help-23

[broken yew]

(-2)(-3) = 6
1 - 12 + 12 = 1

[tawdry salmon]

$x^2+x-6$

[flat frigate]

geoxcaliber

[tawdry salmon]

nvm you don't plug it into this one

$(x-2)(x+3)$

[flat frigate]

geoxcaliber

[broken yew]

Im just saying for a quick mistake check.

[tawdry salmon]

sorry I'm lost

$-2x^3(x+3)^2$

[flat frigate]

geoxcaliber

[tawdry salmon]

so I did x^2 and 3^2 = 9 in the top then -2x^3 in the left

ohh am so stupid

$-2x^5 - 18x^3$

[flat frigate]

geoxcaliber

[tawdry salmon]

Ok I get it better now, thanks a lot. My main confusing point was the fact that x = (x - 0)

[tawdry salmon]

so how would I check my expansion is correct in this one?

put 1 into each x?

[broken yew]

.

I mean thats not guaranteed to check if its correct

its just checking if its wrong.

[broken yew]

this looks incorrect.

[broken yew]

if ur doing this

[safe radish]

@tawdry salmon Has your question been resolved?

[broken yew]

bruh

[tawdry salmon]

so does that mean doing x^2 and + 9 is wrong?

[broken yew]

your (x+3) squared

is big wrong

$$(1+3)^2 \neq 1^2 + 3^2$$

[flat frigate]

Shuri2060

[tawdry salmon]

What would it equal?

ohh lol

wait no

but (x)^2 = x^2

[broken yew]

$$(a+b)^2 \neq a^2 + b^2$$

[flat frigate]

Shuri2060

[broken yew]

You realise this right?

Where have all the middle terms gone

[tawdry salmon]

does it equal

$$(a+b)^2 = a + b^2$$

[flat frigate]

geoxcaliber

[broken yew]

???????

bruh 🤦

[tawdry salmon]

lmao

[broken yew]

Really - practice these expansions

expansion of factors

And get a better method

[tawdry salmon]

so what would it be?

ohh lmao

do you add the two things in parenthesis first

[broken yew]

idk, look up videos

how to multiply out brackets

[tawdry salmon]

this shit is so confusing

[broken yew]

just look up a video how to multiply out brackets

cus this aint working for you clearly

[broken yew]

how is -2 times 3 -9

[tawdry salmon]

I think I read the 2 as 3

but it's supposed to be 9 right

(x+3) = 3x

(3x)^2 = 9x^2

[broken yew]

??????????????????

[tawdry salmon]

im gonna get an algebra book and just start algebra from over lmao

[broken yew]

(x+3) = 3x

what is this?????/

Yes, you need to start basic algebra again

[tawdry salmon]

is it wrong

[broken yew]

yes

wrong

bruh

[tawdry salmon]

you can't add x and 3?

[barren rose]

3x is 3 times x

x+3 is x plus 3

what is the question again? the discussion is super long lol

[tawdry salmon]

$-2x^3(x+3)^2$

[flat frigate]

geoxcaliber

[tawdry salmon]

trying to factor this

I did

$$(a+b)^2 \neq a^2 + b^2$$

[flat frigate]

geoxcaliber

[tawdry salmon]

so if that doesn't work I turned to PEMDAS, which has parenthesis first so I attempted adding the two

so if neither that or this doesn't work

$$(a+b)^2 = a + b^2$$

[flat frigate]

geoxcaliber

[tawdry salmon]

I have no clue

oh

so it's just

[barren rose]

this equation is wrong

[tawdry salmon]

$$(x+3) (x+3)$$

[flat frigate]

geoxcaliber

[barren rose]

first of all the equation(first one) is wrong

$$(a+b)^2 = a^2 + 2ab + b^2$$

[flat frigate]

blackmamba[they/them]

[barren rose]

I don't remember factoring too much but I think the best thing to do right here is to open the brackets

either through calculating (x+3)^2 via the equation I posted

or calculating it via $-2x^3(x+3)(x+3)$

[flat frigate]

blackmamba[they/them]

[tawdry salmon]

I see

well all imma say is I hate algebra :/

that one has nothing to do with this right

Oh I see, nevermind. I had notes on this "square of a binomial" which calculates like you said

[barren rose]

no

you don't need cube ones here

calculate $(x+3)^2$ via the equation I gave you

[flat frigate]

blackmamba[they/them]

[barren rose]

then open the brackets by multiuplying each element with $-2x^3$

[flat frigate]

blackmamba[they/them]

[tawdry salmon]

Okay, thanks

by the way, when you do this, does (a+b) count as the factor?

[barren rose]

probably yes but don't think you're gonna get to that

you'll get a cube but the factor won't look like that

[tawdry salmon]

oh ok

is it because a factor is supposed to look like x - 5 and that looks like 3 -/+ 5? (a + b)

[barren rose]

not sure what you're talking about

try doing what I suggested and come w/ an answer

[tawdry salmon]

for this, to get the root of x - 2 do you do
x - 2 = 0
x = 2
or
x + 2 = 0
x = -2

[barren rose]

the root?

you mean the limit

or like

not limit

[tawdry salmon]

it's called zero, x-intercept, solution (of a function)

[barren rose]

an intercept is when the lines reach the x or y axis

that;'s when the entire equation equals 0

(for x-intercept)

not the root, that's where the function is undefined

[tawdry salmon]

teacher's notes

[barren rose]

notice

f(r)=0

[barren rose]

your equation here is (x^3 + 5x^2 -3x + 6) / (x-2)

in other words

to find r... you need to find an x such that f(x) = 0

or (x^3 + 5x^2 -3x + 6) / (x-2) = 0

2 is NOT a root here

2 is undefined

[safe radish]

@tawdry salmon Has your question been resolved?

Channel closed

Closed by @tawdry salmon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lean otter]

im solving for tan2x

where sinx is 4/radical 19

is the answer positive or negative

when i plug that expression in the calculator, it says negative

but this is in quadrant 1

so is the answer positive?

this is the formula i used

this is what it says in the calculator

[safe radish]

@lean otter Has your question been resolved?

[safe radish]

@lean otter Has your question been resolved?

Channel closed

Closed by @jovial robin

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[slim urchin]

can someone explain why i am getting the critical point wrong?

it is meant to be -3/2 but i got 0 and -5/3

[broken yew]

cant read the q

[slim urchin]

i can send it in enlarged peices

1 sec

[broken yew]

can u just write it

Find the point

on

the

line

[slim urchin]

yep

[broken yew]

that is closest to

to what?

[slim urchin]

find the point on the line y=3x+5 that is closest to the origin

[broken yew]

ok

by the way

critical point

has a different meaning

so avoid using that

i was confused

[slim urchin]

should i say critical values in stead?

sorry

[broken yew]

no, avoid critical

[slim urchin]

or just zeroes of the first derivative?

[broken yew]

wait what

ok ignore me

i just assumed from your picture we were doing a linear function lmao

didnt actually read

[slim urchin]

thats okay 🙂

[broken yew]

wait but

no im still confused lmao

we are just doing it for

y=3x+5

right

[slim urchin]

yes i think so

its an optimisation problem

[broken yew]

i dont get where all that math comes from

i think it can be done a lot simpler than that?

oh i see,

ur finding the circle which is tangent to it

[slim urchin]

ahh im not sure, this is from organic chemistry tutor. i am practicing optimisation problems

he used this as an example

it is a common optimisation problem it hink

[broken yew]

well alright

i feel like basic trig should get u answer

but i can check your way as well

[slim urchin]

i mean i am watching him do it

it all seemed fine until the critical point'

[broken yew]

just gonna try it this way first to check

https://i.imgur.com/PAUYzYC.png

hyp = 5sqrt10/3

sqrt10 is ratio

1/6-5/3

yh so i get x = -3/2

Then calculus way 🤔

[slim urchin]

im so confused haha

[broken yew]

I think i found it

its

2x + ....

not multiply?

or wait

[slim urchin]

i am thinking he has made a mistake

[broken yew]

yh thats it

the answer is x = -3/2 for sure

[slim urchin]

thats so weird no one pointed it out

[broken yew]

here is the mistake

[slim urchin]

in the comment section

[broken yew]

?

[slim urchin]

wait nvm its me who made a mistake

give me a second

oh yeah

that makes sense

thank you :3

[broken yew]

way quicker with geometry lol

[slim urchin]

ahh yeah...

i am trying to practice optimisation problems though

[broken yew]

oh ic

so the video just chose this example

[slim urchin]

thanks for the help

yeah i think so

yeah il close channel

.close

[safe radish]

Channel closed

Closed by @slim urchin

Use .reopen if this was a mistake.

[slim urchin]

you can just use the channel

i just closed it so it doesnt have my name on it anymore

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ancient escarp]

<@&268886789983436800> (posting in all channels)

[hot thistle]

.close

[safe radish]

Channel closed

Closed by @hot thistle

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[peak jetty]

What does it mean by a>1?

[latent flume]

That a is greater than 1

[peak jetty]

Yeah but why does it mention it in the question

It has no use or am I wrong?

<@&286206848099549185>

[latent flume]

It’s so that the denominator will never be negative

[peak jetty]

But why does that matter?

[hot thistle]

because if it was you'd need to change the direction of the inequality

[peak jetty]

Oh

So let’s say a<-1

[peak jetty]

How would we do this equation to solve for x

[hot thistle]

probably the same way

but when dividing by 3a-2

you flip the inequality

side it would be negative

[peak jetty]

So can we write this equation -ax<=2x+1/3 if it was a<-1

Then solve for x

?

[hot thistle]

I believe so

[peak jetty]

Ahh ok

Makes more sense to me now

Cheers Danny devito

.close

[safe radish]

Channel closed

Closed by @peak jetty

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ancient escarp]

what exactly is your goal here

[bronze rivet]

I think they wanna factor it

[lean otter]

yep

im confused how to

[ancient escarp]

p/q

[lean otter]

oh?

is it not grouping factoring

[ancient escarp]

uhm

[lean otter]

why r u saying uhm

use ur words

yes or no question

how do u know when to use p/q

cuz theres also a grouping fcoting method

[ancient escarp]

lmfao calm down chief i'm trying to see if i can factor this by grouping

[lean otter]

where u group it by 2 and 2

or 3 and 1

or 1 and 3

ok

[ancient escarp]

yes i'm aware of what factoring is lmao

[lean otter]

k

[ancient escarp]

i'm not sure you can

[lean otter]

yea

well how do u know when to use p/q

[ancient escarp]

when other methods fail

[lean otter]

k.

thanks.

.close

[safe radish]

Channel closed

Closed by @tough wind

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[meager chasm]

hi

[meager chasm]

suppose t ∈ (0, 1)

for any x, y ∈ R, if x < y, why is x < tx + (1 - t)y < y true?

[inner tapir]

this is kind of like a one-dimensional bezier curve

you can think of it like having some percent of x added to some percent ofy
that percent will always be between 0 and 100

[meager chasm]

bezier curve??

[meager chasm]

isn’t this supposed to be elementary algebra

i’ve been told it is

[inner tapir]

sorry didn't mean to scare you; some people are familiar, you use them a lot in like paint applications

you can ignore it tho

[meager chasm]

what ways do i have to prove this

currently in calc 1

[inner tapir]

are you asked to prove this, or are you looking for intuition?

[meager chasm]

prove

it’s intuitively true but why

[inner tapir]

i was always bad at analysis and inequalities lol
hmm maybe rearrange center t (x - y) + y
just thinking out loud

[meager chasm]

how does that help

[meager chasm]

i’m investigating concave functions and their equivalent definitions

i suppose that’s not analysis

[inner tapir]

idk you gotta play with it, again i'm just thinking out loud

[meager chasm]

<@&286206848099549185> ?

[broken yew]

suppose t ∈ (0, 1)
for any x, y ∈ R, if x < y, why is x < tx + (1 - t)y < y true?

Can you see what that middle expression represents?

@meager chasm

[meager chasm]

yes

[broken yew]

visually?

as you vary t from 0 to 1

[meager chasm]

congrats on your role

[inner tapir]

so the rhs can sort of come from this

x < y
x - y < 0
t (x - y) < 0
t (x - y) + y < y

[meager chasm]

also kinda…?

[broken yew]

ty

you are kinda like varying from x to y

as t goes from 1 to 0

[meager chasm]

yea

[broken yew]

anyways, I don't think its too hard to show if you tackle one inequality at a time

[meager chasm]

let’s start with x then?

[broken yew]

x < tx + (1 - t)y
x - tx < (1 - t)y
(1 - t)x < (1 - t)y

then same for other side

this is me showing it backwards

you show forwards ofc

[meager chasm]

oh shit yea

never thought of going backwards

.close

[safe radish]

Channel closed

Closed by @meager chasm

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lean otter]

I just don't get q 27 ;-;

[inner tapir]

,rotate

[lean otter]

How do I do it

[lean otter]

;-;

[inner tapir]

i'd prob just factorize it; don't really see another way

like 216 = 6^3 = 2^3 * 3^3

then use exponent rules

[lean otter]

ok

. close

.close

[safe radish]

Channel closed

Closed by @dreamy idol

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[inner tapir]

the taylor series one?

do you know the definition for the terms of a taylor series?

[safe radish]

@copper wraith Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[shy dune]

Let T be the smallest positive integer which, when divided by 11, 13, 15 leaves remainders in the sets {7, 8, 9}, {1, 2, 3}, {4, 5, 6} respectively.

[shy dune]

how a number gives 3 remainder when divided by one number

[broken yew]

16 divided by 13

gives 1 remainder 3

cus 16 = 1(13) + 3

[split ether]

I think they meant that the remainders are somewhere in sets

And not that all of the elements in each set is a remainder

[broken yew]

oh 3 different ones

[shy dune]

3 remainders*

[broken yew]

I see

Think of it as an OR

I think

[shy dune]

hm

[broken yew]

x = 7 mod 11
x = 3 mod 13
x = 6 mod 15

Is possible

You choose 1 from each set

[shy dune]

maybe

i ll check the solution later

i was trying it on my own first

this is what they meant

whoever is wondering

thanks Shuri2060

.close

[safe radish]

Channel closed

Closed by @shy dune

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[kind beacon]

for sinsiduoal functions, when i find the k value and x value on a graph and write the equation, do i still need to factor

[lean otter]

Can u be a bit more specific

Like show the exact question

What do u mean by K value

[kind beacon]

Ok

oh nvm

.close

[safe radish]

Channel closed

Closed by @kind beacon

Use .reopen if this was a mistake.

[lean otter]

Ok

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[zinc bronze]

Stuck again on a similar problem as last time 😩

[zinc bronze]

Again I can do the zero vector axiom, but when it comes to showing X + Y is closed on addition or scalar multiplication, I'm stuck

[broken yew]

.

alright lets try

[broken yew]

So first line, you will write? @zinc bronze

[zinc bronze]

$Let a,b \in X and c,d \in Y$

[flat frigate]

hello2248

[broken yew]

ehh u can do that

yes that is fine

Let $\boldsymbol{v_1},\boldsymbol{v_2}\in X+Y$.

Then let $\boldsymbol{x_1}, \boldsymbol{x_2}\in X, \boldsymbol{y_1}, \boldsymbol{y_2}\in Y$ such that $\boldsymbol{v_1} = \boldsymbol{x_1} +\boldsymbol{ y_1}$, $\boldsymbol{v_2} = \boldsymbol{x_2} + \boldsymbol{y_2}$.

[flat frigate]

Shuri2060

[broken yew]

Perhaps I would prefer this lettering

Then it is clearer than a, b, c, d?

it doesnt matter in the end, though

[zinc bronze]

Yah makes sense

[broken yew]

So if we know X and Y are subspaces

What can we say about those 4 vectors

[broken yew]

.

First we are doing addition

Usually to prove a property, you just use the same property (if you have something combined from vector spaces)

[zinc bronze]

$x_1 + x_2 + y_1 + y_2 \in X + Y$ because $x_1 + x_2 \in X$ and $y_1 + y_2 \in Y$

[flat frigate]

hello2248

[zinc bronze]

So $v_1 + v_2 \in X+Y$

[broken yew]

yes, thats the way

[flat frigate]

hello2248

[broken yew]

yes good

Ok, scalar multiplication

Do you know how to start the proof?

By the way, it's been a long time for me. We just need to prove closure for both and 0 is in it? I forgot haha

[zinc bronze]

Yep, just those 3

Let $v \in X + Y$ such that $v = x + y$ where $x \in X$ and $y \in Y$ and $λ \in (howToDoInLatex?)$
$λx \in X$ and $λy \in Y$
thus $λx + λy \in X + Y$ hence $λv \in X + Y$
X + Y is closed on scalar multiplication

[flat frigate]

hello2248

[zinc bronze]

idk how to use latex apparently

[broken yew]

aha I just use it because looks nice and practice

$$\bR$$

[flat frigate]

Shuri2060

[broken yew]

Sure, your proof is fine

[zinc bronze]

Aha alrighty thanks again!

[broken yew]

Usually, since the concepts are so simple

I write out every step

v = x + y

kx, ky in V

you had those

but then i write

kx + ky = k(x + y) = kv in V

[zinc bronze]

Ok sure yeah, makes sense to be detailed

[broken yew]

wait what am i doing

@zinc bronze wait lol

oh right nvm

all is good 💤 haha

[broken yew]

So here you are technically using distributative property of vector spaces for that factorisation

[zinc bronze]

Mhm thanks for the help and advice!

[broken yew]

👌

[zinc bronze]

.close

[safe radish]

Channel closed

Closed by @zinc bronze

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fathom parcel]

$e^(iy)*sin(x)/(cos(x)-1)=O$

[fathom parcel]

does this stay true if i swap around the fraction?

[worthy hemlock]

Use curly brackets instead of parentheses for exponents

[flat frigate]

Sparky

[rigid oracle]

$e^{iy}\cdot\frac{\sin(x)}{\cos(x)-1}=O$

[flat frigate]

Luca

[fathom parcel]

thx 😄

[worthy hemlock]

Hold up, was that an O, like the letter or zero?

Cause latex says it's the letter

[fathom parcel]

supposed to be zero

but can i turn around my fraction and it still stays true?

[river granite]

$e^9×9=

[pulsar condor]

#❓how-to-get-help

Oh they left

[rigid oracle]

You mean $\frac{\cos(x)-1}{\sin(x)}$?

[flat frigate]

Luca

[fathom parcel]

$e^{-iy}\cdot\frac{\cos(x)-1}{\sin(x)}=O$

[flat frigate]

Sparky

[fathom parcel]

is this also true?

[rigid oracle]

what you wanna say is $e^{iy}\cdot\frac{\sin(x)}{\cos(x)-1}=0=e^{-iy}\cdot\frac{\cos(x)-1}{\sin(x)}$

[flat frigate]

Luca

[fathom parcel]

yeah exactly

[rigid oracle]

you mean if the same x'es satisfy this equation?

[broken yew]

what?

[rigid oracle]

i am confused by the question

$e^{iy}\cdot\frac{\sin(x)}{\cos(x)-1}=0\not =e^{-iy}\cdot\frac{\cos(x)-1}{\sin(x)}$

[flat frigate]

Luca

[fathom parcel]

i have a linear system of equations and one equation is what i posted first. And i want to transform it so that i just turn around my fraction. Am i allowed to do this?

[rigid oracle]

because to turn the equation around $\frac{\cos(x)-1}{\sin(x)} = \frac{\sin(x)}{\cos(x)-1}$ would have to hold

[flat frigate]

Luca

[rigid oracle]

so no, you can't turn around the fraction

or do you mean this

$e^{iy}\cdot\frac{\sin(x)}{\cos(x)-1}=0\qquad\bigg|()^{-1}\\ \frac{1}{e^{iy}}\cdot\frac{\cos(x)-1}{\sin(x)}=0$

[flat frigate]

Luca

[fathom parcel]

yes thats what i want to do

[rigid oracle]

that you can do

[fathom parcel]

thank you very much.

.close

[safe radish]

Channel closed

Closed by @fathom parcel

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lean otter]

Hi! I don’t get q 11

[scarlet sage]

What have you tried so far

nvm i cant do this

mb

[quasi bison]

@lean otter how familiar are you with exponent laws?

[lean otter]

Idk mb 50%?

[quasi bison]

kind of weird that you'd give a percentage like that.

but ok

can you say which exponent laws you are familiar with enough to remember them off the top of your head?

[lean otter]

.close

[safe radish]

Channel closed

Closed by @radiant fiber

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[frozen sluice]

I want to find the zeros of $f(x)=x^4+4$. Wolfram Alpha tells me its $\pm(1+i)$ and $\pm(1-i)$. But when i use the quadratic formula i get $\pm\sqrt{2i}$ and $\pm i \sqrt{2i}$

[flat frigate]

Kurama

[frozen sluice]

what am i doing wrong

[marsh walrus]

can i ask a dumb question

how are you using the quadratic formula

just substitution?

[frozen sluice]

yes, just substituting x^2

[marsh walrus]

hmm i dont get the root

,w x^2+4=0

[flat frigate]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by jan Niku#2119

[marsh walrus]

without the root both answers make sense

[frozen sluice]

you have to substitute it back. now you have the solution for x^2, and to get it for x^4 you have to take the root again

but i might be doing something worng

[marsh walrus]

idk if you start from like 2i and then just solve x^2=2i

youll get out the two sensible solutions

same with -2i

these correspond well with the original solution set you got

like 2i=(i+i+1-1)=(1+i+i-1)=(1+i)(1+i)=(1+i)^2

[frozen sluice]

ah, so what i did was correct then

thanks

.close

[safe radish]

Channel closed

Closed by @frozen sluice

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fleet saddle]

I know I'm supposed to explain what I've tried and how far I've gotten, but I have basically no clue how to even approach these. A push in the right direction at minimum or a good explanation would be great.

[half cove]

f-1(x) = -2 ==> x = f(-2)

Then find x

[safe radish]

@fleet saddle Has your question been resolved?

[fleet saddle]

Is that a known rule or just intuitively finding the inverse?

Also for the middle one do I just assume f(x)=x-5?

Never mind, that doesn't work.

[safe radish]

@fleet saddle Has your question been resolved?

[safe radish]

@fleet saddle Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[bitter geode]

hi

[bitter geode]

look at this question

it is an right riemann sum approximation for a definite integral from 1 to 4

the function we are integrating is rf(r)

let's say we know r is increasing

and f(r) is also increasing

is that enough reason to say that their product (rf(r)) is also increasing?

[sonic shoal]

not necessarily

say f(r) = r

r f(r) = r^2

r, f(r) both increasing

r^2 not increasing in (-inf, 0)

is (rf(r))' > 0 ?

[bitter geode]

oh yeah I guess

wait but

well

yeah

ok what about this

(rf(r))' = f(r) + f(r)'r

since f(r) is increasing, f(r)' is positive

hence, f(r)'r is also increasing

[sonic shoal]

do you know exactly what f(r) is or do you only know that f(r) is increasing

[bitter geode]

it's a table

we know it's increasing from a table

[sonic shoal]

ah okay

[bitter geode]

so its derivative is positive

[sonic shoal]

can you limit the range of r?

[bitter geode]

the integral is from 1 to r

1 to 4*

so r is in [1, 4]

[sonic shoal]

is f(r) > 0 hopefully when r in [1, 4]

[bitter geode]

hence it's also positive and increasing

[bitter geode]

yes

[sonic shoal]

yeah then (rf(r))' = f(r) + r f'(r)

and we know that f(r) > 0, r >0, f'(r) > 0

[bitter geode]

wait butt

[sonic shoal]

so (r f(r))' > 0

that's fine then

[bitter geode]

since they're both positive

over the interval

r*f(r) is always positive

and

r*f(r) is increasing

ah nvm

yeah the other way is much better

yeah trhanks

brother

[sonic shoal]

np

[safe radish]

@bitter geode Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stray granite]

I want to find a cubic function with a y-intercept at 12,000, a minimum at (5, 6000), and a maximum at (10, 10000). I've tried ax^3 + bx^2 + cx + d and its derivative, but I can't get all of the equations into one system.

[stray granite]

.close

[safe radish]

Channel closed

Closed by @stray granite

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lean otter]

Ok, this is might be a very silly question but this isn't working for me. This is how the question goes, "If the unit price for almonds is $0.13 per oz, how much does a 3 pound tub cost?". Isn't the answer suppose to be $0.39? Because that what I got and the answer to the problem is $6.24. Is there a step that I am missing because I'm just using cross multiplication. Thanks.

[frigid geyser]

check units

a pound is 16 ounces iirc

[lean otter]

wow, ok

I didn't think that they would use that in way

thanks

.close

[safe radish]

Channel closed

Closed by @tawny marten

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[spark lagoon]

How do you get the domain?

[plucky elk]

Domain is where the function can be defined.

[sonic shoal]

you can start from the fact that a fraction is not defined if the denominator is zero

[spark lagoon]

.close

[safe radish]

Channel closed

Closed by @spark lagoon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[next gulch]

i am trying to calculate this from x=0 to x= 10 with 5 rectangles only

the solution is above im trying to figure this out

what i do know so far

but im a little stumped as to where to go from here

do i have to plug x into this?

[sonic shoal]

you just find the area of each rectangle

[inner tapir]

essentially yes
but it looks scarier than it is

[sonic shoal]

and add them up

[inner tapir]

those function values are the heights of each rectangle

[next gulch]

right this makes sense let me try

[ember bough]

command+shift+4 exists

[next gulch]

what does this do?

[sonic shoal]

screen capture lol

[ember bough]

takes a screenshot....

[inner tapir]

drag a region for the screenshot

[next gulch]

ohh yeah im not too familiar with this stuff

noted

[safe radish]

@next gulch Has your question been resolved?

Channel closed

Closed by @next gulch

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lean otter]

$\int x^3e^x^2dx$

[marsh walrus]

almost did it again lol

$\int x^3 e^{x^2} \dd x$

[lean otter]

look man im new to this

[flat frigate]

jan Niku

[marsh walrus]

ur good

[lean otter]

yeah but why the dd?

[marsh walrus]

it shouldnt be coded that way

[marsh walrus]

its not important

[sonic shoal]

wow \dd, fancy

[marsh walrus]

you can juste use dx

[lean otter]

okey thaks

thats what i did? .... kinda

[marsh walrus]

yea

you did

oo

[lean otter]

do i need to type the \ before the dx?

[marsh walrus]

nonelementary?

no

\dd x just makes it so the d is straight

$\dd x$ vs $dx$

[flat frigate]

jan Niku

[marsh walrus]

anyways

wheres this integral from?

[lean otter]

from my book? or what do u mean?

[sonic shoal]

try substituting $t = x^2$

[flat frigate]

xdk1235

[lean otter]

i did

[sonic shoal]

reading the integral as $\int x^3 e^{x^2} dx = \int \left(x^2 e^{x^2} \cdot x \right) dx$ might help

[flat frigate]

xdk1235

[marsh walrus]

$\frac 1 2 \int u e^u \dd u$?

[flat frigate]

jan Niku

[lean otter]

thats where im stuck, do i go ibp now?

[sonic shoal]

yes

but honestly i think ibp for that is kinda silly (this is how textbooks tell you to do)

$(x e^x)' = x e^x + e^x$ so you can kinda guess the answer from this

[flat frigate]

xdk1235

[marsh walrus]

why does symbo and IC think this needs erfi

oh, symbo gets it correct

weird

[lean otter]

solved it now, thanks guys

i had the answer but didnt know how to solve it

[lean otter]

If you have, then please close the channel by .close :)

[safe radish]

@lean otter Has your question been resolved?

Channel closed

Closed by @foggy fractal

Use .reopen if this was a mistake.

[lean otter]

thanks, didnt know how to close b4

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stoic pilot]

$NN(x) = \sigma ( w^{(3)} \sigma (w^{(2)} \sigma ( w^{(1)} x + b^{(1)} ) + b^{(2)}) + b^{(3)} )$

$\pdv{NN}{x} = ?$

is this WA thing right or did I screw that up

[flat frigate]

THEBIGTHREE

[stoic pilot]

shit thats right isnt it

fml

.close

[safe radish]

Channel closed

Closed by @stoic pilot

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gleaming yacht]

Hello.
How can I find the number of perfect squares between two number?

[ember bough]

find the lowest and highest perfect square possible

[gleaming yacht]

Okay and then?

[ember bough]

find the number of numbers between them?

[lean otter]

Uh

The squares r huge

[ember bough]

uh
so what?

[lean otter]

The values I am getting are 2559999 and 6250001

[ember bough]

...so?

[lean otter]

Then how to solve?

[ember bough]

1. find the highest possible a^2 in the interval
2. find the lowest possible b^2 in the interval
3. find the number of numbers between a and b inclusive

[lean otter]

Getting 3690002

[ember bough]

do you even know how the method works

it's literally the easiest thing in the world

[lean otter]

OH

I get it

[gleaming yacht]

Thank you very much.

[sleek sparrow]

Hello can I ask for help please?

[gleaming yacht]

.close

[safe radish]

Channel closed

Closed by @gleaming yacht

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[zinc hearth]

Alright so about these I just don't know how to start and go from there so if we can go through them at least somewhat completely so I can grab the fundamentals that would be great!

[safe radish]

@zinc hearth Has your question been resolved?

[zinc hearth]

<@&286206848099549185>

[safe radish]

@zinc hearth Has your question been resolved?

[zinc hearth]

.close

[safe radish]

Channel closed

Closed by @zinc hearth

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[knotty sigil]

what have u tried

do u know the radius of the circle

[knotty sigil]

.

i dont care

tell me what u have tried

[knotty sigil]

.

arc length = central angle x radius

apply this u get ur answer

dude i already told u

arc length = central angle x radius
apply this u get ur answer

arc length = central angle x radius

that they must give

or assume it as r

55

take it as r

[thin bridge]

apply the definition / relation between the central angle and the measure of the respective arc

(note that you aren't being asked for arc length)

[safe radish]

@lean otter Has your question been resolved?

[crisp latch]

@lean otter arc length formula is (a/360) ( 2 pi r )

[thin bridge]

apply the definition / relation between the central angle and the measure of the respective arc
(note that you aren't being asked for arc length)

where does it say that

[safe radish]

Channel closed

Closed by @next sandal

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fervent igloo]

A recursion equation is determined by:
[pic]
a) Show that the equation can be written in the form y_n + 1 = a · y_n
b) write down all the solutions to the equation
c) determine the solution to the equation that satisfies that y0 = 6

[fervent igloo]

So I'm kind of new to this, so I need guidance for this

[safe radish]

@fervent igloo Has your question been resolved?

[quasi bison]

are you able to isolate $y_{n+1}$ from the equatoin $9y_{n+1} - 3y_n = 0$?

[flat frigate]

Ann

[fervent igloo]

like if im allowed to?

[quasi bison]

"able" and "allowed" are two different things

[fervent igloo]

well I can yes

[quasi bison]

so do it

[fervent igloo]

so 9 - 3y_n = y_n+1

[quasi bison]

???

how did you get that?

[fervent igloo]

or should 9 follow with y_n+1

im lost ig

idk how to isolate

[stoic dune]

Isolate y in:
9y - 3x = 0

[fervent igloo]

then divide with 9 on both sides?

[stoic dune]

Now that you have that, you can see a clearer pattern. What function gets multiplied by 1/3 every increase in n?

[fervent igloo]

y_n

or y

[stoic dune]

True lol. I mean, polynomial? Trig? Exponential? Logarithmic?

[fervent igloo]

oh uhm

exponential?

or linear

[stoic dune]

Linear would be adding something every n

Exponential was good, where something gets multiplied every n

Namely, (1/3)ⁿ works

[fervent igloo]

aa makes sense

I can also use 3^-1 instead of 1/3

right?

[safe radish]

@fervent igloo Has your question been resolved?

Channel closed

Closed by @fervent igloo

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lean otter]

How would we find the range

[lean otter]

Can anyone help pls

[safe radish]

@lean otter Has your question been resolved?

[opaque sentinel]

f(x) is decreasing for all x

so maximum value will be at x = 5

and minimum will be the asymptote at x = infinity

range will be b/w them

[safe radish]

@lean otter Has your question been resolved?

[lean otter]

Ty

[safe radish]

Channel closed

Closed by @crystal sierra

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[slate holly]

I need help for an equation : (-10)-(11,3*x)+(2,67*x^2)=y and i need X in function of Y

[slate holly]

Could anyone help with this please ?

[zinc crown]

use the quadratic formula

move y to the x side and then use the quadratic formula

assuming that (-10 - y) = c

[sonic shoal]

huh are these all vectors or

ahh you use , for the decimal point ig

[slate holly]

yeah these are decimal points lol

[slate holly]

ah

yes

.close

[safe radish]

Channel closed

Closed by @slate holly

Use .reopen if this was a mistake.

[slate holly]

.reopen

[safe radish]

✅

[slate holly]

except how am i supposed to find the delta

how am i supposed to know it's positive

@zinc crown :/

also Y never goes under 0

[zinc crown]

wait what

you have to use the + or - notation

if you want x as a function of y

[slate holly]

i mean for the quadratic formula

[zinc crown]

,w graph 2.67x^2 - 11.3x -10 = y

[flat frigate]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Yottachad#0445

[zinc crown]

wait wdym a delta?

$x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$

[slate holly]

this

[flat frigate]

Yottachad

[slate holly]

yeah ik that

[zinc crown]

well y isn't defined for x values < ~ -23

so you don't have to worry about the square root because it would simply be not in the domain of x(y)

[slate holly]

but what guarantees me that b²-4ac will always be positive

okok

nice

thanks

[zinc crown]

yeah

[slate holly]

gonna try that

[zinc crown]

see how the function isn't defined for some y values (that is, it doesn't drop below a certain point)?

so we could simply say that our x of y function doesn't have those y values in its domain

[safe radish]

@slate holly Has your question been resolved?

Channel closed

Closed by @slate holly

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[west bison]

How do I find the resultant force on the right hand side

[west bison]

<@&286206848099549185>

[worthy hemlock]

Which question?

[west bison]

Well both but if you explain one of them I’ll know how to di the other

[worthy hemlock]

What's the question asking for?

[west bison]

Magnitude and direction of the resultant force

[worthy hemlock]

That force that is straight down, find the x and y components of that force

With respect to the box

Then sum up the x forces and the y forces, find the magnitude, then angle

[west bison]

Thanks mate

.close

[safe radish]

Channel closed

Closed by @west bison

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rancid solstice]

I’m trying to find the equation used to solve for this sequence but it’s been years since I solved for something like this and even something as simple as this eludes me.
Here’s what I know: the sequence decreases by a set value (at first this value seems to be 10%) then +40 is added and the number decreases by a set value again.

[rancid solstice]

What I’ve tried: I solved for the percent each set goes down by then when I got to the end of the set I calculated the amount it decreased by 707 and divided it by the original number thinking it’s supposed to tell me something I’m not sure what but that did not work. It’s possible that +40 being added to the number chain is being ignored when it decreases by a set value but wouldn’t that have a bigger impact on the larger number and the effect would decrease as the numbers got smaller idk even this simple stuff makes the gears in my head screech to a grinding halt

[safe radish]

@rancid solstice Has your question been resolved?

[rancid solstice]

<@&286206848099549185>

[safe radish]

@rancid solstice Has your question been resolved?

[safe radish]

@rancid solstice Has your question been resolved?

[plucky elk]

@rancid solstice I don't know what you're asking. Can you rephrase your question with only the minimal details

[rancid solstice]

@plucky elk point A is 2583 and point B is 0 how did I get from A to B

The sequence is written on that paper but it goes

2583
2325
+40 2365
2106
+40 2146
1860
+40 1900
1502
+40 1542
835
+40 875
0

[safe radish]

@rancid solstice Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[rancid solstice]

2583
2325
+40 2365
2106
+40 2146
1860
+40 1900
1502
+40 1542
835
+40 875
0
Of this sequence how do I find what it is decreasing by

[steel stag]

idk what those numbers mean, you're just adding 40

[rancid solstice]

So the start is 2583 then it decreases to 2325

Then 40 is added and it decreases to 2106

[steel stag]

ok it seems to be decreasing by different amounts, so you'd need more context to know what's happening

[rancid solstice]

What context do I need?

[plucky elk]

The meaning of the numbers. If this is a hw question, post the whole thing

[lean otter]

@rancid solstice give us the exact question

[rancid solstice]

It’s not an exact question nor is it any sort of homework. I could post a video that might give more context but I’m not sure it will help with the math

[plucky elk]

Just type the context where the numbers come from

No one's gonna watch a video lol

[rancid solstice]

It’s 15 seconds long

Alright let me put it like this you have 2583 health after one second it drops to 2325 then you gain 40 back leaving you with 2365 then another second passes and your health decreases to 2106 and gain 40 back

That is all the context I can give in words because that is all the information I have

[lean otter]

Bruh

Is this a question from a video game

[rancid solstice]

Yes

I remember there is pre calc math or algebra II math that’s supposed to allow you to work out equations by graphing them and running the numbers thru a specific method but I can’t remember how

@lean otter is this not what the channels are supposed to be used for

[lean otter]

I’m sorry I’m not interested in this

[rancid solstice]

Lol

@lean otter can you tell me the name of math that would be used to solve for this so I can look it up

[vagrant pawn]

sus

[rancid solstice]

Sus you

[lean otter]

Oh

It is basically this

Nvm it’s not an AP either

It’s some weird shit

I thought it was a sequence with an AP and +40 stitched together

But nope

[rancid solstice]

No I’m not sure it would be an arithmetic process I want to say the equation y=abX is useful for modeling the relationship and somehow you can do some number wizardry to magic the numbers for the equation up

[safe radish]

@rancid solstice Has your question been resolved?

Channel closed

Closed by @rancid solstice

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[little mountain]

(10^(10^76)*((10^(10^100))^(10^185))
How can I express this as a single power tower?

[ancient escarp]

for what possible reason may i ask

you might as well write infinity

[safe radish]

@little mountain Has your question been resolved?

[quasi bison]

@little mountain can you write your thing out on paper? the parentheses look a little cluttered

actually your parentheses are unbalanced

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[undone fiber]

Can someone solve this puzzle. I am doing this from past 2 days. Anyone knows the answer?
U can only move top cube it means u are not allowed to move two cubes simultaneously or cubes below the top cube. Just top one on the stack you can move. find number of moves

[meager chasm]

wdym by moving?

[safe radish]

@undone fiber Has your question been resolved?

[undone fiber]

It's similar to tower of Hanoi problem

Moving= taking the top cube and placing it on any of the stacks

<@&286206848099549185>

[safe radish]

@undone fiber Has your question been resolved?

[safe radish]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ruby cloak]

<@&286206848099549185> I need help doing this problem

[lean otter]

Use the Quadratic formula

[ruby cloak]

What’s my friend

Can you tech me foil formula

[safe radish]

@ruby cloak Has your question been resolved?

[ruby cloak]

No

@vocal rampart I need help

<@&286206848099549185> I need help

[quiet vector]

@ruby cloak u still need help?

[ruby cloak]

Yes I do

Please help me factor this

@quiet vector

You there

I need help

[quiet vector]

so do u know what the quadratic formula is?

[ruby cloak]

No

Nobody wants to teach me 😔

[quiet vector]

i can teach you but i haven't used it in like... 2+ years so i might be a bit rusty

[ruby cloak]

It’s fine

[quiet vector]

k so this is it

[ruby cloak]

Is there easier method

Foil method how about ?

[quiet vector]

and in ur quadratic a is the number before x^2, b is the number before x, and c is the number on it's own

this is the easiest method

it isn't possible to do another method with ur quadratic i don't think

[ruby cloak]

Can you write my equation into that formula

[quiet vector]

at least not with ease

well u need a calculator to do it

but first tell me what a b and c are

like i said, a is before x^2, b is before x and c is the number on it's own

[ruby cloak]

But I did like this

[quiet vector]

just a sec, i need 2 check something

[ruby cloak]

K

[quiet vector]

ok i'm back

there is another method mb

like i said i'm rusty

ok so this is gonna be a bit hard to explain but i'll try my best