#help-23
1 messages Β· Page 304 of 1
whats ur method?
never thought of it that way ios mbmb
find the % of 50 ppl via z score
u just look at the graph
lol
but u can do it that way too
it all works
okay
so 15 people but i need the percentage
tell me what the question is asking
this
i think u can answer this urself
just ur gut
okay
so is ir a yes or no
mhmmm
be exact
0.9375
dont forget the %
o yeah
0.9375%
just leave it as that and byebye a mark maybe
but yeahhh
thats the answer
does this process make sense?
bro i could not do all of this in the hsc π
ye
hurray
nppp
try to understand what the qn wants first then break it down
see with what resources u have are able to help u solve it
π«‘
ahh lmao nice
multi tasking eating dinner while helping with math and then brushing teeth
lol yes
i waws planning to do this trial paper in timed conditions because i was doing hsc 2021 and 2022 yesterday in timed conditions
but this trial paper cooked me so bad in mutliple choice and first few questions i jsut gave up bruh
π
noo dont give up
for me
even if u get cooked
read thru the solutions
keep reading until u understand what they do
once u understand it, all other qns similar to it will work quite similar
keep grinding papers
u got thissss
me fr
same bro
i hope the majority of this years hsc will be calc related π
im gonna mald over probablity
if they make it all stats its actually ggs
thatβll be amazing
fair enough
nah i dont like biavraite
like the explain qns
no maths
just englsih
end of me
i have that too
its such a lifesaver
but the explain quesitons r so bs
theyre aight
there was like this explain qn in my trial
and they didnβt take extrapolation as an answer
π«‘
π
i have one more quick q if ur able to help wit it
uhh ill try
i think so
whats the A for
oh wait
i dont think u need it
i think u can find radius with area of triangle
is radius 5.32 ish
mhmm
ye
okay gawt it
thanks for all the help
OMG THE MATH TEST IS TOMORRRORWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWW\
ITS TOMORRRRRRRRRRRRRRRRRROWWWWWWWWWWWWWWWWWWWWWWWWWWWWW
NOOOO
yeah but they rounded it to 32.6
ITS TOMORROWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWWW π
yep
hurray
AHHHHHHHHHHHHHHHHHHHHHHHHHHHH
do u have another more qns?
oh god
ohhh my god
it looks so
so not nice
wait actually
its a sequences and series
but it has like
the financial math questions format
?
this is like a loan
yeah sorta
$P_{n+1}=P_{n}\left(1+r\right)-Q$
water beam
is it ?
i remembered the formula my math teacher gave me
i was gonna do it in a diff way
its from annuities
ohhh i never seen that before
i have never touched annuities in school besides for 1 period
fun
NOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOO DONT SCARE ME
ideallu not pls im gonna die if i see annuties
what way were you thinking>
whats amazing abt ext is that thers no fnancial maths
uhh
i was gonna find like p1 p2 and p3
and find a pattern from it
then turn it into pn
HUH
WHATS THE EXACT THING THE QN TOLD U NOT TO DO
w a i t
WA I T
I PROVED THAT
TOO
AHOFSFSDV
FDP
goodbye
wha the acutal flip
lmaooo and its 2 marks only we're not gonna get any marks for that
more like we did more working out then needed for 2 marks
bye i proved that
i actually did not see that
i swear i have selective reading
idk if thats a real thing
selective hearing is
lmfao π
im tryna simplify the geometric series rn
lock in
$P_{n}=1000\left(1.1\right)^{n}-Q\left(\frac{1.1^{n}-1}{0.1}\right)$
water beam
is it this
this is what im getting for the geometric series thing
lmao i did exactly what u did π
yes
how do i get it to look like the question tho
u could start off by getting rid of thebfraction
since the thing we want to get doesnt have any fractions
the rigght part, u can simply move the 1/0.1 out of the brackets since its a constant
-Q/0.1 times (1.1^n -1)
ohhh okay
makes sense?
so 1/0.1 becomes 10
yuhhh
$P_{n}=1000\left(1.1\right)^{n}-10Q\left(1.1^{n}-1\right)$
water beam
yus
now
theres not rlly much we can do with that
i guess thers bascially only one obvious move
what do u thinj we would do next?
expand and factor out the 1.1^n
yus
woop woop
still cant believed we proved it lol
i hope i dont accidentally do this tomorrow and waste time
costing me my ranks π
there was never a task besides once where i did selective reading
like
in at1 for ext
i coepmetpely
didnt see part b of a qn
like
i went from a to c
and i didnt even realise i skipped b
I DIDNT SEE A B
so sad
yesyes
could u send part b qn here
hmm let me try smt
so i know from a previous financial maths question similar to this u have to end up setting the sequence P_n = 0 and solve for n but i think theres steps we need to do before that
what aboutthe year
what
wat happen
ohhhhhhhhh
hello water how have you beam 
hello convergence im doing good i have my final math exam tmrw
another aussie??
i got the answer hbu?
oh all the best you got this 
naw jus a friend
ahh
thank u 
nah i dont know how to start π do you plug in n=20
ok so
the first part
is to find how many deers r left after 20 years since stuff changes after the 20th year
yes and what will this allow us to find?
wait but i have to also consider that 80 deer will be removed
so Q = 80 right
n = 20
and this finds us
uh
the amount of deer left?
after 20 years
more specfic pls
300 deer will be removed and i need to find n such that P_n = 1000 or something?
semi correct
yk the fomrula we got from part a
1.1^n (1000-10Q) + 10Q
tell me what the 1000 means
in there
1000 is the initial number of deer?
uh im not sure, why would it change?
lets think of this
with that correct formula
it worked up until now
with 80 deers
but now we changed our deers to 300 at the start of 2045
u can think of the next year, for 2046
uhh not sure what ur trying to say
as the start of a whole new formula
like
new year most things are different
for the 21st year/2046
1000 is no longer ur intial maount of deers
it is 2145.5 now
so this is our new initial for the year 2045?
idrk how to explain it properly
yes
and that is bc
the deer is changing to 300
so the old formula isnt consistent anymore
u can think of it so rn were at end of 2045 as 20 years has past
u can say we start at 2046 rn
let end of 2046 be p1
so that means we get our inital value fromthe value in 2045
so do we have to replace our old formula for 2025 with our new iniital in 2045?
i made edits to that whole blob u could read it again
does this kinda clarify it more
yeah
u tell me
yerah
mhmm!
is that the only thing we have to change there
so that saying, whenwe solve for n were gonna get some amount of years BUT REMEMBER IT WILL BE N YEARS AFTER 2045
o okay
what do u think the new formula will ve
do yk why?
its from 2045 onwards right because for the first 20 years 2145.5 was our initial value which means the years after that will be 2045 + n years?
$A_{n}=\left(1.1\right)^{n}\left(2145.5-10Q\right)+10Q$
water beam
good so far
yus
youll later get n=8.9
so remeber that
the answer wont be 8.9
itll be 8.9 years after 2045
since we started from 2045
to get the answer of during 2053
ujst trying makw that part clear first
makes sense?
yep
hm
Q = 300
hm
so we got Q = 300
i have no idea how to use bots
im just gonna
$A_{n}=\left(1.1\right)^{n}\left(2145.5-10(300)\right)+10(300)$
kristy
we have this so far
$A_{n}=\left(1.1\right)^{n}\left(2145.5-3000\right)+3000$
water beam
yuh
were trying to find how many years does it take to get number of deers to be less than 1000 yeah?
yeah
n
since those 2 are the only unknown variables we have left
A_n is the amount of deers left after 2045 + n years
correct
so what will An be then
it has to be a number since we want to solve for n
and to solve for n, n can be the only unknown variavle
the rest has to be some number right
mhmmm
okay
essentially this means how many N years will it take to reach 1000 deers right?
yea
before u start
if i said
what if i wanted to find how long itll take to get the deers to be extinct
what would An be
0
$\left(1.1\right)^{n}\left(2145.5-3000\right)+3000=1000$
water beam
ye
lmk when u get an answer
we want the year but A_n gives us the answer from 2045 + n years so we add n to 2045
do we round down or up our answer for n tho
could u sned the qn again
in some financial math questions when u solve for n sometimes u round down i think
if it refers to time i would say it depends
its more like
u gotta think logically which makes more sense
find the year in which the number od deer in the park will first fall below 1000
that means
if its 8.9
added to 2045
itll be 2053 and some months
this means
itll fall below 1000 some time during 2053
ahh okay
there will be no more deer during the end of this month
not neccessially
there will be less than 1000 deers at the end of the month
oh yeah true
dont misread the qn!
yep
and the qn only wants us to find the year it happens during
in this qn it happens during 2053 right
thus the answer is 2053
yesyes
since the qn only asks for year
then no
i mean u can say like
number of deers will drop below 1000 during 2053
should be sufficient
they got 985 from plugging in n = 8.9 or something?
ya
i got october form the 0.9, 8 years and 0.9 of a year which is ocrober
when they round 8.9 to 9
itll be 985 population of deer
ohh yeah because n is an integer in the question
the 8.9 is when it FIRST goes under 1000
they usbbed n=9
yea
ig it jujst shows like any n number after 8.9, the populaton will be less than 1000
yep yep
this deer question will help me deal with future financial maths questions i think when money is involved it really confuses me but ill just think of deer from now on
thank you π
LMAOO
i mean
maybe
they make money
decnetly enough for a teenager
u must be like rank 1 or something in ur class π
more than mininum wage at kmart or smt
super cracked at maths
i wihs
lol
i think overall im 15 in adv
7th in ext
imtrying to push higher in ext
nice nice u still have a lot of time
qn
do yk how like ur school needs to submit ur ranks anf stuff to nesa by a certain due date
aka early septemner
yeah
so like
there was an error in my ext trial
so that means either marks will be added or removed
to make it equal
it was a 2 marker
so ppl who got marks
either eveyrone will get 0/2 or 2/2 for i
since the qn was wrong
BUT WE ONL FOUND THE ERROR AFTER THE SUBMISSION DATE
rank as in are you referring to year 11 or year 12 final ranks
i think i could go up a rank or 2 after its been fixed if it even can
im atually gonna be like so mad if i dont
bc its unfair
im not entirely sure if you can change the ranks after youve submitted an assessment because my math teacher would always make sure we check our paper before he submits our marks to nesa but i think you can appeal
does ur teacher know>
its the teachers fault π
hm
but itll be unfair cause techcnially i would be ranked higher than
i think you can maybe appeal but if she doesnt know then its worth bringing up with your principal
U WILL BE CRAKED AT MATHS TOO U GOT A DAY
scary
i got a new principal
i have ancient history the day after weeeeeeeeeeeeeeeee wooohoo!!!!!!!!!!
oh my
goodluck to u
yep
oh im not
unless its vectors or projectile
the thing is
i dont do physics
but im going to do year 11 and 12 physics concurrently
ahahahahah
fun
ye
i didint pick physics to do in year11
and
i hate my subejjcts rn
and i appealed and im able to pick up phhiscs now, but i have to sit in both a year 11 and 12 class for phsyocs
economis my opp
i got a very great feeling i will hate it too
but not more than ECONOMCIS
i looked a bit into mod6
magnetic flux
torque
faradays law
idk what they r
but yeah
u do eco too???
ahh
module 6 is the worst thing ever
do u do adv eng
mhm
the crazy part is that i odnt even find eco that bad but the teachers r what makes it like rlly rlly bad
its bad when prelim avg for btoh class was udner 50%
ahh i see
similar situation with physics
my teacher is horrid
yk for the whole year
oh no
i just didnt pay attention to her class
and became my own teacher
and studied at home and outside of school
hey thats me with all my subjejcts
our class average for trials was 51
i managed to get 70
ye ye
rank 4
thats even better
ya i reallyt need that band 6 lmaooo
i have a friend who state ranked physics last year so i go to him for any physics questions π€£ hes a way better teacher than my actual one
i think with rank 4 it should be easier to band 6
dayummm
state ranks crazy
if i get a band 6 π
believe
lmao ye hes currently studying physics in uni rn too
u from james ruse or sum π
yeahbut the thing is our school only got like 2 band 6's in physics last year
wiat no
which is scary
no π
prob not
o h
MAYBE UR COHORT WILL BE TOP 4 BAND 6
π
beleiveee
our school is rlly only good at english advanced
itll all turn out well
i think my school just dpeends on the year
i think in terms of actually teachers englsh and va
agree to disagree
englsih is my biggest opp
more opp than eco
i disagree
theres always a common pattern with people who are really good at math they tend to really dislike english for some reason π
and vice versa
yeahh
sounds like ur the love englsih not math
im opposite lol
if i was as good at math as english id be doing ext π€£
u do ext eng?
i mean if u do physis itll help with ext1 a bit ig
na but i was offered a place to do extension in yr 11 but i declined
ahhh
in hindsight i probably shouldve chosen but its whatever now
it is what it is
yepyep
altho im the problem lol
ah i c
ye true
wake up early tomorrow for some maths and history
wake up early this morning technically
yess
i wanna get 8 hrs for the math test
yeaeyeyeye
me too
fair enouh
u should
yeas
we should sleep now
ye ye
thank u sm for the help
dont forget the stuff i told u for math
npp
ill remember the deer question tomorrow when i see that financial maths q cuz i know theres gonna be one
π
think deer not money
all good
prob should study myself too
yep yep
iβve been procrastinating on doing past papers with helping other ppl instead ππ
LMAO
dont worry ur kindness will come back and pay off maybe
maybe

hopefully
im gaslighting myself in saying
if i can help other ppl th
that means i understand the content well enough
to hopefully avoid less past papers
true!
maybe
ok gonna get off now
if ur past papers include a lot of deer questions even better
goodluck!
ye same
AHAHSHHAAHA
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So, I had similar problems before, but they were as far as x^3 for which I subtracted and added 1, and I used the x^3-1 formula or x^3+1 formula depending on the denominator
Hello Baby Einstein
What do I have to solve?
Just calculating the difference of these 2 integrals
The algebra here outmatches my intuition, as I said, I had two problems for which the formulas we know (as for example x^2-1 or x^3-1) were used
For sure there is a formula for x^2017-1 or x^2018-1 but it's counterproductive to write out thousands of terms and integrate the same terms again
Maybe writing out the formulas for each, integrate and then cancel out the twins?
Combine the two integrals into one integral and factor the numerator
Yea sum of indefinite integrals is the integral of the sum
Should be -x^2018 / 2018 + c then
yep
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x/x = 1
Not "remove" but more like cancel
Because any number divided by itself is 1
yeah like I get that u can cancel the x's out but what does it have to do with x not being 0
like this spart
x/x is only 1 when x is not 0
When x is not 0, x/x is undefined
Because any dividing by 0 is undefined
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this is a box and whisker for diameters of pipes made by companies A and B
can i say one comparison between the diameters is : pipes made by company B have greater diameters than companyA
too vague
..
i imagine youre trying to say, Company B offers pipes of larger diameter than A does
its not quite the same, as you were just describing general pipes (which implies all of them) are wider, while im saying they just have wider pipes available
i can say that?
the range of the diameters
company B offers wider
and narrower
you can say that
or you can just say company B produced a wider range of diameters for pipes
as a general statement
No problem
@past birch Has your question been resolved?
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hello, given n! > b^n , b element of N i should proove via induction as well as via prime factorisation that for b = 7, 18! > 7^18 how to do that? (exercise in german, i hope it is still clear what is asked)
@cosmic cairn Has your question been resolved?
so b is fixed and the induction needs to be proofen for n -> n+1
but n0 > b
and yes for n0 = 1 this doesnt hold
so if i choose n0 = 1 there is no b so that 1 > b
Are you asking about part a) or b)?
so my question is refering especially to the part in b) where one should proofe 18! > 7^18 for the induction start/assumption for b = 7 via prime factorization
i have a different approach, where i could more or less estimate the result is correct (i also confirmed via wolfram alpha, that it is in fact correct)
i just dont see how to do it with prime factorization...
@cosmic cairn Has your question been resolved?
@cosmic cairn Has your question been resolved?
@cosmic cairn Has your question been resolved?
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i know this is a bit basic but i cant exactly figure it out: suppose BC is a chord of circle A, and that chord EF is perpendicular to BC at D. how do you show precisely that ED is maximized when EF is a diameter?
What type of class is this for?
itβs just needed for a small part of a contest problem I did in my math team. (the contest was already finished)
Iβm just trying to see why it makes sense for sure
even though intuitively I can definitely see
Offhand, I would say it's a matter of showing that ED is shorter than HJ in this image for whenver EF is not on the diameter.
@sharp lotus Has your question been resolved?
You should be able to prove that x is less than r if the angle is greater than 0 degrees.
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isnβt drawing that perpendicular and creating that setup already sort of assuming the fact?
@charred gale Has your question been resolved?
<@&286206848099549185> I think I got another point but im not sure if this observation really helps:
- S must have at least |W| black squares since it has an equal amount of black and white squares.
I think the tricky part is saying that of these black squares, they are really adjacent to the white squares. Maybe it follows by two coloring but I feel I cant make a rigorous argument
do we get to use the obvious fact about a checkerboard?
Which perpendicular line? Your question specifically said that chord EF is perpendicular to BC at D.
wdym obvious fact?
do you mean how its layed out like
B W B W
W B W B
..............? Because i would guess so
i represented it as a graph with horizontal and vertical edges
from E to K that it lies in the circle like that? or nah?
r u making any assumptions in that or nah
but then yeah that works
No. Wherever E lies on the circle, there is a corresponding point on a diameter line. I just happen to orient the diameter line so that it is horizontal.
this is kinda stupid but what if i thought the perpendicular was past H then it wouldnt exactly work? if u wanted to be very picky? maybe im overcomplicating things
You're overthinking this. You can presume the diameter line HI is parallel with EF because that question states that ED is maximized when EF is a diameter line. The naming of HI is arbitrary. I could have named the endpoints as E' and F'.
@charred gale pls make a new channel
@charred gale Has your question been resolved?
Ok
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I don't understand how this is infinite possibilities... π¦
should be pretty easy
bc z can be anything
can you write out that augmented matrix as a system of linear equations?
u practically wrote out the solution
so you have 0*z = 0. what values of z satisfy that equation?
bro got us frozen
well a solution is in the form (x,y,z). you have written out the form that y and z can take, but what about x?
idk about x
i wouldn't understand x = x
maybe let's write it out in full then:
0x + 1y + 0z = -8
0x + 0y + 1z = 9
sure
wait let's make this simpler
how about every time there's a row of 0 it means that it's infinite?
except if last collum is 0=other than 0
that's not necessarily true, though:
1x + 0y + 0z = 1
0x + 1y + 0z = 1
0x + 0y + 1z = 1
0x + 0y + 0z = 0
only has 1 solution, despite having a row of 0s
if you have a column of 0s (which is not the augmented column), then that variable can be anything, yes
so infinite?
yep
ty man that'll help me
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Can anyone verify these are correct?
You're more likely to get a response if you just upload one at a time
@full quarry Has your question been resolved?
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does anyone have any ideas about making a summation or generating function similar to the binomial formula to create a polynomial from repeatedly inputting a polynomial into itself n number of times, like what is pictured
although i also want to do it for (x^2+x)
This is asking about the recursion $$f_n (x)=(f_{n-1} (x))^2+1$$ with $f_1=x^2+1$
Civil Service Pigeon
yessir
Given that $a_{n+1}=a_n ^2+c$ only has known closed forms for $c=-2, 0$, I doubt youβre going to be able to find a closed form
Civil Service Pigeon
figures
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Can someone please help me solve 5a/3+1/2=8
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
3
what is the answer you got?
I got a=4.5 but the sheet says x=14
wait
lemme check its the right thing first
because a x answer doesnt make sense
Nevermind!
it was q 11 and I was right
nvm, thanks!
Have a great day/night!
At least I wasnt wrong π
u 2 π π
Closed by @lavish rivet
Use .reopen if this was a mistake.
.reopen
β
could someone please help me with Q12? I cant land the correct answer
its 5x/2-3=7/2
ans says x=2.6
5x/2 = 7/2 + 6/2 = 13/2
yeah x = 13/5 = 2.6
that's correct
Yep, I just cant figure how to get that
do you understand this step at least?
Im not sure why you did the 6/2 part
we add 3 to both sides, so that we have 5x/2 - 3 + 3 on the left
on the right we have 7/2 + 3
to simplify that we can do 7/2 + 6/2, write 3 as 6/2
So, we transpose it?
what do you mean by transpose?
put like terms on each others sides