#help-23

1 messages · Page 476 of 1

spiral crescent
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What advice☠️

final loom
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btw for the "what's wrong" part, I'd say you probably fucked up the notthis part

flat frigateBOT
final loom
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or $(x + 4)(2x + 17) > 0$

flat frigateBOT
final loom
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Ah, I see.. 👀 I wonder how you went from [ 2x² + 25x + 68 > 0 ] to [2x² - 8x - 17x + 68 > 0 ] 👀

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what's with the sudden sign change?

spiral crescent
spiral crescent
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Oh f

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Bruhhh

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Lol

final loom
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👀

spiral crescent
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I was trying to speedrun a lot of these

final loom
# spiral crescent What advice☠️

oh that's ... from the start, the question says: $$2(x + 4) > \sqrt{(x + 4)(2x - 1)}$$ but you clearly know that $\sqrt{\text{anything}} > 0$ so you're given that $x + 4 > 0$ so, $2x - 1 > 0$ should also be true

flat frigateBOT
final loom
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and so, $x > 0.5$ must be true

flat frigateBOT
final loom
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with exceptions of x = -4 / 0.5

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and so, you can avoid the notthis part

spiral crescent
spiral crescent
final loom
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👀 trivial solutions to the inequality if the inequality sign was ≥

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but the question only asks for >, so the solution set will be concurrent only with x > 0.5

spiral crescent
final loom
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oiiii

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trivial means easy

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simple

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convenient

spiral crescent
final loom
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nope,

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I'm saying

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The question is

spiral crescent
final loom
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$2(x + 4) > \sqrt{(x+4)(2x-1)}$ and not $$2(x + 4) \geq \sqrt{(x+4)(2x-1)}$$

flat frigateBOT
final loom
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so, the solution set won't contain $x = {-4, \frac{1}{2}}$

spiral crescent
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Yes

flat frigateBOT
spiral crescent
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Yes

final loom
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can you do the question again now?

spiral crescent
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Why would i do the question again what

final loom
final loom
spiral crescent
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Not completely from fresh

final loom
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oh great !! good luck !!

spiral crescent
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Why 2 mistakes👿

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Wont those not come in the solution with the intersection eventually?

final loom
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one was the sign change from plus to minus, and the other was including {-4} and {1/2} in the solution

spiral crescent
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Wait let me do it

spiral crescent
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According to the solution answers for the excercise at least

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Yes whats wrong with 1/2 if we put it we have
2(1/2+4)> 0

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👿

final loom
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ahem

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yes ... sir (@_@;) 1/2 is okay

spiral crescent
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Thanks i didnt have to do a through checking of these

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Also finished 3 days of hw in one day

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Thanks

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.close

safe radishBOT
#
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final loom
safe radishBOT
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iron lintel
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what could be another formula to write on these figures?

i have:

iron lintel
woeful plume
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That's it! That's the formula for the triangular numbers

iron lintel
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ahh but for my practice task it says i have to find another way too :(

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i was thinking if it was possible to simplify or change it so it would still work

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n^2

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or something

woeful plume
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Another way to get the formula, or another formula in itself?

iron lintel
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another formula i guess that would work for the triangular numbers figures

wintry musk
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well

woeful plume
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I guess you could write it as a sum...? But that's the same thing as the above equation

wintry musk
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i can see 1 way if u want to use like $a_{n +1} = a_{n} + \text{something}$

flat frigateBOT
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madlor

iron lintel
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ahh yes that could work :D

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ty bros

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.close

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stoic dust
safe radishBOT
stoic dust
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is the circled section a right angled triangle

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and if so

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how do we know?

quasi bison
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inscribed angle theorem

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an angle inscribed in a circle equals half the arc upon which it rests

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and here your angle rests on an arc that is half the circle

safe radishBOT
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@stoic dust Has your question been resolved?

stoic dust
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could u show visually?

lean otter
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degrees

stoic dust
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yes ik thats what im trying to understand tho

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how to tell whether it is 90 deg or not

lean otter
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idk how to word it but like

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ok wait

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so we learnt

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angle formed at center is 2x the angle at circumference

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so u see the angle formed at the center is 180

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thus 90 at the circumference

stoic dust
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@quasi bison so is it 90 degrees?

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abstract kayak
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so for the first question, am i meant to sub in 1000cm^3 and 8 into the equation V= LWH?

abstract kayak
safe radishBOT
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@abstract kayak Has your question been resolved?

abstract kayak
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<@&286206848099549185>

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safe radishBOT
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@lean otter Has your question been resolved?

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raw tusk
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Jack is going to cut an A4 paper so that it becomes a rectangular prism. He want's the rectangular prism to have the biggest surface area as possible. What will the lenghts of that rectangular prism?

raw tusk
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Btw, we want to lengths to be integers and not fractions

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This is a difficult approach to me, since there are endless way you could find lengths to an A4 paper, which has the lengths of 210 x 297 mm, aka 62 370 mm^2

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What I know is that you should factor out 62370 into 3 factors, but this is again a pain to do, considerin the amount of possible factors you have

safe radishBOT
#

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valid crow
#

having evaluated the following limit using the epsilon delta definition: $lim_{x \to 0} x^2=0$ is this evaluation correct? I'm afraid I missed up something in the absolute values.
I started with: $|x^2| \le \epsilon \implies x^2\le \epsilon \implies x \le \sqrt{\epsilon}$ choose $\delta(\epsilon)=\sqrt{\epsilon} \ |x| \le \sqrt{\epsilon} \implies -\sqrt{\epsilon} \le x \le \sqrt{\epsilon} \implies \epsilon \le x^2 \le \epsilon$ but here I got $x^2=\epsilon$ not $|x^2| \le \epsilon$ Any ideas?

flat frigateBOT
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planeboi

shy temple
safe radishBOT
#

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fleet chasm
#

I have
D1:(x,y) = (-1,3) + t(2,1)
D2:(x,y)= (1,a) +k(1,b)

I need to find the a,b values so D2 so it is the same as D1 and also, the intersection point and of the x axis

fleet chasm
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I have found that d(D1,O) = 7/sqrt(5)

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so D1 is also: x-2y+7=0 in cartesian form

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but I am lost for the rest

sharp island
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What do you mean that D1 is the same as D2?

fleet chasm
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the answer is a=4 and b=1/2 so I think it is asking for the a,b values where both equations are equal

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sorry it is french so I am trying to translate it at the same time

sharp island
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That's alright

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Yeah, that seems reasonable, so would you like an explanation of how they got that?

fleet chasm
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yes that I am lost when they asked the a,b value then to find the intersection point

sharp island
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Oke, so to get the values of a and b, what I would get first is the position vector (1,a). So we know that this must give a point on D1, therefore we should find what value of t gives the point with an x coordinate of 1. So -1 +2t = 1, this gives t=1

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Now we can find the value of a by calculating the y coordinate of this point again from D1, 3+ 1×1 =4, therefore the y coordinate is 4 of the point with x coordinate 1

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Now we have the position vector of D2, we just need to get a vector in the same direction as D1, for this we need a vector which is some scaled version of (2,1) which has an x coordinate of 1, this must mean (2,1) has been scaled down by a half, so b must be 1/2

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Is that alright?

fleet chasm
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I don't get how you got the 3 + 1x1 =4

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wait is it from 3+t=0?

sharp island
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So the second row of D1, the row corresponding to y coordinate is

fleet chasm
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y=3+t?

sharp island
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Yes

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And we found that t is 1 so y is 4

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The 1×1 is just the value of t times the 1 in the vector

fleet chasm
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ok I understand now

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and the intersection point would be to do D1 = D2 and isolate?

sharp island
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Well if they are the same line, then they share every single point so this confuses me a bit

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Does it mean where they intersect with the x or y axis?

fleet chasm
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I think I translated it poorly

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Let me rephrase

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Find a point of intersection of the D1 and the x axis

sharp island
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So if it intersects the x axis, what will the y coordinate be?

fleet chasm
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should be (-7,0) the answer

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That's all I have

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a,b and d(D,O(0,0)) = 7/sqrt(5)

sharp island
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Not quite sure why you are finding a distance here. Basically the point of intersection with the x axis must have a y coordinate of 0, therefore, we can find the value of t for which this occurs (we can use D1 or D2, they are the same), and then use that value of t to get the x coordinate

fleet chasm
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so in the example of D1, I would say D1: x-2y=-7 and replace y by 0?

sharp island
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Oh, have you converted it to just a normal straight line equation without the parameter t? That works too, and you can get the value of x directly by doing that

fleet chasm
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Well I didn't understand with the t unfortunetly so I thought of this way

sharp island
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That's no problem, you are actually doing the exact same thing, but the y=0 gets substituted at a later point in your method

fleet chasm
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alright thank you so much 🙂

sharp island
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No problem at all!

fleet chasm
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.close

safe radishBOT
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pastel abyss
#

.close

safe radishBOT
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spiral crescent
safe radishBOT
spiral crescent
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are the answers- no, yes, no?

merry sleet
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how would you justify your answers?

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theyre right btw

spiral crescent
merry sleet
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yes

spiral crescent
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for the second i just cudnt find any contradictions💀

merry sleet
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just a tip for counter examples just take a concrete example

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in this case

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1-2 =-1

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which is not a natural number

spiral crescent
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for the third, i just wrote 9/12 is not natural number

merry sleet
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first what is the definition of a natural number?

spiral crescent
merry sleet
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in what grade are you?

spiral crescent
merry sleet
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ok

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yeah i would have expected a better definition att this level tbh

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i guess then you dont have to justify that much and just state your answers

spiral crescent
merry sleet
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oh yeah ok

spiral crescent
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even this chapter that ive started today is only in one of the entrance exams here, not in most

merry sleet
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just say no yes no then

spiral crescent
merry sleet
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well how you usually define a natural number is this way:

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you state that 0 is a natural number

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and then yopu have an operation called "successor"

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and for each natural number

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the successor of this number exists and is a natural number

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so

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natural numbers are:

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0

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S(0) (successor of 0)

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S(S(0))

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S(S(S(0)))

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but for simplicity's sake

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we call them

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0

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1

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2
3

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.....

spiral crescent
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where does the part come where u say 0 is not a natural number

merry sleet
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it is a natural number tho in most definitions

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but you could do the same and start at 1

spiral crescent
spiral crescent
spiral crescent
merry sleet
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so a natural number is essentially something that can be expressed as the successor of 0 enough times

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for c, your proof is good you gave a counter example

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so if you have the product of a and b to natural numbers

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a*b = a+a+ ...... +a (b times)

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and adding a is doing the successor operation a times

spiral crescent
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b times?

merry sleet
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2*3 = 2 + 2 + 2

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we add 2 to itself 3 times

spiral crescent
merry sleet
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yeah

spiral crescent
merry sleet
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oh

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hgere i'm talking about

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a+a

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or c+a

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to do c+a

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you take c

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and do the successor operation a times

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so c+a is still something of the form S(S(S(......S(0).....)))

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so a*b can be expressed as an addition

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and any addition of two natural numbers is of the form S(S(S(......S(0).....)))

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so a*b is of the form S(S(S(......S(0).....)))

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so its also a natural number

spiral crescent
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just the a part i mean

merry sleet
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a is a natural number

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so you can write it using digits

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or you can use the successor operation

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to describe it

spiral crescent
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so if 1 is a natural number, and if 0 is ur starting value for natural numbers, isnt 1 the successor operator 1 time?

merry sleet
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yeah

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1 = S(0)

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2=S(1)

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2=S(S(0)) by substitution

spiral crescent
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but if 1 was the starting value wudnt it be the successor operator 0 times?

merry sleet
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yeah

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but if we start at 1

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we would have stated that 1 is a natural number

merry sleet
spiral crescent
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but wudnt we need to state

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0 is the first natural number?

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or 1 is the first natural number

merry sleet
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its already stated in a way

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0 is the only one that is the successor of no natural number

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that means its the first

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in a certain way

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you can compare natural numbers using successors

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like a>b

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if a= S(S(....(S(b))....))

spiral crescent
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natural number*

merry sleet
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the limit is that we dont define negative numbers this way

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you can notice that i only defined natural numbers

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and not other numbers

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to get whole numbers its another construction that stems from this one

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to state it simply: any set of numbers that follows the rules i stated

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is "like" the natural numbers

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but you can add other definitions

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to add other numbers

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here i just did the basics

spiral crescent
merry sleet
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to make the proof about

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multiplication

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if you want to dig deeper

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what i talkied bout is called peano arithmetic

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or peano axioms

spiral crescent
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i have another question btw

merry sleet
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go ahead

spiral crescent
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here its said power has to be greater than equal to two, but is it talking only abt integer values, or can it also be fractions greater than two like 4^5/2 as long as we have an integer as the final value?

merry sleet
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well for some advanced reasons if n is a natural number, and a is not

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n^a is not a natural number

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unless n i s0

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or 1

spiral crescent
merry sleet
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well i would have to explain to you what is the definition of a power of a real number

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like do you know what 2^3.7 means?

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or 2^pi

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?

spiral crescent
merry sleet
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its true

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buteven with the fraction

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what does that mean

spiral crescent
merry sleet
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what is the definition of this

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for example 2^3 = 2x2x2

spiral crescent
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yes

merry sleet
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but you cant do this definition with non natural numbers

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you cant multiply 2 by itself 3.7 times or pi times

spiral crescent
merry sleet
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without exceptions

spiral crescent
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ok can you explain why the example 4^(5/2) wont be a natural number

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is it something to do with a given statement?

merry sleet
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ok

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so do you know what the exponential is?

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function

spiral crescent
merry sleet
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i'm sorry its too deep then,

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i dont want to do a lecture on this

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Exponentiation is a mathematical operation, written as bn, involving two numbers, the base b and the exponent or power n, and pronounced as "b raised to the power of n". When n is a positive integer, exponentiation corresponds to repeated multiplication of the base: that is, bn is the product of multiplying n bases:
The exponent is usually shown...

spiral crescent
merry sleet
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yeah

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like anyways

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only natural number powers make sense

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at the level of your class

spiral crescent
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alright thanks, ill look into those two things when im free

spiral crescent
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but that is something any high school student has

merry sleet
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oh ok

spiral crescent
#

.close

safe radishBOT
#
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orchid rapids
#

@lean otter come here

safe radishBOT
tall bough
fading raft
#

oh this should be interesting

orchid rapids
fading raft
#

some jee advanced topper stuff

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eh whats this

tall bough
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ever heard of helmholtz decomposition?

orchid rapids
#

ok so, here, u want to find the area of the triangle and multiply it with the length of the pyramid

orchid rapids
tall bough
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yes volume

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next time u post a question say whats it about lol

orchid rapids
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do u know how to calculate the area of a triangle

tall bough
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ys

undone umbra
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Cool question

orchid rapids
#

?

tall bough
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nice triangle

orchid rapids
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im not sure how this helps

tall bough
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you solved it?

fading raft
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bro this is cheat

tall bough
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whats the answer

lean otter
tall bough
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you sur

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you sure

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it was 2?

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how can the volume be lower than the base, height and length

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whats the formula of the area of a traignle

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gogole it

undone umbra
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I like to think of it like this, we got the height of the triangle, we got the base of it, so we got the face of the front of triangle
But we want to find the volume so like in the 3D image we drag the face of the triangle along which is the (10 x 9) then multiply by how long it is (10 x 9) x 8.
And the volume would be the answer

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Oh we’re long past that stage

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Y not?

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It’s really simple when you understand it

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That’s fair

tall bough
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ur going to have an exam about it right?

lean otter
undone umbra
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No?

lean otter
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Yes ok right I was wrong

undone umbra
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I swear that was a thing

tall bough
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Still we dont give answer away

undone umbra
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If you get the concept it’s easier to remember

lean otter
#

Grades won't give you anything
Math will give you a lot

undone umbra
#

Year 8?

tall bough
#

When asking for help, do not insist on getting just the answer; we are here to help you learn, not do the work for you. Likewise, if you are providing help to others, try your best to explain and elaborate instead of simply giving away the answer.

lean otter
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You're in 8th you definitely need Math

undone umbra
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What’s 8th?

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Even construction workers use math

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Math is basically a requirement for everything

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Bro it’s volume

tall bough
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architecture? engineering?

undone umbra
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I feel like engineering would use volume a lot

tall bough
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tbh if u just spend 10 minutes studying that topic, u will be easily be able to do it

fading raft
#

this is important math you need to learn before your jee exams bro

lean otter
#

You will use it
It's just that you don't see common people using it outside of their profession beacause they simply never understood it and rote learned it

undone umbra
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😶

tall bough
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@lean otter Do you want to get help or you just want the answer?

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Then sorry, we can't.

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No, you may close the channel if you don't want help.

undone umbra
#

You learn from the process not from the results

#

Volume = width x length x height

#

Use the formula triangle from science to rearrange if ur stuck

#

The height

tall bough
#

height

lean otter
#

No

undone umbra
#

Look at ur units of measurement

lean otter
#

Bruh the area of triangle

tall bough
#

^

lean otter
#

Not units

undone umbra
#

What

#

It’s volume tho

tall bough
#

wbh is for 3d rectangle

undone umbra
#

What

#

Really?

tall bough
#

yess

undone umbra
#

Wtf

tall bough
#

its (bhl)/2

#

,w (533)/2

tall bough
#

lol

undone umbra
tall bough
#

its not 21.5 fella

#

well you get it, it seems all th questions are about the volume of the same object

undone umbra
#

:0

#

Rectangle!

lean otter
#

I thought this channel was only for above 13 y/o's

undone umbra
#

☠️

#

I’m 16

#

Meh

#

Lovely

#

Volume is in non calculator paper tho I’m pretty sure

tall bough
#

ummm

#

does that look like that figure

safe radishBOT
#

@orchid rapids Has your question been resolved?

safe radishBOT
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south moat
#

I'm trying to calculate the probability of winning 7 games in a row with a 50% win rate while being able to lose one game for free (mercy).

I understand that to calculate it without a mercy game is simply .5^7 or 0.78%. But I don't know where to start when trying to include the free game. I think it has something to do with 8 games instead of 7 games and thought maybe I would just multiply the the base probability by 8/7 but I'm not sure if that's correct.
Thanks 🙂

safe radishBOT
#

@south moat Has your question been resolved?

south moat
#

<@&286206848099549185>

safe pelican
#

im not a helper but these are my thoughts. You must play 7 total games (not eight) but you only have to win 6 of the seven games because you are allowed to lose one game…

south moat
#

so it's at least 7/8

safe pelican
#

Gotcha, I haven’t taken statistics so im lost now lol... Is this a problem from a textbook? If it is, I can try to find a step by step solution on quizlet

safe pelican
#

darn. i wish i coulda helped more. best of luck to you tho!!! 🙌🏻

safe radishBOT
#

@south moat Has your question been resolved?

south moat
safe radishBOT
#

@south moat Has your question been resolved?

fiery merlin
#

You add the probabilities of all eight instances together.

south moat
#

ooh

fiery merlin
#

Sorry, 7 wins in a row with no losses.

#

Or you can do it a simpler way.

#

There are 9 relevant outcomes for the first 8 plays: ```
WWWWWWWW
WWWWWWWL
WWWWWWLW
WWWWWLWW
WWWWLWWW
WWWLWWWW
WWLWWWWW
WLWWWWWW
LWWWWWWW

#

And there are 2⁸ total outcomes.

#

So, 9/2⁸.

#

This only works when each outcome is equally likely, which is the case here, since both wins and losses are 50%.

south moat
#

I'm trying to wrap my brain around this so I can do 5 wins on my own lol

delicate aspen
#

start smaller

#

try 3 wins

#

actually start with 1

south moat
#

So 3 wins would be, WWWW, LWWW, WLWW, WWLW, WWWL

#

so 5/2^8

#

oh 1 win would be W or L or 1/1^1

delicate aspen
#

no

#

the possibilities would be

south moat
#

oh

delicate aspen
#

sorry

#

for 3 wins

#

you could WWW (succeed)

#

WWLW

#

WLWW

#

LWWW

#

those are the possible successes

#

what are the possible failurs?

#

WWLL

#

WLWL

#

WLL

south moat
#

oooh

delicate aspen
#

LWWL

#

LWL

#

LL

south moat
#

so 2^X where X is the number of games played (aka target consecutive wins+1)

#

and the numerator would be how many combinations that succeed

#

so 5 would be WWWWW, LWWWW, WLWWW, WWLWW, WWWLW, WWWWL

#

or 6/2^6

#

does that look right?

#

nope it doesn't

#

hang on

#

lol

#

WWWWWW, LWWWWW, WLWWWW, WWLWWW, WWWLWW, WWWWLW, WWWWWL

#

7/2^6 would be 5 in a row

#

or 10.9%

delicate aspen
#

what is the probability of winning 1 game with a mercy?

south moat
#

that would WW, WL, LW
so 3/2^2
75%?

delicate aspen
#

i disagree

#

1 game with a mercy

#

either you win the first

#

W

#

lose the 1st, win the 2nd

#

LW

#

or fail, LL

delicate aspen
south moat
#

oh

#

hmmm

delicate aspen
#

i highly recommend that you start with smaller numbers and build up until you see the patter

#

*pattern

safe radishBOT
#
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mint bloom
#

I need to simplify these, would love some help!!

lilac patio
flat frigateBOT
#

Arctic

lilac patio
#

ugh

#

You know what I mean

mint bloom
#

yeah ik, you’re good

#

So I just apply that to the question

lilac patio
#

yes

mint bloom
#

alright

#

Hate to admit but I am to sure how to do that

lilac patio
#

OK for a

#

x^2k-5

#

x^2k*x^-5

#

x^2k/x^5

#

Simplified

mint bloom
#

that’s the answer right?

lilac patio
#

yea

mint bloom
#

How did you apply the rule

lilac patio
#

What rule

mint bloom
#

The general rule

mint bloom
lilac patio
#

that's not what its called

#

Just saying its important to know

mint bloom
#

Aha, sorry

lilac patio
#

if there's two terms in an exponent

#

You can split it

#

any amount of terms in the exponent you can split it

mint bloom
#

Yes and then?

lilac patio
#

then you have a negative exponent

#

Have to simplify that

#

x^-5 is 1/x^5

#

oh wait

#

I just realized that whole thing is a

mint bloom
#

Wdym

#

Question a?

lilac patio
#

So yeah just use two things for the problem

#

I thought a was just x^2k-5

mint bloom
#

I mean there’s more to it rather than only x^2k-5

lilac patio
#

that's what I just realized

#

but its the same two rules to do the whole problem

mint bloom
#

Ohh LOL

mint bloom
#

I just apply those rules to it

#

Thank you

#

.close

safe radishBOT
#
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mint flax
#

would $\dv x \iint f(x)^2\mathrm dx\mathrm dx= \int f(x)^2\mathrm dx$?

flat frigateBOT
delicate aspen
#

i think you are missing a chain rule

mint flax
#

oh really

delicate aspen
#

i may be mistaken

mint flax
#

so I would then multiply by 2f(x)f'(x)??

delicate aspen
#

i have to write it down

final halo
#

You're correct gmod

mint flax
delicate aspen
#

you have all the assumptions of continuity and differentiability right?

mint flax
#

yeah

final halo
mint flax
#

alright ty

#

.close

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mint flax
#

alright so im trying to write $\int f(x)^2\mathrm dx$ in terms of $f(x)$ and $\int f(x)\mathrm dx$ and I keep running into trouble: I started by stating that $$\left(\int f(x)\mathrm dx\right)^2=\iint f(x)^2 \mathrm dx \mathrm dx$$ and then I took the derivative of both sides to achieve $$2f(x)\int f(x)\mathrm dx = \int f(x)^2 \mathrm dx$$ but when I try the example $f(x)=x$ it doesn't work soooooo im assuming I made a mistake somewhere but I cant find it

flat frigateBOT
stone oasis
#

is the first line really true?

#

ive never seen that before

mint flax
#

I dont see why not

#

lemme show u

#

$\left(\int f(x)\mathrm dx\right)^2=\int f(x)\mathrm dx\int f(x)\mathrm dx=\iint f(x)^2\mathrm dx\mathrm dx$

stone oasis
#

that cant be right

mint flax
#

do u know multivariable calc

stone oasis
#

yes

flat frigateBOT
mint flax
#

made a typo

#

but like how is it not right

#

oh wait

#

im stupid

#

nvm

#

im dumb

stone oasis
#

wat?

final halo
#

You're taking a double integral over the same variable twice

mint flax
#

yeah that only works if the two variables are different

#

and independent of each other

merry sleet
#

yeah

mint flax
#

whoops

#

alright thanks guys

#

.close

safe radishBOT
#
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true ingot
#

Anyone have any idea how to do this?

safe radishBOT
true ingot
#

my brother got this for 7th grade math homework and in my opinion if the teacher actually expects them to be able to solve it she's on something

#

but it's mandatory

young zinc
#

largest group? isn't that infinity

true ingot
#

I would imagine like

young zinc
#

think of any large prime number

#

and it cannot be divided into 7, 13 and 25s

merry sleet
#

it can be, the decomposition here

#

involves additions

#

not only multiplications

true ingot
#

yeah I was about to say

#

like

young zinc
#

wait yes

true ingot
#

13 is a prime number lol

#

that's a bad example

#

uhh

#

but yeah

#

intuitively it makes sense there's a largest number

#

cause I would assume anything past 10^100 (idk) would have to be some combination of 7,13,25

young zinc
#

why would that be 💀

true ingot
#

idk

#

but like

#

well if I knew the answer I wouldn't have posted here

#

but

#

idk intuitively the premise of the question sounds like there's an answer

young zinc
#

we need to analyze 7a + 13b + 25c

true ingot
#

wait

young zinc
#

and somehow prove that every number after a certain number can be divided by that

true ingot
#

I found the question

#

this mf took a grade 12 challenge problem

#

and made it grade 7 mandatory homework

#

LOL

young zinc
#

yeah this doesn't look like grade 7

true ingot
#

oh well

#

yeah I have no idea

young zinc
#

i have no idea either

true ingot
#

.close

safe radishBOT
#
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delicate aspen
#

trying again:

safe radishBOT
delicate aspen
#

is the reasoning here circular? was I supposed to substitute the polynomial expression of f into the uniform norm?

plucky elk
#

Did you learn Lebesgue's dominated convergence theorem?

#

I think uniform convergence works too

delicate aspen
#

i will look it up

plucky elk
#

You're essentially swapping the derivative operator and the summation.

delicate aspen
#

right, or at least trying to say why it makes sense to do so

safe radishBOT
#

@delicate aspen Has your question been resolved?

safe radishBOT
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sullen jetty
safe radishBOT
#

@sullen jetty Has your question been resolved?

safe radishBOT
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sudden harbor
#

Hi, i’m in an intro to calculus course and need some help evaluating this graph. the topic is limits.

if x is approaching -2 from both sides, does that mean that the limit is 3 because the limit is defined there? or is it just DNE since the two sides don’t meet? wasn’t getting it when my prof explained.

quasi bison
#

or is it just DNE since the two sides don’t meet?
yes

#

if you want to look at the one-sided limits, from the left it's 3 but from the right it's +∞

sudden harbor
#

Alright i think i got it. using the graph i sent..if x was approaching 10 it would also be DNE as well?

quasi bison
#

no

sullen jetty
#

A simple thing to remember is a function should not have two diff values for one input

quasi bison
#

the limit of your function at 10 does exist.

sullen jetty
#

Functions cannot show many to many relationships

sudden harbor
#

will try to remember that!!

#

thank you, i’m prepping for a quiz and trying to do some review questions.

sullen jetty
#

Np ✌️

safe radishBOT
#

@sudden harbor Has your question been resolved?

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violet sundial
#

i think the answer is +/- sqr(3i)

safe radishBOT
violet sundial
#

is that complex and rational?

#

SORRY IRRATIONAL

limber patio
#

1 sec

#

Yup, complex and irrational

violet sundial
#

thank you

#

.close

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violet sundial
safe radishBOT
violet sundial
#

The answer is A right?

#

@limber patio

#

this topic is complex numbers

#

or anyone else else

#

there is my working

#

just 1

trim trench
#

not really

#

-3 x 3 = -9 not 9

limber patio
trim trench
#

yes

violet sundial
#

sorry

#

would it be +/- 3i

trim trench
#

is this your alt?

violet sundial
#

but why

#

no it is not

#

ignore my pfp

trim trench
#

ah sorry

violet sundial
#

lmao

trim trench
violet sundial
#

ohh k

#

i see where i went wrong

flat frigateBOT
#

||𝓚𝓪𝓼𝓹𝓮𝓻||

violet sundial
#

when i expand it

#

it is x^2 -9

#

wait

#

nv,

#

nvm

#

i understand

#

thank you everyone for the help

#

i also don't understnad this question

#

nvm got it

#

thanks

#

.close

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#
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quaint needle
safe radishBOT
#

@quaint needle Has your question been resolved?

safe radishBOT
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vapid wasp
#

What does $z \in i \mathbb{R}$ mean?

safe radishBOT
flat frigateBOT
vapid wasp
#

is this same thing as Complex set?

regal girder
#

I assume maybe $i\mathbb R = {ir | r \in \mathbb R}$?

flat frigateBOT
regal girder
#

C would be in the form a + bi

#

but again, this was just a guess

vapid wasp
#

uh thank you then

#

.close

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quaint needle
#

Hello

safe radishBOT
#

Please don't occupy multiple help channels.

quaint needle
inner nest
#

.close

safe radishBOT
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inner nest
#

@quaint needle don't use multiple channels

safe radishBOT
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glad frost
#

Hi guys can anyone help me with my homework, thanks in advance

safe radishBOT
#

@glad frost Has your question been resolved?

glad frost
#

<@&286206848099549185> sorry for pinging you guys but can anyone help me solve these questions, thanks a bunch

safe radishBOT
#

@glad frost Has your question been resolved?

cinder viper
#

@glad frost For the first one, you can try multiplying/dividing by the conjugate $\sqrt{4x^2 - 4x + 2} + (3x + 1)$

flat frigateBOT
cinder viper
#

Second one try factoring

glad frost
glad frost
glad frost
cinder viper
#

Whole

glad frost
#

oh that makes sense

#

thanks a bunch

#

also how about turning the (x^2 - 6x +9) into a 1/(x-3)^2, will that also work?

cinder viper
#

Yes

#

and factor x^2 - x - 6

glad frost
#

what will the factoring result be, though, im having a tough time with it

cinder viper
#

$\frac{-5x^2 - 10x + 1}{\sqrt{4x^2 - 4x + 2} + 3x + 1}$ is what you should get after rationalizing the first question

flat frigateBOT
cinder viper
#

x^2 - x - 6 = (x + 2)(x - 3)

glad frost
#

ohhh yeah, thanks

glad frost
cinder viper
#

If you want

#

I have to go

glad frost
#

oh its ok

#

thanks a bunch

#

have a nice day too

#

.close

safe radishBOT
#
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wraith root
#

Nowadays restaurants throw away a lot of excess food while other people can’t afford it.
This type of app will allow the restaurant to call on the charities that surround their area to donate excess food everyday to homeless

wraith root
#

anyone can help lol

safe radishBOT
#

@wraith root Has your question been resolved?

wraith root
#

How the product solves the problem:
With our application we collect all the remaining and edible food in restaurants rearrange it, pack it and send it to people in need.This app helps people in need to get food and also helps restaurants dispose remaining food, most importantly it decreases the damage done to the environment by all the leftovers restaurants throw away .
It also helps people who need food, they get the food packed from the restaurants for free,and it reduces hunger,which improves the relations between residents.

#

i have to write 2 questions to ask the person who made the app

potent roost
#

how does this relate to math?

wraith root
#

engineering thinking x)

#

do you have a question even?

#

its hard

lean otter
# wraith root do you have a question even?

what are you gonna do about the legal part? Much of the food is thrown away because of strict goverment's standarts. What if a person gets sick and dies from eating it? Will you or the restaurant be responsible?
how are you gonna pack and send everything fast enough so the food doesn't become spoiled?

wraith root
#

do you have more ?

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i will send you what i wrote

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so you dont think iam just taking from others xd

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  1. How will the app distinguish people who need food?

  2. How is that app different from normal packing the food and give it to the people who wants?

3.What if the excessive food can cause disease transmission by the people who ate it to others?

4.Why does the restaurants have to pay some money since the main goal is charitable work?

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if you have more pls give

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i only need 2 but i want the best 2

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@lean otter sorry for mention 😅

lean otter
wraith root
#

alright

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thanks so much!!

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.close

safe radishBOT
#
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haughty sapphire
#

Hi there, I have a stochastics problem I'm unable to solve

Following scenario:
Imagine a bowl of 10 different kind of balls labeled from 'A' to 'J'. In total, there are 100 balls in the bowl in the following constellation:
25 balls labeled 'A'
22 balls labeled 'B'
13 balls labeled 'C'
12 balls labeled 'D'
10 balls labeled 'E'
6 balls labeled 'F'
4 balls labeled 'G'
3 balls labeled 'H'
3 balls labeled 'I'
2 balls labeled 'J'

Now, we will draw 5 balls, but between every draw, all balls from the respective category that has been drawn will get removed. For example, if a ball labeled 'A' gets drawn in the first round, all balls labeled 'A' will get removed from the bowl. The bowl now only contains 75 balls for the second draw.

The question now is: How do I calculate the probability of each ball actually being picked after 5 draws? How would I go about this?

I think I could bruteforce my way through this by building a stochastics tree diagram; however this quickly gets out of hand considering the amount of possibilities. I don't really know if this would be the way to go, but it seems there must be a better way to get there.

Some help is greatly appreciated 🙂

safe radishBOT
#

@haughty sapphire Has your question been resolved?

haughty sapphire
#

<@&286206848099549185> Could really need some help on this statistics problem here, thanks so much

safe radishBOT
#

@haughty sapphire Has your question been resolved?

safe radishBOT
#

@haughty sapphire Has your question been resolved?

safe radishBOT
#

@haughty sapphire Has your question been resolved?

young osprey
#

5040x4!

safe radishBOT
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viral gate
#

HELP ME PLS

safe radishBOT
drowsy moss
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add up the area of each side

viral gate
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so 7x8

drowsy moss
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that's the area of one side

viral gate
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so how do i get the surface area

drowsy moss
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add up the area of each side

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you can see 3 rectangles in the image. What is the area of each rectangle?

viral gate
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56?

drowsy moss
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so that's the area of one rectangle

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what about the other two?

viral gate
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56

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?

worthy hemlock
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The area of each rectangle

drowsy moss
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56 is the area of rectangle 1. What is the area of rectangle 2?

viral gate
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28?

drowsy moss
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good

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now what about rectangle 3?

viral gate
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im not sure

safe radishBOT
#

@viral gate Has your question been resolved?

safe radishBOT
#

@viral gate Has your question been resolved?

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safe radishBOT
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storm vine
#

Can someone explain to me how I can get a and b please

safe radishBOT
#

@storm vine Has your question been resolved?

safe radishBOT
#

@storm vine Has your question been resolved?

storm vine
#

<@&286206848099549185>

safe radishBOT
#

@storm vine Has your question been resolved?

storm vine
#

<@&286206848099549185>

safe radishBOT
#

@storm vine Has your question been resolved?

marsh walrus
storm vine
#

nah

marsh walrus
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what have you tried?

storm vine
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bro ive been waiting for help man😭😭

marsh walrus
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i know sadcat

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so many askers today

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so lemme make a graph we can reference

marsh walrus
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this may help at least get an idea of whats going on

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can you tell which two points we need to go through?

storm vine
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well we have the limits pi/6 and pi/3

marsh walrus
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(they're kind of your choice, but you should make a good choice)

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yea

storm vine
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so what i was assuming is that

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the trapezium is a result of a revolution so could u say that acos^2(pi/6)=1

marsh walrus
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hmm

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im not sure i follow your reasoning

storm vine
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i think we should ignore the curves icl

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i think since the handle has been revolved around, that 2cm distance PQ is actually a diameter idk if im making sence

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so i think we can halve it and say that acos^2(pi/3) is equal to it

marsh walrus
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oh, i see what you mean, i think

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so the beginning x coordinate must be 1

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this corresponds to the lowest value of theta plugged into that function

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let me see

marsh walrus
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then we want the latter bound

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as long as we let a>0 this should be true

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so the point "starts at" R and goes to Q along the parameterization

storm vine
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oh i think i was assuming that this trapezium was on a polar graph

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wait no nvm ignore what i typed

marsh walrus
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so i like your idea

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i would flip it to be the latter bound

storm vine
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this is what i was thinking

marsh walrus
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ok

storm vine
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if we were to plot this on a graph

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and make a half line at pi/3

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hmm wait i dont think we can do this can we

marsh walrus
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i dont think this is the way that the parameterization is being done

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theta is a parameter, its not passed directly to the graph

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it moves through functions

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well, the point moves through theta

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but on a cartesian graph

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thats my impression

storm vine
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ahh man

marsh walrus
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i am explaining it poorly and making it sound more complicated

storm vine
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the thing is we are given the theta limits but this question is worded hella weird lowkey

marsh walrus
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try to imagine instead of theta

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its t for time

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so instead of being given a segment of a graph

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you are being given a start point, an end point, and the direction you draw the curve in

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so instead of just having a range of values, instead you have like

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a mapping that defines how the point of the pencil moves on the plane

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idk if that helps blobsweat

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your idea for solving this is very good

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i think it will lead us to the solution thonk

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cos^2 t at p/3 is 1/4

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cos^2 t at p/6 is 3/4

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so it seems to me that we want the pi/3 one to be making that radius 1

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like you said

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meaning a would be 4

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seem reasonable?

storm vine
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yeah

marsh walrus
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im just trying to extrapolate ur suggestion

storm vine
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if we use pi/6 we get four too so i think what i was saying might be leading to smthn

marsh walrus
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so a looks good happy

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it goes from 1 to 3 along x

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which tracks with our two radii

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of 1 and 3

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we just need to repeat this process for b

storm vine
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i dont think we do it the same for b right

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since the height isnt being revolved we cant just set it up like that i think it should be smthn like

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btan(pi/3)-btan(pi/6)=2

marsh walrus
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sure, that works

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i think alternatively since you only have one degree of freedom

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either way works

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unless the problem has no solution

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but a geometric way of approaching it is maybe better

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oh, wait, i see what youre saying

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happy yea youre right

storm vine
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okay

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ty for helping tho

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b should be lightwork now

marsh walrus
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come to think

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you could probably have done this in a system

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if youre into those

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since all the functions collapse into constants

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it would have just been a matter of arranging it correctly

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then RREF and pow

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anyways, you think youre set?

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or ping if u want more help

storm vine
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yhh im chilling now

marsh walrus
storm vine
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how do i close this

marsh walrus
#

.close

storm vine
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ty btw

#

.close

safe radishBOT
#
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marsh walrus
#

np 😊

safe radishBOT
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mild mulch
#

Hey

safe radishBOT
mild mulch
#

idk how to turn 1-x^2 into cos^2(sqrtx)

storm vine
#

Here’s what I did

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let me know if u cant understand my handwriting ill rewrite it

mild mulch
#

because if y = cos(sqrtx) then dy/dx is just -sin(sqrtx) no?

storm vine
#

no you have to apply chain rule

#

so it becomes 1/2x^-1/2 times by -sin(x)

safe radishBOT
#

@mild mulch Has your question been resolved?

safe radishBOT
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lean otter
#

Is this the basis of a diagonal matrix nxn?:

lean otter
#

.close

safe radishBOT
#
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timber schooner
#

before i ask my question ill send an image to tell u what im working on

safe radishBOT
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timber schooner
#

here is the image

safe radishBOT
timber schooner
#

basically i am trying to find a better way to represent that number in the bottom maybe as a fraction connected to some other mathematical constant

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how do I do that?

timber schooner
#

exact

timber schooner
supple ore
timber schooner
#

the number on the bottom w is the limit of the lower bound that still allows the integral in the middle to have a definite answer, it is a decimal expansive number

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the bottom number does not include all of the possible digits

safe radishBOT
#

@timber schooner Has your question been resolved?

delicate aspen
#

thinking

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how did you find that w_m?