)

[royal kiln]

I didn't say that my math got good on the internet 👀

[buoyant shadow]

no i mean from michal

i'm looking into yours now

[royal kiln]

well, my answer is astronomical still and there's really no way for me to feel-out how this should go

I'm just trying to replicate the pattern

oh.

that last number should not be a factorial.

in fact all of it is dumb, lemme try this again

[kind dove]

idk

the problem is not clear for me even in my native language

[buoyant shadow]

after noticing the semicolon i'm like super certain we got it right at the beginning

[kind dove]

hmm

maybe yes

for sure its meant for PIE

[buoyant shadow]

. . . , Filip, Nina, Iveta, . . . is fine, the order is unforbidden

[kind dove]

because its the last subtask...

[buoyant shadow]

. . . , Silvia, Lenka, Tomas, Emil, Denis, . . . the order is forbidden but they are not all together so again fine

[royal kiln]

okokok

28! - [(28-(3-1))3! + (28-(4-1))4! + (28-(4-1))4!] + (28-(3+4+4-1))3!4!4!

=28! - [26*3! + 25*4! + 25*4!] + 17*3!4!4!

[kind dove]

hmm

[royal kiln]

pretty sure that's more than there are stars in the universe

3.04*10^29

so...I'm skeptical

oh...I forgot to factor in the other kids

that will fix this

28! - [(28-(3-1))3!25! + (28-(4-1))4!24! + (28-(4-1))4!24!] + (28-(3+4+4-1))3!4!4!17!

nah, nevermind

3.01724057785000942887763968 × 10^29

too big. maybe

[kind dove]

ok thank you guys, i will consult it with teacher and classmates

[buoyant shadow]

but we basically agreed?

it's just you're saying 25! is permutation of 2 groups together

and i don't know how you got it, it should be smaller than for single groups

26,25,25 and then 23,23,22

hm

[kind dove]

yes, my bad calculations

[kind dove]

this is right

[buoyant shadow]

awesome

[kind dove]

.close

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[quaint spear]

I think it's C... I'm not sure.

<@&286206848099549185>

[cedar rover]

Can you show how did you find C?

[quaint spear]

I realized I messed a step up so now I have no idea which one it is

[vast obsidian]

Can you show your work?

[quaint spear]

I just plugged random stuff from the problem into my calculator like 12 for r

[vast obsidian]

Mhhhh

[cedar rover]

Did you square r?

[quaint spear]

yeah I think so

[vast obsidian]

That's what we're looking for, isn't it?

[quaint spear]

so do I use that and plug in numbers for n that get bigger and bigger

[vast obsidian]

No, you shouldn't do that as it's not a proof

[quaint spear]

oh, what should i do instead?

i was planning on plugging in 10, then 100, then 10000, to see what limit it gets close to

[vast obsidian]

You could technically do it in a multiple choice question, but practice is useful

You could substitute n = 1/t

[quaint spear]

What does t represent

[vast obsidian]

Geometrically? I don't think it is like something you could „find“

But it makes the maths easier

[vast obsidian]

What do you get then?

[quaint spear]

I got approximately 452.39, so the first one

Your equation helped a lot

Do you mind helping with another? It's about rational equations.

[vast obsidian]

It should be right. Do you want to learn how to proof it?

Are you studying maths?

[quaint spear]

It's okay, if I was going to continue taking this course for awhile then I'd say yes, but this course is ending and I won't be taking calculus next year

Yea, precalc

[vast obsidian]

So what are you studying?

Probably doesn't matter for you...

[quaint spear]

I'm just studying functions and stuff, it's like review of everything we've learned in precalculus this year

woah what you did was too advanced LOL

[vast obsidian]

The limit ist just r^2*pi

[vast obsidian]

I don't think it is. I haven't even studied maths yet.

[quaint spear]

?????????????how do you know all this then

[vast obsidian]

Maybe I could help you

[quaint spear]

i like the way you write lim

[quaint spear]

okok ill show you

[vast obsidian]

We're learning it in school. 11th class

[quaint spear]

ohhh wait when you asked me if I'm studying math do you mean like college

I'm in 11th grade too if thats what you meant

[vast obsidian]

Well, I've just finished with school.

[vast obsidian]

OK, good to know

[quaint spear]

like finished with highschool???

did i do this right? i think i did

[vast obsidian]

Precalculus sounds like University for me as a german.

[quaint spear]

ohh your german

the only thing i can say in german is fick dich

i forgot what it means

[vast obsidian]

Don't say it ever again

It is an severe insult.

[quaint spear]

OMG really

[vast obsidian]

The english translation of it sounds less hard (it's an insult)

[quaint spear]

I just searched it up, I didn't know 😭

[vast obsidian]

OK xd

Where did you get to know it

[quaint spear]

my german friend taught me it LOL

OH and fotze

i just remembered

[vast obsidian]

I don't know what's meant with rate, but it makes sense 👍 You could also try to find x if you assume they run the same time, but idk if you're allowed to do that

[quaint spear]

It ended up being right LOL

I'll probably need help later

[vast obsidian]

Good 👍

[safe radish]

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[lean otter]

hey im doing this question who is willing to help?

[lean otter]

i mean

i need to figure out whats Y

I need to find TAS

.close

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[pallid dune]

the probability of winning in three different lotteries is
2/5, 1/100 and 1/20
what's the probability of winning in all three lotteries when you buy one ticket for each one

[safe radish]

@pallid dune Has your question been resolved?

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@pallid dune Has your question been resolved?

[pallid dune]

<@&286206848099549185>

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@pallid dune Has your question been resolved?

[pallid dune]

<@&286206848099549185>

[lethal musk]

I assume you just multiply all of them right?

because they are independent of each other

winning at one doesn't affect winning at the other

and it says all of them so multiply

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[quaint spear]

I need help on which one it is :)

[cedar rover]

E(n): dollars → euros
D(x): euros → UAE

First of all you have to convert the dollars in euros and then you have to convert the euros in UAE

Do you agree @quaint spear ?

[quaint spear]

Yes that makes sense

I dont know where to go from there though

[cedar rover]

Ok

Let's look at the notation first

What does F o G mean?

[quaint spear]

umm

function of G

[cedar rover]

Hmm

[cedar rover]

This is the same as F(G(x))

if you plug something in, you have first to calculate g(x), then to get your output of g(x) and then to plug that in f(x)

The inner part first

did you understand?

[quaint spear]

ohhh ok

i see

you have to subsitute it

[cedar rover]

Yes

[quaint spear]

I got A

is a correct

[cedar rover]

Yes

well done

but

Remember!
f o g ≠ g o f

F x G, instead, means that you have to simply multiply the two functions
and F x G = G x F

[cedar rover]

Otherwise you can literally plug g(x) in f(x)
for example:
g(x) = x² + x
f(x) = (1 / x) - 3
f(g(x)) = (1 / (x² + x) ) - 3 = f o g

[quaint spear]

ohhhhhh

ok

took me a while to

process what ur saying

but i get it

[cedar rover]

I'm sorry my english is bad lol

[quaint spear]

ur good at explaining stuff

no its not!!

ive been stuck on this and you explained it well

do you mind helping me with one more? im trying to review for an important test

[cedar rover]

Sure

[cedar rover]

Thanks bro 👍

[quaint spear]

thanks

i got 0.75 but i'm scared its wrong

[cedar rover]

How did you get that?

[quaint spear]

i forgot i was putting random stuff in my calculator and combining equations i made

or functions* ig

whats the proper way to do that problem

[cedar rover]

oh ok ahah

quick question: the tax is calculated before or after the discount, after, right?

but at the moment it does not matter

[quaint spear]

after yea

oh

[cedar rover]

This question is about function composition, so what we just saw before

How many functions do we need and what are those functions?

Do you need help?

[quaint spear]

the functions are the discount and tax and the area

?

😭

[cedar rover]

what do you mean by area?

oh, is that because the problem called the total amount "A"?

@quaint spear ?

[quaint spear]

yeah