#help-23
1 messages · Page 469 of 1
What is -2 + 2
0
2
yes
What can we do now?
you are learning calculus even though you cant solve simple equations? 🤔
Could you write the equation in words?
dude please don’t judge me
i have really bad difficulties with math
Ignore him, do this
what do u mean by that?
two x equals two
What sort of operation is that?
i wouldnt know
What are we doing with the numbers 2 and x?
Not quite
Let's step back a bit
I want you to read this equation out loud:
3(5) = 15
three times five equals fifteen
times ?
you multiply
Yes!
Yeah x is 1
ohhhhh ok
i see
and so my final answer would be
2(1)=2?
or
something like that?
hang on
wait i don’t understand one part
2x-2 = 0 but 2•1 is 2
so why 0
oh wait
i think i see
no wait h
hang on i am confusing myself one second
ahhh ok
i get it now
ok so far so good
Yes. Now when is 2x-2 greater than 0?
If 2x-2 = 0, then x = 1
yes
So then if 2x - 2 > 0, then?
Yeah we already solved that. We know when 2x-2 is 0. But now we want to find when it's greater than 0
2x - 2 + 2 > 0 + 2?
times? you there? 🥲
anyone else who can help?
<@&286206848099549185> any one of you guys? 😅🥲
@broken ether Has your question been resolved?
idk how to continue
we multiply by a POSITIVE real c
we have that a>b is equivalent to ac>bc
here 2x>2
we multiply by the positive number 1/2
we get x>1
o oops
this is so confusing
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✅
$2x>2 \iff 2(1/2)x>2(1/2) \iff x>1$
HUUH
Hwai
i don’t understand so completely why we do 1/2
to cancel the 2?
Because knowing things about 2x is weird, it's much more convenient to know things about just x
wait how come the original question equality
is that a question
yes
idk what u are asking
Let's take it from the start
kk
We know that f(x) is increasing if and only if f'(x) ≥ 0
well anyway f(x) is monotonically increasing on the interval [1,+inf)
(the equality case isn't really relevant here, but let's include it for completeness's sake)
okay
However f'(x)=2x-2, so we want to know for which x (and not for which 2x or 3x or whatever) we have 2x-2 ≥ 0
When 2x-2 ≥ 0, f'(x) ≥ 0 so f is increasing
When 2x-2 ≤ 0, f'(x) ≤ 0 so f is decreasing
ok i understand that
So then the question is : for which x do we have 2x-2 ≥ 0
Now, the first golden rule is that you can add anything to both sides of an inequality
what’s an inequality?
a ≤ b is an "inequality", it's a way of saying how a and b compare to one another
In this case "a ≤ b" means that "a is less than or equal to b"
For example, 1 ≤ 3 because 1 is less than 3
Ah ok
But it's also true that 1 ≤ 1, because the definition is "less than or equal to"
If we write a < b, we remove that "or equal to" part
It's called a strict inequality
When the symbols go the other way, so does the relation
a ≥ b means "a is greater than or equal to b"
a > b means "a is greater than b (and not equal)"
I see
perhaps a better word for "inequality" would be "comparison", because that's really what we're doing here
Now, let's use a simple example to make obvious the various transformations you can do to an inequality
Let's compare my amount of money (written a) with my neighbor's (written b)
Think of them as bank balances, so they can actually go negative
kk
I have strictly more money than my neighbour (written a ≥ b), then that won't change as long as we both receive (or lose) the same amount of money
If we both receive a million bucks (it's our lucky day), I will still have more money than him (it's a bit less flagrant, but it is still true, and that's all we care about)
If we both lose 100 (an unluckier day), the same will be true
Now, to put this everyday obviousness in mathematical terms
If a ≥ b, then it stays true as long as we add the same amount to a and b
If we write that added quantity c (which may be negative, like when we lose money instead of gaining it), then we can write this as a+c ≥ b+c
Follow so far?
Yes
This property is sometimes pompously called "translation invariance" or "shift invariance"
Because as long as you shift or translate both quantities by the same amount, inequalities stay the same
(note that this is also true of equalities)
Ah
and it's even more trivial in that case
If two things are the same, they stay the same as long as you do the same operations to each of them, because, well... they're... the same.
Although it would be nice, the same thing isn't true of inequalities, and as such we have to be a bit more precise
Now, in a very similar fashion to solving equalities/equations where we have a quantity that we don't know
A good rule of thumb is to isolate that quantity on one side of the inequality
Hence, suppose you know 2x-2 ≥ 0 and you want to only have x on the left side : what do you need to add to both sides to achieve that?
2?
wait can you add negatives
Yes
but in case you feel confused with what you heard before, they were talking about multiplying by negatives, not adding them
ah wait
And yes, 2 is the right answer
You get 2x-2+2 ≥ 0+2, which simplifies to 2x ≥ 2
Now we're getting somewhere
Right, so now we'll discuss multiplication with inequalities
(by the way, if you can't type ≤ and ≥, the standard way to write them on keyboards is <= and >= )
Now, let's also make some obvious observations and deduce mathematical generality
ah ok
I still have more money than my neighbour in this scenario. If both me and my neighbour's bank accounts get doubled, then I will still have more money than them.
Mathematically, if a ≥ b then 2a ≥ 2b
But it's also true in the other direction. If both of our accounts get halved, I still have more money than them.
(you can see it as the "reverse" step of doubling, which conserved the inequality)
So a/2 ≥ b/2
In fact, this is true for any positive constant
No matter how small or how big
if c > 0, then ac ≥ bc
In our case, from 2x ≥ 2 we want to really isolate the x, so we want to get rid of that pesky factor of 2
So we multiply by 1/2 because 2*1/2=1
Thus, (1/2)*2*x ≥ (1/2)*2. Simplifying, we get x ≥ 1.
But before i go (gotta eat), a final remark about negative factors
if the multiplicative constant is 0, it's kinda boring
because a*0=b*0=0
But if it's negative, things get flipped around
ahh
If i have 1000 and my neighbor has 900, and somehow our accounts get turned into negatives (i.e multiplied by -1), then I have -1000 and my neighbour has -900
But notice, -1000 is less than -900
Because it's further out in the negatives
Here, the general rule is that if c < 0 (negative !!) and a ≥ b, then ca ≤ cb (crucial ! notice how the inequality sign has been flipped !)
In other words, multiplying by negative numbers flips inequalities.
Right, now I have to go, I'll let this sink in
I'm back, if you have any questions don't hesitate
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can anyone confirm my answer of 19/12
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How I can do integral for this 1 ??
,rotate
Wt is this xd
Oh k
Nice bot ;-;
Can u tell me step by step cuz I actually forgot how to do integral for this
sub sqrt(1-2x)
@covert fiber Has your question been resolved?
<@&286206848099549185>
substitution
Is that the result or wt ?
What is “u” xd
you just make it as a temporary variable
This calculus video tutorial provides a basic introduction into u-substitution. It explains how to integrate using u-substitution. You need to determine which part of the function to set equal to the u variable and you to find the derivative of u to get du and solve for dx. After replacing all x variables with u variables, find the antideriva...
There is other way right ?
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need help with the parametrization
@devout frigate Has your question been resolved?
<@&286206848099549185>
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.colose
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Why is the answer E? As far as I can recall, the derivative should be $e^{x+x^2}(2x)$, and so at $x=1$ we get $2e^2$
cgodfrey
My recollection is that $\frac{\mathrm d}{\mathrm dx}\left(\int_{f(x)}^{g(x)}h(t),\mathrm dt\right)=h(g(x))g'(x)-h(f(x))f'(x)$
cgodfrey
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<@&286206848099549185>
You missed product rule
@winter fern Has your question been resolved?
Where is the product rule coming from? Isn't it just $e^{x+x^2}$ times the derivative of $x^2$?
cgodfrey
Nope. Factor out an e^x from the integrand outside the integral
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@lean otter Has your question been resolved?
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are those two linear mappings surjective?
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can anyone tell me what should I do next
Idk how to compute the partial 4n times thing
And I am not sure am I on the right track
Use the hint. The coefficient of $x^{2n} y^{2n}$ in the Taylor expansion about $0$ of $f$ is given by that partial derivative times $\dfrac{1}{(2n)!^2}$
1345631
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i dont get how the first asymptote is -3pi/4
the answer sheet showed that the first one is -3pi/4
but i dont get how that is -3pi/4
it looks like -pi/4
range?
what is the domain of that
i didnt learn how to find the domain from the function sry
otherwise there are infinitely many asymptotes
this is the answer
so what you’re saying isn’t much,
this is just a graph transformation question
yes
pi is the translation, and 2x is the stretch of 1/2 on the x
i dont get anything u say sorry
ok
yes
It’s got infinitely many asymptotes
yeah
so!
*?
there is still not first or last
oh wait
look
that doesnt do anything
lol ok
you need a domain
ok
do you get why
yes
it doesnt specify
it should in theory
anyways, back to what I was saying
you can do general case
i dont know what that is
whenever cos(x) = 0
ok
yes
yeah
ok thanks
pi/2 even
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hi guys I need help, I'm French and I have a hot exercise. The question of the exercise is: For what value x is the area of rectangle 1 equal to the area of rectangle 2? ( solve this problem using an equation ) , rectangle 1 has a width of 5 and the length is 3 x + 1 and rectangle 2 has a width of 4 x and a length of 6, thank you for helping me as soon as possible I have difficulties in mathematics 🙂
we can show the area for the first one as this
5(3x+1)
and that is equal to the rectangle 2 area
which is 6(4x)
so we can show this equation like this
5(3x+1)=6(4x)
and you can solve that right?
ah okay thanks but suddenly for part 5 (3x + 1) we have to perform the double distributivity?
yep
yw
A = (3x+1)×5=4x×6
A = 5 x 3x + 5 x 1 = 4x x 6
A = 15x + 5 = 24x
A = 15x + 5 - 15x = 24x - 15x
A= 5 = 9x
A= x = 9/5
is that the result?
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Prove the identity 1/cosθ - cosθ/1+sinθ = tanθ
cosθ?
LCM
or 1
because i know at some point tanθ= sinθ/cosθ will help
but if you say i should use Sin²x +Cos²x=1
Yup, for the final step but let's go step by step for now
so i take lowest common multiple first
First take the LCM
Yup
And tell me what's the numerator you get
i just don't understand how you use lcm here to be honest
1-cos²(θ) +sin (θ) / (1+sin(θ)) cos(θ)
Yup you're right
Now in the numerator, instead of writing 1
Change it to sin²θ + cos²θ
sin(θ) / cos (θ)
Got it?
this is step by step?
What do you mean?
Replace 1 by what I wrote and you'll see your answer
Be back in 10 mins
ok
sin²θ + cos²θ-cos²(θ) +sin (θ) / ( sin²θ + cos²θ+sin(θ)) cos(θ)
@limber patio
<@&286206848099549185>
i think my man just has better shit to do
it's understandable though
thank you for the help up until now
i shall patiently wait for your return
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Hello guys, i have a problem :
I have : (u - a.idE) ° (u - b.idE) = 0 (L(E)), u is linear
With a =/ b
And my first question is to prove that a or b is a eigenvalues
It was easy
But the second one is to proove that
If u is not a homotheties, a and b are eigen values of u
I don’t know how to process
(I don’t speak fluently English, so sry for the potential error)
So i have to demonstrate this :
u is a homothety => a and b are not eigen values of u
$(u - a.Id_E) \circ (u - b.Id_E) = 0_{L(E)}$
Pako
I don’t know if i have to post in advanced math or not
<@&268886789983436800> could you guide me pls
Is it the appropriate channel ?
#linear-algebra might be better
Thx, but i can’t write
Oh sry, i can
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Would someone please tell me what I have done wrong? 😀
@gray plaza can't. Don't actually know what you're supposed to be doing
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I have to do integration of that function.
But the answer I received doesn't match with the correct answer.
So, I am wondering what I have done wrong.
nothing wrong
@gray plaza Has your question been resolved?
In video the answer is shown as :
HAHAHAHA
you made it way more complicated like doing ibp for xe^(x^2)
normally
your answer should be equal to that
check it by a calculator
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my online school has very outdated videos to "explain" equations and i don't understand how to do this
Do you know the inscribed angle thereom and understand how it works?
not at all
Ah
yes i believe so
And you know the measure of arc ED :)
ED is 52*
So, the inscribed angle thereom states...
idk the thereom
Ah
yeah...
Draw a diagram of an inscribed angle then :)
oh wait isn't the arc 2x the angle so c is 26?
Yep :D
Mhm!
how about fiunding BSD?
Instead of directly finding BSD...
What other angle can we find that helps with the problem?
Ah I missed that LOL
lol
I found it by using another thereom
what formula can i use to get s?
Like the one that says CSB = 57 x 2 + 52 / 2
for triangle BSD
Well the sum of the angles of a triangle are 180
So you're basically done with the problem! :D
Yeah it can be difficult sometimes :D
s=97
ty for the help!
yw!
how do i close this?
.close?
.close
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How can i make *1 summation skip the term when k = *2
@urban shore Has your question been resolved?
for this problem it'll probably be easier to just write out every term
but https://tex.stackexchange.com/questions/80460/expression-under-summation-on-multiple-lines shows how to do it
@urban shore Has your question been resolved?
You can use a (1 - delta_k2) where delta is the dirac delta function.
This will give you 1 on all k not equal to do, and 0 when it does.
$\sum_{k=1}^4 (1 - \delta_{k2}) \left(k - \left(\frac1{2}k - 1 \right) \right)$
OmnipotentEntity
sorry, not dirac delta, that's the kronecker delta. https://en.wikipedia.org/wiki/Kronecker_delta
In mathematics, the Kronecker delta (named after Leopold Kronecker) is a function of two variables, usually just non-negative integers. The function is 1 if the variables are equal, and 0 otherwise:
or with use of Iverson brackets:
where the Kronecker delta δij is a piecewise function of variables i and j. For example, δ1 2 = 0, whereas δ3 3 =...
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I need help to show that $\frac{2n+1}{(2n+2)^2}<\frac{1}{2n+3}$ for all n≥1
Goose on a Moose
what have you tried, what is the method you want to use?
Besides graphing it on desmos to convince myself that it is true, I'm stuck on the first step haha
Here's a hint: maybe it is easier to show that $\frac{1}{(2n+2)^2}<\frac{1}{(2n+1)(2n+3)}$
dackid
try showing $\frac{1}{2n+3}-\frac{2n+1}{(2n+2)^2}$ is positive
Zybikron
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Good luck goose
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i am 99% sure that both b and c needs to have the angle but i cant seem to find it
like the equation is supposed to be 1/2sin^-1((gx)/v^2) or something like that
but then i get this which isnt even an answer choice
@runic socket Has your question been resolved?
<@&286206848099549185>
<@&286206848099549185>
@runic socket Has your question been resolved?
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how do you determine if a function is continious on a given value of X
@floral wasp Has your question been resolved?
take the limit of the function at both sides.
In this section we will introduce the concept of continuity and how it relates to limits. We will also see the Intermediate Value Theorem in this section and how it can be used to determine if functions have solutions in a given interval.
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This is a binary operation right?
You are asking in terms of group theory?
If yes then operate A-¹ on both sides
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hey what’s newton’s method for
By newton’s method I assume you mean newton’s method of approximation
ig? what’s that
how does it work, why does it work and what do i need it for :>
okay maybe one at the time
What do i need Newtons method of approximation for?
You can look it up on Wikipedia - that page is pretty helpful @lean otter
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How long will it take for an investment of 1100 dollars to grow to 6900 dollars, if the effective rate of interest is 6.2 percent? (Assume compound interest at all times.)
Anwer in years
I originally got 29.6 years as I used the monthly compound formula but I am not sure if that's correct
can you show how you got it?
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Can anybody help me on this question
$\frac {x-6}{y-6} =\frac 1 2$
Deep.
$\frac {x-14}{y-14} =\frac 2 5$
Deep.
Ohh
you should guide them
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how do i solve this?
@viral current Has your question been resolved?
you are told that this is an arithmetic sequence
can you determine the common difference between consecutive terms?
An "arithmetic sequence" is a sequence that has a common difference. You wrote down a sequence with a common ratio, which is a "geometric sequence."
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✅
i tried n-9 and n+9 but its still wrong
is there a way to approach these type of problems
ok -18-9n did not work but -9-9n did
Think about what happens when you replace n=1,2,3 etc
so u used index 1 instead of 0?
If you have n-9, you'll get (-8, -7, -6, -5...)
Clearly this isn't the sequence you see.
oh right
A good way to approach arithmetic sequences is to see what the common difference is, then use that difference with an offset
In this case the common difference is -9
how did u get the offset?
Which is why it was a-9n
For the offset, because it's one indexed, you have -18 = a - 9n = a - 9(1)
Solve for a to get the offfset
Meaning that counting for n starts at 1.
In math you generally, but not always start at 1. In computers you generally, but not always start at 0. Because there's a lot of overlap between math and computers, there has been a lot of starting at 0. I find it's nicer in general to start at 0.
Alas, not everyone agrees.
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this question has to do with statistics.
I am told to find population mean from this X ~ N(μ; σ2 = 625) and I have no idea how to do it. I get that 625 is standard deviation squared, but how do I find the mean?
@warped fulcrum Has your question been resolved?
not enough information given
show the original problem
ok let me translate it real quick
We know that X ~ N(μ; σ2 = 625),
What is the number of subjects so that the width of the 99% confidence interval for measuring blood cholesterol does not exceed: (a) 11; b) 3?
you don't need the mean to calculate width
take mu to be 0 and you'll still get the right answer
ok so the question asks me to find the number of subjects when blood cholesterol <=11, when confidence interval is 99% and population variance is 625.
So if I get this straight, I need to find sample size right?
but don't I need margin of error to find it?
@warped fulcrum Has your question been resolved?
I've tried to use this site to help me find the answer(https://www.statisticshowto.com/probability-and-statistics/find-sample-size/) But even though it has an example of finding a Sample Size Given a Confidence Level and Width (known population standard deviation)
I don't see the width being used in the example.
'Example question: Suppose we want to know the average age of an Florida State College student, plus or minus 0.5 years. We’d like to be 99% confident about our result. From a previous study, we know that the standard deviation for the population is 2.9.'
Where is the confidence level width?
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i am just so confused on how to even begin to solve this
the way i did it before was completely wrong
First of all, the derivative of g is just f
That's the fundamental theorem of calculus
Put another way, the fundamental theorem of calculus states that for any antiderivative F of f (i.e F'=f), then $\int_a^b f(t)\mathrm{d}t = F(b)-F(a)$
Syst3ms
In this case, $g(x) = \int_{-1}^x f(t)\mathrm{d}t = F(x)-F(-1)$.
Syst3ms
When you take the derivative you indeed get g' = f
For the first two questions, it's just calculating the area with some good old geometry formulas
But remember, the area is signed. If it's under the curve it counts as negative
okay so when im finding the first two, i am finding the area between the axis and the function, correct?
wait actually
im still confused
cuz isnt the graph showing f(x) and i need to find g(1)?
oh
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How’s is lim x-> infinity [(a+2)x+b+c/x+d+3/x*2] equal to 4?
@bleak orchid Has your question been resolved?
hmmm
yeah that limit should be diverging or be infinity
Unless there's some information above that was not part of the picture
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Can someone please help me solve and understand this? I wasnt at school for the unit and it's homework for tomorrow
@long magnet oddly worded problem. is x = width and y = girth or the other way around?
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Please don't occupy multiple help channels.
@light frigate Has your question been resolved?
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so if $G$ (with $|G|=p^n m$ and $p$ does not divide $m$) has more than $1$ Sylow $p$-subgroup, then are these subgroups always disjoint (other than the identity)?
Beous
i know if n=1 then they are disjoint, but what if n>1?
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Can someone help or guide me in the right direction to do the first question? I have no clue how to start
you can use identity cos^2(x) + sin^2(x) = 1
once you find the values of trig ratios, be sure to give the appropriate sign
depending on which quadrant theta is located in
since im just given cos(x) is cos^2(x) just the value squared?
so, for the 28th ques... when you find cos(theta) youll get a positive value from (-0.886)^2 + cos^2(x) = 1, but you need to add a negative sign
Thats question 27. Does that look right? If so what do I do now?
looks good
find sqrt
and let the sign remain positive since its in the 1st quadrant
Ty so is this it?
yes
ty ty. Also is there any shortcut to seeing that sin(x) and cos(x) will be the same or do u have to just do it?
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I’m confused on the x-int’s
plot them?
Jun♾
-3=a(x-3)(x+1)
So the answer says this
Ok i see
Where did the -2 come from here?
That’s what I’m confused at
this is smarter
Still confused here
.
x times x
Is x^2
x times 1 is x
-3 times x is -3x
x-3x=-2x
-3 times 1 is -3
add it all together
x^2-2x-3
there's no a value aka stretch factor
So basically (x-3)(x+1) and just multiply together
yes but you have to multiply every component together
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Can someone explain this question?
example 3?
Yes
ok well what part of the solution dont u understand
i feel it would be better for me to explain that
um
Hello there I am trying to punch in this equation in my calculator
let me finish explaining to reet pkls
and the answer should be 4.6, however I am doing aomething wrong
How did they find out the ways letter can be arranged?
I see that tour helping Reet, however I feel like that would take a fair bit of time
so if you don’t mind sorting out my issue rq that would be nice with all due respect
yep reets will takle 30 seconds i understand the concept - but thanks
Oh there is a formula
alright
so reet when you have a question like that the vowels are considered one letter
so without the vowels there are 7 letters
n!/(d1! * d2! * d3!...) where nis the total number of letters in the word and d1, d2, d3, etc. are letters that repeat more than once in the word
thats not the same as what reet is asking?
Thats for any permutation of letters
Okay yes they have put the formula
he has a group of letters to be next to each other
I know
I don't understand the last sentance
Total number of arrangements in which vowels are always together
yes
so thats the total number of ways that the letters can be rearranged while having the letters together in one way or another
For the combination of vowels, you have 4 vowels, which can be arranged in a line 4! times. I believe the 2! comes from the places in the string of characters where 4 vowels can go but I may be wrong
the 2! is for repeats
Ahhh
so you do the 8!/2! for the original
then multiply by arrangements for vowels
which also has reapeats as established
Why did we multiply?
bc it can go anywhere in the group of letters (constanants)
In 8!/2!2! you did not include the 4 vowels
thanks for the help bro
no problem
unfortunately I don't, sorry man ☹️
eesh ok all good
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jimmy
@void cosmos Has your question been resolved?
how do u get the answer
like the way they went from step 2 to 3
multiplying
hmm?
yep i got -1.37
how did u solve it
so are u using calc
yea
oh ok lol
ye
same
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well you've highlighted the leading entries
now you just need to tick the checkboxes for their coordinates
is that something that's giving you trouble?
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what are geometric means
<@&286206848099549185>
@lean otter Has your question been resolved?
@lean otter Has your question been resolved?
@lean otter the geometric mean of two numbers a and b is $\sqrt{a \cdot b}$
Alexander42
I'm not entirely sure that is helpful in this problem
If you don’t know the Geometric Mean Theorem for right triangles, I would go back to proportions of similar triangles
an hour and a half pasted, I figured everything out
b
That’s right
use that the angles are very special. You might think about ||how you can fit it into an equilateral triangle||
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Hello, I have a theory question. Is it possible for a formula to exist that for any complex function will yield all derivatives of that function?
Or maybe better stated, can a function exist for any coords (x,y,z) that can yield (x,y,z,t) where t = z if you can bound it to another function that contains all possible paths for (x,y,z)?
all derivatives?
position and momentum.
Is how I'm thinking about it anyway, I don't know the math speak equivalent.
i dont rly understand ur Q, but im pretty sure the answer is no
i mean that A formula exists for ANY function seems surreal
I'm sorry I don't know how to ask it better. Perhaps not a single formula, but a formula that will give you all potential formulas is a better way to say it.
Is it possible for me to post an image to help illustrate?
i dont know if its possible to you, but the option is given to anyone 😄
d'oh -- sorry I'm a discord newb, I thought it was restricted.
For any complex function can I draw another version of it that yields more information about that shape in polynomial time?
Then, using this magically function, turn that image, into it's derivatives:
would be the derivatives of the smoothest line in the first picture.
If I can ensure that every point is bound to some other know it all function:
<@&286206848099549185>
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