help-23

[obsidian pivot]

2(p + q) = 8

p + q = 4

Only works in 2 + 2

Uhh forget that

[empty gyro]

Any introductory book on number theory would be fine.

[safe radish]

@obsidian pivot Has your question been resolved?

[obsidian pivot]

I will work on that later

.close

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[jagged trellis]

Does anyone know what topic this is?

[timid ridge]

geometry?

[jagged trellis]

I'm trying to learn and study it but I can't find it anywhere online

[jagged trellis]

Yes

But specifically

[timid ridge]

supplementary angles

[jagged trellis]

It's not that, for this one you look at it and determine which angles are bigger then the given based off a set of rules

[timid ridge]

uhm just angles

idk

[safe radish]

@jagged trellis Has your question been resolved?

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@jagged trellis Has your question been resolved?

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@jagged trellis Has your question been resolved?

[jagged trellis]

<@&286206848099549185>

[robust jackal]

I think what you might be dealing with is angle proofs

There should be theorems that can help prove what angles are bigger than angle 3

[jagged trellis]

Dear God..

Thanks so much

[robust jackal]

Np

I'm not an expert I learned this stuff a few weeks ago but based on the question and what is given that's what it looks like

👍

[ancient socket]

exterior angle theorem can be used here

[open junco]

.close@jagged trellis

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[west hedge]

Can someone check my process

[west hedge]

Im trying to get the value of x

And there’s a list to help me achieving so

[empty gyro]

I can't read the problem

[queen ingot]

=10*-0.0223

you lost a "-" sign

[west hedge]

what

[west hedge]

got it, but should the value of x be negative?

x is positive, no?

[queen ingot]

no, x should be positive

it's ok because 10^-0.223 is positive

[west hedge]

Why I get this nonsense result

[empty gyro]

I cannot read what you wrote. I find the writing difficult to see clearly

[west hedge]

I’m so sad

[queen ingot]

do you understand this?

it's not a nonsense result

[west hedge]

10 multiplied by -0.223 is negative

[queen ingot]

yes

but we are not multiplying, are we?

[west hedge]

We are multiplying

[queen ingot]

no, "^" represents exponentiation

[west hedge]

I mean it should be multiplication

As the process illustrates

[queen ingot]

yes, in one step you are multiplying by 10
but in the final step, you need to use exponentiation to change log(x) to x

[west hedge]

can we redo it from the start

I got 0.95^10=x

[queen ingot]

sure

[west hedge]

I want to solve for x and only two things I got is my pen and a list for value of some log with base 10

I transform both sides to log with base 10

[queen ingot]

then how did you get x=1.67 in the final step?

[west hedge]

I got logx= 10 * log (0.95)

[queen ingot]

yes

[west hedge]

I search up the list and I find that log(0.95)=0.9777-1=0.2=0.0233

fk

typo

[queen ingot]

typo

[west hedge]

I search up again to find what logx would 0.0233 be equivalent to.

[queen ingot]

no

[west hedge]

WHAT

ohhh

[queen ingot]

log(0.95) is not 0.0233

[west hedge]

it is negative

it is -0.0233

Okay so I got log(0.95)=-0.0233

[queen ingot]

no

[west hedge]

what

what do you mean

[queen ingot]

log(0.95) is -0.0223

you typed -0.0233

[west hedge]

my bad

So I got log(0.95)=-0.0223

[queen ingot]

ok

[west hedge]

so logx= 10 * log (0.95) = 10 * (-0.0223) = -0.2230

then I search up the list to find what logx would be equivalent to -0.2230

[queen ingot]

yes

[west hedge]

I found log(1.67)=0.2227, which is roughly equals to 0.2230.

[queen ingot]

but 0.2227 is positive

[west hedge]

you are right.

I can consider -0.2230 as 0.7770-1

Hence, logx=log(r*1/10) where, log r =0.7770.

then I search up the list again. to find the r.

I found log5.98 = 0.7767 approximately equals to 0.7770.

Hence, x=5.98*(1/10)=0.598

[queen ingot]

that seems right

[west hedge]

The process is long as hell

[queen ingot]

yes

well done

[west hedge]

there must be a better solution

Some step should have be omittable.

[queen ingot]

a calculator

i doubt you can omit any steps

it seems that your table doesn't have negative values

[west hedge]

Most of tables do not have negative values, no?

[queen ingot]

well maybe there is a faster way, i'm not sure

well anyway, has your question been answered?

[west hedge]

yes, thank you

.close

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[sour rose]

not sure what steps were involved to go from first equation to second

[empty gyro]

Multiply everything by vs

[sour rose]

lol i was just typing that!

[empty gyro]

Then move everything to one side

[sour rose]

ok cool

thx man

im on like 8 hours of sleep in 3 days

finals week u k now!

[empty gyro]

Same

Sleep eludes me even now

[sour rose]

hehe

get to bed!

this is the last question to the last overdue exam i owe

i'm right behind ya! 😂 cheers! 🙏🏻

[sour rose]

oh hey 1 more if ur still around. how the heck did pull out 2/g out of the square root? treat the square root of 2/g as multiplier and pull it out?

[empty gyro]

Yes

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[left sapphire]

how do i open achanel?

[clear blade]

congrats, you just did

[vagrant ice]

a small loan of a million dollars, that's all

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[gritty agate]

anybody help

[gritty agate]

i have a doubt

can i bring all the variables at right side and all the terms at left side

[noble kiln]

You could just let 9x-6 = 3y and then find y

[noble kiln]

But think this would work

[gritty agate]

so basically

6x-9x = -6+4+4

which is -3x = 2

-x = 2/3

[noble kiln]

Ah i see

[gritty agate]

then x = -2/3

[noble kiln]

Yes

[gritty agate]

now

3*-2/3-2

[noble kiln]

3x = -2

[gritty agate]

so it's -4

[noble kiln]

Ya

[gritty agate]

am i right

[noble kiln]

Ya

[gritty agate]

yes

[noble kiln]

A then

[gritty agate]

thx

[noble kiln]

Np

Have a good day

[gritty agate]

k SAT starts in 30 minutes

gotta go bye

have a great day

[noble kiln]

Bye

good luck

Do .close when done 🙂

[gritty agate]

anyways from which country u belong from

[noble kiln]

In bio

[gritty agate]

singapore

right

[noble kiln]

Mhm

[gritty agate]

i'm from india

nice to meet ya

[noble kiln]

Ah ok

[noble kiln]

Same

[gritty agate]

bye

.close

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[charred cedar]

yo

[charred cedar]

Can u please verify my work for this power series de ?

[lean otter]

yo

[safe radish]

@charred cedar Has your question been resolved?

[safe radish]

@charred cedar Has your question been resolved?

[safe radish]

@charred cedar Has your question been resolved?

[safe radish]

@charred cedar Has your question been resolved?

[safe radish]

@charred cedar Has your question been resolved?

[safe radish]

@charred cedar Has your question been resolved?

[queen ingot]

@charred cedar looks good to me

[charred cedar]

Okay

Thanks

.close

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[pliant sail]

Hello

[safe radish]

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[timber osprey]

What is SAT?

[safe radish]

Please don't occupy multiple help channels.

@timber osprey Has your question been resolved?

[timber osprey]

<@&286206848099549185>

[safe radish]

@timber osprey Has your question been resolved?

[timber osprey]

<@&286206848099549185>

[safe radish]

@timber osprey Has your question been resolved?

[timber osprey]

What is the test about?

SAT…

About which math is it?

[plucky elk]

https://en.wikipedia.org/wiki/SAT

[plucky elk]

https://satsuite.collegeboard.org/practice/practice-tests/paper

[timber osprey]

@plucky elk how to take it?

[plucky elk]

https://satsuite.collegeboard.org/sat/registration

[timber osprey]

I want to take it for MYSELF

not sign up a school for it

@young nexus why did you delete your messages?

[timber osprey]

@plucky elk

<@&286206848099549185>

[plucky elk]

i don't know what you mean "take it for myself"

[plucky elk]

did you open this link?

[timber osprey]

Im not in USA to have college board account.:..

[plucky elk]

that's the registration link?

[plucky elk]

does this link require registration ?

[timber osprey]

What do you mean?

Im not an US student

To register an exam for this…

I need to be active student?

[plucky elk]

.close

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[timber osprey]

How to do SAT?

[young nexus]

was answered by riemann above,

[timber osprey]

Idk

[timber osprey]

He didn’t help me

[young nexus]

you didnt read.

[timber osprey]

How

I need school registration

[young nexus]

where?

[timber osprey]

@young nexus

[young nexus]

and?

[spiral saddle]

you don't need to live in USA to take sat

[hearty egret]

but it helps

[spiral saddle]

I took it in chile

and is very far from usa

also you don't need to live in USA to register a account in college board

have you tried googling alex? btw?

[young nexus]

you dont answer questions. where do you need registration?

[timber osprey]

I want to take test and know my score

@spiral saddle @young nexus

How to do that

[spiral saddle]

I dont remember my college board account password

but register for a college board account first

once you do that, look for the first date that the exam is held, every country has designated places where you need to go and take it

you need to pay a fee in order to register for those exams, after you took them on that day, wait a month and they give you the results in the college board account

[timber osprey]

I want to do that for free

??

[spiral saddle]

maybe is possible, check the info provided in college board

do you have an account?

[timber osprey]

@young nexus

[spiral saddle]

https://satsuite.collegeboard.org/sat/registration/fee-waivers

[spiral saddle]

Google bro, you are going to need it when you enter university

I didnt had no one to ask for this info, I had to Google it myself when I was 17

I am done helping you, ping Thm and Riemann for more questions I'm sure they will be willing to help

[timber osprey]

@young nexus @plucky elk

[safe radish]

Please do not ping individual helpers unprompted.

@timber osprey Has your question been resolved?

[timber osprey]

It costs literally $68….

.close

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[analog falcon]

yo

can sm1 give me a quick answer

Are definite integrals basically antiderivatives?

[icy lance]

id consider that more to be indefinite integrals

[severe pond]

no

[analog falcon]

so indefinite integrals are antiderivs'

i think i had them around

.close

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[glossy cosmos]

what is 1+1 🤔

[glossy cosmos]

11 right ??

[brave wolf]

Would you like to ask moderators or will you rather close this channel and try asking e.g. a calculator?

[glossy cosmos]

thats a hard question

[wet wigeon]

"pending postgrad" ....

[hollow siren]

calc is slang for calculator

[brave wolf]

And 's is shortand for is btw

[hollow siren]

chat clip that

[wet wigeon]

so

do you have a real question or are you just gonna occupy the channel for no reason?

.close

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[polar lynx]

You're muted for today. Don't troll in the help channels in the future.

[polar lynx]

.close

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[forest maple]

I have a question about dot products

[forest maple]

So the dot product of the same vector v•v is |v|² and the angle between 2 vectors is given by this

Why not just use |v|=root(a²+b²) with a and b being the coefficients of î and ĵ and just do this:

[fathom adder]

Well, the angle is the oriented angle between the two vectors

So if its the same vectors

The angle is 0

And cos(0) is 1

So v•v = |v|²

[forest maple]

Okay? I get that

[forest maple]

Why learn even learn dot product if u can just do this

[fresh wasp]

It’s useful in other areas

Like checking if vectors are normal

The direction derivative of a function

Depends on your application really

[fathom adder]

Well if you have the components u don't use this formula, you just do sum of product of components to know

[short topaz]

dot product generalises nicer to higher dimensions

and also to abstract vector spaces

like how do you define the angle between $f,g:[0,1] \to \mathbb{R}$ given by $f(x) = x$, $g(x)=x^2$

[flat frigate]

LY

[fresh wasp]

You also won’t be able to easily switch between different areas of math, for instance you can use this ( dot product with cos)for physics and for dimensional analysis

[forest maple]

Thats not my point, mine is why use dot product when u can just use arctan

[fresh wasp]

Easier

[forest maple]

So essentially for what Im learning now its useless

[fresh wasp]

Arctan isn’t defined everywhere either

[fathom adder]

Why would you use arctan if you can just do a cos, cos is easier

[forest maple]

For who? Everyone has their own way

[fresh wasp]

Yes but it generally takes less work which is why I say easier

And it’s not defined for all reals

[short topaz]

sorry i'm kinda confused by ur question? as in you can compute the angle between 2 vectors however you want but it's always nice to have multiple formulas available

[fresh wasp]

Exactly

[forest maple]

Im sorry isnt arctan's domain (-infinity,infinity)

[short topaz]

as in like sure, we can solve the set of equations:
2x+3y = 1
3x-8y = -7
by matrices, but like you would just solve them by like substitution

it's helpful for theory to develop multiple different ways to solve this, cus differing methods have differing uses

[fresh wasp]

Tan isn’t defined for cos =0

[short topaz]

ofc if you actually need to find the angle between 2 vectors u can just use ur arctan thingy but like ur learning about it cus different methods have different uses

[forest maple]

You mean pi/2???

I talking about arctan

tan^-1

[short topaz]

like u learn about matrices cus even though u wouldn't use matrices to solve smth like that in ur head, it's useful for developing theory

[fresh wasp]

Someone else can help you with that imma explode 😭

[forest maple]

Just

Fine

I got my answer ish

.close

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[fresh wasp]

Tan is sin/cos

Cos =0 which yes is at pi/2

[forest maple]

Im talking about arctan

[fresh wasp]

But also other places

Arc tan is the inverse nothing changes

Its still not defined for pi/2 +npi

Where n is an integer

[forest maple]

Im sorry, youre wrong

[fresh wasp]

Sure bud

[forest maple]

Arw we two even talking about the same thing

[fresh wasp]

Yes arctan isn’t defined for all reals

[forest maple]

All x values have a y value

It is defined for all reals

[fresh wasp]

?

1/0 is undefined

I don’t know how to help you with that

[forest maple]

Tell me the domain of arctan

[fresh wasp]

It in the graph 😭

[forest maple]

Tell me yourself

[fresh wasp]

I’m not gonna be degraded by you because you don’t understand

I’m just trying to help

[forest maple]

Im sorry Im not trying to degrade Im trying to understand if we're on the same page

We might be talking abt different things

[fresh wasp]

In your example where you want to use tan ^-1 of (a/b) b=/ 0

[forest maple]

Ahm yeah

[fresh wasp]

The cos (theta) equation allows you to still calculate a value even when cos wouldn’t have a value and I’m talking about the vectors

Like if one of your vectors was 0i +3j that equation wouldn’t work

[forest maple]

But arctangent's domain is (-infinity,infinity) and range is [-pi/2,pi/2]

[forest maple]

Yeah it would

Use the limit

[fresh wasp]

3/0 is undefined

And you know how much more work that is just use the equation 😭

[forest maple]

Limit x-> 0 of arctan(a/x)=pi/2 where a isnt 0

[fresh wasp]

Not even sure if that would prove it I haven’t been educated on that method

[forest maple]

Yeah plugging in 4 values

[fresh wasp]

It’s the same for the other one

If the equation you thought of was easily aplicable they would have taught you it, there is a reason it’s not used often

[forest maple]

You clearly see at x=0 a value exists

[fresh wasp]

I’m no

It’s undefined for a reason

It approaches two different values from each side

[forest maple]

So use the limit

Lim x->infinity arctan(x) is most definitely pi/2

[fresh wasp]

Bruh

[fresh wasp]

That’s wrong but ok

You would have to do lim x-> 0 (+ or -)

[forest maple]

Sure 0+

Defined enough?

[fresh wasp]

Just use the equation bro

[forest maple]

Yeah aight this convo is useless for both of us lets just free up space jeez

Byebye:3

[fathom jewel]

[safe radish]

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[shadow glade]

that's just plain wrong

[fresh wasp]

You can see by what I mean which is for pi/2 +npi where n is an integer, for their example I was going the right direction but yea it is defined for all reals

In their example it wouldn’t work tho

[shadow glade]

@forest maple I would just reopen the channel and ask your question again because a lot of the information you got was confused and inaccurate

[fresh wasp]

You can read it all and come back I don’t need to go through this torture again

[fresh wasp]

I explained it right, just becuase you don’t like how i said something doesn’t mean it’s wrong

😭

[stiff bobcat]

it is. Though you are correct in saying that arctan(1/x) doesn't have a limit as x->0 if I'm understanding this convo correctly

[fresh wasp]

That’s what I was talking about according to their example

Becuase it was tan^-1 (a/b) which b isn’t defined for all reals

[forest maple]

Yeah I know I reported misleading info for moderators :3

[fresh wasp]

What. 😭

[forest maple]

Yeahhhh mistake on my part I shouldve said 0+ or 0- sorgy

[stiff bobcat]

I don't think anyone is being intentionally misleading here

[fresh wasp]

Didn’t mean to make it confusing, which is why I included a graph sorry for the confusion

[shadow glade]

anyway just miscommunication, probably best to move on

.close

[safe radish]

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[fresh wasp]

Yup

Good day ❤️

[stiff bobcat]

👍

[safe radish]

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[fair goblet]

Hi im gonna a dumb qetsikn because imqda dumb

[fair goblet]

isnt 1 e suppose to be true

because for a graph to be concave up f'' needs to be + and f' increasing

tahts what i thought

unless

its the opposite

is it the opposite

☠️

[fathom adder]

Idts

[icy lance]

you just need f''>0 for all x in there

[fathom adder]

f'' >0 is enough

[fair goblet]

oh

[fathom adder]

Well

[fair goblet]

i uh

misread the question ti hink

[fair goblet]

but is my claimc orrect

?

[fathom adder]

f' increasing is a deduction from f'' being > 0

So

[icy lance]

f'' being + and f' increasing are the same statement

[fathom adder]

Yeah

[fair goblet]

ah ic

thank

.close

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[ashen kestrel]

I’m 2008, in June 2024 I finished primary school and now in September I began first year in in high school.

What grade or year am I in us and uk school system?

[icy lance]

first year high school is age 10-11 in UK, year 7
at 15-16 ish typically in year 11, last year of high school

[ashen kestrel]

Don’t understand

So what YEAR am I in UK?

[icy lance]

i dont quite get how you worded it

you started high school at 15/16?

[ashen kestrel]

Yes….

This year

In September

[icy lance]

first year of high school in the UK is year 7, at age around 10-11
at around 15 or 16 people would be in their last year of high school, year 11

thats the english system at least

scotland is a bit different, not sure of wales

[ashen kestrel]

But US?

Isn’t high school after the mandatory school and high school is not mandatatory ?

<@&286206848099549185>

[icy lance]

in US from my little research first year high school is 9th grade

in England you have primary school (mandatory) year 1 to 6, high school (mandatory) year 7 to 11, college (mandatory unless doing apprenticeship) (2 years), then university (3 to 4 years)

[ashen kestrel]

So I’m in 10th grade

[icy lance]

seems like it

about year 11 in uk, last year of high school

[ashen kestrel]

And year 12th in uk

I started school at 6

okay

ty

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[wind abyss]

plz

[wind abyss]

I think this is like a chem concept but its just formulas and numbers

Idk what im doing

Am i atleast on the right track

.close nvm i didnt save the work omg

[safe radish]

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[compact kiln]

Hrlp mr

G

Plass

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[compact kiln]

Open

[compact kiln]

G

How do i do g

[junior raven]

use the hint

i is one implies x^2 + 1 is a factor

[compact kiln]

I dont know how to get there

Yea thats what the answer key says but how do i get there

Im so lost

[junior raven]

what equation is i a root of

with real coefficients

[compact kiln]

Idk

😭

[junior raven]

x^2 + 1

use polynomial long division to find the other quadratic factor

[compact kiln]

I know how to the long division but how do you get to point to be able to get x swuated +1

[junior raven]

well

pbviously i is a root of x - i

but that doesnt help cos you want real coefficients

so from $x - i = 0$

[flat frigate]

ashy!

[junior raven]

multiply both sides with the conjugate

[pure agate]

Every complex root has a conjugate root as well.

You can use that with long division to simplify the equation.

[compact kiln]

I get that

I get long division

But how do you know its apart of the 2 factors

[pure agate]

The problem states one of the roots is x=i.

[compact kiln]

Ok

Than you just go through i see

What abiut this

Nvm

Let me woek thotugh it

How do you do this @pure agate @junior raven

How do i write 1/2|x-8|-5 as a piece wise function?

[deep lily]

$|x-8|$ behaves differently when $x<8$ and when $x\geq8$. Just split the function into these two ranges and find the corresponding function without the absolute values/.

[flat frigate]

如月あやみ　Kisaragi Ayami

[compact kiln]

Im sorry but i still dont get how to split or any

[plucky elk]

,tex .abs val

[halcyon flame]

What is the value of |3-8|

[flat frigate]

riemann
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[deep lily]

$|t|$=\left{ \begin{matrix}
t &\text{, when }t\geq0 \
-t &\text{, when }t<0
\end{matrix}\right.

[halcyon flame]

@compact kiln what is the value of |3-8| ?

[flat frigate]

如月あやみ　Kisaragi Ayami
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[compact kiln]

5 becuase of absolute

[halcyon flame]

What is the value of |8-3| ?

[compact kiln]

5

[halcyon flame]

Correct
IIn other words, |3-8| is not equal to 3-8, but rather to -(3-8) = -(-5) = 5

[compact kiln]

Ok

Yes

[halcyon flame]

On the other hand |8-3| is equal directly to 8-3

Therefore, |x-8| can be either equal to -(x-8)
or simply to x-8

It depends on whether or not (x-8) is positive or negative

[compact kiln]

Ok

[halcyon flame]

This tells you that if x-8 is larger than 0, |x-8| = x-8

[compact kiln]

Ok

[halcyon flame]

But if x-8 is less than 0, |x-8| = ... ?

[deep lily]

no

[compact kiln]

Greater

[deep lily]

what is -5 to 5

[compact kiln]

Smaller to large

[halcyon flame]

Wait

[compact kiln]

It cant be less becuase of the absolute

[deep lily]

do you understand what this means?

[halcyon flame]

What are you talking about !

[compact kiln]

Me ir

Him

Or her

[halcyon flame]

I feel like you didnt understand

I didnt ask you what is greater or less

[deep lily]

@compact kiln do you understand what this means?

[compact kiln]

He said no when i said less

I said greater and you say no

[compact kiln]

Yes

[halcyon flame]

I asked you to complete the three dots

[compact kiln]

Les

Gre

[deep lily]

the answer is -(x-8)

not greater

not lesser

[compact kiln]

Thats not 3 dots

But i see

Ok

🤯

[halcyon flame]

Maybe you can let him answer though because he seems very lost

[deep lily]

it turns out he thinks 3 dots means 3 letters so idk how you're expecting him to get to the answer on that premise

[halcyon flame]

Then its up to him to verbalize

That he doesnt get the question

Not just throw random words

[deep lily]

something something monkey something type shakespeare something takes a million years

I'm not insulting you

I'm just suggesting that he could have made it easier for you to answer his questions given you were misleaded to a completely different direction of interpreting it as a whole

[compact kiln]

I see ok

I apologize to you

[safe radish]

@compact kiln Has your question been resolved?

[safe radish]

@compact kiln Has your question been resolved?

[safe radish]

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[tiny jewel]

Help me

[tiny jewel]

I have a question with a polar eq, (In precalc)

R = 40sin(θ)cos^2θ

Can anyone identify the type of graph this is and how I would begin to solve?

Mainly need help with Converting to rectangular form, and also graphing it.

[vagrant ice]

I'm answering in another channel

.close

[safe radish]

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[wise pine]

what is the definition of mod?

[queen ingot]

in modular arithmetic we say
1 is congruent to 5 (mod 4)

[wise pine]

no like how do u define it?

[queen ingot]

what exactly are you referring to though

the modulo operator?

modular arithmetic in general?

congruence?

[wise pine]

i am asking abt the operator

[queen ingot]

i haven't actually seen it used in math, only programming

[severe pond]

remainder

division theorem

[wise pine]

oh

[buoyant shadow]

the smallest positive number in that class

[queen ingot]

yes it's the remainder

[wise pine]

yea related to it'

[buoyant shadow]

,calc ((-20) % 1000)

[flat frigate]

Result:

980

[wise pine]

.close ty guys

[safe radish]

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[wise pine]

.reopen

[safe radish]

✅

[queen ingot]

smallest non-negative

[wise pine]

u guys know gif?

*GIF

Greatest integer function

[queen ingot]

is that like floor or ceiling?

[quick crater]

ceiling?

[wise pine]

wat?

[queen ingot]

floor(x) is the greatest integer <= x

[quick crater]

oh floor

[queen ingot]

or the integer part of x

[wise pine]

oh that

nvm

ty

[buoyant shadow]

one thing is that some languages don't follow this, like C will tell you −20 % 1000 is −20
(you didn't say in programming so nvm)

[wise pine]

ye

ty guys

.close

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[candid ocean]

The sound level of a moving power lawn mower is 109 DB the noise level in front of the amplifiers at a conseert is about 118 dB. how many times louder is the noise at the front of the amplifier than the noise of a moving power lawn mower.

[candid ocean]

ok so ill say how i tried to approach this

i did 10^1.18 / 10^1.09

because i did a question in class and thats the way the teacher explained it

so idk why it doesnt work for this example

like if its 80db compared to 30db then you do 10^8 divide by 10^3 do ykwim

[bronze gust]

I mean it should work

Why do you say it doesn't work

Do you have the answer key

[candid ocean]

ya

the answer is 10^0.9

[bronze gust]

Yea

Did you not get that

10^1.18/10^1.09=10^(1.18-1.09)

U know the indice law

[candid ocean]

is my calculator stupid

wait one sec whatt

[bronze gust]

Your calculator isn't stupid

[candid ocean]

but

[bronze gust]

It just doesn't express the answer as a power of 10

[bronze gust]

Yea 10^0.09 is approximately 1.23

[candid ocean]

but the answer is 7.94

[bronze gust]

Show me your answer key

[bronze gust]

Didn't you say it was 10^0.09

[candid ocean]

nono the answer says its 10^0.9

which is 7.94 ish

chatgpt says 7.94

answer key says 7.98

idrc i just wanna get between that LOL

[bronze gust]

Oh mb

[candid ocean]

hmm

[bronze gust]

Oh nvm

[candid ocean]

ur right about the subtracting thing tho like

doesnt it make sense

1.18 - 1.09 = 0.09

why is it 0.9 for the answer

[bronze gust]

10^11. 8/10^11. 9=10^(11.8-10.9)

Because you took dB divided by 100 instead of 10

[candid ocean]

but isnt it divide by 10

[bronze gust]

Jn

[candid ocean]

why all of a sudden its 100

for 80dB comapred to 30dB we divided it by 10

[bronze gust]

I don't know you divided by 100

[candid ocean]

😭 LOL

[bronze gust]

You made the error of dividing by 100

118/100=1.18
118/10=11.8

[candid ocean]

oh

[bronze gust]

I just kinda assumed you got that part correct cuh😭

[candid ocean]

OHHH

AHAHAH

wait im tired its 2 am

CATCHING UP ON LIKE 100 sets of homework sooo

ah i got it now

bruh i forgot how to divide a number by 10 omg ahaha

💀

lol tysm anyways

.close

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[mellow mountain]

how would i do this without using the addition formula for tangent

[mellow mountain]

would i have to use tan^-1 to find each angle and add the angles?

[dense prism]

why do you want to do it without that

[mellow mountain]

i have a final soon, this was a review question and im not allowed to use that on the test

[dense prism]

this works as well

[mellow mountain]

the only trig function stuff we can use it fundamental, reduction and cofunction identities

[mellow mountain]

alr thanks

1s let me solve

[faint seal]

it amounts to the same thing

if you're thinking of using the arctan addition identity

[dense prism]

obv it will, but i think he means hell use a calculator to find the arctans

and then again use the calc to find the tan

[faint seal]

that seems unnecessary

[dense prism]

if youre not allowed to use the formula

then it kinda becomes necessary

[mellow mountain]

im not allowed

how would i find an exact value

cuz calculator just gives a number i need to find exact

[faint seal]

you can't

[dense prism]

youre not evne allowed to use the sin and cosine addition formulas i believe?

[faint seal]

you're trying to find the addition formula for tangent without using the addition formula for tangent

it doesn't make sense

you could only do that if the values were nice

[mellow mountain]

in yellow

this is all i get

[dense prism]

if youre allowed a calculator lmao

[mellow mountain]

1: why did you add pi to that
2: i plugged in tan(1/4 + 3/7) and got 0.8

[dense prism]

dont worry about the pi since it doesnt change the value, i did that to satisfy their quadrant needs in the question

and tan(1/4+3/7) is just wrong

you need tan(a+b), a is not 1/4

tan a is 1/4

[mellow mountain]

oh oops

[dense prism]

a is tan^-1 (1/4), arctan's range by convention is between -pi/2 and pi/2

so i added the pi, you can ignore that since it doesnt affect the value

[mellow mountain]

alr

[queen ingot]

when you take the inverse tan it only gives you 1 of the possible answers
so you might need to add pi if you want the other answer

same with inverse sine and cosine

[mellow mountain]

so if i get a question like that on the test i should do arctan 1/4 and arctan 3/7 to find the values to plug in as a and b

[dense prism]

yes

[mellow mountain]

and in these cases if the answer is in quadrant 2 or 4 (pi/2 < x < pi OR 3pi/2 < x < 2pi) the answers to a and b would be negative

bc tan is sin/cos and if one is negative the answer it

is

• i would plug in -1/4 and -3/7

.close

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[thorn sandal]

I keep getting rlly weird numbers for the outlier calculations...

[safe radish]

@thorn sandal Has your question been resolved?

[native hemlock]

helo @safe radish

hello @safe radish

[safe radish]

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[river nexus]

lan arnavutköy

[gilded vault]

simply use the rule on the second line to calculate f(2),f(3),f(4), and f(5)

[river nexus]

I can’t do it

[gilded vault]

plug in $x=1$ to the second line

[flat frigate]

Arnavutköy

[river nexus]

being the which-a-why that i sent it in here

Anyways I solved it

.close

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[signal kettle]

I got a question, I'll send a picture

[signal kettle]

I am pretty lost here, I feel like I don't have enough iformation

so far I found that CB = 100

but then I'm kinda lost

[latent terrace]

DE forms a segment in circle B

[signal kettle]

yes, but don't we need to find angles to find those?

[junior raven]

i would connect db and eb

find the angles using trig

and find the area of the sector - the triangle

[signal kettle]

then DEB is a triangle

[junior raven]

yeah subtract that

[signal kettle]

ah

[junior raven]

you can find ab and ad

[signal kettle]

AD is 30 but I'm not 100% sure about AB

[junior raven]

you have cb

ac is 10

[signal kettle]

ah, the final answer is 408.753

[signal kettle]

but I'm not sure is CB is 100

if*

[junior raven]

it is

by intersecting chords theorem

[signal kettle]

intersecting chords theorem?

wait lemme

I havnt heard of that

at all before

[junior raven]

how did you get 100 then

[signal kettle]

I did similar triangles

DCA and DCB

[junior raven]

hang on

[signal kettle]

alright

[junior raven]

am i using intersectimg chords wrong

bc should equal bd

[signal kettle]

I'm sorry I don't know about that

[signal kettle]

yes it should

[junior raven]

hm

[signal kettle]

since BC and BD are radius of circle B

[junior raven]

seems as if bc cant be 100

becasue bd cant be 100

[signal kettle]

then whats the correct value

[junior raven]

sqrt(ab^2 + 30^2) = ab + 10

[signal kettle]

ohhhhh

wait holup why ab^2

ah

okay I'm still lost

[junior raven]

its a quadratic

solve for ab

[signal kettle]

wait I'm doing other questions first

thanks for the little guide tho

.close

[safe radish]

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[brazen nimbus]

yo is this correct

[safe radish]

Please don't occupy multiple help channels.

[brazen nimbus]

,rotate

[brazen nimbus]

i was confused by the -k

please

<@&286206848099549185>

[ornate skiff]

what is exactly the problem?

all I see is that there's 2 known values of L(t), and you need to compute a and k.

[brazen nimbus]

yes

im trying to get the function

but i think i ddi it wrong

[ornate skiff]

well you calculated "a" correctly. let me see the 2nd equation.

[flat frigate]

Wild123

[ornate skiff]

what's the value of t when we calculate L(12)?

[ornate skiff]

^

[brazen nimbus]

uhh

-2,48k?

[ornate skiff]

the function is L(t)

when we compute L(12), t is...?

[brazen nimbus]

OHH

BRUH

yo

i messed up

[brazen nimbus]

12

[ornate skiff]

t isn't 2,48

yes

[brazen nimbus]

but its -k12 then

or -12k

is it rhe same

?

[ornate skiff]

yes

multiplication is commutative.

[brazen nimbus]

okay perfect and lets say

[ornate skiff]

and -12k is preferred

[brazen nimbus]

we would have -1,2 for a

when u put that itno the function

because a is - a in the function

does it become a + in the function too?

like 3 + a

instead of 3-a

[ornate skiff]

yes, if a was negative, the - would become + after the 3.

but a is positive here

here a=1,2

so 3-1,2... is correct

you have to solve again from 0,43=e^...

and correct the value of t.

[brazen nimbus]

yeah

see man

[ornate skiff]

although you made quite a few approximations. does your teacher accept that? like, -0.52 divided by -1.2 gives 0.4(3), not just 0.43

[brazen nimbus]

i have like small things i dont understand

it buidls up

[brazen nimbus]

yeah i mean

i just write it like that

wdym by (3)

[ornate skiff]

I put numbers in calculator

and the division gives 0.433333...

Know about ...(math) periods? the way we write numbers with infinite, repeating decimals?

[brazen nimbus]

yeah ofc

but its over the 3

a line

but uhh

id just write the period sign with it

it didnt show up on my calculator

but tysm man for helping me

i mihht need help in a bit again

[ornate skiff]

You're welcome.

Is this for school, and such?

In theoretical maths, it's better to leave it as 0.52/1.2

in practice, I suppose approximations are fine, but it depends "how early" you approximate.

Even then, you want to be as close to theoretical value as possible.

[brazen nimbus]

im studying for an exam

but im in school yeah

[ornate skiff]

I think not dividing -0.52 and -1.2 is better idea then.

0.43 is a pretty bad approximation. might cost you points, in an exam.

[brazen nimbus]

yeah

of course

thanks

same goes for ln too right

ln values

[flat frigate]

Wild123

[ornate skiff]

yes.

the ln on the right side is fine. the one on left side, not so much.

[brazen nimbus]

also if you know it wasnt there something with ln(a+b)

some rule like that

[flat frigate]

Wild123

[ornate skiff]

yes, there are 4 properties of logarithm (not only ln, all log in any base) that are useful. one of them is

[flat frigate]

Wild123

[brazen nimbus]

oh yeah right

this is useful for when you calculate the area between 2 e functions right

or the points where they uhhh

collide

sorry enlgihs isnt my first language

[ornate skiff]

it's alright; I am not sure. I'll need an example.

[brazen nimbus]

okay man if i need help can i ping u or something

[ornate skiff]

sure; if I am available, I'll help. If not, probably someone else will.

Don't hesitate to tag helpers if some time passes and I cannot respond. Might be unable to assist...

[safe radish]

@brazen nimbus Has your question been resolved?

[safe radish]

@brazen nimbus Has your question been resolved?

[safe radish]

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[fathom hamlet]

is it right to assume that for a given sequence, every number in the sequence is also part in a subsequence of the main one?

[edgy isle]

sure, the sequence itself can be considered a subsequence for example

[fathom hamlet]

oh wait really

waiwaitwait

so

if i need to prove the claim "if every subsequence converges then the main one converges too" can i use what you said?

[sudden forum]

convergence of any subsequence implies convergence of the main one, in fact

[edgy isle]

na

[fathom hamlet]

thats not true though, take (-1)^n

(-1)^2n = 1 and it converges to 1
(-1)^2n+1 = -1 which converges to -1

so the main one jumps between 1 and -1

so doesnt converge

[sudden forum]

🙊

Yeah, you're right

[fathom hamlet]

the opposite of what you said is true according to the Bolzano–Weierstrass theorem

[edgy isle]

not really the opposite

[fathom hamlet]

eh fair

[edgy isle]

sure

that statement is kinda trivial

[fathom hamlet]

everything is trivial and super intuitive until you need to write a formal proof xD

[edgy isle]

even the formal proof for this

it could be strengthened by excluding certain subsequences

[fathom hamlet]

actually the definition of subsequence the lecturer gave us says "a subsequence is a sequence that contains a part of the numbers of the original sequence in the same order" so idk if saying a sequence is also a subsequence of itself is right in this case

is there any other way to prove it?

[edgy isle]

not that rigurous of a definition

given a sequence $\left(a_n\right)_{n \in \mathbb{N}}$

[flat frigate]

rbit

[edgy isle]

then a subsequence $\left(a_{\varphi(k)}\right)_{k\in \mathbb{N}}$ is given by a strict monotone increasing function $\varphi: \mathbb{N} \to \mathbb{N}$

[flat frigate]

rbit

[fathom hamlet]

why did you assume its monotone let alone strict monotone

[edgy isle]

so that the order doesn't get shuffled around

if you have a sequence 1, 2, 3, 4, 5, 6, ...

then 1, 3, 10, 11, 17, ... would be a subsequence, but not 1, 8, 4, 9, 2, ...

[fathom hamlet]

i see

[edgy isle]

like

if you take phi = identity, you get the original sequence

id(1) = 1
id(2) = 2
id(3) = 3
...
and one way to construct subsequences is by leaving out certain members of the original sequence, which will be noticable by the phi function making certain jumps
phi(1) = 1
phi(2) = 3 (we left out element 2)
phi(3) = 6 (we left out elements 4 and 5)
...
but then it wouldn't make much sense for it to suddenly be decreasing

[safe radish]

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[fair citrus]

help

[untold helm]

can anyone help me in my channel

[fair citrus]

its fine i got help

.close

[safe radish]

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[misty abyss]

im stupid or something but i cant figure this out
so i got a function f that can tell a number in pascals triangle by 2 coordinates the direction of which is on the picture
problem is i want to specify row and one of these instead
what do i have to add to the coordinates to make this work?

[brave wolf]

can you give an example?

[obsidian oracle]

looks like (n+k)Ck

[untold helm]

combinations

just google binomial theorem

[obsidian oracle]

k = position on the green line (starting from position 0)

n = position on the purple line (starting from position 0)

[misty abyss]

def f(n, s):
    s += n
    a = factorial(n+s)
    b = factorial(s)
    c = factorial(n)
    return a/(b*c)

this is the function

i am trying to get it so n is row and s is the "col" but i can get it right

[untold helm]

binomial theorem

into wikipedia

[brave wolf]

i dont think thats too relevant

[untold helm]

can u help me in my chanel

channel*

[solid shell]

$f(n,s)=\frac{(2n+s)!}{n!(n+s)!}$

I have translated python to math

[brave wolf]

Hmm, wouldnt that just be n choose s

[flat frigate]

al-jebruh

[solid shell]

Using your code

[brave wolf]

e.g. 4 choose 2 would be 6