#help-23

1 messages ¡ Page 322 of 1

lean otter
#

ok so in this case, u didn't add the length of other triangle

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wait x can't be 10 💀

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6 / 9 = 8/12

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its 9

odd nest
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X is 18

lean otter
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thats impossible

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u have missed calls from issac newtons

odd nest
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10 + y / y = x / 6

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@lean otter

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It’s gonna be X / 6

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they’re SIMILAR

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congruent

lean otter
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RIGHT?!

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U APPLY THAT FOR THE RIGHT SIDE

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SOOOOO X + 6 / 6

odd nest
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X + 6 are NOT connected like y + y + 10

lean otter
odd nest
#

It’s not?

lean otter
#

u just have to apply that

odd nest
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It’s a single line

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Those are only congruent

lean otter
#

thats not how it works

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if u add two side, u just have to add it

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regardless of connectives

odd nest
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How is it X / x+6?

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Ok I’m not gonna fight with you

lean otter
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u should apply that for x

odd nest
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8 / 12+8 = 6 / x

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12 + 8 IS ADDED BECAUSE ITS A SINGLE LINE of the triangle

lean otter
odd nest
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Yes…

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Of the BIG triangle

lean otter
#

it doesnt need to be a single line

odd nest
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Single side of a BIG triangle

lean otter
#

like

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it can be two seperated line, and still be added

lean otter
#

$$\frac{\text{side of small triangle}}{\text{corresponding side of large triangle}} = \text{constant ratio} $$

flat frigateBOT
#

Da pro

lean otter
#

@odd nest id calculate it with the small triangle and the large triangle in the first place

odd nest
#

7 is 6,67 correction.

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@lean otter

lean otter
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x = 15

odd nest
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8x = 120

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120:8

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15

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Somehow chat gpt tells me x = 9

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Can Anyone clarify ? <@&286206848099549185>

lean otter
odd nest
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Omg idk now

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6,67 / 16,67 = 6 / x

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6,67x = 100,02

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100,02 : 6,67

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X = 15

lean otter
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yh it seems legit

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ask chatgpt to think again

odd nest
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Now chat got now says it’s 5

austere cypress
#

chatgpt is dum

summer rover
lean otter
safe radishBOT
#

@odd nest Has your question been resolved?

safe radishBOT
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granite seal
safe radishBOT
granite seal
#

who down 2 help me

#

uh HELLO im some dire need of help

#

<@&286206848099549185>

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glad river
safe radishBOT
glad river
#

.close

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versed wave
#

brother i was about to help

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but oh well

glad river
#

oh

versed wave
#

.reopen

safe radishBOT
#

✅

versed wave
#

just so you know, this problem is called the napkin ring problem

glad river
#

okay

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i just dont understand how to set it up

versed wave
#

theres actually a rather counterintuitive formula for it, but you can derive it yourself

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it helps to just consider the cross section of the sphere instead

glad river
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the way i think of it is the volume of the sphere minus the hole

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i honestly dont understand it at all

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i get disk method and washer method but not this

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.close

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lean otter
safe radishBOT
lean otter
#

Can someone help me with congruency?

tardy mango
# lean otter

This is mainly just knowing how to interpret the symbols

#

If two angles are marked with the same (nonzero) number of arcs, then that means that they’re congruent

lean otter
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Oh I see

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So angle KLM is congruent to JIH

tardy mango
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Those arent marked with any arcs

lean otter
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Wdym arc?

tardy mango
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The curve thing that the red arrow is pointing to

lean otter
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Is K and J not marked with arcs?

tardy mango
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There are angles with vertices at those points that are marked if that’s what you mean

lean otter
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I’m still confused

tardy mango
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These angles are marked if that’s what you’re saying

tardy mango
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The vertex name goes in the middle

lean otter
lean otter
tardy mango
tardy mango
# tardy mango

The vertex is where the two rays that make the angle intersect

#

In the case of the top circled angle, the vertex is J (as both of the rays that make that angle extend from J)

lean otter
# tardy mango ??

Im horrible in math just excuse if I say anything dumb i thought the vertex was the thing that connected things between two lines so like L connections to K and M

tardy mango
#

i thought the vertex was the thing that connected things between two lines

A better (aka more rigorous) way to frame this is where the two lines/rays/segments that make the angle intersect is the vertex

tardy mango
tardy mango
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See how JH and JI are the sides of the arc

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They meet at J

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Hence J is the vertex

lean otter
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Ohh

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So the answer would be smth like IJH is congruent to LKM

lean otter
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Thank u bro

#

.close

safe radishBOT
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safe radishBOT
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versed smelt
#

part b

safe radishBOT
versed smelt
#

Could someone check where I went wrong???

brave wolf
#

here I think

versed smelt
#

i assumed, but idk what i did wrong there 🤧

vernal crystal
#

I'm not sure if a direct u substitution will work with the problem, you could trying multiplying the numerator and denominator with e^-x and then try

brave wolf
#

it's $\left(1 - \frac{e^t}{u}\right) dt$

flat frigateBOT
#

MĂŚthIsAlwaysRight

brave wolf
#

you cant just cancel the e^t and replace dt with du

digital sparrow
#

what does \left and \right do?

quick crater
#

make brackets be an appropriate size

digital sparrow
flat frigateBOT
#

Skissue ping4response

versed smelt
#

huh 😭

brave wolf
versed smelt
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why tho?

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cause ive made e^t dt = -du

brave wolf
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there are parenthesis

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we omit them by convention, but act like if they were there

versed smelt
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so its taken as 1 term?

brave wolf
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Yeah

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and unless you factor out e^t from both terms, you cant cancel it so easily

vernal crystal
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Also the constant 1 you've integrated should be in terms of t instead of u

vernal crystal
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Like when you distribute the dt, you could only covert the e^tdt to du but not with the 1

vernal crystal
#

The u/u they've cancelled

brave wolf
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oh, ic, thats what i was saying

versed smelt
#

mm

vernal crystal
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oh lol

versed smelt
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this is the answer btw

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photon mentioned smth about multiplying by e^t

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just curious

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how do i recognise when to multiply by e^t?

vernal crystal
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Yeah multiply the denominator and numeraetor by e^-t

vernal crystal
versed smelt
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we were taught we either mutliply by "1/1" or "+-1"

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when the integration is to complicated

brave wolf
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Your approach isnt entirely wrong btw, I think that you could continue with that

vernal crystal
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Yeah seems like if you fixed few steps, your method should work fine

versed smelt
#

oo

versed smelt
versed smelt
vernal crystal
versed smelt
#

oo

versed smelt
#

and would that overcomplicate my solution?

versed smelt
#

.close

safe radishBOT
#
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versed smelt
#

thanks!

brave wolf
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oh wait, nvm, i was looking at the answer key to b

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the results i got were correct

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basically at this poitn you can split the integral

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integral of 1 is gonna be t

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and integral of e^t / u dt is gonna be -ln(u) = -ln(1-e^t)

versed smelt
#

ooo

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splitting the integral

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never thought of that

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so thats where the t came from

safe radishBOT
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river bolt
safe radishBOT
digital sparrow
#

!status

safe radishBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
river bolt
#

1

digital sparrow
#

tell me what a_3 will be

river bolt
#

(a_1)(a_2)

digital sparrow
#

ok and what about a_4

river bolt
#

(a_4) = (a_1)(a_2)(a_3)

digital sparrow
#

substitue a_3 in this

river bolt
#

so its just (a_3)(a_3)?

digital sparrow
#

yup

digital sparrow
river bolt
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im thinkin 1 sec

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since n > 2 lets take 3 for example so a_3 = t which means a_(3+2) is a_5 right?

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and sincr we know a_5 = (a1)(a2)(a3)(a4) thats basically (a3)(a3)(a3)(a3) which is (a3)^4

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and since a_n = t, then a_5 = t^4?

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or does this not work

digital sparrow
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this is correct

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now try for a_n

river bolt
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a_n = t though

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little bit stuck now ngl

digital sparrow
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write a_(n+1)

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sorry had to go

river bolt
#

nw

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a_(n+1) = (a_n) (a1) ?

digital sparrow
#

nope

#

$a_{n+1} = a_n * a_{n-1} * a_{n-2} * a_{n-3} ..... * a_2 * a_1$

flat frigateBOT
#

Wumpus Man

river bolt
#

but if you used lets say n = 3, that would work? at some point you are getting a_(3-4) which is a_(-1) and how do a2 and a1 come into play here?

digital sparrow
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it just means you go from a_n all the way a_1 multiplying all the terms

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for a_3 it will just be a_2 * a_1
a_4 = a_3 * a_2 * a_1

river bolt
#

ok i see makes sense

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$a{n+2} = a_(n+1) * a_n * a{n-1} * a{n-2} * a{n-3} ..... a_3 * a_2 * a_1$

flat frigateBOT
river bolt
#

damn didnt turn out right

#

$a{n+1} = a_n * a{n+1} * a{n-1} * a{n-2} * a{n-3} ..... a_3 * a_2 * a_1$

flat frigateBOT
river bolt
#

still doesnt work ok idk why its not coming out correctly

safe radishBOT
#

@river bolt Has your question been resolved?

safe radishBOT
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zealous jetty
#

how do you come to that answer??

safe radishBOT
digital sparrow
#

$\log({a^b}) = b\log{a}\newline$
$\log({ab}) = \log{a} + \log{b}\newline$
$\log({a/b}) = \log{a} - \log{b}\newline$

flat frigateBOT
#

Wumpus Man

safe radishBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

verbal token
#

whoops

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sorry

digital sparrow
zealous jetty
zealous jetty
#

one sec

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okay no

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am i supposed to solve it like the log isn’t there

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just w the numbers

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or like

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make separate logs

safe radishBOT
#

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fast sierra
safe radishBOT
fast sierra
#

heyo, im just confirming that this wants me to basicly carry out differantiation of "10 x -2^3 + 8 + -2^2 + 5"

fast sierra
#

could you explain then?

lean otter
#

you are first supposed to differentiate it wrt x and then input x=-2

fast sierra
#

wrt x ?

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sorry?

lean otter
#

?

fast sierra
#

ih

#

oh

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you ment with?

lean otter
#

oh

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wrt expands to "with respect to"

fast sierra
#

oh

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never seen anyone else write that in that way but sure

lean otter
#

sad

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i thought it was quite common

fast sierra
#

but in that case, 30x^2+16x

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then replace x with -2?

lean otter
#

yep

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whhat you are doing here is

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finding the slope of the tangent of the curve 10 x^3 + 8x^2 + 5

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at x= -2

fast sierra
#

huh?

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🤔

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i am more confused by "the tangent of the curve"

thin bridge
#

*to the curve

fast sierra
#

.close

safe radishBOT
#
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pearl sphinx
#

.

#

Okay so

safe radishBOT
pearl sphinx
#

Can someone please help me understand this and also like if this data has a positive correlation to the 3 variables

#

I know that (r= .008 , p=.954 ) but which of the both do I base as closer to 1 ? the r or the p ?

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<@&286206848099549185>

#

or maybe I'm thinking of it wrongly

#

I'm so lost...

#

:>

safe radishBOT
#

@pearl sphinx Has your question been resolved?

safe radishBOT
#

@pearl sphinx Has your question been resolved?

safe radishBOT
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lilac shale
#

a) Angle POQ = 1.75 rad
b) Length of PX = 4.7896cm
c) Area of shaded region = ???

lilac shale
#

I found area of segment QP

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which is 6.128cm

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squared

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Maybe I can use triangle formula Half * r^2 * sin theta. But idk about theta here

#

Can you help with 5 (c) please

#

......

safe radishBOT
#

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lilac shale
#

.close

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upbeat current
#

How do u do this?

safe radishBOT
upbeat current
#

<@&286206848099549185>

safe radishBOT
#

@upbeat current Has your question been resolved?

little ibex
#

i can try helping

#

a sinusoidal function would mean f(x) has sin function with some additional things attached

#

maximum value of a regular sine function is 1 & minimum is -1

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so you need to change it in such a way that the maximum is 100 and minimum is 20

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so something like f(x) = ksin(x) + c

upbeat current
#

Oh

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Hmm

little ibex
#

and for a pt to be on the curve

noble frigate
#

$f(x)=a\sin{(bx)}+c, \text{where a is amplitude, b is frequency, and c is midline}$

#

whoops

upbeat current
little ibex
#

point (x,y) to be on curve, f(x) = y

upbeat current
#

Oh

little ibex
upbeat current
#

yea ik

flat frigateBOT
#

UrMom73

upbeat current
#

Alr

noble frigate
#

try finding the midline and amplitude first

upbeat current
#

a = max-min á 2

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That's 40

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c = 60

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What about the period and d?

noble frigate
#

the equation for period is 2π/b

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so find a value for b that will result in a period of 30

upbeat current
#

b?

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I use k but it doesn't matter

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Period is 30

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So 2pi/30

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Which is pi/15

#

@noble frigate

#

Right?

noble frigate
#

yup

upbeat current
#

Perfect

#

Thanks

#

.close

safe radishBOT
#
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flat frigateBOT
safe radishBOT
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carmine latch
#

Hey,
A coin is tossed 8 times what is the probability that there are no 3 consecutive head or tails?
i solved it using combinatorics, but i want to solve it using only probability, i am thinking of using binomial distribution, but i am unsure of how to

safe radishBOT
#

@carmine latch Has your question been resolved?

carmine latch
#

any helpers Pepe5head

safe radishBOT
#

@carmine latch Has your question been resolved?

unique venture
#

actually, 8 times would be difficult to draw

unique venture
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urban sapphire
#

Hello please help I’ve been stuck for 2 hours on this

urban sapphire
#

It looks really easy but for some reason I got stuck

lean otter
#

I hate geometry

tulip acorn
#

AC=BC so the big triangle has equal sides so the symetric of A is B where the axis is the perpendeicular line to AB passing by C then you can prove that the symmetric of the point of intersection of the circle of radius AD and the line AB is the the intersection of the cercle of the same radius wich is AD(=BE) and the line AB which is E so the symmetric of D is E so CDE is a triangle of equal sides so the angles are equal

#

there are other methods but i didnt know what lessons and theorems you can use

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so i just wrote down any idea i got

urban sapphire
urban sapphire
#

Algebra is way better

lean otter
tulip acorn
urban sapphire
#

Unless I just wasn’t paying attention

#

lol

tulip acorn
#

do you have the theorem that says 2 triangles that has 2 equal sides and equal angle between those side are equal or smthing like that

urban sapphire
#

You mean for isosceles triangle?

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Or SAS

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@tulip acorn

tulip acorn
#

i think so i didnt study math in english so i dont know the names

urban sapphire
#

Oh ok

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Yeah like Side angle Side congruency right

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I was trying to prove angle A is equal to angle B

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But found my figure out how to prove that

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Because if those two angles are equal then CPCTC right?

tulip acorn
urban sapphire
#

CPCTC…you know corresponding parts of congruent triangles are congruent

tulip acorn
#

oh ok

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ye

#

exactly

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you can use that

urban sapphire
#

But how can I prove angle A is equal to angle B?

tulip acorn
#

you have a triangle ABC where AC=BC

urban sapphire
#

OHHHHHHHHHHHHHHH

tulip acorn
#

conclusion its isosceles triangle

urban sapphire
#

Now I get it thanksssss

#

Cuz it’s isosceles

tulip acorn
#

np

urban sapphire
#

Appreciate it bro

#

That got me stuck for so long 😅

tulip acorn
#

just focus and try to start with small conclusions dont look at the whole picture at one go

urban sapphire
#

Okay, thanks for the advice

safe radishBOT
#

@urban sapphire Has your question been resolved?

safe radishBOT
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weary sandal
safe radishBOT
weary sandal
#

Hey can I get some help with this one?

#

For some reason I feel like none of the answers are correct so I'm kinda stuck

#

<@&286206848099549185>

safe radishBOT
#

@weary sandal Has your question been resolved?

weary sandal
#

So my understanding of this is that we have something like this:

v0 -----------  v1
|               |
|               |
|               |
v2 ----------- v3

I don't think the first one is right because the dot product also takes into account the lengths of the vectors ||a|| ||b|| cos(theat) . I don't think the second is correct because it takes into account the size of the paralellogram spanned by the vectors. I don't think the 3rd is right because the diagonals are not always perpendicular and I don't think the last is right due to the same problem as answer 2.

#

Am I missing something here? <@&286206848099549185>

safe radishBOT
#

@weary sandal Has your question been resolved?

weary sandal
#

I'm pretty sure the second is the closest but one could be a scalar mult of the other right?

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lost cargo
safe radishBOT
lost cargo
#

vector equation

azure delta
#

Vector equation, like the one with the parameter?

#

Or like some cross product equalling zero?

lost cargo
#

i don't need to do ii and iii

#

just i

azure delta
#

Do you know how cross products identify paralellity?

kind forge
#

wait hold on

lost cargo
#

yes

kind forge
#

are we not overthinking this

#

isn't the vec eqn form of a line just a point plus λ × some vector?

lost cargo
#

yeah

#

i was sick for two days and my class just went through vectors at rocket speed

kind forge
#

oof

kind forge
#

ah

azure delta
#

Cause that uses a parameter

#

In any case, if you don't remember what the cross product does, it will be good for you to review it

lost cargo
#

so how do i approach these questions in general

#

when i was given a vector and a point

azure delta
#

Forget the point for a moment. What vector equation using cross product can you write that describes vectors parallel to the given vector?

lost cargo
#

v*w=|v||w|cos theta

#

?

azure delta
#

That's dot product

#

And oddly enough, we don't really care what the formula for cross product is. We care that the cross product of parallel vectors is zero

lost cargo
#

oh

#

is it sin theta

azure delta
#

It is

lost cargo
#

so if its parallel it would be sin 0?

azure delta
#

Yes

lost cargo
#

so cross product = 0

#

or do i need to divide magnitude to the left

azure delta
#

You do not

#

Once a product is zero, it doesn't matter if you multiply or divide it

lost cargo
#

so for this question it should be a^2 * 2^2 + b^2 * 1^2 + c^2 * 3^2 = 0?

#

and i solve for a b and c?

azure delta
#

Are you doing for product again?

#

But with squares?

lost cargo
#

oh wait

azure delta
#

Again, you don't need any formulas for the cross product. You only need to understand that the cross product of parallel vectors is zero.

lost cargo
#

so its (2,1,3) times another vector = 0

#

if its parallel

azure delta
#

yes

#

You can just call it v

#

v x (2,1,3) = 0

lost cargo
#

how can i solve for v

azure delta
#

why are you trying to solve for v?

lost cargo
#

don't i need to find the vector equation

azure delta
#

that is a vector equation

lost cargo
#

wait what

#

i don't get it

azure delta
#

v x (2,1,3) = 0 is an equation of vectors

lost cargo
#

isn't vector equation r = a + lambda b

azure delta
#

lambda is a parameter, so I think that's a parametric equation

#

but if you want that, you can write that in one step cause they give you a and b

#

I guess the parametric equations could be that equation you gave but pulled apart into its components

lost cargo
#

i thought parametric is x=somehting y=something and z=something

#

with lambda

azure delta
#

the words are a big ambiguous without the context of your lessons

azure delta
lost cargo
#

a is (1,3,-7)

#

not sure about b

azure delta
#

lambda just lets you go any distance away from point a. b tells you the direction that you need to be going. What direction does the question tell you to go?

lost cargo
#

wait

#

is b just (2,1,3)

#

ok

#

i get it now

#

thank u very much

#

.close

safe radishBOT
#
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dense wadi
#

if im not mistaken

safe radishBOT
dense wadi
#

can i think of x_o like

#

b in a linear equation y=ax+b

#

wait

#

it literally is no?

median vigil
#

we can rewrite $y = mx + b$ as [ \underbrace{\begin{pmatrix} x \ y \end{pmatrix}}{\vb x} = t\underbrace{\begin{pmatrix} 1 \ m \end{pmatrix}}{\vb v} + \underbrace{\begin{pmatrix} 0 \ b \end{pmatrix}}_{\vb x_0} ]
note that this is not the only form that $\vb v$ and $\vb x_0$ have to take

flat frigateBOT
median vigil
#

and you are correct that in both cases it shifts the line away from the origin

safe radishBOT
#

@dense wadi Has your question been resolved?

dense wadi
#

anyway ty

#

.close

safe radishBOT
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dense wadi
#

are v1 and v2 parallen to x_0?

safe radishBOT
plucky elk
#

Doesn't look parallel

dense wadi
#

coz in b here it asks the x_0 to be parallel to v1 and v2

plucky elk
#

Yes these two images look unrelated

dense wadi
#

but they used the equation like there

#

so

#

thats why im like wtf

mossy lotus
#

the vectors v1 and v2 are parallel to the plane thru x_0

#

The vectors v1, v2, x_0 all share the origin as starting point. Ofc they wont be parallel

dense wadi
#

yeha i realized

mossy lotus
#

If you draw the parallelogram law of vector addition on x = x_0 + t1v1, youd see the different values of t1 yield different vectors parallel to v1. Similarly for v2

dense wadi
#

ig the importance is they form a plane thats parallel to each other

mossy lotus
#

and those vectors span the plane parallel to v1 and v2

dense wadi
#

ok tysm

#

.close

safe radishBOT
#
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karmic falcon
#

hello, undergraduate need help for an exam that's after 1 hour calculus derivatives

karmic falcon
#

Genuinely cannot understand example 1

daring crescent
#

Do you understand what it is asking in part a?

#

and not know how to do it, or do you not know what it is asking at all?

safe radishBOT
#

@karmic falcon Has your question been resolved?

daring crescent
#

@karmic falcon !status

karmic falcon
#

didnt see ur massage

#

This also if you can

daring crescent
#

hmmm, wording this will be a bit awkward, the slopes can make there own graph and it is asking how that graph behaves (you can assess that with the equation of the slops of 1/a)

karmic falcon
#

Steps

daring crescent
#

Guesstimate the slope and draw a tangent line at the given points on the graph

karmic falcon
#

say num 1 for example

#

u get the point y,x

#

what should u do after it

daring crescent
#

There is nothing you can do without the function being written out, unless you know how to get the function for those graphs

karmic falcon
daring crescent
#

All it's asking is for you to draw the tangent line at that point

daring crescent
#

The only one that has a slope that you can tell accurately is the p2 on 2

karmic falcon
daring crescent
#

yeah, the red lines are tangent lines

safe radishBOT
#

@karmic falcon Has your question been resolved?

safe radishBOT
#
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deep imp
safe radishBOT
deep imp
#

i know how to subsitutue it but i want to see how its graphed

young nexus
#

take an x (e.g. -3), calculate y, draw a point, take the next x ....

wild copper
#

Ah, yes. The "let's eyeball it" method.
But on a more serious note, a question like graphing is not something that you can ask over internet, because it depends more on your drawing skills. The best we can do is to tell you how to do it.

deep imp
#

how should i set it up to standard form

young nexus
#

why do you need a standard form?

deep imp
#

im not even sure brah

#

can i just get some steps to graph it

#

@young nexus

deep imp
#

like find aos or vertex

young nexus
#

easier than typing a tons of questions in a discord channel? during the time i am typing all this messages i would have done this twice.

faint seal
lean otter
#

I think it'll be more rewarding and better practice if you understand how the shapes of these graphs are affected by translations, stretches, etc. It will take you less time to draw them if you understand how the functions behave in general and are able to apply your knowledge of how these various transformations affect them. @deep imp For example x^2 - 16 is just a translation of the function f(x) = x^2 down by 16 units. If you know the shape of the graph, you should be able to draw it in a few seconds.

lean otter
#

,w graph f(x) = x^2

lean otter
#

what can you say about x^2 - 16?

deep imp
#

it opens up

#

it would shift

#

-16

lean otter
#

correct

deep imp
#

but -16 in which way

#

x or y

lean otter
#

that's a good question and I'm glad you are no longer trying to find the easy method but the one that'll help you solve these types of problems in the future

#

so, what do you think?

deep imp
#

downwards y axis

lean otter
#

yep

#

tell me why you think this is the case

deep imp
#

im not sure

#

it was a guess

lean otter
#

not a bad start

#

so, in general we say that $f(x - a)$ where $a$ is a constant $\in \mbb{R}$ will translate the graph of $f(x)$ $\emph{horizontally}$ by $a$ units to the right. If we have $f(x) - a$ then it will shift the graph of $f(x)$ to downwards by $a$ units (this is all provided that $a > 0$). So, let's take $f(x) = x^2$ as an example: if we have $h(x) = f(x-1) = (x - 1)^2$ and $g(x) = f(x) - 1 = x^2 - 1$, then which one will result in a horizontal shift and which one will result in a vertical shift?

flat frigateBOT
deep imp
#

fx results in a downshift g of

#

oh

#

nvm i thought it was deleted

lean otter
#

nah I just realized that I used the same notation twice

deep imp
#

hx is to the right

lean otter
#

exactly

deep imp
#

gx is to down

lean otter
#

nice

#

good

#

and if you want to convince yourself that this is true you can plug in a few values into both functions and play around with them on Desmos, for example

#

so, back to your question

#

,w graph f(x) = x^2 for -9 \leq x \leq 9 \land -18 \leq y \leq 18

lean otter
#

huh

deep imp
#

i believe both of my equations are quadratics

#

cuz of the x^2

lean otter
#

yeah, i'll just use desmos to show you

deep imp
#

i already tried using it earlier

#

im just confused about the setup

#

as in how do i show my work via table of values or whatever

lean otter
#

ah okay, so have you done this type of stuff with linear equations and graphs of them?

deep imp
#

yes

lean otter
#

perfect

#

so with linear equations

#

you look at the intersection of the lines

#

it's the same with this

#

so you want to look at the points of intersection

#

so when $x^2 - 16 = -(x + 4)^2$

flat frigateBOT
lean otter
#

if you hover over the points of intersection on Desmos, you'll see that (0, -16), is, for example, a point of intersection. Can you find the other pair (x, y)?

deep imp
#

-4,0

lean otter
#

yup

#

so the two solutions are x = -4 and x = 0

#

and the ordered pair solutions are (0, -16) and (-4, 0)

deep imp
#

do i plug -4,0 back into for x

#

and solvefor y

lean otter
#

$0^2 - 16 = -(0 - 4)^2$

flat frigateBOT
lean otter
#

since $0^2 - 16 = -16$ and $-(-4)^2 = -16$

flat frigateBOT
deep imp
#

ah i see

#

now how do i go on about making my table of values

lean otter
#

table of values?

deep imp
#

my teacher wants 2 to the left and 2 to the right of a given point

#

perferably the intersections are within the 5

lean otter
#

can you give me an example of what you need?

deep imp
lean otter
#

ah

#

okay so what you want to do is plug in values into both functions and fill the table up. The harder part is finding the y for each corresponding x. You can pick any value you like for x unless your teacher has specified what they want, but otherwise, it's just a matter of plugging things in

deep imp
#

yo thank u for ur help @lean otter

#

u actually took time to bless me up for free

#

something tutors charge hella for

lean otter
#

np np happy to help :D

safe radishBOT
#

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raw orchid
#

Continuing with this because it timed out

#

I have no idea how I'd go about constructing Jordan blocks

#

Is there some way I can do that

safe radishBOT
#

@raw orchid Has your question been resolved?

raw orchid
#

<@&286206848099549185>

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#

@raw orchid Has your question been resolved?

safe radishBOT
#

@raw orchid Has your question been resolved?

raw orchid
#

<@&286206848099549185>

lime apex
#

Helo

#

Im noob at fortnite

raw orchid
#

.close

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red swan
#

Can anyone tell me if I did this good?

The image shows two congruent triangles. Calculate the length of x and y.

safe radishBOT
#

Please don't occupy multiple help channels.

digital sparrow
#

Yes this is correct

red swan
#

Fr?

red swan
digital sparrow
#

Wdym 2?

#

You could have also used y/(y+10) but yours is better

#

Other than that I don't think

red swan
#

Method 1:
20/8 = x / 6

Method 2:
y+10 = x / 6

digital sparrow
#

not y+10

#

(y+10)/y

#

But this is essentially the same as 20/8

red swan
#

ye ye ye

#

(y+10) / y = x / 6

digital sparrow
#

Yup

red swan
#

two ways

#

to do that

#

@digital sparrow

digital sparrow
#

Yes you can say that

#

But imo they are the same thing

red swan
#

someone said

#

20 / 8 = (x+6) / 6

#

and i was like

#

confused

digital sparrow
#

That is incorrect lol

red swan
#

fr

#

i was like

#

bruh

digital sparrow
red swan
#

and also

#

i put that

#

into chatgpt

#

and it told me the SAME answer as the other dude

#

good that i didnt fix that to theirs method

#

otherwise i wouldve gotten worse grade

simple gazelle
red swan
#

It’s using taught formulas

simple gazelle
#

exhibit a

#

also there's literally a command in this server

#

i think

red swan
simple gazelle
#

!help

safe radishBOT
#

To ask for mathematics help on this server, please open your own help channel or help thread. See #❓how-to-get-help for instructions.

simple gazelle
#

no

#

!chatgpt

#

!gpt

#

!nogpt

safe radishBOT
#

Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).

simple gazelle
#

there we go

#

oh wait no unrelated

#

nvm

safe radishBOT
#

@red swan Has your question been resolved?

digital sparrow
#

Lmao

#

@red swan is your doubt still there?

#

If not then I recommend closing this channel

#

!done

safe radishBOT
#

If you are done with this channel, please mark your problem as solved by typing .close

red swan
#

.close

safe radishBOT
#
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hollow reef
#

Guys help me with solving this

safe radishBOT
fathom kraken
#

Hint 2: Write equations for square side length

hollow reef
fathom kraken
#

Why

safe radishBOT
#

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somber cape
#

were going over hypothesis testing

safe radishBOT
somber cape
#

What is the population here?

#

I was thinking the population is just all people?

#

or all people who had their normal diastolic blood pressure measured

#

oh

#

wait the population is just the. Mexican American adults in that california town

#

and the sample is a small portion of them

#

But how do I test whether there is evidence to suggest that the mean blood pressure of the population differs from 120 without a confidence interval given?

honest perch
#

is 120 the normal for all people or only mexican americcans

safe radishBOT
#

@somber cape Has your question been resolved?

somber cape
#

Question doesn’t specify any more than that

honest perch
#

im guessing it's for all people and the population is mexican americans. if the sample mean is different from 120 then that's evidence. that's just my guess tho i haven't studied this stuff

safe radishBOT
#

@somber cape Has your question been resolved?

rain gale
#

i believe 120 should be for all people (generally speaking), you don't know what blood pressure is average for mexican american adults in small california town (x), do you have reason to believe that (x) is significantly different from 120 given that you took a sample from that population

#

there should exist some formula out there for calculating significant difference between two means where one of the population sizes is unknown

#

this is AI generated so be careful, but it sounds reasonable enough:

#

id suggest confirming this with a reputable source

safe radishBOT
#
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south lynx
#

could we not factorise it? how did we think of this substitution?

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#

@south lynx Has your question been resolved?

empty gyro
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#
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south lynx
#

.reopen

safe radishBOT
#

✅

south lynx
empty gyro
south lynx
#

no worries!

empty gyro
#

@south lynx i think you want to take advantage of difference of cubes. But I'm not sure yet

#

It can be factored. Every rational function with a limit can be found through factoring. But damn this one is hard

south lynx
#

what exactly is h here again?

#

ah

#

wait

#

we're trying to find RHL

empty gyro
#

Okay i have an idea. Get rid of square roots on numerator by multiplying by its conjugate

south lynx
#

i tried that

empty gyro
#

At the same time, get rid of cube roots on denominator by multiplying by its conjugate

south lynx
#

but isn't that just rationalization

#

so you mean we don't simplify it first?

#

while multiplying by their conjugates?

#

oh wait lmao

#

wow

#

never mind yeah, you're right. i was originally supposed to rationalize it

#

we're taught that whenever you see 0/0 or infinity/infinity form, you rationalize/factorise/use l'hĂ´pital's rule

#

i mis-wrote (?) rationalization as factorisation

#

my original question still stands

#

why the substitution (more like how)?

toxic stratus
#

there is no need to make a substitution

south lynx
#

i get that. i was just wondering about the approach

toxic stratus
#

x -> 2, if x = 2 + h, then it is equivalent to saying h -> 0

#

one makes this substitution because early on in calculus, one is taught to take h -> 0

#

so the substituion is essentially made so that people don't get scared by a limit not going to 0 and not using h for whatever reason

south lynx
#

ah

#

makes sense

#

could we use binomial theorem here?

#

after the substitution

toxic stratus
#

it shouldnt be necessary

south lynx
#

okay, got it

#

thank you! 🌸

#

.close

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lean otter
#

how do u find critical points

safe radishBOT
lean otter
#

pLs help

lean otter
smoky nacelle
#

graphically, flat graph or sharp turn.

lean otter
#

bro i got 5/2root7

#

what am i doing wrong h e e l p

smoky nacelle
lean otter
#

i thought i had to like derive gx

#

cuz that is fx and i tried 3 and 5 already

#

3, 5, 9 too

#

<@&286206848099549185>

#

what do i do

safe radishBOT
#

@lean otter Has your question been resolved?

safe radishBOT
#

@lean otter Has your question been resolved?

safe radishBOT
#

@lean otter Has your question been resolved?

minor socket
#

@lean otter you were on the right track when you put 3 and 5, I think you just forgot about your end points. 5 is one because g'(x)=0 at x=5, and 3 is one because g'(x) is undefined there. notice that x=7 is in the domain of g(x) but not in the domain of g'(x). just like 3, 7 is a critical number because g'(x) is undefined there
we all forget to check little things like that sometimes, hopefully that helps

#

ngl no clue where the 9 came from or the 5/2root7 that you mentioned earlier though, I can't figure out how you got there

lean otter
#

thank u for responding omg that thought process came from g(x)= root f(x)

minor socket
#

sorry I saw it so much later than you'd sent the question

lean otter
#

thank u bro u saved my life

minor socket
#

no problem

lean otter
#

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azure kayak
#

how would you plug this equation into a calculator like this? whenever I try I end up with 13.99 when the answer is 0.262

median vigil
#

you need to add parentheses around the numerator and denominator

azure kayak
#

tysm it worked 🙂‍↕️

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vocal ibex
#

Are u able to partial fraction decompose this?

tardy mango
#

,w partial fractions 4x^2 /(x*(x^4+16))

flat frigateBOT
tame chasm
# flat frigate

(hi im working with the person above) how did wolfram get to this answer? to decompose, dont you have to turn the denominator into at most repeated quadratic factors?

tardy mango
flat frigateBOT
#

Civil Service Pigeon

tardy mango
#

that's the roots of unity nuke

vocal ibex
#

is this trig-level math

#

high school

tame chasm
tame chasm
#

but its interesting

tardy mango
#

rlly?

#

seems like high school concepts to me

rapid trellis
tardy mango
tame chasm
vocal ibex
tardy mango
rapid trellis
tardy mango
tardy mango
#

I think I learned it when I was 15 or smt?

rapid trellis
#

Wow

vocal ibex
#

bro ur insane

#

did u take multi infreshmen year

rapid trellis
vocal ibex
rapid trellis
#

I love maths. I'm not deep into it

tame chasm
#

@vocal ibex the people in calc BC at our school learned partial fraction decomposition along with integrals

safe radishBOT
#

@vocal ibex Has your question been resolved?

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cursive slate
#

Math help with similar polygons

safe radishBOT
cursive slate
stray hinge
cursive slate
#

???

cursive slate
stray hinge
#

The ratio of their perimeters would be the same as the ratio of corresponding side lengths

cursive slate
#

And how do I get that

stray hinge
#

find the ratio of corresponding side lengths

cursive slate
#

I think it’s 21

tough briar
#

How did you get 21?

cursive slate
#

By doing a maths trick my teacher taught me

#

X/14 = 12/8

#

Then

#

8x=12 x 14/ 8

#

X=168/8

#

X=21

#

Wait

#

Whoops

#

I read the question wrong

cursive slate
#

Okay thanks

tough briar
cursive slate
#

Okay peace ✌️

#

.closw

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.closw

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.close

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pale zenith
#

I’m stuck on the concept, I know you need to convert them into ax + by = c, but I’m confused as to how the slope is calculated with this format as I always am used to y= Mx+b. Also, once converted, it gets more confusing as you need to somehow get the p value, which I’m confused about as well.

stray hinge
#

,rotate

flat frigateBOT
stray hinge
#

ok so first

#

when does a system of two linear equations have no solution?

#

in other words, in what case would two lines never intersect?

pale zenith
#

when they are parrale

#

parallel*

#

aka same slope, different y intercept

#

js confused about how I can notice that in this form, and after that, how I can figure out the P value.

stray hinge
#

since they didn't really give it in any specific form like standard form, it would be easiest to just manipulate the equation into a form you know

#

and then like you said same slopes so set the slopes to equal to each other which will create an equation where you solve for p

pale zenith
#

true, but I wanna understand standard form bc it’s probs gonna be on the SAT

pale zenith
stray hinge
#

yes

#

you can convert to standard form which is $Ax+By = C$

flat frigateBOT
#

Smiley ッ

stray hinge
#

which if you were to convert to slope intercept form

#

you get

#

$y = \frac{-A}{B}*x + \frac{C}{B}$

#

so if you do have standard form the slope would be -A/B

pale zenith
#

ohhh

#

-A being the (negative) coefficient of X, and B being the coefficnet of Y?

stray hinge
#

yes

#

if you have any doubts

#

there's no harm in just converting to slope intercept form

#

since it would only be two steps

flat frigateBOT
#

Smiley ッ

pale zenith
#

and what would I do once in slope intercept?

stray hinge
stray hinge
pale zenith
#

hmm

#

and then you set the slopes equal to eachother and see what number is needed to bring the lower one equivalents higher?

stray hinge
#

I'm not completely sure what you mean by the 2nd half, but we would set the slopes equal to each other to find the value of p for which the two lines are parallel

pale zenith
#

tysm

#

u helped me a lot bro

stray hinge
#

ofc, np

pale zenith
#

,close

#

.close

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#
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karmic stream
#

can anyone help me with part b onwards?

lilac crane
#

The bold 0 means neutral element, so an element such that a+0=a for any a. So you check if (a_1,a_2)+(0,0)=(a_1,a_2)

karmic stream
#

where should a be added?

safe radishBOT
#

@karmic stream Has your question been resolved?

opaque fern
flat frigateBOT
opaque fern
#

but you also know [
(u_1, u_2) + (v_1, v_2) = (u_1 + v_1 +1, u_2 + v_2 +1)
]

flat frigateBOT
opaque fern
#

try setting $(v_1, v_2) = \vb 0$. How does the above equation become?

flat frigateBOT
safe radishBOT
#

@karmic stream Has your question been resolved?

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signal notch
#

how to solve this problem

safe radishBOT
signal notch
#

<@&286206848099549185>

pine horizon
signal notch
#

next

#

i took sin2x as 2sinxcosx

pine horizon
#

(cosx + sinx)dx = dt

#

t^2 = (cosx-sinx)^2 => t^2 = sin^2x - 2sinxcosx + cos^2x => sin2x = 1 - t^2

signal notch
#

i did that but . i am getting wrong answer

safe radishBOT
#

Show your work, and if possible, explain where you are stuck.

signal notch
#

i will say cuz i dont have mobile

#

wait for 2min let me redo

signal notch
pine horizon
#

so 1 - sin2x = t^2 => sin2x = 1 - t^2

signal notch
#

ok ok i got it

#

i can continue after that . thanks

#

can i close

pine horizon
#

yeah

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lean otter
safe radishBOT
lean otter
#

having trouble not sure what to do with absolute value in integral