help-23

[left gyro]

it would be on the plane

a plane made out of two vectors that, by definition, are perpendicular from the green vector

and so this point dot the green vector would be 0

no other point on the purple line would do this

see here the purple vector is perpendicular to the green vector

[tulip plover]

so the purple one intersects with the green one yes

[left gyro]

intersects?

that doesnt really relate with this

[tulip plover]

I meant perpendicular

[left gyro]

alr

it is true though that the purple line and the green vector do look like they intersect

thats interesting

oh nvm

just a coincidence

I moved y4, z4 around

the purple stuff move as well but the green vector stays put (its only based on the unmoving blue vectors)

now to find that point,

I have to as before find when green dot purple = 0

here I am having a computer solve it for me first

the ~ command lets me define this t4 in the point in the middle of that as being the value that would make this 0

it seems to have found it, and thats the (t4, y4, z4) that shows up in the image

I do still need to solve for t4, but I have a computer telling me what the final number should be

[tulip plover]

🐙

[left gyro]

V[2], V[3], V[4] are defined on line 2

after putting them in then simplifying, I get

this needing to be 0

looking at this,

it calculates that x-coordinate is √24,

y-coordinate we can see is 2 √2
z-coordinate is 2

alr

and so, I get this needing to be 0

which finally tells me

with the coordinates of the point,

round the x-coordinate to the nearest block

then using for, repeat the same for all the dots

tobe honest, at no stage is there a guarantee that this would line up with the corresponding horizontal slice the 2D link would calculate

theres only that the methods should be close enough that any errors can be fixed

[tulip plover]

that's fine

I think I can just make the tetrahedron and just cut off excess part and sculpt it a little to match the original 2d triangle

[left gyro]

alr go refresh the page

see if it lines up more

theres something Id want to point out here

[tulip plover]

same result?

[left gyro]

you have an outdated copy

go use https://www.desmos.com/3d/dedvuwvoxj

[tulip plover]

that's the only link you gave 😭

[left gyro]

whoops

thats likely true

I never wanted to update this link with how tedious the work is, so I never ended up giving a new version

theres nothing newer here than just face 4

[tulip plover]

same result?

oh

[left gyro]

have Z = -.5 then drag the s slider

it looks pretty satisfying

[tulip plover]

yes I was about to comment on that

so much better than the visually confusing one before

[left gyro]

its a good sign that its doing what its supposed to be doing

thats the same kind of effect as in the 2D case

the movement matches

[tulip plover]

it's all coming together so much win

all that needs to be done is the option for double tip and more accurate to the 2d one

[left gyro]

double tips happen when s is even

thats because the triangle would have a side length of an even number of blocks

[tulip plover]

interesting visual effect

[left gyro]

strange

[tulip plover]

I use the same s value from my inner triangle?

[left gyro]

oh right

whats the X Y d you have on the 2D link?

[tulip plover]

did you change it?

I am not getting the same s value as before

it was just y = 17 d = .5 and x = 1

but before the value of s for the inner triangle was 27.1576766498

oops

I was looking at blue triangle

[left gyro]

lol

[tulip plover]

nevermind the green one is the same

[left gyro]

it is?

[tulip plover]

27.1576766498

yes

[left gyro]

oh I thought you were talking about something else

Im gonna try on your values as an example to see if I can get them to match up exactly

again as before, you need those lower-left corners to be at the center of the block

[tulip plover]

that's basically what I am going to use

yes they are

[left gyro]

what values are you using for this?

[left gyro]

1, 17, .5?

[tulip plover]

yes

[left gyro]

hm

[tulip plover]

d = .555?

[left gyro]

alr now go try it out to see if they match up

[tulip plover]

they don't seem to match

[left gyro]

oh thats no good

[tulip plover]

3 1 2 1 3 1 3

[left gyro]

also look at the double tip

[tulip plover]

yes

[left gyro]

the / side matches only

thats no good

that might very much mean theres no way around this

[tulip plover]

it's so ovee

[left gyro]

that shouldnt be happening though

maybe its just really sensitive to change?

[left gyro]

theres an issue here where double tips happen differently for the 3D than the 2D version

theres no guarantee for the 3D version then

I think I see the why now

they would line up if this is exactly at (.5, .5) of the block

but even a slight difference means the shapes dont line up

[tulip plover]

it's so ovee

[left gyro]

we could fix having to care about this if the 3D version had like

(X, Y, Z)

or something like that

actually it might not be that painful to put in

lets see what happens

[velvet nebula]

is this a 3d render of a tetrahedron

[left gyro]

sure

a summary of what needed to be done hasnt been made yet

as well as a summary of what has been done so far

[velvet nebula]

yeah because if one wants to pick cells to form a tetrahedon, it's probably prudent to inscribe it in a cube

so the question is what the exact requirements are

[left gyro]

?

they want a tetrahedron in minecraft

Im making something that is flexible enough to suit what they want out of it

[velvet nebula]

ah, so it has to be upright

[left gyro]

and has one of the sides be parallel to the axes

Im rather busy redoing the 3D link which is a desmos to a 3D version that displays where to place the blocks

[velvet nebula]

though there's also blocks which are shaped differently from cubes

[left gyro]

theyre not considering that

whole blocks only

[velvet nebula]

ah okay

[left gyro]

@tulip plover

[tulip plover]

hmm

[left gyro]

@tulip plover https://www.desmos.com/3d/qdwneckeak

[tulip plover]

you made it using the triangle I gave?

[left gyro]

no

this is a new version of the 3D link that draws a concentric slice at each z level

really there was nothing stopping this idea from the first place other than that you need the stuff to properly handle non-integer inputs

[tulip plover]

hmm I see

[left gyro]

you line up (X, Y) with the centroid (X, Y)
then set Z such that s would match se

I havent tested it but it should produce the same triangle

[tulip plover]

hmm okay

putting the s in solely gave a triangle that was 21 blocks tall opposed to the original one being like 40 blocks tall

[left gyro]

whats your centroid (X, Y) and se

[tulip plover]

33.1576766498 se

would the cords of the centroid work for here when half the triangle is in the negative side?

I tried messing with other values but didn't know what to put in z

[tulip plover]

set z that s would match se?

wait are you telling me I have to change the value of z multiple times until the s value is the same one from 2d se one?

is there not a way for me to plug in the se value into this?

because I don't seem to be able to get the same value

well I think I got the same triangle basically even though it's not the exact same s value

it's brilliant

now I can finally have my tetrahedron thank you very much

it's a been a long journey

now I have the best possible concentric equilateral triangle and tetrahedron I can have

I will never try to test Minecraft accuracy limits like this again a week of triangles 😭

[tulip plover]

anyways before I go I've been wanting to notify you about the security issues and concerns that arise due to your use of firefox ever since you mentioned you used it when you couldn't access the site I provided

here are some things from security researchers that speak of browser security and speak of the issues of firefox and one that shows you options that are more secure
https://madaidans-insecurities.github.io/firefox-chromium.html

https://github.com/RKNF404/chromium-hardening-guide?tab=readme-ov-file

I feel these are worth the read even though security on PCs kind of suck inherently unless it's a macos since they use microkernels or like a hybrid that has it I myself just use hardened google chrome but an alternative is brave which is the best you will get in the pc world but the absolute best browser has to be vanadium which is only exclusive to grapheneos which is exclusive to pixels at the moment currently the most secure devices you can have until they start producing their own devices soon unless you want to count an hsm or an air gapped seL4 workstation but what's also important to know is that Linux is very insecure contrary to what people think so it is good to be aware of this stuff as security has a lot of misinformation circulating around detailed in this link

https://privsec.dev/posts/linux/linux-insecurities/

anyways you should check out grapheneos if you are interested in getting the best security you possibly can and their discord server is full of useful information that is factually correct and not driven by the feeling of doing things just because they feel good regardless of the actual effect

https://grapheneos.org

anyways bye bye

.close

[safe radish]

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[elder cypress]

What about firefox forks

Like Librewolf

[tulip plover]

same issue

librewolf is still based on firefox

and it carries all the issues along with it

you can also argue librewolf is worse than base firefox

[elder cypress]

Can you even get any non chromium and non firefox browsers that are good

[tulip plover]

as it takes them longer to get the updates out

[elder cypress]

Other than safari

[tulip plover]

chromium is what is good there should be no reason to try to avoid it

[elder cypress]

Monopoly

[tulip plover]

if you truly wish to reject chromium at the cost of your security that is you but it is objectively the best for security

[left gyro]

@tulip plover Ive just woken up

[left gyro]

Im not sure if you understood my instructions but it looks like you did get the exact same equilateral triangle, right?

[tulip plover]

tip is 3 blocks tall on the 2d one but it is not an issue I just cut the top part off

[left gyro]

yea alr

[tulip plover]

now I am going to build a hollow triangle pillar connecting the 2 parts

and then to close this gap from the pillar I am going to turn the bigger triangle into a tetrahedron until it wraps around the pillar

[safe radish]

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[gilded bison]

Does an eulerian figure with 0 odd vertices HAVE TO end up at the same point it began?

[gilded bison]

is it necessary that it creates an eulerian circuit or is it also possibile to end up at another point (also covering all intersections)

[pine rain]

Yes, an eulerian figure with 0 odd vertices must by definition be an eulerian circuit and end at the same point it began.

[safe radish]

@gilded bison Has your question been resolved?

[gilded bison]

thank yo

[safe radish]

@gilded bison Has your question been resolved?

[safe radish]

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[vague rain]

Help how i can find sides

[near atlas]

here is a, the length of side opposite to angle A

?

[rugged bluff]

not enough info?

wheres the right angle

[ornate wyvern]

ah mb

consider one of the angle as 90 degrees with the help of the data

[rugged bluff]

C or A can be the right angle

[ornate wyvern]

check check

i hv a class ping me when neccesary

[rugged bluff]

cos A, csc B = 0, 3/2 or 2/sqrt(13), sqrt(13)/2 if my mental math is correct

[fallow marsh]

Hope you mean the above

[rugged bluff]

theres no reason for the right angle not to be A

you would have sides sqrt(5), 2, 3

[fallow marsh]

But then cosA would be 0

[rugged bluff]

that is valid

[safe radish]

@vague rain Has your question been resolved?

[safe radish]

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[tough mortar]

help

[supple radish]

isnt this physics

[tough mortar]

yeahh they said physics is math

[supple radish]

lmao alright

[near atlas]

would be great if you provide like a screenshot or something

[zealous ingot]

sorry yo

[supple radish]

first

[tough mortar]

this is hard i am only g10 but this is i think college level

[supple radish]

see

g only effects

the downward velocity

here the car has no downwaerd velocity

inititally

you have done problems on range?

like

[tough mortar]

1b until 5b i didnt make it yet

my prof didnt teach us this

[supple radish]

oh

see u can still solve this

[tough mortar]

how

[near atlas]

seems like a horizontal projection problem

[supple radish]

the horizotal

velocity

will not be affected

at all

in air

you just to make sure till the time

car lands

it covesr the distance needed

[tough mortar]

i am already done at the height the problem is the coefficient

[supple radish]

to reach the cushion

so u just find the time taken to reach ground

by normal falling down

and then multiply the time taken with horizontal velocity

[near atlas]

can the car is being projected with a initial velocity of us 90kmph

[supple radish]

to find how much it will travel horizontally till it hits the ground

[near atlas]

thats its horizontal velocity

itll stay unchanged throughout the motion

[supple radish]

g acts downward

no acceleration present in forward direction

[near atlas]

the car will keep gaining a downward velocity component the moment its in air

[tough mortar]

the only problem is the coefficient

[near atlas]

of friction?

[supple radish]

nooo

[tough mortar]

yeah

[supple radish]

yeah

wait

thtas also simple see

u know friction formula?

how it relates to the normal

[tough mortar]

nooo

[supple radish]

frictional force is

Normal * coefficient of kinetic here

your normal force is equal to the weight of the car

but there is no weight..

hmm

it does say

[near atlas]

erm if im not wrong the deflation in the cushion will prevent movement along the y axis and the friction in the cushion will prevent the car from moving further along the x axis upon impact

[supple radish]

normal = weight of car = force on car by cushion

[supple radish]

yea

so to find the normal

u find the impulse on y axis

[tough mortar]

the thing needed is the coeffient of kinetic force

[supple radish]

as the velocity in y direction completely stops after impact

[supple radish]

yeah i know

for that u need to find the

force

on the car by friction

do u have answer key

[tough mortar]

nooo

[supple radish]

oof

well what i though it

😅

just equate this

m * coeff * g = m * a

[tough mortar]

hes so selfish no answer key he said this "Answer key for the Problem Set will NOT be uploaded."

[supple radish]

m cancels out

coeff * g = a

coeff = a / g

formula for knettic fricton is

Normal force * coeff of kinetic

normal force here is just weight

so normal = mg

do you understand?

[tough mortar]

yeah

[supple radish]

i was kinda over complicating

u know both g and a

u will get the answer

[tough mortar]

so the coefficient is 1.53?

[supple radish]

correct

[tough mortar]

since -15/-9.8

[supple radish]

yeah

atleast according to me

which i do believe is correct

[tough mortar]

yooo thank you

[supple radish]

welcome

anything else

?

i mean u sent many problems 😅

[tough mortar]

there is 8 more questions bruhhhh

[supple radish]

see

have u tried all by urself?

and how is this grade 10 😢

i studied these myself in grade 11

[tough mortar]

yesss

[supple radish]

i mean ur teacher gave these problems as an assignment right?

[tough mortar]

and my brain hurts

[supple radish]

it should be solved by u

not me

if u are not able to do it

[tough mortar]

ik lmao

but thanks

[supple radish]

it will be discussed in class

lmao try rest urself

as its an assignment

[tough mortar]

guess what

our exam is at wednesday

[supple radish]

ooohhh

well u can ask me

i dont mind

but atleast try urself

[tough mortar]

yeah thank you

[supple radish]

welcome

[safe radish]

@tough mortar Has your question been resolved?

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[native flume]

would the equation be a quadratic or quartic (if im even right to deduce that it is one of these), since i found some points, sketched it, appears to be an even function

[grim plover]

f(x) is a cubic

i think

[native flume]

why

[grim plover]

hmm on second thought a could be 0

[grim plover]

degree of lhs is atmost deg f + 2 = rhs degree = 5
so deg f <= 3

[native flume]

would RHS degree be 4? due to the x^4?

.close

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[grim plover]

oh i read that 2x-x^4 as 2x \dot x^4 mb then its a quadratic

[grim plover]

.close

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[hoary pecan]

Can anyone tell me how to find the direction of cross product of 2 arbitrary vectors?

[quasi bison]

right hand rule

[hoary pecan]

What is that

[primal bone]

The Internet is an amazing invention sometimes

[hoary pecan]

I don't understand how to apply it

[quasi bison]

show your question(s).

[hoary pecan]

This

[primal bone]

Do you know how to make the gesture here?

[hoary pecan]

Nope

[primal bone]

No, like, this hand gesture

[spiral bronze]

make a finger pistol and extend your middle finger out to 90 degrees

[hoary pecan]

Yea

[primal bone]

Okay

Your first vector is the thumb

Your second is the index finger

First X second will be in the direction of the middle finger

[hoary pecan]

Oh, but should there always be a 90° gap between my thumb and index?

[primal bone]

No, since the vectors you're cross-product-ing aren't necessarily orthogonal

[hoary pecan]

Oh

[primal bone]

Not that it matters, since the middle finger is going to point in a direction orthogonal to the plane the original two vectors have in common

[primal bone]

The point necessarily is to figure out which way out of the plane (hence the specifying which vector's which finger)

[hoary pecan]

Okay

[primal bone]

Related: that's in part why Ann asked you for the original question, i.e.

!xy

[safe radish]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[hoary pecan]

So uh

[primal bone]

-# Good bot, have a cookie

[hoary pecan]

I had this doubt

Where the first vector, 'a' was subtended towards the left side from origin and the 2nd vector 'b' was subtended towards the right side from the origin. The angle between them was 90°. I wanted to know if a×b was into the plane or out of the plane

And I think I found my answer. a×b is into the plane and b×a is out of the plane, am I right?

[primal bone]

ye

[hoary pecan]

Ty

How do I end this?

[primal bone]

Sign off with Yours Faithfully
-# /s

.close to close the channel

[hoary pecan]

Oh ty

.close

[safe radish]

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[safe radish]

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[finite heron]

Let’s say we have a metric space (M,m)

[finite heron]

and then a subset S of M

When we talk about covers

of S

Do the covers have to be countable

Because

usually they are indexed

because I have a problem

[ashen sedge]

Nope
Convers don't have to be countable in general

[finite heron]

Ok then one more question

If we have the set of real numbers under the metric where we take the distance to be the maximum of the absolute values

[ashen sedge]

Unless there are spaces like R^n
(Couldn't find that symbol)

Are you referring to sub-metric?

[finite heron]

Then the set of every point except 0 is open I think?

[finite heron]

I mean in conjunction with d=0 if they are the same point

Wait no

I worded that wrong

For every x in R-{0}, {x} is open?

Is what I meant

under that metric

[ashen sedge]

Thanks alot otherwise I was about to open my book

Yep it is because "R" sub-metric is just the usual metric.
d(x,y) = |x-y|

[finite heron]

Ok thanks

.close

[safe radish]

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[shell horizon]

hi everyone i have a quick question if x in A△B△C the x can be on A and C on the same time ?

[shell horizon]

so is the △ the overlap of the two groups or all the groups

[ashen sedge]

It can be but only when the X is not on B

And no it's not overlap of two groups

It's more of like across sets

[shell horizon]

its the first drawing not the second right?

[keen tulip]

The symmetric difference of several sets consists of all elements that belong to an odd number of the sets.

[ashen sedge]

Yeah
(Sorry my English is bad so couldn't frame it)

[shell horizon]

thank you

[safe radish]

@shell horizon Has your question been resolved?

[safe radish]

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[safe radish]

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[upper arrow]

i have skipped the calculations here, but can someone please confirm if my final answer is correct?

[safe radish]

@upper arrow Has your question been resolved?

[fathom jewel]

but then i would have to do the calculations to check

[safe radish]

@upper arrow Has your question been resolved?

[upper arrow]

😭

I didn't do the calculations honestly, a friend sent me this

[fathom jewel]

I actually believe you

,w det{[-3-lambda,2,5],[9,0-lambda,-9],[0,3,3-lambda]}=0

[flat frigate]

Results provided by WolframAlpha

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Requested by adoniszgks

[upper arrow]

so the answer should be correct right

[upper arrow]

.close

[safe radish]

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[brazen portal]

how am i supposed to find the equation for this table?

[brazen portal]

isn’t it not constant?

[quasi bison]

,rccw

[timid ridge]

looks like they want you to draw the line of best fit

[quasi bison]

wdym by "constant"

[brazen portal]

like it doesnt increase by a constant rate

because it takes a jump of 20 instead of 15 from 4-6

[quasi bison]

so the relationship is not perfectly linear yes

that's why you're supposed to give a line of best fit

[brazen portal]

ohhh okay

that’s probably what we learned in class today since i had to stay home

thanks bro

wait a minute

i just remembered that wasnt what i asked

how am i supposed to find the equation

not the line

[torn obsidian]

you can use the equation of a straight line y - y1 = m*(x-x1) where (x, y) and (x1, y1) are points from your graph. m is the gradient/slope and its formula is m = (y-y1) / (x-x1). alternatively you can use another formula y = mx + C, where C is the point where your line intercepts the y-axis

[safe radish]

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[lean otter]

hi i need help

[lean otter]

starting with part a

Must i apply RREF or REF?

i can already tell the row vectors are linearly independent

[last wren]

I think you can just say that neither row is a multiple of the other and you're good

[lean otter]

but then my concern is you can still apply RREF and get 2 different vectors

than the original ones

i wanna know the correlation

[safe radish]

@lean otter Has your question been resolved?

[last wren]

they look different yes, but they still span the same space since RREF is obtained by a sequence of row operations on the original matrix

adding 2 vectors together and dividing them by constants doesn't change their span

[safe radish]

@lean otter Has your question been resolved?

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[slow sluice]

i dont want the answer i just want to know where to start, not having that resistor at the beggining fucked my shit up 😭

[slow sluice]

i know Iin = If and I1= I2 becase of kcl and how the amp gets 0 current in the input

<@&286206848099549185>

[stoic dune]

The other rule is that the Op amp has no voltage difference between the inputs. If there's 10V at the + side, there must also be 10V at the - side

This makes a lot fall into place pretty quick

Watch your signs btw, Iin = -If, I1 = -I2

@slow sluice

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@slow sluice Has your question been resolved?

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[wild mountain]

F(x, y) = \int_{y}^{x} \cos(e^{t}) , dt

[charred jetty]

$F(x, y) = \displaystyle \int_{y}^{x} \cos(e^{t}) , dt$

[wild mountain]

find partial derivatives

thanks

[flat frigate]

Erebus

[wild mountain]

do i need to solve the integral? i have no idea how to

[round notch]

what’s ur question?

[charred jetty]

I don't have much thought on this matter, but I think Leibniz rule would help.

Let me do more research.

[charred jetty]

@round notch

[round notch]

i saw but what do u want to do with this integral lmao

[errant bison]

Isnt that a definite integral

[wild mountain]

need to find partial derivatives of F

ik how to do it but the integral is tripping me up

[round notch]

use FTC i guess

[wild mountain]

thought so but how?

[errant bison]

Ig , js integrate first normally the cos(e^t)

[twilit spindle]

don't even need to compute the integral of cos(e^t) outright (which you may find to be a bit hard anyways), FTC, just as tm said

[errant bison]

So do they still get same results

[charred jetty]

Isn't there a shorter way?

[errant bison]

Ig ftc is better

[wild mountain]

ftc would be F(x) - F(y) right

[errant bison]

Prop ye cuz i remember it was higher - lower

[twilit spindle]

using F again could lead to confusion because F is already the integral but yes

[wild mountain]

let's say G(x)-G(y)

how do i find G?

[charred jetty]

$f(t) = G'(t)$?

[errant bison]

So cos(f)/cos(y) ?

[flat frigate]

Erebus

[charred jetty]

I mean then $F(x, y) = G(x) - G(y)$

[flat frigate]

Erebus

[charred jetty]

But what's your thought?

[wild mountain]

well i'd need to figure out what is G

[round notch]

u don’t need to find G

[errant bison]

Why

[round notch]

differentiate this relation wrt x or y

[errant bison]

So just ignore it?

[twilit spindle]

you now have F(x,y)=G(x)-G(y) (F in terms of x and y explicitly)

[wild mountain]

so ts the key?

[charred jetty]

Yeah, you could say that

We don't need to solve for G(x)

We can immediately find the partial derivatives.

[wild mountain]

lemme try

so

$F_x(x, y) = G'(x) = \cos(e^{x})$

[flat frigate]

dovx

[wild mountain]

and then for F_y it's -cos(e^y)?

[charred jetty]

YES!

[wild mountain]

i seeee

been a while ive seen FTC

anyways thanks a lot 🙏

[charred jetty]

No problem man, we're here if you need help! 🫡

[wild mountain]

.close

[safe radish]

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[toxic plinth]

Trying to understand Jordan basis. For an eigenvalue do i just find a vector v that is in the ker(T-lambda) and then try find the vector before that st that Tu = v and keep going until i have enough basis vectors for the size of the dimension?

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[empty forge]

amc 10 stuff?

ur drawing is inaccurate?

[vale vessel]

^^^

[empty sky]

js pretend A B diameters but is aight

all points have diff names wrong

[empty sky]

what's the amc10

[empty forge]

nvm

[empty sky]

tf

is not a math competition my teacher gave this as extra credit on test

tryna understand

[empty forge]

its a comp exam in US

[empty sky]

yeah I looked it up

no1 rlly solved it

[empty forge]

Aight

I can't wrap my head around the drawing

[empty sky]

yeah knowing him he prolly got it from there

[empty forge]

could you add the specified lengths to it?

That way I can look at it without getting a headache

[empty sky]

obv the radius is 3 I got there on the fkn test

[empty forge]

Ok then you can solve this with law of sines and cosine

but this wouldnt make any sense

if PQB is a equalateral triangle then we have qp =3

[empty sky]

PQB isn't equilateral

[empty forge]

since qr = 3sqrt3 then we would have angle q =90 degreed

it is

[empty sky]

the entire angle is 60, there's a little portion of the 60 in RBP

[empty forge]

OHHHHH

[empty sky]

wha

[empty forge]

https://tenor.com/view/i-saw-w-gus-fring-gus-gustavo-deleted-gif-25440636

[empty sky]

wasnt me what

[empty forge]

Who was that then?

Should we report?

[empty sky]

it dont matter

[empty forge]

Ill just report it

Anyways I found the solutions

https://artofproblemsolving.com/wiki/index.php/2021_AMC_12A_Problems/Problem_24?srsltid=AfmBOool265pnKAd6JQaN-za5zT-Pn0HGL4-BxY_as48iLpE_DNzWt4-

It was from the AMC

[empty sky]

ion wanna see them js like

[empty forge]

are not in america?

[empty sky]

i am in america

it was an extra credit problem on my test

[empty forge]

how have you not heard of the AMC then lol

[empty sky]

nah

[empty forge]

Ok

[empty sky]

is in 3 days tho so

no point

[empty forge]

yea

so

[empty sky]

you boutta do it?

[empty forge]

no

imma just tell ya something

[empty sky]

what

[empty forge]

ya see the link?

it says problem 24

Your not going to get the problem right

The AMC is one of the hardest math tests you can do in hs that you dont need to get invited too

[empty sky]

fuck that shit I'm getting it right

[empty forge]

you can look at the solution

the question is 24 / 25

[empty sky]

no solution

needed im built diff

[empty forge]

that means its one of the hardest of the hard on the test

[empty sky]

shi rlly

damn

[empty forge]

noone in your class is expected to get that right

your teacher is trolling you

[empty sky]

nah we're lowk smart like top 50 in class of like 700

massive hs

[empty forge]

the extra credit is probably just a guess and if you get it right then thats good for you

[empty forge]

oh ok

[empty sky]

but still no1 got it

cause there's also an entire other fkn test

[empty forge]

Thats expected lol

btw the answer is 122

you can look at solution by going to 2021 amc 12a and scroll to prob 24

the answer is complex

[empty sky]

ill attempt on my own for a minute rq

[empty forge]

aight

gl

[empty sky]

im close

[empty forge]

Nice lol

[safe radish]

@empty sky Has your question been resolved?

[empty sky]

alr I figured it out

99sqrt3/20

interesting

[untold charm]

i need help

with math

[tardy mango]

!occupied

[safe radish]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

@empty sky Has your question been resolved?

[safe radish]

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[silver pawn]

Hi

[main musk]

what are you being asked to find?

[silver pawn]

All angle of game

50 is arc

[tribal garnet]

Hmm

Which arc?

[silver pawn]

Ag

[tribal garnet]

Hmm

You can prove that AE, EM and AM are equal somehow, I can't remember

Thatt makes angle AME to be 60

[austere goblet]

might wanna consider involving OP in the answering process, btw.

[silver pawn]

What

[tribal garnet]

OA is a perpendicular

Butt

Angle oem is 90

[noble kiln]

!original

[safe radish]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[noble kiln]

@silver pawn

[silver pawn]

Hello

[lean otter]

That's like a grade 7 question

[noble kiln]

Please look at my query.

[noble kiln]

Probably 5 or 6

[noble kiln]

.

[noble kiln]

But we dont judge, do we

[silver pawn]

What is query????

[lean otter]

You were 1 number away from the meme

[noble kiln]

Please send the original question. Thank you

[noble kiln]

[silver pawn]

Need all angle

[noble kiln]

What are the conditions?

Send the original question or it is hard to help.

Thank you

[silver pawn]

And need to find what two side of quadertal is congrunt

[tribal garnet]

Can't help without knowing the conditions🥀

Gotta need it🦄

[noble kiln]

Send the original question.

I will not repeat myself.

[minor gulch]

What are you trying to find

[silver pawn]

Find all angle of game

[minor gulch]

Angle GAM?

[silver pawn]

No

[minor gulch]

Oh

[noble kiln]

you are very vague in your explanation

Please tell us where you are stuck.

!status

[safe radish]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[minor gulch]

What are the knowns?

Like what is given

[tribal garnet]

Dude won't send the full question 🤷🏻‍♀️

[minor gulch]

Any angles or lengths given?

Alr

[noble kiln]

Good.

[minor gulch]

That's better

[noble kiln]

You should have sent it much earlier.

Now where are you stuck?

[silver pawn]

In wahsing machine

Everything i dont get it sir

[noble kiln]

Do you want us to help you?

[silver pawn]

Yes please

[noble kiln]

Then dont be a troll

Thank you

[silver pawn]

Ok sorry please

Thank tou

[noble kiln]

Start thinking from the known angle.

[silver pawn]

What???

Only 50degre is there

[noble kiln]

Yes.

Start from there

[silver pawn]

Now what

It is arc???

[fierce nimbus]

Bro ain’t no way ur still going

[noble kiln]

So?

What else is it

[silver pawn]

It is diferent problem this time bro

[fierce nimbus]

Ong bro

[silver pawn]

50degre?

[noble kiln]

Seems that you did this before, i remind you to be more specific and clear in your elaborations.

[tribal garnet]

Did you even try to do it by yourself? @silver pawn

[noble kiln]

What does that relate to?

[silver pawn]

Yes but ai said other answer and another ai said different answer

[noble kiln]

!nogpt

[safe radish]

Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).

[fierce nimbus]

💀

[tribal garnet]

Ai🥀🥀🥀🥀🥀

[fierce nimbus]

I’m crine

[tribal garnet]

Dude is cooked

[silver pawn]

Semicircle???

[noble kiln]

Which part

What is 50 degrees

Relate it to the diagram.

[silver pawn]

Part of 180?

[noble kiln]

No.

[silver pawn]

What???

[noble kiln]

What angle is 50 degrees

[silver pawn]

50is arc

[noble kiln]

Do you know what the measure of an arc means?

[turbid pond]

The analog to the Oppenheimer project but for Poopydoopy

[lean otter]

Chatgpt helped me in A levels I got AAA because of it

[silver pawn]

Yes i know

[lean otter]

It's good only if you know how to use it

[silver pawn]

Measure of line of circle

[noble kiln]

So what angle is 50 degrees in the diagram?

[tribal garnet]

Idk, we didn't had gpt and still scored 90+/100, of course, i didn't, i clocked out at 84

[silver pawn]

M?

[noble kiln]

M is not an angle

[silver pawn]

50 degrenis Ga

[noble kiln]

?

what is degrenis

[silver pawn]

50 degree Ag

[noble kiln]

sigh

What angle does it represent here

[silver pawn]

What???

The arc

[noble kiln]

An arc is not an angle.

[silver pawn]

Right angle??

[noble kiln]

No.

You should be thinking of angle GOA being 50 degrees

Now do it

[silver pawn]

Ok

[noble kiln]

Wait

[silver pawn]

Now what

[noble kiln]

mb i typoed

do it

[silver pawn]

What next

[tribal garnet]

Hmm

[silver pawn]

Focus on me

[tribal garnet]

It says mAG is 50

It didn't even say degrees or radian

[silver pawn]

What

@noble kiln

[noble kiln]

Why did I get pinged?

I am doing my own math

[silver pawn]

What next step

[noble kiln]

What have you gotten?

[silver pawn]

Goa is 50

[noble kiln]

Then?

[silver pawn]

Then what

[noble kiln]

fair point lmao

[noble kiln]

What do you think you should do

[silver pawn]

Subtract?

[tribal garnet]

50 what? Apples? Bananas?

[minor gulch]

In the diagram it says 50

Degrees

[silver pawn]

Is a 155????

[fierce nimbus]

Maybe

[silver pawn]

What maybe???

[fierce nimbus]

Keep going to see if it’s right

Why is everyone u say a question have some confidence bro

Go off on what u think u know and see what answer u get

[silver pawn]

Is g 65???

[fierce nimbus]

Find the other angles and add it up to see if it checks out

[minor gulch]

I believe so yes

I might be wrong idk

I'm dumb

[turbid pond]

I got 65 for angle G.

[silver pawn]

Is m 50???

[minor gulch]

But

[turbid pond]

I got 50 for angle M.

[silver pawn]

Dude please dont sabotage i need for grade

Is e 90??

[turbid pond]

I got 90 for angle E. Yes.

[silver pawn]

Do exterior angles aplly????

What is a then?????

[austere goblet]

do you have to always end questions with three question marks???

[silver pawn]

Plese this is urgent

[fierce nimbus]

Urgent for how many hours 🥀

[silver pawn]

How to know what two sides of the quadertal is congruent?

Guys where you???

[noble kiln]

Patience.

[silver pawn]

I am trying to patient but you guys always leave

[fierce nimbus]

I’ll hold ur hand bro it’s ok

[silver pawn]

What is angle A

[fierce nimbus]

U got angle G and M and E

What could that make angle A

Sum of all angles in a quadrilateral = …

[silver pawn]

155?

[fierce nimbus]

Okay for A yes that’s correct

Assuming the angles were calculated correctly

[silver pawn]

Is this corect????

@fierce nimbus

[fierce nimbus]

I’m right here bro just a sec

Everything looks fine idk where u got 230 from but as long as u got the right answer ig

[silver pawn]

What if they are wrong i will blame u??

[fierce nimbus]

If u blame me im gonna send this whole convo to ur school

[silver pawn]

What please no im sorry

[clever granite]

Blame Yeet.

[silver pawn]

So is it corect?

[fierce nimbus]

Ur fine but please brush up on some terms

[silver pawn]

What terms

[fierce nimbus]

Like arcs, chords, tangents

[silver pawn]

So which two sides are congruent??

Toji????

Is it the two tangent??

[fierce nimbus]

Why are u confused

[vagrant ice]

the tangents to a circle theorem

[silver pawn]

Thank you good sir you have help me more than all of them combine

[fierce nimbus]

Ain’t no way

[noble kiln]

mesaage.append (??) ahh

[noble kiln]

.

[zealous ingot]

You absolute G

[vagrant ice]

you absolute donkey

[silver pawn]

Close.

[vagrant ice]

. first

.close

[safe radish]

Channel closed

Closed by @vagrant ice

Use .reopen if this was a mistake.

[tribal garnet]

Lmao

Jeez you are funny

[turbid pond]

Poor Toji

[safe radish]

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[elder moss]

<@&268886789983436800> scam

[lean otter]

Wait what scam? Can you tell me about it so I avoid falling for it...

[safe radish]

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[true gazelle]

Help

[true gazelle]

10th grade mathematics
I don't need the answer can someone just please explain to me what circle theorem thingy i should use in order to get x or what equation i should use in order to get x

Im sorry i am ashamed almost everyone using this help thing are college students

I really can't find a way to get x . I know all the basic (angles formed by tangents & secants) theorems but I can't seem to apply them

Plz

<@&286206848099549185>

[mossy lotus]

dont worry about that, there are a ton of school students who need help and they are the majority of people who ask the questions in here. It is a good thing that you seek to improve yourself by asking for help

[mossy lotus]

lets see, you have the line SUW passing thru the center of the circle

what does that tell you?

[true gazelle]

Hello thanks

Yea i saw that too it looks like a diameter but i thought I shouldn't assume that cause it wasnt put in the given thing

Secant thing

[mossy lotus]

they called the circle U, so you can safely say U is the center here

[true gazelle]

But how do I know the line passes through the center tho lol

Is the problem the question or am I actually overthinking it

[mossy lotus]

yea, I'm gonna say you are overthinking. Since U is the center of the circle, any line that has U on it, passes thru the center

[true gazelle]

I might be slow to type I'll try to get x with that info present inside my head now hmm

[mossy lotus]

you dont have to think x is the first piece of information you need to calculate

feel free to find rest of the angles in terms of x and then try to see if you find anything friendly with what you know that helps you

[true gazelle]

Is it wrong to assume that angle 1 and 2 are equal

[mossy lotus]

NO!!

thats the hint I wanted to give you when I said SU passes thru the center

Its absolutely correct

[true gazelle]

Oh gosh lol im sorry if im taking way too long wih this i know it absolutely infuriates you

[mossy lotus]

lol no worries

[true gazelle]

My thought process went to 2x=1/2[(3x-20)-somethih] but itfeels wrong

[mossy lotus]

this is not even close to the longest i have spent in here

[true gazelle]

I'm rehinking it

6x-40=4x+4? hehe

[mossy lotus]

that is pretty close. Hint: ||connect the radius to the tangent UT||

[mossy lotus]

thats good, thats correct

[true gazelle]

Yeayy i got it 2x=44 x=22

I think i got the rest now

This math help thing is extremely helpful man you're really patient with me

[mossy lotus]

good job

[mossy lotus]

np man, as long as you are able to solve the problem

[true gazelle]

How do i close this help thing exactly

Thank you man

[mossy lotus]

type .close

[true gazelle]

thanks

.close

[safe radish]

Channel closed

Closed by @true gazelle

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
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• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[soft spoke]

how to integrate e^-x^5?

[quasi bison]

you can't

!xy

[safe radish]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[timid escarp]

that sounds like you're inviting the Gaussian error function to show up.

[soft spoke]

this is the original queestion

[quasi bison]

ok and your work?

[soft spoke]

got to dy *y=e^-x^5 cos(2x)-5x^4

[quasi bison]

mmm show your work

i think you did some fuck shit

[soft spoke]

probably hahah

have i went wrong when rearanging

[languid monolith]

line 2 going to 3

imma be honest im not capable of solving this but i know for a fact you didnt divide correctly, and you did some weird shit with the differential operator

[soft spoke]

okay thankyou anyway

.close

[safe radish]

Channel closed

Closed by @soft spoke

Use .reopen if this was a mistake.

[languid monolith]

nooo someone else will help you

oh man

[lean otter]

it's okay man we all make mistakes

the good thing about math is that you rarely do the same mistake twice

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[near atlas]

Let f(x) be any continuous function on [0,2] and twice differentiable on (0,2). If f(0) = 0, f(1) = 1 and f(2) = 2, then which of the following is true?

1. f"(x) = 0 for all x in (0,2)
2. f"(x) = 0 for some x in (0,2)
3. f'(x) = 0 for some x in [0,2]
4. f"(x) > 0 for all x in (0,2)

[lime dust]

What is your question?

[near atlas]

this

[quasi bison]

what does f'(x)" mean

[lime dust]

I asked what is your question, not what is the question.

[near atlas]

sorry typo

[quasi bison]

ok so where is your doubt

[serene fog]

3. ?

is the ans 3)
(my bad didnt realize someone else helping, @lime dust pls carry on.)

[near atlas]

idk how to begin honestly. this question is from "application of derivatives "

[serene fog]

this guy has to be from india

and jee.

[near atlas]

😭 caught me

[serene fog]

sigh

is the ans 3rd option tho?

im rusty shd revise

[near atlas]

no, the 2nd

i have no idea how tho

[timid ridge]

1. what does it mean when f''(x) = 0

[quasi bison]

are we supposed to pick one only

[serene fog]

oh yea mb bro

[quasi bison]

cause like 2 implies 3 lmao

[serene fog]

+1.

[near atlas]

yes, only one option is correct here

[quasi bison]

anyway consider mvt

[lime dust]

How many critical points does have at least a function with three zeros? @near atlas

[serene fog]

+1 means i agree to ur statement

[quasi bison]

bruh then it's unanswerable

[near atlas]

to have at least 3 zeros we need at least 2 critical points

[serene fog]

this is some rolle theorem shit bro..

i swear.

mb bye.

[lime dust]

How is that true?

[near atlas]

sorry made a typo. at least 2 crit. points

[near atlas]

ohh i see

let me try

[lime dust]

Ok and a function with 2 critical points, his second derivative will have at least how many zeroes?

[near atlas]

hmm im not sure. maybe one zero?

[lime dust]

Yes, at least 1

[near atlas]

i see

so how do i relate this to the question

[near atlas]

is this okay?

[sharp sentinel]

2 is only correct one

[quasi bison]

sure this is OK

[quasi bison]

but 2 logically implies 3 tho

maybe it's correct in a bureaucratic sense

[sharp sentinel]

no lol

just consider f(x)=x

f'(x) is never zero

[quasi bison]

oh 3 talks about the FIRST derivative

wait does it