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why does $10e^{-t}$ antiderivative become $-10e^{-t}$
wakamole
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can sum1 help me
i needa find x
equilateral triangle
its isosceles
since its isosceles, the bottom 2 angles must be equal
which would then mean the third angle is equal to 180-2*60
which is 60
so all three angles are 60
and only equilateral triangles have three 60 degree angles
oh
you could have also used law of sines if you didn’t realize it was equilateral
and gotten the same answer
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Can someone teach me how to set up a differential equation for this question?
There are too many variables and I am confused by the prompt
@reef aspen Has your question been resolved?
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,
an issue on function solution:
when i am doing a problem like :
f(x) is a function on R.For any a, b ∈ R, f(a+b)+f(a-b)=2f(a)*f(b).f(0)≠0, and there exists a positive m,s.t. f(m) = 0.Find a T(T≠0), s.t. f(x+T)=f(x).
the solution in ans for reference is like:
f(0+0)+f(0-0)=2f(0)*f(0).
∴f(0)[f(0)-1]=0, and f(0)≠0, ∴ f(0) = 1.
For any a ∈ R, f(0+a) + f(0-a) = 2f(0)*f(a), ∴f(a)+f(-a)=2f(a),
∴f(a)=f(-a), indicating that f(x) is an even function on R.
∵f(m)=0,∴f(x+m+m)+f(x+m-m)=2f(x+m)*f(m)=0,
∴f(x+2m)+f(x)=0,∴f(x+2m)=-f(x).
and my issue caused here
in the ref sol it replaces x in the term 'f(x+2m)=-f(x)' with x + 2m and gets:
f(x+4m)=-f(x+2m)=f(x).
so is the replacement legal?
@random helm Has your question been resolved?
yes
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guys is that a math question or not? cause it is in the middle of my homework
help 😐
Translate?
nah just look at the numbers these words are from another question
Okay, this looks like some pattern analysis
What are you supposed to do with the numbers
I remember answering it 6 before but I forgot my logic in answering it 
And, was that correct?
yeah
Okay, so we are now certain that we gotta look for some logic herr
As I said
I think there is a relation between 9 and 3 to give us 5 but I don't really know what
This is hard bruh
right grid has same pattern as left grid?
Are you sure that arabic text ain't related to this?
nope
Its just says find the answer :|||
Oh
You must remember some bits of the logic you thought
Like something
<@&286206848099549185>
<@&286206848099549185>
maybe show us the other square?
the one with 5, 7, 2,6 ?
its another question
and the arabic text doesn't lead to anything
there is a relation between 9 and 3 that gives us 5
I think
these both have the same idea, the first picture you multiply 1 and 6 then add one to get seven, and multiply 4 and 3 to get 12 then add one to get 13, so the answer of the first picture is 1
the second one , when you look at the first square, 8+9 = 17 , add the sveen and carry the one, so 9 would be 10 then add it to 7 so it would be 17, carry the 1 and 4 would be 5 then 5 + 3= 8
so in the second picture the answer is 6
<@&286206848099549185>
@chilly wraith Has your question been resolved?
This one is really tough, for it is not solved still
I have no idea how to initiate this
wait I solved it 
962 - 568 = 394
726 - 289 = 437
so the answer 6 is correct
FINALLY
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This was a very good question actually
How simple shit, but felt like impossible to find out
Opens up the mind
Good you find it out yourself
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How to solve this limit?
[\lim_{n\to\infty}n\tan\left(\frac{\pi}{4n}\right)]
Slowaq
What have you tried so far?
As a start maybe take advantage of tan(x) = sin(x)/cos(x)
Uh if it’s of the appropriate form I suppose yeah, but not really needed here
ah yes i can try that
I.e tanx/x goes to 1, which is implicitly the same thing as above
Yes you would if you’re not aware of that fact
Mmm..
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can someone explain how this result in blue is reached
I am also curious why the way to get to the result is different from a and b
but more importantly how is a done
<@&286206848099549185>
@agile wraith Has your question been resolved?
It’s just the matrix such that the basis vectors of B are the columns of the matrix.
Applying this to vectors in the space B gets you to canonical space (which is C in this case). To get a vector in canonical space to B space you would apply the inverse which is what is happening in (b)
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all correct?
👍
is Angle 1 and 4 alternate interior or exterior? ill answer either way cause both are congruent anyway based on theorem
erm
they'll be equal
but are not alternate angles
1+2 and 3+4 will be
wait holdon, what theorem is this
like i know they’re perpendicular; but how do we know that they’re equal?
since 2 and 3 are alternate angles
they'll be equal
ohhhh
and hence cancels out in this equation
exterior?
?
they''ll all be interior
Exterior ones are greater than 90 degrees
does it also apply in this case? the one next to the 5x - 20 and the one before 3(x + 10) are exterior aswell and they look like acute angles
also; theres like a tip given by someone that if u have 2 transversal lines; essentially “cancel out one first” so that you can focus on that first set of angles or something
its hard to explain in this but here is what i mean
Obtuse* you meant
I got what you mean
It is completely your choice how you want to understand it
both are correct
alr so recap:
Alternating (Interior Exterior) and Corresponding angles are congruent
Same Side Interior-Exterior Angles are supplementary
@twin prawn Has your question been resolved?
sorry one last thngg
is this correct? heres how i got it (sorry for blurry pic btw)
3 and 4 are vertical due to them being nonadjacent; 1 and 2 are interior alternates
since there is a right angle in between angle 3 and 2 therefore 3 and 2 must equate to 90 (ive experienced this problem before and someone told be that if an angle is 90 degrees; the angles surrounding it must equate to 90, though idk what statement (postu, theo, coro) it is)
It is just that the Sum of all the angles of any triangle is 180 degrees
since one of them is 90 degrees then other has to be add upto 90 as well
gotcha
this is a right triangle correct
yeah
and is there any other way to explain without having to use polygons (unit 1: lines and angles hehe)
I don't think so
maybe trigonometry
if lenghts are given
pythagorean theorem?
or at least ratio of lenghts is given
That works only for lengths of a right triangle only
it has nothing muchh to do with angle
gotcha
however there is a law of cosine
I am not sure if you know about it or not
ive heard somehwere but defo forgot
It's just Big Daddy of Pythagoras theorem
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Ummm
I set f(x) and h(x) equal and got 0 and -1 as solutions
How do I prove it with that? 😅
try turning one of the functions into the other
uhhh
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
oh mb
Wym by rationalize sry
I will drop another hint: u have to use the a^2 - b^2 identity
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letters of word PROBABILITY are arranged. the chance that two B and two I occur together.
so far I've solved is that:
we take BB as W and II as X, so we have to arrange PROWXALTY (9 letters). so total ways 9! and to arrange W and X, further 2! => total ways 9!×2!. but there are 2 B and 2 I, they are repeated, so we divide by 2!×2!. => total ways 9!×2!/(2!×2!).
and total cases of usual word PROBABILITY= 11!/(2!×2!)
cali_owt
its weird putting the two I’s together
they can be separate
if you say theyre x and put it together youre getting rid of combs
buy my answer is wrong
there arent a further 2! ways to arrange W and X there should be a further 2! for W and 2! for X, but those cases should have been ignored in the first place tbh
can you explain it more
you sound right, but i don't understand
well W is BB which has 2! ways of being arranged and X is II which has another 2! ways of being arranged
but u can just ignore them since it doesnt matter which B is first its still BB
so shouldnt it be 2!×2!×2!.
first for W and X, and then 2! each for letter inside W and X
but we also have to divide by repeated cases. 2 B and 2 I mean , divide by 2!×2!
yes but u could have ignored it in the first place
so it cancels out
there was no point in multiplying by 2!2! only to then divide by 2!2!
apart from numerical significance, I need to get concept right
so what will be final cases
the concept is you said BB and BB, but because BB, its divide by 2
like going in circles
theres no point
so you mean it's 9!×2!×2! and nothing in denominator?
no-
with the B’s together, you dont need to do anything. with the I’s together you dont need to do anything
the only thing you need is the IIBB or BBII
hence 2!
but he said this
so would it be 9!×2!×2!/(2!×2!)
I've tried every thing possible. and because this actually giving right answer
whats the actual answer
2/55
ahhh
and for the denominator for whole big fraction, we need to have total cases for first word PROBABILITY, which will be 11!/(2!2!)
😭.
my comprehension skills are out of this world
anyway
you have 9 terms
so tis 9! right?
lets start with that
then you have BB and II as a group
its the same as I said before for these
so it becomes 2!/2! for the both
that leaves us with just 9! in the numerator
can you please not focus on 'it multiply and divide by same number so let's not write it'
if it's right, then answer will be right
normally we have smth like AB
this we just 2! right?
but if we have the same letter
BB
its 2!/2!
were not grouping the BB and II together tho
theyre together as BB and II, but theyre not BBII
wording of this question is hella weird lmao
yo
so for WX and XW, there were 2! for each of them
this is the problem
its not WX and XW
if they were together, it would be a different question
but if they are BBII and IIBB it's 2!×2! for each of the group
also if they were together, the 9! just wouldnt work at all too
yea its not
its like
exactly it would be 8!
okay I get it now
we are supposed to keep BB and II together, and not W and X together
when I did 2! with WX it meant WX and XW
but W and X can be separate
we are supposed to keep only BB and II together. which are already together when we take W and X
so we arrange PROWXALTY simply with 9!
and no further arrangements
yessss
and when I was doing arrangement for BB and II, there's no arrangement possible. BB is only one arrangement, so no multiply or divide with by any number needed
I was confused because I saw repeated letters and I was stuck on dividing by 2!×2! for 4 letters
yep
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Hey im just on A and am wondering if it is negative
cause example
-/3/2
is equal to 30º right and its negative so why isnt one of the values -30
instead its 150
see cosine is negative in which quadrant
then starting from 0° rotate to that quadrant, and add 30°
@wheat temple Has your question been resolved?
How is (a-b)² = a²-2ab+b²?
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This is because (a-b)^2 = (a-b)(a-b). a times a is a squared, a times -b is -ab, you have two of those that are negative, so -2ab, and -b times -b is a positive b squared (this is the FOIL method, multiplying First, Outside, Inside, Last, and combining like terms)
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I understand most of it, the only thing I don't understand is the step where 6x turns into 3x and 2 into 1
2/6 = 1/3
ah so they just simplified it
yep
ah alright, and they can because it doesn't do anything to the term as it will still be (x+2) after you times it with 1
Im not sure what u mean

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Is this correct down to where I stopped?
am I going to have to do IBP there?
nope
okay let me figure that out
is it an ln(x) on the right?
q(x)?
yeah
x ln x
$let y = e^{\ln x} \$
$\ln y = \ln e^{\ln x} \$
$\ln y = \ln(x) \cdot \ln(e) \$
$\ln y = \ln(x) \cdot 1 \ $
$\ln(y) = \ln(x) \$
$y = x$
Tomi
so let me now put a minus there
yeah i get thta
im jus tryna figure out why what i said is incorrect
i thought deriving it might make it clear
you moved things from the exponent out front
-x=e^ln(-x)
you had e^[-ln(x)]
bit different
if it helps $$e^{-a}=\left[e^a\right]^{-1}$$
AℤØ
x^-1?
$x \cdot \int \frac{1}{x} \cdot x\ln x dx + C$
this seems fine i think
Tomi
so here q(x) supposed to be from the original rhs
or from the standard form
oh damn i missed something
i have made an oversight
what happened here?
if you just divided by x then the right should be 2ln(x)
🙂 yeah
oh dear
fuck
sorry
nah i just made a really bad move there
just change the x before the ln(x) to a 2
and then youll be doing a substitution instead of IBP
if I write it in this form:
$\int \frac{2 \ln x}{x} dx + c$
here i cant simply by x right? or can i
nvm
that should be 2
you cant factor the x into it if thats what you did
Tomi
try letting u=ln(x)
nicely done
thank you very much!
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is my selection correct?
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Function:
Calculate the sum of elements of their domain and range
I tried creating an equation with two points
y = -4x + 17
in order to find a
but when I replace y with 4, I get x = 13/4
<@&286206848099549185>
shawn_xu
so $b^2=9$ by definition
shawn_xu
the range is ${4, 9, 5}$
shawn_xu
yes
but I don't actually need to find that b^2
I tried this
it seems that some information is missing
mm idk
i mean the mapping doesn't need to be able to be expressed as an equation
mm right
@lean otter Has your question been resolved?
@lean otter Has your question been resolved?
@lean otter Has your question been resolved?
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for this question im having trouble visualising
i know this but apparntly u cant just put the f(y) function
what does it mean between x=4 and x axis
the x intercept?
since x axis to me is the y=0 is it not
pls @ me if reply
the x axis is also known as the line y = 0
it means the region "cut off" by these two lines
it is the shaded area of the graph in the picture
how would you find the volume around y axis then? how come is it 4^2 - f(y)
since isnt it that area shaded around y?
here you cant just plug in the f(y) because there is a "space" between the area and the axis of rotation
ok
so in this example theres a space between the area and the y axis
so you have to use the washer method
$\pi * \int _a ^b R^2(y) - r^2(y)dy$
NORMAL HUMAN
so R(y) denotes the radius of the outer function and r(y) denotes the radius of the inner function
in this case your outer function is x = 4, and your inner function is f(y)
does this make sense?
i would definitely recommend looking up a video for better visual intuition
could you depict/draw what the outer and inner function are if its fine
i tried graphing on desmos but cant figure whats the actual area and volume we find
ah okay thanks will do
like outer being the furthest away from the y axis
like idrk
yeah
just consider a flat 2d "disc" being rotated around the y axis
essentially just a line segment
you can see it doesnt create a full circle, theres like a hole in the middle right?
where at? lol
in this picture the area starts at x = 2, and ends at x = 4
and theres like an empty space between x = 0 and x = 2
if you imagine just rotating the points from x = 2 to x = 4 around the y axis theres going to be a space right
because the segment from x = 0 to x = 2 isnt rotated too
yep
NORMAL HUMAN
so now let the curve start at f(y) and end at 4
the formula for the washer shape made is
$\pi * (4^2 - f^2(y))$
NORMAL HUMAN
and then we just integrate this over the region we want
so thats like finding the area between 2 curves, but where its f(x) - g(x)
basilcy doing from 0 - 4 then subtract 0 - 2? - to get 2 - 4
then square cuz like pi*r^2?
yeah
wdym
hmm well ill watch a video probably to fully understanding this but
its the line bounded - f(y)
i dont rly get why its f(y) not f(x) but eh
what if its between two curves, do you do pi * (g(y)^2 - f(y)^2)?
how would u find the bound tho
wdym?
for say this around y
intergation between a and b
depends on the problem
i.e in this case ln3 and 0
you just have to solve. you are given the lower bound of 0, and the upperbound of x = 4 goes into y = ln(4 - 1) = ln(3)
just look at where it stops making an area on the y axis
okay thanks thats all
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can anyone check my work
I believe your coefficient of 3 is too large
Since sin(…) can potentially reach 1, your equation could reach a value of 6, but the graph shows 5 is the highest point
@fleet summit Has your question been resolved?
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for iii
this method makes perfect sense
however, why cant you do the integrtal from 2 - 0 of the f(y)^2 - g(y)^2
if we say make one f(x) and another g(x)
pls @ me if reply
since isnt the top line 2cosx and the bottom e^x/2 -1?
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Q15
@lean otter
what transformation did you try
I tried making k+1 square
But that didn’t do much
not really getting the idea but i think we'll have to apply a transformation on C3
Nono I’m talking about the 15th question
oops
wait
Lemme see
You understood that you need to apply the sigma on C1 right ?@lean otter
in 15th
problem
Yeah
But it’s a determinant not a matrix so can’t do that directly
I'll just show you
👍🏾
wdym
I just mean I’m waiting 😭✨
@lean otter did you get it?
I got this
Gosh it's been almost a year I've dealt with a determiniant lmao
You can’t put the summation inside the determinant
Try C2-C1
Why ?
That’s only for matrix
I can prove it that I can do it
lol
I’ll show you one min
if that's the case then I'll have to go over linear aljebra all over
Matrices and determinants
it's been a long time anyway
Hello
@lean otter
Hmmmmm
one sec
@lean otter
Does that make sense?
I need some time ill try and solve it
It’s cause you’re multiplying in determinants
No problem tysm ✨✨
But that's not a determinant lol
The one you asked me
I told you it’s a determinant even in the q it’s 2 straight lines not square brackets
And it should be a matrix I think
No it’s not
no idea to go about the problem if it's a determinant
i have a really narrow understanding of these
Aah I see
No problem thank you tho✨
Have you tried carrying out some row operations on the matrix
bro how will you even get a numerical answer while dealing with matrices
Yup I tried making k+1 square
but you have to apply the sigma to whole column then... so you must have taken sigma 1 too
But it didn’t get me anywhere
You can’t take sigma at all here
You can’t sum individual terms in determinants
right
I have school tomorrow but I can’t go to sleep without solving this💀
mhm
Also what is pre university math?
sorry tho can't really recall things ill have to go over them
Like high school?
No problem!
Like someone who is not in uni
not necessarily in high school
Oh I see I have no idea where to put myself,cause my country has a completely different curriculum
i am in highschool yes
Were you able to solve it?
Aah I see
yeah ig
oh i see the whole row/column must contain that variable my bad
What did you get?
Can someone tell me what role I should select (I know it’s unrelated to the question so feel free to ignore)
how old are you
17
do you go to school
what's the system there?
preuniversity math
We learn everything from calculus to 3d algebra to probability statistics so on
Got it ty!
Oh
Are you from india too
We learn all that too
Aaah
my love
agreed
I love math cause I’m good at it,that’s my only reason
I've read alot of chemistry too for competitives
I read clayden
Best book
I literally can’t,I just 💥
Idk what that is
fr literally
I didn't prepare for any particular competitives lol
I do blackbook tho ,that’s fun
My parents put me in a jee coaching i barely go
I see I see
you gave JEE this year btw?
Same but I go everyday
Nono next year
Colorful book for organic chemistry
As in January
you can ask me that aswell
organic
and anything about calc
That I think I will do by myself 💀✨
then here's you competitor
no we don't have cal 3
Damn hi
it's cal 2 we study
in our curriculum
What is cal3
What does it include
Ye idk too
please be easy on me, I was literally demolished by Advanced this year😭
cal 3 would be multivariable calculus
Jee?
Partial derivatives
Vector curves
fr
Parametric curves
Oh you took a drop year?
Etc
Same
We did that in my coaching
have to
never studied competitive in 11th/12th
12th
Ok
When is JEE 2025?
January
nah i don't think you did it according to standard university text , they teach some methods go deal with competitive problems using parametrisation
Ok
I tried i didn't get it
sry
Hmm I don’t know unless I see an example
I need to learn Matrices and Determinants again
Lmao same but I don't do much
Bro why is no one getting😭
Idk maybe wrong question??
And maybe bcus idk Im not in 12th
Idts
That’s probably why💀
You’re in 12th?
yes ?
i am 17 too
How did you do det in 11th?
I definetly need to touch Matrices and Determinants
i did almost all math in 11th
except probability and permutations
I see
Guys can you give me guidance for 11th and 12th
Because my coaching teachers sucked
Bro I got lucky all my teachers are from iit or nit
Literally every single one
They were so called head of departments as i was in batch 1 but they still they sucked
same
but they all still were bad
the chemistry teacher is good I am still in contact with him
Phy-iit Kharagpur
Math-some nit I forgot
Chem-iit Delhi
Phy chem-some other iit
I see I see
I see I see
Can we get back to the question
I could just teach math better than my math teacher
how do we solve it
yeah
I tried grouping didn’t work
I tried Solving the determinant
Of
got an equation
But that will be painful to solve
I solved it like that tho that was a method taught to me in 7th grade :-;
Why were you learning det in 7th💀
why were you learning at all in 7th
My school taught it from 5th
I'm in 10th rn
But idk man
the answer for that
Maybe ask google?
Or use doubtnut
lol
I think I almost got it
what did u get
I didn’t feel like simplifying but you have to apply transformation till c1 is only 2n take it out and then you can use summation of n natural no and eq to 72
correct!
I think this is correct approach
Here the flaw is that summation must not start from zero BUT 1
then we can do by @lean otter way
aaa
I think my brain will explode after this much brain stroming but at the end I got the reasoning 🙂
okay so I was thinking right @cedar void you distracted me buddy!
huh?
what did I say?
None
@lean otter case you took and the the thing I did are entirely different we can put the summation inside
In the problem you sent
You can think about it intuitively by basic idea of summation of determinants
@cedar void if you're a jee aspirant why don't you study chemistry
It's actually my brain has become so analytic that it doesn't compile chem anymore
definitely not💀
competitives make things boring
for sure
lmao definitely yes
Those were literally my words before this year Mains
I just somehow don't like the prep one has to do for JEE
yeah there's stuff to remember but again it all makes sense lol everything can be explained
I don't feel that chem
yes all 3 subjects at once is terrible
not terrible
but it is just the way it is given
Maybe people aspiring engineering find it the right way but somehow I don't
I feel so empty about JEE
I lack that Engineer mindset required for it
nah that's no engineering either
it is fr
nope
it's only a piece of paper
lol
not even a good engineer without tough preparation can ace it
it is cummulation of many results , memories and practice
it has nothing to do with "engineer mindset"
engineer mindset is innovative
yeah definitely but in terms of examination it doesn't give me the vibe I want that pure sciences thing
it focuses on applied science rather than Pure Science
wait you're in what?
you're in uni?
the coaching i mean
how in the world people get IIT, and then join coaching
what are you talking about lad
dude my teachers all iitians
even the fucking administrators are iitians
So boring lmao
okok
nice thing they did
Lmao
it seems like you're not into Applied sciences too?
I am into applied sciences only
am I right about it?
Physics is applied science lol
uhhhhhhh
I mean applied physics is indeed engineering
But yes i am more into theoratical physics
that's what I'm into too
pure science rules the worlds
!done
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@lean otter
I was almost there!
yea good job brother i just completed your steps👍
now I can sleep peacefully
oh thanks
yes
ok cya
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what’s the right answer and why?
i think it’s d but i wanna confirm?
Both c and d should be correct
It could pass through tho
it’s d Right
Yeah
what about this one im struggling with
First thing to do figure what the kind(order) of polynomial is
wait
just wanna ask this isn’t part of the question
but what would be the least possible degree for this
And the coefficient of the x^3 term has to be negative (
4 turning points so the derivative is at least 4th order polynomial
so 4?
What's the line for?
What do you think so far?
c?
Why?
Not gonna drill on that but yeah it's d
Also c doesn't seem very exponential. Looks like it's slowly increasing
a) is exponential tho
Let's break it down.
An odd-degree polynomial would have its leading term as ax^n where n is odd
What can we say about the sign and magnitude of of x^n as x - > infinity?
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Idk why WRA wont answer my query
I just wanna know if its true or false 😭
Its true right?
yeah
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Did I do this correct? I got h≈38.79
@kindred fjord Has your question been resolved?
@raven vessel
<@&286206848099549185>
<@&286206848099549185> this is what I got
Please help
this looks right
or at the very least I can't see a glaring error and you have the right answer at the end
okay thanks so much guys
Yeah looks right also for me when I calculated it.
okay thank you so much
@kindred fjord Has your question been resolved?
Wouldnt it actually be 38 feet and 9 inches
because the things holding the tree are 6 feet longer than the tree not 6 inches
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what website would I use to graph polar coordinates?
I don't actually know of any off the top of my head, but you can probably easily google one
A Ti-84 can do that easily- maybe an emulator?
i tried desmos and couldnt figure it out after watching a video
how would i put that into a ti 84
Or just do it by hand ?
Iirc it’s a button in the window menu
i tried but i keep gettings negatives for x
so im doing something wrong
im plugging in the coords into x=rcostheta
You should get a negative x
Yeah, trust yourself! You got this!
Also you can kinda visualize it as pi+ 2pi/7 so like just below the x axis and left of the origin
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.if you select the polar grid, then stuff comes default as polar coordinates btw
hi everyone