#help-23

1 messages · Page 312 of 1

torpid fable
#

Show its bijective or find another linear map that works as a left/right inverse

junior smelt
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(As you're mapping from the 2x2 matrices to the 2x2 matrices, you only need to check one of injectivity or surjectivity to get bijectivity)

torpid fable
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See if 2X-X^T=Y has a solution for all Y

junior smelt
#

(you may potentially find checking injectivity easier, and can check to see that as you have a linear map, whether the kernel [things that get sent to 0] is just {0})

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(pretty much yep, if the only solution to $T(X) = 2X - X^T = 0$ is $X = 0$, then you have your trivial kernel and your injectivity!)

flat frigateBOT
#

@junior smelt

junior smelt
#

And P2 being polynomials of degree 2 or less? If so, yes, that's a consequence of rank-nullity, if you've seen it

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Not quite, no, at best if you have your linear map injective, you wouldn't have it surjective as the dimension of the image would be strictly less than that of the "whole space"

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Yep (the idea is that T : V -> W injective means ker(T) = {0}, so null(T) = 0 (dimension of kernel),
and as rank nullity states null(T) + rank(T) = dim(V), you'd get rank(T) = dim(V), but then the image is a subspace of W, and W has the same dimension as V, so the image of T must be the whole of W)

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You can do those in reverse as well happyCat

safe radishBOT
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sour gull
#

Sorry this is so simple but I can’t seem to figure why the 1/4 is wrong considering 2^-2 is 1/4

sour gull
delicate sphinx
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Pretty much

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1/4 is correct, I'm just assuming that the answer key did 1/(1/4) = 4 and has that in the numerator

sour gull
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Oh yeah it did lol

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okay tysms

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.close

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idle fjord
#

can someone hepl me with this calc question?

idle fjord
#

I don't need answers

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but I do need a guide

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<@&286206848099549185>

lean otter
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wdym you need a guide

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for explaining stuff?

idle fjord
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like steps

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idk how to tackle this question

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like what should I first thing first

idle fjord
lean otter
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sure

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what is the question?

idle fjord
#

it's in the picture

idle fjord
lean otter
#

what is it asking?

idle fjord
#

represent the function by a power series

idle fjord
lean otter
#

wait so how do i help you

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what do i help you with

idle fjord
#

with solving the problem?

idle fjord
#

.close

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#
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quiet plume
#

If you know the power series for arctan (or can find it), then you can multiply it by (x^2 +1) and recover the coefficients by adding like terms

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I think that's usually the way you'd go about this once you know a few of the common power series @idle fjord

lean otter
#

oh you wanted the coefficients of the power series

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my bad lmao

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safe radishBOT
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@twilit sluice Has your question been resolved?

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modern bloom
#

I want to ask why 2k-1/n is the x here and how to understand it by drawing
P.s. I know basic definitions I know Riemann i know integrals etc.

humble fossil
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and u plug in x_k* to every x in a function

safe radishBOT
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@modern bloom Has your question been resolved?

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pale pecan
#

I have this question where i need to use Taylor's Theorem, and i don't understnad the phrasing of this question too well. for 3B where it asks to find the radius and interval of convergence, how can i find the radius and interval of a number that wasn't pre set? and how can i find the power series reperesentaion of f(x) where the functoin isn't given?

safe radishBOT
#

@pale pecan Has your question been resolved?

safe radishBOT
#

@pale pecan Has your question been resolved?

safe radishBOT
#

@pale pecan Has your question been resolved?

safe radishBOT
#

@pale pecan Has your question been resolved?

safe radishBOT
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high grove
safe radishBOT
high grove
#

can anyone help me solve this problem

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this is in partial derivative

teal thicket
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the function is e^x right?

high grove
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no

teal thicket
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ohh..

high grove
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how do i approach this

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this is meant to be the answer

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but i dont get it

safe radishBOT
#

@high grove Has your question been resolved?

high grove
#

yea

safe radishBOT
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left tinsel
#

Can someone tell me what went wrong

safe radishBOT
left tinsel
#

In this equation

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@teal thicket

teal thicket
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hello!

left tinsel
#

Yoyo 😄

teal thicket
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IVE BEEN SUMMONED

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explain me what you did

left tinsel
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Yeah my hero!

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Well I basically put all the numbers in the formule

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First I did 2-3

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Then 3-1

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And then the equation 1 - equation 2

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To find b

teal thicket
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alright

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Correct

left tinsel
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I got b = 3 but answer is b = 5

teal thicket
#

give me 5 mins…

left tinsel
valid olive
left tinsel
#

Could you explain

valid olive
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like can you see those 2 equations

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in 2nd and 3rd line

left tinsel
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Yea

valid olive
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1=a(b-7)..........

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yeah so

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in elimination method

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we try to remove a variable

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to make it easy for solving

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by cancelling out

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what I mean is

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subtract the third one from second one

left tinsel
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So 0=9a+3b+c+16 - 0=49a+3b+c-16

valid olive
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you don't have to do it like that

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try to make it more simple

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like can you see that -4 becoming +4

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ab getting canclled out

left tinsel
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yes

valid olive
valid olive
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on both sides

left tinsel
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5= a(b-10)

valid olive
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wrong

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multiply the a first

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that will help

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then solve

left tinsel
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1=ab-7a

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-4=ab+3a

valid olive
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1 = ab - 7a
-4 = ab + 3a

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yeah

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now see and tell what do you get

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on subtracting

left tinsel
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i see the method yeah

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but

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what formule is this

valid olive
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not a formula

left tinsel
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y=a(x-r)(x-s)?

valid olive
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but method

left tinsel
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since the (-1,0) was a zero point you can fill it in like

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y=a(x+1)(

valid olive
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I though those equations

left tinsel
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i meant how do we fill up the method

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so we got y=a(x+1)(x+b)

valid olive
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I don't really know what it is

left tinsel
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what means b ?

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in my class we learnt this formulla for zero point and extra point

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a(x-r)(x-s)

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but in the answer book we use a(x-r)(x+b)

valid olive
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most prob that r is -1 here

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so it's y = a(x+1)(x+b)

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about that b part i have no idea

left tinsel
#

Yea

valid olive
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try to look for exmples related to it

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or more sol where it is used

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it will give you an idea of what it is

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or consult with your teachers if any

left tinsel
#

Oh wait I think I got it

valid olive
left tinsel
#

I still don’t get the +b but I’ll just try to keep it in my mind if I get one zero point for the exam and 2 others points

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.cloes

#

.close

safe radishBOT
#
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midnight sail
safe radishBOT
midnight sail
#

This is a review question for are class, my teach says that its not imaginary numbers and you don't use the quadratic equation but whenever I do it I get imaginary

frozen marlin
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yeah the answers are complex

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check the question again

left tinsel
#

i got - 12 / t^2 - t - 2

safe radishBOT
#

@midnight sail Has your question been resolved?

delicate sphinx
safe radishBOT
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@midnight sail Has your question been resolved?

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raven veldt
#

I need to find the next largest permutation of these integers. I am pretty sure what I currently have is wrong

cold relic
raven veldt
#

I think it needs to be the next one that is larger than the current

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I am not exactly sure about the wording of the question:
It just says next larger permutation after 217345689

cold relic
#

Ah okay

#

So I’m not sure about your reasoning, as I have trouble understanding it, but your result should be right

raven veldt
cold relic
#

As far as I can see, yes

safe radishBOT
#

@raven veldt Has your question been resolved?

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rugged surge
#

A person has a coin. he moves towards left if its a head and right if its a tail. he flips the coin 4 times. what is the probability that at the end, his displacement is 0

rugged surge
#

i tried writing down all the possibilities

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and got the right answer

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but is there a more easier way to do it?

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can we apply binomial here?

kind fractal
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both probabilities are the same

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so you need a success of 2 when p=0.5 (?

green fern
#

This remember me about the drunk walker

rugged surge
rugged surge
kind fractal
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yes

kind fractal
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in this case, where each step has the same length

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and the number of trials is even

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xd

rugged surge
#

fair

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thankyouu

#

.close

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ionic oar
#

Can anyone give me the formulas for the following:

  • Calculate % X number of Z number
  • Calculate the increase in % from X to Z number
  • Calculate the decrease in % from X to Z number
  • How to find if for example if someone goes on sale by X%, and find new price
  • How to find if for example if a X number went on sale and find how many x% was the price discounted
ionic oar
#

ALL.

safe radishBOT
#

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

frozen marlin
#

jeez

frozen marlin
# ionic oar ALL.

jesus man chill out; every time someone tries to help you this happens
calm down

safe radishBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

lean otter
#

ah my bad

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true

frozen marlin
#

wtf?

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you don't just

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decide

frozen marlin
#

whether someone gets to break the rules?

frozen marlin
ionic oar
#

u heared it

frozen marlin
#

yes but i didn't quite understand it

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expand upon it, will you

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this is perhaps the fourth time this has happened within the last week siryeet

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every time you open a channel you treat your helpers with disrespect

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and those are the times that i have encountered you

ionic oar
#

i didnt?

#

ur the one trolling now

frozen marlin
#

oh you most certainly did

ionic oar
#

.close

safe radishBOT
#
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frozen marlin
#

oooooookay then

safe radishBOT
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hollow prism
#

hello so i was solving this inexact differential equation and in the following step i had to integrate 2/x dx and that gives 2 ln| x | + C so i was wondering where did he get that x^2 from?

frozen marlin
#

2 ln x = ln(x^2)

hollow prism
safe radishBOT
#

@hollow prism Has your question been resolved?

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north robin
#

How do I start

safe radishBOT
charred saffron
#

ur gonna use the basic trig formulas

#

remember SOH CAH TOA

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the angle we have is 51°

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@north robin

north robin
#

Can you tell me how to start?

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Like the formula

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@charred saffron

delicate sphinx
#

You should apply that

north robin
#

Only this?

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I thought it would be more complicated than that

delicate sphinx
north robin
#

And the angles only to 189?

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180* lol

delicate sphinx
#

Yes, sum of angles in a triangle equals 180

north robin
#

Let me try rq

#

Could I use either angle for both?

safe radishBOT
#

@north robin Has your question been resolved?

safe radishBOT
#

@north robin Has your question been resolved?

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wet frost
#

is it possible to find the bases here?

safe radishBOT
dusty fiber
#

not with only the given information

#

you would need something like an angle measure or the radius of the circle

wet frost
#

I completely forgot

#

my bad

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the radius is 12

dusty fiber
#

I believe its possible but I haven't worked through it to know the specifics of how to do it

wet frost
#

I guess I can make something out of this

narrow ridge
#

i think you could use 7-24-25 triangle

wet frost
#

I'm not too sure where to use the hypotenuse for tho

narrow ridge
#

draw a line from B to AD such that its perpendicular to AD

wet frost
narrow ridge
wet frost
narrow ridge
#

AH = 7

narrow ridge
wet frost
#

oh yea

#

you're right

wet frost
narrow ridge
#

yes

wet frost
#

we can do the same for the other side right

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just drop a height

narrow ridge
#

ye

wet frost
#

BC = HK

narrow ridge
#

x = 24

wet frost
#

since it's a square right

narrow ridge
#

yes

#

90 degree angles

wet frost
#

ironically

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in the answerkeys

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it's 32 and 18

narrow ridge
#

huh

wet frost
#

geometry moment 🥲

narrow ridge
#

not a square then

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oops

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bad assumption

wet frost
#

AD and BC are parallel so

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I suspect similarity?

dusty fiber
#

rectangle not square

narrow ridge
#

ye

wet frost
#

yea you're right

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is BH considered a chord as well?

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nevermind that's silly

narrow ridge
#

secant

wet frost
#

if we connect radius with BC

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would it cut it in half

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or rather a height

narrow ridge
#

yes

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it should

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since the circle is inscribed

wet frost
#

not sure what to do after that

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I do see similarity but

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kind of useless

#

this looks like a square

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yeah no

narrow ridge
#

nope

wet frost
#

🥲

narrow ridge
#

radius of circle

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😭

wet frost
#

isn't it atleast a rectangle

narrow ridge
#

ig

wet frost
#

oh wait

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this isnt gonna work

#

yeah this looks stupid

narrow ridge
#

ohh

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@wet frost

wet frost
#

yea

narrow ridge
#

the trapazoid

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has a cricle in it

wet frost
#

yea

narrow ridge
#

tangetial trapazoid

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AB + CD = BC + AD

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or

wet frost
#

oh

narrow ridge
#

50 = x + x+ 7 + 7

wet frost
#

🤣

#

you right

narrow ridge
#

50 = 2x + 14

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😭

#

2x = 36
x = 18

wet frost
#

4 sided figures are drawn in circles if the side's sum are the same right

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yeaaah that makes sense

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thank you for the help 👍

#

would have been stuck on this for the next 30 minutes

narrow ridge
#

👍

wet frost
#

.close

safe radishBOT
#
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true echo
#

y = 5x + 450

safe radishBOT
true echo
#

y = 10x + 300

#

ik this but

#

how do i graph it on a ti-84 calc

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and how do i use the window properly to show this intersection

fathom adder
#

y is the same as f(x)

true echo
#

wdym

fathom adder
#

In your ti

#

You have probably something written as f(x) = ... in the graph part no ?

true echo
#

no

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im wondering

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in the window part

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how do i adjust the numbers so i can see the intersection clearly

fathom adder
#

Oh like scale ?

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To zoom etc ?

true echo
#

yeah

#

yeah

fathom adder
#

Let me see rq

true echo
#

ok

#

ty

fathom adder
true echo
#

.close

safe radishBOT
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short bridge
#

$$5\ 200\bullet\frac{1-\left(\frac{26}{25}\right)^4}{1-\frac{26}{25}}$$
Hi, I was wondering what is the easiest and fastest way to solve this, I already did it and found the answer but I have to show my work and I don’t know how to solve it without getting excessively large numbers.

short bridge
#

$$5\ 200\bullet\frac{1-\left(\frac{26}{25}\right)^4}{1-\frac{26}{25}}$$

flat frigateBOT
#

Etamenta

vapid glen
#

is that 5*200 or 5200

short bridge
#

5200

vapid glen
#

gotcha, also you might want to try using $a \cdot b$ or $a \times b$ for multiplication instead of the bullet, just more common to see.

flat frigateBOT
#

Merosity

vapid glen
#

I'd probably try multiplying by 25^4 / 25^4 and factor the numerator as a difference of squares twice

#

idk if that's the fastest way but we can try to work out some tricks if that doesn't seem fast enough

vapid glen
#

that make sense or how do you feel about that, just throwing ideas out there

short bridge
#

$$1-\frac{{26}^4}{{25}^4}$$

flat frigateBOT
#

Etamenta

short bridge
#

$$\frac{{25}^4-{26}^4}{{25}^4}$$

flat frigateBOT
#

Etamenta

short bridge
vapid glen
#

$$134^25^2 * \frac{25^4- 26^4}{25^4-2625^3}$$
Just factoring loosely at first since I know a deck of 52 has 13 cards in each suit, then cancel out the $25^2$ out and the diff of squares (combined a few steps here maybe too many!)
$$13
4^2* \frac{(25^2 +26^2)(25- 26)(25+26)}{25^2-26*25}$$

flat frigateBOT
#

Merosity

vapid glen
#

to be a bit clearer on diff sq twice: $$x^4-y^4 = (x^2+y^2)(x^2-y^2) = (x^2+y^2)(x+y)(x-y)$$

flat frigateBOT
#

Merosity

vapid glen
#

since 25(25-26) cancels with the numerator (although it's not hard to simplify regardless as -1 lol)

#

the 25-26 part I mean, not the 25

short bridge
vapid glen
#

no, I'd keep working at it

#

I just stopped to explain the difference of squares but

#

I feel like once it's broken down to there, it becomes easier to deal with

short bridge
vapid glen
vapid glen
#

I might be going in the wrong direction in all honesty!

short bridge
#

It gave me 22 081.6128

#

but it was after something like

vapid glen
#

I might have assumed you were trying to get it in the form integer/integer

short bridge
#

$$\frac{81\ 250\ 000-95\ 051\ 008}{-625}$$

flat frigateBOT
#

Etamenta

vapid glen
#

If approximation is what you want there is a strange trick I think here

#

I'm thinking multiply by (25/26)^4 since 25/26 < 1. Then you can start computing an expansion with the geometric progression.

#

well, I really need more context because probably that's already too complicated sounding, is this for competition math or are you just trying to get better at computing things by hand without a calculator for fun or where does this problem actually come from?

short bridge
#

I have to find the sum of the first 4 terms of a geometric progression using that general term.

vapid glen
#

ah

#

that's why it's important to post the original question 😛

short bridge
#

And I got that

short bridge
vapid glen
#

Can you post the full question actually with this

#

if you're allowed to use a calcuator then you probably are fine, but I'm not your teacher so I don't know what they want or what the question is specifically expecting. What you wrote without simplifying might even be sufficient.

short bridge
#

I think I should solve until the end.

#

But if those terms appear it will be very obvious that I used the calculator.

vapid glen
short bridge
#

Ok, thanks. I was also wondering if I should work with decimals or fractions.

#

I tried both and I think the decimals are easier.

#

What do you suggest?

#

@vapid glen Sorry, me again, I have another question, what should I use to separate the decimals and what to separate the thousands?

#

My main language is spanish btw, I found that for decimals is the dot and for thousands just a space, is that right?

vapid glen
short bridge
#

That was all.

vapid glen
#

de nada

short bridge
#

.close

safe radishBOT
#
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dense hatch
safe radishBOT
dense hatch
#

How would I have been able to determine those values?

#

If sin(A) = 8/17, how do I find out cos(A) = -15/17?

#

If sin(B) = -5/13, how do I find out cos(B) = -12/13?

lean otter
#

See that it gives the quadrants of the respective angles. One way to visualize it would be to draw the trigonometric circle and make respective right triangles in this way you could find The cosine of both angles by the identity sin²x+cos²x=1

safe radishBOT
#

@dense hatch Has your question been resolved?

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solemn ravine
safe radishBOT
solemn ravine
#

i got here

#

but then i used bahagutpra's formula

#

but i calculated it wrong

#

essentially, my question is how do you determine if a quadrilaterial is cyclic

safe radishBOT
#

@solemn ravine Has your question been resolved?

solemn ravine
#

actually yes i did find out

#

.close

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odd widget
#

I’m losing my mind—please help! I have no idea which of these could be wrong

odd widget
#

I must be missing something obvious

#

(This is homework)

tall spade
#

A few hints: 1.) consider f(x) = x^3 at x=0. 2.) consider f(x)=-sqrt(x) at x=0.

#

and 4.) What if f is positive and rises quickly while g is negative and rises slowly, calculate some easy examples.

odd widget
#

Ohhhh okay—I’m sketching some graphs out and I think I follow

#

Arghhh

#

I appreciate the sanity check

#

That cleared it up, thank you!

#

.close

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#
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red lava
#

Can u help me do 0 divided by 0

safe radishBOT
red lava
#

I know its undefined but i still think there is a way

frank horizon
#

this is the only setting in which 0/0 is meaningful

red lava
#

no im very young lets say

#

Because no matter how many groups u put u still have zero

#

that doesnt make sense

#

alright then, thanks i got it

#

its just undefined

#

but the wheel is the only setting where 0 divided by 0 is meaningful

#

u can move this to availible

frank horizon
#

yeah, you can't assign a value to 0/0 if you are referring to 0 in the usual sense

red lava
#

alr thanks

safe radishBOT
#

@red lava Has your question been resolved?

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celest musk
#

A projectile is shot from the edge of a cliff 115 m above ground level with an initial speed of 65.0 m/s at an angle of 35.0° with the horizontal, as shown. (a) Determine the time taken by the projectile to hit point P at ground level. (b) Determine the distance X of point P from the base of the vertical cliff. At the instant just before the projectile hits point P, find (c) the horizontal and the vertical components of its velocity and (d) the magnitude of the velocity. (e) Find the maximum height above the cliff top reached by the projectile.

celest musk
#

honeslty i think if i can get the first steps im good from there

#

but i dont understand how to get (a)

exotic bolt
#

find inital

#

horizontal and vertical componets

celest musk
#

got that part

exotic bolt
#

ok then what are u confused about

#

what is the velocity of the object once it hits the ground

#

in y direction

celest musk
#

do i need to find its max height first?

exotic bolt
#

no

#

u can

#

but u dont need to

#

what is the velocity of the object once it hits the ground

celest musk
#

0

#

no?

exotic bolt
#

yes

#

so

#

what kinematic

#

do u think

#

we use

#

if we have an intital velocity, final velocity, and acceleration (-g), and want to find t

celest musk
#

distance kinematic

exotic bolt
#

which one cuh

celest musk
#

jitalagang distance = vit +1/2(g)t^2

#

fuck i had to type that out

exotic bolt
#

yes cuh

celest musk
#

ong jit

exotic bolt
#

now plug and chug

severe pond
#

yo this guy benches 75

celest musk
#

who me?

exotic bolt
#

🙏😭

celest musk
#

some bs

#

nah propus benches 225

exotic bolt
#

hurry up lil bro

celest musk
#

aight bbg

#

t=2.9 or 7.9

#

hol up

#

nah my math right

exotic bolt
#

yye

#

it aint

celest musk
#

diddy no

exotic bolt
#

bro cant use a calc 🙏😭🙏🙏😭😭

celest musk
#

ion have one on me

exotic bolt
#

so u got 7.9 in your head

#

use demos lil bro

celest musk
#

desmos has calculators

#

?

exotic bolt
#

u can graph

#

and see intersections

#

u bafoon

#

and yes it has a calculator 😭🙏😭😭

celest musk
#

hye mwan u hwurgint my fweelings

#

imma throw hands

exotic bolt
#

hurry up

#

enter into demos

#

or just to y=

#

on ti84

#

plug in qudratic

#

and see intersections there

#

aint nobody got time for the quad formula

celest musk
#

tf is a ti84

#

im doing desmos rn

exotic bolt
#

what calculator do u use wtf

#

are you in the us?

celest musk
#

nrn

exotic bolt
#

oh u in a diffirent country

#

make sense ig

#

ti 84 is standard calc in america

celest musk
#

even when i was in us i didng use that

#

we didnt need graphing calcs

#

-5.42857 -259.4

#

aint no way thats right

#

i might be dumb

exotic bolt
#

.

#

shoq

#

ewuqaiton

celest musk
#

115=53.2t +1/2(-9.8)t^2

#

and then just rearranged

exotic bolt
#

-115

#

shoul look like this unsimp,ifed

#

idk the actual numbers

celest musk
#

im still getting 7.92

#

or 2.94

exotic bolt
#

send

#

photo

#

of ur equaton

#

and make sure ur in degrees

celest musk
#

oh smeat

#

its 12.70

exotic bolt
#

no

celest musk
#

or 1.85

celest musk
exotic bolt
#

idk how ur entering an equaiton

#

in wrong

#

when its right in front of you

celest musk
#

were all talented in our own ways

#

my grandma says im special

exotic bolt
#

this is why the us the smartest country

#

!!!

celest musk
#

wait on desmos what should i be looking for

#

the peak?

#

dont really do much graphing

exotic bolt
#

intersection

#

of x axis

celest musk
#

12.7

#

again

#

desmos equation is y=53.2t+1/2(-9.8)t^{2}+115

#

NO WAIT IM A DUMBASS

#

fuck

#

me

#

9.96

#

is t

#

propus one more question

exotic bolt
#

yes

celest musk
#

if u have time

#

can i do the same thing if i want to find max height

#

because vf on max height would be 0

#

(given time)

exotic bolt
#

ye

#

t is just 1/2 ttoal time

celest musk
#

yeah

#

aight thank you man

#

.close

safe radishBOT
#
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safe radishBOT
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dim herald
#

So I have a polynomial

safe radishBOT
dim herald
#

$W(x) = x^{2}-3456x+1$

flat frigateBOT
#

_hhashh

dim herald
#

and a polynomial

#

$P(x) = x^{4}-Nx^{2}+1$

flat frigateBOT
#

_hhashh

dim herald
#

what should be N to make their roots equal?

#

I calculated that for W(x)

#

the root is

#

$x = y \pm \sqrt{y^{2}-1}$

frozen marlin
#

"y"?

wooden vine
#

What’s y

frozen marlin
#

also \pm for +- and \sqrt

flat frigateBOT
#

_hhashh

dim herald
#

so I substituted y = 1728

#

i mean i should probably use like a

#

but i used y

frozen marlin
#

mhm

eternal carbon
#

yes correct

#

good process

dim herald
#

why tho?

#

wait

#

i dont get it

#

i know the answer is

#

$3456^{2}$

flat frigateBOT
#

_hhashh

dim herald
#

but i dont get how i prove it

eternal carbon
#

that is not the answer

dim herald
#

no?

#

oh

#

im kinda stuck and idk why

eternal carbon
#

the answer is x^2, where x is what you found up there

#

or i am deeply mistaken

dim herald
#

bro i made a graph in desmos

#

and its the b squared

#

see?

#

or am i wrong on this... 😭

#

no i think im wrong

#

cause the x is very close to 3456

#

but not exactly

#

its like 3455.999...

#

so if you square it

#

you get the exact answer i think

#

but why square it?

#

can you explain it?

#

I dont get your reasoning

eternal carbon
#

i was mistaken

#

for problem like this you can i guess just work backwards

#

you know that from definition of P(x), there is roots x^2 = [apply quadratic formula]

eternal carbon
dim herald
#

so how were you mistaken?

#

so you do something like this?

dim herald
#

x' instead

#

so then you P(x')?

#

right?

#

and then you solve for N?

#

it would mean you get something like that?

#

$P(x') = (x')^{2}-Nx'+1$

flat frigateBOT
#

_hhashh

dim herald
#

or am i wrong?

#

I think im kinda lost

#

It seems for me that the exact answer is

#

$11,943,934$

flat frigateBOT
#

_hhashh

dim herald
#

but im not sure

#

so I basically changed P(x)

#

into $N = \frac{x^{4}+1}{x^{2}}$

flat frigateBOT
#

_hhashh

dim herald
#

and put it to calculate n

dim herald
#

does this make sense?

#

hmmm

#

no its not the answer

#

the answer should be $3456^{2} = 11943936$

flat frigateBOT
#

_hhashh

dim herald
#

i would be thankful if someone explained why its that

safe radishBOT
#

@dim herald Has your question been resolved?

#
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nocturne phoenix
#

Does anyone know what is this actually? And how is its's anwer 16?

frozen marlin
#

that's tetration

#

2 tetrated 3, written like that, is 2^2^2

#

"a power tower"

#

in general

nocturne phoenix
#

so if its 10 tetrated 3 its answer is 10^100? or

frozen marlin
#

${}^ba = \underbrace{a^{a^{a^{\cdots^a}}}}_{b\text{ times}}$

flat frigateBOT
nocturne phoenix
#

And why was I never taught this in school?

frozen marlin
#

because it's generally useless

#

no no no

#

10 tetrated 3 is not 10^100

#

who thumbs-upped that

#

10 tetrated 3 is 10^10^10

cold relic
frozen marlin
#

you evaluate the power tower starting from the top

#

so 10^(10^10)

nocturne phoenix
#

wow that is very big number

cold relic
nocturne phoenix
#

ok so why is it useless?

frozen marlin
#

because
it has no uses?

#

can't think of a single place where i'd use tetration

nocturne phoenix
frozen marlin
#

nobody

#

learnt it myself

nocturne phoenix
#

I came to know about this rn

frozen marlin
#

i learn most things myself

noble kiln
frozen marlin
#

i can send you a video on very large numbers if you'd like

nocturne phoenix
#

Why it exists if it has no use?

cold relic
#

It has uses

frozen marlin
frozen marlin
#

and it does have uses--just not very common ones

nocturne phoenix
frozen marlin
#

not really

#

easy in theory yes, hard in practice

frozen marlin
#

frankly i have no idea

empty ice
#

compt science?

frozen marlin
#

but there are definitely some lol

frozen marlin
empty ice
cold relic
#

I suppose grahams number is in part tetration

nocturne phoenix
#

@frozen marlin@cold relic@noble kiln@empty ice Thank you so much. I just learned a new concept thanks

noble kiln
#

np

#

thank them more fr

frozen marlin
#

interestingly, sqrt(2) tetrated infinitely is 2

frozen marlin
cold relic
#

Well it’s a further generalization of the concept (the arrow up notation)

frozen marlin
#

well

#

i mean it's like saying exponentiation is in part addition

#

which is in part true

noble kiln
#

technically yes right

frozen marlin
#

but you don't think of it that way do you

frozen marlin
nocturne phoenix
#

.close

safe radishBOT
#
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sage patrol
#

why are my answers flipped?

safe radishBOT
#

@sage patrol Has your question been resolved?

safe radishBOT
#

@sage patrol Has your question been resolved?

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lime lark
safe radishBOT
lime lark
#

how would I solve this integral?

#

I’m aware 1-sin^2 x = cosx and ik u substitution but I just get stuck

last wren
#

i think you mean cos^2 x

wooden vine
#

Oh I was going to say that

lime lark
#

mb

last wren
#

so you end up with the integral of sinx/cosx

#

what did you choose to be your u

lime lark
#

I chose sinθ

#

should I be choosing cos?

last wren
#

yes

lime lark
#

so I change the bottom to sqrt cosθ and use cos as my u?

last wren
#

the bottom should just be cosx, no sqrt

wooden vine
#

Sqrt cancels

#

The squared

lime lark
#

ohhhhh right

charred saffron
#

why cancel it out

#

actually maybe its better

#

nvm

wooden vine
#

Isn’t sin over cos just tan or is that wrong? I’m kinda tweaking today

lime lark
#

wait what do I do after that

charred saffron
#

change that to tantheta

#

and u got ur answer

lime lark
#

but now cosθ is u

charred saffron
#

oh wait did u guys substitute smt?

lime lark
#

yes

#

u substitution

charred saffron
#

u sub?

#

what is u equal to?

lime lark
#

cosθ

charred saffron
#

noo

#

dont do that

lime lark
#

….

#

what should u be then

charred saffron
#

there is no need of subbing

#

u got to integral of sin(theta)/cos(theta) d(theta) , yes?

lime lark
#

yes

charred saffron
#

that can be written as tan(theta) like reaver said

#

no need for "u" sub

lime lark
#

integral of tanx is what

#

theta*

charred saffron
#

its -|cos(theta)| + C

lime lark
#

alright ty

#

.close

safe radishBOT
#
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modern bloom
#

Why does continuity of the partial derivatives imply continuity of all directional derivatives?

frozen marlin
#

because directional derivatives are just linear combinations of partial derivatives

modern bloom
#

Ok

#

.close

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#
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frozen marlin
rustic goblet
#

nah

#

the speedrun record goes to the people who open a channel and instantly clear their own doubt

upbeat swan
#

fr

safe radishBOT
#
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cloud pagoda
#

can u help me? I dont even know what to do here

safe radishBOT
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@cloud pagoda Has your question been resolved?

safe radishBOT
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@cloud pagoda Has your question been resolved?

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safe radishBOT
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cold relic
#

b*1/x = a implies b | a if and only if 1/x is an integer

#

But for x>1 that isn’t the case

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Which is why this doesn’t prove that b | a

#

If a | b and b | a then necessarily a = b. This follows from the fact that a | b implies a<=b and b | a implies b<=a

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ionic oar
#

If someone asks me a question and gives me 4 possible option and one is correct, my chance of guessing the answer is 1/4 or 25%, but what would be the change of winning the whole show if it costs of 8 rounds, and each round has different available answers?

1-4th round - 4 answer options
5-7th round - 3 answer options
8th round - 2 answer options

What’s the chance of me winning the show if I only guess the answer?

brisk shard
safe radishBOT
#

@ionic oar Has your question been resolved?

empty gyro
ionic oar
#

And?

#

Calculate

brisk shard
#

should be something like (1/4)^4 × (1/3)^3 × (1/2)

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#

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clear geode
#

Consider the theoretical implications and existence conditions of the following hyper-abstract construct:

flat frigateBOT
#

altaccountinthespotline

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#

@clear geode Has your question been resolved?

hard crest
#

.close

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thick dagger
safe radishBOT
thick dagger
#

ok im 100% lost on this

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idk how to start this

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but all ik is similar triangles

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but i cant see any similar triangles ;-;

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this is the answer!!

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oh wait now i see the similar triangles but idk how to start it!

spark zinc
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isnt it 6

thick dagger
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x = 6?

spark zinc
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sorry nevermind

thick dagger
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oh ok!

spark zinc
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I misinterpreted the shape

thick dagger
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oh nwrs

spark zinc
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I feel like they might be similar triangles

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because they're both isosceles

unborn relic
#

Do you know the similarity types @thick dagger

spark zinc
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also simultaneous will probably work

unborn relic
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Yea ur correct here

spark zinc
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this owuld be SSS

spark zinc
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we dont know angles and they're irrelevant

unborn relic
#

Well actually i was gonna say AA

thick dagger
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the only thing i know is big triangle over little triangle!!

spark zinc
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I hate how there are no angles that's what makes this hard

thick dagger
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i was kinda just tossed in here!!

spark zinc
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Use AA similarity

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that's my hint

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I dont want to give it away totally

thick dagger
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ok wait im gonna take a picture of my attempt

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and tell me where i went wrong ;-;

spark zinc
#

this angle belongs to both triangles what can we infer form that?

spark zinc
thick dagger
thick dagger
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so uhm i guess i am delayed!!

thick dagger
spark zinc
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Hmmm you have not simplified your answer

thick dagger
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i kinda been just winging everything guys!!

spark zinc
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It should be 6+sqrt14

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sorry 3+sqrt14

thick dagger
spark zinc
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its still incorrect let me see what you did wrong

unborn relic
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You didn't put 5x on left side

thick dagger
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err i am wrong

thick dagger
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OH

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OH I SEE WHAT U MEAN

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WILL TRY AGAIN

spark zinc
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shouldn't this be it's inverse... x/(6+x-4)

unborn relic
thick dagger
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wait im still wrong if i get 5x

thick dagger
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wait wouldnt that be the same thing

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itll just be x/x yes?

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cuz the 6's cancel each other out!

spark zinc
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i think

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let me actually do this on paper hang on

thick dagger
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okok ty

spark zinc
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tryna do this in my head is pointless

thick dagger
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guys im now kinda sad that this is gr 8 level.

spark zinc
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no its not

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the basis of similairty is yr 8

thick dagger
#

oh so purple and green go together?

spark zinc
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this is like 10/11

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I think so...

thick dagger
thick dagger
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wait i think i got it

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but like i did trial and error

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and idrk how i got it ;-;

spark zinc
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that's it

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exactly what I was using

thick dagger
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okok

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wait but is there a fast way to know what values to use?

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or is it trial and error or just eyeballing everything ;-;

spark zinc
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no

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I'll show you

thick dagger
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okok tyty!!

spark zinc
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these are similar triangles, they share the angle in the bottom right and are isosceles

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we can therefore imply that the ratio's of their correspondant sides will be equal

thick dagger
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mhmm

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wait but dont at least two angles have to be equal for them to be proportional?

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how would we know another angle is equal?

spark zinc
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the "xm" on the big triangle is equal to the "5m" on the small one, so we will use these as our numerators.... but can also be used as denominators

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We can also see that the "5m" on the big triangle is equal to the "(x-6)m" on the small triangle

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these will be set as our denominators (or numerators if we set the other sides before to the denominators)

thick dagger
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ohh okok

spark zinc
thick dagger
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OHH

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I FORGOT ISOCELES DO THAT

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OK THAT MAKES SO MUCH SENSE

spark zinc
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one side of the equation should only consist of side lengths of one triangle and the other side of the equation the other triangle

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so in the same fraction you SHOULD NOT have side lengths from different triangles

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then it will fuck it up