help-23

[fathom jewel]

wow

[lean otter]

FINALLY I CAN REST IN PEACE

[fathom jewel]

you actualyl

deserved my help

[lean otter]

I LOVE YOU

[fathom jewel]

,,x_p = b^{1-e^{-at}}

[lean otter]

YOU SAVED MY FRIED BRAIN

[flat frigate]

𝔸dωn𝓲²s

[lean otter]

period period

[fathom jewel]

If you're fried

then your professor is more fried

[lean otter]

https://tenor.com/view/jm-gif-18068790282636308332

[fathom jewel]

actually the friedest

[lean otter]

fr

[fathom jewel]

should get fired

[lean otter]

LMAO

[fathom jewel]

enjoy your day

[lean otter]

you too

<#

❤️

[fathom jewel]

haha thanks

[lean otter]

cant even herat correctly

SPELL EITHER APPARENTLY

[fathom jewel]

you can close the channel

[lean otter]

🤦‍♂️

.close

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[fiery ibex]

how do they get 4^2 and 9^-1 for the exponents to factor out to get n-1 in the exponent

since isnt 4^2 * 4^n-1 = 4^2n-2 ?

likewise with the denominator

[still charm]

no

review your exponent rules

5^2 x 5^3 = 5^5, not 5^6

[fiery ibex]

WAIT IM SO BRAINDEAD

bruh 😭

[still charm]

yeah...

[fiery ibex]

i forgot that its adding exponents not multiplying

[still charm]

lol...

[fiery ibex]

😭 how did i even get here 💀

[still charm]

you'll be fine...

[fiery ibex]

tysm tho 💀

.close

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[still charm]

gj

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[violet mango]

logically how does this make sense

am i just following a formula that 3 | 53 - 17

?

since 3 divides 36 the statment is true?

[hard crest]

well they're both in the "2" equivalence class, mod 3

so they're equivalent to each other mod 3

[violet mango]

what does this mean

[hard crest]

when we look at the integers mod 3, we divide them into three boxes

the first box contains 0,3,6,9,12, ...
the second box contains 1,4,7,...
and the third box contains 2,5,8,...

[violet mango]

how does this relate to 53 = 17 mod 3

im so confused

[hard crest]

okay here's one thing -- the notation kinda sucks. the (mod 3) gets tacked onto the end when it should really be attached to the = sign.

like what we're really saying is $53 \overset^{\mod3}{\equiv} 17$

[flat frigate]

hayley table
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[violet mango]

this notation?

[hard crest]

hang on

"when considered modulo 3, 53 is equivalent to 17" because they both have a remainder of 2 when divided by 3

[violet mango]

OHHHH

is it like

53 mod 3 = 17 mod 3

?

[hard crest]

you can think about it that way yeah, if you're from programming you'll expect mod to be an operator. it's not really used that way in math; it's a... contextualizer I guess? it changes the way you interpret the rest of the equation

again it's in the wrong place, it should be attached to the equals sign

$53 \equiv_3 17$

[flat frigate]

hayley table

[violet mango]

so what does the 3 line equal sign mean

does it mean it goes both ways

[hard crest]

"is equivalent to"

which means like - ok yeah they're not equal because like 53 and 17 are not the same number, but as far as mod3 is concerned, they act the same so they're equivalent

in practice you'll see people using = instead of the triple equal which is totally fine

[violet mango]

is it bc mod 3 is in parentheses at the end with the statment so its saying 53 = 17 when interperting (mod 3) ?

[hard crest]

so the (mod 3) is saying "hey those equivalence signs in that equation? yeah interpret those under the idea of mod3"

yeah

[violet mango]

oh ok that makes it more clear

so what is the difference between that notatioon and regular equal sign

dont they both mean equal to

[hard crest]

yeah and there's very little meaningful distinction between them

equivalent would be like "indistinguishable" but not necessarily equal I guess? idk. a lot of it is tradition

which is again why you see people using = in this context and it's totally understandable

[violet mango]

ok thank you for the help

[hard crest]

yw, you ask good questions!

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[rose stag]

How is this last step work?

[rose stag]

sureley you cant just put sin either side

And if you do how you know its equak

[timid ridge]

why not?

[timid ridge]

2 theta = phi

if the angles are the same then sine of those should be the same

no?

[rose stag]

Sorry I dont get it

do you mind breaking it downn

[rose stag]

pkls

pls

[timid ridge]

Sine is just a function

if 2x = y

f(2x) = f(y)

[rose stag]

f(x)=sinx?

[timid ridge]

yes

[rose stag]

ah ok

[timid ridge]

you could say that

it's true for any function

[rose stag]

ahhh ok

thankyou my frined

hope you have a great day

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[prisma roost]

question reads as follow:
n is the highest positive integer such that n^2+4567n is a perfect square, find the remainder of n divided by 1000.

i tried to write it as n^2+4567n=k^2 then 4567n=(k-n)(k+n) but the only answer i got was -4567 which is not a positive integer. I also tried many different cases but they're not an integer. Please help.

[spice wing]

Hi

n² + 4567n is a perfect square

So n(n+4567) is a perfect square

So in most simple case we should have n is a perfect square too

[prisma roost]

ohhh

i never think about it like that

[prisma roost]

so we can substitute n=m^2 then get 4567=(k/m -m)(k/m +m)

is that right?

since 4567 is prime we can go k/m-m=1 and k/m+m=4567

[spice wing]

Hmm

[prisma roost]

i got m=2283

so n=2283^2

[prisma roost]

i checked it, it's actually a square

[spice wing]

Cool 🙂

[neat fable]

yes i got this as well

[prisma roost]

tysm, i think i can find the remainder myself

.close

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[spice wing]

Ofc

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[craggy field]

I need to answer letter B

I'm done is 1 A

I need to do 1 B next

[lean otter]

do you have an idea on where to start?

[craggy field]

Nope

[lean otter]

The exercise tells you which sides and angles are congruent

[craggy field]

I only understand find measure of A

[lean otter]

it says that

32 = 9x + 14

Solving which will give you the value of X

[craggy field]

X value is 2

[lean otter]

Indeed

Then it asks you the angle of A

[craggy field]

How do I get the angle of A

[lean otter]

In the prior point

We just mentioned that the congruent angles

[craggy field]

E?

[lean otter]

And we said that
32° = A = 9x +14

E is congruent to A

Therefore A is 32°

[craggy field]

So the answer for it is 32°?

Ok how can we solve number 2 A

[lean otter]

Try using the same principle

Find the congruence and solve for X

[craggy field]

1.2?

[lean otter]

How'd you get to that?

[craggy field]

6 divide by 5

[lean otter]

Why'd you think of that

do you know the concept of congruence?
consider, HN is = to BG

and HN is 35mm

Therefore?

[craggy field]

What to do in BG?

Is X= 1.2?

[lean otter]

BG = HN
And since HN is = 35mm
BG = 35mm
It also states that BG = 6x +5

Substitute that, getting: 6x +5 = 35

solve for X

[craggy field]

X=5

What to do in 2 B

[lean otter]

Look at this

Read

[craggy field]

35mm?

[lean otter]

Yes

[craggy field]

Ok

Is that all? :))

[lean otter]

Mhm

[craggy field]

Ok

Thanks

.solved

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[desert onyx]

I have to do some integral, so what I did is integrate for x first

[hazy elbow]

ok

[desert onyx]

ignore the top right thing

but idk how to integrate for y now

or maybe I have done something wrong

If I try to integrate for y first, I have the same problem, that I dont know how to integrate e^(y^3)

[safe radish]

@desert onyx Has your question been resolved?

[desert onyx]

<@&286206848099549185>

[safe radish]

@desert onyx Has your question been resolved?

[safe radish]

@desert onyx Has your question been resolved?

[safe radish]

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[tribal inlet]

!help

[safe radish]

To ask for mathematics help on this server, please open your own help channel or help thread. See #❓how-to-get-help for instructions.

[tribal inlet]

hi

[vale oriole]

question?

[spice wing]

Hi

[spice wing]

Dont you have manners to wave back a hi

[tribal inlet]

heres the question

so i already did the steps

the slope is -7

[spice wing]

Yeah we see

[tribal inlet]

is it y - 6 / y - 9

or is it y - 6 / y - (-9)

which one is it

i mean soryry

y - 6 / x - 9

[spice wing]

Therfore y-6/x+9 = -7

[tribal inlet]

or y - 6 / x - (-9)

do u know which one it is

[spice wing]

Yes

[tribal inlet]

ok which one is it

[spice wing]

So y-6 = -7(x+9)

[tribal inlet]

y - 6 / x - (-9)
y - 6 / x - 9

so its gonna be the x - (-9)

is what ur saying

[spice wing]

Yeah

[tribal inlet]

ok thx

[safe radish]

@tribal inlet Has your question been resolved?

[safe radish]

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[deep comet]

How many ways can a clerk give a customer 25c in change?

[deep comet]

I know how to do this manually. I'm just wondering if I solve it sonehow using math. (Alg 2)

[tender meteor]

@deep comet do you have the solution?

[deep comet]

No, but I might could get it from the teacher.

Ok there are 13 ways

According to the answer guide.

I got all 13, but its messy because I did it manually.

[eternal carbon]

you can think of this situation represented by an equation like 25a + 10b + 5c + d = 25 where a, b, c, d are non-negative integers

[deep comet]

Okay

So what then?

[vagrant ice]

Just try listing all the possible cases

For example you could have a = 1 and the rest being 0

So for all the other cases, you need a = 0 and that simplifies things

Similarly, b can only be 1 or 2

[vagrant ice]

Yeah there's no systematic way to do this other than by listing them out

https://en.wikipedia.org/wiki/Integer_partition

For example there's no pattern for this

and there's also no pattern for a derangement

https://en.wikipedia.org/wiki/Stars_and_bars_(combinatorics)

Stars and bars only works cause you can imagine the different bins being separated by lines

And then the number of ways to arrange the lines and the objects to create the different possibilities given by a combination, nCr

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[safe radish]

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[late prism]

how do you find the number a when its a probability but not a number?

[late prism]

how do u find the total?

[tardy mango]

$n(A)=n(A \cup B)-n(\overline{A} \cap B)$

[flat frigate]

Civil Service Pigeon

[tardy mango]

This gives you n(A)=86

Using probability = favored/total,

0.2 = 86/(total)

Which gives you the total as 430

[late prism]

ohhhh

tysm

saved me mate

also how did u get the rest? as in a' and b'

[late prism]

the 335 one

[tardy mango]

?

[late prism]

how did u get this one

[tardy mango]

$n(\overline{B})=430-n(B)$

[flat frigate]

Civil Service Pigeon

[late prism]

do i have to memorise these?

[late prism]

these types of formulas?

[tardy mango]

I mean

Just draw a venn diagram

[safe radish]

@late prism Has your question been resolved?

[safe radish]

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[hot wren]

1. Given h(x)=2x^2+7x
   a) Find the AROC between X=3 and X=3+h
   ok got it, i solved 2h+19

2. Find the IROC for h(x) at the point (3, 39)
   ok done, lim approaches 0 2h+19 = 19

3. Write the equation of the tangent line to h(x) at the point (3, 39)
   ok don't get it

[hot wren]

I need help with part 3

pre-calculus

nvm i get it

.close

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[young basin]

Z = -1 0
0 0

how do i find nullspace of Z

[young basin]

i know that i should solve for Zx = 0

but then i get all 0

ans must be 0
1

[novel stag]

can you show how you got 0?

[young basin]

-1X = 0
x = 0
its wrong but thats how it works for other problems if there is y component

[novel stag]

yes the x is zero, but what about the y?

[young basin]

2 row is 0

so what does y become actualy?

[novel stag]

try to multiply Z with a vector like (0,1)

[young basin]

its 0

[novel stag]

the thing you are forgetting is the free variable

[young basin]

can u please explain that

i do know about free variable but i havent encounterd this kindof problem

[novel stag]

why its a free variable or how you find out it is one?

[young basin]

i know that freee varaible is the column that will not have pivot

[young basin]

Idk please explain

[novel stag]

yes, so then y in your case is a free variable, as you can look at the first column as x and second as y

[young basin]

Ohh okay. What should i do next

[novel stag]

i usually set it up like

x = 0

y = t (t is your free variable)

[young basin]

Ohkay

So basis is (0 1)

[novel stag]

the nullspace is the span of (0,1), yes

[young basin]

Ohh fine thanks 🙏🏻

[novel stag]

np 🙂

[young basin]

.close

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[west wharf]

Could I please get a hint for 5.4?
this is the expression I have so far
Thanks!

[safe radish]

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[fathom vessel]

perimeter is 60 cm im stuck on how to find the x

[thin bridge]

apply definition of perimeter to set up an equation

[fathom vessel]

the perimeter is 60 centimeters around. you have to add all of the numbers to find the perimeter. you have to find x before you can see how the numbers add up. does this work for you?

[thin bridge]

you don't need to know x to be able to add stuff

[fathom vessel]

...oh...

.close

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[primal cape]

Help

[primal cape]

@help

<@&286206848099549185>

[cobalt sinew]

what is the question

[primal cape]

Iam writing

[cobalt sinew]

write first then mention helper

[tough heart]

Hey it's ok. He didn't mean it

[cobalt sinew]

im chill, just telling him the procedure

[tough heart]

Oki

[flat frigate]

Daksh_GamerYT

[primal cape]

I got from my techer

Teacher

<@&286206848099549185>

<@&286206848099549185>

Pls it's urgent homework

[drowsy moss]

!15min

[safe radish]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[primal cape]

Zybikron pls

Help me

@drowsy moss

[tardy pivot]

lmaoo

[primal cape]

What?

[tardy pivot]

u shouldn't spam helpers and also don't @ individual helpers if they cant help u

anyway

[primal cape]

Sorry I didn't know

[tardy pivot]

you want to eliminate x or y in one of the equations

[tardy pivot]

np

[primal cape]

X

[tardy pivot]

so write x = 12/y then substitute into the other equation

[primal cape]

Oh ok

Done

[tardy pivot]

what do u get?

[primal cape]

13

[tardy pivot]

i dont understand what u did to get 13

[thick plaza]

me too

you should have a biquadratic equation

[drowsy moss]

glad to see this was such an urgent and important question that they vanished 🙄

[thick plaza]

🤣

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@primal cape Has your question been resolved?

[safe radish]

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[safe radish]

@lean otter Has your question been resolved?

[knotty pier]

Tf is that

A triangle is never a rectangle?

[safe radish]

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[lean otter]

what

[spice wing]

bro simply find the length of sides and use formula

Else it is said one side is perpendicular so cam use 1/2 ×b×h too

[lean otter]

Okay

.close

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[jovial crest]

I need help

[jovial crest]

What am I missing

1st and 2nd equation i think is right, but im not sure about 3rd and dont know what to do next

[finite yacht]

It is 21 instead of 27

The next thing you should do is to solve the first two equations

[jovial crest]

And then put in 3d

[finite yacht]

Yes

[jovial crest]

But why there is that angle between x axis and a is wide?

Where i should use it

[finite yacht]

You should write the solutions of the first two using a parameter

[jovial crest]

Oh i think i know

From 3d eq i get module

[finite yacht]

||If there are quadratic equations, you always need some condition like this one, to be able to choose one of the two solutions||

[jovial crest]

And need to take with - sign

[finite yacht]

Yes, the three equations determine a up to multiplying by -1

[jovial crest]

Ill try

@finite yacht are u still there?

[finite yacht]

Yes

[jovial crest]

I did smth wrong

[finite yacht]

84/21 is not 21

Near the end

[jovial crest]

Jesus

Lol

Day was long 😂

So its +- 2

I need to take -

Right?

[finite yacht]

These things always happen to me, it always is annoying

[jovial crest]

Classic me

[finite yacht]

It depends

[jovial crest]

But if my angle with x axis is wide

[finite yacht]

The vector is either (-4,1,2) or (4,-1,-2)

[jovial crest]

Then cos from wide angle is negative

Oh

[finite yacht]

So x<0

a_z = 2

[jovial crest]

Hmm

In answer its -2

[finite yacht]

Strange

Are you sure it is the angle with the x axis?

[jovial crest]

But its right what am i saying?

[finite yacht]

Yes, but in this case the cos has the same sign as a_x

[jovial crest]

76.a

I think then its just mistake in the answers

But im still not sure how to get sign

If i need to explain to myself why its - sign, then i cant 😅

[finite yacht]

Use dot product

sqrt(21) equals a•(1,0,0) times cos(θ)

No

Divided by

[jovial crest]

(1;0;0) is because x axis?

Right

[finite yacht]

So sqrt(21)=a_x/cos θ

[finite yacht]

Yes

The angle is wide if cos θ < 0

And sqrt(21) > 0

So a_x has to be negative

[jovial crest]

What is this what u use?

[finite yacht]

One of the properties / definitions of the dot product

[jovial crest]

The part where i need to understand that i need - sign is okey, my problem is that i forgot about vectors so much

[finite yacht]

$u\cdot v = |u||v|\cos\theta$

[flat frigate]

d

[jovial crest]

Yes

So u is a

And v is x

[finite yacht]

(1,0,0)

So |v|=1

[thick plaza]

or it can be u1·v1+u2·v2

[finite yacht]

Yes, that's the point, with that definition it equals a_x and with the other one, sqrt(21) cos θ

[jovial crest]

Wait

So i get it?

@finite yacht thanks a lot

[safe radish]

@jovial crest Has your question been resolved?

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[lean otter]

whats ur questions

😭

[dark cargo]

do you know the formula for the vertex of a parabola

[pure lark]

No i don't

-b/2a?

.close

[safe radish]

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[safe radish]

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[iron coral]

i need help with this!

[iron coral]

<@&286206848099549185> i need help with this urgently

[severe pond]

what’s confusing

[iron coral]

all of this ngl but i don’t wanna take up all your time but can we start of with did i get 7 and 8 right?

hey @severe pond are you ther

sorry for the ping

[severe pond]

hello

[iron coral]

sorry for the ping

[severe pond]

so he grabs two large pieces

the large pie is divided into 5 pieces

so 2 pieces make up 2/5 of the pie

you know the circumference is pi times the diameter

so it should be (2/5)(pi)(14)

[iron coral]

wait which question are yoh talking about

[severe pond]

7

[iron coral]

oh ok sorry

[severe pond]

did that make sense

[iron coral]

so did i get it right?

i’m still confused sorry 😞

[severe pond]

i didn’t do the calculation

but did you multiply what i wrote

[iron coral]

oh i’ll do it right now

[severe pond]

^

[iron coral]

yea hold on i’m putting it in

so would i do 2/5pi x 14?

[severe pond]

(2/5)(pi)(14)

[iron coral]

ok thanks

i got 17.5929188601

is that right?

wait wouldn’t be 3/5?

because he has 3/5 slices left

@severe pond

sorry for the ping agian

[severe pond]

i assumed they meant of the pieces he took that stayed together

and he took 2 pieces

[iron coral]

i’m so confused i’m sorry i’ll just email my teacher and hope he doesn’t gatekeep the answers

.close

[safe radish]

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[safe radish]

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[versed kayak]

hi

[versed kayak]

I dont understand anything

like I do not know anything

<@&286206848099549185> Grade 11 Precalc Rationals word problem

[distant finch]

if two numbers are x and y

how would you write their reciprocals?

[severe pond]

write two equations

[versed kayak]

so the x+y=41?

what now

[distant finch]

.

[severe pond]

the sum of their reciprocals

[versed kayak]

what is reciprocals mean

[severe pond]

1/x

1/y

[distant finch]

switch the numerator and denominator

[versed kayak]

ok

1/x+1/y=41/400??

[distant finch]

yeah

[versed kayak]

what now

😭

[distant finch]

what if they both had the same denominator

[versed kayak]

whay

wdym

[distant finch]

it would definitely make it easy to work on the equation

[granite idol]

combine the fractions

[severe pond]

get a common denominator

[versed kayak]

im visual learner

can u draw

or write

pls

🙏

[severe pond]

how would you combine 3/8 +1/2

[granite idol]

https://www.khanacademy.org/math/cc-fifth-grade-math/imp-fractions-3/imp-adding-and-subtracting-fractions-with-unlike-denominators/v/adding-small-fractions-with-unlike-denominators

[severe pond]

and write it as a fraction

[versed kayak]

u do

4×1/2?

[versed kayak]

so 4/8

[severe pond]

and add the numerators

[versed kayak]

11/8?

[severe pond]

4+3≠11

[severe pond]

(x+y)/(xy)=41/400

but what is x+y

[versed kayak]

xy=400?

[severe pond]

mhm

[versed kayak]

y+x=41

[severe pond]

yup

[versed kayak]

y=40 x=1

[severe pond]

no

[versed kayak]

what

why

[severe pond]

(40)(1)≠400

[versed kayak]

oh

[severe pond]

you have a system of equations

xy=400

x+y=41

there are multiple ways to solve this

maybe you’d want to isolate one variable

[versed kayak]

ohhh

I kinda get it

[severe pond]

and write it in terms of the other

[versed kayak]

it's like the trinomial

thing

right

[granite idol]

you already started writing one variable in terms of the other

specifically, you had x = 41 - y

[versed kayak]

only factors of 41 is 1 and 41

[severe pond]

but that’s not the question

you have xy=400

you could say x=400/y

or you could do the same with y

and use the other equation

x+y=41

[severe pond]

and use this value for x

or you reverse it and do x=41-y

and use that in the other equation

won’t matter

[versed kayak]

WOWWW

16+25

41

WOWW

THANK U SO MUCH

🙏🙏🙏

[versed kayak]

thank u thank u

[severe pond]

you’re welcome

[versed kayak]

🙂🙂🙂

[versed kayak]

what do I do now

[severe pond]

well you already found the two numbers

x,y=16,25

[versed kayak]

did I finish solving it

[severe pond]

yes

it said find the two numbers

[versed kayak]

do I make the statement now

[severe pond]

the numbers are 16 and 25

[versed kayak]

🙂🙂🙂

OKAI

YAY

THANK U

[severe pond]

mhm you’re welcome

[versed kayak]

I dont get this now

I dont understand word problems

it says rate×time but there's no rate

oh wait

no theres no time

there is raye

[versed kayak]

do u have time to help me with another one😞

[severe pond]

yea sure

maybe you should draw a diagram

and set up some equations

and variables

distance=(rate)(time)

time=(distance)/(rate)

let t=time for simplicity

we can label d1=20km

d2=12 km

so if they travel downstream what do you think happens with the rate at which they travel compared to when they travel upstream

[versed kayak]

it no sned

ok it sent

[versed kayak]

what is a diagram

[severe pond]

like a picture

[versed kayak]

ok

brb I draw

[versed kayak]

I dont understand

[severe pond]

ok well you have t=d1v1

where v1 is the rate

or speed

but the rate

isn’t the same

in each case

the rate upstream is not the same

[versed kayak]

yk whay

maybe I need break from

math

my brain is too like

I cant process anything

that 1 word problem took all my brain power

[safe radish]

@versed kayak Has your question been resolved?

[safe radish]

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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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[severe garden]

Hi, I have no idea what I’m doing honestly but if I could get some help getting on the right track that would be helpful, this is the work I’ve done so far, not sure if my equations are even right in the first place, thanks

[granite idol]

looks like you're on the right track

[severe garden]

Not really sure where to go from here, would I replace cost with the 1200000 and solve for w? I’m not sure how to do that especially with the h variable still in the equation

[safe radish]

@severe garden Has your question been resolved?

[granite idol]

I can't stay to help but this looks like a Lagrange multipliers problem

[severe garden]

that's okay, thanks for the help

[unkempt perch]

hmmm, i think i can help with this one

[severe garden]

Just looked it up and I've never seen anything like a Lagrange multipliers problem before, definitely did not go over that in class.

thank you!

[unkempt perch]

gimme a sec to look it over some more

[severe garden]

no problem, take your time i appreciate it

[safe radish]

@severe garden Has your question been resolved?

[unkempt perch]

i'm making a mistake somewhere. pretty sure i know what the answer should be, but i know i'm making a mistake somewhere

[severe garden]

that's okay im still trying to figure it out myself rn

[unkempt perch]

i've done these sorts of problems before. the way i did them was to solve for one of the variables, substitute for that variable, find the derivative, set it equal to zero, solve the for the remaining variable, plug that back into the other equation, solve for the other variable

[severe garden]

ohhh, yea that makes sense, i think i've done some of those in physics before

[unkempt perch]

so i figure that we're trying to maximize volume, so that's the equation we want to find the derivative of

so i set up the other equation with the costs

[severe garden]

yea, this is part of the optimization unit,

[unkempt perch]

and then solve for one of those variables. h is the only variable that can really be singled out there, so i solved for that one, sub'd that into the volume equation, found the derivative

the problem i'm having is making it equal to zero

so i'm pretty confident that i'm making a mistake somewhere

[severe garden]

i'm gonna try to figure it out using that method rn

[unkempt perch]

i think i may have found my problem

[severe garden]

I just found this in my notes, idk if this question is kinda the reverse of the one I’m having issues with or if I should just ignore it

[unkempt perch]

lol, still made a mistake, ending up with a negative number for h

about to head home from work, sorry, have to go 😦

[severe garden]

it's all good, I think this helped a bit

thanks!

[granite idol]

You didn't calculate V' correctly. Fix that and it'll be correct

[severe garden]

wait would it be v'=-6w+2000=333.33?

w=333.33 i mean

messed up the derivative too lol, v'=-6w^2+2000 and then w=18.257

[granite idol]

I think square root it

[severe garden]

yea, messed that up, I think i've got it, then just sub w into my other equations for the answer

thank you!!! I spent way too long trying to figure that out lol

.close

[safe radish]

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[granite idol]

Stop spamming this. Open your own help channel.

[last heath]

yea open a help channel

[safe radish]

To ask for mathematics help on this server, please open your own help channel or help thread. See #❓how-to-get-help for instructions.

[safe radish]

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[wispy pivot]

Why couldn't we just mult row 2 by -1 and add to row 3?

[wispy pivot]

I have just been confused because couldn't you really zero out the last row?

[median vigil]

that's fine, they just chose to do it in a different order

[wispy pivot]

man! i got a diff answer hold on

[lean otter]

What is the purpose of the question?

[wispy pivot]

row reduce

[lean otter]

Probably wanted amost of the elements to be 1

[lean otter]

You mean to the most simplified form ?

[wispy pivot]

yeah row reduced echelon form

[lean otter]

[wispy pivot]

ahh ok

i think i got it now

[safe radish]

@wispy pivot Has your question been resolved?

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[gusty lodge]

How do I solve this?

[safe radish]

@gusty lodge Has your question been resolved?

[lean otter]

! status

[safe radish]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[gusty lodge]

2

[lean otter]

<@&286206848099549185>

Someone more competent than me

Please help

[gusty lodge]

Thank you😭!!

[lean otter]

I'm an expert at deflecting problems

[safe radish]

@gusty lodge Has your question been resolved?

[safe radish]

@gusty lodge Has your question been resolved?

[light stone]

what you need help with

[gusty lodge]

Idk how to solve it

[gusty lodge]

For question 3

Idk if I did it right bc how am I meant to integrate the RHS

[light stone]

,w solve mv'+bv=ksin(ct)

[flat frigate]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by hrdxpqurcxktdbanql

[light stone]

lol good luck

[light stone]

do you know laplace transforms?

[gusty lodge]

Nope

I’m guessing this is a uni question? I’m doing a levels rn so probs won’t be able to solve it

[light stone]

is that high school level?

[gusty lodge]

Yeah, I’m 18 so pre college

[light stone]

ok

you are familar with solving first order differentials, right?

[gusty lodge]

Yes

[light stone]

i see

i would help you but the only thing i remember is solving by laplace transforms

[gusty lodge]

Are they hard or would I be able to use it for this question with no previous knowledge of it?

[light stone]

it requires knowing how to do laplace transforms and inverse transforms

so it owuld require some knowledge

[gusty lodge]

oh okay nevermind

Thank anyway though!

[safe radish]

@gusty lodge Has your question been resolved?

[safe radish]

@gusty lodge Has your question been resolved?

[safe radish]

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[plain dove]

Help.

[plain dove]

How can I prove this?

[spice grove]

There's no parallel lines, atleast not according to the given information. (For whoever said alternate interior)

[flint pike]

go off of the 119 first

the angle on the other side of that is what

[plain dove]

Pardon me?

[spice grove]

Do you understand why the angle 1 is also 32? Or is that your question?

[plain dove]

I have given the answer. I want to know how to justify it with correct geometric reasons.

[spice grove]

The 32 degree angles. (Both of them) Are subtended by the same arc.

[plain dove]

Oh ok...

[spice grove]

For a given arc length, all the subtended angles on the circumference of the circle are the same.

[plain dove]

Same with the shaded ones right?

They are also subtended by the same arc.

[spice grove]

There's only one shaded angle?

[plain dove]

I meant like the un-labelled one.

[spice grove]

yes

[plain dove]

Would this also be another question of the same sort?

[spice grove]

Yes.

[plain dove]

Are those two points the angle on the same arc?

[spice grove]

Yeah.

[plain dove]

Same with these two?

[spice grove]

This arc doesn't subtend any angle on the circumference does it?

[plain dove]

I'm not sure lol.

[spice grove]

Circumference is like on the circle.

[plain dove]

Yes...

[spice grove]

The angle this arc subtends is somewhere inside the circle as is apparent in this figure.

[plain dove]

OK.

Thanks!

.close

[safe radish]

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[plain dove]

.reopen

[safe radish]

✅

[plain dove]

How can I justify this?

Thanks.

[drowsy moss]

which part?

[plain dove]

65 deg.

I would assume we would have to justify every part of the working out.

How we got 65 deg, 39 deg, etc.

[acoustic wharf]

this question is based on one of the theorem u have studied in 9th standard

if u use NCERT books...

[plain dove]

But I don't.

So what would that theorem be?

[drowsy moss]

the 65 is because it's on a line with 115, angles making a straight line are supplimentary

the purple 39 is then just using the angles of triangles.

[plain dove]

Oh... didn't notice that! Thanks.

[drowsy moss]

then you have that two angles inscribed in a circle with the same arc are congruent. So knowing the purple 39 should tell you the red 39

[plain dove]

Angles subtended by same arc is equal?

That's the one for the purple 39 deg right?

Thanks so much guys!

.close

[safe radish]

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[safe radish]

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[dire storm]

i saw the emojis you sent in my help channel

show me the rest of the screenshot

some text is left out

let me see it

ok, but why is it mentioning logarithms in question 2?

[safe radish]

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[flint loom]

can anyone explain how to do part b?

[warm stirrup]

do you know newton's method

[flint loom]

kind of

[warm stirrup]

try using that on y'

[flint loom]

are you always supposed to use newtons method on the derivative of a function?

because in some other questions I did they used newton method direclty on the function and not the derivative of it so I'm confused as to when you're supposed to use it on the derivative or not

[warm stirrup]

you use newton's method to find when a function is 0

in this case you want the stationary point, which is when the derivative is 0

if it asked for when y=0 then you would do it on the function itself

[flint loom]

ohh i see

[safe radish]

@flint loom Has your question been resolved?

[safe radish]

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[lean otter]

Dumb question but is this right?

[devout lodge]

Whom needs help

[lean otter]

Me

[devout lodge]

For some reason the image won’t load for me

[lean otter]

Now?

[devout lodge]

No.

[lean otter]

Uhh

Can i dm it lmao

[devout lodge]

No lmao

[lean otter]

☠️

[devout lodge]

tryna cheat ☠️

[lean otter]

Huh?

[devout lodge]

dumbass

[lean otter]

What

Tf

Anyway <@&286206848099549185>

[tribal prawn]

They’re suppose to help not give u answers

[lean otter]

…

What are yaal on abt

I did the work..

[devout lodge]

wrong image

[lean otter]

.close

[safe radish]

Channel closed

Closed by @still musk

Use .reopen if this was a mistake.

[tribal prawn]

stop trolling

[devout lodge]

trolling?

[granite idol]

don't be rude or you'll get muted

[devout lodge]

Who are you

shivering

[lean otter]

☠️

Your this bored huh

[devout lodge]

No I was trying to help

[lean otter]

Nah you clearly wasnt

Im good tho

You can keep it

[granite idol]

what's your original question?

[lean otter]

It wasn’t a question i just wanted to know if what i did was right

Well perse

[granite idol]

looking for min/max or what? need some context

[lean otter]

Yea

Min and max

Yes

[granite idol]

yeah the critical points are at 0 and 2/3

[lean otter]

Thank you berry much

[safe radish]

Available help channel!

Send your question here to claim the channel.

Remember:
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• Show your work, and if possible, explain where you are stuck.
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[ruby musk]

Hi, I have a new answer here that I would like to check with you guy

s

This is my original work and I discussed with someone else why my answer was wrong but they had to go before I could submit my new answer

now I have com up with (-1)^n + 1(n!)(6)/ (1 / 1 + 3^x) ^ n + 1

<@&286206848099549185> bump

[timber night]

I am not gonna be helping you with that definitely

[ruby musk]

why?

should i rewrite it

[timber night]

Yes.

[ruby musk]

I dont know but I dont think it is super relevant because it is just a draft

but my point is just that I found the derivatives and now I am looking for the pattern to all of them

are the numbers readable?

[lavish scaffold]

should be -2x-6 on top for f'(x)

no he is multiplying 2 by (1 + 3x)

[ruby musk]

the new one?

[ruby musk]

how come?

I use n factorial to cover the 2s I believe

[lavish scaffold]

oh my bad misread then, but it should be -6x

unless thats a product and not -

[ruby musk]

wait i will send a pic of my new answer

,rotate

[ruby musk]

yeah so i coul djust change the (1/ 1 + 3x) ^ n+1 and put it in the denominator right

[lavish scaffold]

btw if you know leibniz formula you can try getting a reccurent formula of f^(n)

[ruby musk]

wait really

oh okay

i dont think we use those formulas for this question

[lavish scaffold]

this?

you can set g = (1+3x) so youd get (fg)^(n) = 0 for n >= 2

and (3x)'' = 0 so itd be C_0^n*f^(n)(x)g(x) + C_1^n*f^(n-1)g'(x) = 0 for n>=2

[ruby musk]

yes but in the way my professor does taylor series he says we should guess the pattern

[lavish scaffold]

ohh okay

i see

[ruby musk]

btw

I am not able to get this euqal to -1.386

[lavish scaffold]

(i mean that way is like a tip then lol, to "guess" the pattern)

[ruby musk]

am I doing math wrong

which one

yeah but that one is so wrong

the new one looks a little bit better

ohh

right

thank you

am i allowed to ask other questions in here

or should i make a new one

so

This question i am not sure how to do

to be honest

i dont evne know how to start

i dont remember doing something like this

well

hmm

they have the same slope

?

angle of the function i guess

ok so i can first take derivative of these functions

yes i know vectors

wait i just got the derivative

should i plug in 1

wait nvm

so I got the slope but I am not sure how to use it

are both of these linear algebra?

to be honest im sorry but i still dont understand how to use vectors or the angle to do this

do you mind showing me?

tg(a)?

to be honest

i dont know that

is vectors linear algebra though

I could try g'(x) = tg(B)

okay

that makes more sense to me

to be honest

yes

so the derivative i got was 5x^4 / 4 + 1 for g

and for f I got 2 / ( 1 + 3x)^2

so (1, 5x^4/4 + 1)

?

yeah

then what can i do?

oh yeah

i know how to find it

but how would that help me get the angle here

ohhh

wait is this absolute value sign or magnitude

so i would get

1, 5x^4/4 + 1 . 1. 2/(1 + 3x)^2 on left side

hmm