#help-23
1 messages ¡ Page 322 of 1
X is 18
the mark scheme?
thats impossible
u have missed calls from issac newtons
so u added two side on the numerator of left side... right?
RIGHT?!
U APPLY THAT FOR THE RIGHT SIDE
SOOOOO X + 6 / 6
X + 6 are NOT connected like y + y + 10
thats fine lol
Itâs not?
u just have to apply that
thats not how it works
if u add two side, u just have to add it
regardless of connectives
it doesnt need to be... but u added two side on the numerator of other side right?
u should apply that for x
ok ok so u added it because its a single line right?
it doesnt need to be a single line
Single side of a BIG triangle
im sry btw
$$\frac{\text{side of small triangle}}{\text{corresponding side of large triangle}} = \text{constant ratio} $$
Da pro
@odd nest id calculate it with the small triangle and the large triangle in the first place
8x = 120
120:8
15
Somehow chat gpt tells me x = 9
Can Anyone clarify ? <@&286206848099549185>
so im right?!
Now chat got now says itâs 5
chatgpt is dum
Whatâs the answer?
15
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â
just so you know, this problem is called the napkin ring problem
theres actually a rather counterintuitive formula for it, but you can derive it yourself
it helps to just consider the cross section of the sphere instead
the way i think of it is the volume of the sphere minus the hole
i honestly dont understand it at all
i get disk method and washer method but not this
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Can someone help me with congruency?
This is mainly just knowing how to interpret the symbols
If two angles are marked with the same (nonzero) number of arcs, then that means that theyâre congruent
Those arent marked with any arcs
Wdym arc?
So KL and JI?
The curve thing that the red arrow is pointing to
Is K and J not marked with arcs?
There are angles with vertices at those points that are marked if thatâs what you mean
Iâm still confused
If these names were supposed to refer to those angles, then the names are wrong
The vertex name goes in the middle
Isnt L and I not the vertex
Yea thatâs what I was referring to
??
The vertex is where the two rays that make the angle intersect
In the case of the top circled angle, the vertex is J (as both of the rays that make that angle extend from J)
Im horrible in math just excuse if I say anything dumb i thought the vertex was the thing that connected things between two lines so like L connections to K and M
i thought the vertex was the thing that connected things between two lines
A better (aka more rigorous) way to frame this is where the two lines/rays/segments that make the angle intersect is the vertex
Which is what I said here
Returning back to this example,
See how JH and JI are the sides of the arc
They meet at J
Hence J is the vertex
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part b
Could someone check where I went wrong???
here I think
i assumed, but idk what i did wrong there đ¤§
I'm not sure if a direct u substitution will work with the problem, you could trying multiplying the numerator and denominator with e^-x and then try
it's $\left(1 - \frac{e^t}{u}\right) dt$
MĂŚthIsAlwaysRight
you cant just cancel the e^t and replace dt with du
what does \left and \right do?
make brackets be an appropriate size
ooh
Skissue ping4response
huh đ
so yeah, this is the issue with your sub
in reality, it looks like this
there are parenthesis
we omit them by convention, but act like if they were there
so its taken as 1 term?
Also the constant 1 you've integrated should be in terms of t instead of u
ohh
Like when you distribute the dt, you could only covert the e^tdt to du but not with the 1
wait where?
The u/u they've cancelled
oh, ic, thats what i was saying
mm
oh lol
this is the answer btw
photon mentioned smth about multiplying by e^t
just curious
how do i recognise when to multiply by e^t?
Yeah multiply the denominator and numeraetor by e^-t
Practice
we were taught we either mutliply by "1/1" or "+-1"
when the integration is to complicated
Your approach isnt entirely wrong btw, I think that you could continue with that
Yeah seems like if you fixed few steps, your method should work fine
oo
okok lets get back this then
separating the term like this isnt wrong right? its just how i move on from there?
The motivation of muliplying the num and den was so we could subsitute e^-x-1 as as u then the integral would turn into a simple 1/u integral
oo
how can i do this?
and would that overcomplicate my solution?
nvm i think ill try this
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thanks!
Idk yet, i was trying it and I got pretty weird results for some reasons. ill try to figure it out
oh wait, nvm, i was looking at the answer key to b
the results i got were correct
basically at this poitn you can split the integral
integral of 1 is gonna be t
and integral of e^t / u dt is gonna be -ln(u) = -ln(1-e^t)
ooo
splitting the integral
never thought of that
so thats where the t came from
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!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
1
tell me what a_3 will be
(a_1)(a_2)
ok and what about a_4
(a_4) = (a_1)(a_2)(a_3)
substitue a_3 in this
so its just (a_3)(a_3)?
yup
now can you think of how to do this?
im thinkin 1 sec
since n > 2 lets take 3 for example so a_3 = t which means a_(3+2) is a_5 right?
and sincr we know a_5 = (a1)(a2)(a3)(a4) thats basically (a3)(a3)(a3)(a3) which is (a3)^4
and since a_n = t, then a_5 = t^4?
or does this not work
Wumpus Man
but if you used lets say n = 3, that would work? at some point you are getting a_(3-4) which is a_(-1) and how do a2 and a1 come into play here?
this is just a generalization
it just means you go from a_n all the way a_1 multiplying all the terms
for a_3 it will just be a_2 * a_1
a_4 = a_3 * a_2 * a_1
ok i see makes sense
$a{n+2} = a_(n+1) * a_n * a{n-1} * a{n-2} * a{n-3} ..... a_3 * a_2 * a_1$
Sven
damn didnt turn out right
$a{n+1} = a_n * a{n+1} * a{n-1} * a{n-2} * a{n-3} ..... a_3 * a_2 * a_1$
Sven
still doesnt work ok idk why its not coming out correctly
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how do you come to that answer??
$\log({a^b}) = b\log{a}\newline$
$\log({ab}) = \log{a} + \log{b}\newline$
$\log({a/b}) = \log{a} - \log{b}\newline$
Wumpus Man
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
a list of identites that will help you
lmaoo
i do know that i just get a different thing
one sec
okay no
am i supposed to solve it like the log isnât there
just w the numbers
or like
make separate logs
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heyo, im just confirming that this wants me to basicly carry out differantiation of "10 x -2^3 + 8 + -2^2 + 5"
no
could you explain then?
differentiating that would give you a 0
you are first supposed to differentiate it wrt x and then input x=-2
?
^
ih
oh
you ment with?
yep
whhat you are doing here is
finding the slope of the tangent of the curve 10 x^3 + 8x^2 + 5
at x= -2
*to the curve
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Can someone please help me understand this and also like if this data has a positive correlation to the 3 variables
I know that (r= .008 , p=.954 ) but which of the both do I base as closer to 1 ? the r or the p ?
<@&286206848099549185>
or maybe I'm thinking of it wrongly
I'm so lost...
:>
@pearl sphinx Has your question been resolved?
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a) Angle POQ = 1.75 rad
b) Length of PX = 4.7896cm
c) Area of shaded region = ???
I found area of segment QP
which is 6.128cm
squared
Maybe I can use triangle formula Half * r^2 * sin theta. But idk about theta here
Can you help with 5 (c) please
......
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How do u do this?
<@&286206848099549185>
@upbeat current Has your question been resolved?
im not familiar with this exact type but
i can try helping
a sinusoidal function would mean f(x) has sin function with some additional things attached
maximum value of a regular sine function is 1 & minimum is -1
so you need to change it in such a way that the maximum is 100 and minimum is 20
so something like f(x) = ksin(x) + c
and for a pt to be on the curve
$f(x)=a\sin{(bx)}+c, \text{where a is amplitude, b is frequency, and c is midline}$
whoops
Pt?
point (x,y) to be on curve, f(x) = y
Oh
pointt
yea ik
UrMom73
Alr
try finding the midline and amplitude first
the equation for period is 2Ď/b
so find a value for b that will result in a period of 30
b?
I use k but it doesn't matter
Period is 30
So 2pi/30
Which is pi/15
@noble frigate
Right?
yup
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Donut
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Hey,
A coin is tossed 8 times what is the probability that there are no 3 consecutive head or tails?
i solved it using combinatorics, but i want to solve it using only probability, i am thinking of using binomial distribution, but i am unsure of how to
@carmine latch Has your question been resolved?
any helpers 
@carmine latch Has your question been resolved?
could you use tree diagrams?
actually, 8 times would be difficult to draw
ok so to find the total number of outcomes, you do 2^8 which is 256. youre looking for every probability excluding "HHH" or "TTT"
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Hello please help Iâve been stuck for 2 hours on this
It looks really easy but for some reason I got stuck
I hate geometry
AC=BC so the big triangle has equal sides so the symetric of A is B where the axis is the perpendeicular line to AB passing by C then you can prove that the symmetric of the point of intersection of the circle of radius AD and the line AB is the the intersection of the cercle of the same radius wich is AD(=BE) and the line AB which is E so the symmetric of D is E so CDE is a triangle of equal sides so the angles are equal
there are other methods but i didnt know what lessons and theorems you can use
so i just wrote down any idea i got
Thanks a lot. Do you know how I could write that in a plain theorem sense for the proof?
Me tooâŚthe answer is so obvious but then to find a way to prove it lol
Algebra is way better
FOR REAL
can you use the symmetry theorems
Iâm not sureâŚthis module is supposed to just be about congruence I donât think weâve learned any symmetry theorems yet
Unless I just wasnât paying attention
lol
do you have the theorem that says 2 triangles that has 2 equal sides and equal angle between those side are equal or smthing like that
i think so i didnt study math in english so i dont know the names
Oh ok
Yeah like Side angle Side congruency right
I was trying to prove angle A is equal to angle B
But found my figure out how to prove that
Because if those two angles are equal then CPCTC right?
didnt understand that
CPCTCâŚyou know corresponding parts of congruent triangles are congruent
But how can I prove angle A is equal to angle B?
you have a triangle ABC where AC=BC
OHHHHHHHHHHHHHHH
conclusion its isosceles triangle
np
just focus and try to start with small conclusions dont look at the whole picture at one go
Okay, thanks for the advice
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Hey can I get some help with this one?
For some reason I feel like none of the answers are correct so I'm kinda stuck
<@&286206848099549185>
@weary sandal Has your question been resolved?
So my understanding of this is that we have something like this:
v0 ----------- v1
| |
| |
| |
v2 ----------- v3
I don't think the first one is right because the dot product also takes into account the lengths of the vectors ||a|| ||b|| cos(theat) . I don't think the second is correct because it takes into account the size of the paralellogram spanned by the vectors. I don't think the 3rd is right because the diagonals are not always perpendicular and I don't think the last is right due to the same problem as answer 2.
Am I missing something here? <@&286206848099549185>
@weary sandal Has your question been resolved?
Yeah, those all look wrong.
I'm pretty sure the second is the closest but one could be a scalar mult of the other right?
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vector equation
Vector equation, like the one with the parameter?
Or like some cross product equalling zero?
Do you know how cross products identify paralellity?
wait hold on
yes
are we not overthinking this
isn't the vec eqn form of a line just a point plus Îť Ă some vector?
oof
I think that's part 2
ah
Cause that uses a parameter
In any case, if you don't remember what the cross product does, it will be good for you to review it
so how do i approach these questions in general
when i was given a vector and a point
Forget the point for a moment. What vector equation using cross product can you write that describes vectors parallel to the given vector?
That's dot product
And oddly enough, we don't really care what the formula for cross product is. We care that the cross product of parallel vectors is zero
It is
so if its parallel it would be sin 0?
Yes
so for this question it should be a^2 * 2^2 + b^2 * 1^2 + c^2 * 3^2 = 0?
and i solve for a b and c?
oh wait
Again, you don't need any formulas for the cross product. You only need to understand that the cross product of parallel vectors is zero.
how can i solve for v
why are you trying to solve for v?
don't i need to find the vector equation
that is a vector equation
v x (2,1,3) = 0 is an equation of vectors
isn't vector equation r = a + lambda b
lambda is a parameter, so I think that's a parametric equation
but if you want that, you can write that in one step cause they give you a and b
I guess the parametric equations could be that equation you gave but pulled apart into its components
the words are a big ambiguous without the context of your lessons
if you want this, do you know how to find a and b?
lambda just lets you go any distance away from point a. b tells you the direction that you need to be going. What direction does the question tell you to go?
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if im not mistaken
we can rewrite $y = mx + b$ as [ \underbrace{\begin{pmatrix} x \ y \end{pmatrix}}{\vb x} = t\underbrace{\begin{pmatrix} 1 \ m \end{pmatrix}}{\vb v} + \underbrace{\begin{pmatrix} 0 \ b \end{pmatrix}}_{\vb x_0} ]
note that this is not the only form that $\vb v$ and $\vb x_0$ have to take
cloud
and you are correct that in both cases it shifts the line away from the origin
@dense wadi Has your question been resolved?
ill understand this in a few chapters hopefully LOL
anyway ty
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are v1 and v2 parallen to x_0?
Doesn't look parallel
Yes these two images look unrelated
the vectors v1 and v2 are parallel to the plane thru x_0
The vectors v1, v2, x_0 all share the origin as starting point. Ofc they wont be parallel
yeha i realized
If you draw the parallelogram law of vector addition on x = x_0 + t1v1, youd see the different values of t1 yield different vectors parallel to v1. Similarly for v2
ig the importance is they form a plane thats parallel to each other
and those vectors span the plane parallel to v1 and v2
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hello, undergraduate need help for an exam that's after 1 hour calculus derivatives
Do you understand what it is asking in part a?
and not know how to do it, or do you not know what it is asking at all?
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@karmic falcon !status
c isnt clear
didnt see ur massage
This also if you can
hmmm, wording this will be a bit awkward, the slopes can make there own graph and it is asking how that graph behaves (you can assess that with the equation of the slops of 1/a)
Guesstimate the slope and draw a tangent line at the given points on the graph
There is nothing you can do without the function being written out, unless you know how to get the function for those graphs
All it's asking is for you to draw the tangent line at that point
See in figure 3.3
The only one that has a slope that you can tell accurately is the p2 on 2
yeah, the red lines are tangent lines
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i know how to subsitutue it but i want to see how its graphed
take an x (e.g. -3), calculate y, draw a point, take the next x ....
Ah, yes. The "let's eyeball it" method.
But on a more serious note, a question like graphing is not something that you can ask over internet, because it depends more on your drawing skills. The best we can do is to tell you how to do it.
its 2 quadratic equations
how should i set it up to standard form
why do you need a standard form?
as i said. do this.
easier than typing a tons of questions in a discord channel? during the time i am typing all this messages i would have done this twice.
You'll still need at least some reference points to draw the graph accurately
I think it'll be more rewarding and better practice if you understand how the shapes of these graphs are affected by translations, stretches, etc. It will take you less time to draw them if you understand how the functions behave in general and are able to apply your knowledge of how these various transformations affect them. @deep imp For example x^2 - 16 is just a translation of the function f(x) = x^2 down by 16 units. If you know the shape of the graph, you should be able to draw it in a few seconds.
,w graph f(x) = x^2
what can you say about x^2 - 16?
correct
that's a good question and I'm glad you are no longer trying to find the easy method but the one that'll help you solve these types of problems in the future
so, what do you think?
downwards y axis
not a bad start
so, in general we say that $f(x - a)$ where $a$ is a constant $\in \mbb{R}$ will translate the graph of $f(x)$ $\emph{horizontally}$ by $a$ units to the right. If we have $f(x) - a$ then it will shift the graph of $f(x)$ to downwards by $a$ units (this is all provided that $a > 0$). So, let's take $f(x) = x^2$ as an example: if we have $h(x) = f(x-1) = (x - 1)^2$ and $g(x) = f(x) - 1 = x^2 - 1$, then which one will result in a horizontal shift and which one will result in a vertical shift?
maxim
nah I just realized that I used the same notation twice
hx is to the right
exactly
gx is to down
nice
good
and if you want to convince yourself that this is true you can plug in a few values into both functions and play around with them on Desmos, for example
so, back to your question
,w graph f(x) = x^2 for -9 \leq x \leq 9 \land -18 \leq y \leq 18
huh
yeah, i'll just use desmos to show you
i already tried using it earlier
im just confused about the setup
as in how do i show my work via table of values or whatever
ah okay, so have you done this type of stuff with linear equations and graphs of them?
yes
perfect
so with linear equations
you look at the intersection of the lines
it's the same with this
so you want to look at the points of intersection
so when $x^2 - 16 = -(x + 4)^2$
maxim
if you hover over the points of intersection on Desmos, you'll see that (0, -16), is, for example, a point of intersection. Can you find the other pair (x, y)?
-4,0
yup
so the two solutions are x = -4 and x = 0
and the ordered pair solutions are (0, -16) and (-4, 0)
for 0,-16 how do we get that because when i subsitute for x i get -4,0
do i plug -4,0 back into for x
and solvefor y
$0^2 - 16 = -(0 - 4)^2$
maxim
since $0^2 - 16 = -16$ and $-(-4)^2 = -16$
maxim
table of values?
my teacher wants 2 to the left and 2 to the right of a given point
perferably the intersections are within the 5
can you give me an example of what you need?
ah
okay so what you want to do is plug in values into both functions and fill the table up. The harder part is finding the y for each corresponding x. You can pick any value you like for x unless your teacher has specified what they want, but otherwise, it's just a matter of plugging things in
yo thank u for ur help @lean otter
u actually took time to bless me up for free
something tutors charge hella for
np np happy to help :D
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Continuing with this because it timed out
I have no idea how I'd go about constructing Jordan blocks
Is there some way I can do that
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Can anyone tell me if I did this good?
The image shows two congruent triangles. Calculate the length of x and y.
Please don't occupy multiple help channels.
Yes this is correct
Fr?
Are there two ways possible of calculating x?
Wdym 2?
You could have also used y/(y+10) but yours is better
Other than that I don't think
Method 1:
20/8 = x / 6
Method 2:
y+10 = x / 6
Yup
That is incorrect lol

and also
i put that
into chatgpt
and it told me the SAME answer as the other dude
good that i didnt fix that to theirs method
otherwise i wouldve gotten worse grade
don't trust chatgpt with mathematics
U can tell him to say that beforehand
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@red swan Has your question been resolved?
Lmao
@red swan is your doubt still there?
If not then I recommend closing this channel
!done
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Guys help me with solving this
Hint: Square - Areas you know
Hint 2: Write equations for square side length
I don't think we can create an equation for the side of square
Why
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were going over hypothesis testing
What is the population here?
I was thinking the population is just all people?
or all people who had their normal diastolic blood pressure measured
oh
wait the population is just the. Mexican American adults in that california town
and the sample is a small portion of them
But how do I test whether there is evidence to suggest that the mean blood pressure of the population differs from 120 without a confidence interval given?
is 120 the normal for all people or only mexican americcans
@somber cape Has your question been resolved?
Iâm not sure
Question doesnât specify any more than that
im guessing it's for all people and the population is mexican americans. if the sample mean is different from 120 then that's evidence. that's just my guess tho i haven't studied this stuff
@somber cape Has your question been resolved?
i believe 120 should be for all people (generally speaking), you don't know what blood pressure is average for mexican american adults in small california town (x), do you have reason to believe that (x) is significantly different from 120 given that you took a sample from that population
there should exist some formula out there for calculating significant difference between two means where one of the population sizes is unknown
this is AI generated so be careful, but it sounds reasonable enough:
id suggest confirming this with a reputable source
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could we not factorise it? how did we think of this substitution?
@south lynx Has your question been resolved?
Factorizing might work. What did you have in mind?
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â
I think factorisation should work yes but it makes it a little complicated? the substitution makes the problem a lot easier so I wondering how we thought of that
will respond in a minute, on the phone rn

no worries!
@south lynx i think you want to take advantage of difference of cubes. But I'm not sure yet
It can be factored. Every rational function with a limit can be found through factoring. But damn this one is hard
Okay i have an idea. Get rid of square roots on numerator by multiplying by its conjugate
i tried that
At the same time, get rid of cube roots on denominator by multiplying by its conjugate
but isn't that just rationalization
so you mean we don't simplify it first?
while multiplying by their conjugates?
oh wait lmao
wow
never mind yeah, you're right. i was originally supposed to rationalize it
we're taught that whenever you see 0/0 or infinity/infinity form, you rationalize/factorise/use l'hĂ´pital's rule
i mis-wrote (?) rationalization as factorisation
my original question still stands
why the substitution (more like how)?
there is no need to make a substitution
i get that. i was just wondering about the approach
x -> 2, if x = 2 + h, then it is equivalent to saying h -> 0
one makes this substitution because early on in calculus, one is taught to take h -> 0
so the substituion is essentially made so that people don't get scared by a limit not going to 0 and not using h for whatever reason
it shouldnt be necessary
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how do u find critical points
pLs help
Critical points are points where the derivative is 0 or undefined
graphically, flat graph or sharp turn.
what?
i thought i had to like derive gx
cuz that is fx and i tried 3 and 5 already
3, 5, 9 too
<@&286206848099549185>
what do i do
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@lean otter Has your question been resolved?
@lean otter you were on the right track when you put 3 and 5, I think you just forgot about your end points. 5 is one because g'(x)=0 at x=5, and 3 is one because g'(x) is undefined there. notice that x=7 is in the domain of g(x) but not in the domain of g'(x). just like 3, 7 is a critical number because g'(x) is undefined there
we all forget to check little things like that sometimes, hopefully that helps
ngl no clue where the 9 came from or the 5/2root7 that you mentioned earlier though, I can't figure out how you got there
thank u for responding omg that thought process came from g(x)= root f(x)
sorry I saw it so much later than you'd sent the question
thank u bro u saved my life
no problem
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how would you plug this equation into a calculator like this? whenever I try I end up with 13.99 when the answer is 0.262
you need to add parentheses around the numerator and denominator
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Are u able to partial fraction decompose this?
Technically? Yes. Is it disgusting and painful? Also yes.
,w partial fractions 4x^2 /(x*(x^4+16))
(hi im working with the person above) how did wolfram get to this answer? to decompose, dont you have to turn the denominator into at most repeated quadratic factors?
$x^4+16=0 \implies x=2e^{\frac{(2n+1) i \pi}{4}}, n=1,3,5,7$
Civil Service Pigeon
that's the roots of unity nuke
gotcha, makes sense
What type of mathematics is that wow?
complex numbers (specifically, roots of unity.)
we haven't learned it in our classes, so i'm saying no for it lol
calc?
đ¤ˇââď¸
Thanks, when do people usually learn this?
eh most ppl learn pfd in calc but it's all algebra in the end
idk
I think I learned it when I was 15 or smt?
Wow
I love your avatar
thx bro
I love maths. I'm not deep into it
@vocal ibex the people in calc BC at our school learned partial fraction decomposition along with integrals
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Math help with similar polygons
Same ratio as corresponding side lengths
???
What
The ratio of their perimeters would be the same as the ratio of corresponding side lengths
And how do I get that
find the ratio of corresponding side lengths
I think itâs 21
How did you get 21?
By doing a maths trick my teacher taught me
X/14 = 12/8
Then
8x=12 x 14/ 8
X=168/8
X=21
Wait
Whoops
I read the question wrong
Yep! 12:8 = 3:2
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Iâm stuck on the concept, I know you need to convert them into ax + by = c, but Iâm confused as to how the slope is calculated with this format as I always am used to y= Mx+b. Also, once converted, it gets more confusing as you need to somehow get the p value, which Iâm confused about as well.
,rotate
ok so first
when does a system of two linear equations have no solution?
in other words, in what case would two lines never intersect?
when they are parrale
parallel*
aka same slope, different y intercept
js confused about how I can notice that in this form, and after that, how I can figure out the P value.
since they didn't really give it in any specific form like standard form, it would be easiest to just manipulate the equation into a form you know
and then like you said same slopes so set the slopes to equal to each other which will create an equation where you solve for p
true, but I wanna understand standard form bc itâs probs gonna be on the SAT
but what are the slopes in this form? The coefficient of X, like in Mx+b?
Smiley ă
which if you were to convert to slope intercept form
you get
$y = \frac{-A}{B}*x + \frac{C}{B}$
so if you do have standard form the slope would be -A/B
yes
if you have any doubts
there's no harm in just converting to slope intercept form
since it would only be two steps
Smiley ă
and what would I do once in slope intercept?
btw I had a typo here but it doesn't change anything relating to slope
you get the slope explicitly stated
hmm
and then you set the slopes equal to eachother and see what number is needed to bring the lower one equivalents higher?
I'm not completely sure what you mean by the 2nd half, but we would set the slopes equal to each other to find the value of p for which the two lines are parallel
ofc, np
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can anyone help me with part b onwards?
The bold 0 means neutral element, so an element such that a+0=a for any a. So you check if (a_1,a_2)+(0,0)=(a_1,a_2)
where should a be added?
@karmic stream Has your question been resolved?
So in vector spaces, the additive identity $\vb v + \vb 0 = \vb v$ should hold
Aero
but you also know [
(u_1, u_2) + (v_1, v_2) = (u_1 + v_1 +1, u_2 + v_2 +1)
]
Aero
try setting $(v_1, v_2) = \vb 0$. How does the above equation become?
Aero
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how to solve this problem
<@&286206848099549185>
sinx - cosx = t
(cosx + sinx)dx = dt
t^2 = (cosx-sinx)^2 => t^2 = sin^2x - 2sinxcosx + cos^2x => sin2x = 1 - t^2
i did that but . i am getting wrong answer
Show your work, and if possible, explain where you are stuck.
cos^2 x + sin ^2 x - 2sinxcosx => 1 - 2sinxcosx ..... how 2 sinxcox be t^2 ..
2sinxcosx = sin2x
so 1 - sin2x = t^2 => sin2x = 1 - t^2
yeah
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having trouble not sure what to do with absolute value in integral
