#help-23

1 messages · Page 373 of 1

neon vapor
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you give yourself not nearly enough credit

cloud hound
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If you have any feedback I'm very willing to hear though 👌

cloud hound
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Proofs with no words

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All symbols 💀

neon vapor
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i see both that and proofs with only words

cloud hound
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I'm sure you would love some of my proofs from freshman year where I get distracted in the middle and have to come back later to finish

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No no that makes sense, I've never heard of structural induction tbh so I was just making up what I thought might be right

safe radishBOT
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@cloud hound Has your question been resolved?

cloud hound
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I'll be continuing to do exercises from the book for at least a week

safe radishBOT
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silk cove
#

how do I strat it?

safe radishBOT
silk cove
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x=10 mod 21
x=10 mod 22
x=10 mod 56

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x=0mod37

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x can be replace by 37k

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looking for any kind of short approach which takes very low time

plucky elk
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Find the least common multiple of 21,22,56 and express x in terms of the LCM

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Then plug that expression into mod 37

silk cove
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LCM of 21,22,56 is 2^3.3.7.11

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i did not understand express x in terms of LCM

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you meant like 37

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big divide wait

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1848/37 so we get

vivid bison
silk cove
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i got 1848=37.49+35

vivid bison
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How's that useful?

silk cove
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i have no idea

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i only worked what they suggested

vivid bison
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Do yk how to find lcm?

silk cove
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35=-2 mod 37

silk cove
vivid bison
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Now find lcm of 1848 and 37

silk cove
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damn

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1848.37

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big number

vivid bison
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Yep

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Any questions?

silk cove
plucky elk
quasi bison
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x-10 is a multiple of LCM(21, 22, 56) and x-10 ≡ -10 (mod 37)

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so we should be looking for the least value of x-10 in light of this, i think

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@silk cove

silk cove
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x-10 ≡ -10 (mod 37)

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ohh 1848k+10 mod 37

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so we need to check by putting k=1,2,3,4

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so on

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k=5 works

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ohh simple

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.close

safe radishBOT
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strong pike
#

Question and book solution

safe radishBOT
strong pike
quasi bison
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you're applying both discounts to both bills at once

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in reality the 9800 bill is supposed to ONLY get the 2% off for 'within ten days' and the 5480 gets ONLY the 5% off for 'payment the day-of'.

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these discounts don't stack in any way!

safe radishBOT
#

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strong pike
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midnight sonnet
#

Can someone please walk me throught his dry run of the Dijkstra's algorithm

midnight sonnet
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I mean I know how it works but I do not know how to fill this table

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the table is for this graph

safe radishBOT
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@midnight sonnet Has your question been resolved?

midnight sonnet
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alright, ping pong people

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<@&286206848099549185>

livid lodge
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mhm, I'll try to explain it in the best of how I can word it. So you know the Dijkstra algorithm. It starts from a permanent point and adds a certain weight to each other point. V(T) is all the points you've crossed at step 1,2,... E(T) is the connection. F is a sort of buffer I believe, to see which points you haven't yet used. and L is the weight of each point at every step.

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So at step 0 you know know that point a is 0 and all others haven't been checked so therefore they are inf

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once you set that first step and check from a-b you know the weight of b

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does this help? or is something in my explenation confusing?

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@midnight sonnet

midnight sonnet
livid lodge
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Alright, feel free to ping me when you're stuck

midnight sonnet
midnight sonnet
# midnight sonnet

@livid lodge This is the graph and here is the table from before, now as you can see that after we assess the distances of b and c from a, we put F as {b,c} in the table. Which are the vertices that we have checked the distance of a from. But in step #2 of this table, we are checking the distances of d and e from b. Then why do we have to include c in F too? As you can see, F in step #2 is {c,d,e}, whereas I think that it should have been {d,e}, because we are only checking b's distance from d and e, but not c.

livid lodge
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F is a sort of buffer, it stores the points not checked. So in Step 0 you have a in F, so that's the on you check in that step and fill in all the neighbours of a. These are 'temporary points'(idk how your professor explained Dijkstra, that's how he explained it to me).
So next step, you have {b,c} in your buffer, so you see the weight of each point from a. for b that's 3, c that's 4. Next step you choose the one with the lowest weight, in this case b(since b<c obv.) so we remove b from the buffer F and make it a 'permenant point'(meaning this is decided to be the shortest path from your origin point, in this case a). Then you repeat stap 0, check all the neighbours of b: d & e and fill their weight in. Once you've done that you now have the buffer F that started like this: a[origin, therefore smallest point] -> b,c [neighbours of a, with b smallers, take this one out of the buffer] -> c,d,e[neighbours of b, with c the smallest, take this one out].

This is a bit of extra info for the next step if you're still confused, text above should have everything already explained. So now we have c, we make that point permanent, and check it's neighbours, that's a and e. a has already been checked so doesn't get added to the buffer, e is already in the buffer so nothing changes. Check the weights of c to e, that's 1. Add the original weight from c + {{e,c}} and you get 5, this is FAR shorter than from a-b-e so it gets changed in the table. Now e has become the smallest point and rinse and repeat

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If something is still confusing you, I'll try to visualise it more in the next explenation :) feel free to still ping me

safe radishBOT
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@midnight sonnet Has your question been resolved?

safe radishBOT
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@midnight sonnet Has your question been resolved?

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spare shale
#

"Hi everyone! I'm from the Philippines and I'm aiming to win the Division Math Celebration Quiz Bee for senior high school. I'm in Grade 11. I think the competition will focus on statistics what i would do

safe radishBOT
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nimble vine
#

what topics are you looking for?

safe radishBOT
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@spare shale Has your question been resolved?

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covert rain
#

$\int^1_{-2} \frac{x+1}{\sqrt{x+3}+2}dx$

flat frigateBOT
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Professor Edward C. Hawthorne

safe radishBOT
covert rain
#

How could one understand that the best substitution was √(x+3)=t?

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I tried to rationalize it since there was a root underneath, by parts...

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Also it's not clear to me after the substitutions, how you break the numerator and denominator like that

flat frigateBOT
untold magnet
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no idea about why he thought about taking root x+3 as t tho

covert rain
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Ok this Is clear

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Thanks

untold magnet
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mb small mistake

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welc

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.close if youre done btw

covert rain
#

.close

safe radishBOT
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midnight sonnet
#

please give me a proof question

safe radishBOT
midnight sonnet
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(either direct or contraposition or contradiction)

hard crest
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prove √3 is irrational

midnight sonnet
#

okies

midnight sonnet
hard crest
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of course it does, a = 3(n/a)

faint hornet
midnight sonnet
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does that break anything

hard crest
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then i suppose m wouldn't be an integer either, but what does that mean?

midnight sonnet
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does k here has to strictly be an integer?

hard crest
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well given that you defined it that way.... yes

midnight sonnet
hard crest
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why can n/a not be an integer?

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i'm having trouble following your train of logic; could you state it in a more self-contained manner?

midnight sonnet
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will it always be an integer

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if a^2 = 3n

severe pond
midnight sonnet
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alright i'll just state the condition that i faced in the proof

severe pond
midnight sonnet
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i got a^2 = 3b^2

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can i say that a = 3m

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(multiple of 3)

severe pond
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again

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where is n coming from?

midnight sonnet
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basically i got a/b = root 3

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then a^2/b^2 = 3

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a^2 = 3b^2

severe pond
midnight sonnet
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now i wanna conclude a is a multiple of 3

severe pond
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prove that 3 | n^2 —> 3 | n

faint hornet
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(where a | b means that b is divisible by a)

midnight sonnet
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a | b means b = ak?

severe pond
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yes

midnight sonnet
#

n^2 = 3k
n = 3(k/n)
n = 3l for l = k/n

midnight sonnet
midnight sonnet
severe pond
midnight sonnet
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yea thats what im talkin abt 😭

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it might notbe

faint hornet
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you wanted a proof by contradiction / contraposition question right?

you can in fact, use one of those to prove what knief is asking

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so why don't you give it a go first and forget about hayley's question for now

then use this result to come back to it

midnight sonnet
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ok if i assume k/n is not an integer

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how do i move forward

severe pond
midnight sonnet
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alright well contraposition proof works

premise: 3 not | n
then n != 3k
n^2 != 9k^2
n^2 != 3(3k^2)
n^2 != 3l

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hence n^2 not | 3

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so 3 | n^2 means 3 | n

faint hornet
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yeah, the main idea being that is 3 does not divide n, then it cannot divide n^2 either

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so could you perhaps use this now to prove hayley's problem from before?

midnight sonnet
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or is it implied (was very non obvious to me )

faint hornet
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that depends on how much detail you want to put in, but it is worth knowing if it's non obvious to you

midnight sonnet
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do you have another proof question

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i did the root 3 one

faint hornet
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prove there are infinitely many primes

midnight sonnet
#

okay uhh

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ig i can try

midnight sonnet
faint hornet
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if by N you mean naturals, then it is almost right; the only difference is that 1 is not prime

midnight sonnet
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what about now

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GCD(m,n) = n

faint hornet
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no

midnight sonnet
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after excluding 1

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?

faint hornet
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you should just think of primes as positive integers that are not 1 that are only divisible by 1 and themselves

midnight sonnet
faint hornet
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suppose you have say 3, an obvious prime

then gcd(5,3) = 1, not 3

midnight sonnet
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wat now?

faint hornet
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what

midnight sonnet
faint hornet
midnight sonnet
faint hornet
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okay how about we start like this

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look at the question, do you think you would use contradiction or contraposition?

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and why

midnight sonnet
faint hornet
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right, exactly

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so what do you want to assume

midnight sonnet
faint hornet
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okay, good

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so one thing we can do with this, is suppose that we have this finite list of primes p_1, ..., p_n

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if we can find a prime NOT in this list, then we are finished

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we're trying to look for a way to achieve this

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can you think of any methods

midnight sonnet
# faint hornet with this as a hint

well if for every n belong to N, there is a unique combination of product of primes, then we need an infinite amount of combination of primes to accomodate every n. That would mean that there are infinite primes

faint hornet
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not quite, because we can make infinitely many numbers with even one prime! since we can just take 2^n for any n

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what i am rather hinting towards is trying to find a number which is not divisible by any of these primes

midnight sonnet
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like suppose if 3 is the only prime

faint hornet
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you tell me!

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that's the crux of the problem :)

midnight sonnet
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thats why there are infinite primes

faint hornet
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right but that is not a proof

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often times in math there are things that work very unintuively

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so we can't just say "i think this will happen" and then call it a proof

midnight sonnet
faint hornet
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well can you prove that

midnight sonnet
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if u have infinite numbers then u got infinite combinations

faint hornet
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suppose our only prime was 2

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then 2, 2^2, 2^3, 2^4, ..., 2^n, ... are only "combinations" of one prime

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and yet you have infinitely many numbers

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so this is not a valid argument for saying there are infinitely many primes

midnight sonnet
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that p_1...p_n , i add all these, and add a 1

faint hornet
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that does not prove anything

midnight sonnet
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okay how abt i multiply them and then add 1

faint hornet
#

okay, why?

midnight sonnet
# faint hornet okay, why?

if i can prove that the new number is also prime then there is a prime that is bigger than my original existing largest prime

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i.e a contradiction

faint hornet
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okay, but what if it is NOT a prime

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for example, 2*7+1 = 15 is not prime

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but it still proves existence of a new prime... why?

midnight sonnet
faint hornet
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yes!

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exactly this, so where is the contradiction

midnight sonnet
faint hornet
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that is precisely the definition of a composite number, yes

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so if the product + 1 is composite, why does a prime from our list not divide it?

midnight sonnet
faint hornet
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sure, we can say that

midnight sonnet
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ok so the list is not complete

faint hornet
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more precisely it's because it would have to divide 1 also, and there is no such prime

midnight sonnet
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there is a prime that is out of our list that divides our number

faint hornet
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exactly

midnight sonnet
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alr so the original assumption was false

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hence proved

faint hornet
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yep :) nice job

midnight sonnet
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here's the thing

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how do i come up with all this rocket science in the exam hall

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there is less time and more pressure and problems harder than this

faint hornet
faint hornet
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i think, these are kind of natural proofs that you were asked so far

midnight sonnet
#

btw why are all composites divisible by some prime

faint hornet
midnight sonnet
faint hornet
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okay, and what if we keep splitting up this composite number into its divisors

midnight sonnet
#

but idk why is that the answer to this question

faint hornet
#

our divisors keep getting smaller and smaller

midnight sonnet
faint hornet
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so eventually, we need to find a number which has no divisors other than 1 and itself

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which is precisely what a prime is

safe radishBOT
#
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viscid monolith
safe radishBOT
viscid monolith
#

a)
Since $a_n = \frac{a_{n-1}}{2+a_{n-1}}$ then $a_{n+1} = \frac{a_n}{2+a_n}$
$\frac{a_{n+1}}{a_n} < 1$ as $a_n >0$ it simply implies that it would be a decreasing sequence. We also know that $a_n > 0$ Hence, it is bounded by 0.
So, by the monotone convergent theorem, ${a_n}$ is convergent.

b) Since it's a decreasing monotone function, I inferred that $a_1 > a_2 > a_3 ... > a_{n-1} > a_n$. Since $\lim_{n\to \infty} [a_n] = L = \lim_{n\to \infty} [a_{n-1}]$ then
$\lim_{n\to \infty} [a_n] = \lim_{n\to \infty} \frac{a_{n-1}}{2 + a_{n-1}}$ is same as saying L = $\frac{L}{2+L}$? $\therefore$ the limit of ${a_n}$ as n tends to $\infty$ is 0.

flat frigateBOT
#

Maddie

viscid monolith
#

I tried this question and I would like to get inputs on whether I did it correctly or not?

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The answer is 0 - textbook solution.

cloud hound
#

I can't say anything on correctness but I am wondering how you derived a_n+1 = in a)

viscid monolith
# viscid monolith

So my thinking was if the $a_n = \frac{a_{n-1}}{2+a_{n-1}}$ it would mean that at some n, the value of $a_n$ is that of the previous value. Hence, $a_{n+1}$ would be $a_n$.

flat frigateBOT
#

Maddie

viscid monolith
#

I think I worded this really really badly blobcry

viscid monolith
#

.close

safe radishBOT
#
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opaque fern
#

Note

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You should explicitly mention why you chose to ignore -1

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Otherwise, good job

viscid monolith
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Sorry, what do you mean by -1?

cloud hound
#

I thought it was multiplication 😅

keen tulip
#

yeah bad tex

opaque fern
viscid monolith
#

Oh!!! Yes yes, thank you so much for your help!

keen tulip
#

you're welcome

safe radishBOT
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safe radishBOT
#

Please don't occupy multiple help channels.

magic junco
#

.solved

safe radishBOT
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glossy bear
#

Can someone check if this proof is right?

safe radishBOT
glossy bear
cedar widget
#

Its fine

#

Just you gotta work on the handwriting monkey

glossy bear
#

Ok thx

primal bone
#

And, also, to draw the implies symbol clearly

#

It's not a closed-arrow:

flat frigateBOT
#

Waes (Wires)

cedar widget
#

Also $\in$

flat frigateBOT
#

ExpertEsquieESQUIE

safe radishBOT
#

@glossy bear Has your question been resolved?

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midnight sonnet
safe radishBOT
midnight sonnet
#

is this a PHP question

cloud hound
#

What is PHP?

midnight sonnet
cloud hound
#

Ah

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I do suppose you could use it here

midnight sonnet
#

idk what the buckets would be tho

quasi bison
#

maybe you could try to contrive a scenario where NOBODY is surrounded by two boys

glass wasp
#

I suppose yes, since the only way to avoid that would be to have girl-girl-boy-boy-girl-girl-...
And eventually the last spot would cause 2 boy neighbours

midnight sonnet
#

will that invlove PHP

glass wasp
quasi bison
#

number the seats 0 to 24

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put a boy in seat 0

quasi bison
#

seats 23 and 2 will have to be girls bc then seats 24 and 1 can't have two boy neighbors

midnight sonnet
quasi bison
#

try to continue filling it in like this

glass wasp
midnight sonnet
#

.close

safe radishBOT
#
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vague glen
#

Can someone explain if in the last step, the solution, could it be written as -3sinx³ instead of -3x² as the constant is put in the front , like with 10 here.

I do the formula differently(2nd pic) so naturally the values are placed differently compared to the 1st pic.

I'm stuck pls help

plucky elk
#

,rotate

flat frigateBOT
vague glen
#

How'd u get this exact pic to rotate, does it do it automatically

iron estuary
vague glen
iron estuary
#

the 3 is a constant and can be moved but x^2 is not

#

it arises from the chain rule while differentiating x^3

#

so writing -3sinx^3 would be wrong

vague glen
iron estuary
#

because 10 is just a number, so it’s a constant

#

you can move constants around not variable dependent factors

vague glen
iron estuary
#

yes 3 is a constant but x^2 is not

vague glen
#

Which aren't constant

iron estuary
#

10 comes from constant × constant (2 x 5) right?

vague glen
iron estuary
#

3x^2 comes from constant × variable so only the constant part can be moved around

iron estuary
#

“moved” just means rearranged in the product

vague glen
iron estuary
#

$-3x^2\sin^2(x^5)\sin(x^3)\quad \text{or}\quad -3x^2\sin(x^3)\sin^2(x^5)$

flat frigateBOT
iron estuary
#

or $-,\sin^2(x^5)\sin(x^3),3x^2 ;\text{or}; -3\sin(x^3)\sin^2(x^5),x^2$

flat frigateBOT
iron estuary
#

is the fourth one what you mean?

vague glen
vague glen
iron estuary
#

i thought you were removing the x^2 my bad

vague glen
#

Oh...m

#

Dang

iron estuary
#

as long as you don't do that its good

vague glen
#

So constant can go anywhere regardless

iron estuary
#

yeah

vague glen
#

Hmmm

iron estuary
vague glen
#

I was stuck as to what to do

iron estuary
#

ah okay

vague glen
#

How're you so good ar maths

#

It's hard to get answers to such minor questions w/o a teacher so this server is yhr last resort sadly

iron estuary
#

tbh asking these kinds of questions is how it starts

#

the rest is just practice and time

vague glen
#

Alright thanks

#

.closs

#

.close

safe radishBOT
#
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radiant ice
#

I have two answers: 123° and 66°.

For 123°, if we look at the top left corner, the lower angle is 90° - y, and the upper angle is 90° - x. In a rectangle, and then 33° is the middle angle. These angles form a right angle according to rectangles. So, 90° - y + 90° - x + 33° equals 90°. Adding x and y from the left, subtracting 90° from the right, we get 90° + 33° equals x + y, which is 123.

For 66°, we use the alternate interior angles, which means that y and x are both 33°. Adding both of them gives us 66°.

radiant ice
proud tree
#

alt int angles requires parallel lines

radiant ice
#

oooh wait

#

i just noticed

#

it would be 33 + 90-x

proud tree
#

for alt int you require red and yellow segments to be parallel

#

ignore how horribly I've shaded it

radiant ice
radiant ice
proud tree
#

👍

proud tree
radiant ice
#

horrible to draw on phone

radiant ice
#

red, y = 90 - x + 33

proud tree
#

that's correct

radiant ice
#

yeah that’s what alt int for me was

#

but i did it wrong

#

o well

proud tree
#

happens

radiant ice
#

thanks

#

.close

safe radishBOT
#
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safe radishBOT
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quasi timber
safe radishBOT
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midnight sonnet
safe radishBOT
midnight sonnet
#

How to disprove isomorphism between these two

#

I have checked 11 invariants so far, number of vertices, edges, degree sequence, existence of circuit, euler circuit, hamiltonian circuit, and bipartiteness

#

They satisfied all of them

cloud hound
#

Better start comparing adjacency matrices and showing that no rearrangement of rows can make them equal

#

The way things keep going with you and these invariants 😂

quasi bison
midnight sonnet
#

does the in/out sequence have to be exactly equal?

quasi bison
#

obviously yes it does

midnight sonnet
quasi bison
#

well there you have it

midnight sonnet
quasi bison
#

redraw the first one by swapping the positions of u1 and u3 on the page

midnight sonnet
#

although the first graph has a longest path of length 3 while the second graph has the longest path of length 2, so they are not isomorphic

quasi bison
#

yes or that

midnight sonnet
#

not?

#

ok

quasi bison
#

autocorrect bs

#

on my end

midnight sonnet
#

ty

#

.close

safe radishBOT
#
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midnight sonnet
safe radishBOT
solar hazel
#

imagine coloring all the edges in K_10 red or blue

safe radishBOT
#

@midnight sonnet Has your question been resolved?

safe radishBOT
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serene fog
#

By examining the chest X-ray, probability that T.B is detected when a person is actually suffering is 0.99. the probability that the doctor diagnoses incorrectly that a person has T.B. on the basis of X-ray is 0.001. in a certain city 1 in 100 persons suffers from T.B. A person is selected at random is diagnosed to have T.B. What is the chance that he actually has T.B.?

can someone draw probability tree for this and show pls

serene fog
#

idh my mobile so i cant show my working

keen tulip
#

latex your probability tree

#

oh you want us to draw the tree

safe radishBOT
#

@serene fog Has your question been resolved?

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umbral parcel
safe radishBOT
lone void
#

what have u tried

umbral parcel
#

i drew a diagram

lone void
#

send

umbral parcel
#

idek if that's right

lone void
nimble vine
lone void
#

can u use different variable for the 2 surfaces

#

both ur frictions are F(r)

#

and also how can u say that F(r) = u1 R?

#

this is only limiting case

umbral parcel
#

because Fr = Fmax = uR no?

#

in limiting equilibrium

iron estuary
#

fix the notation

lone void
umbral parcel
umbral parcel
iron estuary
#

the diagram's fine

umbral parcel
#

is it the Frs?

iron estuary
#

yeah its the F_r labels

umbral parcel
#

what should i change them to?

#

FrA and FrB? 😭

lone void
# umbral parcel

i dont think u need any more equations..u just have to substitute stuff from here

lone void
iron estuary
umbral parcel
#

so my 1/2 mg cos theta = Rb sin theta + Fr Cos theta equation is right?

lone void
#

ye

#

specify the Fr tho

umbral parcel
#

FrB right?

#

cause i'm doing moments around A

lone void
#

yeah

umbral parcel
#

so then FrB cos theta turns into u2R cos theta?

iron estuary
umbral parcel
#

hmm ok

#

i hate applied so much

iron estuary
#

lol yeah it can be brutal sometimes

#

once the moments are written with the correct lever arms try eliminating R_a and R_b

#

if the forces disappear and only θ is left, you’re on the right track

iron estuary
#

oh, what's wrong?

umbral parcel
#

wait maybe i've got it 😭

#

i'll come back if i get it wrong

#

Did I make a silly mistake?

#

@iron estuary

iron estuary
#

oh you’re really close just a small slip

umbral parcel
#

nooo 😭

iron estuary
#

in the force balance $R_A \neq R_B$

flat frigateBOT
iron estuary
#

when eliminating $mg$ use $R_A = mg - \mu_2 R_B$ not $R_B$

flat frigateBOT
iron estuary
#

fixing that gives the missing $\mu_1 \mu_2$ term

flat frigateBOT
umbral parcel
#

how is one so helpful 😭

#

i'll go revisit it lol

iron estuary
#

yes yes you got it

umbral parcel
#

Does tan theta equal that?

#

@iron estuary

iron estuary
#

at this stage yep

#

but don't stop here

umbral parcel
#

where the hell is u1 😭

iron estuary
#

replace R_a using vertical equilibrium, then simplify

iron estuary
umbral parcel
iron estuary
#

horizontal equilibrium is just $R_B = \mu_1 R_A$ right?

flat frigateBOT
iron estuary
#

vertical is $R_A = mg - \mu_2 R_B$

flat frigateBOT
umbral parcel
#

i've made this harder by not including Ra and Rb haven't i?

iron estuary
#

well i wouldn't say harder... you just took a slightly longer scenic route

umbral parcel
#

man i don't wanna do this anymore, i've got 5 more of these 😭

iron estuary
#

its okayy you’re literally one substitution away 😭

#

next 5 will feel way nicer

umbral parcel
#

i feel like i'm being really thick 😭

#

i'm just not understanding

iron estuary
#

oh no where are you stuck

umbral parcel
#

I’ve gotten here idk if that Rbs and Ras are correct but idk how to get rid of that Ra at the beginning

iron estuary
umbral parcel
#

but didn't i just sub out mg? 😭

#

why am i putting mg back in?

iron estuary
#

this is just substitution whiplash

#

you’re allowed to use mg temporarily if it helps eliminate R_a​

#

think of it as changing variables not undoing work

umbral parcel
#

ok then (1/2 (mg) - u2Rb)/u1Rb?

iron estuary
#

yep that idea just keep mg u2Rb and together in brackets 😭

#

after that i promise it simplifies cleanly

#

use your horizontal balance

umbral parcel
#

Am I close? 😭🙏 @iron estuary

iron estuary
#

$mg = R_A + \mu_2 R_B$

flat frigateBOT
iron estuary
#

what have you written?

umbral parcel
#

i wrote mg = u2Ra + Ra...

iron estuary
#

well its u2Rb right 😭

verbal void
#

for this you have to equate torque as well right?

umbral parcel
#

what the hell is torque? 😭

verbal void
#

i might be wrong then

umbral parcel
#

this is making me wanna cry 😭

umbral parcel
#

@iron estuary

verbal void
umbral parcel
#

i've thought about vertical equilibrium and horizontal

#

used Fr = Fmax = uR

#

and took moments around A

#

which is against the floor

verbal void
#

wait im stupid my bad

iron estuary
#

$F_{rB} = \mu_2 R_B$

flat frigateBOT
umbral parcel
umbral parcel
verbal void
iron estuary
umbral parcel
#

i thought you saw the screenshots 😭

umbral parcel
verbal void
iron estuary
#

OHH

umbral parcel
#

i'm going crazy, i just wanna go to sleep 😭

#

do i have to do the whole question again from the start?

iron estuary
#

im so sorry 🙏

umbral parcel
iron estuary
#

well whatever you've done so far is right luckily

umbral parcel
#

i should be able to do this

verbal void
#

btw torque is basicaly moment sorry i confused you

umbral parcel
iron estuary
umbral parcel
#

wait no FrA = u1Rb

#

is that not true?

verbal void
#

u1Ra

umbral parcel
#

but Fra = Rb

verbal void
#

because friction is coefficient of friction x normal force at that point

umbral parcel
#

if left = right

verbal void
#

so u1Ra=Rb

iron estuary
#

horizontal equilibrium gives Rb = Fa = u1Ra but that doesn't mean Fa = u1Rb

umbral parcel
#

should i just do the whole question again but with the right equations?

iron estuary
#

aa im so sorry i feel like ive caused all this 😭

umbral parcel
#

nonono there's two people helping me now and i still don't fully get it 😭

umbral parcel
iron estuary
#

if you don't get the idea behind it you should start over

umbral parcel
#

ok 💔

iron estuary
#

i'll actually read everything this time omg 😭

umbral parcel
#

did you not the first time ⁉️ 😭

iron estuary
#

i didn't see the right side, well i did kinda but i just didn't notice the A and B

umbral parcel
#

okok 😭

iron estuary
#

its okay it'll be quick quick

opaque fern
umbral parcel
#

omg is there another helper here? 😭

#

you're like the third one 😭

austere goblet
#

some channels have like ten of them rotating in and out
but usually courtesy is that if a channel already has good progress with a helper we don't step in unless to correct mistakes

iron estuary
#

really ten?

umbral parcel
iron estuary
#

😭

umbral parcel
#

anflo's doing a great job

austere goblet
iron estuary
umbral parcel
nimble vine
#

the coordinate system guy

iron estuary
#

oh wow

umbral parcel
nimble vine
austere goblet
#

ok let's get the channel back on track

umbral parcel
opaque fern
lost jewel
umbral parcel
iron estuary
#

just remember friction is μ × normal at the same contact point

umbral parcel
#

I DID IT 😭😭😭 @iron estuary

#

god that took forever

#

thank youu!! @iron estuary

iron estuary
#

you did most of the work!

#

and np

umbral parcel
iron estuary
#

now you can sleep peacefully

umbral parcel
#

i'm contemplating if i want to so another question 😭

umbral parcel
iron estuary
#

next one will feel way shorter after this

iron estuary
umbral parcel
#

6, 3 then 8 marks

iron estuary
#

oh

#

maybe not then

#

thenn get some rest, you've earned it

umbral parcel
#

okayy, can i find you if i need help again? 😭

iron estuary
#

sure

umbral parcel
#

okk

#

.close

safe radishBOT
#
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safe radishBOT
open wedge
#

<@&268886789983436800>

#

spam for sure

safe radishBOT
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turbid salmon
#

Given a pyramid S.ABCD with base ABCD being a trapezoid with bases AD and BC, let M be the midpoint of SA. Knowing that BM is parallel to the plane (SCD), calculate the ratio AD/BC.

turbid salmon
#

I know I have to use Thales theorem but I just can’t prove it

safe radishBOT
#

@turbid salmon Has your question been resolved?

lost jewel
#

If so, send it here, else make one and send it here

turbid salmon
#

wait me

#

here

#

<@&286206848099549185>

radiant ice
# turbid salmon

try making the base lie in the plane z = 0, and make abcd coordinates

turbid salmon
#

ok

#

i got 2

#

the final answer is 2

radiant ice
#

that’s what i got

turbid salmon
#

thank you

#

.close

safe radishBOT
#
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safe radishBOT
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latent solar
latent solar
#

oh give me a sec

#

i don't understand how they derive the A

#

like capital A

#

i know what it's helpful, but idk what they did to get A

cloud hound
#

(Denominator of s)

latent solar
#

yea but like the coefficnets of cos and sin are different

cloud hound
#

Draw a triangle

#

Hypotenuse A

#

One side 7sqrt(3)

#

The other 11

#

By pythagorean thm, A = what they write

latent solar
#

well yea i know that

cloud hound
#

Mark the angle adjacent to the 7sqrt(3) side as alpha

#

Then cos(alpha) = 7sqrt(3)/A and sin(alpha) = 11/A

latent solar
#

wait i'm dumb

cloud hound
#

This gives us the rewriting of the fraction

latent solar
#

.close

safe radishBOT
#
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trim slate
#

hello i need help with factoring, i dont understand how im supposed to know which numbers are the right ones to use if that makes sense.

for example i wanna use 7,8 to factor here but ik it will be smaller numbers but im so confused how im supposed to figure them out

trim slate
#

hopefully that makes sense

rustic goblet
trim slate
#

how am i supposed to know what the smallest square is..

#

is that something you just memorize

primal bone
#

(well, technically the largest square that divides 56)

rustic goblet
#

whoops, I dunno why I said smallest KEK

rustic goblet
crimson python
rustic goblet
#

for instance, it can't be 7 because 7^2 = 49 doesn't divide 56

#

so it's gotta be smaller

trim slate
#

the only thing is i try to do trial and error but its hard when i dont know whats right or wrong

uneven knoll
#

ie the largest square factor?

uneven knoll
#

in that case write the prime factorization of the number that you have

rustic goblet
#

oh, prime factorization is a bit different pikathink

uneven knoll
#

so you said that 56=7*8

trim slate
#

right

uneven knoll
#

now 7 is prime, but 8 isnt

#

so write 8 as a product of primes too, how does that look like?

trim slate
#

so that means i need to go lower?

trim slate
uneven knoll
primal bone
uneven knoll
trim slate
#

so that will tell me what primes numbers are?

primal bone
#

-# And also learning what prime numbers are, since that's paramount to what the goal here is

trim slate
uneven knoll
#

so like a natural number p is said to be prime if the only divisors of p are 1 and p

#

lets have some examples

trim slate
#

so basically like 2 and 3 because they cant get lower without 1?

uneven knoll
#

for example the number 13, the only numbers that divide 13 are 1 and 13 right?

#

so 13 is prime

primal bone
#

-# Okay, to paraphrase Inigo Montoya, you keep using that word [lowest] but I don't think you're quite clear on what you mean by that

uneven knoll
#

so it isnt prime

trim slate
#

so basically what i would need to do, if i assumed 7,8 could work, i need to test to see of both are prime numbers, if not i go lower?

primal bone
#

-# [you've missed 4, but yes]

uneven knoll
trim slate
#

wait so since i wanted to try 7,8 since 7 is a prime number but ik that 8 isnt, wouldn’t i just be able to break down 8

#

but keep 7?

crimson python
#

yep

uneven knoll
trim slate
#

it cant be 4 because of 2, meankng it would have to be 2 right?

#

but 2x2x2

uneven knoll
#

right

trim slate
#

OKOK i get it but

uneven knoll
#

so 2 is the only prime divisor

#

and it occurs 3 times

#

so 2^3. Now to answer your question, find the largest square in the factorization 7*2^3 of 56

trim slate
#

so like here, how 5 stayed the same, 7 would also stay the same correct?

uneven knoll
#

is 7 the only thing that stays the same tho?

trim slate
#

no the z^7 aswell right?

uneven knoll
#

hmmm no not quite

#

forget about the z^7 for now

#

lets just focus on 56 first

trim slate
#

okok

#

ohhh largest square

uneven knoll
#

you said that 56=7*2^3 and that 7 is a prime so it certainly isnt a square

trim slate
#

to find the largest square that’s something ill just have to memorize aswell for future questions?

trim slate
#

so prime numbers cant be square?

uneven knoll
#

now what about 2^3? is 2^3 a square? if no then whats the largest square in 2^3?

uneven knoll
uneven knoll
crimson python
uneven knoll
primal bone
#

/genuine - Do you know what a square number is?

uneven knoll
#

what is the meaning of a square number

trim slate
trim slate
#

ive looked it up on a couple past questions so ik like a few

uneven knoll
#

have you seen the term perfect square before?

trim slate
#

i think so, when i was breaking down past example questions

uneven knoll
#

a square number is the same as a perfect square, i just used a different name. Anyways, a square number/perfect square is a number that can be written in the form of a^2 for some a

#

like 25=5^2, 9=3^2, 49=7^2 etc...

trim slate
#

ohhh i see, but to confirm “a” in this situation is the perfect square right?

#

so 5 3 7 are the perfect squares?

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or id it 25 9 49 that are the perfect squares?

primal bone
#

A square number is a number that is the area of a square with unit-lengths

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So for example, if you have a square of side-length 3, it has area 9

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So 9 is a square number

trim slate
#

but doesn’t that mean anything could be a square number?

primal bone
#

Why do you think that?

trim slate
#

because you say it’s anything that is side length, couldn’t any number be used for a square?

primal bone
#

Any whole-number side-length, yes

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But the square number is the AREA there

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Not the length

primal bone
trim slate
#

but if i did area of square as 4 wouldn’t that mean 16 is also a square number?

uneven knoll
primal bone
#

(because you ought to define what "squaring" even does)

uneven knoll
#

i see, fair point

primal bone
#

So yes, both 4 and 16 are square numbers

crimson python
trim slate
#

so does that mean 25 is also a square number?

uneven knoll
primal bone
#

yes

trim slate
#

SO ANYTHING TIMES ITSELF IS A SQUARE NUMBER?

crimson python
primal bone
#

ye

trim slate
#

ong

#

omg

#

that makes it all make sense

primal bone
crimson python
trim slate
#

omgg that makes everything so much easier

uneven knoll
trim slate
#

so square number and perfect square are the same thing correct? not 2 different terms?

crimson python
#

yep

trim slate
#

okok

#

so back to the equation

trim slate
primal bone
#

If you write it as 2 x 2 x 2, ...

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Can you spot where we're multiplying the same number with itself?

trim slate
#

with 2x2

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so just 2x2^2???

primal bone
#

2 x 2 IS the square number

trim slate
#

that just confuses me now

trim slate
#

what am i supposed to do with it

uneven knoll
primal bone
#

When we write a x a to mean a times a, THIS we can rewrite as a^2

uneven knoll
#

and 2^2 is the square number

primal bone
#

yh that works

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So you've got 7 x 2 x 2^2 - there any more squares?

trim slate
#

wait why cant i write it as 2^3 x 7

uneven knoll
#

you can, and you should

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56=2^3*7=2^2x2x7

primal bone
uneven knoll
#

thats what you have reached from all of the work done above

trim slate
#

okok

#

so here, im on the right track so far?

crimson python
#

yep

trim slate
#

okay so what about z^7

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since its 7 and a cant go lower does it stay?

crimson python
#

you should look at 2^3 first

trim slate
#

wait so 2^3 goes lower?

crimson python
#

2^3=2 x 2 x 2

uneven knoll
trim slate
crimson python
trim slate
#

so at the end i just remove the ^3 and left with 2 correct?

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usually i do that at the end

crimson python
#

nit exactly

crimson python
trim slate
#

i dont actually know the reason behind it

crimson python
#

oh

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see you broke root(56) into root(7) x root(8) right?

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and 8 is 2x2x2

trim slate
#

right

crimson python
#

you can see that there is a square number hiding in 8 what would it?

trim slate
#

its 4?

crimson python
#

yes!

trim slate
#

ohhh

#

wIt

#

wait*

crimson python
#

so can you write root(8) as root(4) x root(2)

trim slate
#

so i can write it as 4^2?

crimson python
#

no thats 4x4

trim slate
#

ohh

#

wait

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they would be 2 separate numbers?

crimson python
#

can you explain more what you mean by 2 separate numbers?

trim slate
#

like this?

crimson python
#

yes so now what is root(4) ?

trim slate
#

2 right?

crimson python
#

yes

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so what does root(56) comes out to be?

trim slate
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2?

crimson python
#

thats what you get outside the root

trim slate
#

ohh 4

crimson python
#

theres still something left inside the root

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no..

trim slate
#

okay now im lost

crimson python
#

see root(56)=root(4) x root(7) x root(2) you got till here right?

trim slate
#

right

crimson python
#

now you know root(4) is just 2 so you write is at 2

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but you cant forget about the non square numbers

trim slate
#

wait now im confused

crimson python
#

you may not be able to write them outside the root but they still exist

trim slate
crimson python
#

so root(4)=2
root(56)=2xroot(7)xroot(2)

crimson python
trim slate
#

im confused what keep them under the root means

crimson python
#

its like you keep root(2) as root(2) as it isnt a perfect

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you cant write it as 2 without the root

trim slate
#

im still confused

#

what do i do with the equation then

#

so i should or shouldnt write it as 7x 4x 2

crimson python
#

you can write root(56)=root(7x4x2)

trim slate
#

but how do i solve it

crimson python
#

but 4 is a perfect sqaure so you took it out as a normal number that is 2

trim slate
#

so i got the root part right?

crimson python
#

now you are left with root(56)=2xroot(2x7)

trim slate
crimson python
trim slate
#

wait im confused how is 2xroot(2x7) written like

split kayak
#

If i might add a detail, you know exponents right?
$16 = 2^4 = 2\cdot2\cdot2\cdot2$

crimson python
flat frigateBOT
trim slate
#

im just even more confused where is 16 coming from😭

split kayak
#

Is just an example

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On that line, you know the exponent rules?

trim slate
#

i dont know what exponent rules mean but looking at a picture i know what that is

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i know that 16 = 2x2x2x2 = 2^4

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if thatswhat ur asking

split kayak
#

like:
$$2^3 \cdot 2^2 = 2^{3+2} = 2^5$$
$$\left(2^3\right)^2 = 2^{3\cdot2} = 2^6$$

flat frigateBOT
split kayak
#

The second one is important

trim slate
#

well kinda, i just relearned it today so its familiar but idk anything beyond the basics

split kayak
#

well, square roots are a sort of exponent too

#

to be specific, we say that $\sqrt 2 = 2^{\frac 12}$

flat frigateBOT
split kayak
#

thats why elements that are a perfect square become an integer

trim slate
#

im getting more n more confused 😭

split kayak
#

$$4 = 2^2$$
$$\sqrt 4 = \sqrt{2^2} = \left(2^2\right)^{\frac 12}$$

flat frigateBOT
split kayak
#

and 2 * 1/2 = 1

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so you end up with 2^1 = 2

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And this not only applies to 2^2, also for 2^4, 2^6, etc...

trim slate
#

im really trying to understand but im just getting more n more lost😭

split kayak
#

could you rewrite 81 in terms of its prime factorization?

trim slate
#

?!?!??

split kayak
#

81 is a perfect square btw.

trim slate
#

whats that gotta do with my question man im getting confused cus im straying more n more away from what im trying to figure out😭

split kayak
#

understanding how square roots work as exponents basically simplifies all of this to a purely symbolical thing

trim slate
#

arent square roots just numbers that r times eachother

#

81 is a square root cus 9x9

split kayak
#

Nope, thats perfect squares.

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the square root is an operation that undoes the "squaring" of a number

trim slate
#

so then how does square roors factor into my equation

split kayak
#

3 squared (3^2) is 9

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so the square root of 9 is 3

trim slate
split kayak
#

yea

trim slate
#

cus 9x9…

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😭

mighty mango
#

-# you're doing amazing char!!!!!!!

split kayak
#

now, prime factorization is useful, because it allows you to easily find the square root

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If its an integer number

#

similar example to your problem:
the square root of 20.

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do you agree that 20 is equal to 2 * 2 * 5?

trim slate
#

yea

split kayak
#

then we can rewrite it as 2^2 * 5

trim slate
#

i know

#

i just learned this

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this is what i was confused on

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but i got an understanding of it now im just trying to incorporate it into my problem

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wont work like that

split kayak
#

can you find the factorization of 56? we will then deal with the z^7

trim slate
#

i already did

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i need help on the next step

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this is what i got so far🫩

split kayak
crimson python
split kayak
#

!occupied

safe radishBOT
#

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

trim slate
#

or 7x2^3

crimson python
trim slate
#

i thought it was about square numbers

crimson python
#

genuine question you do know that this symbol is the symbol for sqaure root?

trim slate
#

i needed help factoring the 56 right, which is square numbers

split kayak
#

for easy visualization: $\sqrt{2^2 \cdot 2 \cdot 7} = \sqrt{2^2}\cdot\sqrt{2\cdot7}$

flat frigateBOT
split kayak
#

I hope it eventually makes sense why i divided it like that

trim slate
#

wait

#

im confused

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where did 2^2x2x7 come from

crimson python
#

<@&268886789983436800> troll in help channel

split kayak
#

1900 gang

trim slate
#

so why can i not just use 2^3 x 7 if they equal the same thing?

mighty mango
#

I've already redirected you to #❓how-to-get-help if you're actually genuine about wanting help. eitherway, the mods will probably warn you blobsatisfied

split kayak
exotic anvil
split kayak
#

means, if you got $\sqrt{2^2}$, thats just equal to $2$

flat frigateBOT
trim slate
#

right

mighty mango