#help-23

1 messages · Page 270 of 1

safe radishBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

clever ridge
#

why does $10e^{-t}$ antiderivative become $-10e^{-t}$

flat frigateBOT
#

wakamole

clever ridge
#

i know why but what's a good way of identifying it?

#

.close

safe radishBOT
#
Channel closed

Closed by @clever ridge

Use .reopen if this was a mistake.

safe radishBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

dusty cosmos
#

can sum1 help me

safe radishBOT
dusty cosmos
#

i needa find x

lean otter
#

equilateral triangle

dusty cosmos
#

its isosceles

sleek plank
#

since its isosceles, the bottom 2 angles must be equal

#

which would then mean the third angle is equal to 180-2*60

#

which is 60

dusty cosmos
#

yeah

#

i just need to find x

sleek plank
#

so all three angles are 60

#

and only equilateral triangles have three 60 degree angles

dusty cosmos
#

oh

sleek plank
#

you could have also used law of sines if you didn’t realize it was equilateral

#

and gotten the same answer

dusty cosmos
#

tysm 😭

#

.close

safe radishBOT
#
Channel closed

Closed by @dusty cosmos

Use .reopen if this was a mistake.

safe radishBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

reef aspen
#

Can someone teach me how to set up a differential equation for this question?

reef aspen
#

There are too many variables and I am confused by the prompt

safe radishBOT
#

@reef aspen Has your question been resolved?

safe radishBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

random helm
#

,

safe radishBOT
random helm
#

an issue on function solution:

#

when i am doing a problem like :

#

f(x) is a function on R.For any a, b ∈ R, f(a+b)+f(a-b)=2f(a)*f(b).f(0)≠0, and there exists a positive m,s.t. f(m) = 0.Find a T(T≠0), s.t. f(x+T)=f(x).

#

the solution in ans for reference is like:

#

f(0+0)+f(0-0)=2f(0)*f(0).

#

∴f(0)[f(0)-1]=0, and f(0)≠0, ∴ f(0) = 1.

#

For any a ∈ R, f(0+a) + f(0-a) = 2f(0)*f(a), ∴f(a)+f(-a)=2f(a),

#

∴f(a)=f(-a), indicating that f(x) is an even function on R.

#

∵f(m)=0,∴f(x+m+m)+f(x+m-m)=2f(x+m)*f(m)=0,

#

∴f(x+2m)+f(x)=0,∴f(x+2m)=-f(x).

#

and my issue caused here

#

in the ref sol it replaces x in the term 'f(x+2m)=-f(x)' with x + 2m and gets:

#

f(x+4m)=-f(x+2m)=f(x).

#

so is the replacement legal?

safe radishBOT
#

@random helm Has your question been resolved?

left gyro
random helm
#

simply close Bot

#

.close

safe radishBOT
#
Channel closed

Closed by @random helm

Use .reopen if this was a mistake.

safe radishBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

chilly wraith
#

guys is that a math question or not? cause it is in the middle of my homework

chilly wraith
#

help 😐

upper basalt
#

Translate?

chilly wraith
#

nah just look at the numbers these words are from another question

mental forge
#

Okay, this looks like some pattern analysis

upper basalt
#

What are you supposed to do with the numbers

chilly wraith
#

I remember answering it 6 before but I forgot my logic in answering it awooDEMON

mental forge
#

And, was that correct?

chilly wraith
mental forge
#

Okay, so we are now certain that we gotta look for some logic herr

mental forge
chilly wraith
mental forge
#

This is hard bruh

terse lichen
#

right grid has same pattern as left grid?

mental forge
#

Are you sure that arabic text ain't related to this?

chilly wraith
mental forge
#

Oh

#

You must remember some bits of the logic you thought

#

Like something

#

<@&286206848099549185>

chilly wraith
#

<@&286206848099549185>

waxen sphinx
#

maybe show us the other square?

chilly wraith
#

its another question

#

and the arabic text doesn't lead to anything

#

there is a relation between 9 and 3 that gives us 5

#

I think

#

these both have the same idea, the first picture you multiply 1 and 6 then add one to get seven, and multiply 4 and 3 to get 12 then add one to get 13, so the answer of the first picture is 1

#

the second one , when you look at the first square, 8+9 = 17 , add the sveen and carry the one, so 9 would be 10 then add it to 7 so it would be 17, carry the 1 and 4 would be 5 then 5 + 3= 8

#

so in the second picture the answer is 6

#

<@&286206848099549185>

safe radishBOT
#

@chilly wraith Has your question been resolved?

chilly wraith
#

<@&286206848099549185>

#

help

mental forge
#

This one is really tough, for it is not solved still

#

I have no idea how to initiate this

chilly wraith
#

962 - 568 = 394

#

726 - 289 = 437

#

so the answer 6 is correct

#

FINALLY

#

.close

safe radishBOT
#
Channel closed

Closed by @chilly wraith

Use .reopen if this was a mistake.

mental forge
#

This was a very good question actually

#

How simple shit, but felt like impossible to find out

#

Opens up the mind

#

Good you find it out yourself

safe radishBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

trail otter
#

How to solve this limit?
[\lim_{n\to\infty}n\tan\left(\frac{\pi}{4n}\right)]

flat frigateBOT
#

Slowaq

long oracle
#

What have you tried so far?

trail otter
#

lhopital?

long oracle
#

As a start maybe take advantage of tan(x) = sin(x)/cos(x)

long oracle
trail otter
knotty pier
#

Or when x tends to zero tanx is x

#

Best method

long oracle
knotty pier
#

Works

#

But no need to write tanx as sinx/cosx tho

long oracle
#

Yes you would if you’re not aware of that fact

knotty pier
#

Mmm..

trail otter
#

yes ive got it now thx

#

.close

safe radishBOT
#
Channel closed

Closed by @trail otter

Use .reopen if this was a mistake.

safe radishBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

agile wraith
safe radishBOT
agile wraith
#

can someone explain how this result in blue is reached

#

I am also curious why the way to get to the result is different from a and b

#

but more importantly how is a done

#

<@&286206848099549185>

safe radishBOT
#

@agile wraith Has your question been resolved?

mellow cypress
# agile wraith can someone explain how this result in blue is reached

It’s just the matrix such that the basis vectors of B are the columns of the matrix.

Applying this to vectors in the space B gets you to canonical space (which is C in this case). To get a vector in canonical space to B space you would apply the inverse which is what is happening in (b)

safe radishBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

twin prawn
safe radishBOT
twin prawn
#

all correct?

versed wave
#

👍

twin prawn
#

wait wrong send

#

if BC parallels DE; then is line BD a transversal line?

twin prawn
# twin prawn

is Angle 1 and 4 alternate interior or exterior? ill answer either way cause both are congruent anyway based on theorem

cedar void
#

they'll be equal

#

but are not alternate angles

#

1+2 and 3+4 will be

twin prawn
#

OH RIGHT

#

theyre both perpendicular anyways

twin prawn
twin prawn
# twin prawn

like i know they’re perpendicular; but how do we know that they’re equal?

cedar void
cedar void
twin prawn
#

exterior?

cedar void
twin prawn
#

exterior or interior

cedar void
#

Exterior ones are greater than 90 degrees

twin prawn
#

does it also apply in this case? the one next to the 5x - 20 and the one before 3(x + 10) are exterior aswell and they look like acute angles

#

also; theres like a tip given by someone that if u have 2 transversal lines; essentially “cancel out one first” so that you can focus on that first set of angles or something

twin prawn
cedar void
#

yo

#

sorry I got busy

cedar void
cedar void
# twin prawn

It is completely your choice how you want to understand it

#

both are correct

twin prawn
#

alr so recap:

Alternating (Interior Exterior) and Corresponding angles are congruent

Same Side Interior-Exterior Angles are supplementary

safe radishBOT
#

@twin prawn Has your question been resolved?

twin prawn
#

sorry one last thngg

#

is this correct? heres how i got it (sorry for blurry pic btw)

#

3 and 4 are vertical due to them being nonadjacent; 1 and 2 are interior alternates

#

since there is a right angle in between angle 3 and 2 therefore 3 and 2 must equate to 90 (ive experienced this problem before and someone told be that if an angle is 90 degrees; the angles surrounding it must equate to 90, though idk what statement (postu, theo, coro) it is)

cedar void
#

since one of them is 90 degrees then other has to be add upto 90 as well

twin prawn
cedar void
twin prawn
#

and is there any other way to explain without having to use polygons (unit 1: lines and angles hehe)

cedar void
#

maybe trigonometry

#

if lenghts are given

twin prawn
cedar void
cedar void
cedar void
#

it has nothing muchh to do with angle

twin prawn
#

gotcha

cedar void
#

however there is a law of cosine

cedar void
twin prawn
cedar void
twin prawn
#

gotcha; thanks.

#

.close

safe radishBOT
#
Channel closed

Closed by @twin prawn

Use .reopen if this was a mistake.

safe radishBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

steep magnet
safe radishBOT
steep magnet
#

Ummm

#

I set f(x) and h(x) equal and got 0 and -1 as solutions

#

How do I prove it with that? 😅

vale oriole
#

that doesnt prove they are equal

#

and besides 0 isnt a solution

steep magnet
#

Ya thats what I was thinking

#

So what should I do?

vale oriole
#

try turning one of the functions into the other

steep magnet
#

Ah ok

#

Any one you would recommend to use

#

To turn into the other

hearty wolf
#

uhhh

vale oriole
#

usually functions with sqrts as we like to rationalise them

#

!nosols

safe radishBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

hearty wolf
#

oh mb

steep magnet
hearty wolf
#

you make the denominator rational

#

so the only surd is the numerator

steep magnet
#

I will go try that

grim plover
#

I will drop another hint: u have to use the a^2 - b^2 identity

steep magnet
#

Ahh I got it!

#

It only took 3 steps wtf haha

#

Thanks everyone!

#

❤️

#

.close

safe radishBOT
#
Channel closed

Closed by @steep magnet

Use .reopen if this was a mistake.

safe radishBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

molten flume
#

letters of word PROBABILITY are arranged. the chance that two B and two I occur together.

so far I've solved is that:

we take BB as W and II as X, so we have to arrange PROWXALTY (9 letters). so total ways 9! and to arrange W and X, further 2! => total ways 9!×2!. but there are 2 B and 2 I, they are repeated, so we divide by 2!×2!. => total ways 9!×2!/(2!×2!).

and total cases of usual word PROBABILITY= 11!/(2!×2!)

flat frigateBOT
#

cali_owt

steel agate
#

consider two Bs as 1 letter lets say x

#

and then try doing it

river oriole
#

its weird putting the two I’s together

#

they can be separate

#

if you say theyre x and put it together youre getting rid of combs

molten flume
vale oriole
#

there arent a further 2! ways to arrange W and X there should be a further 2! for W and 2! for X, but those cases should have been ignored in the first place tbh

river oriole
#

oh shit

#

i did not read thwt well

#

ok

molten flume
#

you sound right, but i don't understand

vale oriole
#

well W is BB which has 2! ways of being arranged and X is II which has another 2! ways of being arranged

#

but u can just ignore them since it doesnt matter which B is first its still BB

molten flume
#

so shouldnt it be 2!×2!×2!.
first for W and X, and then 2! each for letter inside W and X

molten flume
river oriole
#

ok

#

if we had A and B

#

thatd would be 2!

#

but its the same letter

vale oriole
river oriole
#

so it cancels out

vale oriole
#

there was no point in multiplying by 2!2! only to then divide by 2!2!

molten flume
#

so what will be final cases

river oriole
#

like going in circles

#

theres no point

molten flume
#

so you mean it's 9!×2!×2! and nothing in denominator?

river oriole
#

no-

#

with the B’s together, you dont need to do anything. with the I’s together you dont need to do anything

#

the only thing you need is the IIBB or BBII

#

hence 2!

molten flume
river oriole
#

ok

#

let me ask you this

molten flume
#

I've tried every thing possible. and because this actually giving right answer

river oriole
#

whats the actual answer

molten flume
#

2/55

river oriole
#

ahhh

molten flume
#

and for the denominator for whole big fraction, we need to have total cases for first word PROBABILITY, which will be 11!/(2!2!)

river oriole
#

sorry

#

i took it as IIBB were a group

#

yea

#

ignore the 2!

molten flume
#

😭.

river oriole
#

my comprehension skills are out of this world

#

anyway

#

you have 9 terms

#

so tis 9! right?

#

lets start with that

#

then you have BB and II as a group

#

its the same as I said before for these

#

so it becomes 2!/2! for the both

#

that leaves us with just 9! in the numerator

molten flume
#

can you please not focus on 'it multiply and divide by same number so let's not write it'

river oriole
#

uhh

#

what you want me to focus on

molten flume
#

if it's right, then answer will be right

river oriole
#

yea

#

what im doing is right

molten flume
#

for both

river oriole
#

normally we have smth like AB

#

this we just 2! right?

#

but if we have the same letter

#

BB

#

its 2!/2!

molten flume
#

yes

#

but you should also consider that if it's BBII then it's 4!/(2!2!)

river oriole
#

were not grouping the BB and II together tho

#

theyre together as BB and II, but theyre not BBII

#

wording of this question is hella weird lmao

molten flume
#

wait let me think a bit

#

hi

river oriole
#

yo

molten flume
#

so for WX and XW, there were 2! for each of them

river oriole
#

this is the problem

#

its not WX and XW

#

if they were together, it would be a different question

molten flume
river oriole
#

also if they were together, the 9! just wouldnt work at all too

river oriole
#

its like

molten flume
river oriole
#

BBPROIILTYA

#

I def spelt thwt wrong

#

but you get what i mean

molten flume
#

okay I get it now

#

we are supposed to keep BB and II together, and not W and X together

#

when I did 2! with WX it meant WX and XW

#

but W and X can be separate

#

we are supposed to keep only BB and II together. which are already together when we take W and X

#

so we arrange PROWXALTY simply with 9!

#

and no further arrangements

river oriole
#

yessss

molten flume
#

and when I was doing arrangement for BB and II, there's no arrangement possible. BB is only one arrangement, so no multiply or divide with by any number needed

#

I was confused because I saw repeated letters and I was stuck on dividing by 2!×2! for 4 letters

river oriole
#

yep

molten flume
#

thanks for discussion sho

#

.close

safe radishBOT
#
Channel closed

Closed by @molten flume

Use .reopen if this was a mistake.

safe radishBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

wheat temple
safe radishBOT
wheat temple
#

Hey im just on A and am wondering if it is negative

#

cause example

#

-/3/2

#

is equal to 30º right and its negative so why isnt one of the values -30

#

instead its 150

molten flume
#

see cosine is negative in which quadrant

#

then starting from 0° rotate to that quadrant, and add 30°

safe radishBOT
#

@wheat temple Has your question been resolved?

normal sand
#

How is (a-b)² = a²-2ab+b²?

safe radishBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lean otter
# normal sand How is (a-b)² = a²-2ab+b²?

This is because (a-b)^2 = (a-b)(a-b). a times a is a squared, a times -b is -ab, you have two of those that are negative, so -2ab, and -b times -b is a positive b squared (this is the FOIL method, multiplying First, Outside, Inside, Last, and combining like terms)

lean otter
#

.close

safe radishBOT
#
Channel closed

Closed by @bright mantle

Use .reopen if this was a mistake.

safe radishBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

sacred fjord
#

I understand most of it, the only thing I don't understand is the step where 6x turns into 3x and 2 into 1

crude star
#

2/6 = 1/3

sacred fjord
#

ah so they just simplified it

crude star
#

yep

sacred fjord
#

ah alright, and they can because it doesn't do anything to the term as it will still be (x+2) after you times it with 1

crude star
#

Im not sure what u mean

sacred fjord
#

im over complicating it, my bad lol

#

i see what they did now

crude star
sacred fjord
#

.close

safe radishBOT
#
Channel closed

Closed by @sacred fjord

Use .reopen if this was a mistake.

safe radishBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

safe radishBOT
#
Channel closed

Closed by @left mist

Use .reopen if this was a mistake.

safe radishBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

surreal fable
#

Is this correct down to where I stopped?

safe radishBOT
surreal fable
#

am I going to have to do IBP there?

icy lance
surreal fable
icy lance
#

is it an ln(x) on the right?

surreal fable
icy lance
#

yeah

surreal fable
#

x ln x

icy lance
#

ah alright

#

by parts then

surreal fable
#

$let y = e^{\ln x} \$
$\ln y = \ln e^{\ln x} \$
$\ln y = \ln(x) \cdot \ln(e) \$
$\ln y = \ln(x) \cdot 1 \ $
$\ln(y) = \ln(x) \$
$y = x$

flat frigateBOT
surreal fable
#

so let me now put a minus there

icy lance
#

that is an awful amount of contrived work for that

#

by definition e^(lnx)=x

surreal fable
#

im jus tryna figure out why what i said is incorrect

icy lance
#

ah

#

its similar to what happened last time

surreal fable
#

i thought deriving it might make it clear

icy lance
#

you moved things from the exponent out front

#

-x=e^ln(-x)
you had e^[-ln(x)]

#

bit different

#

if it helps $$e^{-a}=\left[e^a\right]^{-1}$$

flat frigateBOT
#

AℤØ

surreal fable
icy lance
#

yeah

#

1/x

surreal fable
#

oh okay

#

gotcha

#

so let me correct it from that point

surreal fable
icy lance
#

this seems fine i think

flat frigateBOT
icy lance
#

simplify the integrand though

#

oh yeah, you also lost a 2

#

wait did you

surreal fable
#

or from the standard form

icy lance
#

oh damn i missed something

surreal fable
#

cause i had to put it in standard form

#

and then q(x) became x ln x

icy lance
#

i have made an oversight

#

what happened here?

#

if you just divided by x then the right should be 2ln(x)

surreal fable
icy lance
#

oh dear

surreal fable
#

fuck

icy lance
#

sorry

surreal fable
#

nah i just made a really bad move there

icy lance
#

it doesnt change much

#

honestly

icy lance
#

and then youll be doing a substitution instead of IBP

surreal fable
#

here i cant simply by x right? or can i

#

nvm

#

that should be 2

icy lance
#

you cant factor the x into it if thats what you did

flat frigateBOT
surreal fable
#

this is irrevelant

#

now

icy lance
#

try letting u=ln(x)

surreal fable
#

this is what I got

icy lance
#

nicely done

surreal fable
#

thank you very much!

icy lance
#

np, its all about being careful

#

otherwise youre all good

surreal fable
#

thanks again

#

.close

safe radishBOT
#
Channel closed

Closed by @surreal fable

Use .reopen if this was a mistake.

safe radishBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

oak violet
#

is my selection correct?

safe radishBOT
#

@oak violet Has your question been resolved?

oak violet
#

.close

safe radishBOT
#
Channel closed

Closed by @oak violet

Use .reopen if this was a mistake.

safe radishBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lean otter
#

Function:
Calculate the sum of elements of their domain and range

lean otter
#

I tried creating an equation with two points

#

y = -4x + 17

#

in order to find a

#

but when I replace y with 4, I get x = 13/4

#

<@&286206848099549185>

proven burrow
#

well you want to apply the defintion of a function

#

$h(2)=9, h(2)=b^2$

flat frigateBOT
#

shawn_xu

proven burrow
#

so $b^2=9$ by definition

flat frigateBOT
#

shawn_xu

proven burrow
#

the range is ${4, 9, 5}$

flat frigateBOT
#

shawn_xu

lean otter
#

but I don't actually need to find that b^2

proven burrow
#

yeah

#

but i'm not sure how you get a

lean otter
proven burrow
#

it seems that some information is missing

lean otter
proven burrow
#

i mean the mapping doesn't need to be able to be expressed as an equation

safe radishBOT
#

@lean otter Has your question been resolved?

safe radishBOT
#

@lean otter Has your question been resolved?

safe radishBOT
#

@lean otter Has your question been resolved?

safe radishBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

safe radishBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

ionic zenith
#

for this question im having trouble visualising

ionic zenith
#

i know this but apparntly u cant just put the f(y) function

#

what does it mean between x=4 and x axis

#

the x intercept?

#

since x axis to me is the y=0 is it not

#

pls @ me if reply

trim birch
trim birch
#

it is the shaded area of the graph in the picture

ionic zenith
#

since isnt it that area shaded around y?

trim birch
#

here you cant just plug in the f(y) because there is a "space" between the area and the axis of rotation

ionic zenith
#

ok

trim birch
#

so in this example theres a space between the area and the y axis

#

so you have to use the washer method

#

$\pi * \int _a ^b R^2(y) - r^2(y)dy$

flat frigateBOT
#

NORMAL HUMAN

trim birch
#

so R(y) denotes the radius of the outer function and r(y) denotes the radius of the inner function

#

in this case your outer function is x = 4, and your inner function is f(y)

#

does this make sense?

#

i would definitely recommend looking up a video for better visual intuition

ionic zenith
#

could you depict/draw what the outer and inner function are if its fine
i tried graphing on desmos but cant figure whats the actual area and volume we find

ionic zenith
#

like outer being the furthest away from the y axis

#

like idrk

trim birch
#

yeah

trim birch
#

essentially just a line segment

#

you can see it doesnt create a full circle, theres like a hole in the middle right?

ionic zenith
#

where at? lol

trim birch
#

anywhere

#

maybe just consider the line y = 0

trim birch
#

and theres like an empty space between x = 0 and x = 2

#

if you imagine just rotating the points from x = 2 to x = 4 around the y axis theres going to be a space right

#

because the segment from x = 0 to x = 2 isnt rotated too

ionic zenith
#

yep

trim birch
#

so intuitively the area created is

#

$\pi * (4^2 - 2^2)$

flat frigateBOT
#

NORMAL HUMAN

trim birch
#

so now let the curve start at f(y) and end at 4

#

the formula for the washer shape made is

#

$\pi * (4^2 - f^2(y))$

flat frigateBOT
#

NORMAL HUMAN

trim birch
#

and then we just integrate this over the region we want

ionic zenith
# flat frigate **NORMAL HUMAN**

so thats like finding the area between 2 curves, but where its f(x) - g(x)
basilcy doing from 0 - 4 then subtract 0 - 2? - to get 2 - 4
then square cuz like pi*r^2?

trim birch
#

yeah

ionic zenith
#

thats only for y = 0 line

#

and curve is needed to go up the y axis

trim birch
ionic zenith
#

like adding each area line from y = 0 to y = 4

#

in a sense

#

im going crazy here

trim birch
#

yeah

#

no its just that

#

you integrate the area lines

ionic zenith
#

hmm well ill watch a video probably to fully understanding this but

#

its the line bounded - f(y)

#

i dont rly get why its f(y) not f(x) but eh

#

what if its between two curves, do you do pi * (g(y)^2 - f(y)^2)?

trim birch
#

yup

#

that exactly how it works

ionic zenith
#

how would u find the bound tho

trim birch
#

wdym?

ionic zenith
#

intergation between a and b

trim birch
#

depends on the problem

ionic zenith
#

i.e in this case ln3 and 0

trim birch
#

you just have to solve. you are given the lower bound of 0, and the upperbound of x = 4 goes into y = ln(4 - 1) = ln(3)

ionic zenith
#

just look at where it stops making an area on the y axis

#

okay thanks thats all

#

.close

safe radishBOT
#
Channel closed

Closed by @ionic zenith

Use .reopen if this was a mistake.

safe radishBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

fleet summit
#

can anyone check my work

safe radishBOT
torpid fable
#

Since sin(…) can potentially reach 1, your equation could reach a value of 6, but the graph shows 5 is the highest point

safe radishBOT
#

@fleet summit Has your question been resolved?

safe radishBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

ionic zenith
#

for iii

safe radishBOT
ionic zenith
#

this method makes perfect sense

#

however, why cant you do the integrtal from 2 - 0 of the f(y)^2 - g(y)^2

#

if we say make one f(x) and another g(x)

#

pls @ me if reply

#

since isnt the top line 2cosx and the bottom e^x/2 -1?

safe radishBOT
#

@ionic zenith Has your question been resolved?

safe radishBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

ionic zenith
#

.

#

d

safe radishBOT
ionic zenith
#

^ same question

#

as before the close

#

@ me plz

#

.

safe radishBOT
#

@ionic zenith Has your question been resolved?

safe radishBOT
#

@ionic zenith Has your question been resolved?

safe radishBOT
#

@ionic zenith Has your question been resolved?

safe radishBOT
#

@ionic zenith Has your question been resolved?

ionic zenith
#

k

#

😦

#

.close

safe radishBOT
#
Channel closed

Closed by @ionic zenith

Use .reopen if this was a mistake.

safe radishBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

lean otter
safe radishBOT
lean otter
#

@lean otter

#

what transformation did you try

#

I tried making k+1 square

#

But that didn’t do much

#

not really getting the idea but i think we'll have to apply a transformation on C3

#

Nono I’m talking about the 15th question

#

oops

#

wait

#

Lemme see

#

You understood that you need to apply the sigma on C1 right ?@lean otter

#

in 15th

#

problem

#

Yeah

#

But it’s a determinant not a matrix so can’t do that directly

#

I'll just show you

#

👍🏾

#

wdym

#

I just mean I’m waiting 😭✨

#

@lean otter did you get it?

#

I got this

#

Gosh it's been almost a year I've dealt with a determiniant lmao

#

You can’t put the summation inside the determinant

#

Try C2-C1

lean otter
#

That’s only for matrix

#

I can prove it that I can do it

#

lol

lean otter
#

if that's the case then I'll have to go over linear aljebra all over

#

Matrices and determinants

#

it's been a long time anyway

#

Hello

lean otter
#

Hmmmmm

#

one sec

#

@lean otter

#

Does that make sense?

#

I need some time ill try and solve it

lean otter
lean otter
#

But that's not a determinant lol

#

The one you asked me

lean otter
#

To solve

#

I solved it as a matrix

lean otter
#

And it should be a matrix I think

lean otter
#

no idea to go about the problem if it's a determinant

#

i have a really narrow understanding of these

#

Aah I see

#

No problem thank you tho✨

desert swallow
#

Have you tried carrying out some row operations on the matrix

cedar void
lean otter
still thunder
lean otter
lean otter
#

You can’t sum individual terms in determinants

lean otter
#

I have school tomorrow but I can’t go to sleep without solving this💀

#

mhm

lean otter
#

sorry tho can't really recall things ill have to go over them

lean otter
cedar void
#

not necessarily in high school

lean otter
#

Oh I see I have no idea where to put myself,cause my country has a completely different curriculum

#

i am in highschool yes

lean otter
lean otter
cedar void
still thunder
lean otter
cedar void
#

wait

lean otter
#

how old are you

#

17

#

do you go to school

lean otter
#

preuniversity math

lean otter
lean otter
#

Oh

#

Are you from india too

#

We learn all that too

lean otter
#

JEE?💀

#

Nice

#

No

lean otter
#

fun

#

physics

lean otter
cedar void
lean otter
#

I hate chemistry I can tolerate everything else

#

i am doing math for physics

lean otter
#

I love math cause I’m good at it,that’s my only reason

lean otter
#

I read clayden

#

Best book

lean otter
lean otter
cedar void
lean otter
#

I didn't prepare for any particular competitives lol

#

I do blackbook tho ,that’s fun

#

My parents put me in a jee coaching i barely go

lean otter
cedar void
lean otter
lean otter
lean otter
lean otter
#

you can ask me that aswell

#

organic

#

and anything about calc

lean otter
lean otter
#

also

cedar void
lean otter
#

no we don't have cal 3

lean otter
#

it's cal 2 we study

#

in our curriculum

#

What is cal3

#

What does it include

#

Ye idk too

cedar void
#

please be easy on me, I was literally demolished by Advanced this year😭

lean otter
#

cal 3 would be multivariable calculus

lean otter
#

Partial derivatives

#

Vector curves

cedar void
lean otter
#

Parametric curves

lean otter
#

Etc

#

Same

lean otter
cedar void
lean otter
#

Maybe cause it’s batch1

lean otter
#

Ok

#

When is JEE 2025?

#

January

#

nah i don't think you did it according to standard university text , they teach some methods go deal with competitive problems using parametrisation

#

Ok

#

I tried i didn't get it

#

sry

lean otter
#

I need to learn Matrices and Determinants again

lean otter
lean otter
lean otter
lean otter
lean otter
lean otter
#

lol

lean otter
lean otter
#

yes ?

#

i am 17 too

#

How did you do det in 11th?

lean otter
#

i did almost all math in 11th

#

except probability and permutations

#

I see

#

Guys can you give me guidance for 11th and 12th

lean otter
lean otter
#

Literally every single one

#

They were so called head of departments as i was in batch 1 but they still they sucked

lean otter
#

but they all still were bad

#

the chemistry teacher is good I am still in contact with him

lean otter
lean otter
#

Can we get back to the question

#

I could just teach math better than my math teacher

#

how do we solve it

#

yeah

lean otter
#

I tried Solving the determinant

#

Of

#

got an equation

lean otter
lean otter
#

Why were you learning det in 7th💀

#

why were you learning at all in 7th

lean otter
#

I'm in 10th rn

#

But idk man

#

the answer for that

#

Maybe ask google?

#

Or use doubtnut

#

lol

#

I think I almost got it

lean otter
#

I didn’t feel like simplifying but you have to apply transformation till c1 is only 2n take it out and then you can use summation of n natural no and eq to 72

#

correct!

still thunder
still thunder
#

then we can do by @lean otter way

lean otter
#

aaa

still thunder
#

I think my brain will explode after this much brain stroming but at the end I got the reasoning 🙂

lean otter
#

okay so I was thinking right @cedar void you distracted me buddy!

lean otter
#

None

#

@lean otter case you took and the the thing I did are entirely different we can put the summation inside

#

In the problem you sent

#

You can think about it intuitively by basic idea of summation of determinants

#

@cedar void if you're a jee aspirant why don't you study chemistry

cedar void
lean otter
#

chem is analytic lol

#

give that you study it the right way

cedar void
lean otter
#

competitives make things boring

cedar void
#

for sure

lean otter
cedar void
#

I just somehow don't like the prep one has to do for JEE

lean otter
#

yeah there's stuff to remember but again it all makes sense lol everything can be explained

cedar void
#

I don't feel that chem

lean otter
cedar void
#

Maybe people aspiring engineering find it the right way but somehow I don't

#

I feel so empty about JEE

#

I lack that Engineer mindset required for it

lean otter
#

nah that's no engineering either

cedar void
lean otter
#

nope

#

it's only a piece of paper

#

lol

#

not even a good engineer without tough preparation can ace it

#

it is cummulation of many results , memories and practice

#

it has nothing to do with "engineer mindset"

#

engineer mindset is innovative

cedar void
lean otter
#

i don't get why people are fascinated about the iits

#

lol

cedar void
lean otter
#

people at my classes are also iitians i look at them i find their lives pathetic

#

lol

cedar void
#

you're in uni?

lean otter
#

the coaching i mean

cedar void
#

how in the world people get IIT, and then join coaching

#

what are you talking about lad

lean otter
#

dude my teachers all iitians

#

even the fucking administrators are iitians

#

So boring lmao

cedar void
lean otter
#

They did iit

#

Then chose to teach jee

cedar void
lean otter
#

Lmao

cedar void
#

it seems like you're not into Applied sciences too?

lean otter
#

I am into applied sciences only

cedar void
lean otter
#

Physics is applied science lol

cedar void
#

I mean applied physics is indeed engineering

lean otter
#

But yes i am more into theoratical physics

cedar void
#

pure science rules the worlds

#

!done

safe radishBOT
#

If you are done with this channel, please mark your problem as solved by typing .close

still thunder
still thunder
lean otter
still thunder
lean otter
#

thanks

#

Your writing is really nice

still thunder
#

now I can sleep peacefully

still thunder
lean otter
#

yes

still thunder
#

ok cya

safe radishBOT
#

@lean otter Has your question been resolved?

safe radishBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

quick bison
#

what’s the right answer and why?

safe radishBOT
quick bison
#

i think it’s d but i wanna confirm?

soft matrix
desert swallow
#

It could pass through tho

quick bison
#

it’s d Right

desert swallow
#

Yeah

quick bison
#

what about this one im struggling with

desert swallow
quick bison
#

i got do

#

d

desert swallow
#

Yeah

#

It's a cubic

quick bison
#

wait

#

just wanna ask this isn’t part of the question

#

but what would be the least possible degree for this

desert swallow
desert swallow
quick bison
#

so 4?

desert swallow
#

5

#

I said the derivative

#

So the actual polynomial would be one degree higher

quick bison
#

oh

#

okay thanks that makes sense

#

i also drew the line

desert swallow
#

What's the line for?

quick bison
#

idk ive seen it done like this 😭

#

can u help me with this?

desert swallow
quick bison
#

c?

desert swallow
#

Why?

quick bison
#

cuz it’s exponential?

#

oh wait

#

sorry

#

i think it’s d

desert swallow
#

Not gonna drill on that but yeah it's d

#

Also c doesn't seem very exponential. Looks like it's slowly increasing

#

a) is exponential tho

quick bison
#

yea i realized it wasnt asking which is not lol

#

can u help me with this?

desert swallow
#

Let's break it down.

An odd-degree polynomial would have its leading term as ax^n where n is odd

#

What can we say about the sign and magnitude of of x^n as x - > infinity?

safe radishBOT
#

@quick bison Has your question been resolved?

#
Channel closed

Closed by @quick bison

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

steep magnet
safe radishBOT
steep magnet
#

Idk why WRA wont answer my query

#

I just wanna know if its true or false 😭

#

Its true right?

indigo wave
#

yeah

steep magnet
#

Thanks

#

❤️

#

.close

safe radishBOT
#
Channel closed

Closed by @steep magnet

Use .reopen if this was a mistake.

safe radishBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

kindred fjord
#

Did I do this correct? I got h≈38.79

safe radishBOT
#

@kindred fjord Has your question been resolved?

kindred fjord
#

@raven vessel

#

<@&286206848099549185>

#

<@&286206848099549185> this is what I got

#

Please help

steep lily
#

this looks right

#

or at the very least I can't see a glaring error and you have the right answer at the end

white yoke
#

Yeah, it looks right

#

I've tried to calculate on my own and it gives the same answer

kindred fjord
#

okay thanks so much guys

main island
#

Yeah looks right also for me when I calculated it.

kindred fjord
#

okay thank you so much

safe radishBOT
#

@kindred fjord Has your question been resolved?

kindred fjord
kindred fjord
safe radishBOT
#

@kindred fjord Has your question been resolved?

safe radishBOT
#
Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

safe radishBOT
#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

dark warren
#

what website would I use to graph polar coordinates?

dark warren
rustic goblet
#

I don't actually know of any off the top of my head, but you can probably easily google one

jolly shard
#

A Ti-84 can do that easily- maybe an emulator?

dark warren
#

i tried desmos and couldnt figure it out after watching a video

#

how would i put that into a ti 84

jolly shard
#

Or just do it by hand ?

jolly shard
dark warren
#

i tried but i keep gettings negatives for x

#

so im doing something wrong

#

im plugging in the coords into x=rcostheta

jolly shard
dark warren
#

oh

#

alright

jolly shard
#

Yeah, trust yourself! You got this!

#

Also you can kinda visualize it as pi+ 2pi/7 so like just below the x axis and left of the origin

dark warren
#

yeah thank you I got it right

#

.close

safe radishBOT
#
Channel closed

Closed by @dark warren

Use .reopen if this was a mistake.

#
Available help channel!

Send your question here to claim the channel.

Remember:
Ask your math question in a clear, concise manner.
Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

junior smelt
lapis badger
#

hi everyone

safe radishBOT
lapis badger
#

im stuck on this

#

ive completely factored it down

#

im just confused on

#

how i should be counting the cases

safe radishBOT
#

@lapis badger Has your question been resolved?

#
Channel closed

Closed by @lapis badger

Use .reopen if this was a mistake.