#help-23
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(also, don't forget to divide the diameter by 2, and when putting it to the equation, square the radius)
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Question regarding Kolmogorov's theorem about laws of large numbers and theorem about martingales.
I researched a bit on my own but I want hint or confirmation I am going in right way.
I found I need:
- obviously ones in topic of question,
- theorem about convergence of martingales,
- borel-cantelli lemma,
- theorem about 3 ranges of kolmogorov,
- chebyshev inequality,
- theorem about convergence of martingales (Doob's),
- theorem about expected value,
- random valubes
- independent random variables
What sort of definitions, theorems, lemma and perhaps examples i should/could use showing connections between martingales about laws of large numbers? Are those enough or am I missing something?
@jagged spruce Has your question been resolved?
<@&286206848099549185>
You can also try using the topic chanels
Yeah, I tried my chances in probability channel with no response, so since I just need a reasurence that I am going right way, I thought to ask here.
@jagged spruce Has your question been resolved?
.
@jagged spruce Has your question been resolved?
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Can someone please explain to me in simple terms why some series that as they increase get close to 0 still diverge? Series like 1/n, sqrt n/n
What reason do we have to believe that all series whose terms approach 0 converge? Why should adding infinitely many terms, although close to 0, result in some finite value?
they just dont get to zero "fast enough"
i mean aren't they convergent if after a certain number of terms the distance between any 2 terms is smaller than epsilon
or do i have it wrong
this sounds more like convergence of sequence
ohhh
yeah I'm learning these to retake an exam that i failed so i'm kinda lost through them
series converges iff the sequence of its partial sums converges
I was doing the comparison with a limit criterium and couldn't understand why bn being 1/n or sqrtn/n would result in divergence
integral test might be a good option for 1/n
and sqrt(n) / n >= 1/n, so once you find out that 1/n diverges, this can be done by comparision
i see
in general, 1/n^p converges only for p > 1
i think i kinda get the gist of it now more or less.. I guess you start recognizing them more easily with practice
and diverges for p <= 1
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angle ABC = 0.5 into what ?
can you take a pic of waht the site is saying
oh
is it to be corrected?
idk what it will be tho
yeah
like i'ma write the right thing down
in my notebook
or i cri
≅
nice sign
the stuff they wrote doesn't match their colouring
look up outside angles theorem, circle
I mean we can completely alter it, can't we?
for that one, looks like they mixed up the positions of points A and B
and for the next one they mixed up the positions of D and E
please do
just tell me what's angle ABC
look up
outside angles theorem, circle
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whats the difference between this ∈ and the other one that has a line under it
That E thing means belongs to
This means is subset or equal to
The symbol here means (belongs to) or (element of)
Whereas the symbol in image means (is a subset of)
Or equals to
Line under
E.g.
1 ∈ N, pi ∈ R, 3/4 ∈ Q
N ⊆ Z, Z ⊆ Q, Q ⊆ R
Ur just making it hard for him to understand
if you have a bag of marbles, then each marble is an element of the bag (∈), on the other hand if you take another bag and put copies of some of the marbles from the first bag in there, the new bag is a subset of the original bag (⊆)
subset usually means subseteq
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They mean to accelerate it
well those would be the same amount of force either way
@hasty mason Has your question been resolved?
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why are these triangle similar i know the answer is 80
because they have a side in common (CB) and two angles in common
oh yeah similar, not congruent
they are congruent too
wait we dont know the angles though
i think i meant to say congruent not similar
side lenghts are all same
assuming CD and AB are parallel lines, the line CB will produce the same angles
we only see 2 sides are equals how do we know the 3rd is equal
it is common in both the triangles
we arent given this information
oh yeah im stupid
so sss is congruency
what does congruency and similarity mean
is congruency that they are similar
i mean equal
and similar is like same ratios
two triangles are similar if all of their angles are equal
two triangles are congruent if they have all angles equal and all sides equal too
ok yeah thanks
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I need help
Not for a quiz or test
I am incredibly bad at math and need someone to break this down step by step please
So there is an equation and you can do the same modifications to the both sides: First try to multiple both sides by 3 to get rid of division
After multiflying please let me know what do you find as result
@limpid cosmos Has your question been resolved?
Stil need help?
Multiply both sides by 3 to get $y+1 = -15y-15$
747244351179980930
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No thank you thanks for the help
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9 Please
Table
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
4
@glad yacht Has your question been resolved?
<@&286206848099549185>
What is the issue?
Show your work, and if possible, explain where you are stuck.
Above
this one?
Yes
number 9, lets see
ok
So for 9a: they ask what is the toll for entering at exit 8 and leaving at exit 15?
Do you have an idea on how to start this?
Im rpetty sure its using Exit 8 to ten and then 10 to 15 but Im not confident what proeprty that would be
1.25$
you did (price of 8 + price of 10) + (price of 10 + price of 15)
yes
so that is the first part of 9a
now
you have to find equivalent amounts
where tolls of entrance and exit = $1.25
so
what tolls get $1.25 as a total?
1:00$ + 0.25$
0.50$
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How do you find the piecewise function for this graph:
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
2
What have you done so far?
I know one of the functions is a square root function but im not sure about the others
One equation is square root of x + 1 ; x > -1
The other one looks like a rational function
Specifically, some transformation of 1/x
Oh ok then what abt the one in the middle
i believe that is part oof the fxn on the left
x = -3 is a vertical asymptote
for the fxn
Ohhhh that makes more sense
smtg like 1/x+c
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they halve the coefficient in order to complete the square
Why do they need to cpmplete the square
to rewrite the equation in standard form so that p can be solved for (equated to r)
Oh ok
So then in the next step why does x^2 become just x
They probably factored it
I feel like this solution is missing some parentheses
so like (x+7p)^2 would equal to x^2+14px+49p^2
Yeah I get that part
But then wouldn't it have to be x^2+7p^2
And why did the 9p^2 become 3p^2
Ok
So if I encounter this kind of problem again i just do exakly the same thing as the explanation?
i mean if the problem is exactly the same format, sure
ok
make sure you understand why you’re doing these steps tho
Can you also help me with this
makes it easier to apply to other questions especially similar but not the same ones
yeah I understood everything up until the part where you said they're prob missing parenthesis
Thanks
ok, give me some time to do it first
Go ahead, take your time
ok so
f(-9) equals f(3)
you can just plug in these x values for f(x) and equate them to solve for a
then they give you that it has a vertex at (h,k) and k<0
so you then convert the equation into vertex form
f(x)=a(x-h)^2+k iirc
How do I solve for a if c is still a variable
c cancels out when you equate the two functions
since its a constant not a coefficient
Ohhh ok
anyway
to solve for h
im not too sure on what that equation is
something like -b/2a
plug in the known values (a is 2/3 btw)
to this
Oh oops
I do this for both -9 and 3?
How did you get 2/3 😭
Sorry I'm rlly struggling with this
remember -9 is squared, not multiplied by 2
Yes
Then it would be 81 right
and then 81a-9a=72a
and now 72a=48
Wait omg
Oops
mhm
What is -b
-b is -4
Oh righht
so solving for h, its -4/4/3
mhm
which is 3
Yes
So then
f(x)= 2/3 (3+3)^2+k
2/3 (36)?
which is
24
so k =-24?
And the vertex qeuals to (-3,-24)
wait not so fast
Do I include c
yes
ok
remember to write k as an unknown btw
24 shouldn’t be negative
18+c=24+k -> c-6=k
yes
Okok
which means both i and ii are wrong
Np
Ok yeah now that I'm looking at some of these explanations theyre missing parenthesis
Which I didn't earlier some how
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Could anyone help understand this notation, I understand just negate the statement but some of the notation confuses me
@safe sparrow Has your question been resolved?
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sorry i dont know
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Could anyone explain why A^T . A has to be invertible and well conditioned for the normal equation? (And the connection with eigenvalues)
It does? What if A=0?
I am not sure, I'm specifically referring to this slide
Point 1: A^T A should be invertible makes sense
But Point 2 and Point 3 I don't have the intuition for
I found this, but its not directly linked to normal equation
I may have overlooked something but it doesn't seem particularly helpful, can you give a specific section there?
i mean invertibility of A^T A is all you need to solve the equation for u and v
but in life, you'd want to be able to numerically calculate these things using a computer or something
@patent topaz Has your question been resolved?
the other two conditions are just saying that if the eigenvalues are too small or far apart in magnitude, you might not get good numerical results
are there any chapters i can read to better understand the other two conditions?
thanks btw!
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How to find the maximum for this expression: (24+12sin(x))(2cos(x))
I found the derivative to be 48cos(x)+24sin(x)cos(x) and set the equation to zero but got pi/2, which, when plugging back in gives 0
which is not the maximum of that expression
isnt 48cos(x)+24sin(x)cos(x) just the expansion of it?
wait
ok yeah let me solve it again
I got -48sin(x)+24cos^2(x)-24sin^2(x)
oh that's just correct
nvm
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Guys, do we not include the negative for b?
its being squared
it wont matter as it will turn out positive
$[-(k+2)]^2 = (-1)^2 * (k+2)^2$
Galaxy
Ohhhh
Okok thankssss
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very quick question for my sleep deprived brain
is it possible to do log 7 right away and what would that look like?
like i get that you want to add exponents in LHS together so you get 7^1/2 = 7^x
7 log and then 1/2 = x
but is it possible to do it another way?
you could, but you would be effectively doing the same thing
what would that look like then? because i did kinda try that route without success hence the asking
because i 7log the entire LHS and entire RHS right?
so i get
log(7^(-/2) * 7^4) = log(7^x)
use log(ab) = log(a) + log(b)
log(7^(-7/2)) + log(7^4) = log(7^x)
use log(a^b) = blog(a)
-7/2 + 4 = x
1/2 = x
(all these logs have base 7)
oh so
hm
but this is the correct interpretation so far?
or you never take it up in the exponent it seems like
so you're saying like this then?
so if I have e^x = 5
i do ln ( e^x) = ln (5)
not ln ^ (e^x) = ln^5
not sure why i raise it to the power then
nvm im stopid i guess
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Mitochondria is the power house of the cell
please do not post spam.
@timid flume Has your question been resolved?
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Given that the radius of the small circle is 1, find the area of the shaded region (there are 6 small circles total and 1 big circle)
and the two circles next to one circle intersect at the circle's center
i got that the radius of the big circle is sqrt(3)
okay so now i got the area of the flower looking thing in the middle to be 2pi - 3sqrt(3)
got it
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what is this notation
@elder cypress Has your question been resolved?
@elder cypress Has your question been resolved?
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could you provide with a source to where you found this
Wait
The following is a list of significant formulae involving the mathematical constant π. Many of these formulae can be found in the article Pi, or the article Approximations of π.
Check the "other infinite series" section
The screenshot is of the series involving rising factorials
@elder cypress Has your question been resolved?
that answers the question doesn't it
the subscript is the rising factorial, the superscript is just "to the power of two"
Why would they write 1/2 to the power of two
And not 1/4
Or is the square after the rising factorial
i believe so, yes
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I need help with a soroban addition problem.
103 + 48 + 74
I know addition is commutative, but I cannot get to the answer if I do (103 + 48) + 74 instead of (103 + 74) + 48.
I appreciate if you could send me a video showing how to move the pieces in this case 🙏
@ruby delta Has your question been resolved?
Do you need help with the commutative property or the puzzle?
the puzzle
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What method has been used here with the lambdas and mu's? I think I've done it a valid (different) way but no idea whats going in the model answer
like why would you write A^2 as λA + μI
they previously figured out that you can write A^(k+1) with A and A^2
so if you can write the A^2 in terms of I and A, you are done
Ohh ok thanks
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how does he go from 3pi/2 to 5pi/6
Those are two different questions
For which part?
You have sinx = -1 and sinx = 1/2
Both are solutions to the original problem
then whats 5pi/6
That is also a solution to it
how
Do you know the property that sin(x) = sin(pi - x)?
what property is that
Or at least when you solve a sin problem you get the first solution x from doing arcsin and then you can do combinations of plus and minus 2pi along with pi - x to get every other solution
Sinx = -1
,w tan(3pi/2)+sec(3pi/2)=2cos (3pi/2)
Am i missing something? I might i am about to sleep
Give me a sec
so 5pi/6 doesnt work?
Well that isn’t a solution to sinx = -1
It’s one of the solutions to sinx = 1/2
So it will work
None of the solutions to sinx = -1 will work
why is that
Because any solutions to sinx = -1 are solutions to cosx = 0
still confused
And there are cosx terms in the denominators of that equation
What happens when you try and evaluate secx at an x value where cosx is 0?
Yeah
Yeah basically
Since technically you are only solving the equation that you get after multiplying both sides by cosx
You would have to divide both sides of the equation you solved by cosx to get back to the original equation
And so any solutions to the original equation would have to be a solution of the equation you just solved and each solution would also have to be one where cosx isnt 0, otherwise you are dividing by 0 to get back to the original equation
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alguien que hable spanish?
bot
umpoco, manda su cuestion
@pure garnet Has your question been resolved?
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could someone please tell me why? and how can i tell that i should do this?
what sre you not understanding by chance?
why 2 is factored out
so we can simplify yeah but how can i tell? i got alot of my practice questions wrong because of this part
$-10=2\cdot(-5)$ and $2\sqrt{5}=2\cdot\sqrt5$, so $-10+2\sqrt{5}=2\cdot(-5)+2\cdot\sqrt5$ and because both expressions have a 2, you can factor it out and just add $-5$ and $\sqrt5$
SWR
so I'll just look for factors?
yup
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can anyone solve this for me please?
uh doesent that mean $\frac{x^2-a^2}{x-a}=10$ or am i stupid
Skill_Issue
@hard turtle Has your question been resolved?
NO I WAS DUMB
ITS a = 5
OIAJIARJIAJIR
THANK U THO
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use the given point
U can’t find equation of line with just -4,0
you have the derivative
What about the derivative
well why did you even differentiate?
Cause it’s a differentiation paper
do you know the relation between derivatives and slope
its known as the gradient function
you can use that to determine the slope at your point
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✅
np. should always try to apply basic definitions/properties
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If possible could I get help on this question
What have you tried?
@buoyant cedar Has your question been resolved?
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whats this function
whats the bar x=x0
the bar means it is evaluated at a specific point x = x0
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shadow D:
yeah mb the light was like really weird
Have you found smt already?
i split it into 4 triangles idk if u can see it that well
split it into more triangles
wait how do u know theyre all equal?
midpoints with midpoints with midpoints
this, plus symmetry of the construction
thank god you brought this up lmao
i was thinking finding blue then red then area lmao
Btw, if you want to prove that all of the triangles are equal, focus on one of the purple triangles. Since the whole shape is a regular hexagon, the purple triangle must be equilateral (equal sides)
and if you ccan prove that all the triangles inside it are congreunt, then by symmetry it extends to every other triangle
and to actually prove it, just look at the midpoints, look for parallel lines and maybe few angles
the whole thing is so symmetrical that there are thousands of ways to prove it
Also, we could find the size of triangle's side form formula S = sqrt(3)/4 * a^2
This side should be average of hexagon's side and hexagon's diagonal (which is twice bigger than it's side), so we can calculate hexagon's side b
Finally there is formula for finding area for arbitrary polygons with polygon side b and amount of sides n (in our case, 6 sides): S = (n * b^2) / (4 * tan( 180degree / n))
But graphical solution like@brave wolf give is way more convenient😅
wait im kinda dumb i dont rlly understand the midpoint thingys 😭 if u could kinda explain it a bit that would be great
@brave wolf ?
I'm back
it tells us that the vertices of triangle are at midpoints of the sides
hence the green and blue sides must be the same
But we also know that yellow-green angle and orange-green angle are 60°
that's again more or less by construction
same for purple-light blue and dark blue - light blue angles
and yellow, orange, purple, dark blue are also of same length
hence those 2 small triangles are equilateral and furthermore congruent
It's hard to explain it because i cant explicitly point at lines and stuff, and there is not that many colors to color everything
how do we know yellow and purple are parallel?
there is a trapezium hidden
right here
we know that the purple sides are equal, and orange angles too
i think i get it a bit but dou thinku could help me with one more?
<@&286206848099549185> ?
<@&286206848099549185> ples
@tropic charm Has your question been resolved?
6^8?
It's probably incorrect tho
20?
for what
Answer
120?
are you guessing
No
where's 120 from
I was counting
yeah
how many corners are in a cube?
8
let dice speak
8
so if each corner has a face-diagonal triangle that would single it out,
I was also trying to solve it 😦
this isnt your channel
Sowwy

and there are 8 corners,
how many face-diagonals are there?
12?
how does it turn from 8 to 12?
Im naming the triangles by the name that goes along with them
how many three-face-diagonal triangles are there?
@tropic charm
ye im trying to look at it rn
would there be 1 for every corner?
yea
are there any more than 1 per corner?
lets consider how that would be possible
can you draw a second one that hasnt already been counted?
you can go diagonally across the base and back up either way for 2?
dont they all use corners?
We are talking about 1 corner
Can you find any more triangles which single out that corner?
@left gyro where you at bruv?
if you want to continue with dice, go continue, theres nothing stopping you
wdym by single out? cause they all use corners mb im a bit dumb
No I don't have enough braincells that I could help him
Im the typa guy who counts in the math problems
@left gyro help @tropic charm bruh
you mean this?
from the same corner thats shown diagonally across
no
draw in the three corners that you are using as the vertices of the triangle for me
those were already counted
they single out the lower-left corner and the lower-right corner
do you know what I mean by "single out a corner"?
yeah i think thats wjhat im confused abt
i think i misunderstood what you were asking
mb, what is it meant to mean
this triangle has a front and a back, right?
the yellow point is in front of the triangle
the blue points are behind the triangle
the red points are on the side of the triangle
do you understand?
yeah
you need to reply to the correct message
its easier to not need to reply to a specific message
one point is in front of this red triangle
if I choose this triangle, you can color in the points the same way
but theres only one such triangle for each of the points
right
yes
i think i understand this one now but theres still 2 more
the next one should be easier
this wants you to use two edges
then to connect them with a face diagonal
to form a triangle
this kind of triangle is flat on the face
oh that should just be 12 right
so is there an easy way to tell how many there are?
lets keep going
for an edge base, there are two vertex tips that are possible
now how many edges are in a cube?
12
each edge can work as a base of the triangle
each edge has two corners it can use as the tip of the triangle
yes?
yeah
so how many triangles total?
24?
so the answer is 56?
yes
np
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guys how am i wrong?
so your solution is on the left?
(2sqrt(5))^2 is not 50
4sqrt(2) * 3sqrt(2) isn't 24sqrt(2) either
yes
ohhhh i miscalculated it
oooo okayokay
my calculator won't give me an answer with square roots 😭 i think it might be bcs of some miscalculations
i'm gonna fix it first
i don't know how to deal with square roots 
try fix those mistakes mentioned first
np
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@sinful wyvern Has your question been resolved?
bro in this 2^1/2 * 2^1/2 = 2 and wht u have gotten in x1 and x2 respectively are just approximations
help me with sets pls
why is there a + for the sqrt(10) in your x_2
ok, i suppose that works
For the x2, does the negative means the whole thing is being times with negative?
Like -sqrt(22) and -sqrt(10) over -2
no
multiple to one of the numerator or denominator if you want to distribute it
not both
Ohhh
We doing quadratic? Damn I remember grade 7
Ohhh so if multiply with numerator, the sqrt(22) will be negative, and sqrt(10) will be negative too?
yes
Yeaah quadratic
Ohhh okk soo my answer matches the answer keyy
Thank you sosoo much everyone who helpedd 
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What statistical model could I use to predict tarantula molting dates and how much they'll grow on that molt
@warped rampart Has your question been resolved?
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@keen trail Has your question been resolved?
the pdf of a continuous unifon (a,b) is
why?
b) is weird because i agree you seem to get P(X=0) but for continuous distribution function P(X=x)=0
only P(x<X<y) has non zero probability
Consider first if a<2b. if x < a , X can’t be lower than a>x so P(X<x)=0 similarly if x > 2b, X will always be less than x so P(X<x)=1
does that make sense?
this is finding the cdf?
yeah
why did you find from a to x instead of from a to 2b
you're answering part (a) right?
integrating a to 2b would be 1
as you would “sum” the probability that X takes all it’s possible values
wait so the cdf isn't a piecewise function but just a fraction?
that’s the case when x is between a and 2b if x is less than a with a < 2b then F_X(x)=0.
yea if it's between a and 2b, i still don't understand why wouldn't you integrate from a to 2b
and instead just integrate from a to x
the density of a continuous df when integrated on a range [a,b] gives you P(a<X<b) by definition almost like that’s what the density is. so if since we want P(X<x) with x between a and 2b then we set the bounds accordingly.
isn't P(X<x) with x between a and 2b the same as P(a<X<2b)
therefore you integrate from a to 2b
no these 2 interval are not the same. one ask what’s the chance the random quantity X is less than x the other one what’s the probability that it’s in the range [a,2b] the two interval mesured by the probability function P are not the same.
okay so why is it to find P(X<x) with a<x<2b, you integrate from a to x?
density means probability?
no f_X(x) the pdf probability density function. it’s what the mass function for discrete random variables is for continuous random variables
sorry but i gtg, feel free to ping helper
hmm i think i got it
can any <@&286206848099549185> help with parts (b) and (c)?
@keen trail Has your question been resolved?
i blundered sorry, for b) i think the awnser is 0 because as i said for a continuous random variable P(X=x)=0 only P(x<X<y) can be positive in contrast to discrete random variables.
for c) the case b >= a make sense but b < a i’m not too sure because from my definition (Wikipedia) the parameter a must be less than b.
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I need help with a math packet
I have a seven page math packet
a or the
but its a algebra packet
its a packet so I can be prepared for a test I have to do to get into geometry honors
interesting
Can u explain to me what he is saying 
he has a set of math exercises, and he is expected to do them so that he will be prepared for the test
moreover this test will enable him to get into the geometry honors
Ohhhh so where did math packet come from 
maybe the professor gave it to him one day
but these further questions have to be done to @vapid leaf
Understandable
@vapid leaf Has your question been resolved?
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How do I do this?
What have u tried
I cannot think of anything rn
dam
Hii
partial fractions should work here, although it would probably be really tedious
A little too tedious
Another tedious method will be by parts

There should be some trick here which I can't see
Yeah I've done that much
no
split the fraction
do not do that
what
start by rewriting the numerator in terms of a(2v + 1) + b
where a and b are constants
- c*
that's not even the full solution
Got it, thanks.
said that but ok
You can manipulate, it if it's easy
whats 1+1 help😰
0
still tho
Wasn't 1+1 = 1 ?
Its 1?
I tried it by parts and now I have a even harder integral to solve 
i thought it was 11
I think you re using XOR gate so 1+1 = 0
huhh
Nah it can be 10, 1, 0 never 11
10
Unless you define some special "+"
Nah I'm a bot
Huh !?
And he's trolling.
Nah I'm absolutely not
It's a bot which executes xor gate on repeat 😭
I have valid points to proof every statement
oh
bitch
💀
Erm
😭😭😭
i have amnesia
NVM i think it's insulting*
so OF COURSE I FELL FOR THAT
Isn't amnesia memory loss
What is dementia?
Idk how this even relates
I think both are nearly same
Oh
oh
Quite a imp discussion on the Millenium problem 1+1
yes, I will talk to my professor about it surely
The debate about 1+1 never ends
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hi
Which problem/question is presenting the most trouble?
honestly all i just wanna know if i did it right or not
For A, the graph doesn't show any signs of stopping at 4
And -14 is a closed circle, meaning it is part of the domain (parentheses mean that the point is not part of the interval/domain)
so a is right?
Well, the initial value, or start of the interval for the domain is correct, the symbol for the start is incorrect, and the value for the end of the interval isn't completely correct
yeah bro i did hella bad
It's all good, dw
For A, whenever you have a value of infinity, you can only put parentheses bc brackets mean you include infinity, which won't work in this case, as infinity isn't 1 number, it's all of them
So by putting infinity in parentheses, you say that you include all numbers from -14 to whatever the last number is
Out of all countable numbers
Tbh, I could be explaining this wrong, but infinity won't have brackets
is this good?
@midnight mirage Has your question been resolved?
which part is the problem? @midnight mirage
honestly all of them, i just have been very sick so i missed class a lot
tried learning online but i just didnt get it :(
I see
i had to do like 20 math homework, just this question and another graph question i got wrong sadly
okay, let's start with a)
for sure!
what's the domain of f(x)?
can you answer that?
if not, then I ask that you state the definition of domain 
so the asymptope is at 6
mhm
so the domain is [inifity , 6) ?
assuming the graph starts from the left, [neative infinty , 6 )?
well, f(x) is defined for all values in each of those intervals
so the domain should include both of them
oh

i am also excited to see his answer
[-infnity , 6) U (6, infnity]?

I GOT IT RIGHT??
yes, but use ( and ) instead of [ and ] 
we can't include infinity as part of the domain
it's not a real number
so (-infinity , 6) (6, inifinity) ?
yup!
okay, part b)

