#help-23

1 messages · Page 469 of 1

broken ether
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ok

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now that ive got this where do i go further ?

winter pivot
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What is -2 + 2

broken ether
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0

winter pivot
#

Yep

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And what is 0+2

broken ether
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2

winter pivot
#

So then we have:

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2x = 2

broken ether
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yes

winter pivot
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What can we do now?

broken ether
#

uh

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i do not know

lean otter
#

you are learning calculus even though you cant solve simple equations? 🤔

winter pivot
#

Could you write the equation in words?

broken ether
#

i have really bad difficulties with math

winter pivot
broken ether
winter pivot
#

If you had to say that equation out loud

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How would you say it

broken ether
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two x equals two

winter pivot
#

Alright that's a good start!

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But what exactly do we mean by "two x"?

broken ether
#

uhhh

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yea no idea

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we have

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2 and an unknown

winter pivot
#

What sort of operation is that?

broken ether
#

i wouldnt know

winter pivot
#

What are we doing with the numbers 2 and x?

broken ether
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they equal 2

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so x is 0

#

because 2 =2?

winter pivot
#

Not quite

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Let's step back a bit

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I want you to read this equation out loud:

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3(5) = 15

broken ether
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three times five equals fifteen

winter pivot
#

Yes

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There is a specific word you used there

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It is very important

broken ether
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times ?

winter pivot
#

"times"

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Yes

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What does that mean?

broken ether
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you multiply

winter pivot
#

Yes!

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So what does "2x" mean?

broken ether
#

we multiply 2 by x?

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2(x)?

winter pivot
#

Yes!

broken ether
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so it’s 1?

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2 • 1 = 2

winter pivot
#

Yeah x is 1

broken ether
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ohhhhh ok

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i see

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and so my final answer would be

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2(1)=2?

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or

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something like that?

winter pivot
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So we had that f'(x) = 2x - 2.
And 2x-2=0 when x=1

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So far so good?

broken ether
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hang on

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wait i don’t understand one part

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2x-2 = 0 but 2•1 is 2

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so why 0

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oh wait

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i think i see

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no wait h

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hang on i am confusing myself one second

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ahhh ok

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i get it now

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ok so far so good

winter pivot
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Yes. Now when is 2x-2 greater than 0?

broken ether
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when x id higher than 2?

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is*

winter pivot
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If 2x-2 = 0, then x = 1

broken ether
#

yes

winter pivot
#

So then if 2x - 2 > 0, then?

broken ether
#

wouldn’t that be equal to zero though?

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2x-2=0?

winter pivot
#

Yeah we already solved that. We know when 2x-2 is 0. But now we want to find when it's greater than 0

broken ether
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ah ok

#

i think i see now

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so since it’s greater than 0 what does it mean?

winter pivot
#

2x - 2 > 0

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add 2 to both sides

broken ether
broken ether
#

anyone else who can help?

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<@&286206848099549185> any one of you guys? 😅🥲

sudden briar
#

continue

safe radishBOT
#

@broken ether Has your question been resolved?

broken ether
sudden briar
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2x>2

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so???????????????????/

broken ether
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ok

#

uhhh

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i don’t know

sudden briar
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multiply by a positive number

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do what to the inequality

broken ether
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yes

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häääh im confused by what u mean by that

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ok so

sudden briar
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so basically

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say we have a>b

broken ether
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2(1)

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for example

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2=2

sudden briar
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we multiply by a POSITIVE real c

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we have that a>b is equivalent to ac>bc

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here 2x>2

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we multiply by the positive number 1/2

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we get x>1

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o oops

broken ether
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this is so confusing

safe radishBOT
#
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broken ether
#

.reopen

safe radishBOT
#

sudden briar
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$2x>2 \iff 2(1/2)x>2(1/2) \iff x>1$

broken ether
#

HUUH

flat frigateBOT
broken ether
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i don’t understand so completely why we do 1/2

sudden briar
#

to cancel the 2?

bronze prism
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Because knowing things about 2x is weird, it's much more convenient to know things about just x

broken ether
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ok wait

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back track for a second im still completely lost

sudden briar
#

wait how come the original question equality

broken ether
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is that a question

sudden briar
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yes

broken ether
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idk what u are asking

sudden briar
#

oh

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nvm

bronze prism
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Let's take it from the start

broken ether
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kk

bronze prism
#

We know that f(x) is increasing if and only if f'(x) ≥ 0

sudden briar
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well anyway f(x) is monotonically increasing on the interval [1,+inf)

bronze prism
#

(the equality case isn't really relevant here, but let's include it for completeness's sake)

broken ether
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okay

bronze prism
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However f'(x)=2x-2, so we want to know for which x (and not for which 2x or 3x or whatever) we have 2x-2 ≥ 0

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When 2x-2 ≥ 0, f'(x) ≥ 0 so f is increasing

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When 2x-2 ≤ 0, f'(x) ≤ 0 so f is decreasing

broken ether
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ok i understand that

bronze prism
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So then the question is : for which x do we have 2x-2 ≥ 0

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Now, the first golden rule is that you can add anything to both sides of an inequality

broken ether
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what’s an inequality?

bronze prism
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a ≤ b is an "inequality", it's a way of saying how a and b compare to one another

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In this case "a ≤ b" means that "a is less than or equal to b"

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For example, 1 ≤ 3 because 1 is less than 3

broken ether
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Ah ok

bronze prism
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But it's also true that 1 ≤ 1, because the definition is "less than or equal to"

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If we write a < b, we remove that "or equal to" part

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It's called a strict inequality

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When the symbols go the other way, so does the relation

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a ≥ b means "a is greater than or equal to b"

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a > b means "a is greater than b (and not equal)"

broken ether
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I see

bronze prism
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perhaps a better word for "inequality" would be "comparison", because that's really what we're doing here

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Now, let's use a simple example to make obvious the various transformations you can do to an inequality

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Let's compare my amount of money (written a) with my neighbor's (written b)

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Think of them as bank balances, so they can actually go negative

broken ether
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kk

bronze prism
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I have strictly more money than my neighbour (written a ≥ b), then that won't change as long as we both receive (or lose) the same amount of money

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If we both receive a million bucks (it's our lucky day), I will still have more money than him (it's a bit less flagrant, but it is still true, and that's all we care about)

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If we both lose 100 (an unluckier day), the same will be true

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Now, to put this everyday obviousness in mathematical terms

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If a ≥ b, then it stays true as long as we add the same amount to a and b

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If we write that added quantity c (which may be negative, like when we lose money instead of gaining it), then we can write this as a+c ≥ b+c

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Follow so far?

broken ether
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Yes

bronze prism
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This property is sometimes pompously called "translation invariance" or "shift invariance"

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Because as long as you shift or translate both quantities by the same amount, inequalities stay the same

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(note that this is also true of equalities)

broken ether
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Ah

bronze prism
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and it's even more trivial in that case

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If two things are the same, they stay the same as long as you do the same operations to each of them, because, well... they're... the same.

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Although it would be nice, the same thing isn't true of inequalities, and as such we have to be a bit more precise

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Now, in a very similar fashion to solving equalities/equations where we have a quantity that we don't know

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A good rule of thumb is to isolate that quantity on one side of the inequality

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Hence, suppose you know 2x-2 ≥ 0 and you want to only have x on the left side : what do you need to add to both sides to achieve that?

broken ether
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2?

bronze prism
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Yes

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but in case you feel confused with what you heard before, they were talking about multiplying by negatives, not adding them

broken ether
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ah wait

bronze prism
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And yes, 2 is the right answer

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You get 2x-2+2 ≥ 0+2, which simplifies to 2x ≥ 2

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Now we're getting somewhere

broken ether
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ah ok

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so now with 2x >_ 2

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where do we go further?

bronze prism
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Right, so now we'll discuss multiplication with inequalities

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(by the way, if you can't type ≤ and ≥, the standard way to write them on keyboards is <= and >= )

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Now, let's also make some obvious observations and deduce mathematical generality

bronze prism
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I still have more money than my neighbour in this scenario. If both me and my neighbour's bank accounts get doubled, then I will still have more money than them.

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Mathematically, if a ≥ b then 2a ≥ 2b

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But it's also true in the other direction. If both of our accounts get halved, I still have more money than them.

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(you can see it as the "reverse" step of doubling, which conserved the inequality)

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So a/2 ≥ b/2

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In fact, this is true for any positive constant

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No matter how small or how big

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if c > 0, then ac ≥ bc

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In our case, from 2x ≥ 2 we want to really isolate the x, so we want to get rid of that pesky factor of 2

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So we multiply by 1/2 because 2*1/2=1

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Thus, (1/2)*2*x ≥ (1/2)*2. Simplifying, we get x ≥ 1.

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But before i go (gotta eat), a final remark about negative factors

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if the multiplicative constant is 0, it's kinda boring

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because a*0=b*0=0

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But if it's negative, things get flipped around

broken ether
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ahh

bronze prism
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If i have 1000 and my neighbor has 900, and somehow our accounts get turned into negatives (i.e multiplied by -1), then I have -1000 and my neighbour has -900

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But notice, -1000 is less than -900

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Because it's further out in the negatives

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Here, the general rule is that if c < 0 (negative !!) and a ≥ b, then ca ≤ cb (crucial ! notice how the inequality sign has been flipped !)

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In other words, multiplying by negative numbers flips inequalities.

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Right, now I have to go, I'll let this sink in

broken ether
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Thanks so much system :D

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I think I’m getting a better understanding

bronze prism
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I'm back, if you have any questions don't hesitate

safe radishBOT
#

@broken ether Has your question been resolved?

safe radishBOT
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devout frigate
#

can anyone confirm my answer of 19/12

safe radishBOT
devout frigate
#

if its right id like help with this too

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<@&286206848099549185>

safe radishBOT
#

@devout frigate Has your question been resolved?

devout frigate
#

no

#

<@&286206848099549185>

safe radishBOT
#

@devout frigate Has your question been resolved?

devout frigate
#

.close

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covert fiber
#

How I can do integral for this 1 ??

safe radishBOT
ancient escarp
#

,rotate

flat frigateBOT
covert fiber
#

Wt is this xd

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Oh k

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Nice bot ;-;

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Can u tell me step by step cuz I actually forgot how to do integral for this

tall bough
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sub sqrt(1-2x)

covert fiber
#

?

#

Can u be more clear pls xd

safe radishBOT
#

@covert fiber Has your question been resolved?

covert fiber
#

<@&286206848099549185>

mossy bramble
#

its just a u sub

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u=sqrt(1-2x)

covert fiber
#

What is u sub

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What is sub xd

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My English isn’t that good xd

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pls don’t go 🥲

inland rune
#

substitution

covert fiber
#

I don’t think I learned that

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Or know it

covert fiber
inland rune
#

u=sqrt(1-2x)

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you replace sqrt(1-2x) with u

covert fiber
#

What is “u” xd

inland rune
#

you just make it as a temporary variable

covert fiber
#

There is other way right ?

safe radishBOT
#

@covert fiber Has your question been resolved?

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devout frigate
#

need help with the parametrization

safe radishBOT
#

@devout frigate Has your question been resolved?

devout frigate
#

<@&286206848099549185>

safe radishBOT
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@devout frigate Has your question been resolved?

devout frigate
#

still waiting

#

<@&286206848099549185>

safe radishBOT
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@devout frigate Has your question been resolved?

devout frigate
#

.colose

safe radishBOT
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@devout frigate Has your question been resolved?

devout frigate
#

.close

safe radishBOT
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safe radishBOT
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winter fern
#

Why is the answer E? As far as I can recall, the derivative should be $e^{x+x^2}(2x)$, and so at $x=1$ we get $2e^2$

flat frigateBOT
#

cgodfrey

winter fern
#

My recollection is that $\frac{\mathrm d}{\mathrm dx}\left(\int_{f(x)}^{g(x)}h(t),\mathrm dt\right)=h(g(x))g'(x)-h(f(x))f'(x)$

flat frigateBOT
#

cgodfrey

safe radishBOT
#

@winter fern Has your question been resolved?

winter fern
#

<@&286206848099549185>

plucky elk
safe radishBOT
#

@winter fern Has your question been resolved?

winter fern
flat frigateBOT
#

cgodfrey

plucky elk
winter fern
#

ooh I see

#

.close

safe radishBOT
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safe radishBOT
#

@lean otter Has your question been resolved?

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gilded delta
#

are those two linear mappings surjective?

safe radishBOT
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tribal cove
safe radishBOT
tribal cove
#

can anyone tell me what should I do next
Idk how to compute the partial 4n times thing
And I am not sure am I on the right track

shy temple
flat frigateBOT
#

1345631

safe radishBOT
#

@tribal cove Has your question been resolved?

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warm niche
#

i dont get how the first asymptote is -3pi/4

warm niche
#

the answer sheet showed that the first one is -3pi/4

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but i dont get how that is -3pi/4

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it looks like -pi/4

woven kiln
warm niche
#

i dont get it

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i just started trigonometry

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so

woven kiln
warm niche
#

i didnt learn how to find the domain from the function sry

woven kiln
#

otherwise there are infinitely many asymptotes

warm niche
#

this is the answer

woven kiln
#

so what you’re saying isn’t much,

warm niche
#

i dont get how the first line is at -3pi/4

woven kiln
#

this is just a graph transformation question

warm niche
#

yes

woven kiln
#

yeah

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so what’s the domain of x

warm niche
#

umm

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what x cannot be right

woven kiln
#

pi is the translation, and 2x is the stretch of 1/2 on the x

woven kiln
#

so range of x values

warm niche
#

i dont get anything u say sorry

woven kiln
#

not range of f(x)

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ok

#

wait

warm niche
#

ok

woven kiln
#

see that

warm niche
#

yes

woven kiln
#

It’s got infinitely many asymptotes

warm niche
#

yeah

woven kiln
#

yeah,

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so you can only find them within a region

warm niche
#

but for this function the period is pi/2

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i think

woven kiln
#

*?

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there is still not first or last

warm niche
#

oh wait

woven kiln
warm niche
#

that doesnt do anything

woven kiln
#

exactly

#

you have half a question kid

warm niche
#

lol ok

woven kiln
#

you need a domain

warm niche
#

ok

woven kiln
#

do you get why

warm niche
#

yes

woven kiln
#

anyways,

#

general cases

warm niche
#

it doesnt specify

woven kiln
warm niche
#

ok

#

imma leave the question black

woven kiln
#

anyways, back to what I was saying

warm niche
#

blank

#

ok

#

yes

woven kiln
#

you can do general case

warm niche
#

i dont know what that is

woven kiln
#

whenever cos(x) = 0

warm niche
#

ok

woven kiln
#

tan(x) has an asymptote

#

yes?

warm niche
#

yes

woven kiln
#

so if cos(2x+pi) = 0

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you’ll have an asymptote

warm niche
#

ok

#

i get it

woven kiln
#

yeah

woven kiln
#

you’ll get it

warm niche
#

ok thanks

woven kiln
#

and it repeats every pi

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no worries man

woven kiln
warm niche
#

ok

#

got u

#

i can close this now right

#

i think i know what am doing now

#

.close

safe radishBOT
#
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crystal rampart
#

hi guys I need help, I'm French and I have a hot exercise. The question of the exercise is: For what value x is the area of rectangle 1 equal to the area of rectangle 2? ( solve this problem using an equation ) , rectangle 1 has a width of 5 and the length is 3 x + 1 and rectangle 2 has a width of 4 x and a length of 6, thank you for helping me as soon as possible I have difficulties in mathematics 🙂

warm niche
#

we can show the area for the first one as this

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5(3x+1)

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and that is equal to the rectangle 2 area

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which is 6(4x)

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so we can show this equation like this

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5(3x+1)=6(4x)

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and you can solve that right?

crystal rampart
#

ah okay thanks but suddenly for part 5 (3x + 1) we have to perform the double distributivity?

warm niche
#

yep

crystal rampart
#

okay

#

rlly thx

warm niche
#

yw

crystal rampart
#

A = (3x+1)×5=4x×6
A = 5 x 3x + 5 x 1 = 4x x 6
A = 15x + 5 = 24x
A = 15x + 5 - 15x = 24x - 15x
A= 5 = 9x
A= x = 9/5
is that the result?

warm niche
#

very well done

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yep

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if u want to check just substitute x into the equation

crystal rampart
#

okay

#

good day

#

English > French

#

x)

warm niche
#

u too

#

🙂

safe radishBOT
#

@crystal rampart Has your question been resolved?

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boreal haven
#

Prove the identity 1/cosθ - cosθ/1+sinθ = tanθ

boreal haven
#

Prove the identity 1/cosθ - cosθ/1+sinθ = tanθ

#

Can you help

limber patio
#

And use the identity, Sin²x +Cos²x=1

boreal haven
#

cosθ?

#

LCM

#

or 1

#

because i know at some point tanθ= sinθ/cosθ will help

#

but if you say i should use Sin²x +Cos²x=1

limber patio
boreal haven
#

so i take lowest common multiple first

limber patio
#

First take the LCM

limber patio
limber patio
boreal haven
#

i just don't understand how you use lcm here to be honest

#

1-cos²(θ) +sin (θ) / (1+sin(θ)) cos(θ)

limber patio
#

Now in the numerator, instead of writing 1
Change it to sin²θ + cos²θ

boreal haven
#

sin(θ) / cos (θ)

limber patio
boreal haven
#

this is step by step?

limber patio
limber patio
#

Be back in 10 mins

boreal haven
#

ok

#

sin²θ + cos²θ-cos²(θ) +sin (θ) / ( sin²θ + cos²θ+sin(θ)) cos(θ)

#

@limber patio

#

<@&286206848099549185>

#

i think my man just has better shit to do

#

it's understandable though

#

thank you for the help up until now

#

i shall patiently wait for your return

#

.close

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radiant latch
#

Hello guys, i have a problem :

safe radishBOT
radiant latch
#

I have : (u - a.idE) ° (u - b.idE) = 0 (L(E)), u is linear

#

With a =/ b

#

And my first question is to prove that a or b is a eigenvalues

#

It was easy

#

But the second one is to proove that

#

If u is not a homotheties, a and b are eigen values of u

#

I don’t know how to process

#

(I don’t speak fluently English, so sry for the potential error)

#

So i have to demonstrate this :

#

u is a homothety => a and b are not eigen values of u

#

$(u - a.Id_E) \circ (u - b.Id_E) = 0_{L(E)}$

flat frigateBOT
radiant latch
#

I don’t know if i have to post in advanced math or not

#

<@&268886789983436800> could you guide me pls

#

Is it the appropriate channel ?

timber valve
radiant latch
#

Oh sry, i can

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gray plaza
safe radishBOT
gray plaza
#

Would someone please tell me what I have done wrong? 😀

covert yoke
#

@gray plaza can't. Don't actually know what you're supposed to be doing

gray plaza
#

I have to do integration of that function.

#

But the answer I received doesn't match with the correct answer.

#

So, I am wondering what I have done wrong.

tall bough
#

nothing wrong

safe radishBOT
#

@gray plaza Has your question been resolved?

gray plaza
gray plaza
tall bough
#

HAHAHAHA

#

you made it way more complicated like doing ibp for xe^(x^2)

#

normally

#

your answer should be equal to that

#

check it by a calculator

gray plaza
#

Haha

#

Gotcha

#

Thank you ❤️

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queen parcel
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somber hazel
#

my online school has very outdated videos to "explain" equations and i don't understand how to do this

latent sage
#

Do you know the inscribed angle thereom and understand how it works?

somber hazel
#

not at all

latent sage
somber hazel
#

yeah idk how to find c for example

#

if i find angle c i get b

latent sage
#

I see

#

Hint:

#

Isn't angle ECD an inscribed angle?

somber hazel
#

yes i believe so

latent sage
#

And you know the measure of arc ED :)

somber hazel
#

ED is 52*

latent sage
#

So, the inscribed angle thereom states...

somber hazel
#

idk the thereom

latent sage
#

Ah

somber hazel
#

yeah...

latent sage
#

Draw a diagram of an inscribed angle then :)

somber hazel
#

oh wait isn't the arc 2x the angle so c is 26?

latent sage
#

Yep :D

somber hazel
#

so

#

c and b are 26*

latent sage
#

Mhm!

somber hazel
#

how about fiunding BSD?

latent sage
#

Instead of directly finding BSD...

#

What other angle can we find that helps with the problem?

somber hazel
#

uhhhhh

#

d = 57*
b = 26*
s = x*

latent sage
#

Ah I missed that LOL

somber hazel
#

lol

latent sage
#

I found it by using another thereom

somber hazel
#

what formula can i use to get s?

latent sage
#

Like the one that says CSB = 57 x 2 + 52 / 2

somber hazel
#

for triangle BSD

latent sage
#

So you're basically done with the problem! :D

somber hazel
#

oml how did i forget that

#

57+26=83
180-83=97

latent sage
somber hazel
#

s=97

latent sage
#

Nice job :D

somber hazel
#

ty for the help!

latent sage
#

yw!

somber hazel
#

how do i close this?

latent sage
#

.close?

somber hazel
#

.close

safe radishBOT
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urban shore
#

How can i make *1 summation skip the term when k = *2

safe radishBOT
#

@urban shore Has your question been resolved?

crisp oxide
#

for this problem it'll probably be easier to just write out every term

safe radishBOT
#

@urban shore Has your question been resolved?

covert yoke
#

This will give you 1 on all k not equal to do, and 0 when it does.

#

$\sum_{k=1}^4 (1 - \delta_{k2}) \left(k - \left(\frac1{2}k - 1 \right) \right)$

flat frigateBOT
#

OmnipotentEntity

covert yoke
#

sorry, not dirac delta, that's the kronecker delta. https://en.wikipedia.org/wiki/Kronecker_delta

In mathematics, the Kronecker delta (named after Leopold Kronecker) is a function of two variables, usually just non-negative integers. The function is 1 if the variables are equal, and 0 otherwise:

or with use of Iverson brackets:

where the Kronecker delta δij is a piecewise function of variables i and j. For example, δ1 2 = 0, whereas δ3 3 =...

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frosty ridge
#

I need help to show that $\frac{2n+1}{(2n+2)^2}<\frac{1}{2n+3}$ for all n≥1

flat frigateBOT
#

Goose on a Moose

drowsy moss
#

what have you tried, what is the method you want to use?

frosty ridge
#

Besides graphing it on desmos to convince myself that it is true, I'm stuck on the first step haha

simple radish
#

Here's a hint: maybe it is easier to show that $\frac{1}{(2n+2)^2}<\frac{1}{(2n+1)(2n+3)}$

flat frigateBOT
#

dackid

drowsy moss
flat frigateBOT
#

Zybikron

frosty ridge
#

thanks for the hints peeps. Ill give this problem another go.

#

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simple radish
#

Good luck goose

safe radishBOT
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runic socket
#

i am 99% sure that both b and c needs to have the angle but i cant seem to find it

runic socket
#

like the equation is supposed to be 1/2sin^-1((gx)/v^2) or something like that

#

but then i get this which isnt even an answer choice

safe radishBOT
#

@runic socket Has your question been resolved?

runic socket
#

<@&286206848099549185>

runic socket
#

<@&286206848099549185>

safe radishBOT
#

@runic socket Has your question been resolved?

runic socket
#

bruh

#

.close

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true zodiac
safe radishBOT
true zodiac
#

I literally just dont get it

#

.close

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floral wasp
#

how do you determine if a function is continious on a given value of X

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plucky elk
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wraith root
safe radishBOT
#

@wraith root Has your question been resolved?

normal wharf
#

You are asking in terms of group theory?

#

If yes then operate A-¹ on both sides

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lean otter
#

hey what’s newton’s method for

safe radishBOT
valid grove
#

By newton’s method I assume you mean newton’s method of approximation

lean otter
#

ig? what’s that

#

how does it work, why does it work and what do i need it for :>

#

okay maybe one at the time

#

What do i need Newtons method of approximation for?

queen parcel
#

You can look it up on Wikipedia - that page is pretty helpful @lean otter

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dreamy dagger
#

How long will it take for an investment of 1100 dollars to grow to 6900 dollars, if the effective rate of interest is 6.2 percent? (Assume compound interest at all times.)

dreamy dagger
#

Anwer in years

#

I originally got 29.6 years as I used the monthly compound formula but I am not sure if that's correct

buoyant shadow
#

can you show how you got it?

dreamy dagger
#

Yeah sure

#

!close

#

.close

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worthy owl
#

Can anybody help me on this question

safe radishBOT
valid grove
#

$\frac {x-6}{y-6} =\frac 1 2$

flat frigateBOT
valid grove
#

$\frac {x-14}{y-14} =\frac 2 5$

flat frigateBOT
spice grove
#

@valid grove

#

Why are you doing their work?

grave flint
#

they just showed how to express the ratios with the variables

#

they didnt solve it

valid grove
next crater
#

you should guide them

spice grove
#

Right.

#

They legit gave the answer away.

#

Bu forming equations.

valid grove
#

Sorry

safe radishBOT
#

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viral current
#

how do i solve this?

safe radishBOT
#

@viral current Has your question been resolved?

thin bridge
#

you are told that this is an arithmetic sequence

#

can you determine the common difference between consecutive terms?

covert yoke
# viral current how do i solve this?

An "arithmetic sequence" is a sequence that has a common difference. You wrote down a sequence with a common ratio, which is a "geometric sequence."

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viral current
#

.reopen

safe radishBOT
#

viral current
#

is there a way to approach these type of problems

covert yoke
#

Try -18-9n

#

Or -9-9n depending on the indexing (starting from 0 or 1)

viral current
#

ok -18-9n did not work but -9-9n did

covert yoke
#

Think about what happens when you replace n=1,2,3 etc

viral current
#

so u used index 1 instead of 0?

covert yoke
#

If you have n-9, you'll get (-8, -7, -6, -5...)

#

Clearly this isn't the sequence you see.

viral current
#

oh right

covert yoke
#

A good way to approach arithmetic sequences is to see what the common difference is, then use that difference with an offset

#

In this case the common difference is -9

viral current
#

how did u get the offset?

covert yoke
#

Which is why it was a-9n

#

For the offset, because it's one indexed, you have -18 = a - 9n = a - 9(1)

#

Solve for a to get the offfset

viral current
#

gotcha tysm

#

wait uh wdym by "one indexed"

covert yoke
#

In math you generally, but not always start at 1. In computers you generally, but not always start at 0. Because there's a lot of overlap between math and computers, there has been a lot of starting at 0. I find it's nicer in general to start at 0.

#

Alas, not everyone agrees.

safe radishBOT
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@viral current Has your question been resolved?

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warped fulcrum
#

this question has to do with statistics.

I am told to find population mean from this X ~ N(μ; σ2 = 625) and I have no idea how to do it. I get that 625 is standard deviation squared, but how do I find the mean?

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#

@warped fulcrum Has your question been resolved?

plucky elk
#

show the original problem

warped fulcrum
#

ok let me translate it real quick

#

We know that X ~ N(μ; σ2 = 625),

What is the number of subjects so that the width of the 99% confidence interval for measuring blood cholesterol does not exceed: (a) 11; b) 3?

plucky elk
#

you don't need the mean to calculate width

#

take mu to be 0 and you'll still get the right answer

warped fulcrum
#

ok so the question asks me to find the number of subjects when blood cholesterol <=11, when confidence interval is 99% and population variance is 625.

So if I get this straight, I need to find sample size right?

#

but don't I need margin of error to find it?

safe radishBOT
#

@warped fulcrum Has your question been resolved?

warped fulcrum
#

I've tried to use this site to help me find the answer(https://www.statisticshowto.com/probability-and-statistics/find-sample-size/) But even though it has an example of finding a Sample Size Given a Confidence Level and Width (known population standard deviation)

I don't see the width being used in the example.

Sample size definition and how to find one in easy steps Hundreds of statistics videos, how-to articles, experimental design tips, and more!

#

'Example question: Suppose we want to know the average age of an Florida State College student, plus or minus 0.5 years. We’d like to be 99% confident about our result. From a previous study, we know that the standard deviation for the population is 2.9.'

Where is the confidence level width?

warped fulcrum
#

eh whatever, I'll skip this one

#

.close

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dusk solar
safe radishBOT
dusk solar
#

i am just so confused on how to even begin to solve this

#

the way i did it before was completely wrong

bronze prism
#

First of all, the derivative of g is just f

#

That's the fundamental theorem of calculus

#

Put another way, the fundamental theorem of calculus states that for any antiderivative F of f (i.e F'=f), then $\int_a^b f(t)\mathrm{d}t = F(b)-F(a)$

flat frigateBOT
#

Syst3ms

bronze prism
#

In this case, $g(x) = \int_{-1}^x f(t)\mathrm{d}t = F(x)-F(-1)$.

flat frigateBOT
#

Syst3ms

bronze prism
#

When you take the derivative you indeed get g' = f

crisp linden
#

A very fun theorem to prove

#

(actually fun that is)

bronze prism
#

For the first two questions, it's just calculating the area with some good old geometry formulas

#

But remember, the area is signed. If it's under the curve it counts as negative

dusk solar
#

okay so when im finding the first two, i am finding the area between the axis and the function, correct?

#

wait actually

#

im still confused

#

cuz isnt the graph showing f(x) and i need to find g(1)?

#

oh

safe radishBOT
#

@dusk solar Has your question been resolved?

dusk solar
#

.close

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bleak orchid
#

How’s is lim x-> infinity [(a+2)x+b+c/x+d+3/x*2] equal to 4?

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#

@bleak orchid Has your question been resolved?

lean thorn
#

hmmm

#

yeah that limit should be diverging or be infinity

#

Unless there's some information above that was not part of the picture

bleak orchid
#

This is the whole sheet

#

@lean thorn

bleak orchid
#

<@&286206848099549185>

#

.close

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long magnet
#

Can someone please help me solve and understand this? I wasnt at school for the unit and it's homework for tomorrow

long magnet
#

why is it sidewaysss

sharp crane
#

@long magnet oddly worded problem. is x = width and y = girth or the other way around?

long magnet
#

idkkk he didn't specify

#

does it matter?

#

<@&286206848099549185>

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long magnet
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light frigate
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Please don't occupy multiple help channels.

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low nest
#

so if $G$ (with $|G|=p^n m$ and $p$ does not divide $m$) has more than $1$ Sylow $p$-subgroup, then are these subgroups always disjoint (other than the identity)?

flat frigateBOT
low nest
#

i know if n=1 then they are disjoint, but what if n>1?

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@low nest Has your question been resolved?

low nest
#

<@&286206848099549185>

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ionic patio
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rotund prairie
#

Can someone help or guide me in the right direction to do the first question? I have no clue how to start

upper badge
#

you can use identity cos^2(x) + sin^2(x) = 1

#

once you find the values of trig ratios, be sure to give the appropriate sign

#

depending on which quadrant theta is located in

rotund prairie
#

since im just given cos(x) is cos^2(x) just the value squared?

upper badge
#

so, for the 28th ques... when you find cos(theta) youll get a positive value from (-0.886)^2 + cos^2(x) = 1, but you need to add a negative sign

rotund prairie
upper badge
#

looks good

#

find sqrt

#

and let the sign remain positive since its in the 1st quadrant

rotund prairie
upper badge
#

yes

rotund prairie
#

ty ty. Also is there any shortcut to seeing that sin(x) and cos(x) will be the same or do u have to just do it?

upper badge
#

not sure

#

they will be same only when equal to 1/√2 ~ 0.707

rotund prairie
#

oh ok tu so much for the help

#

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timber atlas
safe radishBOT
timber atlas
#

I’m confused on the x-int’s

plucky elk
timber atlas
#

Mm.

#

,tex y=$x^2-2x-3$

flat frigateBOT
#

Jun♾

lilac patio
#

-3=a(x-3)(x+1)

timber atlas
#

So the answer says this

timber atlas
#

Where did the -2 come from here?

#

That’s what I’m confused at

lilac patio
#

factor it out

#

x times x

#

x times 1

#

-3 times x

#

-3 times 1

plucky elk
timber atlas
lilac patio
#

.

#

x times x

#

Is x^2

#

x times 1 is x

#

-3 times x is -3x

#

x-3x=-2x

#

-3 times 1 is -3

#

add it all together

#

x^2-2x-3

#

there's no a value aka stretch factor

timber atlas
#

So basically (x-3)(x+1) and just multiply together

lilac patio
#

yes but you have to multiply every component together

timber atlas
#

Yh

#

Ok I get how you did it

#

Thanks

lilac patio
#

np

#

good luck

timber atlas
#

Thks

#

.close

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candid grove
#

Can someone explain this question?

safe radishBOT
mighty dew
#

example 3?

candid grove
#

Yes

mighty dew
#

ok well what part of the solution dont u understand

#

i feel it would be better for me to explain that

void cosmos
mighty dew
#

um

void cosmos
#

Hello there I am trying to punch in this equation in my calculator

mighty dew
#

let me finish explaining to reet pkls

void cosmos
#

and the answer should be 4.6, however I am doing aomething wrong

candid grove
#

How did they find out the ways letter can be arranged?

void cosmos
#

I see that tour helping Reet, however I feel like that would take a fair bit of time

#

so if you don’t mind sorting out my issue rq that would be nice with all due respect

candid grove
#

I don't understand the underlined part

mighty dew
#

yep reets will takle 30 seconds i understand the concept - but thanks

vocal sun
#

Oh there is a formula

void cosmos
#

alright

mighty dew
#

so reet when you have a question like that the vowels are considered one letter

#

so without the vowels there are 7 letters

vocal sun
#

n!/(d1! * d2! * d3!...) where nis the total number of letters in the word and d1, d2, d3, etc. are letters that repeat more than once in the word

mighty dew
#

thats not the same as what reet is asking?

vocal sun
#

Thats for any permutation of letters

candid grove
#

Okay yes they have put the formula

mighty dew
#

he has a group of letters to be next to each other

vocal sun
#

I know

candid grove
#

I don't understand the last sentance

#

Total number of arrangements in which vowels are always together

mighty dew
#

yes

#

so thats the total number of ways that the letters can be rearranged while having the letters together in one way or another

vocal sun
#

For the combination of vowels, you have 4 vowels, which can be arranged in a line 4! times. I believe the 2! comes from the places in the string of characters where 4 vowels can go but I may be wrong

mighty dew
#

the 2! is for repeats

vocal sun
#

Ahhh

mighty dew
#

so you do the 8!/2! for the original

#

then multiply by arrangements for vowels

#

which also has reapeats as established

candid grove
#

Why did we multiply?

mighty dew
#

bc it can go anywhere in the group of letters (constanants)

vocal sun
#

In 8!/2!2! you did not include the 4 vowels

mighty dew
#

yep^

#

so u must inlclude the arrangements of the 4 vowels by multiplying

candid grove
#

Okay

#

Got it

mighty dew
vocal sun
mighty dew
#

hey u cant help me again rq?

#

u dont know much about logger pro?

vocal sun
#

unfortunately I don't, sorry man ☹️

mighty dew
#

eesh ok all good

safe radishBOT
#

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void cosmos
safe radishBOT
void cosmos
#

how does this work

mighty dew
#

ye

#

which part

#

or do u mean how do u get that answer

safe radishBOT
#

@void cosmos Has your question been resolved?

void cosmos
#

like the way they went from step 2 to 3

#

multiplying

mighty dew
#

it looks wrong to me

#

they should multiply brackets by 7/8

#

then take that from 1

void cosmos
#

hmm?

mighty dew
#

yep i got -1.37

void cosmos
#

how did u solve it

mighty dew
#

so are u using calc

void cosmos
#

yea

mighty dew
#

ok so put 7/8(71+root3505/48)

#

then 1 - ans for above

void cosmos
#

no

#

I want to understand

#

how did they get

#

that 113

#

and - 7

mighty dew
#

oh ok lol

void cosmos
#

ye

mighty dew
#

bro i have no idea

#

the 7 obv multiplies to the root3505

#

but the 113 no idea

void cosmos
#

same

mighty dew
#

do u understand my othr working tho

#

like how to do it

safe radishBOT
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bronze moth
safe radishBOT
quasi bison
#

well you've highlighted the leading entries

#

now you just need to tick the checkboxes for their coordinates

#

is that something that's giving you trouble?

bronze moth
#

lmao

#

i am dumb

#

@quasi bison Thanks

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.close

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lean otter
#

what are geometric means

safe radishBOT
lean otter
#

<@&286206848099549185>

safe radishBOT
#

@lean otter Has your question been resolved?

safe radishBOT
#

@lean otter Has your question been resolved?

mortal meteor
#

@lean otter the geometric mean of two numbers a and b is $\sqrt{a \cdot b}$

flat frigateBOT
#

Alexander42

lean otter
#

oh

#

ty

simple radish
#

I'm not entirely sure that is helpful in this problem

tidal imp
lean otter
#

an hour and a half pasted, I figured everything out

tidal imp
#

oh ok good

#

What’s your answer

lean otter
#

b

tidal imp
#

That’s right

lean otter
#

yup

#

now

#

how do I find the perimeter of a triangle with 1 side and 3 angles given

mortal meteor
#

use that the angles are very special. You might think about ||how you can fit it into an equilateral triangle||

safe radishBOT
#

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maiden tartan
#

Hello, I have a theory question. Is it possible for a formula to exist that for any complex function will yield all derivatives of that function?

maiden tartan
#

Or maybe better stated, can a function exist for any coords (x,y,z) that can yield (x,y,z,t) where t = z if you can bound it to another function that contains all possible paths for (x,y,z)?

potent bay
#

all derivatives?

maiden tartan
#

position and momentum.

#

Is how I'm thinking about it anyway, I don't know the math speak equivalent.

potent bay
#

i dont rly understand ur Q, but im pretty sure the answer is no

#

i mean that A formula exists for ANY function seems surreal

maiden tartan
#

I'm sorry I don't know how to ask it better. Perhaps not a single formula, but a formula that will give you all potential formulas is a better way to say it.

#

Is it possible for me to post an image to help illustrate?

potent bay
#

i dont know if its possible to you, but the option is given to anyone 😄

maiden tartan
#

d'oh -- sorry I'm a discord newb, I thought it was restricted.

#

For any complex function can I draw another version of it that yields more information about that shape in polynomial time?

#

Then, using this magically function, turn that image, into it's derivatives:

#

would be the derivatives of the smoothest line in the first picture.

#

If I can ensure that every point is bound to some other know it all function:

#

<@&286206848099549185>

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