help-23

[slow mesa]

I don't know if it's correct

and now i'm kinda stuck

[slow mesa]

.close

[safe radish]

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[safe radish]

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[crude star]

how is $n \bar{x} \bar{y}$ = 2476 here?

[flat frigate]

Worth

[crude star]

shouldnt it be $n \bar{x} \bar{y} = 10 \frac{460}{10} \frac{760}{10}$

[flat frigate]

Worth

[crude star]

which is way bigger thn 2476

[safe radish]

@crude star Has your question been resolved?

[crude star]

https://tenor.com/view/you-are-driving-me-crazy-headbang-against-the-wall-gif-13855136

<@&286206848099549185>

[safe radish]

@crude star Has your question been resolved?

[safe radish]

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[feral thicket]

Anyone can explain how to graph 5 b and Q6

[feral thicket]

Also for Q5 a

I’m assuming this is correct

Nvm i got it

@shy beacon can u check q5 a tho

That’s correct right

[shy beacon]

Your first answer?yeah it seems right to me

[feral thicket]

Yeah thanks

.close

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[feral thicket]

How of close

Oh

[safe radish]

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[next olive]

i need help with zis question

[next olive]

hello uh, im stuck at collecting like problems which i think i got until i got to THIS question i know the -4 one is 3 -n and I DONT know how, but the answer sheet said 1 and unlike some people i want to actually know how to get 1 ive been stuck at this for HOURS

thata

and i really am confused on how like problems work at all!!

[austere cypress]

i'm not sure i understand what you're saying

what do you mean by "-4 is 3 - n"?

[next olive]

thats what i got

for the question before 3n + 3 and 2n^2

im confused abt how do you get 1 from 3n + 3 + 2n squared 2

how would you BE able to subtract THAT

[delicate sphinx]

Can you show the original problem?

It doesn't make sense because you have two different variables

[next olive]

its this image

[delicate sphinx]

Without the writing on it

[delicate sphinx]

.

[next olive]

genuinely confused

[haughty anchor]

you have an x over the N

[next olive]

my bad

but yes i got the first one right specifically

but the one 3n

[delicate sphinx]

Show your answer key too

[next olive]

• 3 + 2n^2

alr

[haughty anchor]

are you just simplifying?

[next olive]

i think so,

i dont know how to get the 1 though

[delicate sphinx]

Show your answer key

[next olive]

getting it

[delicate sphinx]

It does not make sense that it's 1

[haughty anchor]

collect your terms first

constants: -4 +3
terms of n: -3n
terms of n^2: -2n^2 + 2n^2

awsner: -1-3n

[safe radish]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[haughty anchor]

oh my bad

[next olive]

i outlined it

cause its too blurry

[delicate sphinx]

That does not say 1

That says -3n - 1

[next olive]

so howd you get 1

in that equation

WAIT

[delicate sphinx]

You said that

[next olive]

i think you got it wrong

i think its my bad as well

i meant to be as

the first one before 3n + 3 + 2n^2 is a seperate simplified polynomial or whatever

im stuck at the 2nd one

how would you subtract

if you had like

only plus's

and squared

is there anything im missing

[delicate sphinx]

You literally said the answer was 1 here, that does not say 1 in your image

[delicate sphinx]

You group the like terms

Reorganize the terms

[next olive]

alrighty

after grouping the terms

how would i simplify them

or something

to get 1

[delicate sphinx]

What do you get when you regroup the terms?

What does it look like?

[next olive]

..oh my gosh

[delicate sphinx]

Where are you getting 1 from?

The answer key doesn't even say 1

[next olive]

but it does

[delicate sphinx]

That says -3n - 1

Where does it say 1?

[next olive]

Right there

• 1

[delicate sphinx]

That's - 1

[next olive]

Wait

What's the difference

Can you explain

[delicate sphinx]

-1 and 1 is not the same

[next olive]

OH

OHH

I meant - 1

How'd you get -1

[delicate sphinx]

Did you group the terms?

What does it look like when you do that?

[next olive]

Well minda

I do it in my mind

[delicate sphinx]

That's not what I'm asking

If you're having trouble doing it in your mind, you should do it on paper instead

[next olive]

I know that the 2x^2 and 2x^2 r the same

And are like terms

[delicate sphinx]

Where did the x come from?

[next olive]

WAIT

Wrong question

I keep relooking at the wrong question at the page

I know that 3n and 3 are the same and I was thinking there like terms

But I genuinely don't get how to group them together, like the last question I did

[delicate sphinx]

No those are not like terms

[next olive]

Can you explain

[delicate sphinx]

Like terms are terms that are the same variable and the same power

3n and 3 are not like terms because 3n has an n while 3 does not

[next olive]

Ohh

So which ones can be grouped?

[delicate sphinx]

.

[next olive]

i cant tell

which one can be grouped

thats what i meant

[delicate sphinx]

You have -4 -2n^2 - 3n + 3 + 2n^2

Group the terms that have the same variable and the same power

[next olive]

alright

would i put the terms

without similar variables/same variables

and power

its own group

[austere cypress]

it's a group with one element

[delicate sphinx]

You can just separate those, it's not going to be its own group. You're just grouping like terms, you're overthinking this

Start with -4, what terms are considered like terms with that?

[next olive]

uhhh

3?

[delicate sphinx]

https://www.youtube.com/watch?v=eNv4fHb7OvU&ab_channel=MathwithMr.J
If you're having trouble I suggest watching something like this

[next olive]

alr

thanks

thanks for your help

.close

[safe radish]

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[safe radish]

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[tardy violet]

Hi how do you do part iii

[frank horizon]

plug in theta=pi/8

and use the factorization you got in ii to solve for cos theta

[austere belfry]

yes

[tardy violet]

into the equation in part i?

[frank horizon]

right

[vagrant ice]

the idea is that if you sub theta = pi/8, then because x = cos theta
x = cos(pi/8)

so cos(pi/8) is one of the solutions of 8x^4 - 8x^2 + 1 = 0

now the question is: which one though?

well you are finding cos of an angle in the 1st quadrant, so it has to be positive

great, that eliminates two of the negative solutions

now you also need to realise that cos(pi/8) > cos(pi/4) = 1/sqrt(2)

that gives you the only value that works

[vagrant ice]

try to pause here and consider the shape of cos(x) between x = 0 and x = pi
what happens to the y-values as you increase x?

[tardy violet]

sorry i dont get this bit, why does this matter?

[vagrant ice]

part ii has 4 real roots

by only considering the positive roots, that reduces it to 2 possible values of cos(pi/8)

you need to eliminate one more root to find the unique candidate of cos(pi/8)

[tardy violet]

ohh right

[tardy violet]

decreases

[vagrant ice]

cool

so the value of cos(pi/4) must be less than cos(pi/8)

but we know that cos(pi/4) = 1/sqrt(2) already

[tardy violet]

so the value has to be more than 1/sqrt(2)?

[vagrant ice]

mhm!

that's enough info to figure out the unique value

[tardy violet]

that makes a lot of sense thank you!

[vagrant ice]

no worries!

[tardy violet]

.close

[safe radish]

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[safe radish]

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[neon ginkgo]

can sm1 help me with geometry i have been sleeping for the whole time in class can sm1 sed me the curriculum i have 10 hours left to study

[vagrant ice]

there is no singular curriculum for geometry

if you really want to use your time well, practice on Khan Academy

also you should find out what you are going to be tested on
email your teacher for a list of topics

I swear you or someone else has posted the exact same question

[kind tinsel]

you might fail the exam. that’s on you for sleeping through it. for what it’s worth though, the exam will probably not matter in the grand scheme of things, so your life will not be too drastically affected by it.

[neon ginkgo]

its 11pm my test is at 9

what should i need to review everything

[humble fossil]

well..

ig that’s what u get for sleeping !! do u even know any geometry contents

[vagrant ice]

you should spend at least 7 hours sleeping otherwise what you know will fly out the window

a lack of sleep makes you forget things you already know

[vagrant ice]

as I said Khan Academy

https://www.khanacademy.org/math/geometry-home

[neon ginkgo]

i just review everything?

[vagrant ice]

well I mean you shouldn't think about your upcoming test, moreso how you can improve in the next few months or year

[neon ginkgo]

u mean few hours

[vagrant ice]

you would know what to review if you weren't sleeping in class

if you can sleep in class and know what topics you've covered each lesson

great

[mossy lotus]

wdym lack of sleep? did you not read what he said? He has so much sleep in store already

[vagrant ice]

but it doesn't sound like that

[mossy lotus]

I hate my internet

so much delay

[neon ginkgo]

it wasnt my sleep much it was also a lack of chapters my teacher didnt cover

[vagrant ice]

or as I said you could email your teacher
your teacher just might not reply to you, oh well, at least you should try

[neon ginkgo]

my teacher is dead asleep

and hasnt sent any emails we had a real teacher for 5 months so we didnt get to cover all chapters

what shouldi be focusing on

[humble fossil]

Did he not say the topic of the test

wait

u were asleep..

[neon ginkgo]

i slept for the last review of class

[humble fossil]

and any time before that??

[delicate sphinx]

That's on you

[neon ginkgo]

its all the topics

[humble fossil]

boy the first semester is almost over wdym all the topics

[neon ginkgo]

ahhh tbh i just wanted to get it over the way cause its to ez

[delicate sphinx]

If it's "to ez", then you don't need to study

[vagrant ice]

I mean if you are fine with sleeping in class and bombing your test, it's not our job to make you care about school

[neon ginkgo]

that was a lie

[vagrant ice]

or if you can somehow ace your test (real, happens to a lot of gifted students, and then they realise they don't know how to study)

(when something slightly exceeds their skill level)

[neon ginkgo]

i just want to finish studying geometry cause i have to study for another course

[vagrant ice]

I see

just a warning, what you didn't learn previously in maths may come back to bite you

actually will, if you study enough maths at a high enough level

[neon ginkgo]

proving congruence

[vagrant ice]

we're talking algebra 1/2, precalc, and calculus

[vagrant ice]

okay that's like not too useful for later maths

until you do proofs at uni

[neon ginkgo]

im taking algebra 2 over the summer

[vagrant ice]

you'd be surprised at how many questions have hidden circle theorems in high school though

like it will be coordinate geometry, or look like it

[neon ginkgo]

so i have 1/2 of the year t study geometry then the other half for algebra 2

[delicate sphinx]

You know, you just spent 20 minutes here when you could have been studying

[vagrant ice]

and you'll need angle at the centre is 2x that on the circumference

[neon ginkgo]

maybe cause i was asking for help

[humble fossil]

boy just study the triangle congruence theorems

[vagrant ice]

do you not even know ppl from class who might know the syllabus?

(someone in hlounge said this)

[neon ginkgo]

oh

[vagrant ice]

great go away and do that

[neon ginkgo]

i have the syllabus there are alot of lessons that are missing which caused to fail a test

[vagrant ice]

...

[neon ginkgo]

her

here

u see dividing line segments is missing

[vagrant ice]

probably in a previous year's syllabus

hey, maths builds on what you've learned before

[neon ginkgo]

this is a question from what im taslking abt

The coordinates of the endpoints of
AB
are A(3,1) and B(19,9). Point C is on
AB
and divides it such that AC:BC is 3:5.
What are the coordinates of C?

she never taught that and i got a 59 percent on my test

[humble fossil]

go to mrmathblog.com

has all the lessons and videos for geo

[neon ginkgo]

bro..

[humble fossil]

take ur chances

[neon ginkgo]

im playing clash royale gimme a ec

sec

[gleaming hawk]

.-.

[humble fossil]

Ykw..

[neon ginkgo]

dont make me lose

im losing flip

[humble fossil]

bitch get off the phone

or the game

[neon ginkgo]

hahahaha' i won

i got a 59 but the average is a 40

[gleaming hawk]

[neon ginkgo]

so i failed but

....

ok lemme get off my phone

anyone play cr?

nvm

[languid quest]

Yes but wrong place to talk about it

[neon ginkgo]

im masters 1 ok lemme study i also donh have gw for any class

[vagrant ice]

the concept is that you want to divide 3 and 19 in the ratio 3:5

so 19 - 3 = 16 which is 3 + 5 = 8 parts
1 part = 2
so you have x-coordinate is 3 + 3 parts = 3 + 3 * 2 = 9

similarly, 9 - 1 = 8 is 8 parts
y = 1 + 3 parts = 1 + 3 * 1 = 4

[delicate sphinx]

35 minutes now

[neon ginkgo]

ik how to do it

but i learned it on my own

[gleaming hawk]

Bro then what do you want .-.

What should we tell you

What do you want us to say

[neon ginkgo]

tbh i want a hard math problem ima try and solve

anyone have algebra 2 lesson plan?

[vagrant ice]

lmao.......

[neon ginkgo]

i have a whole week off

[gleaming hawk]

.-.

I genuinely don't know what he is talking about

[humble fossil]

Ur gonna take geometry instead of algebra 2 in the summer if u don’t raise that grade up tf

[neon ginkgo]

i have 4.0

[humble fossil]

and also who takes alg 2 in the summer

[neon ginkgo]

me

[humble fossil]

disgusting

[neon ginkgo]

im taking it for fun ig

[humble fossil]

hope u suffer <33

[languid quest]

Don’t be elitist

[vagrant ice]

do you need our help or do you not need our help right now

[neon ginkgo]

yeah

how do i find the circumfrence of a circle

im stuck

[vagrant ice]

are you trolling us

[neon ginkgo]

nah

[delicate sphinx]

Google the formula

[gleaming hawk]

Circumference of circle

Are you on heroine?

[neon ginkgo]

no im on fent and cocaine

whats the hardest part of geometry?\

chess 1v1?

[languid quest]

Acclimating to radians

[neon ginkgo]

u guys know a mock test i can take?

[neon ginkgo]

so i can have ap pre cal

im so close to masters 2 with royale recruits drill

[gleaming hawk]

<@&268886789983436800>

[versed wave]

what??

[hard crest]

.close

[safe radish]

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[eager garden]

anyone can help me with this

[humble fossil]

what’s with the ln

wait

I see it now

[eager garden]

yes

[humble fossil]

did u try putting parentheses around the absolute value signs

[eager garden]

it didnt work

[humble fossil]

Interesting

there’s no space between the 1/9 and ln right

[eager garden]

no

no there are not any spaces

[humble fossil]

okay weird

it’s all correct

[eager garden]

hmm

[humble fossil]

maybe do absolute value on the outside and parentheses in the inside

like ln |sin(9x)|

[safe radish]

@eager garden Has your question been resolved?

[safe radish]

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[deft sparrow]

i nida some help. I got ''0'', thats ok?

[empty gyro]

Yes

Hmm

Actually I'm not 100% certain

Zero feels right but I'm not certain

[eager plover]

Lemme see

It would help if I could see your work

[gusty trench]

since the thing looks like 0 / 0, just lhopitals and apply FTC

denominator becomes 3x^2, numerator becomes (integral from 1 to x of ue^-u du)^2 * e^(integral from 1 to x of ue^-u du) * d/dx (integral from 1 to x of ue^-u du) = (integral from 1 to x of ue^-u du)^2 * e^(integral from 1 to x of ue^-u du) * xe^-x from FTC

as x goes to 1, the denominator goes to 3, and the numerator goes to 0 since the integrals collapse

[eager plover]

Just because it looks like 0/0 doesn’t justify using lhopitals. You need to prove that it is 0/0

Can’t just go off of vibes to use lhopitals yk?

[gusty trench]

proof: integral's upper bound is an integral from 1 to 1 and is therefore 0, then the numerator integral becomes an integral from 0 to 0 and is therefore 0. the denominator becomes 1^3 - 1 which is 0

there's your 0 / 0

you only need it to be 0 / 0 after direct substitution

[zinc berry]

To be intentionally annoying, a typical calculus class doesn't teach the continuity of a functions like f(x) = int_a^x g(t)dt to evaluate a limit like that, but a regular course would not ask something like this to begin with

[gusty trench]

also just evaluated the thing with wolfram, it also gives 0 lol

[deft sparrow]

I got a similar idea. After all, that was correct

[deft sparrow]

the teacher was something crazy

National University of San Marcos

[eager plover]

Perfect that’s all I needed to hear

[eager plover]

Omg this is calculus in Spanish- I’d cry

[deft sparrow]

Thanks to everyone, this group is very active

[deft sparrow]

yeah, im from Peru

jeje

[safe radish]

@deft sparrow Has your question been resolved?

[safe radish]

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[livid igloo]

guys can someone help me in mathematics olympiad quiz

[livid igloo]

.close

[safe radish]

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[stray hinge]

rip

[livid igloo]

can you help

[split ether]

Why did you close the channel if you are still looking for help?

[safe radish]

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[burnt grail]

where did i go wrong for q3

[burnt grail]

the gave 180 degrees and 223 degrees 8 minutes as solutions

but i got 284 degrees 2 minutes

please ping me if you can help me

[safe radish]

@burnt grail Has your question been resolved?

[burnt grail]

.close

[safe radish]

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[wheat gyro]

can anyone help me with c

[wheat gyro]

.close

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[astral helm]

1. A paper in the shape of triangle ABC is cut along the line segments [AK] and [BK] as shown in Figure 1, and it separates into two pieces as shown in Figure 2. Point K is the center of the inscribed circle of triangle ABC.

The sum of the perimeters of the pieces in Figure 2 is 28 units more than the perimeter of triangle ABC.

Given that 4|AK| = 3|KB|, what is the sum of possible integer values that the length of side AB can take?

A) 33 B) 35 C) 36 D) 37 E) 46

[astral helm]

please help :D

[safe radish]

@astral helm Has your question been resolved?

[safe radish]

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[sweet gyro]

ive been stuck on this question for 2 days idk how ill go about solving it

[obsidian oracle]

You can maybe start by finding the surface area before the columns are removed
Afterwards, when the columns are removed, how does each column affect the surface area

[safe radish]

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[slim lion]

bro

what question

[hollow grotto]

A

[slim lion]

just sub in x = 0

e^5(0) - 7e^5(0) + 8
= 1 - 7 + 8

= 2

[hollow grotto]

Omg tyu

[slim lion]

ok but can u do B?

have u learnt l'hopitals rule

[hollow grotto]

I just fail my exam I just wanna came back and review it

[hollow grotto]

No I'm still new

[slim lion]

no but did u learn it in class

[hollow grotto]

Yes the teacher gave us a few formula

[slim lion]

https://www.khanacademy.org/math/calculus-1/cs1-limits-and-continuity/cs1-limits-by-direct-substitution/v/limit-by-substitution
just do this

all the limit ones here

they help

[hollow grotto]

Oke oke ty!!

[slim lion]

finish the whole module

oh wait nono

this one

https://www.khanacademy.org/math/calculus-1/cs1-limits-and-continuity/cs1-limits-using-algebraic-manipulation/v/limit-example-1

[hollow grotto]

Okay okay imma check it out and trying to redo it

Tysm!!

[safe radish]

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@modern bloom Has your question been resolved?

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[harsh field]

Exercise that another group got for the midterm exam, I am trying to solve it but I think that I am misunderstanding the question and I don't know how to solve it the right way

[harsh field]

I took a=6

And I tried to prove that these 2 are bases for the same subspace of R³

But I got different subspaces

For each base

[safe radish]

@harsh field Has your question been resolved?

[vagrant ice]

well, (3, -3, 6)^t = 3 * (1, -1, 2)^t

now you just need to show there exist nonzero m, n such that m(1, 0, a) + n(1, -1, 2) = (3, -2, 4 + a)

then any linear combination of vectors in S1 will be a linear combination of vectors in S2, and vice versa

[harsh field]

Ohhh

What I tried to do was

[vagrant ice]

,w m + n = 3, -n = -2

[flat frigate]

Results provided by WolframAlpha

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Upgrade to WolframAlpha Pro!

Requested by sooouth.

[vagrant ice]

ah yes and then 1 * a + 2 * 2 = 4 + a checks out

[harsh field]

Determine the base from the linear combination equal to a vector with random values

I see now

What about the dimension then?

[vagrant ice]

since they span the same subspace the dimension of V should just be 2

cause the dimension of S1 and S2 is just 2, 2 linearly independent vectors

[harsh field]

Makes sense

Thanks I was having some trouble figuring it out

[vagrant ice]

as in you're not adding any new lin indep vectors when you take the union of S1 and S2

it's literally the same subspace

[harsh field]

Yep

[vagrant ice]

cool nw

[harsh field]

Have a nice one

[vagrant ice]

you too!

[harsh field]

.close

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[fair obsidian]

how to solve limx->0+ (lnx)^x ?

[vagrant ice]

isn't that undefined

Desmos says it equals 1 though

[safe radish]

@fair obsidian Has your question been resolved?

[fair obsidian]

yeah apparently it's not

someone said you have to use principal form of something

[vagrant ice]

cause if L is the limit, then ln L would be the limit of x ln(ln x)

[fair obsidian]

thing is that it works if you e^ln(f(x)) with the absolute value of f(x)

[vagrant ice]

but that's not defined for 0 < x < 1

[vagrant ice]

ah interesting go try that then

[fair obsidian]

yeah but usually it should not be absolute value

actually I don't know

[safe radish]

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[safe radish]

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[magic plover]

.close

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[safe radish]

@wintry elm Has your question been resolved?

[wintry elm]

<@&286206848099549185>

is that the role i ping

😭

[devout scroll]

do you know similarity?

Basically ABC similat to ADB

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[opaque fern]

how do i compute the limit
$$
\lim_{t\to-\infty}\left[e^{-t(i\omega-3)}(\cos(2t) + \frac{1}{2}\sin(2t))\right]
$$

[flat frigate]

Aero

[opaque fern]

i is the imaginary number

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[tight hill]

Hi, can anyone explain how this works? I don't understand how the PDF in question could be derived from the PDF of Weibull

[tight hill]

isnt it like missing the square root of pi?? does it not matter?

I'm even more lost with deriving it from the PDF of Gamma. How would that work?

with this being the PDF of Gamma

Getting even more confused on the Weibull one because jotting a two down right there wouldnt make sense? since we'd want that to be x^2?? or am i just understanding this wrong

[desert juniper]

okay, on weibull's:
everywhere that you see a gamma, put a 2

everywhere that you see beta, put beta squared

[tight hill]

what about the pi then? in the original equation

[desert juniper]

it doesnt have to be the exact same equation

it's just telling you to use that specific weibull pdf

[tight hill]

i dont really understand how this ends up showing that its a valid PDF

i thought i was supposed to show it integrated to 1 by making it show similarities to the Weibull pdf? or am i thinking about this wrong

[safe radish]

@tight hill Has your question been resolved?

[tight hill]

<@&286206848099549185>

[pallid crystal]

@tight hill hello morgana

[tight hill]

LMAO hi

fatamoru lives on

[pallid crystal]

i think your weibull pdf is wrong

there should be ^\gamma on the betas

use this definition

then to show your pdf is value

u need to find int_{x > 0} f(x) = 1

thats the same as the weibull with extra x

therefore you are finding E(c*X) for X ~ weibull

plug in the parameters and ull see it is indeed 1

[tight hill]

how should i tackle a problem like this if i encounter it in the future?? because i couldnt really immediately see its relation to weibulls pdf

[pallid crystal]

its hard

but clearly its impossible to integrate

so you try to think of possible distributions

standard ones: normal, exp

you'd first try exp here cuz bound x > 0

then maybe pareto, gamma

honestly i dont remember weibull

maybe gamma is easier here

[tight hill]

we get a sheet of most distributions on a sheet, we just have to make the connection during the actual exam but i'm so bad at making that connection 😭

[tight hill]

how would i compare it to gamma? like what parameters would i use??

[pallid crystal]

in your f(x)

sub y = x^2

then y >=0 is still fine

now it looks more like gamma

match parameters

[tight hill]

I think I'll just let this be for today and look over it tomorrow 😭 Thank you for your help, though!!

.close

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[tiny vault]

need help with simplifying algebraic fractions, i cant figure this out at all

[tiny vault]

on the other problems ive just been finding what they have in common but i cant find it for this one so im lost

[delicate sphinx]

Start with the numerator

What do they have in common, between 8xy and -12x

[tiny vault]

4x

?

[delicate sphinx]

Yes

So when you factor that out, what you do get?

[tiny vault]

4x(2y - 3) ?

[delicate sphinx]

Yes

Do the same with the denominator

[tiny vault]

3y(2y-3) ?

[delicate sphinx]

Yes

So what is the fraction that you have now, after you factored the numerator and denominator?

[tiny vault]

4x(2y - 3) / 3y(2y-3)

OMG

woah

[delicate sphinx]

Do you see anything that could be canceled out?

[tiny vault]

yes the parantheses

things

so now theres 4x/3y?

[delicate sphinx]

Yes

[tiny vault]

but question

what do i do in cases where they dont have anything in common

can i simplify it then through factorization

[delicate sphinx]

If you can factor it, yes

[tiny vault]

ohh oki

tysmm i appreciate it sm

have a nice day

.close

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[snow stag]

how do I split it up if I have three exponents with n

[severe pond]

wdym split it up

[snow stag]

so i got this

[severe pond]

yea you’ve just rewritten one part

if this helps then by all means

but now you need to use the ratio test

[snow stag]

yeah but how

normally we would just elimnate the n

but I would still have a n left over

[still charm]

use the fact that exponents distribute over multiplication

for instance

3^5 x 7^5 = (3 x 7)^5

[snow stag]

nvm

I see

[severe pond]

🤝🏻

[snow stag]

it wasnt rocket science

just got thrown off by the third one

thanks though

.close

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[severe pond]

yep

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[unkempt thicket]

What am I supposed to do here

[unkempt thicket]

I don’t understand anything🥲

[lime dust]

Do you know Newton Method?

[unkempt thicket]

Nope

[lime dust]

Then it is gonna be hard to do it

[unkempt thicket]

What does x1 2 and 3 mean

Or 0

[lime dust]

You have to study first the method

[unkempt thicket]

I’m trying I don’t get it

[lime dust]

https://en.m.wikipedia.org/wiki/Newton's_method

[desert juniper]

x1, x2 and x3 are the first three steps of newton's method

[unkempt thicket]

Oh they are the 0’s?

[desert juniper]

no

[unkempt thicket]

Then I don’t get it

[desert juniper]

You have a function. You want to obtain its roots.

[unkempt thicket]

Roots is 0’s

[lime dust]

Because you need to read first the definitions

[unkempt thicket]

From what I know

[desert juniper]

Newton's method allows you to get an approximate value of those roots, by iteration

[unkempt thicket]

It says it there too

[lime dust]

You cant start the house from the… whatever is called in the top xD

[desert juniper]

in theory, each iteration gets you closer to the root

[unkempt thicket]

Ohh

[desert juniper]

assuming the function behaves well, and that you have selected a sensible starting point

[unkempt thicket]

You have one root but each calculation gets you closer and closer to the actual answer?

[desert juniper]

yes

[unkempt thicket]

I see

And the calculation is the function divided by its derivative?

[desert juniper]

not exactly

The steps are as follows:
a) Select starting point. You're given x0=3
b) Compute the tangent line to the function at the point.
c) Compute the zero of that tangent line. This will be your next point, x1.
d) Repeat a,b and c until you get close enough

[unkempt thicket]

Computing the tangent line is taking the derivative then plugging 3 right?

[desert juniper]

no

[unkempt thicket]

So 2(3)

Bruh

Then idk🥲

You said compute at that point

[desert juniper]

the derivative at 3 would be the slope of the tangent line, not the tangent line itself

but there's an unlimited number of lines that have that slope

[unkempt thicket]

I thought the slope is the tangent line

[desert juniper]

no

there's exactly one line that has that slope and also goes through the point

[unkempt thicket]

How do you calculate that

[desert juniper]

im gonna use an easy example.
Say you have the function y=x^2

[unkempt thicket]

The others are secent lines

[desert juniper]

i want the tangent line at x=1

i need the derivative of the function. y'=2x

the function itself gives me that for x=1, then y=1

the derivative gives me that for x=1, the slope of the tangent is 2

so i need the line that has slope 2, and goes through the point (1, 1)

[unkempt thicket]

Oh so you need to plug in y and x

[desert juniper]

so the tangent line would be 2x-1

[unkempt thicket]

Ohh they want the function

Like mx+b

[desert juniper]

yes

[unkempt thicket]

Ohh okay I see

[desert juniper]

now, you can compute when that tangent line is 0

[unkempt thicket]

Lemme try

[desert juniper]

which in this example, will be at 1/2

so your new starting point, x1, will be x1=1/2

now do it for your function

[unkempt thicket]

y=2x derivative
Y=3^2-2
9-2
Y=7

I forgot how to calculate x

I thought you plug it in the derivative anyway

To find m

Oh wait x is given bruh

But to find m you gotta plug x no?

2(3)

Then
x=3
y=7
m=6

y-7=6(x-3)

y-7=6x-18
y=6x-18+7

y=6x-11

[desert juniper]

and what is the intersection of that line with X axis?

[unkempt thicket]

What does that mean

[desert juniper]

at which x-value is y equal to 0?

[unkempt thicket]

6x-11=0
6x=11
x=11/6

?

[desert juniper]

so you got your first value, x1

now repeat the procedure to get x2

[unkempt thicket]

Where is the part where you do the function over derivative

That i saw in that website

[desert juniper]

?

[unkempt thicket]

These formulas

[desert juniper]

that's the same as you got

[unkempt thicket]

How so?

[desert juniper]

x0=3
f(3)=7
f'(3)=6
x1=3-(7/6)=11/6

[unkempt thicket]

Ohh

What’s the point of this formula then

[desert juniper]

i showed you the whole procedure. The formula is a shortcut

[unkempt thicket]

If you have to find all the information anyway it doesn’t really look like a shortcut

You just use this formula instead of y-y1=m(x-x1)

[desert juniper]

well, it allows you to not get the actual equation of the line, so you save that bit

[unkempt thicket]

Ohh cuz you don’t need to equal it to 0

[desert juniper]

you now have x1. Repeat the procedure for x2, and again for x3

[unkempt thicket]

The professor is so useless he could have simply introduced the topic by saying “this is another method to finding this” and no one would have been confused

[desert juniper]

¯_(ツ)_/¯

[unkempt thicket]

Tf

Do I flip it and multiply

I got this

.close

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[lyric belfry]

This isn't diagonalizable. how on earth can we solve this then?

[lyric belfry]

the hint tells me to look at this for inspiration but it honestly feels like they just pulled this out of thin air

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@lyric belfry Has your question been resolved?

[lyric belfry]

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[ruby crest]

@meager igloo Can anyone help me make the graph of this question i am getting confused.
And also should i use the COSINE rule?

[safe radish]

@ruby crest Has your question been resolved?

[ruby crest]

<@&286206848099549185>

[safe radish]

@ruby crest Has your question been resolved?

[lean otter]

yes

by cosine rule i suppose you mean $f_1^2+f_2^2+2f_1 f_2 cos(\theta)$ where $\theta$ is the angle between $f_1 and f_2$

[safe radish]

@ruby crest Has your question been resolved?

[ruby crest]

Yea

Can you draw me the graph?

[lean otter]

try drawing it yourself and then check it with this

[safe radish]

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[wooden moon]

can someone please check if i found the maximum flow and so the minimum cut capacity correct? I found it as 9 but in some parts i had hesitation which i dont have answers to.

[buoyant shadow]

it's not 9, i can see 10

[wooden moon]

from where to where

[wooden moon]

okay so one augmenting path is s, a, d, g, t

another one is s, c, f, t

or did you go with another sequence?

[buoyant shadow]

i don't know waht it means

i just see 10

maybe it's not maximal

actually 11

[wooden moon]

oh okay i see it now

[buoyant shadow]

@wooden moonso why is there no 11 cut ?

i don't get it

[wooden moon]

no thats not what i ment, by the maximum flow minimum cut theorem the value of the maximum flow is equal to the capacity of the minimum cut

[buoyant shadow]

that's what i mean too

[wooden moon]

oh you mean where is the cut

i did not find it yet hold on

[buoyant shadow]

this is 11 right?

yeah ok

[wooden moon]

like this

but i am confused about fining the cut now

[safe radish]

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[plush mortar]

How do I determine the truth value?

[young nexus]

!15min

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Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

@plush mortar Has your question been resolved?

[plush mortar]

<@&286206848099549185>

[timid ocean]

p and q must be true because p ∧ q is only true when both propositions are true

r and s must be false because r ∨ s is false only when both propositions are false

and with this information you can evaluate the proposition ¬q↔(s→¬r)

(you can do this by setting up a truth table for example)

[plush mortar]

I did the truth table

how do i identify the answer?

there's too many T or F right

[timid ocean]

to find the truth value you have to look if the main operator is true or false

in this case your main operator is <->

[plush mortar]

is it always <->?

[timid ocean]

first you break the proposition up in smaller parts and evaluate if they are true or false by looking at the operator. in this case we will be first evaluating (p -> q).

then we evaluate (-r -> q)

in both of these propositions "->" is the main operator (in your case its basically just looking at the letters that are in bold in the truth table) . we will use this to determine the actual main operator of the whole proposition

[timid ocean]

no, not always

[plush mortar]

So far, this is my answer to my worksheet, my friend said all of my answers are wrong. correct me if im wrong did I determine the truth value?

I did follow all the steps to get the truth value

[timid ocean]

number one is correct!

wait let me just quickly look at the other ones

[plush mortar]

no worries, take your time

[timid ocean]

the second one is incorrect

wait, i'll write it down

[plush mortar]

okay

[timid ocean]

you got them all right except for number 2

try that one again, and if you don't get it i'll draw the truthtable for u :p

[plush mortar]

Okay, I'll try it again

[timid ocean]

isn't it -[(r v s ) <=> q] -> r and not -r?

the original question

[plush mortar]

r is false, s is false = false v false is false

q is true, so false <-> true is false but "~", so TRUE

[timid ocean]

wait what is the original question

the proposition

[plush mortar]

~ [(r v s) q]→r

[timid ocean]

<=> q or ^ q

[plush mortar]

r = false, so true -> false is false

[plush mortar]

q

[timid ocean]

yes

correct

so the proposition is false

[plush mortar]

there is no need to explain right? to prove my answers are right because the solution is there

im just doubting myself, if my friends asked for an explanation, I might not able to explain it properly to them

[timid ocean]

i would just change the last part to "r = false, so true -> false is false"

[timid ocean]

i think the easiest way to explain this stuff is by using truth tables because if you type it out it can get confusing

but don't doubt yourself, you got most of the questions right :)

[plush mortar]

what would you change it? and why?

[timid ocean]

you originally had the second question wrong. so just change the last part to make it correct

[plush mortar]

okay

one last thing, earlier, when you checked my answers are right or wrong did you draw a truthtable?

[timid ocean]

yep

[plush mortar]

May I kindly request a copy of your truth table? I believe it would be helpful if I ever feel confused or uncertain again.

[timid ocean]

yes ofc

wait

the different colors are for marking the order

0 = false and 1 = true

[plush mortar]

I see

Thank you so much for your help, Simona. I believe that’s all I need for now.

[timid ocean]

no problem 😊

[plush mortar]

Thank you so much for your time and help

.close

[safe radish]

Channel closed

Closed by @plush mortar

Use .reopen if this was a mistake.

[safe radish]

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[mortal gulch]

Hi, I have a probability problem

[mortal gulch]

Basically I have a probability density function of a continuous random variable X, and I have to find a value b such that P(X<b)=0.7

Is this the right approach?

I'm in doubt because the remaining equation is very hard to solve analytically

[safe radish]

@mortal gulch Has your question been resolved?

[safe radish]

@mortal gulch Has your question been resolved?

[mortal gulch]

.close

[safe radish]

Channel closed

Closed by @mortal gulch

Use .reopen if this was a mistake.

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dense sphinx]

guys

[dense sphinx]

when does the sin and cos repeat?

cos repeat each time we get a odd pi/2

so

they give zero

but what about the sin?

they both give the same result

but I cannot figure out the logic behind it

[peak siren]

you mean the period?

[dense sphinx]

yeah

I don't get it

like

yeah period is 2pi

but like

[peak siren]

yea

[dense sphinx]

that's not 2pi FUCK

so why

why does it repeat

before 2pi

[peak siren]

uhhhh

[dense sphinx]

that's not 2pi

Is it?

[peak siren]

no

[dense sphinx]

so

why

[peak siren]

the WHOLE function doesn’t repeat

[dense sphinx]

why does it repeat before 2pi

[peak siren]

only one value

[dense sphinx]

wdym

yeah

but like

they both give 0

but

yeah, no 2pi interval there

[peak siren]

yeah but the next values aren’t the same

[dense sphinx]

i don't get it.

[peak siren]

don’t get what

[dense sphinx]

why do they give the same value

WH

why is pi/2 = 0

and 3/2 = 0

WHY

[peak siren]

if you draw out a triangle

and the angle is those

the cosine will be 0

there is no “why” i can think of

just that’s how the function works

[dense sphinx]

but like

man

if they ask me to find the values where the derivative become zero

how am I supposed to know the value of cos that will make it zero

like

yeah 90 is one

[peak siren]

show problem

[dense sphinx]

but what about the rest?

[dense sphinx]

gotta find maximun and minimums

so, derivative = 0

yeah, there's a problem

[peak siren]

sen = sine?

[dense sphinx]

yeah

sen = sin

[peak siren]

okay

[dense sphinx]

like

yeah, fuck

[peak siren]

what’s this equal?

oh min and max

[dense sphinx]

oh, the derivative?

[peak siren]

my bad

[dense sphinx]

yeah

min max

like

FUCK

there are two solutions

that make sin 0 and cos 0

but like

how am I supposed to know them

I need a formula

a formula to 'after a certain degree, i get the same sin0

[peak siren]

i don’t understand what you mean

[peak siren]

have you taken the derivative of this

i have dinner right now. if no one has helped i can after

[dense sphinx]

YEAH

the problem is I gotta find the values of X that make the derivative zero

BUT LIKE

THERE ARE TWO SOLUTIONS

I CAN TELL the first solution

but not the second one

yeah, sin and cos repeat their value once during 360 degrees

so I wanna know the formula to find the value of the angle where cos and sin repeat again

so far with sin i noticed that 180 - first sin is the second time it repeats

[peak siren]

2cos(x) - 2sin(2x)
2(cosx - sin2x)

right?

[dense sphinx]

yeah

[peak siren]

ohhh wait

look at the inverse functions

not for this

they are where all values of the given trig thing until they repear

so like sin it repeats -pi/2 to pi/2 and then pi/2 to 3pi/2

etc

[dense sphinx]

OKAY I GET IT NOW

[peak siren]

may be a little convoluted

[peak siren]

yay

[dense sphinx]

EACH 2PI

[peak siren]

YES

[dense sphinx]

SO EVERYTIME I GET 2PI

FOR COS

THE FIRST TIME IS POSITIVE

no.

that's not right

I mean for cos is every 2 pi

[peak siren]

looo at unit circle

it may help you

[dense sphinx]

but for sin, what the hell

Yeah

lemme see.

So

what should I see here?

[peak siren]

where stuff repeats

[dense sphinx]

yeah

lemme see

yeah, this makes sense now

[peak siren]

yay

[dense sphinx]

yeah so

If i am not mistaken

FUCK

in order to reach 180

I need 30

YES

FUCK

I GET IT NOW FUCK

[peak siren]

yippeee

[dense sphinx]

yeah, it makes sense now

so, this is what I understand now.

each cuadrant