#help-23

1 messages · Page 382 of 1

edgy breach
#

sorry, I mean can you use an arrangement of smaller areas to find the total area?

naive osprey
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Yes

safe radishBOT
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@naive osprey Has your question been resolved?

radiant canopy
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@naive osprey do vu have to find the area of the whole shape

radiant canopy
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k

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so how many triangle can fit in the shape

naive osprey
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7

radiant canopy
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sos find the area of triangle and * by 7

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and show ur work

naive osprey
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okk

naive osprey
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But ChatGPT says the answer is 84

radiant canopy
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yes

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why did u do sq root 6^2

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whats area of triangle

naive osprey
naive osprey
radiant canopy
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y

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do u know area of triangle = bh/2

naive osprey
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Yes

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that’s what I did

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4b • 5,66h • 1/2

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So why’s my answer wrong

radiant canopy
#

pythagoras works on right angled triangle right

naive osprey
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yes

radiant canopy
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is the bigger triangle a right angle triangle

naive osprey
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Idk

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but I divided it

radiant canopy
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2 sec

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is 6 the base or height'

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@naive osprey

naive osprey
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it isn’t the height

radiant canopy
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1 sec

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ur answer is correct

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@naive osprey

naive osprey
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Okok

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Good

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Ty

radiant canopy
#

the method chatgpt tried

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was

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0.5* perimeter * apothem

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apothem is center to the side

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this is only applicable for regular polygons

safe radishBOT
#

@naive osprey Has your question been resolved?

safe radishBOT
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tardy mango
#

nooooooooo a helpful has fallen

#

<@&268886789983436800>

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wild cape
tardy mango
#

"crypto casino"

vivid stream
#

Very sad

tardy mango
#

I hope they scam the house happy

quasi timber
#

A helpful!?

safe radishBOT
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atomic river
#

My professor sent me this slide and the middle definition is confusing me, I'm not sure what it meant by bit-level and pattern-level, I would like to see some examples to clarify this.

  • Does "NOT (x AND y)" has the pattern level of 2?
  • Does "NOT (x OR y OR z)" has the pattern level of 2 or 3?
  • Does "x NAND y" has the pattern level of 1 or 2 (since NAND could be said to be made up from NOT and AND)
    • But since NAND is the universal logic operation, does that mean the opposite that "x AND y" is actually "NOT (x NAND y)" and therefore has pattern-level of 2?
  • Does "1011 AND 1001" has the bit-level of 2, or 4?
  • Does "(1011 OR 1110) AND 1011" has the bit level of 12, or 8, or 2 if the original statement is "(x OR y) AND x"?
median vigil
#

the slide doesn't say there is a number associated with bit level or pattern level

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it just means a logical operation at the bit level is an operation on a single bit, e.g. 0 AND 1 = 0, and on the pattern level is a bunch of bit level operations on corresponsing bits, e.g. 011 AND 101 = 001

strong scarab
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a pattern-level operation here simply means an operation applied to one or two bitstrings, whereas a bit-level operation is an operstion on individual bits.

vagrant steppe
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Mind me asking what kind of math that is

strong scarab
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digital logic, mostly.

vagrant steppe
#

Ahhh okay thanks

safe radishBOT
#

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safe radishBOT
#

@tidal haven Has your question been resolved?

tardy mango
#

Differentiate the Pythagorean theorem with respect to time

safe radishBOT
#

@tidal haven Has your question been resolved?

safe radishBOT
#

@tidal haven Has your question been resolved?

onyx tiger
#

however this will only give for 1 time where the car is moving towards the intersection

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fickle mantle
safe radishBOT
fickle mantle
#

My teacher got 81k

median vigil
#

you went from 3^-3 in line 2 to 3^-2 in line 3

fickle mantle
#

Ohh

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Ty

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Wil j be able to do this

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Is it the correct process pls?

prisma elk
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ye that is fine

fickle mantle
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But how do I cancel out the brackets

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Idk how to make them look the same

gritty sable
fickle mantle
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Tysmawoo

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Ty everyone

gritty sable
#

yea

fickle mantle
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.close

gritty sable
#

Always

safe radishBOT
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solar hazel
safe radishBOT
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serene locust
#

i need to use the iroc formula

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@meager igloo

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im sorry its 3 in the morning i have an exam tomorrow i really need this

safe radishBOT
safe radishBOT
mighty mango
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huh what's the bot doing

serene locust
#

idek

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u have an undergrad in math?

mighty mango
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no, geography

serene locust
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this is gr12 so it might be easy for u

serene locust
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js pls

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help

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this is the formula i need to use @mighty mango

mighty mango
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you surely are supposed to use differnetiation rules... right?

mighty mango
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otherwise, I have quite hte trauma with that specific formula

serene locust
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whats differnetiation rules

serene locust
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☠️

mighty mango
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okay... yeah I'm sorry, I cant differnetiate with that specific formula

serene locust
#

damn

astral glacier
#

,tex .diff trig

flat frigateBOT
#

Xavier 🌺

serene locust
#

i dont think this is what its about

astral glacier
#

This combined with chain rule should get you there

serene locust
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these are th naswers

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and we are specificly told to use the IROC formula

astral glacier
#

Wrong answer

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Your question is 5

mighty mango
astral glacier
#

You're showing us the answers to 4

serene locust
#

the textbook has the question answers mixed up

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question 4 is the answer to question 5 its confusing

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but u just gota figure it out by looking at the answer

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oh wait

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nvm that is the right answer

astral glacier
#

The unit of the equation isn't years anywhere

astral glacier
serene locust
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so how is the answer "answers may vary"

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cus theres different methods correct?

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i need to use this formula, and h=0.0001

astral glacier
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I mean in that case it looks like you've got your work cut out for you

serene locust
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is what youd think

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but i got 1800 as my answer

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which is pretty different than 4.19

astral glacier
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Did you remember to set the calculator to degrees

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(or to convert the stuff to radians)

serene locust
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wel its an exam, and a bunch of units need it to be in radians

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so my calc is in radians

astral glacier
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Well then did you remember to convert 120° to radians

serene locust
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no

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wait converting to radians or from radians to degreees

astral glacier
#

The formula you're given is in degrees

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And your calculator is in radians

serene locust
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oh

astral glacier
#

You either change your calculator to work with degrees or change the formula to be in radians

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(don't do both)

serene locust
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yeah so how would i edit the formula to be in radians

astral glacier
#

Do you know how to convert from degrees to radians

serene locust
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we ac we were never told that

astral glacier
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There are π radians in 180 degrees

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So how many radians is 120°

serene locust
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OHH

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wait

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what

serene locust
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wiat ik pie is 180 degrees

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bro im confused as shit

astral glacier
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Just set your calculator to degrees at this point

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That's easier

serene locust
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how do i know when a question needs radians or

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degrees

astral glacier
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When a question has degrees in it, it needs degrees

serene locust
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but we always used radians for the degree questions like

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theta and beta

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quadrants

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all that

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this is our lesson if that helps

safe radishBOT
#

@serene locust Has your question been resolved?

safe radishBOT
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dry forum
#

Help me

safe radishBOT
dry forum
#

,rccq

glass edge
#

,rccw

flat frigateBOT
glass edge
#

,rc

dry forum
glass edge
#

np

proud tree
# flat frigate

set up the integral then you use integration by parts i believe

dry forum
proud tree
dry forum
proud tree
#

i think i got it, i may have made a mistake

dry forum
dry forum
proud tree
#

you start from the equation you get from the first part

dry forum
proud tree
#

$A_n < \frac{1}{2n-2}$ is equivalent to showing $A_n<\frac{1}{2}\left(A_n+A_{n-2}\right)$

flat frigateBOT
proud tree
#

after simplifying the inequality, consider the interval over which we are integrating

safe radishBOT
#

@dry forum Has your question been resolved?

safe radishBOT
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frosty leaf
safe radishBOT
frosty leaf
#

would the majority imply "in relation to the other content" or no?

#

in my mind 1ist statement is correct because it has the largest proportions relative to each other category

safe radishBOT
#

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sterile grove
#

for the question just want to make sure i'm doing this correctly.

to find out how far he is horizontally you do tan(35) = 125/a

sterile grove
#

and then for the direct distance you're trying to find the hyp so you take what you got for the horizontal^2 + 130^2 then take the root of it?

fading phoenix
sterile grove
#

so 50+80-5 right?

astral glacier
#

Would be helpful to everyone to draw a diagram

fading phoenix
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um

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sorry

onyx tiger
fading phoenix
sterile grove
#

does what i did look right scoob

onyx tiger
#

yh

astral glacier
#

The lighthouse is 50m and the light is 5m below the peak

sterile grove
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right so that's why i used 125 in the first part

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I have it drawn out on my paper but I can't send a pic lolol

onyx tiger
sterile grove
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so it doesn't add an extra 5m

austere goblet
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125 is correct, and scoob's diagram, while a bit awkward and off-scale (why is the 50 so much longer than the 80) also looks correct from the way he placed the 5

onyx tiger
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😢

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i drew in a hurry

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to scale

sterile grove
#

lmfaoooo ur awesome scoob

onyx tiger
#

ah it labelled wrong but you get the feel

safe radishBOT
#

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vast lagoon
#

Consider set S={1,2,3....50}, where m,n belong to S, if P is number of ways such that 6 to power m + 9 to power n is divisible by 5 and Q is the number of ways in which (m+n) is the square of prime number, find(P+Q)

i couldnt find the question online and wanted to verify my answer as i have a different answer from where i got the question

naive dragon
#

First of all, are for example (1,3) and (3,1) counted as 1?

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It does not seem like the first part and the second part of your solution agree on this

vast lagoon
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counting as 2

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which part did i count them same as? first or second?

naive dragon
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The second part

vast lagoon
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for m+n to be 4 its either 1,3 or 3,1 and i did write 2 ways

naive dragon
#

9=
1+8
2+7
3+6
4+5
5+4
6+3
7+2
8+1

vast lagoon
#

n can only be odd right as we calculated in the first part

naive dragon
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That would be 8

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Wait what

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No

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The second part does not related to the first one

vast lagoon
#

AH

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thats probably it

naive dragon
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Or does it?

vast lagoon
#

whats the answer with your way?

naive dragon
#

It's the wording fault

vast lagoon
naive dragon
vast lagoon
#

so yeah 1333

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thank you!

naive dragon
#

meowdy np

vast lagoon
#

.close

safe radishBOT
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safe radishBOT
glacial oyster
#

Let two circles of equal radii with centres A and B intersect at C and D. Let EDF || AB as shown. IDH is another line not parallel to AB.
I lies on the minor arc ED between E and D and H on the minor arc FJ between F and J.
Q.1

ID < ED and DH > DF.
Is this true?
Q.2 If yes, how can one prove this?

safe radishBOT
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glacial oyster
#

yeah

#

I have opened another channel.

safe radishBOT
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faint glade
#

Does anyone know at which step I'm going wrong here?

mighty mango
#

did you multiply everything by 5

gray mulch
mighty mango
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and neglect the 3t

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3t is human too

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please treat it equally

faint glade
#

Ohhh

gray mulch
#

When you multiply both sides, you do it for the whole sum

faint glade
#

So wqhen you need to multiply something on one side, you multiply everything in the expression?

quasi bison
#

you multiply the ENTIRE left side and the ENTIRE right side by that

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so really the fully 100% formally correct step would be $$5 \paren{3T + \frac{8T-8}{5}} = 5 \cdot 7$$ which then simplifies to $$5 \cdot 3T + 5 \cdot \frac{8T-8}{5} = 5 \cdot 7$$

flat frigateBOT
faint glade
#

This makes so much more sense

mighty mango
#

indeed! refer to the lovely distribution property you probably learned.

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okay 🤩

faint glade
#

should be 8t - 8

mighty mango
#

good that you noticed

faint glade
#
  • -8
mighty mango
safe radishBOT
#

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safe radishBOT
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formal grail
#

i'm having trouble with this

safe radishBOT
formal grail
#

prove that for any x,y in Z
if x in Z+ and y not in Z+ then xy not in Z+
if xy = 1 then either x=y=1 or x=y=-1

using the equivalence class definition and properties of Z

safe radishBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
formal grail
#

I know what I need to do but I dont know how to make it fully work without assuming things that rent explicity proven

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by def, x = (a,b) (with a stick on top) with a>b, and y = (c,d) (with a stick on top) with d≥c

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so i can multiply those and get (ac+bd, ad+bc) with a stick on top

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but idk how to prove that it's not in Z+ by using a>b and d≥c and N inequality properties

#

2

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ok I found a way for the first one even if it's too long its the only one that satisfies em

safe radishBOT
#

@formal grail Has your question been resolved?

tardy mango
formal grail
#

thank you! it might be honestly, i didnt consider that approach since we didnt really delve into divisors

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they are defined in the material there just wasnt really any exercises around them

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and i can use this, which isnt in the material, because its the logical conclusion of the first thign proposed

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for the first one i did this, it's correct right

If i imagine all sets of parentheses have bars on top

x is in Z+ so x is (a,b) such that a>b
y is not in Z+ so y is (c,d) such that d≥c -> either d=c or d>c
its a known that for everything in Z always exactly 1 of in Z+ in Z- or =0 is true (the material calls this trichotomy)
And product in Z is such as (a,b)(c,d) = (ac+bd, ad+bc)

case 1: c=d
if c=d then (c,d) ~ (1,1) so it's 0 in Z
since for all Z, x*0 = 0, xy = 0 and 0 not in Z+ (the material says x*(1,1) = (1,1) which is the same thing but more convoluted)

case 2: d>c
the > in N is defined such that
if a>b, then there exists n in N such that a = b+n
same thing -> d = c+m

so ac + bd = (b+n)c + b(c+m)
= 2bc + nc + bm
and ad + bc = (b+n)(c+m) + bc
= 2bc + nc + bm + nm (only difference)

so using those two it can be seen that ac+bd = ad+bc +nm, and nm is in N (duh), so by def of > it implies that
ad+bc > ac+bd
so since the right side of the equivalence class that is the product > the right side, the product is in Z- and not in Z+ in case 2

so no matter what the product of a Z+ and a not in Z+ will not be in Z+

formal grail
#

so best to not mess w signs imo

#

9)b)
let x = (a,b) and y = (c,d), with a,b,c,d all in N ofc
1 = (2,1), so
(ac+bd, ad+bc) must be = (2,1), and by equivalence it means

ac + bd +2 = ad+bc + 1
ac + bd +1 = ad+bc (since 2=1+1) !!!!

if a=b, then bc+bd = bd+bc+1 not possible in N
same for if c=d, not possible

Case 1: a>b
there exists n in N such that a=b+n. substituting
(b+n)c + bd = (b+n)d + bc + 1
develop and cancel ->
nc = nd +1
so either c<d or c>d
case 1.a.: c<d so there would be k in N such that d=c+m so
nc = n(c+m) +1
nc = nc + nm + 1 not possible, so necessarily in case 1 c>d
so there exists k in N duch that c = d+k.
n(d+k) = nd +1
nd + nk = nd +1
nk = 1
since in N 1*a = a always, it means n=k=1
so a = b+1 and c = d+1
so a=suc(b) and c=suc(d)
so x = (suc(b),b) = 1 and y = (suc(d),d) = 1

Case 2 is the same by analogy but flipping a and b and c and d respectively results in
b = a+1 and d = c+1
so b=suc(a) and d=suc(c)
so x = (a,suc(a)) = -1 and y = (c,suc(c)) = -1
so if xy=1, either x=y=1 or x=y=-1

safe radishBOT
#

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safe radishBOT
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west grail
#

GUYS TELL me what is this jacobimatrix good for?

west grail
#

like its used on Rn->Rm but what does it even do

#

i know how to build it

plucky elk
#

do you know derivatives?

west grail
#

yes i know how to build the gradient as well

plucky elk
#

do you know what slope is in 1 dimension?

#

gradient is just the generalization to n dimensions

west grail
#

slope is steigung i guess yeah i will need to know what this matrix is good for

plucky elk
west grail
#

yeah i guess dunno the dude in our exam preparation just showed us how to do it but not how it is used lol

#

guess the use is secondary in our case

safe radishBOT
#

@west grail Has your question been resolved?

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formal grail
#

is the first one true or false? I know how to prove that it's true but also how to prove that it's false

glass carbon
#

give a counterexample (one is enough)

formal grail
#

nvm ugh

#

I know that the first one is true but some things I see keep attempting to give a counterexample even if there isnt because they wrongly interpret N as including 0

#

which would make the first impossible by saying they aren't the same kind of structure if (N,+) has neuter and (Z-,+) doesnt
But obviously (N,+) doesnt include 0 so this thing doesnt matter and it's easy to find a function that proves they are homomorphic

for the latter though it can be easily disproven by saying that (Z-, *) isnt closed so it cant be possible, right? @glass carbon

uneven ice
#

what is this operator ? same set? same cardinality?

glass carbon
#

if you define the set N as {1,2,3, ...} (without zero) then yes

formal grail
formal grail
uneven ice
#

the equal sign, what does it mean

#

that they are the same set?

formal grail
#

no it means that they are algebraic isomorphisms

uneven ice
#

or that they of the same size?

formal grail
#

that the operation + in the set Z- is algebraically isomorphic to the operation + in the set N

#

and the same for * (although there I need to disprove since it's false)

uneven ice
#

ah okay

#

have you proved it in the end?

formal grail
#

yeah I already knew how to prove it

serene locust
#

.

uneven ice
#

great-o

safe radishBOT
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@formal grail Has your question been resolved?

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mortal sundial
#

This is from the answer key for an exam review package

mortal sundial
#

How do I get the second table??

#

like where does x/2 come from

glass carbon
#

In other words, it is the undo of these transformations, the same with -y+3

glass carbon
mortal sundial
#

but how do we get that x/2 + pi/6 from the original equation

plucky elk
mortal sundial
#

how don't we get (pi/6)/2

#

I understand we don't but i don't know why

plucky elk
#

where did (pi/6) / 2 come from

mortal sundial
#

if i look at 2(x - pi/6) i think (2x - (2pi)/6) OH

#

OHHHH

#

so if you divide it by 2 it's pi/6

#

i'm still struggling to pull it out of the original equatioon

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#

@mortal sundial Has your question been resolved?

mortal sundial
#

I'll just hope

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spark lynx
#

Is this correct? I believe it is I just want someone else to double check me.

#

It does not have to be fully simplified or even simplified at all, I just simplified it enough that people wont have an aneurysm reading it

glass carbon
#

(a+b)^2 isn't a^2 + b^2

spark lynx
glacial cairn
#

spark lynx
#

Oh fair enough

glacial cairn
#

Wdym it doesn't get affected

glass carbon
#

these are not integrals

glacial cairn
#

(x^2+1)^2 is not x^4 + 1^2

spark lynx
#

oki oki

#

So im chilling now then?

glass carbon
spark lynx
#

tyty

safe radishBOT
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sour folio
#

Idk if this question is too short to be asked here but is there a difference between the two sine laws or can I just always use one and I’ll get the same answers

glass carbon
#

one is enough (though it depends), you use it depending on your needs

glacial cairn
#

There is no difference, none of the denominators will ever be zero

sour folio
#

Okey ty less things to memorize 😅

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safe radishBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
tired inlet
#

You just dumped like 20 problems there. pick one and try it

polar lynx
#

Cool

#

So pick one to start

#

And go with that

junior smelt
#

(also please don't spam your question across multiple channels, you have this one for yourself, so there's no need to disrupt other people with their questions sadcat)

tired inlet
#

You have to be trolling

hard crest
#

this is not appropriate and you know that.

safe radishBOT
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sonic basalt
#

can someone tell me where to start number 7?

sonic basalt
#

and also if possible pls teach me how to find direction of force exerted on a hinge because they didnt teach it in the book yet many of the past paper questions uses it

wet maple
sonic basalt
#

i just gotta resolve the forces vertically and horizontally, find moment on a, get y and x and find the magnitude, and use tantheta=y/x

wet maple
#

Ah ok gr8 :)

sonic basalt
#

thanks man

wet maple
#

Np

sonic basalt
#

.close

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dire idol
#

is this wrong

safe radishBOT
formal schooner
#

f'(x) = 6x + 6 is good

dire idol
#

What

formal schooner
#

you're trolling us right

#

you meant to use your alt

#

but you ended up using the same account

#

to reply to yourself

dire idol
#

its the solution and im confused

formal schooner
warm ocean
#

so when you're crossing the y axis youd just be at x = 0

dire idol
#

ye exactly

#

my teacher is tripping

tardy mango
#

,w graph y=3x^2+6x, y=0

flat frigateBOT
tardy mango
safe radishBOT
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@dire idol Has your question been resolved?

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fickle mantle
safe radishBOT
fickle mantle
#

Could u help me

onyx tiger
#

this looks like a common expression

#

try to recall

#

also you can't just do this

fickle mantle
onyx tiger
fickle mantle
onyx tiger
#

also denominator is under square root

onyx tiger
#

,,\sqrt{\frac{(a-1)^2}{a}} = \frac{a-1}{\sqrt{a}}

flat frigateBOT
onyx tiger
#

now try to match it with RHS

fickle mantle
#

I did it

#

Tysm

onyx tiger
fickle mantle
#

Does the cube root desperate?

#

Separate

onyx tiger
#

,, \frac{a+b}{c} = \frac{a}{c} + \frac{b}{c}

flat frigateBOT
onyx tiger
fickle mantle
#

Nvm

#

I meant like bc the root is 3

#

Thank you

safe radishBOT
#

@fickle mantle Has your question been resolved?

fickle mantle
#

Question b

onyx tiger
flat frigateBOT
onyx tiger
#

what have you tried

fickle mantle
onyx tiger
#

,, x = \sqrt{x}\cdot \sqrt{x}

flat frigateBOT
onyx tiger
#

or you could just cancel x in numerator and denominator here

fickle mantle
#

Oh

#

Is that how it works

onyx tiger
#

yh you cannot add numerator and denominator to add fractions

#

,, \frac{a}{b} + \frac{c}{d} \neq \frac{a+c}{b+d}

flat frigateBOT
fickle mantle
#

Oh

#

Ic

#

Wait what should I do again

onyx tiger
fickle mantle
#

Oki

#

Done!

onyx tiger
#

👍

fickle mantle
#

.close

safe radishBOT
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vague rain
#

Hlw i can solve integral dx/((sqrt(6x+1) +2)

safe radishBOT
brave wolf
#

by multiplying by the conjugate

#

or perhaps directly substituting could be quicker

quasi bison
#

i would think u := sqrt(6x+1) would be a better path tbh

quasi bison
safe radishBOT
# vague rain Hlw i can solve integral dx/((sqrt(6x+1) +2)
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
vague rain
#

Where is my mistake?

brave wolf
#

u substituted t only to substitute x back in?

#

why?

quasi bison
#

you might wanna write the characters u, 4 and 6 in a way that doesn't make them all look similar

vague rain
#

But i got a mistake

brave wolf
vague rain
#

Where?

#

6x-1

#

I am so dumb i cant see my mistake i dont know why syntethic division cant work but wether large division

brave wolf
#

hmm, what happened here?

#

i dont really see whats written on the next line

vague rain
#

I deleted it

#

Syntethic division?

brave wolf
#

thats not really common with a square root

#

and ur result is sqrt(u) - 4/(u-4)?

#

$u^{\frac{1}{2}}-\frac{4}{u-4}$

flat frigateBOT
#

MathIsAlwaysRight

brave wolf
#

this?

#

if so, then its wrong

vague rain
#

Yew

#

Hmmm you can work with me?

brave wolf
#

either u := sqrt(6x - 1) or u := sqrt(6x - 1) + 2

vague rain
#

I can continue wirh u message i need 15 minutes me back

formal schooner
#

<@&268886789983436800>

safe radishBOT
#

@vague rain Has your question been resolved?

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vague rain
#

How I can solve thiw

safe radishBOT
buoyant dragon
#

at very start of the question, Put

$u = \sqrt{6 x - 1}$

flat frigateBOT
#

Shikhar

vague rain
#

But i can multiply for conjugat3

safe radishBOT
#

@vague rain Has your question been resolved?

left folio
vague rain
left folio
#

dx # dt

safe radishBOT
#

@vague rain Has your question been resolved?

safe radishBOT
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south parcel
#

I stumbled across this question on a set of integral questions: A toilet roll has an inner radius r = 2 cm and an outer radius R = 7 cm. The thickness of the paper is 0.5 mm. What is the length of the paper when it is completely unrolled?

slim lion
#

the paper is in a spiral

#

so the outer radius of 7cm fluctuates depending on where you take the point

#

but let’s say we assume that the end of the spiral is 7 cm

south parcel
#

yeah ive come so far, and so for every layer the diameter increases by 2*whatever variable

#

is that right?

slim lion
south parcel
#

hahahaha

#

well I solved it without using integrals, however I really want to solve it using it as well

slim lion
#

because we want to take the arc length of the spiral

last belfry
south parcel
#

the circumference is 2pir^2

slim lion
#

why does it lap twice?

#

that’s the diameter, isn’t it?

last belfry
#

Yes

slim lion
#

we seem to only be concerned with the radius

south parcel
#

for the radius it increases by one thickness, however when its the diameter, it gets added to the other side as well

last belfry
#

The integral is int(r>R) (2pix)/thickness I believe

south parcel
#

and so i used a sequence for the circumference Cn = pi*(d+2nt)

slim lion
south parcel
#

100 i can agree on

#

with 0,05cm thickness

slim lion
#

ah it’s mm not cm

#

i see

#

ur right

slim lion
south parcel
#

yup

slim lion
#

and if i’m not wrong

#

we need to determine the arc length of an archimedian spiral

south parcel
#

not sure about that haha, its just 2nd semester economics maths

slim lion
south parcel
#

never hurts to be

#

go on

last belfry
#

For this level

#

But yea

south parcel
#

oh yeah i can see that

#

where r<x<R

slim lion
last belfry
#

Yes

#

Then you have the thickness so area is just thickness x length

#

So you just divide the area by the thickness

#

I think

south parcel
#

i think thats where i fell off a bit

#

are we taking the integral in a way that sums up all the circumferences

#

at each "layer"

last belfry
south parcel
#

yeah I have done that

last belfry
#

Oh ok

south parcel
#

.close

safe radishBOT
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tropic umbra
#

Call a nonnegative integer simple if its only nonzero digits are ones. Suppose S is simple, and R is the number obtained by reversing the order of its digits. If 901·S is simple, 901·R must also be simple. Why?

tropic umbra
#

i solved and the only simple integers works are repunit integers with more than 2 digits such as 111, 1111, ... also can end with 0 as 1110,11110,....

#

but i couldn't express in words so can someone help

quasi bison
#

what do you mean when you say "simple" integer

#

do you mean a number that's divisble by 1, itself and nothing else?

tropic umbra
quasi bison
#

oh nevermind

#

ok i thought you might've mistranslated from another language and meant prime

#

my bad

tropic umbra
quasi bison
#

901S = (1000 - 100 + 1)S. this seems like it would be relevant.

tropic umbra
quasi bison
#

try to write out some simple integers and their products with 901

#

see if anything pops out

quasi bison
#

are you sure that something like 111110000011111000 with the runs of 1's far enough apart wouldn't also work?

#

what exactly breaks down if you try it this way

tropic umbra
quasi bison
#

,w 111,110,000,011,111,000 * 901

#

bruh

quasi bison
#

but it does,no?

#

or you messed something up with your calculation.

tropic umbra
quasi bison
#

ok clearly i need to go rest cause i keep misreading messages here

#

my bad

tropic umbra
safe radishBOT
#

@tropic umbra Has your question been resolved?

austere goblet
#

just react to the bot. the bot can't read text replies to that question

tropic umbra
#

oh my bad😭

naive dragon
tropic umbra
#

ig

#

like 0,1,1011,100,101

safe radishBOT
#

@tropic umbra Has your question been resolved?

onyx tiger
#

so what is left

naive dragon
#

,w 111000111000*901

#

why is it base 2 by default bruh

naive dragon
#

any simple number S with no single 1,0 or no consecutive pair 11 or 00 satisfy that 901*S is a simple integer

#

I think

#

S*901=900*S+S

#

so if S have a string abc111def we can well do addition there would be
...... 9 9 9 ....
........ 1 1 1 .....
there has to be at least 3 consecutive 1 or else when do addition
.....0 9 9 0 ....
.......0 1 1 0 .....
a 9 would appear

#

similarly for string ...1001...
...... 9 0 0 9 ....
........ 1 0 0 1.....
when do addition a 9 could appear, or
...... 9 0 0 9 9 9 ....
........ 1 0 0 1 1 9......
.............. 2 0 0 0....
a 2 would appear

#

ofc when we reverse the order there aren't anything changed with the number of consecutive 1's and 0's

#

So obviously its reversed in order multiply by 900 would also be simple integer

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naive dragon
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sudden crypt
#

Could someone please help me with this question?

lost lily
#

are you familiar with radians?

gleaming coral
sudden crypt
#

Ik that angular velocity is angle turned over tume

#

Time*

sudden crypt
quasi bison
#

!noai

safe radishBOT
#

Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).

lost lily
#

if one revolution is 2 pi radians, then how many radians is 20 revolutions? and how many seconds pass in one minute? then you can find the number of radians per amount of seconds passed

sudden crypt
#

Ok got the first one

#

But how do I do the second question

proud bloom
#

10 pie /3 m/s

lost lily
#

are you familiar with the concept that the distance traversed on a circle is the product of the angle covered and radius?

sudden crypt
#

I am not

proud bloom
#

distance in 1 rev. 2pie r

#

20 rev ( distance = 40 pie r)

#

time = 60 seconds

lost lily
# sudden crypt I am not

when you go around a circle, you are going across a fraction of its perimeter (2 pi r)
when you travel a complete revolution of the circle you are travelling 2 pi radians multiplied by r resulting in 2 pi r
so when you travel any "T" radians across a circle, you are actually travelling T*r length

sudden crypt
#

Okkk

proud bloom
#

speed = distance /time = 40 . 5 pie /60 =10/3pie metre per second

lost lily
#

in your case you can find its rate by dividing with units of time to get linear speed = angular speed * radius

sudden crypt
#

So my radius is 5 so the perimeter would be 10pi

lost lily
#

you found the angular speed in step 1 of the problem in radians per second, this represents how fast the merry go round spins about its centre (how many radians it covers in one second)

sudden crypt
#

Ok...

lost lily
#

for any point on the edge of the merry go round, you would multiply that speed with how far you are from the centre (the radius) to get its linear speed

sudden crypt
#

So liner speed is angular velocity x 2?

lost lily
sudden crypt
#

Oh wait no

lost lily
sudden crypt
#

Linear speed is angular velocity x r

lost lily
sudden crypt
#

I believe I got it

#

?

lost lily
#

yes good job!

sudden crypt
#

Thxx

#

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naive dragon
#

Not really, it's not a complete solution but you get the idea

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tropic umbra
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noble scaffold
#

I have a question. When confirming local extremes, is it correct to say that ‘function(point) is a local extremum’ or that ‘the point is a local extremum’? Or what would be the correct way to say it in an exam?

somber cape
#

point is a critical point

glacial cairn
#

You can say extremum point for the x value and extremum value or just extremum for the y value

noble scaffold
#

Thank you! I have another related question. For this function, I had concluded that (0; 0) is a saddle point, but in an online solution, they stated that (0; 0; f(0; 0)) is the saddle point. Which one is correct, or are both wrong?

#

The exercise asks you to analyse whether f(0; 0) is a local extreme.

glacial cairn
#

Details really

#

(0,0) is the point in the 2D xy-plane which gives a saddle point in the 3D graph of the function

#

(0,0,f(0,0)) being that saddle point

#

Calling (0,0) a saddle point is perfectly fine

noble scaffold
#

That makes sense, thanks

#

In this case, would it be incorrect to say that f(0; 0) is a saddle point?

glacial cairn
#

f(0,0) is the value at that point, so I'd say it's technically incorrect

noble scaffold
#

Thank you very much

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earnest mirage
#

Hello, could someone check if this proof looks good please?

shadow glade
#

kind of confused by your argument here

#

the expression youre saying equals 6l doesn't seem to match the 5^2*k - 1 expression that youre substituting 6l for below

earnest mirage
shadow glade
#

but...in the top expression you have a k in the exponent

#

then below you have multiplication by k

#

ok

#

also need to fix the middle one

#

and i dunno just some thoughts for clarification, you are kind of changing n with k a lot

earnest mirage
#

Fixed 👌

\begin{Definition}[Natural numbers]
The set of the \emph{natural numbers} is the set $\bN = \{1,2,3,4,5,\dots\}$.
\end{Definition}

\begin{Theorem}
Suppose $n \in \bN$, then $6 \mid (5^{2n} - 1)$.
\end{Theorem}

\begin{proof}
Let $n \in \bN$. We proceed by induction.\\

\underline{Base Case.} The base case is when $n = 1$, and $6 \mid (5^2 - 1)$ as desired.\\

\underline{Inductive Hypothesis.} Let $k \in \bN$, and assume $6 \mid (5^{2k} - 1)$.\\

\underline{Induction step.} We aim to prove that the result holds for $k + 1$.
That is, we wish to show that $6 \mid (5^{2(k + 1)} - 1)$.
To do this, we begin with the expression $5^{2(k + 1)} - 1$:
\begin{align*}
5^{2(k + 1)} - 1 &= 5^2(5^{2k}) - 1 \\
&= 24(5^{2k}) + 5^2k - 1 \\
\end{align*}

By the inductive hypothesis, $6 \mid (5^{2k} - 1)$, and so, by definition of divisibility, 
$5^{2k} - 1 = 6l$ for some integer $l$.
Then,
\begin{align*}
24(5^{2k}) + 5^{2k} - 1 &= 24(5^{2k}) + 6l \\
&= 6(4(5^{2k}) + l) \\
\end{align*}

Since $k$ and $l$ are integers, so is $4(5^{2k}) + l$.
Then, $5^{2(n+1)} - 1 = 6m$ where $m = 4(5^{2k}) + l$.
Thus, by the definition of divisibility, $6 \mid (5^{2(k+1)} - 1)$.
Therefore, by induction, $6 \mid (5^{2n} - 1)$ for all $n \in \bN$.
\end{proof}
shadow glade
#

in the hypothesis line, assume the statement is only true for n <= k because the way you phrased the induction hypothesis currently, it sounds like youre assuming the whole thing youre trying to prove

#

changing n to k there made it worse

earnest mirage
#

Yes, I see

#

Let me change that

flat frigateBOT
#

Mor Bras

shadow glade
flat frigateBOT
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@earnest mirage Has your question been resolved?

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sleek current
#

Why wouldn't

$$
t = 5(log25/log0.5)

$$

be correct?

flat frigateBOT
#

Sep
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

sleek current
#

My answer:

median vigil
#

i suspect they want the "percent" to be given as a decimal between 0 and 1

sleek current
#

Ohhhhh

#

Hmm so like .25?

median vigil
#

yes

sleek current
#

Yeah that's it

#

Thank you!

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dim rock
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severe pond
#

you can do a few things here

#

either rewrite 3^(ln x) or just a simple u sub

dim rock
#

I finally tried u-sub but I'm stuck trying to figure out the integral of 3^u

severe pond
#

well

#

whats the derivative of 3^u

dim rock
#

idk

severe pond
#

learn derivatives before integrals

dim rock
#

I got a c in calc 1

severe pond
#

i see

#

you should review those then

dim rock
#

I'm thinking of withdrawling and learning calc 1 all over again

severe pond
#

idk about that

#

what year are you

dim rock
#

first

severe pond
#

its before the deadline?

dim rock
severe pond
#

like you mean drop the class

#

or withdraw

dim rock
#

I can only withdrawal

severe pond
#

then don't withdraw

#

you would waste hella money

#

and also its just a bad look

dim rock
#

I'm good at math it's just last semster was hell

dim rock
severe pond
#

yea it's doable

#

all you need to know is derivatives of common functions

dim rock
#

that's all I need to know catthumbsup

#

thx

severe pond
#

anyways

#

derivative of b^x is b^x ln b

#

so the anti derivative of 3^x is what

dim rock
#

3^x / ln(x) ?

severe pond
#

close

#

3^x / ln(3)

dim rock
#

oh right

severe pond
#

so that it cancels

dim rock
#

Yeah yeah

#

Thank you so much

severe pond
#

you're welcome

#

btw you could've done 3^(ln x) = (e^ln 3)^(ln x) = (e^ln x)^(ln 3) = x^ln(3)

safe radishBOT
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turbid crag
#

do you just want confirmation?

#

^ (sorry, forgot to reply)

#

yep

#

you always want to make it into an "if xxx, then yyy"

#

(well you don't always have to, but this always works)

#

lemme see

#

there are more ways to express this

#

do you know how to turn an implication into an OR statement and vice versa?

lilac crane
hard crest
#

ah pls don't delete modpings even if they've been handled, it gets super confusing when mods show up

#

as evidenced

turbid crag
#

sorry whoops

#

right

hard crest
#

(you can edit them to say resolved or sth)

turbid crag
#

i just did not think of that — but off-topic

#

@drowsy vale sorry for everything that has happened in this channel lmao, you still here?

exotic anvil
#

A mod telling you off is never off topic sully

turbid crag
#

i got a ghost message lmao

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turbid crag
#

confirmation ||your answer is wrong, one of A / B / C / D is correct||

#

do you know how to express implication as OR

turbid crag
#

clearly i'm not in the mental state of doing this rn

#

your answer is right marcel

hard crest
#

yeah. it turns out that p -> q is exactly equal to (not p) or q

safe radishBOT
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twin fulcrum
#

Can you guys check this please

safe radishBOT
quasi bison
#

you will benefit from making your z and 2 look less similar, this much i can tell you immediately

#

your final answer of (-1, 3, 5) satisfies the system, so you have made an even number of mistakes

naive dragon
hard crest
#

one really nice thing about systems of eqns is that you can easily check your own work

#

by simply plugging the solution you get into your starting equations

quasi bison
quasi bison
safe radishBOT
#

@twin fulcrum Has your question been resolved?

twin fulcrum
#

New

#

<@&286206848099549185>

#

tried diff format still got same result, not sure what im doing wrong

clever gale
#

,w solve 2x - y + z = 0, 3x - 2y + 4z = 11, 5x + y - 6z = -32

flat frigateBOT
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quiet field
#

i need help with this one

safe radishBOT
quasi bison
#

the goal is to find DE?

quiet field
#

yup

quasi bison
#

do you have progress so far?

quiet field
#

let me send

quasi bison
#

,rccw

flat frigateBOT
quasi bison
#

hmm might be difficult this way

#

here's a better idea: drop a perpendicular from B into AC. call it BH for example. then consider triangles ADE and ABH

quiet field
#

okay let me

#

smth like this?

#

but idk EH so I can't apply the Pythagoras

hollow trout
quasi bison
#

look at triangles ADE and ABH

#

there is something special about them

#

seeing as DE and BH are parallel

quiet field
#

the way I drew isn't parallel, i kinda get it now

#

nvm I don't get it

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@quiet field Has your question been resolved?

quiet field
#

I give up I won't solve

#

.close

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cerulean dune
#

Hello can anyone help me prove it

austere goblet
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split fulcrum
#

I need help starting with this.

safe radishBOT
quasi bison
#

do you know how spherical (R^3) coords work

split fulcrum
#

uh i think so

quasi bison
#

ok can you state the conversion from cartesian to polar in R^3

split fulcrum
quasi bison
#

misquoted and opposite to what i actually asked

split fulcrum
#

did you mean cylindrical coordinates

quasi bison
#

no, i meant spherical

#

i expected:

x = r cos(θ)
y = r sin(θ) cos(φ)
z = r sin(θ) sin(φ)

or some permutation of this

#

ok i guess actually i am the fool here because i asked the question in the opposite way to my own intentions

split fulcrum
#

so what do we do with this

quasi bison
#

can you come up with a generalization to 4 coordinates in the same way i showed

#

use x_1, x_2, x_3, x_4 for the rectangular coords and r, theta_1, theta_2, theta_3 for the spherical coords

split fulcrum
#

(x1)^2 + (x2)^2 + (x3)^3 + (x4)^4 = r^2

#

x1 = rcos(theta1)
x2 = rsin(theta1)cos(theta2)

#

and

quasi bison
split fulcrum
#

but didnt you say to use x1,x2,...

quasi bison
#

i did, but the equation i specifically replied to is not what im looking for.

split fulcrum
#

x3 = rsin(theta1)sin(theta2)cos(theta3)

#

x4 = rsin(theta1)sin(theta2)sin(theta3)

quasi bison
#

ok great

#

thats good now

#

can you write down the generalization of this to n coordinates

#

you'll have one radial and n-1 angular coordinates on the polar side of things

#

also you will want to write down the ranges that these thetas go over

#

for integration purposes

split fulcrum
#

x_n = rsin(theta1)sin(theta2)...sin(theta_n-2)sin(theta_n-1)

#

x_n-1= rsin(theta1)sin(theta2)...sin(theta_n-2)cos(theta_n-1)

#

theta 1 and theta 2 from 0 to pi maybe

safe radishBOT
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normal moss
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quaint marlin
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dull sequoia
#

What have you tried

quaint marlin
#

Why I should find the constant '' C''??

edgy breach
#

why do you need integration?

dull sequoia
#

On the right side you have an integral with respect to t, and the integrand is a function of t, that’s perfect

#

But on the left side you have that v is a function of t

#

But there’s no dependency on t on the right side

#

Once you integrate the t will disappear and v(t) will always be a constant

#

It’s more like $v(t) = \int_0^t a(\mathcolor{green}{t}),d\mathcolor{green}{t}$

flat frigateBOT
#

frosst

dull sequoia
#

Where the green and white t’s aren’t the same t

#

Does this make sense?

edgy breach
#

i dont understand why you are using calculus at all when acceleration is constant

safe radishBOT
#

@quaint marlin Has your question been resolved?

quaint marlin
#

No
I forgot that v(6)=45

quasi bison
# quaint marlin

$\int_0^2 a(t) \dd{t} = v(2) - v(0)$, and you don't know $v(0)$ (yet).

flat frigateBOT
dull sequoia
quaint marlin
#

Yep

dull sequoia
quaint marlin
quaint marlin
dull sequoia
#

Where did v(6) = 45 come from

quaint marlin
dull sequoia
#

Where in the question does it say that